{"id":4238,"date":"2022-03-26T05:16:34","date_gmt":"2022-03-25T23:46:34","guid":{"rendered":"https:\/\/ccssmathanswers.com\/?p=4238"},"modified":"2022-04-07T12:27:33","modified_gmt":"2022-04-07T06:57:33","slug":"go-math-grade-5-answer-key-chapter-6-add-and-subtract-fractions-with-unlike-denominators","status":"publish","type":"post","link":"https:\/\/bigideasmathanswers.com\/go-math-grade-5-answer-key-chapter-6-add-and-subtract-fractions-with-unlike-denominators\/","title":{"rendered":"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators"},"content":{"rendered":"<p>Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators can be downloaded free of cost from here. HMH <a href=\"https:\/\/ccssmathanswers.com\/go-math-grade-5-answer-key\/\" target=\"_blank\" rel=\"noopener noreferrer\">Go Math Grade 5 Answer Key<\/a> includes topics such as Addition and Subtraction with unlike denominators, Estimate fraction sums and differences, Least Common Denominators, etc. Begin your preparation from Go Math Grade 5 Chapter 6 Solution Key Add and Subtract Fractions with Unlike Denominators and score better grades in your exams.<\/p>\n<h2>Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators<\/h2>\n<p>The Go Math Grade 5 Answer Key Add and Subtract Fractions with Unlike Denominators covers all the Questions in Chapter Tests, Practice Tests, etc., and has detailed solutions for all of them. Try to solve as many problems as possible from the\u00a0 Go Math Answer Key for Grade 5 Chapter 6 Add and Subtract Fractions with Unlike Denominators and know the concepts behind them easily. Access the Topics in 5th Grade Go Math Ch 6 Add and Subtract Fractions with Unlike Denominators via quick links available in the forthcoming modules.<\/p>\n<p><strong>Lesson 1: Investigate \u2022 Addition with Unlike Denominators<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_244\">Share and Show &#8211; Page No. 244<\/a><\/li>\n<li><a href=\"#Investigate_Addition_with_Unlike_Denominators_Page_No_245\">Investigate \u2022 Addition with Unlike Denominators Page No. 245<\/a><\/li>\n<li><a href=\"#Problem_Solving_Page_No_246\">Problem Solving &#8211; Page No. 246<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 2: Investigate \u2022 Subtraction with Unlike Denominators<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_248\">Share and Show &#8211; Page No. 248<\/a><\/li>\n<li><a href=\"#Investigate_Subtraction_with_Unlike_Denominators_Page_No_249\">Investigate \u2022 Subtraction with Unlike Denominators Page No. 249<\/a><\/li>\n<li><a href=\"#UNLOCK_the_Problem_Page_No_250\">UNLOCK the Problem &#8211; Page No. 250<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 3: Estimate Fraction Sums and Differences<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_253\">Share and Show &#8211; Page No. 253<\/a><\/li>\n<li><a href=\"#Problem_Solving_Page_No_254\">Problem Solving &#8211; Page No. 254<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 4: Common Denominators and Equivalent Fractions<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_256\">Share and Show &#8211; Page No. 256<\/a><\/li>\n<li><a href=\"#Common_Denominators_and_Equivalent_Fractions_Page_No_257\">Common Denominators and Equivalent Fractions Page No. 257<\/a><\/li>\n<li><a href=\"#UNLOCK_the_Problem_Page_No_258\">UNLOCK the Problem &#8211; Page No. 258<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 5: Add and Subtract Fractions<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_260\">Share and Show &#8211; Page No. 260<\/a><\/li>\n<li><a href=\"#On_Your_Own_Page_No_261\">On Your Own &#8211; Page No. 261<\/a><\/li>\n<li><a href=\"#Problem_Solving_Page_No_262\">Problem Solving &#8211; Page No. 262<\/a><\/li>\n<\/ul>\n<p><strong>Mid-Chapter Checkpoint<\/strong><\/p>\n<ul>\n<li><a href=\"#Mid_Chapter_Checkpoint_Vocabulary_Page_No_263\">Mid-Chapter Checkpoint &#8211; Vocabulary &#8211; Page No. 263<\/a><\/li>\n<li><a href=\"#Mid_Chapter_Checkpoint_Page_No_264\">Mid-Chapter Checkpoint &#8211; Page No. 264<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 6: Add and Subtract Mixed Numbers<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_266\">Share and Show &#8211; Page No. 266<\/a><\/li>\n<li><a href=\"#Page_No_267\">Page No. 267<\/a><\/li>\n<li><a href=\"#Problem_Solving_Page_No_268\">Problem Solving &#8211; Page No. 268<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 7: Subtraction with Renaming<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_270\">Share and Show &#8211; Page No. 270<\/a><\/li>\n<li><a href=\"#Subtraction_with_Renaming_Page_No_271\">Subtraction with Renaming Page No. 271<\/a><\/li>\n<li><a href=\"#Subtraction_with_Renaming_Page_No_272\">Subtraction with Renaming Page No. 272<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 8: Algebra \u2022 Patterns with Fractions<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_275\">Share and Show &#8211; Page No. 275<\/a><\/li>\n<li><a href=\"#Problem_Solving_Page_No_276\">Problem Solving &#8211; Page No. 276<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 9: Problem Solving \u2022 Practice Addition and Subtraction<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_279\">Share and Show &#8211; Page No. 279<\/a><\/li>\n<li><a href=\"#On_Your_Own_Page_No_280\">On Your Own &#8211; Page No. 280<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 10: Algebra \u2022 Use Properties of Addition<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_283\">Share and Show &#8211; Page No. 283<\/a><\/li>\n<li><a href=\"#Problem_Solving_Page_No_284\">Problem Solving &#8211; Page No. 284<\/a><\/li>\n<\/ul>\n<p><strong>Chapter 6 Review\/Test<\/strong><\/p>\n<ul>\n<li><a href=\"#Chapter_Review_Test_Page_No_285\">Chapter Review\/Test &#8211; Vocabulary &#8211; Page No. 285<\/a><\/li>\n<li><a href=\"#Chapter_Review_Test_Page_No_286\">Chapter Review\/Test &#8211; Page No. 286<\/a><\/li>\n<li><a href=\"#Chapter_Review_Test_Page_No_287\">Chapter Review\/Test &#8211; Page No. 287<\/a><\/li>\n<li><a href=\"#Chapter_Review_Test_Page_No_288\">Chapter Review\/Test &#8211; Page No. 288<\/a><\/li>\n<\/ul>\n<h3><a id=\"Share_and_Show_Page_No_244\"><\/a>Share and Show &#8211; Page No. 244<\/h3>\n<p><strong>Use fraction strips to find the sum. Write your answer in simplest form.<\/strong><\/p>\n<p>Question 1.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-1.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators img 1\" width=\"197\" height=\"73\" \/><br \/>\n\\(\\frac{1}{2}+\\frac{3}{8}=\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{7}{8}\\)<br \/>\nExplanation:<br \/>\nStep 1:<br \/>\nPlace three \\(\\frac{1}{8}\\) fractions strips under the 1 whole strip on your Mathboard. Then place a \\(\\frac{1}{2}\\) fraction strip beside the three \\(\\frac{1}{8}\\) strips.<br \/>\nStep 2:<br \/>\nFind fraction strips, all with the same denominator, that are equivalent to \\(\\frac{1}{2}\\) and \\(\\frac{3}{8}\\). Place the fraction strips under the sum. At the right, draw a picture of the model and write the equivalent fractions.<br \/>\n\\(\\frac{1}{2}\\) = \\(\\frac{1}{2}\\) \u00d7 \\(\\frac{4}{4}\\) = \\(\\frac{4}{8}\\)<br \/>\n\\(\\frac{3}{8}\\)<br \/>\nStep 3:<br \/>\nAdd the fractions with like denominators. Use the 1 whole strip to rename the sum in the simplest form.<br \/>\n\\(\\frac{4}{8}\\) + \\(\\frac{3}{8}\\) = \\(\\frac{7}{8}\\)<\/p>\n<p>Question 2.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-2.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators img 2\" width=\"198\" height=\"74\" \/><br \/>\n\\(\\frac{1}{2}+\\frac{2}{5}=\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{9}{10}\\)<br \/>\nExplanation:<br \/>\nStep 1:<br \/>\nPlace two \\(\\frac{1}{5}\\) fractions strips under the 1 whole strip on your Mathboard. Then place a \\(\\frac{1}{2}\\) fraction strip beside the two \\(\\frac{1}{5}\\) strips.<br \/>\nStep 2:<br \/>\nFind fraction strips, all with the same denominator, that are equivalent to \\(\\frac{1}{2}\\) and \\(\\frac{2}{5}\\). Place the fraction strips under the sum. At the right, draw a picture of the model and write the equivalent fractions.<br \/>\n\\(\\frac{1}{2}\\) = \\(\\frac{1}{2}\\) \u00d7 \\(\\frac{5}{5}\\) = \\(\\frac{5}{10}\\)<br \/>\n\\(\\frac{2}{5}\\) = \\(\\frac{2}{5}\\) \u00d7 \\(\\frac{2}{2}\\) = \\(\\frac{4}{10}\\)<br \/>\nStep 3:<br \/>\nAdd the fractions with like denominators. Use the 1 whole strip to rename the sum in the simplest form.<br \/>\n\\(\\frac{5}{10}\\) + \\(\\frac{4}{10}\\) = \\(\\frac{9}{10}\\)<br \/>\nThus, \\(\\frac{1}{2}\\) + \\(\\frac{2}{5}\\)\u00a0= \\(\\frac{9}{10}\\)<\/p>\n<h3><a id=\"Investigate_Addition_with_Unlike_Denominators_Page_No_245\"><\/a>Page No. 245<\/h3>\n<p><strong>Use fraction strips to find the sum. Write your answer in simplest form.<\/strong><\/p>\n<p>Question 3.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-3.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators img 3\" width=\"198\" height=\"76\" \/><br \/>\n\\(\\frac{3}{8}+\\frac{1}{4}=\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{5}{8}\\)<br \/>\nExplanation:<br \/>\nStep 1:<br \/>\nPlace three \\(\\frac{1}{8}\\) fractions strips under the 1 whole strip on your Mathboard. Then place a \\(\\frac{1}{4}\\) fraction strip beside the three \\(\\frac{1}{8}\\) strips.<br \/>\nStep 2:<br \/>\nFind fraction strips, all with the same denominator, that are equivalent to \\(\\frac{1}{4}\\) and \\(\\frac{3}{8}\\). Place the fraction strips under the sum. At the right, draw a picture of the model and write the equivalent fractions.<br \/>\n\\(\\frac{1}{4}\\) \u00d7 \\(\\frac{2}{2}\\) = \\(\\frac{2}{8}\\)<br \/>\nStep 3:<br \/>\nAdd the fractions with like denominators. Use the 1 whole strip to rename the sum in the simplest form.<br \/>\n\\(\\frac{2}{8}\\) + \\(\\frac{3}{8}\\) = \\(\\frac{5}{8}\\)<\/p>\n<p>Question 4.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-4.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators img 4\" width=\"213\" height=\"73\" \/><br \/>\n\\(\\frac{3}{4}+\\frac{1}{3}=\\)<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 1 \\(\\frac{1}{12}\\)<br \/>\nExplanation:<br \/>\nStep 1:<br \/>\nPlace three \\(\\frac{3}{4}\\) fractions strips under the 1 whole strip on your Mathboard. Then place a \\(\\frac{1}{3}\\) fraction strip beside the three \\(\\frac{1}{4}\\) strips.<br \/>\nStep 2:<br \/>\nFind fraction strips, all with the same denominator, that are equivalent to \\(\\frac{1}{3}\\) and \\(\\frac{3}{4}\\). Place the fraction strips under the sum. At the right, draw a picture of the model and write the equivalent fractions.<br \/>\n\\(\\frac{1}{3}\\) \u00d7 \\(\\frac{4}{4}\\) = \\(\\frac{4}{12}\\)<br \/>\n\\(\\frac{3}{4}\\) \u00d7 \\(\\frac{3}{3}\\) = \\(\\frac{9}{12}\\)<br \/>\nStep 3:<br \/>\nAdd the fractions with like denominators. Use the 1 whole strip to rename the sum in the simplest form.<br \/>\n\\(\\frac{4}{12}\\) + \\(\\frac{9}{12}\\) = \\(\\frac{13}{12}\\) = 1 \\(\\frac{1}{12}\\)<\/p>\n<p><strong>Use fraction strips to find the sum. Write your answer in simplest form.<\/strong><\/p>\n<p>Question 5.<br \/>\n\\(\\frac{2}{5}+\\frac{3}{10}=\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{7}{10}\\)<br \/>\nExplanation:<br \/>\nStep 1:<br \/>\nPlace three \\(\\frac{1}{10}\\) fractions strips under the 1 whole strip on your Mathboard. Then place a two \\(\\frac{2}{5}\\) fraction strip beside the three \\(\\frac{1}{10}\\) strips.<br \/>\nStep 2:<br \/>\nFind fraction strips, all with the same denominator, that are equivalent to \\(\\frac{2}{5}\\) and \\(\\frac{3}{10}\\). Place the fraction strips under the sum. At the right, draw a picture of the model and write the equivalent fractions.<br \/>\n\\(\\frac{2}{5}\\) \u2022 \\(\\frac{2}{2}\\) = \\(\\frac{4}{10}\\)<br \/>\nStep 3:<br \/>\nAdd the fractions with like denominators. Use the 1 whole strip to rename the sum in the simplest form.<br \/>\n\\(\\frac{4}{10}\\) + \\(\\frac{3}{10}\\) = \\(\\frac{7}{10}\\)<\/p>\n<p>Question 6.<br \/>\n\\(\\frac{1}{4}+\\frac{1}{12}=\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{4}{12}\\)<br \/>\nExplanation:<br \/>\nStep 1:<br \/>\nPlace \\(\\frac{1}{12}\\) fractions strips under the 1 whole strip on your Mathboard. Then place a \\(\\frac{1}{4}\\) fraction strip beside the \\(\\frac{1}{12}\\) strips.<br \/>\nStep 2:<br \/>\nFind fraction strips, all with the same denominator, that are equivalent to \\(\\frac{1}{12}\\) and \\(\\frac{1}{4}\\). Place the fraction strips under the sum. At the right, draw a picture of the model and write the equivalent fractions.<br \/>\n\\(\\frac{1}{4}\\) \u2022 \\(\\frac{3}{3}\\) = \\(\\frac{3}{12}\\)<br \/>\n\\(\\frac{1}{12}\\)<br \/>\nStep 3:<br \/>\nAdd the fractions with like denominators. Use the 1 whole strip to rename the sum in the simplest form.<br \/>\n\\(\\frac{3}{12}\\) + \\(\\frac{1}{12}\\) = \\(\\frac{4}{12}\\)<\/p>\n<p>Question 7.<br \/>\n\\(\\frac{1}{2}+\\frac{3}{10}=\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{8}{10}\\)<br \/>\nExplanation:<br \/>\nStep 1:<br \/>\nPlace three \\(\\frac{1}{10}\\) fractions strips under the 1 whole strip on your Mathboard. Then place a \\(\\frac{1}{2}\\) fraction strip beside the three \\(\\frac{1}{10}\\) strips.<br \/>\nStep 2:<br \/>\nFind fraction strips, all with the same denominator, that are equivalent to \\(\\frac{1}{2}\\) and \\(\\frac{3}{10}\\). Place the fraction strips under the sum. At the right, draw a picture of the model and write the equivalent fractions.<br \/>\n\\(\\frac{1}{2}\\) \u2022 \\(\\frac{5}{5}\\) = \\(\\frac{5}{10}\\)<br \/>\nStep 3:<br \/>\nAdd the fractions with like denominators. Use the 1 whole strip to rename the sum in the simplest form.<br \/>\n\\(\\frac{5}{10}\\) + \\(\\frac{3}{10}\\) = \\(\\frac{8}{10}\\)<\/p>\n<p>Question 8.<br \/>\n\\(\\frac{2}{3}+\\frac{1}{6}=\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{5}{6}\\)<br \/>\nExplanation:<br \/>\nStep 1:<br \/>\nPlace two \\(\\frac{1}{3}\\) fractions strips under the 1 whole strip on your Mathboard. Then place a \\(\\frac{1}{6}\\) fraction strip beside the two \\(\\frac{1}{3}\\) strips.<br \/>\nStep 2:<br \/>\nFind fraction strips, all with the same denominator, that are equivalent to \\(\\frac{1}{6}\\) and \\(\\frac{2}{3}\\). Place the fraction strips under the sum. At the right, draw a picture of the model and write the equivalent fractions.<br \/>\n\\(\\frac{2}{3}\\) = \\(\\frac{2}{3}\\) \u2022 \\(\\frac{2}{2}\\) = \\(\\frac{4}{6}\\)<br \/>\nStep 3:<br \/>\nAdd the fractions with like denominators. Use the 1 whole strip to rename the sum in the simplest form.<br \/>\n\\(\\frac{4}{6}\\) + \\(\\frac{1}{6}\\) = \\(\\frac{5}{6}\\)<\/p>\n<p>Question 9.<br \/>\n\\(\\frac{5}{8}+\\frac{1}{4}=\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{7}{8}\\)<br \/>\nExplanation:<br \/>\nStep 1:<br \/>\nPlace five \\(\\frac{1}{8}\\) fractions strips under the 1 whole strip on your Mathboard. Then place a \\(\\frac{1}{4}\\) fraction strip beside the five \\(\\frac{1}{8}\\) strips.<br \/>\nStep 2:<br \/>\nFind fraction strips, all with the same denominator, that are equivalent to \\(\\frac{1}{4}\\) and \\(\\frac{5}{8}\\). Place the fraction strips under the sum. At the right, draw a picture of the model and write the equivalent fractions.<br \/>\n\\(\\frac{1}{4}\\) \u2022 \\(\\frac{2}{2}\\) = \\(\\frac{2}{8}\\)<br \/>\nStep 3:<br \/>\nAdd the fractions with like denominators. Use the 1 whole strip to rename the sum in the simplest form.<br \/>\n\\(\\frac{2}{8}\\) + \\(\\frac{5}{8}\\) = \\(\\frac{7}{8}\\)<\/p>\n<p>Question 10.<br \/>\n\\(\\frac{1}{2}+\\frac{1}{5}=\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{7}{10}\\)<br \/>\nExplanation:<br \/>\nFind fraction strips, all with the same denominator, that are equivalent to \\(\\frac{1}{5}\\) and \\(\\frac{1}{2}\\). Place the fraction strips under the sum. At the right, draw a picture of the model and write the equivalent fractions.<br \/>\n\\(\\frac{1}{5}\\) \u2022 \\(\\frac{2}{2}\\) = \\(\\frac{2}{10}\\)<br \/>\n\\(\\frac{1}{2}\\) \u2022 \\(\\frac{5}{5}\\) = \\(\\frac{5}{10}\\)<br \/>\nAdd the fractions with like denominators. Use the 1 whole strip to rename the sum in the simplest form.<br \/>\n\\(\\frac{2}{10}\\) + \\(\\frac{5}{10}\\) = \\(\\frac{7}{10}\\)<\/p>\n<p>Question 11.<br \/>\n\\(\\frac{3}{4}+\\frac{1}{6}=\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{11}{12}\\)<br \/>\nExplanation:<br \/>\nFind fraction strips, all with the same denominator, that are equivalent to \\(\\frac{3}{4}\\) and \\(\\frac{1}{6}\\). Place the fraction strips under the sum. At the right, draw a picture of the model and write the equivalent fractions.<br \/>\n\\(\\frac{3}{4}\\) \u2022 \\(\\frac{3}{3}\\) = \\(\\frac{9}{12}\\)<br \/>\n\\(\\frac{1}{6}\\) \u2022 \\(\\frac{2}{2}\\)\u00a0 = \\(\\frac{2}{12}\\)<br \/>\nAdd the fractions with like denominators. Use the 1 whole strip to rename the sum in the simplest form.<br \/>\n\\(\\frac{9}{12}\\) + \\(\\frac{2}{12}\\) = \\(\\frac{11}{12}\\)<\/p>\n<p>Question 12.<br \/>\n\\(\\frac{1}{2}+\\frac{2}{3}=\\)<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 1 \\(\\frac{1}{6}\\)<br \/>\nExplanation:<br \/>\nFind fraction strips, all with the same denominator, that are equivalent to \\(\\frac{2}{3}\\) and \\(\\frac{1}{2}\\). Place the fraction strips under the sum. At the right, draw a picture of the model and write the equivalent fractions.<br \/>\n\\(\\frac{2}{3}\\) \u2022 \\(\\frac{2}{2}\\) = \\(\\frac{4}{6}\\)<br \/>\n\\(\\frac{1}{2}\\) \u2022 \\(\\frac{3}{3}\\) = \\(\\frac{3}{6}\\)<br \/>\nAdd the fractions with like denominators. Use the 1 whole strip to rename the sum in the simplest form.<br \/>\n\\(\\frac{4}{6}\\) + \\(\\frac{3}{6}\\) = \\(\\frac{7}{6}\\)<br \/>\n\\(\\frac{7}{6}\\) is greater than 1.<br \/>\nConvert the fraction into the mixed fraction<br \/>\n\\(\\frac{7}{6}\\) = 1 \\(\\frac{1}{6}\\)<\/p>\n<p>Question 13.<br \/>\n\\(\\frac{7}{8}+\\frac{1}{4}=\\)<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 1 \\(\\frac{1}{8}\\)<br \/>\nExplanation:<br \/>\nFind fraction strips, all with the same denominator, that are equivalent to \\(\\frac{7}{8}\\) and \\(\\frac{1}{4}\\). Place the fraction strips under the sum. At the right, draw a picture of the model and write the equivalent fractions.<br \/>\n\\(\\frac{1}{4}\\) \u2022 \\(\\frac{2}{2}\\) = \\(\\frac{2}{8}\\)<br \/>\nAdd the fractions with like denominators. Use the 1 whole strip to rename the sum in the simplest form.<br \/>\n\\(\\frac{7}{8}\\) + \\(\\frac{2}{8}\\) = \\(\\frac{9}{8}\\)<br \/>\nConvert \\(\\frac{9}{8}\\) into the mixed fraction.<br \/>\n\\(\\frac{9}{8}\\) = 1 \\(\\frac{1}{8}\\)<\/p>\n<p>Question 14.<br \/>\nExplain how using fraction strips with like denominators makes it possible to add fractions with unlike denominators.<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: The strips for both fractions need to be the same size. Finding like denominators is done by trying smaller strips so they can all be the same size.<\/p>\n<h3><a id=\"Problem_Solving_Page_No_246\"><\/a>Problem Solving &#8211; Page No. 246<\/h3>\n<p>Question 15.<br \/>\nMaya makes trail mix by combining \\(\\frac{1}{3}\\) cup of mixed nuts and \\(\\frac{1}{4}\\) cup of dried fruit. What is the total amount of ingredients in her trail mix?<br \/>\n\\(\\frac{1}{3}+\\frac{1}{4}=\\frac{7}{12}\\)<br \/>\nMaya uses \\(\\frac{1}{12}\\) cup of ingredients.<br \/>\nWrite a new problem using different amounts for each ingredient. Each amount should be a fraction with a denominator of 2, 3, or 4. Then use fraction strips to solve your problem.<br \/>\nPose a problem\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 Solve your problem. Draw a picture of the<br \/>\nfraction strips you use to solve the problem.<br \/>\nExplain why you chose the amounts you did for your problem.<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer:<br \/>\n\\(\\frac{1}{3}+\\frac{1}{4}=\\frac{7}{12}\\)<br \/>\nMaya uses \\(\\frac{1}{12}\\) cup of ingredients.<br \/>\nMaya makes trail mix by combining \\(\\frac{1}{2}\\) cup of mixed nuts and \\(\\frac{1}{3}\\) cup of dried fruit and \\(\\frac{1}{4}\\) cup of chocolate morsels. What is the total amount of ingredients in her trail mix?<br \/>\n\\(\\frac{1}{2}\\) + \\(\\frac{1}{3}\\) + \\(\\frac{1}{4}\\) = x<br \/>\n2 \u2022 \\(\\frac{1}{2}\\) + \u00a02 \u2022 \\(\\frac{1}{3}\\) + \u00a02 \u2022 \\(\\frac{1}{4}\\) = \u00a02 \u2022 x<br \/>\n1 + \\(\\frac{2}{3}\\) + \\(\\frac{1}{2}\\) = 2x<br \/>\nNow multiply with 3 on both sides<br \/>\n3 \u2022 1 + 3 \u2022 \\(\\frac{2}{3}\\) + 3 \u2022 \\(\\frac{1}{2}\\) = 3 \u2022 2x<br \/>\n3 + 2 + \\(\\frac{3}{2}\\) = 6x<br \/>\n6 + 4 + 1 = 12 x<br \/>\n11 = 12x<br \/>\nx = \\(\\frac{11}{12}\\)<br \/>\n\\(\\frac{1}{2}\\) + \\(\\frac{1}{3}\\) + \\(\\frac{1}{4}\\) = \\(\\frac{11}{12}\\)<\/p>\n<h3><a id=\"Share_and_Show_Page_No_248\"><\/a>Share and Show &#8211; Page No. 248<\/h3>\n<p><strong>Use fraction strips to find the difference. Write your answer in simplest form.<\/strong><\/p>\n<p>Question 1.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-5.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators img 5\" width=\"203\" height=\"108\" \/><br \/>\n\\(\\frac{7}{10}-\\frac{2}{5}=\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{7}{10}\\) &#8211; \\(\\frac{2}{5}\\)<br \/>\n\\(\\frac{7}{10}\\) &#8211; \\(\\frac{2}{5}\\) \u2022 \\(\\frac{2}{2}\\)<br \/>\n\\(\\frac{7}{10}\\) &#8211; \\(\\frac{4}{10}\\) = \\(\\frac{3}{10}\\)<\/p>\n<p>Question 2.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-6.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators img 6\" width=\"197\" height=\"106\" \/><br \/>\n\\(\\frac{2}{3}-\\frac{1}{4}=\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{2}{3}\\) &#8211; \\(\\frac{1}{4}\\)<br \/>\nNow we have to make the fractions like denominators<br \/>\n\\(\\frac{2}{3}\\) \u2022 \\(\\frac{4}{4}\\) &#8211; \\(\\frac{1}{4}\\) \u2022 \\(\\frac{3}{3}\\)<br \/>\n\\(\\frac{8}{12}\\) &#8211; \\(\\frac{3}{12}\\) = \\(\\frac{5}{12}\\)<\/p>\n<h3><a id=\"Investigate_Subtraction_with_Unlike_Denominators_Page_No_249\"><\/a>Page No. 249<\/h3>\n<p><strong>Use fraction strips to find the difference. Write your answer in simplest form.<\/strong><\/p>\n<p>Question 3.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-7.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators img 7\" width=\"192\" height=\"102\" \/><br \/>\n\\(\\frac{5}{6}-\\frac{1}{4}=\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\nStep 1:<br \/>\nFind fraction strips, all with the same denominator, that fit exactly under the difference \\(\\frac{5}{6}-\\frac{1}{4}\\)<br \/>\nStep 2:<br \/>\nFind another set of fraction strips, all with the same the denominator, that fit exactly under the difference \\(\\frac{5}{6}-\\frac{1}{4}\\)<br \/>\nStep 3:<br \/>\nFind other fraction strips, all with the same denominator, that fit exactly under the difference \\(\\frac{5}{6}-\\frac{1}{4}\\)<br \/>\n\\(\\frac{5}{6}\\) \u2022 \\(\\frac{4}{4}\\) &#8211; \\(\\frac{1}{4}\\) \u2022 \\(\\frac{6}{6}\\)<br \/>\n\\(\\frac{20}{24}\\) &#8211; \\(\\frac{6}{24}\\) = \\(\\frac{14}{24}\\) = \\(\\frac{7}{12}\\)<br \/>\nThus, \\(\\frac{5}{6}-\\frac{1}{4}\\) = \\(\\frac{7}{12}\\)<\/p>\n<p>Question 4.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-8.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators img 8\" width=\"202\" height=\"105\" \/><br \/>\n\\(\\frac{1}{2}-\\frac{3}{10}=\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{1}{2}-\\frac{3}{10}\\)<br \/>\n\\(\\frac{1}{2}\\) \u2022 \\(\\frac{5}{5}\\) &#8211; \\(\\frac{3}{10}\\)<br \/>\n\\(\\frac{5}{10}\\) &#8211; \\(\\frac{3}{10}\\) = \\(\\frac{2}{10}\\)<\/p>\n<p>Question 5.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-9.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators img 9\" width=\"193\" height=\"106\" \/><br \/>\n\\(\\frac{3}{8}-\\frac{1}{4}=\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{3}{8}-\\frac{1}{4}\\)<br \/>\n\\(\\frac{3}{8}\\) &#8211; \\(\\frac{1}{4}\\) \u2022 \\(\\frac{2}{2}\\)<br \/>\n= \\(\\frac{3}{8}\\) &#8211; \\(\\frac{2}{8}\\) = \\(\\frac{1}{8}\\)<\/p>\n<p>Question 6.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-10.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators img 10\" width=\"196\" height=\"106\" \/><br \/>\n\\(\\frac{2}{3}-\\frac{1}{2}=\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{2}{3}-\\frac{1}{2}\\)<br \/>\n\\(\\frac{2}{3}\\) \u2022 \\(\\frac{2}{2}\\) &#8211; \\(\\frac{1}{2}\\) \u2022 \\(\\frac{3}{3}\\)<br \/>\n\\(\\frac{4}{6}-\\frac{3}{6}\\) = \\(\\frac{1}{6}\\)<\/p>\n<p><strong>Use fraction strips to find the difference. Write your answer in simplest form.<\/strong><\/p>\n<p>Question 7.<br \/>\n\\(\\frac{3}{5}-\\frac{3}{10}=\\) \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{3}{5}-\\frac{3}{10}\\)<br \/>\n\\(\\frac{3}{5}\\) \u2022 \\(\\frac{2}{2}\\) &#8211; \\(\\frac{3}{10}\\)<br \/>\n= \\(\\frac{6}{10}\\) &#8211; \\(\\frac{3}{10}\\) = \\(\\frac{3}{10}\\)<\/p>\n<p>Question 8.<br \/>\n\\(\\frac{5}{12}-\\frac{1}{3}=\\) \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{5}{12}-\\frac{1}{3}\\)<br \/>\nMake the denominators equal and then subtract the subtract the fraction with lide denominators.<br \/>\n\\(\\frac{5}{12}\\) &#8211; \\(\\frac{1}{3}\\) \u2022 \\(\\frac{4}{4}\\)<br \/>\n\\(\\frac{5}{12}\\) &#8211; \\(\\frac{4}{12}\\) = \\(\\frac{1}{12}\\)<\/p>\n<p>Question 9.<br \/>\n\\(\\frac{1}{2}-\\frac{1}{10}=\\) \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{1}{2}-\\frac{1}{10}\\)<br \/>\nMake the denominators equal and then subtract the subtract the fraction with lide denominators.<br \/>\n\\(\\frac{1}{2}\\) \u2022 \\(\\frac{5}{5}\\) &#8211; \\(\\frac{1}{10}\\)<br \/>\n\\(\\frac{5}{10}\\) &#8211; \\(\\frac{1}{10}\\) = \\(\\frac{4}{10}\\)<\/p>\n<p>Question 10.<br \/>\n\\(\\frac{3}{5}-\\frac{1}{2}=\\) \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{3}{5}-\\frac{1}{2}\\)<br \/>\nMake the denominators equal and then subtract the subtract the fraction with lide denominators.<br \/>\n\\(\\frac{3}{5}\\) \u2022 \\(\\frac{2}{2}\\) &#8211; \\(\\frac{1}{2}\\) \u2022 \\(\\frac{5}{5}\\)<br \/>\n\\(\\frac{6}{10}-\\frac{5}{10}\\) = \\(\\frac{1}{10}\\)<\/p>\n<p>Question 11.<br \/>\n\\(\\frac{7}{8}-\\frac{1}{4}=\\) \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{7}{8}-\\frac{1}{4}\\)<br \/>\nMake the denominators equal and then subtract the subtract the fraction with lide denominators.<br \/>\n\\(\\frac{7}{8}\\) &#8211; \\(\\frac{1}{4}\\) \u2022 \\(\\frac{2}{2}\\)<br \/>\n\\(\\frac{7}{8}\\) &#8211; \\(\\frac{2}{8}\\) = \\(\\frac{5}{8}\\)<\/p>\n<p>Question 12.<br \/>\n\\(\\frac{5}{6}-\\frac{2}{3}=\\) \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{5}{6}-\\frac{2}{3}\\)<br \/>\nMake the denominators equal and then subtract the subtract the fraction with lide denominators.<br \/>\n\\(\\frac{5}{6}\\) &#8211; \\(\\frac{2}{3}\\) \u2022 \\(\\frac{2}{2}\\)<br \/>\n\\(\\frac{5}{6}\\) &#8211; \\(\\frac{4}{6}\\)<br \/>\n\\(\\frac{1}{6}\\)<\/p>\n<p>Question 13.<br \/>\n\\(\\frac{3}{4}-\\frac{1}{3}=\\) \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{3}{4}-\\frac{1}{3}\\)<br \/>\n\\(\\frac{3}{4}\\) \u2022 \\(\\frac{3}{3}\\) &#8211; \\(\\frac{1}{3}\\) \u2022 \\(\\frac{4}{4}\\)<br \/>\n\\(\\frac{9}{12}\\) &#8211; \\(\\frac{4}{12}\\) = \\(\\frac{5}{12}\\)<\/p>\n<p>Question 14.<br \/>\n\\(\\frac{5}{6}-\\frac{1}{2}=\\) \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{5}{6}-\\frac{1}{2}\\)<br \/>\n\\(\\frac{5}{6}\\) &#8211; \\(\\frac{1}{2}\\) \u2022 \\(\\frac{3}{3}\\)<br \/>\n\\(\\frac{5}{6}\\) &#8211; \\(\\frac{3}{6}\\) = \\(\\frac{2}{6}\\)<br \/>\n\\(\\frac{5}{6}-\\frac{1}{2}=\\) \\(\\frac{2}{6}\\)<\/p>\n<p>Question 15.<br \/>\n\\(\\frac{3}{4}-\\frac{7}{12}=\\) \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{3}{4}-\\frac{7}{12}\\)<br \/>\n\\(\\frac{3}{4}\\) \u2022 \\(\\frac{3}{3}\\) &#8211; \\(\\frac{7}{12}\\)<br \/>\n\\(\\frac{9}{12}\\) &#8211; \\(\\frac{7}{12}\\) = \\(\\frac{2}{12}\\)<br \/>\n\\(\\frac{3}{4}-\\frac{7}{12}=\\) \\(\\frac{2}{12}\\)<\/p>\n<p>Question 16.<br \/>\nExplain how your model for \\(\\frac{3}{5}-\\frac{1}{2}\\) is different from your model for \\(\\frac{3}{5}-\\frac{3}{10}\\).<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer:<br \/>\n\\(\\frac{3}{5}-\\frac{3}{10}\\)<br \/>\n\\(\\frac{3}{5}\\) \u2022 \\(\\frac{2}{2}\\) &#8211; \\(\\frac{3}{10}\\)<br \/>\n\\(\\frac{6}{10}\\) &#8211; \\(\\frac{3}{10}\\) = \\(\\frac{3}{10}\\)<\/p>\n<h3><a id=\"UNLOCK_the_Problem_Page_No_250\"><\/a>UNLOCK the Problem &#8211; Page No. 250<\/h3>\n<p>Question 17.<br \/>\nThe picture at the right shows how much pizza was left over from lunch. Jason eats \\(\\frac{1}{4}\\) of the whole pizza for dinner. Which subtraction sentence represents the amount of pizza that is remaining after dinner?<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-11.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators img 11\" width=\"131\" height=\"130\" \/><br \/>\na. What problem are you being asked to solve?<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: I am asked to solve which subtraction sentence represents the amount of pizza that is remaining after dinner.<\/p>\n<p>Question 17.<br \/>\nb. How will you use the diagram to solve the problem?<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: I will use number of slices left in the pizza to solve the problem.<\/p>\n<p>Question 17.<br \/>\nc. Jason eats \\(\\frac{1}{4}\\) of the whole pizza. How many slices does he eat?<br \/>\n______ slices<\/p>\n<p>Answer: 2 slices<\/p>\n<p>Explanation:<br \/>\nGiven that, Jason eats \\(\\frac{1}{4}\\) of the whole pizza.<br \/>\nThe pizza is cut into 8 slices.<br \/>\nSo, 8 \u00d7 \\(\\frac{1}{4}\\) = 2 slices.<br \/>\nThus Jason ate 2 slices.<\/p>\n<p>Question 17.<br \/>\nd. Redraw the diagram of the pizza. Shade the sections of pizza that are remaining after Jason eats his dinner.<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Question 17.<br \/>\ne. Write a fraction to represent the amount of pizza that is remaining.<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\) of a pizza<\/p>\n<p>Answer: \\(\\frac{3}{8}\\) of a pizza<\/p>\n<p>Explanation:<br \/>\nThe fraction of pizzz Jason ate = \\(\\frac{1}{4}\\)<br \/>\nNumber of slices left = \\(\\frac{5}{8}\\)<br \/>\nNow subtract \\(\\frac{5}{8}\\) &#8211; \\(\\frac{1}{4}\\)<br \/>\n= \\(\\frac{3}{8}\\)<br \/>\nThus the fraction to represent the amount of pizza that is remaining is \\(\\frac{3}{8}\\)<\/p>\n<p>Question 17.<br \/>\nf. Fill in the bubble for the correct answer choice above.<br \/>\nOptions:<br \/>\na. 1 &#8211; \\(\\frac{1}{4}\\) = \\(\\frac{3}{4}\\)<br \/>\nb. \\(\\frac{5}{8}\\) &#8211; \\(\\frac{1}{4}\\) = \\(\\frac{3}{8}\\)<br \/>\nc. \\(\\frac{3}{8}\\) &#8211; \\(\\frac{1}{4}\\) = \\(\\frac{2}{8}\\)<br \/>\nd. 1 &#8211; \\(\\frac{3}{8}\\) = \\(\\frac{5}{8}\\)<\/p>\n<p>Answer: B<br \/>\nThe fraction of pizzz Jason ate = \\(\\frac{1}{4}\\)<br \/>\nNumber of slices left = \\(\\frac{5}{8}\\)<br \/>\nNow subtract \\(\\frac{5}{8}\\) &#8211; \\(\\frac{1}{4}\\) = \\(\\frac{3}{8}\\)<br \/>\nThus the correct answer is option B.<\/p>\n<p>Question 18.<br \/>\nThe diagram shows what Tina had left from a yard of fabric. She now uses \\(\\frac{2}{3}\\) yard of fabric for a project. How much of the original yard of fabric does Tina have left after the project?<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-12.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators img 12\" width=\"290\" height=\"33\" \/><br \/>\nOptions:<br \/>\na. \\(\\frac{2}{3}\\) yard<br \/>\nb. \\(\\frac{1}{2}\\) yard<br \/>\nc. \\(\\frac{1}{3}\\) yard<br \/>\nd. \\(\\frac{1}{6}\\) yard<\/p>\n<p>Answer: \\(\\frac{1}{3}\\) yard<\/p>\n<p>Explanation:<br \/>\nThe original yard of fabric is 6<br \/>\nTina uses \\(\\frac{2}{3}\\) yard of fabric for a project.<br \/>\n\\(\\frac{1}{1}\\) &#8211; \\(\\frac{2}{3}\\)<br \/>\n\\(\\frac{3}{3}\\) &#8211; \\(\\frac{2}{3}\\) = \\(\\frac{1}{3}\\) yard<\/p>\n<h3><a id=\"Share_and_Show_Page_No_253\"><\/a>Share and Show &#8211; Page No. 253<\/h3>\n<p><strong>Estimate the sum or difference.<\/strong><\/p>\n<p>Question 1.<br \/>\n\\(\\frac{5}{6}+\\frac{3}{8}\\)<br \/>\na. Round \\(\\frac{5}{6}\\) to its closest benchmark. ____<br \/>\nb. Round \\(\\frac{3}{8}\\) to its closest benchmark. ____<br \/>\nc. Add to find the estimate. ____ + ____ = ____<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\na. Round \\(\\frac{5}{6}\\) to its closest benchmark.<span style=\"text-decoration: underline;\"> \\(\\frac{6}{6}\\) or 1.<\/span><br \/>\nb. Round \\(\\frac{3}{8}\\) to its closest benchmark. \\(\\frac{4}{8}\\) or \\(\\frac{1}{2}\\)<br \/>\nc. Add to find the estimate. ____ + ____ = ____<br \/>\n1 + \\(\\frac{1}{2}\\) = \\(\\frac{3}{2}\\) = 1 \\(\\frac{1}{2}\\)<\/p>\n<p>Question 2.<br \/>\n\\(\\frac{5}{9}-\\frac{3}{8}\\)<br \/>\n_____<\/p>\n<p>Answer: 0<\/p>\n<p>Explanation:<br \/>\nStep 1: Place a point at \\(\\frac{5}{9}\\) on the number line.<br \/>\nThe fraction is between 0 and \\(\\frac{1}{2}\\).<br \/>\nThe fraction rounded to \\(\\frac{5}{9}\\) is \\(\\frac{1}{2}\\)<br \/>\nStep 2: Place a point at \\(\\frac{3}{8}\\) on the number line.<br \/>\nThe fraction is between 0 and \\(\\frac{1}{2}\\).<br \/>\nThe fraction rounded to \\(\\frac{3}{8}\\) is \\(\\frac{1}{2}\\).<br \/>\n\\(\\frac{1}{2}\\) &#8211; \\(\\frac{1}{2}\\) = 0<\/p>\n<p>Question 3.<br \/>\n\\(\\frac{6}{7}+2 \\frac{4}{5}\\)<br \/>\n_____<\/p>\n<p>Answer: 4<\/p>\n<p>Explanation:<br \/>\nStep 1: Place a point at \\(\\frac{6}{7}\\) on the number line.<br \/>\nThe fraction is between \\(\\frac{1}{2}\\) and 1.<br \/>\nStep 2: Place a point at \\(\\frac{4}{5}\\) on the number line.<br \/>\nThe fraction is between \\(\\frac{1}{2}\\) and 1.<br \/>\n1 + 3 = 4<\/p>\n<p>Question 4.<br \/>\n\\(\\frac{5}{6}+\\frac{2}{5}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 1 \\(\\frac{1}{2}\\)<\/p>\n<p>Explanation:<br \/>\nStep 1: Place a point at \\(\\frac{5}{6}\\) on the number line.<br \/>\nThe fraction is between \\(\\frac{1}{2}\\) and 1.<br \/>\nStep 2: Place a point at \\(\\frac{2}{5}\\) on the number line.<br \/>\nThe fraction is between 0 and \\(\\frac{1}{2}\\).<br \/>\n1 + \\(\\frac{1}{2}\\) = \\(\\frac{3}{2}\\) = 1 \\(\\frac{1}{2}\\)<\/p>\n<p>Question 5.<br \/>\n\\(3 \\frac{9}{10}-1 \\frac{2}{9}\\)<br \/>\n_____<\/p>\n<p>Answer: 3<\/p>\n<p>Explanation:<\/p>\n<p>Step 1: Place a point at \\(\\frac{9}{10}\\) on the number line.<br \/>\nThe fraction is between \\(\\frac{1}{2}\\) and 1.<br \/>\nStep 2: Place a point at \\(\\frac{2}{9}\\) on the number line.<br \/>\nThe fraction is between 0 and \\(\\frac{1}{2}\\).<br \/>\n3 \u00d7 1 &#8211; 1 \u00d7 0 = 3 &#8211; 0 = 3<br \/>\n\\(3 \\frac{9}{10}-1 \\frac{2}{9}\\) = 3<\/p>\n<p>Question 6.<br \/>\n\\(\\frac{4}{6}+\\frac{1}{9}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{1}{2}\\)<\/p>\n<p>Explanation:<\/p>\n<p>Step 1: Place a point at \\(\\frac{4}{6}\\) on the number line.<br \/>\nThe fraction is between \\(\\frac{1}{2}\\) and 1.<br \/>\nStep 2: Place a point at \\(\\frac{1}{9}\\) on the number line.<br \/>\nThe fraction is between 0 and \\(\\frac{1}{2}\\).<br \/>\nSo, \\(\\frac{1}{2}\\) + 0 = \\(\\frac{1}{2}\\)<br \/>\n\\(\\frac{4}{6}+\\frac{1}{9}\\) = \\(\\frac{1}{2}\\)<\/p>\n<p>Question 7.<br \/>\n\\(\\frac{9}{10}-\\frac{1}{9}\\)<br \/>\n_____<\/p>\n<p>Answer: 1<\/p>\n<p>Explanation:<br \/>\nStep 1: Place a point at \\(\\frac{9}{10}\\) on the number line.<br \/>\nThe fraction is between \\(\\frac{1}{2}\\) and 1.<br \/>\nStep 2: Place a point at \\(\\frac{1}{9}\\) on the number line.<br \/>\nThe fraction is between 0 and \\(\\frac{1}{2}\\).<br \/>\n1 &#8211; 0 = 1<br \/>\n\\(\\frac{9}{10}-\\frac{1}{9}\\) = 1<\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>Estimate the sum or difference.<\/strong><\/p>\n<p>Question 8.<br \/>\n\\(\\frac{5}{8}-\\frac{1}{5}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{1}{2}\\)<\/p>\n<p>Explanation:<br \/>\nStep 1: Place a point at \\(\\frac{5}{8}\\) on the number line.<br \/>\nThe fraction is between \\(\\frac{1}{2}\\) and 1.<br \/>\nStep 2: Place a point at \\(\\frac{1}{5}\\) on the number line.<br \/>\nThe fraction is between 0 and \\(\\frac{1}{2}\\).<br \/>\n1 &#8211; \\(\\frac{1}{2}\\) = \\(\\frac{1}{2}\\)<\/p>\n<p>Question 9.<br \/>\n\\(\\frac{1}{6}+\\frac{3}{8}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{1}{2}\\)<\/p>\n<p>Explanation:<br \/>\nStep 1: Place a point at \\(\\frac{1}{6}\\) on the number line.<br \/>\nThe fraction is between 0 and \\(\\frac{1}{2}\\)<br \/>\nStep 2: Place a point at \\(\\frac{3}{8}\\) on the number line.<br \/>\nThe fraction is between 0 and \\(\\frac{1}{2}\\)<br \/>\n0 + \\(\\frac{1}{2}\\) = \\(\\frac{1}{2}\\)<\/p>\n<p>Question 10.<br \/>\n\\(\\frac{6}{7}-\\frac{1}{5}\\)<br \/>\n_____<\/p>\n<p>Answer: 1<\/p>\n<p>Explanation:<br \/>\nStep 1: Place a point at \\(\\frac{6}{7}\\) on the number line.<br \/>\nThe fraction is between \\(\\frac{1}{2}\\) and 1.<br \/>\nStep 2: Place a point at \\(\\frac{1}{5}\\) on the number line.<br \/>\nThe fraction is between 0 and \\(\\frac{1}{2}\\)<br \/>\n1 &#8211; 0 = 1<br \/>\n\\(\\frac{6}{7}-\\frac{1}{5}\\) = 1<\/p>\n<p>Question 11.<br \/>\n\\(\\frac{11}{12}+\\frac{6}{10}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 1 \\(\\frac{1}{2}\\)<\/p>\n<p>Explanation:<br \/>\nStep 1: Place a point at \\(\\frac{11}{12}\\) on the number line.<br \/>\nThe fraction is between \\(\\frac{1}{2}\\) and 1<br \/>\nStep 2: Place a point at \\(\\frac{6}{10}\\) on the number line.<br \/>\nThe fraction is between \\(\\frac{1}{2}\\) and 1<br \/>\n1 + \\(\\frac{1}{2}\\) = \\(\\frac{3}{2}\\) = 1 \\(\\frac{1}{2}\\)<br \/>\n\\(\\frac{11}{12}+\\frac{6}{10}\\) = 1 \\(\\frac{1}{2}\\)<\/p>\n<p>Question 12.<br \/>\n\\(\\frac{9}{10}-\\frac{1}{2}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{1}{2}\\)<\/p>\n<p>Explanation:<br \/>\nStep 1: Place a point at \\(\\frac{9}{10}\\) on the number line.<br \/>\nThe fraction is between \\(\\frac{1}{2}\\) and 1.<br \/>\nStep 2: Place a point at \\(\\frac{1}{2}\\) on the number line.<br \/>\nThe fraction is between 0 and \\(\\frac{1}{2}\\)<br \/>\n1 &#8211; \\(\\frac{1}{2}\\) = \\(\\frac{1}{2}\\)<br \/>\n\\(\\frac{9}{10}-\\frac{1}{2}\\) = \\(\\frac{1}{2}\\)<\/p>\n<p>Question 13.<br \/>\n\\(\\frac{3}{6}+\\frac{4}{5}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 1 \\(\\frac{1}{2}\\)<\/p>\n<p>Explanation:<br \/>\nStep 1: Place a point at \\(\\frac{3}{6}\\) on the number line.<br \/>\nThe fraction is between 0 and \\(\\frac{1}{2}\\)<br \/>\nStep 2: Place a point at \\(\\frac{4}{5}\\) on the number line.<br \/>\nThe fraction is between \\(\\frac{1}{2}\\) and 1<br \/>\n\\(\\frac{1}{2}\\) + 1 = \\(\\frac{3}{2}\\) = 1 \\(\\frac{1}{2}\\)<br \/>\n\\(\\frac{3}{6}+\\frac{4}{5}\\) = 1 \\(\\frac{1}{2}\\)<\/p>\n<p>Question 14.<br \/>\n\\(\\frac{5}{6}-\\frac{3}{8}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{1}{2}\\)<\/p>\n<p>Explanation:<br \/>\nStep 1: Place a point at \\(\\frac{5}{6}\\) on the number line.<br \/>\nThe fraction is between \\(\\frac{1}{2}\\) and 1.<br \/>\nStep 2: Place a point at \\(\\frac{3}{8}\\) on the number line.<br \/>\nThe fraction is between 0 and \\(\\frac{1}{2}\\)<br \/>\n1 &#8211; \\(\\frac{1}{2}\\) = \\(\\frac{1}{2}\\)<br \/>\n\\(\\frac{5}{6}-\\frac{3}{8}\\) = \\(\\frac{1}{2}\\)<\/p>\n<p>Question 15.<br \/>\n\\(\\frac{1}{7}+\\frac{8}{9}\\)<br \/>\n_____<\/p>\n<p>Answer: 1<\/p>\n<p>Explanation:<br \/>\nStep 1: Place a point at \\(\\frac{1}{7}\\) on the number line.<br \/>\nThe fraction is between 0 and \\(\\frac{1}{2}\\)<br \/>\nStep 2: Place a point at \\(\\frac{8}{9}\\) on the number line.<br \/>\nThe fraction is between \\(\\frac{1}{2}\\) and 1.<br \/>\n0 + 1 = 1<br \/>\n\\(\\frac{1}{7}+\\frac{8}{9}\\) = 1<\/p>\n<p>Question 16.<br \/>\n\\(3 \\frac{5}{12}-3 \\frac{1}{10}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{1}{2}\\)<\/p>\n<p>Explanation:<br \/>\nStep 1: Place a point at \\(\\frac{5}{12}\\) on the number line.<br \/>\nThe fraction is between 0 and \\(\\frac{1}{2}\\)<br \/>\nStep 2: Place a point at \\(\\frac{1}{10}\\) on the number line.<br \/>\nThe fraction is between 0 and \\(\\frac{1}{2}\\)<br \/>\n\\(\\frac{1}{2}\\) &#8211; 0 = \\(\\frac{1}{2}\\)<br \/>\n\\(3 \\frac{5}{12}-3 \\frac{1}{10}\\) = \\(\\frac{1}{2}\\)<\/p>\n<h3><a id=\"Problem_Solving_Page_No_254\"><\/a>Problem Solving &#8211; Page No. 254<\/h3>\n<p>Question 17.<br \/>\nLisa and Valerie are picnicking in Trough Creek State Park in Pennsylvania. Lisa has brought a salad that she made with \\(\\frac{3}{4}\\) cup of strawberries, \\(\\frac{7}{8}\\) cup of peaches, and \\(\\frac{1}{6}\\) cup of blueberries. About how many total cups of fruit are in the salad?<br \/>\n_____ cups<\/p>\n<p>Answer: 2 cups<\/p>\n<p>Explanation:<br \/>\nLisa and Valerie are picnicking in Trough Creek State Park in Pennsylvania.<br \/>\nLisa has brought a salad that she made with \\(\\frac{3}{4}\\) cup of strawberries, \\(\\frac{7}{8}\\) cup of peaches, and \\(\\frac{1}{6}\\) cup of blueberries.<br \/>\nStep 1: Place \\(\\frac{3}{4}\\) on the number line.<br \/>\nThe fraction is between \\(\\frac{1}{2}\\) and 1.<br \/>\nStep 2: Place \\(\\frac{7}{8}\\) on the number line.<br \/>\nThe fraction is between \\(\\frac{1}{2}\\) and 1.<br \/>\nStep 3: Place \\(\\frac{1}{6}\\) on the number line.<br \/>\nThe fraction is between 0 and \\(\\frac{1}{2}\\).<br \/>\n1 + 1 + 0 = 2<br \/>\nThus 2 cups of fruit are in the salad.<\/p>\n<p>Question 18.<br \/>\nAt Trace State Park in Mississippi, there is a 25-mile mountain bike trail. If Tommy rode \\(\\frac{1}{2}\\) of the trail on Saturday and \\(\\frac{1}{5}\\) of the trail on Sunday, about what fraction of the trail did he ride?<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{1}{2}\\)<\/p>\n<p>Explanation:<br \/>\nAt Trace State Park in Mississippi, there is a 25-mile mountain bike trail.<br \/>\nIf Tommy rode \\(\\frac{1}{2}\\) of the trail on Saturday and \\(\\frac{1}{5}\\) of the trail on Sunday<br \/>\nStep 1: Place \\(\\frac{1}{2}\\) on the number line.<br \/>\n\\(\\frac{1}{2}\\) lies between 0 and \\(\\frac{1}{2}\\)<br \/>\nStep 2: Place \\(\\frac{1}{5}\\) on the number line.<br \/>\n\\(\\frac{1}{5}\\) 0 and \\(\\frac{1}{2}\\)<br \/>\nThe number closer to \\(\\frac{1}{5}\\) is 0<br \/>\n\\(\\frac{1}{2}\\) &#8211; 0 = \\(\\frac{1}{2}\\)<br \/>\nThe estimated fraction of the trail he ride is \\(\\frac{1}{2}\\)<\/p>\n<p>Question 19.<br \/>\nExplain how you know that \\(\\frac{5}{8}+\\frac{6}{10}\\) is greater than 1.<br \/>\nType below:<br \/>\n__________<\/p>\n<p>Answer:<br \/>\nStep 1: Place \\(\\frac{5}{8}\\) on the number line.<br \/>\n\\(\\frac{5}{8}\\) is closer to \\(\\frac{1}{2}\\)<br \/>\nStep 2: Place \\(\\frac{6}{10}\\) on the number line.<br \/>\n\\(\\frac{6}{10}\\) lies between \\(\\frac{1}{2}\\) and 1.<br \/>\n\\(\\frac{6}{10}\\) is closer to \\(\\frac{1}{2}\\)<br \/>\n\\(\\frac{1}{2}\\) + \\(\\frac{1}{2}\\) = 1<\/p>\n<p>Question 20.<br \/>\nNick estimated that \\(\\frac{5}{8}+\\frac{4}{7}\\) is about 2.<br \/>\nExplain how you know his estimate is not reasonable.<br \/>\nType below:<br \/>\n__________<\/p>\n<p>Answer:<br \/>\nStep 1: Place \\(\\frac{5}{8}\\) on the number line.<br \/>\n\\(\\frac{5}{8}\\) is closer to \\(\\frac{1}{2}\\)<br \/>\nStep 2: Place \\(\\frac{4}{7}\\) on the number line.<br \/>\n\\(\\frac{4}{7}\\) lies between \\(\\frac{1}{2}\\) and 1.<br \/>\n\\(\\frac{1}{2}\\) + \\(\\frac{1}{2}\\) = 1<br \/>\nBy this, we can say that Nick&#8217;s estimation was wrong.<\/p>\n<p>Question 21.<br \/>\nTest Prep Jake added \\(\\frac{1}{8}\\) cup of sunflower seeds and \\(\\frac{4}{5}\\) cup of banana chips to his sundae. Which is the best estimate of the total amount of toppings Jake added to his sundae?<br \/>\nOptions:<br \/>\na. about \\(\\frac{1}{2}\\) cup<br \/>\nb. about 1 cup<br \/>\nc. about 1 \\(\\frac{1}{2}\\) cups<br \/>\nd. about 2 cups<\/p>\n<p>Answer: about 1 cup<\/p>\n<p>Explanation:<br \/>\nGiven, Test Prep Jake added \\(\\frac{1}{8}\\) cup of sunflower seeds and \\(\\frac{4}{5}\\) cup of banana chips to his sundae<br \/>\nStep 1: Place \\(\\frac{1}{8}\\) on the number line.<br \/>\n\\(\\frac{1}{8}\\) lies between 0 and \\(\\frac{1}{2}\\)<br \/>\nStep 2: Place \\(\\frac{4}{5}\\) on the number line.<br \/>\n\\(\\frac{4}{5}\\) lies between \\(\\frac{1}{2}\\) and 1.<br \/>\n0 + 1 = 1<br \/>\nThe best estimate of the total amount of toppings Jake added to his sundae is about 1 cup.<\/p>\n<h3><a id=\"Share_and_Show_Page_No_256\"><\/a>Share and Show &#8211; Page No. 256<\/h3>\n<p>Question 1.<br \/>\nFind a common denominator of \\(\\frac{1}{6}\\) and \\(\\frac{1}{9}\\) . Rewrite the pair of fractions using the common denominator.<br \/>\n\u2022 Multiply the denominators.<br \/>\nA common denominator of \\(\\frac{1}{6}\\) and \\(\\frac{1}{9}\\) is ____.<br \/>\n\u2022 Rewrite the pair of fractions using the common denominator.<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer:<br \/>\nCommon denominator is 18.<br \/>\n\\(\\frac{1}{6}\\) \u00d7 \\(\\frac{3}{3}\\) = \\(\\frac{3}{18}\\)<br \/>\n\\(\\frac{1}{9}\\) \u00d7 \\(\\frac{2}{2}\\) = \\(\\frac{2}{18}\\)<br \/>\nThe pair of fractions using the common denominator is \\(\\frac{3}{18}\\), \\(\\frac{2}{18}\\)<\/p>\n<p><strong>Use a common denominator to write an equivalent fraction for each fraction.<\/strong><\/p>\n<p>Question 2.<br \/>\n\\(\\frac{1}{3}, \\frac{1}{5}\\)<br \/>\ncommon denominator: _________<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: 15<\/p>\n<p>Explanation:<br \/>\nMultiply the denominators of the fraction.<br \/>\n\\(\\frac{1}{3}\\) \u00d7 \\(\\frac{1}{5}\\) = \\(\\frac{1}{15}\\)<br \/>\nThus the common denominator is 15.<\/p>\n<p>Question 3.<br \/>\n\\(\\frac{2}{3}, \\frac{5}{9}\\)<br \/>\ncommon denominator: _________<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: 27<\/p>\n<p>Explanation:<br \/>\nMultiply the denominators<br \/>\n\\(\\frac{2}{3}\\) \u00d7 \\(\\frac{5}{9}\\)<br \/>\n= 3 \u00d7 9 = 27<br \/>\nThus the common denominator of \\(\\frac{2}{3}, \\frac{5}{9}\\) is 27.<\/p>\n<p>Question 4.<br \/>\n\\(\\frac{2}{9}, \\frac{1}{15}\\)<br \/>\ncommon denominator: _________<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: 45<\/p>\n<p>Explanation:<br \/>\nMultiply the denominators<br \/>\n\\(\\frac{2}{9}\\) \u00d7 \\(\\frac{1}{15}\\)<br \/>\nThe least common denominator of 15 and 9 is 45.<br \/>\nSo, the common denominator of \\(\\frac{2}{9}, \\frac{1}{15}\\) is 45.<\/p>\n<h3><a id=\"Common_Denominators_and_Equivalent_Fractions_Page_No_257\"><\/a>Page No. 257<\/h3>\n<p><strong>Use the least common denominator to write an equivalent fraction for each fraction.<\/strong><\/p>\n<p>Question 5.<br \/>\n\\(\\frac{1}{4}, \\frac{3}{8}\\)<br \/>\nleast common denominator: ______<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: 8<\/p>\n<p>Explanation:<\/p>\n<p>First multiply the denominators of the fractions \\(\\frac{1}{4}, \\frac{3}{8}\\)<br \/>\n4 \u00d7 8 = 32<br \/>\nThe least common denominator is 8<br \/>\nThe equivalent fractions with LCD<br \/>\n\\(\\frac{1}{4}\\) = \\(\\frac{2}{8}\\)<br \/>\n\\(\\frac{3}{8}\\) = \\(\\frac{3}{8}\\)<\/p>\n<p>Question 6.<br \/>\n\\(\\frac{11}{12}, \\frac{5}{8}\\)<br \/>\nleast common denominator: ______<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: 24<\/p>\n<p>Explanation:<br \/>\nFirst, multiply the denominators of the fractions.<br \/>\n12 \u00d7 8 = 96<br \/>\nThe least common denominator of 12 and 8 is 24.<br \/>\nThe equivalent fractions with LCD<br \/>\n\\(\\frac{11}{12}\\) \u00d7 \\(\\frac{2}{2}\\)= \\(\\frac{22}{24}\\)<br \/>\n\\(\\frac{5}{8}\\) \u00d7 \\(\\frac{3}{3}\\) = \\(\\frac{15}{24}\\)<\/p>\n<p>Question 7.<br \/>\n\\(\\frac{4}{5}, \\frac{1}{6}\\)<br \/>\nleast common denominator: ______<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: 30<\/p>\n<p>Explanation:<br \/>\nFirst, multiply the denominators of the fractions.<br \/>\n5 \u00d7 6 = 30<br \/>\nThe least common denominator (LCD) = 30<br \/>\n\\(\\frac{4}{5}\\) \u00d7 \\(\\frac{6}{6}\\)= \\(\\frac{24}{30}\\)<br \/>\n\\(\\frac{1}{6}\\) \u00d7 \\(\\frac{5}{5}\\) = \\(\\frac{5}{30}\\)<\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>Use a common denominator to write an equivalent fraction for each fraction.<\/strong><\/p>\n<p>Question 8.<br \/>\n\\(\\frac{3}{5}, \\frac{1}{4}\\)<br \/>\ncommon denominator: ______<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: 20<\/p>\n<p>Explanation:<br \/>\nMultiply the denominators of the fractions to find the common denominator.<br \/>\n5 \u00d7 4 = 20<br \/>\nSo, the common denominator of \\(\\frac{3}{5}, \\frac{1}{4}\\) is 20.<\/p>\n<p>Question 9.<br \/>\n\\(\\frac{5}{8}, \\frac{1}{5}\\)<br \/>\ncommon denominator: ______<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: 40<\/p>\n<p>Explanation:<br \/>\nMultiply the denominators of the fractions to find the common denominator.<br \/>\n8 \u00d7 5 = 40<br \/>\nSo, the common denominator of \\(\\frac{5}{8}, \\frac{1}{5}\\) is 40.<\/p>\n<p>Question 10.<br \/>\n\\(\\frac{1}{12}, \\frac{1}{2}\\)<br \/>\ncommon denominator: ______<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: 24<\/p>\n<p>Explanation:<br \/>\nMultiply the denominators of the fractions to find the common denominator.<br \/>\n12 \u00d7 2 = 24<br \/>\nThe common denominator of \\(\\frac{1}{12}, \\frac{1}{2}\\) is 24.<\/p>\n<p><strong>Practice: Copy and Solve Use the least common denominator to write an equivalent fraction for each fraction.<\/strong><\/p>\n<p>Question 11.<br \/>\n\\(\\frac{1}{6}, \\frac{4}{9}\\)<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: \\(\\frac{3}{18}, \\frac{8}{18}\\)<\/p>\n<p>Explanation:<br \/>\nMultiply the denominators of the fractions.<br \/>\nThe Least Common Denominator = 18<br \/>\nNow rewrite the fractions<br \/>\n\\(\\frac{1}{6}\\) \u00d7 \\(\\frac{3}{3}\\) = \\(\\frac{3}{18}\\)<br \/>\n\\(\\frac{4}{9}\\) \u00d7 \\(\\frac{2}{2}\\) = \\(\\frac{8}{18}\\)<\/p>\n<p>Question 12.<br \/>\n\\(\\frac{7}{9}, \\frac{8}{27}\\)<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: \\(\\frac{21}{27}, \\frac{8}{27}\\)<\/p>\n<p>Explanation:<br \/>\nMultiply the denominators of the fractions.<br \/>\nThe Least Common Denominator = 27<br \/>\nNow rewrite the fractions<br \/>\n\\(\\frac{7}{9}\\) \u00d7 \\(\\frac{3}{3}\\) = \\(\\frac{21}{27}\\)<br \/>\n\\(\\frac{8}{27}\\) \u00d7 \\(\\frac{1}{1}\\) = \\(\\frac{8}{27}\\)<\/p>\n<p>Question 13.<br \/>\n\\(\\frac{7}{10}, \\frac{3}{8}\\)<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: \\(\\frac{28}{40}, \\frac{15}{40}\\)<\/p>\n<p>Explanation:<br \/>\nMultiply the denominators of the fractions.<br \/>\nThe Least Common Denominator = 40<br \/>\nNow rewrite the fractions<br \/>\n\\(\\frac{7}{10}\\) \u00d7 \\(\\frac{4}{4}\\) = \\(\\frac{28}{40}\\)<br \/>\n\\(\\frac{3}{8}\\) \u00d7 \\(\\frac{5}{5}\\) = \\(\\frac{15}{40}\\)<\/p>\n<p>Question 14.<br \/>\n\\(\\frac{1}{3}, \\frac{5}{11}\\)<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: \\(\\frac{11}{33}, \\frac{15}{33}\\)<\/p>\n<p>Explanation:<br \/>\nMultiply the denominators of the fractions.<br \/>\nThe Least Common Denominator = 33<br \/>\nNow rewrite the fractions<br \/>\n\\(\\frac{1}{3}\\) \u00d7 \\(\\frac{11}{11}\\) = \\(\\frac{11}{33}\\)<br \/>\n\\(\\frac{5}{11}\\) \u00d7 \\(\\frac{3}{3}\\) = \\(\\frac{15}{33}\\)<\/p>\n<p>Question 15.<br \/>\n\\(\\frac{5}{9}, \\frac{4}{15}\\)<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: \\(\\frac{25}{45}, \\frac{12}{45}\\)<\/p>\n<p>Explanation:<br \/>\nMultiply the denominators of the fractions.<br \/>\nThe Least Common Denominator of \\(\\frac{5}{9}, \\frac{4}{15}\\)= 45<br \/>\nNow rewrite the input fractions<br \/>\n\\(\\frac{5}{9}\\) \u00d7 \\(\\frac{5}{5}\\) = \\(\\frac{25}{45}\\)<br \/>\n\\(\\frac{4}{15}\\) \u00d7 \\(\\frac{3}{3}\\) = \\(\\frac{12}{45}\\)<\/p>\n<p>Question 16.<br \/>\n\\(\\frac{1}{6}, \\frac{4}{21}\\)<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: \\(\\frac{7}{42}, \\frac{8}{42}\\)<\/p>\n<p>Explanation:<br \/>\nMultiply the denominators of the fractions.<br \/>\nThe Least Common Denominator = 42<br \/>\nNow rewrite the fractions<br \/>\n\\(\\frac{1}{6}\\) \u00d7 \\(\\frac{7}{7}\\) = \\(\\frac{7}{42}\\)<br \/>\n\\(\\frac{4}{21}\\) \u00d7 \\(\\frac{2}{2}\\) = \\(\\frac{8}{42}\\)<\/p>\n<p>Question 17.<br \/>\n\\(\\frac{5}{14}, \\frac{8}{42}\\)<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: \\(\\frac{15}{42}, \\frac{8}{42}\\)<\/p>\n<p>Explanation:<br \/>\nMultiply the denominators of the fractions.<br \/>\nThe Least Common Denominator = 42<br \/>\nNow rewrite the fractions<br \/>\n\\(\\frac{5}{14}\\) \u00d7 \\(\\frac{3}{3}\\) = \\(\\frac{15}{42}\\)<br \/>\n\\(\\frac{8}{42}\\) \u00d7 \\(\\frac{1}{1}\\) = \\(\\frac{8}{42}\\)<\/p>\n<p>Question 18.<br \/>\n\\(\\frac{7}{12}, \\frac{5}{18}\\)<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: \\(\\frac{21}{36}, \\frac{10}{36}\\)<\/p>\n<p>Explanation:<br \/>\nMultiply the denominators of the fractions.<br \/>\nThe Least Common Denominator = 36<br \/>\nNow rewrite the fractions<br \/>\n\\(\\frac{7}{12}\\) \u00d7 \\(\\frac{3}{3}\\) = \\(\\frac{21}{36}\\)<br \/>\n\\(\\frac{5}{18}\\) \u00d7 \\(\\frac{2}{2}\\) = \\(\\frac{10}{36}\\)<\/p>\n<p><strong>Algebra Write the unknown number for each \u25a0.<\/strong><\/p>\n<p>Question 19.<br \/>\n\\(\\frac{1}{5}, \\frac{1}{8}\\)<br \/>\nleast common denominator: \u25a0<br \/>\n\u25a0 = ______<\/p>\n<p>Answer: 40<\/p>\n<p>Explanation:<br \/>\nMultiply the denominators of the fractions.<br \/>\n5 \u00d7 8 = 40<br \/>\nTherefore, \u25a0 = 40<\/p>\n<p>Question 20.<br \/>\n\\(\\frac{2}{5}, \\frac{1}{\u25a0}\\)<br \/>\nleast common denominator: 15<br \/>\n\u25a0 = ______<\/p>\n<p>Answer: 3<\/p>\n<p>Explanation:<br \/>\nMultiply the denominators of the fractions.<br \/>\n5 \u00d7 \u25a0 = 15<br \/>\n\u25a0 = 15\/5 = 3<br \/>\nThus \u25a0 = 3<\/p>\n<p>Question 21.<br \/>\n\\(\\frac{3}{\u25a0}, \\frac{5}{6}\\)<br \/>\nleast common denominator: 42<br \/>\n\u25a0 = ______<\/p>\n<p>Answer: 7<\/p>\n<p>Explanation:<br \/>\n\\(\\frac{3}{\u25a0}, \\frac{5}{6}\\)<br \/>\n\u25a0 \u00d7 6 = 42<br \/>\n\u25a0 = 42\/6<br \/>\n\u25a0 = 7<\/p>\n<h3><a id=\"UNLOCK_the_Problem_Page_No_258\"><\/a>UNLOCK the Problem &#8211; Page No. 258<\/h3>\n<p><img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-13.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators img 13\" width=\"246\" height=\"134\" \/><\/p>\n<p>Question 22.<br \/>\nKatie made two pies for the bake sale. One was cut into three equal slices and the other into 5 equal slices. She will continue to cut the pies so each one has the same number of equal-sized slices. What is the least number of equal-sized slices each pie could have?<br \/>\na. What information are you given?<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: I have the information about the two pies for the bake sale. One was cut into three equal slices and the other into 5 equal slices. She will continue to cut the pies so each one has the same number of equal-sized slices.<\/p>\n<p>Question 22.<br \/>\nb. What problem are you being asked to solve?<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: I am asked to solve the least number of equal-sized slices each pie could have.<\/p>\n<p>Question 22.<br \/>\nc. When Katie cuts the pies more, can she cut each pie the same number of times and have all the slices the same size? Explain.<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: Yes she can cut into more equal pieces. Katie can cut the pie into 6 equal pieces and 10 equal pieces. But the least number of equal-sized slices each pie could have is 3 and 5.<\/p>\n<p>Question 22.<br \/>\nd. Use the diagram to show the steps you use to solve the problem.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-14.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators img 14\" width=\"241\" height=\"115\" \/><br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer:<br \/>\nThere are 2 pies. One pie is cut into 3 equal pieces and the second pie is cut into 5 equal pieces.<br \/>\nSo, there are 15 pieces of pies.<\/p>\n<p>Question 22.<br \/>\ne. Complete the sentences.<br \/>\nThe least common denominator of \\(\\frac{1}{3}\\) and \\(\\frac{1}{5}\\) is ____.<br \/>\nKatie can cut each piece of the first pie into ____ and each piece of the second pie into ____ .<br \/>\nThat means that Katie can cut each pie into pieces that are ____ of the whole pie.<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer:<br \/>\nThe least common denominator of \\(\\frac{1}{3}\\) and \\(\\frac{1}{5}\\) is <span style=\"text-decoration: underline;\">15<br \/>\n<\/span>5 \u00d7 3 = 15<br \/>\nKatie can cut each piece of the first pie into <span style=\"text-decoration: underline;\">three<\/span> and each piece of the second pie into <span style=\"text-decoration: underline;\">five.<br \/>\n<\/span>That means that Katie can cut each pie into pieces that are <span style=\"text-decoration: underline;\">15<\/span> of the whole pie.<\/p>\n<p>Question 23.<br \/>\nA cookie recipe calls for \\(\\frac{1}{3}\\) cup of brown sugar and \\(\\frac{1}{8}\\) cup of walnuts. Find the least common denominator of the fractions used in the recipe.<br \/>\n____<\/p>\n<p>Answer: 24<\/p>\n<p>Explanation:<\/p>\n<p>A cookie recipe calls for \\(\\frac{1}{3}\\) cup of brown sugar and \\(\\frac{1}{8}\\) cup of walnuts.<br \/>\nWe can calculate the LCD by multiplying the denominators of the fraction.<br \/>\n3 \u00d7 8 = 24.<\/p>\n<p>Question 24.<br \/>\nTest Prep Which fractions use the least common denominator and are equivalent to \\(\\frac{5}{8}\\) and \\(\\frac{7}{10}\\) ?<br \/>\nOptions:<br \/>\na. \\(\\frac{10}{40} \\text { and } \\frac{14}{40}\\)<br \/>\nb. \\(\\frac{25}{40} \\text { and } \\frac{28}{40}\\)<br \/>\nc. \\(\\frac{25}{80} \\text { and } \\frac{21}{80}\\)<br \/>\nd. \\(\\frac{50}{80} \\text { and } \\frac{56}{80}\\)<\/p>\n<p>Answer: \\(\\frac{50}{80} \\text { and } \\frac{56}{80}\\)<\/p>\n<p>Explanation:<br \/>\nThe least common denominator of \\(\\frac{5}{8}\\) and \\(\\frac{7}{10}\\) is 80.<br \/>\n\\(\\frac{5}{8}\\) \u00d7 \\(\\frac{10}{10}\\) and \\(\\frac{7}{10}\\) \u00d7 \\(\\frac{8}{8}\\)<br \/>\n= \\(\\frac{50}{80} \\text { and } \\frac{56}{80}\\)<br \/>\nThus the correct answer is option D.<\/p>\n<h3><a id=\"Share_and_Show_Page_No_260\"><\/a>Share and Show &#8211; Page No. 260<\/h3>\n<p><strong>Find the sum or difference. Write your answer in simplest form.<\/strong><\/p>\n<p>Question 1.<br \/>\n\\(\\frac{5}{12}+\\frac{1}{3}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\nFind a common denominator by multiplying the denominators.<br \/>\n\\(\\frac{5}{12}+\\frac{1}{3}\\)<br \/>\n\\(\\frac{5}{12}\\) + \\(\\frac{1}{3}\\) \u00d7 \\(\\frac{4}{4}\\)<br \/>\n\\(\\frac{5}{12}\\) + \\(\\frac{4}{12}\\)<br \/>\n\\(\\frac{9}{12}\\)<\/p>\n<p>Question 2.<br \/>\n\\(\\frac{2}{5}+\\frac{3}{7}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\nFind a common denominator by multiplying the denominators.<br \/>\nUse the common denominator to write equivalent fractions with like denominators. Then add, and write your answer in simplest form.<br \/>\n\\(\\frac{2}{5}+\\frac{3}{7}\\)<br \/>\n\\(\\frac{2}{5}\\) \u00d7 \\(\\frac{7}{7}\\) + \\(\\frac{3}{7}\\) \u00d7 \\(\\frac{5}{5}\\)<br \/>\n\\(\\frac{14}{35}+\\frac{15}{35}\\)<br \/>\n= \\(\\frac{29}{35}\\)<br \/>\n\\(\\frac{2}{5}+\\frac{3}{7}\\) = \\(\\frac{29}{35}\\)<\/p>\n<p>Question 3.<br \/>\n\\(\\frac{1}{6}+\\frac{3}{4}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\nFind a common denominator by multiplying the denominators.<br \/>\nUse the common denominator to write equivalent fractions with like denominators. Then add, and write your answer in simplest form.<br \/>\n\\(\\frac{1}{6}\\) \u00d7 \\(\\frac{2}{2}\\) + \\(\\frac{3}{4}\\) \u00d7 \\(\\frac{3}{3}\\)<br \/>\n\\(\\frac{2}{12}+\\frac{9}{12}\\) = \\(\\frac{11}{12}\\)<br \/>\nSo, \\(\\frac{1}{6}+\\frac{3}{4}\\) = \\(\\frac{11}{12}\\)<\/p>\n<p>Question 4.<br \/>\n\\(\\frac{3}{4}-\\frac{1}{8}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\nFirst, find a common denominator by multiplying the denominators.<br \/>\nUse the common denominator to write equivalent fractions with like denominators. Then add, and write your answer in simplest form.<br \/>\n\\(\\frac{3}{4}-\\frac{1}{8}\\)<br \/>\n\\(\\frac{3}{4}\\) \u00d7 \\(\\frac{2}{2}\\) &#8211; \\(\\frac{1}{8}\\)<br \/>\n\\(\\frac{6}{8}\\) &#8211; \\(\\frac{1}{8}\\) = \\(\\frac{5}{8}\\)<br \/>\nThus \\(\\frac{3}{4}-\\frac{1}{8}\\) = \\(\\frac{5}{8}\\)<\/p>\n<p>Question 5.<br \/>\n\\(\\frac{1}{4}-\\frac{1}{7}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\nFirst, find a common denominator by multiplying the denominators.<br \/>\nUse the common denominator to write equivalent fractions with like denominators. Then add, and write your answer in simplest form.<br \/>\n\\(\\frac{1}{4}-\\frac{1}{7}\\)<br \/>\n\\(\\frac{1}{4}\\) \u00d7 \\(\\frac{7}{7}\\) &#8211; \\(\\frac{1}{7}\\) \u00d7 \\(\\frac{4}{4}\\)<br \/>\n\\(\\frac{7}{28}\\) &#8211; \\(\\frac{4}{28}\\) = \\(\\frac{3}{28}\\)<br \/>\n\\(\\frac{1}{4}-\\frac{1}{7}\\) = \\(\\frac{3}{28}\\)<\/p>\n<p>Question 6.<br \/>\n\\(\\frac{9}{10}-\\frac{1}{4}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\nFirst, find a common denominator by multiplying the denominators.<br \/>\nUse the common denominator to write equivalent fractions with like denominators. Then add, and write your answer in simplest form.<br \/>\n\\(\\frac{9}{10}-\\frac{1}{4}\\)<br \/>\n\\(\\frac{9}{10}\\) \u00d7 \\(\\frac{4}{4}\\) &#8211; \\(\\frac{1}{4}\\) \u00d7 \\(\\frac{10}{10}\\)<br \/>\n\\(\\frac{36}{40}\\) &#8211; \\(\\frac{10}{40}\\) = \\(\\frac{26}{40}\\)<br \/>\n\\(\\frac{9}{10}-\\frac{1}{4}\\) = \\(\\frac{26}{40}\\)<\/p>\n<h3><a id=\"On_Your_Own_Page_No_261\"><\/a>On Your Own &#8211; Page No. 261<\/h3>\n<p><strong>Find the sum or difference. Write your answer in simplest form.<\/strong><\/p>\n<p>Question 7.<br \/>\n\\(\\frac{3}{8}+\\frac{1}{4}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{5}{8}\\)<\/p>\n<p>Explanation:<br \/>\n\\(\\frac{3}{8}+\\frac{1}{4}\\) = \\(\\frac{3}{8}\\) + \\(\\frac{1}{4}\\)<br \/>\nLCD = 8<br \/>\n\\(\\frac{3}{8}\\) + \\(\\frac{1}{4}\\) \u00d7 \\(\\frac{2}{2}\\)<br \/>\n\\(\\frac{3}{8}\\) + \\(\\frac{2}{8}\\) = \\(\\frac{5}{8}\\)<br \/>\nThus \\(\\frac{3}{8}+\\frac{1}{4}\\) = \\(\\frac{5}{8}\\)<\/p>\n<p>Question 8.<br \/>\n\\(\\frac{7}{8}+\\frac{1}{10}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{7}{8}+\\frac{1}{10}\\)<br \/>\nFirst, find the Least Common Denominator and rewrite the fractions with the common denominator.<br \/>\nLCD = 40<br \/>\n\\(\\frac{7}{8}\\) \u00d7 \\(\\frac{5}{5}\\) + \\(\\frac{1}{10}\\) \u00d7 \\(\\frac{4}{4}\\)<br \/>\n\\(\\frac{35}{40}\\) + \\(\\frac{4}{40}\\) = \\(\\frac{39}{40}\\)<br \/>\n\\(\\frac{7}{8}+\\frac{1}{10}\\) = \\(\\frac{39}{40}\\)<\/p>\n<p>Question 9.<br \/>\n\\(\\frac{2}{7}+\\frac{3}{10}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{2}{7}+\\frac{3}{10}\\)<br \/>\nFirst, find the Least Common Denominator and rewrite the fractions with the common denominator.<br \/>\nLCD = 70<br \/>\n\\(\\frac{2}{7}\\) \u00d7 \\(\\frac{10}{10}\\) + \\(\\frac{3}{10}\\) \u00d7 \\(\\frac{7}{7}\\)<br \/>\n\\(\\frac{20}{70}\\) + \\(\\frac{21}{70}\\) = \\(\\frac{41}{70}\\)<br \/>\n\\(\\frac{2}{7}+\\frac{3}{10}\\) = \\(\\frac{41}{70}\\)<\/p>\n<p>Question 10.<br \/>\n\\(\\frac{5}{6}+\\frac{1}{8}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{5}{6}+\\frac{1}{8}\\)<br \/>\nFirst, find the Least Common Denominator and rewrite the fractions with the common denominator.<br \/>\n\\(\\frac{5}{6}\\) + \\(\\frac{1}{8}\\)<br \/>\nLCD = 24<br \/>\n\\(\\frac{5}{6}\\) \u00d7 \\(\\frac{4}{4}\\) + \\(\\frac{1}{8}\\) \u00d7 \\(\\frac{3}{3}\\)<br \/>\n\\(\\frac{20}{24}\\) + \\(\\frac{3}{24}\\) = \\(\\frac{23}{24}\\)<br \/>\n\\(\\frac{5}{6}+\\frac{1}{8}\\) = \\(\\frac{23}{24}\\)<\/p>\n<p>Question 11.<br \/>\n\\(\\frac{5}{12}+\\frac{5}{18}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{5}{12}+\\frac{5}{18}\\) = \\(\\frac{5}{12}\\) + \\(\\frac{5}{18}\\)<br \/>\nFirst, find the Least Common Denominator and rewrite the fractions with the common denominator.<br \/>\nLCD = 36<br \/>\n\\(\\frac{5}{12}\\) \u00d7 \\(\\frac{3}{3}\\) + \\(\\frac{5}{18}\\) \u00d7 \\(\\frac{2}{2}\\)<br \/>\n\\(\\frac{15}{36}\\) + \\(\\frac{10}{36}\\) = \\(\\frac{25}{36}\\)<br \/>\n\\(\\frac{5}{12}+\\frac{5}{18}\\) = \\(\\frac{25}{36}\\)<\/p>\n<p>Question 12.<br \/>\n\\(\\frac{7}{16}+\\frac{1}{4}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{7}{16}+\\frac{1}{4}\\)<br \/>\nFirst, find the Least Common Denominator and rewrite the fractions with the common denominator.<br \/>\nLCD = 16<br \/>\n\\(\\frac{7}{16}\\) + \\(\\frac{1}{4}\\) = \\(\\frac{7}{16}\\) + \\(\\frac{1}{4}\\) \u00d7 \\(\\frac{4}{4}\\)<br \/>\n\\(\\frac{7}{16}\\) + \\(\\frac{4}{16}\\) = \\(\\frac{11}{16}\\)<\/p>\n<p>Question 13.<br \/>\n\\(\\frac{5}{6}+\\frac{3}{8}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{5}{6}+\\frac{3}{8}\\)<br \/>\nFirst, find the Least Common Denominator and rewrite the fractions with the common denominator.<br \/>\n\\(\\frac{5}{6}\\) + \\(\\frac{3}{8}\\)<br \/>\nLCD = 24<br \/>\n\\(\\frac{5}{6}\\) \u00d7 \\(\\frac{4}{4}\\) + \\(\\frac{3}{8}\\) \u00d7 \\(\\frac{3}{3}\\)<br \/>\n= \\(\\frac{20}{24}\\) + \\(\\frac{9}{24}\\) = \\(\\frac{29}{24}\\)<br \/>\n\\(\\frac{5}{6}+\\frac{3}{8}\\) = \\(\\frac{29}{24}\\)<\/p>\n<p>Question 14.<br \/>\n\\(\\frac{3}{4}+\\frac{1}{2}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{3}{4}+\\frac{1}{2}\\)<br \/>\nFirst, find the Least Common Denominator and rewrite the fractions with the common denominator.<br \/>\n\\(\\frac{3}{4}\\) + \\(\\frac{1}{2}\\)<br \/>\nLCD = 4<br \/>\n\\(\\frac{3}{4}\\) + \\(\\frac{1}{2}\\) \u00d7 \\(\\frac{2}{2}\\)<br \/>\n= \\(\\frac{3}{4}\\) + \\(\\frac{2}{4}\\) = \\(\\frac{5}{4}\\)<br \/>\nThe miced fractiion of \\(\\frac{5}{4}\\) is 1 \\(\\frac{1}{4}\\)<\/p>\n<p>Question 15.<br \/>\n\\(\\frac{5}{12}+\\frac{1}{4}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{5}{12}+\\frac{1}{4}\\)<br \/>\nFirst, find the Least Common Denominator and rewrite the fractions with the common denominator.<br \/>\n\\(\\frac{5}{12}\\) + \\(\\frac{1}{4}\\)<br \/>\nLCD = 12<br \/>\n\\(\\frac{5}{12}\\) + \\(\\frac{1}{4}\\) \u00d7 \\(\\frac{3}{3}\\)<br \/>\n\\(\\frac{5}{12}\\) + \\(\\frac{3}{12}\\) = \\(\\frac{8}{12}\\) = \\(\\frac{2}{3}\\)<\/p>\n<p><strong>Practice: Copy and Solve Find the sum or difference. Write your answer in simplest form.<\/strong><\/p>\n<p>Question 16.<br \/>\n\\(\\frac{1}{3}+\\frac{4}{18}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{1}{3}+\\frac{4}{18}\\)<br \/>\nFirst, find the Least Common Denominator and rewrite the fractions with the common denominator.<br \/>\nLCD = 18<br \/>\n\\(\\frac{1}{3}\\) + \\(\\frac{4}{18}\\)<br \/>\n\\(\\frac{1}{3}\\) \u00d7 \\(\\frac{6}{6}\\) + \\(\\frac{4}{18}\\)<br \/>\n\\(\\frac{6}{18}\\) + \\(\\frac{4}{18}\\) = \\(\\frac{10}{18}\\) = \\(\\frac{5}{9}\\)<br \/>\n\\(\\frac{1}{3}+\\frac{4}{18}\\) = \\(\\frac{5}{9}\\)<\/p>\n<p>Question 17.<br \/>\n\\(\\frac{3}{5}+\\frac{1}{3}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{3}{5}+\\frac{1}{3}\\)<br \/>\nFirst, find the Least Common Denominator and rewrite the fractions with the common denominator.<br \/>\nLCD = 15<br \/>\n\\(\\frac{3}{5}\\) + \\(\\frac{1}{3}\\)<br \/>\n\\(\\frac{3}{5}\\) \u00d7 \\(\\frac{3}{3}\\) + \\(\\frac{1}{3}\\) \u00d7 \\(\\frac{5}{5}\\)<br \/>\n\\(\\frac{9}{15}\\) + \\(\\frac{5}{15}\\) = \\(\\frac{14}{15}\\)<br \/>\n\\(\\frac{3}{5}+\\frac{1}{3}\\) = \\(\\frac{14}{15}\\)<\/p>\n<p>Question 18.<br \/>\n\\(\\frac{3}{10}+\\frac{1}{6}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{3}{10}+\\frac{1}{6}\\)<br \/>\nFirst, find the Least Common Denominator and rewrite the fractions with the common denominator.<br \/>\nLCD = 30<br \/>\n\\(\\frac{3}{10}\\) + \\(\\frac{1}{6}\\)<br \/>\n\\(\\frac{3}{10}\\) \u00d7 \\(\\frac{3}{3}\\) + \\(\\frac{1}{6}\\) \u00d7 \\(\\frac{5}{5}\\)<br \/>\n\\(\\frac{9}{30}\\) + \\(\\frac{5}{30}\\) = \\(\\frac{14}{30}\\)<br \/>\n\\(\\frac{3}{10}+\\frac{1}{6}\\) = \\(\\frac{14}{30}\\)<\/p>\n<p>Question 19.<br \/>\n\\(\\frac{1}{2}+\\frac{4}{9}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{1}{2}+\\frac{4}{9}\\)<br \/>\nFirst, find the Least Common Denominator and rewrite the fractions with the common denominator.<br \/>\nLCD = 18<br \/>\n\\(\\frac{1}{2}\\) + \\(\\frac{4}{9}\\)<br \/>\n\\(\\frac{1}{2}\\) \u00d7 \\(\\frac{9}{9}\\) + \\(\\frac{4}{9}\\) \u00d7 \\(\\frac{2}{2}\\)<br \/>\n= \\(\\frac{9}{18}\\) + \\(\\frac{8}{18}\\) = \\(\\frac{17}{18}\\)<br \/>\n\\(\\frac{1}{2}+\\frac{4}{9}\\) = \\(\\frac{17}{18}\\)<\/p>\n<p>Question 20.<br \/>\n\\(\\frac{1}{2}-\\frac{3}{8}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{1}{2}-\\frac{3}{8}\\)<br \/>\nFirst, find the Least Common Denominator and rewrite the fractions with the common denominator.<br \/>\nLCD = 8<br \/>\n\\(\\frac{1}{2}\\) &#8211; \\(\\frac{3}{8}\\)<br \/>\n\\(\\frac{1}{2}\\) \u00d7 \\(\\frac{4}{4}\\) &#8211; \\(\\frac{3}{8}\\)<br \/>\n\\(\\frac{4}{8}\\) &#8211; \\(\\frac{3}{8}\\) = \\(\\frac{1}{8}\\)<br \/>\n\\(\\frac{1}{2}-\\frac{3}{8}\\) = \\(\\frac{1}{8}\\)<\/p>\n<p>Question 21.<br \/>\n\\(\\frac{5}{7}-\\frac{2}{3}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{5}{7}-\\frac{2}{3}\\)<br \/>\nFirst, find the Least Common Denominator and rewrite the fractions with the common denominator.<br \/>\nLCD = 21<br \/>\n\\(\\frac{5}{7}\\) &#8211; \\(\\frac{2}{3}\\)<br \/>\n\\(\\frac{5}{7}\\) \u00d7 \\(\\frac{3}{3}\\) &#8211; \\(\\frac{2}{3}\\) \u00d7 \\(\\frac{7}{7}\\)<br \/>\n\\(\\frac{15}{21}\\) &#8211; \\(\\frac{14}{21}\\) = \\(\\frac{1}{21}\\)<br \/>\n\\(\\frac{5}{7}-\\frac{2}{3}\\) = \\(\\frac{1}{21}\\)<\/p>\n<p>Question 22.<br \/>\n\\(\\frac{4}{9}-\\frac{1}{6}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{4}{9}-\\frac{1}{6}\\)<br \/>\nFirst, find the Least Common Denominator and rewrite the fractions with the common denominator.<br \/>\nLCD = 18<br \/>\n\\(\\frac{4}{9}\\) &#8211; \\(\\frac{1}{6}\\)<br \/>\n\\(\\frac{4}{9}\\) \u00d7 \\(\\frac{2}{2}\\) &#8211; \\(\\frac{1}{6}\\) \u00d7 \\(\\frac{3}{3}\\)<br \/>\n\\(\\frac{8}{18}\\) &#8211; \\(\\frac{3}{18}\\) = \\(\\frac{5}{18}\\)<br \/>\n\\(\\frac{4}{9}-\\frac{1}{6}\\) = \\(\\frac{5}{18}\\)<\/p>\n<p>Question 23.<br \/>\n\\(\\frac{11}{12}-\\frac{7}{15}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{11}{12}-\\frac{7}{15}\\)<br \/>\nFirst, find the Least Common Denominator and rewrite the fractions with the common denominator.<br \/>\nLCD = 60<br \/>\n\\(\\frac{11}{12}\\) &#8211; \\(\\frac{7}{15}\\)<br \/>\n\\(\\frac{11}{12}\\) \u00d7 \\(\\frac{5}{5}\\) &#8211; \\(\\frac{7}{15}\\) \u00d7 \\(\\frac{4}{4}\\)<br \/>\n\\(\\frac{55}{60}\\) &#8211; \\(\\frac{28}{60}\\) = \\(\\frac{27}{60}\\)<br \/>\n\\(\\frac{11}{12}-\\frac{7}{15}\\) = \\(\\frac{27}{60}\\) = \\(\\frac{9}{20}\\)<\/p>\n<p><strong>Algebra Find the unknown number.<\/strong><\/p>\n<p>Question 24.<br \/>\n\\(\\frac{9}{10}\\) \u2212 \u25a0 = \\(\\frac{1}{5}\\)<br \/>\n\u25a0 = \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{9}{10}\\) &#8211; \\(\\frac{1}{5}\\) = \u25a0<br \/>\n\u25a0 = \\(\\frac{9}{10}\\) &#8211; \\(\\frac{1}{5}\\)<br \/>\n\u25a0 = \\(\\frac{9}{10}\\) &#8211; \\(\\frac{2}{10}\\) = \\(\\frac{7}{10}\\)<br \/>\n\u25a0 = \\(\\frac{7}{10}\\)<\/p>\n<p>Question 25.<br \/>\n\\(\\frac{5}{12}\\) + \u25a0 = \\(\\frac{1}{2}\\)<br \/>\n\u25a0 = \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{5}{12}\\) + \u25a0 = \\(\\frac{1}{2}\\)<br \/>\n\\(\\frac{5}{12}\\) \u2212 \\(\\frac{1}{2}\\) = &#8211; \u25a0<br \/>\n&#8211; \u25a0 = \\(\\frac{5}{12}\\) \u2212 \\(\\frac{1}{2}\\)<br \/>\n&#8211; \u25a0 = \\(\\frac{5}{12}\\) \u2212 \\(\\frac{1}{2}\\) \u00d7 \\(\\frac{6}{6}\\)<br \/>\n&#8211; \u25a0 = \\(\\frac{5}{12}\\) \u2212 \\(\\frac{6}{12}\\) = &#8211; \\(\\frac{1}{12}\\)<br \/>\n\u25a0 =\u00a0\\(\\frac{1}{12}\\)<\/p>\n<h3><a id=\"Problem_Solving_Page_No_262\"><\/a>Problem Solving &#8211; Page No. 262<\/h3>\n<p><strong>Use the picture for 26\u201327.<\/strong><br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-15.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators img 15\" width=\"213\" height=\"128\" \/><\/p>\n<p>Question 26.<br \/>\nSara is making a key chain using the bead design shown. What fraction of the beads in her design are either blue or red?<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{11}{15}\\)<\/p>\n<p>Explanation:<br \/>\nTotal number of red beads = 6<br \/>\nTotal number of blue beads = 5<br \/>\nTotal number of beads = 6 + 5 = 11<br \/>\nThe fraction of beads = \\(\\frac{11}{15}\\)<\/p>\n<p>Question 27.<br \/>\nIn making the key chain, Sara uses the pattern of beads 3 times. After the key chain is complete, what fraction of the beads in the key chain are either white or blue?<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 1 \\(\\frac{4}{5}\\)<\/p>\n<p>Explanation:<br \/>\nIn making the key chain, Sara uses the pattern of beads 3 times.<br \/>\nGiven that Sara uses the pattern of beads 3 times.<br \/>\nTotal number of blue beads = 5<br \/>\n5 \u00d7 3 = 15<br \/>\nNumber of white beads = 4<br \/>\n4 \u00d7 3 = 12<br \/>\n15 + 12 = 27<br \/>\nActual number of beads = 15<br \/>\nSo, the fraction is \\(\\frac{27}{15}\\) = \\(\\frac{9}{5}\\)<br \/>\nThe mixed fraction of \\(\\frac{9}{5}\\) is 1 \\(\\frac{4}{5}\\)<\/p>\n<p>Question 28.<br \/>\nJamie had \\(\\frac{4}{5}\\) of a spool of twine. He then used \\(\\frac{1}{2}\\) of a spool of twine to make friendship knots. He claims to have \\(\\frac{3}{10}\\) of the original spool of twine left over. Explain how you know whether Jamie\u2019s claim is reasonable.<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: Jamie\u2019s claim is reasonable<\/p>\n<p>Explanation:<br \/>\nJamie had \\(\\frac{4}{5}\\) of a spool of twine. He then used \\(\\frac{1}{2}\\) of a spool of twine to make friendship knots. He claims to have \\(\\frac{3}{10}\\) of the original spool of twine left over.<br \/>\nTo know whether his estimation is reasonable or not we have to subtract the total spool of twine from used spool of twine.<br \/>\n\\(\\frac{4}{5}\\) &#8211; \\(\\frac{1}{2}\\)<br \/>\nLCD = 10<br \/>\n\\(\\frac{4}{5}\\) \u00d7 \\(\\frac{2}{2}\\)\u00a0 &#8211; \\(\\frac{1}{2}\\) \u00d7 \\(\\frac{5}{5}\\)<br \/>\n\\(\\frac{8}{10}\\) &#8211; \\(\\frac{5}{10}\\) = \\(\\frac{3}{10}\\)<br \/>\nBy this is can that Jamie\u2019s claim is reasonable.<\/p>\n<p>Question 29.<br \/>\nTest Prep Which equation represents the fraction of beads that are green or yellow?<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-16.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators img 16\" width=\"209\" height=\"45\" \/><br \/>\nOptions:<br \/>\na. \\(\\frac{1}{4}+\\frac{1}{8}=\\frac{3}{8}\\)<br \/>\nb. [atex]\\frac{1}{2}+\\frac{1}{4}=\\frac{3}{4}[\/latex]<br \/>\nc. \\(\\frac{1}{2}+\\frac{1}{8}=\\frac{5}{8}\\)<br \/>\nd. \\(\\frac{3}{4}+\\frac{2}{8}=1\\)<\/p>\n<p>Answer: [atex]\\frac{1}{2}+\\frac{1}{4}=\\frac{3}{4}[\/latex]<\/p>\n<p>Explanation:<br \/>\nNumber of green beads = 4 = [atex]\\frac{1}{2}[\/latex]<br \/>\nNumber of blue beads = 3 = [atex]\\frac{3}{4}[\/latex]<br \/>\nNumber of yellow beads = 1 [atex]\\frac{1}{4}[\/latex]<br \/>\nThe fraction of beads that are green or yellow is [atex]\\frac{1}{2}+\\frac{1}{4}=\\frac{3}{4}[\/latex]<br \/>\nThe correct answer is option B.<\/p>\n<h3><a id=\"Mid_Chapter_Checkpoint_Vocabulary_Page_No_263\"><\/a>Mid-Chapter Checkpoint &#8211; Vocabulary &#8211; Page No. 263<\/h3>\n<p><strong>Choose the best term from the box.<\/strong><br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-17.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators Mid-Chapter Checkpoint img 17\" width=\"215\" height=\"151\" \/><\/p>\n<p>Question 1.<br \/>\nA ________ is a number that is a multiple of two or more numbers.<br \/>\n________<\/p>\n<p>Answer: Common Multiple<br \/>\nA Common Multiple is a number that is a multiple of two or more numbers.<\/p>\n<p>Question 2.<br \/>\nA ________ is a common multiple of two or more denominators.<br \/>\n________<\/p>\n<p>Answer: Common denominator<br \/>\nA Common denominator is a common multiple of two or more denominators.<\/p>\n<p><strong>Concepts and Skills<\/strong><\/p>\n<p><strong>Estimate the sum or difference.<\/strong><\/p>\n<p>Question 3.<br \/>\n\\(\\frac{8}{9}+\\frac{4}{7}\\)<br \/>\nabout ______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 1 \\(\\frac{1}{2}\\)<\/p>\n<p>Place \\(\\frac{8}{9}\\) on the number line.<br \/>\n\\(\\frac{8}{9}\\) lies between \\(\\frac{1}{2}\\) and 1.<br \/>\n\\(\\frac{8}{9}\\) is closer to 1.<br \/>\nPlace \\(\\frac{4}{7}\\) on the number line.<br \/>\n\\(\\frac{4}{7}\\) lies between \\(\\frac{1}{2}\\) and 1.<br \/>\n\\(\\frac{4}{7}\\) is closer to \\(\\frac{1}{2}\\).<br \/>\n1 + \\(\\frac{1}{2}\\) = 1 \\(\\frac{1}{2}\\)<\/p>\n<p>Question 4.<br \/>\n\\(3 \\frac{2}{5}-\\frac{5}{8}\\)<br \/>\nabout ______<\/p>\n<p>Answer: 3<\/p>\n<p>Explanation:<br \/>\nPlace \\(\\frac{2}{5}\\) on the number line.<br \/>\n\\(\\frac{2}{5}\\) lies between 0 and \\(\\frac{1}{2}\\)<br \/>\n\\(\\frac{2}{5}\\) is closer to \\(\\frac{1}{2}\\)<br \/>\nPlace \\(\\frac{5}{8}\\) on the number line.<br \/>\n\\(\\frac{5}{8}\\) lies between \\(\\frac{1}{2}\\) and 1.<br \/>\n\\(\\frac{5}{8}\\) is closer to \\(\\frac{1}{2}\\)<br \/>\n3 + \\(\\frac{1}{2}\\) &#8211; \\(\\frac{1}{2}\\) = 3<br \/>\n\\(3 \\frac{2}{5}-\\frac{5}{8}\\) = 3<\/p>\n<p>Question 5.<br \/>\n\\(1 \\frac{5}{6}+2 \\frac{2}{11}\\)<br \/>\nabout ______<\/p>\n<p>Answer: 4<\/p>\n<p>Explanation:<br \/>\nPlace \\(\\frac{5}{6}\\) on the number line.<br \/>\n\\(\\frac{5}{6}\\) lies between \\(\\frac{1}{2}\\) and 1.<br \/>\n\\(\\frac{5}{6}\\) is closer to 1.<br \/>\nPlace \\(\\frac{2}{11}\\) on the number line.<br \/>\n\\(\\frac{2}{11}\\) lies between \\(\\frac{1}{2}\\) and 0.<br \/>\n\\(\\frac{2}{11}\\) is closer to 0<br \/>\n1 + 1 + 2 + 0 = 4<br \/>\n\\(1 \\frac{5}{6}+2 \\frac{2}{11}\\) = 4<\/p>\n<p><strong>Use a common denominator to write an equivalent fraction for each fraction.<\/strong><\/p>\n<p>Question 6.<br \/>\n\\(\\frac{1}{6}, \\frac{1}{9}\\)<br \/>\ncommon denominator:<br \/>\nType below:<br \/>\n__________<\/p>\n<p>Answer: 54<br \/>\nMultiply the denominators<br \/>\n6 \u00d7 9 = 54<br \/>\nThus the common denominator of \\(\\frac{1}{6}, \\frac{1}{9}\\) is 54<\/p>\n<p>Question 7.<br \/>\n\\(\\frac{3}{8}, \\frac{3}{10}\\)<br \/>\ncommon denominator:<br \/>\nType below:<br \/>\n__________<\/p>\n<p>Answer: 80<br \/>\nMultiply the denominators<br \/>\n8 \u00d7 10 = 80<br \/>\nThe common denominator of \\(\\frac{3}{8}, \\frac{3}{10}\\) is 80<\/p>\n<p>Question 8.<br \/>\n\\(\\frac{1}{9}, \\frac{5}{12}\\)<br \/>\ncommon denominator:<br \/>\nType below:<br \/>\n__________<\/p>\n<p>Answer: 36<br \/>\nMultiply the denominators<br \/>\n9 \u00d7 12 = 108<br \/>\nThe common denominator of \\(\\frac{1}{9}, \\frac{5}{12}\\) is 108<\/p>\n<p><strong>Use the least common denominator to write an equivalent fraction for each fraction.<\/strong><\/p>\n<p>Question 9.<br \/>\n\\(\\frac{2}{5}, \\frac{1}{10}\\)<br \/>\nleast common denominator: ______<br \/>\nExplain:<br \/>\n__________<\/p>\n<p>Answer: 10<\/p>\n<p>Explanation:<br \/>\nMultiply the denominators<br \/>\n5 \u00d7 10 = 50<br \/>\nThe least common denominators of \\(\\frac{2}{5}, \\frac{1}{10}\\) is 10.<\/p>\n<p>Question 10.<br \/>\n\\(\\frac{5}{6}, \\frac{3}{8}\\)<br \/>\nleast common denominator: ______<br \/>\nExplain:<br \/>\n__________<\/p>\n<p>Answer: 24<\/p>\n<p>Explanation:<br \/>\nMultiply the denominators<br \/>\nThe least common denominator of 6 and 8 is 24<br \/>\nThus the LCD of \\(\\frac{5}{6}, \\frac{3}{8}\\) is 24<\/p>\n<p>Question 11.<br \/>\n\\(\\frac{1}{3}, \\frac{2}{7}\\)<br \/>\nleast common denominator: ______<br \/>\nExplain:<br \/>\n__________<\/p>\n<p>Answer: 21<\/p>\n<p>Explanation:<br \/>\nMultiply the denominators<br \/>\nThe least common denominator of 3 and 7 is 21.<br \/>\nThus the LCD of \\(\\frac{1}{3}, \\frac{2}{7}\\) is 21.<\/p>\n<p><strong>Find the sum or difference. Write your answer in simplest form.<\/strong><\/p>\n<p>Question 12.<br \/>\n\\(\\frac{11}{18}-\\frac{1}{6}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{8}{18}\\)<\/p>\n<p>Explanation:<br \/>\nMake the fractions like denominators.<br \/>\n\\(\\frac{11}{18}\\) &#8211; \\(\\frac{1}{6}\\)<br \/>\n\\(\\frac{1}{6}\\) \u00d7 \\(\\frac{3}{3}\\) = \\(\\frac{3}{18}\\)<br \/>\n\\(\\frac{11}{18}\\) &#8211; \\(\\frac{3}{18}\\) = \\(\\frac{8}{18}\\)<\/p>\n<p>Question 13.<br \/>\n\\(\\frac{2}{7}+\\frac{2}{5}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{24}{35}\\)<\/p>\n<p>Explanation:<br \/>\nMake the fractions like denominators.<br \/>\n\\(\\frac{2}{7}\\) \u00d7 \\(\\frac{5}{5}\\) = \\(\\frac{10}{35}\\)<br \/>\n\\(\\frac{2}{5}\\) \u00d7 \\(\\frac{7}{7}\\) = \\(\\frac{14}{35}\\)<br \/>\n\\(\\frac{10}{35}\\) + \\(\\frac{14}{35}\\) = \\(\\frac{24}{35}\\)<br \/>\nThus \\(\\frac{2}{7}+\\frac{2}{5}\\) = \\(\\frac{24}{35}\\)<\/p>\n<p>Question 14.<br \/>\n\\(\\frac{3}{4}-\\frac{3}{10}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{18}{40}\\)<\/p>\n<p>Explanation:<br \/>\nMake the fractions like denominators.<br \/>\n\\(\\frac{3}{4}\\) \u00d7 \\(\\frac{10}{10}\\) = \\(\\frac{30}{40}\\)<br \/>\n\\(\\frac{3}{10}\\) \u00d7 \\(\\frac{4}{4}\\) = \\(\\frac{12}{40}\\)<br \/>\n\\(\\frac{30}{40}\\) &#8211; \\(\\frac{12}{40}\\) = \\(\\frac{18}{40}\\)<\/p>\n<h3><a id=\"Mid_Chapter_Checkpoint_Page_No_264\"><\/a>Mid-Chapter Checkpoint &#8211; Page No. 264<\/h3>\n<p>Question 15.<br \/>\nMrs. Vargas bakes a pie for her book club meeting. The shaded part of the diagram below shows the amount of pie left after the meeting. That evening, Mr. Vargas eats \\(\\frac{1}{4}\\) of the whole pie. What fraction represents the amount of pie remaining?<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-18.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators Mid-Chapter Checkpoint img 18\" width=\"119\" height=\"117\" \/><br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{1}{4}\\)<\/p>\n<p>Explanation:<br \/>\nMrs. Vargas bakes a pie for her book club meeting. The shaded part of the diagram below shows the amount of pie left after the meeting.<br \/>\nSo, the fraction of the pie is \\(\\frac{1}{2}\\)<br \/>\nThat evening, Mr. Vargas eats \\(\\frac{1}{4}\\) of the whole pie.<br \/>\n\\(\\frac{1}{2}\\) &#8211; \\(\\frac{1}{4}\\) = \\(\\frac{1}{4}\\)<br \/>\nThus the fraction represents the amount of pie remaining is \\(\\frac{1}{4}\\)<\/p>\n<p>Question 16.<br \/>\nKeisha makes a large sandwich for a family picnic. She takes \\(\\frac{1}{2}\\) of the sandwich to the picnic. At the picnic, her family eats \\(\\frac{3}{8}\\) of the whole sandwich. What fraction of the whole sandwich does Keisha bring back from the picnic?<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{1}{8}\\)<\/p>\n<p>Explanation:<br \/>\nKeisha makes a large sandwich for a family picnic. She takes \\(\\frac{1}{2}\\) of the sandwich to the picnic.<br \/>\nAt the picnic, her family eats \\(\\frac{3}{8}\\) of the whole sandwich.<br \/>\n\\(\\frac{1}{2}\\) &#8211; \\(\\frac{3}{8}\\)<br \/>\n\\(\\frac{1}{2}\\) \u00d7 \\(\\frac{4}{4}\\) &#8211; \\(\\frac{3}{8}\\)<br \/>\n\\(\\frac{4}{8}\\) &#8211; \\(\\frac{3}{8}\\) = \\(\\frac{1}{8}\\)<br \/>\nThus Keisha brought \\(\\frac{1}{8}\\) of the sandwich from the picnic.<\/p>\n<p>Question 17.<br \/>\nMike is mixing paint for his walls. He mixes \\(\\frac{1}{6}\\) gallon blue paint and \\(\\frac{5}{8}\\) gallon green paint in a large container. What fraction represents the total amount of paint Mike mixes?<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{19}{24}\\)<\/p>\n<p>Explanation:<br \/>\nMike is mixing paint for his walls. He mixes \\(\\frac{1}{6}\\) gallon blue paint and \\(\\frac{5}{8}\\) gallon green paint in a large container.<br \/>\n\\(\\frac{1}{6}\\) + \\(\\frac{5}{8}\\)<br \/>\n\\(\\frac{1}{6}\\) \u00d7 \\(\\frac{8}{8}\\)\u00a0 + \\(\\frac{5}{8}\\) \u00d7 \\(\\frac{6}{6}\\)<br \/>\n\\(\\frac{8}{48}\\)\u00a0 + \\(\\frac{30}{48}\\)<br \/>\n\\(\\frac{38}{48}\\) = \\(\\frac{19}{24}\\)<br \/>\nTherefore the total amount of paint Mike mixes is \\(\\frac{19}{24}\\)<\/p>\n<h3><a id=\"Share_and_Show_Page_No_266\"><\/a>Share and Show &#8211; Page No. 266<\/h3>\n<p>Question 1.<br \/>\nUse a common denominator to write equivalent fractions with like denominators and then find the sum. Write your answer in simplest form.<br \/>\n7 \\(\\frac{2}{5}\\) = \u25a0<br \/>\n+ 4 \\(\\frac{3}{4}\\) = + \u25a0<br \/>\n&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;&#8212;<br \/>\n\u25a0<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 12 \\(\\frac{3}{20}\\)<\/p>\n<p>Explanation:<br \/>\nFirst convert the mixed fraction to proper fraction.<br \/>\n7 \\(\\frac{2}{5}\\) = \\(\\frac{37}{5}\\)<br \/>\n4 \\(\\frac{3}{4}\\) = \\(\\frac{19}{4}\\)<br \/>\n\\(\\frac{37}{5}\\) + \\(\\frac{19}{4}\\)<br \/>\n= \\(\\frac{37}{5}\\) \u00d7 \\(\\frac{4}{4}\\) = \\(\\frac{148}{20}\\)<br \/>\n\\(\\frac{19}{4}\\) \u00d7 \\(\\frac{5}{5}\\) = \\(\\frac{95}{20}\\)<br \/>\n\\(\\frac{148}{20}\\) + \\(\\frac{95}{20}\\) = \\(\\frac{243}{20}\\)<br \/>\nNow convert it into mixed fraction = 12 \\(\\frac{3}{20}\\)<\/p>\n<p><strong>Find the sum. Write your answer in simplest form.<\/strong><\/p>\n<p>Question 2.<br \/>\n\\(2 \\frac{3}{4}+3 \\frac{3}{10}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 6 \\(\\frac{1}{20}\\)<\/p>\n<p>Explanation:<br \/>\nFirst convert the mixed fraction to proper fraction.<br \/>\n\\(2 \\frac{3}{4}\\) = \\(\\frac{11}{4}\\)<br \/>\n3 \\(\\frac{3}{10}\\) = \\(\\frac{33}{10}\\)<br \/>\nNow make the common denominators of the above fractions.<br \/>\n\\(\\frac{11}{4}\\) \u00d7 \\(\\frac{10}{10}\\) = \\(\\frac{110}{40}\\)<br \/>\n\\(\\frac{33}{10}\\) \u00d7 \\(\\frac{4}{4}\\) = \\(\\frac{132}{40}\\) = \\(\\frac{121}{20}\\)<br \/>\nNow convert the fraction into mixed fraction.<br \/>\n\\(\\frac{121}{20}\\) = 6 \\(\\frac{1}{20}\\)<\/p>\n<p>Question 3.<br \/>\n\\(5 \\frac{3}{4}+1 \\frac{1}{3}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 7 \\(\\frac{1}{12}\\)<\/p>\n<p>Explanation:<br \/>\nFirst convert the mixed fraction to proper fraction.<br \/>\n5 \\(\\frac{3}{4}\\) = \\(\\frac{23}{4}\\)<br \/>\n1 \\(\\frac{1}{3}\\) = \\(\\frac{4}{3}\\)<br \/>\n\\(\\frac{23}{4}\\) + \\(\\frac{4}{3}\\)<br \/>\n\\(\\frac{23}{4}\\) \u00d7 \\(\\frac{3}{3}\\) = \\(\\frac{69}{12}\\)<br \/>\n\\(\\frac{4}{3}\\) \u00d7 \\(\\frac{4}{4}\\) = \\(\\frac{16}{12}\\)<br \/>\n\\(\\frac{69}{12}\\) + \\(\\frac{16}{12}\\) = \\(\\frac{85}{12}\\)<br \/>\nThe mixed fraction of \\(\\frac{85}{12}\\) = 7 \\(\\frac{1}{12}\\)<\/p>\n<p>Question 4.<br \/>\n\\(3 \\frac{4}{5}+2 \\frac{3}{10}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 6 \\(\\frac{1}{10}\\)<\/p>\n<p>Explanation:<br \/>\nFirst convert the mixed fraction to proper fraction.<br \/>\n3 \\(\\frac{4}{5}\\) = \\(\\frac{19}{5}\\)<br \/>\n2 \\(\\frac{3}{10}\\) = \\(\\frac{23}{10}\\)<br \/>\n\\(\\frac{19}{5}\\) + \\(\\frac{23}{10}\\)<br \/>\nNow make the common denominators of the above fractions.<br \/>\n\\(\\frac{19}{5}\\) \u00d7 \\(\\frac{2}{2}\\) = \\(\\frac{38}{10}\\)<br \/>\n\\(\\frac{38}{10}\\) + \\(\\frac{23}{10}\\) = \\(\\frac{61}{10}\\)<br \/>\nThe mixed fraction of \\(\\frac{61}{10}\\) = 6 \\(\\frac{1}{10}\\)<\/p>\n<h3><a id=\"Page_No_267\"><\/a>Page No. 267<\/h3>\n<p><strong>Find the difference. Write your answer in simplest form.<\/strong><\/p>\n<p>Question 5.<br \/>\n\\(9 \\frac{5}{6}-2 \\frac{1}{3}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 7 \\(\\frac{1}{2}\\)<\/p>\n<p>Explanation:<br \/>\n\\(9 \\frac{5}{6}-2 \\frac{1}{3}\\) = \\(\\frac{59}{6}\\) &#8211; \\(\\frac{14}{6}\\)<br \/>\n= \\(\\frac{45}{6}\\) = \\(\\frac{15}{2}\\) = 7 \\(\\frac{1}{2}\\)<\/p>\n<p>Question 6.<br \/>\n\\(10 \\frac{5}{9}-9 \\frac{1}{6}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 1 \\(\\frac{7}{18}\\)<\/p>\n<p>Explanation:<br \/>\n\\(10 \\frac{5}{9}-9 \\frac{1}{6}\\) = \\(\\frac{95}{9}\\) &#8211; \\(\\frac{55}{6}\\)<br \/>\n= \\(\\frac{190}{18}\\) &#8211; \\(\\frac{165}{18}\\) = \\(\\frac{25}{18}\\)<br \/>\n= 1 \\(\\frac{7}{18}\\)<br \/>\n\\(10 \\frac{5}{9}-9 \\frac{1}{6}\\) = 1 \\(\\frac{7}{18}\\)<\/p>\n<p>Question 7.<br \/>\n\\(7 \\frac{2}{3}-3 \\frac{1}{6}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 4 \\(\\frac{1}{2}\\)<\/p>\n<p>Explanation:<br \/>\n\\(7 \\frac{2}{3}-3 \\frac{1}{6}\\)<br \/>\n\\(\\frac{23}{3}\\) &#8211; \\(\\frac{19}{6}\\) = \\(\\frac{46}{6}\\) &#8211; \\(\\frac{19}{6}\\)<br \/>\n= \\(\\frac{27}{6}\\) = 4 \\(\\frac{1}{2}\\)<br \/>\n\\(7 \\frac{2}{3}-3 \\frac{1}{6}\\) = 4 \\(\\frac{1}{2}\\)<\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>Find the sum or difference. Write your answer in simplest form.<\/strong><\/p>\n<p>Question 8.<br \/>\n\\(1 \\frac{3}{10}+2 \\frac{2}{5}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 3 \\(\\frac{7}{10}\\)<\/p>\n<p>Explanation:<br \/>\n\\(1 \\frac{3}{10}+2 \\frac{2}{5}\\)<br \/>\n\\(\\frac{13}{10}\\) + \\(\\frac{12}{5}\\) = \\(\\frac{13}{10}\\) + \\(\\frac{24}{10}\\)<br \/>\n= \\(\\frac{37}{10}\\) = 3 \\(\\frac{7}{10}\\)<br \/>\nThus \\(1 \\frac{3}{10}+2 \\frac{2}{5}\\) = 3 \\(\\frac{7}{10}\\)<\/p>\n<p>Question 9.<br \/>\n\\(3 \\frac{4}{9}+3 \\frac{1}{2}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 6 \\(\\frac{17}{18}\\)<\/p>\n<p>Explanation:<br \/>\n\\(3 \\frac{4}{9}+3 \\frac{1}{2}\\)<br \/>\n\\(\\frac{31}{9}\\) + \\(\\frac{7}{2}\\) = \\(\\frac{62}{18}\\) + \\(\\frac{63}{18}\\)<br \/>\n\\(\\frac{125}{18}\\) = 6 \\(\\frac{17}{18}\\)<br \/>\n\\(3 \\frac{4}{9}+3 \\frac{1}{2}\\) = 6 \\(\\frac{17}{18}\\)<\/p>\n<p>Question 10.<br \/>\n\\(2 \\frac{1}{2}+2 \\frac{1}{3}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 4 \\(\\frac{5}{6}\\)<\/p>\n<p>Explanation:<br \/>\n\\(2 \\frac{1}{2}+2 \\frac{1}{3}\\) = \\(\\frac{5}{2}\\) + \\(\\frac{7}{3}\\)<br \/>\n\\(\\frac{15}{6}\\) + \\(\\frac{14}{6}\\)= \\(\\frac{29}{6}\\)<br \/>\nThe mixed fraction of \\(\\frac{29}{6}\\) is 4 \\(\\frac{5}{6}\\)<\/p>\n<p>Question 11.<br \/>\n\\(5 \\frac{1}{4}+9 \\frac{1}{3}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 14 \\(\\frac{7}{12}\\)<\/p>\n<p>Explanation:<br \/>\n\\(5 \\frac{1}{4}+9 \\frac{1}{3}\\) = \\(\\frac{21}{4}\\) + \\(\\frac{28}{3}\\)<br \/>\n\\(\\frac{63}{12}\\) + \\(\\frac{112}{12}\\) = \\(\\frac{175}{12}\\)<br \/>\nThe mixed fraction of \\(\\frac{175}{12}\\) is 14 \\(\\frac{7}{12}\\)<\/p>\n<p>Question 12.<br \/>\n\\(8 \\frac{1}{6}+7 \\frac{3}{8}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 15 \\(\\frac{13}{24}\\)<\/p>\n<p>Explanation:<br \/>\n\\(8 \\frac{1}{6}+7 \\frac{3}{8}\\) = \\(\\frac{49}{6}\\) + \\(\\frac{59}{8}\\)<br \/>\n\\(\\frac{196}{24}\\) + \\(\\frac{177}{24}\\) = \\(\\frac{373}{24}\\)<br \/>\nThe mixed fraction of \\(\\frac{373}{24}\\) is 15 \\(\\frac{13}{24}\\)<\/p>\n<p>Question 13.<br \/>\n\\(14 \\frac{7}{12}-5 \\frac{1}{4}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 9 \\(\\frac{1}{3}\\)<\/p>\n<p>Explanation:<br \/>\n\\(14 \\frac{7}{12}-5 \\frac{1}{4}\\) = \\(\\frac{175}{12}\\) &#8211; \\(\\frac{21}{4}\\)<br \/>\n\\(\\frac{175}{12}\\) &#8211; \\(\\frac{63}{12}\\) = \\(\\frac{112}{12}\\)<br \/>\nThe mixed fraction of \\(\\frac{112}{12}\\) is 9 \\(\\frac{1}{3}\\)<\/p>\n<p>Question 14.<br \/>\n\\(12 \\frac{3}{4}-6 \\frac{1}{6}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 6 \\(\\frac{7}{12}\\)<\/p>\n<p>Explanation:<br \/>\n\\(12 \\frac{3}{4}-6 \\frac{1}{6}\\) = \\(\\frac{51}{4}\\) &#8211; \\(\\frac{37}{6}\\)<br \/>\n\\(\\frac{153}{12}\\) &#8211; \\(\\frac{74}{12}\\) = \\(\\frac{79}{12}\\)<br \/>\nThe mixed fraction of \\(\\frac{79}{12}\\) is 6 \\(\\frac{7}{12}\\)<\/p>\n<p>Question 15.<br \/>\n\\(2 \\frac{5}{8}-1 \\frac{1}{4}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 1 \\(\\frac{3}{8}\\)<\/p>\n<p>Explanation:<br \/>\n\\(2 \\frac{5}{8}-1 \\frac{1}{4}\\)<br \/>\n\\(\\frac{21}{8}\\) &#8211; \\(\\frac{5}{4}\\) = \\(\\frac{21}{8}\\) &#8211; \\(\\frac{10}{8}\\)<br \/>\n= \\(\\frac{11}{8}\\)<br \/>\nThe mixed fraction of \\(\\frac{11}{8}\\) is 1 \\(\\frac{3}{8}\\)<\/p>\n<p>Question 16.<br \/>\n\\(10 \\frac{1}{2}-2 \\frac{1}{5}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 8 \\(\\frac{3}{10}\\)<\/p>\n<p>Explanation:<br \/>\n\\(10 \\frac{1}{2}-2 \\frac{1}{5}\\) = \\(\\frac{21}{2}\\) &#8211; \\(\\frac{11}{5}\\)<br \/>\n\\(\\frac{105}{10}\\) &#8211; \\(\\frac{22}{10}\\) = \\(\\frac{83}{10}\\)<br \/>\nThe mixed fraction of \\(\\frac{83}{10}\\) is 8 \\(\\frac{3}{10}\\)<\/p>\n<p><strong>Practice: Copy and Solve Find the sum or difference. Write your answer in simplest form.<\/strong><\/p>\n<p>Question 17.<br \/>\n\\(1 \\frac{5}{12}+4 \\frac{1}{6}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 5 \\(\\frac{7}{12}\\)<\/p>\n<p>Explanation:<br \/>\n\\(1 \\frac{5}{12}+4 \\frac{1}{6}\\) = \\(\\frac{17}{12}\\) + \\(\\frac{25}{6}\\)<br \/>\n\\(\\frac{17}{12}\\) + \\(\\frac{50}{12}\\) = \\(\\frac{67}{12}\\)<br \/>\nThe mixed fraction of \\(\\frac{67}{12}\\) is 5 \\(\\frac{7}{12}\\)<\/p>\n<p>Question 18.<br \/>\n\\(8 \\frac{1}{2}+6 \\frac{3}{5}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 15 \\(\\frac{1}{10}\\)<\/p>\n<p>Explanation:<br \/>\n\\(8 \\frac{1}{2}+6 \\frac{3}{5}\\) = \\(\\frac{17}{2}\\) + \\(\\frac{33}{5}\\)<br \/>\n\\(\\frac{85}{10}\\) + \\(\\frac{66}{10}\\) = \\(\\frac{151}{10}\\)<br \/>\nThe mixed fraction of \\(\\frac{151}{10}\\) is 15 \\(\\frac{1}{10}\\)<br \/>\n\\(8 \\frac{1}{2}+6 \\frac{3}{5}\\) = 15 \\(\\frac{1}{10}\\)<\/p>\n<p>Question 19.<br \/>\n\\(2 \\frac{1}{6}+4 \\frac{5}{9}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 6 \\(\\frac{13}{18}\\)<\/p>\n<p>Explanation:<br \/>\n\\(2 \\frac{1}{6}+4 \\frac{5}{9}\\) = \\(\\frac{13}{6}\\) + \\(\\frac{41}{9}\\)<br \/>\n\\(\\frac{39}{18}\\) + \\(\\frac{82}{18}\\) = \\(\\frac{121}{18}\\)<br \/>\nThe mixed fraction of \\(\\frac{121}{18}\\) is 6 \\(\\frac{13}{18}\\)<br \/>\n\\(2 \\frac{1}{6}+4 \\frac{5}{9}\\) = 6 \\(\\frac{13}{18}\\)<\/p>\n<p>Question 20.<br \/>\n\\(20 \\frac{5}{8}+\\frac{5}{12}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 21 \\(\\frac{1}{24}\\)<\/p>\n<p>Explanation:<br \/>\n\\(20 \\frac{5}{8}+\\frac{5}{12}\\) = \\(\\frac{165}{8}\\) + \\(\\frac{5}{12}\\)<br \/>\n\\(\\frac{495}{24}\\) + \\(\\frac{10}{24}\\) = \\(\\frac{505}{24}\\)<br \/>\nThe mixed fraction of \\(\\frac{505}{24}\\) is 21 \\(\\frac{1}{24}\\)<br \/>\n\\(20 \\frac{5}{8}+\\frac{5}{12}\\) = 21 \\(\\frac{1}{24}\\)<\/p>\n<p>Question 21.<br \/>\n\\(3 \\frac{2}{3}-1 \\frac{1}{6}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 2 \\(\\frac{1}{2}\\)<\/p>\n<p>Explanation:<br \/>\n\\(3 \\frac{2}{3}-1 \\frac{1}{6}\\) = \\(\\frac{11}{3}\\) &#8211; \\(\\frac{7}{6}\\)<br \/>\n\\(\\frac{22}{6}\\) &#8211; \\(\\frac{7}{6}\\) = \\(\\frac{15}{6}\\) = \\(\\frac{5}{2}\\)<br \/>\nThe mixed fraction of \\(\\frac{5}{2}\\) is 2 \\(\\frac{1}{2}\\)<br \/>\n\\(3 \\frac{2}{3}-1 \\frac{1}{6}\\) = 2 \\(\\frac{1}{2}\\)<\/p>\n<p>Question 22.<br \/>\n\\(5 \\frac{6}{7}-1 \\frac{2}{3}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 4 \\(\\frac{4}{21}\\)<\/p>\n<p>Explanation:<br \/>\n\\(5 \\frac{6}{7}-1 \\frac{2}{3}\\) = \\(\\frac{41}{7}\\) &#8211; \\(\\frac{5}{3}\\)<br \/>\n\\(\\frac{123}{21}\\) &#8211; \\(\\frac{35}{21}\\) = \\(\\frac{88}{21}\\)<br \/>\nThe mixed fraction of \\(\\frac{88}{21}\\) is 4 \\(\\frac{4}{21}\\)<\/p>\n<p>Question 23.<br \/>\n\\(2 \\frac{7}{8}-\\frac{1}{2}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 2 \\(\\frac{3}{8}\\)<\/p>\n<p>Explanation:<br \/>\n\\(2 \\frac{7}{8}-\\frac{1}{2}\\) = \\(\\frac{23}{8}\\) &#8211; \\(\\frac{1}{2}\\)<br \/>\n= \\(\\frac{23}{8}\\) &#8211; \\(\\frac{4}{8}\\) = \\(\\frac{19}{8}\\)<br \/>\nThe mixed fraction of \\(\\frac{19}{8}\\) is 2 \\(\\frac{3}{8}\\)<br \/>\nSo, \\(2 \\frac{7}{8}-\\frac{1}{2}\\) = 2 \\(\\frac{3}{8}\\)<\/p>\n<p>Question 24.<br \/>\n\\(4 \\frac{7}{12}-1 \\frac{2}{9}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 3 \\(\\frac{13}{36}\\)<\/p>\n<p>Explanation:<br \/>\n\\(4 \\frac{7}{12}-1 \\frac{2}{9}\\) = \\(\\frac{55}{12}\\) &#8211; \\(\\frac{11}{9}\\)<br \/>\n\\(\\frac{165}{36}\\) &#8211; \\(\\frac{44}{36}\\) = \\(\\frac{121}{36}\\)<br \/>\nThe mixed fraction of \\(\\frac{121}{36}\\) is 3 \\(\\frac{13}{36}\\)<\/p>\n<h3><a id=\"Problem_Solving_Page_No_268\"><\/a>Problem Solving &#8211; Page No. 268<\/h3>\n<p><strong>Use the table to solve 25\u201328.<\/strong><br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-19.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators img 19\" width=\"320\" height=\"414\" \/><\/p>\n<p>Question 25.<br \/>\nGavin is mixing a batch of Sunrise Orange paint for an art project. How much paint does Gavin mix?<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\) ounces<\/p>\n<p>Answer: 5 \\(\\frac{7}{8}\\) ounces<\/p>\n<p>Explanation:<br \/>\nGavin is mixing a batch of Sunrise Orange paint for an art project.<br \/>\n2 \\(\\frac{5}{8}\\) + 3 \\(\\frac{1}{4}\\)<br \/>\nSolving the whole numbers<br \/>\n2 + 3 = 5<br \/>\nAdd the fraction parts<br \/>\n\\(\\frac{5}{8}\\) + \\(\\frac{1}{4}\\)<br \/>\nLCD = 8<br \/>\n\\(\\frac{5}{8}\\) + \\(\\frac{2}{8}\\) = \\(\\frac{7}{8}\\)<br \/>\n5 + \\(\\frac{7}{8}\\) = 5 \\(\\frac{7}{8}\\) ounces<\/p>\n<p>Question 26.<br \/>\nGavin plans to mix a batch of Tangerine paint. He expects to have a total of 5 \\(\\frac{3}{10}\\) ounces of paint after he mixes the amounts of red and yellow. Explain how you can tell if Gavin\u2019s expectation is reasonable.<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer:<br \/>\nGavin plans to mix a batch of Tangerine paint. He expects to have a total of 5 \\(\\frac{3}{10}\\) ounces of paint after he mixes the amounts of red and yellow.<br \/>\nTo mix a batch of Tangerine paint he need 3 \\(\\frac{9}{10}\\) red and 2 \\(\\frac{3}{8}\\) yellow paint.<br \/>\nAdd the fractions<br \/>\n3 + \\(\\frac{9}{10}\\) + 2 + \\(\\frac{3}{8}\\)<br \/>\nSolving the whole numbers<br \/>\n3 + 2 = 5<br \/>\n\\(\\frac{9}{10}\\) + \\(\\frac{3}{8}\\)<br \/>\nLCD = 40<br \/>\n\\(\\frac{9}{10}\\) + \\(\\frac{3}{8}\\) = \\(\\frac{36}{40}\\) + \\(\\frac{15}{40}\\) = \\(\\frac{51}{40}\\) = 1 \\(\\frac{11}{40}\\)<br \/>\n5 + 1 \\(\\frac{11}{40}\\) = 6 \\(\\frac{11}{40}\\)<\/p>\n<p>Question 27.<br \/>\nFor a special project, Gavin mixes the amount of red from one shade of paint with the amount of yellow from a different shade. He mixes the batch so he will have the greatest possible amount of paint. What amounts of red and yellow from which shades are used in the mixture for the special project? Explain your answer.<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer:<br \/>\nGavin used red paint from mango and yellow paint from Sunrise Orange.<br \/>\n5 \\(\\frac{5}{6}\\) + 3 \\(\\frac{1}{4}\\)<br \/>\nSolving the whole numbers parts<br \/>\n5 + 3 = 8<br \/>\nSolving the fraction part<br \/>\n\\(\\frac{5}{6}\\) + \\(\\frac{1}{4}\\)<br \/>\nLCD = 12<br \/>\n\\(\\frac{10}{12}\\) + \\(\\frac{3}{12}\\) = \\(\\frac{13}{12}\\)<br \/>\n\\(\\frac{13}{12}\\) = 1 \\(\\frac{1}{12}\\)<\/p>\n<p>Question 28.<br \/>\nGavin needs to make 2 batches of Mango paint. Explain how you could find the total amount of paint Gavin mixed.<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer:<br \/>\nGavin used Red paint and Yellow Paint to make Mango shade.<br \/>\nFor one batch he need to add 5 \\(\\frac{5}{6}\\) + 5 \\(\\frac{5}{6}\\)<br \/>\nFoe 2 batches<br \/>\n5 \\(\\frac{5}{6}\\)+ 5 \\(\\frac{5}{6}\\) + 5 \\(\\frac{5}{6}\\) + 5 \\(\\frac{5}{6}\\)<br \/>\nSolving the whole numbers<br \/>\n5 + 5 + 5 + 5 = 20<br \/>\nSolving the fractions part<br \/>\n\\(\\frac{5}{6}\\) + \\(\\frac{5}{6}\\) + \\(\\frac{5}{6}\\) + \\(\\frac{5}{6}\\) = \\(\\frac{20}{6}\\)<br \/>\n= \\(\\frac{10}{3}\\)<br \/>\nGavin mixed \\(\\frac{10}{3}\\) of paint to make 2 batches of Mango Paint.<\/p>\n<p>Question 29.<br \/>\nTest Prep Yolanda walked 3 \\(\\frac{6}{10}\\) miles. Then she walked 4 \\(\\frac{1}{2}\\) more miles. How many miles did Yolanda walk?<br \/>\nOptions:<br \/>\na. 7 \\(\\frac{1}{10}\\) miles<br \/>\nb. 7 \\(\\frac{7}{10}\\) miles<br \/>\nc. 8 \\(\\frac{1}{10}\\) miles<br \/>\nd. 8 \\(\\frac{7}{10}\\) miles<\/p>\n<p>Answer: 8 \\(\\frac{1}{10}\\) miles<\/p>\n<p>Explanation:<br \/>\nTest Prep Yolanda walked 3 \\(\\frac{6}{10}\\) miles.<br \/>\nThen she walked 4 \\(\\frac{1}{2}\\) more miles.<br \/>\n3 \\(\\frac{6}{10}\\) + 4 \\(\\frac{1}{2}\\) = 3 + \\(\\frac{6}{10}\\) + 4 + \\(\\frac{1}{2}\\)<br \/>\nAdd whole numbers<br \/>\n3 + 4 = 7<br \/>\nAdd the fractions<br \/>\n\\(\\frac{6}{10}\\) + \\(\\frac{1}{2}\\)<br \/>\nLCD = 10<br \/>\n\\(\\frac{6}{10}\\) + \\(\\frac{5}{10}\\) = \\(\\frac{11}{10}\\)<br \/>\n\\(\\frac{11}{10}\\) = 8 \\(\\frac{1}{10}\\) miles<br \/>\nThus the correct answer is option C.<\/p>\n<h3><a id=\"Share_and_Show_Page_No_270\"><\/a>Share and Show &#8211; Page No. 270<\/h3>\n<p><strong>Estimate. Then find the difference and write it in simplest form.<\/strong><\/p>\n<p>Question 1.<br \/>\nEstimate: ______<br \/>\n1 \\(\\frac{3}{4}-\\frac{7}{8}\\)<br \/>\nEstimate: _____ \\(\\frac{\u25a1}{\u25a1}\\)<br \/>\nDifference: _____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\nEstimate: 1<br \/>\nDifference: \\(\\frac{7}{8}\\)<\/p>\n<p>Explanation:<br \/>\nEstimation: 1 + \\(\\frac{3}{4}\\) &#8211; \\(\\frac{7}{8}\\)<br \/>\n\\(\\frac{7}{8}\\) is close to 1.<br \/>\n\\(\\frac{3}{4}\\) is close to 1.<br \/>\n1 + 1 &#8211; 1 = 1<br \/>\nDifference: 1 \\(\\frac{3}{4}-\\frac{7}{8}\\)<br \/>\n1 + \\(\\frac{3}{4}\\) &#8211; \\(\\frac{7}{8}\\)<br \/>\n\\(\\frac{3}{4}\\) &#8211; \\(\\frac{7}{8}\\)<br \/>\n\\(\\frac{3}{4}\\) \u00d7 \\(\\frac{8}{8}\\) &#8211; \\(\\frac{7}{8}\\) \u00d7 \\(\\frac{4}{4}\\)<br \/>\n\\(\\frac{24}{32}\\) &#8211; \\(\\frac{28}{32}\\) = &#8211; \\(\\frac{1}{8}\\)<br \/>\n1 &#8211; \\(\\frac{1}{8}\\) = \\(\\frac{7}{8}\\)<\/p>\n<p>Question 2.<br \/>\nEstimate: ______<br \/>\n\\(12 \\frac{1}{9}-7 \\frac{1}{3}\\)<br \/>\nEstimate: _____ \\(\\frac{\u25a1}{\u25a1}\\)<br \/>\nDifference: _____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\nEstimate: 5<br \/>\nDifference: 4 \\(\\frac{7}{9}\\)<\/p>\n<p>Explanation:<br \/>\nEstimate: 12 + 0 &#8211; 7 &#8211; 0 = 5<br \/>\nDifference:<br \/>\n12 + \\(\\frac{1}{9}\\) &#8211; 7 &#8211; \\(\\frac{1}{3}\\)<br \/>\n12 &#8211; 7 = 5<br \/>\n\\(\\frac{1}{9}\\) &#8211; \\(\\frac{1}{3}\\) = \\(\\frac{1}{9}\\) &#8211; \\(\\frac{3}{9}\\) = &#8211; \\(\\frac{2}{9}\\)<br \/>\n5 &#8211; \\(\\frac{2}{9}\\) = 4 \\(\\frac{7}{9}\\)<\/p>\n<h3><a id=\"Subtraction_with_Renaming_Page_No_271\"><\/a>Page No. 271<\/h3>\n<p><strong>Estimate. Then find the difference and write it in simplest form.<\/strong><\/p>\n<p>Question 3.<br \/>\nEstimate: ________<br \/>\n\\(4 \\frac{1}{2}-3 \\frac{4}{5}\\)<br \/>\nEstimate: _____ \\(\\frac{\u25a1}{\u25a1}\\)<br \/>\nDifference: _____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\nEstimate: \\(\\frac{1}{2}\\)<br \/>\nDifference: \\(\\frac{7}{10}\\)<\/p>\n<p>Explanation:<br \/>\n\\(4 \\frac{1}{2}-3 \\frac{4}{5}\\)<br \/>\n4 &#8211; \\(\\frac{1}{2}\\) &#8211; 3 &#8211; 1<br \/>\n= \\(\\frac{1}{2}\\)<br \/>\nDifference:<br \/>\n\\(4 \\frac{1}{2}-3 \\frac{4}{5}\\)<br \/>\n4 \\(\\frac{1}{2}\\) &#8211; 3 \\(\\frac{4}{5}\\)<br \/>\nSolving the whole number parts<br \/>\n4 &#8211; 3 = 1<br \/>\nSolving the fraction parts<br \/>\n\\(\\frac{1}{2}\\) &#8211; \\(\\frac{4}{5}\\)<br \/>\nLCD = 10<br \/>\n\\(\\frac{5}{10}\\) &#8211; \\(\\frac{8}{10}\\) = &#8211; \\(\\frac{3}{10}\\)<br \/>\n1 &#8211; \\(\\frac{3}{10}\\) = \\(\\frac{7}{10}\\)<\/p>\n<p>Question 4.<br \/>\nEstimate: ________<br \/>\n\\(9 \\frac{1}{6}-2 \\frac{3}{4}\\)<br \/>\nEstimate: _____ \\(\\frac{\u25a1}{\u25a1}\\)<br \/>\nDifference: _____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\nEstimate: 6<br \/>\nDifference: 6 \\(\\frac{5}{12}\\)<\/p>\n<p>Explanation:<br \/>\n\\(9 \\frac{1}{6}-2 \\frac{3}{4}\\)<br \/>\n9 + 0 &#8211; 2 &#8211; 1 = 6<br \/>\nDifference:<br \/>\n\\(9 \\frac{1}{6}-2 \\frac{3}{4}\\)<br \/>\n9 + \\(\\frac{1}{6}\\) &#8211; 2 &#8211; \\(\\frac{3}{4}\\)<br \/>\n9 &#8211; 2 = 7<br \/>\n\\(\\frac{1}{6}\\) &#8211; \\(\\frac{3}{4}\\)<br \/>\nLCD = 12<br \/>\n\\(\\frac{2}{12}\\) &#8211; \\(\\frac{9}{12}\\) = &#8211; \\(\\frac{7}{12}\\)<br \/>\n7 &#8211; \\(\\frac{7}{12}\\) = 6 \\(\\frac{5}{12}\\)<br \/>\n\\(9 \\frac{1}{6}-2 \\frac{3}{4}\\) = 6 \\(\\frac{5}{12}\\)<\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>Estimate. Then find the difference and write it in simplest form.<\/strong><\/p>\n<p>Question 5.<br \/>\nEstimate: ________<br \/>\n\\(3 \\frac{2}{3}-1 \\frac{11}{12}\\)<br \/>\nEstimate: _____ \\(\\frac{\u25a1}{\u25a1}\\)<br \/>\nDifference: _____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\nEstimate: 2<br \/>\nDifference: 1 \\(\\frac{3}{4}\\)<\/p>\n<p>Explanation:<br \/>\nEstimate:<br \/>\n\\(3 \\frac{2}{3}-1 \\frac{11}{12}\\)<br \/>\n\\(\\frac{2}{3}\\) is close to 1.<br \/>\n\\(\\frac{11}{12}\\) is close to 1.<br \/>\n3 + 1 &#8211; 1 &#8211; 1 = 2<br \/>\nDifference:<br \/>\n\\(3 \\frac{2}{3}-1 \\frac{11}{12}\\)<br \/>\n3 + \\(\\frac{2}{3}\\) &#8211; 1 &#8211; \\(\\frac{11}{12}\\)<br \/>\n3 &#8211; 1 = 2<br \/>\nSolving the fractions part<br \/>\n\\(\\frac{2}{3}\\) &#8211; \\(\\frac{11}{12}\\)<br \/>\nLCD = 12<br \/>\n\\(\\frac{8}{12}\\) &#8211; \\(\\frac{11}{12}\\) = &#8211; \\(\\frac{3}{12}\\) = &#8211; \\(\\frac{1}{4}\\)<br \/>\n3 &#8211; \\(\\frac{1}{4}\\) = 1 \\(\\frac{3}{4}\\)<br \/>\n\\(3 \\frac{2}{3}-1 \\frac{11}{12}\\) = 1 \\(\\frac{3}{4}\\)<\/p>\n<p>Question 6.<br \/>\nEstimate: ________<br \/>\n\\(4 \\frac{1}{4}-2 \\frac{1}{3}\\)<br \/>\nEstimate: _____ \\(\\frac{\u25a1}{\u25a1}\\)<br \/>\nDifference: _____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\nEstimate: 2<br \/>\nDifference: 1 \\(\\frac{11}{12}\\)<\/p>\n<p>Explanation:<br \/>\n\\(4 \\frac{1}{4}-2 \\frac{1}{3}\\)<br \/>\n\\(\\frac{1}{4}\\) is close to 0.<br \/>\n\\(\\frac{1}{3}\\) is close to 0.<br \/>\n4 &#8211; 2 = 2<br \/>\nSolving the fractions part<br \/>\n\\(\\frac{1}{4}\\) &#8211; \\(\\frac{1}{3}\\)<br \/>\nLCD = 12<br \/>\n\\(\\frac{1}{4}\\) \u00d7 \\(\\frac{3}{3}\\) &#8211; \\(\\frac{1}{3}\\) \u00d7 \\(\\frac{4}{4}\\)<br \/>\n\\(\\frac{3}{12}\\) &#8211; \\(\\frac{4}{12}\\) = &#8211; \\(\\frac{1}{12}\\)<br \/>\n2 &#8211; \\(\\frac{1}{12}\\) = 1 \\(\\frac{11}{12}\\)<\/p>\n<p>Question 7.<br \/>\nEstimate: ________<br \/>\n\\(5 \\frac{2}{5}-1 \\frac{1}{2}\\)<br \/>\nEstimate: _____ \\(\\frac{\u25a1}{\u25a1}\\)<br \/>\nDifference: _____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\nEstimate: 4<br \/>\nDifference: 3 \\(\\frac{9}{10}\\)<\/p>\n<p>Explanation:<br \/>\nEstimate:<br \/>\n\\(5 \\frac{2}{5}-1 \\frac{1}{2}\\)<br \/>\n5 + \\(\\frac{1}{2}\\) &#8211; 1 &#8211; \\(\\frac{1}{2}\\)<br \/>\n5 &#8211; 1 = 4<br \/>\nSolving the fractions part<br \/>\n\\(5 \\frac{2}{5}-1 \\frac{1}{2}\\)<br \/>\nLCD = 10<br \/>\n\\(\\frac{4}{10}\\) &#8211; \\(\\frac{5}{10}\\) = &#8211; \\(\\frac{1}{10}\\)<br \/>\n4 &#8211; \\(\\frac{1}{10}\\) = 3 \\(\\frac{9}{10}\\)<\/p>\n<p>Question 8.<br \/>\n\\(7 \\frac{5}{9}-2 \\frac{5}{6}\\)<br \/>\nEstimate: _____ \\(\\frac{\u25a1}{\u25a1}\\)<br \/>\nDifference: _____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\nEstimate: 4 \\(\\frac{1}{2}\\)<br \/>\nDifference: 4 \\(\\frac{13}{18}\\)<\/p>\n<p>Explanation:<br \/>\nEstimate:<br \/>\n\\(7 \\frac{5}{9}-2 \\frac{5}{6}\\)<br \/>\n\\(\\frac{5}{9}\\) is close to \\(\\frac{1}{2}\\)<br \/>\n\\(\\frac{5}{6}\\) is close to 1.<br \/>\n7 + \\(\\frac{1}{2}\\) &#8211; 2 &#8211; 1<br \/>\n4 \\(\\frac{1}{2}\\)<br \/>\nDifference:<br \/>\n\\(7 \\frac{5}{9}-2 \\frac{5}{6}\\)<br \/>\n7 + \\(\\frac{5}{9}\\) &#8211; 2 &#8211; \\(\\frac{5}{6}\\)<br \/>\nSolving the whole numbers<br \/>\n7 &#8211; 2 = 5<br \/>\nSolving the fraction part<br \/>\n\\(\\frac{5}{9}\\) &#8211; \\(\\frac{5}{6}\\)<br \/>\nLCD = 18<br \/>\n\\(\\frac{10}{18}\\) &#8211; \\(\\frac{15}{18}\\) = &#8211; \\(\\frac{5}{18}\\)<br \/>\n5 &#8211; \\(\\frac{5}{18}\\) = 4 \\(\\frac{13}{18}\\)<\/p>\n<p>Question 9.<br \/>\nEstimate: ________<br \/>\n\\(7-5 \\frac{2}{3}\\)<br \/>\nEstimate: _____ \\(\\frac{\u25a1}{\u25a1}\\)<br \/>\nDifference: _____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\nEstimate: 1<br \/>\nDifference: 1 \\(\\frac{1}{3}\\)<\/p>\n<p>Explanation:<br \/>\nEstimate:<br \/>\n\\(7-5 \\frac{2}{3}\\)<br \/>\n7 &#8211; 5 &#8211; \\(\\frac{2}{3}\\)<br \/>\n7 &#8211; 5 &#8211; 1 = 1<br \/>\nDifference:<br \/>\n\\(7-5 \\frac{2}{3}\\)<br \/>\n7 &#8211; 5 = 2<br \/>\n2 &#8211; \\(\\frac{2}{3}\\) = 1 \\(\\frac{1}{3}\\)<br \/>\nThus \\(7-5 \\frac{2}{3}\\) = 1 \\(\\frac{1}{3}\\)<\/p>\n<p>Question 10.<br \/>\nEstimate: ________<br \/>\n\\(2 \\frac{1}{5}-1 \\frac{9}{10}\\)<br \/>\nEstimate: _____ \\(\\frac{\u25a1}{\u25a1}\\)<br \/>\nDifference: _____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\nEstimate: 0<br \/>\nDifference: \\(\\frac{3}{10}\\)<\/p>\n<p>Explanation:<br \/>\nEstimate:<br \/>\n\\(2 \\frac{1}{5}-1 \\frac{9}{10}\\)<br \/>\n2 + 0 &#8211; 1 &#8211; 1 = 0<br \/>\nDifference:<br \/>\n\\(2 \\frac{1}{5}-1 \\frac{9}{10}\\)<br \/>\n2 \\(\\frac{1}{5}\\) &#8211; 1 \\(\\frac{9}{10}\\)<br \/>\n2 + \\(\\frac{1}{5}\\)\u00a0&#8211; 1 &#8211; \\(\\frac{9}{10}\\)<br \/>\nSolving the whole number parts<br \/>\n2 &#8211; 1 = 1<br \/>\n\\(\\frac{1}{5}\\) &#8211; \\(\\frac{9}{10}\\)<br \/>\nLCD = 10<br \/>\n\\(\\frac{2}{10}\\) &#8211; \\(\\frac{9}{10}\\) = &#8211; \\(\\frac{7}{10}\\)<br \/>\n1 &#8211; \\(\\frac{7}{10}\\) = \\(\\frac{3}{10}\\)<\/p>\n<p><strong>Practice: Copy and Solve Find the difference and write it in simplest form.<\/strong><\/p>\n<p>Question 11.<br \/>\n\\(11 \\frac{1}{9}-3 \\frac{2}{3}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 7 \\(\\frac{4}{9}\\)<\/p>\n<p>Explanation:<br \/>\nRewriting our equation with parts separated<br \/>\n11 + \\(\\frac{1}{9}\\) &#8211; 3 &#8211; \\(\\frac{2}{3}\\)<br \/>\nSolving the whole number parts<br \/>\n11 &#8211; 3 = 8<br \/>\nSolving the fraction parts<br \/>\nLCD = 9<br \/>\n\\(\\frac{1}{9}\\) &#8211; \\(\\frac{2}{3}\\)<br \/>\n\\(\\frac{1}{9}\\) &#8211; \\(\\frac{6}{9}\\) = &#8211; \\(\\frac{5}{9}\\)<br \/>\n8 &#8211; \\(\\frac{5}{9}\\) = 7 \\(\\frac{4}{9}\\)<\/p>\n<p>Question 12.<br \/>\n\\(6-3 \\frac{1}{2}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 2 \\(\\frac{1}{2}\\)<\/p>\n<p>Explanation:<br \/>\nRewriting our equation with parts separated<br \/>\n6 &#8211; 3 &#8211; \\(\\frac{1}{2}\\)<br \/>\n3 &#8211; \\(\\frac{1}{2}\\) = 2 \\(\\frac{1}{2}\\)<\/p>\n<p>Question 13.<br \/>\n\\(4 \\frac{3}{8}-3 \\frac{1}{2}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{7}{8}\\)<\/p>\n<p>Explanation:<br \/>\nRewriting our equation with parts separated<br \/>\n4 + \\(\\frac{3}{8}\\) &#8211; 3 &#8211; \\(\\frac{1}{2}\\)<br \/>\nSolving the whole number parts<br \/>\n4 &#8211; 3 = 1<br \/>\nSolving the fraction parts<br \/>\n\\(\\frac{3}{8}\\) &#8211; \\(\\frac{1}{2}\\) = \\(\\frac{3}{8}\\) &#8211; \\(\\frac{4}{8}\\)<br \/>\n= &#8211; \\(\\frac{1}{8}\\)<br \/>\n1 &#8211; \\(\\frac{1}{8}\\) = \\(\\frac{7}{8}\\)<\/p>\n<p>Question 14.<br \/>\n\\(9 \\frac{1}{6}-3 \\frac{5}{8}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 5 \\(\\frac{13}{24}\\)<\/p>\n<p>Explanation:<br \/>\nRewriting our equation with parts separated<br \/>\n9 + \\(\\frac{1}{6}\\) &#8211; 3 &#8211; \\(\\frac{5}{8}\\)<br \/>\nSolving the whole number parts<br \/>\n9 &#8211; 3 = 6<br \/>\nSolving the fraction parts<br \/>\n\\(\\frac{1}{6}\\) &#8211; \\(\\frac{5}{8}\\)<br \/>\n\\(\\frac{4}{24}\\) &#8211; \\(\\frac{15}{24}\\) = &#8211; \\(\\frac{11}{24}\\)<br \/>\n6 &#8211; \\(\\frac{11}{24}\\) = 5 \\(\\frac{13}{24}\\)<\/p>\n<p>Question 15.<br \/>\n\\(1 \\frac{1}{5}-\\frac{1}{2}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: \\(\\frac{7}{10}\\)<\/p>\n<p>Explanation:<br \/>\nRewriting our equation with parts separated<br \/>\n1 + \\(\\frac{1}{5}\\) &#8211; \\(\\frac{1}{2}\\)<br \/>\nSolving the whole number parts<br \/>\n1 + 0 = 1<br \/>\nSolving the fraction parts<br \/>\n\\(\\frac{1}{5}\\) &#8211; \\(\\frac{1}{2}\\)<br \/>\nLCD = 10<br \/>\n\\(\\frac{2}{10}\\) &#8211; \\(\\frac{5}{10}\\) = &#8211; \\(\\frac{3}{10}\\)<br \/>\n1 &#8211; \\(\\frac{3}{10}\\) = \\(\\frac{7}{10}\\)<\/p>\n<p>Question 16.<br \/>\n\\(13 \\frac{1}{6}-3 \\frac{4}{5}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 9 \\(\\frac{11}{30}\\)<\/p>\n<p>Explanation:<br \/>\nRewriting our equation with parts separated<br \/>\n13 + \\(\\frac{1}{6}\\) &#8211; 3 &#8211; \\(\\frac{4}{5}\\)<br \/>\nSolving the whole number parts<br \/>\n13 &#8211; 3 = 10<br \/>\nSolving the fraction parts<br \/>\n\\(\\frac{1}{6}\\) &#8211; \\(\\frac{4}{5}\\)<br \/>\nLCD = 30<br \/>\n\\(\\frac{5}{30}\\) &#8211; \\(\\frac{24}{30}\\) = &#8211; \\(\\frac{19}{30}\\)<br \/>\n10 &#8211; \\(\\frac{19}{30}\\) = 9 \\(\\frac{11}{30}\\)<\/p>\n<p>Question 17.<br \/>\n\\(12 \\frac{2}{5}-5 \\frac{3}{4}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 6 \\(\\frac{13}{20}\\)<\/p>\n<p>Explanation:<br \/>\nRewriting our equation with parts separated<br \/>\n12 + \\(\\frac{2}{5}\\) &#8211; 5 &#8211; \\(\\frac{3}{4}\\)<br \/>\nSolving the whole number parts<br \/>\n12 &#8211; 5 = 7<br \/>\nSolving the fraction parts<br \/>\n\\(\\frac{2}{5}\\) &#8211; \\(\\frac{3}{4}\\)<br \/>\nLCD = 20<br \/>\n\\(\\frac{8}{20}\\) &#8211; \\(\\frac{15}{20}\\) = &#8211; \\(\\frac{7}{20}\\)<br \/>\n7 &#8211; \\(\\frac{7}{20}\\) = 6 \\(\\frac{13}{20}\\)<\/p>\n<p>Question 18.<br \/>\n\\(7 \\frac{3}{8}-2 \\frac{7}{9}\\)<br \/>\n_____ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 4 \\(\\frac{43}{72}\\)<\/p>\n<p>Explanation:<br \/>\n7 + \\(\\frac{3}{8}\\) &#8211; 2 &#8211; \\(\\frac{7}{9}\\)<br \/>\n7 &#8211; 2 = 5<br \/>\n\\(\\frac{3}{8}\\) &#8211; \\(\\frac{7}{9}\\) = \\(\\frac{27}{72}\\) &#8211; \\(\\frac{56}{72}\\)<br \/>\n&#8211; \\(\\frac{29}{72}\\)<br \/>\n5 &#8211; \\(\\frac{29}{72}\\) = 4 \\(\\frac{43}{72}\\)<\/p>\n<h3><a id=\"Subtraction_with_Renaming_Page_No_272\"><\/a>Page No. 272<\/h3>\n<p><strong>Connect to Reading<\/strong><br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-20.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators img 20\" width=\"298\" height=\"380\" \/><\/p>\n<p><strong>Summarize<\/strong><br \/>\nAn amusement park in Sandusky, Ohio, offers 17 amazing roller coasters for visitors to ride. One of the roller coasters runs at 60 miles per hour and has 3,900 feet of twisting track. This coaster also has 3 trains with 8 rows per train. Riders stand in rows of 4, for a total of 32 riders per train.<\/p>\n<p>The operators of the coaster recorded the number of riders on each train during a run. On the first train, the operators reported that 7 \\(\\frac{1}{4}\\) rows were filled. On the second train, all 8 rows were filled, and on the third train, 5 \\(\\frac{1}{2}\\) rows were filled. How many more rows were filled on the first train than on the third train?<\/p>\n<p>When you summarize, you restate the most important information in a shortened form to more easily understand what you have read.<br \/>\n<strong>Summarize the information given.<\/strong><br \/>\n______________________<br \/>\n<strong>Use the summary to solve.<\/strong><\/p>\n<p>Question 19.<br \/>\nSolve the problem above.<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer:<br \/>\nOn the first train, the operators reported that 7 \\(\\frac{1}{4}\\) rows were filled.<br \/>\nOn the third train, 5 \\(\\frac{1}{2}\\) rows were filled.<br \/>\n7 \\(\\frac{1}{4}\\) &#8211; 5 \\(\\frac{1}{2}\\)<br \/>\nSolving the whole numbers<br \/>\n7 &#8211; 5 = 2<br \/>\nSolving the fractions<br \/>\n\\(\\frac{1}{4}\\) &#8211; \\(\\frac{1}{2}\\) = &#8211; \\(\\frac{1}{4}\\)<br \/>\n2 &#8211; \\(\\frac{1}{4}\\) = 1 \\(\\frac{3}{4}\\)<br \/>\n1 \\(\\frac{3}{4}\\) more rows were filled on the first train than on the third train.<\/p>\n<p>Question 20.<br \/>\nHow many rows were empty on the third train? How many additional riders would it take to fill the empty rows? Explain your answer.<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer:<br \/>\nThe coaster also has 3 trains with 8 rows per train.<br \/>\nThe third train has 8 rows.<br \/>\nOn the third train, 5 \\(\\frac{1}{2}\\) rows were filled.<br \/>\n8 &#8211; 5 \\(\\frac{1}{2}\\)<br \/>\n8 &#8211; 5 &#8211; \\(\\frac{1}{2}\\) = 2 \\(\\frac{1}{2}\\)<br \/>\n2 \\(\\frac{1}{2}\\) rows are empty.<br \/>\nSo, it takes 10 additional riders to fill the empty rows on the third train.<\/p>\n<h3><a id=\"Share_and_Show_Page_No_275\"><\/a>Share and Show &#8211; Page No. 275<\/h3>\n<p><strong>Write a rule for the sequence.<\/strong><\/p>\n<p>Question 1.<br \/>\n\\(\\frac{1}{4}, \\frac{1}{2}, \\frac{3}{4}, \\cdots\\)<br \/>\nThink: Is the sequence increasing or decreasing?<br \/>\nRule: _________<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: The sequence is increasing order with difference \\(\\frac{1}{4}\\)<\/p>\n<p>Question 2.<br \/>\n\\(\\frac{1}{9}, \\frac{1}{3}, \\frac{5}{9}, \\ldots\\)<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: The sequence is increasing order with difference 2 in numerataor.<\/p>\n<p><strong>Write a rule for the sequence. Then, find the unknown term.<\/strong><\/p>\n<p>Question 3.<br \/>\n\\(\\frac{3}{10}, \\frac{2}{5}\\), \\(\\frac{\u25a1}{\u25a1}\\) , \\(\\frac{3}{5}, \\frac{7}{10}\\)<\/p>\n<p>Answer: The sequence is increasing order with difference \\(\\frac{1}{2}\\)<br \/>\nLCD = 10<br \/>\nAdd \\(\\frac{1}{2}\\) to each term<br \/>\nLet the unknown fraction be x<br \/>\n\\(\\frac{3}{10}\\), \\(\\frac{4}{10}\\), x, \\(\\frac{6}{10}\\), \\(\\frac{7}{10}\\)<br \/>\nx = \\(\\frac{5}{10}\\) = \\(\\frac{1}{2}\\)<\/p>\n<p>Question 4.<br \/>\n\\(10 \\frac{2}{3}, 9 \\frac{11}{18}, 8 \\frac{5}{9}\\), ______ \\(\\frac{\u25a1}{\u25a1}\\) , \\(6 \\frac{4}{9}\\)<\/p>\n<p>Answer: 7 \\(\\frac{1}{2}\\)<\/p>\n<p>Explanation:<br \/>\n\\(\\frac{32}{3}\\), \\(\\frac{173}{18}\\), \\(\\frac{77}{9}\\), x, \\(\\frac{58}{9}\\)<br \/>\nLCD = 54<br \/>\n\\(\\frac{576}{54}\\), \\(\\frac{519}{54}\\), \\(\\frac{462}{54}\\), x, \\(\\frac{348}{54}\\)<br \/>\nAccording to the series x = \\(\\frac{405}{54}\\) = \\(\\frac{15}{2}\\)<br \/>\nThe mixed fraction of \\(\\frac{15}{2}\\) is 7 \\(\\frac{1}{2}\\)<\/p>\n<p>Question 5.<br \/>\n\\(1 \\frac{1}{6}\\), ______ \\(\\frac{\u25a1}{\u25a1}\\) , \\(1, \\frac{11}{12}, \\frac{5}{6}\\)<\/p>\n<p>Answer: 1 \\(\\frac{1}{12}\\)<\/p>\n<p>Explanation:<br \/>\n\\(1 \\frac{1}{6}\\), ______ \\(\\frac{\u25a1}{\u25a1}\\) , \\(1, \\frac{11}{12}, \\frac{5}{6}\\)<br \/>\nThe LCD of the above fractons is 12<br \/>\nConvert them into improper fractions<br \/>\n\\(\\frac{14}{12}\\), x, \\(\\frac{12}{12}\\), \\(\\frac{11}{12}\\), \\(\\frac{10}{12}\\)<br \/>\nAccording to the series x = \\(\\frac{13}{12}\\)<br \/>\nThe mixed fraction of \\(\\frac{13}{12}\\) is 1 \\(\\frac{1}{12}\\)<\/p>\n<p>Question 6.<br \/>\n\\(2 \\frac{3}{4}, 4,5 \\frac{1}{4}, 6 \\frac{1}{2}\\), ______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 7 \\(\\frac{3}{4}\\)<\/p>\n<p>Explanation:<br \/>\n\\(2 \\frac{3}{4}, 4,5 \\frac{1}{4}, 6 \\frac{1}{2}\\), ______ \\(\\frac{\u25a1}{\u25a1}\\)<br \/>\nConvert the mixed fractions into improper fractions<br \/>\n\\(\\frac{11}{4}\\), \\(\\frac{4}{1}\\), \\(\\frac{21}{4}\\), \\(\\frac{13}{2}\\), x<br \/>\n\\(\\frac{11}{4}\\), \\(\\frac{16}{4}\\), \\(\\frac{21}{4}\\), \\(\\frac{26}{4}\\), x<br \/>\nAccording to the series x = \\(\\frac{31}{4}\\)<br \/>\nThe mixed fraction of \\(\\frac{31}{4}\\) is 7 \\(\\frac{3}{4}\\)<\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>Write a rule for the sequence. Then, find the unknown term.<\/strong><\/p>\n<p>Question 7.<br \/>\n\\(\\frac{1}{8}, \\frac{1}{2}\\), \\(\\frac{\u25a1}{\u25a1}\\) , \\(1 \\frac{1}{4}, 1 \\frac{5}{8}\\)<\/p>\n<p>Answer: \\(\\frac{7}{8}\\)<\/p>\n<p>Explanation:<br \/>\n\\(\\frac{1}{8}, \\frac{1}{2}\\), \\(1 \\frac{1}{4}, 1 \\frac{5}{8}\\), x<br \/>\nLCD = 8<br \/>\n\\(\\frac{1}{8}, \\frac{4}{8}\\), \\(\\frac{10}{8}, \\frac{26}{8}\\), x<br \/>\n\\(\\frac{1}{8}\\), \\(\\frac{4}{8}\\), x, \\(\\frac{10}{8}\\), \\(\\frac{26}{8}\\)<br \/>\nThe difference between the series is 3 in numerator.<br \/>\nx = \\(\\frac{7}{8}\\)<\/p>\n<p>Question 8.<br \/>\n\\(1 \\frac{2}{3}, 1 \\frac{3}{4}, 1 \\frac{5}{6}, 1 \\frac{11}{12}\\), ______<\/p>\n<p>Answer: 2<\/p>\n<p>Explanation:<br \/>\n1 \\(\\frac{2}{3}\\), 1 \\(\\frac{3}{4}\\), 1 \\(\\frac{5}{6}\\), 1 \\(\\frac{11}{12}\\)<br \/>\nConvert the mixed fractions into improper fractions<br \/>\n\\(\\frac{5}{3}\\), \\(\\frac{7}{4}\\), \\(\\frac{11}{6}\\), \\(\\frac{23}{12}\\), x<br \/>\nThe LCD is 12<br \/>\n\\(\\frac{20}{12}\\), \\(\\frac{21}{12}\\), \\(\\frac{22}{12}\\), \\(\\frac{23}{12}\\), x<br \/>\nx = \\(\\frac{24}{12}\\) = 2<\/p>\n<p>Question 9.<br \/>\n\\(12 \\frac{7}{8}, 10 \\frac{3}{4}\\), ______ \\(\\frac{\u25a1}{\u25a1}\\) , \\(6 \\frac{1}{2}, 4 \\frac{3}{8}\\)<\/p>\n<p>Answer: 8 \\(\\frac{5}{8}\\)<\/p>\n<p>Explanation:<br \/>\n\\(12 \\frac{7}{8}, 10 \\frac{3}{4}\\), x , \\(6 \\frac{1}{2}, 4 \\frac{3}{8}\\)<br \/>\nConvert the mixed fractions into improper fractions<br \/>\n\\(\\frac{103}{8}\\), \\(\\frac{43}{4}\\), x, \\(\\frac{13}{2}\\), \\(\\frac{35}{8}\\)<br \/>\nThe LCD is 8<br \/>\n\\(\\frac{103}{8}\\), \\(\\frac{86}{8}\\), x, \\(\\frac{52}{8}\\), \\(\\frac{35}{8}\\)<br \/>\nx = \\(\\frac{69}{8}\\)<br \/>\nThe mixed fraction of \\(\\frac{69}{8}\\) is 8 \\(\\frac{5}{8}\\)<\/p>\n<p>Question 10.<br \/>\n\\(9 \\frac{1}{3}\\), ______ \\(\\frac{\u25a1}{\u25a1}\\) , \\(6 \\frac{8}{9}, 5 \\frac{2}{3}, 4 \\frac{4}{9}\\)<\/p>\n<p>Answer: 8 \\(\\frac{1}{9}\\)<\/p>\n<p>Explanation:<br \/>\n\\(9 \\frac{1}{3}\\), x , \\(6 \\frac{8}{9}, 5 \\frac{2}{3}, 4 \\frac{4}{9}\\)<br \/>\nConvert the mixed fractions into improper fractions<br \/>\n\\(\\frac{28}{3}\\), x, \\(\\frac{62}{9}\\), \\(\\frac{17}{3}\\), \\(\\frac{40}{9}\\)<br \/>\nLCD = 9<br \/>\n\\(\\frac{84}{9}\\), x, \\(\\frac{62}{9}\\), \\(\\frac{51}{9}\\), \\(\\frac{40}{9}\\)<br \/>\nAccording to the series x =\u00a0 \\(\\frac{73}{9}\\) = 8 \\(\\frac{1}{9}\\)<\/p>\n<p><strong>Write the first four terms of the sequence.<\/strong><\/p>\n<p>Question 11.<br \/>\nRule: start at 5 \\(\\frac{3}{4}\\), subtract \\(\\frac{5}{8}\\)<br \/>\nFirst term: ______ \\(\\frac{\u25a1}{\u25a1}\\)<br \/>\nSecond term: ______ \\(\\frac{\u25a1}{\u25a1}\\)<br \/>\nThird term: ______ \\(\\frac{\u25a1}{\u25a1}\\)<br \/>\nFourth term: ______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\nLet the first term be 5 \\(\\frac{3}{4}\\)<br \/>\nSecond term = 5 \\(\\frac{3}{4}\\) &#8211; \\(\\frac{5}{8}\\) = \\(\\frac{41}{8}\\) = 5 \\(\\frac{1}{8}\\)<br \/>\nThird term = 5 \\(\\frac{1}{8}\\) &#8211; \\(\\frac{5}{8}\\) = \\(\\frac{36}{8}\\) = 4 \\(\\frac{1}{2}\\)<br \/>\nFourth term = \\(\\frac{36}{8}\\) &#8211; \\(\\frac{5}{8}\\) = \\(\\frac{31}{8}\\) = 3 \\(\\frac{7}{8}\\)<\/p>\n<p>Question 12.<br \/>\nRule: start at \\(\\frac{3}{8}\\), add \\(\\frac{3}{16}\\)<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer:<br \/>\nLet the first term be \\(\\frac{3}{8}\\)<br \/>\nSecond term = \\(\\frac{3}{8}\\) + \\(\\frac{3}{16}\\) = \\(\\frac{9}{16}\\)<br \/>\nThird term = \\(\\frac{9}{16}\\) + \\(\\frac{3}{16}\\) = \\(\\frac{12}{16}\\)<br \/>\nFourth term = \\(\\frac{12}{16}\\) + \\(\\frac{3}{16}\\) = \\(\\frac{15}{16}\\)<\/p>\n<p>Question 13.<br \/>\nRule: start at 2 \\(\\frac{1}{3}\\), add 2 \\(\\frac{1}{4}\\)<br \/>\nFirst term: ______ \\(\\frac{\u25a1}{\u25a1}\\)<br \/>\nSecond term: ______ \\(\\frac{\u25a1}{\u25a1}\\)<br \/>\nThird term: ______ \\(\\frac{\u25a1}{\u25a1}\\)<br \/>\nFourth term: ______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\nLet the first term be 2 \\(\\frac{1}{3}\\)<br \/>\nSecond term = 2 \\(\\frac{1}{3}\\) + 2 \\(\\frac{1}{4}\\) = \\(\\frac{7}{3}\\) + \\(\\frac{9}{4}\\)<br \/>\n= \\(\\frac{55}{12}\\) = 4 \\(\\frac{7}{12}\\)<br \/>\nThird term = 4 \\(\\frac{7}{12}\\) + 2 \\(\\frac{1}{4}\\) = 6 \\(\\frac{5}{6}\\)<br \/>\nFourth term = 6 \\(\\frac{5}{6}\\) + 2 \\(\\frac{1}{4}\\) = 9 \\(\\frac{1}{12}\\)<\/p>\n<p>Question 14.<br \/>\nRule: start at \\(\\frac{8}{9}\\), subtract \\(\\frac{1}{18}\\)<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer:<br \/>\nLet the first term be \\(\\frac{8}{9}\\)<br \/>\nSecond term = \\(\\frac{8}{9}\\) &#8211; \\(\\frac{1}{18}\\) = \\(\\frac{15}{18}\\) = \\(\\frac{5}{6}\\)<br \/>\nThird term = \\(\\frac{15}{18}\\)\u00a0&#8211; \\(\\frac{1}{18}\\) = \\(\\frac{14}{18}\\) = \\(\\frac{7}{9}\\)<br \/>\nFourth term = \\(\\frac{14}{18}\\) &#8211; \\(\\frac{1}{18}\\) = \\(\\frac{13}{18}\\)<\/p>\n<h3><a id=\"Problem_Solving_Page_No_276\"><\/a>Problem Solving &#8211; Page No. 276<\/h3>\n<p><img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-21.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators img 21\" width=\"226\" height=\"298\" \/><\/p>\n<p>Question 15.<br \/>\nWhen Bill bought a marigold plant, it was \\(\\frac{1}{4}\\) inch tall. After the first week, it measured 1 \\(\\frac{1}{12}\\) inches tall. After the second week, it was 1 \\(\\frac{11}{12}\\) inches. After week 3, it was 2 \\(\\frac{3}{4}\\) inches tall. Assuming the growth of the plant was constant, what was the height of the plant at the end of week 4?<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\) inches<\/p>\n<p>Answer: 3 \\(\\frac{7}{12}\\) inches<\/p>\n<p>The sequence is the increasing where the first term is \\(\\frac{1}{4}\\)<br \/>\nLCD = 12<br \/>\nFirst week is \\(\\frac{3}{12}\\)<br \/>\nSecond week = \\(\\frac{13}{12}\\) = 1 \\(\\frac{1}{12}\\)<br \/>\nThird week = 1 \\(\\frac{11}{12}\\) = \\(\\frac{23}{12}\\)<br \/>\nFourth week = \\(\\frac{33}{12}\\) = 2 \\(\\frac{3}{4}\\)<br \/>\nAt the end of fourth week = \\(\\frac{43}{12}\\) = 3 \\(\\frac{7}{12}\\) inches<br \/>\nThe height of the plant at the end of the week is 3 \\(\\frac{7}{12}\\) inches.<\/p>\n<p>Question 16.<br \/>\nWhat if Bill\u2019s plant grew at the same rate but was 1 \\(\\frac{1}{2}\\) inches when he bought it? How tall would the plant be after 3 weeks?<br \/>\n______ inches<\/p>\n<p>Answer: 4 inches<\/p>\n<p>Explanation:<br \/>\nThe sequence is increasing.<br \/>\nFirst week 1 \\(\\frac{1}{2}\\)<br \/>\nLet the first term is \\(\\frac{6}{12}\\)<br \/>\nSecond term is 1 \\(\\frac{16}{12}\\)<br \/>\nThird term is 1 \\(\\frac{26}{12}\\)<br \/>\nFourth week is 1 \\(\\frac{36}{12}\\)<br \/>\n1 \\(\\frac{36}{12}\\) = 1 \\(\\frac{3}{1}\\) = 1 + 3 = 4<br \/>\nAfter 4 weeks the plant grew 4 inches.<\/p>\n<p>Question 17.<br \/>\nVicki wanted to start jogging. The first time she ran, she ran \\(\\frac{3}{16}\\) mile. The second time, she ran \\(\\frac{3}{8}\\) mile, and the third time, she ran \\(\\frac{9}{16}\\) mile. If she continued this pattern, when was the first time she ran more than 1 mile? Explain.<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: Sixth time<\/p>\n<p>Explanation:<br \/>\nVicki wanted to start jogging. The first time she ran, she ran \\(\\frac{3}{16}\\) mile. The second time, she ran \\(\\frac{3}{8}\\) mile, and the third time, she ran \\(\\frac{9}{16}\\) mile.<br \/>\nThe difference is \\(\\frac{3}{16}\\)<br \/>\nFirst time = \\(\\frac{3}{16}\\) mile<br \/>\nSecond time = \\(\\frac{3}{16}\\) + \\(\\frac{3}{16}\\) = \\(\\frac{3}{8}\\) mile<br \/>\nThird time = \\(\\frac{3}{8}\\) + \\(\\frac{3}{16}\\) = \\(\\frac{9}{16}\\) mile<br \/>\nFourth time = \\(\\frac{9}{16}\\) + \\(\\frac{3}{16}\\) = \\(\\frac{12}{16}\\) mile<br \/>\nFifth time = \\(\\frac{12}{16}\\) + \\(\\frac{3}{16}\\) = \\(\\frac{15}{16}\\) mile<br \/>\nSixth time = \\(\\frac{15}{16}\\) + \\(\\frac{3}{16}\\) = \\(\\frac{18}{16}\\) mile<br \/>\n\\(\\frac{18}{16}\\) = 1 \\(\\frac{2}{16}\\) = 1 \\(\\frac{1}{8}\\)<\/p>\n<p>Question 18.<br \/>\nMr. Conners drove 78 \\(\\frac{1}{3}\\) miles on Monday, 77 \\(\\frac{1}{12}\\) miles on Tuesday, and 75 \\(\\frac{5}{6}\\) miles on Wednesday. If he continues this pattern on Thursday and Friday, how many miles will he drive on Friday?<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\) miles<\/p>\n<p>Answer:<br \/>\nGiven that,<br \/>\nMr. Conners drove 78 \\(\\frac{1}{3}\\) miles on Monday, 77 \\(\\frac{1}{12}\\) miles on Tuesday, and 75 \\(\\frac{5}{6}\\) miles on Wednesday.<br \/>\nThe sequence is the decreasing where the first term is 78 \\(\\frac{4}{12}\\)<br \/>\n78 \\(\\frac{4}{12}\\) &#8211; 77 \\(\\frac{1}{12}\\) = 1 \\(\\frac{3}{12}\\)<br \/>\nThe difference between the term is 1 \\(\\frac{3}{12}\\)<br \/>\nOn thursday, 75 \\(\\frac{5}{6}\\) &#8211; 1 \\(\\frac{3}{12}\\) = 74 \\(\\frac{7}{12}\\)<br \/>\nOn friday, 74 \\(\\frac{7}{12}\\) &#8211; 1 \\(\\frac{3}{12}\\) = 73 \\(\\frac{4}{12}\\) = 73 \\(\\frac{1}{3}\\)<\/p>\n<p>Question 19.<br \/>\nTest Prep Zack watered his garden with 1 \\(\\frac{3}{8}\\) gallons of water the first week he planted it. He watered it with 1 \\(\\frac{3}{4}\\) gallons the second week, and 2 \\(\\frac{1}{8}\\) gallons the third week. If he continued watering in this pattern, how much water did he use on the fifth week?<br \/>\nOptions:<br \/>\na. 2 \\(\\frac{1}{2}\\) gallons<br \/>\nb. 2 \\(\\frac{7}{8}\\) gallons<br \/>\nc. 3 \\(\\frac{1}{4}\\) gallons<br \/>\nd. 6 \\(\\frac{7}{8}\\) gallons<\/p>\n<p>Answer: 2 \\(\\frac{7}{8}\\) gallons<\/p>\n<p>Explanation:<br \/>\nFirst term = 1 \\(\\frac{3}{8}\\)<br \/>\nThe difference is \\(\\frac{3}{4}\\) &#8211; \\(\\frac{3}{8}\\) = \\(\\frac{3}{8}\\)<br \/>\nSecond term is 1 \\(\\frac{3}{8}\\) + \\(\\frac{3}{8}\\) = 1 \\(\\frac{3}{4}\\)<br \/>\nThird term = 1 \\(\\frac{3}{4}\\) + \\(\\frac{3}{8}\\) = 1 + 1 \\(\\frac{1}{8}\\) = 2 \\(\\frac{1}{8}\\)<br \/>\nFourth term = 2 \\(\\frac{1}{8}\\) + \\(\\frac{3}{8}\\) = 2 \\(\\frac{1}{2}\\)<br \/>\nFifth term = 2 \\(\\frac{1}{2}\\) + \\(\\frac{3}{8}\\) = 2 \\(\\frac{7}{8}\\) gallons<br \/>\nThus the correct answer is option B.<\/p>\n<h3><a id=\"Share_and_Show_Page_No_279\"><\/a>Share and Show &#8211; Page No. 279<\/h3>\n<p>Question 1.<br \/>\nCaitlin has 4 \\(\\frac{3}{4}\\) pounds of clay. She uses 1 \\(\\frac{1}{10}\\) pounds to make a cup, and another 2 pounds to make a jar. How many pounds are left?<br \/>\nFirst, write an equation to model the problem.<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: 4 \\(\\frac{3}{4}\\) &#8211; 1 \\(\\frac{1}{10}\\) &#8211; 2<\/p>\n<p>Explanation:<br \/>\nSubtract the total pound of clay from used clay.<br \/>\nSo, the equation of the clay leftover is 4 \\(\\frac{3}{4}\\) &#8211; 1 \\(\\frac{1}{10}\\) &#8211; 2<\/p>\n<p>Question 1.<br \/>\nNext, work backwards and rewrite the equation to find x.<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: 4 \\(\\frac{3}{4}\\) &#8211; 1 \\(\\frac{1}{10}\\) &#8211; 2\u00a0= x<\/p>\n<p>Explanation:<br \/>\nLet the leftover clay be x<br \/>\n4 \\(\\frac{3}{4}\\) &#8211; 1 \\(\\frac{1}{10}\\) &#8211; 2\u00a0= x<br \/>\nx = 4 \\(\\frac{3}{4}\\) &#8211; 1 \\(\\frac{1}{10}\\) &#8211; 2<\/p>\n<p>Question 1.<br \/>\nSolve.<br \/>\n_____________________<br \/>\nSo, ________ pounds of clay remain.<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer: 1 \\(\\frac{13}{20}\\) pounds<\/p>\n<p>Explanation:<br \/>\n4 \\(\\frac{3}{4}\\) &#8211; 1 \\(\\frac{1}{10}\\) &#8211; 2<br \/>\n4 + \\(\\frac{3}{4}\\) &#8211; 1 &#8211; \\(\\frac{1}{10}\\) &#8211; 2<br \/>\n4 &#8211; 3 = 1<br \/>\n\\(\\frac{3}{4}\\) &#8211; \\(\\frac{1}{10}\\) = \\(\\frac{13}{20}\\)<br \/>\n1 + \\(\\frac{13}{20}\\) = 1 \\(\\frac{13}{20}\\) pounds<\/p>\n<p>Question 2.<br \/>\nWhat if Caitlin had used more than 2 pounds of clay to make a jar? Would the amount remaining have been more or less than your answer to Exercise 1?<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer:<br \/>\nLet us assume that Catlin used 2 \\(\\frac{1}{4}\\) pounds of clay to make a jar and 1 \\(\\frac{1}{10}\\) pounds to make a cup.<br \/>\n4 \\(\\frac{3}{4}\\) &#8211; 1 \\(\\frac{1}{10}\\) &#8211; 2 \\(\\frac{1}{4}\\) = 2 \\(\\frac{1}{20}\\)<\/p>\n<p>Question 3.<br \/>\nA pet store donated 50 pounds of food for adult dogs, puppies, and cats to an animal shelter. 19 \\(\\frac{3}{4}\\) pounds was adult dog food and 18 \\(\\frac{7}{8}\\) pounds was puppy food. How many pounds of cat food did the pet store donate?<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\) pounds of cat food<\/p>\n<p>Answer: 11 \\(\\frac{3}{8}\\) pounds of cat food<\/p>\n<p>Explanation:<br \/>\nA pet store donated 50 pounds of food for adult dogs, puppies, and cats to an animal shelter.<br \/>\n19 \\(\\frac{3}{4}\\) pounds was adult dog food and 18 \\(\\frac{7}{8}\\) pounds was puppy food.<br \/>\n19 \\(\\frac{3}{4}\\) + 18 \\(\\frac{7}{8}\\) = 38 \\(\\frac{5}{8}\\)<br \/>\n50 &#8211; 38 \\(\\frac{5}{8}\\) = 11 \\(\\frac{3}{8}\\) pounds of cat food<br \/>\nThus the pet store donate 11 \\(\\frac{3}{8}\\) pounds of cat food<\/p>\n<p>Question 4.<br \/>\nThelma spent \\(\\frac{1}{6}\\) of her weekly allowance on dog toys, \\(\\frac{1}{4}\\) on a dog collar, and \\(\\frac{1}{3}\\) on dog food. What fraction of her weekly allowance is left?<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\) of her weekly allowance<\/p>\n<p>Answer: \\(\\frac{1}{4}\\)<\/p>\n<p>Explanation:<br \/>\nGiven that, Thelma spent \\(\\frac{1}{6}\\) of her weekly allowance on dog toys, \\(\\frac{1}{4}\\) on a dog collar, and \\(\\frac{1}{3}\\) on dog food.<br \/>\n\\(\\frac{1}{6}\\) + \\(\\frac{1}{4}\\) + \\(\\frac{1}{3}\\)\u00a0 = \\(\\frac{3}{4}\\)<br \/>\n1 &#8211; \\(\\frac{3}{4}\\) = \\(\\frac{1}{4}\\)<br \/>\n\\(\\frac{1}{4}\\) of her weekly allowance.<\/p>\n<h3><a id=\"On_Your_Own_Page_No_280\"><\/a>On Your Own &#8211; Page No. 280<\/h3>\n<p>Question 5.<br \/>\nMartin is making a model of a Native American canoe. He has 5 \\(\\frac{1}{2}\\) feet of wood. He uses 2 \\(\\frac{3}{4}\\) feet for the hull and 1 \\(\\frac{1}{4}\\) feet for the paddles and struts. How much wood does he have left?<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\) feet<\/p>\n<p>Answer: 1 \\(\\frac{1}{2}\\) feet<\/p>\n<p>Explanation:<br \/>\nMartin is making a model of a Native American canoe.<br \/>\nHe has 5 \\(\\frac{1}{2}\\) feet of wood.<br \/>\nHe uses 2 \\(\\frac{3}{4}\\) feet for the hull and 1 \\(\\frac{1}{4}\\) feet for the paddles and struts.<br \/>\n2 \\(\\frac{3}{4}\\) + 1 \\(\\frac{1}{4}\\)<br \/>\n2 + \\(\\frac{3}{4}\\) + 1 + \\(\\frac{1}{4}\\)<br \/>\n2 + 1 = 3<br \/>\n\\(\\frac{3}{4}\\) + \\(\\frac{1}{4}\\) = 1<br \/>\n3 + 1 = 4<br \/>\n5 \\(\\frac{1}{2}\\) &#8211; 4 = 1 \\(\\frac{1}{2}\\)<\/p>\n<p>Question 6.<br \/>\nWhat if Martin makes a hull and two sets of paddles and struts? How much wood does he have left?<\/p>\n<p>Answer: 1 \\(\\frac{1}{4}\\)<\/p>\n<p>Explanation:<br \/>\nHe has 5 \\(\\frac{1}{2}\\) feet of wood.<br \/>\nIf Martin makes a hull and two sets of paddles and struts<br \/>\n1 \\(\\frac{1}{4}\\) + 1 \\(\\frac{1}{4}\\) = 2 \\(\\frac{1}{2}\\)<br \/>\n2 \\(\\frac{1}{2}\\) + 2 \\(\\frac{3}{4}\\) = 4 \\(\\frac{1}{4}\\)<br \/>\n5 \\(\\frac{1}{2}\\) &#8211; 4 \\(\\frac{1}{4}\\)<br \/>\n5 + \\(\\frac{1}{2}\\) &#8211; 4 &#8211; \\(\\frac{1}{4}\\)<br \/>\n1 + \\(\\frac{1}{4}\\) = 1 \\(\\frac{1}{4}\\)<\/p>\n<p>Question 7.<br \/>\nBeth\u2019s summer vacation lasted 87 days. At the beginning of her vacation, she spent 3 weeks at soccer camp, 5 days at her grandmother\u2019s house, and 13 days visiting Glacier National Park with her parents. How many vacation days remained?<br \/>\n______ days<\/p>\n<p>Answer: 48 days<\/p>\n<p>Explanation:<br \/>\nGiven,<br \/>\nBeth\u2019s summer vacation lasted 87 days.<br \/>\nAt the beginning of her vacation, she spent 3 weeks at soccer camp, 5 days at her grandmother\u2019s house, and 13 days visiting Glacier National Park with her parents.<br \/>\n87 &#8211; 21 &#8211; 5 &#8211; 13 = 48 days<br \/>\nThe remaining vacation days are 48.<\/p>\n<p>Question 8.<br \/>\nYou can buy 2 DVDs for the same price you would pay for 3 CDs selling for $13.20 apiece. Explain how you could find the price of 1 DVD.<br \/>\n$ ______<\/p>\n<p>Answer: $19.8<\/p>\n<p>Explanation:<br \/>\nTo find what is the price of 1 DVD we will find what is the price of 3 DVDs and then because 2 DVDs price is the same than 3 CDs we can easily find the price of 1 DVD.<br \/>\n$13.20 \u00d7 3 = $39.6<br \/>\nWe will divide $39.6 by 2.<br \/>\n$39.6 \u00f7 2 = $19.8<br \/>\nThe price of 1 DVD is $19.8<\/p>\n<p>Question 9.<br \/>\nTest Prep During the 9 hours between 8 A.M. and 5 P.M., Bret spent 5 \\(\\frac{3}{4}\\) hours in class and 1 \\(\\frac{1}{2}\\) hours at band practice. How much time did he spend on other activities?<br \/>\nOptions:<br \/>\na. \\(\\frac{3}{4}\\) hour<br \/>\nb. 1 \\(\\frac{1}{4}\\) hour<br \/>\nc. 1 \\(\\frac{1}{2}\\) hour<br \/>\nd. 1 \\(\\frac{3}{4}\\) hour<\/p>\n<p>Answer: 1 \\(\\frac{3}{4}\\) hour<\/p>\n<p>Explanation:<br \/>\nTest Prep During the 9 hours between 8 A.M. and 5 P.M., Bret spent 5 \\(\\frac{3}{4}\\) hours in class and 1 \\(\\frac{1}{2}\\) hours at band practice.<br \/>\n5 \\(\\frac{3}{4}\\) + 1 \\(\\frac{1}{2}\\) = 7 \\(\\frac{1}{4}\\) hour<br \/>\n9 &#8211; 7 \\(\\frac{1}{4}\\) hour<br \/>\n8 + 1 &#8211; 7 &#8211; \\(\\frac{1}{4}\\)<br \/>\n1 \\(\\frac{3}{4}\\) hour<br \/>\nThe correct answer is option D.<\/p>\n<h3><a id=\"Share_and_Show_Page_No_283\"><\/a>Share and Show &#8211; Page No. 283<\/h3>\n<p><strong>Use the properties and mental math to solve. Write your answer in simplest form.<\/strong><\/p>\n<p>Question 1.<br \/>\n\\(\\left(2 \\frac{5}{8}+\\frac{5}{6}\\right)+1 \\frac{1}{8}\\)<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\left(2 \\frac{5}{8}+\\frac{5}{6}\\right)+1 \\frac{1}{8}\\)<br \/>\n2 \\(\\frac{5}{8}\\) + \\(\\frac{5}{6}\\)<br \/>\n2 + \\(\\frac{5}{8}\\) + \\(\\frac{5}{6}\\)<br \/>\nLCD = 24<br \/>\n\\(\\frac{15}{24}\\) + \\(\\frac{20}{24}\\) = \\(\\frac{35}{24}\\)<br \/>\n\\(\\frac{35}{24}\\) = 1\u00a0\\(\\frac{11}{24}\\)<br \/>\n2 + 1 \\(\\frac{11}{24}\\) = 3 \\(\\frac{11}{24}\\)<br \/>\n3 \\(\\frac{11}{24}\\) + 1 \\(\\frac{1}{8}\\) = 4 \\(\\frac{7}{12}\\)<\/p>\n<p>Question 2.<br \/>\n\\(\\frac{5}{12}+\\left(\\frac{5}{12}+\\frac{3}{4}\\right)\\)<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{5}{12}+\\left(\\frac{5}{12}+\\frac{3}{4}\\right)\\)<br \/>\n\\(\\frac{5}{12}\\) + \\(\\frac{3}{4}\\)<br \/>\nLCD = 12<br \/>\n\\(\\frac{5}{12}\\) + \\(\\frac{3}{4}\\) \u00d7 \\(\\frac{3}{3}\\)<br \/>\n\\(\\frac{5}{12}\\) + \\(\\frac{9}{12}\\) = \\(\\frac{14}{12}\\)<br \/>\n\\(\\frac{5}{12}\\) + \\(\\frac{14}{12}\\) = \\(\\frac{19}{12}\\)<br \/>\n\\(\\frac{19}{12}\\) = 1 \\(\\frac{7}{12}\\)<\/p>\n<p>Question 3.<br \/>\n\\(\\left(3 \\frac{1}{4}+2 \\frac{5}{6}\\right)+1 \\frac{3}{4}\\)<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<\/p>\n<p>\\(\\left(3 \\frac{1}{4}+2 \\frac{5}{6}\\right)\\)<br \/>\n2 + \\(\\frac{5}{6}\\) + 3 + \\(\\frac{1}{4}\\)<br \/>\n2 + 3 = 5<br \/>\n\\(\\frac{5}{6}\\) + \\(\\frac{1}{4}\\)<br \/>\nLCD = 12<br \/>\n\\(\\frac{5}{6}\\) \u00d7 \\(\\frac{2}{2}\\) + \\(\\frac{1}{4}\\) \u00d7 \\(\\frac{3}{3}\\)<br \/>\n\\(\\frac{10}{12}\\) + \\(\\frac{3}{12}\\) = \\(\\frac{13}{12}\\) = 1 \\(\\frac{1}{12}\\)<br \/>\n5 + 1 \\(\\frac{1}{12}\\) = 6\u00a0\\(\\frac{1}{12}\\)<br \/>\n6 \\(\\frac{1}{12}\\) + 1 \\(\\frac{3}{4}\\)<br \/>\n6 + \\(\\frac{1}{12}\\) + 1 + \\(\\frac{3}{4}\\)<br \/>\n6 + 1 = 7<br \/>\n\\(\\frac{1}{12}\\) + \\(\\frac{3}{4}\\)<br \/>\n\\(\\frac{1}{12}\\) + \\(\\frac{9}{12}\\) = \\(\\frac{10}{12}\\) = \\(\\frac{5}{6}\\)<br \/>\n7 + \\(\\frac{5}{6}\\) = 7 \\(\\frac{5}{6}\\)<\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>Use the properties and mental math to solve. Write your answer in simplest form.<\/strong><\/p>\n<p>Question 4.<br \/>\n\\(\\left(\\frac{2}{7}+\\frac{1}{3}\\right)+\\frac{2}{3}\\)<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\left(\\frac{2}{7}+\\frac{1}{3}\\right)+\\frac{2}{3}\\)<br \/>\n\\(\\left(\\frac{2}{7}+\\frac{1}{3}\\right)\\)<br \/>\nLCD = 21<br \/>\n\\(\\left(\\frac{6}{21}+\\frac{7}{21}\\right)\\) = \\(\\frac{13}{21}\\)<br \/>\n\\(\\frac{13}{21}\\) + \\(\\frac{2}{3}\\)<br \/>\nLCD = 21<br \/>\n\\(\\frac{13}{21}\\) + \\(\\frac{14}{21}\\)<br \/>\n\\(\\frac{27}{21}\\) = \\(\\frac{9}{7}\\)<br \/>\n= 1 \\(\\frac{2}{7}\\)<\/p>\n<p>Question 5.<br \/>\n\\(\\left(\\frac{1}{5}+\\frac{1}{2}\\right)+\\frac{2}{5}\\)<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\left(\\frac{1}{5}+\\frac{1}{2}\\right)\\)<br \/>\n\\(\\frac{1}{5}\\) + \\(\\frac{1}{2}\\)<br \/>\nLCD = 10<br \/>\n\\(\\frac{2}{10}\\) + \\(\\frac{5}{10}\\) = \\(\\frac{7}{10}\\)<br \/>\n\\(\\frac{7}{10}\\) + \\(\\frac{2}{5}\\)<br \/>\n\\(\\frac{7}{10}\\) + \\(\\frac{4}{10}\\) = \\(\\frac{11}{10}\\)<br \/>\n\\(\\frac{11}{10}\\) = 1 \\(\\frac{1}{10}\\)<\/p>\n<p>Question 6.<br \/>\n\\(\\left(\\frac{1}{6}+\\frac{3}{7}\\right)+\\frac{2}{7}\\)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\left(\\frac{1}{6}+\\frac{3}{7}\\right)\\)<br \/>\nLCD = 42<br \/>\n\\(\\left(\\frac{7}{42}+\\frac{18}{42}\\right)\\) = \\(\\frac{25}{42}\\)<br \/>\n\\(\\frac{25}{42}\\) + \\(\\frac{2}{7}\\)<br \/>\nLCD = 42<br \/>\n\\(\\frac{25}{42}\\) + \\(\\frac{12}{42}\\) = \\(\\frac{37}{42}\\)<br \/>\n\\(\\left(\\frac{1}{6}+\\frac{3}{7}\\right)+\\frac{2}{7}\\) = \\(\\frac{37}{42}\\)<\/p>\n<p>Question 7.<br \/>\n\\(\\left(2 \\frac{5}{12}+4 \\frac{1}{4}\\right)+\\frac{1}{4}\\)<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\left(2 \\frac{5}{12}+4 \\frac{1}{4}\\right)\\)<br \/>\n2 \\(\\frac{5}{12}\\) + 4 \\(\\frac{1}{4}\\)<br \/>\n2 + \\(\\frac{5}{12}\\) + 4 + \\(\\frac{1}{4}\\)<br \/>\n2 + 4 = 6<br \/>\n\\(\\frac{5}{12}\\) + \\(\\frac{1}{4}\\) = \\(\\frac{8}{12}\\)<br \/>\n6 \\(\\frac{8}{12}\\) = 6 \\(\\frac{2}{3}\\)<br \/>\n6 \\(\\frac{2}{3}\\) + \\(\\frac{1}{4}\\) = 6 \\(\\frac{11}{12}\\)<\/p>\n<p>Question 8.<br \/>\n\\(1 \\frac{1}{8}+\\left(5 \\frac{1}{2}+2 \\frac{3}{8}\\right)\\)<br \/>\n______<\/p>\n<p>Answer:<br \/>\n5 \\(\\frac{1}{2}\\) + 2 \\(\\frac{3}{8}\\)<br \/>\n5 + 2 = 7<br \/>\n\\(\\frac{1}{2}\\) + \\(\\frac{3}{8}\\)<br \/>\nLCD = 8<br \/>\n\\(\\frac{4}{8}\\) + \\(\\frac{3}{8}\\) = \\(\\frac{7}{8}\\)<br \/>\n= 7 \\(\\frac{7}{8}\\)<br \/>\n1 \\(\\frac{1}{8}\\) + 7 \\(\\frac{7}{8}\\) = 9<\/p>\n<p>Question 9.<br \/>\n\\(\\frac{5}{9}+\\left(\\frac{1}{9}+\\frac{4}{5}\\right)\\)<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer:<br \/>\n\\(\\frac{1}{9}\\) + \\(\\frac{4}{5}\\)<br \/>\nLCD = 45<br \/>\n\\(\\frac{5}{45}\\) + \\(\\frac{36}{45}\\) = \\(\\frac{41}{45}\\)<br \/>\n\\(\\frac{41}{45}\\) + \\(\\frac{5}{9}\\)<br \/>\nLCD = 45<br \/>\n\\(\\frac{41}{45}\\) + \\(\\frac{25}{45}\\) = \\(\\frac{66}{45}\\)<br \/>\n\\(\\frac{66}{45}\\) = 1 \\(\\frac{7}{15}\\)<\/p>\n<h3><a id=\"Problem_Solving_Page_No_284\"><\/a>Problem Solving &#8211; Page No. 284<\/h3>\n<p><strong>Use the map to solve 10\u201312.<\/strong><br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-22.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators img 22\" width=\"367\" height=\"314\" \/><\/p>\n<p>Question 10.<br \/>\nIn the morning, Julie rides her bike from the sports complex to the school. In the afternoon, she rides from the school to the mall, and then to Kyle\u2019s house. How far does Julie ride her bike?<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\) miles<\/p>\n<p>Answer: 1 \\(\\frac{13}{15}\\) miles<\/p>\n<p>Explanation:<br \/>\nJulie rides her bike from the sports complex to the school = \\(\\frac{2}{3}\\) mile<br \/>\nIn the afternoon, she rides from the school to the mall, and then to Kyle\u2019s house. = \\(\\frac{2}{5}\\) + \\(\\frac{4}{5}\\) = \\(\\frac{6}{5}\\) = 1 \\(\\frac{1}{5}\\)<br \/>\n1 \\(\\frac{1}{5}\\) + \\(\\frac{2}{3}\\) mile = 1 \\(\\frac{13}{15}\\) miles<\/p>\n<p>Question 11.<br \/>\nOn one afternoon, Mario walks from his house to the library. That evening, Mario walks from the library to the mall, and then to Kyle\u2019s house. Describe how you can use the properties to find how far Mario walks.<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\) miles<\/p>\n<p>Answer:<br \/>\nMario walks from his house to the library = 1 \\(\\frac{3}{5}\\) miles<br \/>\nMario walks from the library to the mall, and then to Kyle\u2019s house = 1 \\(\\frac{1}{3}\\) and \\(\\frac{4}{5}\\)<br \/>\n1 \\(\\frac{3}{5}\\) + (1 \\(\\frac{1}{3}\\) + \\(\\frac{4}{5}\\))<br \/>\n1 \\(\\frac{3}{5}\\) + 2 \\(\\frac{2}{15}\\) = 3 \\(\\frac{11}{15}\\) miles<\/p>\n<p>Question 12.<br \/>\nPose a Problem Write and solve a new problem that uses the distances between four locations.<br \/>\nType below:<br \/>\n_________<\/p>\n<p>Answer:<br \/>\nIn the evening Kyle rides his bike from the sports complex to school. Then he rides from School to the mall and then to his house. How far does Kyle ride his bike?<br \/>\nThe distance from Sports complex to School is \\(\\frac{2}{3}\\) mile<br \/>\nThe distance from School to the mall is \\(\\frac{2}{5}\\)<br \/>\nThe distance from the mall to Kyle house is \\(\\frac{4}{5}\\)<br \/>\n\\(\\frac{2}{3}\\) + (\\(\\frac{2}{5}\\) + \\(\\frac{4}{5}\\))<br \/>\n\\(\\frac{2}{3}\\) + \\(\\frac{6}{5}\\) = 1 \\(\\frac{13}{15}\\) miles<\/p>\n<p>Question 13.<br \/>\nTest Prep Which property or properties does the problem below use?<br \/>\n\\(\\frac{1}{9}+\\left(\\frac{4}{9}+\\frac{1}{6}\\right)=\\left(\\frac{1}{9}+\\frac{4}{9}\\right)+\\frac{1}{6}\\)<br \/>\nOptions:<br \/>\na. Commutative Property<br \/>\nb. Associative Property<br \/>\nc. Commutative Property and Associative Property<br \/>\nd. Distributive Property<\/p>\n<p>Answer: Associative Property<br \/>\nThe associative property states that you can add or multiply regardless of how the numbers are grouped. By &#8216;grouped&#8217; we mean &#8216;how you use parenthesis&#8217;. In other words, if you are adding or multiplying it does not matter where you put the parenthesis.<\/p>\n<h3><a id=\"Chapter_Review_Test_Page_No_285\"><\/a>Chapter Review\/Test &#8211; Vocabulary &#8211; Page No. 285<\/h3>\n<p><strong>Choose the best term from the box.<\/strong><br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-23.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators Chapter Review\/Test img 23\" width=\"232\" height=\"134\" \/><\/p>\n<p>Question 1.<br \/>\nA _________ is a number that is a common multiple of two or more denominators.<br \/>\n_________<\/p>\n<p>Answer: Common Denominator<\/p>\n<p><strong>Concepts and Skills<\/strong><\/p>\n<p><strong>Use a common denominator to write an equivalent fraction for each fraction.<\/strong><\/p>\n<p>Question 2.<br \/>\n\\(\\frac{2}{5}, \\frac{1}{8}\\)<br \/>\ncommon denominator: ______<br \/>\nExplain:<br \/>\n_________<\/p>\n<p>Answer: 40<br \/>\nMultiply the denominators of the fractions<br \/>\n5 \u00d7 8 = 40<\/p>\n<p>Question 3.<br \/>\n\\(\\frac{3}{4}, \\frac{1}{2}\\)<br \/>\ncommon denominator: ______<br \/>\nExplain:<br \/>\n_________<\/p>\n<p>Answer: 8<br \/>\nMultiply the denominators of the fractions<br \/>\n4 \u00d7 2 = 8<\/p>\n<p>Question 4.<br \/>\n\\(\\frac{2}{3}, \\frac{1}{6}\\)<br \/>\ncommon denominator: ______<br \/>\nExplain:<br \/>\n_________<\/p>\n<p>Answer: 18<br \/>\nMultiply the denominators of the fractions<br \/>\n3 \u00d7 6 = 18<\/p>\n<p><strong>Find the sum or difference. Write your answer in simplest form<\/strong><\/p>\n<p>Question 5.<br \/>\n\\(\\frac{5}{6}+\\frac{7}{8}\\)<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 1 \\(\\frac{17}{24}\\)<\/p>\n<p>Explanation:<br \/>\n\\(\\frac{5}{6}+\\frac{7}{8}\\) = \\(\\frac{20}{24}\\) + \\(\\frac{21}{24}\\)<br \/>\n= \\(\\frac{41}{24}\\) = 1 \\(\\frac{17}{24}\\)<\/p>\n<p>Question 6.<br \/>\n\\(2 \\frac{2}{3}-1 \\frac{2}{5}\\)<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 1 \\(\\frac{4}{15}\\)<\/p>\n<p>Question 7.<br \/>\n\\(7 \\frac{3}{4}+3 \\frac{7}{20}\\)<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 11 \\(\\frac{1}{10 }\\)<\/p>\n<p><strong>Estimate. Then find the difference and write it in simplest form.<\/strong><\/p>\n<p>Question 8.<br \/>\n\\(1 \\frac{2}{5}-\\frac{2}{3}\\)<br \/>\nType below:<br \/>\n________<\/p>\n<p>Answer:<br \/>\nEstimate: \\(\\frac{1}{2}\\)<br \/>\nDifference:<br \/>\nRewriting our equation with parts separated<br \/>\n1 + \\(\\frac{2}{5}\\) &#8211; \\(\\frac{2}{3}\\)<br \/>\n\\(\\frac{7}{5}\\) &#8211; \\(\\frac{2}{3}\\)<br \/>\n\\(\\frac{7}{5}\\) \u00d7 \\(\\frac{3}{3}\\) &#8211; \\(\\frac{2}{3}\\) \u00d7 \\(\\frac{5}{5}\\)<br \/>\n= \\(\\frac{21}{15}\\) &#8211; \\(\\frac{10}{15}\\)<br \/>\n= \\(\\frac{11}{15}\\)<\/p>\n<p>Question 9.<br \/>\n\\(7-\\frac{3}{7}\\)<br \/>\nType below:<br \/>\n________<\/p>\n<p>Answer: 6 \\(\\frac{4}{7}\\)<\/p>\n<p>Explanation:<br \/>\n\\(7-\\frac{3}{7}\\) = \\(\\frac{49}{7}\\) &#8211; \\(\\frac{3}{7}\\)<br \/>\n\\(\\frac{46}{7}\\) = 6 \\(\\frac{4}{7}\\)<br \/>\n\\(7-\\frac{3}{7}\\) = 6 \\(\\frac{4}{7}\\)<\/p>\n<p>Question 10.<br \/>\n\\(5 \\frac{1}{9}-3 \\frac{5}{6}\\)<br \/>\nType below:<br \/>\n________<\/p>\n<p>Answer: 1 \\(\\frac{5}{18}\\)<\/p>\n<p>Explanation:<br \/>\n\\(5 \\frac{1}{9}-3 \\frac{5}{6}\\) = 5 + \\(\\frac{1}{9}\\) &#8211; 3 &#8211; \\(\\frac{5}{6}\\)<br \/>\n5 &#8211; 3 = 2<br \/>\n\\(\\frac{1}{9}\\) &#8211; \\(\\frac{5}{6}\\) = \\(\\frac{2}{18}\\) &#8211; \\(\\frac{15}{18}\\) = &#8211; \\(\\frac{13}{18}\\)<br \/>\n2 &#8211; \\(\\frac{13}{18}\\) = 1 \\(\\frac{5}{18}\\)<\/p>\n<p><strong>Use the properties and mental math to solve. Write your answer in simplest form.<\/strong><\/p>\n<p>Question 11.<br \/>\n\\(\\left(\\frac{3}{8}+\\frac{2}{3}\\right)+\\frac{1}{3}\\)<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 1 \\(\\frac{3}{8}\\)<\/p>\n<p>Explanation:<br \/>\n\\(\\frac{3}{8}\\) + \\(\\frac{2}{3}\\) = \\(\\frac{9}{24}\\) + \\(\\frac{16}{24}\\) = \\(\\frac{25}{24}\\)<br \/>\n\\(\\frac{25}{24}\\) + \\(\\frac{1}{3}\\)<br \/>\n= \\(\\frac{25}{24}\\) + \\(\\frac{8}{24}\\) = \\(\\frac{33}{24}\\) = \\(\\frac{11}{8}\\)<br \/>\nThe mixed fraction of \\(\\frac{11}{8}\\) is 1 \\(\\frac{3}{8}\\).<\/p>\n<p>Question 12.<br \/>\n\\(1 \\frac{4}{5}+\\left(2 \\frac{3}{20}+\\frac{3}{5}\\right)\\)<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 4 \\(\\frac{11}{20}\\)<\/p>\n<p>Explanation:<br \/>\nRewriting our equation with parts separated<br \/>\n2 \\(\\frac{3}{20}\\) + \\(\\frac{3}{5}\\) = \\(\\frac{43}{20}\\) + \\(\\frac{3}{5}\\)<br \/>\n\\(\\frac{43}{20}\\) + \\(\\frac{3}{5}\\) = \\(\\frac{215}{100}\\) + \\(\\frac{60}{100}\\)<br \/>\n= \\(\\frac{275}{100}\\) = 2 \\(\\frac{3}{4}\\)<br \/>\n2 \\(\\frac{3}{4}\\) + 1 \\(\\frac{4}{5}\\) = 2 + \\(\\frac{3}{4}\\) + 1 + \\(\\frac{4}{5}\\)<br \/>\n2 + 1 = 3<br \/>\n\\(\\frac{3}{4}\\) + \\(\\frac{4}{5}\\) = \\(\\frac{15}{20}\\) + \\(\\frac{16}{20}\\) = \\(\\frac{31}{20}\\)<br \/>\n\\(\\frac{31}{20}\\) = 4 \\(\\frac{11}{20}\\)<\/p>\n<p>Question 13.<br \/>\n\\(3 \\frac{5}{9}+\\left(1 \\frac{7}{9}+2 \\frac{5}{12}\\right)\\)<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 7 \\(\\frac{3}{4}\\)<\/p>\n<p>Explanation:<br \/>\n1 \\(\\frac{7}{9}\\) + 2 \\(\\frac{5}{12}\\)<br \/>\n1 + 2 = 3<br \/>\n\\(\\frac{7}{9}\\) + \\(\\frac{5}{12}\\)<br \/>\nLCD is 36<br \/>\n\\(\\frac{28}{36}\\) + \\(\\frac{15}{36}\\) = \\(\\frac{43}{36}\\)<br \/>\n\\(\\frac{43}{36}\\) = 1 \\(\\frac{7}{36}\\)<br \/>\n3 + 1 + \\(\\frac{7}{36}\\) = 4\u00a0\\(\\frac{7}{36}\\)<br \/>\n4 \\(\\frac{7}{36}\\) + 3 \\(\\frac{5}{9}\\)<br \/>\n4 + \\(\\frac{7}{36}\\) + 3 + \\(\\frac{5}{9}\\)<br \/>\n4 + 3 = 7<br \/>\n\\(\\frac{7}{36}\\) + \\(\\frac{5}{9}\\)<br \/>\n= \\(\\frac{7}{36}\\) + \\(\\frac{20}{36}\\) = \\(\\frac{27}{36}\\) = \\(\\frac{3}{4}\\)<br \/>\n7 + \\(\\frac{3}{4}\\) = 7 \\(\\frac{3}{4}\\)<\/p>\n<h3><a id=\"Chapter_Review_Test_Page_No_286\"><\/a>Chapter Review\/Test &#8211; Page No. 286<\/h3>\n<p>Question 14.<br \/>\nUrsula mixed 3 \\(\\frac{1}{8}\\) cups of dry ingredients with 1 \\(\\frac{2}{5}\\) cups of liquid ingredients. Which answer represents the best estimate of the total amount of ingredients Ursula mixed?<br \/>\nOptions:<br \/>\na. about 4 cups<br \/>\nb. about 4 \\(\\frac{1}{2}\\) cups<br \/>\nc. about 5 cups<br \/>\nd. about 5 \\(\\frac{1}{2}\\) cups<\/p>\n<p>Answer: about 4 \\(\\frac{1}{2}\\) cups<\/p>\n<p>Explanation:<br \/>\nUrsula mixed 3 \\(\\frac{1}{8}\\) cups of dry ingredients with 1 \\(\\frac{2}{5}\\) cups of liquid ingredients.<br \/>\n3 + 1 = 4<br \/>\n\\(\\frac{1}{8}\\) is closer to 0.<br \/>\n\\(\\frac{2}{5}\\) is closer to \\(\\frac{1}{2}\\)<br \/>\n4 + \\(\\frac{1}{2}\\) = 4 \\(\\frac{1}{2}\\)<br \/>\nThus the correct answer is option B.<\/p>\n<p>Question 15.<br \/>\nSamuel walks in the Labor Day parade. He walks 3 \\(\\frac{1}{4}\\) miles along the parade route and 2 \\(\\frac{5}{6}\\) miles home. How many miles does Samuel walk?<br \/>\nOptions:<br \/>\na. \\(\\frac{5}{10}\\) mile<br \/>\nb. 5 \\(\\frac{1}{12}\\) miles<br \/>\nc. 5 \\(\\frac{11}{12}\\) miles<br \/>\nd. 6 \\(\\frac{1}{12}\\) miles<\/p>\n<p>Answer: 6 \\(\\frac{1}{12}\\) miles<\/p>\n<p>Explanation:<br \/>\nSamuel walks in the Labor Day parade.<br \/>\nHe walks 3 \\(\\frac{1}{4}\\) miles along the parade route and 2 \\(\\frac{5}{6}\\) miles home.<br \/>\n3 + \\(\\frac{1}{4}\\) + 2 + \\(\\frac{5}{6}\\)<br \/>\n3 + 2 =5<br \/>\n\\(\\frac{5}{6}\\) + \\(\\frac{1}{4}\\) = \\(\\frac{10}{12}\\) + \\(\\frac{3}{12}\\) = \\(\\frac{13}{12}\\)<br \/>\n\\(\\frac{13}{12}\\) = 6 \\(\\frac{1}{12}\\) miles<br \/>\nThus the correct answer is option D.<\/p>\n<p>Question 16.<br \/>\nA gardener has a container with 6 \\(\\frac{1}{5}\\) ounces of liquid plant fertilizer. On Sunday, the gardener uses 2 \\(\\frac{1}{2}\\) ounces on a flower garden. How many ounces of liquid plant fertilizer are left?<br \/>\nOptions:<br \/>\na. 3 \\(\\frac{7}{10}\\) ounces<br \/>\nb. 5 \\(\\frac{7}{10}\\) ounces<br \/>\nc. 6 \\(\\frac{7}{10}\\) ounces<br \/>\nd. 9 \\(\\frac{7}{10}\\) ounces<\/p>\n<p>Answer: 9 \\(\\frac{7}{10}\\) ounces<\/p>\n<p>Explanation:<br \/>\nA gardener has a container with 6 \\(\\frac{1}{5}\\) ounces of liquid plant fertilizer.<br \/>\nOn Sunday, the gardener uses 2 \\(\\frac{1}{2}\\) ounces on a flower garden.<br \/>\n6 + \\(\\frac{1}{5}\\) + 2 + \\(\\frac{1}{2}\\)<br \/>\n6 + 2 = 8<br \/>\n\\(\\frac{1}{5}\\) + \\(\\frac{1}{2}\\)<br \/>\nLCD = 10<br \/>\n\\(\\frac{2}{10}\\) + \\(\\frac{5}{10}\\) = \\(\\frac{7}{10}\\)<br \/>\n8 \\(\\frac{7}{10}\\)<\/p>\n<p>Question 17.<br \/>\nAaron is practicing for a triathlon. On Sunday, he bikes 12 \\(\\frac{5}{8}\\) miles and swims 5 \\(\\frac{2}{3}\\) miles. On Monday, he runs 6 \\(\\frac{3}{8}\\) miles. How many total miles does Aaron cover on the two days?<br \/>\nOptions:<br \/>\na. 23 \\(\\frac{1}{6}\\) miles<br \/>\nb. 24 \\(\\frac{7}{12}\\) miles<br \/>\nc. 24 \\(\\frac{2}{3}\\) miles<br \/>\nd. 25 \\(\\frac{7}{12}\\) miles<\/p>\n<p>Answer: 24 \\(\\frac{2}{3}\\) miles<\/p>\n<p>Explanation:<br \/>\nAaron is practicing for a triathlon.<br \/>\nOn Sunday, he bikes 12 \\(\\frac{5}{8}\\) miles and swims 5 \\(\\frac{2}{3}\\) miles.<br \/>\nOn Monday, he runs 6 \\(\\frac{3}{8}\\) miles.<br \/>\n5 \\(\\frac{2}{3}\\) + 6 \\(\\frac{3}{8}\\) = 12 \\(\\frac{1}{24}\\)<br \/>\n12 \\(\\frac{1}{24}\\) + 12 \\(\\frac{5}{8}\\) miles<br \/>\n12 + \\(\\frac{1}{24}\\) + 12 + \\(\\frac{5}{8}\\)<br \/>\n12 + 12 = 24<br \/>\n\\(\\frac{1}{24}\\) + \\(\\frac{5}{8}\\) = \\(\\frac{1}{24}\\) + \\(\\frac{15}{24}\\) = \\(\\frac{16}{24}\\) = \\(\\frac{2}{3}\\)<br \/>\n24 + \\(\\frac{2}{3}\\) = 24 \\(\\frac{2}{3}\\) mile<br \/>\nThe correct answer is option D.<\/p>\n<h3><a id=\"Chapter_Review_Test_Page_No_287\"><\/a>Chapter Review\/Test &#8211; Page No. 287<\/h3>\n<p><strong>Fill in the bubble completely to show your answer.<\/strong><\/p>\n<p>Question 18.<br \/>\nMrs. Friedmon baked a walnut cake for her class. The pictures below show how much cake she brought to school and how much she had left at the end of the day.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-24.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators Chapter Review\/Test img 24\" width=\"414\" height=\"106\" \/><br \/>\nWhich fraction represents the difference between the amounts of cake Mrs. Friedmon had before school and after school?<br \/>\nOptions:<br \/>\na. \\(\\frac{5}{8}\\)<br \/>\nb. 1 \\(\\frac{1}{2}\\)<br \/>\nc. 1 \\(\\frac{5}{8}\\)<br \/>\nd. 2 \\(\\frac{1}{2}\\)<\/p>\n<p>Answer: 1 \\(\\frac{5}{8}\\)<\/p>\n<p>Explanation:<br \/>\nThe fraction for the above figure is 1 \\(\\frac{7}{8}\\)<br \/>\nThe fraction for the second figure is \\(\\frac{1}{4}\\)<br \/>\n1 + \\(\\frac{7}{8}\\) &#8211; \\(\\frac{1}{4}\\)<br \/>\n\\(\\frac{7}{8}\\) &#8211; \\(\\frac{1}{4}\\) = \\(\\frac{7}{8}\\) &#8211; \\(\\frac{2}{8}\\)<br \/>\n\\(\\frac{7}{8}\\) &#8211; \\(\\frac{2}{8}\\) = \\(\\frac{5}{8}\\)<br \/>\n1 + \\(\\frac{5}{8}\\) = 1 \\(\\frac{5}{8}\\)<br \/>\nThe correct answer is option C.<\/p>\n<p>Question 19.<br \/>\nCody is designing a pattern for a wood floor. The length of the pieces of wood are 1 \\(\\frac{1}{2}\\) inches, 1 \\(\\frac{13}{16}\\) inches, and 2 \\(\\frac{1}{8}\\) inches. What is the length of the 5th piece of wood if the pattern continues?<br \/>\nOptions:<br \/>\na. 2 \\(\\frac{7}{6}\\) inches<br \/>\nb. 2 \\(\\frac{3}{4}\\) inches<br \/>\nc. 3 \\(\\frac{1}{2}\\) inches<br \/>\nd. 4 inches<\/p>\n<p>Answer: 2 \\(\\frac{3}{4}\\) inches<\/p>\n<p>Explanation:<br \/>\nThe length of the pieces of wood are 1 \\(\\frac{1}{2}\\) inches, 1 \\(\\frac{13}{16}\\) inches, and 2 \\(\\frac{1}{8}\\) inches<br \/>\n1 \\(\\frac{1}{2}\\) = \\(\\frac{3}{2}\\)<br \/>\n1 \\(\\frac{13}{16}\\) inches = \\(\\frac{29}{16}\\)<br \/>\n\\(\\frac{29}{16}\\) &#8211; \\(\\frac{3}{2}\\) = latex]\\frac{5}{16}[\/latex]<br \/>\n5th piece = \\(\\frac{3}{2}\\) + latex]\\frac{5}{16}[\/latex] (5 &#8211; 1)<br \/>\n= \\(\\frac{3}{2}\\) + latex]\\frac{5}{16}[\/latex] 4<br \/>\n= \\(\\frac{3}{2}\\) + latex]\\frac{20}{16}[\/latex]<br \/>\n= \\(\\frac{3}{2}\\) \u00d7 latex]\\frac{8}{8}[\/latex] + latex]\\frac{20}{16}[\/latex]<br \/>\n= latex]\\frac{44}{16}[\/latex] = 2 latex]\\frac{3}{4}[\/latex]<br \/>\nThus the correct answer is option B.<\/p>\n<p>Question 20.<br \/>\nJulie spends \\(\\frac{3}{4}\\) hour studying on Monday and \\(\\frac{1}{6}\\) hour studying on Tuesday. How many hours does Julie study on those two days?<br \/>\nOptions:<br \/>\na. \\(\\frac{1}{3}\\) hour<br \/>\nb. \\(\\frac{2}{5}\\) hour<br \/>\nc. \\(\\frac{5}{6}\\) hour<br \/>\nd. \\(\\frac{11}{12}\\) hour<\/p>\n<p>Answer: \\(\\frac{11}{12}\\) hour<\/p>\n<p>Explanation:<br \/>\nJulie spends \\(\\frac{3}{4}\\) hour studying on Monday and \\(\\frac{1}{6}\\) hour studying on Tuesday.<br \/>\n\\(\\frac{3}{4}\\) + \\(\\frac{1}{6}\\)<br \/>\nLCD = 12<br \/>\n\\(\\frac{9}{12}\\) + \\(\\frac{2}{12}\\) = \\(\\frac{11}{12}\\) hour<br \/>\nSo, the correct answer is option D.<\/p>\n<h3><a id=\"Chapter_Review_Test_Page_No_288\"><\/a>Chapter Review\/Test &#8211; Page No. 288<\/h3>\n<p><strong>Constructed Response<\/strong><\/p>\n<p>Question 21.<br \/>\nA class uses 8 \\(\\frac{5}{6}\\) sheets of white paper and 3 \\(\\frac{1}{12}\\) sheets of red paper for a project. How much more white paper is used than red paper? Show your work using words, pictures, or numbers. Explain how you know your answer is reasonable.<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\) sheet of white paper<\/p>\n<p>Answer: 5 \\(\\frac{3}{4}\\) sheet of white paper<\/p>\n<p>Explanation:<br \/>\nA class uses 8 \\(\\frac{5}{6}\\) sheets of white paper and 3 \\(\\frac{1}{12}\\) sheets of red paper for a project.<br \/>\n8 \\(\\frac{5}{6}\\) &#8211; 3 \\(\\frac{1}{12}\\)<br \/>\n8 + \\(\\frac{5}{6}\\) &#8211; 3 &#8211; \\(\\frac{1}{12}\\)<br \/>\n8 &#8211; 3 = 5<br \/>\n\\(\\frac{5}{6}\\) &#8211; \\(\\frac{1}{12}\\)<br \/>\n\\(\\frac{10}{12}\\) &#8211; \\(\\frac{1}{12}\\) = \\(\\frac{9}{12}\\)<br \/>\n\\(\\frac{9}{12}\\) = \\(\\frac{3}{4}\\)<br \/>\n5 + \\(\\frac{3}{4}\\) = 5 \\(\\frac{3}{4}\\)<\/p>\n<p><strong>Performance Task<\/strong><\/p>\n<p>Question 22.<br \/>\nFor a family gathering, Marcos uses the recipe below to make a lemon-lime punch.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-5-Answer-Key-Chapter-6-Add-and-Subtract-Fractions-with-Unlike-Denominators-img-25.jpg\" alt=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators Chapter Review\/Test img 25\" width=\"262\" height=\"146\" \/><br \/>\nA). How would you decide the size of a container you need for one batch of the Lemon-Lime Punch?<br \/>\nType below:<br \/>\n________<\/p>\n<p>Answer: He may use \\(\\frac{1}{4}\\) gallon lime juice for one batch of the lemon-lime punch.<\/p>\n<p>Question 22.<br \/>\nB). If Marcos needs to make two batches of the recipe, how much of each ingredient will he need? How many gallons of punch will he have? Show your math solution and explain your thinking when you solve both questions.<br \/>\nType below:<br \/>\n________<\/p>\n<p>Answer: \\(\\frac{2}{3}\\) gallon lime juice<\/p>\n<p>Question 22.<br \/>\nC). Marcos had 1 \\(\\frac{1}{3}\\) gallons of punch left over. He poured all of it into several containers for family members to take home. Use fractional parts of a gallon to suggest a way he could have shared the punch in three different-sized containers.<br \/>\nType below:<br \/>\n________<\/p>\n<p>Answer: 1 \\(\\frac{1}{12}\\)<\/p>\n<h3>Conclusion<\/h3>\n<p>Answering the concepts in Go Math Grade 5 Chapter 6 Solution Key helps students to attempt the exam with confidence and prepare accordingly. Once you get to know the concept better you can solve any kind of question framed on Addition and Subtraction of Fractions with Unlike Denominators. Check your knowledge by taking an Assessment Test on Chapter 6 available.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators can be downloaded free of cost from here. HMH Go Math Grade 5 Answer Key includes topics such as Addition and Subtraction with unlike denominators, Estimate fraction sums and differences, Least Common Denominators, etc. Begin your preparation from Go Math &#8230; <a title=\"Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators\" class=\"read-more\" href=\"https:\/\/bigideasmathanswers.com\/go-math-grade-5-answer-key-chapter-6-add-and-subtract-fractions-with-unlike-denominators\/\" aria-label=\"More on Go Math Grade 5 Answer Key Chapter 6 Add and Subtract Fractions with Unlike Denominators\">Read more<\/a><\/p>\n","protected":false},"author":2,"featured_media":8849,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[2],"tags":[],"jetpack_featured_media_url":"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/10\/go-math-grade-5-chapter-6-add-and-subtract-fractions-with-unlike-denominators-answer-key.jpeg","_links":{"self":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts\/4238"}],"collection":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/comments?post=4238"}],"version-history":[{"count":1,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts\/4238\/revisions"}],"predecessor-version":[{"id":92755,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts\/4238\/revisions\/92755"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/media\/8849"}],"wp:attachment":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/media?parent=4238"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/categories?post=4238"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/tags?post=4238"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}