{"id":59659,"date":"2021-03-23T16:34:36","date_gmt":"2021-03-23T11:04:36","guid":{"rendered":"https:\/\/ccssmathanswers.com\/?p=59659"},"modified":"2022-04-01T10:27:42","modified_gmt":"2022-04-01T04:57:42","slug":"eureka-math-grade-4-module-2-lesson-5","status":"publish","type":"post","link":"https:\/\/bigideasmathanswers.com\/eureka-math-grade-4-module-2-lesson-5\/","title":{"rendered":"Eureka Math Grade 4 Module 2 Lesson 5 Answer Key"},"content":{"rendered":"

7Engage NY Eureka Math 4th Grade Module 2 Lesson 5 Answer Key<\/h2>\n

Eureka Math Grade 4 Module 2 Lesson 5 Sprint Answer Key<\/h3>\n

A
\nConvert to Kilograms and Grams
\n\"Eureka
\n\"Eureka<\/p>\n

\"Eureka
\n\"Eureka<\/p>\n

Question 1.
\n2,000 g = 2 kg 0 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 2,000 g = 2 X 1000 g \u00f7 1000 = 2 kg 0 g.<\/p>\n

Question 2.
\n3,000 g = 3 kg 0 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 3,000 g = 3 X 1000 g \u00f7 1000 = 3 kg 0 g.<\/p>\n

Question 3.
\n4,000 g = 4 kg 0 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 4,000 g = 4 X 1000 g \u00f7 1000 = 4 kg 0 g.<\/p>\n

Question 4.
\n9,000 g = 9 kg 0 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 9,000 g = 9 X 1000 g \u00f7 1000 = 9 kg 0 g.<\/p>\n

Question 5.
\n6,000 g = 6 kg 0 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 6,000 g = 6 X 1000 g \u00f7 1000 = 6 kg 0 g.<\/p>\n

Question 6.
\n1,000 g = 1 kg 0 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 1,000 g = 1 X 1000 g \u00f7 1000 = 1 kg 0 g.<\/p>\n

Question 7.
\n8,000 g = 8 kg 0 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 8,000 g = 8 X 1000 g \u00f7 1000 = 8 kg 0 g.<\/p>\n

Question 8.
\n5,000 g = 5 kg 0 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 5,000 g = 5 X 1000 g \u00f7 1000 = 5 kg 0 g.<\/p>\n

Question 9.
\n7,000 g = 7 kg 0 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 7,000 g = 7 X 1000 g \u00f7 1000 = 7 kg 0 g.<\/p>\n

Question 10.
\n6,100 g = 6 kg 100 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 6,100 g = 6,100 g \u00f7 1000 = 6 kg 100 g.<\/p>\n

Question 11.
\n6,110 g = 6 kg 110 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 6,110 g = 6 ,110 g \u00f7 1000 = 6 kg 110 g.<\/p>\n

Question 12.
\n6,101 g = 6 kg 101 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 6,101 g = 6,101 g \u00f7 1000 = 6 kg 101 g.<\/p>\n

Question 13.
\n6,010 g = 6 kg 10 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 6,010 g = 6,010 g \u00f7 1000 = 6 kg 10 g.<\/p>\n

Question 14.
\n6,011 g = 6 kg 11 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 6,011 g = 6,011 g \u00f7 1000 = 6 kg 11 g.<\/p>\n

Question 15.
\n6,001 g = 6 kg 1 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 6,001 g = 6,001 g \u00f7 1000 = 6 kg 1 g.<\/p>\n

Question 16.
\n8,002 g = 8 kg 2 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 8,002 g = 8,002 g \u00f7 1000 = 8 kg 2 g.<\/p>\n

Question 17.
\n8,020 g = 8 kg 20 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 8,002 g = 8,002 g \u00f7 1000 = 8 kg 2 g.<\/p>\n

Question 18.
\n8,200 g = 8 kg 200 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 8,200 g = 8,200 g \u00f7 1000 = 8 kg 200 g.<\/p>\n

Question 19.
\n8,022 g = 8 kg 22 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 8,022 g = 8,022 g \u00f7 1000 = 8 kg 22 g.<\/p>\n

Question 20.
\n8,220 g = 8 kg\u00a0 220 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 8,220 g = 8,220 g \u00f7 1000 = 8 kg 220 g.<\/p>\n

Question 21.
\n8,222 g = 8 kg 222 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 8,222 g = 8,222 g \u00f7 1000 = 8 kg 222 g.<\/p>\n

Question 22.
\n7,256 g = 7 kg 256 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 7,256 g = 7,256 g \u00f7 1000 = 7 kg 256 g.<\/p>\n

Question 23.
\n3,800 g = 3 kg 800 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 3,800 g = 3,800 g \u00f7 1000 = 3 kg 800 g.<\/p>\n

Question 24.
\n4,770 g = 4 kg 770 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 4,770 g = 4,770 g \u00f7 1000 = 4 kg 770 g.<\/p>\n

Question 25.
\n4,807 g = 4 kg 807 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 4,807 g = 4,807 g \u00f7 1000 = 4 kg 807 g.<\/p>\n

Question 26.
\n5,065 g = 5 kg 065 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 5,065 g = 5,065 g \u00f7 1000 = 5 kg 065 g.<\/p>\n

Question 27.
\n5,040 g = 5 kg 40 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 5,040 g = 5,040 g \u00f7 1000 = 5 kg 40 g.<\/p>\n

Question 28.
\n6,007 g = 6 kg 7 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 6,007 g = 6,007 g \u00f7 1000 = 6 kg 7 g.<\/p>\n

Question 29.
\n2,003 g = 2 kg 3 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 2,003 g = 2,003 g \u00f7 1000 = 2 kg 3 g.<\/p>\n

Question 30.
\n1,090 g = 1 kg 90 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 1,090 g = 1,090 g \u00f7 1000 = 1 kg 90 g.<\/p>\n

Question 31.
\n1,055 g = 1 kg 55 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 1,055 g = 1,055 g \u00f7 1000 = 1 kg 55 g.<\/p>\n

Question 32.
\n9,404 g = 9 kg 404 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 9,404 g = 9,404 g \u00f7 1000 = 9 kg 404 g.<\/p>\n

Question 33.
\n9,330 g = 9 kg 330 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo 9,330 g = 9,330 g \u00f7 1000 = 9 kg 330 g.<\/p>\n

Question 34.
\n3,400 g = 3 kg 400 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 3,400 g = 3,400 g \u00f7 1000 = 3 kg 400 g.<\/p>\n

Question 35.
\n4,000 g + 2,000 g = 6 kg 0 g,<\/p>\n

Explanation:
\nGiven 4,000 g + 2,000 g = 6,000 g
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo 4,000 g + 2,000 g = 6,000 g = 6,000 g \u00f7 1000 = 6 kg 0 g.<\/p>\n

Question 36.
\n5,000 g + 3,000 g = 8 kg 0 g,<\/p>\n

Explanation:
\nGiven 5,000 g + 3,000 g = 8,000 g
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo 5,000 g + 3,000 g = 8,000 g = 8,000 g \u00f7 1000 = 8 kg 0 g.<\/p>\n

Question 37.
\n4,000 g + 4,000 g = 8 kg 0 g,<\/p>\n

Explanation:
\nGiven 4,000 g + 4,000 g = 8,000 g
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 4,000 g + 4,000 g = 8,000 g = 8,000 g \u00f7 1000 = 8 kg 0 g.<\/p>\n

Question 38.
\n8 \u00d7 7,000 g = 56 kg 0 g,<\/p>\n

Explanation:
\nGiven 8 X 7,000 g = 56,000 g
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo 8 \u00d7 7,000 g = 56,000 g = 56,000 g \u00f7 1000 = 56 kg 0 g.<\/p>\n

Question 39.
\n49,000 g \u00f7 7 = 7 kg 0 g,<\/p>\n

Explanation:
\nGiven 49,000 g \u00f7 7 = 7,000 g
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo 49,000 g \u00f7 7 = 7,000 g = 7,000 g \u00f7 1000 = 7 kg 0 g.<\/p>\n

Question 40.
\n16,000 g \u00d7 5 = 80 kg 0 g,<\/p>\n

Explanation:
\nGiven 16,000 g X 5 = 80,000 g
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo 16,000 g X 5 = 80,000 g = 80,000 g \u00f7 1000 = 80 kg 0 g.<\/p>\n

Question 41.
\n63,000 g \u00f7 7 = 9 kg 0 g,<\/p>\n

Explanation:
\nGiven 63,000 g \u00f7 7 = 9,000 g
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo 63,000 g \u00f7 7 = 9,000 g = 9,000 g \u00f7 1000 = 9 kg 0 g.<\/p>\n

Question 42.
\n17 \u00d7 4,000 g = 68 kg 0 g,<\/p>\n

Explanation:
\nGiven 17 X 4,000 g\u00a0 = 68,000 g
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo 17 X 4,000 g = 68,000 g = 68,000 g \u00f7 1000 = 68 kg 0 g.<\/p>\n

Question 43.
\n13,000 g \u00d7 5 = 65 kg 0 g,<\/p>\n

Explanation:
\nGiven 13,000 g X 5 = 65,000 g
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo 13,000 g X 5 = 65,000 g = 65,000 g \u00f7 1000 = 65 kg 0 g.<\/p>\n

Question 44.
\n84,000 g \u00f7 7 = 12 kg 0 g,<\/p>\n

Explanation:
\nGiven 84,000 g \u00f7 7 = 12,000 g
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo 84,000 g \u00f7 7 = 12,000 g = 12,000 g \u00f7 1000 = 12 kg 0 g.<\/p>\n

B
\nConvert to Kilograms and Grams
\n\"Eureka
\n\"Eureka<\/p>\n

\"Eureka
\n\"Eureka
\nQuestion 1.
\n1,000 g = 1 kg 0 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 1,000 g = 1 X 1000 g \u00f7 1000 = 1 kg 0 g.<\/p>\n

Question 2.
\n2,000 g = 2 kg 0 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 2,000 g = 2 X 1000 g \u00f7 1000 = 2 kg 0 g.<\/p>\n

Question 3.
\n3,000 g = 3 kg 0 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 3,000 g = 3 X 1000 g \u00f7 1000 = 3 kg 0 g.<\/p>\n

Question 4.
\n8,000 g = 8 kg 0 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 8,000 g = 8 X 1000 g \u00f7 1000 = 8 kg 0 g.<\/p>\n

Question 5.
\n6,000 g = 6 kg 0 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 6,000 g = 6 X 1000 g \u00f7 1000 = 6 kg 0 g.<\/p>\n

Question 6.
\n9,000 g = 9 kg 0 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 9,000 g = 9 X 1000 g \u00f7 1000 = 9 kg 0 g.<\/p>\n

Question 7.
\n4,000 g = 4 kg 0 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 4,000 g = 4 X 1000 g \u00f7 1000 = 4 kg 0 g.<\/p>\n

Question 8.
\n7,000 g = 7 kg 0 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 7,000 g = 7 X 1000 g \u00f7 1000 = 7 kg 0 g.<\/p>\n

Question 9.
\n5,000 g = 5 kg 0 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 5,000 g = 5 X 1000 g \u00f7 1000 = 5 kg 0 g.<\/p>\n

Question 10.
\n5,100 g = 5 kg 100 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 5,100 g = 5,100 g \u00f7 1000 = 5 kg 100 g.<\/p>\n

Question 11.
\n5,110 g = 5 kg 110 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 5,110 g = 5 ,110 g \u00f7 1000 = 5 kg 110 g.<\/p>\n

Question 12.
\n5,101 g = 5 kg 101 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 5,101 g = 5,101 g \u00f7 1000 = 5 kg 101 g.<\/p>\n

Question 13.
\n5,010 g = 5 kg 10 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 5,010 g = 5,010 g \u00f7 1000 = 5 kg 10 g.<\/p>\n

Question 14.
\n5,011 g = 5 kg 11 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 5,011 g = 5,011 g \u00f7 1000 = 5 kg 11 g.<\/p>\n

Question 15.
\n5,001 g = 5 kg 1 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 5,001 g = 5,001 g \u00f7 1000 = 5 kg 1 g.<\/p>\n

Question 16.
\n7,002 g = 7 kg 2 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 7,002 g = 7,002 g \u00f7 1000 = 7 kg 2 g.<\/p>\n

Question 17.
\n7,020 g = 7kg 20 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 7,020 g = 7,020 g \u00f7 1000 = 7 kg 20 g.<\/p>\n

Question 18.
\n7,200 g = 7 kg 200 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 7,200 g = 7,200 g \u00f7 1000 = 7 kg 200 g.<\/p>\n

Question 19.
\n7,022 g = 7 kg 22 g,
\n7,022 g = 7 kg 22 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 7,022 g = 7,022 g \u00f7 1000 = 7 kg 22 g.<\/p>\n

Question 20.
\n7,220 g = 7 kg 220 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 7,220 g = 7,220 g \u00f7 1000 = 7 kg 220 g.<\/p>\n

Question 21.
\n7,222 g = 7 kg 222 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 7,222 g = 7,222 g \u00f7 1000 = 7 kg 222 g.<\/p>\n

Question 22.
\n4,378 g = 4 kg 378 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 4,378 g = 4,378 g \u00f7 1000 = 4 kg 378 g.<\/p>\n

Question 23.
\n2,700 g = 2 kg 700 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 2,700 g = 2,700 g \u00f7 1000 = 2 kg 700 g.<\/p>\n

Question 24.
\n3,660 g = 3 kg 660 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 3,660 g = 3,660 g \u00f7 1000 = 3 kg 660 g.<\/p>\n

Question 25.
\n3,706 g = 3 kg 706 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 3,706 g = 3,706 g \u00f7 1000 = 3 kg 706 g.<\/p>\n

Question 26.
\n4,095 g = 4 kg 95 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 4,095 g = 4,095 g \u00f7 1000 = 4 kg 95 g.<\/p>\n

Question 27.
\n4,030 g = 4 kg 30 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 4,030 g = 4,030 g \u00f7 1000 = 4 kg 30 g.<\/p>\n

Question 28.
\n5,006 g = 5 kg 6 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 5,006 g = 5,006 g \u00f7 1000 = 5 kg 6 g.<\/p>\n

Question 29.
\n3,004 g = 3 kg 4 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 3,004 g = 3,004 g \u00f7 1000 = 3 kg 4 g.<\/p>\n

Question 30.
\n2,010 g = 2 kg 10 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 2,010 g = 2,010 g \u00f7 1000 = 2 kg 10 g.<\/p>\n

Question 31.
\n2,075 g = 2 kg 75 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 2,075 g = 2,075 g \u00f7 1000 = 2 kg 75 g.<\/p>\n

Question 32.
\n1,504 g = 1 kg 504 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 1,504 g = 1,504 g \u00f7 1000 = 1 kg 504 g.<\/p>\n

Question 33.
\n1,440 g = 1 kg 440 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 1,440 g = 1,440 g \u00f7 1000 = 1 kg 440 g.<\/p>\n

Question 34.
\n4,500 g = 4 kg 500 g,<\/p>\n

Explanation:
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 4,500 g = 4,500 g \u00f7 1000 = 4 kg 500 g.<\/p>\n

Question 35.
\n3,000 g + 2,000 g = 5 kg 0 g,<\/p>\n

Explanation:
\nGiven 3,000 g + 2,000 g = 5,000 g
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo\u00a0 3,000 g + 2,000 g = 5,000 g = 5,000 g \u00f7 1000 = 5 kg 0 g.<\/p>\n

Question 36.
\n4,000 g + 3,000 g = 7 kg 0 g,<\/p>\n

Explanation:
\nGiven 4,000 g + 3,000 g = 7,000 g
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo 4,000 g + 3,000 g = 7,000 g = 7,000 g \u00f7 1000 = 7 kg 0 g.<\/p>\n

Question 37.
\n5,000 g + 4,000 g = 9 kg 0 g,<\/p>\n

Explanation:
\nGiven 5,000 g + 4,000 g = 9,000 g
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo 5,000 g + 4,000 g = 9,000 g = 9,000 g \u00f7 1000 = 9 kg 0 g.<\/p>\n

Question 38.
\n9 \u00d7 8,000 g = 72 kg 0 g,<\/p>\n

Explanation:
\nGiven 9 X 8,000 g = 72,000 g
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo 9 \u00d7 8,000 g = 72,000 g = 72,000 g \u00f7 1000 = 72 kg 0 g.<\/p>\n

Question 39.
\n64,000 g \u00f7 8 = 8 kg 0 g,<\/p>\n

Explanation:
\nGiven 64,000 g \u00f7 8 = 8,000 g
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo 64,000 g \u00f7 8 = 8,000 g = 8,000 g \u00f7 1000 = 8 kg 0 g.<\/p>\n

Question 40.
\n17,000 g \u00d7 5 = 85 kg 0 g,<\/p>\n

Explanation:
\nGiven\u00a0 17,000 g X 5\u00a0 = 85,000 g
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo 17,000 g X 5 = 85,000 g = 85,000 g \u00f7 1000 = 85 kg 0 g.<\/p>\n

Question 41.
\n54,000 g \u00f7 6 = 9 kg 0 g,<\/p>\n

Explanation:
\nGiven 54,000 g \u00f7 6 = 9,000 g
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo 54,000 g \u00f7 6 = 9,000 g = 9,000 g \u00f7 1000 = 9 kg 0 g.<\/p>\n

Question 42.
\n18,000 g \u00d7 4 = 72 kg 0 g,<\/p>\n

Explanation:
\nGiven\u00a0 18,000 g X 4\u00a0 = 72,000 g
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo 18,000 g X 4 = 72,000 g = 72,000 g \u00f7 1000 = 72 kg 0 g.<\/p>\n

Question 43.
\n14 \u00d7 5,000 g = 70 kg 0 g,<\/p>\n

Explanation:
\nGiven\u00a0 14 X 5,000 g\u00a0 = 70,000 g
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo 14 X 5,000 g = 70,000 g = 70,000 g \u00f7 1000 = 70 kg 0 g.<\/p>\n

Question 44.
\n96,000 g \u00f7 8 = 12 kg 0 g,<\/p>\n

Explanation:
\nGiven 96,000 g \u00f7 8 = 12,000 g
\nConverted the conversion table as shown above as
\nWe know 1000 g or 103 <\/sup>\u00a0= 1 kg,
\nSo 96,000 g \u00f7 8 = 12,000 g = 12,000 g \u00f7 1000 = 12 kg 0 g.<\/p>\n

Eureka Math Grade 4 Module 2 Lesson 5 Problem Set Answer Key<\/h3>\n

Model each problem with a tape diagram.
\nSolve and answer with a statement.<\/p>\n

Question 1.
\nThe potatoes Beth bought weighed 3 kilograms 420 grams.
\nHer onions weighed 1,050 grams less than the potatoes.
\nHow much did the potatoes and onions weigh together?
\n\"Eureka
\nThe potatoes and onions wiegh together 5,790 g or 5 kg 790 g,
\n\"Eureka
\nStatement: Both the potatoes and onions wiegh together are
\nfive thousand seven hundred ninety grams or five kilograms and
\nseven hundred ninety grams,<\/p>\n

Explanation:
\nGiven the potatoes Beth bought weighed 3 kilograms 420 grams.
\nHer onions weighed 1,050 grams less than the potatoes.
\nSo onions wiegh is 3 kg 420 g – 1,050 g =
\n3 X 1000 g + 420 g = 3,420 g,
\nnow 3,420 g – 1,050 g = 2,370 g,
\nSo the potatoes and onions weigh together are
\n3,420 g + 2,370 g = 5,790 g or 5,790 \u00f7 1,000 = 5 kg 790 g,
\nTherefore, the potatoes and onions weigh together
\n5,790 g or 5 kg 790 g,
\nModeled\u00a0 problem with a tape diagram as shown above and
\nstatement is both the potatoes and onions wiegh together are
\nfive thousand seven hundred ninety grams or five kilograms and
\nseven hundred ninety grams.<\/p>\n

Question 2.
\nAdele let out 18 meters 46 centimeters of string to fly her kite.
\nShe then let out 13 meters 78 centimeters more before
\nreeling back in 590 centimeters. How long was her string
\nafter reeling it in?
\n\"Eureka
\nAdele string is 26,34 centimeters or 26 meters 34 centimeters long
\nafter reeling it in.
\n\"Eureka
\nStatement: Adele string is twenty six thousand thirty centimeters or
\ntwenty six meters and thirty centimeters long after reeling it in,<\/p>\n

Explanation:
\nGiven Adele let out 18 meters 46 centimeters of string to fly her kite.
\nShe then let out 13 meters 78 centimeters more before
\nreeling back in 590 centimeters. So Adele string length after
\nreeling it in is 18 m 46 cm + 13 m 78 cm – 590 cm =
\nas 18 m 46 cm = 18 x 100 cm + 46 cm = 18,00 cm + 46 cm =
\n18,46 cm and 13 m 78 cm = 13\u00a0 X 100 cm + 78 cm =
\n13,00 cm + 78 cm = 13,78 cm.
\nNow (18,46 cm + 13,78 cm) – 590 cm = 32,24 cm – 590 cm =
\n26,34 cm or\u00a0 26,34 cm \u00f7 100 = 26 m 34 cm,
\nTherefore, Adele string is 26,34 centimeters or
\n26 meters 34 centimeters long after reeling it in.
\nModeled\u00a0 problem with a tape diagram as shown above and
\nstatement is Adele string is twenty six thousand thirty centimeters or
\ntwenty six meters and thirty centimeters long after reeling it in.<\/p>\n

Question 3.
\nShyan\u2019s barrel contained 6 liters 775 milliliters of paint.
\nShe poured in 1 liter 118 milliliters more.
\nThe first day, Shyan used 2 liters 125 milliliters of the paint.
\nAt the end of the second day, there were 1,769 milliliters of paint remaining in the barrel.
\nHow much paint did Shyan use on the second day?<\/p>\n

On the second day Shyan uses 3,999 milliliters or
\n3 liters 999 milliliters of the paint,
\n\"Eureka
\nStatement : Shyan on the second day uses three thousand
\nnine hundred ninety nine milliliters or 3 liters and nine
\nhundred ninety nine milliliters of the paint,<\/p>\n

Explanation:
\nGiven Shyan\u2019s barrel contained 6 liters 775 milliliters of paint.
\nShe poured in 1 liter 118 milliliters more.
\nThe first day, Shyan used 2 liters 125 milliliters of the paint.
\nAt the end of the second day, there were 1,769 milliliters of paint remaining in the barrel. Total amount of the paint is
\n6 L 775 mL + 1 L 118 mL = 7 L 893 mL,
\nPaint left after first day is 7 L 893 mL – 2 L 125 mL =
\n7 L 893 mL = 7 X 1000 mL + 893 mL = 7,893 mL,
\n2 L 125 mL = 2 X 1000 mL + 125 mL = 2,125 mL,
\nSo 7,893 mL – 2,125 mL = 5,768 mL paint is left after first day,
\nNow Second day paint used is 5,768 mL – 1,769 mL = 3,999 mL
\nor 3,999 mL \u00f7 1000 = 3 L 999 mL paint has been
\nused on the second day by Shyan.
\nModeled\u00a0 problem with a tape diagram as shown above and
\nstatement Shyan on the second day uses three thousand
\nnine hundred ninety nine milliliters or 3 liters and nine
\nhundred ninety nine milliliters of the paint.<\/p>\n

Question 4.
\nOn Thursday, the pizzeria used 2 kilograms 180 grams
\nless flour than they used on Friday. On Friday, they used
\n12 kilograms 240 grams. On Saturday, they used 1,888 grams
\nmore than on Friday. What was the total amount of flour used
\nover the three days?
\n\"Eureka
\nThe total amount of flour used over three days is
\n36,428 grams or 36 kilograms 428 grams,
\n\"Eureka
\nStatement : The total amount of flour used over three days is
\nthirty six thousand four hundred twenty eight grams or thirty six
\nkilograms and four hundred twenty eight grams,<\/p>\n

Explanation:
\nGiven On Thursday, the pizzeria used less 2 kilograms 180 grams
\nless flour than they used on Friday. On Friday, they used
\n12 kilograms 240 grams. On Saturday, they used 1,888 grams
\nmore than on Friday. So on Thursday they used
\n12 kg 240 g – 2 kg 180 g =
\n12 X 1000 g + 240 g = 12,240 g,
\n2 X 1000 + 180 g = 2,180g,
\n12,240 g – 2,180 g = 10,060 g on Thursday,
\nOn Saturday they used 1,888 g + 12,240 g = 14,128 g,
\nNow the total amount of flour used over the three days is
\n10,060 g + 12,240 g + 14,128 g = 36,428 g or 36,428 g \u00f7 1000 =
\n36 kg 428 g. Therefore the total amount of flour used over three days is
\n36,428 grams or 36 kilograms 428 grams,
\nModeled problem with a tape diagram as shown above and
\nstatement is the total amount of flour used over three days is
\nthirty six thousand four hundred twenty eight grams or thirty six
\nkilograms and four hundred twenty eight grams.<\/p>\n

Question 5.
\nThe gas tank in Zachary\u2019s car has a capacity of 60 liters.
\nHe adds 23 liters 825 milliliters of gas to the tank,
\nwhich already has 2,050 milliliters of gas.
\nHow much more gas can Zachary add to the gas tank?<\/p>\n

More 34,125 milliliters or 34 L 125 mL gas can Zachary
\nadd to the gas tank,
\n\"Eureka
\nStatement : More thirty four thousand one hundred twenty five milliliters or thirty four liters and one hundred twenty five milliliters gas can
\nZachary add to the gas tank,<\/p>\n

Explanation:
\nGiven the gas tank in Zachary\u2019s car has a capacity of 60 liters.
\nHe adds 23 liters 825 milliliters of gas to the tank,
\nwhich already has 2,050 milliliters of gas.
\nSo\u00a0 the gas tank has\u00a0 23 L 825 mL + 2,050 mL =
\nas 23 L 825 mL = 23 X 1000 mL + 825 mL =
\n23,000 mL + 825 mL = 23,825 mL gas,
\nNow 23,825 mL + 2,050 mL = 25,875 mL
\nMore gas can Zachary add to the gas tank is 60 L – 25,875 mL =
\nas 60 L = 60 X 1,000 mL = 60,000 mL,
\nSo 60,000 – 25,875 mL = 34,125 mL or 34,125 mL \u00f7 1000 =
\n34 L 125 mL, therefore, more 34,125 milliliters or
\n34 L 125 mL gas can Zachary add to the gas tank.
\nModeled problem with a tape diagram as shown above and
\nstatement is more thirty four thousand one hundred
\ntwenty five milliliters or thirty four liters and one hundred
\ntwenty five milliliters gas can Zachary add to the gas tank.<\/p>\n

Question 6.
\nA giraffe is 5 meters 20 centimeters tall. An elephant is
\n1 meter 77 centimeters shorter than the giraffe.
\nA rhinoceros is 1 meter 58 centimeters shorter than
\nthe elephant. How tall is the rhinoceros?<\/p>\n

The rhinoceros is 185 centimeters tall or 1 meter 85 centimeters tall,
\n\"Eureka
\nStatement: The rhinoceros is one hundred eighty five
\ncentimeters tall or one meter eighty five centimeters tall,<\/p>\n

Explanation:
\nGiven A giraffe is 5 meters 20 centimeters tall. An elephant is
\n1 meter 77 centimeters shorter than the giraffe and
\nA rhinoceros is 1 meter 58 centimeters shorter than
\nthe elephant. So height of rhinoceros is first we see
\nheight of elephant as 5 m 20 cm – 1 m 77 cm =
\nas 5 X 100 cm + 20 cm = 5,20 cm and
\n1 m 77 cm = 1 X 100 cm +77 cm = 1,77 cm,
\nso 520 cm – 177 cm = 343 cm, Now rhinoceros is
\n343 cm – 1 m 58 cm =
\nas 1 m 58 cm = 1 X 100 cm + 58 cm = 158 cm
\nso 343 cm – 158 cm = 185 cm or 185 cm \u00f7 100 = 1 m 85 cm,
\ntherefore the rhinoceros is 185 centimeters tall or
\n1 meter 85 centimeters tall, modeled problem with a
\ntape diagram as shown above and statement is the
\nrhinoceros is one hundred eighty five centimeters tall or
\none meter eighty five centimeters tall.<\/p>\n

Eureka Math Grade 4 Module 2 Lesson 5 Exit Ticket Answer Key<\/h3>\n

Model each problem with a tape diagram.
\nSolve and answer with a statement.<\/p>\n

Question 1.
\nJeff places a pineapple with a mass of 890 grams on a
\nbalance scale. He balances the scale by placing two oranges,
\nan apple, and a lemon on the other side. Each orange weighs
\n280 grams. The lemon weighs 195 grams less than each orange.
\nWhat is the mass of the apple?
\n\"Engage
\nThe mass of the apple is 245 grams,
\n\"Eureka
\nStatement : The mass of the apple is two hundred forty five grams,<\/p>\n

Explanation:
\nGiven Jeff places a pineapple with a mass of 890 grams on a
\nbalance scale. He balances the scale by placing two oranges,
\nan apple, and a lemon on the other side. Each orange weighs
\n280 grams. The lemon weighs 195 grams less than each orange.
\nSo the lemon weighs 280 g – 195 g =\u00a0 85 grams,
\nNow weigh of two oranges is 280 g + 280 g = 560 grams,
\ngiven\u00a0 2 oranges + lemon + apple = 890 grams, therefore weigh of
\napple = 890 g – (560g + 85 g) = 890 g – 645 g = 245 g,
\ntherefore, the mass of the apple is 245 g, modeled problem
\nwith a tape diagram as shown above and statement is mass
\nof apple is two hundred fortyy five grams.<\/p>\n

Question 2.
\nBrian is 1 meter 87 centimeters tall. Bonnie is 58 centimeters
\nshorter than Brian. Betina is 26 centimeters taller than Bonnie.
\nHow tall is Betina?
\nBetina is 155 cm or 1 m 55 cm tall,
\n\"Eureka
\nStatement: Betina is one hundred fifty five centimeters or
\none meter fifty five centimeters tall,<\/p>\n

Explanation:
\nGiven Brian is 1 meter 87 centimeters tall.
\nBonnie is 58 centimeters shorter than Brian means
\nBonnie is 1 m 87 cm – 58 = as 1 m 87 cm =
\n1 X 100 cm + 87 cm = 187 cm, 187 cm – 58 cm = 129 cm,
\nBonnie is 129 cm and Betina is 26 centimeters taller than
\nBonnie means Betina is 129 cm + 26 cm = 155 cm or
\n155\u00a0 cm \u00f7 100 = 1 m 55 cm,
\nSo Betina is 155 cm or 1 m 55 cm tall, modeled problem
\nwith a tape diagram as shown above and statement is
\nBetina is one hundred fifty five centimeters or
\none meter fifty five centimeters tall.<\/p>\n

Eureka Math Grade 4 Module 2 Lesson 5 Homework Answer Key<\/h3>\n

Model each problem with a tape diagram. Solve and answer with a statement.<\/p>\n

Question 1.
\nThe capacity of Jose\u2019s vase is 2,419 milliliters of water.
\nHe poured 1 liter 299 milliliters of water into the empty vase.
\nThen, he added 398 milliliters. How much more water will
\nthe vase hold?<\/p>\n

Jose’s vase can hold more 722 milliliters of water,
\n\"Eureka
\nStatement : Jose’s vase can hold more seven hundred twenty
\ntwo milliliters of water,<\/p>\n

Explanation:
\nGiven the capacity of Jose\u2019s vase is 2,419 milliliters of water.
\nHe poured 1 liter 299 milliliters of water into the empty vase.
\nThen, he added 398 milliliters. So now water in the vase is
\n1 L 299 mL + 398 mL as 1 L 299 mL = 1 X 1000 mL + 299 mL =
\n1,299 mL +\u00a0 398 mL = 1,697 mL of water,
\nNow we can pour more is 2,419 mL – 1,697 mL = 722 mL more,
\ntherefore, Jose’s vase can hold more 722 milliliters of water,
\nmodeled problem with a tape diagram as shown above and
\nstatement is Jose’s vase can hold more seven hundred
\ntwenty two milliliters of water.<\/p>\n

Question 2.
\nEric biked 1 kilometer 125 meters on Monday.
\nOn Tuesday, he biked 375 meters less than on Monday.
\nHow far did he bike both days?<\/p>\n

Eric biked both days as 1,875 meters or 1 kilometer 875 meters,
\n\"Eureka
\nStatement : Eric biked both days as one thousand eight
\nhundred seventy five meters or one kilometer eight
\nhundred seventy five meters,<\/p>\n

Explanation:
\nGiven Eric biked 1 kilometer 125 meters on Monday.
\nOn Tuesday, he biked 375 meters less than on Monday.
\nSo on Tuesday he biked 1 k 125 m – 375 m =
\nas 1 X 1000 m + 125 m = 1,125 m ,
\n1125 m – 375 m = 750 m,
\ntherefore Eric biked on Monday and Tuesday is
\n1,125 m + 750 m = 1,875 m or 1,875 m \u00f7 1,000 = 1 k 875 m,
\ntherefore, Eric biked both days as 1,875 meters or
\n1 kilometer 875 meters, modeled problem with a tape diagram
\nas shown above and statement is Eric biked both days as one thousand eight hundred seventy five meters or one kilometer eight
\nhundred seventy five meters.<\/p>\n

Question 3.
\nZachary weighs 37 kilograms 95 grams. Gabe weighs
\n4,650 grams less than Zachary. Harry weighs
\n2,905 grams less than Gabe. How much does Harry weigh?<\/p>\n

Harry weigh 29,540 grams or 29 kilogram 540 grams,
\n\"Eureka
\nStatement : Harry weigh’s twenty nine thousand five hundred
\nforty grams or twenty nine kilograms five hundred
\nforty grams,<\/p>\n

Explanation:
\nGiven Zachary weighs 37 kilograms 95 grams. Gabe weighs
\n4,650 grams less than Zachary and Harry weighs
\n2,905 grams less than Gabe. So Gabe weigh’s
\n37 kg 95 g – 4,650 g as 37 kg 95 g =
\n37 X 1000 g + 95 g = 37,095 g so Gabe is
\n37,095 g – 4,650 g = 32,445 g,
\nNow Harry weigh’s 32,445 g – 2,905 g = 29,540 grams or
\n29,540 g \u00f7 1,000 = 29 kilograms 540 grams,
\ntherefore, Harry weigh 29,540 grams or 29 kilogram 540 grams,
\nmodeled problem with a tape diagram as shown above and
\nstatement is Harry weigh’s twenty nine thousand five hundred
\nforty grams or twenty nine kilograms five hundred
\nforty grams.<\/p>\n

Question 4.
\nA Springer Spaniel weighs 20 kilograms 490 grams.
\nA Cocker Spaniel weighs 7,590 grams less than a
\nSpringer Spaniel. A Newfoundland weighs
\n52 kilograms 656 grams more than a Cocker Spaniel.
\nWhat is the difference, in grams, between the weights of the Newfoundland and the Springer Spaniel?<\/p>\n

The difference in grams, between the weights of the
\nNewfoundland and the Springer Spaniel is 45,066 grams,
\n\"EurekaStatement: The difference in grams, between the weights of the
\nNewfoundland and the Springer Spaniel is forty five thousand
\nsixty six grams,<\/p>\n

Explanation:
\nGiven a\u00a0Springer Spaniel weighs 20 kilograms 490 grams.
\nA Cocker Spaniel weighs 7,590 grams less than a
\nSpringer Spaniel. A Newfoundland weighs
\n52 kilograms 656 grams more than a Cocker Spaniel.
\nSo Cocker spaniel weigh’s 20 kg 490 g – 7,590 g
\nas 20 kg 490 g = 20 X 1000 g + 490 g = 20,490 g,
\nSo 20,490 g – 7,590 g = 12,900 g,
\nNow Newfoundland weighs 52 kg 656 g +12,900 g as
\n52 kg 656 g = 52 X 1000 g + 656 g = 52,656 g,
\n52,656 g + 12,900 g = 65,556 g,
\nNow the difference in grams, between the weights of the
\nNewfoundland and the Springer Spaniel is
\n65,556 g – 20,490 g = 45,066 grams,
\nmodeled problem with a tape diagram as shown above and
\nstatement is the difference in grams, between the weights of the
\nNewfoundland and the Springer Spaniel is forty five thousand
\nsixty six grams.<\/p>\n

Question 5.
\nMarsha has three rugs. The first rug is 2 meters 87 centimeters long.
\nThe second rug has a length 98 centimeters
\nless than the first. The third rug is 111 centimeters
\nlonger than the second rug. What is the difference in
\ncentimeters between the length of the first rug and the third rug?<\/p>\n

The difference in centimeters between the length of
\nthe first rug and the third rug is 13 cm,
\n\"Eureka
\nStatement : The difference in centimeters between the length of
\nthe first rug and the third rug is thirteen centimeters,<\/p>\n

Explanation:
\nGiven Marsha has three rugs. The first rug is
\n2 meters 87 centimeters long.
\nThe second rug has a length 98 centimeters
\nless than the first. The third rug is 111 centimeters
\nlonger than the second rug so the second rug is
\n2 m 87 cm – 98 cm as 2 m 87 cm = 2 X 100 cm + 87 cm = 287 cm,
\nNow 287 cm – 98 cm = 189 cm and the third rug is
\n189 cm + 111 cm = 300 cm,
\nfirst rug is 287 cm, second rug is 189 cm and third rug is 300 cm,
\nNow the difference in centimeters between the length of
\nthe first rug and the third rug is 300 cm – 287 cm = 13 cm,
\nmodeled problem with a tape diagram as shown above and
\nstatement is the difference in centimeters between the length of
\nthe first rug and the third rug is thirteen centimeters.<\/p>\n

Question 6.
\nOne barrel held 60 liters 868 milliliters of sap.
\nA second barrel held 20,089 milliliters more sap than the first.
\nA third barrel held 40 liters 82 milliliters less sap than the second.
\nIf the sap from the three barrels was poured into a
\nlarger container, how much sap would there be in all ?<\/p>\n

182,700 milliliters or 182 liters 700 milliliters of sap
\nwould be there in all,
\n\"Eureka
\nStatement: one lakh eighty two thousand seven hundred
\nmilliliters or one hundred eighty two liters and
\nseven hundred milliliters of sap would be there in all,<\/p>\n

Explanation:
\nGiven one barrel held 60 liters 868 milliliters of sap.
\nA second barrel held 20,089 milliliters more sap than the first.
\nA third barrel held 40 liters 82 milliliters less sap than the second.
\nSecond barrel holds 60 L 868 mL + 20,089 mL as
\n60 L 868 mL = 60 X 1000 mL + 868 mL = 60,868 mL,
\n60,868 mL + 20,089 mL = 80,957 mL,
\nThird barrel holds 80,957 mL – 40 L 82 mL as
\n40 L 82 mL = 40 X 1000 mL + 82 mL = 40,082 mL,
\nso 80,957 mL – 40,082 mL = 40,875 mL,
\nFirst barrel holds 60,868 mL,
\nSecond barrel holds 80,957 mL,
\nThird barrel holds 40,875 mL,
\nNow if the sap from the three barrels was poured into a
\nlarger container it will contain
\n60,868 mL + 80,957 mL + 40,875 mL = 182,700 mL,
\nmodeled problem with a tape diagram as shown above and
\nstatement is one lakh eighty two thousand seven hundred
\nmilliliters or one hundred eighty two liters and
\nseven hundred milliliters of sap would be there in all.<\/p>\n

Eureka Math Grade 4 Module 2 Answer Key<\/a><\/h3>\n","protected":false},"excerpt":{"rendered":"

7Engage NY Eureka Math 4th Grade Module 2 Lesson 5 Answer Key Eureka Math Grade 4 Module 2 Lesson 5 Sprint Answer Key A Convert to Kilograms and Grams Question 1. 2,000 g = 2 kg 0 g, Explanation: Converted the conversion table as shown above as We know 1000 g or 103 \u00a0= 1 … Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[1],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts\/59659"}],"collection":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/comments?post=59659"}],"version-history":[{"count":1,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts\/59659\/revisions"}],"predecessor-version":[{"id":92240,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts\/59659\/revisions\/92240"}],"wp:attachment":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/media?parent=59659"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/categories?post=59659"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/tags?post=59659"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}