Go Math Grade 2 Answer Key | Download Primary School Second Grade HMH Go Math Answers

Go Math Grade 2 Answer Key

Go Math Grade 2 Solution Key keeps your kid on the right track and offers you a seamless learning experience. Use the learning aids over here to score better grades in your exams. Have deeper insight into the concepts of Primary School Second Grade and stand out from the crowd. Avail the Chapterwise HMH Go Math Answer Key for Grade 2 via quick links available and take your preparation to the next level.

HMH Go Math Second Grade Answers provided are given by subject experts and meets the Common Core State Standards 2019 Curriculum. Primary School Go Math 2nd Grade Answer Key includes Questions from Exercises, Chapter Tests, Assessments, Review Tests, Cumulative Practice, etc. Make the most out of the quick resources and grasp the fundamentals of maths that might be useful for you in the mere future.

Primary School Go Math Grade 2 Answer Key for all Chapters

Learn the concepts of 2nd Grade Math in a fun and engaging way. HMH Go Math Grade 2 Answer Key is curated by subject experts keeping in mind students’ level of understanding. Keep your kid on the right track and help them become proficient in maths. Access the Chapterwise Go Math Second Grade Answer Key in PDF Format via quick links available. Just click on the respective chapter you feel like preparing and improve on the areas you feel difficult.

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Features of Common Core Go Math Grade 2 Solution Key

Learn the importance of the HMH Go Math Second Grade Answers by referring to the below-listed steps. They are along the following lines

  • Go Math Grade 2 Solutions are free to download and we don’t charge a single penny from you.
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  • HMH Go Math Second Grade Answer Key is given by subject experts adhering to the Common Core State Standards.
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FAQs on Primary School Go Math 2nd Grade Answer Key

1. Is there any portal that provides the Go Math Grade 2 Answer Key for free?

ccssmathanswers.com is a trusted portal that provides the Go Math Grade 2 Answer Key for free of cost.

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You can access the HMH Go Math Grade 2 Answers via quick links available. Simply click on the direct links available to avail the respective chapter.

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You can get the Chapterwise Go Math Second Grade Answer Key organized efficiently on our page.

Go Math Grade 1 Answer Key | HMH Go Math First Grade Solutions PDF Free Download

Go Math Grade 1 Answer Key

Teach your kid the basic math skills he might need using the Go Math Grade 1 Answer Key. Create an Impact on their Regular Thinking and help them improve their problem-solving skills and subject knowledge. Look no further and begin your preparation right away to score higher grades in exams. HMH Go Math Answer Key for Grade 1 provided is given after extensive research and is sequenced as per the Go Math 1st Grade Textbooks.

Primary School First Grade Go Math Solution Key PDF format is given for a better learning experience. Solutions provided in the Go Math 1st Grade Answers Key cover questions from all the Exercises, Chapter Tests, Review Tests, Cumulative Practice, etc.  You can download the Chapterwise Go Math Grade 1 Answers in PDF Format and we don’t charge a single penny from you.

Download Chapterwise Go Math First Grade Answer Key

Avail the Primary School Go Math Answer PDF through the quick links provided below. All you have to do is simply click on the respective chapter you wish to prepare and allot time accordingly. Bridge the Knowledge Gap taking the help of the Go Math Grade 1 Solution Key. Kick start your preparation using these resources and clear the exams with flying colors.

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Advantages of Referring to Go Math Grade 1 Answers

Students who are in need of Go Math Grade 1 Homework or Assignments help can access the Grade 1 Go Math Answer Key to resolve their queries. The major benefits of referring to HMH Go Math 1st Grade Answers are as follows

  • HMH Go Math Grade 1 Answers provided boost your confidence while attempting the final exams.
  • Go Math Grade 1 Answer Key provided includes Questions from Chapter Tests, Assessment Tests, Review Tests, Practice Tests, etc.
  • Step by Step Solutions provided for all the Go Math Textbook Questions helps you to gain deeper level knowledge on all the concepts.
  • Solving the Primary School Go Math First Grade Answer Key on a regular basis enhances your speed and accuracy in the actual exams.
  • First Grade Go Math Solution Key is prepared by subject experts and meets the Common Core State Standards Initiative.

FAQs on Primary School Go Math 1st Grade Solution Key

1. Where do I get Primary School Go Math Grade 1 Answers Chapterwise?

You can get Primary School Go Math 1st Grade Answers Chapterwise arranged in an efficient manner.

2. Does practicing from HMH Go Math First Grade Answer Key help you score better marks?

Yes, Practicing from HMH Go Math Grade 1 Answer Key help you score better marks as all the concepts are explained in detail.

3. How to download Common Core Go Math Grade 1 Answers PDF for free? 

You can download the Common Core Go Math Grade 1 Answers PDF for free of cost via quick links. Simply, tap on them and prepare offline too to get a grip on all the concepts.

Download Go Math Answer Key for Grades K-8 | HMH Go Math Solution Key for Grades Kindergarten, 1, 2, 3, 4, 5, 6, 7, 8

Go Math Answer Key: HMH Go Math Solutions Key provided helps students to have learning targets and achieve success at chapter and lesson level and makes learning visible. Give your kid the right amount of knowledge he needs as a part of your preparation by taking the help of our HMH Go Math Answer Key for Grades K-8. Resolve all your queries and assess your preparation standard using the Common Core Go Math Solution Key.

All the Concepts in the CCSS Go Math Answer Key for Grades Kindergarten, 1, 2, 3, 4, 5, 6, 7, 8 are given with straightforward and detailed descriptions. Practicing from the Go Math Answer Key for Grades K to 8 will provide a grade by grade roadmap and prepares students for College Readiness. Gradewise HMH Go Math Answer Key provided will develop problem-solving skills among students thereby helping them to Think, Explore and Grow. The Diverse Opportunities provided helps Kids to master the content with engaging activities.

Free Download Go Math Answer Key from Kindergarten to 8th Grade

Students can find Go Math Answer Keys right from  Primary School to High School all in one place. You just need to tap on the quick links available in order to access them and learn all the Chapters in each grade. Once you tap on the quick link you will be directed to the respective Grade Solutions Key wherein you can access the complete information. You can find Solutions for all the Go Math Textbook Questions free of cost and we don’t charge any amount.

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Go through the below-listed features of referring to the HMH Go Math Anwer Key for Grades K to 8. They are outlined as follows

  • All the Go Math Answer Key for Grades K to 8 are easy to download and we don’t charge any penny from you.
  • Step by Step Solutions provided in the HMH Go Math Practice Key is aligned as per the College and Career Expectations.
  • Solving from the Math 101 Practice Key helps you inculcate Higher Order Thinking Skills and you can answer any Question from your Homework, Assessment, or Review Test.
  • More Rigorous Content made available meets the Common Core State Standards Initiative.
  • You can gain a deeper knowledge of mathematical concepts and find solutions to all the Questions from Go Math Textbooks for Grades K, 1, 2, 3, 4, 5, 6, 7, 8

FAQs on Common Core HMH Go Math Answer Key

1. When Can I use the Go Math Answer Key for Grades K-8?

You can use the HMH Go Math Answer Key for Grades K to 8 while practicing the Go Math Textbook Questions as a part of your Homework or Assessment and make the most out of them.

2. Is there any site that provides the Common Core Go Math Solutions Key for Grades K, 1, 2, 3, 4, 5, 6, 7, 8?

Yes, you can find Go Math Answer Key for Grades K, 1, 2, 3, 4, 5, 6, 7, 8 all in one place i.e. ccssmathanswers.com a trusted and reliable portal.

3. Can I download HMH Go Math Answer Key PDF for free?

Yes, you can download the HMH Math 101 Practice Key for free on our page via quick links available and we don’t charge any amount for it.

Go Math Grade K Answer Key | Download HMH Go Math Kindergarten Solution Key

Go Math Grade K Answer Key

Achieve your learning targets easily taking the help of the Go Math Grade K Answer Key. Practice using the Go Math Kindergarten Solution Key and reach better grades in the exams. Resolve all your queries taking the help of Go Math Grade K Solution Key and kick start your preparation. Solving the Questions from Kindergarten Go Math Answers enhances your speed and accuracy in the actual exams.

You need not worry about the accuracy of the Primary School HMH Go Math Answer Key for Grade K as all of them are given by subject experts. In fact, you can access the Chapterwise Go Math Kindergarten Answers via quick links available. Go Math Grade K Solutions prepared meets the Common Core State Standards Curriculum and are up to date.

Download Chapterwise Grade K Go Math Answer Key

Access the Primary School Go Math Grade K Answer Key for all the Chapters via quick links. Simply click on the chapter you wish to prepare and learn all the related concepts in no time. The Solutions provided in the Go Math Grade K Solution Key include Questions from Chapter Tests, Review Tests, Practice Tests, Cumulative Practice, etc. For the sake of a better searching experience, the Kindergarten Go Math Answers sequenced as per the Go Math Grade K Textbooks.

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Refer to the below-listed features of the Go Math Grade K Answer Key and learn the importance of it. They are along the lines

  • Solving the Go Math Kindergarten Answer Key regularly improves your higher-order thinking skills.
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  • Gain Deeper Insights into the mathematical concepts of HMH Go Math Grade K.
  • Tests your preparation levels and you can bridge the knowledge gap and allot time to the areas you are facing difficulty with.

FAQs on Common Core Go Math Grade K Answer Key

1. Where do I get the Go Math Answer Key for Grade K?

You can get Go Math Grade K Answer Key for free of cost on our page.

2. Is there any site that provides the Chapterwise Kindergarten Go Math Answer Key?

Yes, ccssmathanswers.com is a trusted portal that provides the Chapterwise Go Math Grade K Answer Key.

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You can download the HMH Go Math Grade K Solution Key via quick links available on our page. Simply tap on them to access the HMH Go Math Grade K Answers for all Chapters.

Constants and Variables Definitions | Difference Between Constants and Variables with Examples

Constants and Variables

Constants and Variables are the popular terms used in algebra. Every expression or equation will be implemented with a combination of constants and variables. Constant is a fixed value in every expression and the variables are not fixed values. Learn different problems on Constants and Variables and get a grip on the complete concept.
Example:
x^2 + 2xy + 6 is an algebraic equation.
Here, 6 cannot be changed and it is the constant number in the equation, and x^2, 2xy values are varied depends on the values. So, x^2 and 2xy are variables in the equation.

Constant & Variables – Definitions

Constant: A Constant is defined as a fixed value in algebraic expressions or equations. Constant will not change with time and has a fixed value. For instance, Shoe Size will not vary at any point.

In an algebraic expression, x+y = 5, 5 is a constant value, and will not be changed.

Variables: Variables are terms that can change or differ over time. It will not have a fixed value unlike a constant. For example, the Height and Weight of a Person will not remain constant and will vary with time.

In an algebraic expression, x+y = 5, x and y are the variables and can be varied. Go through the below modules to know more about the key differences between Constants and Variables.

Difference Between Constants and Variables

See the main differences between Constants and Variables here. ?They are along the lines

  • The main difference between the constants and variables, constant is a fixed value and a variable is not a fixed value.
  • Constants are indicated by the numerical values and the variables are indicated by any alphabetical values like a, b, c, d, ………..z.

Examples of Constants and Variables

Find the Constants and Variables of Given Expressions.

1. x + y + 2 =0.

Solution:
The given expression is x + y + 2 = 0.
Here, x and y are variables.
2 is a constant number.

2. x^2 + y^2 + 20 = 0.

Solution:
The given expression is x^2 + y^2 + 20 = 0.
Here, x^2 and y^2 are variables.
20 is a constant number.

3. xy + x^2 + 15 = 0.

Solution:
The given expression is xy + x^2 + 15 = 0.
Here, xy and x^2 are variables.
15 is a constant number.

4. 2xy + 6 = x^2y.

Solution:
The given expression is 2xy + 6 = x^2y.
Here, 2xy and x^2y are variables.
6 is a constant number.

5. x^3 + y^3 = 2xy + 8.

Solution:
The given expression is x^3 + y^3 = 2xy + 8.
Here, x^3, y^3, and 2xy are variables.
8 is a constant number.

6. Find out the constants and variables in the below questions

(i) In 5m, 5 is a constant and m is a variable.
(ii) In -3ab, -3 is a constant and a and b are variables.
(iii) In 4b, 4 is constant and b is variable but together 4b is a variable.
(iv) If 2 is a constant and a is a variable, then 2 + a, 2 – a, 2/a, 2a, a/2, etc., are also variables.

FAQs on Constants and Variables

1. What is the main difference between variables and constant?
The major difference between variables and constants is variable is a varying quantity, and a constant is a fixed value.

2. What are the variables?
The variables are the terms in an algebraic equation that can be changed or that are not fixed. Example: a + b = 8, where a and b are the variables, and 8 is a constant.

3. What are constants? 
The constants are the value in an algebraic expression that cannot be modified or changed. For example, in an equation x + y = 9, 9 is the constant value.

4. What is an algebraic expression?
The algebraic expression is a combination of constants, variables, integers, and mathematical operations.

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Calculate Profit and Profit Percent – Formula, Examples | How to find Profit from Profit Percent?

Calculate Profit and Profit Percent

Calculate Profit and Profit Percent using Profit formula. Easily calculate the profit gained for a product by selling it. All the business or financial transactions are used the profit formula. The profit is calculated when the selling price of any product sold is greater than the cost price. Check out how the profit is calculated and know the profit gained by your business. We have included solved problems along with explanations.

Also, Read:

Formulas to Calculate Profit

If the selling price is more than the cost price (S.P. > C.P.), there is a profit. Various formulas to calculate profit are given below. Remember all of them for better learning.

  • Formula for Profit Profit = S.P – C.P.
  • Formula for Profit Percentage = Profit Percent Formula = (Profit x 100)/C.P.
  • Gross Profit Formula = Gross Profit = Revenue – Cost of Goods Sold
  • Profit Margin Formula = Profit Margin = (Total Income/Net Sales) x 100
  • Gross Profit Margin Formula = Gross Profit Margin = (Gross Profit/Net Sales) x 100

Notation Used in Profit Formula

  • S.P. = Selling Price i.e. the cost at which the product is sold
  • C.P. = Cost price i.e. the cost at which the product is originally bought

Profit and Profit Percent Examples

Example 1.

Ram purchased 300 calculators at $100 each. He spent $5 on packing each calculator, paid $50 to the carrying for loading, and $500 on transportation. He sold 200 at a rate of $180 each and 100 at the rate of $80 each. Find his profit or loss percent in the whole transportation.

Solution:
Given that Ram purchased 300 calculators at $100 each.
C.P. of 1 calculator = $100
C.P. of 300 calculators = $100 x 300 = $30000
Money spent on packing 1 calculator = $5
Money spent on packing 300 calculators = $300 x 5 = $1500
Overhead expenses = $(1500 + 50 + 500) = $2050
C.P. of 300 calculators = Actual C.P. + Overhead expenses
C.P. of 300 calculators = $30000 + $2050 = $32050
S.P. of 300 calculators = S.P. of 200 calculators + S.P. of 100 calculators
S.P. of 1 calculator = $180
S.P. of 200 calculators = $180 x 200 = $36000
S.P. of 1 calculator = $80
S.P. of 100 calculators = $80 x 100 = $8000
S.P. of 300 calculators = $36000 + $8000 = $44000
S. P. > C. P., there is profit, therefore, profit – S.P. – C.P.
Profit = $44000 – $32050 = $11950
Profit% = P/C.P. x 100%
Profit% = $11950/$32050 x 100%
Profit% = 37.28%

The profit percentage is 37.28%.

Example 2.

A cloth merchant bought 25 shirts, each at a price of Rs 280. He sold each of them for Rs. 300. Find his percentage profit.

Solution:
Given that a cloth merchant bought 25 shirts, each at a price of Rs 280. He sold each of them for Rs. 300.
The profit percentage remains the same for one unit as well for all the units. Thus the calculations should be done for one unit only.
The Cost Price = Rs 280
Selling Price = Rs. 300
Profit = Selling Price – Cost Price
Substitute Selling Price and Cost Price in the above formula.
Profit = Rs. 300 – Rs 280 = Rs 20.
Now, find out the profit percentage formula.
Profit percentage = P/C.P. x 100%
Profit percentage = 100 × 20/280 = 7.14%

Therefore, the profit percentage is 7.14%

Example 3.

A retail fruit vendor buys pineapples at a score of Rs. 200/-,  and retails them at a dozen for Rs 156. Did he gain or lose in the transaction and what % was his gain or loss?

Solution:
Given that a retail fruit vendor buys pineapples at a score of Rs 200, and retails them at a dozen for Rs 156.
The cost price = Rs 220
C.P/Pineapple = 200/20 = 10
1 score = 20 nos
S.P = Rs.156/dozen
S.P/Pineapple = 156/12 = 13.
Profit = Rs. 13 – Rs. 10 = Rs. 3.
% Profit = 100 × 3/10 = 30%

Therefore, the profit percentage is 30%

FAQs on Profit and Profit Percent

1. How do I calculate profit percentage?

The profit percentage can be calculated using the below formula.
Formula for Profit Percentage = Profit Percent Formula = (Profit x 100)/C.P.

2. Is profit and profit percent different?

Yes, Profit is the difference between the Selling price and the Cost price when the Selling price is more than the Cost price.
P = SP – CP; SP>CP
Profit percent will obtain by dividing the Profit with Cost price and multiplying the resultant with the 100.
Profit percent = (Profit x 100)/C.P

3. What is the formula of Selling Price?

Selling Price can be found when the Profit Percentage and Cost Price are given is
SP = {(100 + P%)/100} x CP where SP is Selling Price, P% is Profit Percentage, and CP is Cost Price.

4. How to Calculate the Percentage Gain on an Investment?

  • In calculating the percentage gain on an investment, first, determine the original cost.
  • Next, Subtract the Cost Price from the Selling price of the investment.
  • Take the gain from the investment and divide it by the original amount of the investment.
  • Finally, multiply the result by 100 to get the percentage change in the investment.

Calculate Cost Price using Sell Price and Loss Percent – Formula, Examples

Calculate Cost Price using Sell Price and Loss Percent

Loss and Loss Percent is raised when the cost price is higher than the selling price. We can calculate the Cost Price when Sell Price and Loss Percent are given. Improve your preparation by referring to the complete article. Check out how to find the Cost Price and different solved examples on finding the Cost Price using Sell Price and Loss Percent from the below article. Also, find out the different formulas to use to find the cost price.

Also, See:

How to Calculate Cost Price using Sell Price and Loss Percent?

To find out the Cost Price using Sell Price and Loss Percent, use the below formula.
Cost price = selling price + loss
Cost price = selling price + loss% × cost price/100
The Cost price – loss% × cost price/100 = selling price
Cost price(1 – loss%)/100 = selling price
Cost price(100 – loss%)/100 = selling price
Also, Cost price = selling price × 100/100 – loss% (on cross multiplication)

Examples for finding Cost Price using Sell Price and Loss Percent

1. By selling a bicycle for $145, a shopkeeper loses 10%. How much percent would he gain or lose by selling it for $175?

Solution:
Given that by selling a bicycle for $145, a shopkeeper loses 10%.
The selling price = $145
Loss Percentage = 10%
We know that cost price = selling price × 100/100 – loss%
Substitute the selling price and the loss% in the above formula.
Cost price = $145 × 100/100-10
Cost price = $145 × 100/90
The Cost price = $14500/90
Cost price = $161.11
Therefore, cost price of the bicycle = $161.11
Now, if the selling price = $175, then gain = $175 – $161.11  = $13.89
Therefore, gain% = gain/cost price × 100
= 13.89/161.11 × 100
= 1500/150
= 8.62%

Therefore, he would have gained 8.62%.

2. If the selling price of a pen is $9 and the loss percent is 2%, then what is the cost price?

Solution:
Given that the selling price of a pen is $9 and the loss percent is 2%.
The selling price of a pen = $9
The loss percent is 2%.
Cost price = selling price × 100/100 – loss%
Substitute the selling price and the loss% in the above formula.
Cost price = $9 × 100/100 – 2
Cost price = $9 × 100/98
The Cost price = $900/98 = $9.18

Therefore, the cost price of the pen is $9.18.

3. Find out the cost price of the vehicle if the selling price is $3350 and the Loss is $154.

Solution:
Given that the selling price is $3350 and the Loss is $154.
The selling price of a pen = $3350
The loss = $154
Loss = Cost Price – Selling Price
Cost Price = Loss + Selling Price
Substitute the selling price and the loss in the above formula.
Cost Price = $154 + $3350
Cost Price = $3504

Therefore, the cost price of the vehicle is $3504.

FAQs on finding C.P using S.P and Loss%

1. What Does Cost Price Mean?

The cost price is the original price of an item. The cost is the total amount need to produce a product or carry out a service.

2. What is the Formula for the Cost Price?

The formula for Cost Price when the SP and L% are given
CP = {100/(100 – L%)} x SP where SP is the Selling Price and L is the Loss.

3. What are the types of Cost Prices?

Cost Price (CP) is the amount paid to buy the product is known as Cost Price. It is denoted by CP. Also, the cost price classified into two different categories. They are
Fixed Cost: The fixed cost is constant and it doesn’t vary under any circumstances.
Variable Cost: It could change depending on the number of units.

4. How to Calculate Cost Price?

Follow the below steps and find out the process to calculate cost price when the selling price and loss% are given.
1. Note down the selling price and loss%.
2. Write the formula of cost price i.e, CP = {100/(100 – L%)} x SP
3. Substitute the SP and L% in the above formula.
4. Calculate and find the Cost Price of the product.

Calculate Loss and Loss Percent – Definition, Formulas, Examples | How to Calculate Loss Percent?

Calculate Loss and Loss Percent

Loss and Loss Percent are used for calculating the loss that occurred in a business. The loss is the difference between the cost price and the selling price. Loss Percent is the percent of loss in terms of actual cost price. The loss will occur when the selling price is less than the cost price. We have given how to Calculate Loss and Loss Percent and the formula of loss. Know the process to find them and learn how to apply them in your real life. Also, check the solved examples for a better understanding.

Do Read:

Formula to Calculate Loss and Loss Percent

The loss occurs when a cost price is more than the selling price of a product in a business. The loss is calculated by subtracting the selling price from a cost price. The formula to calculate loss and loss percentage are

  • Loss = Cost Price – Selling Price when the Cost Price is higher than the Selling Price.
    or
    Loss = C.P. – S.P. (C.P.>S.P.)
  • Loss percentage = (Loss × 100) / C.P
  • Selling Price: The Selling Price is the price of a product that was sold by the shopkeeper to the customer for a particular price. Selling price is denoted by S.P.
    Selling Price(SP)= Cost Price(CP) – Loss(L)
  • Cost Price: The cost price is the price of a product it is the original cost of a product that was brought from the retailer. Cost Price is denoted by C.P.
    Cost Price(CP)= Selling Price(SP) + Loss(L)

Loss and Loss Percent Examples

Example 1.

A shirt was bought for $300 and sold for $250. Find the loss and loss percent.

Solution:
Given that a shirt was bought for $300 and sold for $250.
The cost price = $300
Also, the selling price = $250
Since, S. P. < C. P., there is loss.
Therefore, loss = cost price – selling price
Substitute the cost price and selling price in the above formula.
Loss = $300 – $250 = $50.
So, loss% = loss/cost price × 100%
Substitute the cost price and loss in the above formula.
loss% = $50/$300 × 100% = 16.66%

Therefore, the loss is $50 and the loss% is 16.66%

Example 2.

If the cost price of 30 pens is equal to the selling price of 35 pens, find a loss percent?

Solution:
Given that the cost price of 30 pens is equal to the selling price of 35 pens.
Let cost price of 1 pen = $1
Then cost price of 30 pens = $30
Also, cost price of 35 pens = $35
Since, selling price of 35 pens = cost price of 30 pens
Therefore, the selling price of 25 pens = $30
Therefore, loss = cost price – selling price
Loss = $35 – $30 = $5.
Therefore, loss% = loss/cost price × 100
loss% = $5/$35 × 100
loss% = 14.28%

Therefore, the loss is $5 and the loss% is 14.28%

Example 3.

Find the loss and loss percentage provided that the cost price is Rs. 60 and the selling price is Rs. 55.

Solution:
Given that the cost price is Rs. 60 and the selling price is Rs. 55.
The cost price = Rs. 60
Also, the selling price = Rs. 55
Since, S. P. < C. P., there is loss.
Therefore, loss = cost price – selling price
Substitute the cost price and selling price in the above formula.
Loss = Rs. 60 – Rs. 55 = Rs. 5.
So, loss% = loss/cost price × 100%
Substitute the cost price and loss in the above formula.
loss% = Rs. 5/Rs. 60 × 100% = 8.33%

Therefore, the loss is Rs. 5 and the loss% is 8.33%

Example 4.

If a house was bought by a man for Rupees 60 Lakhs and he sold it in 40 Lakhs. What is a loss percentage from this business?

Solution:
Given that a house was bought by a man for Rupees 60 Lakhs and he sold it in 40 Lakhs.
The cost price = Rs. 60 Lakhs
Also, the selling price = Rs. 40 Lakhs
Since, S. P. < C. P., there is loss.
Therefore, loss = cost price – selling price
Substitute the cost price and selling price in the above formula.
Loss = Rs. 60 Lakhs – Rs. 40 Lakhs = Rs. 20 Lakhs.
So, loss% = loss/cost price × 100%
Substitute the cost price and loss in the above formula.
loss% = Rs. 20 Lakhs/Rs. 60 Lakhs × 100% = 33.33%

Therefore, the loss is Rs. 20 Lakhs and the loss% is 33.33%

FAQs on Loss and Loss Percent

1. How do you calculate percentage loss?

Follow the below steps to find the percentage loss.
1. Note down the cost price.
2. Then, check out the Selling Price, and calculate the loss.
3. Substitute the Loss and cost price in the Loss percentage formula.
4. Finally, find the Loss percentage.
Loss percentage = (Loss × 100) / C.P

2. What are the Loss and Loss Percent Formulas?

The formula for Loss and Loss Percent are
Loss = C.P. – S.P. (C.P.>S.P.)
Loss percentage = (Loss × 100) / C.P where C.P. is cost price and S.P. is selling price.

3. What is the formula for S.P when Loss and C.P. are given?

The formula for Loss = C.P. – S.P.
Therefore, S.P. = C.P. – Loss

4. How to find the C.P. when Loss and S.P. are given?

The formula for Loss = C.P. – S.P.
Therefore, C.P. = Loss + S.P.

5. How to find loss from loss percentage?

The Loss percentage = (Loss × 100) / C.P
Firstly, multiply C.P with Loss percentage and then divide it by 100 to get a Loss from the loss percentage.
Loss = (Loss percentage × C.P)/100

Calculate Cost Price using Sell Price and Profit Percent – Formula, Examples

Calculate Cost Price using Sell Price and Profit Percent

Calculate Cost Price using Sell Price and Profit Percent when the inputs are Sell Price and Profit Percent and the output is Cost Price. By simply using the Cost Price formula, one can find out the Cost Price of a product. The cost price is always less than the selling price when the profit percent is given. We have detailed explanations and solved examples are included in this article. All the different methods to find Cost Prices using Sell Price and Profit Percent are given below.

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How to Calculate Cost Price Using Sell Price and Profit Percent?

Follow the below process to find out the Cost Price Using Sell Price and Profit Percent. Also, get the Cost Price Formula to solve all the problems.

1. Write down the Sell Price and Profit Percent.
2. Note Down the Cost Price Formula.
3. Substitute the Sell Price and Profit Percent in the Cost Price Formula.
4. Finally, find out the Cost Price Using Sell Price and Profit Percent.

Cost Price Formula

Use the below formulas according to the problem and get the cost price easily.

Cost price = selling price – profit
Cost price = selling price – profit% × cost price/100
The Cost price + profit% × cost price/100 = selling price
Cost price(1 – profit%)/100 = selling price
Cost price(100 + profit%)/100 = selling price
Also, cost price = selling price × 100/100 + profit% (on cross multiplication);
Here, selling price and loss% is known.

Finding Cost Price Using Sell Price and Profit Percent Examples

1. A box was sold for $428 thereby gaining 8%. Find the cost price of the bag?

Solution:

Given that a box was sold for $428 thereby gaining 8%.
The selling price = $428
Gain Percentage = 8%
We know that cost price = selling price × 100/100 + gain%
Substitute the selling price and the gain% in the above formula.
Cost price = $428 × 100/(100 + 8)
Cost price = $428 × 100/108
The Cost price = $42800/108 = $396.29

Therefore, the cost price of the bag is $396.29

2. A fan was sold for $625 thereby gaining 15%. Find the cost price of the fan.

Solution:

Given that a fan was sold for $625 thereby gaining 15%.
The selling price = $625
Gain Percentage = 15%
We know that cost price = selling price × 100/100 + gain%
Substitute the selling price and the gain% in the above formula.
Cost price = $625 × 100/(100 + 15)
Cost price = $625 × 100/115
The Cost price = $62500/115= $543.47

Therefore, the cost price of the fan is $543.47

3. By selling a mobile for $1,240, a trader gains 10%. Find the cost price of the mobile?

Solution:

Given that by selling a mobile for $1,240, a trader gains 10%.
The selling price = $1,240
Gain Percentage = 10%
We know that cost price = selling price × 100/100 + gain%
Substitute the selling price and the gain% in the above formula.
Cost price = $1240 × 100/(100 + 10)
Cost price = $1240 × 100/110
The Cost price = $124000/110 = $1127.27

Therefore, the cost price of the mobile is $1127.27

Calculate Selling Price using Cost and Loss Percent – Formula, Worked Out Problems

Calculate Selling Price using Cost and Loss Percent

The amount of a thing that can be sold is known as the Selling Price. It is denoted by SP. Also, the Selling Price is also called the sale price. The selling price can be calculated when the Cost price and Loss Percent are given. Solve all the given related to Selling price problems to get a complete grip on the concept. Also, check out the given explanation of problems to find the Selling Price using Cost and Loss Percent in the later modules.

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How to Calculate Selling Price Using Cost and Loss Percent?

Follow the complete process to find out the Selling Price Using Cost and Loss Percent. Also, know the Cost Price Formula to solve all the problems easily.

1. Note down the Cost Price and Loss Percent.
2. Write Down the Selling Price Formula.
3. Substitute the Cost Price and Loss Percent in the Selling Price Formula.
4. Finally, find out the Selling Price Using Cost Price and Loss Percent.

Selling Price Formula when Cost and Loss Percent are Known

You can use the below formula to find the Selling Price of a product when you know the Cost and Loss Percent of that product. The formulas for Selling Price Formula when Cost and Loss Percent Known are

  • Selling price = cost price – loss
  • Selling price = cost price – loss% × cost price/100
  • Selling price = 100 × cost price – loss% × cost price/100
  • Selling price = (100 – loss%)cost price/100, [Here, cost price and loss% are known.]

Solved Examples to Find Selling Price using Cost and Loss Percent

1. Sam bought a dress for $250 and sold it to Olivia thereby suffering a loss of 10%. Find the selling price of the dress?

Solution:
Given that Sam bought a dress for $250 and sold it to Olivia thereby suffering a loss of 10%.
The cost price = $250
Loss Percentage = 10%
We know that selling price = (100 – loss%) cost price/100
Substitute the cost price and the loss% in the above formula.
Selling price = (100 – 10)250/100
Selling price = 90 × 250/100
The Selling price = $22500/100 = $225

Therefore, the Selling price of the dress is $225

2. Alex bought a laptop for $600 and sold it to Jack thereby suffering a loss of 12%. Find the selling price of the laptop?

Solution:
Given that Alex bought a laptop for $600 and sold it to Jack thereby suffering a loss of 12%.
The cost price = $600
Loss Percentage = 12%
We know that selling price = (100 – loss%) cost price/100
Substitute the cost price and the loss% in the above formula.
Selling price = (100 – 12)600/100
Selling price = 88 × 600/100
The Selling price = $52800/100 = $528

Therefore, the Selling price of the dress is $528

3. By selling a table for $630, Daisy loses 7%. At what price must she sell it to gain 10%.

Solution:
Given that By selling a table for $630, Daisy loses 7%.
Given that the selling price = $ 630
Loss % = 7%
We know, cost price = selling price × 100/100 – loss%
Substitute the selling price and the loss% in the above formula.
Therefore, cost price = 630 × 100/(100 – 7)
= 630 × 100/93
= $677.41
Now cost price = $677.41
Gain% = 10%
Therefore, selling price = (100 + gain%)cost price/100
= (100 + 10)677.41/100
= 110 × 6.77
= $744.7

At $744.7 price she can sell it to gain 10%.

Examples on Calculating Profit or Loss | Profit and Loss Questions and Answers

Looking for help on finding Profit and Loss Concepts? Then, you have come the right way. Here let us observe some fully solved example problems on calculating profit or loss. You can find step by step solutions to all the Profit and Loss Questions available here. Try Practicing from the Profit and Loss Problems and get acquainted with the concepts better. Learn various methods for Calculating Profit and Loss and solve related problems easily. Assess your preparation standards on the concept and concentrate on the areas you are lagging in accordingly.

Question 1:
If a manufacturer allows 40% commission on the retail price of his product, he earns a profit of 9%. What would be his profit percent if the commission is reduced by 25 percent?

Solution:

We need to find out the profit % when the given commission is reduced by 25 percent.
Given data:
According to the question consider
Cost price (C.P.) of the product = $ 100
Then, a commission of the product = $ 40
Therefore selling price (S.P.) = $ (cost price (C.P.) – commission)
= $ (100 – 40)
= $ 60
Given that profit = 9%
Therefore Cost price (C.P.) = \(\frac { 100 }{ 100+gain%} \)* S.P
So,
C.P. = $ \(\frac { 100 }{ 100+9 } \)* 60
= $ \(\frac { 6000 }{109 } \)
Now new commission = $ 15
Therefore new selling price (S.P.) = $ 100 – 15
= $ 75
Gain = S.P. – C.P.
= $ (75 – \(\frac { 6000 }{109 } \))
= $ \(\frac { 2175 }{109 } \)
Gain% = (\(\frac { Profit }{C.P. } \)*100)%

=(\(\frac { 2175 }{109 } \)*\(\frac { 109 }{6000 } \)*100)%

= 36.25 %
Hence, gain % is 36.25.
Question 2:
After getting two successive discounts, a pant with the least price of $ 200 is available at $ 125. If the second discount is 14%, find the first discount.

Solution:
Let the first discount be ‘P%’
Then, 86% of (100 – P) % of 200 = 125

\(\frac { 86 }{ 100 } \)*\(\frac { (100 – P) }{ 100 } \)*200 = 125

100-P = \(\frac {(125*100*100) }{ 200*86 } \)
100 – P = 72.67
P = 100 – 72.67
P = 27.32%
Therefore, first discount price of pant is 27.32%.
Question 3:
A women sells an article at a profit of 20%. If he had bought it at 15% less and sold it for $ 11.50 less, he would have gained 25%. Find the cost price of the article.

Solution:
Given data:
Consider cost price (C.P.) of article be ‘X’
First selling price of article ‘X’ = 120% of ‘X’

= \(\frac { 120 }{ 100 } \)*X
= \(\frac { 6 }{ 5 } \)*X
Cost price of article for ‘X’ at 75% = 75% of ‘X’
=\(\frac { 75 }{ 100 } \)*X

=\(\frac { 3 }{ 4 } \)*X
Second selling price of article ‘X’ = 125% of 3/4 * X
= \(\frac { 125 }{ 100 } \)*\(\frac { 3x }{ 4 } \)

= \(\frac { 15x }{ 16 } \)

As given the article is sold at $ 11.50 less
Therefore, selling prices are equalized to a reduced price

\(\frac { 6x }{5 } \) –\(\frac { 15x }{ 16 } \) = 11.50
\(\frac { 21x }{80 } \) = 11.50
X = $ 43.8
Almost equal to $ 44
Hence, the cost price of an article is given as $ 44.
Question 4:
A dealer sold three – fourth of his articles at a gain of 25% and the remaining at cost price. Find the profit earned by him in the whole transaction.

Solution:
A dealer sold his ¾ th quantity with a gain of 25% and the remaining ¼ that its cost price.
Given data:
Consider cost price (C.P.) of whole articles be ‘X’
Cost price (C.P.) of \(\frac { 3}{ 4} \)th quantity = $ \(\frac { 3x}{ 4} \)
Cost price (C.P.) of \(\frac { 1}{ 4} \)th quantity = $ \(\frac { x}{ 4} \)
Total selling price (S.P.) = $ ((125% of \(\frac { 3x}{ 4} \)) + \(\frac { x}{ 4} \))
= $ (\(\frac { 15x}{ 16} \) + \(\frac { x}{ 4} \))
= $ (\(\frac { 19x}{ 16} \))
Profit / Gain = S.P. – C.P.
= $ (\(\frac { 19x}{ 16} \) – x)
= $ \(\frac { 3x}{ 16} \).
Gain % = (\(\frac { gain}{ C.P. } \)*100)%

= (\(\frac {3x}{ 16 } \)*\(\frac {1}{ x } \)*100)%

= 18.75%.
Hence, the gain % of the article is 18.75%.
Question 5:
A man sold two flats for $ 775,000 each. On one he gains 18% while on the other he losses 18%. How much does he gain or lose in the whole transaction?

Solution:
In this problem he gets an equal amount of profit and loss such cases there is always a loss. Therefore the selling price (S.P.) is immaterial.
Loss % = (\(\frac {common loss and gain %}{ 10 } \))2

= (\(\frac {18 }{ 10 } \))2

= (\(\frac {324 }{ 100 } \))

= 3.24%
The total loss incurred by the person is 3.24%.
Question 6:
Pure petrol costs $ 100 per lit. After adulterating it with kerosene costing $ 50 per lit, a shopkeeper sells the mixture at the rate of $ 96 per lit, thereby making a profit of 20%. In what ratio does he mix the two?

Solution:
Here, we have two different cost prices for different mixtures and one selling price (S.P.).
Given data:
Cost price (C.P.) of petrol = $ 100 per lit
Cost price (C.P.) of kerosene = $ 50 per lit
Selling price (S.P.) of mixture = $ 96 per lit
As we have two cost prices,
Mean cost price = $(\(\frac {100 }{ 120 } \))* 96)

= $ 80 per lit.
Since they asked us to find a ratio it is easy to find out by the allegation rule
Cost price (C.P.) of a unit Cost price (C.P.) of a unit quantity of $ X item quantity of $ Y item
Mean cost
$ M
(M – Y) (X – M)
Similarly using this concept here,
Cost price (C.P.) of a unit Cost price (C.P.) of a unit quantity of $ 100 item quantity of $ 50 item
Mean cost
$ 80
(80 – 50) (100 – 80)
Therefore, required ratio = 30 : 20
= 3 : 2.

Question 7:
Find cost price (C.P.), when
1. Selling price (S.P.) = $ 50, Gain = 18%
2. Selling price (S.P.) = $ 51, Loss = 14%

Solution:
Here, we need to find cost price (C.P.) using below formulae
1. Given data
Selling price (S.P.) = $ 50 & Gain = 18%
C.P. = \(\frac { 100 + Gain%) }{ 100 } \)*S.P.

=$ \(\frac { 100 + 18 }{ 100 } \)*50= $ 59.
2. Given data
Selling price (S.P.) = $ 51, Loss = 14%

C.P. = \(\frac { 100 – Loss% }{ 100 } \)*S.P.

= $ \(\frac { 100 – 14 }{ 100 } \)*51

= $ 43.86.

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Calculate Selling Price using Cost and Profit Percent – Formula, Solved Examples

Calculate Selling Price using Cost and Profit Percent

The Selling Price is easily calculated when the Cost and Profit Percent are given. Calculate Selling Price using Cost and Profit Percent and apply them to your real-time problems. Check out the various problems and their solving methods to find the Selling Price when the Cost Price and Profit Percent are given. We have included real-life examples for your practice. Don’t miss any problems to learn the complete concept.

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How to Calculate Selling Price Using Cost and Profit Percent?

Step by step procedure is given for you to find out the Selling Price Using Cost and Profit Percent. It is really easy to find the selling price when you know the cost price and Profit Percent. Therefore, check out the procedure and follow the steps while solving problems.

1. Find out the Cost price and Profit Percent from the given problem.
2. Note down the formula of Selling Price.
3. In the next step, substitute the Cost price and Profit Percent in the formula.
4. Finally, find the selling price.

Selling Price Formula when Cost and Profit Percent are Known

The Selling Price Formula is the important thing to remember to calculate all the problems when Cost and Profit Percent are given. Without missing, anyone, remember all the formulas and use them while calculating problems.

  • Selling price = cost price + profit
  • Selling price = cost price + profit%/100 × cost price
  • The selling price = 100 × cost price + profit% × cost price/100
  • selling price = (100 + profit%)cost price/100; [Here, cost price and profit% are known.]

Solved Examples to Find the Selling Price Using Cost and Profit Percent

1. Ram bought a Colors Box for $100 and sold it at a profit of 20%. Find the selling price of the book?

Solution:
Given that Ram bought a Colors Box for $100 and sold it at a profit of 20%.
The cost price of the Colors Box = $100
Profit Percentage = 20%
We know that selling price = (100 + profit%)cost price/100
Substitute the cost price and the profit% in the above formula.
Selling price = (100 + 20)100/100
Selling price = 120 × 100/100
The Selling price = $120

Therefore, the Selling price of the Colors Box is $120.

2. Alex bought a music system for $180. For how much should he sell the music system to gain 10%?

Solution:
Given that Alex bought a music system for $180.
The cost price of the music system = $180
Profit Percentage = 10%
We know that selling price = (100 + profit%)cost price/100
Substitute the cost price and the profit% in the above formula.
Selling price = (100 + 10)180/100
Selling price = 110 × 180/100
The Selling price = $198

Therefore, the Selling price of the music system is $198.

3. Robert bought a washing machine for $800 and sold it at a profit of 4%. Find the selling price of the washing machine?

Solution:
Given that Robert bought a washing machine for $800 and sold it at a profit of 4%.
The cost price of the washing machine = $800
Profit Percentage = 4%
We know that selling price = (100 + profit%)cost price/100
Substitute the cost price and the profit% in the above formula.
Selling price = (100 + 4)800/100
Selling price = 104 × 800/100
The Selling price = $832

Therefore, the Selling price of the washing machine is $832.

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Discount – Types, Formula, Examples | How to Calculate Discount?

Discount

Discount is defined as the amount or percentage that deducted or reduced from the normal selling price of any product. Shortly, discount means the reduction in the price of a good or service. Refer to the marked price, list price and discount, and the formula of discount, and procedure to find out the discount, and solved examples in this article and get a grip on the total discount concept. Subtracting the Sale price from the Regular price minus gives the amount of discount. Check out various problems on discount and improve your math knowledge easily.

Discount Formula

Check out the formula of discount and Rate of Discount in the below section. Use the below formulas to find different problems on discount.

  • Discount = List Price – Selling Price
  • Therefore, Selling Price = List Price + Discount
  • List Price = Selling Price + Discount

Discount Percentage Formula is

  • Rate of Discount or Discount% = (Discount/List Price) * 100
  • Selling Price = List Price ((100 – Discount)/100)%
  • List Price = Selling Price (100/(100-Discount)%)

Discount Formula

Concept of Discount

Sometimes, the retailers don’t directly sell the old items, defective items. They offer less price for those products to sell. Such a price is called the sale price. The difference between the Marked price (selling price) and the sale price is called a discount.
Discount = Marked Price – Sale Price

Marked Price

The price on the label of a product is called the Marked Price. The marked price is the price at which the product ready to be sold. Marked price is represented by MP.
Example: The price printed on the books is called the Marked Price.

List Price

The products that are manufactured in a factory and marked with a price by the retailer to sell them are called the List Price. The list price is represented as LP.

Selling price = Marked price – Discount
where the selling price is the amount that actually pays for the product when you purchase.
The marked price is the general price of the product without any discount.
Discount is a percentage of the Marked price.

Example:
If the cost of the pen is $10 and the shopkeeper reducing the amount of $8 on that pen, then there is a discount of $2 is available for that pen.
Sometimes, the discount is also available in percentages ‘%’.

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How to Find Discount?

The below procedure will help you to find a discount on a product. Follow the procedure and practice different problems on discount using the below process.

1. The rate given for a product is considered as a percentage value.
2. In the next step, to find out the discount, multiply the rate by the original price.
3. To find the sale price, Subtract the discount from the original price.

Types of Discounts

Basically, Discounts are classified into three types. They are

Trade Discounts: The trade discounts are offered by the distributors. Trade discounts are the discounts where the amount of the product is reduced to sell the product.
Quantity Discounts: Quantity discounts are applied to a buyer depending on the number of items he purchased in greater numbers. Mainly, to sell the items in huge amounts to buyers, the sellers offer Quantity discounts.
Promotional Discounts: Promotional discounts are applied to do sales promotions. It is most preferable amongst shopkeepers. Generally, the Promotional discounts appear in % or buy 2 & get 1 free, etc.

Discount Examples

1. The marked price of a table fan is $ 750 and the shopkeeper offers a discount of 5% on it. Find the selling price of the table fan?

Solution:
Given that the marked price of a table fan is $ 750 and the shopkeeper offers a discount of 5% on it.
The Marked Price of the table fan = $750.
Discount on the table fan = 5%
We know that Discount = 5% of Marked Price
Discount = 5% of $ 750 = 750 * \(\frac { 5 }{ 100 } \) = 750 * 0.05 = 37.5
Discount = $37.5
To find the selling price of the table fan, subtract the discount from the Marked Price of the table fan.
Selling price = (Marked Price) – (discount)
Selling price = $750 – $37.5 = $712.5

Hence, the selling price of the table fan is $712.5.

2. A trader fixed the cost of his goods at 30% above the cost price and allows a discount of 15%. What is his gain percent?

Solution:
Given that a trader fixed the cost of his goods at 30% above the cost price and allows a discount of 15%.
Let the cost price be $ 100.
Therefore, the marked price = $130
We know that Discount = 15% of Marked Price
Discount = 15% of $130 = 130 * \(\frac { 15 }{ 100 } \) = 19.5
Discount =$19.5
To find the selling price of the table fan, subtract the discount from the Marked Price of the table fan.
Selling price = (Marked Price) – (discount)
Selling price = $130 – $19.5 = $110.5
Gain% = (Selling price – cost price)% = (110.5 – 100)% = 10.5%

Hence, the trader gains 10.5%.

3. A dealer purchased a cooler for $ 3830. He allows a discount of 6% on its marked price and still gains 5%. Find the marked price of the cooler?

Solution:
Given that a dealer purchased a cooler for $ 3830. He allows a discount of 6% on its marked price and still gains 5%.
The Cost price of the cooler = $ 3830
Gain% = 5%.
Now, find out the selling price.
To find the selling price, Substitute the Cost price and Gain% in the selling price formula.
Therefore, selling price = [{(100 + gain%)/100} × CP]
Selling price = $ [{(100 + 5)/100} × 3830] = $4021.5
The selling price is $4021.5
Let the marked price be $ x.
Then, the discount = 6% of marked price = 6% of $ x.
discount = $ {x × (6/100)} = = $ 3x/50
To find the selling price of the table fan, subtract the discount from the Marked Price of the table fan.
Selling price = (Marked Price) – (discount)
Selling price = $ x – $ 3x/50 = $47x/50
But, the SP = $4021.5
Therefore, $47x/50 = $4021.5
$47x = $4021.5 * 50
$47x = 201075
x = 201075/47 = $4278.19

Hence, the Marked price of the cooler is $4278.19.

4. How much percent above the cost price should a shopkeeper mark his goods so that after allowing a discount of 15% on the marked price, he gains 30%?

Solution:
Let the cost price be $ 100.
Gain required = 30%.
Therefore, the selling price = $ 130.
Let the marked price be $x.
Then, discount = 15% of $x
discount = $ (x × 15/100)
discount = $ 3x/20
To find the selling price of the table fan, subtract the discount from the Marked Price of the table fan.
Therefore, selling price = (Marked Price) – (discount)
= $ {x – ($ 3x/20)
= $ 17x/20
Therefore, $ 17x/20 = 130
⇔ x = {130 × (20/17)} = 152.94
Therefore, marked price = $ 152.94.

Hence, the marked price is 52.94% above the cost price.

Successive Discounts

If two or more discounts are applied one after the other on a single product, then such discounts are called Successive Discounts. The Successive Discounts are also called discounts in series.

For example, if a discount of 30% is given for a product and later 10% of discount is given due to the reduced price. In such a situation, we can say successive discounts of 30% and 10% are given.

5. Find the single discount equivalent to two successive discounts of 30% and 20%.

Solution:
Let the marked price of the product be $ 100.
Then, the first discount on it = $ 30.
Price after first discount = $ (100 – 30) = $ 70.
Second discount on it = 20% of $ 70
= $ {70 × (20/100)} = $ 14.
Price after second discount = $ (70 – 14) = $ 56.
Net selling price = $ 56.

Single discount equivalent to given successive discounts = (100 – 56)% = 44%.

Fake Discounts

Fake Discounts also exist where the product pre-sale price may immoderately increase, or else the post-sale price of the product is actually its market price. This may feel the customers that they are getting a discount to make them purchase a product.

Frequently Asked Questions on Discounts

1. What is the Discount?

Discount is the amount deducted from the list price of the commodity before selling it to the customer.

2. How to Calculate Discount?

Check out the below steps to calculate the discount.
1. Find out the original price of the product.
2. Know the discount percentage.
3. Calculate the savings.
4. Calculate the sale price by subtracting the savings from the original price.
To calculate the discount, we need to subtract the selling price from the list price.
Discount = Selling Price – List Price

3. What is the Discounted Rate?

The discounted rate is also called the discount percentage. It is defined as the percentage by which list price is reduced before selling.

4. What is the Discount Percentage Formula?

The formula for Discount Percentage is
Rate of Discount or Discount% = (Discount/List Price) * 100
Selling Price = List Price ((100 – Discount)/100)%
List Price = Selling Price (100/(100-Discount)%)

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Calculating Profit Percent and Loss Percent | Profit and Loss Problems and Solutions

The profit and loss are the basic components of the income statement that summarizes the revenues, costs, and expenses subjected during a certain period. We use basic concepts in the calculation of profit percentage and loss percentage. Find Formulas for Calculating Profit % and Loss % and Problems on the Same in the forthcoming modules.

Cost Price (CP)

The price at which we purchase an item is called the cost price. In short, it is written as CP.

Example: A merchant bought an item at a cost of Rs. 150 and gain a profit of Rs. 30.

In the above example, Rs.150 is the cost price.

Selling Price (SP)

The price at which we sell an item is called the selling price. In short, it is written as SP.

Example: A shop keeper purchased a pen at Rs. 40 and he sold it at Rs.50 to a customer.

In the above example Rs. 50 is the selling price.

Profit or Gain

If the selling price of an item is more than the cost price of the same item, then it is said to be gain (or) profit i.e. S.P. > C.P.

Net profit= S.P. – C.P.

Loss

If the selling price of an item is less than the cost price of the same item, then it is said to be a loss i.e. S.P.  < C.P.

Net loss= C.P. – S.P.

NOTE:

It is important to note that the profit or loss is always calculated based on the cost price of an item.

Profit and Loss Formulas for Calculating Profit % and Loss%

Have a glance at the Profit and Loss Formulas for finding the Profit and Loss Percentage. They are along the lines

  • Net Gain = (S.P.) – (C.P.)
  • Net Loss = (C.P.) – (S.P.)
  • Gain % = (S.P. – C.P./C.P. *100)% = (gain/C.P. *100)%
  • Loss % = (C.P. – S.P./C.P. *100)%  = (loss/C.P. * 100)%
  • To find S.P. when C.P. and gain% or loss% are given :
    • P. = [(100 + Gain %) /100] * C.P.
    • P. = [(100 – Loss %) /100] * C.P.
  • To find C.P. when S.P. and gain% or loss% are given :
    • P. = [(100 + Gain %) /100] * S.P.
    • P. = [(100 – Loss %) /100] * S.P.

Profit and Loss Percent Questions and Answers

Question 1:

A man buys a book for Rs. 60 and sells it for Rs. 90. Find his gain/loss percentage?

Solution:

By seeing the question we can understand that the Selling price of the book is more than its cost price, therefore the man has profited on his total transaction.

Given data:

Cost price (C.P.) = Rs.60

Selling price (S.P.) =Rs. 90

Net profit = S.P. – C.P.

= 90 – 60

= 30

Profit % = ((Net profit)/C.P. *100)

= (30/60 *100)

= 50%

The total gain percentage is 50%.

Question 2:

If a fruit vendor purchases 9 oranges for Rs.8 and sells 8 oranges for Rs. 9. How much profit or loss percentage does he makes?

Solution:

By seeing the question we can understand that he bought 9 oranges at cost prices Rs.8 and sells 8 oranges at Rs. 9.

Given data:

Buying 9 oranges at Rs. 8

And Selling 8 oranges at Rs. 9

Here we are making quantities equal by multiplying the prices on both sides

We get,

Quantity            Price

Buying                 9 * 8                8 * 8

Selling                 8 * 9                9 * 9

By calculating,

Quantity            Price

Buying                 72                      64

Selling                 72                       81

By observing the above calculation we can see that the vendor bought 72 oranges for Rs. 64 while he sold 72 oranges at Rs. 81. This shows that the vendor is having profit in the entire transaction.

Profit percentage = ((S.P. – C.P.)/C.P. * 100)

= ((81-64)/64 * 100)

= 26.56 %

The total gain percentage for fruit vendors selling oranges is 26.56%.

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Examples on Fundamental Operations | Questions on Fundamental Operations

Examples on Fundamental Operations are here. Get step by step procedure and ways to apply the formulae to the problems. Know the various operations like addition, subtraction, division, multiplication problems. Get all the simple and easy tips to complete the problem without any confusion. Refer to all the problems in the below sections and also follow various methods to solve those problems.

Basic Mathematical Operations Examples

Before knowing the examples, first, you must know the important points of fundamental operations on integers. We are giving the complete details regarding the integer’s fundamental operations.

Important Points

  • The integers are defined by the numbers …,-4, -3,-2,-1, 0,1, 2, 3, 4…
  • 1, 2, 3, 4,… are called positive (+) integers and -1,-2,-3,… are called negative (-) integers. 0 is defined as neither a positive value nor a negative value.
  • Integer 0 is considered as a value that is less than every positive number and greater than every negative number.
  • The absolute value of an integer is considered as its numerical value of that integer without the consideration of its sign.
  • The absolute value of an integer is considered as either positive or zero which cannot be a negative number.
  • The sum of two integer numbers having the same sign is the sum of their absolute values with a positive sign.
  • The sum of two integer numbers having the opposite signs is the “difference” of their absolute values and indicates the sign of the greater absolute value.
  • To subtract an integer y from x, we change the sign of y and add, i.e., x + (-y)
  • The product of two integer numbers having the same sign is positive (+).
  • The product of two integer numbers having different signs is negative (-).
  • 2 integers, which when added give 0, are called the additive inverse of each other.
  • The additive inverse of zero is zero.

Four Fundamental Operations Problems

Problem 1:

Two lakh sixty-three thousand nine hundred fifty-three visitors visited the trade fair on Sunday, four lakh thirty-three thousand visited on Monday, and three lakh twenty thousand six hundred fifty-six visited on Tuesday. How many visitors in all visited the trade fair in these three days?

Solution:

As per. the given question,

Visitors visited the trade fair on Sunday = 2,63,953

Visitors visited the trade fair on Monday = 4,33,000

Vistors visited the trade fair on Tuesday = 3,20,656

To find the no of visitors in all visited the trade fair, we have to apply the addition fundamental operation.

Therefore, the total visitors on 3 days = 2,63,953 + 4,33,000 + 3,20,656

= 10,17,609

Thus, the final solution is 10,17,609 visitors

Problem 2:

From a book store, 12,685 books were bought for the primary section of the school library. 15,790 books were bought for the middle section; and 13,698 books for the senior section. What was the total number of books bought?

Solution:

As per the given question,

Number of books bought for Primary section = 12,685

Number of books bought for Middle Section = 15,790

Number of books bought for Senior Section = 13,698

To find, the total no of books bought, the fundamental operation of addition is to be applied

Therefore, the total number of books = 12,685+15,790+13,698 = 42,173

Thus, the final solution is 42,173 books

Problem 3:

The masons used 1,75,692 bricks for the construction of Mr. Sharma’s house, and 2,16,785 bricks for the construction of Mr. Verma’s house. For whose house the masons used more bricks and how many bricks were used?

Solution:

As per the given question,

Bricks used for Mr. Sharms’s house = 1,75,692

More bricks were used for the construction of Mr. Verma’s house.

To find the number of bricks that were used, we apply the fundamental operation of subtraction.

The number of more bricks used for Mr. Verma’s house = 2,16,785 – 1,75,692

= 41,093

Thus, the final solution is 41,093 bricks.

Problem 4:

In a month, 1,23,498 people travel from one station to another by metro. If the distance fare Rs.32 paid by each traveler, then how much money will be collected in a month?

Solution:

As per the question,

Number o0f people travel by metro = ,1,23,498

Distance fair paid by each traveler = Rs.32

To find the money, collected in a monthy, we apply the fundamental operation of multiplication.

The amount of money collected in a month = 1,23,498 x 32 = 39,51,936

Thus, the final solution is 39,51,936 Rs

Problem 5:
If a dictionary contains 3,215 pages and there are 215 words arranged on each page, then how many words are there in the whole dictionary?

Solution:

As per the given question,

Total number of pages in the dictionary = 3,215

Number of words on each page = 215

To find the number of words in the whole dictionary, we apply the fundamental operation of multiplication.

Therefore, the number of words in whole dictionary = 3,215 x 215 = 6,91,225 words

Thus, a total number of words in the dictionary =6,91,225 words.

Problem 6:

An organizer has 25,90,488 tickets to be equally sold among 358 singing concerts. How many people will be there in each singing concert?

Solution:

As per the given question,

Total number of tickets = 25,90,488

Number of singing concerts = 358

To find the number of people in each singing concert, we apply the fundamental operation of division.

Therefore, the number of people in each singing concert = 25,90,488 / 358 =7,236 people

Thus, the final solution is 7,236 people.

Problem 7:

A contractor sent 76,95,940 bricks for the construction of 70 chambers. If an equal number of bricks was required for each chamber, how many bricks were used for each chamber?

Solution:

As per the given question,

Total number of bricks = 76,95,940

Number of chambers = 70

To find the total number of bricks used for each chamber, we apply the fundamental operation of division.

Therefore, The total number of bricks used for each chamber = 76,95,940 / 70 =1,09,942 bricks.

Thus, the final solution is 1,09,942 bricks.

Problem 8:

Mohan bought a table for Rs 12,450 and a chair for Rs. 5,400. Find the total money spend by him on buying two items?

Solution:

As per the given equation,

Cost of the table = Rs 12,450

Cost of the chair = Rs 5,400

To find the total cost, we apply the fundamental operation of addition.

Therefore, the total cost of items = Rs 12,450 + 5,400 = 17,850

Thus, the total money spent by him in buying two items is Rs. 17,850

Hence, the final solution is 17,850 Rs.

Problem 9:

Rahul bought a laptop for Rs 1,02,500, video game for Rs 5,600 and furniture for Rs 72,500. How much did he spend in all?

Solution:

As per the given question,

The cost of the laptop = Rs 1,02,500

The cost of the video game = Rs 5,600

The cost of the furniture = Rs 72,500

To find the total cost, we apply the fundamental operation of addition

Therefore, total cost = 102500 + 5600 + 72500 =180600

Thus, the total amount spent in all is Rs 180600

Hence, the final solution is 180600 Rs.

Problem 10:

The cost of the toy car is Rs 7,300 and the cost of a toy scooter is Rs 5,286. Which toy is cheaper and by how much?

Solution:

As per the given question,

The cost of a toy car = Rs 7,300

The cost of the toy scooter = Rs 5,286

To find the cheapest toy, we apply fundamental operations for subtraction.

Hence, the cheaper toy = 7300-5286 =2014

Therefore, the amount of the toy that is cheap = 2014 Rs

Thus, the final solution = Rs 2014

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