Multiplication Tables for 0 to 25

Below is the list of Math Tabes for 0 to 25 to make your math calculations easier and faster. These Time Tables from 0 to 25 help your child to skillfully tackle complex problems too with ease. Remembering the Multiplication Tables not just brings out self-confidence in you but also keeps information prepared at your fingertips so that you can use it whenever required. On Mastering the 0 to 25 Multiplication Charts children can enhance their speed and accuracy.

Importance of Math Tables or Multiplication Tables

Math Tables are the basic blocks of arithmetic calculations. Learning these Multiplication Tables can stimulate the memory power in kids and develop observation skills. Things learned at an early age can be retained for a long time. Refer to the below modules to know why one should learn Maths Tables and they are as such

• Multiplication Tables are quite important as they support in student’s mathematical learning.
• Students can get a strong grasp of facts associated with multiplication.
• Makes it easier to solve problems in Mathematics.
• The one who tends to be good at these Times Tables will be self-confident while learning new math concepts.

Tips to Memorize Multiplication Times Tables

Most of you might struggle to memorize the math tables. However, we have curated few effective tips that help you to learn the Math Times Tables easily. They are in the following fashion

• Practice Skip Counting i.e. if you start with a number 2 keep adding 2 every time you count. That is you would say 2, 4, 6, 8, 10, 12, 14…..
• Recite the multiplication tables in order at least once a day until you remember them. Also, learn reverse recitation of tables.
• If you have any difficulty in remembering you can always opt for writing and memorizing. Make it a habit in your daily routine and try to memorize once.
• Apply multiplication tables to real life and try to understand them using real-life scenarios.
• Identify the Multiplication Table Patterns so that you can remember them much faster.

Learn 2 to 9 Times Multiplication Tricks

FAQs on Maths Times Tables

1. What is the easiest way to memorize the multiplication tables?

One of the easiest ways to memorize the Math Tables is through addition. We know the number of times a number is multiplied with another number it is added to itself the same number of times repeatedly.

2. How to memorize Multiplication Times Table?

In order to memorize the Multiplication Times Table start reciting it verbally on a regular basis or write it down on paper. In fact, you can solve questions involving multiplication charts to retain them for a long time.

 3. How Can I Learn Tables Fast?

Start with the easiest ones and then work on them until you feel confident. Learn the Tips & Tricks to memorize the Math Tables easily. Recite them as many times as possible or write to remember them fast.

3 Times Multiplication Chart

Learning Table of 3 is quite essential to do your math calculations in a much faster way. Utilize the Table of 3 to understand and gain a deeper insight into the multiplication operation. For your idea, we have given the 3 Times Multiplication Table in image format. You can download and save it without paying us a single penny. Use this Table of 3 Chart for quick reference and try to recite it every day and memorize it easily.

How to Read Three Times Multiplication Table?

One time three is 3

Two times three is 6

Three times three is 9

Four times three is 12

Five times three is 15

Six times three is 18

Seven times three is 21

Eight times three is 24

Nine times three is 27

Ten times three is 30

Eleven times three is 33

Twelve times three is 36

How to write a Multiplication Table of 3? | Three Times Table upto 20

Learn how to write Table of 3 by checking out the below table. We have outlined the 3 Times Table up to 20 natural numbers so that you can get deeper knowledge on the multiplication which would be beneficial in the long run.

Why should you Learn the Multiplication Table of 3?

Go through the below lines to know the importance of the Three Table. They are along the lines

• Learning the Table of 3 is a necessary skill to solve problems on long division and multiplication.
• You can perform your metal math calculations right in your head and improve your problem-solving skills.
• By Learning the Multiplication Table of 3, you can understand the pattern of multiples.
• Ensures faster calculations and saves a lot of time.

Tips to Memorize 3 Times Table

Follow the below-listed tips & tricks to keep in mind to learn and memorize the Multiplication Table of 3. They are in the below fashion

• • • • Apparently, there are any rules that make the table of 3 easy to remember. However, there is a pattern for every 10 multiples of 3 i.e. 3, 6, 9, 12, 15, 18, 21, 24, 27, 30.
      • The last digit of these multiples will always repeat. You can remember these digits to memorize the multiples of 3 easily.
      • Another way to learn 3 up to 10 is through skip counting.

    

By referring to the above image you can understand that the units digit are nothing but counting numbers written three in one column in descending order from right to left. 0 is left outside the grid. Later, place the digit 0 before the units digit in row 1 and digit 1 in the second row and digit 2 in the third row. Also, place 3 before the digit 0 outside the grid. That’s it you have got the first ten multiples of 3.

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Solved Examples Involving 3 Times Table

1. Using 3 times table, evaluate 3 times 6 minus 3?

Solution:

From the given statement we can write the mathematical expression as follows

= 3*6-3

= 18-3

=15

Thus, 3 times 6 minus 3 is 15

2. Using the table of 3, Find the value of 3 plus 3 times 7 minus 5?

Solution:

First, let us write 3 plus 3 times 7 minus 5 mathematically

= 3+3*7-5

= 3+21-5

= 24-5

= 19

Hence, 3 plus 3 times 7 minus 5 is 19

3. Find the value of 4 plus 3 times 6?

Solution:

Let us write the given statement mathematically

= 4+3*6

= 4+18

= 22

Hence, 4 plus 3 times 6 is 22

4. Using the table of 3, find the value of 3 times 5 minus 3 times 2?

Solution:

Let us write the given statement mathematically

= 3*5-3*2

= 15-6

=9

Hence, 3 times 5 minus 3 times 2 is 9.

Multiplication Table of 2

Here is the Multiplication Chart of Two in image format. Use it as a quick reference to make your mental math calculations much easier. Learning Table of 2 Promotes a better understanding of the multiplication operation. Knowing the basic math tables you can solve the maths problems in no time. You can save a lot of time in your competitive exams by learning the 2 Times Multiplication Table.

How to Read Table of Two?

One time two is 2

Two times two is 4

Three times two is 6

Four times two is 8

Five times two is 10

Six times two is 12

Seven times two is 14

Eight times two is 16

Nine times two is 18

Ten times two is 20

Eleven times two is 22

Twelve times two is 24

Multiplication Table of Two upto 20 | How to Write 2 Times Table?

Below is the Table of 2 up to 20 Natural Numbers. You can avail the Multiplication Table of Two here and use it whenever you need to perform quick calculations. Refer to the 2 Times Table over here to memorize it quickly and recite it on a regular basis so that you can retain it for a long time.

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How to Learn Multiplication Table of Two?

Table of 2 is quite basic and one of the easiest tables to learn and memorize. Let us learn how to obtain and memorize the multiplication table of 2 in the below sections. Basic things to observe in the Multiplication Table of Two are as such

• 2 Times Table follows the pattern 2, 4, 6, 8, 0 in the units place.
• It will always have even numbers
• It is simple as we can learn using skip counting i.e. 2, 4, 6, 8, 10, 12……

Tips to Memorize Two Times Table

Follow the tips & tricks to memorize the multiplication table of 2 by referring to the below modules. They are along the lines

• Two Times Table always follows the pattern of the even numbers i.e. 2, 4, 6, 8, 10, ….
• Another simple way to memorize the Table of Two is through addition.
• You can memorize the Two Table taking the help of the 1 Times Table. All you have to do is simply add the natural numbers to multiples of 1 to get the Two Table.
  • 1×1+1 = 2
  • 1×2+2 =4
  • 1×3+3 =6
  • 1×4+4 =8
  • 1×5+5=10
  • 1×6+6 =12
  • 1×7+7=14
  • 1×8+8=16
  • 1×9+9=18
  • 1×10+10=20 and so on.

Solved Examples Involving Multiplication Table of 2

1. If Reethu eats 2 chocolates per day, Using the table of 2 find how many chocolates will she have eaten at the end of the 5th day?

Solution:

Reetu eats a number of chocolates per day = 2

Number of Chocolates Reethu eats at the end of the 5th day = 2*5

= 10

Therefore, Reethu eats 10 chocolates at the end of the 5th day.

2. Using 2 times table, find 2 times 3 times 4 times 2?

Solution:

Expressing the given statement in the form of mathematical expression we have

= 2*3*4*2

= 48

Therefore, 2 times 3 times 4 times 2 is 48.

3. James wants to buy 6 Pencils. If the cost of one Pencil is $2, using the table of 2, find the cost of 6 Pencils?

Solution:

The Cost of one Pencil is $2

No. of Pencils James wants to buy = 6

Cost of 6 Pencils = $2*6

= $12

Therefore, the cost of 6 Pencils is $12.

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Constant & Variables – Definitions

Constant: A Constant is defined as a fixed value in algebraic expressions or equations. Constant will not change with time and has a fixed value. For instance, Shoe Size will not vary at any point.

In an algebraic expression, x+y = 5, 5 is a constant value, and will not be changed.

Variables: Variables are terms that can change or differ over time. It will not have a fixed value unlike a constant. For example, the Height and Weight of a Person will not remain constant and will vary with time.

In an algebraic expression, x+y = 5, x and y are the variables and can be varied. Go through the below modules to know more about the key differences between Constants and Variables.

Difference Between Constants and Variables

See the main differences between Constants and Variables here. ?They are along the lines

• The main difference between the constants and variables, constant is a fixed value and a variable is not a fixed value.
• Constants are indicated by the numerical values and the variables are indicated by any alphabetical values like a, b, c, d, ………..z.

Examples of Constants and Variables

Find the Constants and Variables of Given Expressions.

1. x + y + 2 =0.

Solution:
The given expression is x + y + 2 = 0.
Here, x and y are variables.
2 is a constant number.

2. x^2 + y^2 + 20 = 0.

Solution:
The given expression is x^2 + y^2 + 20 = 0.
Here, x^2 and y^2 are variables.
20 is a constant number.

3. xy + x^2 + 15 = 0.

Solution:
The given expression is xy + x^2 + 15 = 0.
Here, xy and x^2 are variables.
15 is a constant number.

4. 2xy + 6 = x^2y.

Solution:
The given expression is 2xy + 6 = x^2y.
Here, 2xy and x^2y are variables.
6 is a constant number.

5. x^3 + y^3 = 2xy + 8.

Solution:
The given expression is x^3 + y^3 = 2xy + 8.
Here, x^3, y^3, and 2xy are variables.
8 is a constant number.

6. Find out the constants and variables in the below questions

(i) In 5m, 5 is a constant and m is a variable.
(ii) In -3ab, -3 is a constant and a and b are variables.
(iii) In 4b, 4 is constant and b is variable but together 4b is a variable.
(iv) If 2 is a constant and a is a variable, then 2 + a, 2 – a, 2/a, 2a, a/2, etc., are also variables.

FAQs on Constants and Variables

1. What is the main difference between variables and constant?
The major difference between variables and constants is variable is a varying quantity, and a constant is a fixed value.

2. What are the variables?
The variables are the terms in an algebraic equation that can be changed or that are not fixed. Example: a + b = 8, where a and b are the variables, and 8 is a constant.

3. What are constants? 
The constants are the value in an algebraic expression that cannot be modified or changed. For example, in an equation x + y = 9, 9 is the constant value.

4. What is an algebraic expression?
The algebraic expression is a combination of constants, variables, integers, and mathematical operations.

Read More:

PAGEIND Pivot Point Calculator

Also, Read:

• Concept of Profit and Loss
• Practice Test on Profit and Loss
• Examples on Calculating Profit or Loss
• INFY Pivot Point Calculator

Formulas to Calculate Profit

If the selling price is more than the cost price (S.P. > C.P.), there is a profit. Various formulas to calculate profit are given below. Remember all of them for better learning.

• Formula for Profit Profit = S.P – C.P.
• Formula for Profit Percentage = Profit Percent Formula = (Profit x 100)/C.P.
• Gross Profit Formula = Gross Profit = Revenue – Cost of Goods Sold
• Profit Margin Formula = Profit Margin = (Total Income/Net Sales) x 100
• Gross Profit Margin Formula = Gross Profit Margin = (Gross Profit/Net Sales) x 100

Notation Used in Profit Formula

• S.P. = Selling Price i.e. the cost at which the product is sold
• C.P. = Cost price i.e. the cost at which the product is originally bought

Profit and Profit Percent Examples

Example 1.

Ram purchased 300 calculators at $100 each. He spent $5 on packing each calculator, paid $50 to the carrying for loading, and $500 on transportation. He sold 200 at a rate of $180 each and 100 at the rate of $80 each. Find his profit or loss percent in the whole transportation.

Solution:
Given that Ram purchased 300 calculators at $100 each.
C.P. of 1 calculator = $100
C.P. of 300 calculators = $100 x 300 = $30000
Money spent on packing 1 calculator = $5
Money spent on packing 300 calculators = $300 x 5 = $1500
Overhead expenses = $(1500 + 50 + 500) = $2050
C.P. of 300 calculators = Actual C.P. + Overhead expenses
C.P. of 300 calculators = $30000 + $2050 = $32050
S.P. of 300 calculators = S.P. of 200 calculators + S.P. of 100 calculators
S.P. of 1 calculator = $180
S.P. of 200 calculators = $180 x 200 = $36000
S.P. of 1 calculator = $80
S.P. of 100 calculators = $80 x 100 = $8000
S.P. of 300 calculators = $36000 + $8000 = $44000
S. P. > C. P., there is profit, therefore, profit – S.P. – C.P.
Profit = $44000 – $32050 = $11950
Profit% = P/C.P. x 100%
Profit% = $11950/$32050 x 100%
Profit% = 37.28%

The profit percentage is 37.28%.

Example 2.

A cloth merchant bought 25 shirts, each at a price of Rs 280. He sold each of them for Rs. 300. Find his percentage profit.

Solution:
Given that a cloth merchant bought 25 shirts, each at a price of Rs 280. He sold each of them for Rs. 300.
The profit percentage remains the same for one unit as well for all the units. Thus the calculations should be done for one unit only.
The Cost Price = Rs 280
Selling Price = Rs. 300
Profit = Selling Price – Cost Price
Substitute Selling Price and Cost Price in the above formula.
Profit = Rs. 300 – Rs 280 = Rs 20.
Now, find out the profit percentage formula.
Profit percentage = P/C.P. x 100%
Profit percentage = 100 × 20/280 = 7.14%

Therefore, the profit percentage is 7.14%

Example 3.

A retail fruit vendor buys pineapples at a score of Rs. 200/-,  and retails them at a dozen for Rs 156. Did he gain or lose in the transaction and what % was his gain or loss?

Solution:
Given that a retail fruit vendor buys pineapples at a score of Rs 200, and retails them at a dozen for Rs 156.
The cost price = Rs 220
C.P/Pineapple = 200/20 = 10
1 score = 20 nos
S.P = Rs.156/dozen
S.P/Pineapple = 156/12 = 13.
Profit = Rs. 13 – Rs. 10 = Rs. 3.
% Profit = 100 × 3/10 = 30%

Therefore, the profit percentage is 30%

FAQs on Profit and Profit Percent

1. How do I calculate profit percentage?

The profit percentage can be calculated using the below formula.
Formula for Profit Percentage = Profit Percent Formula = (Profit x 100)/C.P.

2. Is profit and profit percent different?

Yes, Profit is the difference between the Selling price and the Cost price when the Selling price is more than the Cost price.
P = SP – CP; SP>CP
Profit percent will obtain by dividing the Profit with Cost price and multiplying the resultant with the 100.
Profit percent = (Profit x 100)/C.P

3. What is the formula of Selling Price?

Selling Price can be found when the Profit Percentage and Cost Price are given is
SP = {(100 + P%)/100} x CP where SP is Selling Price, P% is Profit Percentage, and CP is Cost Price.

4. How to Calculate the Percentage Gain on an Investment?

• In calculating the percentage gain on an investment, first, determine the original cost.
• Next, Subtract the Cost Price from the Selling price of the investment.
• Take the gain from the investment and divide it by the original amount of the investment.
• Finally, multiply the result by 100 to get the percentage change in the investment.

Also, See:

• Calculate Profit and Profit Percent
• Calculate Loss and Loss Percent
• IDFC Pivot Point Calculator

How to Calculate Cost Price using Sell Price and Loss Percent?

To find out the Cost Price using Sell Price and Loss Percent, use the below formula.
Cost price = selling price + loss
Cost price = selling price + loss% × cost price/100
The Cost price – loss% × cost price/100 = selling price
Cost price(1 – loss%)/100 = selling price
Cost price(100 – loss%)/100 = selling price
Also, Cost price = selling price × 100/100 – loss% (on cross multiplication)

Examples for finding Cost Price using Sell Price and Loss Percent

1. By selling a bicycle for $145, a shopkeeper loses 10%. How much percent would he gain or lose by selling it for $175?

Solution:
Given that by selling a bicycle for $145, a shopkeeper loses 10%.
The selling price = $145
Loss Percentage = 10%
We know that cost price = selling price × 100/100 – loss%
Substitute the selling price and the loss% in the above formula.
Cost price = $145 × 100/100-10
Cost price = $145 × 100/90
The Cost price = $14500/90
Cost price = $161.11
Therefore, cost price of the bicycle = $161.11
Now, if the selling price = $175, then gain = $175 – $161.11  = $13.89
Therefore, gain% = gain/cost price × 100
= 13.89/161.11 × 100
= 1500/150
= 8.62%

Therefore, he would have gained 8.62%.

2. If the selling price of a pen is $9 and the loss percent is 2%, then what is the cost price?

Solution:
Given that the selling price of a pen is $9 and the loss percent is 2%.
The selling price of a pen = $9
The loss percent is 2%.
Cost price = selling price × 100/100 – loss%
Substitute the selling price and the loss% in the above formula.
Cost price = $9 × 100/100 – 2
Cost price = $9 × 100/98
The Cost price = $900/98 = $9.18

Therefore, the cost price of the pen is $9.18.

3. Find out the cost price of the vehicle if the selling price is $3350 and the Loss is $154.

Solution:
Given that the selling price is $3350 and the Loss is $154.
The selling price of a pen = $3350
The loss = $154
Loss = Cost Price – Selling Price
Cost Price = Loss + Selling Price
Substitute the selling price and the loss in the above formula.
Cost Price = $154 + $3350
Cost Price = $3504

Therefore, the cost price of the vehicle is $3504.

FAQs on finding C.P using S.P and Loss%

1. What Does Cost Price Mean?

The cost price is the original price of an item. The cost is the total amount need to produce a product or carry out a service.

2. What is the Formula for the Cost Price?

The formula for Cost Price when the SP and L% are given
CP = {100/(100 – L%)} x SP where SP is the Selling Price and L is the Loss.

3. What are the types of Cost Prices?

Cost Price (CP) is the amount paid to buy the product is known as Cost Price. It is denoted by CP. Also, the cost price classified into two different categories. They are
Fixed Cost: The fixed cost is constant and it doesn’t vary under any circumstances.
Variable Cost: It could change depending on the number of units.

4. How to Calculate Cost Price?

Follow the below steps and find out the process to calculate cost price when the selling price and loss% are given.
1. Note down the selling price and loss%.
2. Write the formula of cost price i.e, CP = {100/(100 – L%)} x SP
3. Substitute the SP and L% in the above formula.
4. Calculate and find the Cost Price of the product.

Do Read:

• Concept of Profit and Loss
• Calculate Profit and Profit Percent
• Examples on Calculating Profit or Loss
• EXIDEIND Pivot Point Calculator

Formula to Calculate Loss and Loss Percent

The loss occurs when a cost price is more than the selling price of a product in a business. The loss is calculated by subtracting the selling price from a cost price. The formula to calculate loss and loss percentage are

• Loss = Cost Price – Selling Price when the Cost Price is higher than the Selling Price.
  or
  Loss = C.P. – S.P. (C.P.>S.P.)
• Loss percentage = (Loss × 100) / C.P
• Selling Price: The Selling Price is the price of a product that was sold by the shopkeeper to the customer for a particular price. Selling price is denoted by S.P.
  Selling Price(SP)= Cost Price(CP) – Loss(L)
• Cost Price: The cost price is the price of a product it is the original cost of a product that was brought from the retailer. Cost Price is denoted by C.P.
  Cost Price(CP)= Selling Price(SP) + Loss(L)

Loss and Loss Percent Examples

Example 1.

A shirt was bought for $300 and sold for $250. Find the loss and loss percent.

Solution:
Given that a shirt was bought for $300 and sold for $250.
The cost price = $300
Also, the selling price = $250
Since, S. P. < C. P., there is loss.
Therefore, loss = cost price – selling price
Substitute the cost price and selling price in the above formula.
Loss = $300 – $250 = $50.
So, loss% = loss/cost price × 100%
Substitute the cost price and loss in the above formula.
loss% = $50/$300 × 100% = 16.66%

Therefore, the loss is $50 and the loss% is 16.66%

Example 2.

If the cost price of 30 pens is equal to the selling price of 35 pens, find a loss percent?

Solution:
Given that the cost price of 30 pens is equal to the selling price of 35 pens.
Let cost price of 1 pen = $1
Then cost price of 30 pens = $30
Also, cost price of 35 pens = $35
Since, selling price of 35 pens = cost price of 30 pens
Therefore, the selling price of 25 pens = $30
Therefore, loss = cost price – selling price
Loss = $35 – $30 = $5.
Therefore, loss% = loss/cost price × 100
loss% = $5/$35 × 100
loss% = 14.28%

Therefore, the loss is $5 and the loss% is 14.28%

Example 3.

Find the loss and loss percentage provided that the cost price is Rs. 60 and the selling price is Rs. 55.

Solution:
Given that the cost price is Rs. 60 and the selling price is Rs. 55.
The cost price = Rs. 60
Also, the selling price = Rs. 55
Since, S. P. < C. P., there is loss.
Therefore, loss = cost price – selling price
Substitute the cost price and selling price in the above formula.
Loss = Rs. 60 – Rs. 55 = Rs. 5.
So, loss% = loss/cost price × 100%
Substitute the cost price and loss in the above formula.
loss% = Rs. 5/Rs. 60 × 100% = 8.33%

Therefore, the loss is Rs. 5 and the loss% is 8.33%

Example 4.

If a house was bought by a man for Rupees 60 Lakhs and he sold it in 40 Lakhs. What is a loss percentage from this business?

Solution:
Given that a house was bought by a man for Rupees 60 Lakhs and he sold it in 40 Lakhs.
The cost price = Rs. 60 Lakhs
Also, the selling price = Rs. 40 Lakhs
Since, S. P. < C. P., there is loss.
Therefore, loss = cost price – selling price
Substitute the cost price and selling price in the above formula.
Loss = Rs. 60 Lakhs – Rs. 40 Lakhs = Rs. 20 Lakhs.
So, loss% = loss/cost price × 100%
Substitute the cost price and loss in the above formula.
loss% = Rs. 20 Lakhs/Rs. 60 Lakhs × 100% = 33.33%

Therefore, the loss is Rs. 20 Lakhs and the loss% is 33.33%

FAQs on Loss and Loss Percent

1. How do you calculate percentage loss?

Follow the below steps to find the percentage loss.
1. Note down the cost price.
2. Then, check out the Selling Price, and calculate the loss.
3. Substitute the Loss and cost price in the Loss percentage formula.
4. Finally, find the Loss percentage.
Loss percentage = (Loss × 100) / C.P

2. What are the Loss and Loss Percent Formulas?

The formula for Loss and Loss Percent are
Loss = C.P. – S.P. (C.P.>S.P.)
Loss percentage = (Loss × 100) / C.P where C.P. is cost price and S.P. is selling price.

3. What is the formula for S.P when Loss and C.P. are given?

The formula for Loss = C.P. – S.P.
Therefore, S.P. = C.P. – Loss

4. How to find the C.P. when Loss and S.P. are given?

The formula for Loss = C.P. – S.P.
Therefore, C.P. = Loss + S.P.

5. How to find loss from loss percentage?

The Loss percentage = (Loss × 100) / C.P
Firstly, multiply C.P with Loss percentage and then divide it by 100 to get a Loss from the loss percentage.
Loss = (Loss percentage × C.P)/100

Also, Check:

• Calculate Cost Price using Sell Price and Loss Percent
• Concept of Profit and Loss
• Calculate Profit and Profit Percent
• Calculate Loss and Loss Percent
• DABUR Pivot Point Calculator

How to Calculate Cost Price Using Sell Price and Profit Percent?

Follow the below process to find out the Cost Price Using Sell Price and Profit Percent. Also, get the Cost Price Formula to solve all the problems.

1. Write down the Sell Price and Profit Percent.
2. Note Down the Cost Price Formula.
3. Substitute the Sell Price and Profit Percent in the Cost Price Formula.
4. Finally, find out the Cost Price Using Sell Price and Profit Percent.

Cost Price Formula

Use the below formulas according to the problem and get the cost price easily.

Cost price = selling price – profit
Cost price = selling price – profit% × cost price/100
The Cost price + profit% × cost price/100 = selling price
Cost price(1 – profit%)/100 = selling price
Cost price(100 + profit%)/100 = selling price
Also, cost price = selling price × 100/100 + profit% (on cross multiplication);
Here, selling price and loss% is known.

Finding Cost Price Using Sell Price and Profit Percent Examples

1. A box was sold for $428 thereby gaining 8%. Find the cost price of the bag?

Solution:

Given that a box was sold for $428 thereby gaining 8%.
The selling price = $428
Gain Percentage = 8%
We know that cost price = selling price × 100/100 + gain%
Substitute the selling price and the gain% in the above formula.
Cost price = $428 × 100/(100 + 8)
Cost price = $428 × 100/108
The Cost price = $42800/108 = $396.29

Therefore, the cost price of the bag is $396.29

2. A fan was sold for $625 thereby gaining 15%. Find the cost price of the fan.

Solution:

Given that a fan was sold for $625 thereby gaining 15%.
The selling price = $625
Gain Percentage = 15%
We know that cost price = selling price × 100/100 + gain%
Substitute the selling price and the gain% in the above formula.
Cost price = $625 × 100/(100 + 15)
Cost price = $625 × 100/115
The Cost price = $62500/115= $543.47

Therefore, the cost price of the fan is $543.47

3. By selling a mobile for $1,240, a trader gains 10%. Find the cost price of the mobile?

Solution:

Given that by selling a mobile for $1,240, a trader gains 10%.
The selling price = $1,240
Gain Percentage = 10%
We know that cost price = selling price × 100/100 + gain%
Substitute the selling price and the gain% in the above formula.
Cost price = $1240 × 100/(100 + 10)
Cost price = $1240 × 100/110
The Cost price = $124000/110 = $1127.27

Therefore, the cost price of the mobile is $1127.27

Also, See:

• Calculate Cost Price using Sell Price and Loss Percent
• Calculate Cost Price using Sell Price and Profit Percent
• Calculate Profit and Profit Percent
• BANKNIFTY Pivot Point Calculator

How to Calculate Selling Price Using Cost and Loss Percent?

Follow the complete process to find out the Selling Price Using Cost and Loss Percent. Also, know the Cost Price Formula to solve all the problems easily.

1. Note down the Cost Price and Loss Percent.
2. Write Down the Selling Price Formula.
3. Substitute the Cost Price and Loss Percent in the Selling Price Formula.
4. Finally, find out the Selling Price Using Cost Price and Loss Percent.

Selling Price Formula when Cost and Loss Percent are Known

You can use the below formula to find the Selling Price of a product when you know the Cost and Loss Percent of that product. The formulas for Selling Price Formula when Cost and Loss Percent Known are

• Selling price = cost price – loss
• Selling price = cost price – loss% × cost price/100
• Selling price = 100 × cost price – loss% × cost price/100
• Selling price = (100 – loss%)cost price/100, [Here, cost price and loss% are known.]

Solved Examples to Find Selling Price using Cost and Loss Percent

1. Sam bought a dress for $250 and sold it to Olivia thereby suffering a loss of 10%. Find the selling price of the dress?

Solution:
Given that Sam bought a dress for $250 and sold it to Olivia thereby suffering a loss of 10%.
The cost price = $250
Loss Percentage = 10%
We know that selling price = (100 – loss%) cost price/100
Substitute the cost price and the loss% in the above formula.
Selling price = (100 – 10)250/100
Selling price = 90 × 250/100
The Selling price = $22500/100 = $225

Therefore, the Selling price of the dress is $225

2. Alex bought a laptop for $600 and sold it to Jack thereby suffering a loss of 12%. Find the selling price of the laptop?

Solution:
Given that Alex bought a laptop for $600 and sold it to Jack thereby suffering a loss of 12%.
The cost price = $600
Loss Percentage = 12%
We know that selling price = (100 – loss%) cost price/100
Substitute the cost price and the loss% in the above formula.
Selling price = (100 – 12)600/100
Selling price = 88 × 600/100
The Selling price = $52800/100 = $528

Therefore, the Selling price of the dress is $528

3. By selling a table for $630, Daisy loses 7%. At what price must she sell it to gain 10%.

Solution:
Given that By selling a table for $630, Daisy loses 7%.
Given that the selling price = $ 630
Loss % = 7%
We know, cost price = selling price × 100/100 – loss%
Substitute the selling price and the loss% in the above formula.
Therefore, cost price = 630 × 100/(100 – 7)
= 630 × 100/93
= $677.41
Now cost price = $677.41
Gain% = 10%
Therefore, selling price = (100 + gain%)cost price/100
= (100 + 10)677.41/100
= 110 × 6.77
= $744.7

At $744.7 price she can sell it to gain 10%.

Question 1:
If a manufacturer allows 40% commission on the retail price of his product, he earns a profit of 9%. What would be his profit percent if the commission is reduced by 25 percent?

Solution:

We need to find out the profit % when the given commission is reduced by 25 percent.
Given data:
According to the question consider
Cost price (C.P.) of the product = $ 100
Then, a commission of the product = $ 40
Therefore selling price (S.P.) = $ (cost price (C.P.) – commission)
= $ (100 – 40)
= $ 60
Given that profit = 9%
Therefore Cost price (C.P.) = \(\frac { 100 }{ 100+gain%} \)* S.P
So,
C.P. = $ \(\frac { 100 }{ 100+9 } \)* 60
= $ \(\frac { 6000 }{109 } \)
Now new commission = $ 15
Therefore new selling price (S.P.) = $ 100 – 15
= $ 75
Gain = S.P. – C.P.
= $ (75 – \(\frac { 6000 }{109 } \))
= $ \(\frac { 2175 }{109 } \)
Gain% = (\(\frac { Profit }{C.P. } \)*100)%

=(\(\frac { 2175 }{109 } \)*\(\frac { 109 }{6000 } \)*100)%

= 36.25 %
Hence, gain % is 36.25.
Question 2:
After getting two successive discounts, a pant with the least price of $ 200 is available at $ 125. If the second discount is 14%, find the first discount.

Solution:
Let the first discount be ‘P%’
Then, 86% of (100 – P) % of 200 = 125

\(\frac { 86 }{ 100 } \)*\(\frac { (100 – P) }{ 100 } \)*200 = 125

100-P = \(\frac {(125*100*100) }{ 200*86 } \)
100 – P = 72.67
P = 100 – 72.67
P = 27.32%
Therefore, first discount price of pant is 27.32%.
Question 3:
A women sells an article at a profit of 20%. If he had bought it at 15% less and sold it for $ 11.50 less, he would have gained 25%. Find the cost price of the article.

Solution:
Given data:
Consider cost price (C.P.) of article be ‘X’
First selling price of article ‘X’ = 120% of ‘X’

= \(\frac { 120 }{ 100 } \)*X
= \(\frac { 6 }{ 5 } \)*X
Cost price of article for ‘X’ at 75% = 75% of ‘X’
=\(\frac { 75 }{ 100 } \)*X

=\(\frac { 3 }{ 4 } \)*X
Second selling price of article ‘X’ = 125% of 3/4 * X
= \(\frac { 125 }{ 100 } \)*\(\frac { 3x }{ 4 } \)

= \(\frac { 15x }{ 16 } \)

As given the article is sold at $ 11.50 less
Therefore, selling prices are equalized to a reduced price

\(\frac { 6x }{5 } \) –\(\frac { 15x }{ 16 } \) = 11.50
\(\frac { 21x }{80 } \) = 11.50
X = $ 43.8
Almost equal to $ 44
Hence, the cost price of an article is given as $ 44.
Question 4:
A dealer sold three – fourth of his articles at a gain of 25% and the remaining at cost price. Find the profit earned by him in the whole transaction.

Solution:
A dealer sold his ¾ th quantity with a gain of 25% and the remaining ¼ that its cost price.
Given data:
Consider cost price (C.P.) of whole articles be ‘X’
Cost price (C.P.) of \(\frac { 3}{ 4} \)th quantity = $ \(\frac { 3x}{ 4} \)
Cost price (C.P.) of \(\frac { 1}{ 4} \)th quantity = $ \(\frac { x}{ 4} \)
Total selling price (S.P.) = $ ((125% of \(\frac { 3x}{ 4} \)) + \(\frac { x}{ 4} \))
= $ (\(\frac { 15x}{ 16} \) + \(\frac { x}{ 4} \))
= $ (\(\frac { 19x}{ 16} \))
Profit / Gain = S.P. – C.P.
= $ (\(\frac { 19x}{ 16} \) – x)
= $ \(\frac { 3x}{ 16} \).
Gain % = (\(\frac { gain}{ C.P. } \)*100)%

= (\(\frac {3x}{ 16 } \)*\(\frac {1}{ x } \)*100)%

= 18.75%.
Hence, the gain % of the article is 18.75%.
Question 5:
A man sold two flats for $ 775,000 each. On one he gains 18% while on the other he losses 18%. How much does he gain or lose in the whole transaction?

Solution:
In this problem he gets an equal amount of profit and loss such cases there is always a loss. Therefore the selling price (S.P.) is immaterial.
Loss % = (\(\frac {common loss and gain %}{ 10 } \))²

= (\(\frac {18 }{ 10 } \))²

= (\(\frac {324 }{ 100 } \))

= 3.24%
The total loss incurred by the person is 3.24%.
Question 6:
Pure petrol costs $ 100 per lit. After adulterating it with kerosene costing $ 50 per lit, a shopkeeper sells the mixture at the rate of $ 96 per lit, thereby making a profit of 20%. In what ratio does he mix the two?

Solution:
Here, we have two different cost prices for different mixtures and one selling price (S.P.).
Given data:
Cost price (C.P.) of petrol = $ 100 per lit
Cost price (C.P.) of kerosene = $ 50 per lit
Selling price (S.P.) of mixture = $ 96 per lit
As we have two cost prices,
Mean cost price = $(\(\frac {100 }{ 120 } \))* 96)

= $ 80 per lit.
Since they asked us to find a ratio it is easy to find out by the allegation rule
Cost price (C.P.) of a unit Cost price (C.P.) of a unit quantity of $ X item quantity of $ Y item
Mean cost
$ M
(M – Y) (X – M)
Similarly using this concept here,
Cost price (C.P.) of a unit Cost price (C.P.) of a unit quantity of $ 100 item quantity of $ 50 item
Mean cost
$ 80
(80 – 50) (100 – 80)
Therefore, required ratio = 30 : 20
= 3 : 2.

Question 7:
Find cost price (C.P.), when
1. Selling price (S.P.) = $ 50, Gain = 18%
2. Selling price (S.P.) = $ 51, Loss = 14%

Solution:
Here, we need to find cost price (C.P.) using below formulae
1. Given data
Selling price (S.P.) = $ 50 & Gain = 18%
C.P. = \(\frac { 100 + Gain%) }{ 100 } \)*S.P.

=$ \(\frac { 100 + 18 }{ 100 } \)*50= $ 59.
2. Given data
Selling price (S.P.) = $ 51, Loss = 14%

C.P. = \(\frac { 100 – Loss% }{ 100 } \)*S.P.

= $ \(\frac { 100 – 14 }{ 100 } \)*51

= $ 43.86.

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Also, See:

• Calculate Cost Price using Sell Price and Loss Percent
• Calculate Cost Price using Sell Price and Profit Percent
• Calculate Selling Price using Cost and Loss Percent

How to Calculate Selling Price Using Cost and Profit Percent?

Step by step procedure is given for you to find out the Selling Price Using Cost and Profit Percent. It is really easy to find the selling price when you know the cost price and Profit Percent. Therefore, check out the procedure and follow the steps while solving problems.

1. Find out the Cost price and Profit Percent from the given problem.
2. Note down the formula of Selling Price.
3. In the next step, substitute the Cost price and Profit Percent in the formula.
4. Finally, find the selling price.

Selling Price Formula when Cost and Profit Percent are Known

The Selling Price Formula is the important thing to remember to calculate all the problems when Cost and Profit Percent are given. Without missing, anyone, remember all the formulas and use them while calculating problems.

• Selling price = cost price + profit
• Selling price = cost price + profit%/100 × cost price
• The selling price = 100 × cost price + profit% × cost price/100
• selling price = (100 + profit%)cost price/100; [Here, cost price and profit% are known.]

Solved Examples to Find the Selling Price Using Cost and Profit Percent

1. Ram bought a Colors Box for $100 and sold it at a profit of 20%. Find the selling price of the book?

Solution:
Given that Ram bought a Colors Box for $100 and sold it at a profit of 20%.
The cost price of the Colors Box = $100
Profit Percentage = 20%
We know that selling price = (100 + profit%)cost price/100
Substitute the cost price and the profit% in the above formula.
Selling price = (100 + 20)100/100
Selling price = 120 × 100/100
The Selling price = $120

Therefore, the Selling price of the Colors Box is $120.

2. Alex bought a music system for $180. For how much should he sell the music system to gain 10%?

Solution:
Given that Alex bought a music system for $180.
The cost price of the music system = $180
Profit Percentage = 10%
We know that selling price = (100 + profit%)cost price/100
Substitute the cost price and the profit% in the above formula.
Selling price = (100 + 10)180/100
Selling price = 110 × 180/100
The Selling price = $198

Therefore, the Selling price of the music system is $198.

3. Robert bought a washing machine for $800 and sold it at a profit of 4%. Find the selling price of the washing machine?

Solution:
Given that Robert bought a washing machine for $800 and sold it at a profit of 4%.
The cost price of the washing machine = $800
Profit Percentage = 4%
We know that selling price = (100 + profit%)cost price/100
Substitute the cost price and the profit% in the above formula.
Selling price = (100 + 4)800/100
Selling price = 104 × 800/100
The Selling price = $832

Therefore, the Selling price of the washing machine is $832.

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