{"id":5460,"date":"2022-03-28T21:07:02","date_gmt":"2022-03-28T15:37:02","guid":{"rendered":"https:\/\/ccssmathanswers.com\/?p=5460"},"modified":"2022-04-07T12:23:00","modified_gmt":"2022-04-07T06:53:00","slug":"go-math-grade-6-answer-key-chapter-11-surface-area-and-volume","status":"publish","type":"post","link":"https:\/\/bigideasmathanswers.com\/go-math-grade-6-answer-key-chapter-11-surface-area-and-volume\/","title":{"rendered":"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume"},"content":{"rendered":"<p>Go Math solutions for Class 6 Maths Provide detailed explanations for all the questions provided in the HMH Go Math. We provide topic wise Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume to help the students clear their doubts by offering an understanding of concepts in depth. You can practice different types of questions in <a style=\"font-size: 16px; background-color: #ffffff;\" href=\"https:\/\/ccssmathanswers.com\/go-math-grade-6-answer-key\/\" target=\"_blank\" rel=\"noopener noreferrer\">Go Math Grade 6 Answer Key<\/a><span style=\"font-size: 16px;\"> Chapter 11 Surface Area and Volume.\u00a0<\/span><\/p>\n<h2>Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume<\/h2>\n<p>Download HMH Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume and learn offline. With the help of these Go Math 6th Grade Solution Key Chapter 11 Surface Area and Volume, you can score good marks in the exams. The topics include 3-D figures and Nets, Explore Surface Area Using Nets, Surface Area of Prisms, and so on. This will also help to build a strong foundation of all these concepts for secondary level classes.<\/p>\n<p><strong>Lesson 1: Three-Dimensional Figures and Nets<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_599\">Share and Show &#8211; Page No. 599<\/a><\/li>\n<li><a href=\"#Problem_Solving_Applications_Page_No_600\">Problem Solving + Applications &#8211; Page No. 600<\/a><\/li>\n<li><a href=\"#Three_Dimensional_Figures_and_Nets_Page_No_601\">Three-Dimensional Figures and Nets &#8211; Page No. 601<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_602\">Lesson Check &#8211; Page No. 602<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 2: Investigate \u2022 Explore Surface Area Using Nets<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_605\">Share and Show &#8211; Page No. 605<\/a><\/li>\n<li><a href=\"#Whats_the_Error_Page_No_606\">What\u2019s the Error? &#8211; Page No. 606<\/a><\/li>\n<li><a href=\"#Explore_Surface_Area_Using_Nets_Page_No_607\">Explore Surface Area Using Nets &#8211; Page No. 607<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_608\">Lesson Check &#8211; Page No. 608<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 3: Algebra \u2022 Surface Area of Prisms<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_611\">Share and Show &#8211; Page No. 611<\/a><\/li>\n<li><a href=\"#Unlock_the_Problem_Page_No_612\">Unlock the Problem &#8211; Page No. 612<\/a><\/li>\n<li><a href=\"#Surface_Area_of_Prisms_Page_No_613\">Surface Area of Prisms &#8211; Page No. 613<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_614\">Lesson Check &#8211; Page No. 614<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 4: Algebra \u2022 Surface Area of Pyramids<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_617\">Share and Show &#8211; Page No. 617<\/a><\/li>\n<li><a href=\"#Problem_Solving_Applications_Page_No_618\">Problem Solving + Applications &#8211; Page No. 618<\/a><\/li>\n<li><a href=\"#Surface_Area_of_Pyramids_Page_No_619\">Surface Area of Pyramids &#8211; Page No. 619<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_620\">Lesson Check &#8211; Page No. 620<\/a><\/li>\n<\/ul>\n<p><strong>\u00a0Mid-Chapter Checkpoint<\/strong><\/p>\n<ul>\n<li><a href=\"#Mid_Chapter_Checkpoint_Vocabulary_Page_No_621\">Mid-Chapter Checkpoint &#8211; Vocabulary &#8211; Page No. 621<\/a><\/li>\n<li><a href=\"#Page_No_622\">Page No. 622<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 5: Investigate \u2022 Fractions and Volume<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_625\">Share and Show &#8211; Page No. 625<\/a><\/li>\n<li><a href=\"#Problem_Solving_Applications_Page_No_626\">Problem Solving + Applications &#8211; Page No. 626<\/a><\/li>\n<li><a href=\"#Fractions_and_Volume_Page_No_627\">Fractions and Volume &#8211; Page No. 627<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_628\">Lesson Check &#8211; Page No. 628<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 6: Algebra \u2022 Volume of Rectangular Prisms<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_631\">Share and Show &#8211; Page No. 631<\/a><\/li>\n<li><a href=\"#Aquariums_Page_No_632\">Aquariums &#8211; Page No. 632<\/a><\/li>\n<li><a href=\"#Volume_of_Rectangular_Prisms_Page_No_633\">Volume of Rectangular Prisms &#8211; Page No. 633<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_634\">Lesson Check &#8211; Page No. 634<\/a><\/li>\n<\/ul>\n<p><strong>Lesson 7: Problem Solving \u2022 Geometric Measurements<\/strong><\/p>\n<ul>\n<li><a href=\"#Share_and_Show_Page_No_637\">Share and Show &#8211; Page No. 637<\/a><\/li>\n<li><a href=\"#On_Your_Own_Page_No_638\">On Your Own &#8211; Page No. 638<\/a><\/li>\n<li><a href=\"#Problem_Solving_Geometric_Measurements_Page_No_639\">Problem Solving Geometric Measurements &#8211; Page No. 639<\/a><\/li>\n<li><a href=\"#Lesson_Check_Page_No_640\">Lesson Check &#8211; Page No. 640<\/a><\/li>\n<\/ul>\n<p><strong>Chapter 11 Review\/Test<\/strong><\/p>\n<ul>\n<li><a href=\"#Chapter_11_Review_Test_Page_No_641\">Chapter 11 Review\/Test &#8211; Page No. 641<\/a><\/li>\n<li><a href=\"#Page_No_642\">Page No. 642<\/a><\/li>\n<li><a href=\"#Page_No_643\">Page No. 643<\/a><\/li>\n<li><a href=\"#Page_No_644\">Page No. 644<\/a><\/li>\n<li><a href=\"#Page_No_645\">Page No. 645<\/a><\/li>\n<li><a href=\"#Page_No_646\">Page No. 646<\/a><\/li>\n<\/ul>\n<h3><a id=\"Share_and_Show_Page_No_599\"><\/a>Share and Show &#8211; Page No. 599<\/h3>\n<p><strong>Identify and draw a net for the solid figure.<\/strong><\/p>\n<p>Question 1.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-1.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 1\" width=\"135\" height=\"121\" \/><\/p>\n<p>Answer: The base Square or Rectangle, and lateral faces are Triangle and the figure is a Square pyramid or Rectangular pyramid.<\/p>\n<p>Explanation:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-6962\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-72.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"157\" height=\"151\" \/><\/p>\n<p>Question 2.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-2.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 2\" width=\"115\" height=\"130\" \/><br \/>\nAnswer: Cube or Rectangular prism.<\/p>\n<p>Explanation: The base is a square or rectangle and lateral faces are squares are rectangle. The figure is a Cube or Rectangular prism.<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-7001\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-96.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"162\" height=\"214\" \/><\/p>\n<p><strong>Identify and sketch the solid figure that could be formed by the net.<\/strong><\/p>\n<p>Question 3.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-3.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 3\" width=\"196\" height=\"181\" \/><\/p>\n<p>Answer: Triangular pyramid.<\/p>\n<p>Explanation: The net has four triangles, so it is a triangular pyramid.<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-7002\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-99.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"169\" height=\"154\" \/><\/p>\n<p>Question 4.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-4.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 4\" width=\"180\" height=\"142\" \/><br \/>\nAnswer: Cube<\/p>\n<p>Explanation: The net has six squares.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-6998\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-94.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"122\" height=\"120\" \/><\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>Identify and draw a net for the solid figure.<\/strong><\/p>\n<p>Question 5.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-5.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 5\" width=\"150\" height=\"144\" \/><\/p>\n<p>Answer: Triangular prism.<\/p>\n<p>Explanation: The base is a rectangle and the lateral faces are triangle and rectangles, so it is a triangular prism.<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-6963\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-73.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"231\" height=\"117\" \/><\/p>\n<p>Question 6.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-6.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 6\" width=\"178\" height=\"144\" \/><\/p>\n<p>Answer:\u00a0 Rectangular Prism.<\/p>\n<p>Explanation: The base is a rectangle and the lateral faces are squares and rectangles. And it is a Rectangular prism.<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-6965\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-75.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"223\" height=\"104\" \/><\/p>\n<h3><a id=\"Problem_Solving_Applications_Page_No_600\"><\/a>Problem Solving + Applications &#8211; Page No. 600<\/h3>\n<p><strong>Solve.<\/strong><\/p>\n<p>Question 7.<br \/>\nThe lateral faces and bases of crystals of the mineral galena are congruent squares. Identify the shape of a galena crystal.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-7.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 7\" width=\"387\" height=\"186\" \/><br \/>\nAnswer: Cube<\/p>\n<p>Explanation: The shape of the galena is Cube.<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-6998\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-94.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"122\" height=\"120\" \/><\/p>\n<p>Question 8.<br \/>\nRhianon draws the net below and labels each square. Can Rhianon fold her net into a cube that has letters A through G on its faces? Explain.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-8.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 8\" width=\"223\" height=\"135\" \/><\/p>\n<p>Answer: No, she cannot fold her net into a cube. Rhianon&#8217;s net has seven squares but there are only six squares in a net of a cube.<\/p>\n<p>Question 9.<br \/>\nDescribe A diamond crystal is shown. Describe the figure in terms of the solid figures you have seen in this lesson.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-9.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 9\" width=\"158\" height=\"301\" \/><\/p>\n<p>Answer: We can see that Diamond crystal consists of two square pyramids with congruent bases and the pyramids are reversed and placed base to base.<\/p>\n<p>Question 10.<br \/>\nSasha makes a triangular prism from paper.<br \/>\nThe bases are _____.<br \/>\nThe lateral faces are _____.<\/p>\n<p>Answer:<br \/>\nThe bases are Triangle<br \/>\nThe lateral faces are Rectangle<\/p>\n<h3><a id=\"Three_Dimensional_Figures_and_Nets_Page_No_601\"><\/a>Three-Dimensional Figures and Nets &#8211; Page No. 601<\/h3>\n<p><strong>Identify and draw a net for the solid figure.<\/strong><\/p>\n<p>Question 1.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-10.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 10\" width=\"161\" height=\"182\" \/><\/p>\n<p>Answer: Rectangular Prism<\/p>\n<p>Explanation:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-6960\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-70.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"289\" height=\"197\" \/><\/p>\n<p>Question 2.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-11.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 11\" width=\"173\" height=\"156\" \/><\/p>\n<p>Answer: Cube, Rectangular prism<\/p>\n<p>Explanation:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-6961\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-71.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"89\" height=\"120\" \/><\/p>\n<p>Question 3.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-12.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 12\" width=\"198\" height=\"211\" \/><\/p>\n<p>Answer: Square Pyramid<\/p>\n<p>Explanation:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-6962\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-72.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"157\" height=\"151\" \/><\/p>\n<p>Question 4.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-13.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 13\" width=\"211\" height=\"190\" \/><\/p>\n<p>Answer: Triangular Prism<\/p>\n<p>Explanation:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-6963\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-73.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"231\" height=\"117\" \/><\/p>\n<p><strong>Problem Solving<\/strong><\/p>\n<p>Question 5.<br \/>\nHobie\u2019s Candies are sold in triangular-pyramidshaped boxes. How many triangles are needed to make one box?<\/p>\n<p>Answer: 4<\/p>\n<p>Explanation: As triangled pyramids have four faces.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-6964\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-74.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"126\" height=\"159\" \/><\/p>\n<p>Question 6.<br \/>\nNina used plastic rectangles to make 6 rectangular prisms. How many rectangles did she use?<\/p>\n<p>Answer: 36<\/p>\n<p>Explanation:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-6965\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-75.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"223\" height=\"104\" \/><\/p>\n<p>Question 7.<br \/>\nDescribe how you could draw more than one net to represent the same three-dimensional figure. Give examples.<\/p>\n<p>Answer:<\/p>\n<p>Explanation:<\/p>\n<h3><a id=\"Lesson_Check_Page_No_602\"><\/a>Lesson Check &#8211; Page No. 602<\/h3>\n<p>Question 1.<br \/>\nHow many vertices does a square pyramid have?<\/p>\n<p>Answer: 5<\/p>\n<p>Explanation:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-6962\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-72.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"157\" height=\"151\" \/><\/p>\n<p>Question 2.<br \/>\nEach box of Fred\u2019s Fudge is constructed from 2 triangles and 3 rectangles. What is the shape of each box?<\/p>\n<p>Answer: Triangular Prism<\/p>\n<p>Explanation:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-6963\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-73.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"231\" height=\"117\" \/><\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p>Question 3.<br \/>\nBryan jogged the same distance each day for 7 days. He ran a total of 22.4 miles. The equation 7d = 22.4 can be used to find the distance d in miles he jogged each day. How far did Bryan jog each day?<\/p>\n<p>Answer: 3.2 miles<\/p>\n<p>Explanation: As given equation 7d= 22.4,<br \/>\nd= 22.4\u00f77<br \/>\n= 3.2 miles.<\/p>\n<p>Question 4.<br \/>\nA hot-air balloon is at an altitude of 240 feet. The balloon descends 30 feet per minute. What equation gives the altitude y, in feet, of the hot-air balloon after x minutes?<\/p>\n<p>Answer: Y= 240- 30X.<\/p>\n<p>Explanation: Given altitude Y, and the ballon was descended 30 feet per minute. So the equation is Y= 240- 30X.<\/p>\n<p>Question 5.<br \/>\nA regular heptagon has sides measuring 26 mm and is divided into 7 congruent triangles. Each triangle has a height of 27 mm. What is the area of the heptagon?<\/p>\n<p>Answer: 351 mm<sup>2<\/sup><\/p>\n<p>Explanation: Area of heptagon= 1\/2 b\u00d7h<br \/>\n= 1\/2 (26)\u00d7(27)<br \/>\n= 13\u00d727<br \/>\n= 351 mm<sup>2<\/sup><\/p>\n<p>Question 6.<br \/>\nAlexis draws quadrilateral STUV with vertices S(1, 3), T(2, 2), U(2, \u20133), and V(1, \u20132). What name best classifies the quadrilateral?<\/p>\n<p>Answer: Parallelogram<\/p>\n<p>Explanation:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-medium wp-image-7094\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-138-300x207.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"300\" height=\"207\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-138-300x207.png 300w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-138.png 649w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<h3><a id=\"Share_and_Show_Page_No_605\"><\/a>Share and Show &#8211; Page No. 605<\/h3>\n<p><strong>Use the net to find the surface area of the prism.<\/strong><\/p>\n<p>Question 1.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-14.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 14\" width=\"489\" height=\"173\" \/><\/p>\n<p>Answer:<\/p>\n<p>Explanation: First we must find the area of each face<br \/>\nA= 4\u00d73= 12<br \/>\nB= 4\u00d73= 12<br \/>\nC= 5\u00d74= 20<br \/>\nD= 5\u00d74= 20<br \/>\nE= 5\u00d73= 15<br \/>\nF= 5\u00d73= 15<br \/>\nSo, the surface area is 12+12+20+20+15+15= 94 cm<sup>2<\/sup><\/p>\n<p><strong>Find the surface area of the rectangular prism.<\/strong><\/p>\n<p>Question 2.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-15.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 15\" width=\"317\" height=\"214\" \/><\/p>\n<p>Answer: 222 cm<sup>2<\/sup><\/p>\n<p>Explanation: Area of a rectangular prism is 2(wl+hl+hw) = 2(7\u00d79+ 3\u00d79+ 3\u00d77)<br \/>\n= 2(63+27+21)<br \/>\n= 2(111)<br \/>\n= 222 cm<sup>2<\/sup><\/p>\n<p>Question 3.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-16.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 16\" width=\"266\" height=\"240\" \/><\/p>\n<p>Answer:<\/p>\n<p>Explanation: Area of a rectangular prism is 2(wl+hl+hw) = 2(10\u00d710+ 10\u00d710+ 10\u00d710)<br \/>\n= 2(100+100+100)<br \/>\n= 2(300)<br \/>\n= 600 cm<sup>2<\/sup><\/p>\n<p>Question 4.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-17.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 17\" width=\"253\" height=\"156\" \/><\/p>\n<p>Answer: 350 cm<sup>2<\/sup><\/p>\n<p>Explanation: Area of a rectangular prism is 2(wl+hl+hw) = 2(15\u00d75+ 5\u00d75+ 15\u00d75)<br \/>\n= 2(75+25+75)<br \/>\n= 2(175)<br \/>\n= 350 cm<sup>2<\/sup><\/p>\n<p><strong>Problem Solving + Applications<\/strong><\/p>\n<p>Question 5.<br \/>\nA cereal box is shaped like a rectangular prism. The box is 20 cm long by 5 cm wide by 30 cm high. What is the surface area of the cereal box?<\/p>\n<p>Answer: 1700 cm<sup>2<\/sup><\/p>\n<p>Explanation: The length of the box is 20 cm, the wide is 5 cm and the height is 30 cm. So surface area of the cereal box is 2(wl+hl+hw)= 2(20\u00d75+30\u00d720+30\u00d75)<br \/>\n= 2(100+600+150)<br \/>\n= 2(850)<br \/>\n= 1700 cm<sup>2<\/sup><\/p>\n<p>Question 6.<br \/>\nDarren is painting a wooden block as part of his art project. The block is a rectangular prism that is 12 cm long by 9 cm wide by 5 cm high. Describe the rectangles that make up the net for the prism.<\/p>\n<p>Answer:<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-6970\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-78.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"210\" height=\"112\" \/><\/p>\n<p>Question 7.<br \/>\nIn Exercise 6, what is the surface area, in square meters, that Darren has to paint?<\/p>\n<p>Answer: 416 cm<sup>2<\/sup><\/p>\n<p>Explanation: Surface area = 2(wl+hl+hw)<br \/>\n= 2(9\u00d712+5\u00d712+ 5\u00d79)<br \/>\n= 2(108+60+45)<br \/>\n= 2(213)<br \/>\n= 416 cm<sup>2<\/sup><\/p>\n<h3><a id=\"Whats_the_Error_Page_No_606\"><\/a>What\u2019s the Error? &#8211; Page No. 606<\/h3>\n<p>Question 8.<br \/>\nEmilio is designing the packaging for a new MP3 player. The box for the MP3 player is 5 cm by 3 cm by 2 cm. Emilio needs to find the surface area of the box.<br \/>\nLook at how Emilio solved the problem. Find his error.<br \/>\nSTEP 1: Draw a net.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-18.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 18\" width=\"350\" height=\"231\" \/><br \/>\nSTEP 2: Find the areas of all the faces and add them.<br \/>\nFace A: 3 \u00d7 2 = 6 cm<sup>2<\/sup>.<br \/>\nFace B: 3 \u00d7 5 = 15 cm<sup>2<\/sup>.<br \/>\nFace C: 3 \u00d7 2 = 6 cm<sup>2<\/sup>.<br \/>\nFace D: 3 \u00d7 5 = 15 cm<sup>2<\/sup>.<br \/>\nFace E: 3 \u00d7 5 = 15 cm<sup>2<\/sup>.<br \/>\nFace F: 3 \u00d7 5 = 15 cm<sup>2<\/sup>.<br \/>\nThe surface area is 6 + 15 + 6 + 15 + 15 + 15 = 72 cm<sup>2<\/sup>.<br \/>\nCorrect the error. Find the surface area of the prism.<\/p>\n<p>Answer: Emilio drew the net incorrectly Face D and F should have been 2 cm by 5 cm, not 3 cm by 5 cm<\/p>\n<p>Explanation:<br \/>\nFace A: 3\u00d72= 6 cm<sup>2<\/sup><br \/>\nFace B: 3\u00d75= 15 cm<sup>2<\/sup><br \/>\nFace C: 3\u00d72= 6 cm<sup>2<\/sup><br \/>\nFace D: 2\u00d75= 10 cm<sup>2<\/sup><br \/>\nFace E: 3\u00d75= 15 cm<sup>2<\/sup><br \/>\nFace F: 2\u00d75= 10 cm<sup>2<\/sup><br \/>\nSo, the surface area of the prism area is 6+15+6+10+15+10= 62 cm<sup>2.<\/sup><\/p>\n<p>Question 9.<br \/>\nFor numbers 9a\u20139d, select True or False for each statement.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-19.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 19\" width=\"430\" height=\"230\" \/><br \/>\n9a. The area of face A is 10 cm<sup>2<\/sup>.<br \/>\n9b. The area of face B is 10 cm<sup>2<\/sup>.<br \/>\n9c. The area of face C is 40 cm<sup>2<\/sup>.<br \/>\n9d. The surface area of the prism is 66 cm<sup>2<\/sup>.<\/p>\n<p>9a. The area of face A is 10 cm<sup>2<\/sup>.<\/p>\n<p>Answer: True<\/p>\n<p>Explanation: The area of face A is 2\u00d75= 10 cm<sup>2<\/sup>.<\/p>\n<p>9b. The area of face B is 10 cm<sup>2<\/sup>.<\/p>\n<p>Answer: False<\/p>\n<p>Explanation: The area of face B is 2\u00d78= 16\u00a0 cm<sup>2<\/sup>.<\/p>\n<p>9c. The area of face C is 40 cm<sup>2<\/sup>.<\/p>\n<p>Answer: The area of face C is 8\u00d75= 40 cm<sup>2<\/sup>.<\/p>\n<p>9d. The surface area of the prism is 66 cm<sup>2<\/sup>.<\/p>\n<p>Answer: 160 cm<sup>2<\/sup>.<\/p>\n<p>Explanation: The surface area of the prism is<br \/>\n= 2\u00d710+2\u00d710+2\u00d740<br \/>\n= 20+20+80<br \/>\n= 160 cm<sup>2<\/sup>.<\/p>\n<h3><a id=\"Explore_Surface_Area_Using_Nets_Page_No_607\"><\/a>Explore Surface Area Using Nets &#8211; Page No. 607<\/h3>\n<p><strong>Use the net to find the surface area of the rectangular prism.<\/strong><\/p>\n<p>Question 1.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-20.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 20\" width=\"269\" height=\"273\" \/><br \/>\n_______ square units<\/p>\n<p>Answer: 52 square units.<\/p>\n<p>Explanation:<br \/>\nThe area of face A is 6 squares.<br \/>\nThe area of face B is 8 squares.<br \/>\nThe area of face C is 6 squares.<br \/>\nThe area of face D is 12 squares.<br \/>\nThe area of face E is 8 squares.<br \/>\nThe area of face F is 12 squares.<br \/>\nThe surface area is 6+8+6+12+8+12= 52 square units.<\/p>\n<p>Question 2.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-21.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 21\" width=\"331\" height=\"323\" \/><br \/>\n_______ square units<\/p>\n<p>Answer: 112 square units.<\/p>\n<p>Explanation:<br \/>\nThe area of face A is 16 squares.<br \/>\nThe area of face B is 8 squares.<br \/>\nThe area of face C is 32 squares.<br \/>\nThe area of face D is 16 squares.<br \/>\nThe area of face E is 32 squares.<br \/>\nThe area of face F is 8 squares.<br \/>\nThe surface area is 112 square units.<\/p>\n<p>Question 3.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-22.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 22\" width=\"298\" height=\"153\" \/><\/p>\n<p>Answer: 102 mm<sup>2<\/sup><\/p>\n<p>Explanation: Area= 2(wl+hl+hw)<br \/>\n= 2(3\u00d77+3\u00d77+3\u00d73)<br \/>\n= 2(21+21+9)<br \/>\n= 2(51)<br \/>\n= 102 mm<sup>2<\/sup><\/p>\n<p>Question 4.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-23-1.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 23\" width=\"221\" height=\"179\" \/><br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 58 in.<sup>2<\/sup><\/p>\n<p>Explanation: Area= 2(wl+hl+hw)<br \/>\n= 2(5\u00d71+ 4\u00d71+ 4\u00d75)<br \/>\n= 2(5+4+20)<br \/>\n= 2(29)<br \/>\n= 58 in.<sup>2<\/sup><\/p>\n<p>Question 5.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-24.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 24\" width=\"272\" height=\"161\" \/><br \/>\n_______ ft<sup>2<\/sup><\/p>\n<p>Answer: 77 ft<sup>2<\/sup><\/p>\n<p>Explanation: Area= 2(wl+hl+hw)<br \/>\n= 2(6.5\u00d72+3\u00d72+3\u00d76.5)<br \/>\n= 2(13+6+19.5)<br \/>\n= 2(38.5)<br \/>\n= 77 ft<sup>2<\/sup><\/p>\n<p><strong>Problem Solving<\/strong><\/p>\n<p>Question 6.<br \/>\nJeremiah is covering a cereal box with fabric for a school project. If the box is 6 inches long by 2 inches wide by 14 inches high, how much surface area does Jeremiah have to cover?<br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 248 in.<sup>2<\/sup><\/p>\n<p>Explanation: Surface area of a cereal box is 2(wl+hl+hw)<br \/>\n= 2(2\u00d76+14\u00d76+14\u00d72)<br \/>\n= 2(12+84+28)<br \/>\n= 2(124)<br \/>\n= 248 in.<sup>2<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-6971\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-80.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"164\" height=\"120\" \/><br \/>\n<\/sup><\/p>\n<p>Question 7.<br \/>\nTia is making a case for her calculator. It is a rectangular prism that will be 3.5 inches long by 1 inch wide by 10 inches high. How much material (surface area) will she need to make the case?<br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 97 in.<sup>2<\/sup><\/p>\n<p>Explanation: Surface Area= 2(wl+hl+hw)<br \/>\n= 2(1\u00d73.5+ 10\u00d73.5+ 10\u00d71)<br \/>\n= 2(3.5+35+10)<br \/>\n= 2(48.5)<br \/>\n= 97 in.<sup>2<\/sup><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-6973\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-82.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"163\" height=\"120\" \/><\/p>\n<p>Question 8.<br \/>\nExplain in your own words how to find the surface area of a rectangular prism.<\/p>\n<p>Answer: To find the surface area we must know the width, length, and height of the prism and then we can apply the formula which is<br \/>\nSurface area= 2(width \u00d7length)+ 2(length\u00d7height)+ 2(height\u00d7width)<br \/>\n= 2(width \u00d7length+ length\u00d7height+ 2(height\u00d7width)<\/p>\n<h3><a id=\"Lesson_Check_Page_No_608\"><\/a>Lesson Check &#8211; Page No. 608<\/h3>\n<p>Question 1.<br \/>\nGabriela drew a net of a rectangular prism on centimeter grid paper. If the prism is 7 cm long by 10 cm wide by 8 cm high, how many grid squares does the net cover?<br \/>\n_______ cm<sup>2<\/sup><\/p>\n<p>Answer: 412 cm<sup>2.<\/sup><\/p>\n<p>Explanation: Surface area is 2(wl+hl+hw)<br \/>\n= 2(10\u00d77+8\u00d77+8\u00d710)<br \/>\n= 2(70+56+80)<br \/>\n= 2(206)<br \/>\n= 412 cm<sup>2.<\/sup><\/p>\n<p>Question 2.<br \/>\nBen bought a cell phone that came in a box shaped like a rectangular prism. The box is 5 inches long by 3 inches wide by 2 inches high. What is the surface area of the box?<br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 62 in.<sup>2<\/sup><\/p>\n<p>Explanation: Surface area is 2(wl+hl+hw)<br \/>\n= 2(3\u00d75+2\u00d75+2\u00d73)<br \/>\n= 2(15+10+6)<br \/>\n= 2(31)<br \/>\n= 62 in.<sup>2<\/sup><\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p>Question 3.<br \/>\nKatrin wrote the inequality x + 56 &lt; 533. What is the solution of the inequality?<\/p>\n<p>Answer: X&lt;477.<\/p>\n<p>Explanation: X+56&lt;533<br \/>\n= X&lt;533-56<br \/>\n= X&lt;477.<\/p>\n<p>Question 4.<br \/>\nThe table shows the number of mixed CDs y that Jason makes in x hours.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-25.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 25\" width=\"468\" height=\"119\" \/><br \/>\nWhich equation describes the pattern in the table?<\/p>\n<p>Answer: y= 5x<\/p>\n<p>Explanation:<br \/>\ny\/x = 10\/2= 15\/4= 3<br \/>\ny= 5x<br \/>\nThe pattern is y is x multipled by 5.<\/p>\n<p>Question 5.<br \/>\nA square measuring 9 inches by 9 inches is cut from a corner of a square measuring 15 inches by 15 inches. What is the area of the L-shaped figure that is formed?<br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 144 in.<sup>2<\/sup><\/p>\n<p>Explanation: The area of a square A= a<sup>2<\/sup>, so we will find the area of each square.<br \/>\nArea= 9<sup>2<\/sup><br \/>\n= 9\u00d79<br \/>\n= 81 in.<sup>2<\/sup><br \/>\nAnd the area of another square is<br \/>\nA= 15<sup>2<br \/>\n<\/sup>= 15\u00d715<br \/>\n= 225 in.<sup>2<br \/>\n<\/sup>So the area of L shaped figure is 225-81= 144 in.<sup>2<\/sup><\/p>\n<p>Question 6.<br \/>\nBoxes of Clancy\u2019s Energy Bars are rectangular prisms. How many lateral faces does each box have?<\/p>\n<p>Answer: 4<\/p>\n<p>Explanation: As Lateral faces are not included in the bases, so rectangular prism has 4.<\/p>\n<h3><a id=\"Share_and_Show_Page_No_611\"><\/a>Share and Show &#8211; Page No. 611<\/h3>\n<p><strong>Use a net to find the surface area.<\/strong><\/p>\n<p>Question 1.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-26.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 26\" width=\"156\" height=\"146\" \/><br \/>\n_______ ft<sup>2<\/sup><\/p>\n<p>Answer: 24 ft<sup>2<\/sup><\/p>\n<p>Explanation: The area of each face is 2 ft\u00d72 ft= 4 ft and the number of faces is 6, so surface area is 6\u00d74= 24 ft<sup>2<\/sup><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-7001\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-96.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"162\" height=\"214\" \/><\/p>\n<p>Question 2.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-27.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 27\" width=\"199\" height=\"127\" \/><\/p>\n<p>Answer: 432 cm<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of face A is 16\u00d76= 96 cm<sup>2<br \/>\n<\/sup>The area of face B is 16\u00d78= 128 cm<sup>2<\/sup><br \/>\nThe area of face C and D is 1\/2 \u00d7 6\u00d78= 24 cm<sup>2<\/sup><br \/>\nThe area of face E is 16\u00d710= 160 cm<sup>2<\/sup><br \/>\nThe surface 96+128+2\u00d724+160= 432 cm<sup>2<\/sup><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-medium wp-image-7003\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-102-300x163.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"300\" height=\"163\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-102-300x163.png 300w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-102.png 327w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>Question 3.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-28.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 28\" width=\"134\" height=\"145\" \/><br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 155.5 in.<sup>2<\/sup><\/p>\n<p>Explanation:<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-medium wp-image-7005\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-104-300x105.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"300\" height=\"105\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-104-300x105.png 300w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-104.png 557w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><br \/>\nThe area of face A and E is\u00a0 8 \u00bd \u00d7 3\u00bd<br \/>\n= 17\/2 \u00d7 7\/2<br \/>\n= 119\/4<br \/>\n= 29.75 in.<sup>2<\/sup><br \/>\nThe area of face B and F is 8 \u00bd\u00d74<br \/>\n= 17 \u00bd \u00d7 4<br \/>\n= 34 in.<sup>2<br \/>\n<\/sup>The area of face C and D is 3 \u00bd\u00d74<br \/>\n7\/2 \u00d7 4= 14 in.<sup>2<br \/>\n<\/sup>The surface area is 2\u00d729.75+2\u00d734+2\u00d714<br \/>\n= 59.5+68+28<br \/>\n= 155.5 in.<sup>2<\/sup><\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>Use a net to find the surface area.<\/strong><\/p>\n<p>Question 4.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-29.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 29\" width=\"137\" height=\"161\" \/><br \/>\n_______ m<sup>2<\/sup><\/p>\n<p>Answer:<\/p>\n<p>Explanation:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-medium wp-image-7007\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-106-1-300x117.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"300\" height=\"117\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-106-1-300x117.png 300w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-106-1.png 533w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><br \/>\nThe area of face A and E is 8\u00d73= 24 m<sup>2<br \/>\n<\/sup>The area of face B and F is 8\u00d75= 40 m<sup>2<br \/>\n<\/sup>The area of face C and D is 3\u00d75= 15 m<sup>2<br \/>\n<\/sup>The surface area is 2\u00d724+2\u00d740+2\u00d715<br \/>\n= 48+80+30<br \/>\n= 158 m<sup>2<\/sup><\/p>\n<p>Question 5.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-30.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 30\" width=\"208\" height=\"188\" \/><br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) in.<sup>2<\/sup><\/p>\n<p>Answer:<\/p>\n<p>Explanation:<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-medium wp-image-7008\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-108-300x131.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"300\" height=\"131\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-108-300x131.png 300w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-108.png 459w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>The area of each face is 7 1\/2 \u00d7 7 1\/2<br \/>\n= 15\/2 \u00d7 15\/2<br \/>\n= 225\/4 in.<sup>2<\/sup><br \/>\nThe no.of faces are 6 and the surface area is 6\u00d7 225\/4<br \/>\n= 675\/4<br \/>\n= 337 1\/2 in.<sup>2<\/sup><\/p>\n<p>Question 6.<br \/>\nAttend to Precision Calculate the surface area of the cube in Exercise 5 using the formula S = 6s<sup>2<\/sup>. Show your work.<\/p>\n<p>Answer: 337 1\/2 in.<sup>2<\/sup><\/p>\n<p>Explanation: As S= s<sup>2<\/sup><br \/>\n= 6(7 1\/2)<sup>2<\/sup><br \/>\n= 6(15\/2)<sup>2<\/sup><br \/>\n= 6(225\/4)<br \/>\n= 675\/2<br \/>\n= 337 1\/2 in.<sup>2<\/sup><\/p>\n<h3><a id=\"Unlock_the_Problem_Page_No_612\"><\/a>Unlock the Problem &#8211; Page No. 612<\/h3>\n<p>Question 7.<br \/>\nThe Vehicle Assembly Building at Kennedy Space Center is a rectangular prism. It is 218 m long, 158 m wide, and 160 m tall. There are four 139 m tall doors in the building, averaging 29 m in width. What is the building\u2019s outside surface area when the doors are open?<br \/>\na. Draw each face of the building, not including the floor.<\/p>\n<p>Answer:<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-medium wp-image-7009\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-110-300x126.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"300\" height=\"126\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-110-300x126.png 300w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-110.png 425w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>Question 7.<br \/>\nb. What are the dimensions of the 4 walls?<\/p>\n<p>Answer: The 2 walls measure 218 m \u00d7160 m and 2 walls measure by 158 m\u00d7160 m.<\/p>\n<p>Question 7.<br \/>\nc. What are the dimensions of the roof?<\/p>\n<p>Answer: The dimensions of the roof are 218 m\u00d7158 m.<\/p>\n<p>Question 7.<br \/>\nd. Find the building\u2019s surface area (not including the floor) when the doors are closed.<br \/>\n_______ m<sup>2<\/sup><\/p>\n<p>Answer: 1,54,764 m<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of two walls is 218\u00d7160= 34,880 m<sup>2<\/sup><br \/>\nThe area of the other two walls is 158\u00d7160= 25,280 m<sup>2<br \/>\n<\/sup>The area of the roof 158\u00d7218= 34,444 m<sup>2<br \/>\n<\/sup>The surface area is 2\u00d7 34,880+ 2\u00d7 25,280+ 34,444<br \/>\n= 69,760+ 50,560+ 34,444<br \/>\n= 1,54,764 m<sup>2<\/sup><\/p>\n<p>Question 7.<br \/>\ne. Find the area of the four doors.<br \/>\n_______ m<sup>2<\/sup><\/p>\n<p>Answer: 16,124 m<sup>2<\/sup><\/p>\n<p>Explanation: Area of a door is 139\u00d729 = 4031 m<sup>2<\/sup><br \/>\nAnd the area of 4 doors is 4\u00d74031= 16,124 m<sup>2<\/sup><\/p>\n<p>Question 7.<br \/>\nf. Find the building\u2019s surface area (not including the floor) when the doors are open.<br \/>\n_______ m<sup>2<\/sup><\/p>\n<p>Answer: 1,38,640 m<sup>2<\/sup><\/p>\n<p>Explanation: The building&#8217;s surface area (not including the floor) when the doors are open is<br \/>\n1,54,764 &#8211; 16,124= 1,38,640 m<sup>2<\/sup><\/p>\n<p>Question 8.<br \/>\nA rectangular prism is 1 \\(\\frac{1}{2}\\) ft long, \\(\\frac{2}{3}\\) ft wide, and \\(\\frac{5}{6}\\) ft high. What is the surface area of the prism in square inches?<br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 808 in.<sup>2<\/sup><\/p>\n<p>Explanation: The area of two faces is 1 1\/2\u00d7 5\/6<br \/>\n= 3\/2 \u00d7 5\/6<br \/>\n= 5\/4 cm<sup>2<br \/>\n<\/sup>The area of two faces is 2\/3 \u00d7 5\/6<br \/>\n= 5\/9 ft<sup>2<\/sup><br \/>\nThe area of two faces is 1 1\/2\u00d7 2\/3<br \/>\n= 3\/2 \u00d7 2\/3<br \/>\n= 1 ft<sup>2<br \/>\n<\/sup>The surface area of the prism is 2(wl+hl+hw)<br \/>\n= 2(5\/4 + 5\/9 + 1)<br \/>\n= 2( 1.25+0.55+1)<br \/>\n= 2.5+1.1+2<br \/>\n= 5.61 ft<sup>2<br \/>\n<\/sup>As 1 square foot = 144 square inches<br \/>\nso 5.61\u00d7144 = 807.84<br \/>\n= 808 in.<sup>2<\/sup><\/p>\n<p>Question 9.<br \/>\nA gift box is a rectangular prism. The box measures 8 inches by 10 inches by 3 inches. What is its surface area?<br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 268 in.<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of face A and Face E is 8\u00d710= 80 in.<sup>2<\/sup><br \/>\nThe area of face B and Face F is 8\u00d73= 24 in.<sup>2<\/sup><br \/>\nThe area of face C and Face D is 10\u00d73= 30 in.<sup>2<\/sup><br \/>\nThe surface area is 2\u00d780+2\u00d724+2\u00d730<br \/>\n= 160+48+60<br \/>\n= 268 in.<sup>2<\/sup><\/p>\n<h3><a id=\"Surface_Area_of_Prisms_Page_No_613\"><\/a>Surface Area of Prisms &#8211; Page No. 613<\/h3>\n<p><strong>Use a net to find the surface area.<\/strong><\/p>\n<p>Question 1.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-31.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 31\" width=\"266\" height=\"81\" \/><br \/>\n_______ cm<sup>2<\/sup><\/p>\n<p>Answer: 104 cm<sup>2<\/sup><\/p>\n<p>Explanation: Surface area= 2(wl+hl+hw)<br \/>\n= 2(6\u00d75+2\u00d75+2\u00d76)<br \/>\n= 2(30+10+12)<br \/>\n= 2(52)<br \/>\n= 104 cm<sup>2<\/sup><\/p>\n<p>Question 2.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-32.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 32\" width=\"169\" height=\"164\" \/><br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 118 in.<sup>2<\/sup><\/p>\n<p>Explanation: Surface area= 2(wl+hl+hw)<br \/>\n= 2(3.5\u00d74+6\u00d74+6\u00d73.5)<br \/>\n= 2(59)<br \/>\n= 118 in.<sup>2<\/sup><\/p>\n<p>Question 3.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-33.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 33\" width=\"190\" height=\"176\" \/><br \/>\n_______ ft<sup>2<\/sup><\/p>\n<p>Answer: 486 ft<sup>2<\/sup><\/p>\n<p>Explanation: Surface area= 2(wl+hl+hw)<br \/>\n= 2(9\u00d79+9\u00d79+9\u00d79)<br \/>\n= 2(81+81+81)<br \/>\n= 2(243)<br \/>\n= 486 ft<sup>2<\/sup><\/p>\n<p>Question 4.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-34.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 34\" width=\"225\" height=\"168\" \/><br \/>\n_______ cm<sup>2<\/sup><\/p>\n<p>Answer: 336 cm<sup>2.<\/sup><\/p>\n<p>Explanation: Area = 1\/2 bh<br \/>\n= 1\/2 (6)(8)<br \/>\n= 3\u00d78<br \/>\n= 24.<br \/>\nAs there are 2 triangles, so 2\u00d724= 48.<br \/>\nSurface Area= (wl+hl+hw)<br \/>\n= (6\u00d712+8\u00d712+12\u00d710)<br \/>\n= 228<br \/>\nTotal Surface area = 228+48<br \/>\n= 336 cm<sup>2<\/sup><\/p>\n<p><strong>Problem Solving<\/strong><\/p>\n<p>Question 5.<br \/>\nA shoe box measures 15 in. by 7 in. by 4 \\(\\frac{1}{2}\\) in. What is the surface area of the box?<br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 408 in.<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of two faces is 15\u00d77= 105 in.<sup>2<br \/>\n<\/sup>The area of two faces is 15\u00d7 4 1\/2<br \/>\n= 15 \u00d7 9\/2<br \/>\n= 15 \u00d7 4.5<br \/>\n= 67.5 in.<sup>2<\/sup><br \/>\nThe area of two faces is 7\u00d7 4 1\/2<br \/>\n= 7\u00d7 9\/2<br \/>\n= 7\u00d7 4.5<br \/>\n= 31.5 in.<sup>2<br \/>\n<\/sup>The surface area is 2\u00d7105+ 2\u00d767.5+ 2\u00d731.5<br \/>\n= 210+ 135+ 63<br \/>\n= 408 in.<sup>2<\/sup><\/p>\n<p>Question 6.<br \/>\nVivian is working with a styrofoam cube for art class. The length of one side is 5 inches. How much surface area does Vivian have to work with?<br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 150 in.<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of each face is 5\u00d75= 25 in.<sup>2<\/sup><br \/>\nThe number of faces that styrofoam cube has is 6<br \/>\nSo the surface area is 6\u00d725= 150 in.<sup>2<\/sup><\/p>\n<p>Question 7.<br \/>\nExplain why a two-dimensional net is useful for finding the surface area of a three-dimensional figure.<\/p>\n<p>Answer: Two-dimensional net is useful because by using a two-dimensional net you can calculate the surface area of each face and add them up to find the surface area of the three-dimensional figure.<\/p>\n<h3><a id=\"Lesson_Check_Page_No_614\"><\/a>Lesson Check &#8211; Page No. 614<\/h3>\n<p>Question 1.<br \/>\nWhat is the surface area of a cubic box that contains a baseball that has a diameter of 3 inches?<br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 54 in.<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of each face is 3\u00d73= 9 in.<sup>2<\/sup><br \/>\nThe number of faces for a cubic box is 6 in.<sup>2<\/sup><br \/>\nThe surface area of box that contains a baseball is 6\u00d79= 54 in.<sup>2<\/sup><\/p>\n<p>Question 2.<br \/>\nA piece of wood used for construction is 2 inches by 4 inches by 24 inches. What is the surface area of the wood?<br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 304 in.<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of two faces is 4\u00d72= 8 in.<sup>2<\/sup><br \/>\nThe area of two faces is 2\u00d724= 48 in.<sup>2<\/sup><br \/>\nThe area of two faces is 24\u00d74= 96 in.<sup>2<br \/>\n<\/sup>So the surface area is 2\u00d78+ 2\u00d748+ 2\u00d796<br \/>\n= 16+96+192<br \/>\n= 304 in.<sup>2<\/sup><\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p>Question 3.<br \/>\nDetergent costs $4 per box. Kendra graphs the equation that gives the cost y of buying x boxes of detergent. What is the equation?<\/p>\n<p>Answer: Y= 4X.<\/p>\n<p>Explanation: The total price Y and the price is equal to 4 \u00d7 X, and X is the number of boxes that Kendra buys. So the equation is Y=4X.<\/p>\n<p>Question 4.<br \/>\nA trapezoid with bases that measure 8 inches and 11 inches has a height of 3 inches. What is the area of the trapezoid?<br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 28.5 in.<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nArea of a trapezoid is 1\/2(b1+b2)h<br \/>\n= 1\/2(8+11)3<br \/>\n= 1\/2(19)3<br \/>\n= 1\/2 (57)<br \/>\n= 28.5 in.<sup>2<\/sup><\/p>\n<p>Question 5.<br \/>\nCity Park is a right triangle with a base of 40 yd and a height of 25 yd. On a map, the park has a base of 40 in. and a height of 25 in. What is the ratio of the area of the triangle on the map to the area of City Park?<\/p>\n<p>Answer: 1296:1.<\/p>\n<p>Explanation:<br \/>\nArea= 1\/2 bh<br \/>\n= 1\/2 (40)(25)<br \/>\n= (20)(25)<br \/>\n= 500 yd<sup>2<\/sup><br \/>\nSo area of city park is 500 yd<sup>2<\/sup><br \/>\nArea= 1\/2 bh<br \/>\n= 1\/2 (40)(25)<br \/>\n= (20)(25)<br \/>\n= 500 in<sup>2<br \/>\n<\/sup>So area on the map is 500 in<br \/>\nas 1 yd<sup>2<\/sup>= 1296 in<sup>2<\/sup><br \/>\nSo 500 in<sup>2<\/sup> = 500\u00d71296<br \/>\n= 648,000<br \/>\nSo, the ratio of the area of the triangle on the map to the area of City Park is 648,000:500<br \/>\n= 1296:1.<\/p>\n<p>Question 6.<br \/>\nWhat is the surface area of the prism shown by the net?<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-35.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 35\" width=\"247\" height=\"209\" \/><br \/>\nAnswer: 72 square units.<\/p>\n<p>Explanation:<br \/>\nThe area of two faces is 18 squares<br \/>\nThe area of two faces is 6 squares<br \/>\nThe area of two faces is 12 squares<br \/>\nSo the surface area is 2\u00d718+ 2\u00d76+ 2\u00d712<br \/>\n= 72 square units.<\/p>\n<h3><a id=\"Share_and_Show_Page_No_617\"><\/a>Share and Show &#8211; Page No. 617<\/h3>\n<p>Question 1.<br \/>\nUse a net to find the surface area of the square pyramid.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-36.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 36\" width=\"149\" height=\"129\" \/><br \/>\n_______ cm<sup>2<\/sup><\/p>\n<p>Answer: 105 cm<sup>2<\/sup><\/p>\n<p>Explanation:<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-7015\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-112.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"221\" height=\"206\" \/><br \/>\nArea of the base 5\u00d75= 25 ,<br \/>\nand area of one face is 1\/2 \u00d7 5 \u00d7 8<br \/>\n= 5\u00d7 4<br \/>\n= 20 cm<sup>2<\/sup><br \/>\nThe surface area of a pyramid is 25+ 4\u00d720<br \/>\n= 25+80<br \/>\n= 105 cm<sup>2<\/sup><\/p>\n<p>Question 2.<br \/>\nA triangular pyramid has a base with an area of 43 cm<sup>2<\/sup> and lateral faces with bases of 10 cm and heights of 8.6 cm. What is the surface area of the pyramid?<br \/>\n_______ cm<sup>2<\/sup><\/p>\n<p>Answer: 172 cm<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of one face is 1\/2\u00d710\u00d78.6<br \/>\n= 5\u00d78.6<br \/>\n= 43 cm<sup>2<\/sup><br \/>\nThe surface area of the pyramid is 43+3\u00d743<br \/>\n= 43+ 129<br \/>\n= 172 cm<sup>2<\/sup><\/p>\n<p>Question 3.<br \/>\nA square pyramid has a base with a side length of 3 ft and lateral faces with heights of 2 ft. What is the lateral area of the pyramid?<br \/>\n_______ ft<sup>2<\/sup><\/p>\n<p>Answer: 12 ft<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of one face is 1\/2\u00d73\u00d72= 3 ft<sup>2<\/sup><br \/>\nThe lateral area of the pyramid is 4\u00d73= 12 ft<sup>2<\/sup><\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>Use a net to find the surface area of the square pyramid.<\/strong><\/p>\n<p>Question 4.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-37.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 37\" width=\"169\" height=\"150\" \/><br \/>\n_______ ft<sup>2<\/sup><\/p>\n<p>Answer: 208 ft<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-7016\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-114.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"210\" height=\"237\" \/><br \/>\nThe area of the base is 8\u00d78= 64<br \/>\nThe area of one face is 1\/2 \u00d78\u00d79<br \/>\n= 36 ft<sup>2<\/sup><br \/>\nThe surface area of the pyramid is 64+4\u00d736<br \/>\n= 64+144<br \/>\n= 208 ft<sup>2<\/sup><\/p>\n<p>Question 5.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-38.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 38\" width=\"186\" height=\"96\" \/><br \/>\n_______ cm<sup>2<\/sup><\/p>\n<p>Answer: 220 cm<sup>2<\/sup><\/p>\n<p>Explanation:<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-7018\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-119.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"204\" height=\"149\" \/><br \/>\nThe area of base is 10\u00d710= 100<br \/>\nThe area of one place is 1\/2\u00d710\u00d76<br \/>\n= 10\u00d73<br \/>\n= 30<br \/>\nThe surface area of the pyramid is 100+4\u00d730<br \/>\n= 100+120<br \/>\n= 220 cm<sup>2<\/sup><\/p>\n<p>Question 6.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-39.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 39\" width=\"191\" height=\"111\" \/><br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 264 in.<sup>2<\/sup><\/p>\n<p>Explanation:<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-7017\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-116.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"211\" height=\"208\" \/><br \/>\nThe area of the base is 8\u00d78= 64<br \/>\nThe area of one face is 1\/2\u00d78\u00d712.5<br \/>\n= 4\u00d712.5<br \/>\n= 50 in.<sup>2<\/sup><br \/>\nThe surface area of the pyramid is 64+ 4\u00d750<br \/>\n= 64+200<br \/>\n= 264 in.<sup>2<\/sup><\/p>\n<p>Question 7.<br \/>\nThe Pyramid Arena is located in Memphis, Tennessee. It is in the shape of a square pyramid, and the lateral faces are made almost completely of glass. The base has a side length of about 600 ft and the lateral faces have a height of about 440 ft. What is the total area of the glass in the Pyramid Arena?<br \/>\n_______ ft<sup>2<\/sup><\/p>\n<p>Answer: 5,28,000 ft<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of one face is 1\/2\u00d7600\u00d7440= 1,32,000 ft<sup>2<\/sup><br \/>\nThe surface of tha lateral faces is 4\u00d7 1,32,000= 5,28,000 ft<sup>2<\/sup><br \/>\nSo, the total area of the glass in the arena is 5,28,000 ft<sup>2<\/sup><\/p>\n<h3><a id=\"Problem_Solving_Applications_Page_No_618\"><\/a>Problem Solving + Applications &#8211; Page No. 618<\/h3>\n<p><strong>Use the table for 8\u20139.<\/strong><br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-40.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 40\" width=\"277\" height=\"165\" \/><\/p>\n<p>Question 8.<br \/>\nThe Great Pyramids are located near Cairo, Egypt. They are all square pyramids, and their dimensions are shown in the table. What is the lateral area of the Pyramid of Cheops?<br \/>\n_______ m<sup>2<\/sup><\/p>\n<p>Answer: 82,800 m<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of one face is 1\/2\u00d7230\u00d7180<br \/>\n= 230\u00d790<br \/>\n= 20,700 m<sup>2<\/sup><br \/>\nThe lateral area of the pyramid of Cheops is 4\u00d720,700= 82,800 m<sup>2<\/sup><\/p>\n<p>Question 9.<br \/>\nWhat is the difference between the surface areas of the Pyramid of Khafre and the Pyramid of Menkaure?<br \/>\n_______ m<sup>2<\/sup><\/p>\n<p>Answer: 93,338 m<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of the base is 215\u00d7215= 46,225<br \/>\nThe area of one face is 1\/2\u00d7215\u00d7174<br \/>\n= 215\u00d7 87<br \/>\n18,705 m<sup>2<\/sup><br \/>\nThe surface area of Pyramid Khafre is= 46,225+4\u00d718,705<br \/>\n= 46,225+ 74820<br \/>\n= 121,045 m<sup>2<\/sup><br \/>\nThe area of the base 103\u00d7103= 10,609<br \/>\nThe area of one face is 1\/2\u00d7103\u00d783<br \/>\n= 8549\u00f72<br \/>\n= 4274.4 m<sup>2<\/sup><br \/>\nThe surface area of the Pyramid of Menkaure is 10,609+4\u00d74274.5<br \/>\n= 10,609+ 17,098<br \/>\n= 27,707 m<sup>2<\/sup><\/p>\n<p>The difference between the surface areas of the Pyramid of Khafre and the Pyramid of Menkaure<br \/>\n= 121,405-27,707<br \/>\n= 93,338 m<sup>2<\/sup><\/p>\n<p>Question 10.<br \/>\nWrite an expression for the surface area of the square pyramid shown.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-41.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 41\" width=\"157\" height=\"125\" \/><\/p>\n<p>Answer: 6x+9 ft<sup>2.<\/sup><\/p>\n<p>Explanation: The expression for the surface area of the square pyramid is 6x+9 ft<sup>2.<\/sup><\/p>\n<p>Question 11.<br \/>\nMake Arguments A square pyramid has a base with a side length of 4 cm and triangular faces with a height of 7 cm. Esther calculated the surface area as (4 \u00d7 4) + 4(4 \u00d7 7) = 128 cm<sup>2<\/sup>. Explain Esther\u2019s error and find the correct surface area<\/p>\n<p>Answer: 72 cm<sup>2<\/sup>.<\/p>\n<p>Explanation: Esther didn&#8217;t apply the formula correctly, she forgot to include 1\/2 in the calculated surface area.<br \/>\nThe correct surface area is (4\u00d74)+4(1\/2 \u00d74\u00d77)<br \/>\n= 16+4(14)<br \/>\n= 16+56<br \/>\n= 72 cm<sup>2<\/sup>.<\/p>\n<p>Question 12.<br \/>\nJose says the lateral area of the square pyramid is 260 in.<sup>2<\/sup>. Do you agree or disagree with Jose? Use numbers and words to support your answer.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-42.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 42\" width=\"251\" height=\"127\" \/><\/p>\n<p>Answer: 160 in.<sup>2<\/sup><\/p>\n<p>Explanation: No, I disagree with Jose as he found surface area instead of the lateral area, so the lateral area is<br \/>\n4\u00d71\/2\u00d710\u00d78<br \/>\n= 2\u00d710\u00d78<br \/>\n= 160 in.<sup>2<\/sup><\/p>\n<h3><a id=\"Surface_Area_of_Pyramids_Page_No_619\"><\/a>Surface Area of Pyramids &#8211; Page No. 619<\/h3>\n<p><strong>Use a net to find the surface area of the square pyramid.<\/strong><\/p>\n<p>Question 1.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-43.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 43\" width=\"166\" height=\"137\" \/><br \/>\n_______ mm<sup>2<\/sup><\/p>\n<p>Answer: 95 mm<sup>2<\/sup><\/p>\n<p>Explanation:<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-7045\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-124.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"211\" height=\"206\" \/><br \/>\nThe area of the base is 5\u00d75= 25 mm<sup>2<\/sup><br \/>\nThe area of one face is 1\/2\u00d75\u00d77<br \/>\n= 35\/2<br \/>\n= 17.5 mm<sup>2<\/sup><br \/>\nThe surface area is 25+4\u00d717.5<br \/>\n= 25+4\u00d717.5<br \/>\n= 25+70<br \/>\n= 95 mm<sup>2<\/sup><\/p>\n<p>Question 2.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-44.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 44\" width=\"172\" height=\"95\" \/><br \/>\n_______ cm<sup>2<\/sup><\/p>\n<p>Answer: 612 cm<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-7047\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-126.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"193\" height=\"142\" \/><\/p>\n<p>The area of the base is 18\u00d718= 324 cm<sup>2<\/sup><br \/>\nThe area of one face is 1\/2\u00d718\u00d78<br \/>\n= 18\u00d74<br \/>\n=\u00a0 72 cm<sup>2<\/sup><br \/>\nThe surface area is 324+4\u00d772<br \/>\n= 25+4\u00d717.5<br \/>\n= 25+70<br \/>\n= 612 cm<sup>2<\/sup><\/p>\n<p>Question 3.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-45.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 45\" width=\"162\" height=\"146\" \/><br \/>\n_______ yd<sup>2<\/sup><\/p>\n<p>Answer: 51.25 yd<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-7046\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-125.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"213\" height=\"211\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-125.png 213w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-125-150x150.png 150w\" sizes=\"(max-width: 213px) 100vw, 213px\" \/><\/p>\n<p>The area of the base is 2.5\u00d72.5= 6.25\u00a0 mm<sup>2<\/sup><br \/>\nThe area of one face is 1\/2\u00d72.5\u00d79<br \/>\n= 22.5\/2<br \/>\n= 11.25 yd<sup>2<\/sup><br \/>\nThe surface area is 25+4\u00d717.5<br \/>\n= 6.25+4\u00d711.25<br \/>\n= 6.25+45<br \/>\n= 51.25 yd<sup>2<\/sup><\/p>\n<p>Question 4.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-46.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 46\" width=\"173\" height=\"105\" \/><br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 180 in<sup>2<\/sup><\/p>\n<p>Explanation:<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-7048\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-127.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"183\" height=\"143\" \/><\/p>\n<p>The area of the base is 10\u00d710= 100 in<sup>2<\/sup><br \/>\nThe area of one face is 1\/2\u00d74\u00d710<br \/>\n= 2\u00d710<br \/>\n= 20 in<sup>2<\/sup><br \/>\nThe surface area is 100+4\u00d720<br \/>\n= 100+4\u00d720<br \/>\n= 100+80<br \/>\n= 180 in<sup>2<\/sup><\/p>\n<p><strong>Problem Solving<\/strong><\/p>\n<p>Question 5.<br \/>\nCho is building a sandcastle in the shape of a triangular pyramid. The area of the base is 7 square feet. Each side of the base has a length of 4 feet and the height of each face is 2 feet. What is the surface area of the pyramid?<br \/>\n_______ ft<sup>2<\/sup><\/p>\n<p>Answer: 19 ft<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of one face is 1\/2\u00d74\u00d72= 4 ft<sup>2<\/sup><br \/>\nThe surface area of the triangular pyramid is 7+3\u00d74<br \/>\n= 7+12<br \/>\n= 19 ft<sup>2<\/sup><\/p>\n<p>Question 6.<br \/>\nThe top of a skyscraper is shaped like a square pyramid. Each side of the base has a length of 60 meters and the height of each triangle is 20 meters. What is the lateral area of the pyramid?<br \/>\n_______ m<sup>2<\/sup><\/p>\n<p>Answer: 2400 m<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of the one face is 1\/2\u00d760\u00d720<br \/>\n= 600 m<sup>2<\/sup><br \/>\nThe lateral area of the pyramid is 4\u00d7600= 2400 m<sup>2<\/sup><\/p>\n<p>Question 7.<br \/>\nWrite and solve a problem finding the lateral area of an object shaped like a square pyramid.<\/p>\n<p>Answer: Mary has a triangular pyramid with a base of 10cm and a height of 15cm. What is the lateral area of the pyramid?<\/p>\n<p>Explanation:<br \/>\nThe area of one face is 1\/2\u00d710\u00d715<br \/>\n= 5\u00d715<br \/>\n= 75 cm<sup>2<\/sup><br \/>\nThe lateral area of the triangular pyramid is 3\u00d775<br \/>\n= 225 cm<sup>2<\/sup><\/p>\n<h3><a id=\"Lesson_Check_Page_No_620\"><\/a>Lesson Check &#8211; Page No. 620<\/h3>\n<p>Question 1.<br \/>\nA square pyramid has a base with a side length of 12 in. Each face has a height of 7 in. What is the surface area of the pyramid?<br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 312 in.<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of the base is 12\u00d712= 144 in.<sup>2<\/sup><br \/>\nThe area of one face is 1\/2\u00d712\u00d77<br \/>\n= 6\u00d77<br \/>\n= 42 in.<sup>2<\/sup><br \/>\nThe surface area of the square pyramid is 144+4\u00d742<br \/>\n= 144+ 168<br \/>\n= 312 in.<sup>2<\/sup><\/p>\n<p>Question 2.<br \/>\nThe faces of a triangular pyramid have a base of 5 cm and a height of 11 cm. What is the lateral area of the pyramid?<br \/>\n_______ cm<sup>2<\/sup><\/p>\n<p>Answer: 82.5 cm<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of one face is 1\/2\u00d75\u00d711<br \/>\n= 55\/2<br \/>\n= 27.5 cm<sup>2<\/sup><br \/>\nThe lateral area of the triangular pyramid is 3\u00d727.5= 82.5 cm<sup>2<\/sup><\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p>Question 3.<br \/>\nWhat is the linear equation represented by the graph?<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-47.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 47\" width=\"239\" height=\"239\" \/><\/p>\n<p>Answer: y=x+1.<\/p>\n<p>Explanation: As the figure represents that every y value is 1 more than the corresponding x value, so the linear equation is y=x+1.<\/p>\n<p>Question 4.<br \/>\nA regular octagon has sides measuring about 4 cm. If the octagon is divided into 8 congruent triangles, each has a height of 5 cm. What is the area of the octagon?<br \/>\n_______ cm<sup>2<\/sup><\/p>\n<p>Answer:<\/p>\n<p>Explanation:<br \/>\nArea is 1\/2bh<br \/>\n= 1\/2\u00d7 4\u00d75<br \/>\n= 2\u00d75<br \/>\n= 10 cm<sup>2<\/sup><br \/>\nSo the area of each triangle is 10 cm<sup>2<\/sup><br \/>\nand the area of the octagon is 8\u00d710= 80 cm<sup>2<\/sup><\/p>\n<p>Question 5.<br \/>\nCarly draws quadrilateral JKLM with vertices J(\u22123, 3), K(3, 3), L(2, \u22121), and M(\u22122, \u22121). What is the best way to classify the quadrilateral?<\/p>\n<p>Answer: It is a Trapezoid.<\/p>\n<p>Explanation: It is a Trapezoid.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-medium wp-image-7073\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-129-300x199.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"300\" height=\"199\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-129-300x199.png 300w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-129.png 645w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<p>Question 6.<br \/>\nA rectangular prism has the dimensions 8 feet by 3 feet by 5 feet. What is the surface area of the prism?<br \/>\n_______ ft<sup>2<\/sup><\/p>\n<p>Answer: 158 ft<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of the two faces of the rectangular prism is 8\u00d73= 24 ft<sup>2<\/sup><br \/>\nThe area of the two faces of the rectangular prism is 8\u00d75= 40 ft<sup>2<\/sup><br \/>\nThe area of the two faces of the rectangular prism is 3\u00d75= 15 ft<sup>2<\/sup><br \/>\nThe surface area of the rectangular prism is 2\u00d724+2\u00d740+2\u00d715<br \/>\n= 48+80+30<br \/>\n= 158 ft<sup>2<\/sup><\/p>\n<h3><a id=\"#Mid_Chapter_Checkpoint_Vocabulary_Page_No_621\"><\/a>Mid-Chapter Checkpoint &#8211; Vocabulary &#8211; Page No. 621<\/h3>\n<p><strong>Choose the best term from the box to complete the sentence.<\/strong><br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-48.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 48\" width=\"269\" height=\"229\" \/><\/p>\n<p>Question 1.<br \/>\n_____ is the sum of the areas of all the faces, or surfaces, of a solid figure.<\/p>\n<p>Answer: Surface area is the sum of the areas of all the faces, or surfaces, of a solid figure.<\/p>\n<p>Question 2.<br \/>\nA three-dimensional figure having length, width, and height is called a(n) _____.<\/p>\n<p>Answer: A three-dimensional figure having length, width, and height is called a(n) solid figure.<\/p>\n<p>Question 3.<br \/>\nThe _____ of a solid figure is the sum of the areas of its lateral faces.<\/p>\n<p>Answer: The lateral area of a solid figure is the sum of the areas of its lateral faces.<\/p>\n<p><strong>Concepts and Skills<\/strong><\/p>\n<p>Question 4.<br \/>\nIdentify and draw a net for the solid figure.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-49.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 49\" width=\"223\" height=\"209\" \/><\/p>\n<p>Answer: Triangular prism<\/p>\n<p>Explanation:<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-6963\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-73.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"231\" height=\"117\" \/><\/p>\n<p>Question 5.<br \/>\nUse a net to find the lateral area of the square pyramid.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-50.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 50\" width=\"174\" height=\"154\" \/><br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 216 in.<sup>2<\/sup><\/p>\n<p>Explanation:<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-7076\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-131-1.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"211\" height=\"200\" \/><br \/>\nThe area of one face is 1\/2\u00d79\u00d712<br \/>\n= 9\u00d76<br \/>\n= 54 in.<sup>2<\/sup><br \/>\nThe lateral area of the square pyramid is 4\u00d754= 216 in.<sup>2<\/sup><\/p>\n<p>Question 6.<br \/>\nUse a net to find the surface area of the prism.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-51.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 51\" width=\"212\" height=\"200\" \/><br \/>\n_______ cm<sup>2<\/sup><\/p>\n<p>Answer: 310 cm<sup>2<\/sup><\/p>\n<p>Explanation:<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-medium wp-image-7078\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-133-300x203.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"300\" height=\"203\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-133-300x203.png 300w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-133.png 431w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><br \/>\nThe area of face A and E is 10\u00d75= 50 cm<sup>2<\/sup><br \/>\nThe area of face B and F is 10\u00d77= 70 cm<sup>2<\/sup><br \/>\nThe area of face C and D is 7\u00d75= 35 cm<sup>2<\/sup><br \/>\nThe surface area of the prism is 2\u00d750+2\u00d770+2\u00d735<br \/>\n= 100+140+70<br \/>\n= 310 cm<sup>2<\/sup><\/p>\n<h3><a id=\"Page_No_622\"><\/a>Page No. 622<\/h3>\n<p>Question 7.<br \/>\nA machine cuts nets from flat pieces of cardboard. The nets can be folded into triangular pyramids used as pieces in a board game. What shapes appear in the net? How many of each shape are there?<\/p>\n<p>Answer: 4 triangles.<\/p>\n<p>Explanation: There are 4 triangles.<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-6964\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-74-e1599324193300.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"126\" height=\"159\" \/><\/p>\n<p>Question 8.<br \/>\nFran\u2019s filing cabinet is 6 feet tall, 1 \\(\\frac{1}{3}\\) feet wide, and 3 feet deep. She plans to paint all sides except the bottom of the cabinet. Find the area of the sides she intends to paint.<br \/>\n_______ ft<sup>2<\/sup><\/p>\n<p>Answer: 56 ft<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe two lateral face area is 6\u00d71 1\/3<br \/>\n= 6\u00d7 4\/3<br \/>\n= 2\u00d74<br \/>\n= 8 ft<sup>2<\/sup><br \/>\nThe area of the other two lateral faces is 6\u00d73= 18<br \/>\nThe area of the top and bottom is 3\u00d7 1 1\/3<br \/>\n= 3\u00d7 4\/3<br \/>\n= 4 ft<sup>2<\/sup><br \/>\nThe area of the sides she intends to paint is 2\u00d78+2\u00d718+4<br \/>\n= 16+36+4<br \/>\n= 56 ft<sup>2<\/sup><\/p>\n<p>Question 9.<br \/>\nA triangular pyramid has lateral faces with bases of 6 meters and heights of 9 meters. The area of the base of the pyramid is 15.6 square meters. What is the surface area of the pyramid?<\/p>\n<p>Answer: 96.6 m<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of one face is 1\/2\u00d7 6\u00d7 9<br \/>\n= 3\u00d79<br \/>\n= 27 m<sup>2<\/sup><br \/>\nThe surface area of the triangular pyramid is 15.6+3\u00d727<br \/>\n= 15.6+ 81<br \/>\n= 96.6 m<sup>2<\/sup><\/p>\n<p>Question 10.<br \/>\nWhat is the surface area of a storage box that measures 15 centimeters by 12 centimeters by 10 centimeters?<br \/>\n_______ cm<sup>2<\/sup><\/p>\n<p>Answer: 900 cm<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of two faces is 15\u00d712= 180 cm<sup>2<\/sup><br \/>\nThe area of another two faces is 15\u00d710= 150 cm<sup>2<\/sup><br \/>\nThe area of the other two faces is 10\u00d712= 120 cm<sup>2<\/sup><br \/>\nSo surface area of the storage box is 2\u00d7180+2\u00d7150+2\u00d7120 cm<sup>2<\/sup><br \/>\n= 360+300+240<br \/>\n= 900 cm<sup>2<\/sup><\/p>\n<p>Question 11.<br \/>\nA small refrigerator is a cube with a side length of 16 inches. Use the formula S = 6s<sup>2<\/sup> to find the surface area of the cube.<br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 1,536 in.<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nArea = s<sup>2<\/sup><br \/>\n= 6\u00d7(16)<sup>2<\/sup><br \/>\n= 6\u00d7 256<br \/>\n= 1,536 in.<sup>2<\/sup><\/p>\n<h3><a id=\"Share_and_Show_Page_No_625\"><\/a>Share and Show &#8211; Page No. 625<\/h3>\n<p>Question 1.<br \/>\nA prism is filled with 38 cubes with a side length of \\(\\frac{1}{2}\\) unit. What is the volume of the prism in cubic units?<br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) cubic units<\/p>\n<p>Answer: 4.75 cubic units<\/p>\n<p>Explanation:<br \/>\nThe volume of the cube is S<sup>3<br \/>\n<\/sup>The volume of a cube with S= (1\/2)<sup>3<br \/>\n<\/sup>= 1\/2\u00d71\/2\u00d71\/2<br \/>\n= 1\/8<br \/>\n= 0.125 cubic units<br \/>\nAs there are 38 cubes so 38\u00d70.125= 4.75 cubic units.<\/p>\n<p>Question 2.<br \/>\nA prism is filled with 58 cubes with a side length of \\(\\frac{1}{2}\\) unit. What is the volume of the prism in cubic units?<br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) cubic units<\/p>\n<p>Answer: 7.25 cubic units.<\/p>\n<p>Explanation:<br \/>\nThe volume of the cube is S<sup>3<br \/>\n<\/sup>The volume of a cube with S= (1\/2)<sup>3<br \/>\n<\/sup>= 1\/2\u00d71\/2\u00d71\/2<br \/>\n= 1\/8<br \/>\n= 0.125 cubic units<br \/>\nAs there are 58 cubes so 58\u00d70.125= 7.25 cubic units.<\/p>\n<p><strong>Find the volume of the rectangular prism.<\/strong><\/p>\n<p>Question 3.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-52.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 52\" width=\"201\" height=\"113\" \/><br \/>\n_______ cubic units<\/p>\n<p>Answer: 33 cubic units.<\/p>\n<p>Explanation:<br \/>\nThe volume of the rectangular prism is= Width\u00d7Height\u00d7Length<br \/>\n= 5 1\/2 \u00d73\u00d72<br \/>\n= 11\/2 \u00d73\u00d72<br \/>\n= 33 cubic units.<\/p>\n<p>Question 4.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-53.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 53\" width=\"165\" height=\"134\" \/><br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) cubic units<\/p>\n<p>Answer: 91 1\/8 cubic units.<\/p>\n<p>Explanation:<br \/>\nThe volume of the rectangular prism is= Width\u00d7Height\u00d7Length<br \/>\n= 4 1\/2 \u00d74 1\/2\u00d74\u00a01\/2<br \/>\n= 9\/2 \u00d79\/2\u00d79\/2<br \/>\n= 729\/8<br \/>\n= 91 1\/8 cubic units.<\/p>\n<p>Question 5.<br \/>\nTheodore wants to put three flowering plants in his window box. The window box is shaped like a rectangular prism that is 30.5 in. long, 6 in. wide, and 6 in. deep. The three plants need a total of 1,200 in.<sup>3<\/sup> of potting soil to grow well. Is the box large enough? Explain.<\/p>\n<p>Answer: No, the box is not large enough as the three plants need a total of 1,200 in.<sup>3<\/sup> and here volume is 1,098 in.<sup>3<\/sup><\/p>\n<p>Explanation:<br \/>\nVolume= Width\u00d7Height\u00d7Length<br \/>\n= 30.5\u00d76\u00d76<br \/>\n= 1,098 in.<sup>3<\/sup><\/p>\n<p>Question 6.<br \/>\nExplain how use the formula V = l \u00d7 w \u00d7 h to verify that a cube with a side length of \\(\\frac{1}{2}\\) unit has a volume of \\(\\frac{1}{8}\\) of a cubic unit.<\/p>\n<p>Answer: 1\/8 cubic units<\/p>\n<p>Explanation:<br \/>\nAs length, width and height is 1\/2&#8242; so<br \/>\nVolume = Width\u00d7Height\u00d7Length<br \/>\n= 1\/2 \u00d7 1\/2 \u00d7 1\/2<br \/>\n= 1\/8 cubic units<\/p>\n<h3><a id=\"Problem_Solving_Applications_Page_No_626\"><\/a>Problem Solving + Applications &#8211; Page No. 626<\/h3>\n<p><strong>Use the diagram for 7\u201310.<\/strong><br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-54.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 54\" width=\"215\" height=\"304\" \/><\/p>\n<p>Question 7.<br \/>\nKaryn is using a set of building blocks shaped like rectangular prisms to make a model. The three types of blocks she has are shown at right. What is the volume of an A block? (Do not include the pegs on top.)<br \/>\n\\(\\frac{\u25a1}{\u25a1}\\) cubic units<\/p>\n<p>Answer: 1\/2 cubic units<\/p>\n<p>Explanation: Volume = Width\u00d7Height\u00d7Length<br \/>\n= 1\u00d7 1\/2 \u00d71<br \/>\n= 1\/2 cubic units<\/p>\n<p>Question 8.<br \/>\nHow many A blocks would you need to take up the same amount of space as a C block?<br \/>\n_______ A blocks<\/p>\n<p>Answer: No of blocks required to take up the same amount of space as a C block is 4 A blocks.<\/p>\n<p>Explanation: Volume = Width\u00d7Height\u00d7Length<br \/>\n= 1\u00d72\u00d71<br \/>\n= 2 cubic unit<br \/>\nNo of blocks required to take up the same amount of space as a C block is 1\/2 \u00f72<br \/>\n= 2\u00d72<br \/>\n= 4 A blocks<\/p>\n<p>Question 9.<br \/>\nKaryn puts a B block, two C blocks, and three A blocks together. What is the total volume of these blocks?<br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) cubic units<\/p>\n<p>Answer: 6 1\/2 cubic units<\/p>\n<p>Explanation: The volume of A block is<br \/>\nVolume = Width\u00d7Height\u00d7Length<br \/>\n= 1\u00d71 \u00d71\/2<br \/>\n= 1\/2 cubic units.<br \/>\nAs Karyn puts three A blocks together, so 3\u00d7 1\/2= 3\/2 cubic units.<br \/>\nThe volume of B block is<br \/>\nVolume = Width\u00d7Height\u00d7Length<br \/>\n= 1\u00d71 \u00d7 1<br \/>\n= 1 cubic units.<br \/>\nAs Karyn puts only one B, so 1 cubic unit.<br \/>\nThe volume of C block is<br \/>\nVolume = Width\u00d7Height\u00d7Length<br \/>\n= 2\u00d71\u00d71<br \/>\n= 2 cubic units.<br \/>\nAs Karyn puts two C blocks together, so 2\u00d7 2= 4 cubic units.<br \/>\nSo, the total volume of these blocks is 3\/2 + 1+ 4<br \/>\n= 3\/2+5<br \/>\n= 13\/2<br \/>\n= 6 1\/2 cubic units<\/p>\n<p>Question 10.<br \/>\nKaryn uses the blocks to make a prism that is 2 units long, 3 units wide, and 1 \\(\\frac{1}{2}\\) units high. The prism is made of two C blocks, two B blocks, and some A blocks. What is the total volume of A blocks used?<br \/>\n_______ cubic units<\/p>\n<p>Answer: 3 cubic units.<\/p>\n<p>Explanation:<br \/>\nVolume = Width\u00d7Height\u00d7Length<br \/>\n= 2\u00d73\u00d71 1\/2<br \/>\n= 2\u00d73\u00d7 3\/2<br \/>\n= 9 cubic units.<br \/>\nThe total volume of A block used is 9-(2\u00d72)-(2\u00d71)<br \/>\n= 9- 4- 2<br \/>\n= 9-6<br \/>\n= 3 cubic units.<\/p>\n<p>Question 11.<br \/>\nVerify the Reasoning of Others Jo says that you can use V = l \u00d7 w \u00d7 h or V = h \u00d7 w \u00d7 l to find the volume of a rectangular prism. Does Jo\u2019s statement make sense? Explain.<\/p>\n<p>Answer: Yes<\/p>\n<p>Explanation: Yes, Jo&#8217;s statement makes sense because by the commutative property we can change the order of the variables of length, width, height and both will produce the same result.<\/p>\n<p>Question 12.<br \/>\nA box measures 5 units by 3 units by 2 \\(\\frac{1}{2}\\) units. For numbers 12a\u201312b, select True or False for the statement.<br \/>\n12a. The greatest number of cubes with a side length of \\(\\frac{1}{2}\\) unit that can be packed inside the box is 300.<br \/>\n12b. The volume of the box is 37 \\(\\frac{1}{2}\\) cubic units.<br \/>\n12a. __________<br \/>\n12b. __________<\/p>\n<p>Answer:<br \/>\n12a True.<br \/>\n12b True.<\/p>\n<p>Explanation:\u00a0The volume of the cube is S<sup>3<br \/>\n<\/sup>The volume of a cube with S= (1\/2)<sup>3<br \/>\n<\/sup>= 1\/2\u00d71\/2\u00d71\/2<br \/>\n= 1\/8 cubic units<br \/>\nAs there are 300 cubes so 300\u00d7 1\/8= 75\/2<br \/>\n= 37 1\/2 cubic units.<\/p>\n<h3><a id=\"Fractions_and_Volume_Page_No_627\"><\/a>Fractions and Volume &#8211; Page No. 627<\/h3>\n<p><strong>Find the volume of the rectangular prism.<\/strong><\/p>\n<p>Question 1.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-55.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 55\" width=\"226\" height=\"116\" \/><br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) cubic units<\/p>\n<p>Answer: 6 3\/4 cubic units<\/p>\n<p>Explanation: Volume = Width\u00d7Height\u00d7Length<br \/>\n= 3\u00d7 1 1\/2\u00d7 1 1\/2<br \/>\n= 3\u00d7 3\/2 \u00d7 3\/2<br \/>\n= 27\/4<br \/>\n= 6 3\/4 cubic units<\/p>\n<p>Question 2.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-56.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 56\" width=\"178\" height=\"130\" \/><br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) cubic units<\/p>\n<p>Answer: 22 1\/2 cubic units<\/p>\n<p>Explanation: Volume = Width\u00d7Height\u00d7Length<br \/>\n= 5\u00d71\u00d7 4 1\/2<br \/>\n= 5\u00d7 9\/2<br \/>\n= 45\/2<br \/>\n= 22 1\/2 cubic units<\/p>\n<p>Question 3.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-57.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 57\" width=\"240\" height=\"123\" \/><br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) cubic units<\/p>\n<p>Answer: 16 1\/2 cubic units.<\/p>\n<p>Explanation: Volume = Width\u00d7Height\u00d7Length<br \/>\n= 5 1\/2\u00d7 1 1\/2\u00d7 2<br \/>\n= 11\/2\u00d73\/2\u00d72<br \/>\n= 33\/2<br \/>\n= 16 1\/2 cubic units.<\/p>\n<p>Question 4.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-58.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 58\" width=\"197\" height=\"191\" \/><br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) cubic units<\/p>\n<p>Answer: 28 1\/8 cubic units.<\/p>\n<p>Explanation: Volume = Width\u00d7Height\u00d7Length<br \/>\n= 2 1\/2\u00d7 2 1\/2 \u00d7 4 1\/2<br \/>\n= 5\/2 \u00d7 5\/2 \u00d7 9\/2<br \/>\n= 225\/8<br \/>\n= 28 1\/8 cubic units.<\/p>\n<p><strong>Problem Solving<\/strong><\/p>\n<p>Question 5.<br \/>\nMiguel is pouring liquid into a container that is 4 \\(\\frac{1}{2}\\) inches long by 3 \\(\\frac{1}{2}\\) inches wide by 2 inches high. How many cubic inches of liquid will fit in the container?<br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) in.<sup>3<\/sup><\/p>\n<p>Answer: 31 1\/2 cubic units<\/p>\n<p>Explanation: Volume = Width\u00d7Height\u00d7Length<br \/>\n= 4 1\/2 \u00d7 3 1\/2 \u00d72<br \/>\n= 9\/2 \u00d7 7\/2 \u00d7 2<br \/>\n= 63\/2<br \/>\n= 31 1\/2 cubic units<\/p>\n<p>Question 6.<br \/>\nA shipping crate is shaped like a rectangular prism. It is 5 \\(\\frac{1}{2}\\) feet long by 3 feet wide by 3 feet high. What is the volume of the crate?<br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) ft<sup>3<\/sup><\/p>\n<p>Answer: 49 1\/2 ft<sup>3<\/sup><\/p>\n<p>Explanation: Volume = Width\u00d7Height\u00d7Length<br \/>\n= 5 1\/2 \u00d7 3 \u00d7 3<br \/>\n= 11\/2 \u00d79<br \/>\n= 99\/2<br \/>\n= 49 1\/2 ft<sup>3<\/sup><\/p>\n<p>Question 7.<br \/>\nHow many cubes with a side length of \\(\\frac{1}{4}\\) unit would it take to make a unit cube? Explain how you determined your answer.<\/p>\n<p>Answer: There will be 4\u00d74\u00d74= 64 cubes and 1\/4 unit in the unit cube.<\/p>\n<p>Explanation:<br \/>\nAs the unit cube has a 1 unit length, 1 unit wide, and 1 unit height<br \/>\nSo length 4 cubes = 4\u00d7 1\/4= 1 unit<br \/>\nwidth 4 cubes = 4\u00d7 1\/4= 1 unit<br \/>\nheight 4 cubes = 4\u00d7 1\/4= 1 unit<br \/>\nSo there will be 4\u00d74\u00d74= 64 cubes and 1\/4 unit in the unit cube.<\/p>\n<h3><a id=\"Lesson_Check_Page_No_628\"><\/a>Lesson Check &#8211; Page No. 628<\/h3>\n<p>Question 1.<br \/>\nA rectangular prism is 4 units by 2 \\(\\frac{1}{2}\\) units by 1 \\(\\frac{1}{2}\\) units. How many cubes with a side length of \\(\\frac{1}{2}\\) unit will completely fill the prism?<\/p>\n<p>Answer: 120 cubes<\/p>\n<p>Explanation:<br \/>\nNo of cubes with a side length of 1\/2 unit is<br \/>\nLength 8 cubes= 8\u00d7 1\/2= 4 units<br \/>\nWidth 5 cubes= 5\u00d7 1\/2= 5\/2= 2 1\/2 units<br \/>\nHeight 3 cubes= 3\u00d7 1\/2= 3\/2= 1 1\/2 units<br \/>\nSo there are 8\u00d75\u00d73= 120 cubes in the prism.<\/p>\n<p>Question 2.<br \/>\nA rectangular prism is filled with 196 cubes with \\(\\frac{1}{2}\\)-unit side lengths. What is the volume of the prism in cubic units?<br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) cubic units<\/p>\n<p>Answer: 24 1\/2 cubic units.<\/p>\n<p>Explanation: As it takes 8 cubes with a side length of 1\/2 to form a unit cube, so the volume of the prism in the cubic units is 196\u00f78= 24 1\/2 cubic units.<\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p>Question 3.<br \/>\nA parallelogram-shaped piece of stained glass has a base measuring 2 \\(\\frac{1}{2}\\) inches and a height of 1 \\(\\frac{1}{4}\\) inches. What is the area of the piece of stained glass?<br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) in.<sup>2<\/sup><\/p>\n<p>Answer: 3 1\/8 in.<sup>2<\/sup><\/p>\n<p>Explanation: Area of a parallelogram = base\u00d7height<br \/>\n= 2 1\/2 \u00d7 1 1\/4<br \/>\n= 5\/2 \u00d7 5\/4<br \/>\n= 25\/8<br \/>\n= 3 1\/8 in.<sup>2<\/sup><\/p>\n<p>Question 4.<br \/>\nA flag for the sports club is a rectangle measuring 20 inches by 32 inches. Within the rectangle is a yellow square with a side length of 6 inches. What is the area of the flag that is not part of the yellow square?<br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 604 in.<sup>2<\/sup><\/p>\n<p>Explanation: Area of a flag= Length\u00d7width<br \/>\n= 20\u00d732<br \/>\n= 640 in.<sup>2<\/sup><br \/>\nArea of the yellow square= S<sup>2<\/sup><br \/>\n= 6<br \/>\n= 36 in.<sup>2<\/sup><br \/>\nSo the area of the flag that is not a part of the yellow square is 640-36= 604 in.<sup>2<\/sup><\/p>\n<p>Question 5.<br \/>\nWhat is the surface area of the rectangular prism shown by the net?<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-59.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 59\" width=\"282\" height=\"202\" \/><br \/>\n_______ square units<\/p>\n<p>Answer: 80 square units<\/p>\n<p>Explanation:<br \/>\nArea of two faces is 12 squares<br \/>\nArea of other two faces is 16 squares<br \/>\nArea of another two faces is 12 squares<br \/>\nSo the surface area is 2\u00d712+2\u00d716+2\u00d712<br \/>\n= 24+32+24<br \/>\n= 80 square units<\/p>\n<p>Question 6.<br \/>\nWhat is the surface area of the square pyramid?<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-60.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 60\" width=\"163\" height=\"149\" \/><br \/>\n_______ cm<sup>2<\/sup><\/p>\n<p>Answer: 161 cm<sup>2<\/sup><\/p>\n<p>Explanation: The area of the base is 7\u00d77= 49 cm<sup>2<\/sup><br \/>\nAnd the area of one face is 1\/2 \u00d7 7\u00d7 8<br \/>\n= 7\u00d74<br \/>\n= 28 cm<sup>2<\/sup><br \/>\nThe surface area of the square pyramid is 49+4\u00d728<br \/>\n= 49+112<br \/>\n= 161 cm<sup>2<\/sup><\/p>\n<h3><a id=\"Share_and_Show_Page_No_631\"><\/a>Share and Show &#8211; Page No. 631<\/h3>\n<p><strong>Find the volume.<\/strong><\/p>\n<p>Question 1.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-61.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 61\" width=\"136\" height=\"166\" \/><br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) in.<sup>3<\/sup><\/p>\n<p>Answer: 3,937 1\/2 in.<sup>3<\/sup><\/p>\n<p>Explanation: Volume= Length\u00d7 wide\u00d7 heght<br \/>\n= 10 1\/2 \u00d715 \u00d7 25<br \/>\n= 11\/2 \u00d7 15 \u00d7 25<br \/>\n= 4,125\/2<br \/>\n= 3,937 1\/2 in.<sup>3<\/sup><\/p>\n<p>Question 2.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-62.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 62\" width=\"127\" height=\"128\" \/><br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) in.<sup>3<\/sup><\/p>\n<p>Answer: 27\/512 in.<sup>3<\/sup><\/p>\n<p>Explanation: Volume= Length\u00d7 wide\u00d7 height<br \/>\n=3\/8 \u00d73\/8 \u00d7 3\/8<br \/>\n= 27\/512 in.<sup>3<\/sup><\/p>\n<p><strong>On Your Own<\/strong><\/p>\n<p><strong>Find the volume of the prism.<\/strong><\/p>\n<p>Question 3.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-63.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 63\" width=\"192\" height=\"177\" \/><br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) in.<sup>3<\/sup><\/p>\n<p>Answer: 690 5\/8in.<sup>3<\/sup><\/p>\n<p>Explanation: Volume= Length\u00d7 wide\u00d7 height<br \/>\n= 8 1\/2 \u00d7 6 1\/2 \u00d7 12 1\/2<br \/>\n= 17\/2 \u00d7 13\/2\u00d7 25\/2<br \/>\n= 5525\/2<br \/>\n= 690 5\/8in.<sup>3<\/sup><\/p>\n<p>Question 4.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-64.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 64\" width=\"130\" height=\"127\" \/><br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) in.<sup>3<\/sup><\/p>\n<p>Answer: 125\/4096 in.<sup>3<\/sup><\/p>\n<p>Explanation: Volume= Length\u00d7 wide\u00d7 height<br \/>\n= 5\/16 \u00d75\/16 \u00d7 5\/16<br \/>\n= 125\/4096 in.<sup>3<\/sup><\/p>\n<p>Question 5.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-65.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 65\" width=\"268\" height=\"88\" \/><br \/>\n_______ yd<sup>3<\/sup><\/p>\n<p>Answer: 20 yd<sup>3<\/sup><\/p>\n<p>Explanation:<br \/>\nArea= 3 1\/3 yd<sup>2<\/sup><br \/>\nSo Area= wide\u00d7height<br \/>\n3 1\/3= w \u00d7 1 1\/3<br \/>\n10\/3= w\u00d7 4\/3<br \/>\nw= 10\/3 \u00d7 3\/4<br \/>\nw= 5\/2<br \/>\nw= 2.5 yd<br \/>\nVolume= Length\u00d7width\u00d7height<br \/>\n= 6\u00d7 2.5\u00d7 1 1\/3<br \/>\n= 6\u00d72.5\u00d7 4\/3<br \/>\n= 2\u00d72.5\u00d74<br \/>\n= 20 yd<sup>3<\/sup><\/p>\n<p>Question 6.<br \/>\nWayne\u2019s gym locker is a rectangular prism with a width and height of 14 \\(\\frac{1}{2}\\) inches. The length is 8 inches greater than the width. What is the volume of the locker?<br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) in.<sup>3<\/sup><\/p>\n<p>Answer: 4,730 5\/8 in.<sup>3<\/sup><\/p>\n<p>Explanation: As length is 8 inches greater than width, so 14 1\/2+ 8<br \/>\n= 29\/2+8<br \/>\n= 45\/2<br \/>\n= 22 1\/2 in<br \/>\nThen volume= Length\u00d7width\u00d7height<br \/>\n= 22 1\/2 \u00d7 14 1\/2 \u00d7 14 1\/2<br \/>\n= 45\/2\u00d7 29\/2\u00d7 29\/2<br \/>\n= 37845\/8<br \/>\n= 4,730 5\/8 in.<sup>3<\/sup><\/p>\n<p>Question 7.<br \/>\nAbraham has a toy box that is in the shape of a rectangular prism.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-66.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 66\" width=\"251\" height=\"198\" \/><br \/>\nThe volume is _____.<br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) ft<sup>3<\/sup><\/p>\n<p>Answer: 33 3\/4 ft<sup>3<\/sup><\/p>\n<p>Explanation: Volume of rectangular prism is= Length\u00d7width\u00d7height<br \/>\n= 4 1\/2\u00d7 2 1\/2\u00d7 3<br \/>\n= 9\/2 \u00d7 5\/2\u00d7 3<br \/>\n= 135\/3<br \/>\n= 33 3\/4 ft<sup>3<\/sup><\/p>\n<h3><a id=\"Aquariums_Page_No_632\"><\/a>Aquariums &#8211; Page No. 632<\/h3>\n<p>Large public aquariums like the Tennessee Aquarium in Chattanooga have a wide variety of freshwater and saltwater fish species from around the world. The fish are kept in tanks of various sizes.<br \/>\nThe table shows information about several tanks in the aquarium. Each tank is a rectangular prism.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-67.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 67\" width=\"479\" height=\"280\" \/><br \/>\nFind the length of Tank 1.<br \/>\nV = l w h<br \/>\n52,500 = l \u00d7 30 \u00d7 35<br \/>\n\\(\\frac{52,500}{1,050}\\) = l<br \/>\n50 = l<br \/>\nSo, the length of Tank 1 is 50 cm.<\/p>\n<p><strong>Solve.<\/strong><\/p>\n<p>Question 8.<br \/>\nFind the width of Tank 2 and the height of Tank 3.<\/p>\n<p>Answer: Width of Tank 2= 8m, Height of the Tank 3= 10 m<\/p>\n<p>Explanation:<br \/>\nThe volume of Tank 2= 384 m<sup>3<\/sup><br \/>\nso V= LWH<br \/>\n384=\u00a0 12\u00d7W\u00d74<br \/>\nW= 384\/48<br \/>\nW= 8 m<br \/>\nSo the width of Tank 2= 8m<br \/>\nThe volume of Tank 3= 2160 m<br \/>\nSo V= LWH<br \/>\n2160= 18\u00d712\u00d7H<br \/>\nH= 2160\/216<br \/>\nH= 10 m<br \/>\nSo the height of the Tank 3= 10 m<\/p>\n<p>Question 9.<br \/>\nTo keep the fish healthy, there should be the correct ratio of water to fish in the tank. One recommended ratio is 9 L of water for every 2 fish. Find the volume of Tank 4. Then use the equivalencies 1 cm<sup>3<\/sup> = 1 mL and 1,000 mL = 1 L to find how many fish can be safely kept in Tank 4.<\/p>\n<p>Answer: 35 Fishes<\/p>\n<p>Explanation:<br \/>\nVolume of Tank 4 = LWH<br \/>\n= 72\u00d755\u00d740<br \/>\n= 1,58,400 cm<sup>3<\/sup><br \/>\nAs 1 cm<sup>3<\/sup> = 1 mL and 1,000 mL = 1 L<br \/>\n1,58,400 cm<sup>3<\/sup> = 1,58,400 mL and 1,58,400 mL = 158.4 L<br \/>\nSo tank can keep safely (158.4\u00f7 9)\u00d72<br \/>\n= (17.6)\u00d7 2 = 35.2<br \/>\n= 35 Fishes<\/p>\n<p>Question 10.<br \/>\nUse Reasoning Give another set of dimensions for a tank that would have the same volume as Tank 2. Explain how you found your answer.<\/p>\n<p>Answer:\u00a0Another set of dimensions for a tank that would have the same volume as Tank 2 is 8m by 8m by 6m.<br \/>\nSo when we multiply the product will be 384<\/p>\n<h3><a id=\"Volume_of_Rectangular_Prisms_Page_No_633\"><\/a>Volume of Rectangular Prisms &#8211; Page No. 633<\/h3>\n<p><strong>Find the volume.<\/strong><\/p>\n<p>Question 1.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-68.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 68\" width=\"115\" height=\"114\" \/><br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) m<sup>3<\/sup><\/p>\n<p>Answer: 150 5\/16 m<sup>3<\/sup><\/p>\n<p>Explanation: Volume= Length\u00d7width\u00d7height<br \/>\n= 5\u00d7 3 1\/4\u00d7 9 1\/4<br \/>\n= 5\u00d7 13\/4 \u00d7 37\/4<br \/>\n= 2405\/16<br \/>\n= 150 5\/16 m<sup>3<\/sup><\/p>\n<p>Question 2.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-69.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 69\" width=\"199\" height=\"125\" \/><br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) in.<sup>3<\/sup><\/p>\n<p>Answer: 27 1\/2 in.<sup>3<\/sup><\/p>\n<p>Explanation: Volume= Length\u00d7width\u00d7height<br \/>\n= 5 1\/2 \u00d7 2 1\/2 \u00d7 2<br \/>\n= 11\/2 \u00d7 5\/2 \u00d7 2<br \/>\n= 55\/2<br \/>\n= 27 1\/2 in.<sup>3<\/sup><\/p>\n<p>Question 3.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-70.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 70\" width=\"163\" height=\"142\" \/><br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) mm<sup>3<\/sup><\/p>\n<p>Answer: 91 1\/8 mm<sup>3<\/sup><\/p>\n<p>Explanation: Volume= Length\u00d7width\u00d7height<br \/>\n= 4 1\/2 \u00d7 4 1\/2 \u00d7 4 1\/2<br \/>\n= 9\/2 \u00d7 9\/2 \u00d7 9\/2<br \/>\n= 729\/8<br \/>\n= 91 1\/8 mm<sup>3<\/sup><\/p>\n<p>Question 4.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-71.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 71\" width=\"183\" height=\"160\" \/><br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) ft<sup>3<\/sup><\/p>\n<p>Answer: 112 1\/2 ft<sup>3<\/sup><\/p>\n<p>Explanation: Volume= Length\u00d7width\u00d7height<br \/>\n= 7 1\/2 \u00d7 2 1\/2 \u00d7 6<br \/>\n= 15\/2 \u00d7 5\/2 \u00d7 6<br \/>\n= 225\/2<br \/>\n= 112 1\/2 ft<sup>3<\/sup><\/p>\n<p>Question 5.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-72.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 72\" width=\"144\" height=\"117\" \/><br \/>\n_______ m<sup>3<\/sup><\/p>\n<p>Answer: 36 m<sup>3<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of shaded face is Length \u00d7 width= 8 m<sup>2<\/sup><br \/>\nVolume of the prism= Length\u00d7width\u00d7height<br \/>\n= 8 \u00d7 4 1\/2<br \/>\n= 8 \u00d7 9\/2<br \/>\n= 4 \u00d7 9<br \/>\n= 36 m<sup>3<\/sup><\/p>\n<p>Question 6.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-73.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 73\" width=\"250\" height=\"195\" \/><br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) ft<sup>3<br \/>\n<\/sup><\/p>\n<p>Answer: 30 3\/8 ft<sup>3<\/sup><\/p>\n<p>Explanation: Volume of the prism= Length\u00d7width\u00d7height<br \/>\n= 2 1\/4 \u00d7 6 \u00d7 2 1\/4<br \/>\n= 9\/4 \u00d7 6 \u00d7 9\/4<br \/>\n= 243\/8<br \/>\n= 30 3\/8 ft<sup>3<\/sup><\/p>\n<p><strong>Problem Solving<\/strong><\/p>\n<p>Question 7.<br \/>\nA cereal box is a rectangular prism that is 8 inches long and 2 \\(\\frac{1}{2}\\) inches wide. The volume of the box is 200 in.<sup>3<\/sup>. What is the height of the box?<br \/>\n_______ in.<\/p>\n<p>Answer: H= 10 in<\/p>\n<p>Explanation: As volume = 200 in.<sup>3<\/sup>. So<br \/>\nV= LWH<br \/>\n200= 8 \u00d7 2 1\/2 \u00d7 H<br \/>\n200= 8 \u00d7 5\/2 \u00d7 H<br \/>\n200= 20 \u00d7 H<br \/>\nH= 10 in<\/p>\n<p>Question 8.<br \/>\nA stack of paper is 8 \\(\\frac{1}{2}\\) in. long by 11 in. wide by 4 in. high. What is the volume of the stack of paper?<br \/>\n_______ in.<sup>3<\/sup><\/p>\n<p>Answer: 374 in.<sup>3<\/sup><\/p>\n<p>Explanation: The volume of the stack of paper= LWH<br \/>\n= 8 1\/2 \u00d7 11 \u00d7 4<br \/>\n= 17\/2 \u00d7 11 \u00d7 4<br \/>\n= 374 in.<sup>3<\/sup><\/p>\n<p>Question 9.<br \/>\nExplain how you can find the side length of a rectangular prism if you are given the volume and the two other measurements. Does this process change if one of the measurements includes a fraction?<\/p>\n<p>Answer: We can find the side length of a rectangular prism if you are given the volume and the two other measurements by dividing the value of the volume by the product of the values of width and height of the prism. And the process doesn&#8217;t change if one of the measurements include a fraction.<\/p>\n<h3><a id=\"Lesson_Check_Page_No_634\"><\/a>Lesson Check &#8211; Page No. 634<\/h3>\n<p>Question 1.<br \/>\nA kitchen sink is a rectangular prism with a length of 19 \\(\\frac{7}{8}\\) inches, a width of 14 \\(\\frac{3}{4}\\) inches, and height of 10 inches. Estimate the volume of the sink.<\/p>\n<p>Answer: 3,000 in.<sup>3<\/sup><\/p>\n<p>Explanation: Length = 19 7\/8 as the number was close to 20 and width 14 3\/4 which is close to 15 and height is 10<br \/>\nSo Volume= LBH<br \/>\n= 20 \u00d7 15 \u00d7 10<br \/>\n= 3,000 in.<sup>3<\/sup><\/p>\n<p>Question 2.<br \/>\nA storage container is a rectangular prism that is 65 centimeters long and 40 centimeters wide. The volume of the container is 62,400 cubic centimeters. What is the height of the container?<\/p>\n<p>Answer: H= 24 cm<\/p>\n<p>Explanation: Volume of container= LBH<br \/>\nVolume= 62,400 cubic centimeters<br \/>\n62,400 = 65\u00d7 40 \u00d7 H<br \/>\n62,400 = 2600 \u00d7 H<br \/>\nH= 62,400\/ 2600<br \/>\nH= 24 cm<\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p>Question 3.<br \/>\nCarrie started at the southeast corner of Franklin Park, walked north 240 yards, turned and walked west 80 yards, and then turned and walked diagonally back to where she started. What is the area of the triangle enclosed by the path she walked?<br \/>\n_______ yd<sup>2<\/sup><\/p>\n<p>Answer: 9,600 yd<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nArea of triangle= 1\/2 bh<br \/>\n= 1\/2 \u00d7 240 \u00d7 80<br \/>\n= 240 \u00d7 40<br \/>\n= 9,600 yd<sup>2<\/sup><\/p>\n<p>Question 4.<br \/>\nThe dimensions of a rectangular garage are 100 times the dimensions of a floor plan of the garage. The area of the floor plan is 8 square inches. What is the area of the garage?<\/p>\n<p>Answer: 80,000 in<sup>2<\/sup><\/p>\n<p>Explanation: As 1 in<sup>2<\/sup>= 10,000 in<sup>2<\/sup>, so area of the floor plan 8 in<br \/>\n= 8\u00d710000<br \/>\n= 80,000 in<sup>2<\/sup><\/p>\n<p>Question 5.<br \/>\nShiloh wants to create a paper-m\u00e2ch\u00e9 box shaped like a rectangular prism. If the box will be 4 inches by 5 inches by 8 inches, how much paper does she need to cover the box?<\/p>\n<p>Answer: 184 in<sup>2<\/sup><\/p>\n<p>Explanation: Area of the rectangular prism= 2(wl+hl+hw)<br \/>\n= 2(4\u00d75 + 5\u00d78 + 8\u00d74)<br \/>\n= 2(20+40+32)<br \/>\n= 2(92)<br \/>\n= 184 in<sup>2<\/sup><\/p>\n<p>Question 6.<br \/>\nA box is filled with 220 cubes with a side length of \\(\\frac{1}{2}\\) unit. What is the volume of the box in cubic units?<br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) cubic units<\/p>\n<p>Answer: 27.5 cubic units.<\/p>\n<p>Explanation: The volume of a cube side is (1\/2)<sup>3<\/sup> = 1\/8<br \/>\nSo 220 cubes= 220\u00d7 1\/8<br \/>\n= 27.5 cubic units.<\/p>\n<h3><a id=\"Share_and_Show_Page_No_637\"><\/a>Share and Show &#8211; Page No. 637<\/h3>\n<p>Question 1.<br \/>\nAn aquarium tank in the shape of a rectangular prism is 60 cm long, 30 cm wide, and 24 cm high. The top of the tank is open, and the glass used to make the tank is 1 cm thick. How much water can the tank hold?<br \/>\n_______ cm<sup>3<\/sup><\/p>\n<p>Answer: So tank can hold 37,352 cm<sup>3<\/sup><\/p>\n<p>Explanation: As Volume= LBH<br \/>\nLet&#8217;s find the inner dimensions of the tank, so 60-2 \u00d7 30-2 \u00d7 24-1<br \/>\n= 58\u00d728\u00d723<br \/>\n= 37,352 cm<sup>3<\/sup><\/p>\n<p>Question 2.<br \/>\nWhat if, to provide greater strength, the glass bottom were increased to a thickness of 4 cm? How much less water would the tank hold?<br \/>\n_______ cm<sup>3<\/sup><\/p>\n<p>Answer: 4,872 cm<sup>3<\/sup><\/p>\n<p>Explanation: As the glass bottom was increased to a thickness of 4 cm, 60-2 \u00d7 30-2 \u00d7 24-4<br \/>\n= 58\u00d728\u00d720<br \/>\n= 32,480 cm<sup>3<\/sup><br \/>\nSo the tank can hold 37,352- 32,480= 4,872 cm<sup>3<\/sup><\/p>\n<p>Question 3.<br \/>\nAn aquarium tank in the shape of a rectangular prism is 40 cm long, 26 cm wide, and 24 cm high. If the top of the tank is open, how much tinting is needed to cover the glass on the tank? Identify the measure you used to solve the problem.<br \/>\n_______ cm<sup>3<\/sup><\/p>\n<p>Answer: 4,208 cm<sup>3 <\/sup>\u00a0tinting needed to cover the glass on the tank.<\/p>\n<p>Explanation:<br \/>\nThe lateral area of the two faces is 26\u00d724= 624 cm<sup>2<\/sup><br \/>\nThe lateral area of the other two faces is 40\u00d724= 960 cm<sup>2<\/sup><br \/>\nAnd the area of the top and bottom is 40\u00d726= 1040 cm<sup>2<\/sup><br \/>\nSo the surface area of the tank without the top is 2\u00d7624 + 2\u00d7960 + 1040<br \/>\n= 1,248+1,920+1,040<br \/>\n= 4,208 cm<sup>3<\/sup><\/p>\n<p>Question 4.<br \/>\nThe Louvre Museum in Paris, France, has a square pyramid made of glass in its central courtyard. The four triangular faces of the pyramid have bases of 35 meters and heights of 27.8 meters. What is the area of glass used for the four triangular faces of the pyramid?<\/p>\n<p>Answer: 1946 m<sup>2<\/sup><\/p>\n<p>Explanation: The area of one face is 1\/2 \u00d7 35 \u00d7 27.8= 486.5 m<sup>2<\/sup><br \/>\nAnd the area of glass used for the four triangular faces of the pyramid is 4\u00d7486.5= 1946 m<sup>2<\/sup><\/p>\n<h3><a id=\"On_Your_Own_Page_No_638\"><\/a>On Your Own &#8211; Page No. 638<\/h3>\n<p>Question 5.<br \/>\nA rectangular prism-shaped block of wood measures 3 m by 1 \\(\\frac{1}{2}\\) m by 1 \\(\\frac{1}{2}\\) m. How much of the block must a carpenter carve away to obtain a prism that measures 2 m by \\(\\frac{1}{2}\\) m by \\(\\frac{1}{2}\\) m?<br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) m<sup>3<\/sup><\/p>\n<p>Answer: 6 1\/4 m<sup>3<\/sup><\/p>\n<p>Explanation: The volume of the original block= LWH<br \/>\n= 3 \u00d7 1 1\/2 \u00d7 1 1\/2<br \/>\n= 3\u00d7 3\/2 \u00d7 3\/2<br \/>\n= 27\/4<br \/>\n= 6 3\/4 m<sup>2<\/sup><br \/>\nAnd volume of carpenter carve is 2\u00d7 1\/2 \u00d7 1\/2<br \/>\n= 1\/2 m<sup>2<\/sup><br \/>\nSo, the carpenter must carve 27\/4 &#8211; 1\/2<br \/>\n= 25\/2<br \/>\n= 6 1\/4 m<sup>3<\/sup><\/p>\n<p>Question 6.<br \/>\nThe carpenter (Problem 5) varnished the outside of the smaller piece of wood, all except for the bottom, which measures \\(\\frac{1}{2}\\) m by \\(\\frac{1}{2}\\) m. Varnish costs $2.00 per square meter. What was the cost of varnishing the wood?<br \/>\n$ _______<\/p>\n<p>Answer: $8.50<\/p>\n<p>Explanation: The area of two lateral faces are 2\u00d71\/2= 1 m<sup>2<\/sup><br \/>\nThe area of the other two lateral faces are 2\u00d71\/2= 1 m<sup>2<\/sup><br \/>\nThe area of the top and bottom is 1\/2\u00d71\/2= 1\/4 m<sup>2<\/sup><br \/>\nAnd the surface area is 2\u00d71 + 2\u00d71 + 1\/4<br \/>\n= 2+2+1\/4<br \/>\n= 17\/4<br \/>\n= 4.25 m<sup>2<\/sup><br \/>\nAnd the cost of vanishing the wood is $2.00\u00d7 4.25= $8.50<\/p>\n<p>Question 7.<br \/>\nA wax candle is in the shape of a cube with a side length of 2 \\(\\frac{1}{2}\\) in. What volume of wax is needed to make the candle?<br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) in.<sup>3<\/sup><\/p>\n<p>Answer:<\/p>\n<p>Explanation: The Volume of wax is needed to make the candle is= LWH<br \/>\n= 2 1\/2 \u00d7 2 1\/2 \u00d7 2 1\/2<br \/>\n= 5\/2 \u00d7 5\/2 \u00d7 5\/2<br \/>\n= 125\/8<br \/>\n= 15 5\/8 in.<sup>3<\/sup><\/p>\n<p>Question 8.<br \/>\nDescribe A rectangular prism-shaped box measures 6 cm by 5 cm by 4 cm. A cube-shaped box has a side length of 2 cm. How many of the cube-shaped boxes will fit into the rectangular prismshaped box? Describe how you found your answer.<\/p>\n<p>Answer: 12 cube-shaped boxes<\/p>\n<p>Explanation: As 6 small boxes can fit on the base i.e 6 cm by 5 cm, as height is 4cm there can be a second layer of 6 small boxes. So, there will be a total of 12 cube-shaped boxes and will fit into a rectangular prism-shaped box<\/p>\n<p>Question 9.<br \/>\nJustin is covering the outside of an open shoe box with colorful paper for a class project. The shoe box is 30 cm long, 20 cm wide, and 13 cm high. How many square centimeters of paper are needed to cover the outside of the open shoe box? Explain your strategy<br \/>\n_______ cm<sup>2<\/sup><\/p>\n<p>Answer: 1,900 cm<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of the two lateral faces of the shoebox is 20\u00d713= 260 cm<sup>2<\/sup><br \/>\nThe area of another two lateral faces of the shoebox is 30\u00d713= 390 cm<sup>2<\/sup><br \/>\nThe area of the top and bottom is 30\u00d720= 600 cm<sup>2<\/sup><br \/>\nSo, the surface area of the shoebox without the top is 2\u00d7260 + 2\u00d7 390 + 600<br \/>\n= 520+780+600<br \/>\n= 1,900 cm<sup>2<\/sup><\/p>\n<h3><a id=\"Problem_Solving_Geometric_Measurements_Page_No_639\"><\/a>Problem Solving Geometric Measurements &#8211; Page No. 639<\/h3>\n<p><strong>Read each problem and solve.<\/strong><\/p>\n<p>Question 1.<br \/>\nThe outside of an aquarium tank is 50 cm long, 50 cm wide, and 30 cm high. It is open at the top. The glass used to make the tank is 1 cm thick. How much water can the tank hold?<br \/>\n_______ cm<sup>3<\/sup><\/p>\n<p>Answer: So water tank can hold 66,816 cm<sup>3<\/sup><\/p>\n<p>Explanation: The volume of inner dimensions of the aquarium is 50-2 \u00d7 50-2 \u00d7 30-1<br \/>\n= 48\u00d748\u00d729<br \/>\n= 66,816 cm<sup>3<\/sup><br \/>\nSo water tank can hold 66,816 cm<sup>3<\/sup><\/p>\n<p>Question 2.<br \/>\nArnie keeps his pet snake in an open-topped glass cage. The outside of the cage is 73 cm long, 60 cm wide, and 38 cm high. The glass used to make the cage is 0.5 cm thick. What is the inside volume of the cage?<br \/>\n_______ cm<sup>3<\/sup><\/p>\n<p>Answer: The volume of the cage is 1,59,300 cm<sup>3<\/sup><\/p>\n<p>Explanation: The volume of inner dimensions is 73-1 \u00d7 60-1 \u00d7 38-0.5<br \/>\n= 72\u00d759\u00d737.5<br \/>\n= 1,59,300 cm<sup>3<br \/>\n<\/sup>So, the volume of the cage is 1,59,300 cm<sup>3<\/sup><\/p>\n<p>Question 3.<br \/>\nA display number cube measures 20 in. on a side. The sides are numbered 1\u20136. The odd-numbered sides are covered in blue fabric and the even-numbered sides are covered in red fabric. How much red fabric was used?<br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 1200 in.<sup>2<\/sup><\/p>\n<p>Explanation: The area of each side of a cube is 20\u00d720= 400 in.<sup>2<\/sup>, as there are 3 even-numbered sides on the cube. So there will be<br \/>\n3\u00d7400= 1200 in.<sup>2<\/sup><\/p>\n<p>Question 4.<br \/>\nThe caps on the tops of staircase posts are shaped like square pyramids. The side length of the base of each cap is 4 inches. The height of the face of each cap is 5 inches. What is the surface area of the caps for two posts?<br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 112 in.<sup>2<\/sup><\/p>\n<p>Explanation: The area of the base is 4\u00d74= 16 in.<sup>2<\/sup><br \/>\nThe area of one face is 1\/2\u00d75\u00d74= 10 in.<sup>2<\/sup><br \/>\nThe surface area of one cap is 16+4\u00d710<br \/>\n= 16+40<br \/>\n= 56 in.<sup>2<\/sup><br \/>\nAnd the surface area of the caps for two posts is 2\u00d756= 112 in.<sup>2<\/sup><\/p>\n<p>Question 5.<br \/>\nA water irrigation tank is shaped like a cube and has a side length of 2 \\(\\frac{1}{2}\\) feet. How many cubic feet of water are needed to completely fill the tank?<br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) ft<sup>3<\/sup><\/p>\n<p>Answer: 15 5\/8 ft<sup>3<\/sup><\/p>\n<p>Explanation: Volume= LWH<br \/>\n= 2 1\/2 \u00d7 2 1\/2 \u00d7 2 1\/2<br \/>\n= 5\/2 \u00d7 5\/2 \u00d7 5\/2<br \/>\n= 125\/8<br \/>\n= 15 5\/8 ft<sup>3<\/sup><\/p>\n<p>Question 6.<br \/>\nWrite and solve a problem for which you use part of the formula for the surface area of a triangular prism.<\/p>\n<p>Answer: In a triangular prism, the triangular end has a base of 5cm and the height is 8 cm. The length of each side is 4 cm and the height of the prism is 10 cm. What is the lateral area of this triangular prism?<\/p>\n<p>Explanation: The area of two triangular faces is 1\/2 \u00d7 5 \u00d7 8<br \/>\n= 5\u00d74<br \/>\n= 20 cm<sup>2<\/sup><br \/>\nThe area of two rectangular faces is 4\u00d710= 40 cm<sup>2<\/sup><br \/>\nThe lateral area is 2\u00d720+2\u00d740<br \/>\n= 40+80<br \/>\n= 120 cm<sup>2<\/sup><\/p>\n<h3><a id=\"Lesson_Check_Page_No_640\"><\/a>Lesson Check &#8211; Page No. 640<\/h3>\n<p>Question 1.<br \/>\nMaria wants to know how much wax she will need to fill a candle mold shaped like a rectangular prism. What measure should she find?<\/p>\n<p>Answer: Maria needs to find the volume of the mold.<\/p>\n<p>Question 2.<br \/>\nThe outside of a closed glass display case measures 22 inches by 15 inches by \\(\\frac{1}{2}\\) inches. The glass is 12 inch thick. How much air is contained in the case?<br \/>\n_______ in.<sup>3<\/sup><\/p>\n<p>Answer: 3381 in.<sup>3<\/sup><\/p>\n<p>Explanation: The inner dimensions are 22-1\u00d7 15-1 \u00d7 12- 1\/2<br \/>\n= 21 \u00d714\u00d723\/2<br \/>\n= 3381 in.<sup>3<\/sup><\/p>\n<p><strong>Spiral Review<\/strong><\/p>\n<p>Question 3.<br \/>\nA trapezoid with bases that measure 5 centimeters and 7 centimeters has a height of 4.5 centimeters. What is the area of the trapezoid?<br \/>\n_______ cm<sup>2<\/sup><\/p>\n<p>Answer: 27 cm<sup>2<\/sup><\/p>\n<p>Explanation: Area of trapezoid= 1\/2 \u00d7(7+5)\u00d74.5<br \/>\n= 6\u00d74.5<br \/>\n= 27 cm<sup>2<\/sup><\/p>\n<p>Question 4.<br \/>\nSierra has plotted two vertices of a rectangle at (3, 2) and (8, 2). What is the length of the side of the rectangle?<br \/>\n_______ units<\/p>\n<p>Answer: 5 units.<\/p>\n<p>Explanation: The length of the side of the rectangle is 8-3= 5 units.<\/p>\n<p>Question 5.<br \/>\nWhat is the surface area of the square pyramid?<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-74.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 74\" width=\"183\" height=\"171\" \/><br \/>\n_______ m<sup>2<\/sup><\/p>\n<p>Answer: 104 m<sup>2<\/sup><\/p>\n<p>Explanation: The area of the base 4\u00d74= 16<br \/>\nThe area of the one face is 1\/2 \u00d7 4 \u00d7 11<br \/>\n= 2\u00d711<br \/>\n= 22 m<sup>2<\/sup><br \/>\nThe surface area of the square pyramid is 16+4\u00d722<br \/>\n= 16+88<br \/>\n= 104 m<sup>2<\/sup><\/p>\n<p>Question 6.<br \/>\nA shipping company has a rule that all packages must be rectangular prisms with a volume of no more than 9 cubic feet. What is the maximum measure for the height of a box that has a width of 1.5 feet and a length of 3 feet?<br \/>\n_______ feet<\/p>\n<p>Answer: 2 feet.<\/p>\n<p>Explanation: As given volume = 9 cubic feet<br \/>\nSo 1.5\u00d73\u00d7H &lt; 9<br \/>\n4.5\u00d7H &lt; 9<br \/>\nH&lt; 9\/4.5<br \/>\nand H&lt;2<br \/>\nSo maximum measure for the height of the box is 2 feet.<\/p>\n<h3><a id=\"Chapter_11_Review_Test_Page_No_641\"><\/a>Chapter 11 Review\/Test &#8211; Page No. 641<\/h3>\n<p>Question 1.<br \/>\nElaine makes a rectangular pyramid from paper.<br \/>\nThe base is a _____. The lateral faces are _____.<br \/>\nThe base is a ___________ .<br \/>\nThe lateral faces are ___________ .<\/p>\n<p>Answer:<br \/>\nThe base is a rectangle.<br \/>\nThe lateral faces are triangles.<\/p>\n<p>Question 2.<br \/>\nDarrell paints all sides except the bottom of the box shown below.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-75.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 75\" width=\"263\" height=\"183\" \/><br \/>\nSelect the expressions that show how to find the surface area that Darrell painted. Mark all that apply.<br \/>\nOptions:<br \/>\na. 240 + 240 + 180 + 180 + 300 + 300<br \/>\nb. 2(20 \u00d7 12) + 2(15 \u00d7 12) + (20 \u00d7 15)<br \/>\nc. (20 \u00d7 12) + (20 \u00d7 12) + (15 \u00d7 12) + (15 \u00d7 12) + (20 \u00d7 15)<br \/>\nd. 20 \u00d7 15 \u00d7 12<\/p>\n<p>Answer: b,c<\/p>\n<p>Explanation: The expressions that show how to find the surface area is 2(20 \u00d7 12) + 2(15 \u00d7 12) + (20 \u00d7 15), (20 \u00d7 12) + (20 \u00d7 12) + (15 \u00d7 12) + (15 \u00d7 12) + (20 \u00d7 15)<\/p>\n<p>Question 3.<br \/>\nA prism is filled with 44 cubes with \\(\\frac{1}{2}\\)-unit side lengths. What is the volume of the prism in cubic units?<br \/>\n_______ \\(\\frac{\u25a1}{\u25a1}\\) cubic unit<\/p>\n<p>Answer:<\/p>\n<p>Explanation:<br \/>\nThe volume of a cube with S= (1\/2)<sup>3<br \/>\n<\/sup>= 1\/2\u00d71\/2\u00d71\/2<br \/>\n= 1\/8<br \/>\n= 0.125 cubic units<br \/>\nAs there are 44 cubes so 44\u00d70.125=5.5 cubic units.<\/p>\n<p>Question 4.<br \/>\nA triangular pyramid has a base with an area of 11.3 square meters, and lateral faces with bases of 5.1 meters and heights of 9 meters. Write an expression that can be used to find the surface area of the triangular pyramid.<\/p>\n<p>Answer: 11.3+ 3 \u00d7 1\/2+ 5.1\u00d79<\/p>\n<p>Explanation: The expression that can be used to find the surface area of the triangular pyramid is 11.3+ 3 \u00d7 1\/2+ 5.1\u00d79<\/p>\n<h3><a id=\"Page_No_642\"><\/a>Page No. 642<\/h3>\n<p>Question 5.<br \/>\nJeremy makes a paperweight for his mother in the shape of a square pyramid. The base of the pyramid has a side length of 4 centimeters, and the lateral faces have heights of 5 centimeters. After he finishes, he realizes that the paperweight is too small and decides to make another one. To make the second pyramid, he doubles the length of the base in the first pyramid.<br \/>\nFor numbers 5a\u20135c, choose Yes or No to indicate whether the statement is correct.<br \/>\n5a. The surface area of the second pyramid is 144 cm<sup>2<\/sup>.<br \/>\n5b. The surface area doubled from the first pyramid to the second pyramid.<br \/>\n5c. The lateral area doubled from the first pyramid to the second pyramid.<br \/>\n5a. ___________<br \/>\n5b. ___________<br \/>\n5c. ___________<\/p>\n<p>Answer:<br \/>\n5a. True.<br \/>\n5b. False<br \/>\n5c. True.<\/p>\n<p>Explanation:<br \/>\nThe area of the base is 4\u00d74= 16 cm<sup>2<\/sup>.<br \/>\nThe area of one face is 1\/2\u00d74\u00d75<br \/>\n= 2\u00d75<br \/>\n= 10 cm<sup>2<\/sup>.<br \/>\nThe surface area of the First pyramid is 16+ 4\u00d710<br \/>\n= 16+40<br \/>\n= 56 cm<sup>2<\/sup>.<br \/>\nThe area of the base is 8\u00d78= 64<br \/>\nThe area of one face is 1\/2\u00d78\u00d75<br \/>\n= 4\u00d75<br \/>\n= 20 cm<sup>2<\/sup>.<br \/>\nThe surface area od the second pyramid is 64+ 4\u00d720<br \/>\n= 64+80<br \/>\n= 144 cm<sup>2<\/sup>.<\/p>\n<p>Question 6.<br \/>\nIdentify the figure shown and find its surface area. Explain how you found your answer.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-76.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 76\" width=\"193\" height=\"178\" \/><\/p>\n<p>Answer: 369 in<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of the base is 9\u00d79= 81 in<sup>2<\/sup><br \/>\nThe area of one face is 1\/\/2 \u00d7 16\u00d7 9<br \/>\n= 8\u00d79<br \/>\n= 72 in<sup>2<\/sup><br \/>\nThe surface area of a square pyramid is 81+ 4\u00d7 72<br \/>\n= 81+ 288<br \/>\n= 369 in<sup>2<\/sup><\/p>\n<p>Question 7.<br \/>\nDominique has a box of sewing buttons that is in the shape of a rectangular prism.<br \/>\nThe volume of the box is 2 \\(\\frac{1}{2}\\) in. \u00d7 3 \\(\\frac{1}{2}\\) in. \u00d7 _____ = _____.<\/p>\n<p>Answer: 17.5 in<sup>3<\/sup><\/p>\n<p>Explanation: The volume of the box is 2 1\/2 \u00d7 3 1\/2 \u00d7 2<br \/>\n= 5\/2 \u00d7 7\/2 \u00d7 2<br \/>\n= 5\/2 \u00d7 7<br \/>\n= 35\/2<br \/>\n= 17.5 in<sup>3<\/sup><\/p>\n<h3><a id=\"Page_No_643\"><\/a>Page No. 643<\/h3>\n<p>Question 8.<br \/>\nEmily has a decorative box that is shaped like a cube with a height of 5 inches. What is the surface area of the box?<br \/>\n_______ in.<sup>2<\/sup><\/p>\n<p>Answer: 150 in.<sup>2<\/sup><\/p>\n<p>Explanation: Surface area of the box is 6 a<sup>2<\/sup><br \/>\nSo 6 \u00d7 5<sup>2<\/sup><br \/>\n= 6\u00d75\u00d75<sup>2<\/sup><br \/>\n= 150 in.<sup>2<\/sup><\/p>\n<p>Question 9.<br \/>\nAlbert recently purchased a fish tank for his home. Match each question with the geometric measure that would be most appropriate for each scenario.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-77.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 77\" width=\"737\" height=\"443\" \/><\/p>\n<p>Answer:<br \/>\n<img loading=\"lazy\" class=\"alignnone wp-image-7090\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-135-300x180.png\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume\" width=\"467\" height=\"281\" srcset=\"https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-135-300x180.png 300w, https:\/\/bigideasmathanswers.com\/wp-content\/uploads\/2020\/08\/Screenshot-135.png 638w\" sizes=\"(max-width: 467px) 100vw, 467px\" \/><\/p>\n<p>Question 10.<br \/>\nSelect the expressions that show the volume of the rectangular prism. Mark all that apply.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-78.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 78\" width=\"212\" height=\"185\" \/>Options:<br \/>\na. 2(2 units \u00d7 2 \\(\\frac{1}{2 }\\) units) + 2(2 units \u00d7 \\(\\frac{1}{2}\\) unit) + 2(\\(\\frac{1}{2}\\) unit \u00d7 2 \\(\\frac{1}{2}\\) units)<br \/>\nb. 2(2 units \u00d7 \\(\\frac{1}{2}\\) unit) + 4(2 units \u00d7 2 \\(\\frac{1}{2}\\) units)<br \/>\nc. 2 units \u00d7 \\(\\frac{1}{2}\\) unit \u00d7 2 \\(\\frac{1}{2}\\) units<br \/>\nd. 2.5 cubic units<\/p>\n<p>Answer: c, d<\/p>\n<p>Explanation: 2 units \u00d71\/2 unit \u00d7 2 1\/2 units and 2.5 cubic units<\/p>\n<h3><a id=\"Page_No_644\"><\/a>Page No. 644<\/h3>\n<p>Question 11.<br \/>\nFor numbers 11a\u201311d, select True or False for the statement.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-79.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 79\" width=\"378\" height=\"235\" \/><br \/>\n11a. The area of face A is 8 square units.<br \/>\n11b. The area of face B is 10 square units.<br \/>\n11c. The area of face C is 8 square units.<br \/>\n11d. The surface area of the prism is 56 square units.<br \/>\n11a. ___________<br \/>\n11b. ___________<br \/>\n11c. ___________<br \/>\n11d. ___________<\/p>\n<p>Answer:<br \/>\n11a. True.<br \/>\n11b. True.<br \/>\n11c. False.<br \/>\n11d. False.<\/p>\n<p>Explanation:<br \/>\nThe area of the face A is 4\u00d72= 8 square units<br \/>\nThe area of the face B is 5\u00d72= 10 square units<br \/>\nThe area of the face C is 5\u00d74= 20 square units<br \/>\nSo the surface area is 2\u00d78+2\u00d710+2\u00d720<br \/>\n= 16+20+40<br \/>\n= 76 square units<\/p>\n<p>Question 12.<br \/>\nStella received a package in the shape of a rectangular prism. The box has a length of 2 \\(\\frac{1}{2}\\) feet, a width of 1 \\(\\frac{1}{2}\\) feet, and a height of 4 feet.<br \/>\nPart A<br \/>\nStella wants to cover the box with wrapping paper. How much paper will she need? Explain how you found your answer<\/p>\n<p>Answer: 39.5 ft<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of two lateral faces is 4 \u00d7 2 1\/2<br \/>\n= 4 \u00d7 5\/2<br \/>\n= 2\u00d75<br \/>\n= 10 ft<sup>2<\/sup><br \/>\nThe area of another two lateral faces is 4 \u00d7 1 1\/2<br \/>\n= 4 \u00d7 3\/2<br \/>\n= 2\u00d73<br \/>\n= 6 ft<sup>2<\/sup><br \/>\nThe area of the top and bottom is 2 1\/2 \u00d7 1 1\/2<br \/>\n= 5\/2 \u00d7 3\/2<br \/>\n= 15\/4<br \/>\n= 3 3\/4 ft<sup>2<\/sup><br \/>\nSo Stella need 2\u00d710+ 2\u00d76 + 2 \u00d7 15\/4<br \/>\n= 20+ 12+15\/2<br \/>\n= 20+12+7.5<br \/>\n= 39.5 ft<sup>2<\/sup><\/p>\n<p>Question 12.<br \/>\nPart B<br \/>\nCan the box hold 16 cubic feet of packing peanuts? Explain how you know<\/p>\n<p>Answer: The box cannot hold 16 cubic feet of the packing peanuts<\/p>\n<p>Explanation: Volume = LWH<br \/>\n= 2 1\/2 \u00d71 1\/2 \u00d7 4<br \/>\n= 5\/2 \u00d7 3\/2 \u00d74<br \/>\n= 5\u00d73<br \/>\n= 15 ft<sup>3<br \/>\n<\/sup>So the box cannot hold 16 cubic feet of the packing peanuts.<\/p>\n<h3><a id=\"Page_No_645\"><\/a>Page No. 645<\/h3>\n<p>Question 13.<br \/>\nA box measures 6 units by \\(\\frac{1}{2}\\) unit by 2 \\(\\frac{1}{2}\\) units.<br \/>\nFor numbers 13a\u201313b, select True or False for the statement.<br \/>\n13a. The greatest number of cubes with a side length of \\(\\frac{1}{2}\\) unit that can be packed inside the box is 60.<br \/>\n13b. The volume of the box is 7 \\(\\frac{1}{2}\\) cubic units.<br \/>\n13a. ___________<br \/>\n13b. ___________<\/p>\n<p>Answer:<br \/>\n13a. True<br \/>\n13b. True.<\/p>\n<p>Explanation:<br \/>\nLength is 12 \u00d7 1\/2= 6 units<br \/>\nWidth is 1\u00d7 1\/2= 1\/2 units<br \/>\nHeight is 5\u00d7 1\/2= 5\/2 units<br \/>\nSo, the greatest number of cubes with a side length of 1\/2 unit that can be packed inside the box is 12\u00d71\u00d75= 60<br \/>\nThe volume of the cube is S<sup>3<br \/>\n<\/sup>The volume of a cube with S= (1\/2)<sup>3<br \/>\n<\/sup>= 1\/2\u00d71\/2\u00d71\/2<br \/>\n= 1\/8<br \/>\n= 0.125 cubic units<br \/>\nAs there are 60 cubes so 60\u00d70.125= 7.5cubic units.<\/p>\n<p>Question 14.<br \/>\nBella says the lateral area of the square pyramid is 1,224 in.<sup>2<\/sup>. Do you agree or disagree with Bella? Use numbers and words to support your answer. If you disagree with Bella, find the correct answer.<\/p>\n<p>Answer: 900 in<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nArea= 4\u00d7 1\/2 bh<br \/>\n= 4\u00d7 1\/2 \u00d7 18 \u00d7 25<br \/>\n= 2\u00d7 18 \u00d7 25<br \/>\n=\u00a0 900 in<sup>2<\/sup><br \/>\nSo lateral area is 900 in<sup>2<\/sup>, so I disagree<\/p>\n<p>Question 15.<br \/>\nLourdes is decorating a toy box for her sister. She will use self-adhesive paper to cover all of the exterior sides except for the bottom of the box. The toy box is 4 feet long, 3 feet wide, and 2 feet high. How many square feet of adhesive paper will Lourdes use to cover the box?<br \/>\n_______ ft<sup>2<\/sup><\/p>\n<p>Answer: 40 ft<sup>2<\/sup><\/p>\n<p>Explanation:<br \/>\nThe area of two lateral faces is 4\u00d72= 8 ft<sup>2<\/sup><br \/>\nThe area of another two lateral faces is 3\u00d72= 6 ft<sup>2<\/sup><br \/>\nThe area of the top and bottom is 4\u00d73= 12 ft<sup>2<\/sup><br \/>\nSo Lourdes uses to cover the box is 2\u00d78 + 2\u00d76 + 12<br \/>\n= 16+12+12<br \/>\n= 40 ft<sup>2<\/sup><\/p>\n<p>Question 16.<br \/>\nGary wants to build a shed shaped like a rectangular prism in his backyard. He goes to the store and looks at several different options. The table shows the dimensions and volumes of four different sheds. Use the formula V = l \u00d7 w \u00d7 h to complete the table.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-80.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 80\" width=\"609\" height=\"249\" \/><\/p>\n<p>Answer:<br \/>\nLength of shed 1= 12 ft<br \/>\nWidth of shed 2= 12 ft<br \/>\nHeight of shed 3= 6 ft<br \/>\nVolume of shed 4= 1200 ft<sup>3<\/sup><\/p>\n<p>Explanation: Volume= LWH<br \/>\nVolume of shed1= 960 ft<br \/>\nSo 960= L\u00d710\u00d78<br \/>\n960= 80\u00d7L<br \/>\nL= 960\/80<br \/>\nL= 12 ft<br \/>\nVolume of shed2= 2160 ft<br \/>\nSo 2160= 18\u00d7W\u00d710<br \/>\n960= 180\u00d7W<br \/>\nW= 2160\/180<br \/>\nW= 12 ft<br \/>\nVolume of shed3= 288 ft<br \/>\nSo 288= 12\u00d74\u00d7H<br \/>\n288= 48\u00d7H<br \/>\nH= 288\/48<br \/>\nW= 6 ft<br \/>\nVolume of shed2= 10\u00d712\u00d710<br \/>\nSo V= 10\u00d712\u00d710<br \/>\nV= 1200 ft<sup>3<\/sup><\/p>\n<h3><a id=\"Page_No_646\"><\/a>Page No. 646<\/h3>\n<p>Question 17.<br \/>\nTina cut open a cube-shaped microwave box to see the net. How many square faces does this box have?<br \/>\n_______ square faces<\/p>\n<p>Answer: The box has 6 square faces.<\/p>\n<p>Question 18.<br \/>\nCharles is painting a treasure box in the shape of a rectangular prism.<br \/>\nWhich nets can be used to represent Charles\u2019 treasure box? Mark all that apply.<br \/>\nOptions:<br \/>\na. <img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-81.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 81\" width=\"170\" height=\"214\" \/><br \/>\nb. <img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-82.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 82\" width=\"330\" height=\"135\" \/><br \/>\nc. <img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-83.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 83\" width=\"335\" height=\"99\" \/><br \/>\nd. <img loading=\"lazy\" src=\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2020\/08\/Go-Math-Grade-6-Answer-Key-Chapter-11-Surface-Area-and-Volume-img-84.jpg\" alt=\"Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume img 84\" width=\"133\" height=\"331\" \/><\/p>\n<p>Answer: a and b can be used to represent Charle&#8217;s treasure box.<\/p>\n<p>Question 19.<br \/>\nJulianna is lining the inside of a basket with fabric. The basket is in the shape of a rectangular prism that is 29 cm long, 19 cm wide, and 10 cm high. How much fabric is needed to line the inside of the basket if the basket does not have a top? Explain your strategy.<br \/>\n_______ cm<sup>2<\/sup><\/p>\n<p>Answer: 1511 cm<sup>2<\/sup><\/p>\n<p>Explanation: The surface area= 2(WL+HL+HW)<br \/>\nThe surface area of the entire basket= 2(19\u00d729)+2(10\u00d729)+2(10\u00d719)<br \/>\n= 2(551)+2(290)+2(190)<br \/>\n= 1102+580+380<br \/>\n= 2,062 cm<sup>2<\/sup><br \/>\nThe surface area of the top is 29\u00d719= 551<br \/>\nSo Julianna needs 2062-551= 1511 cm<sup>2<\/sup><\/p>\n<p><em>Conclusion<\/em><\/p>\n<p>Click on the related links and begin your preparation. Make your preparation perfect by practicing the problems a number of times. We wish the info provided in the Go Math 6th Standard Answer Key Chapter 11 Surface Area and Volume is satisfactory for all of you. Keep in touch with us to get the latest updates regarding the HMH Go Math Grade 6 Answer Key.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Go Math solutions for Class 6 Maths Provide detailed explanations for all the questions provided in the HMH Go Math. We provide topic wise Go Math Grade 6 Answer Key Chapter 11 Surface Area and Volume to help the students clear their doubts by offering an understanding of concepts in depth. 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