{"id":56320,"date":"2021-03-03T11:22:14","date_gmt":"2021-03-03T05:52:14","guid":{"rendered":"https:\/\/ccssmathanswers.com\/?p=56320"},"modified":"2022-04-01T10:28:06","modified_gmt":"2022-04-01T04:58:06","slug":"eureka-math-grade-3-module-7-lesson-24","status":"publish","type":"post","link":"https:\/\/bigideasmathanswers.com\/eureka-math-grade-3-module-7-lesson-24\/","title":{"rendered":"Eureka Math Grade 3 Module 7 Lesson 24 Answer Key"},"content":{"rendered":"

Engage NY Eureka Math 3rd Grade Module 7 Lesson 24 Answer Key<\/h2>\n

Eureka Math Grade 3 Module 7 Lesson 24 Pattern Sheet Answer Key<\/h3>\n

Multiply.
\n\"Engage
\nmultiply by 6 (6\u201310)
\nAnswer:
\n\"Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka
\nExplanation:
\n6 \u00d7 6 = 36
\n6 \u00d7 7 = 42
\n6 \u00d7 8 = 48
\n6 \u00d7 9 = 54
\n6 \u00d7 10 = 60.<\/p>\n

Eureka Math Grade 3 Module 7 Lesson 24 Problem Set Answer Key<\/h3>\n

Use the given perimeters in the chart below to choose the widths and lengths of your robot\u2019s rectangular body parts. Write the widths and lengths in the chart below. Use the blank rows if you want to add extra rectangular body parts to your robot.<\/p>\n\n\n\n\n\n\n\n\n\n\n\n\n\n
\n

Letter<\/strong><\/p>\n<\/td>\n

Body Part<\/strong><\/td>\nPerimeter<\/strong><\/td>\n\n

Width and Length<\/strong><\/p>\n<\/td>\n<\/tr>\n

A<\/td>\narm<\/td>\n14 cm<\/td>\n__________ cm by __________cm<\/td>\n<\/tr>\n
B<\/td>\narm<\/td>\n14 cm<\/td>\n__________ cm by __________cm<\/td>\n<\/tr>\n
C<\/td>\nleg<\/td>\n18 cm<\/td>\n__________ cm by __________cm<\/td>\n<\/tr>\n
D<\/td>\nleg<\/td>\n18 cm<\/td>\n__________ cm by __________cm<\/td>\n<\/tr>\n
E<\/td>\nbody<\/td>\nDouble the perimeter of one arm = _______ cm<\/td>\n__________ cm by __________cm<\/td>\n<\/tr>\n
F<\/td>\nhead<\/td>\n16 cm<\/td>\n__________ cm by __________cm<\/td>\n<\/tr>\n
G<\/td>\nneck<\/td>\nHalf the perimeter of the head =<\/p>\n

_______ cm<\/td>\n

__________ cm by __________cm<\/td>\n<\/tr>\n
H<\/td>\n<\/td>\n<\/td>\n__________ cm by __________cm<\/td>\n<\/tr>\n
I<\/td>\n<\/td>\n<\/td>\n__________ cm by __________cm<\/td>\n<\/tr>\n
My robot has 7 to 9 rectangular body parts.\u00a0 Number of body parts: \u00a0_______<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Answer:
\n\"Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka \"Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka<\/p>\n

Use the information in the chart below to plan an environment for your robot. Write the width and length for each rectangular item. Use the blank rows if you want to add extra circular or rectangular items to your robot\u2019s environment.<\/p>\n\n\n\n\n\n\n\n\n\n\n\n\n
Letter<\/strong><\/td>\nItem<\/strong><\/td>\nShape<\/strong><\/td>\nPerimeter<\/strong><\/td>\n\n

Width and Length<\/strong><\/p>\n<\/td>\n<\/tr>\n

J<\/td>\nsun<\/td>\ncircle<\/td>\nabout 25 cm<\/td>\n<\/td>\n<\/tr>\n
K<\/td>\nhouse<\/td>\nrectangle<\/td>\n82 cm<\/td>\n__________ cm by __________cm<\/td>\n<\/tr>\n
L<\/td>\ntree top<\/td>\ncircle<\/td>\nabout 30 cm<\/td>\n<\/td>\n<\/tr>\n
M<\/td>\ntree trunk<\/td>\nrectangle<\/td>\n30 cm<\/td>\n__________ cm by __________cm<\/td>\n<\/tr>\n
N<\/td>\ntree top<\/td>\ncircle<\/td>\nabout 20 cm<\/td>\n<\/td>\n<\/tr>\n
O<\/td>\ntree trunk<\/td>\nrectangle<\/td>\n20 cm<\/td>\n__________ cm by __________cm<\/td>\n<\/tr>\n
P<\/td>\n<\/td>\n<\/td>\n<\/td>\n<\/td>\n<\/tr>\n
Q<\/td>\n<\/td>\n<\/td>\n<\/td>\n<\/td>\n<\/tr>\n
My robot\u2019s environment has 6 to 8 items.\u00a0 Number of items: \u00a0_______<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Answer:
\n\"Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka<\/p>\n

Eureka Math Grade 3 Module 7 Lesson 24 Exit Ticket Answer Key<\/h3>\n

Estimate to draw three different rectangles with a perimeter of 16 centimeters. Label the width and length of each rectangle.
\nAnswer:
\n\"Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka<\/p>\n

Explanation:
\nUsing the Perimeter of 16 cm we can draw three rectangles ABCD, EFGH, IJKL with different lengths and width.<\/p>\n

 <\/p>\n

Eureka Math Grade 3 Module 7 Lesson 24 Homework Answer Key<\/h3>\n

Question 1.
\nBrian draws a square with a perimeter of 24 inches. What is the length of the side of the square?
\nAnswer:
\nLength of the side of the square = 6 inches.<\/p>\n

Explanation:
\nPerimeter of the Square = 24 inches
\nNumber of sides in the square = 4
\nLength of the side of the square = Perimeter of the Square\u00a0 \u00f7 Number of sides in the square
\n= 24 inches \u00f7 4
\n= 6 inches.<\/p>\n

Question 2.
\nA rectangle has a perimeter of 18 centimeters.
\na. Estimate to draw as many different rectangles as you can that have a perimeter of 18 centimeters. Label the width and length of each rectangle.
\nb. How many different rectangles did you find?
\nc. Explain the strategy you used to find the rectangles.
\nAnswer:
\na. \"Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka<\/p>\n

b. I could find three different rectangles having perimeter as 18 centimeters.<\/p>\n

c. The strategy which I used to find the rectangles is that :
\nStep 1:\u00a0 Considered the Perimeter formula 2 ( Length + Width ) and its perimeter value 18 centimeters.
\nStep 2: Calculated the Length and width values.
\nStep 3: Keeping in mind highest value as length and lesser as Width.<\/p>\n

Explanation:
\na. \"Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka
\nb. I could find three different rectangles having perimeter as 18 centimeters.
\nc. The strategy which I used to find the rectangles is that :
\nStep 1:\u00a0 Considered the Perimeter formula 2 ( Length + Width ) and its perimeter value 18 centimeters.
\nStep 2: Calculated the Length and width values.
\nStep 3: Keeping in mind highest value as length and lesser as Width.<\/p>\n

 <\/p>\n

Question 3.
\nThe chart below shows the perimeters of three rectangles.
\na. Write possible widths and lengths for each given perimeter.<\/p>\n\n\n\n\n\n\n
Rectangle<\/strong><\/td>\nPerimeter<\/strong><\/td>\n\n

Width and Length<\/strong><\/p>\n<\/td>\n<\/tr>\n

A<\/td>\n6 cm<\/td>\n__________ cm by __________ cm<\/td>\n<\/tr>\n
B<\/td>\n10 cm<\/td>\n__________ cm by __________ cm<\/td>\n<\/tr>\n
C<\/td>\n14 cm<\/td>\n__________ cm by __________ cm<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

b. Double the perimeters of the rectangles in part (a). Then, find possible widths and lengths.<\/p>\n\n\n\n\n\n\n
Rectangle<\/strong><\/td>\nPerimeter<\/strong><\/td>\n\n

Width and Length<\/strong><\/p>\n<\/td>\n<\/tr>\n

A<\/td>\n12 cm<\/td>\n__________ cm by __________ cm<\/td>\n<\/tr>\n
B<\/td>\n<\/td>\n__________ cm by __________ cm<\/td>\n<\/tr>\n
C<\/td>\n<\/td>\n__________ cm by __________ cm<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Answer:
\na. \"Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka
\nb. \"Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka
\nExplanation:
\na. For the perimeter of 6cm, we have a rectangle length as 2cm and width as 1cm.
\nFor the perimeter of 10cm, we have a rectangle length as 2cm and width as 3cm.
\nFor the perimeter of 14cm, we have a rectangle length as 3cm and width as 4cm.<\/p>\n

b. For the perimeter of 12cm, we have a rectangle length as 2cm and width as 4cm.<\/p>\n

 <\/p>\n","protected":false},"excerpt":{"rendered":"

Engage NY Eureka Math 3rd Grade Module 7 Lesson 24 Answer Key Eureka Math Grade 3 Module 7 Lesson 24 Pattern Sheet Answer Key Multiply. multiply by 6 (6\u201310) Answer: Explanation: 6 \u00d7 6 = 36 6 \u00d7 7 = 42 6 \u00d7 8 = 48 6 \u00d7 9 = 54 6 \u00d7 10 = … Read more<\/a><\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[6],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts\/56320"}],"collection":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/users\/9"}],"replies":[{"embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/comments?post=56320"}],"version-history":[{"count":1,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts\/56320\/revisions"}],"predecessor-version":[{"id":92422,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts\/56320\/revisions\/92422"}],"wp:attachment":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/media?parent=56320"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/categories?post=56320"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/tags?post=56320"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}