\nWrite at least 2 numerical expressions for each phrase below. Then, solve.
\na. Two thirds of eight
\nb. One sixth of the product of four and nine
\nAnswer:
\na. Numerical expression:
\n\\(\\frac{2}{3}\\) (8 )or \\(\\frac{2}{3}\\) \u00d7\u00a0<\/strong>8
\nSolution:
\n\\(\\frac{2}{3}\\) \u00d7\u00a0<\/strong>8 = \\(\\frac{16}{3}\\) = 5 \\(\\frac{1}{3}\\) .
\nb. Numerical expression:
\n\\(\\frac{1}{6}\\) (4 \u00d7 <\/strong>9 ) or \\(\\frac{1}{6}\\) (9 \u00d7 <\/strong>4\u00a0)
\nSolution:
\n\\(\\frac{1}{6}\\) (4 \u00d7 <\/strong>9 ) = \\(\\frac{1}{2}\\) (4 \u00d7 <\/strong>3 ) = 2 \u00d7 <\/strong>3 = 6<\/p>\n
Question 3.
\nUse <, >, or = to make true number sentences without calculating. Explain your thinking.
\na. 217 \u00d7 (42 + \\(\\frac{48}{5}\\)) ![\"Engage](\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2021\/03\/Engage-NY-Math-Grade-5-Module-6-Lesson-26-Problem-Set-Answer-Key-1.png\")
(217 \u00d7 42) + \\(\\frac{48}{5}\\)
\nb. (687 \u00d7 \\(\\frac{3}{16}\\)) \u00d7 \\(\\frac{7}{12}\\) (687 \u00d7 \\(\\frac{3}{16}\\)) \u00d7 \\(\\frac{3}{12}\\)
\nc.\u00a0 5 \u00d7 3.76 + 5 \u00d7 2.68 5 \u00d7 6.99<\/p>\n
Answer:
\na. 217 \u00d7 (42 + \\(\\frac{48}{5}\\)) > (217 \u00d7 42) + \\(\\frac{48}{5}\\)
\nExplanation :
\nThe left number is multiplied by greater number .
\nb. (687 \u00d7 \\(\\frac{3}{16}\\)) \u00d7 \\(\\frac{7}{12}\\) >\u00a0(687 \u00d7 \\(\\frac{3}{16}\\)) \u00d7 \\(\\frac{3}{12}\\)
\nExplanation :
\n\\(\\frac{7}{2}\\) is bigger than \\(\\frac{3}{12}\\) . So, Multiplying the same factor by \\(\\frac{7}{2}\\) will give you greater answer than multiplying by \\(\\frac{3}{2}\\) or \\(\\frac{1}{4}\\)
\nc. 5 \u00d7 3.76 + 5 \u00d7 2.68 <\u00a05 \u00d7 6.99
\nExplanation :
\nIf you add 3.76 and 2.68 its not as much as 6.99 and using the Distributive property , the first equation could be
\n5 ( 3.76 + 2.68 ) = 5 (6.44 ) .<\/p>\n
Eureka Math Grade 5 Module 6 Lesson 26 Reflection Answer Key<\/h3>\n
How did the games we played today prepare you to practice writing, solving, and comparing expressions this summer? Why do you think these are important skills to work on over the summer? Will you teach someone at home how to play these games with you? What math skills will you need to teach in order for someone at home to be able to play with you?
\nAnswer:
\nThis Expressions help in comparing the costs of goods while doing shopping and critical thinking skills\u00a0and ability to utilize math in everyday life.
\nIt is Important to work on this skills on over summer helps in increasing the solving of problems in different approach and constantly Learning .
\nYes , Teaching some one to play these games helps me to become perfect in that game .
\nMath skills that i need is to have\u00a0patience\u00a0and\u00a0understanding in order to Explain clearly to all.<\/p>\n
Eureka Math Grade 5 Module 6 Lesson 26 Homework Answer Key<\/h3>\n
Question 1.
\nFor each written phrase, write a numerical expression, and then evaluate your expression.
\na. Forty times the sum of forty-three and fifty-seven
\nNumerical expression:
\nSolution:
\nAnswer:
\nNumerical expression:
\n40 ( 43 + 57 )
\nSolution:
\n40 ( 43 + 57 ) = 40 ( 100 ) = 4000 .<\/p>\n
b. Divide the difference between one thousand three hundred and nine hundred fifty by four.
\nNumerical expression:
\nSolution:
\nAnswer:
\nNumerical expression:
\n\\(\\frac{1300 – 950}{4}\\)
\nSolution:
\n\\(\\frac{1300 – 950}{4}\\) = \\(\\frac{350}{4}\\) = \\(\\frac{175}{2}\\) = 87\\(\\frac{1}{2}\\) .<\/p>\n
c. Seven times the quotient of five and seven
\nNumerical expression:
\nSolution:
\nAnswer:
\nNumerical expression:
\n7\u00d7(5\u00f77)
\nSolution:
\n7\u00d7(5\u00f77) = 7 (\\(\\frac{5}{7}\\) ) = 5<\/p>\n
d. One fourth the difference of four sixths and three twelfths
\nNumerical expression:
\nSolution:
\nAnswer:
\nNumerical expression:
\n\\(\\frac{1}{4}\\)( \\(\\frac{4}{6}\\) – \\(\\frac{3}{12}\\))
\nSolution:
\n\\(\\frac{1}{4}\\)( \\(\\frac{4}{6}\\) – \\(\\frac{3}{12}\\))
\n= \\(\\frac{1}{4}\\)( \\(\\frac{2}{3}\\) – \\(\\frac{1}{4}\\))
\n= \\(\\frac{1}{4}\\)( \\(\\frac{8- 3}{12}\\))
\n=\u00a0\\(\\frac{1}{4}\\)( \\(\\frac{5}{12}\\))
\n=\\(\\frac{5}{48}\\)<\/p>\n
Question 2. Question 3. Engage NY Eureka Math 5th Grade Module 6 Lesson 26 Answer Key Eureka Math Grade 5 Module 6 Lesson 26 Problem Set Answer Key Question 1. For each written phrase, write a numerical expression, and then evaluate your expression. a. Three fifths of the sum of thirteen and six Numerical expression: (13 + 6 ) … Read more<\/a><\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[6],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts\/62673"}],"collection":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/comments?post=62673"}],"version-history":[{"count":1,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts\/62673\/revisions"}],"predecessor-version":[{"id":91573,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/posts\/62673\/revisions\/91573"}],"wp:attachment":[{"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/media?parent=62673"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/categories?post=62673"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/bigideasmathanswers.com\/wp-json\/wp\/v2\/tags?post=62673"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
\nWrite at least 2 numerical expressions for each written phrase below. Then, solve.
\na. Three fifths of seven
\nb. One sixth the product of four and eight
\nAnswer a :
\nNumerical expression:
\n\\(\\frac{3}{5}\\)( 7) or \\(\\frac{3}{5}\\) \u00d7\u00a0<\/strong>7
\nSolution:
\n\\(\\frac{3}{5}\\)( 7) = \\(\\frac{21}{5}\\)<\/p>\n
\nUse <, >, or = to make true number sentences without calculating. Explain your thinking.
\na. 4 tenths + 3 tens + 1 thousandth ![\"Eureka](\"https:\/\/ccssmathanswers.com\/wp-content\/uploads\/2021\/03\/Eureka-Math-Grade-5-Module-6-Lesson-26-Homework-Answer-Key-1.png\")
30.41
\nb. (5 \u00d7 \\(\\frac{1}{10}\\)) + (7 \u00d7 \\(\\frac{1}{100}\\)) 0.507
\nc. 8 \u00d7 7.20 8 \u00d7 4.36 + 8 \u00d7 3.59
\nAnswer:
\na. 4 tenths + 3 tens + 1 thousandth <\u00a030.41
\nExplanation :
\nWe have thousandth in the left\u00a0 that means 0.001 (43) = 0.043
\nb. (5 \u00d7 \\(\\frac{1}{10}\\)) + (7 \u00d7 \\(\\frac{1}{100}\\))\u00a0 = 0.507
\nExplanation :
\n(5 \u00d7 \\(\\frac{1}{10}\\)) + (7 \u00d7 \\(\\frac{1}{100}\\))
\n= 0.5 + 0.07 = 0.57
\nwe have only \\(\\frac{1}{100}\\) that means only 2 points of decimals
\nWhere as the in 0.507 we have 3 decimal points .
\nc.
\n8 \u00d7 7.20 <\u00a08 \u00d7 4.36 + 8 \u00d7 3.59
\nExplanation :
\nIf you add 4.36 and 3.59 is greater than as 7.20 and using the Distributive property , the Second equation could be
\n8 ( 4.36 + 3.59 ) = 8 (7.95 ) .<\/p>\n","protected":false},"excerpt":{"rendered":"