# Eureka Math Grade 5 Module 2 Lesson 20 Answer Key

## Engage NY Eureka Math 5th Grade Module 2 Lesson 20 Answer Key

### Eureka Math Grade 5 Module 2 Lesson 20 Problem Set Answer Key

Question 1.
Divide. Then, check with multiplication. The first one is done for you.
a. 65 ÷ 17

Answer:
65/17 = 14.

Explanation:
In the above-given question,
given that,
Divide, and then check.
17 x 3 = 51.
65 – 51 = 14.

b. 49 ÷ 21

Answer:
49/21 = 7.

Explanation:
In the above-given question,
given that,
Divide, and then check.
21 x 2 = 42.
49 – 42 = 7.

c. 78 ÷ 39

Answer:
78/39 = 0.

Explanation:
In the above-given question,
given that,
Divide, and then check.
39 x 2 = 78.
78 – 78 = 0.

d. 84 ÷ 32

Answer:
84/32 = 20.

Explanation:
In the above-given question,
given that,
Divide, and then check.
32 x 2 = 64.
84 – 64 = 20.

e. 77 ÷ 25

Answer:
77/25 = 2.

Explanation:
In the above-given question,
given that,
Divide, and then check.
25 x 3 = 75.
77 – 75 = 2.

f. 68 ÷ 17

Answer:
68/17 = 0.

Explanation:
In the above-given question,
given that,
Divide, and then check.
17 x 4 = 68.
68 – 68 = 0.

Question 2.
When dividing 82 by 43, Linda estimated the quotient to be 2. Examine Linda’s work, and explain what she needs to do next. On the right, show how you would solve the problem.

Answer:
82/43 = 39 .

Explanation:
In the above-given question,
given that,
Divide, and then check.
43 x 1 = 43.
82 – 43 = 39.

Question 3.
A number divided by 43 has a quotient of 3 with 28 as a remainder. Find the number. Show your work.

Answer:
The number = 5.

Explanation:
In the above-given question,
given that,
A number divided by 43 has a quotient 0f 3 with 28 as a remainder.
5 x 3 = 15.
43 – 15 = 28.

Question 4.
Write another division problem that has a quotient of 3 and a remainder of 28.

Answer:
The number = 7.

Explanation:
In the above-given question,
given that,
A number divided by 49 has a quotient 0f 3 with 28 as a remainder.
7 x 3 = 21.
49 – 21 = 28.

Question 5.
Mrs. Silverstein sold 91 cupcakes at a food fair. The cupcakes were sold in boxes of “a baker’s dozen,” which is 13. She sold all the cupcakes at $15 per box. How much money did she receive? Answer: The money she received =$1365.

Explanation:
In the above-given question,
given that,
Mrs. Silverstein sold 91 cupcakes at a food fair.
The cupcakes were sold in boxes of “a baker’s dozen,” which is 13.
91 x $15 =$1365.

### Eureka Math Grade 5 Module 2 Lesson 20 Exit Ticket Answer Key

Divide. Then, check with multiplication.

a. 78 ÷ 21

Answer:
78/21 = 15.

Explanation:
In the above-given question,
given that,
Divide, and then check.
21 x 3 = 63.
78 – 63 = 15.

b. 89 ÷ 37

Answer:
89/37 = 15.

Explanation:
In the above-given question,
given that,
Divide, and then check.
37 x 2 = 74.
89 – 74 = 15.

### Eureka Math Grade 5 Module 2 Lesson 20 Homework Answer Key

Question 1.
Divide. Then, check with multiplication. The first one is done for you.
a. 72 ÷ 31

Answer:
72/31 = 10.

Explanation:
In the above-given question,
given that,
Divide, and then check.
31 x 2 = 62.
72 – 62 = 10.

b. 89 ÷ 21

Answer:
89/21 = 5.

Explanation:
In the above-given question,
given that,
Divide, and then check.
21 x 4 = 84.
89 – 84 =5.

c. 94 ÷ 33

Answer:
94/33 = 29.

Explanation:
In the above-given question,
given that,
Divide, and then check.
33 x 2 = 66.
94 – 66 = 29.

d. 67 ÷ 19

Answer:
67/19 = 10.

Explanation:
In the above-given question,
given that,
Divide, and then check.
19 x 3 = 57.
67 – 57 = 10.

e. 79 ÷ 25

Answer:
79/25 = 4.

Explanation:
In the above-given question,
given that,
Divide, and then check.
25 x 3 = 75.
79 – 75 = 4.

f. 83 ÷ 21

Answer:
83/21 = 20.

Explanation:
In the above-given question,
given that,
Divide, and then check.
21 x 3 = 63.
83 – 63 = 20.

Question 2.
A 91 square foot bathroom has a length of 13 feet. What is the width of the bathroom?

Answer:
The width of the bathroom = 7.

Explanation:
In the above-given question,
given that,
A 91 square foot bathroom has a length of 13 feet.
91/13 = 7.
The width of the bathroom = 7.

Question 3.
While preparing for a morning conference, Principal Corsetti is laying out 8 dozen bagels on square plates. Each plate can hold 14 bagels.
a. How many plates of bagels will Mr. Corsetti have?

Answer:
The plates of bagels will Mr. Corsetti have = 7.

Explanation:
In the above-given question,
given that,
while preparing for a morning conference, principal Corsetti is laying out 8 dozen bagels on square plates.
Each plate can hold 14 bagels.
8 x 12 = 96.
96/14 = 7.

b. How many more bagels would be needed to fill the final plate with bagels ?

Answer:
The bagels needed to fill the final plate = 56.

Explanation:
In the above-given question,
given that,
7 x 8 = 56.