Eureka Math Grade 3 Module 7 Lesson 29 Answer Key

Engage NY Eureka Math 3rd Grade Module 7 Lesson 29 Answer Key

Eureka Math Grade 3 Module 7 Lesson 29 Sprint Answer Key

A
Multiply or Divide by 8
Engage NY Math 3rd Grade Module 7 Lesson 29 Sprint Answer Key s 1
Question 1.
2 × 8 =
Answer:

Question 2.
3 × 8 =
Answer:

Question 3.
4 × 8 =
Answer:

Question 4.
5 × 8 =
Answer:

Question 5.
1 × 8 =
Answer:

Question 6.
16 ÷ 8 =
Answer:

Question 7.
24 ÷ 8 =
Answer:

Question 8.
40 ÷ 8 =
Answer:

Question 9.
8 ÷ 8 =
Answer:

Question 10.
32 ÷ 8 =
Answer:

Question 11.
6 × 8 =
Answer:

Question 12.
7 × 8 =
Answer:

Question 13.
8 × 8 =
Answer:

Question 14.
9 × 8 =
Answer:

Question 15.
10 × 8 =
Answer:

Question 16.
64 ÷ 8 =
Answer:

Question 17.
56 ÷ 8 =
Answer:

Question 18.
72 ÷ 8 =
Answer:

Question 19.
48 ÷ 8 =
Answer:

Question 20.
80 ÷ 8 =
Answer:

Question 21.
___ × 8 = 40
Answer:

Question 22.
___ × 8 = 8
Answer:

Question 23.
___ × 8 = 80
Answer:

Question 24.
___ × 8 = 16
Answer:

Question 25.
___ × 8 = 24
Answer:

Question 26.
80 ÷ 8 =
Answer:

Question 27.
40 ÷ 8 =
Answer:

Question 28.
8 ÷ 8 =
Answer:

Question 29.
16 ÷ 8 =
Answer:

Question 30.
24 ÷ 8 =
Answer:

Question 31.
___ × 8 = 48
Answer:

Question 32.
___ × 8 = 56
Answer:

Question 33.
___ × 8 = 72
Answer:

Question 34.
___ × 8 = 64
Answer:

Question 35.
56 ÷ 8 =
Answer:

Question 36.
72 ÷ 8 =
Answer:

Question 37.
48 ÷ 8 =
Answer:

Question 38.
64 ÷ 8 =
Answer:

Question 39.
11 × 8 =
Answer:

Question 40.
88 ÷ 8 =
Answer:

Question 41.
12 × 8 =
Answer:

Question 42.
96 ÷ 8 =
Answer:

Question 43.
14 × 8 =
Answer:

Question 44.
112 ÷ 8 =
Answer:

B
Multiply or Divide by 8
Engage NY Math 3rd Grade Module 7 Lesson 29 Sprint Answer Key s 2
Question 1.
1× 8 =
Answer:

Question 2.
2 × 8 =
Answer:

Question 3.
3 × 8 =
Answer:

Question 4.
4 × 8 =
Answer:

Question 5.
5 × 8 =
Answer:

Question 6.
24 ÷ 8 =
Answer:

Question 7.
16 ÷ 8 =
Answer:

Question 8.
32 ÷ 8 =
Answer:

Question 9.
8 ÷ 8 =
Answer:

Question 10.
40 ÷ 8 =
Answer:

Question 11.
10 × 8 =
Answer:

Question 12.
6 × 8 =
Answer:

Question 13.
7 × 8 =
Answer:

Question 14.
8 × 8 =
Answer:

Question 15.
9 × 8 =
Answer:

Question 16.
56 ÷ 8 =
Answer:

Question 17.
8 ÷ 8 =
Answer:

Question 18.
64 ÷ 8 =
Answer:

Question 19.
80 ÷ 8 =
Answer:

Question 20.
72 ÷ 8 =
Answer:

Question 21.
___ × 8 = 8
Answer:

Question 22.
___ × 8 = 40
Answer:

Question 23.
___ × 8 = 16
Answer:

Question 24.
___ × 8 = 80
Answer:

Question 25.
___ × 8 = 24
Answer:

Question 26.
16 ÷ 8 =
Answer:

Question 27.
8 ÷ 8 =
Answer:

Question 28.
80 ÷ 8 =
Answer:

Question 29.
40 ÷ 8 =
Answer:

Question 30.
24 ÷ 8 =
Answer:

Question 31.
___ × 8 = 24
Answer:

Question 32.
___ × 8 = 32
Answer:

Question 33.
___ × 8 = 72
Answer:

Question 34.
___ × 8 = 56
Answer:

Question 35.
64 ÷ 8 =
Answer:

Question 36.
72 ÷ 8 =
Answer:

Question 37.
48 ÷ 8 =
Answer:

Question 38.
56 ÷ 8 =
Answer:

Question 39.
11 × 8 =
Answer:

Question 40.
88 ÷ 8 =
Answer:

Question 41.
12 × 8 =
Answer:

Question 42.
96 ÷ 8 =
Answer:

Question 43.
13 × 8 =
Answer:

Question 44.
104 ÷ 8 =
Answer:

Eureka Math Grade 3 Module 7 Lesson 29 Problem Set Answer Key

Question 1.
Kyle puts two rectangles together to make the L-shaped figure below. He measures some of the side lengths and records them as shown.
Engage NY Math Grade 3 Module 7 Lesson 29 Problem Set Answer Key p 1
a. Find the perimeter of Kyle’s shape.
b. Find the area of Kyle’s shape.
c. Kyle makes two copies of the L-shaped figure to create the rectangle shown below. Find the perimeter of the rectangle.
Engage NY Math Grade 3 Module 7 Lesson 29 Problem Set Answer Key p 2
Answer:

Question 2.
Jeremiah and Hayley use a piece of rope to mark a square space for their booth at the science fair. The area of their space is 49 square feet. What is the length of the rope that Jeremiah and Hayley use if they leave a 3-foot opening so they can get in and out of the space?
Answer:

Question 3.
Vivienne draws four identical rectangles as shown below to make a new, larger rectangle. The perimeter of one of the small rectangles is 18 centimeters, and the width is 6 centimeters. What is the perimeter of the new, larger rectangle?
Engage NY Math Grade 3 Module 7 Lesson 29 Problem Set Answer Key p 3
Answer:

Question 4.
A jogging path around the outside edges of a rectangular playground measures 48 yards by 52 yards. Maya runs 3\(\frac{1}{2}\) laps on the jogging path. What is the total number of yards Maya runs?
Answer:

Eureka Math Grade 3 Module 7 Lesson 29 Exit Ticket Answer Key

Jeannette draws four identical squares as shown below to make a new, larger square. The length of one of the small square sides is 8 centimeters. What is the perimeter of the new, larger square?
Eureka Math 3rd Grade Module 7 Lesson 29 Exit Ticket Answer Key t 1
Answer:

Eureka Math Grade 3 Module 7 Lesson 29 Homework Answer Key

Question 1.
Katherine puts two squares together to make the rectangle below. The side lengths of the squares measure 8 inches.
Eureka Math Grade 3 Module 7 Lesson 29 Homework Answer Key h 1
a. What is the perimeter of the rectangle Katherine made with her 2 squares?
b. What is the area of Katherine’s rectangle?
c. Katherine decides to draw another rectangle of the same size. What is the area of the new, larger rectangle?
Eureka Math Grade 3 Module 7 Lesson 29 Homework Answer Key h 2
Answer:

Question 2.
Daryl draws 6 equal-sized rectangles as shown below to make a new, larger rectangle. The area of one of the small rectangles is 12 square centimeters, and the width of the small rectangle is 4 centimeters..
Eureka Math Grade 3 Module 7 Lesson 29 Homework Answer Key h 3
a. What is the perimeter of Daryl’s new rectangle?
b. What is the area of Daryl’s new rectangle?
Answer:

Question 3.
The recreation center soccer field measures 35 yards by 65 yards. Chris dribbles the soccer ball around the perimeter of the field 4 times. What is the total number of yards Chris dribbles the ball?
Answer:

Eureka Math Grade 3 Module 7 Lesson 27 Answer Key

Engage NY Eureka Math 3rd Grade Module 7 Lesson 27 Answer Key

Eureka Math Grade 3 Module 7 Lesson 27 Sprint Sheet Answer Key

A
Multiply or Divide by 7
Engage NY Math 3rd Grade Module 7 Lesson 27 Sprint Answer Key s 1
Question 1.
2 × 7 =
Answer:

Question 2.
3 × 7 =
Answer:

Question 3.
4 × 7 =
Answer:

Question 4.
5 × 7 =
Answer:

Question 5.
1 × 7 =
Answer:

Question 6.
14 ÷ 7 =
Answer:

Question 7.
21 ÷ 7 =
Answer:

Question 8.
35 ÷ 7 =
Answer:

Question 9.
7 ÷ 7 =
Answer:

Question 10.
28 ÷ 7 =
Answer:

Question 11.
6 × 7 =
Answer:

Question 12.
7 × 7 =
Answer:

Question 13.
8 × 7 =
Answer:

Question 14.
9 × 7 =
Answer:

Question 15.
10 × 7 =
Answer:

Question 16.
56 ÷ 7 =
Answer:

Question 17.
49 ÷ 7 =
Answer:

Question 18.
63 ÷ 7 =
Answer:

Question 19.
42 ÷ 7 =
Answer:

Question 20.
70 ÷ 7 =
Answer:

Question 21.
___ × 7 = 35
Answer:

Question 22.
___ × 7 = 7
Answer:

Question 23.
___ × 7 = 70
Answer:

Question 24.
___ × 7 = 14
Answer:

Question 25.
___ × 7 = 21
Answer:

Question 26.
70 ÷ 7 =
Answer:

Question 27.
35 ÷ 7 =
Answer:

Question 28.
7 ÷ 7 =
Answer:

Question 29.
14 ÷ 7 =
Answer:

Question 30.
21 ÷ 7 =
Answer:

Question 31.
___ × 7 = 42
Answer:

Question 32.
___ × 7 = 49
Answer:

Question 33.
___ × 7 = 63
Answer:

Question 34.
___ × 7 = 56
Answer:

Question 35.
49 ÷ 7 =
Answer:

Question 36.
63 ÷ 7 =
Answer:

Question 37.
42 ÷ 7 =
Answer:

Question 38.
56 ÷ 7 =
Answer:

Question 39.
11 × 7 =
Answer:

Question 40.
77 ÷ 7 =
Answer:

Question 41.
12 × 7 =
Answer:

Question 42.
84 ÷ 7 =
Answer:

Question 43.
14 × 7 =
Answer:

Question 44.
98 ÷ 7 =
Answer:

B
Multiply or Divide by 7
Engage NY Math 3rd Grade Module 7 Lesson 27 Sprint Answer Key s 2
Question 1.
1 × 7 =
Answer:

Question 2.
2 × 7 =
Answer:

Question 3.
3 × 7 =
Answer:

Question 4.
4 × 7 =
Answer:

Question 5.
5 × 7 =
Answer:

Question 6.
21 ÷ 7 =
Answer:

Question 7.
14 ÷ 7 =
Answer:

Question 8.
28 ÷ 7 =
Answer:

Question 9.
7 ÷ 7 =
Answer:

Question 10.
35 ÷ 7 =
Answer:

Question 11.
10 × 7 =
Answer:

Question 12.
6 × 7 =
Answer:

Question 13.
7 × 7 =
Answer:

Question 14.
8 × 7 =
Answer:

Question 15.
9 × 7 =
Answer:

Question 16.
49 ÷ 7 =
Answer:

Question 17.
42 ÷ 7 =
Answer:

Question 18.
56 ÷ 7 =
Answer:

Question 19.
70 ÷ 7 =
Answer:

Question 20.
63 ÷ 7 =
Answer:

Question 21.
___ × 7 = 7
Answer:

Question 22.
___ × 7 = 35
Answer:

Question 23.
___ × 7 = 14
Answer:

Question 24.
___ × 7 = 70
Answer:

Question 25.
___ × 7 = 21
Answer:

Question 26.
14 ÷ 7 =
Answer:

Question 27.
7 ÷ 7 =
Answer:

Question 28.
70 ÷ 7 =
Answer:

Question 29.
35 ÷ 7 =
Answer:

Question 30.
21 ÷ 7 =
Answer:

Question 31.
___ × 7 = 21
Answer:

Question 32.
___ × 7 = 28
Answer:

Question 33.
___ × 7 = 63
Answer:

Question 34.
___ × 7 = 49
Answer:

Question 35.
56 ÷ 7 =
Answer:

Question 36.
63 ÷ 7 =
Answer:

Question 37.
42 ÷ 7 =
Answer:

Question 38.
49 ÷ 7 =
Answer:

Question 39.
11 × 7 =
Answer:

Question 40.
77 ÷ 7 =
Answer:

Question 41.
12 × 7 =
Answer:

Question 42.
84 ÷ 7 =
Answer:

Question 43.
13 × 7 =
Answer:

Question 44.
91 ÷ 7 =
Answer:

Eureka Math Grade 3 Module 7 Lesson 27 Problem Set Answer Key

Question 1.
Use the chart below to evaluate your friend’s robot. Measure the width and length of each rectangle. Then, calculate the perimeter. Record that information in the chart below. If your measurements differ from those listed on the project, put a star by the letter of the rectangle.

Item

Width and Length Student’s Perimeter

Required Perimeter

J About 25 cm
K __________ cm by __________cm 82 cm
L About 30 cm
M __________ cm by __________cm 30 cm
N About 20 cm
O __________ cm by __________cm 20 cm
P
Q

Answer:

Question 2.
Is the perimeter of the robot’s body double that of the arm? Show calculations below.
Answer:

Question 3.
Is the perimeter of the robot’s neck half the perimeter of the head? Show calculations below.
Answer:

Question 4.
Use the chart below to evaluate your friend’s robot environment. Measure the width and length of each rectangle. Then, calculate the perimeter. Use your string to measure the perimeters of nonrectangular items. Record that information in the chart below. If your measurements differ from those listed on the project, put a star by the letter of the shape.

Rectangle: Width and Length: Perimeter

Area

A _________ cm by _________cm
B _________ cm by _________cm

Answer:

Eureka Math Grade 3 Module 7 Lesson 27 Exit Ticket Answer Key

Question 1.
Record the perimeters and areas of Rectangles A and B in the chart below.
Eureka Math 3rd Grade Module 7 Lesson 27 Exit Ticket Answer Key t 1
tableee
Answer:

Question 2.
What is the same about Rectables A and B? What is different?
Answer:

Eureka Math Grade 3 Module 7 Lesson 27 Homework Answer Key

Record the perimeters and areas of the rectangles in the chart on the next page.
Eureka Math Grade 3 Module 7 Lesson 27 Homework Answer Key h 1

Question 1.
Find the area and perimeter of each rectangle.

Rectangle

Width and Length Perimeter

Area

A __________ cm by __________cm
B __________ cm by __________cm
C __________ cm by __________cm
D __________ cm by __________cm
E _________ cm by __________cm
F __________ cm by __________cm

Answer:

Question 2.
What do you notice about the perimeters of Rectangles A, B, and C?
Answer:

Question 3.
What do you notice about the perimeters of Rectangles D, E, and F?
Answer:

Question 4.
Which two rectangles are squares? Which square has the greater perimeter?
Answer:

Eureka Math Grade 3 Module 7 Lesson 27 Evaluation Rubric Answer Key

Evaluation Rubric

4 3 2 2 Subtotal
Perimeter calculations for all shapes are correct, and both evaluations of a classmate’s project have been completed. Perimeter calculations include 1 to 2 errors, and both evaluations of a classmate’s project have been completed. Perimeter calculations include 3 to 4 errors, and at least 1 evaluation of a classmate’s project has been completed. Perimeter calculations include 5 or more errors, and at least 1 evaluation of a classmate’s project has been completed. _____/4

Eureka Math Grade 3 Module 7 Lesson 26 Answer Key

Engage NY Eureka Math 3rd Grade Module 7 Lesson 26 Answer Key

Eureka Math Grade 3 Module 7 Lesson 26 Pattern Sheet Answer Key

Multiply.
Engage NY Math 3rd Grade Module 7 Lesson 26 Sprint Answer Key p 1
multiply by 7 (6–10)
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-26-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 26 Pattern Sheet Answer Key
Explanation:
7 × 6 = 42
7 × 7 = 49
7 × 8 = 56
7 × 9 = 63
7 × 10 = 70.

Eureka Math Grade 3 Module 7 Lesson 26 Problem Set Answer Key

Question 1.
Collect the area measurements of your classmates’ robot bodies. Make a line plot using everyone’s area measurements.
Areas of Robot Bodies
Engage NY Math Grade 3 Module 7 Lesson 26 Problem Set Answer Key pr 1
a. How many different measurements are on the line plot? Why are the measurements different?
b. What does this tell you about the relationship between area and perimeter?
Answer:
a. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-26-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 26 Problem Set Answer Key-1a
There are four different kinds of measurements represented on the number line. They are different in values because the values of every rectangle is different from each other.

b. Perimeter is the measurement of the distance around a shape. Area is the measurement of space inside a shape. Area and Perimeter are not having any relationship because they are totally two different things. Perimeter is going to be more than the area of the rectangle.

Explanation:
a.
Eureka Math Grade 3 Module 7 Lesson 25 Homework Answer Key h 1
Area of the A rectangle = Length × Width = 4cm × 4cm = 16 square cm.
Area of the B rectangle = Length × Width = 2cm × 2cm = 16 square cm.
Area of the C rectangle = Length × Width = 8cm × 6cm = 48 square cm.
Area of the D rectangle = Length × Width = 5cm × 2cm = 10 square cm.
Area of the E rectangle = Length × Width = 5cm × 2cm = 10 square cm.
Area of the F rectangle = Length × Width = 7cm × 2cm = 14 square cm.
Area of the G rectangle = Length × Width = 7cm × 2cm = 14 square cm.
There are four different kinds of measurements represented on the number line. They are different in values because the values of every rectangle is different from each other.

b. Perimeter is the measurement of the distance around a shape. Area is the measurement of space inside a shape.
For Example : If a rectangle having length as 2cm and width as 1cm.
Perimeter = 2 (Length + Width) = 2 ( 2cm + 1cm) = 2 × 3cm = 6cm.
Area = length × Width = 2cm × 1cm = 2 square cm.
Area and Perimeter are not having any relationship because they are totally two different things.

 

Question 2.
Measure and calculate the perimeter of your construction paper in inches. Show your work below.
Answer:
Perimeter of my construction paper = 80 inches.

Explanation:
This is my construction paper.
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-26-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 26 Problem Set Answer Key-2
Length of my construction paper = 28 inches.
Width of my construction paper = 12 inches.
Perimeter of my construction paper = 2 ( Length + Width )
= 2 ( 28 inches + 12 inches )
= 2 × 40 inches
= 80 inches.

 

Question 3.
Sketch and label two shapes with the same perimeter from the robot’s environment. What do you notice about the way they look?
Answer:
Even though my two figure have the same Perimeter as 20cm yet they appearances are complete different in size and looks.

Explanation:

Same in perimeter the figure are yet different in size and appearance.

 

 

Question 4.
Write two or three sentences describing your robot and the environment in which it lives.
Answer:
My Robot name is Mr. Kool. He lives in machine land, where there are different kinds of Robots.  He is very friendly in nature. He loves to help others in their works. He is taller than other Robots in his locality. He does all kinds of works and loves to be around people. He makes difficult works in a easy way.

Explanation:
My Robot name is Mr. Kool. He lives in machine land, where there are different kinds of Robots. He is taller than other Robots in his locality. He is very friendly in nature. He loves to help others in their works.

 

Eureka Math Grade 3 Module 7 Lesson 26 Exit Ticket Answer Key

Question 1.
Use string to help you sketch a circle with a perimeter of about 15 centimeters.
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-26-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 26 Exit Ticket Answer Key-1

Explanation:
A figure is the circle having its Perimeter as 15 centimeters.

 

Question 2.
Estimate to draw a rectangle with a perimeter of 15 centimeters. Label the width and length.
Answer:
Perimeter of the ABCD rectangle = 15 centimeters.

Explanation:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-26-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 26 Exit Ticket Answer Key-2
Length of the ABCD rectangle = 4.5cm
Width of the ABCD rectangle =  3cm
Perimeter of the ABCD rectangle = 2 ( Length + Width )
= 2 ( 4.5cm + 3cm )
= 2 × 7.5cm
= 15 centimeters.

 

Eureka Math Grade 3 Module 7 Lesson 26 Homework Answer Key

Question 1.
Use Rectangles A and B to answer the questions below.
Eureka Math Grade 3 Module 7 Lesson 26 Homework Answer Key h 1
a. What is the perimeter of Rectangle A?
b. What is the perimeter of Rectangle B?
c. What is the area of Rectangle A?
d. What is the area of Rectangle B?
e. Use your answers to parts (a–d) to help you explain the relationship between area and perimeter.

Answer:
a. Perimeter of the Rectangle A =  16cm.
b. Perimeter of the Rectangle B = 16cm.
c. Area of the Rectangle A = 16 Square cm.
d. Area of the Rectangle B = 15 square cm.
e. The Perimeter of Rectangle A and Rectangle B are same 16cm. The Area of the Rectangle A is 16 square cm and Rectangle B is 15 square cm. There is no connection between the Perimeter and the Area. It is observed that the Perimeter values are more than the Area values of the rectangles.

Explanation:
a. Eureka Math Grade 3 Module 7 Lesson 26 Homework Answer Key h 1
Length of the Rectangle A = 4cm
Width of the Rectangle A =  4cm
Perimeter of the Rectangle A = 2 ( Length + Width )
= 2 ( 4cm + 4cm )
= 2 × 8cm
= 16cm.

b. Length of the Rectangle B = 5cm
Width of the Rectangle B =  3cm
Perimeter of the Rectangle B = 2 ( Length + Width )
= 2 ( 5cm + 3cm )
= 2 × 8cm
= 16cm.

c. Length of the Rectangle A = 4cm
Width of the Rectangle A =  4cm
Area of the Rectangle A =  Length × Width
=  4cm × 4cm
= 16 Square cm.

d. Length of the Rectangle B = 5cm
Width of the Rectangle B =  3cm
Area of the Rectangle B =  Length × Width
=  5cm × 3cm
= 15 square cm.

e. There is no connection between the Perimeter and the Area. It is observed that the Perimeter values are more than the Area values of the rectangles.

 

Question 2.
Each student in Mrs. Dutra’s class draws a rectangle with whole number side lengths and a perimeter of 28 centimeters. Then, they find the area of each rectangle and create the table below.

Area in Square Centimeters

Number of Students

13 2
24 1
33 3
40 5
45 4
48 2
49 2

a. Give two examples from Mrs. Dutra’s class to show how it is possible to have different areas for rectangles that have the same perimeter.
b. Did any students in Mrs. Dutra’s class draw a square? Explain how you know.
c. What are the side lengths of the rectangle that most students in Mrs. Dutra’s class made with a perimeter of 28 centimeters?
Answer:
a. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-26-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 26 Exit Ticket Answer Key-3a
b. Yes, among all students in  Mrs. Dutra’s class there is one student whose rectangle is said to be a square because all the sides are of 6cm each and have an area as 24 square cm.

c. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-26-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 26 Exit Ticket Answer Key-3c

Explanation:
a. Here are two students rectangles having same perimeters yet different in areas for their rectangles are shown.

b. Area of the rectangles whose is 24 square cm, is said to be a square of having side length value as 6 cm.

c. Well, the side lengths of the rectangle that most students in Mrs. Dutra’s class made with a perimeter of 28 centimeters are: ( Length, Width)
(12,2);  (11,3);  (10,4);  (9,5);  (8,6);  (7,7).

Eureka Math Grade 3 Module 7 Lesson 25 Answer Key

Engage NY Eureka Math 3rd Grade Module 7 Lesson 25 Answer Key

Eureka Math Grade 3 Module 25 Lesson 4 Sprint Answer Key

A
Multiply or Divide by 6
Engage NY Math 3rd Grade Module 7 Lesson 25 Sprint Answer Key s 1
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-25-Answer-Key-Eureka Math Grade 3 Module 25 Lesson 4 Sprint Answer Key
Question 1.
2 × 6 =
Answer:
2 × 6 = 12.

Question 2.
3 × 6 =
Answer:
3 × 6 = 18.

Question 3.
4 × 6 =
Answer:
4 × 6 = 24.

Question 4.
5 × 6 =
Answer:
5 × 6 = 30.

Question 5.
1 × 6 =
Answer:
1 × 6 = 6.

Question 6.
12 ÷ 6 =
Answer:
12 ÷ 6 = 2.

Question 7.
18 ÷ 6 =
Answer:
18 ÷ 6 = 3.

Question 8.
30 ÷ 6 =
Answer:
30 ÷ 6 = 5.

Question 9.
6 ÷ 6 =
Answer:
6 ÷ 6 = 1.

Question 10.
24 ÷ 6 =
Answer:
24 ÷ 6 = 4.

Question 11.
6 × 6 =
Answer:
6 × 6 = 36.

Question 12.
7 × 6 =
Answer:
7 × 6 = 42.

Question 13.
8 × 6 =
Answer:
8 × 6 = 48.

Question 14.
9 × 6 =
Answer:
9 × 6 = 54.

Question 15.
10 × 6 =
Answer:
10 × 6 = 60.

Question 16.
48 ÷ 6 =
Answer:
48 ÷ 6 = 8.

Question 17.
42 ÷ 6 =
Answer:
42 ÷ 6 = 7.

Question 18.
54 ÷ 6 =
Answer:
54 ÷ 6 = 9.

Question 19.
36 ÷ 6 =
Answer:
36 ÷ 6 = 6.

Question 20.
60 ÷ 6 =
Answer:
60 ÷ 6 = 10.

Question 21.
___ × 6 = 30
Answer:
_5__ × 6 = 30.

Question 22.
___ × 6 = 6
Answer:
_1__ × 6 = 6.

Question 23.
___ × 6 = 60
Answer:
_10__ × 6 = 60.

Question 24.
___ × 6 = 12
Answer:
_2__ × 6 = 12.

Question 25.
___ × 6 = 18
Answer:
_3__ × 6 = 18.

Question 26.
60 ÷ 6 =
Answer:
60 ÷ 6 = 10.

Question 27.
30 ÷ 6 =
Answer:
30 ÷ 6 = 5.

Question 28.
6 ÷ 6 =
Answer:
6 ÷ 6 = 1.

Question 29.
12 ÷ 6 =
Answer:
12 ÷ 6 = 2.

Question 30.
18 ÷ 6 =
Answer:
18 ÷ 6 = 3.

Question 31.
___ × 6 = 36
Answer:
_6__ × 6 = 36.

Question 32.
___ × 6 = 42
Answer:
_7__ × 6 = 42.

Question 33.
___ × 6 = 54
Answer:
_9__ × 6 = 54.

Question 34.
___ × 6 = 48
Answer:
_8__ × 6 = 48.

Question 35.
42 ÷ 6 =
Answer:
42 ÷ 6 = 7.

Question 36.
54 ÷ 6 =
Answer:
54 ÷ 6 = 9.

Question 37.
36 ÷ 6 =
Answer:
36 ÷ 6 = 6.

Question 38.
48 ÷ 6 =
Answer:
48 ÷ 6 = 8.

Question 39.
11 × 6 =
Answer:
11 × 6 = 66.

Question 40.
66 ÷ 6 =
Answer:
66 ÷ 6 = 11.

Question 41.
12 × 6 =
Answer:
12 × 6 = 72.

Question 42.
72 ÷ 6 =
Answer:
72 ÷ 6 = 12.

Question 43.
14 × 6 =
Answer:
14 × 6 = 84.

Question 44.
84 ÷ 6 =
Answer:
84 ÷ 6 = 14.

B
Multiply or Divide by 6
Engage NY Math 3rd Grade Module 7 Lesson 25 Sprint Answer Key s 2
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-25-Answer-Key-Eureka Math Grade 3 Module 25 Lesson 4 Sprint Answer Key-B
Question 1.
1 × 6 =
Answer:
1 × 6 = 6.

Question 2.
2 × 6 =
Answer:
2 × 6 = 12.

Question 3.
3 × 6 =
Answer:
3 × 6 = 18.

Question 4.
4 × 6 =
Answer:
4 × 6 = 24.

Question 5.
5 × 6 =
Answer:
5 × 6 = 30.

Question 6.
18 ÷ 6 =
Answer:
18 ÷ 6 = 3.

Question 7.
12 ÷ 6 =
Answer:
12 ÷ 6 = 2.

Question 8.
24 ÷ 6 =
Answer:
24 ÷ 6 = 4.

Question 9.
6 ÷ 6 =
Answer:
6 ÷ 6 = 1.

Question 10.
30 ÷ 6 =
Answer:
30 ÷ 6 = 5.

Question 11.
10 × 6 =
Answer:
10 × 6 = 60.

Question 12.
6 × 6 =
Answer:
6 × 6 = 36.

Question 13.
7 × 6 =
Answer:
7 × 6 = 42.

Question 14.
8 × 6 =
Answer:
8 × 6 = 48.

Question 15.
9 × 6 =
Answer:
9 × 6 = 54.

Question 16.
42 ÷ 6 =
Answer:
42 ÷ 6 = 7.

Question 17.
36 ÷ 6 =
Answer:
36 ÷ 6 = 6.

Question 18.
48 ÷ 6 =
Answer:
48 ÷ 6 = 8.

Question 19.
60 ÷ 6 =
Answer:
60 ÷ 6 = 10.

Question 20.
54 ÷ 6 =
Answer:
54 ÷ 6 = 9.

Question 21.
___ × 6 = 6
Answer:
__1_ × 6 = 6.

Question 22.
___ × 6 = 30
Answer:
_5__ × 6 = 30.

Question 23.
___ × 6 = 12
Answer:
_2__ × 6 = 12.

Question 24.
___ × 6 = 60
Answer:
_10__ × 6 = 60.

Question 25.
___ × 6 = 18
Answer:
_3__ × 6 = 18.

Question 26.
12 ÷ 6 =
Answer:
12 ÷ 6 = 2.

Question 27.
6 ÷ 6 =
Answer:
6 ÷ 6 = 1.

Question 28.
60 ÷ 6 =
Answer:
60 ÷ 6 = 10.

Question 29.
30 ÷ 6 =
Answer:
30 ÷ 6 = 5.

Question 30.
18 ÷ 6 =
Answer:
18 ÷ 6 = 3.

Question 31.
___ × 6 = 18
Answer:
_3__ × 6 = 18 .

Question 32.
___ × 6 = 24
Answer:
_4__ × 6 = 24.

Question 33.
___ × 6 = 54
Answer:
_9__ × 6 = 54.

Question 34.
___ × 6 = 42
Answer:
_7__ × 6 = 42.

Question 35.
48 ÷ 6 =
Answer:
48 ÷ 6 = 8.

Question 36.
54 ÷ 6 =
Answer:
54 ÷ 6 = 9.

Question 37.
36 ÷ 6 =
Answer:
36 ÷ 6 = 6.

Question 38.
42 ÷ 6 =
Answer:
42 ÷ 6 = 7.

Question 39.
11 × 6 =
Answer:
11 × 6 = 66.

Question 40.
66 ÷ 6 =
Answer:
66 ÷ 6 = 11.

Question 41.
12 × 6 =
Answer:
12 × 6 = 72.

Question 42.
72 ÷ 6 =
Answer:
72 ÷ 6 = 12.

Question 43.
13 × 6 =
Answer:
13 × 6 = 78.

Question 44.
78 ÷ 6 =
Answer:
78 ÷ 6 = 13.

Eureka Math Grade 3 Module 7 Lesson 25 Problem Set Answer Key

Draw a picture of your robot in its environment in the space below. Label the widths, lengths, and perimeters of all rectangles. Label the perimeters of all circular shapes.
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-25-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 25 Problem Set Answer Key

Explanation:
Here is the picture of my Robot with all the labeling of its body parts and their perimeters.

Eureka Math Grade 3 Module 7 Lesson 25 Exit Ticket Answer Key

Question 1.
1. Sketch rectangles with the following perimeters. Label the side lengths.
a. 22 cm
b. 30 cm
Answer:
a. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-25-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 25 Exit Ticket Answer Key-1a

b. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-25-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 25 Exit Ticket Answer Key-1b
Explanation:
a. We could draw four different rectangles for having Perimeter as 22cm.
b. We could draw five different rectangles for having Perimeter as 30cm.

 

Question 2.
Explain the steps you took to create the rectangles with the given perimeters.
Answer:
Step 1 : Considered the perimeter value.
Step 2 : Later, considered the formula of perimeter of rectangle = 2 ( Length + Width ).
Step 3 : Divided the perimeter value by 2.
Step 4 : Result  is taken and divided into two parts where one value is going to be higher than the other.
Step 5 : Considered higher value as Length and smaller as Width.

Explanation:
Steps taken to create the rectangles with the given perimeters are:
Step 1 : Considered the perimeter value.
Step 2 : Later, considered the formula of perimeter of rectangle = 2 ( Length + Width ).
Step 3 : Divided the perimeter value by 2.
Step 4 : Result  is taken and divided into two parts where one value is going to be higher than the other.
Step 5 : Considered higher value as Length and smaller as Width.

 

Eureka Math Grade 3 Module 7 Lesson 25 Homework Answer Key

The robot below is made of rectangles. The side lengths of each rectangle are labeled. Find the perimeter of each rectangle, and record it in the table on the next page.
Eureka Math Grade 3 Module 7 Lesson 25 Homework Answer Key h 1

Rectangle

Perimeter

A P = 4 × 4 cm
P = 16 cm
B
C
D
E
F
G

Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-25-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 25 Homework Answer Key
Explanation:
The Robot all body Parts  Perimeters are calculated in the above chart.

 

Eureka Math Grade 3 Module 7 Lesson 25 Evaluation Rubric Answer Key

Evaluation Rubric

4 3 2 1 Subtotal
Perimeter calculations for all shapes are correct, and both evaluations of a classmate’s project have been completed. Perimeter calculations include 1 to 2 errors, and both evaluations of a classmate’s project have been completed. Perimeter calculations include 3 to 4 errors, and at least 1 evaluation of a classmate’s project has been completed. Perimeter calculations include 5 or more errors, and at least 1 evaluation of a classmate’s project has been completed. _____/4
Perimeter calculations include 1 2 3  to 5 errors, and all evaluation of a classmate’s project has been completed.

Eureka Math Grade 3 Module 7 Lesson 24 Answer Key

Engage NY Eureka Math 3rd Grade Module 7 Lesson 24 Answer Key

Eureka Math Grade 3 Module 7 Lesson 24 Pattern Sheet Answer Key

Multiply.
Engage NY Math 3rd Grade Module 7 Lesson 23 Pattern Sheet Answer Key p 1
multiply by 6 (6–10)
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 24 Pattern Sheet Answer Key
Explanation:
6 × 6 = 36
6 × 7 = 42
6 × 8 = 48
6 × 9 = 54
6 × 10 = 60.

Eureka Math Grade 3 Module 7 Lesson 24 Problem Set Answer Key

Use the given perimeters in the chart below to choose the widths and lengths of your robot’s rectangular body parts. Write the widths and lengths in the chart below. Use the blank rows if you want to add extra rectangular body parts to your robot.

Letter

Body Part Perimeter

Width and Length

A arm 14 cm __________ cm by __________cm
B arm 14 cm __________ cm by __________cm
C leg 18 cm __________ cm by __________cm
D leg 18 cm __________ cm by __________cm
E body Double the perimeter of one arm = _______ cm __________ cm by __________cm
F head 16 cm __________ cm by __________cm
G neck Half the perimeter of the head =

_______ cm

__________ cm by __________cm
H __________ cm by __________cm
I __________ cm by __________cm
My robot has 7 to 9 rectangular body parts.  Number of body parts:  _______

Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 24 Problem Set Answer Key Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 24 Problem Set Answer Key-

Use the information in the chart below to plan an environment for your robot. Write the width and length for each rectangular item. Use the blank rows if you want to add extra circular or rectangular items to your robot’s environment.

Letter Item Shape Perimeter

Width and Length

J sun circle about 25 cm
K house rectangle 82 cm __________ cm by __________cm
L tree top circle about 30 cm
M tree trunk rectangle 30 cm __________ cm by __________cm
N tree top circle about 20 cm
O tree trunk rectangle 20 cm __________ cm by __________cm
P
Q
My robot’s environment has 6 to 8 items.  Number of items:  _______

Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 24 Problem Set Answer Key-1

Eureka Math Grade 3 Module 7 Lesson 24 Exit Ticket Answer Key

Estimate to draw three different rectangles with a perimeter of 16 centimeters. Label the width and length of each rectangle.
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 24 Exit Ticket Answer Key

Explanation:
Using the Perimeter of 16 cm we can draw three rectangles ABCD, EFGH, IJKL with different lengths and width.

 

Eureka Math Grade 3 Module 7 Lesson 24 Homework Answer Key

Question 1.
Brian draws a square with a perimeter of 24 inches. What is the length of the side of the square?
Answer:
Length of the side of the square = 6 inches.

Explanation:
Perimeter of the Square = 24 inches
Number of sides in the square = 4
Length of the side of the square = Perimeter of the Square  ÷ Number of sides in the square
= 24 inches ÷ 4
= 6 inches.

Question 2.
A rectangle has a perimeter of 18 centimeters.
a. Estimate to draw as many different rectangles as you can that have a perimeter of 18 centimeters. Label the width and length of each rectangle.
b. How many different rectangles did you find?
c. Explain the strategy you used to find the rectangles.
Answer:
a. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 24 Homework Answer Key-2a

b. I could find three different rectangles having perimeter as 18 centimeters.

c. The strategy which I used to find the rectangles is that :
Step 1:  Considered the Perimeter formula 2 ( Length + Width ) and its perimeter value 18 centimeters.
Step 2: Calculated the Length and width values.
Step 3: Keeping in mind highest value as length and lesser as Width.

Explanation:
a. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 24 Homework Answer Key-2a
b. I could find three different rectangles having perimeter as 18 centimeters.
c. The strategy which I used to find the rectangles is that :
Step 1:  Considered the Perimeter formula 2 ( Length + Width ) and its perimeter value 18 centimeters.
Step 2: Calculated the Length and width values.
Step 3: Keeping in mind highest value as length and lesser as Width.

 

Question 3.
The chart below shows the perimeters of three rectangles.
a. Write possible widths and lengths for each given perimeter.

Rectangle Perimeter

Width and Length

A 6 cm __________ cm by __________ cm
B 10 cm __________ cm by __________ cm
C 14 cm __________ cm by __________ cm

b. Double the perimeters of the rectangles in part (a). Then, find possible widths and lengths.

Rectangle Perimeter

Width and Length

A 12 cm __________ cm by __________ cm
B __________ cm by __________ cm
C __________ cm by __________ cm

Answer:
a. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 24 Homework Answer Key-3
b. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 24 Homework Answer Key-3b
Explanation:
a. For the perimeter of 6cm, we have a rectangle length as 2cm and width as 1cm.
For the perimeter of 10cm, we have a rectangle length as 2cm and width as 3cm.
For the perimeter of 14cm, we have a rectangle length as 3cm and width as 4cm.

b. For the perimeter of 12cm, we have a rectangle length as 2cm and width as 4cm.

 

Eureka Math Grade 3 Module 7 Lesson 23 Answer Key

Engage NY Eureka Math 3rd Grade Module 7 Lesson 23 Answer Key

Eureka Math Grade 3 Module 7 Lesson 23 Sprint Answer Key

A
Multiply or Divide by 5
Engage NY Math 3rd Grade Module 7 Lesson 23 Sprint Answer Key s 1
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-23-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 23 Sprint Answer Key-A
Question 1.
2 × 5 =
Answer:
2 × 5 = 10.

Question 2.
3 × 5 =
Answer:
3 × 5 = 15.

Question 3.
4 × 5 =
Answer:
4 × 5 = 20.

Question 4.
5 × 5 =
Answer:
5 × 5 = 25.

Question 5.
1 × 5 =
Answer:
1 × 5 = 5.

Question 6.
10 ÷ 5 =
Answer:
10 ÷ 5 = 2.

Question 7.
15 ÷ 5 =
Answer:
15 ÷ 5 = 3.

Question 8.
25 ÷ 5 =
Answer:
25 ÷ 5 = 5.

Question 9.
5 ÷ 5 =
Answer:
5 ÷ 5 = 1.

Question 10.
20 ÷ 5 =
Answer:
20 ÷ 5 = 4.

Question 11.
6 × 5 =
Answer:
6 × 5 = 30.

Question 12.
7 × 5 =
Answer:
7 × 5 = 35.

Question 13.
8 × 5 =
Answer:
8 × 5 = 40.

Question 14.
9 × 5 =
Answer:
9 × 5 = 45.

Question 15.
10 × 5 =
Answer:
10 × 5 = 50.

Question 16.
40 ÷ 5 =
Answer:
40 ÷ 5 = 8.

Question 17.
35 ÷ 5 =
Answer:
35 ÷ 5 = 7.

Question 18.
45 ÷ 5 =
Answer:
45 ÷ 5 = 9.

Question 19.
30 ÷ 5 =
Answer:
30 ÷ 5 = 6.

Question 20.
50 ÷ 5 =
Answer:
50 ÷ 5 = 10.

Question 21.
___ × 5 = 25
Answer:
_5__ × 5 = 25.

Question 22.
___ × 5 = 5
Answer:
_1__ × 5 = 5.

Question 23.
___ × 5 = 50
Answer:
_10__ × 5 = 50.

Question 24.
___ × 5 = 10
Answer:
_2__ × 5 = 10.

Question 25.
___ × 5 = 15
Answer:
_3__ × 5 = 15.

Question 26.
50 ÷ 5 =
Answer:
50 ÷ 5 = 10.

Question 27.
25 ÷ 5 =
Answer:
25 ÷ 5 = 5.

Question 28.
5 ÷ 5 =
Answer:
5 ÷ 5 = 1.

Question 29.
10 ÷ 5 =
Answer:
10 ÷ 5 = 2.

Question 30.
15 ÷ 5 =
Answer:
15 ÷ 5 = 3.

Question 31.
___ × 5 = 30
Answer:
_6__ × 5 = 30.

Question 32.
___ × 5 = 35
Answer:
_7__ × 5 = 35.

Question 33.
___ × 5 = 45
Answer:
__9_ × 5 = 45.

Question 34.
___ × 5 = 40
Answer:
__8_ × 5 = 40.

Question 35.
35 ÷ 5 =
Answer:
35 ÷ 5 = 7.

Question 36.
45 ÷ 5 =
Answer:
45 ÷ 5 = 9.

Question 37.
30 ÷ 5 =
Answer:
30 ÷ 5 = 6.

Question 38.
40 ÷ 5 =
Answer:
40 ÷ 5 = 8.

Question 39.
11 × 5 =
Answer:
11 × 5 = 55.

Question 40.
55 ÷ 5 =
Answer:
55 ÷ 5 = 11.

Question 41.
15 ÷ 5 =
Answer:
15 ÷ 5 = 3.

Question 42.
60 ÷ 5 =
Answer:
60 ÷ 5 = 12.

Question 43.
12 × 5 =
Answer:
12 × 5 = 60.

Question 44.
70 ÷ 5 =
Answer:
70 ÷ 5 = 14.

B
Multiply or Divide by 5
Engage NY Math 3rd Grade Module 7 Lesson 23 Sprint Answer Key s 2
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-23-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 23 Sprint Answer Key-B
Question 1.
1 × 5 =
Answer:
1 × 5 = 5.

Question 2.
2 × 5 =
Answer:
2 × 5 = 10.

Question 3.
3 × 5 =
Answer:
3 × 5 = 15.

Question 4.
4 × 5 =
Answer:
4 × 5 = 20.

Question 5.
5 × 5 =
Answer:
5 × 5 = 25.

Question 6.
15 ÷ 5 =
Answer:
15 ÷ 5 = 3.

Question 7.
10 ÷ 5 =
Answer:
10 ÷ 5 = 2.

Question 8.
20 ÷ 5 =
Answer:
20 ÷ 5 = 4.

Question 9.
5 ÷ 5 =
Answer:
5 ÷ 5 = 1.

Question 10.
25 ÷ 5 =
Answer:
25 ÷ 5 = 5.

Question 11.
10 × 5 =
Answer:
10 × 5 = 50.

Question 12.
6 × 5 =
Answer:
6 × 5 = 30.

Question 13.
7 × 5 =
Answer:
7 × 5 = 35.

Question 14.
8 × 5 =
Answer:
8 × 5 = 40.

Question 15.
9 × 5 =
Answer:
9 × 5 = 45.

Question 16.
35 ÷ 5 =
Answer:
35 ÷ 5 = 7.

Question 17.
30 ÷ 5 =
Answer:
30 ÷ 5 = 6.

Question 18.
40 ÷ 5 =
Answer:
40 ÷ 5 = 8.

Question 19.
50 ÷ 5 =
Answer:
50 ÷ 5 = 10.

Question 20.
45 ÷ 5 =
Answer:
45 ÷ 5 = 9.

Question 21.
___ × 5 = 5
Answer:
_1__ × 5 = 5.

Question 22.
___ × 5 = 25
Answer:
_5__ × 5 = 25.

Question 23.
___ × 5 = 10
Answer:
_2__ × 5 = 10.

Question 24.
___ × 5 = 50
Answer:
_10__ × 5 = 50.

Question 25.
___ × 5 = 15
Answer:
_3__ × 5 = 15.

Question 26.
10 ÷ 5 =
Answer:
10 ÷ 5 = 50.

Question 27.
5 ÷ 5 =
Answer:

Question 28.
50 ÷ 5 =
Answer:

Question 29.
25 ÷ 5 =
Answer:

Question 30.
15 ÷ 5 =
Answer:

Question 31.
___ × 5 = 15
Answer:

Question 32.
___ × 5 = 20
Answer:

Question 33.
___ × 5 = 45
Answer:

Question 34.
___ × 5 = 35
Answer:

Question 35.
40 ÷ 5 =
Answer:

Question 36.
45 ÷ 5 =
Answer:

Question 37.
30 ÷ 5 =
Answer:

Question 38.
35 ÷ 5 =
Answer:

Question 39.
11 × 5 =
Answer:

Question 40.
55 ÷ 5 =
Answer:

Question 41.
12 × 5 =
Answer:

Question 42.
60 ÷ 5 =
Answer:

Question 43.
13 × 5 =
Answer:

Question 44.
65 ÷ 5 =
Answer:

Eureka Math Grade 3 Module 7 Lesson 23 Problem Set Answer Key

Question 1.
Gale makes a miniature stop sign, a regular octagon, with a perimeter of 48 centimeters for the town he built with blocks. What is the length of each side of the stop sign?
Answer:
The length of each side of the stop sign = 6 centimeters.
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-23-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 23 Problem Set Answer Key-1

Explanation:
Perimeter of Gale a miniature stop sign, a regular octagon = 48 centimeters
Number of sides of Gale a miniature stop sign, a regular octagon = 8
The length of each side of the stop sign = Perimeter of Gale a miniature stop sign, a regular octagon  ÷ Number of sides of Gale a miniature stop sign, a regular octagon
= 48 centimeters ÷  8
= 6 centimeters.

 

Question 2.
Travis bends wire to make rectangles. Each rectangle measures 34 inches by 12 inches. What is the total length of the wire needed for two rectangles?
Answer:
The total length of the wire needed for two rectangles = 184 inches.

Explanation:
Length of the Travis’s rectangle = 34 inches
Width of the Travis’s rectangle = 12 inches
Perimeter of the Travis’s rectangle = 2 ( Length + Width)
= 2 ( 34 inches + 12 inches )
= 2 × 46 inches
= 92 inches.
The total length of the wire needed for two rectangles = 2 ×  Perimeter of the Travis’s rectangle
= 2 ×  92 inches
= 184 inches.

 

Question 3.
The perimeter of a rectangular bathroom is 32 feet. The width of the room is 8 feet. What is the length of the room?
Answer:
The length of the room = 8 feet.

Explanation:
Perimeter of a rectangular bathroom = 32 feet.
Width of a rectangular bathroom = 8 feet.
Length of a rectangular bathroom = ??
Perimeter of a rectangular bathroom = 2 ( Length + Width)
=> 32 feet = (2 × Length) + (2 × 8 feet)
=> 32 feet = (2 × Length) + 16 feet
=> 32 feet – 16 feet = (2 × Length)
=> 16 feet = (2 × Length)
=> 16 feet ÷ 2 = Length
=> 8 feet = Length

 

Question 4.
Raj uses 6-inch square tiles to make a rectangle, as shown below. What is the perimeter of the rectangle in inches?
Engage NY Math Grade 3 Module 7 Lesson 23 Problem Set Answer Key p 1
Answer:
Perimeter of the rectangle in inches =96-inches.

Explanation:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-23-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 23 Problem Set Answer Key-4
Length of the side square tiles Raj uses to make a rectangle = 6-inch
Number of side of square tiles in the rectangle = 16
Perimeter of the rectangle in inches = Length of the side square tiles Raj uses to make a rectangle × Number of side of square tiles in the rectangle
= 6-inch × 16
= 96-inches.

 

Question 5.
Mischa makes a 4-foot by 6-foot rectangular banner. She puts ribbon around the outside edges. The ribbon costs $2 per foot. What is the total cost of the ribbon?
Answer:
Total cost of the ribbon = $20.

Explanation:
Length of the rectangular banner = 6-foot
Width of the rectangular banner = 4-foot
Perimeter of the rectangular banner = 2 ( Length + Width)
= 2 ( 6-foot + 4-foot )
= 2 × 10-foot
= 20- foot.
Cost of the ribbon per foot = $2
Total cost of the ribbon = Perimeter of the rectangular banner × Cost of the ribbon per foot
= 20- foot × $2
= $40.

 

Question 6.
Colton buys a roll of wire fencing that is 120 yards long. He uses it to fence in his 18-yard by 24-yard rectangular garden. Will Colton have enough wire fencing left over to fence in a 6-yard by 8-yard rectangular play space for his pet rabbit?
Answer:
Yes, Colton has wire fencing left over to fence for rectangular play space for his pet rabbit.

Explanation:
Total length of wire Colton purchased = 120 yards.
Length of the rectangular garden = 24-yard
Width of the rectangular garden = 18-yard
Perimeter of the rectangular garden = 2 ( Length + Width)
= 2 ( 24-yard + 18-yard )
= 2 × 42-yard
= 84-yard.
Wire used = Total length of wire Colton purchased – Perimeter of the rectangular garden
= 120 yards – 84 yards
= 36 yards.
Length of the rectangular play space for his pet rabbit = 8-yard
Width of the rectangular play space for his pet rabbit = 6-yard
Perimeter of the rectangular play space for his pet rabbit = 2 ( Length + Width)
= 2 ( 8-yard + 6-yard )
= 2 × 14-yard
= 28-yard.
Wire left = Wire used – Perimeter of the rectangular play space for his pet rabbit
= 36 yards – 28 yards
= 8 yards.

 

Eureka Math Grade 3 Module 7 Lesson 23 Exit Ticket Answer Key

Adriana traces a regular triangle to create the shape below. The perimeter of her shape is 72 centimeters. What are the side lengths of the triangle?
Eureka Math 3rd Grade Module 7 Lesson 23 Exit Ticket Answer Key t 1
Answer:
The side lengths of the triangle = 9 centimeters.

Explanation:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-23-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 23 Exit Ticket Answer Key
Perimeter of Adriana’s shape = 72 centimeters
Number of sides of the triangle shape = 8
The side lengths of the triangle = Perimeter of Adriana’s shape  ÷ Number of sides of the triangle shape
= 72 centimeters ÷ 8
= 9 centimeters.

 

Eureka Math Grade 3 Module 7 Lesson 23 Homework Answer Key

Question 1.
Rosie draws a square with a perimeter of 36 inches. What are the side lengths of the square?
Answer:
The side lengths of the square = 9 inches.

Explanation:
Perimeter of the Square = 36 inches
Number of sides in the square = 4
The side lengths of the square = Perimeter of the Square  ÷ Number of sides in the square
= 36 inches ÷ 4
= 9 inches.

 

Question 2.
Judith uses craft sticks to make two 24-inch by 12-inch rectangles. What is the total perimeter of the 2 rectangles?
Answer:
Total perimeter of the 2 rectangles = 144 inches.

Explanation:
Length of the rectangle = 24-inch
Width of the rectangle = 12-inch
Perimeter of the rectangle = 2 ( Length + Width)
= 2 ( 24-inch + 12-inch )
= 2 × 36-inch
= 72 inches.
Total perimeter of the 2 rectangles = Perimeter of the rectangle × 2
= 72 inches × 2
= 144 inches.

 

Question 3.
An architect draws a square and a rectangle, as shown below, to represent a house that has a garage. What is the total perimeter of the house with its attached garage?
Eureka Math Grade 3 Module 7 Lesson 23 Homework Answer Key h 1
Answer:
Perimeter of the attached garage = 250 ft.

Explanation:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-23-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 23 Homework Answer Key-3
Length of the side AB in the attached garage = 55 ft
Length of the side BC in the attached garage = 10 ft
Length of the side CD in the attached garage = 30 ft
Length of the side DE in the attached garage = 30 ft
Length of the side EF in the attached garage = 30 ft
Length of the side FG in the attached garage = 55 ft
Length of the side GA in the attached garage = 40 ft
Perimeter of the attached garage = Length of the side AB in the attached garage  +  Length of the side BC in the attached garage + Length of the side CD in the attached garage + Length of the side DE in the attached garage + Length of the side EF in the attached garage + Length of the side FG in the attached garage + Length of the side GA in the attached garage
= 55 ft + 10 ft + 30 ft + 30 ft + 30 ft + 55 ft + 40 ft
= 65 ft + 30 ft + 30 ft + 30 ft + 55 ft + 40 ft
= 95 ft + 30 ft + 30 ft + 55 ft + 40 ft
= 125 ft + 30 ft + 55 ft + 40 ft
= 155 ft + 55 ft + 40 ft
= 210 ft + 40ft
= 250 ft.

 

Question 4.
Manny draws 3 regular pentagons to create the shape shown below. The perimeter of 1 of the pentagons is 45 inches. What is the perimeter of Manny’s new shape?
Eureka Math Grade 3 Module 7 Lesson 23 Homework Answer Key h 2
Answer:
Perimeter of Manny’s new shape = 99 inches.

Explanation:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-23-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 23 Homework Answer Key-4
Perimeter of the regular pentagons Manny draws = 45 inches
Number of side in the regular pentagons Manny draws = 5
Length of the side of the regular pentagons Manny draws = Perimeter of the regular pentagons Manny draws ÷ Number of side in the regular pentagons Manny draws
= 45 inches ÷ 5
= 9 inches.
Number of side Manny’s new shape  has = 11 ( Side AB + Side BC +Side CD + Side DE + Side EF +Side FG + Side GH + Side HI + Side IJ +Side JK + Side KA )
Perimeter of Manny’s new shape = Number of side Manny’s new shape has × Length of the side of the regular pentagons Manny draws
= 11 × 9 inches
= 99 inches.

 

Question 5.
Johnny uses 2-inch square tiles to make a square, as shown below. What is the perimeter of Johnny’s square?
Eureka Math Grade 3 Module 7 Lesson 23 Homework Answer Key h 3
Answer:
Perimeter of Johnny’s square = 24 inches.

Explanation:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-23-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 23 Homework Answer Key-5
Number of side in the Johnny’s square = 12
Length of  side  in the Johnny’s square = 2 inches
Perimeter of Johnny’s square = Number of side in the Johnny’s square  × Length of side in the Johnny’s square
= 12 × 2 inches
= 24 inches.

Question 6.
Lisa tapes three 7-inch by 9-inch pieces of construction paper together to make a happy birthday sign for her mom. She uses a piece of ribbon that is 144 inches long to make a border around the outside edges of the sign. How much ribbon is leftover?
Eureka Math Grade 3 Module 7 Lesson 23 Homework Answer Key h 4
Answer:
Ribbon  leftover = 76 inches.

Explanation:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-23-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 23 Homework Answer Key-6
Length of the Lisa’s piece of construction paper = 9-inch
Width of the Lisa’s piece of construction paper = 7-inch
Perimeter of the pieces of construction paper used to make a happy birthday sign for her mom = Side AB + Side BC + Side CD + Side DE + Side EF + Side FG + Side GH +Side HA
= 9-inch + 9-inch + 9-inch + 7-inch + 9-inch + 9-inch + 9-inch + 7-inch
= 18-inch + 9-inch + 7-inch + 9-inch + 9-inch + 9-inch + 7-inch
= 27-inch + 7-inch + 9-inch + 9-inch + 9-inch + 7-inch
= 34-inch + 9-inch + 9-inch + 9-inch + 7-inch
= 43-inch + 9-inch + 9-inch + 7-inch
= 52-inch + 9-inch + 7-inch
= 61-inch + 7-inch
= 68-inch.
Piece of ribbon Lisa’s  has = 144 inches
Ribbon  leftover = Piece of ribbon Lisa’s  has  – Perimeter of the pieces of construction paper used to make a happy birthday sign for her mom
= 144 inches – 68-inch.
= 76 inches.

Eureka Math Grade 3 Module 7 Lesson 22 Answer Key

Engage NY Eureka Math 3rd Grade Module 7 Lesson 22 Answer Key

Eureka Math Grade 3 Module 7 Lesson 22 Sprint Answer Key

A
Multiply or Divide by 4
Engage NY Math 3rd Grade Module 7 Lesson 22 Sprint Answer Key s 1
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-22-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 22 Sprint Answer Key-A
Question 1.
2 × 4 =
Answer:
2 × 4 = 8.

Question 2.
3 × 4 =
Answer:
3 × 4 = 12.

Question 3.
4 × 4 =
Answer:
4 × 4 = 16.

Question 4.
5 × 4 =
Answer:
5 × 4 = 20.

Question 5.
1 × 4 =
Answer:
1 × 4 = 4.

Question 6.
8 ÷ 4 =
Answer:
8 ÷ 4 = 2.

Question 7.
12 ÷ 4 =
Answer:
12 ÷ 4 = 3.

Question 8.
20 ÷ 4 =
Answer:
20 ÷ 4 = 5.

Question 9.
4 ÷ 4 =
Answer:
4 ÷ 4 = 1.

Question 10.
16 ÷ 4 =
Answer:
16 ÷ 4 = 4.

Question 11.
6 × 4 =
Answer:
6 × 4 = 24.

Question 12.
7 × 4 =
Answer:
7 × 4 = 28.

Question 13.
8 × 4 =
Answer:
8 × 4 = 32.

Question 14.
9 × 4 =
Answer:
9 × 4 = 36.

Question 15.
10 × 4 =
Answer:
10 × 4 = 40.

Question 16.
32 ÷ 4 =
Answer:
32 ÷ 4 = 8.

Question 17.
28 ÷ 4 =
Answer:
28 ÷ 4 = 7.

Question 18.
36 ÷ 4 =
Answer:
36 ÷ 4 = 9.

Question 19.
24 ÷ 4 =
Answer:
24 ÷ 4 = 6.

Question 20.
40 ÷ 4 =
Answer:
40 ÷ 4 = 10.

Question 21.
___ × 4 = 20
Answer:
_5__ × 4 = 20.

Question 22.
___ × 4 = 4
Answer:
_1__ × 4 = 4.

Question 23.
___ × 4 = 40
Answer:
_10__ × 4 = 40.

Question 24.
___ × 4 = 8
Answer:
_2__ × 4 = 8.

Question 25.
___ × 4 = 12
Answer:
_3__ × 4 = 12.

Question 26.
40 ÷ 4 =
Answer:
40 ÷ 4 = 10.

Question 27.
20 ÷ 4 =
Answer:
20 ÷ 4 = 5.

Question 28.
4 ÷ 4 =
Answer:
4 ÷ 4 = 1.

Question 29.
8 ÷ 4 =
Answer:
8 ÷ 4 = 2.

Question 30.
12 ÷ 4 =
Answer:
12 ÷ 4 = 3.

Question 31.
___ × 4 = 24
Answer:
_6__ × 4 = 24.

Question 32.
___ × 4 = 28
Answer:
_7__ × 4 = 28.

Question 33.
___ × 4 = 36
Answer:
_9__ × 4 = 36.

Question 34.
___ × 4 = 32
Answer:
_8__ × 4 = 32.

Question 35.
28 ÷ 4 =
Answer:
28 ÷ 4 = 7.

Question 36.
36 ÷ 4 =
Answer:
36 ÷ 4 = 9.

Question 37.
24 ÷ 4 =
Answer:
24 ÷ 4 = 6.

Question 38.
32 ÷ 4 =
Answer:
32 ÷ 4 = 8.

Question 39.
11 × 4 =
Answer:
11 × 4 = 44.

Question 40.
44 ÷ 4 =
Answer:
44 ÷ 4 = 11.

Question 41.
12 ÷ 4 =
Answer:
12 ÷ 4 = 3.

Question 42.
48 ÷ 4 =
Answer:
48 ÷ 4 = 12.

Question 43.
14 × 4 =
Answer:
14 × 4 = 56.

Question 44.
56 ÷ 4 =
Answer:
56 ÷ 4 = 14.

B
Multiply or Divide by 4
Engage NY Math 3rd Grade Module 7 Lesson 22 Sprint Answer Key s 2
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-22-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 22 Sprint Answer Key-B
Question 1.
1 × 4 =
Answer:
1 × 4 = 4.

Question 2.
2 × 4 =
Answer:
2 × 4 = 8.

Question 3.
3 × 4 =
Answer:
3 × 4 = 12.

Question 4.
4 × 4 =
Answer:
4 × 4 = 16.

Question 5.
5 × 4 =
Answer:
5 × 4 = 20.

Question 6.
12 ÷ 4 =
Answer:
12 ÷ 4 = 3.

Question 7.
8 ÷ 4 =
Answer:
8 ÷ 4 = 2.

Question 8.
16 ÷ 4 =
Answer:
16 ÷ 4 = 4.

Question 9.
4 ÷ 4 =
Answer:
4 ÷ 4 = 1.

Question 10.
20 ÷ 4 =
Answer:
20 ÷ 4 = 5.

Question 11.
10 × 4 =
Answer:
10 × 4 = 40.

Question 12.
6 × 4 =
Answer:
6 × 4 = 24.

Question 13.
7 × 4 =
Answer:
7 × 4 = 28.

Question 14.
8 × 4 =
Answer:
8 × 4 = 32.

Question 15.
9 × 4 =
Answer:
9 × 4 = 36.

Question 16.
28 ÷ 4 =
Answer:
28 ÷ 4 = 7.

Question 17.
24 ÷ 4 =
Answer:
24 ÷ 4 = 6.

Question 18.
32 ÷ 4 =
Answer:
32 ÷ 4 = 8.

Question 19.
40 ÷ 4 =
Answer:
40 ÷ 4 = 10.

Question 20.
36 ÷ 4 =
Answer:
36 ÷ 4 = 9.

Question 21.
___ × 4 = 4
Answer:
_1__ × 4 = 4.

Question 22.
___ × 4 = 20
Answer:
_5__ × 4 = 20.

Question 23.
___ × 4 = 8
Answer:
_2__ × 4 = 8.

Question 24.
___ × 4 = 40
Answer:
_10__ × 4 = 40.

Question 25.
___ × 4 = 12
Answer:
_3__ × 4 = 12.

Question 26.
8 ÷ 4 =
Answer:
8 ÷ 4 = 2.

Question 27.
4 ÷ 4 =
Answer:
4 ÷ 4 = 1.

Question 28.
40 ÷ 4 =
Answer:
40 ÷ 4 = 10.

Question 29.
20 ÷ 4 =
Answer:
20 ÷ 4 = 10.

Question 30.
12 ÷ 4 =
Answer:
12 ÷ 4 = 3.

Question 31.
___ × 4 = 12
Answer:
_3__ × 4 = 12.

Question 32.
___ × 4 = 16
Answer:
_4__ × 4 = 16.

Question 33.
___ × 4 = 36
Answer:
_9__ × 4 = 36.

Question 34.
___ × 4 = 28
Answer:
_7__ × 4 = 28.

Question 35.
32 ÷ 4 =
Answer:
32 ÷ 4 = 8.

Question 36.
36 ÷ 4 =
Answer:
36 ÷ 4 = 9.

Question 37.
24 ÷ 4 =
Answer:
24 ÷ 4 = 6.

Question 38.
28 ÷ 4 =
Answer:
28 ÷ 4 = 7.

Question 39.
11 × 4 =
Answer:
11 × 4 = 44.

Question 40.
44 ÷ 4 =
Answer:
44 ÷ 4 = 11.

Question 41.
12 × 4 =
Answer:
12 × 4 = 48.

Question 42.
48 ÷ 4 =
Answer:
48 ÷ 4 = 12.

Question 43.
13 × 4 =
Answer:
13 × 4 = 52.

Question 44.
52 ÷ 4 =
Answer:
52 ÷ 4 = 13.

Eureka Math Grade 3 Module 7 Lesson 22 Problem Set Answer Key

Question 1.
Use the data you gathered from your Problem Sets to create a line plot for the number of rectangles you created with each given perimeter.
Number of Rectangles Made with a Given Perimeter
Engage NY Math Grade 3 Module 7 Lesson 22 Problem Set Answer Key p 1
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-22-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 22 Problem Set Answer Key-1
Explanation:
The data  gathered from Problem Sets to create a line plot for the number of rectangles created with each given perimeter are : 10 units, 12 units, 14 units, 16 units,18 units, 20 units.

Question 2.
Why are all of the perimeter measurements even? Do all rectangles have an even perimeter?
Answer:
Well all perimeters of the rectangles are even because we have used the whole numbers and when we add them twice, we get the even numbers as the result.

Explanation:
Well all perimeters of the rectangles are even because we have used the whole numbers and when we add them twice, we get the even numbers as the result. Generally we used rulers to find the lengths of rectangles not the string. We have used string to show to get an odd perimeter.

 

Question 3.
Compare the two line plots we created. Is there any reason to think that knowing only the area of a rectangle would help you to figure out its perimeter or knowing only the perimeter of a rectangle would help you figure out its area?
Answer:
No, there is no reason to think that knowing only the area of a rectangle would help you to figure out its perimeter or knowing only the perimeter of a rectangle would help you figure out its area.

Explanation:
There is no connection between the area and perimeter of rectangle. Knowing one, doesnot help you to find the other.

 

Question 4.
Sumi uses unit square tiles to build 3 rectangles that have an area of 32 square units. Does knowing this help her find the number of rectangles she can build for a perimeter of 32 units? Why or why not?
Answer:
No, knowing the number of rectangles she built with the area of 32 square units does not help her to find the number of rectangles she can build for a perimeter of 32 units.

Explanation:
For example, if we do half 32 square units, we have the chance to make more than 3 pairs of number that add to 16. No, knowing the number of rectangles she built with the area of 32 square units does not help her to find the number of rectangles she can build for a perimeter of 32 units.

Question 5.
George draws 3 rectangles that have a perimeter of 14 centimeters. Alicia tells George that there are more than 3 rectangles that have a perimeter of 14 centimeters. Explain why Alicia is correct.
Answer:
Yes, I completely agree with Alicia because George  probably drew the rectangles using the whole numbers side lengths. He could have drawn more rectangles using fraction values as lengths.

Explanation:
Yes, I completely agree with Alicia ” George that there are more than 3 rectangles that have a perimeter of 14 centimeters. ” because George  probably drew the rectangles using the whole numbers side lengths. He could have drawn more rectangles using fraction values as lengths.

 

Eureka Math Grade 3 Module 7 Lesson 22 Exit Ticket Answer Key

Suppose you have a rectangle with a perimeter of 2 cm. What can you conclude about the side lengths? Can all 4 sides of the rectangle measure a whole number of centimeters?
Answer:
Well, if the rectangles perimeter is 2cm, I do not think the lengths are going to be whole numbers of centimeters. Because perimeter  is the total distance covered by the rectangle around its outside.

Explanation:
Perimeter  is the total distance covered by the rectangle around its outside. Well, if the rectangles perimeter is 2cm, I do not think the lengths are going to be whole numbers of centimeters.

 

Eureka Math Grade 3 Module 7 Lesson 22 Homework Answer Key

Question 1.
The following line plot shows the number of rectangles a student made using square unit tiles. Use the line plot to answer the questions below.
Eureka Math Grade 3 Module 7 Lesson 22 Homework Answer Key h 1
a. Why are all of the perimeter measurements even? Do all rectangles have even perimeters?
b. Explain the pattern in the line plot. What types of side lengths make this pattern possible?
c. How many X’s would you draw for a perimeter of 32? Explain how you know.
Answer:
a. Well all perimeters of the rectangles are even because the student has used the whole numbers and when they are added twice, we get the even numbers as the result.  Yes, mostly all rectangles have even perimeters as we use whole numbers not fractions.

b. The pattern in the line plot is showing all rectangles Perimeters which are even in numbers. Whole numbers types of side lengths make this pattern possible.

c. Number of X’s would be drawn for a perimeter of 32 are six or 6: : (2,14) (3,13) (4,12) (5,11) (6,10) (7,9).

Explanation:
a.  Well all perimeters of the rectangles are even because the student has used the whole numbers and when they are added twice, we get the even numbers as the result. Generally we used rulers to find the lengths of rectangles not the string. We have used string to show to get an odd perimeter.

b. The whole numbers are the part of the number system in which it includes all the positive integers from 0 to infinity. The pattern in the line plot is showing all rectangles Perimeters which are even in numbers.

c. Number of X’s would be drawn for a perimeter of 32 are six or 6 : (2,14) (3,13) (4,12) (5,11) (6,10) (7,9).
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-22-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 22 Homework Answer Key-1c

Question 2.
Luis uses square inch tiles to build a rectangle with a perimeter of 24 inches. Does knowing this help him find the number of rectangles he can build with an area of 24 square inches? Why or why not?
Answer:
Luis uses square inch tiles to build a rectangle with a perimeter of 24 inches.
No, knowing this cannot help him find the number of rectangles he can build with an area of 24 square inches because there is no connection  between the area and perimeter to find the number of rectangles to be obtained.

Explanation:
No, knowing this cannot help him find the number of rectangles he can build with an area of 24 square inches because there is no connection  between the area and perimeter to find the number of rectangles to be obtained.

 

Question 3.
Esperanza makes a rectangle with a piece of string. She says the perimeter of her rectangle is 33 centimeters. Explain how it’s possible for her rectangle to have an odd perimeter.
Answer:
Well, Esperanza  is correct in what she says ” the perimeter of her rectangle is 33 centimeters.”
because she is using her string to find the lengths of her rectangle.

Explanation:
Well, Esperanza  is correct in what she says ” the perimeter of her rectangle is 33 centimeters.”
because she is using her string to find the lengths of her rectangle. The measurements of rectangles forming an odd perimeter of Esperanza rectangles can be: (2,14.5) (4,12.5) (4.5,12) (5,11.5) (6, 10.5) ( 7, 9.5).

Eureka Math Grade 3 Module 7 Lesson 21 Answer Key

Engage NY Eureka Math 3rd Grade Module 7 Lesson 21 Answer Key

Eureka Math Grade 3 Module 7 Lesson 21 Sprint Answer Key

A
Multiply or Divide by 3
Engage NY Math 3rd Grade Module 7 Lesson 21 Sprint Answer Key s 1
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-21-Answer-Key-

Question 1.
2 × 3 =
Answer:
2 × 3 = 6.

Question 2.
3 × 3 =
Answer:
3 × 3 = 9.

Question 3.
4 × 3 =
Answer:
4 × 3 = 12.

Question 4.
5 × 3 =
Answer:
5 × 3 = 15.

Question 5.
1 × 3 =
Answer:
1 × 3 = 3.

Question 6.
6 ÷ 3 =
Answer:
6 ÷ 3 = 2.

Question 7.
9 ÷ 3 =
Answer:
9 ÷ 3 = 3.

Question 8.
15 ÷ 3 =
Answer:
15 ÷ 3 = 5.

Question 9.
3 ÷ 3 =
Answer:
3 ÷ 3 = 1.

Question 10.
12 ÷ 3 =
Answer:
12 ÷ 3 = 4.

Question 11.
6 × 3 =
Answer:
6 × 3 = 18.

Question 12.
7 × 3 =
Answer:
7 × 3 = 21.

Question 13.
8 × 3 =
Answer:
8 × 3 = 24.

Question 14.
9 × 3 =
Answer:
9 × 3 = 27.

Question 15.
10 × 3 =
Answer:
10 × 3 = 30.

Question 16.
24 ÷ 3 =
Answer:
24 ÷ 3 = 8.

Question 17.
21 ÷ 3 =
Answer:
21 ÷ 3 = 7.

Question 18.
27 ÷ 3 =
Answer:
27 ÷ 3 = 9.

Question 19.
18 ÷ 3 =
Answer:
18 ÷ 3 = 6.

Question 20.
30 ÷ 3 =
Answer:
30 ÷ 3 = 10.

Question 21.
___ × 3 = 15
Answer:
_5__ × 3 = 15.

Question 22.
___ × 3 = 3
Answer:
__1_ × 3 = 3.

Question 23.
___ × 3 = 30
Answer:
_10__ × 3 = 30.

Question 24.
___ × 3 = 6
Answer:
_2__ × 3 = 6.

Question 25.
___ × 3 = 9
Answer:
_3__ × 3 = 9.

Question 26.
30 ÷ 3 =
Answer:
30 ÷ 3 = 10.

Question 27.
15 ÷ 3 =
Answer:
15 ÷ 3 = 5.

Question 28.
3 ÷ 3 =
Answer:
3 ÷ 3 = 1.

Question 29.
6 ÷ 3 =
Answer:
6 ÷ 3 = 2.

Question 30.
9 ÷ 3 =
Answer:
9 ÷ 3 = 3.

Question 31.
___ × 3 = 18
Answer:
_6__ × 3 = 18.

Question 32.
___ × 3 = 21
Answer:
_7__ × 3 = 21.

Question 33.
___ × 3 = 27
Answer:
_9__ × 3 = 27.

Question 34.
___ × 3 = 24
Answer:
_8__ × 3 = 24.

Question 35.
21 ÷ 3 =
Answer:
21 ÷ 3 = 7.

Question 36.
27 ÷ 3 =
Answer:
27 ÷ 3 = 9.

Question 37.
18 ÷ 3 =
Answer:
18 ÷ 3 = 6.

Question 38.
24 ÷ 3 =
Answer:
24 ÷ 3 = 8.

Question 39.
11 × 3 =
Answer:
11 × 3 = 33.

Question 40.
33 ÷ 3 =
Answer:
33 ÷ 3 = 11.

Question 41.
12 × 3 =
Answer:
12 × 3 = 36.

Question 42.
36 ÷ 3 =
Answer:
36 ÷ 3 = 12.

Question 43.
13 × 3 =
Answer:
13 × 3 = 39.

Question 44.
39 ÷ 3 =
Answer:
39 ÷ 3 = 13.

 

B
Multiply or Divide by 3
Engage NY Math 3rd Grade Module 7 Lesson 21 Sprint Answer Key s 2
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-21-Answer-Key-B

Question 1.
1 × 3 =
Answer:
1 × 3 = 3.

Question 2.
2 × 3 =
Answer:
2 × 3 = 6.

Question 3.
3 × 3 =
Answer:
3 × 3 = 9.

Question 4.
4 × 3 =
Answer:
4 × 3 = 12.

Question 5.
5 × 3 =
Answer:
5 × 3 = 15.

Question 6.
9 ÷ 3 =
Answer:
9 ÷ 3 = 3.

Question 7.
6 ÷ 3 =
Answer:
6 ÷ 3 = 2.

Question 8.
12 ÷ 3 =
Answer:
12 ÷ 3 = 4.

Question 9.
3 ÷ 3 =
Answer:
3 ÷ 3 = 1.

Question 10.
15 ÷ 3 =
Answer:
15 ÷ 3 = 5.

Question 11.
10 × 3 =
Answer:
10 × 3 = 30.

Question 12.
6 × 3 =
Answer:
6 × 3 = 18.

Question 13.
7 × 3 =
Answer:
7 × 3 = 21.

Question 14.
8 × 3 =
Answer:
8 × 3 = 24.

Question 15.
9 × 3 =
Answer:
9 × 3 = 27.

Question 16.
21 ÷ 3 =
Answer:
21 ÷ 3 = 7.

Question 17.
18 ÷ 3 =
Answer:
18 ÷ 3 = 6.

Question 18.
24 ÷ 3 =
Answer:
24 ÷ 3 = 8.

Question 19.
30 ÷ 3 =
Answer:
30 ÷ 3 = 10.

Question 20.
27 ÷ 3 =
Answer:
27 ÷ 3 = 9.

Question 21.
___ × 3 = 3
Answer:
__1_ × 3 = 3.

Question 22.
___ × 3 = 15
Answer:
_5__ × 3 = 15.

Question 23.
___ × 3 = 6
Answer:
_2__ × 3 = 6.

Question 24.
___ × 3 = 30
Answer:
_10__ × 3 = 30.

Question 25.
___ × 3 = 9
Answer:
_3__ × 3 = 9.

Question 26.
6 ÷ 3 =
Answer:
6 ÷ 3 = 2.

Question 27.
3 ÷ 3 =
Answer:
3 ÷ 3 = 1.

Question 28.
30 ÷ 3 =
Answer:
30 ÷ 3 = 10.

Question 29.
15 ÷ 3 =
Answer:
15 ÷ 3 = 5.

Question 30.
9 ÷ 3 =
Answer:
9 ÷ 3 = 3.

Question 31.
___ × 3 = 18
Answer:
_6__ × 3 = 18.

Question 32.
___ × 3 = 24
Answer:
_8__ × 3 = 24.

Question 33.
___ × 3 = 27
Answer:
_9__ × 3 = 27.

Question 34.
___ × 3 = 21
Answer:
_7__ × 3 = 21.

Question 35.
24 ÷ 3 =
Answer:
24 ÷ 3 = 8.

Question 36.
27 ÷ 3 =
Answer:
27 ÷ 3 = 9.

Question 37.
18 ÷ 3 =
Answer:
18 ÷ 3 = 6.

Question 38.
21 ÷ 3 =
Answer:
21 ÷ 3 = 7.

Question 39.
11 × 3 =
Answer:
11 × 3 = 33.

Question 40.
33 ÷ 3 =
Answer:
33 ÷ 3 = 11.

Question 41.
12 × 3 =
Answer:
12 × 3 = 36.

Question 42.
36 ÷ 3 =
Answer:
36 ÷ 3 = 12.

Question 43.
13 × 3 =
Answer:
13 × 3 = 39.

Question 44.
39 ÷ 3 =
Answer:
39 ÷ 3 = 13.

Eureka Math Grade 3 Module 7 Lesson 21 Problem Set Answer Key

Question 1.
On your centimeter grid paper, shade and label as many rectangles as you can with a perimeter of 16 centimeters.
a. Sketch the rectangles below, and label the side lengths.
b. Find the area of each rectangle you drew above.
Answer:
a. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-21-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 21 Problem Set Answer Key-1a
b. Area of the ABCD Rectangle = 7 square cm.
Area of the EFGH Rectangle = 12 square cm.
Area of the IJKL Rectangle = 15 square cm.

Explanation:
a. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-21-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 21 Problem Set Answer Key-1a
b.
Figure 1 : ABCD Rectangle
Length of the ABCD Rectangle = 7cm
Width of the ABCD Rectangle = 1cm
Area of the ABCD Rectangle = Length  × Width
= 7cm × 1cm
= 7 square cm.

Figure 2 : EFGH Rectangle
Length of the EFGH Rectangle = 6cm
Width of the EFGH Rectangle = 2cm
Area of the EFGH Rectangle = Length  × Width
= 6cm × 2cm
= 12 square cm.

Figure 3 : IJKL Rectangle
Length of the IJKL Rectangle = 5cm
Width of the IJKL Rectangle = 3cm
Area of the IJKL Rectangle = Length  × Width
= 5cm × 3cm
= 15 square cm.

 

 

Question 2.
On your centimeter grid paper, shade and label as many rectangles as you can with a perimeter of 18 centimeters.
a. Sketch the rectangles below, and label the side lengths.
b. Find the area of each rectangle you drew above.
Answer:
a. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-21-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 21 Problem Set Answer Key-2a
b. Area of the ABCD Rectangle = 8 square cm.
Area of the EFGH Rectangle = 14 square cm.
Area of the IJKL Rectangle = 18 square cm.
Area of the MNOP Rectangle = 20 square cm.

Explanation:
a.
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-21-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 21 Problem Set Answer Key-2a
b.

Figure 1 : ABCD Rectangle
Length of the ABCD Rectangle = 8cm
Width of the ABCD Rectangle = 1cm
Area of the ABCD Rectangle = Length  × Width
= 8cm × 1cm
= 8 square cm.

Figure 2 : EFGH Rectangle
Length of the EFGH Rectangle = 7cm
Width of the EFGH Rectangle = 2cm
Area of the EFGH Rectangle = Length  × Width
= 7cm × 2cm
= 14 square cm.

Figure 3 : IJKL Rectangle
Length of the IJKL Rectangle = 6cm
Width of the IJKL Rectangle = 3cm
Area of the IJKL Rectangle = Length  × Width
= 6cm × 3cm
= 18 square cm.

Figure 4 : MNOP Rectangle
Length of the MNOP Rectangle = 5cm
Width of the MNOP Rectangle = 4cm
Area of the MNOP Rectangle = Length  × Width
= 5cm × 4cm
= 20 square cm.

 

 

Question 3.
Use centimeter grid paper to shade in as many rectangles as you can with the given perimeters.
a. Use the charts below to show how many rectangles you shaded for each given perimeter. You might not use all the spaces in the charts.

Perimeter = 10 cm
Number of rectangles I made:  _____
Width Length Area
1 cm 4 cm 4 square cm
Perimeter = 20 cm
Number of rectangles I made:  _____
Width Length Area
1 cm 9 cm 9 square cm
3 cm 7 cm  21 square cm
4 cm 6 cm  24 square cm
5 cm 5 cm 25 square cm

b. Did you make a square with either of the given perimeters? How do you know?
Answer:
Yes, I  have made a square with lengths of the given perimeters of 20cm. I know it  because a rectangle with the side length all  equal to 5cm and a rectangle with all equal sides is to be known as Square.

Explanation:
Yes, because a rectangle with side length all  equal to 5cm and a rectangle with all equal sides is to be known as Square.

 

Question 4.
Macy and Gavin both draw rectangles with perimeters of 16 centimeters. Use words and pictures to explain how it is possible for Macy’s and Gavin’s rectangles to have the same perimeters but different areas.
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-21-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 21 Problem Set Answer Key-4
Area of the ABCD Macy’s rectangle = 7 Square cm.
Perimeter of the ABCD Macy’s rectangle = 16cms.
Area of the EFGH Gavin’s rectangle = 12 Square cm.
Perimeter of the EFGH Gavin’s rectangle = 16cms.
Here, Macy and Gavin has drawn two different rectangles with different lengths  perimeters same 16cms yet different areas. Well, its possible to draw as many as rectangles with perimeters of 16 centimeters but different areas.

Explanation:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-21-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 21 Problem Set Answer Key-4
Figure1: Macy’s rectangle:
Length of the ABCD Macy’s rectangle = 7cm
Width of the ABCD Macy’s rectangle = 1cm
Area of the ABCD Macy’s rectangle = Length × Width
= 7cm ×  1cm
= 7 Square cm.
Perimeter of the ABCD Macy’s rectangle =  2 ( Length + Width )
= 2 ( 7cm + 1cm)
= 2 ×  8cm
= 16 cms.

Figure2: Gavin’s rectangle:
Length of the EFGH Gavin’s rectangle = 7cm
Width of the EFGH Gavin’s rectangle = 1cm
Area of the EFGH Gavin’s rectangle = Length × Width
= 6cm ×  2cm
= 12 Square cm.
Perimeter of the EFGH Gavin’s rectangle =  2 ( Length + Width )
= 2 ( 6cm + 2cm)
= 2 ×  8cm
= 16 cms .

 

Eureka Math Grade 3 Module 7 Lesson 21 Exit Ticket Answer Key

On the grid below, shade and label at least two different rectangles with a perimeter of 20 centimeters.
Eureka Math 3rd Grade Module 7 Lesson 21 Exit Ticket Answer Key t 1
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-21-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 21 Exit Ticket Answer Key

Explanation:
I have drawn three rectangles having lengths as ABCD Rectangle ( 8cm,2cm) , EFGH Rectangle  ( 6cm,4cm)  and IJKL Rectangle ( 7cm,3cm).

 

 

Eureka Math Grade 3 Module 7 Lesson 21 Homework Answer Key

Question 1.
Margo finds as many rectangles as she can with a perimeter of 14 centimeters.
a. Shade Margo’s rectangles on the grid below. Label the length and width of each rectangle.
Eureka Math Grade 3 Module 7 Lesson 21 Homework Answer Key h 1
b. Find the areas of the rectangles in part (a) above.
c. The perimeters of the rectangles are the same. What do you notice about the areas?
Answer:
a. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-21-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 21 Homework Answer Key-1a

b. Area of the ABCD Rectangle = 12 square cm.
Area of the EFGH Rectangle = 10 square cm.
Area of the IJKL Rectangle = 6 square cm.

c. Perimeters of the three rectangles are the same having 14 cms, where as their areas are completely different from each other.

Explanation:
a.
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-21-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 21 Homework Answer Key-1a

b. Figure 1 : ABCD Rectangle
Length of the ABCD Rectangle = 4cm
Width of the ABCD Rectangle = 3cm
Area of the ABCD Rectangle = Length  × Width
= 4cm × 3cm
= 12 square cm.

Figure 2 : EFGH Rectangle
Length of the EFGH Rectangle = 5cm
Width of the EFGH Rectangle = 2cm
Area of the EFGH Rectangle = Length  × Width
= 5cm × 2cm
= 10 square cm.

Figure 3 : IJKL Rectangle
Length of the IJKL Rectangle = 6cm
Width of the IJKL Rectangle = 1cm
Area of the IJKL Rectangle = Length  × Width
= 6cm × 1cm
= 6 square cm.

c. Perimeter of the ABCD  rectangle =  2 ( Length + Width )
= 2 ( 4cm + 3cm)
= 2 ×  7cm
= 14 cms.

Perimeter of the EFGH rectangle =  2 ( Length + Width )
= 2 ( 5cm + 2cm)
= 2 ×  7cm
= 14 cms.

Perimeter of the IJKL rectangle =  2 ( Length + Width )
= 2 ( 6cm + 1cm)
= 2 ×  7cm
= 14 cms.
Perimeters of the three rectangles are the same having 14 cms, where as their areas are completely different from each other.
Perimeter requires only the lengths of the four sides of rectangle to be added where as for area we require length and width of the rectangle.

 

Question 2.
Tanner uses unit squares to build rectangles that have a perimeter of 18 units. He creates the chart below to record his findings.
a. Complete Tanner’s chart. You might not use all the spaces in the chart.

Perimeter = 18 units
Number of rectangles I made:  _____
Width Length Area
1 unit 8 units 8 square units
2 unit  7 unit 14 square units
3 unit 6 unit 18 square units
4 unit 5 unit 20 square units

b. Explain how you found the widths and lengths in the chart above.
Answer:
The chart in itself has the labelling heading of the columns as length and width and their areas.
If not always length value is going to be more than the value of width in the measurements of rectangle.

Explanation:
The chart in itself has the labelling heading of the columns as length and width and their areas. If not always length value is going to be more than the value of width in the measurements of rectangle. This is how I found the widths and lengths in the chart above.

 

 

Question 3.
Jason and Dina both draw rectangles with perimeters of 12 centimeters, but their rectangles have different areas. Explain with words, pictures, and numbers how this is possible.
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-21-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 21 Homework Answer Key-3
Area of the Jason’s ABCD Rectangle = 8 square cm.
Perimeter of the Jason’s ABCD Rectangle = 12 cm.
Area of the Dina’s EFGH Rectangle = 5 square cm.
Perimeter of the Dina’s EFGH Rectangle = 12 cm.
Perimeter requires only the lengths of the four sides of rectangle to be added where as for area we require length and width of the rectangle. Jason’s ABCD rectangle and Dina’s EFGH rectangle are having same perimeter yet different areas.

Explanation:
Jason’s ABCD Rectangle:
Length of the Jason’s ABCD Rectangle = 4cm
Width of the Jason’s ABCD Rectangle = 2cm
Area of the Jason’s ABCD Rectangle = Length × Width
= 4cm ×  2cm
= 8 square cm.
Perimeter of the Jason’s ABCD Rectangle = 2 ( Length + Width )
= 2 ( 4cm + 2cm )
= 2 × 6cm
= 12 cm.

Dina’s EFGH Rectangle:
Length of the Dina’s EFGH Rectangle = 5cm
Width of the Dina’s EFGH Rectangle = 1cm
Area of the Dina’s EFGH Rectangle = Length × Width
= 5cm ×  1cm
= 5 square cm.
Perimeter of the Dina’s EFGH Rectangle = 2 ( Length + Width )
= 2 ( 5cm + 1cm )
= 2 × 6cm
= 12 cm.
Jason’s ABCD rectangle and Dina’s EFGH rectangle are having same perimeter yet different areas.

 

 

 

Eureka Math Grade 3 Module 7 Lesson 21 Data Sheet Answer Key

Use the data you gathered from Problem Sets 20 and 21 to complete the charts to show how many rectangles you can create with a given perimeter. You might not use all the spaces in the charts.

Perimeter = 10 units
Number of rectangles you made:  _1____
Width Length Area
1 unit 4 units 4 square units
2 units 3 units 6 square units
Perimeter = 12 units
Number of rectangles you made:  _2____
Width Length Area
1 unit 5 units 5 square units
2 units 4 units 8 square units
Perimeter = 14 units
Number of rectangles you made:  __3___
Width Length Area
1 unit 6 units 6 square units
2 units 5 units 10 square units
3 units 4 units 12 square units
Perimeter = 16 units
Number of rectangles you made:  __4___
Width Length Area
1 unit 7 units 7 square units
2 units 6 units 12 square units
3 units 5 units 15 square units
4 units 4 units 16 square units
Perimeter = 18 units
Number of rectangles you made:  _4____
Width Length Area
1 unit 8 units 8 square units
2 units 7 units 14 square units
3 units 6 units 18 square units
4 units 5 units 20 square units
Perimeter = 20 units
Number of rectangles you made:  __3___
Width Length Area
2 units 8 units 16 square units
4 units 6 units 24 square units
3 units 7 units 21 square units

Eureka Math Grade 3 Module 7 Lesson 20 Answer Key

Engage NY Eureka Math 3rd Grade Module 7 Lesson 20 Answer Key

Eureka Math Grade 3 Module 7 Lesson 20 Sprint Answer Key

A
Multiply or Divide by 2
Engage NY Math 3rd Grade Module 7 Lesson 20 Sprint Answer Key s 1
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-20-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 20 Sprint Answer Key-A

Question 1.
2 × 2 =
Answer:
2 × 2 = 4.

Question 2.
3 × 2 =
Answer:
3 × 2 = 6.

Question 3.
4 × 2 =
Answer:
4 × 2 = 8.

Question 4.
5 × 2 =
Answer:
5 × 2 = 10.

Question 5.
1 × 2 =
Answer:
1 × 2 = 2.

Question 6.
4 ÷ 2 =
Answer:
4 ÷ 2 = 2.

Question 7.
6 ÷ 2 =
Answer:
6 ÷ 2 = 3.

Question 8.
10 ÷ 2 =
Answer:
10 ÷ 2 = 5.

Question 9.
2 ÷ 1 =
Answer:
2 ÷ 1 = 2.

Question 10.
8 ÷ 2 =
Answer:
8 ÷ 2 = 4.

Question 11.
6 × 2 =
Answer:
6 × 2 = 12.

Question 12.
7 × 2 =
Answer:
7 × 2 = 14.

Question 13.
8 × 2 =
Answer:
8 × 2 = 16.

Question 14.
9 × 2 =
Answer:
9 × 2 = 18.

Question 15.
10 × 2 =
Answer:
10 × 2 = 20.

Question 16.
16 ÷ 2 =
Answer:
16 ÷ 2 = 8.

Question 17.
14 ÷ 2 =
Answer:
14 ÷ 2 = 7.

Question 18.
18 ÷ 2 =
Answer:
18 ÷ 2 = 9.

Question 19.
12 ÷ 2 =
Answer:
12 ÷ 2 = 6.

Question 20.
20 ÷ 2 =
Answer:
20 ÷ 2 = 10.

Question 21.
___ × 2 = 10
Answer:
_5__ × 2 = 10.

Question 22.
___ × 2 = 12
Answer:
_6__ × 2 = 12.

Question 23.
___ × 2 = 20
Answer:
_10__ × 2 = 20.

Question 24.
___ × 2 = 4
Answer:
_2__ × 2 = 4.

Question 25.
___ × 2 = 6
Answer:
__3_ × 2 = 6.

Question 26.
20 ÷ 2 =
Answer:
20 ÷ 2 = 10.

Question 27.
10 ÷ 2 =
Answer:
10 ÷ 2 = 5.

Question 28.
2 ÷ 1 =
Answer:
2 ÷ 1 = 2.

Question 29.
4 ÷ 2 =
Answer:
4 ÷ 2 = 2.

Question 30.
6 ÷ 2 =
Answer:
6 ÷ 2 = 3.

Question 31.
___ × 2 = 12
Answer:
_6__ × 2 = 12.

Question 32.
___ × 2 = 14
Answer:
_7__ × 2 = 14.

Question 33.
___ × 2 = 18
Answer:
_9__ × 2 = 18.

Question 34.
___ × 2 = 16
Answer:
_8__ × 2 = 16.

Question 35.
14 ÷ 2 =
Answer:
14 ÷ 2 = 7.

Question 36.
18 ÷ 2 =
Answer:
18 ÷ 2 = 9.

Question 37.
12 ÷ 2 =
Answer:
12 ÷ 2 = 6.

Question 38.
16 ÷ 2 =
Answer:
16 ÷ 2 = 8.

Question 39.
11 × 2 =
Answer:
11 × 2 = 22.

Question 40.
22 ÷ 2 =
Answer:
22 ÷ 2 = 11.

Question 41.
12 × 2 =
Answer:
12 × 2 = 24.

Question 42.
24 ÷ 2 =
Answer:
24 ÷ 2 = 12.

Question 43.
14 × 2 =
Answer:
14 × 2 = 28.

Question 44.
28 ÷ 2 =
Answer:
28 ÷ 2 = 14.

 

B
Multiply or Divide by 2
Engage NY Math 3rd Grade Module 7 Lesson 20 Sprint Answer Key s 2
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-20-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 20 Sprint Answer Key-B
Question 1.
1 × 2 =
Answer:
1 × 2 = 2.

Question 2.
2 × 2 =
Answer:
2 × 2 = 4.

Question 3.
3 × 2 =
Answer:
3 × 2 = 6.

Question 4.
4 × 2 =
Answer:
4 × 2 = 8.

Question 5.
5 × 2 =
Answer:
5 × 2 = 10.

Question 6.
6 ÷ 2 =
Answer:
6 ÷ 2 = 3.

Question 7.
4 ÷ 2 =
Answer:
4 ÷ 2 = 2.

Question 8.
8 ÷ 2 =
Answer:
8 ÷ 2 = 4.

Question 9.
2 ÷ 1 =
Answer:
2 ÷ 1 = 2.

Question 10.
10 ÷ 2 =
Answer:
10 ÷ 2 = 5.

Question 11.
10 × 2 =
Answer:
10 × 2 = 20.

Question 12.
6 × 2 =
Answer:
6 × 2 = 12.

Question 13.
7 × 2 =
Answer:
7 × 2 = 14.

Question 14.
8 × 2 =
Answer:
8 × 2 = 16.

Question 15.
9 × 2 =
Answer:
9 × 2 = 18.

Question 16.
14 ÷ 2 =
Answer:
14 ÷ 2 = 7.

Question 17.
12 ÷ 2 =
Answer:
12 ÷ 2 = 6.

Question 18.
16 ÷ 2 =
Answer:
16 ÷ 2 = 8.

Question 19.
20 ÷ 2 =
Answer:
20 ÷ 2 = 10.

Question 20.
18 ÷ 2 =
Answer:
18 ÷ 2 = 9.

Question 21.
___ × 2 = 12
Answer:
_6__ × 2 = 12.

Question 22.
___ × 2 = 10
Answer:
_5__ × 2 = 10.

Question 23.
___ × 2 = 4
Answer:
_2__ × 2 = 4.

Question 24.
___ × 2 = 20
Answer:
_10__ × 2 = 20.

Question 25.
___ × 2 = 6
Answer:
_3__ × 2 = 6.

Question 26.
4 ÷ 2 =
Answer:
4 ÷ 2 = 2.

Question 27.
2 ÷ 1 =
Answer:
2 ÷ 1 = 2.

Question 28.
20 ÷ 2 =
Answer:
20 ÷ 2 = 10.

Question 29.
10 ÷ 2 =
Answer:
10 ÷ 2 = 5.

Question 30.
6 ÷ 2 =
Answer:
6 ÷ 2 = 3.

Question 31.
___ × 2 = 12
Answer:
_6__ × 2 = 12.

Question 32.
___ × 2 = 16
Answer:
_8__ × 2 = 16.

Question 33.
___ × 2 = 18
Answer:
_9__ × 2 = 18.

Question 34.
___ × 2 = 14
Answer:
_7__ × 2 = 14.

Question 35.
16 ÷ 2 =
Answer:
16 ÷ 2 = 8.

Question 36.
18 ÷ 2 =
Answer:
18 ÷ 2 = 9.

Question 37.
12 ÷ 2 =
Answer:
12 ÷ 2 = 6.

Question 38.
14 ÷ 2 =
Answer:
14 ÷ 2 = 7.

Question 39.
11 × 2 =
Answer:
11 × 2 = 22.

Question 40.
22 ÷ 2 =
Answer:
22 ÷ 2 = 11.

Question 41.
12 × 2 =
Answer:
12 × 2 = 24.

Question 42.
24 ÷ 2 =
Answer:
24 ÷ 2 = 12.

Question 43.
13 × 2 =
Answer:
13 × 2 = 26.

Question 44.
26 ÷ 2 =
Answer:
26 ÷ 2 = 13.

Eureka Math Grade 3 Module 7 Lesson 20 Problem Set Answer Key

Question 1.
Use your square unit tiles to build as many rectangles as you can with a perimeter of 12 units.
a. Estimate to draw your rectangles below. Label the side lengths of each rectangle.
b. Explain your strategy for finding rectangles with a perimeter of 12 units.
c. Find the areas of all the rectangles in part (a) above.
d. The perimeters of all the rectangles are the same. What do you notice about their areas?
Answer:
a.
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-20-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 20 Problem Set Answer Key-1a
b. Well, I have choose the multiples of 12 to draw the rectangles. Perimeter of the rectangles = 12units.

c. Area of the ABCD rectangle = 12 square units.
Area of the EFGH rectangle = 12 square units.
Area of the IJKL rectangle = 12 square units.

d. Perimeter of ABCD Rectangle = 16units.
Perimeter of EFGH Rectangle = 14units.
Perimeter of IJKL Rectangle = 26units.
Well, areas of all rectangles are same yet their perimeters are completely different to one and the another rectangle.

 

Explanation:
a.
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-20-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 20 Problem Set Answer Key-1a

b. Perimeter of the rectangles = 12units.
Well, I have choose the multiples of 12 to draw the rectangles.

c.
Figure 1: ABCD Rectangle:
Length of the ABCD rectangle = 6units
Width of the ABCD rectangle = 2units
Area of the ABCD rectangle = Length × Width
= 6units × 2units
= 12 square units.

Figure 2: EFGH Rectangle:
Length of the EFGH rectangle = 4units
Width of the EFGH rectangle = 3units
Area of the EFGH rectangle = Length × Width
= 4units × 3units
= 12 square units.

Figure 3: IJKL Rectangle:
Length of the IJKL rectangle = 12units
Width of the IJKL rectangle = 1units
Area of the IJKL rectangle = Length × Width
= 12units × 1units
= 12 square units.

d.
Figure 1: ABCD Rectangle:
Length of the ABCD rectangle = 6units
Width of the ABCD rectangle = 2units
Perimeter of ABCD Rectangle = 2 ( Length + Width  )
= 2 ( 6units + 2units )
= 2 × 8units
= 16 units.

Figure 2: EFGH Rectangle:
Length of the EFGH rectangle = 4units
Width of the EFGH rectangle = 3units
Perimeter of EFGH Rectangle = 2 ( Length + Width  )
= 2 ( 4units + 3units )
= 2 × 7units
= 14 units.

Figure 3: IJKL Rectangle:
Length of the IJKL rectangle = 12units
Width of the IJKL rectangle = 1units
Perimeter of IJKL Rectangle = 2 ( Length + Width  )
= 2 ( 12units + 1units )
= 2 × 13units
= 26 units.
Well, areas of all rectangles are same yet their perimeters are completely different to one and the another rectangle.

 

Question 2.
Use your square unit tiles to build as many rectangles as you can with a perimeter of 14 units.
a. Estimate to draw your rectangles below. Label the side lengths of each rectangle.
b. Find the areas of all the rectangles in part (a) above.
c. Given a rectangle’s perimeter, what other information do you need to know about the rectangle to find its area?
Answer:
a. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-20-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 20 Problem Set Answer Key-2a
b. Area of the ABCD rectangle = 30 square units.
Area of the EFGH rectangle = 18 square units.

c.  Perimeter of any figure is basically gives the length of the figure. Area of rectangle is the region covered by the rectangle in a two-dimensional plane. Area requires length and width for its calculation.

 

Explanation:
a.
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-20-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 20 Problem Set Answer Key-2a

b. Figure 1 : ABCD Rectangle:
Length of the ABCD rectangle = 14units
Width of the ABCD rectangle = 1unit
Area of the ABCD rectangle =  Length × Width
= 14units × 1units
= 14 square units.

Figure 2 :EFGH Rectangle:
Length of the EFGH rectangle = 7units
Width of the EFGH rectangle = 2unit
Area of the EFGH rectangle = Length × Width
=  7units × 2units
= 14 square units.

c. Perimeter of any figure is basically gives the length of the figure. Area of rectangle is the region covered by the rectangle in a two-dimensional plane. Area requires length and width for its calculation.

 

Eureka Math Grade 3 Module 7 Lesson 20 Exit Ticket Answer Key

Use your square unit tiles to build as many rectangles as you can with a perimeter of 8 units.
a. Estimate to draw your rectangles below. Label the side lengths of each rectangle.
b. Find the areas of the rectangles in part (a) above.
Answer:
a. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-20-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 20 Exit Ticket Answer Key

b. Area of the ABCD rectangle = 8 square units.
Area of the EFGH rectangle = 8 square units.

Explanation:
a. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-20-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 20 Exit Ticket Answer Key

b. Figure 1  : ABCD Rectangle:
Length of the ABCD rectangle = 4units
Width of the ABCD rectangle = 2unit
Area of the ABCD rectangle = Length × Width
=  4units × 2units
= 8 square units.

Figure 2 : EFGH Rectangle:
Length of the EFGH rectangle = 8units
Width of the EFGH rectangle = 1unit
Area of the EFGH rectangle = Length × Width
=  8units × 1units
= 8 square units.

 

Eureka Math Grade 3 Module 7 Lesson 20 Homework Answer Key

Question 1.
Cut out the unit squares at the bottom of the page. Then, use them to make as many rectangles as you can with a perimeter of 10 units.
a. Estimate to draw your rectangles below. Label the side lengths of each rectangle.
b. Find the areas of the rectangles in part (a) above.
Eureka Math Grade 3 Module 7 Lesson 20 Homework Answer Key h 1
Answer:
a. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-20-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 20 Homework Answer Key-1a

b. Area of the ABCD rectangle = 10 square units.
Area of the EFGH rectangle = 10 square units.

Explanation:
a. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-20-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 20 Homework Answer Key-1a

b. Figure 1  : ABCD Rectangle:
Length of the ABCD rectangle = 10units
Width of the ABCD rectangle = 1unit
Area of the ABCD rectangle =  Length × Width
= 10units × 1units
= 10 square units.

Figure 2: EFGH Rectangle:
Length of the EFGH rectangle = 5units
Width of the EFGH rectangle = 2units
Area of the EFGH rectangle = Length × Width
= 5units × 2units
= 10 square units.

 

Question 2.
Gino uses unit square tiles to make rectangles with a perimeter of 14 units. He draws his rectangles as shown below. Using square unit tiles, can Gino make another rectangle that has a perimeter of 14 units? Explain your answer.
Eureka Math Grade 3 Module 7 Lesson 20 Homework Answer Key h 2
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-20-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 20 Exit Ticket Answer Key-2a

Perimeter of ABCD Rectangle = 14units.
Perimeter of EFGH Rectangle = 14units.

Explanation:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-20-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 20 Exit Ticket Answer Key-2a

Figure 1: ABCD Rectangle
Length of the ABCD Rectangle = 6units
Width of the ABCD Rectangle = 1units
Perimeter of ABCD Rectangle = 2 (Length + Width)
= 2 ( 6units + 1unit )
= 2 × 7units
= 14units.

Figure 2: EFGH Rectangle
Length of the EFGH Rectangle = 4units
Width of the EFGH Rectangle = 3units
Perimeter of EFGH Rectangle = 2 (Length + Width)
= 2 ( 4units + 3unit )
= 2 × 7units
= 14units.

 

Question 3.
Katie draws a square that has a perimeter of 20 centimeters.
a. Estimate to draw Katie’s square below. Label the length and width of the square.
b. Find the area of Katie’s square.
c. Estimate to draw a different rectangle that has the same perimeter as Katie’s square.
d. Which shape has a greater area, Katie’s square or your rectangle?
Answer:
a. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-20-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 20 Exit Ticket Answer Key-3a
b. Area of the ABCD Katie’s Square = 25 square units.

c. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-20-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 20 Exit Ticket Answer Key-3c

Perimeter of the EFGH Rectangle = 20units.

d. Area of the ABCD Katie’s Square = 25 square units.
Area of the EFGH Rectangle = 24 square units.
Area of the ABCD Katie’s Square is greater than the Area of the EFGH Rectangle.

Explanation:
a. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-20-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 20 Exit Ticket Answer Key-3a
b.  Length of the side of the ABCD Katie’s Square = 5units
Area of the ABCD Katie’s Square = Side × Side
= 5units × 5units
= 25 square units.

c. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-20-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 20 Exit Ticket Answer Key-3c
Length of the EFGH Rectangle = 6units
Width of the EFGH Rectangle = 4units
Perimeter of the EFGH Rectangle = 2 ( Length + Width )
= 2 ( 6units + 4units )
= 2 × 10units
= 20units.

d. Length of the side of the ABCD Katie’s Square = 5units
Area of the ABCD Katie’s Square = Side × Side
= 5units × 5units
= 25 square units.

Length of the EFGH Rectangle = 6units
Width of the EFGH Rectangle = 4units
Area of the EFGH Rectangle = Length × Width
= 6units × 4units
= 24 square units.

 

Eureka Math Grade 3 Module 7 Lesson 20 Data Sheet Answer Key

Use the data you gathered from Problem Sets 20 and 21 to complete the charts to show how many rectangles you can create with a given perimeter. You might not use all the spaces in the charts.

Perimeter = 10 units
Number of rectangles you made:  _2____

Width Length Area
1 unit 10 units 10 square units
2 unit 5 units 10 square units

Perimeter = 12 units
Number of rectangles you made:  __3___

Width Length Area
1 units 12 units 12 square units
2 units 6 units 12 square units
3 units 4 units 12 square units

Perimeter = 14 units
Number of rectangles you made:  _2____

Width Length Area
1 units 14 units 14 square units
2 units 7 units 14 square units

Perimeter = 16 units
Number of rectangles you made:  _2____

Width Length Area
1 unit 16 units 16 square units
2 units  8 units 16 square units

Perimeter = 18 units
Number of rectangles you made:  _2____

Width Length Area
1 unit 18 units  18 square units
2 units 9 units 18 square units

Perimeter = 20 units
Number of rectangles you made:  __2___

Width Length Area
1 unit 20 units 20 square units
2 units 10 units 20 square units