{"id":5136,"date":"2022-03-25T10:17:26","date_gmt":"2022-03-25T04:47:26","guid":{"rendered":"https:\/\/ccssmathanswers.com\/?p=5136"},"modified":"2022-04-07T12:25:43","modified_gmt":"2022-04-07T06:55:43","slug":"go-math-grade-6-answer-key-chapter-7-exponents","status":"publish","type":"post","link":"https:\/\/bigideasmathanswers.com\/go-math-grade-6-answer-key-chapter-7-exponents\/","title":{"rendered":"Go Math Grade 6 Answer Key Chapter 7 Exponents"},"content":{"rendered":"<p>The solutions of Grade 6 Go Math Answer Key for Chapter 7 Exponents are available in simple PDFs here. With the help off the HMH Go Math Grade 6 Chapter 7 Exponents Answer Ley can be easily downloaded by the students by using the provided links. You can understand the concept of the standard form in this article. So, Download a free pdf of <a style=\"font-size: 16px; background-color: #ffffff;\" href=\"https:\/\/ccssmathanswers.com\/go-math-grade-6-answer-key\/\" target=\"_blank\" rel=\"noopener noreferrer\">Go Math Grade 6 Answer Key<\/a><span style=\"font-size: 16px;\"> Chapter 7 Exponents. <\/span><\/p>\n<h2>Go Math Grade 6 Answer Key Chapter 7 Exponents<\/h2>\n<p>Our main aim is to provide a brief explanation of all the questions. We have provided the table of contents of chapter 7 Exponents in the below section. So, once go through the topics before you start your preparation. This will help you to know in which topic you are lagging. Hence make use of the resources provided on this page and try to score good marks in the exams. After your preparation we suggest the students to test your skills by solving the questions in the mid-chapter checkpoint and review test.<\/p>\n<p><strong>Lesson 1: Exponents<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_359\">Share and Show &#8211; Page No. 359<\/a><\/li>\n<li><a href=\"#Bacterial_Growth_Page_No_360\">Bacterial Growth &#8211; Page No. 360<\/a><\/li>\n<li><a href=\"#Exponents_Page_No_361\">Exponents &#8211; Page No. 361<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_362\">Lesson Check &#8211; Page No. 362<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 2: Evaluate Expressions Involving Exponents<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_365\">Share and Show &#8211; Page No. 365<\/a><\/li>\n<li><a href=\"#Problem_Solving_+_Applications_Page_No_366\">Problem Solving + Applications &#8211; Page No. 366<\/a><\/li>\n<li><a href=\"#Evaluate_Expressions_Involving_Exponents_Page_No_367\">Evaluate Expressions Involving Exponents &#8211; Page No. 367<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_368\">Lesson Check &#8211; Page No. 368<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 3: Write Algebraic Expressions<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_371\">Share and Show &#8211; Page No. 371<\/a><\/li>\n<li><a href=\"#Unlock_the_Problem_Page_No_372\">Unlock the Problem &#8211; Page No. 372<\/a><\/li>\n<li><a href=\"#Write_Algebraic_Expressions_Page_No_373\">Write Algebraic Expressions &#8211; Page No. 373<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_374\">Lesson Check &#8211; Page No. 374<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 4: Identify Parts of Expressions<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_377\">Share and Show &#8211; Page No. 377<\/a><\/li>\n<li><a href=\"#Problem_Solving_+_Applications_Page_No_378\">Problem Solving + Applications &#8211; Page No. 378<\/a><\/li>\n<li><a href=\"#Identify_Parts_of_Expressions_Page_No_379\">Identify Parts of Expressions &#8211; Page No. 379<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_380\">Lesson Check &#8211; Page No. 380<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 5: Evaluate Algebraic Expressions and Formulas<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_383\">Share and Show &#8211; Page No. 383<\/a><\/li>\n<li><a href=\"#Problem_Solving_+_Applications_Page_No_384\">Problem Solving + Applications &#8211; Page No. 384<\/a><\/li>\n<li><a href=\"#Evaluate_Algebraic_Expressions_and_Formulas_Page_No_385\">Evaluate Algebraic Expressions and Formulas &#8211; Page No. 385<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_386\">Lesson Check &#8211; Page No. 386<\/a><\/li>\n<\/ul>\n<p><strong>Mid-Chapter Checkpoint<\/strong><\/p>\n<ul>\n<li><a href=\"#Mid_Chapter_Checkpoint_Page_No_387\">Mid-Chapter Checkpoint Vocabulary &#8211; Page No. 387<\/a><\/li>\n<li><a href=\"#Mid_Chapter_Checkpoint_Page_No_388\">Mid-Chapter Checkpoint Page No. 388<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 6: Use Algebraic Expressions<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_391\">Share and Show &#8211; Page No. 391<\/a><\/li>\n<li><a href=\"#Problem_Solving_+_Applications_Page_No_392\">Problem Solving + Applications &#8211; Page No. 392<\/a><\/li>\n<li><a href=\"#Use_Algebraic_Expressions_Page_No_393\">Use Algebraic Expressions &#8211; Page No. 393<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_394\">Lesson Check &#8211; Page No. 394<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 7: Problem Solving \u2022 Combine Like Terms<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_397\">Share and Show &#8211; Page No. 397<\/a><\/li>\n<li><a href=\"#On_Your_Own_Page_No_398\">On Your Own &#8211; Page No. 398<\/a><\/li>\n<li><a href=\"#Problem_Solving_Combine_Like_Terms_Page_No_399\">Problem Solving Combine Like Terms &#8211; Page No. 399<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_400\">Lesson Check &#8211; Page No. 400<\/a><\/li>\n<li><a href=\"#Share_and_Show_Page_No_403\">Share and Show &#8211; Page No. 403<\/a><\/li>\n<li><a href=\"#Problem_Solving_+_Applications_Page_No_404\">Problem Solving + Applications &#8211; Page No. 404<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 8: Generate Equivalent Expressions<\/strong><\/p>\n<ul>\n<li><a href=\"#Generate_Equivalent_Expressions_Page_No_405\">Generate Equivalent Expressions &#8211; Page No. 405<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_406\">Lesson Check &#8211; Page No. 406<\/a><\/li>\n<li><a href=\"#Share_and_Show_Page_No_409\">Share and Show &#8211; Page No. 409<\/a><\/li>\n<li><a href=\"#Problem_Solving_+_Applications_Page_No_410\">Problem Solving + Applications &#8211; Page No. 410<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 9: Identify Equivalent Expressions<\/strong><\/p>\n<ul>\n<li><a href=\"#Identify_Equivalent_Expressions_Page_No_411\">Identify Equivalent Expressions &#8211; Page No. 411<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_412\">Lesson Check &#8211; Page No. 412<\/a><\/li>\n<\/ul>\n<p><strong>Chapter 7 Review\/Test<\/strong><\/p>\n<ul>\n<li><a href=\"#Chapter_7_Review_Test_Page_No_413\">Chapter 7 Review\/Test &#8211; Page No. 413<\/a><\/li>\n<li><a href=\"#Chapter_7_Review_Test_Page_No_414\">Chapter 7 Review\/Test &#8211; Page No. 414<\/a><\/li>\n<li><a href=\"#Chapter_7_Review_Test_Page_No_415\">Chapter 7 Review\/Test &#8211; Page No. 415<\/a><\/li>\n<li><a href=\"#Chapter_7_Review_Test_Page_No_416\">Chapter 7 Review\/Test &#8211; Page No. 416<\/a><\/li>\n<li><a href=\"#Chapter_7_Review_Test_Page_No_417\">Chapter 7 Review\/Test &#8211; Page No. 417<\/a><\/li>\n<li><a href=\"#Chapter_7_Review_Test_Page_No_418\">Chapter 7 Review\/Test &#8211; Page No. 418<\/a><\/li>\n<\/ul>\n<h3><a id=\"Share_and_Show_Page_No_359\"><\/a>Share and Show &#8211; Page No. 359<\/h3>\n<p>Question 1.<br \/>\nWrite 2<sup>4<\/sup> by using repeated multiplication. Then find the value of 2<sup>4<\/sup>.<br \/>\n___________<\/p>\n<p>Answer: 16<\/p>\n<p>Explanation:<br \/>\nThe repeated factor is 2<br \/>\nThe number 2 is repeated 4 times.<br \/>\nThe repeated multiplication of 2<sup>4 <\/sup>is 2 \u00d7 2 \u00d7 2 \u00d7 2 = 16<br \/>\nThus the value of 2<sup>4 <\/sup>is 16.<\/p>\n<p><strong>Use one or more exponents to write the expression.<\/strong><\/p>\n<p>Question 2.<br \/>\n7 \u00d7 7 \u00d7 7 \u00d7 7<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 7<sup>4<\/sup><\/p>\n<p>Explanation:<br \/>\nThe repeated factor is 7.<br \/>\n7 is repeated four times.<br \/>\nThe exponent of the repeated multiplication 7 \u00d7 7 \u00d7 7 \u00d7 7 is 7<sup>4<\/sup><\/p>\n<p>Question 3.<br \/>\n5 \u00d7 5 \u00d7 5 \u00d7 5 \u00d7 5<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 5<sup>5<\/sup><\/p>\n<p>Explanation:<br \/>\nThe repeated factor is 5. The number 5 is repeated five times.<br \/>\nThe exponent of the repeated multiplication 5 \u00d7 5 \u00d7 5 \u00d7 5 \u00d7 5 is 5<sup>5<\/sup><\/p>\n<p>Question 4.<br \/>\n3 \u00d7 3 \u00d7 4 \u00d7 4<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 3<sup>2<\/sup> \u00d7 4<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe exponent of the repeated multiplication 3 \u00d7 3 is 3<sup>2<br \/>\n<\/sup>The exponent of the repeated multiplication 4 \u00d7 4 is 4<sup>2<br \/>\n<\/sup>Thus the exponent for 3 \u00d7 3 \u00d7 4 \u00d7 4 is 3<sup>2<\/sup> \u00d7 4<sup>2<\/sup><\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>Find the value.<\/strong><\/p>\n<p>Question 5.<br \/>\n20<sup>2<\/sup><br \/>\n______<\/p>\n<p>Answer: 20 \u00d7 20 = 400<\/p>\n<p>Explanation:<br \/>\nThe repeated factor is 20<br \/>\nWrite the factor 2 times.<br \/>\n20 \u00d7 20 = 400<br \/>\nThe value of 20<sup>2 <\/sup>= 400<\/p>\n<p>Question 6.<br \/>\n82<sup>1<\/sup><br \/>\n______<\/p>\n<p>Answer: 82<\/p>\n<p>Explanation:<br \/>\nThe repeated factor is 82<br \/>\nWrite the factor 1 time.<br \/>\nThe value of 82<sup>1 <\/sup>is 82<\/p>\n<p>Question 7.<br \/>\n3<sup>5<\/sup><\/p>\n<p>Answer: 3 \u00d7 3 \u00d7 3 \u00d7 3 \u00d7 3 = 243<\/p>\n<p>Explanation:<br \/>\nThe repeated factor is 3<br \/>\nWrite the factor 5 times.<br \/>\nThe value of 3<sup>5 <\/sup>is 343<\/p>\n<p>Question 8.<br \/>\nWrite 32 as a number with an exponent by using 2 as the base.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 2<sup>5<\/sup><\/p>\n<p>Explanation:<br \/>\nThe exponent of 32 by using the base 2 is 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2\u00a0 = 2<sup>5<\/sup><\/p>\n<p><strong>Complete the statement with the correct exponent.<\/strong><\/p>\n<p>Question 9.<br \/>\n5<sup>?<\/sup> = 125<br \/>\n______<\/p>\n<p>Answer: 5<sup>3<\/sup><\/p>\n<p>Explanation:<br \/>\nThe exponential form of 125 is 5 \u00d7 5 \u00d7 5 = 5<sup>3<br \/>\n<\/sup>5<sup>?<\/sup> = 125<br \/>\n5<sup>?<\/sup> = 5<sup>3<\/sup><br \/>\nWhen bases are equal powers should be equated.<br \/>\nThus the exponent is 3<\/p>\n<p>Question 10.<br \/>\n16<sup>?<\/sup> = 16<br \/>\n______<\/p>\n<p>Answer: 1<\/p>\n<p>Explanation:<br \/>\nThe exponential form of 16 is 16<sup>1<br \/>\n<\/sup>16<sup>?<\/sup> = 16<sup>1<br \/>\n<\/sup>When bases are equal powers should be equated.<br \/>\nThus the exponent is 1.<\/p>\n<p>Question 11.<br \/>\n30<sup>?<\/sup> = 900<br \/>\n______<\/p>\n<p>Answer: 2<\/p>\n<p>Explanation:<br \/>\nThe exponential form of 900 is 30 \u00d7 30 = 30<sup>2<br \/>\n<\/sup>30<sup>?<\/sup> = 30<sup>2<\/sup><br \/>\nWhen bases are equal powers should be equated.<br \/>\nThus the exponent is 2.<\/p>\n<p>Question 12.<br \/>\nUse Repeated Reasoning Find the values of 4<sup>1<\/sup>, 4<sup>2<\/sup>, 4<sup>3<\/sup>, 4<sup>4<\/sup>, and 4<sup>5<\/sup>. Look for a pattern in your results and use it to predict the ones digit in the value of 4<sup>6<\/sup>.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nThe value of 4<sup>1 <\/sup>is 4.<br \/>\nThe value of 4<sup>2 <\/sup>is 4 \u00d7 4 = 16<br \/>\nThe value of 4<sup>3 <\/sup>is 4 \u00d7 4 \u00d7 4 = 64<br \/>\nThe value of 4<sup>4 <\/sup>is 4 \u00d7 4 \u00d7 4 \u00d7 4 = 256<br \/>\nThe value of 4<sup>5 <\/sup>is 4 \u00d7 4 \u00d7 4 \u00d7 4 \u00d7 4 = 1024<br \/>\nThe value of 4<sup>6 <\/sup>is 4 \u00d7 4 \u00d7 4 \u00d7 4 \u00d7 4 \u00d7 4 = 4096<\/p>\n<p>Question 13.<br \/>\nSelect the expressions that are equivalent to 32. Mark all that apply.<br \/>\nOptions:<br \/>\na. 2<sup>5<\/sup><br \/>\nb. 8<sup>4<\/sup><br \/>\nc. 2<sup>3 <\/sup>\u00d7 4<br \/>\nd. 2 \u00d7 4 \u00d7 4<\/p>\n<p>Answer: 2<sup>5<\/sup><\/p>\n<p>Explanation:<br \/>\nThe exponent of 32 by using the base 2 is 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2\u00a0 = 2<sup>5<br \/>\n<\/sup>32 = 2<sup>5<br \/>\n<\/sup>Thus the correct answer is option A.<\/p>\n<h3><a id=\"Bacterial_Growth_Page_No_360\"><\/a>Bacterial Growth &#8211; Page No. 360<\/h3>\n<p>Bacteria are tiny, one-celled organisms that live almost everywhere on Earth. Although some bacteria cause disease, other bacteria are helpful to humans, other animals, and plants. For example, bacteria are needed to make yogurt and many types of cheese.<\/p>\n<p>Under ideal conditions, a certain type of bacterium cell grows larger and then splits into 2 \u201cdaughter\u201d cells. After 20 minutes, the daughter cells split, resulting in 4 cells. This splitting can happen again and again as long as conditions remain ideal.<\/p>\n<p>Complete the table.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-1.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 7 Exponents img 1\" width=\"685\" height=\"423\" \/><br \/>\nExtend the pattern in the table above to answer 14 and 15.<\/p>\n<p>Question 14.<br \/>\nWhat power of 2 shows the number of cells after 3 hours? How many cells are there after 3 hours?<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 2<sup>9<\/sup><\/p>\n<p>Explanation:<br \/>\nSo, each cell doubles every 20 mins. After 20 minutes, you have 1(2) = 2 cells. After 40 minutes, you have 2(2) = 4 cells, etc.<br \/>\n1 hour = 60 minutes<br \/>\n3 hours = 3 \u00d7 60 minutes = 180 minutes<br \/>\n180\/20 = 9 divisions<br \/>\nThus 2<sup>9 <\/sup>cells are there after 3 hours.<\/p>\n<p>Question 15.<br \/>\nHow many minutes would it take to have a total of 4,096 cells?<br \/>\n_______ minutes<\/p>\n<p>Answer: 240 minutes<\/p>\n<p>Explanation:<br \/>\nFirst, convert the cells into the exponential form.<br \/>\nThe exponential form of 4096 is 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2\u00d7 2 \u00d7 2\u00d7 2 \u00d7 2\u00d7 2 \u00d7 2 = 2<sup>12<br \/>\n<\/sup>Multiply the power with 20<br \/>\n12 \u00d7 20 = 240<br \/>\nThus it would take 240 minutes to have a total of 4,096 cells<\/p>\n<h3><a id=\"Exponents_Page_No_361\"><\/a>Exponents &#8211; Page No. 361<\/h3>\n<p><strong>Use one or more exponents to write the expression.<\/strong><\/p>\n<p>Question 1.<br \/>\n6 \u00d7 6<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nThe number 6 is used as a repeated factor.<br \/>\n6 is used as a factor 2 times.<br \/>\nNow write the base and exponent for 6 \u00d7 6 = 6<sup>2<\/sup><\/p>\n<p>Question 2.<br \/>\n11 \u00d7 11 \u00d7 11 \u00d7 11<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nThe number 11 is used as a repeated factor.<br \/>\n11 is used as a factor 4 times.<br \/>\nNow write the base and exponent for 11 \u00d7 11 \u00d7 11 \u00d7 11 = 11<sup>4<\/sup><\/p>\n<p>Question 3.<br \/>\n9 \u00d7 9 \u00d7 9 \u00d7 9 \u00d7 7 \u00d7 7<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nThe number 9 and 7 is used as a repeated factor.<br \/>\n9 is used as a factor 4 times and 7 is used 2 times.<br \/>\nNow write the base and exponent for 9 \u00d7 9 \u00d7 9 \u00d7 9 \u00d7 7 \u00d7 7 = 9<sup>4 <\/sup>\u00d7 7<sup>2<\/sup><\/p>\n<p>Question 4.<br \/>\n6<sup>4<\/sup><br \/>\n_______<\/p>\n<p>Answer:<br \/>\nThe repeated factor is 6.<br \/>\nWrite the factor 4 times.<br \/>\nThe value of 6<sup>4 <\/sup>is 6 \u00d7 6 \u00d7 6 \u00d7 6 = 1296<\/p>\n<p>Question 5.<br \/>\n1<sup>6<\/sup><br \/>\n_______<\/p>\n<p>Answer:<br \/>\nThe repeated factor is 1.<br \/>\nWrite the factor 6 times.<br \/>\nThe value of 1<sup>6 <\/sup>is 1 \u00d7 1 \u00d7 1 \u00d7 1 \u00d7 1 \u00d7 1 = 1<\/p>\n<p>Question 6.<br \/>\n10<sup>5<\/sup><br \/>\n_______<\/p>\n<p>Answer:<br \/>\nThe repeated factor is 10.<br \/>\nWrite the factor 5 times.<br \/>\nThe value of 10<sup>5 <\/sup>is 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 = 1,00,000<\/p>\n<p>Question 7.<br \/>\nWrite 144 with an exponent by using 12 as the base.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 12 \u00d7 12 = 12<sup>2<br \/>\n<\/sup>The exponential form of 144 is 12 \u00d7 12 = 12<sup>2<\/sup><\/p>\n<p>Question 8.<br \/>\nWrite 343 with an exponent by using 7 as the base.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: The exponential form of 343 is 7 \u00d7 7 \u00d7 7 = 7<sup>3<\/sup><\/p>\n<p>Question 9.<br \/>\nEach day Sheila doubles the number of push-ups she did the day before. On the fifth day, she does 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 push-ups. Use an exponent to write the number of push-ups Shelia does on the fifth day.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nThe number 2 is the repeated factor.<br \/>\n2 is repeated 5 times.<br \/>\nThe exponential form of 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 is 2<sup>5<\/sup><\/p>\n<p>Question 10.<br \/>\nThe city of Beijing has a population of more than 10<sup>7<\/sup> people. Write 10<sup>7<\/sup> without using an exponent.<br \/>\n_______<\/p>\n<p>Answer:<br \/>\nThe repeated factor is 10.<br \/>\nWrite the factor 7 times.<br \/>\nThe value of 10<sup>7 <\/sup>is 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 = 10,000,000<\/p>\n<p>Question 11.<br \/>\nExplain what the expression 4<sup>5<\/sup> means and how to find its value.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nThe repeated factor is 4.<br \/>\nWrite the factor 5 times.<br \/>\nThe value of 4<sup>5 <\/sup>is 4 \u00d7 4 \u00d7 4 \u00d7 4 \u00d7 4 = 1024<\/p>\n<h3><a id=\"Lesson_Check_Page_No_362\"><\/a>Lesson Check &#8211; Page No. 362<\/h3>\n<p>Question 1.<br \/>\nThe number of games in the first round of a chess tournament is equal to 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2. Write the number of games using an exponent.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 2<sup>6<\/sup><\/p>\n<p>Explanation:<\/p>\n<p>The number 2 is the repeated factor.<br \/>\n2 is repeated 6 times.<br \/>\n2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 = 2<sup>6<\/sup><\/p>\n<p>Question 2.<br \/>\nThe number of gallons of water in a tank at an aquarium is equal to 8<sup>3<\/sup>. How many gallons of water are in the tank?<br \/>\n_______ gallons<\/p>\n<p>Answer: 512 gallons<\/p>\n<p>Explanation:<br \/>\nThe repeated factor is 8.<br \/>\nWrite the factor 3 times.<br \/>\nThe value of 8<sup>3 <\/sup>is 8 \u00d7 8 \u00d7 8 = 512 gallons<br \/>\nTherefore there are 512 gallons of water in the tank.<\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p>Question 3.<br \/>\nThe table shows the amounts of strawberry juice and lemonade needed to make different amounts of strawberry lemonade. Name another ratio of strawberry juice to lemonade that is equivalent to the ratios in the table.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-2.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 7 Exponents img 2\" width=\"354\" height=\"60\" \/><br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 5 : 15<\/p>\n<p>Explanation:<br \/>\nBy using the above table we can find the ratio of strawberry juice to lemonade.<br \/>\n2 : 6 = 1 : 3<br \/>\nThe ratio of strawberry juice to lemonade next to 4 : 12 is 5 : 15<\/p>\n<p>Question 4.<br \/>\nWhich percent is equivalent to the fraction \\(\\frac{37}{50}\\)?<br \/>\n_______ %<\/p>\n<p>Answer: 74%<\/p>\n<p>Explanation:<br \/>\n\\(\\frac{37}{50}\\) \u00d7 100<br \/>\n0.74 \u00d7 100 = 74<br \/>\nThus 74% is equivalent to the fraction \\(\\frac{37}{50}\\)<\/p>\n<p>Question 5.<br \/>\nHow many milliliters are equivalent to 2.7 liters?<br \/>\n_______ milliliters<\/p>\n<p>Answer: 2700 milliliters<\/p>\n<p>Explanation:<br \/>\nConvert from liters to milliliters.<br \/>\n1 liter = 1000 milliliters<br \/>\n2.7 liters = 2.7 \u00d7 1000 milliliters = 2700 milliliters<br \/>\n2.7 liters is equivalent to 2700 milliliters.<\/p>\n<p>Question 6.<br \/>\nUse the formula d = rt to find the distance traveled by a car driving at an average speed of 50 miles per hour for 4.5 hours.<br \/>\n_______ miles<\/p>\n<p>Answer: 225 miles<\/p>\n<p>Explanation:<br \/>\nGiven,<br \/>\nr = 50 miles\/hour<br \/>\nt = 4.5 hours<br \/>\nUse the formula d = rt<br \/>\nd = 50 \u00d7 4.5 = 225 miles<br \/>\nThus the distance traveled by a car driving at an average speed of 50 miles per hour for 4.5 hours is 225 miles.<\/p>\n<h3><a id=\"Share_and_Show_Page_No_365\"><\/a>Share and Show &#8211; Page No. 365<\/h3>\n<p>Question 1.<br \/>\nEvaluate the expression 9 + (5<sup>2<\/sup> \u2212 10)<br \/>\n_______<\/p>\n<p>Answer: 24<\/p>\n<p>Explanation:<br \/>\nFirst write the square for 5<sup>2<br \/>\n<\/sup>5<sup>2 <\/sup>is 25<br \/>\nNow simplify the expression 9 + (25 &#8211; 10)<br \/>\n9 + 15 = 24<br \/>\nSo, 9 + (5<sup>2<\/sup> \u2212 10) = 24<\/p>\n<p><strong>Evaluate the expression.<\/strong><\/p>\n<p>Question 2.<br \/>\n6 + 3<sup>3<\/sup> \u00f7 9<br \/>\n_______<\/p>\n<p>Answer: 9<\/p>\n<p>Explanation:<br \/>\n6 + 3<sup>3<\/sup> \u00f7 9<br \/>\n6 + (3<sup>3<\/sup> \u00f7 9)<br \/>\nWrite the factor for 3<sup>3<br \/>\n<\/sup>3<sup>3 <\/sup>= 3 \u00d7 3 \u00d7 3 = 27<br \/>\n6 + (27 \u00f7 9)<br \/>\n27 \u00f7 9 = 3<br \/>\n6 + 3 = 9<br \/>\nThus 6 + 3<sup>3<\/sup> \u00f7 9 = 9<\/p>\n<p>Question 3.<br \/>\n(15 \u2212 3)<sup>2<\/sup> \u00f7 9<br \/>\n_______<\/p>\n<p>Answer: 16<\/p>\n<p>Explanation:<br \/>\nFirst subtract 15 &#8211; 3 = 12<br \/>\n(12)<sup>2<\/sup> \u00f7 9<br \/>\n(12)<sup>2<\/sup> = 12 \u00d7 12 = 144<br \/>\n144 \u00f7 9<br \/>\n9 divides 144 16 times.<br \/>\n144 \u00f7 9 = 16<br \/>\nThus (15 \u2212 3)<sup>2<\/sup> \u00f7 9 = 16<\/p>\n<p>Question 4.<br \/>\n(8 + 9<sup>2<\/sup>) \u2212 4 \u00d7 10<br \/>\n_______<\/p>\n<p>Answer: 49<\/p>\n<p>Explanation:<br \/>\nFirst multiply 9 \u00d7 9 = 81<br \/>\n(8 + 81) &#8211; (4 \u00d7 10)<br \/>\nMultiply 4 and 10.<br \/>\n4 \u00d7 10 = 40<br \/>\n(8 + 81) &#8211; (40)<br \/>\n89 &#8211; 40 = 49<br \/>\n(8 + 9<sup>2<\/sup>) \u2212 4 \u00d7 10 = 49<\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>Evaluate the expression<\/strong><\/p>\n<p>Question 5.<br \/>\n10 + 6<sup>2<\/sup> \u00d7 2 \u00f7 9<br \/>\n_______<\/p>\n<p>Answer: 18<\/p>\n<p>Explanation:<br \/>\n10 + (6<sup>2<\/sup> \u00d7 2) \u00f7 9<br \/>\nMultipley 6 \u00d7 6 = 36<br \/>\n10 + (36 \u00d7 2) \u00f7 9<br \/>\nMultiply 36 and 2 and then divide by 9.<br \/>\n10 + (72 \u00f7 9)<br \/>\n10 + 8 = 18<br \/>\nSo, 10 + 6<sup>2<\/sup> \u00d7 2 \u00f7 9 = 18<\/p>\n<p>Question 6.<br \/>\n6<sup>2<\/sup> \u2212 (2<sup>3<\/sup> + 5)<br \/>\n_______<\/p>\n<p>Answer: 23<\/p>\n<p>Explanation:<\/p>\n<p>The value of 6<sup>2 <\/sup>is 6 \u00d7 6 = 36<br \/>\nThe value of 2<sup>3 <\/sup>is 2 \u00d7 2 \u00d7 2 = 8<br \/>\n36 &#8211; (8 + 5)<br \/>\n36 &#8211; 13 = 23<br \/>\nThus the answer for the expression for 6<sup>2<\/sup> \u2212 (2<sup>3<\/sup> + 5) is 23.<\/p>\n<p>Question 7.<br \/>\n16 + 18 \u00f7 9 + 3<sup>4<\/sup><br \/>\n_______<\/p>\n<p>Answer: 99<\/p>\n<p>Explanation:<br \/>\n16 + (18 \u00f7 9) + 3<sup>4<br \/>\n<\/sup>First divide 18 by 9<br \/>\n16 + 2 + 3<sup>4<br \/>\n<\/sup>18 + 3<sup>4<br \/>\n<\/sup>The value of 3<sup>4 <\/sup>is 3 \u00d7 3 \u00d7 3 \u00d7 3 = 81<br \/>\n18 + 81 = 99<br \/>\nThus the answer for the expression 16 + (18 \u00f7 9) + 3<sup>4 <\/sup>is 99.<\/p>\n<p><strong>Place parentheses in the expression so that it equals the given value.<\/strong><\/p>\n<p>Question 8.<br \/>\n10<sup>2<\/sup> \u2212 50 \u00f7 5<br \/>\nvalue: 10<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 10<\/p>\n<p>Explanation:<br \/>\n10<sup>2<\/sup> \u2212 50 \u00f7 5<br \/>\nThe factor of 10<sup>2<\/sup> is 10 \u00d7 10 = 100<br \/>\n(10<sup>2<\/sup> \u2212 50) \u00f7 5<br \/>\n50 \u00f7 5 = 10<br \/>\n10<sup>2<\/sup> \u2212 50 \u00f7 5 = 10<br \/>\nThe value of 10<sup>2<\/sup> \u2212 50 \u00f7 5 = 10<\/p>\n<p>Question 9.<br \/>\n20 + 2 \u00d7 5 + 4<sup>1<\/sup><br \/>\nvalue: 38<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 38<\/p>\n<p>Explanation:<br \/>\n20 + 2 \u00d7 5 + 4<sup>1<br \/>\n<\/sup>The value of 4<sup>1 <\/sup>is 4.<br \/>\n20 + 2 \u00d7 (5 + 4)<br \/>\n20 + 2 \u00d7 9<br \/>\nNow multiply 2 and 9.<br \/>\n20 + 18 = 38<br \/>\nThe value of 20 + 2 \u00d7 5 + 4<sup>1 <\/sup>= 38<\/p>\n<p>Question 10.<br \/>\n28 \u00f7 2<sup>2<\/sup> + 3<br \/>\nvalue: 4<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 4<\/p>\n<p>Explanation:<br \/>\n28 \u00f7 2<sup>2<\/sup> + 3<br \/>\n28 \u00f7 (2<sup>2<\/sup> + 3)<br \/>\nThe value of 2<sup>2 <\/sup>is 4<br \/>\n28 \u00f7 (4 + 3)<br \/>\n28 \u00f7 7 = 4<br \/>\nThe value of 28 \u00f7 2<sup>2<\/sup> + 3 is 4.<\/p>\n<h3><a id=\"Problem_Solving_+_Applications_Page_No_366\"><\/a>Problem Solving + Applications &#8211; Page No. 366<\/h3>\n<p><strong>Use the table for 11\u201313.<\/strong><br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-3.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 7 Exponents img 3\" width=\"274\" height=\"156\" \/><\/p>\n<p>Question 11.<br \/>\nWrite an Expression To find the cost of a window, multiply its area in square feet by the price per square foot. Write and evaluate an expression to find the cost of a knot window<br \/>\n$ _______<\/p>\n<p>Answer: 108<\/p>\n<p>Explanation:<br \/>\nTo find the cost of the knot window multiply the area with the price per square foot.<br \/>\nArea per square feet is 2<sup>2<br \/>\n<\/sup>Price per square foot is $27<br \/>\nCost = 2<sup>2<\/sup> \u00d7 27 = 4 \u00d7 27 = 108<br \/>\nThus the cost of a knot window is $108<\/p>\n<p>Question 12.<br \/>\nA builder installs 2 rose windows and 2 tulip windows. Write and evaluate an expression to find the combined area of the windows.<br \/>\n_______ square feet<\/p>\n<p>Answer: 50<\/p>\n<p>Explanation:<br \/>\nThe area of rose window is 3<sup>2<br \/>\n<\/sup>The area of tulip windows is 2<sup>2<br \/>\n<\/sup>Combines area of rose and tulip window is 3<sup>2<\/sup> + 2<sup>2<\/sup> = 5<sup>2<br \/>\n<\/sup>5<sup>2<\/sup> \u00d7 2 = 25 \u00d7 2 = 50<br \/>\nThus the area of the combined windows is 50 square feet.<\/p>\n<p>Question 13.<br \/>\nDeShawn bought a tulip window. Emma bought a rose window. Write and evaluate an expression to determine how much more DeShawn paid for his window than Emma paid for hers.<br \/>\n$ _______<\/p>\n<p>Answer: 258<\/p>\n<p>Explanation:<br \/>\nGiven that, DeShawn bought a tulip window.<br \/>\nDeShawn bought it for 4<sup>2<\/sup> \u00d7 $33 = 16 \u00d7 $33 = 528<br \/>\nEmma bought a rose window<br \/>\nEmma bought it for 3<sup>2<\/sup> \u00d7 30 = 9 \u00d7 30 = 270<br \/>\n$528 &#8211; $270 = $258<br \/>\nDeShawn paid $258 for his window than Emma paid for hers.<\/p>\n<p>Question 14.<br \/>\nWhat\u2019s the Error? Darius wrote 17 \u2212 2<sup>2<\/sup> = 225. Explain his error.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 17 &#8211; 4 is actually 13 but not 225.<\/p>\n<p>Question 15.<br \/>\nMs. Hall wrote the expression 2 \u00d7 (3 + 5)<sup>2<\/sup>\u00f7 4 on the board. Shyann said the first step is to evaluate 52. Explain Shyann\u2019s mistake. Then evaluate the expression<br \/>\n_______<\/p>\n<p>Answer: 32<\/p>\n<p>Explanation:<br \/>\n2 \u00d7 (3 + 5)<sup>2<\/sup>\u00f7 4<br \/>\nFirst, add 3 and 5.<br \/>\n2 \u00d7 (8)<sup>2<\/sup>\u00f7 4<br \/>\nThe square of 8 \u00d7 8 is 64.<br \/>\n2 \u00d7 (64 \u00f7 4) = 2 \u00d7 16 = 32<\/p>\n<h3><a id=\"Evaluate_Expressions_Involving_Exponents_Page_No_367\"><\/a>Evaluate Expressions Involving Exponents &#8211; Page No. 367<\/h3>\n<p><strong>Evaluate the expression.<\/strong><\/p>\n<p>Question 1.<br \/>\n5 + 17 \u2212 10<sup>2<\/sup> \u00f7 5<br \/>\n_______<\/p>\n<p>Answer: 2<\/p>\n<p>Explanation:<br \/>\n5 + 17 &#8211; (100 \u00f7 5)<br \/>\nDivide 100 by 5<br \/>\n(5 + 17) &#8211; 20<br \/>\n22 &#8211; 20 = 2<br \/>\nSo, the value for the expression 5 + 17 \u2212 10<sup>2<\/sup> \u00f7 5 = 2<\/p>\n<p>Question 2.<br \/>\n7<sup>2<\/sup> \u2212 3<sup>2<\/sup> \u00d7 4<br \/>\n_______<\/p>\n<p>Answer: 13<\/p>\n<p>Explanation:<br \/>\n7<sup>2<\/sup> \u2212 3<sup>2<\/sup> \u00d7 4<br \/>\n7<sup>2<\/sup> \u2212 (3<sup>2<\/sup> \u00d7 4)<br \/>\n7<sup>2<\/sup> \u2212 (9 \u00d7 4)<br \/>\n49 &#8211; 36 = 13<br \/>\nThus, 7<sup>2<\/sup> \u2212 3<sup>2<\/sup> \u00d7 4 = 13<\/p>\n<p>Question 3.<br \/>\n2<sup>4<\/sup> \u00f7 (7 \u2212 5)<br \/>\n_______<\/p>\n<p>Answer: 8<\/p>\n<p>Explanation:<br \/>\n2<sup>4<\/sup> \u00f7 (7 \u2212 5)<br \/>\n2<sup>4<\/sup> \u00f7 2<br \/>\n2<sup>4<\/sup> = 2 \u00d7 2 \u00d7 2 \u00d7 2 = 16<br \/>\n16 \u00f7 2 = 8<br \/>\n2<sup>4<\/sup> \u00f7 (7 \u2212 5) = 8<\/p>\n<p>Question 4.<br \/>\n(8<sup>2<\/sup> + 36) \u00f7 (4 \u00d7 5<sup>2<\/sup>)<br \/>\n_______<\/p>\n<p>Answer: 1<\/p>\n<p>Explanation:<br \/>\n(8<sup>2<\/sup> + 36) \u00f7 (4 \u00d7 5<sup>2<\/sup>)<br \/>\n8<sup>2<\/sup> = 8 \u00d7 8 = 64<br \/>\n5<sup>2 <\/sup>= 5 \u00d7 5 = 25<br \/>\n(64 + 36) \u00f7 (4 \u00d7 25)<br \/>\n100 \u00f7 100 = 1<br \/>\nSo, (8<sup>2<\/sup> + 36) \u00f7 (4 \u00d7 5<sup>2<\/sup>) = 1<\/p>\n<p>Question 5.<br \/>\n12 + 21 \u00f7 3 + (2<sup>2<\/sup> \u00d7 0)<br \/>\n_______<\/p>\n<p>Answer: 19<\/p>\n<p>Explanation:<br \/>\n12 + 21 \u00f7 3 + 0<br \/>\n12 + (21 \u00f7 3)<br \/>\n12 + 7 = 19<br \/>\n12 + 21 \u00f7 3 + (2<sup>2<\/sup> \u00d7 0) = 19<\/p>\n<p>Question 6.<br \/>\n(12 \u2212 8)<sup>3<\/sup> \u2212 24 \u00d7 2<br \/>\n_______<\/p>\n<p>Answer: 16<\/p>\n<p>Explanation:<br \/>\n(12 \u2212 8)<sup>3<\/sup> \u2212 24 \u00d7 2 = (4)<sup>3<\/sup> \u2212 24 \u00d7 2<br \/>\n64 &#8211; (24 \u00d7 2)<br \/>\n= 64 &#8211; 48 = 16<br \/>\n(12 \u2212 8)<sup>3<\/sup> \u2212 24 \u00d7 2 = 16<\/p>\n<p><strong>Place parentheses in the expression so that it equals the given value.<\/strong><\/p>\n<p>Question 7.<br \/>\n12 \u00d7 2 + 2<sup>3<\/sup><br \/>\nvalue: 120<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\n12 \u00d7 (2 + 2<sup>3<\/sup>)<br \/>\n12 \u00d7 (2 + 8)<br \/>\n12 \u00d7 10 = 120<br \/>\n12 \u00d7 2 + 2<sup>3<\/sup> = 120<\/p>\n<p>Question 8.<br \/>\n7<sup>2<\/sup> + 1 \u2212 5 \u00d7 3<br \/>\nvalue: 135<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\n(7<sup>2<\/sup> + 1 \u2212 5) \u00d7 3<br \/>\n(49 + 1 &#8211; 5) \u00d7 3<br \/>\n(50 &#8211; 5) \u00d7 3<br \/>\n45 \u00d7 3 = 135<br \/>\n7<sup>2<\/sup> + 1 \u2212 5 \u00d7 3 = 135<\/p>\n<p><strong>Problem Solving<\/strong><\/p>\n<p>Question 9.<br \/>\nHugo is saving for a new baseball glove. He saves $10 the first week, and $6 each week for the next 6 weeks. The expression 10 + 6<sup>2<\/sup> represents the total amount in dollars he has saved. What is the total amount Hugo has saved?<br \/>\n$ _______<\/p>\n<p>Answer: $46<\/p>\n<p>Explanation:<br \/>\nHugo is saving for a new baseball glove.<br \/>\nHe saves $10 the first week, and $6 each week for the next 6 weeks.<br \/>\nThe expression 10 + 6<sup>2<\/sup> represents the total amount in dollars he has saved.<br \/>\n10 + 6<sup>2<\/sup> = 10 + 36 = 46<br \/>\ntotal amount Hugo has saved is $46<\/p>\n<p>Question 10.<br \/>\nA scientist placed 5 fish eggs in a tank. Each day, twice the number of eggs from the previous day hatch. The expression 5 \u00d7 2<sup>6<\/sup> represents the number of eggs that hatch on the seventh day. How many eggs hatch on the seventh day?<br \/>\n_______ eggs<\/p>\n<p>Answer: 320 eggs<\/p>\n<p>Explanation:<br \/>\nA scientist placed 5 fish eggs in a tank.<br \/>\nEach day, twice the number of eggs from the previous day hatch.<br \/>\nThe expression 5 \u00d7 2<sup>6<\/sup> represents the number of eggs that hatch on the seventh day.<br \/>\n5 \u00d7 2<sup>6<\/sup> = 5 \u00d7 64 = 320 eggs<br \/>\nTherefore 320 eggs hatch on the seventh day.<\/p>\n<p>Question 11.<br \/>\nExplain how you could determine whether a calculator correctly performs the order of operations.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: Create a problem that must use the order of operations and isn&#8217;t solved by just left to right. Solve it going left to right. Then solve it using the order of operations. Solve it on the calculator. Your answer on the calculator will match the one using the order of operations.<\/p>\n<h3><a id=\"Lesson_Check_Page_No_368\"><\/a>Lesson Check &#8211; Page No. 368<\/h3>\n<p>Question 1.<br \/>\nRitchie wants to paint his bedroom ceiling and four walls. The ceiling and each of the walls are 8 feet by 8 feet. A gallon of paint covers 40 square feet. Write an expression that can be used to find the number of gallons of paint Ritchie needs to buy.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nRitchie wants to paint his bedroom ceiling and four walls.<br \/>\nThe ceiling and each of the walls are 8 feet by 8 feet.<br \/>\nA gallon of paint covers 40 square feet.<br \/>\n8 \u00d7 8 \u00d7 (4 + 1) \u00f7 40<br \/>\n8<sup>2<\/sup> (4 + 1) \u00f7 40<br \/>\nThus the expression that can be used to find the number of gallons of paint Ritchie needs to buy is 8<sup>2<\/sup> (4 + 1) \u00f7 40<\/p>\n<p>Question 2.<br \/>\nA Chinese restaurant uses about 225 pairs of chopsticks each day. The manager wants to order a 30-day supply of chopsticks. The chopsticks come in boxes of 750 pairs. How many boxes should the manager order?<br \/>\n_______ boxes<\/p>\n<p>Answer: 9 boxes<\/p>\n<p>Explanation:<br \/>\nA Chinese restaurant uses about 225 pairs of chopsticks each day.<br \/>\nThe manager wants to order a 30-day supply of chopsticks.<br \/>\nMultiply the number of pairs with the number of days<br \/>\n225 \u00d7 30 = 6750<br \/>\nThe chopsticks come in boxes of 750 pairs.<br \/>\nNow divide the number of chopsticks by the number of pairs.<br \/>\n6750 \u00f7 750 = 9 boxes.<\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p>Question 3.<br \/>\nAnnabelle spent $5 to buy 4 raffle tickets. How many tickets can she buy for $20?<br \/>\n_______ tickets<\/p>\n<p>Answer: 16 tickets<\/p>\n<p>Explanation:<br \/>\nAnnabelle spent $5 to buy 4 raffle tickets.<br \/>\nTo find the number of tickets she can buy for $20.<br \/>\n($20 \u00f7 $5) \u00d7 4<br \/>\n4 \u00d7 4 = 16 tickets<br \/>\nThat means she can buy 16 tickets for $20.<\/p>\n<p>Question 4.<br \/>\nGavin has 460 baseball players in his collection of baseball cards, and 15% of the players are pitchers. How many pitchers are in Gavin\u2019s collection?<br \/>\n_______ pitchers<\/p>\n<p>Answer: 69 pitchers<\/p>\n<p>Explanation:<br \/>\nGavin has 460 baseball players in his collection of baseball cards, and 15% of the players are pitchers.<br \/>\nThe decimal form of 15% is 0.15<br \/>\nNow multiply 460 with 0.15<br \/>\n460 \u00d7 0.15 = 69.00<br \/>\nThus there are 69 pitchers in Gavin&#8217;s collection.<\/p>\n<p>Question 5.<br \/>\nHow many pounds are equivalent to 40 ounces?<br \/>\n_______ pounds<\/p>\n<p>Answer: 2.5 pounds<\/p>\n<p>Explanation:<br \/>\nConvert from ounces to pounds.<br \/>\n1 pound = 16 ounces<br \/>\n1 ounce = 1\/16 pound<br \/>\n40 ounces = 40 \u00d7 1\/16 pound<br \/>\n40 ounces = 2.5 pounds<br \/>\nThus, 2.5 pounds are equivalent to 40 ounces<\/p>\n<p>Question 6.<br \/>\nList the expressions in order from least to greatest.<br \/>\n1<sup>5<\/sup> 3<sup>3<\/sup> 4<sup>2<\/sup> 8<sup>1<\/sup><br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\n1<sup>5<\/sup> 3<sup>3<\/sup> 4<sup>2<\/sup> 8<sup>1<\/sup><br \/>\n1<sup>5<\/sup> = 1 \u00d7 1 \u00d7 1 \u00d7 1 \u00d7 1 = 1<br \/>\n3<sup>3<\/sup> = 3 \u00d7 3 \u00d7 3 = 27<br \/>\n4<sup>2<\/sup> = 4 \u00d7 4 = 16<br \/>\n8<sup>1<\/sup> = 8<br \/>\nThus the order from least to greatest.<br \/>\n1<sup>5<\/sup> 8<sup>1<\/sup> 4<sup>2<\/sup> 3<sup>3<\/sup><\/p>\n<h3><a id=\"Share_and_Show_Page_No_371\"><\/a>Share and Show &#8211; Page No. 371<\/h3>\n<p>Question 1.<br \/>\nWrite an algebraic expression for the product of 6 and p.<br \/>\nWhat operation does the word \u201cproduct\u201d indicate?<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 6 \u00d7 p<br \/>\nExplanation:<br \/>\nThe word product indicates multiplication.<br \/>\nMultiply 6 with p.<br \/>\nThe algebraic expression for the product of 6 and p is 6 \u00d7 p.<\/p>\n<p><strong>Write an algebraic expression for the word expression.<\/strong><\/p>\n<p>Question 2.<br \/>\n11 more than e<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 11 + e<\/p>\n<p>Explanation:<br \/>\nThe word more than indicates addition operation.<br \/>\nSo, the algebraic expression is 11 + e<\/p>\n<p>Question 3.<br \/>\n9 less than the quotient of n and 5<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 9 &#8211; (n \u00f7 5)<\/p>\n<p>Explanation:<br \/>\nThe word &#8220;less than&#8221; indicates subtraction and the &#8220;quotient&#8221; indicates division.<br \/>\nSo, the expression is 9 &#8211; (n \u00f7 5)<\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>Write an algebraic expression for the word expression.<\/strong><\/p>\n<p>Question 4.<br \/>\n20 divided by c<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 20 \u00f7 c<\/p>\n<p>Explanation:<br \/>\nHere we have to divide 20 by c.<br \/>\nThe expression is 20 \u00f7 c<\/p>\n<p>Question 5.<br \/>\n8 times the product of 5 and t<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 8 \u00d7 (5t)<\/p>\n<p>Explanation:<br \/>\nThe word times indicate multiplication and the product indicates multiplication.<br \/>\nHere we have to multiply 8 with 5 and t.<br \/>\nThus the expression is 8 \u00d7 5 \u00d7 t = 8 \u00d7 5t<\/p>\n<p>Question 6.<br \/>\nThere are 12 eggs in a dozen. Write an algebraic expression for the number of eggs in d dozen.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 12d<\/p>\n<p>Explanation:<br \/>\nGiven,<br \/>\nThere are 12 eggs in a dozen.<br \/>\nd represents number of eggs in dozen<br \/>\nSo, we have to multiply 12 with d.<br \/>\nThus the algebraic expression is 12d.<\/p>\n<p>Question 7.<br \/>\nA state park charges a $6.00 entry fee plus $7.50 per night of camping. Write an algebraic expression for the cost in dollars of entering the park and camping for n nights.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: $6.00 + $7.50 n<\/p>\n<p>Explanation:<br \/>\nGiven that, A state park charges a $6.00 entry fee plus $7.50 per night of camping.<br \/>\nFind the camping for n nights. The product of $7.50 camping for n nights.<br \/>\n$7.50 \u00d7 n<br \/>\nNow add park charges to the camping nights.<br \/>\n$6.00 + $7.50 n<br \/>\nThus the algebraic expression for the cost in dollars of entering the park and camping for n nights is $6.00 + $7.50 n<\/p>\n<p>Question 8.<br \/>\nLook for Structure At a bookstore, the expression 2c + 8g gives the cost in dollars of c comic books and g graphic novels. Next month, the store\u2019s owner plans to increase the price of each graphic novel by $3. Write an expression that will give the cost of c comic books and g graphic novels next month.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 2c + 11g<\/p>\n<p>Explanation:<br \/>\nLook for Structure At a bookstore, the expression 2c + 8g gives the cost in dollars of c comic books and g graphic novels.<br \/>\nNext month, the store\u2019s owner plans to increase the price of each graphic novel by $3.<br \/>\nHere we have to add $3 to 8 g = 3g + 8g = 11g<br \/>\nSum of cost of c comic books and g graphic novels<br \/>\nThus the expression is 2c + 11g<\/p>\n<h3><a id=\"Unlock_the_Problem_Page_No_372\"><\/a>Unlock the Problem &#8211; Page No. 372<\/h3>\n<p>Question 9.<br \/>\nMartina signs up for the cell phone plan described at the right. Write an expression that gives the total cost of the plan in dollars if Martina uses it for m months.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-4.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 7 Exponents img 4\" width=\"373\" height=\"240\" \/><br \/>\na. What information do you know about the cell phone plan?<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: Pay a low monthly fee of $50. Receive $10 off your first month&#8217;s fee.<\/p>\n<p>Question 9.<br \/>\nb. Write an expression for the monthly fee in dollars for m months.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nM is the number of months.<br \/>\n50 \u00d7 m<br \/>\nGiven that $10 off on first-month fee.<br \/>\n50m + (50-10)<br \/>\n50m + $40<\/p>\n<p>Question 9.<br \/>\nc. What operation can you use to show the discount of $10 for the first month?<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:\u00a0We have to use subtraction operations to show a discount of $10 for the first month.<\/p>\n<p>Question 9.<br \/>\nd. Write an expression for the total cost of the plan in dollars for m months<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 50m + 40<\/p>\n<p>Question 10.<br \/>\nA group of n friends evenly share the cost of dinner. The dinner costs $74. After dinner, each friend pays $11 for a movie. Write an expression to represent what each friend paid for dinner and the movie.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 74 \u00f7 n + 11n<\/p>\n<p>Explanation:<br \/>\nGiven,<br \/>\nA group of n friends evenly share the cost of dinner.<br \/>\nThe dinner costs $74. After dinner, each friend pays $11 for a movie.<br \/>\nThe word share represents the division operation.<br \/>\nThat means we have to divide 74 by n.<br \/>\n74 \u00f7 n<br \/>\nAfter that n friends paid $11 for movie<br \/>\nMultiply 11 with n.<br \/>\nThus the expression to represent what each friend paid for dinner and the movie is 74 \u00f7 n + 11n<\/p>\n<p>Question 11.<br \/>\nA cell phone company charges $40 per month plus $0.05 for each text message sent. Select the expressions that represent the cost in dollars for one month of cell phone usage and sending m text messages. Mark all that apply.<br \/>\nOptions:<br \/>\na. 40m + 0.05<br \/>\nb. 40 + 0.05m<br \/>\nc. 40 more than the product of 0.05 and m<br \/>\nd. the product of 40 and m plus 0.05<\/p>\n<p>Answer: 40 + 0.05m<\/p>\n<p>Explanation:<br \/>\nA cell phone company charges $40 per month plus $0.05 for each text message sent.<br \/>\nLet m represent the messages sent.<br \/>\n40m + 0.05m<br \/>\nThus the answer is option B.<\/p>\n<h3><a id=\"Write_Algebraic_Expressions_Page_No_373\"><\/a>Write Algebraic Expressions &#8211; Page No. 373<\/h3>\n<p><strong>Write an algebraic expression for the word expression.<\/strong><\/p>\n<p>Question 1.<br \/>\n13 less than p<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 13 &#8211; p<\/p>\n<p>Explanation:<br \/>\nLess than is nothing but subtraction.<br \/>\nSo the expression for 13 less than p is 13 &#8211; p<\/p>\n<p>Question 2.<br \/>\nthe sum of x and 9<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: x + 9<\/p>\n<p>Explanation:<br \/>\nThe sum is nothing but an addition.<br \/>\nThus the expression for the sum of x and 9 is x + 9.<\/p>\n<p>Question 3.<br \/>\n6 more than the difference of b and 5<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 6 + (b &#8211; 5)<\/p>\n<p>Explanation:<br \/>\nMore than is nothing but addition and difference means subtraction.<br \/>\nThe expression for 6 more than the difference of b and 5 is 6 + (b &#8211; 5)<\/p>\n<p>Question 4.<br \/>\nthe sum of 15 and the product of 5 and v<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 15 + 5v<\/p>\n<p>Explanation:<br \/>\nProduct is nothing but multiplication and sum is nothing but an addition.<br \/>\nSo, the expression for the sum of 15 and the product of 5 and v is 15 + 5 \u00d7 v<\/p>\n<p>Question 5.<br \/>\nthe difference of 2 and the product of 3 and k<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 2 &#8211; 3k<\/p>\n<p>Explanation:<br \/>\nThe difference means subtraction and Product is nothing but the multiplication<br \/>\nSo, the difference of 2 and the product of 3 and k is 2 &#8211; 3 \u00d7 k<br \/>\n2 &#8211; 3k<\/p>\n<p>Question 6.<br \/>\n12 divided by the sum of h and 2<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 12 \u00f7 h + 2<\/p>\n<p>Explanation:<br \/>\n12 divided by the sum of h and 2<br \/>\nDivide 12 by sum of h and 2.<br \/>\n12 \u00f7 (h + 2)<\/p>\n<p>Question 7.<br \/>\nthe quotient of m and 7<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: m \u00f7 7<\/p>\n<p>Explanation:<br \/>\nGiven the quotient of m and 7<br \/>\nThat means we have to divide m by 7.<br \/>\nThus the answer is m \u00f7 7<\/p>\n<p>Question 8.<br \/>\n9 more than 2 multiplied by f<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 9 + 2f<\/p>\n<p>Explanation:<br \/>\n9 more than 2 multiplied by f<br \/>\nWe have to add 9 to 2 \u00d7 f<br \/>\nSo, the expression is 9 + 2f<\/p>\n<p>Question 9.<br \/>\n6 minus the difference of x and 3<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 6 &#8211; (x &#8211; 3)<\/p>\n<p>Explanation:<br \/>\nFirst, subtract 3 from x<br \/>\nThe expression for 6 minus the difference of x and 3 is 6 &#8211; (x &#8211; 3)<\/p>\n<p>Question 10.<br \/>\n10 less than the quotient of g and 3<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 10 &#8211; (g \u00f7 3)<\/p>\n<p>Explanation:<br \/>\nThe quotient of g and 3 is nothing but divide g by 3<br \/>\ng \u00f7 3<br \/>\nNow subtract g \u00f7 3 from 10.<br \/>\nSo, the expression for 10 less than the quotient of g and 3 is 10 &#8211; (g \u00f7 3)<\/p>\n<p>Question 11.<br \/>\nthe sum of 4 multiplied by a and 5 multiplied by b<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 4a + 5b<\/p>\n<p>Explanation:<br \/>\nFirst, multiply 4 with a and then multiply 5 with b<br \/>\nAfter that add both the expressions.<br \/>\n4a + 5b<br \/>\nSo, the sum of 4 multiplied by a and 5 multiplied by b is 4a + 5b<\/p>\n<p>Question 12.<br \/>\n14 more than the difference of r and s<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 14 + (r &#8211; s)<\/p>\n<p>Explanation:<br \/>\nSubtract r and s<br \/>\nAnd then add 14 to that r -s<br \/>\n14 + (r &#8211; s)<\/p>\n<p><strong>Problem Solving<\/strong><\/p>\n<p>Question 13.<br \/>\nLet h represent Mark\u2019s height in inches. Suzanne is 7 inches shorter than Mark. Write an algebraic expression that represents Suzanne\u2019s height in inches.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: h &#8211; 7<\/p>\n<p>Explanation:<br \/>\nLet h represent Mark\u2019s height in inches. Suzanne is 7 inches shorter than Mark.<br \/>\nThat means we have to subtract 7 from h.<br \/>\ni.e., h &#8211; 7<br \/>\nThus Suzanne\u2019s height is h &#8211; 7 inches.<\/p>\n<p>Question 14.<br \/>\nA company rents bicycles for a fee of $10 plus $4 per hour of use. Write an algebraic expression for the total cost in dollars for renting a bicycle for h hours.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 10 + 4h<\/p>\n<p>Explanation:<br \/>\nA company rents bicycles for a fee of $10 plus $4 per hour of use.<br \/>\nMultiply 4 with hours<br \/>\nAnd then 10 to 4h<br \/>\n10 + 4h<br \/>\nThus the total cost in dollars for renting a bicycle for h hours is 10 + 4h<\/p>\n<p>Question 15.<br \/>\nGive an example of a real-world situation involving two unknown quantities. Then write an algebraic expression to represent the situation.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nCooper bikes so many miles per day and does it for 7 months.<br \/>\nThe expression for the question is 6m \u00d7 7<\/p>\n<h3><a id=\"Lesson_Check_Page_No_374\"><\/a>Lesson Check &#8211; Page No. 374<\/h3>\n<p>Question 1.<br \/>\nThe female lion at a zoo weighs 190 pounds more than the female cheetah. Let c represent the weight in pounds of the cheetah. Write an expression that gives the weight in pounds of the lion.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: c + 190<\/p>\n<p>Explanation:<br \/>\nGiven that, The female lion at a zoo weighs 190 pounds more than the female cheetah.<br \/>\nLet c represent the weight in pounds of the cheetah.<br \/>\nWe have to add 190 to the weight in pounds of the cheetah.<br \/>\nThat means c + 190<br \/>\nThus the expression that gives the weight in pounds of the lion is c + 190.<\/p>\n<p>Question 2.<br \/>\nTickets to a play cost $8 each. Write an expression that gives the ticket cost in dollars for a group of g girls and b-boys.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 8 \u00d7 (g + b)<\/p>\n<p>Explanation:<br \/>\nFirst add girls group and boys group.<br \/>\ng + b<br \/>\nAnd then multiply 8 with the group of girls and boys.<br \/>\n8 \u00d7 (g + b)<br \/>\nSo, the expression that gives the ticket cost in dollars for a group of g girls and b-boys is 8 \u00d7 (g + b).<\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p>Question 3.<br \/>\nA bottle of cranberry juice contains 32 fluid ounces and costs $2.56. What is the unit rate?<br \/>\n$ _______ per fluid ounce<\/p>\n<p>Answer: 0.08<\/p>\n<p>Explanation:<br \/>\nA bottle of cranberry juice contains 32 fluid ounces and costs $2.56.<br \/>\nDivide the number of fluid ounces by the cost.<br \/>\n32 \u00f7 $2.56<br \/>\n32\/2.56 = 0.08<br \/>\nThe unit rate is 0.08 per fluid ounce.<\/p>\n<p>Question 4.<br \/>\nThere are 32 peanuts in a bag. Elliott takes 25% of the peanuts from the bag. Then Zaire takes 50% of the remaining peanuts. How many peanuts are left in the bag?<br \/>\n_______ peanuts<\/p>\n<p>Answer: 12<\/p>\n<p>Explanation:<br \/>\nFirst, we have to find 25% of 32.<br \/>\n25% of 32 its 0.25 \u00d7 32=8<br \/>\nNow we have to subtract 32 and 8<br \/>\n32 &#8211; 8=24<br \/>\nNow we have to find 50% of 24<br \/>\n50% of 24 = 12<br \/>\n24-12=12.<br \/>\nThus 12 peanuts are left in the bag.<\/p>\n<p>Question 5.<br \/>\nHank earns $12 per hour for babysitting. How much does he earn for 15 hours of babysitting?<br \/>\n$ _______<\/p>\n<p>Answer: 180<\/p>\n<p>Explanation:<br \/>\nHank earns $12 per hour for babysitting.<br \/>\nMultiply $12 with 15<br \/>\n12 \u00d7 15 = $180<br \/>\nHe earned $180 for 15 hours of babysitting.<\/p>\n<p>Question 6.<br \/>\nWrite an expression using exponents that represent the area of the figure in square centimeters<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-5.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 7 Exponents img 5\" width=\"165\" height=\"140\" \/><br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 7<sup>2<\/sup> &#8211; 2<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of the square is 7 cm \u00d7 7 cm = 7<sup>2<\/sup><br \/>\nThe area of the square is 2 cm \u00d7 2 cm = 2<sup>2<br \/>\n<\/sup>Now subtract a small square from the large square.<br \/>\nThe expression that represents the area of the figure is 7<sup>2<\/sup> &#8211; 2<sup>2<\/sup><\/p>\n<h3><a id=\"Share_and_Show_Page_No_377\"><\/a>Share and Show &#8211; Page No. 377<\/h3>\n<p><strong>Identify the parts of the expression. Then, write a word expression for the numerical or algebraic expression.<\/strong><\/p>\n<p>Question 1.<br \/>\n7 \u00d7 (9 \u00f7 3)<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nThe quotient of 9 and 3 and then multiply with 7.<br \/>\nWord expression: Product of 7 with the quotient of 9 and 3.<\/p>\n<p>Question 2.<br \/>\n5m + 2n<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nProduct of 5 and m and product of 2 and n<br \/>\nNow add both the product of 5 and m and 2 and n.<br \/>\nWord Expression: Product of 5 and m plus the product of 2 and n.<\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>Practice: Copy and Solve Identify the parts of the expression. Then write a word expression for the numerical or algebraic expression.<\/strong><\/p>\n<p>Question 3.<br \/>\n8 + (10 \u2212 7)<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nSubtraction is the difference between 10 and 7. Addition to the subtraction of 10 and 7.<br \/>\nWord expression: Add 8 to the difference between 10 and 7.<\/p>\n<p>Question 4.<br \/>\n1.5 \u00d7 6 + 8.3<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nThe addition is the sum of 6 and 8.3 and then multiply the sum to 1.5.<br \/>\nWord expression: 1.5 times the sum of 6 and 8.3<\/p>\n<p>Question 5.<br \/>\nb + 12x<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nProduct of 12 and x. Add b to the product of 12 and x.<br \/>\nWord expression: Sum of b to the product of 12 and x.<\/p>\n<p>Question 6.<br \/>\n4a \u00f7 6<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nThe division is the quotient of 4a and 6. Multiply 4 and a. The expression is the product of 4 and a divided by 6.<br \/>\nWord expression: The quotient of the product 4 and a and 6.<\/p>\n<p><strong>Identify the terms of the expression. Then, give the coefficient of each term.<\/strong><\/p>\n<p>Question 7.<br \/>\nk \u2212 \\(\\frac{1}{3}\\)d<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nThe terms of the expression are k and \\(\\frac{1}{3}\\)d<br \/>\nCoefficients &#8211; 1 and \\(\\frac{1}{3}\\)<\/p>\n<p>Question 8.<br \/>\n0.5x + 2.5y<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nThe terms of the expression are 0.5x and 2.5y<br \/>\nCoefficients &#8211; 0.5 and 2.5<\/p>\n<p>Question 9.<br \/>\nConnect Symbols and Words Ava said she wrote an expression with three terms. She said the first term has the coefficient 7, the second term has the coefficient 1, and the third term has the coefficient 0.1. Each term involves a different variable. Write an expression that could be the expression Ava wrote<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nConnect Symbols and Words Ava said she wrote an expression with three terms.<br \/>\nShe said the first term has the coefficient 7, the second term has the coefficient 1, and the third term has the coefficient 0.1.<br \/>\nThe expression for the first term is 7x<br \/>\nThe expression for the second term is 1y<br \/>\nThe expression for the third term is 0.1z<br \/>\n7x + y + 0.1z<\/p>\n<h3><a id=\"Problem_Solving_+_Applications_Page_No_378\"><\/a>Problem Solving + Applications &#8211; Page No. 378<\/h3>\n<p><strong>Use the table for 10\u201312.<\/strong><br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-6.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 7 Exponents img 6\" width=\"278\" height=\"138\" \/><\/p>\n<p>Question 10.<br \/>\nA football team scored 2 touchdowns and 2 extra points. Their opponent scored 1 touchdown and 2 field goals. Write a numerical expression for the points scored in the game.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nA football team scored 2 touchdowns and 2 extra points.<br \/>\n2 touchdowns = 2 \u00d7 6<br \/>\n2 extra points = 2 \u00d7 1<br \/>\nTheir opponent scored 1 touchdown and 2 field goals.<br \/>\n1 touchdown = 1 \u00d7 6<br \/>\n2 field goals = 2 \u00d7 3<br \/>\nThue the numerical expression is 12 + 2 + 6 + 6<br \/>\n14 + 12<br \/>\nThe numerical expression for the points scored in the game is 14 + 12.<\/p>\n<p>Question 11.<br \/>\nWrite an algebraic expression for the number of points scored by a football team that makes t touchdowns, f field goals, and e extra points<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 6t + 3f + e<\/p>\n<p>Explanation:<br \/>\nThe number of points scored by a football team that makes t touchdowns, f field goals, and e extra points.<br \/>\nThe table shows that touchdown has 6 points, field goal has 3 points and extra point has 1 point.<br \/>\nSo we need to add all the points to make the expressions<br \/>\nThat means 6t + 3f + e<\/p>\n<p>Question 12.<br \/>\nIdentify the parts of the expression you wrote in Exercise 11.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Question 13.<br \/>\nGive an example of an expression involving multiplication in which one of the factors is a sum. Explain why you do or do not need parentheses in your expression<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 6 \u00d7 2 + 3<br \/>\nIn this expression, there is no need for parentheses because there are no exponents or multiple operations.<\/p>\n<p>Question 14.<br \/>\nKennedy bought a pounds of almonds at $5 per pound and p pounds of peanuts at $2 per pound. Write an algebraic expression for the cost of Kennedy\u2019s purchase.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 5 + 2p = x<\/p>\n<p>Explanation:<br \/>\nKennedy bought a pounds of almonds at $5 per pound and p pounds of peanuts at $2 per pound.<br \/>\nWe have to multiply p with $2 per pound.<br \/>\nThe algebraic expression for the cost of Kennedy\u2019s purchase is the sum of 5 and the product of p and 2<br \/>\nThus the expression is 5 + 2p = x<\/p>\n<h3><a id=\"Identify_Parts_of_Expressions_Page_No_379\"><\/a>Identify Parts of Expressions &#8211; Page No. 379<\/h3>\n<p><strong>Identify the parts of the expression. Then write a word expression for the numerical or algebraic expression.<\/strong><\/p>\n<p>Question 1.<br \/>\n(16 \u2212 7) \u00f7 3<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nSubtraction is the difference between 16 and 7. The division is the quotient of the difference and 3<br \/>\nWord expression: the quotient of the difference 16 and 7 and 3.<\/p>\n<p>Question 2.<br \/>\n8 + 6q + q<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nSum of 8 and the product of 6 and q added to q.<br \/>\nAddition &#8211; Sum of 8 plus the product of 6 and q plus q.<br \/>\nAddition &#8211; 6 times q and the sum of q.<br \/>\nMultiply &#8211; the product of 6 and q.<\/p>\n<p><strong>Identify the terms of the expression. Then give the coefficient of each term.<\/strong><\/p>\n<p>Question 3.<br \/>\n11r + 7s<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nThe terms of the expression are 11r and 7s<br \/>\nThe coefficient of each term is 11 and 7.<\/p>\n<p>Question 4.<br \/>\n6g \u2212 h<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nThe terms of the expression are 6g and h<br \/>\nThe coefficient of each term is 6 and 1.<\/p>\n<p><strong>Problem Solving<\/strong><\/p>\n<p>Question 5.<br \/>\nAdam bought granola bars at the store. The expression 6p + 5n gives the number of bars in p boxes of plain granola bars and n boxes of granola bars with nuts. What are the terms of the expression?<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nAdam bought granola bars at the store.<br \/>\nThe expression 6p + 5n gives the number of bars in p boxes of plain granola bars and n boxes of granola bars with nuts.<br \/>\nThe terms of the expression are 6p and 5n.<\/p>\n<p>Question 6.<br \/>\nIn the sixth grade, each student will get 4 new books. There is one class of 15 students and one class of 20 students. The expression 4 \u00d7 (15 + 20) gives the total number of new books. Write a word expression for the numerical expression.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nIn the sixth grade, each student will get 4 new books.<br \/>\nThere is one class of 15 students and one class of 20 students.<br \/>\nThe expression 4 \u00d7 (15 + 20) gives the total number of new books.<br \/>\nThe product of 4 the sum of 15 and 20.<\/p>\n<p>Question 7.<br \/>\nExplain how knowing the order of operations helps you write a word expression for a numerical or algebraic expression.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: Because if you don&#8217;t know and use the order of operations you can get an entirely different answer.<\/p>\n<h3><a id=\"Lesson_Check_Page_No_380\"><\/a>Lesson Check &#8211; Page No. 380<\/h3>\n<p>Question 1.<br \/>\nA fabric store sells pieces of material for $5 each. Ali bought 2 white pieces and 8 blue pieces. She also bought a pack of buttons for $3. The expression 5 \u00d7 (2 + 8) + 3 gives the cost in dollars of Ali\u2019s purchase. How can you describe the term (2 + 8) in words?<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: the sum of 2 and 8<\/p>\n<p>Explanation:<br \/>\nA fabric store sells pieces of material for $5 each.<br \/>\nAli bought 2 white pieces and 8 blue pieces.<br \/>\nShe also bought a pack of buttons for $3.<br \/>\nThe expression 5 \u00d7 (2 + 8) + 3 gives the cost in dollars of Ali\u2019s purchase.<br \/>\nThe word expression for the term 2 + 8 is the sum of 2 and 8.<\/p>\n<p>Question 2.<br \/>\nA hotel offers two different types of rooms. The expression k + 2f gives the number of beds in the hotel where k is the number of rooms with a king-size bed and f is the number of rooms with 2 full-size beds. What are the terms of the expression?<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: k and 2f<\/p>\n<p>Explanation:<br \/>\nThe terms for the expression k + 2f is k and 2f.<\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p>Question 3.<br \/>\nMeg paid $9 for 2 tuna sandwiches. At the same rate, how much does Meg pay for 8 tuna sandwiches?<br \/>\n$ _______<\/p>\n<p>Answer: 36<\/p>\n<p>Explanation:<br \/>\nMeg paid $9 for 2 tuna sandwiches.<br \/>\nTo find how much does Meg pay for 8 tuna sandwiches<br \/>\n2 &#8211; $9<br \/>\n8 -?<br \/>\n$9 \u00d7 8\/2 = 72\/2 = 36<br \/>\nThus Meg pays $36 for 8 tuna sandwiches.<\/p>\n<p>Question 4.<br \/>\nJan is saving for a skateboard. She has saved $30 already, which is 20% of the total price. How much does the skateboard cost?<br \/>\n$ _______<\/p>\n<p>Answer: 150<\/p>\n<p>Explanation:<br \/>\nJan is saving for a skateboard. She has saved $30 already, which is 20% of the total price.<br \/>\nDivide $30 by 20%<br \/>\n30 \u00f7 20%<br \/>\n30 \u00f7 20 \u00d7 1\/100<br \/>\n30 \u00f7 1\/5<br \/>\n30 \u00d7 5 = 150<br \/>\nThus the cost of the skateboard is $150.<\/p>\n<p>Question 5.<br \/>\nIt took Eduardo 8 hours to drive from Buffalo, NY, to New York City, a distance of about 400 miles. Find his average speed.<br \/>\n_______ miles per hour<\/p>\n<p>Answer: 50<\/p>\n<p>Explanation:<br \/>\nGiven,<br \/>\nIt took Eduardo 8 hours to drive from Buffalo, NY, to New York City, a distance of about 400 miles.<br \/>\nWe can use the formula d = rt<br \/>\nr = d\/t<br \/>\nr = 400 miles\/8 hours<br \/>\nr = 50 miles per hour<\/p>\n<p>Question 6.<br \/>\nWrite an expression that represents the value, in cents, of n nickels.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 0.05n<\/p>\n<p>Explanation:<br \/>\nAn expression does not have an equal sign.<br \/>\nSince the value of a nickel is 5 cents and you want to find out the value of n nickels (which means if you had any number of nickels) the expression would be<br \/>\n.05n<\/p>\n<h3><a id=\"Share_and_Show_Page_No_383\"><\/a>Share and Show &#8211; Page No. 383<\/h3>\n<p>Question 1.<br \/>\nEvaluate 5k + 6 for k = 4.<br \/>\n_______<\/p>\n<p>Answer: 26<\/p>\n<p>Explanation:<br \/>\nThe expression is 5k + 6<br \/>\nSubstitute the value k = 4<br \/>\n5(4) + 6 = 20 + 6 = 26<br \/>\n5k + 6 = 26<\/p>\n<p><strong>Evaluate the expression for the given value of the variable.<\/strong><\/p>\n<p>Question 2.<br \/>\nm \u2212 9 for m = 13<br \/>\n_______<\/p>\n<p>Answer: 4<\/p>\n<p>Explanation:<br \/>\nm &#8211; 9<br \/>\nSubstitute the value of m in the expression<br \/>\n13 &#8211; 9 = 4<br \/>\nThus m &#8211; 9 = 4<\/p>\n<p>Question 3.<br \/>\n16 \u2212 3b for b = 4<br \/>\n_______<\/p>\n<p>Answer: 4<\/p>\n<p>Explanation:<br \/>\nGiven the expression 16 &#8211; 3b<br \/>\nNow substitute the value of b in the expression.<br \/>\n16 &#8211; 3b = 16 &#8211; 3(4) = 16 &#8211; 12 = 4<br \/>\n16 &#8211; 3b = 4<\/p>\n<p>Question 4.<br \/>\np<sup>2<\/sup> + 4 for p = 6<br \/>\n_______<\/p>\n<p>Answer: 40<\/p>\n<p>Explanation:<br \/>\nGiven the expression p<sup>2<\/sup> + 4<br \/>\nSubstitute the value of p in the expression<br \/>\n6<sup>2<\/sup> + 4 = 36 + 4 = 40<br \/>\nThus the value of p<sup>2<\/sup> + 4 is 40.<\/p>\n<p>Question 5.<br \/>\nThe formula A = lw gives the area A of a rectangle with length l and width w. What is the area in square feet of a United States flag with a length of 12 feet and a width of 8 feet?<br \/>\n_______ square feet<\/p>\n<p>Answer: 96 square feet<\/p>\n<p>Explanation:<br \/>\nUse the formula A = lw<br \/>\nLength = 12 feet<br \/>\nWidth = 8 feet<br \/>\nA = lw<br \/>\nA = 12 feet \u00d7 8 feet = 96 square feet<br \/>\nThus the area of the United States flag is 96 square feet.<\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>Practice: Copy and Solve Evaluate the expression for the given value of the variable.<\/strong><\/p>\n<p>Question 6.<br \/>\n7s + 5 for s = 3<br \/>\n_______<\/p>\n<p>Answer: 26<\/p>\n<p>Explanation:<br \/>\nGiven the expression 7s + 5<br \/>\nSubstitute\u00a0 the value of S in the above expression<br \/>\n7(3) + 5 = 21 + 5 = 26<\/p>\n<p>Question 7.<br \/>\n21 \u2212 4d for d = 5<br \/>\n_______<\/p>\n<p>Answer: 1<\/p>\n<p>Explanation:<br \/>\nGiven the expression 21 &#8211; 4d<br \/>\nSubstitute\u00a0 the value d = 5 in the above expression<br \/>\n21 &#8211; 4(5) = 21 &#8211; 20 = 1<\/p>\n<p>Question 8.<br \/>\n(t \u2212 6)<sup>2 <\/sup>for t = 11<br \/>\n_______<\/p>\n<p>Answer: 25<\/p>\n<p>Explanation:<br \/>\nGiven the expression (t \u2212 6)<sup>2<br \/>\n<\/sup>Substitute the value t = 11<br \/>\nThus (t \u2212 6)<sup>2<\/sup> = (11\u00a0\u2212 6)<sup>2<\/sup> = 5 \u00d7 5 = 25<\/p>\n<p>9.6 \u00d7 (2v \u2212 3) for v = 5<br \/>\n_______<\/p>\n<p>Answer: 42<\/p>\n<p>Explanation:<br \/>\nGiven the expression 6 \u00d7 (2v &#8211; 3)<br \/>\nSubstitute the value of v in the above expression.<br \/>\n6 \u00d7 (2v &#8211; 3) = 6 \u00d7 (2 \u00d7 5 &#8211; 3)<br \/>\n6 \u00d7 (10 &#8211; 3)<br \/>\n6 \u00d7 7 = 42<br \/>\nThus the value of 6 \u00d7 (2v &#8211; 3) = 42<\/p>\n<p>Question 10.<br \/>\n2 \u00d7 (k<sup>2<\/sup> \u2212 2) for k = 6<br \/>\n_______<\/p>\n<p>Answer: 68<\/p>\n<p>Explanation:<br \/>\nGiven the expression 2 \u00d7 (k<sup>2<\/sup> \u2212 2)<br \/>\nSubstitute the value of k in the above expression<br \/>\n2 \u00d7 (k<sup>2<\/sup> \u2212 2) = 2 \u00d7 (6<sup>2<\/sup> \u2212 2)<br \/>\n2 \u00d7 (36 &#8211; 2) = 2 \u00d7 34 = 68<br \/>\nThus the value of 2 \u00d7 (k<sup>2<\/sup> \u2212 2) is 68<\/p>\n<p>Question 11.<br \/>\n5 \u00d7 (f \u2212 32) \u00f7 9 for f = 95<br \/>\n_______<\/p>\n<p>Answer: 35<\/p>\n<p>Explanation:<br \/>\nThe expression is 5 \u00d7 (f &#8211; 32) \u00f7 9<br \/>\nSubstitute\u00a0 the value f = 95<br \/>\n5 \u00d7 (f &#8211; 32) \u00f7 9 = 5 \u00d7 (95 &#8211; 32) \u00f7 9<br \/>\n5 \u00d7 (63 \u00f7 9) = 5 \u00d7 7 = 35<br \/>\nThe value of 5 \u00d7 (63 \u00f7 9) = 35<\/p>\n<p>Question 12.<br \/>\nThe formula P = 4s gives the perimeter P of a square with side length s. How much greater is the perimeter of a square with a side length of 5 \\(\\frac{1}{2}\\) inches than a square with a side length of 5 inches?<br \/>\n_______ inches<\/p>\n<p>Answer: 2 inches<\/p>\n<p>Explanation:<br \/>\nWe have to use the formula P = 4s to find the perimeter of the square.<br \/>\n4 \u00d7 5 \\(\\frac{1}{2}\\)<br \/>\nConvert the mixed fraction to the improper fraction.<br \/>\n4 \u00d7 11\/2 = 2 \u00d7 11 = 22 inches<br \/>\n4 \u00d7 5 inches = 20 inches<br \/>\nTo find which has the greater\u00a0 perimeter\u00a0 we have to subtract 20 inches from 22 inches<br \/>\n22 inches &#8211; 20 inches = 2 inches<br \/>\nThus the perimeter of a square with 5 \\(\\frac{1}{2}\\) inches is 2 inches greater than a square with a side length of 5 inches.<\/p>\n<h3><a id=\"Problem_Solving_+_Applications_Page_No_384\"><\/a>Problem Solving + Applications &#8211; Page No. 384<\/h3>\n<p><strong>The table shows how much a company charges for skateboard wheels. Each pack of 8 wheels costs $50. Shipping costs $7 for any order. Use the table for 13\u221215.<\/strong><br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-7.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 7 Exponents img 7\" width=\"305\" height=\"256\" \/><\/p>\n<p>Question 13.<br \/>\nComplete the table.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-medium wp-image-6956\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-7-1-300x252.jpg\" alt=\"Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-7\" width=\"300\" height=\"252\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-7-1-300x252.jpg 300w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-7-1.jpg 305w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>Question 14.<br \/>\nA skateboard club has $200 to spend on new wheels this year. What is the greatest number of packs of wheels the club can order?<br \/>\n_______ packs<\/p>\n<p>Answer: 3 packs<\/p>\n<p>Explanation:<br \/>\nA skateboard club has $200 to spend on new wheels this year.<br \/>\nFrom the above table, we can say that the club can order 3 packs of wheels.<\/p>\n<p>Question 15.<br \/>\nMake Sense of Problems A sporting goods store placed an order for 12 packs of wheels on the first day of each month last year. How much did the sporting goods store spend on these orders last year?<br \/>\n$ _______<\/p>\n<p>Answer: 7284<\/p>\n<p>Explanation:<br \/>\nMake Sense of Problems A sporting goods store placed an order for 12 packs of wheels on the first day of each month last year.<br \/>\nSubstitute n = 7 in the expression 50 \u00d7 n + 7<br \/>\nWe get, 50 \u00d7 12 + 7<br \/>\n600 + 7 = 607<br \/>\nNow multiply 607 with 12<br \/>\n607 \u00d7 12 = 7284<br \/>\nTherefore the sporting goods store spent $7284 on these orders last year.<\/p>\n<p>Question 16.<br \/>\nWhat\u2019s the Error? Bob used these steps to evaluate 3m \u2212 3 \u00f7 3 for m = 8. Explain his error.<br \/>\n3 \u00d7 8 \u2212 3 \u00f7 3 = 24 \u2212 3 \u00f7 3<br \/>\n= 21 \u00f7 3<br \/>\n= 7<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nFirst, he has to subtract 8 and 3. But he first multiplied and then subtracted 24 and 3.<br \/>\n3 \u00d7 8 \u2212 3 \u00f7 3 = 3 \u00d7 (8 \u2212 3) \u00f7 3<br \/>\n3 \u00d7 5 \u00f7 3<br \/>\n15 \u00f7 3 = 5<\/p>\n<p>Question 17.<br \/>\nThe surface area of a cube can be found by using the formula 6s<sup>2<\/sup>, where s represents the length of the side of the cube.<br \/>\nThe surface area of a cube that has a side length of 3 meters is _____ meters squared.<br \/>\nThe surface area of a cube that has a side length\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0meters<br \/>\nof 3 meters is _____________ squared<\/p>\n<p>Answer: 5<\/p>\n<p>Explanation:<br \/>\nThe surface area of a cube can be found by using the formula 6s<sup>2<\/sup><br \/>\nhe surface area of a cube that has a side length of 3 meters<br \/>\ns<sup>2<\/sup>\u00a0= 3<sup>2<\/sup>\u00a0= 9<br \/>\n6 \u00d7 9 = 54 square meters<\/p>\n<h3><a id=\"Evaluate_Algebraic_Expressions_and_Formulas_Page_No_385\"><\/a>Evaluate Algebraic Expressions and Formulas &#8211; Page No. 385<\/h3>\n<p><strong>Evaluate the expression for the given values of the variables.<\/strong><\/p>\n<p>Question 1.<br \/>\nw + 6 for w = 11<br \/>\n_______<\/p>\n<p>Answer: 17<\/p>\n<p>Explanation:<br \/>\nGiven the expression w + 6<br \/>\nSubstitute the value w = 6 in the expression<br \/>\nw + 6 = 11 + 6 = 17<\/p>\n<p>Question 2.<br \/>\n17 \u2212 2c for c = 7<br \/>\n_______<\/p>\n<p>Answer: 3<\/p>\n<p>Explanation:<br \/>\nSubstitute\u00a0 the value c = 7 in the given expression<br \/>\n17 &#8211; 2(7) = 17 &#8211; 14 = 3<br \/>\nThus the value for 17 &#8211; 2c is 3.<\/p>\n<p>Question 3.<br \/>\nb<sup>2<\/sup> \u2212 4 for b = 5<br \/>\n_______<\/p>\n<p>Answer: 21<\/p>\n<p>Explanation:<br \/>\nSubstitute the value b = 5 in the expression<br \/>\nb<sup>2<\/sup> \u2212 4 = 5<sup>2<\/sup> \u2212 4 = 25 &#8211; 4 = 21<br \/>\nThus the value for the expression b<sup>2<\/sup> \u2212 4 is 21.<\/p>\n<p>Question 4.<br \/>\n(h \u2212 3)<sup>2<\/sup> for h = 5<br \/>\n_______<\/p>\n<p>Answer: 4<\/p>\n<p>Explanation:<br \/>\nWe have to substitute the value h = 5<br \/>\n(h \u2212 3)<sup>2<\/sup> = (5 \u2212 3)<sup>2<br \/>\n<\/sup>= (2)<sup>2<\/sup> = 4<br \/>\nTherefore the value of (h \u2212 3)<sup>2<\/sup> is 4.<\/p>\n<p>Question 5.<br \/>\nm + 2m + 3 for m = 12<br \/>\n_______<\/p>\n<p>Answer: 39<\/p>\n<p>Explanation:<br \/>\nGiven the expression m + 2m + 3<br \/>\nNow substitute the value m = 12 in the above expression.<br \/>\n12 + 2(12) + 3 = 12 + 24 + 3 = 39.<br \/>\nThe value for m + 2m + 3 = 39.<\/p>\n<p>Question 6.<br \/>\n4 \u00d7 (21 \u2212 3h) for h = 5<br \/>\n_______<\/p>\n<p>Answer: 24<\/p>\n<p>Explanation:<br \/>\nSubstitute h = 5 in the given expression.<br \/>\n4 \u00d7 (21 &#8211; 3h) = 4 \u00d7 (21 &#8211; 3(5))<br \/>\n4 \u00d7 (21 &#8211; 15) = 4 \u00d7 6 = 24<br \/>\nTherefore the value for 4 \u00d7 (21 &#8211; 3h) is 24.<\/p>\n<p>Question 7.<br \/>\n7m \u2212 9n for m = 7 and n = 5<br \/>\n_______<\/p>\n<p>Answer: 4<\/p>\n<p>Explanation:<br \/>\nSubstitute the values m = 7 and n = 5 in the above expression.<br \/>\n7m &#8211; 9n = 7 \u00d7 7 &#8211; 9 \u00d7 5<br \/>\n= 49 &#8211; 45 = 4<br \/>\nThus 7m &#8211; 9n = 4.<\/p>\n<p>Question 8.<br \/>\nd<sup>2<\/sup> \u2212 9k + 3 for d = 10 and k = 9<br \/>\n_______<\/p>\n<p>Answer: 22<\/p>\n<p>Explanation:<br \/>\nGiven the expression d<sup>2<\/sup> \u2212 9k + 3<br \/>\nNow substitute d = 10 and k = 9 in the expression.<br \/>\nd<sup>2<\/sup> \u2212 9k + 3 = 10<sup>2<\/sup> \u2212 9(9) + 3<br \/>\n100 &#8211; 81 + 3 = 22<br \/>\nThus the value for the expression d<sup>2<\/sup> \u2212 9k + 3 is 22.<\/p>\n<p>Question 9.<br \/>\n3x + 4y \u00f7 2 for x = 7 and y = 10<br \/>\n_______<\/p>\n<p>Answer: 41<\/p>\n<p>Explanation:<br \/>\nSubstitute the values x = 7 and y = 10 in the expression.<br \/>\n3x + 4y \u00f7 2 = 3(7) + 4(10) \u00f7 2<br \/>\n21 + 40 \u00f7 2 = 21 + 20 = 41<br \/>\nThus the value for 3x + 4y \u00f7 2 is 41.<\/p>\n<p><strong>Problem Solving<\/strong><\/p>\n<p>Question 10.<br \/>\nThe formula P = 2l + 2w gives the perimeter P of a rectangular room with length l and width w. A rectangular living room is 26 feet long and 21 feet wide. What is the perimeter of the room?<br \/>\n_______ feet<\/p>\n<p>Answer: 94 feet<\/p>\n<p>Explanation:<br \/>\nUse the formula\u00a0 of the perimeter\u00a0 of a rectangle P = 2l + 2w<br \/>\nL = 26 feet<br \/>\nW = 21 feet<br \/>\nP = 2(26) + 2(21)<br \/>\nP = 52 feet + 42 feet<br \/>\nP = 94 feet<br \/>\nTherefore the perimeter of a room is 94 feet.<\/p>\n<p>Question 11.<br \/>\nThe formula C = 5(F \u2212 32) \u00f7 9 gives the Celsius temperature in C degrees for a Fahrenheit temperature of F degrees. What is the Celsius temperature for a Fahrenheit temperature of 122 degrees?<br \/>\n_______ degrees Celsius<\/p>\n<p>Answer: 50<\/p>\n<p>Explanation:<br \/>\nC = 5(F &#8211; 32) \u00f7 9<br \/>\nWe know that F = 122 degrees<br \/>\nSubstitute the value of F in the formula<br \/>\nC = 5(122 &#8211; 32) \u00f7 9<br \/>\nC = 5(90) \u00f7 9<br \/>\nC = 450 \u00f7 9 = 50<br \/>\nThus the answer is 50 degrees Celsius.<\/p>\n<p>Question 12.<br \/>\nExplain how the terms variable, algebraic expression, and evaluate are related.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arthematic operations. If we know the variables, we can replace the variables with their values and then evaluate the expression.<\/p>\n<h3><a id=\"Lesson_Check_Page_No_386\"><\/a>Lesson Check &#8211; Page No. 386<\/h3>\n<p>Question 1.<br \/>\nWhen Debbie baby-sits, she charges $5 to go to the house plus $8 for every hour she is there. The expression 5 + 8h gives the amount in dollars she charges. How much will she charge to baby-sit for 5 hours?<br \/>\n$ _______<\/p>\n<p>Answer: 45<\/p>\n<p>Explanation:<br \/>\nWhen Debbie baby-sits, she charges $5 to go to the house plus $8 for every hour she is there. The expression 5 + 8h gives the amount in dollars she charges.<br \/>\nIf h = 5 hours<br \/>\nSubstitute the value h in the above expression.<br \/>\n5 + 8h = 5 + 8(5) = 5 + 40 = 45<br \/>\nThus she charges $45 to baby-sit for 5 hours.<\/p>\n<p>Question 2.<br \/>\nThe formula to find the cost C in dollars of a square sheet of glass is C = 25s<sup>2<\/sup> where s represents the length of a side in feet. How much will Ricardo pay for a square sheet of glass that is 3 feet on each side?<br \/>\n$ _______<\/p>\n<p>Answer: $225<\/p>\n<p>Explanation:<br \/>\nUse the formula C = 25s<sup>2<\/sup><br \/>\ns represents the length of a side in feet.<br \/>\ns = 3 feet<br \/>\nSubstitute the value s in the above formula.<br \/>\nC = 25s<sup>2<\/sup><br \/>\nC = 25(3<sup>2<\/sup>)<br \/>\nC = 25(9) = 225<br \/>\nRicardo pays $225 for a square sheet of glass that is 3 feet on each side.<\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p>Question 3.<br \/>\nEvaluate using the order of operations.<br \/>\n\\(\\frac{3}{4}+\\frac{5}{6} \\div \\frac{2}{3}\\)<br \/>\n_______<\/p>\n<p>Answer: 2<\/p>\n<p>Explanation:<br \/>\n\\(\\frac{3}{4}\\) + [\/latex]\\frac{5}{6}[\/latex] \u00f7 [\/latex]\\frac{2}{3}[\/latex]<br \/>\n[\/latex]\\frac{5}{6}[\/latex] \u00f7 [\/latex]\\frac{2}{3}[\/latex]<br \/>\n= [\/latex]\\frac{5}{6}[\/latex] \u00d7 [\/latex]\\frac{3}{2}[\/latex] = [\/latex]\\frac{15}{12}[\/latex] = [\/latex]\\frac{5}{4}[\/latex]<br \/>\nNow convert the improper fraction to the mixed fraction.<br \/>\n[\/latex]\\frac{5}{4}[\/latex] = 1 [\/latex]\\frac{1}{4}[\/latex]<br \/>\n1 [\/latex]\\frac{1}{4}[\/latex] + \\(\\frac{3}{4}\\)<br \/>\n1 + [\/latex]\\frac{1}{4}[\/latex] + \\(\\frac{3}{4}\\) = 1 + 1 = 2<br \/>\n\\(\\frac{3}{4}+\\frac{5}{6} \\div \\frac{2}{3}\\) = 2<\/p>\n<p>Question 4.<br \/>\nPatricia scored 80% on a math test. She missed 4 problems. How many problems were on the test?<br \/>\n_______ problems<\/p>\n<p>Answer: 20<\/p>\n<p>Explanation:<br \/>\nPatricia scored 80% on a math test. She missed 4 problems.<br \/>\n4 \u00f7 80%<br \/>\n4 \u00d7 [\/latex]\\frac{100}{80}[\/latex] = 4 \u00d7 5 = 20<br \/>\nTherefore there are 20 questions in the test.<\/p>\n<p>Question 5.<br \/>\nWhat is the value of 7<sup>3<\/sup>?<br \/>\n_______<\/p>\n<p>Answer: 343<\/p>\n<p>Explanation:<br \/>\n7<sup>3<\/sup> = 7 \u00d7 7 \u00d7 7 = 49 \u00d7 7 = 343<br \/>\nThus the value of 7<sup>3<\/sup>\u00a0is 343.<\/p>\n<p>Question 6.<br \/>\nJames and his friends ordered b hamburgers that cost $4 each and f fruit cups that cost $3 each. Write an algebraic expression for the total cost in dollars of their purchases.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 4b + 3f<\/p>\n<p>Explanation:<br \/>\nGiven that, James and his friends ordered b hamburgers that cost $4 each and f fruit cups that cost $3 each.<br \/>\nMultiply b with $4 and multiply $3 with f<br \/>\nAdd 4b and 3f<br \/>\nThus the expression is 4b + 3f.<\/p>\n<h3><a id=\"Mid_Chapter_Checkpoint_Page_No_387\"><\/a>Vocabulary &#8211; Page No. 387<\/h3>\n<p><strong>Choose the best term from the box to complete the sentence.<\/strong><br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-8.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 7 Exponents img 8\" width=\"234\" height=\"169\" \/><\/p>\n<p>Question 1.<br \/>\nA(n) _____ tells how many times a base is used as a factor.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: Exponent<br \/>\nAn Exponent tells how many times a base is used as a factor.<\/p>\n<p>Question 2.<br \/>\nThe mathematical phrase 5+2\u00d718 is an example of a(n) _____.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: Numerical expression<br \/>\nThe mathematical phrase 5+2\u00d718 is an example of Numerical expression.<\/p>\n<p><strong>Concepts and Skills<\/strong><\/p>\n<p><strong>Find the value.<\/strong><\/p>\n<p>Question 3.<br \/>\n5<sup>4<\/sup><br \/>\n________<\/p>\n<p>Answer: 5 \u00d7 5 \u00d7 5 \u00d7 5 = 625<\/p>\n<p>Explanation:<br \/>\nThe number 5 is the repeated factor.<br \/>\n5 is used 4 times.<br \/>\nMultiply 5 four times.<br \/>\n5 \u00d7 5 \u00d7 5 \u00d7 5 = 625<\/p>\n<p>Question 4.<br \/>\n21<sup>2<\/sup><br \/>\n________<\/p>\n<p>Answer: 21 \u00d7 21 = 441<\/p>\n<p>Explanation:<br \/>\nThe number 21 is the repeated factor.<br \/>\n21 is used 2 times.<br \/>\nMultiply 21 two times.<br \/>\n21 \u00d7 21 = 441<\/p>\n<p>Question 5.<br \/>\n8<sup>3<\/sup><br \/>\n________<\/p>\n<p>Answer: 8 \u00d7 8 \u00d7 8 = 512<\/p>\n<p>Explanation:<br \/>\nThe number 8 is the repeated factor.<br \/>\n8 is used 3 times.<br \/>\n8 \u00d7 8 \u00d7 8 = 512<\/p>\n<p><strong>Evaluate the expression.<\/strong><\/p>\n<p>Question 6.<br \/>\n9<sup>2<\/sup> \u00d7 2 \u2212 4<sup>2<\/sup><br \/>\n________<\/p>\n<p>Answer: 146<\/p>\n<p>Explanation:<br \/>\n9<sup>2<\/sup> \u00d7 2 \u2212 4<sup>2<br \/>\n<\/sup>9<sup>2<\/sup> = 9 \u00d7 9 = 81<br \/>\n4<sup>2<\/sup> = 4 \u00d7 4 = 16<br \/>\n81 \u00d7 2 &#8211; 16 = 162 &#8211; 16 = 146<br \/>\nThus 9<sup>2<\/sup> \u00d7 2 \u2212 4<sup>2<\/sup> = 146<\/p>\n<p>Question 7.<br \/>\n2 \u00d7 (10 \u2212 2) \u00f7 2<sup>2<\/sup><br \/>\n________<\/p>\n<p>Answer: 4<\/p>\n<p>Explanation:<br \/>\n2 \u00d7 (10 \u2212 2) \u00f7 2<sup>2<\/sup><br \/>\n2 \u00d7 (10 \u2212 2) \u00f7 4<br \/>\n2 \u00d7 8 \u00f7 4 = 16 \u00f7 4 = 4<br \/>\nThus 2 \u00d7 (10 \u2212 2) \u00f7 2<sup>2<\/sup> = 4<\/p>\n<p>Question 8.<br \/>\n30 \u2212 (3<sup>3<\/sup> \u2212 8)<br \/>\n________<\/p>\n<p>Answer: 11<\/p>\n<p>Explanation:<br \/>\n3<sup>3<\/sup> = 3 \u00d7 3 \u00d7 3 = 27<br \/>\n30 \u2212 (3<sup>3<\/sup> \u2212 8) = 30 &#8211; (27 &#8211; 8) = 30 &#8211; 19 = 11<br \/>\n30 \u2212 (3<sup>3<\/sup> \u2212 8) = 11<br \/>\nSo, 30 \u2212 (3<sup>3<\/sup> \u2212 8) is 11.<\/p>\n<p><strong>Write an algebraic expression for the word expression.<\/strong><\/p>\n<p>Question 9.<br \/>\nthe quotient of c and 8<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: c \u00f7 8<br \/>\nThe quotient is nothing but the division of c by 8. So, the expression is c \u00f7 8.<\/p>\n<p>Question 10.<br \/>\n16 more than the product of 5 and p<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 16 + 5p<\/p>\n<p>Explanation:<br \/>\nThe operation for more than is addition. Here we have to add 16 to the product of 5 and p.<br \/>\nThe product is the operation for multiplication. Multiply 5 and p and then add 16 to it.<br \/>\nThe expression of the word is 16 + 5p.<\/p>\n<p>Question 11.<br \/>\n9 less than the sum of x and 5<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 9 &#8211; x + 5<\/p>\n<p>Explanation:<br \/>\nFirst, we have to evaluate the expression x and 5.<br \/>\nSum of is nothing but adding x and 5.<br \/>\nDifference between 9 and x and 5<br \/>\nThe expression is 9 &#8211; x + 5.<\/p>\n<p><strong>Evaluate the expression for the given value of the variable.<\/strong><\/p>\n<p>Question 12.<br \/>\n5 \u00d7 (h + 3) for h = 7<br \/>\n________<\/p>\n<p>Answer: 50<\/p>\n<p>Explanation:<br \/>\nGiven expression is 5 \u00d7 (h + 3)<br \/>\nSubstitute h = 7 in the above expression.<br \/>\n5 \u00d7 (h + 3) = 5 \u00d7 (7 + 3)<br \/>\n5 \u00d7 10 = 50<br \/>\n5 \u00d7 (h + 3) = 50<\/p>\n<p>Question 13.<br \/>\n2 \u00d7 (c<sup>2<\/sup> \u2212 5) for c = 4<br \/>\n________<\/p>\n<p>Answer: 22<\/p>\n<p>Explanation:<br \/>\nGiven 2 \u00d7 (c<sup>2<\/sup> \u2212 5)<br \/>\nSubstitute c = 4 in the expression<br \/>\n2 \u00d7 (c<sup>2<\/sup> \u2212 5) = 2 \u00d7 (4<sup>2<\/sup> \u2212 5)<br \/>\n= 2 \u00d7 (16 &#8211; 5) = 2 \u00d7 11 = 22<br \/>\n2 \u00d7 (c<sup>2<\/sup> \u2212 5) = 22<\/p>\n<p>Question 14.<br \/>\n7a \u2212 4a for a = 8<br \/>\n________<\/p>\n<p>Answer: 24<\/p>\n<p>Explanation:<br \/>\nGiven, 7a \u2212 4a<br \/>\nSubtract the like terms<br \/>\n7a \u2212 4a = 3a<br \/>\nNow substitute the value a = 8 in the above expression<br \/>\n3a = 3 \u00d7 8 = 24<br \/>\n7a \u2212 4a = 24<\/p>\n<h3><a id=\"Mid_Chapter_Checkpoint_Page_No_388\"><\/a>Page No. 388<\/h3>\n<p>Question 15.<br \/>\nThe greatest value of any U.S. paper money ever printed is 10<sup>5<\/sup> dollars. What is this amount written in standard form?<br \/>\n________<\/p>\n<p>Answer: 100000<\/p>\n<p>Explanation:<br \/>\n10<sup>5<\/sup> dollars = 10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10<br \/>\n10 is a repeated factor.<br \/>\n10 repeated 5 times.<br \/>\n10 \u00d7 10 \u00d7 10 \u00d7 10 \u00d7 10 = 100000 dollars<\/p>\n<p>Question 16.<br \/>\nA clothing store is raising the price of all its sweaters by $3.00. Write an expression that could be used to find the new price of a sweater that originally cost d dollars.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: d + 3<\/p>\n<p>Explanation:<br \/>\nA clothing store is raising the price of all its sweaters by $3.00.<br \/>\nThe cost of the sweater is d dollars. The store is going to add $3.<br \/>\nSo, the new price of a sweater is the sum of d dollars and $3.<br \/>\nThe expression is d + 3.<\/p>\n<p>Question 17.<br \/>\nKendra bought a magazine for $3 and 4 paperback books for $5 each. The expression 3 + 4 \u00d7 5 represents the total cost in dollars of her purchases. What are the terms in this expression?<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 3 and 4 \u00d7 5<\/p>\n<p>Explanation:<br \/>\nKendra bought a magazine for $3 and 4 paperback books for $5 each. The expression 3 + 4 \u00d7 5 represents the total cost in dollars of her purchases.<br \/>\nThe terms in the expression are 3, 4, and 5.<\/p>\n<p>Question 18.<br \/>\nThe expression 5c + 7m gives the number of people who can ride in c cars and m minivans. What are the coefficients in this expression?<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: The coefficients in the expression 5c + 7m are 5 and 7.<\/p>\n<p>Question 19.<br \/>\nThe formula P = a + b + c gives the perimeter P of a triangle with side lengths a, b, and c. How much greater is the perimeter of a triangular field with sides that measure 33 yards, 56 yards, and 65 yards than the perimeter of a triangular field with sides that measure 26 yards, 49 yards, and 38 yards?<br \/>\n________ yards<\/p>\n<p>Answer: 41 yards<\/p>\n<p>Explanation:<br \/>\nFirst, we have to calculate the perimeter of the 1st triangle.<br \/>\nGiven:<br \/>\na = 33 yards<br \/>\nb = 56 yards<br \/>\nc = 65 yards<br \/>\nP1 = a + b + c<br \/>\nP1 = 33 + 56 + 65 = 154 yards<br \/>\nNow we have to calculate the perimeter of 2nd triangle.<br \/>\nGiven:<br \/>\na = 26 yards<br \/>\nb = 49 yards<br \/>\nc = 38 yards<br \/>\nP2 = a + b + c<br \/>\nP2 = 26 + 49 + 38 = 113 yards<br \/>\nNow we have to calculate which triangle has greater perimeter and how much greater.<br \/>\nP1 &#8211; P2 = 154 yards &#8211; 113 yards = 41 yards<br \/>\nTherefore, 41 yards greater is the perimeter of the 1st triangular field than the perimeter of the 2nd triangular field.<\/p>\n<h3><a id=\"Share_and_Show_Page_No_391\"><\/a>Share and Show &#8211; Page No. 391<\/h3>\n<p><strong>Louisa read that the highest elevation of Mount Everest is 8,848 meters. She wants to know how much higher Mount Everest is than Mount Rainier. Use this information for 1\u20132.<\/strong><\/p>\n<p>Question 1.<br \/>\nWrite an expression to represent the difference in the heights of the two mountains. Tell what the variable in your expression represents.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 8848 &#8211; h, where h represents the height of the Mount Rainier<\/p>\n<p>Explanation:<br \/>\nGiven that, the height of the Mount Everest is 8848 meters<br \/>\nLet the height of the Mount Rainier is h<br \/>\nThe difference in height of Mount Everest and height of the Mount Rainier is 8848 &#8211; h.<\/p>\n<p>Question 2.<br \/>\nLouisa researches the highest elevation of Mount Rainier and finds that it is 4,392 meters. Use your expression to find the difference in the mountains\u2019 heights.<br \/>\n________ meters<\/p>\n<p>Answer: 4456 meters<\/p>\n<p>Explanation:<br \/>\nThe height of the Mount Rainier = 4392 meters<br \/>\nReplace the value of height of the Mount Rainier in the above expression.<br \/>\n8848 &#8211; h = 8848 meters &#8211; 4392 meters = 4456 meters<br \/>\nThus the difference between the height of the two mountains is 4456 meters.<\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>A muffin recipe calls for 3 times as much flour as sugar. Use this information for 3\u20135.<\/strong><\/p>\n<p>Question 3.<br \/>\nWrite an expression that can be used to find the amount of flour needed for a given amount of sugar. Tell what the variable in your expression represents.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nLet the amount of sugar used represents the variable is s.<br \/>\nThe expression to find the amount of flour needed for a given amount of sugar is 3 \u00d7 m i.e., 3m<\/p>\n<p>Question 4.<br \/>\nUse your expression to find the amount of flour needed when \\(\\frac{3}{4}\\) cup of sugar is used.<br \/>\n______ \\(\\frac{\u25a1}{\u25a1}\\)<\/p>\n<p>Answer: 2 \\(\\frac{1}{4}\\)<\/p>\n<p>Explanation:<br \/>\nGiven that, A muffin recipe calls for 3 times as much flour as sugar.<br \/>\nThe amount of flour needed when \\(\\frac{3}{4}\\) cup of sugar used is 3 \u00d7 \\(\\frac{3}{4}\\) = \\(\\frac{9}{4}\\)<br \/>\nConvert the improper fraction into the mixed fraction.<br \/>\n\\(\\frac{9}{4}\\) = 2 \\(\\frac{1}{4}\\)<br \/>\nTherefore 2 \\(\\frac{1}{4}\\) amount of flour needed when \\(\\frac{3}{4}\\) cup of sugar is used.<\/p>\n<p>Question 5.<br \/>\nReason Quantitatively Is the value of the variable in your expression restricted to a particular set of numbers? Explain.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: The values that make the denominator equal to zero for a rational expression are known as restricted values. The solutions are the restricted values since they result in a denominator of zero when replaced for the variable(s).<\/p>\n<p><strong>Practice: Copy and Solve Write an algebraic expression for each word expression. Then evaluate the expression for these values of the variable: \\(\\frac{1}{2}\\), 4, and 6.5.<\/strong><\/p>\n<p>Question 6.<br \/>\nthe quotient of p and 4<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: p \u00f7 4<\/p>\n<p>Explanation:<br \/>\nThe expression is p \u00f7 4<br \/>\np = \\(\\frac{1}{2}\\)<br \/>\n\\(\\frac{1}{2}\\) \u00f7 4<br \/>\n\\(\\frac{1}{2}\\)\/4 = \\(\\frac{1}{8}\\)<br \/>\np \u00f7 4 when p = \\(\\frac{1}{2}\\) is \\(\\frac{1}{8}\\)<br \/>\np = 4<br \/>\n4 \u00f7 4 = 1<br \/>\np = 6.5<br \/>\n6.5 \u00f7 4 = 1.625<\/p>\n<p>Question 7.<br \/>\n4 less than the sum of x and 5<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 4 &#8211; (x + 5)<\/p>\n<p>Explanation:<br \/>\nThe expression is 4 &#8211; (x + 5)<br \/>\nx = 1\/2<br \/>\n4 &#8211; (x + 5) = 4 &#8211; 1\/2 + 5<br \/>\n3 1\/2 + 5 = 8 1\/2<br \/>\nx = 4<br \/>\n4 &#8211; x + 5<br \/>\n4 &#8211; 4 + 5 = 5<br \/>\nx = 6.5<br \/>\n4 &#8211; 6.5 + 5 = 2.5<\/p>\n<h3><a id=\"Problem_Solving_+_Applications_Page_No_392\"><\/a>Problem Solving + Applications &#8211; Page No. 392<\/h3>\n<p><strong>Use the graph for 8\u201310.<\/strong><br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-9.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 7 Exponents img 9\" width=\"458\" height=\"411\" \/><\/p>\n<p>Question 8.<br \/>\nWrite expressions for the distance in feet that each animal could run at top speed in a given amount of time. Tell what the variable in your expressions represents.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nThe expression for distance in feet for Elephant = 22t<br \/>\nThe expression for distance in feet for Cheetah = 103t<br \/>\nThe expression for distance in feet for Giraffe = 51t<br \/>\nThe expression for distance in feet for hippopotamus = 21t<br \/>\nWhere t represents the time.<\/p>\n<p>Question 9.<br \/>\nHow much farther could a cheetah run in 20 seconds at top speed than a hippopotamus could?<br \/>\n______ feet<\/p>\n<p>Answer: 1640 feet<\/p>\n<p>Explanation:<br \/>\nThe expression for distance in feet for Cheetah = 103t<br \/>\nwhere t = 20 sec<br \/>\n103t = 103 \u00d7 20 sec = 2060 feet<br \/>\nThe expression for distance in feet for hippopotamus = 21t<br \/>\nwhere t = 20 sec<br \/>\n21t = 21 \u00d7 20 = 420 feet<br \/>\nNow we have to find How much farther could a cheetah run in 20 seconds at top speed than a hippopotamus could<br \/>\n2060 feet &#8211; 420 feet = 1640 feet<\/p>\n<p>Question 10.<br \/>\nA giraffe runs at top speed toward a tree that is 400 feet away. Write an expression that represents the giraffe\u2019s distance in feet from the tree after s seconds.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nThe expression representing the giraffe&#8217;s distance from tree after s seconds, if the rate is 51 ft per second.<br \/>\n7 43\/60 seconds in all<\/p>\n<p>Question 11.<br \/>\nA carnival charges $7 for admission and $2 for each ride. An expression for the total cost of going to the carnival and riding n rides is 7 + 2n.<br \/>\nComplete the table by finding the total cost of going to the carnival and riding n rides.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-10.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 7 Exponents img 10\" width=\"488\" height=\"168\" \/><br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-medium wp-image-6966\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-10-1-300x103.jpg\" alt=\"Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-10\" width=\"300\" height=\"103\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-10-1-300x103.jpg 300w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-10-1.jpg 488w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<h3><a id=\"Use_Algebraic_Expressions_Page_No_393\"><\/a>Use Algebraic Expressions &#8211; Page No. 393<\/h3>\n<p><strong>Jeff sold the pumpkins he grew for $7 each at the farmer\u2019s market.<\/strong><\/p>\n<p>Question 1.<br \/>\nWrite an expression to represent the amount of money in dollars Jeff made selling the pumpkins. Tell what the variable in your expression represents<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 7p, where p is the number of pumpkins<\/p>\n<p>Question 2.<br \/>\nIf Jeff sold 30 pumpkins, how much money did he make?<br \/>\n$ ________<\/p>\n<p>Answer: 210<\/p>\n<p>Explanation:<br \/>\nThe expression is 7p<br \/>\np = 30 pumpkins<br \/>\n7 \u00d7 30 = 210<br \/>\nThus Jeff sold 30 pumpkins for $210.<\/p>\n<p><strong>An architect is designing a building. Each floor will be 12 feet tall.<\/strong><\/p>\n<p>Question 3.<br \/>\nWrite an expression for the number of floors the building can have for a given building height. Tell what the variable in your expression represents.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: The expression for the number of floors is h\/12, where h is the height of the building.<\/p>\n<p>Question 4.<br \/>\nIf the architect is designing a building that is 132 feet tall, how many floors can be built?<br \/>\n________ floors<\/p>\n<p>Answer: 11 floors<\/p>\n<p>Explanation:<br \/>\nGiven the height of the building is 132 feet<br \/>\nSubstitute h in the above expression<br \/>\nh\/12 = 132\/12 = 11 floors<br \/>\nThus 11 floors can be built.<\/p>\n<p><strong>Write an algebraic expression for each word expression. Then evaluate the expression for these values of the variable: 1, 6, 13.5.<\/strong><\/p>\n<p>Question 5.<br \/>\nthe quotient of 300 and the sum of b and 24<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 300 \u00f7 (b + 24)<\/p>\n<p>Explanation:<br \/>\nFor b = 1<br \/>\n300 \u00f7 (b + 24) = 300 \u00f7 (1 + 24)<br \/>\n300 \u00f7 25 = 12<br \/>\nThus 300 \u00f7 (b + 24) when b = 1 is 12.<br \/>\nFor b = 6<br \/>\n300 \u00f7 (b + 24) = 300 \u00f7 (6 + 24)<br \/>\n300 \u00f7 30 = 10<br \/>\nThus 300 \u00f7 (b + 24) when b = 6 is 10.<br \/>\nFor b = 13.5<br \/>\n300 \u00f7 (b + 24) = 300 \u00f7 (13.5 + 24)<br \/>\n300 \u00f7 37.5 = 8<br \/>\n300 \u00f7 (b + 24) when b = 13.5 is 8.<\/p>\n<p>Question 6.<br \/>\n13 more than the product of m and 5<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 13 + 5m<\/p>\n<p>Explanation:<br \/>\nFor m = 1<br \/>\n13 + 5m = 13 + 5(1) = 13 + 6 = 19<br \/>\nFor m = 6<br \/>\n13 + 5m = 13 + 5(6) = 13 + 30 = 43<br \/>\nFor m = 13.5<br \/>\n13 + 5m = 13 + 5(13.5) = 13 + 67.5 = 80.5<\/p>\n<p><strong>Problem Solving<\/strong><\/p>\n<p>Question 7.<br \/>\nIn the town of Pleasant Hill, there is an average of 16 sunny days each month. Write an expression to represent the approximate number of sunny days for any number of months. Tell what the variable represents.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 16m, m for months<\/p>\n<p>Explanation:<br \/>\nIn the town of Pleasant Hill, there is an average of 16 sunny days each month. Write an expression to represent the approximate number of sunny days for any number of months.<br \/>\nwe have to multiply the number of months with 16<br \/>\nThe expression will be 16 times of m = 16m<\/p>\n<p>Question 8.<br \/>\nHow many sunny days can a resident of Pleasant Hill expect to have in 9 months?<br \/>\n________ days<\/p>\n<p>Answer: 144 days<\/p>\n<p>Explanation:<br \/>\nThe expression to represent the approximate number of sunny days for any number of months is 16m<br \/>\nm = 9<br \/>\nSubstitute the value of m in the expression.<br \/>\n16m = 16 \u00d7 9 = 144 days<\/p>\n<p>Question 9.<br \/>\nDescribe a situation in which a variable could be used to represent any whole number greater than 0.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: To represent the number of people any answer can be accepted.<\/p>\n<h3><a id=\"Lesson_Check_Page_No_394\"><\/a>Lesson Check &#8211; Page No. 394<\/h3>\n<p>Question 1.<br \/>\nOliver drives 45 miles per hour. Write an expression that represents the distance in miles he will travel for h hours driven.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 45h<\/p>\n<p>Explanation:<br \/>\nIt is given that Oliver drives 45 miles per hour. Let the number of hours he drove be h. The distance is the product of speed and time. The distance travel by Oliver is defined by the expression is 45h.<\/p>\n<p>Question 2.<br \/>\nSocks cost $5 per pair. The expression 5p represents the cost in dollars of p pairs of socks. Why must p be a whole number?<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: p must be a whole number because in almost 100% of all stores it is not allowed to buy a single sock, you must always buy a pair of socks.<\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p>Question 3.<br \/>\nSterling silver consists of 92.5% silver and 7.5% copper. What decimal represents the portion of the silver in sterling silver?<br \/>\n________<\/p>\n<p>Answer: 0.925<\/p>\n<p>Explanation:<br \/>\nIf Sterling silver is 92.5% silver, that means it has 92.5\/100 * 100% silver<br \/>\nThe fraction 92.5\/100 can be simplified by just moving the decimal 2 places to the left:<br \/>\n92.5\/100 = .925<\/p>\n<p>Question 4.<br \/>\nHow many pints are equivalent to 3 gallons?<br \/>\n________ pints<\/p>\n<p>Answer: 24<\/p>\n<p>Explanation:<br \/>\nConvert from gallons to pints.<br \/>\n1 gallon = 8 pints<br \/>\n3 gallons = 3 \u00d7 8 pints = 24 pints<br \/>\n24 pints are equivalent to 3 gallons.<\/p>\n<p>Question 5.<br \/>\nWhich operation should be done first to evaluate 10 + (66 \u2013 6<sup>2<\/sup>)?<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: Square 6<\/p>\n<p>Question 6.<br \/>\nEvaluate the algebraic expression h(m + n) \u00f7 2 for h = 4, m = 5, and n = 6.<br \/>\n________<\/p>\n<p>Explanation:<br \/>\nGiven the expression h(m + n) \u00f7 2<br \/>\nh = 4<br \/>\nm = 5<br \/>\nn = 6<br \/>\nh(m + n) \u00f7 2 = 4 (5 + 6) \u00f7 2<br \/>\n4 (11) \u00f7 2 = 44 \u00f7 2 = 22<br \/>\nh(m + n) \u00f7 2 = 22<\/p>\n<h3><a id=\"Share_and_Show_Page_No_397\"><\/a>Share and Show &#8211; Page No. 397<\/h3>\n<p>Question 1.<br \/>\nMuseum admission costs $7, and tickets to the mammoth exhibit cost $5. The expression 7p + 5p represents the cost in dollars for p people to visit the museum and attend the exhibit. Simplify the expression by combining like terms.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 12p<\/p>\n<p>Explanation:<\/p>\n<p>7p+5p<br \/>\nWhen you combine like terms, you just add all the terms that have the same variable<br \/>\nso you get 7p + 5p = 12p<\/p>\n<p>Question 2.<br \/>\nWhat if the cost of tickets to the exhibit was reduced to $3? Write an expression for the new cost in dollars for p people to visit the museum and attend the exhibit. Then, simplify the expression by combining like terms.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 10p<\/p>\n<p>Explanation:<br \/>\nMuseum admission costs $7, and tickets to the mammoth exhibit cost $5.<br \/>\nThe expression 7p + 5p represents the cost in dollars for p people to visit the museum and attend the exhibit.<br \/>\nThe cost of tickets to the mammoth exhibit is $5.<br \/>\nIf it is reduced to $3 then the cost will be $5 &#8211; $2 = $3<br \/>\n12p &#8211; 2p = 10p<\/p>\n<p>Question 3.<br \/>\nA store receives tomatoes in boxes of 40 tomatoes each. About 4 tomatoes per box cannot be sold due to damage. The expression 40b \u2212 4b gives the number of tomatoes that the store can sell from a shipment of b boxes. Simplify the expression by combining like terms.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 36b<\/p>\n<p>Explanation:<br \/>\nGiven, A store receives tomatoes in boxes of 40 tomatoes each.<br \/>\nAbout 4 tomatoes per box cannot be sold due to damage.<br \/>\nThe expression 40b \u2212 4b gives the number of tomatoes that the store can sell from a shipment of b boxes.<br \/>\nSubtract 40b and 4b<br \/>\n40b &#8211; 4b = 36b<\/p>\n<p>Question 4.<br \/>\nEach cheerleading uniform includes a shirt and a skirt. The shirts cost $12 each, and skirts cost $18 each. The expression 12u + 18u represents the cost in dollars of buying u uniforms. Simplify the expression by combining like terms.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 30u<\/p>\n<p>Explanation:<br \/>\nThe expression 12u + 18u represents the cost in dollars of buying u uniforms.<br \/>\n12u and 18u are the like terms. So add the two terms<br \/>\n12u + 18u = 30u<\/p>\n<p>Question 5.<br \/>\nA shop sells vases holding 9 red roses and 6 white roses. The expression 9v + 6v represents the total number of roses needed for v vases. Simplify the expression by combining like terms.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 15v<\/p>\n<p>Explanation:<br \/>\nA shop sells vases holding 9 red roses and 6 white roses.<br \/>\nThe expression 9v + 6v represents the total number of roses needed for v vases.<br \/>\nThe like terms are 9v and 6v<br \/>\n9v + 6v = 15v<\/p>\n<h3><a id=\"On_Your_Own_Page_No_398\"><\/a>On Your Own &#8211; Page No. 398<\/h3>\n<p>Question 6.<br \/>\nMarco received a gift card. He used it to buy 2 bike lights for $10.50 each. Then he bought a handlebar bag for $18.25. After these purchases, he had $0.75 left on the card. How much money was on the gift card when Marco received it?<br \/>\n$ _______<\/p>\n<p>Answer:<br \/>\nMarco received a gift card. He used it to buy 2 bike lights for $10.50 each.<br \/>\nThen he bought a handlebar bag for $18.25.<br \/>\nAfter these purchases, he had $0.75 left on the card.<br \/>\nAdd total amount = 2 \u00d7 $10.50 + $18.25 + $0.75<br \/>\n$21 + $19 = $40<br \/>\n$40 was on the gift card when Marco received it.<\/p>\n<p>Question 7.<br \/>\nLydia collects shells. She has 24 sea snail shells, 16 conch shells, and 32 scallop shells. She wants to display the shells in equal rows, with only one type of shell in each row. What is the greatest number of shells Lydia can put in each row?<br \/>\n_______ shells<\/p>\n<p>Answer: 8 shells<\/p>\n<p>Explanation:<br \/>\nLydia collects shells. She has 24 sea snail shells, 16 conch shells, and 32 scallop shells.<br \/>\nShe wants to display the shells in equal rows, with only one type of shell in each row.<br \/>\nThe possible shells in equal rows are 8 because 16, 24, and 32 are the multiples of 8.<br \/>\nThus the greatest number of shells Lydia can put in each row is 8.<\/p>\n<p>Question 8.<br \/>\nThe three sides of a triangle measure 3x + 6 inches, 5x inches, and 6x inches. Write an expression for the perimeter of the triangle in inches. Then simplify the expression by combining like terms.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nPerimeter of the triangle = a + b + c<br \/>\nLet a = 3x + 6 inches<br \/>\nb = 5x inches<br \/>\nc = 6x inches<br \/>\nP = a + b + c<br \/>\nP = 3x + 6 + 5x + 6x<br \/>\nCombine the like terms 3x, 5x, 6x<br \/>\nP = 14x + 6<br \/>\nThus the perimeter of the triangle is 14x + 6.<\/p>\n<p>Question 9.<br \/>\nVerify the Reasoning of Others Karina states that you can simplify the expression 20x + 4 by combining like terms to get 24x. Does Karina\u2019s statement make sense? Explain.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: Karina\u2019s statement doesn&#8217;t make sense. Because the 20x + 4 are not the like terms.<br \/>\nWe can add only the like terms. 20x + 4 \u2260 24x<\/p>\n<p>Question 10.<br \/>\nVincent is ordering accessories for his surfboard. A set of fins costs $24 each and a leash costs $15. The shipping cost is $4 per order. The expression 24b + 15b + 4 can be used to find the cost in dollars of buying b fins and b leashes plus the cost of shipping.<br \/>\nFor numbers 10a\u201310c, select True or False for each statement.<br \/>\n10a. The terms are 24b, 15b and 4.<br \/>\n10b. The like terms are 24b and 15b.<br \/>\n10c. The simplified expression is 43b.<br \/>\n10a. _____________<br \/>\n10b. _____________<br \/>\n10c. _____________<\/p>\n<p>Answer:<br \/>\n10a. True<br \/>\n10b. True<br \/>\n10c. False<\/p>\n<p>Explanation:<br \/>\na. The terms of the expression 24b + 15b + 4 area 24b, 15b, 4.<br \/>\nb. The terms are said to be like if they have the common variable. So, the common terms are 24b, 15b.<br \/>\nc. Combine the like terms 24b and 15b<br \/>\n24b + 15b = 39b<br \/>\nThus the statement is false.<\/p>\n<h3><a id=\"Problem_Solving_Combine_Like_Terms_Page_No_399\"><\/a>Problem Solving Combine Like Terms &#8211; Page No. 399<\/h3>\n<p><strong>Read each problem and solve.<\/strong><\/p>\n<p>Question 1.<br \/>\nA box of pens costs $3 and a box of markers costs $5. The expression 3p + 5p represents the cost in dollars to make p packages that include 1 box of pens and 1 box of markers. Simplify the expression by combining like terms.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 3p + 5p = 8p<\/p>\n<p>Explanation:<br \/>\nA box of pens costs $3 and a box of markers costs $5.<br \/>\nThe expression 3p + 5p represents the cost in dollars to make p packages that include 1 box of pens and 1 box of markers.<br \/>\nAdding the like terms 3p + 5p is 8p.<\/p>\n<p>Question 2.<br \/>\nRiley\u2019s parents got a cell phone plan that has a $40 monthly fee for the first phone. For each extra phone, there is a $15 phone service charge and a $10 text service charge. The expression 40 + 15e + 10e represents the total phone bill in dollars, where e is the number of extra phones. Simplify the expression by combining like terms.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 25e + 40<\/p>\n<p>Explanation:<br \/>\nGiven that,<br \/>\nRiley\u2019s parents got a cell phone plan that has a $40 monthly fee for the first phone.<br \/>\nFor each extra phone, there is a $15 phone service charge and a $10 text service charge.<br \/>\nThe expression 40 + 15e + 10e represents the total phone bill in dollars,<br \/>\nWe have to combine the like terms here<br \/>\nThe like terms in the expression are 15e and 10e.<br \/>\nThat means 40 + 15e + 10e = 25e + 40<\/p>\n<p>Question 3.<br \/>\nA radio show lasts for h hours. For every 60 minutes of air time during the show, there are 8 minutes of commercials. The expression 60h \u2013 8h represents the air time in minutes available for talk and music. Simplify the expression by combining like terms.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 52h<\/p>\n<p>Explanation:<br \/>\nA radio show lasts for h hours. For every 60 minutes of air time during the show, there are 8 minutes of commercials.<br \/>\nThe expression 60h \u2013 8h represents the air time in minutes available for talk and music.<br \/>\nNow we have to Subtract the like terms 60h &#8211; 8h = 52h<\/p>\n<p>Question 4.<br \/>\nA sub shop sells a meal that includes an Italian sub for $6 and chips for $2. If a customer purchases more than 3 meals, he or she receives a $5 discount. The expression 6m + 2m \u2013 5 shows the cost in dollars of the customer\u2019s order for m meals, where m is greater than 3. Simplify the expression by combining like terms.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 8m &#8211; 5<\/p>\n<p>Explanation:<br \/>\nThe expression is 6m + 2m &#8211; 5<br \/>\nNow combine the like terms 6m + 2m &#8211; 5 = 8m &#8211; 5<\/p>\n<p>Question 5.<br \/>\nExplain how combining like terms is similar to adding and subtracting whole numbers. How are they different?<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: It&#8217;s the same because you are adding or subtracting numbers but it&#8217;s different because they can only be added or subtracted if the variable attached is the same. There are no variables when adding\/subtracting regular whole numbers.<\/p>\n<h3><a id=\"Lesson_Check_Page_No_400\"><\/a>Lesson Check &#8211; Page No. 400<\/h3>\n<p>Question 1.<br \/>\nFor each gym class, a school has 10 soccer balls and 6 volleyballs. All of the classes share 15 basketballs. The expression 10c + 6c + 15 represents the total number of balls the school has for c classes. What is a simpler form of the expression?<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 16c + 15<\/p>\n<p>Explanation:<br \/>\nFor each gym class, a school has 10 soccer balls and 6 volleyballs.<br \/>\nAll of the classes share 15 basketballs.<br \/>\nc represents classes.<br \/>\nThe expression is 10c + 6c + 15<br \/>\nCombine the like terms 10c and 6c<br \/>\nNow add common terms 10c + 6c + 15 = 16c + 15<\/p>\n<p>Question 2.<br \/>\nA public library wants to place 4 magazines and 9 books on each display shelf. The expression 4s + 9s represents the total number of items that will be displayed on s shelves. Simplify this expression.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 13s<\/p>\n<p>Explanation:<br \/>\nA public library wants to place 4 magazines and 9 books on each display shelf.<br \/>\nThe expression is 4s + 9s<br \/>\nCombine the like terms 4s + 9s = 13s<\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p>Question 3.<br \/>\nA bag has 8 bagels. Three of the bagels are cranberry. What percent of the bagels are cranberry?<br \/>\n________ %<\/p>\n<p>Answer: 37.5%<\/p>\n<p>Explanation:<br \/>\n[\/latex]\\frac{3}{8}[\/latex] = 0.375<br \/>\n0.375 \u00d7 100 = 37.5 %<br \/>\n37.5% of the bagels are cranberry.<\/p>\n<p>Question 4.<br \/>\nHow many kilograms are equivalent to 3,200 grams?<br \/>\n________ kilograms<\/p>\n<p>Answer: 3.2 kg<\/p>\n<p>Explanation:<br \/>\nConvert from grams into kilograms<br \/>\n1000 grams = 1kg<br \/>\n3200 grams = 3200 \u00d7 1\/1000 kg = 3.2 kg<br \/>\n3.2 kilograms are equivalent to 3,200 grams.<\/p>\n<p>Question 5.<br \/>\nToni earns $200 per week plus $5 for every magazine subscription that she sells. Write an expression that represents how much she will earn in dollars in a week in which she sells s subscriptions.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 200 + 5s<\/p>\n<p>Explanation:<br \/>\nToni earns $200 per week plus $5 for every magazine subscription that she sells.<br \/>\ns represents subscriptions.<br \/>\n200 + 5 \u00d7 s<br \/>\nThus the expression that represents how much she will earn in dollars in a week is 200 + 5s<\/p>\n<p>Question 6.<br \/>\nAt a snack stand, drinks cost $1.50. Write an expression that could be used to find the total cost in dollars of d drinks.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 1.5d<\/p>\n<p>Explanation:<br \/>\nAt a snack stand, drinks cost $1.50.<br \/>\nTo find the total cost in dollars of d drinks we have to multiply 1.50 with d.<br \/>\n1.50 \u00d7 d<br \/>\nThus the expression that could be used to find the total cost in dollars of d drinks is 1.5d<\/p>\n<h3><a id=\"Share_and_Show_Page_No_403\"><\/a>Share and Show &#8211; Page No. 403<\/h3>\n<p><strong>Use properties of operations to write an equivalent expression by combining like terms.<\/strong><\/p>\n<p>Question 1.<br \/>\n\\(3 \\frac{7}{10} r-1 \\frac{1}{5} r\\)<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 2 \\(frac{5}{10}\\)r<\/p>\n<p>Explanation:<br \/>\n3 \\(frac{7}{10}\\)r &#8211; 1 \\(frac{1}{5}\\)r<br \/>\n3 + \\(frac{7}{10}\\)r &#8211; 1 &#8211; \\(frac{1}{5}\\)r<br \/>\n3 &#8211; 1 = 2<br \/>\n\\(frac{7}{10}\\)r &#8211; \\(frac{1}{5}\\)r<br \/>\n\\(frac{7}{10}\\)r &#8211; \\(frac{2}{10}\\)r = \\(frac{5}{10}\\)r<br \/>\n\\(3 \\frac{7}{10} r-1 \\frac{1}{5} r\\) = 2 \\(frac{5}{10}\\)r<\/p>\n<p>Question 2.<br \/>\n20a + 18 + 16a<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 36a + 18<\/p>\n<p>Explanation:<br \/>\nCombine\u00a0 the like terms first<br \/>\n16a and 20a are like terms in the given expression.<br \/>\nAdd 16a and 20a<br \/>\n16a + 20a +18 = 36a + 18<\/p>\n<p>Question 3.<br \/>\n7s + 8t + 10s + 12t<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 17s + 20t<\/p>\n<p>Explanation:<br \/>\nThere are 4 terms in the expression they are 7s, 10s, 8t, 12t.<br \/>\nNow combine the like terms<br \/>\n7s + 10s + 8t + 12t = 17s + 20t<\/p>\n<p><strong>Use the Distributive Property to write an equivalent expression.<\/strong><\/p>\n<p>Question 4.<br \/>\n8(h + 1.5)<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 8h + 12<\/p>\n<p>Explanation:<br \/>\nHere we have to use the distributive property for the above expression.<br \/>\n8(h + 1.5) = 8 \u00d7 h + 1.5 \u00d7 8<br \/>\n= 8h + 12<br \/>\nThus 8(h + 1.5) is 8h + 12.<\/p>\n<p>Question 5.<br \/>\n4m + 4p<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 4(m + p)<\/p>\n<p>Explanation:<br \/>\nHere we have to take 4 as a common factor from the expression.<br \/>\n4m + 4p = 4 \u00d7 m + 4 \u00d7 p<br \/>\nThat implies 4 \u00d7 (m + p)<\/p>\n<p>Question 6.<br \/>\n3a + 9b<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 3(a + 3b)<\/p>\n<p>Explanation:<br \/>\nLet us take 4 as a common factor from the expression.<br \/>\n3a + 9b = 3 \u00d7 a + 9 \u00d7 b<br \/>\n3(a + 3b)<br \/>\n3a + 9b = 3(a + 3b)<\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>Practice: Copy and Solve Use the Distributive Property to write an equivalent expression.<\/strong><\/p>\n<p>Question 7.<br \/>\n3.5(w + 7)<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 3.5w + 24.5<\/p>\n<p>Explanation:<br \/>\nUse the distributive property.<br \/>\nMultiply within the parentheses.<br \/>\n3.5(w + 7) = 3.5 \u00d7 w + 3.5 \u00d7 7<br \/>\n3.5w + 24.5<br \/>\nThus 3.5(w + 7) = 3.5w + 24.5<\/p>\n<p>Question 8.<br \/>\n\\(\\frac{1}{2}\\)(f + 10)<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: \\(\\frac{1}{2}\\)f + 5<\/p>\n<p>Explanation:<br \/>\n\\(\\frac{1}{2}\\)(f + 10)<br \/>\nUse the distributive property.<br \/>\nMultiply within the parentheses.<br \/>\n\\(\\frac{1}{2}\\) \u00d7 f + \\(\\frac{1}{2}\\) \u00d7 10<br \/>\n= \\(\\frac{1}{2}\\)f + 5<br \/>\nThus \\(\\frac{1}{2}\\)(f + 10) = \\(\\frac{1}{2}\\)f + 5<\/p>\n<p>Question 9.<br \/>\n4(3z + 2)<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 12z + 8<\/p>\n<p>Explanation:<br \/>\nUse the distributive property.<br \/>\nMultiply within the parentheses.<br \/>\n4(3z + 2) = 4 \u00d7 3z + 4 \u00d7 2<br \/>\n= 12z + 8<br \/>\nSo, 4(3z + 2) = 12z + 8<\/p>\n<p>Question 10.<br \/>\n20b + 16c<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 4(5b + 4c)<\/p>\n<p>Explanation:<br \/>\n20b + 16c<br \/>\nUse the distributive property.<br \/>\nMultiply within the parentheses.<br \/>\nTake 4 as a common factor.<br \/>\n20b + 16c = 4 \u00d7 5b + 4 \u00d7 4c = 4 (5b + 4c)<br \/>\nThus the expression 20b + 16c = 4 (5b + 4c)<\/p>\n<p>Question 11.<br \/>\n30d + 18<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 6(5d + 3)<\/p>\n<p>Explanation:<br \/>\n30 and 18 are the factors of 6.<br \/>\nSo, take 6 as a common factor.<br \/>\n30d + 18 = 6 \u00d7 5d + 6 \u00d7 3<br \/>\n6 (5d + 3)<br \/>\n30d + 18 = 6 (5d + 3)<\/p>\n<p>Question 12.<br \/>\n24g \u2212 8h<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 8(3g &#8211; h)<\/p>\n<p>Explanation:<br \/>\nGiven the expression 24g \u2212 8h<br \/>\n24 and 8 are the factors of 8.<br \/>\nSo, let us take 8 as a common factor.<br \/>\n24g \u2212 8h = 8 \u00d7 3g &#8211; 8 \u00d7 1h<br \/>\n= 8(3g &#8211; h)<\/p>\n<p>Question 13.<br \/>\nWrite an Expression The lengths of the sides of a triangle are 3t, 2t + 1, and t + 4. Write an expression for the perimeter (sum of the lengths). Then, write an equivalent expression with 2 terms.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 6t + 5<\/p>\n<p>Explanation:<br \/>\nGiven that, The lengths of the sides of a triangle are 3t, 2t + 1, and t + 4.<br \/>\nWe know that the perimeter of the triangle is P = a + b + c<br \/>\nP = 3t + 2t + 1 + t + 4<br \/>\nCombine the like terms.<br \/>\nP = 6t + 5<\/p>\n<p>Question 14.<br \/>\nUse properties of operations to write an expression equivalent to the sum of the expressions 3(g + 5) and 2(3g \u2212 6).<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 3(3g + 1)<\/p>\n<p>Explanation:<br \/>\nGiven two expressions 3(g + 5) and 2(3g \u2212 6).<br \/>\nUse the distributive property to simplify the expressions.<br \/>\n3(g + 5) = 3 \u00d7 g + 3 \u00d7 5 = 3g + 15<br \/>\n2(3g \u2212 6) = 2 \u00d7 3g &#8211; 2 \u00d7 6 = 6g &#8211; 12<br \/>\nAdd both the expressions and combine the like terms<br \/>\n3g + 15 + 6g &#8211; 12 = 9g + 3 = 3(3g + 1)<\/p>\n<h3><a id=\"Problem_Solving_+_Applications_Page_No_404\"><\/a>Problem Solving + Applications &#8211; Page No. 404<\/h3>\n<p>Question 15.<br \/>\nSense or Nonsense Peter and Jade are using what they know about properties to write an expression equivalent to 2 \u00d7 (n + 6) + 3. Whose answer makes sense? Whose answer is nonsense? Explain your reasoning.<br \/>\nPeter&#8217;s Work:<br \/>\nExpression: 2 \u00d7 (n + 6) + 3<br \/>\nAssociative Property of Addition: 2 \u00d7 n + (6 + 3)<br \/>\nAdd within parentheses: 2 \u00d7 n + 9<br \/>\nMultiply: 2n + 9<\/p>\n<p>Jade&#8217;s Work:<br \/>\nExpression: 2 \u00d7 (n + 6) + 3<br \/>\nDistributive Property: (2 \u00d7 n) + (2 \u00d7 6) + 3<br \/>\nMultiply within parentheses: 2n + 12 + 3<br \/>\nAssociative Property of Addition: 2n + (12 + 3)<br \/>\nAdd within parentheses: 2n + 15<br \/>\nFor the answer that is nonsense, correct the statement.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: Jade&#8217;s Work makes sense. Peter&#8217;s Work makes non-sense because<br \/>\nHe must have multiplied n + 6 with 2 but he added 6 with 3.<br \/>\n2 \u00d7 (n + 6) + 3<br \/>\n2 \u00d7 n + 2 \u00d7 6 + 3 = 2n + 12 + 3<br \/>\n= 2n + 15<\/p>\n<p>Question 16.<br \/>\nWrite the algebraic expression in the box that shows an equivalent expression.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-11.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 7 Exponents img 11\" width=\"375\" height=\"61\" \/><br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\n6(z + 5) = 6 \u00d7 z + 6 \u00d7 5 = 6z + 30<br \/>\n6z + 5z = z(6 + 5) = 11z<br \/>\n2 + 6z + 3 = 6z + 5<\/p>\n<h3><a id=\"Generate_Equivalent_Expressions_Page_No_405\"><\/a>Generate Equivalent Expressions &#8211; Page No. 405<\/h3>\n<p><strong>Use properties of operations to write an equivalent expression by combining like terms.<\/strong><\/p>\n<p>Question 1.<br \/>\n7h \u2212 3h<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 4h<\/p>\n<p>Explanation:<br \/>\nCombine the like terms<br \/>\n7h and 3h are the common terms<br \/>\nNow subtract 3h from 7h<br \/>\n7h &#8211; 3h = 4h<\/p>\n<p>Question 2.<br \/>\n5x + 7 + 2x<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 7x + 7<\/p>\n<p>Explanation:<br \/>\nThe given expression is 5x + 7 + 2x<br \/>\nThe common terms are 5x and 2x<br \/>\nCombine the like terms 5x + 7 + 2x = 7x + 7<\/p>\n<p>Question 3.<br \/>\n16 + 13p \u2212 9p<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 16 + 4p<\/p>\n<p>Explanation:<\/p>\n<p>Combine the like terms for the above expressions.<br \/>\nThe like terms are 13p and 9p<br \/>\n16 + 13p \u2212 9p = 16 + 4p<\/p>\n<p>Question 4.<br \/>\ny<sup>2<\/sup> + 13y \u2212 8y<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: y<sup>2<\/sup> + 5y<\/p>\n<p>Explanation:<br \/>\nThe given expression is y<sup>2<\/sup> + 13y \u2212 8y<br \/>\nThe like terms are 13y and 8y<br \/>\ny<sup>2<\/sup> + 13y \u2212 8y = y<sup>2<\/sup> + 5y<\/p>\n<p>Question 5.<br \/>\n5(2h + 3) + 3h<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 13h + 15<\/p>\n<p>Explanation:<br \/>\n5(2h + 3) + 3h = 10h + 15 + 3h<br \/>\nThe like terms are 10h and 3h<br \/>\n10h + 15 + 3h = 13h + 15<\/p>\n<p>Question 6.<br \/>\n12 + 18n + 7 \u2212 14n<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 19 + 4n<\/p>\n<p>Explanation:<br \/>\nThe expression is 12 + 18n + 7 \u2212 14n<br \/>\nThe like terms are 18n and 14n<br \/>\n12 + 18n + 7 \u2212 14n = 19 + 4n<\/p>\n<p><strong>Use the Distributive Property to write an equivalent expression.<\/strong><\/p>\n<p>Question 7.<br \/>\n2(9 + 5k)<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 18 + 10k<\/p>\n<p>Explanation:<br \/>\nUse the Distributive property<br \/>\nMultiply within the parentheses.<br \/>\n2(9 + 5k) = (2 \u00d7 9) + (2 \u00d7 5k)<br \/>\n(2 \u00d7 9) + (2 \u00d7 5k) = 18 + 10k<\/p>\n<p>Question 8.<br \/>\n4d + 8<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 4(d + 2)<\/p>\n<p>Explanation:<br \/>\nUse the Distributive property<br \/>\nMultiply within the parentheses.<br \/>\n4d + 8 = 4 \u00d7 d + 4 \u00d7 2<br \/>\nThe common term is 4.<br \/>\nTake 4 as a common factor.<br \/>\n4d + 8 = 4 (d + 2)<\/p>\n<p>Question 9.<br \/>\n21p + 35q<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 7(3p + 5q)<\/p>\n<p>Explanation:<br \/>\nUse the Distributive property<br \/>\nMultiply within the parentheses.<br \/>\n7 \u00d7 3p + 7 \u00d7 5q<br \/>\nThe common term is 7.<br \/>\n7(3p + 5q)<br \/>\n21p + 35q = 7(3p + 5q)<\/p>\n<p><strong>Problem Solving<\/strong><\/p>\n<p>Question 10.<br \/>\nThe expression 15n + 12n + 100 represents the total cost in dollars for skis, boots, and a lesson for n skiers. Simplify the expression 15n + 12n + 100. Then find the total cost for 8 skiers.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 27n + 100, $316<\/p>\n<p>Explanation:<br \/>\nThe terms that have n can be operated:<br \/>\n15n +12n + 100 = 27n +100. Then, we have that<br \/>\ntotal cost = 27n +100 for n skiers. So, for 8 skiers we have<br \/>\ntotal cost = 27(8) +100 = 216 + 100 = 316.<br \/>\nThen, the total cost of 8 skiers is $316.<\/p>\n<p>Question 11.<br \/>\nCasey has n nickels. Megan has 4 times as many nickels as Casey has. Write an expression for the total number of nickels Casey and Megan have. Then simplify the expression.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: n + 4n; 5n<\/p>\n<p>Explanation:<br \/>\nCasey has n nickels. Megan has 4 times as many nickels as Casey has.<br \/>\nSum of n and 4n<br \/>\nAdd the common terms n and 4n.<br \/>\nn + 4n = 5n<\/p>\n<p>Question 12.<br \/>\nExplain how you would use properties to write an expression equivalent to 7y + 4b \u2013 3y.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\n1st you combine like terms so subtract 7y and 3y and you get 4y.<br \/>\nSo this is the final answer: 4y+4b.<\/p>\n<h3><a id=\"Lesson_Check_Page_No_406\"><\/a>Lesson Check &#8211; Page No. 406<\/h3>\n<p>Question 1.<br \/>\nA ticket to a museum costs $8. A ticket to the dinosaur exhibit costs $5. The expression 8n + 5n represents the cost in dollars for n people to visit the museum and the exhibit. What is a simpler form of the expression 8n + 5n?<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 13n<\/p>\n<p>Explanation:<br \/>\nA ticket to a museum costs $8. A ticket to the dinosaur exhibit costs $5.<br \/>\nThe expression is the sum of 8n and 5n.<br \/>\nThus the simpler form of the expression is 8n + 5n = 13n<\/p>\n<p>Question 2.<br \/>\nWhat is an expression that is equivalent to 3(2p \u2013 3)?<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 6p &#8211; 9<\/p>\n<p>Explanation:<br \/>\nUse the distributive property to find the equivalent expression.<br \/>\n3(2p \u2013 3) = 3 \u00d7 2p &#8211; 3 \u00d7 3<br \/>\n= 6p &#8211; 9<br \/>\nThus the expression that is equivalent to 3(2p \u2013 3) is 6p &#8211; 9.<\/p>\n<p>Question 3.<br \/>\nA Mexican restaurant received 60 take-out orders. The manager found that 60% of the orders were for tacos and 25% of the orders were for burritos. How many orders were for other items?<br \/>\n______ orders<\/p>\n<p>Answer: 9 orders<\/p>\n<p>Explanation:<br \/>\nGiven,<br \/>\nA Mexican restaurant received 60 take-out orders.<br \/>\nThe manager found that 60% of the orders were for tacos and 25% of the orders were for burritos.<br \/>\nThe answer is 9 because 25% of 60 is 15 plus 60% of 60 is 36 so 36+15=51 and 60-51=9<br \/>\nThus 9 orders were for other items.<\/p>\n<p>Question 4.<br \/>\nThe area of a rectangular field is 1,710 square feet. The length of the field is 45 feet. What is the width of the field?<br \/>\n______ feet<\/p>\n<p>Answer: 38 feet<\/p>\n<p>Explanation:<br \/>\nThe area of a rectangular field is 1,710 square feet.<br \/>\nThe length of the field is 45 feet.<br \/>\nThe width of the field is x feet<br \/>\nA = l \u00d7 w<br \/>\n1710 square feet = 45 feet \u00d7 x<br \/>\nx = 1710\/45 = 38 feet<br \/>\nThus the width of the rectangular field is 38 feet.<\/p>\n<p>Question 5.<br \/>\nHow many terms are in 2 + 4x + 7y?<br \/>\n______ terms<\/p>\n<p>Answer: 3<\/p>\n<p>Explanation:<br \/>\nGiven expression 2 + 4x + 7y<br \/>\nThere are 3 terms in the expression 2, 4x, 7y.<\/p>\n<p>Question 6.<br \/>\nBoxes of cereal usually cost $4, but they are on sale for $1 off. A gallon of milk costs $3. The expression 4b \u2013 1b + 3 can be used to find the cost in dollars of buying b boxes of cereal and a gallon of milk. Write the expression in a simpler form.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 3b + 3<\/p>\n<p>Explanation:<br \/>\nBoxes of cereal usually cost $4, but they are on sale for $1 off. A gallon of milk costs $3.<br \/>\nThe expression is 4b \u2013 1b + 3<br \/>\nCombine the like terms for the above expression.<br \/>\n4b \u2013 1b + 3 = 3b + 3 = 3(b + 1)<\/p>\n<h3><a id=\"Share_and_Show_Page_No_409\"><\/a>Share and Show &#8211; Page No. 409<\/h3>\n<p><strong>Use properties of operations to determine whether the expressions are equivalent.<\/strong><\/p>\n<p>Question 1.<br \/>\n7k + 4 + 2k and 4 + 9k<br \/>\nThe expressions are _____________<\/p>\n<p>Answer: equivalent<\/p>\n<p>Explanation:<br \/>\n7k + 4 + 2k<br \/>\nCombine the like terms 7k and 2k<br \/>\nAdd the like terms 7k + 2k + 4 = 9k + 4<br \/>\n9k + 4 and 4 + 9k are equivalent.<\/p>\n<p>Question 2.<br \/>\n9a \u00d7 3 and 12a<br \/>\nThe expressions are _____________<\/p>\n<p>Answer: not equivalent<\/p>\n<p>Explanation:<br \/>\nMultiply 9a with 3.<br \/>\n9a \u00d7 3 = 27a<br \/>\n27a and 12a are not equivalent.<br \/>\nThus the expressions are not equivalent.<\/p>\n<p>Question 3.<br \/>\n8p + 0 and 8p \u00d7 0<br \/>\nThe expressions are ______<\/p>\n<p>Answer: not equivalent<\/p>\n<p>Explanation:<br \/>\n8p + 0 = 8p<br \/>\n8p \u00d7 0 = 0<br \/>\n8p and 0 are not equivalent.<br \/>\nThe expressions 8p + 0 and 8p \u00d7 0 are not equivalent.<\/p>\n<p>Question 4.<br \/>\n5(a + b) and (5a + 2b) + 3b<br \/>\nThe expressions are _____________<\/p>\n<p>Answer: equivalent<\/p>\n<p>Explanation:<br \/>\n5(a + b) = 5a + 5b<br \/>\n(5a + 2b) + 3b<br \/>\nThe like terms are 5a and 2b, 3b<br \/>\nAdd the combine terms 5a + 2b + 3b = 5a + 5b<br \/>\nThus the expressions 5(a + b) and (5a + 2b) + 3b are equivalent.<\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>Use properties of operations to determine whether the expressions are equivalent.<\/strong><\/p>\n<p>Question 5.<br \/>\n3(v + 2) + 7v and 16v<br \/>\nThe expressions are _____________<\/p>\n<p>Answer: not equivalent<\/p>\n<p>Explanation:<br \/>\n3(v + 2) + 7v<br \/>\nCombine the like terms 3v and 7v<br \/>\n3(v + 2) + 7v = 3v + 6 + 7v = 10v + 6<br \/>\nThe expressions 10v + 6 and 16v are not equivalent.<\/p>\n<p>Question 6.<br \/>\n14h + (17 + 11h) and 25h + 17<br \/>\nThe expressions are _____________<\/p>\n<p>Answer: equivalent<\/p>\n<p>Explanation:<br \/>\n14h + (17 + 11h)<br \/>\nCombine the like terms 14h and 11h.<br \/>\n14h + 17 + 11h = 25h + 17<br \/>\nThe expressions 14h + (17 + 11h) and 25h + 17 are equivalent.<\/p>\n<p>Question 7.<br \/>\n4b \u00d7 7 and 28b<br \/>\nThe expressions are _____________<\/p>\n<p>Answer: equivalent<\/p>\n<p>Explanation:<br \/>\nMultiply 4b with 7.<br \/>\n4b \u00d7 7 = 28b<br \/>\nThe expressions 4b \u00d7 7 and 28b are equivalent.<\/p>\n<p>Question 8.<br \/>\nEach case of dog food contains c cans. Each case of cat food contains 12 cans. Four students wrote the expressions below for the number of cans in 6 cases of dog food and 1 case of cat food. Which of the expressions are correct?<br \/>\n6c + 12\u00a0 \u00a0 \u00a06c \u00d7 12\u00a0 \u00a0 \u00a0 6(c + 2)\u00a0 \u00a0 \u00a0 (2c + 4) \u00d7 3<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: The correct expressions are 6c + 12, 6(c + 2), (2c + 4) \u00d7 3<br \/>\n6(c + 2) is the distributive form of the expression.<\/p>\n<h3><a id=\"Problem_Solving_+_Applications_Page_No_410\"><\/a>Problem Solving + Applications &#8211; Page No. 410<\/h3>\n<p><strong>Use the table for 9\u201311.<\/strong><br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-12.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 7 Exponents img 12\" width=\"375\" height=\"241\" \/><\/p>\n<p>Question 9.<br \/>\nMarcus bought 4 packets of baseball cards and 4 packets of animal cards. Write an algebraic expression for the total number of cards Marcus bought.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 4a + 4b<\/p>\n<p>Explanation:<br \/>\nMarcus bought 4 packets of baseball cards and 4 packets of animal cards.<br \/>\nb represents the number per packet<br \/>\nMultiply 4 with b<br \/>\n4 \u00d7 b = 4b<br \/>\na represents the number per packet of animal cards.<br \/>\nMultiply 4 with a.<br \/>\n4 \u00d7 a = 4a<br \/>\nTherefore the algebraic expression for the total number of cards Marcus bought is the sum of 4a and 4b.<br \/>\nThe expression is 4a + 4b<\/p>\n<p>Question 10.<br \/>\nMake Arguments Is the expression for the number of cards Marcus bought equivalent to 4(a + b)? Justify your answer.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: Yes<br \/>\nUse the distributive property to simplify the expression 4a + 4b.<br \/>\nTake 4 as the common factor for the expression 4a + 4b.<br \/>\n4a + 4b = 4(a + b)<\/p>\n<p>Question 11.<br \/>\nAngelica buys 3 packets of movie cards and 6 packets of cartoon cards and adds these to the 3 packets of movie cards she already has. Write three equivalent algebraic expressions for the number of cards Angelica has now<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 3m + 6c + 3m<\/p>\n<p>Explanation:<br \/>\nAngelica buys 3 packets of movie cards and 6 packets of cartoon cards and adds these to the 3 packets of movie cards she already has.<br \/>\nThe expression for 3 packets of movie cards is 3m<br \/>\nThe expression for 6 packets of cartoon cards is 6c.<br \/>\nNow we have to add 3m to the expression.<br \/>\n3m + 6c + 3m<br \/>\nThus the three equivalent algebraic expressions for the number of cards Angelica has now is 3m + 6c + 3m<\/p>\n<p>Question 12.<br \/>\nSelect the expressions that are equivalent to 3(x + 2). Mark all that apply.<br \/>\nOptions:<br \/>\na. 3x + 6<br \/>\nb. 3x + 2<br \/>\nc. 5x<br \/>\nd. x + 5<\/p>\n<p>Answer: 3x + 6<\/p>\n<p>Explanation:<br \/>\nUse distributive property to solve the expression 3(x + 2).<br \/>\n3(x + 2) = 3 \u00d7 x + 3 \u00d7 2 = 3x + 6<br \/>\nThus the correct answer is option A.<\/p>\n<h3><a id=\"Identify_Equivalent_Expressions_Page_No_411\"><\/a>Identify Equivalent Expressions &#8211; Page No. 411<\/h3>\n<p><strong>Use properties of operations to determine whether the expressions are equivalent.<\/strong><\/p>\n<p>Question 1.<br \/>\n2s + 13 + 15s and 17s + 13<br \/>\nThe expressions are _____________<\/p>\n<p>Answer: equivalent<\/p>\n<p>Explanation:<br \/>\n2s + 13 + 15s<br \/>\nCombine the like terms<br \/>\n2s + 13 + 15s = 17s + 13<br \/>\n17s + 13 = 17s + 13<br \/>\nThus the expressions 2s + 13 + 15s and 17s + 13 are equivalent.<\/p>\n<p>Question 2.<br \/>\n5 \u00d7 7h and 35h<br \/>\nThe expressions are _____________<\/p>\n<p>Answer: equivalent<\/p>\n<p>Explanation:<br \/>\n5 \u00d7 7h = 35h<br \/>\n35h = 35h<br \/>\nThe expressions 5 \u00d7 7h and 35h are equivalent.<\/p>\n<p>Question 3.<br \/>\n10 + 8v \u2212 3v and 18 \u2212 3v<br \/>\nThe expressions are _____________<\/p>\n<p>Answer: not equivalent<\/p>\n<p>Explanation:<br \/>\nCombine the like terms 8v and 3v<br \/>\n10 + 8v \u2212 3v = 10 + 5v<br \/>\n10 + 5v \u2260 18 \u2212 3v<br \/>\nThus the expressions 10 + 8v \u2212 3v and 18 \u2212 3v are not equivalent.<\/p>\n<p>Question 4.<br \/>\n(9w \u00d7 0)\u221212 and 9w &#8211; 12<br \/>\nThe expressions are _____________<\/p>\n<p>Answer: not equivalent<\/p>\n<p>Explanation:<br \/>\n(9w \u00d7 0)\u221212 = 0 &#8211; 12 = &#8211; 12<br \/>\n&#8211; 12 \u2260 9w &#8211; 12<br \/>\nSo, the expressions (9w \u00d7 0)\u221212 and 9w &#8211; 12 are not equivalent.<\/p>\n<p>Question 5.<br \/>\n11(p + q) and 11p + (7q + 4q)<br \/>\nThe expressions are _____________<\/p>\n<p>Answer: equivalent<\/p>\n<p>Explanation:<br \/>\n11(p + q) = 11p + 11q<br \/>\nCombine the terms 7q and 4q<br \/>\n11p + (7q + 4q) = 11p + 11q = 11(p + q)<br \/>\nSo, the expressions 11(p + q) and 11p + (7q + 4q) are equivalent.<\/p>\n<p>Question 6.<br \/>\n6(4b + 3d) and 24b + 3d<br \/>\nThe expressions are _____________<\/p>\n<p>Answer: not equivalent<\/p>\n<p>Explanation:<br \/>\n6(4b + 3d) = 24b + 18d<br \/>\n24b + 18d \u2260 24b + 3d<br \/>\nSo, the expressions 6(4b + 3d) and 24b + 3d are not equivalent.<\/p>\n<p>Question 7.<br \/>\n14m + 9 \u2212 6m and 8m + 9<br \/>\nThe expressions are _____________<\/p>\n<p>Answer: equivalent<\/p>\n<p>Explanation:<br \/>\nCombine the like terms 14m and 6m<br \/>\n14m + 9 \u2212 6m = 8m + 9<br \/>\n8m + 9 = 8m + 9<br \/>\nThus the expressions are equivalent.<\/p>\n<p>Question 8.<br \/>\n(y \u00d7 1) + 2 and y + 2<br \/>\nThe expressions are _____________<\/p>\n<p>Answer: equivalent<\/p>\n<p>Explanation:<br \/>\n(y \u00d7 1) + 2 = y + 2<br \/>\ny + 2 = y + 2<br \/>\nThus the expressions (y \u00d7 1) + 2 and y + 2 are equivalent.<\/p>\n<p>Question 9.<br \/>\n4 + 5(6t + 1) and 9 + 30t<br \/>\nThe expressions are _____________<\/p>\n<p>Answer: equivalent<\/p>\n<p>Explanation:<br \/>\n4 + 5(6t + 1) = 4 + 30t + 5 = 9 + 30t<br \/>\n9 + 30t = 9 + 30t<br \/>\nThus the expressions 4 + 5(6t + 1) and 9 + 30t are equivalent.<\/p>\n<p>Question 10.<br \/>\n9x + 0 + 10x and 19x + 1<br \/>\nThe expressions are _____________<\/p>\n<p>Answer: not equivalent<\/p>\n<p>Explanation:<br \/>\n9x + 0 + 10x<br \/>\nCombine the like terms 9x and 10x.<br \/>\n9x + 10x = 19x<br \/>\n19x \u2260 19x + 1<br \/>\nThus the expressions 9x + 0 + 10x and 19x + 1 are not equivalent.<\/p>\n<p>Question 11.<br \/>\n12c \u2212 3c and 3(4c \u2212 1)<br \/>\nThe expressions are _____________<\/p>\n<p>Answer: not equivalent<\/p>\n<p>Explanation:<br \/>\n12c \u2212 3c<br \/>\nTake 3 as a common factor.<br \/>\n3c(4 &#8211; 1) or 3 (4c &#8211; 1c)<br \/>\n3 (4c &#8211; 1c) \u2260 3(4c \u2212 1)<br \/>\nThus the expressions 12c \u2212 3c and 3(4c \u2212 1) are not equivalent.<\/p>\n<p>Question 12.<br \/>\n6a \u00d7 4 and 24a<br \/>\nThe expressions are _____________<\/p>\n<p>Answer: equivalent<\/p>\n<p>Explanation:<br \/>\n6a \u00d7 4 = 24a<br \/>\n24a = 24a<br \/>\nThe expressions 6a \u00d7 4 and 24a are equivalent.<\/p>\n<p><strong>Problem Solving<\/strong><\/p>\n<p>Question 13.<br \/>\nRachel needs to write 3 book reports with b pages and 3 science reports with s pages during the school year. Write an algebraic expression for the total number of pages Rachel will need to write.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 3b + 3s<\/p>\n<p>Explanation:<br \/>\nRachel needs to write 3 book reports with b pages and 3 science reports with s pages during the school year.<br \/>\nMultiply 3 book reports with b pages = 3b.<br \/>\nMultiply 3 science books with s pages = 3s.<br \/>\nThe algebraic expression for the total number of pages Rachel will need to write is 3b + 3s.<\/p>\n<p>Question 14.<br \/>\nRachel\u2019s friend Yassi has to write 3(b + s) pages for reports. Use properties of operations to determine whether this expression is equivalent to the expression for the number of pages Rachel has to write.<br \/>\nThis expression is _____________<\/p>\n<p>Answer: equivalent<\/p>\n<p>Explanation:<br \/>\nRachel\u2019s friend Yassi has to write 3(b + s) pages for reports.<br \/>\nThe equivalent expression of 3(b + s) = 3b + 3s<\/p>\n<p>Question 15.<br \/>\nUse properties of operations to show whether 7y + 7b + 3y and 7(y + b) + 3b are equivalent expressions. Explain your reasoning.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nUse Distributive property to simplify the expressions.<br \/>\nThe equivalent expression of 7y + 7b + 3y = 7(y + b) + 3y<br \/>\nThus 7y + 7b + 3y and 7(y + b) + 3b are equivalent.<\/p>\n<h3><a id=\"Lesson_Check_Page_No_412\"><\/a>Lesson Check &#8211; Page No. 412<\/h3>\n<p>Question 1.<br \/>\nIan had 4 cases of comic books and 6 adventure books. Each case holds c comic books. He gave 1 case of comic books to his friend. Write an expression that gives the total number of books Ian has left.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 3c + 6<\/p>\n<p>Explanation:<br \/>\nIan had 4 cases of comic books and 6 adventure books. Each case holds c comic books. He gave 1 case of comic books to his friend.<br \/>\n4c + 6 &#8211; 1c<br \/>\nCombine the like terms<br \/>\n3c + 6<\/p>\n<p>Question 2.<br \/>\nIn May, Xia made 5 flower planters with f flowers in each planter. In June, she made 8 flower planters with f flowers in each planter. Write an expression in the simplest form that gives the number of flowers Xia has in the planters.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 13f<\/p>\n<p>Explanation:<br \/>\nIn May, Xia made 5 flower planters with f flowers in each planter.<br \/>\nThe expression is 5f<br \/>\nIn June, she made 8 flower planters with f flowers in each planter.<br \/>\nThe expression is 8f.<br \/>\nSum of 5f and 8f is 8f + 5f = 13f<\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p>Question 3.<br \/>\nKeisha wants to read for 90 minutes. So far, she has read 30% of her goal. How much longer does she need to read to reach her goal?<br \/>\n________ minutes<\/p>\n<p>Answer: 63 min<\/p>\n<p>Explanation:<br \/>\nKeisha wants to read for 90 minutes.<br \/>\nSo far, she has read 30% of her goal.<br \/>\n30% = 30\/100 = 0.3<br \/>\nMultiply 90 with 0.3<br \/>\n90 \u00d7 0.3 = 27<br \/>\nSubtract 27 from 90<br \/>\n90 &#8211; 27 = 63<br \/>\nShe needs to read 63 minutes to reach her goal.<\/p>\n<p>Question 4.<br \/>\nMarvyn travels 105 miles on his scooter. He travels for 3 hours. What is his average speed?<br \/>\n________ miles per hour<\/p>\n<p>Answer: 35 miles per hour<\/p>\n<p>Explanation:<br \/>\nDivide the number of miles by hours traveled.<br \/>\nAverage speed = 105 miles\/3 hours = 35 miles per hour<br \/>\nThus the average speed is 35 miles per hour.<\/p>\n<p>Question 5.<br \/>\nThe expression 5(F \u2212 32) \u00f7 9 gives the Celsius temperature for a Fahrenheit temperature of F degrees. The noon Fahrenheit temperature in Centerville was 86 degrees. What was the temperature in degrees Celsius?<br \/>\n________ degrees Celsius<\/p>\n<p>Answer: 30 degrees Celsius<\/p>\n<p>Explanation:<br \/>\nThe expression is 5(F \u2212 32) \u00f7 9<br \/>\nF = 86 degrees<br \/>\nSubstitute F in the above expression.<br \/>\n5(86 \u2212 32) \u00f7 9 = 5(54) \u00f7 9<br \/>\n270 \u00f7 9 = 30<br \/>\nThe temperature is 30 degrees Celsius<\/p>\n<p>Question 6.<br \/>\nAt the library book sale, hardcover books sell for $4 and paperbacks sell for $2. The expression 4b + 2b represents the total cost for b hardcover books and b paperbacks. Write a simpler expression that is equivalent to 4b + 2b.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 6b<\/p>\n<p>Explanation:<br \/>\nGiven expression is 4b + 2b<br \/>\nThe terms are 4b and 2b<br \/>\nNow combine the like terms<br \/>\nThat means 4b + 2b = 6b<\/p>\n<h3><a id=\"Chapter_7_Review_Test_Page_No_413\"><\/a>Chapter 7 Review\/Test &#8211; Page No. 413<\/h3>\n<p>Question 1.<br \/>\nUse exponents to rewrite the expression.<br \/>\n3 \u00d7 3 \u00d7 3 \u00d7 3 \u00d7 5 \u00d7 5<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 3<sup>4<\/sup> \u00d7 5<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\n3 is a repeated factor.<br \/>\nThe number 3 is repeated four times.<br \/>\n5 is a repeated factor.<br \/>\nThe number 5 is repeated two times.<br \/>\nThe exponential form of 3 \u00d7 3 \u00d7 3 \u00d7 3 \u00d7 5 \u00d7 5 is 3<sup>4<\/sup> \u00d7 5<sup>2<\/sup><\/p>\n<p>Question 2.<br \/>\nA plumber charges $10 for transportation and $55 per hour for repairs. Write an expression that can be used to find the cost in dollars for a repair that takes h hours.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 10 + 55h<\/p>\n<p>Explanation:<br \/>\nA plumber charges $10 for transportation and $55 per hour for repairs.<br \/>\nMultiply 55 with an hour<br \/>\nSum of 10 and product of 55 and h.<br \/>\nThe expression is 10 + 55h.<\/p>\n<p>Question 3.<br \/>\nEllen is 2 years older than her brother Luke. Let k represent Luke\u2019s age. Identify the expression that can be used to find Ellen\u2019s age.<br \/>\nOptions:<br \/>\na. k\u22122<br \/>\nb. k+2<br \/>\nc. 2k<br \/>\nd. \\(\\frac{k}{2}\\)<\/p>\n<p>Answer: k+2<\/p>\n<p>Explanation:<br \/>\nGiven, Ellen is 2 years older than her brother Luke. Let k represent Luke\u2019s age.<br \/>\nOlder is nothing but more so we have to add 2 years to k.<br \/>\nThat means k + 2.<br \/>\nThus the correct answer is option B.<\/p>\n<p>Question 4.<br \/>\nWrite 4<sup>3<\/sup> using repeated multiplication. Then find the value of 4<sup>3<\/sup>.<br \/>\n________<\/p>\n<p>Answer:<br \/>\n4<sup>3<\/sup> = 4 \u00d7 4 \u00d7 4 = 64<br \/>\nThe value of 4<sup>3<\/sup> is 64.<\/p>\n<p>Question 5.<br \/>\nJasmine is buying beans. She bought r pounds of red beans that cost $3 per pound and b pounds of black beans that cost $2 per pound. The total amount of her purchase is given by the expression 3r + 2b. Select the terms of the expression. Mark all that apply<br \/>\nOptions:<br \/>\na. 2<br \/>\nb. 2b<br \/>\nc. 3<br \/>\nd. 3r<\/p>\n<p>Answer: B, D<\/p>\n<p>Explanation:<br \/>\nThe expression is 3r + 2b<br \/>\nThe terms of the expressions are 3r and 2b.<br \/>\nThus the correct answers are B and D.<\/p>\n<h3><a id=\"Chapter_7_Review_Test_Page_No_414\"><\/a>Chapter 7 Review\/Test &#8211; Page No. 414<\/h3>\n<p>Question 6.<br \/>\nChoose the number that makes the sentence true. The formula V= s<sup>3<\/sup> gives the volume V of a cube with side length s.<br \/>\nThe volume of a cube that has a side length of 8 inches<br \/>\ninches is _____________ cubed<\/p>\n<p>Answer: 512<\/p>\n<p>Explanation:<br \/>\nUse the formula V= s<sup>3<\/sup><br \/>\ns = 8<br \/>\nV = 8<sup>3<\/sup> = 8 \u00d7 8 \u00d7 8 = 512<\/p>\n<p>Question 7.<br \/>\nLiang is ordering new chairs and cushions for his dining room table. A new chair costs $88 and a new cushion costs $12. Shipping costs $34. The expression 88c + 12c + 34 gives the total cost for buying c sets of chairs and cushions. Simplify the expression by combining like terms.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 100c + 34<\/p>\n<p>Explanation:<br \/>\nLiang is ordering new chairs and cushions for his dining room table.<br \/>\nA new chair costs $88 and a new cushion costs $12. Shipping costs $34.<br \/>\nThe expression is 88c + 12c + 34.<br \/>\nCombine the like terms<br \/>\n88c + 12c + 34 = 100c + 34<\/p>\n<p>Question 8.<br \/>\nMr. Ruiz writes the expression 5 \u00d7 (2 + 1)<sup>2<\/sup> \u00f7 3 on the board. Chelsea says the first step is to evaluate 1<sup>2<\/sup>. Explain Chelsea\u2019s mistake. Then, evaluate the expression<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nShe should have done what was in the parentheses (2 + 1) and then the exponent 3<sup>2<\/sup>= 9<br \/>\n5 \u00d7 (2 + 1)<sup>2<\/sup> \u00f7 3 = 5 \u00d7 9 \u00f7 3<br \/>\n5 \u00d7 3 = 15<\/p>\n<p>Question 9.<br \/>\nJake writes this word expression.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-13.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 7 Exponents img 13\" width=\"268\" height=\"62\" \/><br \/>\nWrite an algebraic expression for the word expression. Then, evaluate the expression for m = 4. Show your work.<br \/>\n________<\/p>\n<p>Answer:<br \/>\nThe expression is 7m<br \/>\nReplace m = 4 with m<br \/>\n7m = 7 \u00d7 4 = 28<\/p>\n<h3><a id=\"Chapter_7_Review_Test_Page_No_415\"><\/a>Chapter 7 Review\/Test &#8211; Page No. 415<\/h3>\n<p>Question 10.<br \/>\nSora has some bags that each contain 12 potatoes. She takes 3 potatoes from each bag. The expression 12p \u2013 3p represents the number of potatoes p left in the bags. Simplify the expression by combining like terms. Draw a line to match the expression with the simplified expression.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-14.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 7 Exponents img 14\" width=\"411\" height=\"273\" \/><br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 9p<br \/>\n<img loading=\"lazy\" class=\"alignnone size-medium wp-image-6939\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-14-1-300x199.jpg\" alt=\"Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-14\" width=\"300\" height=\"199\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-14-1-300x199.jpg 300w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-14-1.jpg 411w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>Question 11.<br \/>\nLogan works at a florist. He earns $600 per week plus $5 for each floral arrangement he delivers. Write an expression that gives the amount in dollars that Logan earns for delivering f floral arrangements. Use the expression to find the amount Logan will earn if he delivers 45 floral arrangements in one week. Show your work.<br \/>\n$ ________<\/p>\n<p>Answer: $825<\/p>\n<p>Explanation:<br \/>\nLogan works at a florist. He earns $600 per week plus $5 for each floral arrangement he delivers. Write an expression that gives the amount in dollars that Logan earns for delivering f floral arrangements.<br \/>\nThe expression is 600 + 5f<br \/>\nf = 45<br \/>\n600 + 5f = 600 + 5(45)<br \/>\n600 + 225 = 825<br \/>\nThus Logan earned $825 for delivering f floral arrangements.<\/p>\n<p>Question 12.<br \/>\nChoose the word that makes the sentence true.<br \/>\nDara wrote the expression 7 \u00d7 (d + 4) in her notebook. She used the _____ Property to write the equivalent expression 7d + 28.<br \/>\nAnswer: Dara wrote the expression 7 \u00d7 (d + 4) in her notebook. She used the <span style=\"text-decoration: underline;\">Distributive<\/span> Property to write the equivalent expression 7d + 28.<br \/>\nUse the distributive property to simplify the expression.<br \/>\n7 \u00d7 (d + 4) = 7d + 28<\/p>\n<h3><a id=\"Chapter_7_Review_Test_Page_No_416\"><\/a>Chapter 7 Review\/Test &#8211; Page No. 416<\/h3>\n<p>Question 13.<br \/>\nUse properties of operations to determine whether 5(n + 1) + 2n and 7n + 1 are equivalent expressions.<br \/>\nThe expressions are _____________<\/p>\n<p>Answer:<br \/>\n5n + 5 + 2n is Distributive property<br \/>\n5n + 2n + 5 is Commutative property of addition<br \/>\n7n + 5 combine like term<br \/>\n5n + 5 + 2n is equivalent to 7n + 5<br \/>\nSince it is not equivalent to 7n + 1, 7n + 5 is not equivalent to 7n.<\/p>\n<p>Question 14.<br \/>\nAlisha buys 5 boxes of peanut butter granola bars and 5 boxes of cinnamon granola bars. Let p represent the number of bars in a box of peanut butter granola bars and c represents the number of bars in a box of cinnamon granola bars. Jaira and Emma each write an expression that represents the total number of granola bars Alisha bought. Are the equivalent of the expression? Justify your answer<br \/>\nJaira<br \/>\n5p + 5c<br \/>\nEmma<br \/>\n5(p + c)<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\nThey are equivalent statements.<br \/>\n5p + 5c = 5(p + c) by the distributive property.<\/p>\n<p>Question 15.<br \/>\nAbe is 3 inches taller than Chen. Select the expressions that represent Abe\u2019s height if Chen\u2019s height is h inches. Mark all that apply<br \/>\nOptions:<br \/>\na. h\u22123<br \/>\nb. h+3<br \/>\nc. the sum of h and 3<br \/>\nd. the difference between h and 3<\/p>\n<p>Answer:<br \/>\nAbe is 3 inches taller than Chen.<br \/>\nLet Chen&#8217;s height is h.<br \/>\nThe expression is the sum of Chen&#8217;s height and 3.<br \/>\nSo, the suitable answers are h + 3 and the sum of h and 3.<br \/>\nThus the correct answers are option B and C.<\/p>\n<p>Question 16.<br \/>\nWrite the algebraic expression in the box that shows an equivalent expression.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-15.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 7 Exponents img 15\" width=\"394\" height=\"64\" \/><br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\n3(k + 2) = 3k + 6<br \/>\n3k + 2k = 5k<br \/>\n2 + 6k + 3 = 6k + 5<\/p>\n<h3><a id=\"Chapter_7_Review_Test_Page_No_417\"><\/a>Chapter 7 Review\/Test &#8211; Page No. 417<\/h3>\n<p>Question 17.<br \/>\nDraw a line to match the property with the expression that shows the property.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-16.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 7 Exponents img 16\" width=\"688\" height=\"128\" \/><br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-medium wp-image-6940\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-16-1-300x56.jpg\" alt=\"Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-16\" width=\"300\" height=\"56\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-16-1-300x56.jpg 300w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-16-1.jpg 688w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>Question 18.<br \/>\nA bike rental company charges $10 to rent a bike plus $2 for each hour the bike is rented. An expression for the total cost of renting a bike for h hours is 10 + 2h. Complete the table to find the total cost of renting a bike for h hours.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-17.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 7 Exponents img 17\" width=\"457\" height=\"153\" \/><br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-medium wp-image-6941\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-17-1-300x100.jpg\" alt=\"Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-17\" width=\"300\" height=\"100\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-17-1-300x100.jpg 300w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-7-Exponents-img-17-1.jpg 457w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>Question 19.<br \/>\nAn online sporting goods store charges $12 for a pair of athletic socks. Shipping is $2 per order<br \/>\nPart A<br \/>\nWrite an expression that Hana can use to find the total cost in dollars for ordering n pairs of socks.<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: 12n + 2<\/p>\n<p>Explanation:<br \/>\nLet n represents a pair of socks.<br \/>\nMultiply the price of pair of athletic socks with pair of socks = 12 \u00d7 n<br \/>\nShipping is $2 per order<br \/>\nThe expression for the total cost in dollars for ordering n pairs of socks is 12n + 2<\/p>\n<p>Question 19.<br \/>\nPart B<br \/>\nHana orders 3 pairs of athletic socks and her friend, Charlie, order 2 pairs of athletic socks. What is the total cost, including shipping, for both orders? Show your work.<br \/>\n$ ________<\/p>\n<p>Answer:<br \/>\nThe cost of Hannah&#8217;s order is 12 \u00d7 3 + 2 = 36 + 2 = 38<br \/>\nThe cost of Charlie&#8217;s order is 12 \u00d7 2 + 2 = 24 + 2 = 26<br \/>\nThe total cost for both is 38 + 26 = 64<\/p>\n<h3><a id=\"Chapter_7_Review_Test_Page_No_418\"><\/a>Chapter 7 Review\/Test &#8211; Page No. 418<\/h3>\n<p>Question 20.<br \/>\nFernando simplifies the expression (6 + 2)<sup>2<\/sup> \u2013 4 \u00d7 3.<br \/>\nPart A<br \/>\nFernando shows his work on the board. Use numbers and words to explain his mistake.<br \/>\n(6 + 2)<sup>2<\/sup> \u2013 4 \u00d7 3<br \/>\n(6 + 4) \u2013 4 \u00d7 3<br \/>\n10 \u2212 4 \u00d7 3<br \/>\n6 \u00d7 3<br \/>\n18<br \/>\nType below:<br \/>\n_____________<\/p>\n<p>Answer: Fernando did not use the correct order of operations. He should have added 6 and 2, then evaluate the exponent. He also subtracted before multiplying. He should have multiplied first.<\/p>\n<p>Question 20.<br \/>\nPart B<br \/>\nSimplify the expression (6 + 2)<sup>2<\/sup> \u2212 4 \u00d7 3 using the order of operations.<br \/>\n_______<\/p>\n<p>Answer: 52<\/p>\n<p>Explanation:<br \/>\n(6 + 2)<sup>2<\/sup> \u2212 4 \u00d7 3<br \/>\nFirst, add 6 and 2 and then subtract with 12.<br \/>\n8<sup>2<\/sup> &#8211; 4 \u00d7 3<br \/>\n= 64 &#8211; 12 = 52<br \/>\n(6 + 2)<sup>2<\/sup> \u2212 4 \u00d7 3 = 52<\/p>\n<p><em>Conclusion:<\/em><\/p>\n<p>In addition to the exercise and homework problems, we have given the solutions for the mid-chapter and review test. Hence the students of grade 6 can check whether the answers are right or wrong. Feel free to post your comments in the below comment box if you have any queries. Bookmark our ccssmathanswers.com to get the go math answer key for all grade 6 chapters.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>The solutions of Grade 6 Go Math Answer Key for Chapter 7 Exponents are available in simple PDFs here. With the help off the HMH Go Math Grade 6 Chapter 7 Exponents Answer Ley can be easily downloaded by the students by using the provided links. You can understand the concept of the standard form &#8230; <a title=\"Go Math Grade 6 Answer Key Chapter 7 Exponents\" class=\"read-more\" href=\"https:\/\/bigideasmathanswers.com\/go-math-grade-6-answer-key-chapter-7-exponents\/\" aria-label=\"More on Go Math Grade 6 Answer Key Chapter 7 Exponents\">Read more<\/a><\/p>\n","protected":false},"author":2,"featured_media":8824,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[2],"tags":[],"jetpack_featured_media_url":"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/10\/go-math-grade-6-chapter-7-exponents-answer-key.jpeg","_links":{"self":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts\/5136"}],"collection":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/comments?post=5136"}],"version-history":[{"count":1,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts\/5136\/revisions"}],"predecessor-version":[{"id":92746,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts\/5136\/revisions\/92746"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/media\/8824"}],"wp:attachment":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/media?parent=5136"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/categories?post=5136"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/tags?post=5136"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}