{"id":12657,"date":"2022-04-07T10:54:01","date_gmt":"2022-04-07T05:24:01","guid":{"rendered":"https:\/\/ccssmathanswers.com\/?p=12657"},"modified":"2022-04-07T11:06:56","modified_gmt":"2022-04-07T05:36:56","slug":"big-ideas-math-answers-grade-4-chapter-12","status":"publish","type":"post","link":"https:\/\/bigideasmathanswers.com\/big-ideas-math-answers-grade-4-chapter-12\/","title":{"rendered":"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas"},"content":{"rendered":"<p>Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas is the best source for students. Students can follow the step-by-step procedure to solve the problems. We have given a detailed explanation for every problem. Also, we included real-time examples to make the student&#8217;s preparation perfect. Get the free pdf <a href=\"https:\/\/bigideasmathanswers.com\/big-ideas-math-answers-grade-4\/\">Big Ideas Math Answers Grade 4<\/a> Chapter 12 Use Perimeter and Area Formulas to learn offline. Important notes provided for every concept where quick preparation is possible. So, immediately, begin your practice now and strengthen your knowledge.<\/p>\n<h2>Big Ideas 4th Grade Chapter 12 Use Perimeter and Area Formulas Math Book Answer Key<\/h2>\n<p>Easily improve your problem-solving skills with the help of Big Ideas Math Book 4th Grade Answer Key Chapter 12 Use Perimeter and Area Formulas. We have also included an additional practice section where you can test your knowledge and find out the difficult concepts for you. Concentrate on the difficult topics and become the expert on the complete concept. Easy learning and fast solving skills will come at the same place by using Big Ideas Math Grade 4 Chapter 12 Use Perimeter and Area Formulas Solution Key.<\/p>\n<p><strong>Lesson: 1 Perimeter Formula for a Rectangle<\/strong><\/p>\n<ul>\n<li><a href=\"#Lesson_12.1_Perimeter_Formula_for_a_Rectangle\">Lesson 12.1 Perimeter Formula for a Rectangle<\/a><\/li>\n<li><a href=\"#Perimeter_Formula_for_a_Rectangle_Homework_&amp;_Practice_12.1\">Perimeter Formula for a Rectangle Homework &amp; Practice 12.1<\/a><\/li>\n<\/ul>\n<p><strong>Lesson: 2 Area Formula for a Rectangle<\/strong><\/p>\n<ul>\n<li><a href=\"#Lesson_12.2_Area_Formula_for_a_Rectangle\">Lesson 12.2 Area Formula for a Rectangle<\/a><\/li>\n<li><a href=\"#Area_Formula_for_a_Rectangle_Homework_&amp;_Practice_12.2\">Area Formula for a Rectangle Homework &amp; Practice 12.2<\/a><\/li>\n<\/ul>\n<p><strong>Lesson: 3 Find Unknown Measures<\/strong><\/p>\n<ul>\n<li><a href=\"#Lesson_12.3_Find_Unknown_Measures\">Lesson 12.3 Find Unknown Measures<\/a><\/li>\n<li><a href=\"#Find_Unknown_Measures_Homework_&amp;_Practice_12.3\">Find Unknown Measures Homework &amp; Practice 12.3<\/a><\/li>\n<\/ul>\n<p><strong>Lesson: 4 Problem Solving: Perimeter and Area<\/strong><\/p>\n<ul>\n<li><a href=\"#Lesson_12.4_Problem_Solving:_Perimeter_and_Area\">Lesson 12.4 Problem Solving: Perimeter and Area<\/a><\/li>\n<li><a href=\"#Problem_Solving:_Perimeter_and_Area_Homework_&amp;_Practice_12.4\">Problem Solving: Perimeter and Area Homework &amp; Practice 12.4<\/a><\/li>\n<\/ul>\n<p><strong>Performance Task<\/strong><\/p>\n<ul>\n<li><a href=\"#Use_Perimeter_and_Area_Formulas_Performance_Task_12\">Use Perimeter and Area Formulas Performance Task 12<\/a><\/li>\n<li><a href=\"#Use_Perimeter_and_Area_Formulas_Activity\">Use Perimeter and Area Formulas Activity<\/a><\/li>\n<li><a href=\"#Use_Perimeter_and_Area_Formulas_Chapter_Practice\">Use Perimeter and Area Formulas Chapter Practice<\/a><\/li>\n<\/ul>\n<h3><a id=\"Lesson_12.1_Perimeter_Formula_for_a_Rectangle\"><\/a>Lesson 12.1 Perimeter Formula for a Rectangle<\/h3>\n<p><strong>Explore and Grow<\/strong><\/p>\n<p>Use color tiles to create a rectangle with a perimeter of 12 units. Compare your rectangle to your partner\u2019s. How are they the same? How are they different?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12723\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-1.png\" alt=\"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas 1\" width=\"197\" height=\"190\" \/><br \/>\nHow do you know that the perimeter of your rectangle is 12 units?<\/p>\n<p>Answer:<br \/>\n<a href=\"https:\/\/ccssmathanswers.com\/big-ideas-math-answers-grade-4-chapter-12\/chap12-perimeter-rectangle-2\/\" rel=\"attachment wp-att-19492\"><img loading=\"lazy\" class=\"alignnone size-full wp-image-19492\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/chap12-perimeter-rectangle-1.png\" alt=\"\" width=\"272\" height=\"225\" \/><\/a><br \/>\nThe perimeter (P) of a rectangle = P=2l+2w( length=l ; width = w)<\/p>\n<p>GIVEN: Perimeter of rectangle =12<br \/>\nP =2l + 2w<br \/>\n12= 2 (l + w)<br \/>\n12\/2=l + w<br \/>\n6= l + w<br \/>\nHence, the rectangle of my friend and mine are going to be same because perimeter given above is same for both the rectangle of us both.<\/p>\n<p><a href=\"https:\/\/ccssmathanswers.com\/big-ideas-math-answers-grade-4-chapter-12\/chap12-perimeter-rectangle\/\" rel=\"attachment wp-att-19489\"><img loading=\"lazy\" class=\"alignnone size-full wp-image-19489\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/chap12-perimeter-rectangle.png\" alt=\"\" width=\"342\" height=\"256\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/chap12-perimeter-rectangle.png 342w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/chap12-perimeter-rectangle-300x225.png 300w\" sizes=\"(max-width: 342px) 100vw, 342px\" \/><\/a><br \/>\nThe rectangle of mine is having a length of 3 units and width of 3 units.<br \/>\nPerimeter of my rectangle= (2 x l) + (2 x w)<br \/>\nP=(2 x 3) + (2 x 3)<br \/>\nP= 6 + 6<br \/>\nP= 12 \u00a0units.<br \/>\nHere, my rectangle has 12 \u00a0units perimeter. This is how I know my rectangle is having 12 units as its perimeter.<\/p>\n<p><strong>Structure<\/strong><br \/>\nHow is the perimeter of a rectangle related to its length and width?<\/p>\n<p>Answer:<br \/>\nThe\u00a0perimeter (P) of a\u00a0rectangle is given by the formula, P=2l+2w , where &#8220;l&#8221; is the length and &#8220;w&#8221; is the width\u00a0of the\u00a0rectangle.<\/p>\n<p><strong>Think and Grow: Use a Formula for Perimeter<\/strong><\/p>\n<p>Perimeter is the distance around a figure. A formula is an equation that uses letters and numbers to show how quantities are related. You can use a formula to show how the length, width, and perimeter of a rectangle are related.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12724\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-2.png\" alt=\"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas 2\" width=\"448\" height=\"129\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-2.png 448w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-2-300x86.png 300w\" sizes=\"(max-width: 448px) 100vw, 448px\" \/><br \/>\n<strong>Example<\/strong><br \/>\nFind the perimeter of the rectangle.<br \/>\nThe length is ___ feet and the width is __ feet.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12667\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-3.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 3\" width=\"203\" height=\"90\" \/><br \/>\nP = (2 \u00d7 l) + (2 \u00d7 W) Formula for perimeter of a rectangle<br \/>\n= (2 \u00d7 ___) + (2 \u00d7 ___)<br \/>\n= __ + __<br \/>\n= ___<br \/>\nThe perimeter is ___ feet.<br \/>\nANSWER:<br \/>\n<img src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-3.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 3\" \/><br \/>\nGiven: Length of Rectangle = 24 feet<br \/>\nWidth of Rectangle = 9 feet<br \/>\nFORMULA: Perimeter = (2 x l) + (2 x w)<br \/>\nP = (2 x 24) + (2 x 9)<br \/>\nP = 48 + 18<br \/>\nP = 66\u00a0 feet.<br \/>\nHence, the Perimeter of the rectangle = 66\u00a0 feet.<\/p>\n<p><strong>Show and Grow<\/strong><\/p>\n<p>Find the perimeter of the rectangle.<\/p>\n<p>Question 1.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12686\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-300.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 300\" width=\"152\" height=\"110\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-300.png 152w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-300-150x110.png 150w\" sizes=\"(max-width: 152px) 100vw, 152px\" \/><br \/>\nAnswer:<br \/>\nGIVEN: Length of rectangle = 16cm<br \/>\nWidth of rectangle = 13 cm<br \/>\nPerimeter of the rectangle = (2 x l) + (2 x w)<br \/>\nP = ( 2 x 16) + ( 2 x 13 )<br \/>\nP = 32 + 26<br \/>\nP = 58\u00a0 cm.<br \/>\nHence, the perimeter of the rectangle = 58\u00a0 cm.<\/p>\n<p>Question 2.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12668\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-4.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 4\" width=\"172\" height=\"96\" \/><br \/>\nAnswer:<br \/>\nGIVEN: Length of the rectangle = 8 inches<br \/>\nWidth of the rectangle = 4 (1\/2) inches =9\/2 = 4.5 inches<br \/>\nPerimeter of the rectangle = (2 x l) + (2 x w) = 2( l + w)<br \/>\nP = 2( 8 + 4.5 )<br \/>\nP = 2(12.5 )<br \/>\nP = 25 inches.<br \/>\nHence, the perimeter of the rectangle = 25 inches.<\/p>\n<p><strong>Apply and Grow: Practice<\/strong><\/p>\n<p>Find the perimeter of the rectangle.<\/p>\n<p>Question 3.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12669\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-5.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 5\" width=\"192\" height=\"122\" \/><br \/>\nAnswer:<br \/>\nGIVEN: Length of the rectangle = 54 yards<br \/>\nWidth of the rectangle = 32 yards<br \/>\nPerimeter of the rectangle = (2 x l) + (2 x w) = 2( l + w)<br \/>\nP = 2(54+32)<br \/>\nP= 2 x 86<br \/>\nP= 172 yards.<br \/>\nHence, the perimeter of the rectangle =172 yards.<\/p>\n<p>Question 4.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12670\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-6.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 6\" width=\"144\" height=\"152\" \/><br \/>\nAnswer:<br \/>\nGIVEN: Length of the rectangle =87 m<br \/>\nWidth of the rectangle = 65 m<br \/>\nPerimeter of the rectangle = (2 x l) + (2 x w) = 2( l + w)<br \/>\nP= 2(87+65)<br \/>\nP= 2 x 153<br \/>\nP= 306\u00a0 m.<br \/>\nHence, the perimeter of the rectangle = 306 m.<\/p>\n<p>Question 5.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12671\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-7.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 7\" width=\"218\" height=\"99\" \/><br \/>\nAnswer:<br \/>\nGIVEN: Length of the rectangle = 49 inches<br \/>\nWidth of the rectangle = 18 inches<br \/>\nPerimeter of the rectangle = (2 x l) + (2 x w) = 2( l + w)<br \/>\nP = 2(49+18)<br \/>\nP =2 x 67<br \/>\nP =134 inches.<br \/>\nHence, the perimeter of the rectangle = 134 inches.<\/p>\n<p>Question 6.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12672\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-8.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 8\" width=\"146\" height=\"175\" \/><br \/>\nAnswer:<br \/>\nGIVEN: Length of the rectangle =11 cm<br \/>\nWidth of the rectangle = 7 (3\/10) cm = 73\/10 cm =7.3 cm<br \/>\nPerimeter of the rectangle = (2 x l) + (2 x w) = 2( l + w)<br \/>\nP = 2(11+7.3)<br \/>\nP = 2 x 18.3<br \/>\nP = 36.6\u00a0 cm.<br \/>\nHence, the perimeter of the rectangle = 36.6 cm.<\/p>\n<p>Question 7.<br \/>\nYou want to string lights around a rectangular room that is 12 feet long and 10 feet wide. How many feet of lights do you need?<br \/>\nAnswer:<br \/>\nGIVEN: Length of the rectangle = 12 feet<br \/>\nWidth of the rectangle = 10 feet<br \/>\nPerimeter of the rectangle = (2 x l) + (2 x w) = 2( l + w)<br \/>\nP = 2(12+10)<br \/>\nP = 2 x 22<br \/>\nP = 44\u00a0 feet<br \/>\nHence, 44\u00a0 feet of light is needed..<\/p>\n<p>Question 8.<br \/>\n<strong>YOU BE THE TEACHER<\/strong><br \/>\nYour friend finds the perimeter of the rectangle. Is your friend correct? Explain.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12673\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-9.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 9\" width=\"156\" height=\"71\" \/><br \/>\np = (2 \u00d7 13) \u00d7 (2 \u00d7 5)<br \/>\n= 26 \u00d7 10<br \/>\n= 260\u00a0 ft<br \/>\nAnswer: GIVEN: Length of the rectangle = 13 feet<br \/>\nWidth of the rectangle = 5 feet<br \/>\nPerimeter of the rectangle = (2 x l) + (2 x w) = 2( l + w)<br \/>\nP = 2(13+5)<br \/>\nP = 2 x 18<br \/>\nP = 36 feet.<br \/>\nHence, the perimeter of the rectangle = 36\u00a0 feet.<br \/>\nTherefore my friend is wrong because his formula for finding perimeter of rectangle is wrong.<br \/>\nPerimeter of the rectangle = (2 x l) + (2 x w) = 2( l + w)<\/p>\n<p>Question 9.<br \/>\n<strong>DIG DEEPER!<\/strong><br \/>\nYou can use the formula for the perimeter of a rectangle to find the perimeter of the square. What other formula can you use to find the perimeter of the square?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12674\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-10.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 10\" width=\"100\" height=\"99\" \/><\/p>\n<p>Answer:<br \/>\nThe\u00a0<b>perimeter\u00a0<\/b>of a square is the total length of the four equal sides of the square.<br \/>\nPerimeter of the square = 4 \u00d7\u00a0<i>s<\/i>\u00a0= 4\u00a0<i>s<br \/>\n<\/i>The\u00a0<b>perimeter\u00a0<\/b>of a rectangle is the total length of the two lengths and two widths of the rectangle.<br \/>\nIf the length and width of a rectangle are\u00a0<i>l<\/i>\u00a0and\u00a0<i>w<\/i>, then its perimeter = 2(<i>l<\/i>\u00a0+\u00a0<i>w<\/i>) units.<br \/>\n<i><\/i>We cannot equate the perimeter of a rectangle to find the perimeter of the square because rectangle has length and width whereas square has four sides.<br \/>\nNo, other ways are there find the perimeter of the square.<\/p>\n<p><strong>Think and Grow: Modeling Real Life<\/strong><\/p>\n<p><strong>Example<\/strong><br \/>\nIn a video game, you make a rectangular castle that is 4 times longer than it is wide. What is the perimeter of the castle?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12675\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-11.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 11\" width=\"229\" height=\"69\" \/><br \/>\nMultiply 4 and the width of the castle to find the length.<br \/>\n4 \u00d7 25 = ___<br \/>\nThe length of the castle is ___ yards.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12676\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-12.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 12\" width=\"584\" height=\"147\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-12.png 584w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-12-300x76.png 300w\" sizes=\"(max-width: 584px) 100vw, 584px\" \/><br \/>\nAnswer:<br \/>\nGIVEN: Width of the rectangular castle\u00a0 = 25 yards<br \/>\nLength of the rectangular castle = 4 times longer than it is wide =4 x 25 yards = 100 yards<br \/>\nPerimeter of the rectangle castle = (2 x l) + (2 x w) = 2( l + w)<br \/>\nP = 2 (100+25)<br \/>\nP = 2 x 125<br \/>\nP = 250\u00a0 yards<br \/>\nHence, Perimeter of the rectangle\u00a0 castle= 250 yards.<\/p>\n<p><strong>Show and Grow<\/strong><\/p>\n<p>Question 10.<br \/>\nA teacher wants to put a border around a rectangular whiteboard. The whiteboard is 2 times longer than it is wide. What is the perimeter of the whiteboard?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12677\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-13.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 13\" width=\"198\" height=\"99\" \/><br \/>\nAnswer:<br \/>\nGIVEN: Width of the rectangular castle\u00a0 =\u00a0 1 m<br \/>\nLength of the rectangular castle = 2 times longer than it is wide = 2 x 1 m = 2 m<br \/>\nPerimeter of the rectangle castle= (2 x l) + (2 x w) = 2( l + w)<br \/>\nP = 2(2+1)<br \/>\nP = 2 x 3<br \/>\nP = 6 m<br \/>\nHence, Perimeter of the rectangle castle = 6 m.<\/p>\n<p>Question 11.<br \/>\nYou want to put a ribbon border around each rectangular card. Which card requires more ribbon? How much more ribbon?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12678\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-14.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 14\" width=\"262\" height=\"114\" \/><br \/>\nAnswer:<br \/>\nGIVEN: FIRST RECTANGULAR CARD<br \/>\nWidth of the rectangular card\u00a0 =\u00a0 18 cm<br \/>\nLength of the rectangular card =\u00a0 18 cm<br \/>\nPerimeter of the rectangle card= (2 x l) + (2 x w) = 2( l + w)<br \/>\nP = 2(18+18)<br \/>\nP = 2 x 36<br \/>\nP = 72 cm.<br \/>\nSECOND RECTANGULAR CARD<br \/>\nWidth of the rectangular card\u00a0 =\u00a0 14cm<br \/>\nLength of the rectangular card =\u00a0 21\u00a0cm<br \/>\nPerimeter of the rectangle = (2 x l) + (2 x w) = 2( l + w)<br \/>\nP = 2(21+14)<br \/>\nP = 2 x 35<br \/>\nP = 70\u00a0 cm.<br \/>\nThe FIRST RECTANGULAR CARD needs the more ribbon than SECOND RECTANGULAR CARD because FIRST RECTANGULAR CARD Perimeter = 72\u00a0 cm and SECOND RECTANGULAR CARD Perimeter = 70 cm.<br \/>\nThat means\u00a0 difference in perimeter of FIRST RECTANGULAR CARD and the perimeter of SECOND RECTANGULAR CARD.<br \/>\n=72\u00a0 cm &#8211; 70\u00a0 cm<br \/>\n= 2\u00a0 cm.<\/p>\n<p>Question 12.<br \/>\n<strong>DIG DEEPER!<\/strong><br \/>\nA rectangular flower bed has a length of 6 feet. The width is 48 inches shorter than the length. What is the perimeter of the flower bed?<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the rectangular bed = 6 feet<br \/>\nWidth of the rectangular bed = 48 inches shorter than the length.<br \/>\n1 inch = 0.08333 feet<br \/>\n48inches = 48 x 0.0833 =\u00a0 4 feet<br \/>\nWidth of the rectangular bed =\u00a0 4 feet<br \/>\nThe perimeter of the\u00a0 rectangular flower bed = (2 x l) + (2 x w) = 2( l + w)<br \/>\nP = 2(6+4)<br \/>\nP = 2 x 10<br \/>\nP = 20 feet.<br \/>\nHence, the perimeter of the\u00a0 rectangular flower bed = 20 feet.<\/p>\n<h3><a id=\"Perimeter_Formula_for_a_Rectangle_Homework_&amp;_Practice_12.1\"><\/a>Perimeter Formula for a Rectangle Homework &amp; Practice 12.1<\/h3>\n<p>Find the perimeter of the rectangle.<\/p>\n<p>Question 1.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12679\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-15.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 15\" width=\"168\" height=\"118\" \/><br \/>\nAnswer:<br \/>\nGIVEN: Length of the rectangle = 22 yards<br \/>\nWidth of the rectangle = 18 yards<br \/>\nPerimeter of the rectangle = (2 x l) + (2 x w) = 2( l + w)<br \/>\nP = 2(22+18)<br \/>\nP = 2 x 40<br \/>\nP = 80 yards.<br \/>\nHence, the Perimeter of the rectangle = 80 yards.<\/p>\n<p>Question 2.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12680\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-16.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 16\" width=\"155\" height=\"168\" \/><br \/>\nAnswer:<br \/>\nGIVEN: Length of the rectangle = 36 mm<br \/>\nWidth of the rectangle = 25 mm<br \/>\nPerimeter of the rectangle = (2 x l) + (2 x w) = 2( l + w)<br \/>\nP = 2(36+25)<br \/>\nP = 2 x 61<br \/>\nP =122 mm<br \/>\nHence, the Perimeter of the rectangle = 122 mm.<\/p>\n<p>Question 3.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12681\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-17.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 17\" width=\"207\" height=\"93\" \/><br \/>\nAnswer:<br \/>\nGIVEN: Length of the rectangle = 30 cm<br \/>\nWidth of the rectangle = 14 cm<br \/>\nPerimeter of the rectangle = (2 x l) + (2 x w) = 2( l + w)<br \/>\nP = 2(30+14)<br \/>\nP = 2 x 44<br \/>\nP = 88 cm<br \/>\nHence, the Perimeter of the rectangle = 88 cm.<\/p>\n<p>Question 4.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12682\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-18.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 18\" width=\"149\" height=\"157\" \/><br \/>\nAnswer:<br \/>\nGIVEN: Length of the rectangle = 12 (1\/4) feet = 49\/4 feet = 12.25 feet<br \/>\nWidth of the rectangle = 8 feet<br \/>\nPerimeter of the rectangle = (2 x l) + (2 x w) = 2( l + w)<br \/>\nP = 2(12.25 + 8)<br \/>\nP = 2 x 20.25<br \/>\nP = 40.5 feet<br \/>\nHence, the Perimeter of the rectangle = 40.5feet.<\/p>\n<p>Question 5.<br \/>\n<strong>Number Sense<\/strong><br \/>\nWhat is the perimeter of a square tabletop with side lengths of 48 inches?<br \/>\nAnswer:<br \/>\nGIVEN: Side of the square tabletop = 48 inches<br \/>\nPerimeter of the square = 4 x sides<br \/>\nP = 4 x 48<br \/>\nP = 192\u00a0 inches.<br \/>\nHence, Perimeter of the square tabletop = 192 inches.<\/p>\n<p>Question 6.<br \/>\n<strong>Structure<\/strong><br \/>\nUse the Distributive Property to write P = (2 \u00d7 l) + (2 \u00d7 w) another way.<br \/>\nAnswer:<br \/>\nAccording to the distributive property, multiplying the sum of two or more addends by a number will give the same result as multiplying each addend individually by the number and then adding the products together.<br \/>\nPerimeter of rectangle = (2 \u00d7 l) + (2 \u00d7 w)<br \/>\nP = 2(l + w)<br \/>\nHence, According to distributive property,\u00a0 the another way of the Perimeter of rectangle = 2(l + w).<\/p>\n<p>Question 7.<br \/>\n<strong>Open-Ended<\/strong><br \/>\nDraw a rectangle that has the same perimeter as the one shown, but different dimensions.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12683\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-19.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 19\" width=\"225\" height=\"120\" \/><br \/>\nAnswer:<br \/>\nGIVEN: Length of the rectangle = 50 m<br \/>\nWidth of the rectangle = 25 m<br \/>\nPerimeter of the rectangle = (2 x l) + (2 x w) = 2( l + w)<br \/>\nP = 2( 50+25)<br \/>\nP = 2 x 75<br \/>\nP = 150 m.<br \/>\nMY FIGURE:<br \/>\n<a href=\"https:\/\/ccssmathanswers.com\/big-ideas-math-answers-grade-4-chapter-12\/chap12-perimeter-rectangle-4\/\" rel=\"attachment wp-att-19548\"><img loading=\"lazy\" class=\"alignnone size-full wp-image-19548\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/chap12-perimeter-rectangle-3.png\" alt=\"\" width=\"279\" height=\"175\" \/><\/a><br \/>\nLength of the rectangle = 49m<br \/>\nWidth of the rectangle = 26 m<br \/>\nPerimeter of the rectangle = (2 x l) + (2 x w) = 2( l + w)<br \/>\nP = 2( 49+26)<br \/>\nP = 2 x 75<br \/>\nP = 150 m.<br \/>\nHence, the given rectangle Perimeter and my figure\u00a0 Perimeter are the same of 150 m.<\/p>\n<p>Question 8.<br \/>\n<strong>Modeling Real Life<\/strong><br \/>\nA worker places tape around a rectangular shipping label that is 2 times longer than it is wide. How much tape does the worker need?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12684\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-20.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 20\" width=\"233\" height=\"171\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nWidth of the rectangle shipping label = 74 mm<br \/>\nLength of the rectangle shipping label = 2 times longer than it is wide =\u00a0 2 x 74mm = 148mm<br \/>\nPerimeter of the rectangle = (2 x l) + (2 x w) = 2( l + w)<br \/>\nP = 2(148+74)<br \/>\nP = 2 x 222<br \/>\nP = 444\u00a0 mm.<br \/>\nHence, Perimeter of the rectangle shipping label = 444 mm.<\/p>\n<p>Question 9.<br \/>\n<strong>Modeling Real Life<\/strong><br \/>\nA coach is painting lines around the perimeter of two rectangular fields. Which field requires more paint?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12685\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answer-Key-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-21.png\" alt=\"Big Ideas Math Answer Key Grade 4 Chapter 12 Use Perimeter and Area Formulas 21\" width=\"300\" height=\"226\" \/><br \/>\nAnswer:<br \/>\nGIVEN: FIRST A COACH<br \/>\nLength of the rectangle field A = 100yards<br \/>\nWidth of the rectangle field A =65 yards<br \/>\nPerimeter of the rectangle field A= (2 x l) + (2 x w) = 2( l + w)<br \/>\nP = 2( 100+65)<br \/>\nP =2 x 165<br \/>\nP = 230 yards<br \/>\nLength of the rectangle field B = 120yards<br \/>\nWidth of the rectangle field B =53 1\/3 yards = 160\/3 = 53.3 yards<br \/>\nP = (2 x l) + (2 x w) = 2( l + w)<br \/>\nP = 2( 120+53.3)<br \/>\nP = 2 x 173.3<br \/>\nP = 346.6\u00a0 yards<br \/>\nHence, Perimeter of the rectangle field B is more than Perimeter of the rectangle field A<br \/>\n=346.6 &#8211; 230 = 116.6\u00a0 yards.<br \/>\nTherefore, Perimeter of the rectangle field A requires more 116.6 square yards than Perimeter of the rectangle field B.<\/p>\n<p><strong>Review &amp; Refresh<\/strong><\/p>\n<p>Write the first six numbers in the pattern. Then describe another feature of the pattern.<\/p>\n<p>Question 10.<br \/>\nRule: Subtract 11.<br \/>\nFirst number: 99<br \/>\nAnswer:<br \/>\nRule: Subtract 11.<br \/>\nGIVEN: First number = 99\u00a0 in the pattern<br \/>\nSecond number = 99-11= 88<br \/>\nThird number = 88-11= 77<br \/>\nFourth number = 77-11 = 66<br \/>\nFifth number = 66-11 = 55<br \/>\nSixth number = 55-11 =44<br \/>\nAnother feature of this pattern is that all the numbers are multiples of table 11.<\/p>\n<p>Question 11.<br \/>\nRule: Multiply by 5.<br \/>\nFirst number: 5<br \/>\nAnswer: Rule: Multiply by 5.<br \/>\nGIVEN: First number = 5 in the pattern<br \/>\nSecond number = 5 x5 =25<br \/>\nThird number = 25 x 5 = 125<br \/>\nFourth number = 125 x 5= 625<br \/>\nFifth number = 625 x 5 = 3125<br \/>\nSixth number = 3125 x 5 = 15625<br \/>\nAnother feature of this pattern is that all the numbers are multiples of table 5.<\/p>\n<h3><a id=\"Lesson_12.2_Area_Formula_for_a_Rectangle\"><\/a>Lesson 12.2 Area Formula for a Rectangle<\/h3>\n<p><strong>Explore and Grow<\/strong><\/p>\n<p>Use color tiles to create a rectangle with an area of 12 square units. Compare your rectangle to your partner\u2019s. How are they the same? How are they different?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12687\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-22.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 22\" width=\"190\" height=\"185\" \/><br \/>\nHow do you know that the area of your rectangle is 12 square units?<br \/>\nAnswer:<br \/>\n<a href=\"https:\/\/ccssmathanswers.com\/big-ideas-math-answers-grade-4-chapter-12\/chap12-perimeter-rectangle-9\/\" rel=\"attachment wp-att-19556\"><img loading=\"lazy\" class=\"alignnone size-full wp-image-19556\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/chap12-perimeter-rectangle-8.png\" alt=\"\" width=\"216\" height=\"166\" \/><\/a><br \/>\nHence, the rectangle of my friend and mine are going to be same because area = 12 square units given above is same for both the rectangle of us both.<br \/>\n<a href=\"https:\/\/ccssmathanswers.com\/big-ideas-math-answers-grade-4-chapter-12\/chap12-perimeter-rectangle-8\/\" rel=\"attachment wp-att-19555\"><img loading=\"lazy\" class=\"alignnone size-full wp-image-19555\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/chap12-perimeter-rectangle-7.png\" alt=\"\" width=\"286\" height=\"168\" \/><\/a><\/p>\n<p>Area of the rectangle =l x w , where &#8220;l&#8221; is the length and &#8220;w&#8221; is the width.<br \/>\nLength of the rectangle = 4units<br \/>\nWidth of the rectangle = 3units<br \/>\nA = l x w<br \/>\nA = 4 x 3<br \/>\nA = 12 square units.<br \/>\nHence, the Area of the rectangle = 12 square units.<\/p>\n<p><strong>Structure<\/strong><br \/>\nHow is the area of a rectangle related to its length and width?<br \/>\nAnswer:<br \/>\nThe\u00a0area &#8220;A&#8221; of a rectangle is given by the formula, A=l x w , where &#8220;l&#8221; is the length and &#8220;w&#8221; is the width.<\/p>\n<p><strong>Think and Grow: Use a Formula for Area<\/strong><\/p>\n<p>Area is the amount of surface a figure covers. You can use a formula to show how the length, width, and area of a rectangle are related.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12688\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-23.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 23\" width=\"635\" height=\"238\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-23.png 635w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-23-300x112.png 300w\" sizes=\"(max-width: 635px) 100vw, 635px\" \/><br \/>\n<strong>Example<\/strong><br \/>\nFind the area of the rectangle.<br \/>\nThe length is ___ inches and the width is ___ inches.<br \/>\nA = l \u00d7 w Formula for area of a rectangle<br \/>\n= ___ \u00d7 ___<br \/>\n= ___<br \/>\nThe area is ___ square inches.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12689\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-24.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 24\" width=\"154\" height=\"165\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the rectangle = 19 inches<br \/>\nWidth of the rectangle = 14 inches<br \/>\nArea of the rectangle = l x w<br \/>\nA = 19 x 14<br \/>\nA = 266\u00a0 square inches<br \/>\nHence, the Area of the rectangle = 266\u00a0 square inches.<\/p>\n<p><strong>Show and Grow<\/strong><\/p>\n<p>Find the area of the rectangle<\/p>\n<p>Question 1.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12690\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-25.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 25\" width=\"119\" height=\"125\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the rectangle = 6 m<br \/>\nWidth of the rectangle = 4 m<br \/>\nArea of the rectangle = l x w<br \/>\nA = 6 x 4<br \/>\nA = 24 square m.<br \/>\nHence, the are of the rectangle = 24 square m.<\/p>\n<p>Question 2.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12691\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-26.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 26\" width=\"191\" height=\"117\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the rectangle = 20 yards<br \/>\nWidth of the rectangle = 12 yards<br \/>\nArea of the rectangle = l x w<br \/>\nA = 20 x 12<br \/>\nA = 240 square yards<br \/>\nHence, the area of the rectangle = 240 square yards.<\/p>\n<p>Question 3.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12692\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-27.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 27\" width=\"152\" height=\"97\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-27.png 152w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-27-150x97.png 150w\" sizes=\"(max-width: 152px) 100vw, 152px\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the rectangle = 11 cm<br \/>\nWidth of the rectangle = 7cm<br \/>\nArea of the rectangle = l x w<br \/>\nA = 11 x 7<br \/>\nA = 77 square cm<br \/>\nHence, the area of the rectangle = 77 square cm.<\/p>\n<p>Question 4.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12693\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-28.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 28\" width=\"163\" height=\"67\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the rectangle =\u00a0 5 feet<br \/>\nWidth of the rectangle = 1 (1\/2) feet = 3\/2 feet = 1.5 feet<br \/>\nArea of the rectangle = l x w<br \/>\nA = 5 x 1.5<br \/>\nA = 7.5 square feet<br \/>\nHence, the area of the rectangle = 7.5 square feet.<\/p>\n<p><strong>Apply and Grow: Practice<\/strong><\/p>\n<p>Find the area of the rectangle.<\/p>\n<p>Question 5.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12694\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-29.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 29\" width=\"147\" height=\"111\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the rectangle =\u00a0 35 mm<br \/>\nWidth of the rectangle = 32 mm<br \/>\nArea of the rectangle = l x w<br \/>\nA = 35 x 32<br \/>\nA = 1120 mm<br \/>\nHence, the area of the rectangle = 1120 mm.<\/p>\n<p>Question 6.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12695\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-30.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 30\" width=\"117\" height=\"151\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the rectangle = 9 inches<br \/>\nWidth of the rectangle = 4 (2\/8) inches = 34\/8 = 4.25 inches<br \/>\nArea of the rectangle = l x w<br \/>\nA = 9 x 4.25<br \/>\nA = 38.25 square inches<br \/>\nHence, the area of the rectangle = 38.25 square inches.<\/p>\n<p>Question 7.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12696\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-31.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 31\" width=\"159\" height=\"98\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the rectangle =\u00a0 8 feet<br \/>\nWidth of the rectangle = 5 (1\/2) feet =11\/2 = 5.5 feet<br \/>\nArea of the rectangle = l x w<br \/>\nA = 8 x 5.5<br \/>\nA = 44 square feet<br \/>\nHence, the area of the rectangle = 44 square feet.<\/p>\n<p>Question 8.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12697\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-32.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 32\" width=\"194\" height=\"101\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the rectangle = 79 cm<br \/>\nWidth of the rectangle = 37 cm<br \/>\nArea of the rectangle = l x w<br \/>\nA = 79 x 37<br \/>\nA = 2923 square cm<br \/>\nHence, the area of the rectangle = 2923 square cm.<\/p>\n<p>Question 9.<br \/>\nYou are installing wall-to-wall carpet in a rectangular bedroom that is 10 feet long and 9 feet wide. How many square feet of carpet do you need?<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the wall-to-wall carpet in a rectangular bedroom = 10 feet<br \/>\nWidth of the wall-to-wall carpet in a rectangular bedroom = 9 feet<br \/>\nArea of the rectangle = l x w<br \/>\nA = 10 x 9<br \/>\nA = 90 square feet.<br \/>\nHence, the area of the wall-to-wall carpet in a rectangular bedroom = 90 square feet<br \/>\nTherefore, 90 square feet of carpet is need.<\/p>\n<p>Question 10.<br \/>\n<strong>YOU BE THE TEACHER<\/strong><br \/>\nNewton says the area of the rectangle is 33 square meters. Descartes says the area is 33 meters. Who is correct? Explain.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12698\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-33.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 33\" width=\"133\" height=\"59\" \/><br \/>\nAnswer:<br \/>\nLength of the rectangle = 11 m<br \/>\nWidth of the rectangle = 3 m<br \/>\nArea of the rectangle = l x w<br \/>\nA = 11 x 3<br \/>\nA = 33 square m<br \/>\nThe area of the rectangle is 33 square meters.<br \/>\nHence, Newton says correct not Descartes.<\/p>\n<p>Question 11.<br \/>\n<strong>DIG DEEPER!<\/strong><br \/>\nWrite a formula for the area of a square that has a side length of s. Then use your formula to \ufb01nd the area of the square shown.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12699\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-34.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 34\" width=\"106\" height=\"118\" \/><br \/>\nAnswer:<br \/>\nArea of the square = 4 x sides = 4 x s<br \/>\nGiven : side of the square = 12 yards<br \/>\nArea of the square = 4 x sides = 4 x s<br \/>\nA= 4 x 12<br \/>\nA = 48 square yards<br \/>\nHence, the Area of the square = 48 square yards.<\/p>\n<p><strong>Think and Grow: Modeling Real Life<\/strong><\/p>\n<p><strong>Example<\/strong><br \/>\nThe length of the rectangular dance floor is 6 feet longer than the width. What is the area of the dance floor?<br \/>\nAdd 6 feet to the width to find the length.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12700\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-35.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 35\" width=\"623\" height=\"305\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-35.png 623w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-35-300x147.png 300w\" sizes=\"(max-width: 623px) 100vw, 623px\" \/><br \/>\nAnswer:<br \/>\nGIVEN: Width of rectangular dance floor = 24 feet<br \/>\nLength of the rectangular dance floor = 6 feet longer than the width = 24 +6 = 30 feet<br \/>\nArea of the\u00a0 rectangular dance floor = l x w<br \/>\nA = 30 X 24<br \/>\nA = 720 square feet<br \/>\nHence, the Area of the\u00a0 rectangular dance floor = 720 square feet.<\/p>\n<p><strong>Show and Grow<\/strong><\/p>\n<p>Question 12.<br \/>\nA designer creates a rectangular advertisement for a website. The length of the advertisement is 1\\(\\frac{1}{2}\\) centimeters longer than the width. What is the area of the advertisement?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12701\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-36.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 36\" width=\"175\" height=\"129\" \/><br \/>\nAnswer:<br \/>\nLength of the rectangular advertisement = 1\\(\\ frac {1}{2}\\) centimeters longer than the width= 1(1 \/2) cm + 7 cm = =3 \/ 2 cm + 7 cm = (1.5 + 7 )cm =8.5 cm<br \/>\nWidth of the rectangular advertisement = 7 cm<br \/>\nArea of the\u00a0 rectangular advertisement = l x w<br \/>\nA = 8.5 x 7<br \/>\nA = 59.5 cm<br \/>\nHence, the Area of the\u00a0 rectangular advertisement = 59.5 cm.<\/p>\n<p>Question 13.<br \/>\nYou create a mural using 4 rectangular posters that are each 4\\(\\frac{1}{4}\\) feet long and 2 feet wide. You put the posters next to each other with no gaps or overlaps. What is the area of the mural?<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nWidth of the rectangular posters=\u00a0 2 feet<br \/>\nLength of the rectangular posters= 4\\(\\frac{1}{4}\\) feet = 4 (1\/4) feet = 17\/4 feet = 4.25 feet<br \/>\nArea of the mural = l x w<br \/>\nA = 4.25 x 2<br \/>\nA =\u00a0 8.5\u00a0 square feet<br \/>\nHence, the Area of the mural = 8.5 square feet.<\/p>\n<p>Question 14.<br \/>\n<strong>DIG DEEPER!<\/strong><br \/>\nTwo rolls of wrapping paper have the same piece. The red roll is 3 feet wide and is 10 yards long when unrolled. The striped roll is 3\\(\\frac{1}{2}\\) feet wide and 8 yards long when unrolled. Which roll is the better buy? Explain.<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nWidth of Red roll =3 feet<br \/>\nCONVERTION : 1 YARD = 3 FEET<br \/>\nWidth of Red roll =3 feet = 1 yard<br \/>\nLength of the red roll = 10 yards<br \/>\nArea of the red roll = l x w<br \/>\nA = 10 x 1<br \/>\nA = 10 square yards.<br \/>\nArea of the red roll = 10 square yards.<br \/>\nWidth of striped roll = 3\\(\\frac{1}{2}\\) feet = 3 1\/2 feet = 3.5 feet.<br \/>\nCONVERTION : 1 YARD = 3 FEET<br \/>\nWidth of striped roll = 3.5 feet<br \/>\nI yard = 3.5 feet<br \/>\nWidth of striped roll = yard = 3.5 \/ 1 feet<br \/>\nWidth of striped roll = 3.5 yard<br \/>\nLength of striped roll = 8 yards<br \/>\nArea of the striped roll = l x w<br \/>\nA = 3.5 x 8<br \/>\nA = 28 square yards.<br \/>\nArea of the striped roll = 28 square yards.<br \/>\nIts better to buy striped roll than red roll because u are going to get more.<\/p>\n<h3><a id=\"Area_Formula_for_a_Rectangle_Homework_&amp;_Practice_12.2\"><\/a>Area Formula for a Rectangle Homework &amp; Practice 12.2<\/h3>\n<p>Find the area of the rectangle<\/p>\n<p>Question 1.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12702\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-37.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 37\" width=\"124\" height=\"108\" \/><br \/>\nAnswer:<br \/>\nGIVEN: Length of the rectangle = 8 m<br \/>\nWidth of the rectangle = 7 m<br \/>\nArea of the rectangle = l x w<br \/>\nA = 8 x 7<br \/>\nA = 42 square m<br \/>\nHence, Area of the rectangle = 42 square m.<\/p>\n<p>Question 2.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12703\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-38.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 38\" width=\"115\" height=\"133\" \/><br \/>\nAnswer:<br \/>\nGIVEN: Length of the rectangle = 21 cm<br \/>\nWidth of the rectangle = 9 cm<br \/>\nArea of the rectangle = l x w<br \/>\nA = 21 x 9<br \/>\nA = 189 square cm<br \/>\nHence, Area of the rectangle = 189 square cm.<\/p>\n<p>Question 3.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12704\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-39.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 39\" width=\"245\" height=\"77\" \/><br \/>\nAnswer:<br \/>\nGIVEN: Length of the rectangle = 56 yards<br \/>\nWidth of the rectangle = 12 yards<br \/>\nArea of the rectangle = l x w<br \/>\nA = 56 x 12<br \/>\nA = 672 square yards<br \/>\nHence, Area of the rectangle = 672 square yards.<\/p>\n<p>Question 4.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12705\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-40.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 40\" width=\"153\" height=\"97\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the rectangle = 10 (3\/4) inches = 43\/4 = 10.75 inches<br \/>\nWidth of the rectangle = 6 inches<br \/>\nArea of the rectangle = l x w<br \/>\nA = 10.75 x 6<br \/>\nA = 64.5 square inches<br \/>\nHence, Area of the rectangle = 64.5\u00a0 square inches.<\/p>\n<p>Question 5.<br \/>\nWhat is the area of the window?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12706\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-41.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 41\" width=\"105\" height=\"154\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the window = 48 inches<br \/>\nWidth of the window = 18 inches<br \/>\nArea of the window = l x w<br \/>\nA = 48 x 18<br \/>\nA = 864 square inches<br \/>\nHence, the Area of the window = 864 square inches.<\/p>\n<p>Question 6.<br \/>\n<strong>Structure<\/strong><br \/>\nA rectangle has an area of 40 square feet. The dimensions are whole numbers. What are all of the possible dimensions of the rectangle?<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nArea of the rectangle = 40 square feet.<br \/>\nThe\u00a0whole numbers\u00a0are the part of the number system in which it includes all the positive integers from 0 to infinity. These numbers exist in the number line.<br \/>\nArea of the rectangle = l x w<br \/>\nAll of the possible dimensions of the rectangle =<br \/>\n40 =1 \u00d7 40<br \/>\n40 = 2 \u00d7 20<br \/>\n40 = 4 \u00d7 10<br \/>\n40 = 5 \u00d7 8.<\/p>\n<p>Question 7.<br \/>\n<strong>Open-Ended<\/strong><br \/>\nDraw a rectangle that has the same area as the one shown, but different dimensions.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12707\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-42.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 42\" width=\"170\" height=\"103\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the rectangle = 40 mm<br \/>\nWidth of the rectangle = 30 mm<br \/>\nArea of the rectangle = l x w<br \/>\nA = 40 x30<br \/>\nA = 1200 mm<br \/>\nArea of the rectangle = 1200 mm.<br \/>\n<a href=\"https:\/\/ccssmathanswers.com\/big-ideas-math-answers-grade-4-chapter-12\/big-ideas-math-answers-grade-4-chapter-12-use-perimeter-area-12-2-open-ended-2\/\" rel=\"attachment wp-att-19761\"><img loading=\"lazy\" class=\"alignnone size-full wp-image-19761\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-open-ended-1.png\" alt=\"\" width=\"417\" height=\"244\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-open-ended-1.png 417w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-open-ended-1-300x176.png 300w\" sizes=\"(max-width: 417px) 100vw, 417px\" \/><\/a><br \/>\nLength of my rectangle = 48 mm<br \/>\nWidth of my rectangle = 25 mm<br \/>\nArea of my rectangle = l x w<br \/>\nA = 48 x 25<br \/>\nA = 1200 mm<br \/>\nHence, the Area of my rectangle = 1200 mm.<\/p>\n<p>Question 8.<br \/>\n<strong>Modeling Real Life<\/strong><br \/>\nAn interior designer says that a rug under a dining room table should be 4 feet longer and 4 feet wider than the table. What is the area of a rug a customer should buy for under the table?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12708\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-43.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 43\" width=\"112\" height=\"141\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the dinning table = 6 feet<br \/>\nWidth of the dinning table = 3feet<br \/>\nAS PER DESIGNER THE DINNING TABLE REQUIRED DIMENSIONS ARE AS BELOW:<br \/>\nLength should be 4 feet longer than table.<br \/>\nLength of the dinning table= 6 feet<br \/>\nLength of the rug = 6 feet + 4 feet = 10 feet<br \/>\nWidth should be 4 feet wider than the table.<br \/>\nWidth of the dinning table = 3feet<br \/>\nWidth of the rug = 3 feet + 4 feet = 7 feet<br \/>\nArea of the rug = l x w<br \/>\nA = 10 x 7<br \/>\nA = 70 square feet.<br \/>\nHence, the Area of the rug = 70\u00a0 square feet.<\/p>\n<p>Question 9.<br \/>\n<strong>DIG DEEPER!<\/strong><br \/>\nA wolf hunts within a rectangular area that is 10 miles long and 5 miles wide. A cougar hunts within a rectangular area that is 8 miles long and 6 miles wide. Which animal hunts within a greater area? How much more area does the animal hunt in?<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the wolf hunts rectangular area=10 miles<br \/>\nWidth of the wolf hunts rectangular area=5 miles<br \/>\nArea the wolf hunts rectangular area= l x w<br \/>\nA = 10 x 5<br \/>\nA = 50 square miles.<br \/>\nArea the wolf hunts rectangular area= 50 square miles.<\/p>\n<p>Length of the cougar hunts rectangular area= 8 miles<br \/>\nWidth of the cougar hunts rectangular area= 6 miles<br \/>\nArea of the cougar hunts rectangular area= l x w<br \/>\nA\u00a0 = 8 x 6<br \/>\nA = 48 square miles<br \/>\nArea of the cougar hunts rectangular area= 48 square miles.<\/p>\n<p>Hence, wolf hunts within a greater area than the cougar hunts.<\/p>\n<p>Area the wolf hunts rectangular area= 50 square miles.<br \/>\nArea of the cougar hunts rectangular area= 48 square miles.<br \/>\nDIFFERENCE:<br \/>\nArea the wolf hunts rectangular area &#8211; Area of the cougar hunts rectangular area<br \/>\n= 50 square miles &#8211; 48 square miles<br \/>\n= 2 miles.<br \/>\nTherefore, Wolf hunts more of 2 square miles area than the cougar hunts.<\/p>\n<p><strong>Review &amp; Refresh<\/strong><\/p>\n<p>Find the quotient.<\/p>\n<p>Question 10.<br \/>\n70 \u00f7 7 = __<br \/>\nAnswer:<br \/>\n70 \u00f7 7 = 10.<br \/>\nThe quotient of 70 \u00f7 7 = 10.<\/p>\n<p>Question 11.<br \/>\n420 \u00f7 6 = ___<br \/>\nAnswer:<br \/>\n420 \u00f7 6 = 70.<br \/>\nThe quotient of 420 \u00f7 6 = 70.<\/p>\n<p>Question 12.<br \/>\n2,400 \u00f7 8 = ___<br \/>\nAnswer:<br \/>\n2,400 \u00f7 8 = 300.<br \/>\nThe quotient of 2,400 \u00f7 8 = 300.<\/p>\n<h3><a id=\" Lesson_12.3_Find_Unknown_Measures\"><\/a>Lesson 12.3 Find Unknown Measures<\/h3>\n<p><strong>Explore and Grow<\/strong><\/p>\n<p>For each row of the table, use color tiles to create the rectangle described. Then complete the table.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12709\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-44.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 44\" width=\"593\" height=\"300\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-44.png 593w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-44-300x152.png 300w\" sizes=\"(max-width: 593px) 100vw, 593px\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12709\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-44.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 44\" width=\"593\" height=\"300\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-44.png 593w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-44-300x152.png 300w\" sizes=\"(max-width: 593px) 100vw, 593px\" \/><br \/>\nArea of the rectangle = 20 square units<br \/>\nlength of the rectangle = 5 units<br \/>\nWidth of the rectangle = ??<br \/>\nLet the Width of the rectangle be W<br \/>\nArea of the rectangle = l x w<br \/>\n=&gt; 20 square units = 5units x W<br \/>\n=&gt; 20 \/ 5 = W<br \/>\n=&gt; 4 units =W<br \/>\nWidth of the rectangle = 4 units<br \/>\n<a href=\"https:\/\/ccssmathanswers.com\/big-ideas-math-answers-grade-4-chapter-12\/big-ideas-math-answers-grade-4-chapter-12-12-3\/\" rel=\"attachment wp-att-19766\"><img loading=\"lazy\" class=\"alignnone size-full wp-image-19766\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-12.3-.png\" alt=\"\" width=\"305\" height=\"238\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-12.3-.png 305w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-12.3--300x234.png 300w\" sizes=\"(max-width: 305px) 100vw, 305px\" \/><\/a><br \/>\nGIVEN:<br \/>\nArea of the rectangle = 24 square units<br \/>\nLength of the rectangle = ??<br \/>\nLet the Length of the rectangle = l<br \/>\nWidth of the rectangle = 4 units<br \/>\nArea of the rectangle = l x w<br \/>\n=&gt; 24 square units = l x 4units<br \/>\n=&gt; 24 \/ 4= l<br \/>\n=&gt; 6 units =l<br \/>\nLength of the rectangle = 6 units<br \/>\n<a href=\"https:\/\/ccssmathanswers.com\/big-ideas-math-answers-grade-4-chapter-12\/big-ideas-math-answers-grade-4-chapter-12-use-perimeter-area-12-2-explore\/\" rel=\"attachment wp-att-19767\"><img loading=\"lazy\" class=\"alignnone size-full wp-image-19767\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-explore.png\" alt=\"\" width=\"269\" height=\"224\" \/><\/a><br \/>\nGIVEN:<br \/>\nPerimeter of the rectangle = 20 units<br \/>\nLength of the rectangle = ??<br \/>\nLet the length of the rectangle be l<br \/>\nWidth of the rectangle = 3 units<br \/>\nPerimeter of the rectangle = 2l x 2w = 2 (l + w)<br \/>\n20 = 2(l+ 3)<br \/>\n20 \/ 2= L + 3<br \/>\n10 = l + 3<br \/>\n10 &#8211; 3 =l<br \/>\nl =7 units.<br \/>\nThe Length of the rectangle = 7 units.<br \/>\n<a href=\"https:\/\/ccssmathanswers.com\/big-ideas-math-answers-grade-4-chapter-12\/big-ideas-math-answers-grade-4-chapter-12-use-perimeter-area-12-2-explore-grow\/\" rel=\"attachment wp-att-19770\"><img loading=\"lazy\" class=\"alignnone size-full wp-image-19770\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-explore-grow.png\" alt=\"\" width=\"318\" height=\"186\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-explore-grow.png 318w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-explore-grow-300x175.png 300w\" sizes=\"(max-width: 318px) 100vw, 318px\" \/><\/a><br \/>\nGIVEN:<br \/>\nPerimeter of the rectangle = 24 units<br \/>\nLength of the rectangle = 8 units<br \/>\nWidth of the rectangle = ??<br \/>\nLet the Width of the rectangle = w<br \/>\nPerimeter of the rectangle = 2l x 2w = 2 (l + w)<br \/>\n24 = 2 ( 8 + w)<br \/>\n24\/2 =8 + w<br \/>\n12 = 8 + w<br \/>\n12 &#8211; 8 = w<br \/>\nw = 4units<br \/>\nWidth of the rectangle = 4units.<br \/>\n<a href=\"https:\/\/ccssmathanswers.com\/big-ideas-math-answers-grade-4-chapter-12\/big-ideas-math-answers-grade-4-chapter-12-use-perimeter-area-12-2-explore-grow1-2\/\" rel=\"attachment wp-att-19774\"><img loading=\"lazy\" class=\"alignnone size-full wp-image-19774\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-explore-grow1-1.png\" alt=\"\" width=\"343\" height=\"162\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-explore-grow1-1.png 343w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-explore-grow1-1-300x142.png 300w\" sizes=\"(max-width: 343px) 100vw, 343px\" \/><\/a><br \/>\nThe required table is as below:<\/p>\n<p><a href=\"https:\/\/ccssmathanswers.com\/big-ideas-math-answers-grade-4-chapter-12\/big-ideas-math-answers-grade-4-chapter-12-use-perimeter-area-12-2-explore-grow1\/\" rel=\"attachment wp-att-19773\"><img loading=\"lazy\" class=\"alignnone size-full wp-image-19773\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-explore-grow1.png\" alt=\"\" width=\"654\" height=\"226\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-explore-grow1.png 654w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-explore-grow1-300x104.png 300w\" sizes=\"(max-width: 654px) 100vw, 654px\" \/><\/a><\/p>\n<p><strong>Reasoning<\/strong><br \/>\nCompare your strategy to your partner\u2019s. How are they the same or different?<br \/>\nAnswer:<br \/>\nThe strategy of mine and my partner does not vary as both the required answers value is same.<\/p>\n<p><strong>Think and Grow : Find Unknown Measures<\/strong><\/p>\n<p><strong>Example<\/strong><br \/>\nThe area of the rectangle is 36 square feet. Find the length.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12710\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-45.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 45\" width=\"618\" height=\"205\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-45.png 618w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-45-300x100.png 300w\" sizes=\"(max-width: 618px) 100vw, 618px\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nArea of the rectangle = 36 square feet.<br \/>\nLength of the rectangle = l feet<br \/>\nWidth of the rectangle = 3 feet<br \/>\nArea of the rectangle = l x w<br \/>\n36 = l x 3<br \/>\n36\/3 = l<br \/>\n12 feet = l<br \/>\nHence, the Length of the rectangle =12 feet<\/p>\n<p><strong>Example<\/strong><br \/>\nThe perimeter of the rectangle is 30 centimeters. Find the width.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12711\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-46.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 46\" width=\"617\" height=\"319\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-46.png 617w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-46-300x155.png 300w\" sizes=\"(max-width: 617px) 100vw, 617px\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nPerimeter of the rectangle = 30 centimeters.<br \/>\nLength of the rectangle = 8 cm<br \/>\nWidth of the rectangle = w cm<br \/>\nPerimeter of the rectangle = (2 x l) + ( 2 x w )<br \/>\n30 = ( 2 x 8) + (2 x w)<br \/>\n30 = 16 + 2w<br \/>\n30 &#8211; 16 = 2w<br \/>\n14 = 2w<br \/>\n14\/2 = w<br \/>\n7 = w<br \/>\nHence, the Width of the rectangle = 7 cm.<\/p>\n<p>&nbsp;<\/p>\n<p><strong>Show and Grow<\/strong><\/p>\n<p>Question 1.<br \/>\nArea = 75 square meters<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12721\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-410.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 410\" width=\"169\" height=\"76\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nArea of the rectangle = 75 square meters<br \/>\nLength of the rectangle = l m<br \/>\nWidth of the rectangle = 5 m<br \/>\nArea of the rectangle =\u00a0 l x w<br \/>\n75 = l x 5<br \/>\n75\/5 = l<br \/>\n15 = l<br \/>\nHence, the length of the rectangle = 15 m.<\/p>\n<p>Question 2.<br \/>\nPerimeter = 42 inches<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12722\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-411.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 411\" width=\"157\" height=\"109\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nPerimeter of the rectangle = 42 inches<br \/>\nLength of the rectangle = 12 inches<br \/>\nWidth of the rectangle = w inches<br \/>\nPerimeter of the rectangle = (2 x l) + ( 2 x w ) = 2 ( l + w )<\/p>\n<p>Hence, the Width of the rectangle =\u00a0 3.5 inches.<\/p>\n<p><strong>Apply and Grow: Practice<\/strong><\/p>\n<p>Find the unknown measure of the rectangle.<\/p>\n<p>Question 3.<br \/>\nArea = 50 square millimeters<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12712\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-47.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 47\" width=\"197\" height=\"63\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nArea of the rectangle = 50 square millimeters<br \/>\nLength of the rectangle = l mm<br \/>\nWidth of the rectangle = 2 mm<br \/>\nArea of the rectangle =\u00a0 l x w<br \/>\n50 = l x 2<br \/>\n50\/2 = l<br \/>\n25 = l<br \/>\nHence, the length of the rectangle = 25 mm.<\/p>\n<p>Question 4.<br \/>\nPerimeter = 30 centimeters<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12713\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-48.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 48\" width=\"109\" height=\"106\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nPerimeter of the rectangle = 30 centimeters<br \/>\nLength of the rectangle = 9 cm<br \/>\nWidth of the rectangle = w cm<br \/>\nPerimeter of the rectangle = (2 x l) + ( 2 x w ) = 2 ( l + w )<br \/>\n30 = 2( 9+w )<br \/>\n30\/2 = 9 + w<br \/>\n15 = 9 + w<br \/>\n15 &#8211; 9 = w<br \/>\n6 = w<br \/>\nHence, the width of the rectangle = 6 cm.<\/p>\n<p>Question 5.<br \/>\nArea = 240 square meters<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12714\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-49.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 49\" width=\"206\" height=\"47\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nArea of the rectangle =\u00a0 240 square meters<br \/>\nLength of the rectangle = 80 m<br \/>\nWidth of the rectangle =\u00a0 w m<br \/>\nArea of the rectangle =\u00a0 l x w<br \/>\n240 = 80 x w<br \/>\n240\/80 = w<br \/>\n3 = w<br \/>\nHence, the Width of the rectangle =\u00a0 3 m.<\/p>\n<p>Question 6.<br \/>\nPerimeter = 86 yards<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12715\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-50.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 50\" width=\"147\" height=\"87\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\n<span id=\"P617_85\" class=\"s1 f2556 fs17 l0\">P<\/span><span id=\"P617_86\" class=\"s1 f2556 fs17 l0\">e<\/span><span id=\"P617_87\" class=\"s1 f2556 fs17 l0\">rimet<\/span><span id=\"P617_88\" class=\"s1 f2556 fs17 l0\">er of the rectangle = 86 yards<br \/>\n<\/span>Length of the rectangle = 23 yards<br \/>\nWidth of the rectangle = w yards<br \/>\nPerimeter of the rectangle = (2 x l) + ( 2 x w ) = 2 ( l + w )<br \/>\n86 = 2( 23 + w)<br \/>\n86\/2 = 23 +w<br \/>\n43 = 23 + w<br \/>\n43 &#8211; 23 = w<br \/>\n20 = w<br \/>\nHence, the Width of the rectangle = 20 yards.<\/p>\n<p>Question 7.<br \/>\n<span id=\"P617_85\" class=\"s1 f2556 fs17 l0\">P<\/span><span id=\"P617_86\" class=\"s1 f2556 fs17 l0\">e<\/span><span id=\"P617_87\" class=\"s1 f2556 fs17 l0\">rimet<\/span><span id=\"P617_88\" class=\"s1 f2556 fs17 l0\">er <\/span><span id=\"P617_90\" class=\"s1 f2556 fs17 l0\"> 44 2\/4 <\/span><span id=\"P617_91\" class=\"s1 f2556 fs17 l0\"><\/span><span id=\"P617_92\" class=\"s1 f2556 fs17 l0\"><\/span><span id=\"P617_99\" class=\"s1 f2556 fs17 l0\">inches<\/span><br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12716\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-51.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 51\" width=\"170\" height=\"99\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\n<span id=\"P617_85\" class=\"s1 f2556 fs17 l0\">P<\/span><span id=\"P617_86\" class=\"s1 f2556 fs17 l0\">e<\/span><span id=\"P617_87\" class=\"s1 f2556 fs17 l0\">rimet<\/span><span id=\"P617_88\" class=\"s1 f2556 fs17 l0\">er of the rectangle = <\/span><span id=\"P617_90\" class=\"s1 f2556 fs17 l0\">44 (2\/4) <\/span><span id=\"P617_91\" class=\"s1 f2556 fs17 l0\"><\/span><span id=\"P617_92\" class=\"s1 f2556 fs17 l0\"><\/span><span id=\"P617_99\" class=\"s1 f2556 fs17 l0\">inches = 90\/4 = 22.5 inches<br \/>\nLength of the rectangle = l inches<br \/>\nWidth of the rectangle = 8 (1\/4) inches = 33\/4 =\u00a0 8.25 inches<br \/>\nPerimeter of the rectangle = (2 x l) + ( 2 x w ) = 2 ( l + w )<br \/>\n22.5 = 2( l+ 8.25)<br \/>\n22.5\/2 = l + 8.25<br \/>\n11.25 = l + 8.25<br \/>\n11.25 &#8211; 8.25 = l<br \/>\n3.00 = l<br \/>\nHence, the Length of the rectangle = 3 inches.<br \/>\n<\/span><br \/>\nQuestion 8.<br \/>\nArea = 108 square feet<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12717\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-52.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 52\" width=\"102\" height=\"116\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nArea of the rectangle =\u00a0 108 square feet<br \/>\nLength of the rectangle = l feet<br \/>\nWidth of the rectangle =\u00a0 9 feet<br \/>\nArea of the rectangle =\u00a0 l x w<br \/>\n108 = l x 9<br \/>\n108\/9 = l<br \/>\n12 = l<br \/>\nHence, the Length of the rectangle = 12 feet.<\/p>\n<p>Question 9.<br \/>\n<strong>DIG DEEPER!<\/strong><br \/>\nWhat are the dimensions of Newton&#8217;s rectangle?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12718\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-53.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 53\" width=\"208\" height=\"220\" \/><br \/>\nAnswer:<br \/>\nArea of the Newton&#8217;s rectangle =\u00a0 24 square meters<br \/>\nLet the Width of the Newton&#8217;s rectangle\u00a0 be w m.<br \/>\nLength of the Newton&#8217;s rectangle = 2 meters longer than the width = 2 + w<br \/>\nArea of the Newton&#8217;s rectangle =\u00a0 l x w<br \/>\nFactors of 24:<br \/>\n1 x 24 = 24 =&gt; 1 x ( 1 + 2 ) = 1 x 3= 3<br \/>\n2 x 12 = 24 =&gt;2 x (2+2) =2 x 4 =8<br \/>\n3 x 8 = 24 =&gt;3 x (3+2) = 3 x 5 = 15<br \/>\n4 x 6 = 24 =&gt; 4 x (4+2) = 4 x 6 = 24<br \/>\nThe dimensions of Newton&#8217;s rectangle:<br \/>\nWidth of the Newton&#8217;s rectangle = 4 m<br \/>\nLength of Newton&#8217;s rectangle = 4 + 2= 6 m<br \/>\nCHECK:<br \/>\nArea of of Newton&#8217;s rectangle =l x w<br \/>\nA = 4 x 6<br \/>\nA = 24 square meters.<br \/>\nHence , the The dimensions of Newton&#8217;s rectangle = 4 m and 6 m.<\/p>\n<p>&nbsp;<\/p>\n<p>Question 10.<br \/>\n<strong>DIG DEEPER!<\/strong><br \/>\nThe area of a square is 81 square centimeters. What is the perimeter of the square?<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nArea of a square = 81 square centimeters.<br \/>\nArea of a square\u00a0 =s<sup>2\u00a0\u00a0<\/sup><br \/>\n81 = s<sup>2<br \/>\n<\/sup>\u221a 81 = s<br \/>\n9 = s<br \/>\nSide of the square = 9 cm<br \/>\nPerimeter of the square = 4x s<br \/>\nP= 4 x 9<br \/>\nP = 36 cm.<br \/>\nHence, Perimeter of the square = 36 cm.<\/p>\n<p><strong>Think and Grow: Modeling Real Life<\/strong><\/p>\n<p><strong>Example<\/strong><br \/>\nThe rectangular park has an area of 200 square yards. You kick a soccer ball straight across the width of the park. How far did you kick the soccer ball?<br \/>\nUse a formula to \ufb01nd the width.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12719\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-54.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 54\" width=\"665\" height=\"278\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-54.png 665w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-54-300x125.png 300w\" sizes=\"(max-width: 665px) 100vw, 665px\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nArea of the rectangular park =200 square yards<br \/>\nLength of the rectangular park = 25 yards<br \/>\nWidth of the rectangular park =w yards<br \/>\nArea of the rectangular park = l x w<br \/>\n200 = 25 x w<br \/>\n200\/25 = w<br \/>\n8 = w<br \/>\nHence, the Width of the rectangular park =9 yards.<br \/>\nTherefore, the soccer kicks the ball 8 yards far in the rectangular park.<br \/>\n<strong>Show and Grow<\/strong><\/p>\n<p>Question 11.<br \/>\nThe rectangular parking spot has an area of 220 square feet. What is the length of the longest car that can fit in the parking spot?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12720\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-4th-Grade-Chapter-12-Use-Perimeter-and-Area-Formulas-55.png\" alt=\"Big Ideas Math Answers 4th Grade Chapter 12 Use Perimeter and Area Formulas 55\" width=\"232\" height=\"99\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nArea of the rectangular parking spot = 220 square feet<br \/>\nWidth of the rectangular parking spot = 10 feet<br \/>\nLength of the rectangular parking spot = l feet<br \/>\nArea of the rectangular parking spot = l x w<br \/>\n220 = l x 10<br \/>\n220\/10 = l<br \/>\n22 = l<br \/>\nHence, the Length of the rectangular parking spot = 22 feet.<br \/>\nTherefore , the length of the longest car that can fit in the parking spot is 22 feet.<\/p>\n<p>Question 12.<br \/>\nYou want to put a frame around the rectangular painting. The painting has a perimeter of 50 inches. How wide should the frame be?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12725\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-56.png\" alt=\"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas 56\" width=\"128\" height=\"117\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nPerimeter of the rectangular painting frame= 50 inches<br \/>\nLength of the rectangular painting\u00a0 frame= 14 inches<br \/>\nWidth of the rectangular painting frame= w inches<br \/>\nPerimeter of the rectangular painting = 2l + 2w = 2( l + w)<br \/>\n50 = 2(14+w)<br \/>\n50\/2 = 14 + w<br \/>\n25 = 14 + w<br \/>\n25 &#8211; 14 =w<br \/>\n11 = w<br \/>\nHence, the Width of the rectangular painting frame= 11 inches.<\/p>\n<p>Question 13.<br \/>\nA rectangular zoo enclosure for a red panda has a perimeter of 116 meters. The length is 50 meters. What is the area of the enclosure?<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nPerimeter of the rectangular zoo = 116 meters<br \/>\nLength of the rectangular zoo = 50 meters<br \/>\nWidth of the rectangular zoo = ??<br \/>\nLet the Width of the rectangular zoo = w meters<br \/>\nPerimeter of the rectangular painting = 2l + 2w = 2( l + w)<br \/>\n116 = 2( 50+ w)<br \/>\n116\/2 = 50 + w<br \/>\n58 = 50 + w<br \/>\n58 &#8211; 50 = w<br \/>\n8 = w<br \/>\nHence, the Width of the rectangular zoo = 8 meters<br \/>\nArea of the rectangular zoo =??<br \/>\nArea of the rectangular zoo = l x w<br \/>\nA = 50 x 8<br \/>\nA = 400 square meters<br \/>\nTherefore, the Area of the rectangular zoo = 400 square meters.<\/p>\n<p>Question 14.<br \/>\n<strong>DIG DEEPER!<\/strong><br \/>\nA rectangular patio at a restaurant has an area of 98 square feet. The dimensions of the patio are whole numbers. The length of the patio is 2 times the width. What are the dimensions of the patio?<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nArea of the rectangular patio = 98 square feet.<br \/>\nThe dimensions of the patio are whole numbers.<br \/>\nThe length of the patio is 2 times the width.<br \/>\nLet the Width of the rectangular patio be w feet.<br \/>\n=&gt; Length of the the rectangular patio = 2 x w = 2w<br \/>\nArea of the rectangular patio = l x w<br \/>\n98 = (2w) x w<br \/>\n98 = 2w<sup>2<\/sup><br \/>\n98\/2 = w<sup>2<\/sup><br \/>\n49 = w<sup>2<\/sup><br \/>\n\u221a 49 = w<br \/>\n7 = w<br \/>\nHence, the Width of the rectangular patio = 7 feet.<br \/>\nLength of the the rectangular patio = 2 x w = 2w= 2 x 7 = 14 feet<br \/>\nTherefore, the dimensions of the patio are 14 feet and 7 feet.<\/p>\n<h3><a id=\"Find_Unknown_Measures_Homework_&amp;_Practice_12.3\"><\/a>Find Unknown Measures Homework &amp; Practice 12.3<\/h3>\n<p>Find the unknown measures of the rectangle.<\/p>\n<p>Question 1.<br \/>\nArea = 63 square feet<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12726\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-57.png\" alt=\"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas 57\" width=\"124\" height=\"120\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nArea of the rectangle = 63 square feet<br \/>\nLength of the rectangle = l feet<br \/>\nWidth of the rectangle = 7 feet<br \/>\nArea of the rectangle = l x w<br \/>\n63 = l x 7<br \/>\n63\/7 = l<br \/>\n9 = l<br \/>\nHence, the Length of the rectangle = 9 feet.<\/p>\n<p>Question 2.<br \/>\nPerimeter = 26 yards<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12727\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-58.png\" alt=\"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas 58\" width=\"199\" height=\"54\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nPerimeter of the rectangle =\u00a0 26 yards<br \/>\nLength of the rectangle = l yard<br \/>\nWidth of the rectangle = 1 yard<br \/>\nPerimeter of the rectangle = 2l + 2w = 2 ( l + w)<br \/>\n26 = 2( l + 1)<br \/>\n26\/2 = l +1<br \/>\n13 = l + 1<br \/>\n13 &#8211; 1 = l<br \/>\n12 = l<br \/>\nHence, the Length of the rectangle = 12 yards.<\/p>\n<p>Find the unknown measure of the rectangle.<\/p>\n<p>Question 3.<br \/>\nPerimeter = 40 centimeters<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12728\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-59.png\" alt=\"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas 59\" width=\"106\" height=\"113\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nPerimeter of the rectangle = 40 centimeters<br \/>\nLength of the rectangle =14 cm<br \/>\nWidth of the rectangle = w cm<br \/>\nPerimeter of the rectangle = 2l + 2w = 2 ( l + w)<br \/>\n40 = 2( 14 + w)<br \/>\n40\/2 =14 + w<br \/>\n20 = 14 + w<br \/>\n20 &#8211; 14= w<br \/>\n6 = w<br \/>\nHence, the Width of the rectangle = 6 cm.<\/p>\n<p>Question 4.<br \/>\nArea = 88 square millimeters<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12737\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-412.png\" alt=\"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas 412\" width=\"125\" height=\"120\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nArea of the rectangle = 88 square millimeters<br \/>\nLength of the rectangle = l mm<br \/>\nWidth of the rectangle = 8 mm<br \/>\nArea of the rectangle = l x w<br \/>\n88 = l x 8<br \/>\n88\/8 = l<br \/>\n11 = l<br \/>\nHence , the Length of the rectangle = 11 mm.<\/p>\n<p>Question 5.<br \/>\nArea = 2,800 square meters<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12729\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-60.png\" alt=\"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas 60\" width=\"185\" height=\"109\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nArea of the rectangle = 2,800 square meters<br \/>\nLength of the rectangle = l m<br \/>\nWidth of the rectangle = 40 m<br \/>\nArea of the rectangle = l x w<br \/>\n2800 = l x 40<br \/>\n2800\/40 = l<br \/>\n70 = l<br \/>\nHence, the Length of the rectangle = 70 m.<\/p>\n<p>Question 6.<br \/>\nPerimeter = 41 inches<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12730\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-61.png\" alt=\"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas 61\" width=\"160\" height=\"111\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nPerimeter of the rectangle = 41 inches<br \/>\nLength of the rectangle =12 (4\/8) inches = 100\/8 = 12.5 inches<br \/>\nWidth of the rectangle = w inches<br \/>\nPerimeter of the rectangle = 2l + 2w = 2 ( l + w)<br \/>\n41 = 2( 12.5 +w)<br \/>\n41\/2 =12.5 + w<br \/>\n20.5 = 12.5 + w<br \/>\n20.5 &#8211; 12.5 = w<br \/>\n8 = w<br \/>\nHence, the Width of the rectangle = 8 inches.<\/p>\n<p>Question 7.<br \/>\n<strong>Structure<\/strong><br \/>\nA rectangle has an area of 18 square inches and a perimeter of 18 inches. What are the dimensions of the rectangle?<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nArea of the rectangle = 18 square inches<br \/>\nPerimeter of the rectangle =18 inches.<br \/>\nLET, the Length of the rectangle be l inches<br \/>\nThe Width of the rectangle be w inches.<br \/>\nFORMULA:<br \/>\nArea of the rectangle = l x w<br \/>\n18 = l x w<br \/>\nThe dimensions of the rectangle :<br \/>\n18 = 1 x 18<br \/>\n18 = 2 x 9<br \/>\n18 = 3 x 6<br \/>\nHence, the dimensions of the rectangle are (1,18);(2,9);(3,6) inches.<\/p>\n<p>Question 8.<br \/>\n<strong>Modeling Real Life<\/strong><br \/>\nThe rectangular fire pit has a perimeter of 176 inches. What is the width of the fire pit?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12731\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-62.png\" alt=\"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas 62\" width=\"137\" height=\"115\" \/><br \/>\nAnswer:<br \/>\nGIVEN :<br \/>\nPerimeter of the rectangular fire pit = 176 inches<br \/>\nLength of the rectangular fire pit = 50 inches<br \/>\nWidth of the rectangular fire pit = ??<br \/>\nLet the Width of the rectangular fire pit be w inches.<br \/>\nPerimeter of the rectangular fire pit = 2l + 2w = 2(l + w)<br \/>\n176 = 2( 50 + w)<br \/>\n176\/2 = 50 + w<br \/>\n88 = 50 + w<br \/>\n88 &#8211; 50 = w<br \/>\n35 = w<br \/>\nHence, the Width of the rectangular fire pit =\u00a0 35 inches.<\/p>\n<p>Question 9.<br \/>\nA painting canvas has an area of 384 square inches. The length and width of the canvas are whole numbers. The length of the canvas is 8 inches greater than the width. What are the dimensions of the canvas?<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nArea of\u00a0 the painting canvas = 384 square inches.<br \/>\nThe length of the canvas is 8 inches greater than the width.<br \/>\nLet the Width of the painting canvas be w inches.<br \/>\nArea of\u00a0 the painting canvas = l x w =&gt; 384 = l x w<br \/>\n384 = 1x 384 =&gt;1 x (1 + 8) = 1 x 9 = 9<br \/>\n384 = 2 x 192 =&gt;2 x (2+8) = 2 x 10 = 20<br \/>\n384 = 3 x 128 =&gt; 3 x (3 + 8) = 3 x 11 = 33<br \/>\n384 = 4 x 96 =&gt; 4 x (4 + 8) = 4 x 12 = 48<br \/>\n384= 6 x 64 =&gt; 6 x (6 + 8) = 6 x 14 = 84<br \/>\n384 = 8 x 48 =&gt; 8 x (8 + 8) =8 x 16 = 128<br \/>\n384 =12 x 32 =&gt;12 x (12 + 8) = 12 x 20 = 240<br \/>\n384 =16 x 24 =&gt; 16 x (16 +8) = 16 x 24 = 384<br \/>\nHence, The dimensions of the canvas=\u00a0 (24,16) inches<br \/>\nLength of the canvas = 24 inches<br \/>\nWidth of the canvas = 16 inches<\/p>\n<p><strong>Review &amp; Refresh<\/strong><\/p>\n<p>Find the equivalent length.<\/p>\n<p>Question 10.<br \/>\n35 ft = __ in.<br \/>\nAnswer:<br \/>\nCONVERTION: 1 feet = 12 inches<br \/>\n35 feet = ?? inches<br \/>\nLet the unknown value be Y inches.<br \/>\n=&gt;35 x 12 = 1 x Y<br \/>\n=&gt;420 = 1 x Y<br \/>\n=&gt; 420\/1 = Y<br \/>\n=&gt; 420 = Y<br \/>\n<span style=\"font-size: 16px;\">Hence, the unknown value = 420 inches.<br \/>\n35 feet = _420_ inches.<\/span><\/p>\n<p>Question 11.<br \/>\n6 mi = __ yd<br \/>\nAnswer:<br \/>\nCONVERTION: 1 mile =1760 yard<br \/>\n6 miles = ?? yard<br \/>\nLet the unknown value be X yards.<br \/>\n=&gt; 1 x X = 1760 x 6<br \/>\n=&gt; 1X = 10560<br \/>\n=&gt; X = 10560\/1<br \/>\n=&gt; X = 10560<br \/>\nHence, the unknown value be 10560 yards.<br \/>\n6 mi = _10560_ yd<\/p>\n<p>Question 12.<br \/>\n17 yd = __ ft<br \/>\nAnswer:<br \/>\nCONVERTION:<br \/>\n1 yard = 3 feet<br \/>\n17 yd = ?? feet<br \/>\nLet the unknown value be X feet.<br \/>\n=&gt;1 x X = 3 x 17<br \/>\n=&gt;1X = 51<br \/>\n=&gt;X = 51\/1<br \/>\n=&gt; X = 51 feet<br \/>\nHence, the unknown value be 51 feet.<br \/>\n17 yd = _51_ ft<\/p>\n<p>Question 13.<br \/>\n4 yd = __ in.<br \/>\nAnswer:<br \/>\nCONVERTION:<br \/>\n1 yard = 36 inches<br \/>\n4 yards = ?? inches<br \/>\nLet the unknown value be Y inches.<br \/>\n=&gt; 1 x Y = 36 x 4<br \/>\n=&gt; 1Y = 144<br \/>\n=&gt; Y = 144\/1<br \/>\n=&gt; Y = 144<br \/>\nHence, the unknown value be 144 inches.<br \/>\n4 yd = _144_ in.<\/p>\n<h3><a id=\"Lesson_12.4_Problem_Solving:_Perimeter_and_Area\"><\/a>Lesson 12.4 Problem Solving: Perimeter and Area<\/h3>\n<p><strong>Explore and Grow<\/strong><\/p>\n<p>An office has a large rectangular window overlooking a city. Describe two methods for finding the area of the rectangular wall around the window.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12732\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-63.png\" alt=\"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas 63\" width=\"495\" height=\"212\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-63.png 495w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-63-300x128.png 300w\" sizes=\"(max-width: 495px) 100vw, 495px\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nArea of the inside window = l x w<br \/>\nArea of the outside wall = l x w<br \/>\nArea of the rectangular wall around the window = area of the outside wall &#8211; Area of the inside window<br \/>\nHence, there is only one way to find the Area of the rectangular wall around the window.<\/p>\n<p><strong>Make Sense of Problems<\/strong><br \/>\nUse one of your methods to estimate the area of a wall with a window.<br \/>\nAnswer:<br \/>\nThe area of the wall can be estimated to be twice the area of the window.<\/p>\n<p><strong>Think and Grow: Problem Solving: Perimeter and Area<\/strong><\/p>\n<p><strong>Example<\/strong><br \/>\nA rectangular board has an area of 1,700 square inches. You cut out a rectangular piece that is 10 inches long and 9 inches wide to make a carnival prop similar to the one shown. What is<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-12733\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-64.png\" alt=\"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas 64\" width=\"105\" height=\"177\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nArea of rectangular board =1,700 square inches<br \/>\nLength of the rectangular piece\u00a0 cut = 10 inches<br \/>\nWidth of the rectangular piece cut = 9 inches<br \/>\nArea of the rectangular piece cut = l x w<br \/>\n=&gt;A = 10 X 9<br \/>\n=&gt; A = 90 square inches<br \/>\nArea of the rectangular piece cut = 90 square inches.<br \/>\nSubtract Area of the cut out piece you cut out from the original area.<br \/>\n= 1700 square inches &#8211; 90 square inches<br \/>\n= 1610 square inches.<br \/>\nHence, the Area of the area of the prop = 1610 square inches.<\/p>\n<p><strong>Understand the Problem<\/strong><br \/>\nWhat do you know?<\/p>\n<ul>\n<li>The original board has an area of 1,700 square inches.<\/li>\n<li>The piece you cut out is 10 inches long and 9 inches wide.<\/li>\n<\/ul>\n<p>What do you need to find?<\/p>\n<ul>\n<li>You need to find the area of the carnival prop.<\/li>\n<\/ul>\n<p><strong>Make a Plan<\/strong><\/p>\n<p>How will you solve?<\/p>\n<ul>\n<li>Find the area of the piece you cut out.<\/li>\n<li>Subtract the area of the piece you cut out from the original area.<\/li>\n<\/ul>\n<p><strong>Solve<\/strong><br \/>\n<strong>Step 1:<\/strong> Find the area of the piece you cut out.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12734\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-65.png\" alt=\"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas 65\" width=\"167\" height=\"105\" \/><br \/>\n<strong>Step 2:<\/strong> Subtract the area of the you cut out piece you cut out from the original area.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12735\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-66.png\" alt=\"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas 66\" width=\"192\" height=\"36\" \/><br \/>\nThe area of the prop is __ square inches.<br \/>\nAnswer:<br \/>\nArea of rectangular board =1,700 square inches<br \/>\nLength of the rectangular piece\u00a0 cut = 10 inches<br \/>\nWidth of the rectangular piece cut = 9 inches<br \/>\nArea of the rectangular piece cut = l x w<br \/>\n=&gt;A = 10 X 9<br \/>\n=&gt; A = 90 square inches<br \/>\nArea of the rectangular piece cut = 90 square inches.<br \/>\nSubtract Area of the cut out piece you cut out from the original area.<br \/>\n= 1700 square inches &#8211; 90 square inches<br \/>\n= 1610 square inches.<br \/>\nHence, the Area of the area of the prop = 1610 square inches<\/p>\n<p><strong>Show and Grow<\/strong><\/p>\n<p>Question 1.<br \/>\nExplain how you can check whether your answer above is reasonable.<br \/>\nAnswer:<br \/>\nMy above answer is reasonable because it satisfies.<br \/>\nArea of the area of the prop + Area of the cut out piece\u00a0 =The Area of the outside rectangular<br \/>\n=&gt;1610 square inches + 90 square inches<br \/>\n=&gt;1700 square inches.<br \/>\nHence, proved my answer is reasonable and correct.<\/p>\n<p><strong>Apply and Grow: Practice<\/strong><\/p>\n<p>Understand the problem. What do you know? What do you need to find? Explain.<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nArea of rectangular board =1,700 square inches<br \/>\nLength of the rectangular piece\u00a0 cut = 10 inches<br \/>\nWidth of the rectangular piece cut = 9 inches<br \/>\nThis is known in the problem.<br \/>\nY<span id=\"P622_290\" class=\"s1 f2581 fs17 l0\">ou need t<\/span><span id=\"P622_291\" class=\"s1 f2581 fs17 l0\">o<\/span><span id=\"P622_292\" class=\"s1 f2581 fs17 l0\"> find the ar<\/span><span id=\"P622_293\" class=\"s1 f2581 fs17 l0\">ea of the <\/span><span id=\"P622_294\" class=\"s1 f2581 fs17 l0\">carnival pr<\/span><span id=\"P622_295\" class=\"s1 f2581 fs17 l0\">op.<\/span><\/p>\n<p>Question 2.<br \/>\nA construction worker has 40 feet of caution tape. Is this enough tape to surround a rectangular region that is 120 inches long and 90 inches wide?<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nA construction worker has 40 feet of caution tape.<br \/>\nLength of the rectangular region = 120 inches<br \/>\nWidth of the rectangular region = 90 inches<br \/>\nPerimeter of the rectangular region = 2l + 2 w = 2( l + w)<br \/>\nP = 2( 120 + 90)<br \/>\nP = 2 x 210<br \/>\nP = 420 inches.<br \/>\nCONVERTION: 1 inch = 0.8333 feet\u00a0 or (1\/12) feet<br \/>\n420 inches = ??<br \/>\nLet the unknown value be X feet<br \/>\n=&gt; 1 x X = 420 x 1\/12<br \/>\n=&gt; 1X = 420\/12<br \/>\n=&gt; 1X = 35 feet.<br \/>\nThe required tape to surround the rectangular region = 35 feet.<br \/>\nA construction worker has 40 feet of caution tape.<br \/>\nTherefore, the tape of construction worker bought will be enough to surround a rectangular region that is 120 inches long and 90 inches wide.<\/p>\n<p>Question 3.<br \/>\nOne ton of salt de-ices a rectangular section of a road that is 10,500 meters long and 3 meters wide. How many square meters does 6 tons of salt de-ice?<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nOne ton of salt de-ices a rectangular section of a road<br \/>\nLength of the One ton of salt de-ices rectangular section of a road = 10500 meters<br \/>\nWidth of the One ton of salt de-ices rectangular section of a road = 3 meters<br \/>\nArea of the One ton of salt de-ices rectangular section of a road = l x w<br \/>\nA = l x w<br \/>\nA = 10500 x 3<br \/>\nA = 31500 square meters<br \/>\nArea of the\u00a0 One ton of salt de-ices rectangular section of a road = 31500 square meters.<br \/>\nArea of the 6 ton of salt de-ices rectangular section of a road\u00a0 = ??<br \/>\nArea of the 6 ton of salt de-ices rectangular section of a road\u00a0 =\u00a0(Area of the one ton of salt de-ices rectangular section of a road) x 6<br \/>\n=&gt; 31500 x 6<br \/>\n=&gt; 189000 square feet.<br \/>\nTherefore, Area of the 6 ton of salt de-ices rectangular section of a road\u00a0 = 189000 square feet.<\/p>\n<p>Understand the problem. Then make a plan. How will you solve? Explain.<\/p>\n<p>Question 4.<br \/>\nA worker installs fencing around two rectangular properties. One is 99 feet long and 80 feet wide. The other is95 feet long and 83 feet wide. Which property requires more fencing? How much more?<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nA worker installs fencing around two rectangular properties.<br \/>\nONE RECTANGULAR PROPERTY<br \/>\nLength of the\u00a0 one rectangular property = 99 feet<br \/>\nWidth of the one rectangular property = 80 feet<br \/>\nPerimeter of the one rectangular property = 2l + 2w = 2( l + w)<br \/>\nP = 2 ( 99+ 80 )<br \/>\nP = 2 x 179<br \/>\nP = 358 feet<br \/>\nPerimeter of the one rectangular property = 358 feet.<br \/>\nOTHER RECTANGULAR PROPERTY<br \/>\nLength of the\u00a0 other rectangular property = 95 feet<br \/>\nWidth of the other rectangular property = 83 feet<br \/>\nPerimeter of the other rectangular property = 2l + 2w = 2( l + w)<br \/>\nP = 2 ( 95 + 83 )<br \/>\nP = 2 x 178<br \/>\nP = 356 feet<br \/>\nPerimeter of the other rectangular property = 356 feet<br \/>\nDIFFERENCE:<br \/>\nPerimeter of the one rectangular property &#8211; Perimeter of the other rectangular property<br \/>\n=&gt; 358 &#8211; 356<br \/>\n=&gt; 2 feet.<br \/>\nOne rectangular property requires more fencing than the other rectangular property.<br \/>\nTherefore, 2 feet more it requires than the one rectangular property than the other rectangular property.<\/p>\n<p>Question 5.<br \/>\nA roofer covers the rectangular roof with shingles. A chimney occupies a rectangular area that is 4 feet long and 2 feet wide. How many square feet of the roof are with shingles?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12736\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-67.png\" alt=\"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas 67\" width=\"237\" height=\"137\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nA roofer covers the rectangular roof with shingles.<br \/>\nLength of the rectangular area of chimney = 4 feet<br \/>\nWidth of the rectangular area of chimney = 2 feet<br \/>\nArea of the rectangular area of chimney = l x w<br \/>\nA = 4 x 2<br \/>\nA = 8 square feet<br \/>\nArea of the rectangular area of chimney = 8 square feet.<br \/>\nLength of the rectangular roof = 60 feet<br \/>\nWidth of the rectangular roof= 30 feet<br \/>\nArea of the rectangular roof = l x w<br \/>\nA = 60 x 30<br \/>\nA = 1800 square feet<br \/>\nArea of the rectangular roof = 1800 square feet.<br \/>\nArea of the roof are with shingles = Area of the rectangular roof &#8211; Area of the rectangular area of chimney<br \/>\n=&gt; 1800 square feet &#8211; 8 square feet<br \/>\n=&gt; 1792 square feet.<br \/>\nArea of the roof are with shingles = 1792 square feet.<\/p>\n<p>Question 6.<br \/>\nYou want to buy a cover for the lid of your laptop. Your laptop is 1\\(\\frac{1}{3}\\) feet long and 1 foot wide. Which cover will fit best on your laptop?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12740\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-68.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 68\" width=\"392\" height=\"140\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-68.png 392w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-68-300x107.png 300w\" sizes=\"(max-width: 392px) 100vw, 392px\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the Laptop = 1\\(\\frac{1}{3}\\) feet long =1 (1\/3) feet = 4\/3 feet = 1. 33 feet.<br \/>\nWidth of the laptop = 1 feet<br \/>\nPerimeter of the laptop =2l + 2w = 2( l + w)<br \/>\nP = 2( 1.33 + 1)<br \/>\nP =2 x 2.33<br \/>\nP = 4.66 feet<br \/>\nPerimeter of the laptop =4.66 feet.<br \/>\nCONVERTION:<br \/>\n1 feet = 12 inches<br \/>\n4.66 feet =??<br \/>\n=&gt; 4.66 x 12<br \/>\n=&gt; 55.92 inches<br \/>\nHence, the perimeter of the laptop = 55.92 inches.<br \/>\nFIRST LAPTOP COVER :<br \/>\nLength of the first Laptop cover = 16 inches<br \/>\nWidth of the first Laptop cover = 12 inches<br \/>\nArea of the first Laptop cover =\u00a0 192 square inches<br \/>\nPerimeter of the first Laptop cover = 2l + 2w = 2( l + w)<br \/>\nP = 2( 16 + 12)<br \/>\nP = 2 x 28<br \/>\nP = 56 inches.<br \/>\nPerimeter of the first Laptop cover = 56 inches.<br \/>\nSECOND LAPTOP COVER :<br \/>\nLength of the second Laptop cover = 13 inches<br \/>\nWidth of the second Laptop cover = 9 (3\/4)inches = 39\/4\u00a0 inches = 9.75 inches<br \/>\nArea of the second Laptop cover =\u00a0 126 (3\/4) square inches<br \/>\nPerimeter of the second Laptop cover = 2l + 2w = 2( l + w)<br \/>\nP = 2( 13 +9.75 )<br \/>\nP = 2 x 22.75<br \/>\nP =\u00a0 45.5 inches.<br \/>\nPerimeter of the second Laptop cover = 45.5 inches.<br \/>\nTHIRD LAPTOP COVER<br \/>\nLength of the third Laptop cover = 14 (1\/2) inches = 29\/2\u00a0 inches= 14.5 inches<br \/>\nWidth of the third Laptop cover = 11 inches<br \/>\nArea of the third Laptop cover =\u00a0 159 (1\/2) square inches<br \/>\nPerimeter of the third Laptop cover = 2l + 2w = 2( l + w)<br \/>\nP = 2( 14.5 + 11 )<br \/>\nP = 2 x 25.5<br \/>\nP = 51 inches.<br \/>\nPerimeter of the third Laptop cover = 51 inches.<br \/>\nTherefore, first laptop cover will fit correctly to the laptop because cover size is more accurate size of 56 inches than other two laptop covers are lesser in size of the laptop size 55.92 inches.<\/p>\n<p><strong>Think and Grow: Modeling Real Life<\/strong><\/p>\n<p><strong>Example<\/strong><br \/>\nA worker wants to cover the miniature golf putting surface with artificial turf. The putting surface is in the shape of two rectangles. How much turf does the worker need?<br \/>\nThink: What do you know? What do you need to find? How will you solve?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12741\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-69.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 69\" width=\"150\" height=\"124\" \/><br \/>\n<strong>Step 1:<\/strong> Divide the surface into two rectangles. Then find the area of each rectangle.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12742\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-70.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 70\" width=\"593\" height=\"315\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-70.png 593w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-70-300x159.png 300w\" sizes=\"(max-width: 593px) 100vw, 593px\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\n<img src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-69.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 69\" \/><br \/>\nDivide the surface into two rectangles. Then find the area of each rectangle.<br \/>\n<a href=\"https:\/\/ccssmathanswers.com\/big-ideas-math-answers-grade-4-chapter-12\/big-ideas-math-answers-grade-4-chapter-12-use-perimeter-area-12-2-modeling-real-life-example\/\" rel=\"attachment wp-att-20393\"><img loading=\"lazy\" class=\"alignnone size-full wp-image-20393\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-modeling-real-life-example.png\" alt=\"\" width=\"232\" height=\"190\" \/><\/a><br \/>\nLength of the Rectangle A = 16 feet<br \/>\nWidth of the Rectangle A = `4 feet<br \/>\nArea of the Rectangle A = l x w<br \/>\nA =16 x 4<br \/>\nA = 64 square feet<br \/>\nArea of the Rectangle A = 64 square feet.<br \/>\nLength of the Rectangle B = `10 feet<br \/>\nWidth of the Rectangle B = `5 feet<br \/>\nArea of the Rectangle B = l x w<br \/>\nA = 10 x 5<br \/>\nA = 50 square feet<br \/>\nArea of the Rectangle B = 50 square feet.<br \/>\nADDITION:<br \/>\nArea of the Rectangle A + Area of the Rectangle B<br \/>\n=&gt; 64 square feet + 50 square feet<br \/>\n=&gt; 114 square feet.<br \/>\nHence, the workers need 114 square feet for artificial turf.<\/p>\n<p>Question 7.<br \/>\nYou want to install new carpet in the rectangular bedroom and the rectangular closet. How much carpet do you need to cover the \ufb02oor?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12738\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-413.png\" alt=\"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas 413\" width=\"214\" height=\"157\" \/><\/p>\n<p>Answer:<br \/>\nGIVEN:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12738\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-413.png\" alt=\"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas 413\" width=\"214\" height=\"157\" \/><br \/>\nLength of the rectangular bedroom = 20 feet<br \/>\nWidth\u00a0 of the rectangular bedroom = 10 feet<br \/>\nArea of the rectangular bedroom = l x w<br \/>\nA = 20 x 10<br \/>\nA = 200 square feet<br \/>\nArea of the rectangular bedroom = 200 square feet.<br \/>\nLength of the rectangular closet = 10 feet<br \/>\nWidth\u00a0 of the rectangular closet= 4 feet<br \/>\nArea of the rectangular closet = l x w<br \/>\nA = 10 x 4<br \/>\nA = 40 square feet<br \/>\nArea of the rectangular closet = 40 square feet.<br \/>\nADDITION:<br \/>\nCarpet\u00a0 needed to cover the \ufb02oor = Area of the rectangular bedroom + Area of the rectangular closet.<br \/>\n=&gt; 200 square feet + 40 square feet<br \/>\n=&gt; 240 square feet.<br \/>\nHence, the Carpet\u00a0 needed to cover the \ufb02oor = 240 square feet.<\/p>\n<p>Question 8.<br \/>\nA gardener wants to enclose the garden with fencing. The garden is in the shape of two rectangles. How much fencing does the gardener need?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12739\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-414.png\" alt=\"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas 414\" width=\"237\" height=\"155\" \/><br \/>\nAnswer:<br \/>\n<img src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-414.png\" alt=\"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas 414\" \/><br \/>\nDivide the surface into two rectangles.<\/p>\n<p><a href=\"https:\/\/ccssmathanswers.com\/big-ideas-math-answers-grade-4-chapter-12\/big-ideas-math-answers-grade-4-chapter-12-use-perimeter-area-12-2-modeling-real-life-example-2\/\" rel=\"attachment wp-att-20406\"><img loading=\"lazy\" class=\"alignnone size-full wp-image-20406\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-modeling-real-life-example-1.png\" alt=\"\" width=\"474\" height=\"261\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-modeling-real-life-example-1.png 474w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-modeling-real-life-example-1-300x165.png 300w\" sizes=\"(max-width: 474px) 100vw, 474px\" \/><\/a><br \/>\nLength of the Rectangle A = 8 yard<br \/>\nWidth of the Rectangle A = 6 yard<br \/>\nPerimeter of the Rectangle A = 2l x 2w = 2( l + w)<br \/>\nP = 2( 8 + 6 )<br \/>\nP = 2 x 14<br \/>\nP = 28 yards<br \/>\nPerimeter of the Rectangle A = 28 yards.<br \/>\nLength of the Rectangle B = 10 yard<br \/>\nWidth of the Rectangle B = 3 yard<br \/>\nPerimeter of the Rectangle B = 2l x 2w = 2( l + w)<br \/>\nP = 2( 10 + 3 )<br \/>\nP = 2 x 13<br \/>\nP = 26 yards<br \/>\nPerimeter of the Rectangle B = 26 yards.<br \/>\nFencing the gardener needed = Perimeter of the Rectangle A + Perimeter of the Rectangle B<br \/>\n=&gt; 28 yards + 26 yards<br \/>\n=&gt; 54 yards.<br \/>\nHence, the Fencing the gardener needed = 54 yards.<\/p>\n<h3><a id=\"Problem_Solving:_Perimeter_and_Area_Homework_&amp;_Practice_12.4\"><\/a>Problem Solving: Perimeter and Area Homework &amp; Practice 12.4<\/h3>\n<p>Understand the problem. Then make a plan. How will you solve? Explain.<\/p>\n<p>Question 1.<br \/>\nAn indoor dog park has an area of 50,000 square feet. The owner creates a square welcome center inside the park that is 100 feet long. What is the area of the section that dogs can play in?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12743\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-71.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 71\" width=\"172\" height=\"210\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12743\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-71.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 71\" width=\"172\" height=\"210\" \/><\/p>\n<p>Area of the indoor dog park = 50,000 square feet.<br \/>\nThe owner creates a square welcome center inside the park that is 100 feet long.<br \/>\n=&gt; side of the square welcome center inside the park = 100 feet<br \/>\nArea of the square welcome center inside the park =\u00a0 s x s<br \/>\nA = 100 x 100<br \/>\nA\u00a0 = 10,000 square feet<br \/>\nArea of the square welcome center inside the park = 10,000 square feet.<br \/>\nArea of the section that dogs can play in = Area of the indoor dog park &#8211; Area of the square welcome center inside the park<br \/>\n=&gt; 50,000 square feet &#8211; 10,000 square feet<br \/>\n=&gt; 40,000 square feet.<br \/>\nHence, the Area of the section that dogs can play in = 40,000 square feet.<\/p>\n<p>Question 2.<br \/>\nYou tile a hallway with square tiles that are 12 inches wide. You completely cover the hallway with 3 rows of 5 tiles. What is the area of the hallway?<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nSide of the square tiles = 12 inches<br \/>\nThe hallway completely covered with 3 rows of 5 tiles.<br \/>\nArea of the square tiles hallway= s x s<br \/>\nA = 12 x 12<br \/>\nA = 144 square inches.<br \/>\nHence, the Area of the square tiles hallway= 144 square inches.<\/p>\n<p>Question 3.<br \/>\nYour friend makes a rectangular poster for a school play. The poster is 4 feet long and 3 feet wide. Ribbon costs $1 per foot. How much does it cost to add a ribbon border to the poster?<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the rectangular poster = 4 feet<br \/>\nWidth of the rectangular poster = 3 feet<br \/>\nPerimeter of the rectangular poster = 2l +2w = 2(l + w)<br \/>\nP = 2 ( 4 + 3 )<br \/>\nP = 2 x 7<br \/>\nP = 14 feet<br \/>\nPerimeter of the rectangular poster = 14 feet.<br \/>\nRibbon costs $1 per foot<br \/>\nCost of the ribbon border to the poster = 14 feet x $1= $14<br \/>\nTherefore, the Cost of the ribbon border to the poster = $14.<\/p>\n<p>Question 4.<br \/>\n<strong>Writing<\/strong><br \/>\nExplain how you know when you need to \ufb01nd the perimeter or the area of a rectangle when solving a word problem.<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nPerimeter can be thought\u00a0 as the length of the outline of a shape.<br \/>\nArea can be defined as the space occupied by a flat shape or the surface of an object.<br \/>\nOn the above referred points,\u00a0 I try to calculate the perimeter or the area of the rectangle when solving a word problem.<\/p>\n<p>Question 5.<br \/>\n<strong>Modeling Real Life<\/strong><br \/>\nYour teacher joins two rectangular tables for students to complete a craft. How much newspaper does your teacher need to cover the tops of the tables with no overlap and no paper hanging over the sides?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12744\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-72.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 72\" width=\"198\" height=\"179\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\n<img src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-72.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 72\" \/><br \/>\nDivide the surface into two rectangles.<br \/>\n<a href=\"https:\/\/ccssmathanswers.com\/big-ideas-math-answers-grade-4-chapter-12\/big-ideas-math-answers-grade-4-chapter-12-use-perimeter-area-12-2-modeling-real-life-question-5\/\" rel=\"attachment wp-att-20435\"><img loading=\"lazy\" class=\"alignnone size-full wp-image-20435\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-modeling-real-life-question-5.png\" alt=\"\" width=\"389\" height=\"332\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-modeling-real-life-question-5.png 389w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-modeling-real-life-question-5-300x256.png 300w\" sizes=\"(max-width: 389px) 100vw, 389px\" \/><\/a><br \/>\nLength of the rectangle A = 72 inches<br \/>\nWidth of the of the rectangle A = 30 inches<br \/>\nPerimeter of the rectangle A = 2l + 2w = 2( l + w)<br \/>\nP = 2( 72 + 30 )<br \/>\nP =\u00a0 2 x 102<br \/>\nP = 204 inches<br \/>\nPerimeter of the rectangle A = 204 inches.<br \/>\nLength of the rectangle B = 60 inches<br \/>\nWidth of the of the rectangle B = 30 inches<br \/>\nPerimeter of the rectangle B = 2l + 2w = 2( l + w)<br \/>\nP = 2( 60 + 30 )<br \/>\nP = 2 x 90<br \/>\nP = 180 inches<br \/>\nPerimeter of the rectangle B = 180 inches.<br \/>\nNewspaper needed to cover the tops of the tables with no overlap and no paper hanging over the sides = Perimeter of the rectangle A + Perimeter of the rectangle B<br \/>\n= 204 inches + 180 inches<br \/>\n= 384 inches.<br \/>\nHence, the newspaper needed to cover the tables = 384 inches.<\/p>\n<p>Question 6.<br \/>\n<strong>Modeling Real Life<\/strong><br \/>\nA landscaper buys 2 bags of grass seed. Each bag covers 5,000 square feet. A rectangular lawn is 200 feet long and 40 feet wide. Does the landscaper have enough seed to cover the lawn once? twice? Explain.<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nA landscaper buys 2 bags of grass seed.<br \/>\nArea of the bags seed covers = 5000 square feet.<br \/>\nLength of the rectangular lawn = 200 feet<br \/>\nWidth of the rectangular lawn = 40 feet<br \/>\nArea of the rectangular lawn = l x w<br \/>\nA = 200 x 40<br \/>\nA = 8000 square feet.<br \/>\nArea of the rectangular lawn = 8000 square feet.<br \/>\nThe landscaper have enough seed to cover the lawn once only not twice because he has\u00a0 bags which can cover only 5000 square feet not 8000 square feet rectangular lawn completely.<\/p>\n<p><strong>Review &amp; Refresh<\/strong><\/p>\n<p>Multiply<\/p>\n<p>Question 7.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12745\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-73.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 73\" width=\"74\" height=\"43\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12745\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-73.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 73\" width=\"74\" height=\"43\" \/>= 2 x 1\/4<br \/>\n= 1 x 1\/2<br \/>\n= 1\/2<br \/>\n= 0.5<br \/>\nHence, <img src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-73.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 73\" \/>= 0.5.<\/p>\n<p>Question 8.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12746\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-74.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 74\" width=\"60\" height=\"49\" \/><br \/>\nAnswer:<br \/>\n<img src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-74.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 74\" \/>= 12\/5<br \/>\n= 2.4.<br \/>\nHence, <img src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-74.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 74\" \/> = 2.4.<\/p>\n<p>Question 9.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12747\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-75.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 75\" width=\"70\" height=\"51\" \/><br \/>\nAnswer:<br \/>\n<img src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-75.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 75\" \/>= 6 x 5\/4<br \/>\n= 3 x 5\/2<br \/>\n=15\/2<br \/>\n= 7.5.<br \/>\nHence, <img src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-75.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 75\" \/> = 7.5.<\/p>\n<h3><a id=\"Use_Perimeter_and_Area_Formulas_Performance_Task_12\"><\/a>Use Perimeter and Area Formulas Performance Task 12<\/h3>\n<p>Stop-motion animation videos are made by taking multiple photographs of an object. Each photograph shows the object in a slightly different position. When all of the photographs are combined into a video, the object appears to be moving.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12748\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-76.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 76\" width=\"547\" height=\"134\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-76.png 547w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-76-300x73.png 300w\" sizes=\"(max-width: 547px) 100vw, 547px\" \/><br \/>\n1. You decide to make a stop-motion video. You make a background with an area of 12 square feet and a perimeter of 14 feet.<br \/>\na. What are the dimensions of your background?<br \/>\nb. The part of the background in each photograph is 45 inches long and 30 inches wide. What is the perimeter of the background in each photograph?<br \/>\nc. What is the area of the background that is not in each photograph?<br \/>\n2. You take photographs for your video. Your video shows 15 photographs each second. How many photographs are in a 24-second video?<br \/>\n3. You start working on your animation at 3:05 P.M. and \ufb01nish at 5:20 P.M. You spend equal amounts of time creating your background, taking photographs, and editing your video. How much time do you spend on each activity?<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nArea of the rectangular background= 12 square feet.<br \/>\nPerimeter\u00a0 of the rectangular background = 14 feet.<br \/>\n<strong>1. a)<\/strong> All dimensions of the rectangular background =<br \/>\nArea of the rectangle = l x w<br \/>\n1 \u00d7\u00a012\u00a0=\u00a012.<br \/>\n2 \u00d7 6 =\u00a012.<br \/>\n3 \u00d7 4 =\u00a012.<br \/>\nThe dimensions of the rectangular background = (1,12); (2,6);(3,4).<br \/>\n<strong>b)<\/strong> The Length of the background in each photograph = 45 inches The Width\u00a0 of the background in each photograph =30 inches\u00a0 The perimeter of the background in each photograph = 2l + 2w = 2(l + w)<br \/>\nP = 2 (45 + 30)<br \/>\nP = 2 x 75<br \/>\nP = 150 inches.<br \/>\nHence, the perimeter of the background in each photograph = 150 inches.<br \/>\n<strong>2)\u00a0<\/strong><br \/>\nGIVEN:<br \/>\n15 photograph taken in 1 second<br \/>\n=&gt; ?? in 24 seconds<br \/>\n=&gt; 24 x 15 = photographs taken in 24 seconds<br \/>\n=&gt; 360 = photographs taken in 24 seconds<br \/>\nHence, photographs taken in 24 seconds = 360.<br \/>\n<strong>3)<br \/>\n<\/strong>GIVEN:<br \/>\nStarting time on animation at 3:05 P.M.<br \/>\nFinishing time on animation at 5:20 P.M.<br \/>\nTime taken on each activity = Finishing time on animation &#8211; Starting time on animation<br \/>\n=&gt; 5:20 P.M &#8211; 3:05 P.M<br \/>\n=&gt; 2: 15 Hours<br \/>\nHence, Time taken on each activity =2:15 Hours.<\/p>\n<h3><a id=\"Use_Perimeter_and_Area_Formulas_Activity\"><\/a>Use Perimeter and Area Formulas Activity<\/h3>\n<p><strong>Area Roll and Conquer<\/strong><\/p>\n<p><strong>Directions:<\/strong><\/p>\n<ol>\n<li>Players take turns rolling two dice.<\/li>\n<li>On your turn, create a rectangle with the numbers on the dice as the length and width. Your rectangle cannot cover another rectangle.<\/li>\n<li>Shade the rectangle in your color. Record the multiplication equation for the rectangle.<\/li>\n<li>If you cannot create a rectangle on the board, then you lose your turn. Play 10 rounds, if possible.<\/li>\n<li>The player with the greatest area covered wins!<\/li>\n<\/ol>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-12749\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-77.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 77\" width=\"196\" height=\"229\" \/><br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12750\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-78.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 78\" width=\"687\" height=\"625\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-78.png 687w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-78-300x273.png 300w\" sizes=\"(max-width: 687px) 100vw, 687px\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<\/p>\n<ol>\n<li>Players take turns rolling two dice.<\/li>\n<\/ol>\n<p>1) <a href=\"https:\/\/ccssmathanswers.com\/big-ideas-math-answers-grade-4-chapter-12\/big-ideas-math-answers-grade-4-chapter-12-use-perimeter-area-12-2-modeling-real-life-activity-4\/\" rel=\"attachment wp-att-20556\"><img loading=\"lazy\" class=\"alignnone size-full wp-image-20556\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-modeling-real-life-activity.-1.png\" alt=\"\" width=\"233\" height=\"94\" \/><\/a><br \/>\n2)<br \/>\n<a href=\"https:\/\/ccssmathanswers.com\/big-ideas-math-answers-grade-4-chapter-12\/big-ideas-math-answers-grade-4-chapter-12-use-perimeter-area-12-2-modeling-real-life-activity-2\/\" rel=\"attachment wp-att-20551\"><img loading=\"lazy\" class=\"alignnone size-full wp-image-20551\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-modeling-real-life-activity-1.png\" alt=\"\" width=\"332\" height=\"204\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-modeling-real-life-activity-1.png 332w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-modeling-real-life-activity-1-300x184.png 300w\" sizes=\"(max-width: 332px) 100vw, 332px\" \/><\/a><br \/>\nLength of the rectangle = 4 units<br \/>\nWidth of the rectangle = 3 units.<br \/>\n<strong>3)<\/strong> <img src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-modeling-real-life-activity-1.png\" \/><br \/>\nEquation of the rectangle = 4 x 3 = 12 square units.<br \/>\n<strong>4)\u00a0 \u00a0 <\/strong><br \/>\n<a href=\"https:\/\/ccssmathanswers.com\/big-ideas-math-answers-grade-4-chapter-12\/big-ideas-math-answers-grade-4-chapter-12-use-perimeter-area-12-2-modeling-real-life-activity-3\/\" rel=\"attachment wp-att-20555\"><img loading=\"lazy\" class=\"alignnone size-full wp-image-20555\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-modeling-real-life-activity..png\" alt=\"\" width=\"1920\" height=\"1080\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-modeling-real-life-activity..png 1920w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-modeling-real-life-activity.-300x169.png 300w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-modeling-real-life-activity.-1024x576.png 1024w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-modeling-real-life-activity.-768x432.png 768w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12-Use-Perimeter-Area-12.2-modeling-real-life-activity.-1536x864.png 1536w\" sizes=\"(max-width: 1920px) 100vw, 1920px\" \/><\/a><strong>5)\u00a0<\/strong><br \/>\nThe player with the greatest area covered wins!<br \/>\nGiven Equation Area = 3 x 2 = 6 square units<br \/>\nMy Equation Area= 4 x 3 =12 square units<\/p>\n<h3><a id=\"Use_Perimeter_and_Area_Formulas_Chapter_Practice\"><\/a>Use Perimeter and Area Formulas Chapter Practice<\/h3>\n<p><strong>12.1 Perimeter Formula for a Rectangle<\/strong><\/p>\n<p>Find the perimeter of the rectangle.<\/p>\n<p>Question 1.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12751\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-79.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 79\" width=\"145\" height=\"115\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the rectangle = 15 yard<br \/>\nWidth of the rectangle = 13 yard<br \/>\nPerimeter of the rectangle = 2l + 2w = 2( l + w)<br \/>\nP = 2 (15 + 13)<br \/>\nP = 2 x 28<br \/>\nP = 56 yards<br \/>\nHence, the Perimeter of the rectangle = 56 yards.<\/p>\n<p>Question 2.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12752\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-80.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 80\" width=\"136\" height=\"128\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the rectangle = 29 mm<br \/>\nWidth of the rectangle = 23 mm<br \/>\nPerimeter of the rectangle = 2l + 2w = 2( l + w)<br \/>\nP = 2 ( 29 + 23)<br \/>\nP = 2 x 52<br \/>\nP = 104 mm<br \/>\nHence, the Perimeter of the rectangle = 104 mm.<\/p>\n<p>Question 3.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12753\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-81.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 81\" width=\"157\" height=\"111\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the rectangle = 55 cm<br \/>\nWidth of the rectangle = 46 cm<br \/>\nPerimeter of the rectangle = 2l + 2w = 2( l + w)<br \/>\nP = 2( 55 + 46)<br \/>\nP = 2 x 101<br \/>\nP = 202 cm<br \/>\nHence, the Perimeter of the rectangle = 202 cm.<\/p>\n<p>Question 4.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12754\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-82.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 82\" width=\"132\" height=\"113\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the rectangle = 10 (2\/12) feet = 20\/12 = 1.67 feet<br \/>\nWidth of the rectangle = 7 feet<br \/>\nPerimeter of the rectangle = 2l + 2w = 2( l + w)<br \/>\nP = 2(1.67 + 7)<br \/>\nP = 2 x 7.67<br \/>\nP = 15.34 feet<br \/>\nHence, the Perimeter of the rectangle = 15.34 feet.<\/p>\n<p><strong>12.2 Area Formula for a Rectangle<\/strong><\/p>\n<p>Find the area of the rectangle.<\/p>\n<p>Question 5.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12755\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-83.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 83\" width=\"164\" height=\"108\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the rectangle =\u00a0 58 m<br \/>\nWidth of the rectangle = 37 m<br \/>\nArea of the rectangle = l x w<br \/>\nA = 58 x 37<br \/>\nA = 2146 square m.<br \/>\nHence, the Area of the rectangle = 2146 square m.<\/p>\n<p>Question 6.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12756\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-84.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 84\" width=\"120\" height=\"133\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the rectangle = 13 (1\/2) inches = 27\/2 = 13.5 inches<br \/>\nWidth of the rectangle = 7 inches<br \/>\nArea of the rectangle = l x w<br \/>\nA = 13.5 x 7<br \/>\nA = 94.5 square inches<br \/>\nHence, the Area of the rectangle = 94.5 square inches.<\/p>\n<p>Question 7.<br \/>\nA rectangle has an area of 60 square feet. The dimensions are whole numbers. What are all of the possible dimensions of the rectangle?<br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the rectangle = l feet<br \/>\nWidth of the rectangle = w feet<br \/>\nArea of the rectangle = 60 square feet<br \/>\nArea of the rectangle = l x w<br \/>\nAll possible dimensions of rectangle =<br \/>\n60\u00a0= 1 x\u00a060,<br \/>\n60 = 2 x 30,<br \/>\n60 = 3 x 20,<br \/>\n60 = 4 x 15<br \/>\n60 = 5 x 12,<br \/>\n60 = 6 x 10.<br \/>\nAll possible dimensions of rectangle =(1,60);(2,30);(3,20);(4,15);(5,12);(6,10).<\/p>\n<p><strong>12.3 Find Unknown Measures<\/strong><\/p>\n<p>Find the unknown measure of the rectangle.<\/p>\n<p>Question 8.<br \/>\nArea = 48 square yards<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12757\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-85.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 85\" width=\"95\" height=\"123\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nArea of the rectangle = 48 square yards<br \/>\nLength of the rectangle = l yards<br \/>\nWidth of the rectangle = 3\u00a0yards<br \/>\nArea of the rectangle = l x w<br \/>\n48 = l x 3<br \/>\n48\/3 = l<br \/>\n16 = l<br \/>\nHence, the Length of the rectangle = 16 yards.<\/p>\n<p>Question 9.<br \/>\nPerimeter = 90 centimeters<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12758\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-86.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 86\" width=\"192\" height=\"80\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nPerimeter of the rectangle = 90 centimeters<br \/>\nLength of the rectangle = l cm<br \/>\nWidth of the rectangle = 12 cm<br \/>\nPerimeter of the rectangle = 2l + 2w = 2( l + w)<br \/>\n90 = 2( l + 12)<br \/>\n90\/2 = l + 12<br \/>\n45 = l + 12<br \/>\n45 &#8211; 12 = l<br \/>\n33 = l<br \/>\nHence, the Length of the rectangle = 33 cm.<\/p>\n<p>Question 10.<br \/>\n<strong>Logic<\/strong><br \/>\nWhat are the dimensions of Descartes\u2019s rectangle?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12759\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-87.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 87\" width=\"233\" height=\"210\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nPerimeter of the rectangle = 10 meters<br \/>\nLength and Width have a product = 6 square meters<br \/>\n=&gt; l x w = 6 square meters<br \/>\n=&gt; Area of the rectangle = l x w = 6 square meters.<br \/>\nAll possible dimensions of the rectangle =<br \/>\n6 = 1 x 6<br \/>\n6 = 2 x 3.<br \/>\nHence, All possible dimensions of the rectangle =(1,6);(2,3).<\/p>\n<p><strong>12.4 Problem Solving: Perimeter and Area<\/strong><\/p>\n<p>Question 11.<br \/>\n<strong>Modeling Real Life<\/strong><br \/>\nYou want to paint the wall. What is the area of the wall you will paint?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12760\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-88.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 88\" width=\"150\" height=\"162\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nLength of the outer rectangle = 14 feet<br \/>\nWidth of the outer rectangle = 10 feet<br \/>\nArea of the outer rectangle = l x w<br \/>\nA = 14 x 10<br \/>\nA = 140 square feet.<br \/>\nArea of the outer rectangle = 140 square feet.<br \/>\nLength of the inside rectangle = 4 feet<br \/>\nWidth of the inside rectangle = 1(1\/2) feet = 3\/2 = 1.5 feet<br \/>\nArea of the inside rectangle = l x w<br \/>\nA = 4 x 1.5<br \/>\nA = 6 square feet.<br \/>\nArea of the inside rectangle = 6 square feet.<br \/>\nSUBTRACTION:<br \/>\nArea of the wall for paint = Area of the outer rectangle\u00a0 &#8211; Area of the inside rectangle<br \/>\n= 140 square feet &#8211; 6 square feet.<br \/>\n= 134 square feet.<br \/>\nHence, the Area of the wall for paint = 134 square feet.<\/p>\n<p>Question 12.<br \/>\nA park director orders 360 feet of fencing. Does he have enough to surround the tennis court?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-12761\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Solutions-Grade-4-Chapter-12-Use-Perimeter-and-Area-Formulas-89.png\" alt=\"Big Ideas Math Solutions Grade 4 Chapter 12 Use Perimeter and Area Formulas 89\" width=\"236\" height=\"126\" \/><br \/>\nAnswer:<br \/>\nGIVEN:<br \/>\nFencing length park director ordered = 360 feet.<br \/>\nLength of the rectangle = 40 yards<br \/>\nWidth of the rectangle = 20 yards<br \/>\nPerimeter of the rectangle =\u00a02l + 2w = 2 ( l + w)<br \/>\nP= 2( 40 + 20)<br \/>\nP = 2 x 60<br \/>\nP = 120 yards<br \/>\nCONVERTION:<br \/>\n1 yard = 3 feet<br \/>\n120 yards = ??<br \/>\n=&gt; 120 x 3<br \/>\n=&gt; 360 feet.<br \/>\nHence, the director ordered fencing\u00a0 360 feet is enough for fencing the tennis court because the required court perimeter is same 360 feet.<\/p>\n<p><em>Conclusion:<\/em><\/p>\n<p>I wish the information provided in the Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas is helpful for you all. Share the pdf links with your friends and help them to overcome the difficulties in maths. If you any doubts feel free to post the comments in the below-mentioned comment box. Bookmark our page to get the updates of Big Ideas Math Grade 4 Answer Key for all Chapters.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas is the best source for students. Students can follow the step-by-step procedure to solve the problems. We have given a detailed explanation for every problem. Also, we included real-time examples to make the student&#8217;s preparation perfect. Get the free pdf Big Ideas &#8230; <a title=\"Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas\" class=\"read-more\" href=\"https:\/\/bigideasmathanswers.com\/big-ideas-math-answers-grade-4-chapter-12\/\" aria-label=\"More on Big Ideas Math Answers Grade 4 Chapter 12 Use Perimeter and Area Formulas\">Read more<\/a><\/p>\n","protected":false},"author":9,"featured_media":89660,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[4],"tags":[],"jetpack_featured_media_url":"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/12\/Big-Ideas-Math-Answers-Grade-4-Chapter-12.png","_links":{"self":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts\/12657"}],"collection":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/users\/9"}],"replies":[{"embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/comments?post=12657"}],"version-history":[{"count":1,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts\/12657\/revisions"}],"predecessor-version":[{"id":90261,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts\/12657\/revisions\/90261"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/media\/89660"}],"wp:attachment":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/media?parent=12657"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/categories?post=12657"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/tags?post=12657"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}