Eureka Math Grade 6 Module 4 Mid Module Assessment Answer Key

Engage NY Eureka Math Grade 6 Module 4 Mid Module Assessment Answer Key

Eureka Math Grade 6 Module 4 Mid Module Assessment Answer Key

Question 1.
Yolanda is planning out her vegetable garden. She decides that her garden will be square. Below are possible sizes of the garden she will create.

a. Complete the table by continuing the pattern.
Eureka Math Grade 6 Module 4 Mid Module Assessment Answer Key 1
Answer:
Eureka Math Grade 6 Module 4 Mid Module Assessment Answer Key 2

b. Yolanda decides the length of her square vegetable garden will be 17 ft. She calculates that the area of the garden is 34 ft2. Determine if Yolanda’s calculation is correct. Explain.
Answer:
A = l.w
A = 17 ft. . 17 ft.
A = 172 ft2
A = 289 ft2

Yolanda is incorrect. Instead of finding 172 (or 17 . 17), she multiplied 17 . 2, the base times the exponent.

Question 2.
Yolanda creates garden cubes to plant flowers. She will fill the cubes with soil and needs to know the amount of soil that will fill each garden cube. The volume of a cube is determined by the following formula: V = s3, where s equals the side length.
Eureka Math Grade 6 Module 4 Mid Module Assessment Answer Key 3

a. Represent the volume, in cubic inches, of the garden cube above using a numerical expression.
Answer:
323 or 32 . 32 . 32

b. Evaluate the expression to determine the volume of the garden cube and the amount of soil, in cubic inches, she will need for each cube.
Answer:
323 = 32 . 32 . 32 = 32,768

Question 3.
Explain why \(\left(\frac{1}{2}\right)^{4}=\frac{1}{16}\)
Answer:
Eureka Math Grade 6 Module 4 Mid Module Assessment Answer Key 4

Question 4.
Yolanda is building a patio in her backyard. She is interested in using both brick and wood for the flooring of the patio. Below is the plan she has created for the patio. All measurements are in feet.

a. Create an expression to represent the area of the patio.
Eureka Math Grade 6 Module 4 Mid Module Assessment Answer Key 5
Answer:
12.5(3 + x) or 37.5 + 12.5x

b. Yolanda’s husband develops another plan for the patio because he prefers the patio to be much wider than Yolanda’s plan. Determine the length of the brick section and the length of the wood section. Then, use the dimensions to write an expression that represents the area of the entire patio.
Eureka Math Grade 6 Module 4 Mid Module Assessment Answer Key 6
Answer:
Eureka Math Grade 6 Module 4 Mid Module Assessment Answer Key 7
24(2x + 4)

Question 5.
The landscaper hired for Yolanda’s lawn suggests a patio that has the same measure of wood as it has brick.
Eureka Math Grade 6 Module 4 Mid Module Assessment Answer Key 8hinery in India in Kannada 48

a. Express the perimeter of the patio in terms of x, first using addition and then using multiplication.
Answer:
x + x + x + 2x + 2x + x + x + x = 10x

b. Use substitution to determine if your expressions are equivalent. Explain.
Answer:
The expressions are equivalent.
Let x = 2
x + x + x + 2x + 2x + x + x + x
2 + 2 + 2 + 4 + 4 + 2 + 2 + 2 = 20
OR
10x = 10(2) = 20

Question 6.
Elena and Jorge have similar problems and find the same answer. Each determines that the solution to the problem is 24.
Elena: (14 + 42) ÷ 7 + 42
Jorge: 14 + (42 ÷ 7) + 42

a. Evaluate each expression to determine if both Elena and Jorge are correct.
Answer:
Elena: (14 + 42) ÷ 7 + 42
= 56 ÷ 7 + 42
= 56 ÷ 7 + 16
= 8 + 16 = 24

Jorge: 14 + (42 ÷ 7) + 42
= 14 + 6 + 42
= 14 + 6 + 16
= 20 + 16 = 36

b. Why would each find the solution of 24? What mistakes were made, if any?
Answer:
Elena followed the order of operations correctly. Jorge made a mistake. He added 14 + 42 first and then divided the sum by 7 to get 8. He did not follow the correct order of operations. He should have evaluated the parentheses first.

Question 7.
Jackson gave Lena this expression to evaluate: 14(8 + 12). Lena said that to evaluate the expression was simple; just multiply the factors 14 and 20. Jackson told Lena she was wrong. He solved it by finding the product of 14 and 8 and then adding that to the product of 14 and 12.

a. Evaluate the expression using each student’s method.

Lena’s Method Jackson’s Method

Answer:

Lena’s Method Jackson’s Method
14(8 + 12) =

14(20) =

280

14(8 + 12) =

112 + 168 =

280

b. Who was right in this discussion? why?
Answer:
They both were correct. Lena used the order of operations correctly to determine 280. Jackson used the distributive property to determine 280.

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