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Engage NY Eureka Math 3rd Grade Module 4 Mid Module Assessment Answer Key

Eureka Math Grade 3 Module 4 Mid Module Assessment Answer Key

Question 1.
Jasmine and Roland each use unit squares to tile a piece of paper. Their work is shown below.

a. Can one of the arrays be used to correctly measure the area of the piece of paper? If so, whose array would you use? Explain why.
Answer:

b. What is the area of the piece of paper? Explain your strategy for finding the area.
Answer:

c. Jasmine thinks she can skip-count by sixes to find the area of her rectangle. Is she correct? Explain why or why not.
Answer:

Question 2.
Jaheim says you can create three rectangles with different side lengths using
12 unit squares. Use pictures, numbers, and words to show what Jaheim is saying.
Answer:

Question 3.
The area of a rectangle is 72 square units. One side has a length of 9 units. What is the other side length? Explain how you know using pictures, equations, and words.
Answer:

Question 4.
Jax started to draw a grid inside the rectangle to find its area.

a. Use a straight edge to complete the drawing of the grid.
Answer:

b. Write a skip-count sequence you could use to find the area.
Answer:

c. Write a multiplication equation that you could use to find the area, and then solve.
Answer:

Question 5.
Half of the rectangle below has been tiled with unit squares.

a. How many more unit squares are needed to fill in the rest of the rectangle?
Answer:

b. What is the total area of the large rectangle? Explain how you found the area.
Answer:

Students of Grade 3 can get a strong foundation on mathematics concepts by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka’s Math Grade 3 Book.

Engage NY Eureka Math 3rd Grade Module 4 End of Module Assessment Answer Key

Eureka Math Answer Key for Grade 3 aids teachers to differentiate instruction, building, and reinforcing foundational mathematics skills that alter from the classroom to real life.
With the help of the Eureka Primary School Grade 3 Answer Key, You can think deeply regarding what you are learning, and you will really learn math easily just like that. So teachers and students can find this Eureka Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students.

Eureka Math Grade 3 Module 4 End of Module Assessment Answer Key

Question 1.
Sarah says the rectangle on the left has the same area as the sum of the two on the right. Pam says they do not have the same areas. Who is correct? Explain using numbers, pictures, and words.

Answer:
Sarah was correct.

Explanation:
In the above-given question,
given that,
the area of the left rectangle = l x b.
area = 5 x 7.
area = 35 sq cm.
the area of the right rectangle 1 = l x b.
area = l x b.
area = 4 x 5.
area = 20 sq cm.
the area of the right rectangle 2 = l x b.
area = l x b.
area = 3 x 5.
area = 15 sq cm.
35 = 20 + 15.
35 = 35.
the area of the left rectangle = sum of the two rectangles on the right.

Question 2.
Draw three different arrays that you could make with 36 square inch tiles. Label the side lengths on each of your arrays. Write multiplication sentences for each array to prove that the area of each array is 36 square inches.

Answer:
The side lengths of the different arrays = 9 x 4, 4 x 9, 6 x 6.

Explanation:
In the above-given question,
given that,
the area of the rectangle 1 = 36 sq in.
area = l x b.
area = 9 x 4.
the area of the rectangle 2 = 36 sq in.
area = l x b.
area = 4 x 9.
the area of the rectangle 3 = 36 sq in.
area = l x b.
area = 6 x 6.

Question 3.
Mr. and Mrs. Jackson are buying a new house. They are deciding between the two floor plans below.

Which floor plan has the greater area? Show how you found your answer on the drawings above. Show your calculations below.

Answer:
The area of the shaded figure = 102 sq m.

Explanation:
In the above-given question,
given that,
area of longer rectangle = 120 sq m.
area = l x b.
area = 12 x 10.
area = 120 sq m.
area of longer rectangle 2 = 36 sq m.
area = l x b.
area = 12 x 3.
area = 36 sq m.
area of smaller rectangle = 18 sq m.
area = l x b.
area = 6 x 3.
area = 18 sq cm.
area of shaded rectangle = area of longer rectangle – area of smaller rectangle.
area of shaded rectangle = 120 – 18.
area of shaded figure = 102.

area of longer rectangle = 48 sq m.
area = l x b.
area = 12 x 4.
area = 48 sq m.
area of longer rectangle 2 = 27 sq m.
area = l x b.
area = 9 x 3.
area = 27 sq m.
area of smaller rectangle = 9 sq m.
area = l x b.
area = 3 x 3.
area = 9 sq cm.
House A has a greater area.

Question 4.
Superior Elementary School uses the design below for their swimming pool. Shapes A, B, and C are rectangles.

a. Label the side lengths of Rectangles A and B on the drawing.

Answer:
The side lengths of Rectangle A = 7 m x 3 m.
The side lengths of Rectangle B = 10 m x 3 m.
The side lengths of Rectangle C = 10 m x 6 m.

Explanation:
In the above-given question,
given that,
the area of the rectangle A = 21 sq m.
area = 7 x 3.
area = 21 sq m.
the area of the rectangle B = 30 sq m.
area = 10 x 3.
area = 30 sq m.
the area of the rectangle C = 60 sq m.
area = 10 x 6.
area = 60 sq m.

b. Find the area of each rectangle.

Answer:
The side lengths of Rectangle A = 7 m x 3 m.
The side lengths of Rectangle B = 10 m x 3 m.
The side lengths of Rectangle C = 10 m x 6 m.

Explanation:
In the above-given question,
given that,
the area of the rectangle A = 21 sq m.
area = 7 x 3.
area = 21 sq m.
the area of the rectangle B = 30 sq m.
area = 10 x 3.
area = 30 sq m.
the area of the rectangle C = 60 sq m.
area = 10 x 6.
area = 60 sq m.

c. Find the area of the entire pool. Explain how you found the area of the pool.

Answer:
The area of the entire pool = 111 sq m.

Explanation:
In the above-given question,
given that,
the area of the rectangle A = 21 sq m.
area = 7 x 3.
area = 21 sq m.
the area of the rectangle B = 30 sq m.
area = 10 x 3.
area = 30 sq m.
the area of the rectangle C = 60 sq m.
area = 10 x 6.
area = 60 sq m.

Eureka Math Answer Key for Grade 3 aids teachers to differentiate instruction, building, and reinforcing foundational mathematics skills that alter from the classroom to real life.
With the help of the Eureka Primary School Grade 3 Answer Key, You can think deeply regarding what you are learning, and you will really learn math easily just like that. So teachers and students can find this Eureka Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students.

Engage NY Eureka Math 3rd Grade Module 4 Lesson 16 Answer Key

Students of Grade 3 can get a strong foundation on mathematics concepts by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka’s Math Grade 3 Book.

Eureka Math Grade 3 Module 4 Lesson 16 Pattern Sheet Answer Key

Multiply
–

Answer:
9 x 1 = 9, 9 x 2 = 18, 9 x 3 = 27, 9 x 4 = 36, 9 x 5 = 45, 9 x 6 = 54, 9 x 7 = 63, 9 x 8 = 72, 9 x 9 = 81, 9 x 10 = 90, 9 x 5 = 45, 9 x 6 = 54, 9 x 5 = 45, 9 x 7 = 63, 9 x 8 = 72, 9 x 5 = 45, 9 x 5 = 45, 9 x 10 = 90, 9 x 6 = 54, 9 x 5 = 45, 9 x 6 = 54, 9 x 7 = 63, 9 x 6 = 54, 9 x 8 = 72, 9 x 6 = 54, 9 x 9 = 81, 9 x 6 = 54, 9 x 7 = 63, 9 x 6 = 54, 9 x 7 = 63, 9 x 8 = 72, 9 x 7 = 63, 9 x 9 = 81, 9 x 7 = 63, 9 x 8 = 72, 9 x 6 = 54, 9 x 8 = 72, 9 x 7 = 63, 9 x 8 = 72, 9 x 9 = 81, 9 x 9 = 81, 9 x 6 = 54, 9 x 9 = 81, 9 x 7 = 63, 9 x 9 = 81, 9 x 8 = 72, 9 x 9 = 81, 9 x 8 = 72, 9 x 6 = 54, 9 x 9 = 81, 9 x 7 = 63, 9 x 9 = 81, 9 x 6 = 54, 9 x 8 = 72, 9 x 9 = 81, 9 x 7 = 63, 9 x 6 = 54, 9 x 8 = 72.

Explanation:
In the above-given question,
given that,
multiply with 9.
9 x 1 = 9, 9 x 2 = 18, 9 x 3 = 27, 9 x 4 = 36, 9 x 5 = 45, 9 x 6 = 54, 9 x 7 = 63, 9 x 8 = 72, 9 x 9 = 81, 9 x 10 = 90, 9 x 5 = 45, 9 x 6 = 54, 9 x 5 = 45, 9 x 7 = 63, 9 x 8 = 72, 9 x 5 = 45, 9 x 5 = 45, 9 x 10 = 90, 9 x 6 = 54, 9 x 5 = 45, 9 x 6 = 54, 9 x 7 = 63, 9 x 6 = 54, 9 x 8 = 72, 9 x 6 = 54, 9 x 9 = 81, 9 x 6 = 54, 9 x 7 = 63, 9 x 6 = 54, 9 x 7 = 63, 9 x 8 = 72, 9 x 7 = 63, 9 x 9 = 81, 9 x 7 = 63, 9 x 8 = 72, 9 x 6 = 54, 9 x 8 = 72, 9 x 7 = 63, 9 x 8 = 72, 9 x 9 = 81, 9 x 9 = 81, 9 x 6 = 54, 9 x 9 = 81, 9 x 7 = 63, 9 x 9 = 81, 9 x 8 = 72, 9 x 9 = 81, 9 x 8 = 72, 9 x 6 = 54, 9 x 9 = 81, 9 x 7 = 63, 9 x 9 = 81, 9 x 6 = 54, 9 x 8 = 72, 9 x 9 = 81, 9 x 7 = 63, 9 x 6 = 54, 9 x 8 = 72.

Eureka Math Grade 3 Module 4 Lesson 16 Problem Set Answer Key

Record the new side lengths you have chosen for each of the rooms and show that these side lengths equal the required area. For non-rectangular rooms, record the side lengths and areas of the small rectangles. Then, show how the areas of the small rectangles equal the required area.

Answer:
The side lengths of Bedroom 1 = 12 cm x 5 cm.
the side lengths of Bedroom 2 = 8 cm x 7 cm.
the side lengths of the Kitchen = 6 cm x 7 cm.
the side lengths of the hallway = 6 cm x 4 cm.
the side lengths of the bathroom = 5 cm x 5 cm.
the side lengths of the dining room = 7 cm x 4 cm.
the side lengths of the living room = 11 cm x 8 cm.

Explanation:
In the above-given question,
given that,
the area of the rooms.
The side lengths of Bedroom 1 = 12 cm x 5 cm.
the side lengths of Bedroom 2 = 8 cm x 7 cm.
the side lengths of the Kitchen = 6 cm x 7 cm.
the side lengths of the hallway = 6 cm x 4 cm.
the side lengths of the bathroom = 5 cm x 5 cm.
the side lengths of the dining room = 7 cm x 4 cm.
the side lengths of the living room = 11 cm x 8 cm.

Eureka Math Grade 3 Module 4 Lesson 16 Exit Ticket Answer Key

Find the area of the shaded figure. Then, draw and label a rectangle with the same area.

Answer:
The area of the shaded figure = 40 sq cm.

Explanation:
In the above-given question,
given that,
area of longer rectangle = 49 sq cm.
area = l x b.
area = 7 x 7.
area = 49 sq cm.
area of smaller rectangle = 9 sq cm.
area = l x b.
area = 3 x 3.
area = 9 sq cm.
area of shaded rectangle = area of the longer rectangle – the area of the smaller rectangle.
area of shaded rectangle = 49 – 9.
area = 40 sq cm

Eureka Math Grade 3 Module 4 Lesson 16 Homework Answer Key

Jeremy plans and designs his own dream playground on grid paper. His new playground will cover a total area of 100 square units. The chart shows how much space he gives for each piece of equipment, or area. Use the information in the chart to draw and label a possible way Jeremy can plan his playground.

Answer:
The area of the basketball court = 10 sq units.
The area of the Jungle gym = 9 sq units.
The area of the slide = 6 sq units.
The area of the soccer area = 24 sq units.

Explanation:
In the above-given question,
given that,
The area of the basketball court = 10 sq units.
area = 5 cm x 2 cm.
The area of the Jungle gym = 9 sq units.
area = 3 cm x 3 cm.
The area of the slide = 6 sq units.
area = 3 cm x 2 cm.
The area of the soccer area = 24 sq units.
area = 6 cm x 4 cm.

Engage NY Eureka Math 3rd Grade Module 4 Lesson 15 Answer Key

Eureka Math Grade 3 Module 4 Lesson 15 Pattern Sheet Answer Key

Multiply

Answer:
9 x 1 = 9, 9 x 2 = 18, 9 x 3 = 27, 9 x 4 = 36, 9 x 5 = 45, 9 x 6 = 54, 9 x 7 = 63, 9 x 8 = 72, 9 x 9 = 81, 9 x 10 = 90, 9 x 4 = 36, 9 x 1 = 9, 9 x 5 = 45, 9 x 1 = 9, 9 x 2 = 18, 9 x 3 = 27, 9 x 2 = 18, 9 x 4 = 36, 9 x 2 = 18, 9 x 5 = 45, 9 x 2 = 18, 9 x 1 = 9, 9 x 2 = 18, 9 x 3 = 27, 9 x 1 = 9, 9 x 3 = 27, 9 x 2 = 18, 9 x 3 = 27, 9 x 4 = 36, 9 x 3 = 27, 9 x 5 = 45, 9 x 3 = 27, 9 x 4 = 36, 9 x 1 = 9, 9 x 4 = 36, 9 x 2 = 18, 9 x 4 = 36, 9 x 3 = 27, 9 x 4 = 36, 9 x 5 = 45, 9 x 4 = 36, 9 x 3 = 27, 9 x 5 = 45, 9 x 4 = 36, 9 x 2 = 18, 9 x 4 = 36, 9 x 3 = 27, 9 x 5 = 45, 9 x 3 = 27, 9 x 2 = 18, 9 x 4 = 36, 9 x 3 = 27, 9 x 5 = 45, 9 x 2 = 18, 9 x 4 = 36.

Explanation:
In the above-given question,
given that,
multiply by 9.
9 x 1 = 9, 9 x 2 = 18, 9 x 3 = 27, 9 x 4 = 36, 9 x 5 = 45, 9 x 6 = 54, 9 x 7 = 63, 9 x 8 = 72, 9 x 9 = 81, 9 x 10 = 90, 9 x 4 = 36, 9 x 1 = 9, 9 x 5 = 45, 9 x 1 = 9, 9 x 2 = 18, 9 x 3 = 27, 9 x 2 = 18, 9 x 4 = 36, 9 x 2 = 18, 9 x 5 = 45, 9 x 2 = 18, 9 x 1 = 9, 9 x 2 = 18, 9 x 3 = 27, 9 x 1 = 9, 9 x 3 = 27, 9 x 2 = 18, 9 x 3 = 27, 9 x 4 = 36, 9 x 3 = 27, 9 x 5 = 45, 9 x 3 = 27, 9 x 4 = 36, 9 x 1 = 9, 9 x 4 = 36, 9 x 2 = 18, 9 x 4 = 36, 9 x 3 = 27, 9 x 4 = 36, 9 x 5 = 45, 9 x 4 = 36, 9 x 3 = 27, 9 x 5 = 45, 9 x 4 = 36, 9 x 2 = 18, 9 x 4 = 36, 9 x 3 = 27, 9 x 5 = 45, 9 x 3 = 27, 9 x 2 = 18, 9 x 4 = 36, 9 x 3 = 27, 9 x 5 = 45, 9 x 2 = 18, 9 x 4 = 36.

Eureka Math Grade 3 Module 4 Lesson 15 Problem Set Answer Key

Question 1.
Make a prediction: Which room looks like it has the biggest area?

Answer:
The living room looks like it has the biggest area.

Explanation:
In the above-given question,
given that,
the living room is the biggest room in the house.
so the living room has the biggest area.

Question 2.
Record the areas and show the strategy you used to find each area.

Answer:
The area of Bedroom 1 = 1200 sq cm.
the area of bedroom 2 = 1000 sq cm.
the area of kitchen = 200 sq cm.
the area of the living room = 1500 sq cm.
the area of hallway = 900 sq cm.
the area of bathroom = 250 sq cm.
the area of the dining room = 500 sq cm.

Explanation:
In the above-given question,
given that,
The area of Bedroom 1 = 1200 sq cm.
the area of bedroom 2 = 1000 sq cm.
the area of kitchen = 200 sq cm.
the area of the living room = 1200 sq cm.
the area of hallway = 900 sq cm.
the area of bathroom = 250 sq cm.
the area of the dining room = 500 sq cm.

Question 3.
Which room has the biggest area? Was your prediction right? Why or why not?

Answer:
The living room has the biggest area.

Explanation:
In the above-given question,
given that,
the living room area is bigger than all other rooms in the house.
area of living room = 1500 sq cm.

Question 4.
Find the side lengths of the house without using your ruler to measure them, and explain the process you used.
Side lengths: _____350_____ centimeters and ___15_______ centimeters

Answer:
The side lengths = 350 cm and 15 cm.

Explanation:
In the above-given question,
given that,
The area of the room = 5250 sq cm.
length = 350 cm and breadth = 15 cm.
area = 5250 sq cm

Question 5.
What is the area of the whole floor plan? How do you know?
Area = _____5250_____ square centimeters

Answer:
The area = 5250 sq cm.

Explanation:
In the above-given question,
given that,
The area of the room = 5250 sq cm.
length = 350 cm and breadth = 15 cm.
area = 5250 sq cm

Eureka Math Grade 3 Module 4 Lesson 15 Exit Ticket Answer Key

Jack uses grid paper to create a floor plan of his room. Label the unknown measurements, and find the area of the items listed below.

Answer:
The area of the Bed = 60 sq units.
the area of the table = 9 sq units.
the area of the dresser = 24 sq units.
the area of the desk = 15 sq units.

Explanation:
In the above-given question,
given that,
The area of the Bed = 60 sq units.
the area of the table = 9 sq units.
the area of the dresser = 24 sq units.
the area of the desk = 15 sq units.

Eureka Math Grade 3 Module 4 Lesson 15 Homework Answer Key

Use a ruler to measure the side lengths of each numbered room in centimeters. Then, find the area. Use the measurements below to match, and label the rooms with the correct areas.
Kitchen: 45 square centimeters
Living Room: 63 square centimeters
Porch: 34 square centimeters
Bedroom: 56 square centimeters
Bathroom: 24 square centimeters
Hallway: 12 square centimeters

Answer:
Kitchen: 45 square centimeters.
Living Room: 63 square centimeters.
Porch: 34 square centimeters.
Bedroom: 56 square centimeters.
Bathroom: 24 square centimeters.
Hallway: 12 square centimeters.

Explanation:
In the above-given question,
given that,
the area of the rooms.
Kitchen: 45 square centimeters
Living Room: 63 square centimeters
Porch: 34 square centimeters
Bedroom: 56 square centimeters
Bathroom: 24 square centimeters
Hallway: 12 square centimeters

Students of Grade 3 can get a strong foundation on mathematics concepts by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka’s Math Grade 3 Book.

Engage NY Eureka Math 3rd Grade Module 4 Lesson 14 Answer Key

Eureka Math Answer Key for Grade 3 aids teachers to differentiate instruction, building, and reinforcing foundational mathematics skills that alter from the classroom to real life.
With the help of the Eureka Primary School Grade 3 Answer Key, You can think deeply regarding what you are learning, and you will really learn math easily just like that. So teachers and students can find this Eureka Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students.

Eureka Math Grade 3 Module 4 Lesson 14 Pattern Sheet Answer Key

Multiply

Answer:
8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 4 = 32, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64, 8 x 9 = 72, 8 x 10 = 80, 8 x 5 = 40, 8 x 6 = 48, 8 x 5 = 40, 8 x 7 = 56, 8 x 5 = 40, 8 x 8 = 64, 8 x 5 = 40, 8 x 9 = 72, 8 x 5 = 40, 8 x 10 = 80, 8 x 6 = 48, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 6 = 48, 8 x 7 = 56, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64, 8 x 7 = 56, 8 x 9 = 72, 8 x 7 = 56, 8 x 8 = 64, 8 x 6 = 48, 8 x 8 = 64, 8 x 7 = 56, 8 x 8 = 64, 8 x 9 = 72, 8 x 9 = 72, 8 x 6 = 48, 8 x 9 = 72, 8 x 7 = 56, 8 x 9 = 72, 8 x 8 = 64, 8 x 9 = 72, 8 x 8 = 64, 8 x 6 = 48, 8 x 9 = 72, 8 x 7 = 56, 8 x 9 = 72, 8 x 6 = 48, 8 x 8 = 64, 8 x 9 = 72, 8 x 7 = 56, 8 x 6 = 48, 8 x 8 = 64.

Explanation:
In the above-given question,
given that,
multiply with 8.
8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 4 = 32, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64, 8 x 9 = 72, 8 x 10 = 80, 8 x 5 = 40, 8 x 6 = 48, 8 x 5 = 40, 8 x 7 = 56, 8 x 5 = 40, 8 x 8 = 64, 8 x 5 = 40, 8 x 9 = 72, 8 x 5 = 40, 8 x 10 = 80, 8 x 6 = 48, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 6 = 48, 8 x 7 = 56, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64, 8 x 7 = 56, 8 x 9 = 72, 8 x 7 = 56, 8 x 8 = 64, 8 x 6 = 48, 8 x 8 = 64, 8 x 7 = 56, 8 x 8 = 64, 8 x 9 = 72, 8 x 9 = 72, 8 x 6 = 48, 8 x 9 = 72, 8 x 7 = 56, 8 x 9 = 72, 8 x 8 = 64, 8 x 9 = 72, 8 x 8 = 64, 8 x 6 = 48, 8 x 9 = 72, 8 x 7 = 56, 8 x 9 = 72, 8 x 6 = 48, 8 x 8 = 64, 8 x 9 = 72, 8 x 7 = 56, 8 x 6 = 48, 8 x 8 = 64.

Eureka Math Grade 3 Module 4 Lesson 14 Problem Set Answer Key

Question 1.
Find the area of each of the following figures. All figures are made up of rectangles.
a.

Answer:
The area of figure 1 = 10 sq cm.
the area of figure 2 = 9 sq cm.

Explanation:
In the above-given question,
given that,
area of the figure 1 = 10 sq cm.
area = l x b.
where l = length and b = breadth.
area = 5 x 2.
area = 10.
area of the figure 2 = 9 sq cm.
area = l x b.
where l = length and b = breadth.
area = 3 x 3.
area = 9.

b.

Answer:
The area of the shaded figure = 78 sq cm.

Explanation:
In the above-given question,
given that,
area of longer rectangle = 12 sq cm.
area = l x b.
area = 3 x 4.
area = 12 sq cm.
area of smaller rectangle = 2 sq cm.
area = l x b.
area = 1 x 2.
area = 2 sq cm.
area of shaded rectangle = area of longer rectangle – area of smaller rectangle.
area of shaded rectangle = 12 – 2.
area = 10 sq cm

Question 2.
The figure below shows a small rectangle in a big rectangle. Find the area of the shaded part of the figure.

Answer:
The area of the shaded figure = 24 sq cm.

Explanation:
In the above-given question,
given that,
the area of the longer rectangle = 30 sq cm.
area = l x b.
area = 6 x 5.
area = 30 sq cm.
area of smaller rectangle = 6 sq cm.
area = l x b.
area = 3 x 2.
area = 6 sq cm.
area of shaded rectangle = area of longer rectangle – area of smaller rectangle.
area of shaded rectangle = 30 – 6.
area of shaded rectangle = 24.

Question 3.
A paper rectangle has a length of 6 inches and a width of 8 inches. A square with a side length of 3 inches was cut out of it. What is the area of the remaining paper?

Answer:
The area of the remaining paper = 25 sq in.

Explanation:
In the above-given question,
given that,
A paper rectangle has a length of 6 inches and a width of 8 inches.
A square with a side length of 3 inches was cut out of it.
area = 6 x 8 = 48.
the area of remaining paper = 25.
8 – 3 = 5.
6 – 1 = 5.
area = 5 x 5.
area = 25.

Question 4.
Tila and Evan both have paper rectangles measuring 6 cm by 9 cm. Tila cuts a 3 cm by 4 cm rectangle out of hers, and Evan cuts a 2 cm by 6 cm rectangle out of his. Tila says she has more paper left over. Evan says they have the same amount. Who is correct? Show your work below.

Answer:
Tila is correct.

Explanation:
In the above-given question,
given that,
Tila and Evan both have paper rectangles measuring 6 cm by 9 cm.
Tila cuts a 3 cm by 4 cm rectangle out of hers,
Evan cuts 2 cm by 6 cm rectangle out of his.
3 x 5 = 15.
4 x 3 = 12.
so Tila is correct.

Eureka Math Grade 3 Module 4 Lesson 14 Exit Ticket Answer Key

Mary draws an 8 cm by 6 cm rectangle on her grid paper. She shades a square with a side length of 4 cm inside her rectangle. What area of the rectangle is left unshaded?

Answer:
The area of the rectangle is left unshaded = 24 sq cm.

Explanation:
In the above-given question,
given that,
area of longer rectangle = 48 sq cm.
area = l x b.
area = 8 x 6.
area = 48 sq cm.
area of smaller rectangle = 24 sq cm.
area = l x b.
area = 6 x 4.
area = 24 sq cm.
area of shaded rectangle = area of longer rectangle – area of smaller rectangle.
area of shaded rectangle = 48 – 24.
area of shaded rectangle = 24 sq cm.

Eureka Math Grade 3 Module 4 Lesson 14 Homework Answer Key

Question 1.
Find the area of each of the following figures. All figures are made up of rectangles.
a.

Answer:
The area of figure 1 = 48 sq cm.
the area of figure 2 = 27 sq cm.

Explanation:
In the above-given question,
given that,
area of the figure 1 = 48 sq cm.
area = l x b.
where l = length and b = breadth.
area = 6 x 8.
area = 48.
area of the figure 2 = 27 sq cm.
area = l x b.
where l = length and b = breadth.
area = 9 x 3.
area = 27.

b.

Answer:
The area of figure 1 = 64 sq in.
the area of figure 2 = 6 sq in.

Explanation:
In the above-given question,
given that,
area of the figure 1 = 64 sq in.
area = l x b.
where l = length and b = breadth.
area = 8 x 8.
area = 64.
area of the figure 2 = 6 sq in.
area = l x b.
where l = length and b = breadth.
area = 2 x 3.
area = 6.

Question 2.
The figure below shows a small rectangle cut out of a big rectangle.

a. Label the side lengths of the unshaded region.

Answer:
The side lengths of the unshaded region is = 5 ft and 3 ft.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 10 x 7.
area = 70 sq ft.
10 – 3 + 2 = 5.
7 – 2 + 2 = 4.
so the side lengths of the unshaded region = 5 ft and 3 ft.

b. Find the area of the shaded region.

Answer:
The area of the shaded figure = 55 sq ft.

Explanation:
In the above-given question,
given that,
area of longer rectangle = 70 sq ft.
area = l x b.
area = 10 x 7.
area = 70 sq cm.
area of smaller rectangle = 15 sq ft.
area = l x b.
area = 5 x 3.
area = 15 sq ft.
area of shaded rectangle = area of longer rectangle – area of smaller rectangle.
area of shaded rectangle = 70 – 15.
area of shaded rectangle = 55.

You may have diverse opportunities to develop math skills and problem-solving skills but practicing with Eureka Math 3rd Grade Answer Key for better and efficient learning. Eureka Math Grade 3 provided Free Access Student Edition of Eureka Math Grade 3 Answers are enough to practice more and get a good grip on the subject. The diverse opportunities will develop problem-solving skills among the primary school kids Practising.

Engage NY Eureka Math 3rd Grade Module 4 Lesson 13 Answer Key

Fun learning activities are the best option to educate primary school students and make them understand the basic mathematical concepts like addition, subtraction, multiplication, division, etc. Grade 3 primary school students can find these fun-learning exercises for all math concepts through the Eureka Math Answers Grade 3 Common Core Curriculum.

Eureka Math Grade 3 Module 4 Lesson 13 Problem Set Answer Key

Question 1.
Each of the following figures is made up of 2 rectangles. Find the total area of each figure.

Figure 1: Area of A + Area of B: ____18_____ sq units + _____9____ sq units = _____27____ sq units

Figure 2: Area of C + Area of D: ____18_____ sq units + ___15______ sq units = ___33______ sq units

Figure 3: Area of E + Area of F: _____9____ sq units + ____21_____ sq units = ____30_____ sq units

Figure 4: Area of G + Area of H: _____49____ sq units + ___6______ sq units = ____55_____sq units

Answer:
The total area of figure 1 = 27 sq units.
the total area of figure 2 = 33 sq units.
the total area of figure 3 = 30 sq units.
the total area of figure 4 = 55 sq units.

Explanation:
In the above-given question,
given that,
the area of rectangle A + rectangle B = figure 1.
area of rectangle A = 18 sq units.
area of rectangle B = 9 sq units.
so the area of figure 1 = 27 sq units.
the area of rectangle C + rectangle D = figure 2.
area of rectangle C = 18 sq units.
area of rectangle D = 15 sq units.
so the area of figure 2 = 33 sq units.
the area of rectangle E + rectangle F = figure 3.
area of rectangle E = 9 sq units.
area of rectangle F = 21 sq units.
so the area of figure 3 = 30 sq units.
the area of rectangle G + rectangle H = figure 4.
area of rectangle G = 49 sq units.
area of rectangle H = 6 sq units.
so the area of figure 4 = 55 sq units.

Question 2.
The figure shows a small rectangle cut out of a bigger rectangle. Find the area of the shaded figure.

Area of the shaded figure: __90____ – __12____ = ___78___
Area of the shaded figure: ___78___ square centimeters

Answer:
The area of the shaded figure = 78 sq cm.

Explanation:
In the above-given question,
given that,
area of longer rectangle = 90 sq cm.
area = l x b.
area = 9 x 10.
area = 90 sq cm.
area of smaller rectangle = 12 sq cm.
area = l x b.
area = 3 x 4.
area = 12 sq cm.
area of shaded rectangle = area of longer rectangle – area of smaller rectangle.
area of shaded rectangle = 90 – 12.
area of shaded rectangle = 78 sq cm.

Question 3.
The figure shows a small rectangle cut out of a big rectangle.

a. Label the unknown measurements.

Answer:
The unknown measurements = 4 cm and 5 cm.

Explanation:
In the above-given question,
given that,
the longer rectangle = 9 x 7 = 63 cm.
9 – 4 = 3.
7 – 3 = 4.
so the unknown measurements = 4 cm and 5 cm.

b. Area of the big rectangle:
___9__ cm × __7___ cm = __63___ sq cm

Answer:
The area of big rectangle = 63 sq cm.

Explanation:
In the above-given question,
given that,
area of the big rectangle = l x b.
where l = length, and b = breadth.
area = 9 x 7 = 63 sq cm.
so the area of big rectangle = 63 sq cm.

c. Area of the small rectangle:
___5__ cm × __4___ cm = ___20__ sq cm

Answer:
The area of small rectangle = 20 sq cm.

Explanation:
In the above-given question,
given that,
area of the big rectangle = l x b.
where l = length, and b = breadth.
area = 5 x 4 = 20 sq cm.
so the area of big rectangle = 20 sq cm.

d. Find the area of the shaded figure.

Answer:
The area of the shaded figure = 43 sq cm.

Explanation:
In the above-given question,
given that,
the area of the longer rectangle = 63 sq cm.
area = l x b.
area = 9 x 7.
area = 63 sq cm.
area of smaller rectangle = 20 sq cm.
area = l x b.
area = 5 x 4.
area = 20 sq cm.
area of shaded rectangle = area of the longer rectangle – the area of the smaller rectangle.
area of shaded rectangle = 63 – 20.
area of shaded rectangle = 43 sq cm.

Eureka Math Grade 3 Module 4 Lesson 13 Exit Ticket Answer Key

The following figure is made up of 2 rectangles. Find the total area of the figure.

Area of A + Area of B: _____32___ sq units + ____20_____ sq units = ___52______ sq units

Answer:
The area of rectangle A and B = 52 sq units.
Explanation:
In the above-given question,
given that,
the area of rectangle A + rectangle B = figure 1.
area of rectangle A = 32 sq units.
area of rectangle B = 20 sq units.
so the area of rectangle A and B = 52 sq units.

Eureka Math Grade 3 Module 4 Lesson 13 Homework Answer Key

Question 1.
Each of the following figures is made up of 2 rectangles. Find the total area of each figure.

Figure 1: Area of A + Area of B: ____15_____ sq units + ____9_____ sq units = ___24______ sq units

Figure 2: Area of C + Area of D: ___3______ sq units + ____8_____ sq units = ____24_____ sq units

Figure 3: Area of E + Area of F: ___12______ sq units + ____32_____ sq units = ____44_____ sq units

Figure 4: Area of G + Area of H: _____15____ sq units + ____25_____ sq units = ___40______ sq units

Answer:
The total area of figure 1 = 24 sq units.
the total area of figure 2 = 24 sq units.
the total area of figure 3 = 44 sq units.
the total area of figure 4 = 40 sq units.

Explanation:
In the above-given question,
given that,
the area of rectangle A + rectangle B = figure 1.
area of rectangle A = 15 sq units.
area of rectangle B = 9 sq units.
so the area of figure 1 = 24 sq units.
the area of rectangle C + rectangle D = figure 2.
area of rectangle C = 3 sq units.
area of rectangle D = 8 sq units.
so the area of figure 2 = 24 sq units.
the area of rectangle E + rectangle F = figure 3.
area of rectangle E = 12 sq units.
area of rectangle F = 32 sq units.
so the area of figure 3 = 44 sq units.
the area of rectangle G + rectangle H = figure 4.
area of rectangle G = 15 sq units.
area of rectangle H = 25 sq units.
so the area of figure 4 = 40 sq units.

Question 2.
The figure shows a small rectangle cut out of a big rectangle. Find the area of the shaded figure.

Answer:
The area of the shaded figure = 45 sq cm.

Explanation:
In the above-given question,
given that,
the area of the longer rectangle = 56 sq cm.
area = l x b.
area = 7 x 8.
area = 56 sq cm.
area of smaller rectangle = 9 sq cm.
area = l x b.
area = 3 x 3.
area = 9 sq cm.
area of shaded rectangle = area of the longer rectangle – the area of the smaller rectangle.
area of shaded rectangle = 56 – 9.
area of shaded rectangle = 45 sq cm.

Question 3.
The figure shows a small rectangle cut out of a big rectangle.

a. Label the unknown measurements.

Answer:
The unknown measurements = 3 cm and 4 cm.

Explanation:
In the above-given question,
given that,
the longer rectangle = 9 x 8 = 72 cm.
9 – 6 = 3.
8 – 4 = 4.
so the unknown measurements = 3 cm and 4 cm.

b. Area of the big rectangle:
____9__ cm × ___8___ cm = ___72___ sq cm

Answer:
The area of big rectangle = 72 sq cm.

Explanation:
In the above-given question,
given that,
area of the big rectangle = l x b.
where l = length, and b = breadth.
area = 9 x 8 = 72 sq cm.
so the area of big rectangle = 72 sq cm.

c. Area of the small rectangle:
___3___ cm × ___4___ cm = __12____ sq cm

Answer:
The area of small rectangle = 12 sq cm.

Explanation:
In the above-given question,
given that,
area of the big rectangle = l x b.
where l = length, and b = breadth.
area = 3 x 4 = 12 sq cm.
so the area of small rectangle = 12 sq cm.

d. Find the area of the shaded figure.

Answer:
The area of the shaded figure = 43 sq cm.

Explanation:
In the above-given question,
given that,
area of longer rectangle = 72 sq cm.
area = l x b.
area = 9 x 8.
area = 72 sq cm.
area of smaller rectangle = 12 sq cm.
area = l x b.
area = 3 x 4.
area = 12 sq cm.
area of shaded rectangle = area of longer rectangle – area of smaller rectangle.
area of shaded rectangle = 72 – 12.
area of shaded rectangle = 60 sq cm.

Eureka Math Grade 3 Module 4 Lesson 13 Template Answer Key

Area of A + Area of B: _____32___ sq units + ____20_____ sq units = ___52______ sq units

Answer:
The area of rectangle A and B = 52 sq units.
Explanation:
In the above-given question,
given that,
the area of rectangle A + rectangle B = figure 1.
area of rectangle A = 32 sq units.
area of rectangle B = 20 sq units.
so the area of rectangle A and B = 52 sq units.

Fun learning activities are the best option to educate primary school students and make them understand the basic mathematical concepts like addition, subtraction, multiplication, division, etc. Grade 3 primary school students can find these fun-learning exercises for all math concepts through the Eureka Math Answers Grade 3 Common Core Curriculum.

Engage NY Eureka Math 3rd Grade Module 4 Lesson 12 Answer Key

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Eureka Math Grade 3 Module 4 Lesson 12 Pattern Sheet Answer Key

Multiply

Answer:
7 x 1 = 7, 7 x 2 = 14, 7 x 3 = 21, 7 x 4 = 28, 7 x 5 = 35, 7 x 6 = 42, 7 x 7 = 49, 7 x 8 = 56, 7 x 9 = 63, 7 x 10 = 70, 7 x 5 = 35, 7 x 6 = 42, 7 x 5 = 35, 7 x 7 = 49, 7 x 5 = 35, 7 x 8 = 56, 7 x 5 = 35, 7 x 9 = 63, 7 x 5 = 35, 7 x 10 = 70, 7 x 6 = 42, 7 x 5 = 35, 7 x 6 = 42, 7 x 7 = 49, 7 x 6 = 42, 7 x 8 = 56, 7 x 6 = 42, 7 x 9 = 63, 7 x 6 = 42, 7 x 7 = 49, 7 x 6 = 42, 7 x 7 = 49, 7 x 8 = 56, 7 x 7 = 49, 7 x 9 = 63, 7 x 7 = 49, 7 x 8 = 56, 7 x 6 = 42, 7 x 8 = 56, 7 x 7 = 49, 7 x 8 = 56, 7 x 9 = 63, 7 x 9 = 63, 7 x 6 = 52, 7 x 9 = 63, 7 x 7 = 49, 7 x 9 = 63, 7 x 8 = 56, 7 x 9 = 63, 7 x 8 = 56, 7 x 6 = 42, 7 x 9 = 63, 7 x 7 = 49, 7 x 9 = 63, 7 x 6 = 42, 7 x 8 = 56, 7 x 9 = 63, 7 x 7 = 49, 7 x 6 = 42, 7 x 8 = 56.

Explanation:
In the above-given question,
given that,
multiply with 7.
7 x 1 = 7, 7 x 2 = 14, 7 x 3 = 21, 7 x 4 = 28, 7 x 5 = 35, 7 x 6 = 42, 7 x 7 = 49, 7 x 8 = 56, 7 x 9 = 63, 7 x 10 = 70, 7 x 5 = 35, 7 x 6 = 42, 7 x 5 = 35, 7 x 7 = 49, 7 x 5 = 35, 7 x 8 = 56, 7 x 5 = 35, 7 x 9 = 63, 7 x 5 = 35, 7 x 10 = 70, 7 x 6 = 42, 7 x 5 = 35, 7 x 6 = 42, 7 x 7 = 49, 7 x 6 = 42, 7 x 8 = 56, 7 x 6 = 42, 7 x 9 = 63, 7 x 6 = 42, 7 x 7 = 49, 7 x 6 = 42, 7 x 7 = 49, 7 x 8 = 56, 7 x 7 = 49, 7 x 9 = 63, 7 x 7 = 49, 7 x 8 = 56, 7 x 6 = 42, 7 x 8 = 56, 7 x 7 = 49, 7 x 8 = 56, 7 x 9 = 63, 7 x 9 = 63, 7 x 6 = 52, 7 x 9 = 63, 7 x 7 = 49, 7 x 9 = 63, 7 x 8 = 56, 7 x 9 = 63, 7 x 8 = 56, 7 x 6 = 42, 7 x 9 = 63, 7 x 7 = 49, 7 x 9 = 63, 7 x 6 = 42, 7 x 8 = 56, 7 x 9 = 63, 7 x 7 = 49, 7 x 6 = 42, 7 x 8 = 56.

Eureka Math Grade 3 Module 4 Lesson 12 Problem Set Answer Key

Question 1.
Each side on a sticky note measures 9 centimeters. What is the area of the sticky note?

Answer:
The area of sticky notes = 81 sq cm.

Explanation:
In the above-given question,
given that,
the area of the sticky notes = 81 sq cm.
area = l x b.
where l = length, and b = breadth.
area = 9 x 9.
area = 81.
so the area of the sticky notes = 81 sq cm.

Question 2.
Stacy tiles the rectangle below using her square pattern blocks.

a. Find the area of Stacy’s rectangle in square units. Then, draw and label a different rectangle with whole number side lengths that has the same area.

Answer:
The area of the stacky tiles = 12 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = length, b = breadth.
area = l x b.
area = 3 x 4.
area = 12 sq units.
so the area of the stacky tiles = 12 sq units.

b. Can you draw another rectangle with different whole number side lengths and have the same area? Explain how you know.

Answer:
The area of the rectangle = 12 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = length, b = breadth.
area = l x b.
area = 2 x 6.
area = 12 sq units.
so the area of the other rectangle = 12 sq units.

Question 3.
An artist paints a 4 foot × 16 foot mural on a wall. What is the total area of the mural? Use the break apart and distribute strategy.

Answer:
The area of the mural on a wall = 64 sq ft.

Explanation:
In the above-given question,
given that,
An artist paints a 4-foot x 16 foot mural on a wall.
area = 4 x 16.
area = 4 x ( 10 + 6 ).
area = ( 4 x 10 ) + 6.
area = 40 + 6.
area = 46.
so the area of the mural on a wall = 64 sq ft.

Question 4.
Alana tiles the 3 figures below. She says, “I’m making a pattern!”

a. Find the area of Alana’s 3 figures and explain her pattern.

Answer:
The area of the square 1 = 4 sq units.
the area of the square 2 = 9 sq units.
the area of the square 3 = 16 sq units.

Explanation:
In the above-given question,
given that,
Alana tiles the 3 figures.
the area of the square 1 = 4 sq units.
area = l x b.
where l = length, b = breadth.
area = 2 x 2.
area = 4.
the area of the square 2 = 9 sq units.
area = l x b.
area = 3 x 3.
area = 9.
the area of the square 3 = 16 sq units.
area = l x b.
area = 4 x 4.
area = 16.

b. Draw the next 2 figures in Alana’s pattern and find their areas.

Answer:
The area of square 1 = 25 sq units.
the area of square 2 = 36 sq units.

Explanation:
In the above-given question,
given that,
Alana tiles the 3 figures.
the area of the square 1 = 25 sq units.
area = l x b.
where l = length, b = breadth.
area = 5 x 5.
area = 25.
the area of the square 2 = 36 sq units.
area = l x b.
area = 6 x 6.
area = 36.

Question 5.
Jermaine glues 3 identical pieces of paper as shown below and makes a square. Find the unknown side length of 1 piece of paper. Then, find the total area of 2 pieces of paper.

Answer:
The unknown side length of 1 piece of paper = 3 cm.

Explanation:
In the above-given question,
given that,
Jermaine glues 3 identical pieces of paper as shown below and makes a square.
area of the rectangle = 3 x 3cm.
area = 3 x 3.
area = 9 cm.
so the unknown side length of 1 piece of paper = 3 cm.

Eureka Math Grade 3 Module 4 Lesson 12 Exit Ticket Answer Key

Question 1.
A painting has an area of 63 square inches. One side length is 9 inches. What is the other side length?

Answer:
The other side length of the rectangle = 7 inches.

Explanation:
In the above-given question,
given that,
A painting has an area of 63 square inches.
one side length is 9 inches.
area of the rectangle is given.
63 = l x b.
l = 9 inches.
63 = 9 x b.
b = 63 / 9.
b = 7 inches.
so the other side length of the rectabgle = 7 inches.

Question 2.
Judy’s mini dollhouse has one floor and measures 4 inches by 16 inches. What is the total area of the dollhouse floor?

Answer:
The total area of the dollhouse floor = 64 sq inches.

Explanation:
In the above-given question,
given that,
Judy’s mini dollhoue has one floor and measures 4 inches by 16 inches.
area = l x b.
where l = length, and b = breadth.
area = 4 x 16.
area = 64 sq inches.

Eureka Math Grade 3 Module 4 Lesson 12 Homework Answer Key

Question 1.
A square calendar has sides that are 9 inches long. What is the calendar’s area?

Answer:
The area of the square calendar = 81 sq inches.

Explanation:
In the above-given question,
given that,
A square calendar has sides that are 9 inches long.
area = l x b.
where l = length and b = breadth.
area = 9 x 9 = 81 sq inches.
so the area of the square calendar = 81 sq inches.

Question 2.
Each is 1 square unit. Sienna uses the same square units to draw a 6 × 2 rectangle and says that it has the same area as the rectangle below. Is she correct? Explain why or why not.

Answer:
Yes, she was correct.

Explanation:
In the above-given question,
given that,
Sienna uses the same square units to draw a 6 x 2 rectangle.
area of the given rectangle = 12 sq units.
area = 4 x 3.
area = 12 sq units.
area of Sienna’s rectangle = 12 sq units.
area = 6 x 2.
area = 12 sq units.

Question 3.
The surface of an office desk has an area of 15 square feet. Its length is 5 feet. How wide is the office desk?

Answer:
The width of the office desk = 3 feet.

Explanation:
In the above-given question,
given that,
The surface of an office desk has an area of 15 square feet.
Its length is 5 feet.
area = l x w.
15 = 5 x w.
w = 15 / 5.
w = 3 feet.
so the width of the office desk = 3 feet.

Question 4.
A rectangular garden has a total area of 48 square yards. Draw and label two possible rectangular gardens with different side lengths that have the same area.

Answer:
The side lengths of the rectangular garden 1 = 6 x 8 yards.
The side lengths of the rectangular garden 2 = 12 x 4 yards.

Explanation:
given that,
A rectangular garden 1 has a total area of 48 square yards.
area = l x b.
where l = length and b = breadth.
area = 6 x 8 = 48 sq yards.
so the area of the rectangular garden 1 = 48 sq yards.
A rectangular garden 2 has a total area of 48 square yards.
area = l x b.
where l = length and b = breadth.
area = 12 x 4 = 48 sq yards.
so the area of the rectangular garden 2 = 48 sq yards

Question 5.
Lila makes the pattern below. Find and explain her pattern. Then, draw the fifth figure in her pattern

Answer:
The area of the square 1 = 2 sq units.
the area of the square 2 = 4 sq units.
the area of the square 3 = 6 sq units.

Explanation:
In the above-given question,
given that,
Alana tiles the 3 figures.
the area of the square 1 = 2 sq units.
area = l x b.
where l = length, b = breadth.
area = 1 x 2.
area = 2.
the area of the square 2 = 4 sq units.
area = l x b.
area = 2 x 2.
area = 4.
the area of the square 3 = 6 sq units.
area = l x b.
area = 3 x 2.
area = 6.

Fun learning activities are the best option to educate primary school students and make them understand the basic mathematical concepts like addition, subtraction, multiplication, division, etc. Grade 3 primary school students can find these fun-learning exercises for all math concepts through the Eureka Math Answers Grade 3 Common Core Curriculum.

Engage NY Eureka Math 3rd Grade Module 4 Lesson 11 Answer Key

You may have diverse opportunities to develop math skills and problem-solving skills but practicing with Eureka Math 3rd Grade Answer Key for better and efficient learning. Eureka Math Grade 3 provided Free Access Student Edition of Eureka Math Grade 3 Answers are enough to practice more and get a good grip on the subject. The diverse opportunities will develop problem-solving skills among the primary school kids Practising.

Eureka Math Grade 3 Module 4 Lesson 11 Problem Set Answer Key

Question 1.
The rectangles below have the same area. Move the parentheses to find the unknown side lengths. Then, solve.
a.

Area: 8 × __6____ = __48____
Area: ___48___ sq cm

Answer:
The area of the rectangle = 48 sq cm.

Explanation:
In the above-given question,
given that,
The area of the rectangle = l x b.
where l = length, b = breadth.
area = 6 x 8 = 48.
area of the rectangle = 48 sq cm.

b.

Area: 1 × 48 = __( 1_x_6)_x 8
Area: __48____ sq cm

Answer:
The area of the rectangle = 48 sq cm.

Explanation:
In the above-given question,
given that,
The area of the rectangle = l x b.
where l = length, b = breadth.
area = 48 x 1 = 48.
area of the rectangle = 48 sq cm.

c.

Area: 8 × 6 = (2 × 4) × 6
= 2 × 4 × 6
= __8____ × __6____
= __48____
Area: __48____ sq cm

Answer:
The area of the rectangle = 48 sq cm.

Explanation:
In the above-given question,
given that,
The area of the rectangle = l x b.
where l = length, b = breadth.
area = 8 x 6 = 48.
area = 8 x 6 = (2 x 4) x 6.
2 x ( 4 x 6).
2 x 24.
area of the rectangle = 48 sq cm.

d.

Area: 8 × 6 = (4 × 2) × 6
= 4 × 2 × 6
= ___4___ × ___12___
= __48____
Area: ___48___ sq cm

Answer:
The area of the rectangle = 48 sq cm.

Explanation:
In the above-given question,
given that,
The area of the rectangle = l x b.
where l = length, b = breadth.
area = 8 x 6 = 48.
area = 8 x 6 = (4 x 2) x 6.
area = 4 x 12.
area of the rectangle = 48 sq cm.

e.

Area: 8 × 6 = 8 × (2 × 3)
= 8 × 2 × 3
= __16____ × ___3__
= ___48___
Area: ___48___ sq cm

Answer:
The area of the rectangle = 48 sq cm.

Explanation:
In the above-given question,
given that,
The area of the rectangle = l x b.
where l = length, b = breadth.
area = 8 x 6 = 48.
area = 8 x 6 = (8 x 2) x 3.
area = 16 x 3.
area of the rectangle = 48 sq cm.

Question 2.
Does Problem 1 show all the possible whole number side lengths for a rectangle with an area of 48 square centimeters? How do you know?

Answer:
The area of the rectangle = 48 sq cm.

Explanation:
In the above-given question,
given that,
The area of the rectangle = l x b.
where l = length, b = breadth.
area = 8 x 6 = 48.
area = 8 x 6 = (4 x 2) x 6.
area = 4 x 12.
area of the rectangle = 48 sq cm.

Question 3.
In Problem 1, what happens to the shape of the rectangle as the difference between the side lengths gets smaller?

Answer:
The area of the rectangle also decreases= 48 sq cm.

Explanation:
In the above-given question,
given that,
The area of the rectangle = l x b.
where l = length, b = breadth.
area = 8 x 6 = 48.
area = 8 x 6 = (4 x 2) x 6.
area = 4 x 12.
area of the rectangle = 48 sq cm.

Question 4.
a. Find the area of the rectangle below.

Answer:
The area of the rectangle = 72 sq cm.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length, b = breadth.
l = 8 cm and b = 9 cm given.
area = l x b.
area = 8 x 9.
area = 72 sq cm.

b. Julius says a 4 cm by 18 cm rectangle has the same area as the rectangle in Part (a). Place parentheses in the equation to find the related fact and solve. Is Julius correct? Why or why not?
4 × 18 = 4 × 2 × 9
= 4 × 2 × 9
= ___8___ × __9____
= __72____
Area: __72___ sq cm

Answer:
Yes, Julius was correct.

Explanation:
In the above-given question,
given that,
The area of the rectangle = l x b.
where l = length, b = breadth.
area = 4 x 18 = 72.
area = 4 x 18 = (4 x 2) x 9.
area = 8 x 9.
area of the rectangle = 72 sq cm.

c. Use the expression 8 × 9 to find different side lengths for a rectangle that has the same area as the rectangle in Part (a). Show your equations using parentheses. Then, estimate to draw the rectangle and label the side lengths.

Answer:
The area of the rectangle = 72 sq cm.

Explanation:
In the above-given question,
given that,
The area of the rectangle = l x b.
where l = length, b = breadth.
area = 8 x 9 = 72.
area = 8 x 9 = (4 x 2) x 9.
area = 4 x 18.
area of the rectangle = 72 sq cm.

Eureka Math Grade 3 Module 4 Lesson 11 Exit Ticket Answer Key

Question 1.
Find the area of the rectangle.

Answer:
The area of the rectangle = 64 sq cm.

Explanation:
In the above-given question,
given that,
The area of the rectangle = l x b.
where l = length, b = breadth.
area = 8 x 8 = 64.
area = 8 x 8 = (4 x 2) x 8.
area = 4 x 16.
area of the rectangle = 64 sq cm.

Question 2.
The rectangle below has the same area as the rectangle in Problem 1. Move the parentheses to find the unknown side lengths. Then, solve.

Area: 8 × 8 = (4 × 2) × 8
= 4 × 2 × 8
= __8____ × __8____
= __64____
Area: __64____ sq cm

Answer:
The area of the rectangle = 64 sq cm.

Explanation:
In the above-given question,
given that,
The area of the rectangle = l x b.
where l = length, b = breadth.
area = 8 x 8 = 64.
area = 8 x 8 = (4 x 2) x 8.
area = 4 x 16.
area of the rectangle = 64 sq cm.

Eureka Math Grade 3 Module 4 Lesson 11 Homework Answer Key

Question 1.
The rectangles below have the same area. Move the parentheses to find the unknown side lengths.
Then, solve.
a.

Area: 4 × ___9___ = ___36___
Area: __36____ sq cm

Answer:
The area of the rectangle = 36 sq cm.

Explanation:
In the above-given question,
given that,
The area of the rectangle = l x b.
where l = length, b = breadth.
area = 4 x 9 = 36.
area = 4 x 9 = (4 x 3) x 3.
area = 4 x 9.
area of the rectangle = 36 sq cm.

b.

Area: 1 × 36 = __36____
Area: ___36___ sq cm

Answer:
The area of the rectangle = 36 sq cm.

Explanation:
In the above-given question,
given that,
The area of the rectangle = l x b.
where l = length, b = breadth.
area = 1 x 36 = 36.
area = 1 x 36 = (1 x 6) x 6.
area = 6 x 6.
area of the rectangle = 36 sq cm.

c.

Area: 4 × 9 = (2 × 2) × 9
= 2 × 2 × 9
= __4____ × __9____
= ___36___
Area: __36____ sq cm

Answer:
The area of the rectangle = 36 sq cm.

Explanation:
In the above-given question,
given that,
The area of the rectangle = l x b.
where l = length, b = breadth.
area = 4 x 9 = 36.
area = 4 x 9 = (4 x 3) x 3.
area = 12 x 3.
area of the rectangle = 36 sq cm.

d.

Area: 4 × 9 = 4 × (3 × 3)
= 4 × 3 × 3
= ___12___ × __3____
= ___36___
Area: ___36___ sq cm

Answer:
The area of the rectangle = 36 sq cm.

Explanation:
In the above-given question,
given that,
The area of the rectangle = l x b.
where l = length, b = breadth.
area = 4 x 9 = 36.
area = 4 x 9 = (4 x 3) x 3.
area = 12 x 3.
area of the rectangle = 36 sq cm.

e.

Area: 12 × 3 = (6 × 2) × 3
= 6 × 2 × 3
= ___6___ × __6____
= __36____
Area: ___36___ sq cm

Answer:
The area of the rectangle = 36 sq cm.

Explanation:
In the above-given question,
given that,
The area of the rectangle = l x b.
where l = length, b = breadth.
area = 12 x 3 = 48.
area = 12 x 3 = (6 x 2) x 3.
area = 12 x 3.
area of the rectangle = 36 sq cm.

Question 2.
Does Problem 1 show all the possible whole number side lengths for a rectangle with an area of 36 square centimeters? How do you know?

Answer:
The area of the rectangle = 36 sq cm.

Explanation:
In the above-given question,
given that,
The area of the rectangle = l x b.
where l = length, b = breadth.
area = 6 x 6 = 36.
area = 6 x 6 = (6 x 2) x 3.
area = 12 x 3.
area of the rectangle = 36 sq cm.

Question 3.
a. Find the area of the rectangle below.

Answer:
The area of the rectangle = 48 sq cm.

Explanation:
In the above-given question,
given that,
The area of the rectangle = l x b.
where l = length, b = breadth.
area = 6 x 8 = 48.
area of the rectangle = 48 sq cm.

b. Hilda says a 4 cm by 12 cm rectangle has the same area as the rectangle in Part (a). Place parentheses in the equation to find the related fact and solve. Is Hilda correct? Why or why not?
4 × 12 = 4 × 2 × 6
= 4 × 2 × 6
= __8____ × __6____
= ___48___
Area: __48____ sq cm

Answer:
The area of the rectangle = 48 sq cm.

Explanation:
In the above-given question,
given that,
The area of the rectangle = l x b.
where l = length, b = breadth.
area = 4 x 12 = 48.
area = 4 x 12 = (4 x 2) x 6.
area = 8 x 6.
area of the rectangle = 48 sq cm.

c. Use the expression 8 × 6 to find different side lengths for a rectangle that has the same area as the rectangle in Part (a). Show your equations using parentheses. Then, estimate to draw the rectangle and label the side lengths.

Answer:
The area of the rectangle = 48 sq cm.

Explanation:
In the above-given question,
given that,
The area of the rectangle = l x b.
where l = length, b = breadth.
area = 4 x 12 = 48.
area = 4 x 12 = (4 x 2) x 6.
area = 8 x 6.
area of the rectangle = 48 sq cm.

Eureka Math Answer Key for Grade 3 aids teachers to differentiate instruction, building, and reinforcing foundational mathematics skills that alter from the classroom to real life.
With the help of the Eureka Primary School Grade 3 Answer Key, You can think deeply regarding what you are learning, and you will really learn math easily just like that. So teachers and students can find this Eureka Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students.

Engage NY Eureka Math 3rd Grade Module 4 Lesson 10 Answer Key

Students of Grade 3 can get a strong foundation on mathematics concepts by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka’s Math Grade 3 Book.

Eureka Math Grade 3 Module 4 Lesson 10 Problem Set Answer Key

Question 1.
Label the side lengths of the shaded and unshaded rectangles when needed. Then, find the total area of the large rectangle by adding the areas of the two smaller rectangles.
a.

8 × 7 = (5 + 3) × 7
= (5 × 7) + (3 × 7)
= ___35___ + ___21___
= __56____
Area: ___56___ square units

Answer:
The area of the larger rectangle = 56 sq unit.
the area of the small rectangle A = 35 sq unit.
the area of the small rectangle B = 21 sq unit.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 56 sq unit.
area = length x breadth.
area = l x b.
area = 8 x 7.
area = 56.
the area of the rectangle A = 35 sq unit.
area = length x breadth.
area = l x b.
area = 5 x 7.
area = 35.
the area of the rectangle B = 21 sq unit.
area = length x breadth.
area = l x b.
area = 3 x 7.
area = 21.

b.

12 × 4 = (___10___ + 2) × 4
= (__10____ × 4) + (2 × 4)
= ___40___ + 8
= ___48___
Area: __48____ square units

Answer:
The area of the larger rectangle = 48 sq unit.
the area of the small rectangle A = 40 sq unit.
the area of the small rectangle B = 8 sq unit.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 48 sq unit.
area = length x breadth.
area = l x b.
area = 12 x 4.
area = 48.
the area of the rectangle A = 40 sq unit.
area = length x breadth.
area = l x b.
area = 10 x 4.
area = 40.
the area of the rectangle B = 8 sq unit.
area = length x breadth.
area = l x b.
area = 2 x 4.
area = 8.

c.

6 × 13 = 6 × (___10___ + 3)
= (6 ×___10___) + (6 × 3)
= __60____ + ___18___
= ___78___
Area: __78____ square units

Answer:
The area of the larger rectangle = 78 sq unit.
the area of the small rectangle A = 60 sq unit.
the area of the small rectangle B = 18 sq unit.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 78 sq unit.
area = length x breadth.
area = l x b.
area = 6 x 13.
area = 78.
the area of the rectangle A = 60 sq unit.
area = length x breadth.
area = l x b.
area = 10 x 6.
area = 60.
the area of the rectangle B = 8 sq unit.
area = length x breadth.
area = l x b.
area = 6 x 3.
area = 18.

d.

8 × 12 = 8 × (___10___ + ___2___)
= (8 × __10____) + (8 × ___2___)
= ___80___ + __16____
= __96____
Area: __96____ square units

Answer:
The area of the larger rectangle = 96 sq unit.
the area of the small rectangle A = 80 sq unit.
the area of the small rectangle B = 16 sq unit.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 96 sq unit.
area = length x breadth.
area = l x b.
area = 8 x 12.
area = 96.
the area of the rectangle A = 80 sq unit.
area = length x breadth.
area = l x b.
area = 10 x 8.
area = 80.
the area of the rectangle B = 16 sq unit.
area = length x breadth.
area = l x b.
area = 8 x 2.

Question 2.
Vince imagines 1 more row of eight to find the total area of a 9 × 8 rectangle. Explain how this could help him solve 9 × 8.

Answer:
The area of the rectangle = 72 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = length and b = breadth.
area = 9 x 8.
area = 72 sq cm.
so the area of the rectangle = 72 sq cm.

Question 3.
Break the 15 × 5 rectangle into 2 rectangles by shading one smaller rectangle within it. Then, find the sum of the areas of the 2 smaller rectangles and show how it relates to the total area. Explain your thinking.

Answer:
The area of the rectangle = 40 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = length and b = breadth.
area = 5 x 8.
area = 40 sq cm.
so the area of the rectangle = 40 sq cm.

Answer:
The area of the rectangle = 35 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = length and b = breadth.
area = 5 x 7.
area = 35 sq cm.
so the area of the rectangle = 35 sq cm.

Eureka Math Grade 3 Module 4 Lesson 10 Exit Ticket Answer Key

Label the side lengths of the shaded and unshaded rectangles. Then, find the total area of the large rectangle by adding the areas of the 2 smaller rectangles.

Question 1.

8 × 7 = 8 × (___5___ + __2____)
= (8 ×___5___) + (8 ×___2___)
= __40____ + __16____
= ___56___
Area: __56____ square units

Answer:
The area of the larger rectangle = 56 sq unit.
the area of the small rectangle A = 40 sq unit.
the area of the small rectangle B = 16 sq unit.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 56 sq unit.
area = length x breadth.
area = l x b.
area = 8 x 7.
area = 56.
the area of the rectangle A = 40 sq unit.
area = length x breadth.
area = l x b.
area = 8 x 5.
area = 40.
the area of the rectangle B = 16 sq unit.
area = length x breadth.
area = l x b.
area = 8 x 2.
area = 16.

Question 2.

9 × 13 = 9 × (___10___+___3___)
= (___9___ × ___10___) + (__9____×___3___)
= __90____ + ___27___
= __117____
Area: ___117___ square units

Answer:
The area of the larger rectangle = 117 sq unit.
the area of the small rectangle A = 90 sq unit.
the area of the small rectangle B = 27 sq unit.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 117 sq unit.
area = length x breadth.
area = l x b.
area = 9 x 13.
area = 117.
the area of the rectangle A = 90 sq unit.
area = length x breadth.
area = l x b.
area = 9 x 10.
area = 90.
the area of the rectangle B = 27 sq unit.
area = length x breadth.
area = l x b.
area = 9 x 3.
area = 27.

Eureka Math Grade 3 Module 4 Lesson 10 Homework Answer Key

Question 1.
Label the side lengths of the shaded and unshaded rectangles. Then, find the total area of the large rectangle by adding the areas of the 2 smaller rectangles.
a.

9 × 8 = (5 + 4) × 8
= (5 × 8) + (4 × 8)
= ___40___ + __32____
= __72____
Area: ___72___ square units

Answer:
The area of the larger rectangle = 72 sq unit.
the area of the small rectangle A = 40 sq unit.
the area of the small rectangle B = 32 sq unit.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 78 sq unit.
area = length x breadth.
area = l x b.
area = 9 x 8.
area = 72.
the area of the rectangle A = 40 sq unit.
area = length x breadth.
area = l x b.
area = 5 x 8.
area = 40.
the area of the rectangle B = 32 sq unit.
area = length x breadth.
area = l x b.
area = 4 x 8.
area = 32.

b.

12 × 5 = (__10____ + 2) × 5
= (___10___ × 5) + (2 × 5)
= ___50___ + 10
= ___60___
Area: __60____ square units

Answer:
The area of the larger rectangle = 60 sq unit.
the area of the small rectangle A = 50 sq unit.
the area of the small rectangle B = 10 sq unit.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 60 sq unit.
area = length x breadth.
area = l x b.
area = 12 x 5.
area = 60.
the area of the rectangle A = 50 sq unit.
area = length x breadth.
area = l x b.
area = 10 x 5.
area = 50.
the area of the rectangle B = 10 sq unit.
area = length x breadth.
area = l x b.
area = 2 x 5.
area = 10.

c.

7 × 13 = 7 × (___10___+ 3)
= (7 × ___10___) + (7 × 3)
= __70____ + __21____
= __91____
Area: __91____ square units

Answer:
The area of the larger rectangle = 91 sq unit.
the area of the small rectangle A = 70 sq unit.
the area of the small rectangle B = 21 sq unit.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 91 sq unit.
area = length x breadth.
area = l x b.
area = 7 x 13.
area = 91.
the area of the rectangle A = 70 sq unit.
area = length x breadth.
area = l x b.
area = 7 x 10.
area = 70.
the area of the rectangle B = 21 sq unit.
area = length x breadth.
area = l x b.
area = 7 x 3.
area = 21.

d.

9 × 12 = 9 × (___10___ + __2____)
= (9 × ___10___) + (9 × __2____)
= __90____ + ___18___
= __108____
Area: __108____ square units

Answer:
The area of the larger rectangle = 108 sq unit.
the area of the small rectangle A = 90 sq unit.
the area of the small rectangle B = 18 sq unit.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 108 sq unit.
area = length x breadth.
area = l x b.
area = 9 x 12.
area = 108.
the area of the rectangle A = 90 sq unit.
area = length x breadth.
area = l x b.
area = 9 x 10.
area = 90.
the area of the rectangle B = 18 sq unit.
area = length x breadth.
area = l x b.
area = 9 x 2.
area = 18.

Question 2.
Finn imagines 1 more row of nine to find the total area of 9 × 9 rectangle. Explain how this could help him solve 9 × 9.

Answer:
The area of the rectangle = 81 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = length and b = breadth.
area = 9 x 9.
area = 81 sq cm.
so the area of the rectangle = 81 sq cm.

Question 3.
Shade an area to break the 16 × 4 rectangle into 2 smaller rectangles. Then, find the sum of the areas of the 2 smaller rectangles to find the total area. Explain your thinking.

Answer:
The area of the rectangle = 40 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = length and b = breadth.
area = 10 x 4.
area = 40 sq cm.
so the area of the rectangle = 40 sq cm.

Answer:
The area of the rectangle = 24 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = length and b = breadth.
area = 6 x 4.
area = 24 sq cm.
so the area of the rectangle = 24 sq cm.

Eureka Math Grade 3 Module 4 Lesson 10 Template Answer Key

____24__sq__cm______
tiling
Answer:
The area of the rectangle = 16 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 4.
area = 16 sq cm.
so the area of the rectangle = 16 sq cm.

Answer:
The area of the rectangle = 8 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 2.
area = 8 sq cm.
so the area of the rectangle = 8 sq cm.

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Engage NY Eureka Math 3rd Grade Module 4 Lesson 9 Answer Key

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Eureka Math Grade 3 Module 4 Lesson 9 Problem Set Answer Key

Question 1.
Cut the grid into 2 equal rectangles.
a. Draw and label the side lengths of the 2 rectangles.

Answer:
The side lengths of the two rectangles = 4 x 4 and 4 x 4.

Explanation:
In the above-given question,
given that,
cut the grid into two equal rectangles.
area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 4.
area = 16.
so the side lengths of 2 rectangles = 4 x 4.

b. Write an equation to find the area of 1 of the rectangles.

Answer:
The area of the 1 of the rectangle = length x breadth.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = l x b.

c. Write an equation to show the total area of the 2 rectangles.

Answer:
The total area of the 2 rectangles = 16 sq cms.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 4.
area = 16.

Question 2.
Place your 2 equal rectangles side by side to create a new, longer rectangle.
a. Draw an area model to show the new rectangle. Label the side lengths.

Answer:

The side lengths of the two rectangles = 4 cm x 8 cm.

Explanation:
In the above-given question,
given that,
cut the grid into two equal rectangles.
area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 8.
area = 32.
so the side lengths of 2 rectangles = 4 x 8.

b. Find the total area of the longer rectangle.

Answer:
The total area of the longer rectangle = 32 sq cms.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 8.
area = 32 sq cms.

Question 3.
Furaha and Rahema use square tiles to make the rectangles shown below.

a. Label the side lengths on the rectangles above, and find the area of each rectangle.

Answer:
The side length of the Rahema rectangle = 4 cms x 6 cms.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 6.
area = 24.

Answer:
The side length of the Rahema rectangle = 4 cms x 7 cms.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 7.
area = 28.

b. Furaha pushes his rectangle next to Rahema’s rectangle to form a new, longer rectangle. Draw an area model to show the new rectangle. Label the side lengths.

Answer:
The side length of the Rahema rectangle = 4 cms x 8 cms.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 8.
area = 32.

c. Rahema says the area of the new, longer rectangle is 52 square units. Is she right? Explain your answer.

Answer:
No, she was not correct.

Explanation:

given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 8.
area = 32.
so the area of the rectangle = 32 sq units.

Question 4.
Kiera says she can find the area of the long rectangle below by adding the areas of Rectangles A and B. Is she right? Why or why not?

Answer:
Yes, she was correct.

Explanation:
In the above-given question,
given that,
Kiera says that she can find the area of the long rectangle below by adding the areas of the rectangles A and B.
area = l x b.
area of the rectangles A + B = rectangle C.
so she was correct.

Eureka Math Grade 3 Module 4 Lesson 9 Exit Ticket Answer Key

Lamar uses square tiles to make the 2 rectangles shown below.

Question 1.
Label the side lengths of the 2 rectangles.

Answer:
The side lengths of rectangle A = 6 cm x 6 cm.
the side lengths of  rectangle B = 6 cm x 3 cm.

Explanation:
In the above-given question,
given that,
area of the rectangle A = l x b.
where l = length and b = breadth.
area = 6 x 6.
area of the rectangle B = l x b.
where l = length and b = breadth.
area = 6 x 3.

Question 2.
Write equations to find the areas of the rectangles.
Area of Rectangle A: ______36_sq__cm______
Area of Rectangle B: ___18__sq__cm________

Answer:
The area of rectangle A = 36 sq cm.
the area of rectangle B = 18 sq cm.

Explanation:
In the above-given question,
given that,
area of the rectangle A = l x b.
where l = length and b = breadth.
area = 6 x 6.
area = 36 sq cm.
area of the rectangle B = l x b.
where l = length and b = breadth.
area = 6 x 3.
area = 18 sq cm.

Question 3.
Lamar pushes Rectangle A next to Rectangle B to make a bigger rectangle. What is the area of the bigger rectangle? How do you know?

Answer:
The area of the bigger rectangle = 6 cms x 9 cms.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 6 x 9.
area = 54.
so the area of the bigger rectangle = 54 sq cms.

Eureka Math Grade 3 Module 4 Lesson 9 Homework Answer Key

Question 1.
Use the grid to answer the questions below.

a. Draw a line to divide the grid into 2 equal rectangles. Shade in 1 of the rectangles that you created.

Answer:
The area of the rectangle = 32 sq cms.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 8 x 4.
area = 32 sq cm.

b. Label the side lengths of each rectangle.

Answer:
The side lengths of rectangle A = 8 cm x 4 cm.
the side lengths of rectangle B = 8 cm x 4 cm.

Explanation:
In the above-given question,
given that,
area of the rectangle A = l x b.
where l = length and b = breadth.
area = 8 x 4.
area = 32 sq cm.
area of the rectangle B = l x b.
where l = length and b = breadth.
area = 8 x 4.
area = 32 sq cm.

c. Write an equation to show the total area of the 2 rectangles.

Answer:
The area of rectangle A = 32 sq cm.
the area of rectangle B = 32 sq cm.

Explanation:
In the above-given question,
given that,
area of the rectangle A = l x b.
where l = length and b = breadth.
area = 8 x 4.
area = 32 sq cm.
area of the rectangle B = l x b.
where l = length and b = breadth.
area = 8 x 4.
area = 32 sq cm.

Question 2.
Alexa cuts out the 2 equal rectangles from Problem 1(a) and puts the two shorter sides together.
a. Draw Alexa’s new rectangle and label the side lengths below.

Answer:
The side lengths of the new rectangle = 4 cm x 4cm.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 4.
area = 16 sq cm.

b. Find the total area of the new, longer rectangle.

Answer:
The area of the new rectangle = 16 sq cm.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 4.
area = 16 sq cm.

c. Is the area of the new, longer rectangle equal to the total area in Problem 1(c)? Explain why or why not.

Answer:
No, the longer rectangle does not equal the total area in the problem.

Explanation:
In the above-given question,
given that,
the area of the longer rectangle = l x b.
where l = length and b = breadth.
area = 4 x 4.
area = 16 sq cm.

Eureka Math Grade 3 Module 4 Lesson 9 Template Answer Key

________64_sq_cm.____
small centimeter grid

Answer:
The area of the rectangle = 64 sq cm.

Explanation:

given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 8 x 8.
area = 64.
so the area of the rectangle = 64 sq cm.

Teachers and students can find this Eureka Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Eureka Math Answer Key for Grade 3 aids teachers to differentiate instruction, building and reinforcing foundational mathematics skills that alter from the classroom to real life. With the help of Eureka’s primary school Grade 3 Answer Key, you can think deeply regarding what you are learning, and you will really learn math easily just like that.

Engage NY Eureka Math 3rd Grade Module 4 Lesson 8 Answer Key

Students of Grade 3 Module 4 can get a strong foundation on mathematics concepts by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka’s Grade 3 Textbook.

Eureka Math Grade 3 Module 4 Lesson 8 Pattern Sheet Answer Key

Multiply

Answer:
6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 6 x 9 = 54, 6 x 10 = 60, 6 x 5 = 30, 6 x 6 = 36, 6 x 5 = 30, 6 x 7 = 42, 6 x 5 = 30, 6 x 8 = 48, 6 x 5 = 30, 6 x 9 = 54, 6 x 5 = 30, 6 x 10 = 60, 6 x 6 = 36, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 6 = 36, 6 x 8 = 48, 6 x 6 = 36, 6 x 9 = 54, 6 x 6 = 36, 6 x 7 = 42, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 6 x 7 = 42, 6 x 9 = 54, 6 x 7 = 42, 6 x 8 = 48, 6 x 6 = 36, 6 x 8 = 48, 6 x 7 = 42, 6 x 8 = 48, 6 x 9 = 54, 6 x 9 = 54, 6 x 6 = 36, 6 x 9 = 54, 6 x 7 = 42, 6 x 9 = 54, 6 x 8 = 48, 6 x 9 = 54, 6 x 8 = 48, 6 x 6 = 36, 6 x 9 = 54, 6 x 7 = 42, 6 x 9 = 54, 6 x 6 = 36, 6 x 8 = 48, 6 x 9 = 54, 6 x 7 = 42, 6 x 6 = 36, 6 x 8 = 48.

Explanation:
In the above-given question,
given that,
multiply with 6.
6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 6 x 9 = 54, 6 x 10 = 60, 6 x 5 = 30, 6 x 6 = 36, 6 x 5 = 30, 6 x 7 = 42, 6 x 5 = 30, 6 x 8 = 48, 6 x 5 = 30, 6 x 9 = 54, 6 x 5 = 30, 6 x 10 = 60, 6 x 6 = 36, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 6 = 36, 6 x 8 = 48, 6 x 6 = 36, 6 x 9 = 54, 6 x 6 = 36, 6 x 7 = 42, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 6 x 7 = 42, 6 x 9 = 54, 6 x 7 = 42, 6 x 8 = 48, 6 x 6 = 36, 6 x 8 = 48, 6 x 7 = 42, 6 x 8 = 48, 6 x 9 = 54, 6 x 9 = 54, 6 x 6 = 36, 6 x 9 = 54, 6 x 7 = 42, 6 x 9 = 54, 6 x 8 = 48, 6 x 9 = 54, 6 x 8 = 48, 6 x 6 = 36, 6 x 9 = 54, 6 x 7 = 42, 6 x 9 = 54, 6 x 6 = 36, 6 x 8 = 48, 6 x 9 = 54, 6 x 7 = 42, 6 x 6 = 36, 6 x 8 = 48.

Eureka Math Grade 3 Module 4 Lesson 8 Problem Set Answer Key

Question 1.
Write a multiplication equation to find the area of each rectangle.
a.

__7_____ × ____4___ = ___28_sqft___

Answer:
The area of the rectangle = 28 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 7.
area = 4 x 7.
area = 28.

b.

__8_____ × ____7___ = ___56___

Answer:
The area of the rectangle = 56 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 8 and b = 7.
area = 8 x 7.
area = 56.

c.

___6____ × ___6____ = ___36___

Answer:
The area of the rectangle = 36 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 6.
area = 6 x 6.
area = 36.

Question 2.
Write a multiplication equation and a division equation to find the unknown side length for each rectangle.

a.

___9____ × __8_____ = __72____
____72___ ÷ __9_____ = ___8____

Answer:
The unknown side length of the rectangle = 8 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 72 and b = 8.
72 = l x 8.
l = 8 x 9 = 72.
l = 72/9 = 8.

b.

___5____ × ___3____ = ___15___
___15____ ÷ ____5___ = ___3____

Answer:
The unknown side length of the rectangle = 5 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 15 and b = 3.
15 = l x 3.
l = 15 / 3 = 5.

c.

___4____ × ____7___ = ___28___
___28____ ÷ ____4___ = ___7____

Answer:
The unknown side length of the rectangle = 7 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 28 and l = 4.
28 = b x 4.
b = 28 / 4 = 7.

Question 3.
On the grid below, draw a rectangle that has an area of 42 square units. Label the side lengths.

Answer:
The area of the rectangle = 42 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 42 and b = 6.
42 = l x 6.
l = 42 / 6 = 7.

Question 4.
Ursa draws a rectangle that has side lengths of 9 centimeters and 6 centimeters. What is the area of the rectangle? Explain how you found your answer.

Answer:
The area of the rectangle = 56 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 9 and b = 6.
area = 9 x 6.
area = 54.

Question 5.
Eliza’s bedroom measures 6 feet by 7 feet. Her brother’s bedroom measures 5 feet by 8 feet. Eliza says their rooms have the same exact floor area. Is she right? Why or why not?

Answer:
No, their rooms do not have the same exact floor area.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 7.
area = 6 x 7.
area = 42.
the area of the rectangle = l x b.
where l = 5 and b = 8.
area = 5 x 8.
area = 40.

Question 6.
Cliff draws a rectangle with a side length of 6 inches and an area of 24 square inches. What is the other side length? How do you know?

Answer:
The unknown side length of the rectangle = 4 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 24 and l = 6.
24 = b x 6.
b = 24 / 6 = 4.

Eureka Math Grade 3 Module 4 Lesson 8 Exit Ticket Answer Key

Question 1.
Write a multiplication equation to find the area of the rectangle below.

___9___ × ___3____ = ___27___

Answer:
The area of the rectangle = 27 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 9 and b = 3.
area = 9 x 3.
area = 27.

Question 2.
Write a multiplication equation and a division equation to find the unknown side length for the rectangle below.

___6____ × ___9____ = ___54___
__54_____ ÷ ___6____ = ____9___

Answer:
The unknown side length of the rectangle = 9 sq in.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 54 and b = 6.
54 = l x 6.
l = 54 / 6 = 9.

Eureka Math Grade 3 Module 4 Lesson 8 Homework Answer Key

Question 1.
Write a multiplication equation to find the area of each rectangle.
a.

___3____ × ___8____ = ___24___

Answer:
The area of the rectangle = 24 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 8 and b = 3.
area = 8 x 3.
area = 24.

b.

____8___ × ___6____ = ___48___

Answer:
The area of the rectangle = 48 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 8 and b = 6.
area = 8 x 6.
area = 48.

c.

____4___ × ____4___ = ___16___

Answer:
The area of the rectangle = 16 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 4.
area = 4 x 4.
area = 16.

d.

___7____ × ____4___ = ___28___

Answer:
The area of the rectangle = 28 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 7 and b = 4.
area = 7 x 4.
area = 28.

Question 2.
Write a multiplication equation and a division equation to find the unknown side length for each rectangle.
a.

__8_____ × ___3____ = __24____
__24_____ ÷ __3_____ = ___8____

Answer:
The unknown side length of the rectangle = 8 sq in.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 24 and b = 3.
24 = l x 3.
l = 24 / 3 = 8.

b.

____9___ × __4_____ = ____36__
___36____ ÷ ___9____ = ___4____

Answer:
The unknown side length of the rectangle = 4 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 36 and l = 9.
36 = b x 9.
b = 36 / 9 = 4.

Question 3.
On the grid below, draw a rectangle that has an area of 32 square centimeters. Label the side lengths.

Answer:
The area of the rectangle = 32 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 32 and b = 4.
32 = l x 4.
l = 32 / 4 = 8.

Question 4.
Patricia draws a rectangle that has side lengths of 4 centimeters and 9 centimeters. What is the area of the rectangle? Explain how you found your answer.

Answer:
The area of the rectangle = 54 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 9.
area = 4 x 9.
area = 36.

Question 5.
Charles draws a rectangle with a side length of 9 inches and an area of 27 square inches. What is the other side length? How do you know?

Answer:
The unknown side length of the rectangle = 3 sq in.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 27 and l = 9.
27 = b x 9.
b = 27 / 9 = 3.

Eureka Math Grade 3 Module 4 Lesson 8 Template Answer Key

_____27 ___sq cm__________
grid

Answer:
The unknown side length of the rectangle = 3 cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 27 and l = 9.
27 = b x 9.
b = 27 / 9 = 3.

Students of Grade 3 Module 4 can get a strong foundation on mathematics concepts by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka’s Grade 3 Textbook.

Engage NY Eureka Math 3rd Grade Module 4 Lesson 7 Answer Key

Teachers and students can find this Eureka Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Eureka Math Answer Key for Grade 3 aids teachers to differentiate instruction, building and reinforcing foundational mathematics skills that alter from the classroom to real life. With the help of Eureka’s primary school Grade 3 Answer Key, you can think deeply regarding what you are learning, and you will really learn math easily just like that.

Eureka Math Grade 3 Module 4 Lesson 7 Problem Set Answer Key

Question 1.
Use a straight edge to draw a grid of equal size squares within the rectangle. Find and label the side lengths. Then, multiply the side lengths to find the area.

a. Area A:
____3____ units × ___4_____ units = ____12____ square units

Answer:
a. The area of the rectangle = 12 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 4.
area = 3 x 4.
area = 12.

b. Area B:
__5______ units × ___4_____ units = ___20_____ square units

Answer:
b. The area of the rectangle = 20 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 4.
area = 5 x 4.
area = 20.

c. Area C:
____2____ units × ___7_____ units = ___14_____ square units

Answer:
c. The area of the rectangle = 14 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 2 and b = 7.
area = 2 x 7.
area = 14.

d. Area D:
___7_____ units × ___4_____ units = ___28_____ square units

Answer:
d. The area of the rectangle = 28 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 7 and b = 4.
area = 7 x 4.
area = 28.

e. Area E:
___1_____ units × ___3_____ units = ___3_____ square units

Answer:
e. The area of the rectangle = 30 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 6.
area = 5 x 6.
area = 30.

f. Area F:
___4_____ units × ___2_____ units = ___8_____ square units

Answer:
f. The area of the rectangle = 8 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 2.
area = 4 x 2.
area = 8.

Question 2.
The area of Benjamin’s bedroom floor is shown on the grid to the right. Each represents 1 square foot. How many total square feet is Benjamin’s floor?

a. Label the side lengths.

Answer:
a. The side lengths of the rectangle = 9 x 11.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 9 and b = 11.
area = 9 x 11.
area = 99.

b. Use a straight edge to draw a grid of equal size squares within the rectangle.

Answer:
b. The area of the rectangle = 99 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 9 and b = 11.
area = 9 x 11.
area = 11.

c. Find the total number of squares.

Answer:
c. The area of the rectangle = 99 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 9 and b = 11.
area = 9 x 11.
area = 99.

Question 3.
Mrs. Young’s art class needs to create a mural that covers exactly 35 square feet. Mrs. Young marks the area for the mural as shown on the grid. Each represents 1 square foot. Did she mark the area correctly? Explain your answer.

Answer:
No, she did not mark the area correctly.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 7 and b = 6.
area = 7 x 6.
area = 42 square feet.

Question 4.
Mrs. Barnes draws a rectangular array. Mila skip-counts by fours and Jorge skip-counts by sixes to find the total number of square units in the array. When they give their answers, Mrs. Barnes says that they are both right.
a. Use pictures, numbers, and words to explain how Mila and Jorge can both be right.

Answer:
The area of the rectangular array = 24 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 6.
area = 4 x 6.
area = 24.

b. How many square units might Mrs. Barnes’ array have had?

Answer:
The area of the rectangular array = 24 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 6.
area = 4 x 6.
area = 24.

Eureka Math Grade 3 Module 4 Lesson 7 Exit Ticket Answer Key

Question 1.
Label the side lengths of Rectangle A on the grid below. Use a straight edge to draw a grid of equal size squares within Rectangle A. Find the total area of Rectangle A.

Area: ___36_____ square units

Answer:
The area of the rectangular array = 36 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 6.
area = 6 x 6.
area = 36.

Question 2.
Mark makes a rectangle with 36 square centimeter tiles. Gia makes a rectangle with 36 square inch tiles. Whose rectangle has a bigger area? Explain your answer.

Answer:
The Gia rectangle has a bigger area.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 6.
area = 6 x 6.
area = 36.

Eureka Math Grade 3 Module 4 Lesson 7 Homework Answer Key

Question 1.
Find the area of each rectangular array. Label the side lengths of the matching area model, and write a multiplication equation for each area model.

Answer:
a.The area of the rectangular array = 6 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 2.
area = 3 x 2.
area = 6.

Answer:
b.The area of the rectangular array = 10 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 2 and b = 5.
area = 2 x 5.
area = 10.

Answer:
c.The area of the rectangular array = 12 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 4.
area = 3 x 4.
area = 12.

Answer:
d.The area of the rectangular array = 16 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 4.
area = 4 x 4.
area = 16.

Question 2.
Jillian arranges square pattern blocks into a 7 by 4 array. Draw Jillian’s array on the the grid below. How many square units are in Jillian’s rectangular array?
a.

Answer:
The area of the rectangular array = 28 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 7 and b = 4.
area = 7 x 4.
area = 28.

b. Label the side lengths of Jillian’s array from Part (a) on the rectangle below. Then, write a multiplication sentence to represent the area of the rectangle.

Answer:
The area of the rectangular array = 28 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 6.
area = 7 x 4.
area = 28.

Question 3.
Fiona draws a 24 square centimeter rectangle. Gregory draws a 24 square inch rectangle. Whose rectangle is larger in area? How do you know?

Answer:
Gregory’s rectangle is larger in area.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 4.
area = 6 x 4.
area = 24.

Eureka Math Grade 3 Module 4 Lesson 7 Template Answer Key

____8__sq__inches_______
area of model

Answer:
The area of the rectangular array = 8 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 2.
area = 4 x 2.
area = 8.

Teachers and students can find this Eureka Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Eureka Math Answer Key for Grade 3 aids teachers to differentiate instruction, building and reinforcing foundational mathematics skills that alter from the classroom to real life. With the help of Eureka’s primary school Grade 3 Answer Key, you can think deeply regarding what you are learning, and you will really learn math easily just like that.

Engage NY Eureka Math 3rd Grade Module 4 Lesson 6 Answer Key

Students of Grade 3 Module 4 can get a strong foundation on mathematics concepts by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka’s Grade 3 Textbook.

Eureka Math Grade 3 Module 4 Lesson 6 Problem Set Answer Key

Question 1.
Each represents 1 square centimeter. Draw to find the number of rows and columns in each array. Match it to its completed array. Then, fill in the blanks to make a true equation to find each array’s area.

Answer:
a. The area of the rectangle = 30 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 6.
area = 5 x 6.
area = 30.

Answer:
b. The area of the rectangle = 21 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 7.
area = 3 x 7.
area = 21.

Answer:
c. The area of the rectangle = 15 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 5.
area = 3 x 5.
area = 15.

Answer:
d. The area of the rectangle = 20 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 4.
area = 5 x 4.
area = 20.

Answer:
e. The area of the rectangle = 12 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 2 and b = 6.
area = 2 x 6.
area = 12.

Answer:
The area of the rectangle = 12 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 3.
area = 4 x 3.
area = 12.

Question 2.
Sheena skip-counts by sixes to find the total square units in the rectangle below. She says there are 42 square units. Is she right? Explain your answer.

Answer:
No, she was not correct.

Explanation:
In the above-given question,
given that,
Sheena skip-count by sixes to find the total square units in the rectangle below.
she says there are 42 square units.
6 x 8 = 48.
No, she was not correct.

Question 3.
The tile floor in Brandon’s living room has a rug on it as shown below. How many square tiles are on the floor, including the tiles under the rug?

Answer:
The number of square tiles on the floor = 90.

Explanation:
In the above-given question,
given that,
The tile floor in Brandon’s living room has a rug on it as shown below.
9 x 10 = 90
the area of the rectangle = l x b.
where l = 9 and b = 10.
area = 9 x 10.
area = 90.

Question 4.
Abdul is creating a stained glass window with square inch glass tiles as shown below. How many more square inch glass tiles does Abdul need to finish his glass window? Explain your answer.

Answer:
The area of the rectangle = 30 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 5.
area = 6 x 5.
area = 30.
so the area of the rectangle = 30 sq inches.

Eureka Math Grade 3 Module 4 Lesson 6 Exit Ticket Answer Key

The tiled floor in Cayden’s dining room has a rug on it as shown below. How many square tiles are on the floor, including the tiles under the rug?

Answer:
The area of the rectangle = 80 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 8 and b = 10.
area = 8 x 10
area = 80.
so the area of the rectangle = 80 sq cms.

Eureka Math Grade 3 Module 4 Lesson 6 Homework Answer Key

Question 1.
Each represents 1 square centimeter. Draw to find the number of rows and columns in each array. Match it to its completed array. Then, fill in the blanks to make a true equation to find each array’s area.

Answer:
a. The area of the rectangle = 36 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 6.
area = 6 x 6.
area = 36.

Answer:
b. The area of the rectangle = 24 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 8.
area = 3 x 8.
area = 24.

Answer:
c. The area of the rectangle = 18 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 6.
area = 3 x 6.
area = 18.

Answer:
d. The area of the rectangle = 25 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 5.
area = 5 x 5.
area = 25.

Answer:
e. The area of the rectangle = 16 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 2 and b = 8.
area = 2 x 8.
area = 16.

Answer:
f. The area of the rectangle = 36 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 3.
area = 4 x 3.
area = 12.

Question 2.
Minh skip-counts by sixes to find the total square units in the rectangle below. She says there are 36 square units. Is she correct? Explain your answer.

Answer:
Yes, she was correct.

Explanation:
In the above-given question,
given that,
the number of rows = 6.
the number of columns = 6.
area of the rectangle = l x b.
where l = 6 and b = 6.
area = 6 x 6.
area = 36.

Question 3.
The tub in Paige’s bathroom covers the tile floor as shown below. How many square tiles are on the floor, including the tiles under the tub?

Answer:
The area of the rectangle = 90 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 9 and b = 10.
area = 9 x 10.
area = 90.

Question 4.
Frank sees a book on top of his chessboard. How many squares are covered by the book? Explain your answer.

Answer:
a. The area of the rectangle = 30 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 6.
area = 5 x 6.
area = 30.

Eureka Math Grade 3 Module 4 Lesson 6 Template 1 Answer Key

____24 sq__cms__________
array 1

Answer:
The area of the rectangle = 24 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 4.
area = 6 x 4.
area = 24.

Eureka Math Grade 3 Module 4 Lesson 6 Template 2 Answer Key

__30__sq__cms__________
array 2

Answer:
a. The area of the rectangle = 30 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 6.
area = 5 x 6.
area = 30.

Students of Grade 3 Module 4 can get a strong foundation on mathematics concepts by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka’s Grade 3 Textbook.

Engage NY Eureka Math 3rd Grade Module 4 Lesson 5 Answer Key

Teachers and students can find this Eureka Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Eureka Math Answer Key for Grade 3 aids teachers to differentiate instruction, building and reinforcing foundational mathematics skills that alter from the classroom to real life. With the help of Eureka’s primary school Grade 3 Answer Key, you can think deeply regarding what you are learning, and you will really learn math easily just like that.

Eureka Math Grade 3 Module 4 Lesson 5 Problem Set Answer Key

Question 1.
Use the centimeter side of a ruler to draw in the tiles, and then skip-count to find the unknown area. Write a multiplication sentence for each tiled rectangle.
a. Area: 18 square centimeters.

  3    × ___6_____ =   18   

Answer:
The area of the rectangle = 18 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 6.
area = 3 x 6.
area = 18.

b. Area: __20___ square centimeters.

____5____ × ___4_____ = __20______

Answer:
The area of the rectangle = 20 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 4.
area = 5 x 4.
area = 20.

c. Area: 18 square centimeters

____3____ × ___6_____ = ____18_sq_cms__

Answer:
The area of the rectangle = 18 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 6.
area = 3 x 6.
area = 18.

d. Area: 24 square centimeters.

___8_____ × ___3_____ = __24_sq_cms___

Answer:
The area of the rectangle = 24 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 8 and b = 3.
area = 8 x 3.
area = 24.

e. Area: 20 square centimeters.

____4____ × ___5_____ = ___20_sq_cms___

Answer:
The area of the rectangle = 20 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 5.
area = 4 x 5.
area = 20.

f. Area: ___9__ square centimeters.

____3____ × ___3_____ = ___9__sq_cms__

Answer:
The area of the rectangle = 9 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 2.
area = 3 x 3.
area = 9.

Question 2.
Lindsey makes a rectangle with 35 square inch tiles. She arranges the tiles in 5 equal rows. What are the side lengths of the rectangle? Use words, pictures, and numbers to support your answer.

Answer:
The area of the rectangle = 35 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 7.
area = 5 x 7.
area = 35.

Question 3.
Mark has a total of 24 square inch tiles. He uses 18 square inch tiles to build one rectangular array. He uses the remaining square inch tiles to build a second rectangular array. Draw two arrays that Mark might have made. Then, write multiplication sentences for each.

Answer:
The area of the rectangle = 18 sq inch.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 3.
area = 6 x 3.
area = 18.

Answer:
The area of the rectangle = 6 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 2.
area = 3 x 2.
area = 6.

Question 4.
Leon makes a rectangle with 32 square centimeter tiles. There are 4 equal rows of tiles.
a. How many tiles are in each row? Use words, pictures, and numbers to support your answer.

Answer:
The area of the rectangle = 32 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 8.
area = 4 x 8.
area = 32.

b. Can Leon arrange all of his 32 square centimeter tiles into 6 equal rows? Explain your answer.

Answer:
No, he cannot arrange all of his 32 square centimeters tiles into 6 rows.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 8.
area = 4 x 8.
area = 32.

Eureka Math Grade 3 Module 4 Lesson 5 Exit Ticket Answer Key

Darren has a total of 28 square centimeter tiles. He arranges them into 7 equal rows. Draw Darren’s rectangle. Label the side lengths, and write a multiplication sentence to find the total area.

Answer:
The area of the rectangle = 28 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 7 and b = 4.
area = 7 x 4.
area = 28.

Eureka Math Grade 3 Module 4 Lesson 5 Homework Answer Key

Question 1.
Use the centimeter side of a ruler to draw in the tiles, and then skip-count to find the unknown area. Write a multiplication sentence for each tiled rectangle.
a. Area: 24 square centimeters.

  4    × ___6_____ =   24  

Answer:
The area of the rectangle = 24 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 6.
area = 4 x 6.
area = 24.

b. Area: 24 square centimeters.

____4____ × ___6_____ = __24_sq_cms____

Answer:
The area of the rectangle = 24 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 6.
area = 4 x 6.
area = 24.

c. Area: 15 square centimeters.

____3____ × ___5_____ = ___15_____

Answer:
The area of the rectangle = 15 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 5.
area = 3 x 5.
area = 15.

d. Area: 15 square centimeters.

____5____ × ____3____ = ____15____

Answer:
The area of the rectangle = 15 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 3.
area = 5 x 3.
area = 15.

Question 2.
Ally makes a rectangle with 45 square inch tiles. She arranges the tiles in 5 equal rows. How many square inch tiles are in each row? Use words, pictures, and numbers to support your answer.

Answer:
The area of the rectangle = 45 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 9.
area = 5 x 9.
area = 45.

Question 3.
Leon makes a rectangle with 36 square centimeter tiles. There are 4 equal rows of tiles.
a. How many tiles are in each row? Use words, pictures, and numbers to support your answer.

Answer:
The area of the rectangle = 36 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 9.
area = 4 x 9.
area = 36.

b. Can Leon arrange all of his 36 square centimeter tiles into 6 equal rows? Use words, pictures, and numbers to support your answer.

Answer:
Yes, Leon can arrange all of his 36 sq cm tiles into 6 equal rows.
The area of the rectangle = 36 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 6.
area = 6 x 6.
area = 36.

c. Do the rectangles in Parts (a) and (b) have the same total area? Explain how you know.

Answer:
Yes, the rectangles have the same area.
The area of the rectangle = 36 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 6.
area = 6 x 6.
area = 36.

Eureka Grade 3 ensures students with the learning targets and success criteria. The Diverse opportunities will develop problem-solving skills among the primary school kids practicing Bigideas Math Grade 3 Solutions. Eureka Textbook Grade 3 answers help Students Master the subject on Consistent practice.

Engage NY Eureka Math 3rd Grade Module 4 Lesson 4 Answer Key

Grade 3 Eureka Math Answer Key is provided by subject experts as per the Common Core curriculum. Grade 3 Eureka Math Solutions provided educates the primary school Kids on all Math concepts of the chapter efficiently. Eureka Math Grade 3 Textbook Answers makes it easy for kids to Grasp the Concepts as well as solve any problem from chapter Tests, Practice Tests, Performance tests, cumulative practice, etc.

Eureka Math Grade 3 Module 4 Lesson 4 Problem Set Answer Key

Question 1.
Use a ruler to measure the side lengths of the rectangle in centimeters. Mark each centimeter with a point and connect the points to show the square units. Then, count the squares you drew to find the total area.

Total area: _____12__sq_units.___________

Answer:
The area of the rectangle = 12 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 2.
area = 6 x 2.
area = 12.

Question 2.
Use a ruler to measure the side lengths of the rectangle in inches. Mark each inch with a point and connect the points to show the square units. Then, count the squares you drew to find the total area.

Total area: _______12_sq_inches__________

Answer:
The area of the rectangle = 12 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 4.
area = 3 x 4.
area = 12.

Question 3.
Mariana uses square centimeter tiles to find the side lengths of the rectangle below. Label each side length. Then, count the tiles to find the total area.

Total area: ___12__sq_cms_____________

Answer:
The area of the rectangle = 12 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 3.
area = 4 x 3.
area = 12.

Question 4.
Each is 1 square centimeter. Saffron says that the side length of the rectangle below is 4 centimeters. Kevin says the side length is 5 centimeters. Who is correct? Explain how you know.

Answer:
Kevin says the side length is 5 centimeters.

Explanation:
In the above-given question,
given that,
5 x 4 = 20.
area = 20 cms.
Saffron was wrong.
Kevin says the side length is 5 centimeters.

Question 5.
Use both square centimeter and square inch tiles to find the area of the rectangle below. Which works best? Explain why.

Answer:
The area of the rectangle = 12 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 2.
area = 6 x 2.
area = 12.

Answer:
The area of the rectangle = 3 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 1.
area = 3 x 1.
area = 3.

Question 6.
How does knowing side lengths A and B help you find side lengths C and D on the rectangle below?

Answer:
The Opposite sides are equal in the rectangle.

Explanation:
In the above-given question,
given that,
the sidelengths AB = CD.
that means opposite sides are equal.

Eureka Math Grade 3 Module 4 Lesson 4 Exit Ticket Answer Key

Label the side lengths of each rectangle. Then, match the rectangle to its total area.

Answer:
The area of the rectangle = 6 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 2.
area = 3 x 2.
area = 6.

Answer:
The area of the rectangle = 12 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 2.
area = 6 x 2.
area = 12.

Answer:
The area of the rectangle = 5 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 1.
area = 5 x 1.
area = 5.

Eureka Math Grade 3 Module 4 Lesson 4 Homework Answer Key

Question 1.
Ella placed square centimeter tiles on the rectangle below, and then labeled the side lengths. What is the area of her rectangle?

Total area: ____8__cm_____________

Answer:
The area of the rectangle = 8 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 2.
area = 4 x 2.
area = 8.

Question 2.
Kyle uses square centimeter tiles to find the side lengths of the rectangle below. Label each side length. Then, count the tiles to find the total area.

Total area: ______20 __sq_cms__________

Answer:
The area of the rectangle = 20 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 4.
area = 5 x 4.
area = 20.

Question 3.
Maura uses square inch tiles to find the side lengths of the rectangle below. Label each side length. Then, find the total area.

Total area: ______14_sq__inches._________

Answer:
The area of the rectangle = 14 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 7 and b = 2.
area = 7 x 2.
area = 14.

Question 4.
Each square unit below is 1 square inch. Claire says that the side length of the rectangle below is 3 inches. Tyler says the side length is 5 inches. Who is correct? Explain how you know.

Total area: ____15_sq_inch_____________

Answer:
Yes, both of them are correct.

Explanation:
In the above-given question,
given that,
Clarie says that the side length of the rectangle below is 3 inches.
Tyler says that the side length is 5 inches.
5 x 3 = 15 inches.
area of the rectangle = 15 sq inches.

Question 5.
Label the unknown side lengths for the rectangle below, and then find the area. Explain how you used the lengths provided to find the unknown lengths and area.

Total area: _____8 _sq_inches.____________

Answer:
The area of the rectangle = 8 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 2.
area = 4 x 2.
area = 8.