## Engage NY Eureka Math 6th Grade Module 1 Lesson 22 Answer Key

### Eureka Math Grade 6 Module 1 Lesson 22 Example Answer Key

Example 1
Walker: Substitute the walker’s distance and time into the equation and solve for the rate of speed.
distance = rate . time
d = r . t

Hint: Consider the units that you want to end up with. If you want to end up with the rate (feet/second), then divide the distance (feet) by time (seconds).

Runner: Substitute the runner’s time and distance into the equation to find the rate of speed.
distance = rate . time
d = r . t
Here is a sample of student work using 8 seconds as an example:
d = r . t and r = $$\frac{d}{t}$$; Distance: 50 feet; TIme: 8 seconds
r = $$\frac{50}{8} \frac{\mathrm{ft}}{\mathrm{sec}}$$ = 6.25 $$\frac{\mathrm{ft}}{\mathrm{sec}}$$

Example 2
Part 1: Chris Johnson ran the 40-yard dash in 4.24 seconds. What is the rate of speed? Round any answer to the nearest hundredth.
distance = rate time
d = r.t
d = r.t and r = $$\frac{d}{t}$$; r = $$\frac{40}{4.24} \frac{y d}{\sec } \approx 9.43 \frac{y d}{\sec }$$

Part 2: In Lesson 21, we converted units of measure using unit rates. If the runner were able to run at a constant rate, how many yards would he run in an hour? This problem can be solved by breaking it down into two steps. Work with a partner, and make a record of your calculations.
a. How many yards would he run in one minute?

b. How many yards would he run in one hour?

We completed that problem in two separate steps, but it is possible to complete this same problem in one step. We can multiply the yards per second by the seconds per minute, then by the minutes per hour.

Cross out any units that are in both the numerator and denominator in the expression because these cancel each other out.

Part 3: How many miles did the runner travel in that hour? Round your response to the nearest tenth.

Cross out any units that are in both the numerator and denominator in the expression because they cancel out.

### Eureka Math Grade 6 Module 1 Lesson 22 Exercise Answer Key

Exercise 1.
I drove my car on cruise control at 65 miles per hour for 3 hours without stopping. How far did I go?
d = r.t

Cross out any units that are in both the numerator and denominator in the expression because they cancel out. d = ____ miles
d = 195 miles

Exercise 2
On the road trip, the speed limit changed to 50 miles per hour in a construction zone. Traffic moved along at a constant rate (50 mph), and it took me 15 minutes (0.25 hours) to get through the zone. What was the distance of the construction zone? (Round your response to the nearest hundredth of a mile.)
d = r t

d = 12.50 miles

### Eureka Math Grade 6 Module 1 Lesson 22 Problem Set Answer Key

Question 1.
If Adam’s plane traveled at a constant speed of 375 miles per hour for six hours, how far did the plane travel?
d = r . t

Question 2.
A Salt March Harvest Mouse ran a 360 centimeter straight course race in 9 seconds. How fast did it run?

Question 3.
Another Salt Marsh Harvest Mouse took 7 seconds to run a 350 centimeter race. How fast did it run?

Question 4.
A slow boat to China travels at a constant speed of 17.25 miles per hour for 200 hours. How far was the voyage?
d = r . t

Question 5.
The Sopwith Camel was a British, First World War, single-seat, biplane fighter introduced on the Western Front in 1917. Traveling at its top speed of 110 mph in one direction for 2$$\frac{1}{2}$$ hours, how far did the plane travel?
d = r . t

Question 6.
A world-class marathon runner can finish 26.2 miles in 2 hours. What is the rate of speed for the runner?