Eureka Math Grade 3 Module 7 Lesson 24 Answer Key

Engage NY Eureka Math 3rd Grade Module 7 Lesson 24 Answer Key

Eureka Math Grade 3 Module 7 Lesson 24 Pattern Sheet Answer Key

Multiply.
Engage NY Math 3rd Grade Module 7 Lesson 23 Pattern Sheet Answer Key p 1
multiply by 6 (6–10)
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 24 Pattern Sheet Answer Key
Explanation:
6 × 6 = 36
6 × 7 = 42
6 × 8 = 48
6 × 9 = 54
6 × 10 = 60.

Eureka Math Grade 3 Module 7 Lesson 24 Problem Set Answer Key

Use the given perimeters in the chart below to choose the widths and lengths of your robot’s rectangular body parts. Write the widths and lengths in the chart below. Use the blank rows if you want to add extra rectangular body parts to your robot.

Letter

Body PartPerimeter

Width and Length

Aarm14 cm__________ cm by __________cm
Barm14 cm__________ cm by __________cm
Cleg18 cm__________ cm by __________cm
Dleg18 cm__________ cm by __________cm
EbodyDouble the perimeter of one arm = _______ cm__________ cm by __________cm
Fhead16 cm__________ cm by __________cm
GneckHalf the perimeter of the head =

_______ cm

__________ cm by __________cm
H__________ cm by __________cm
I__________ cm by __________cm
My robot has 7 to 9 rectangular body parts.  Number of body parts:  _______

Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 24 Problem Set Answer Key Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 24 Problem Set Answer Key-

Use the information in the chart below to plan an environment for your robot. Write the width and length for each rectangular item. Use the blank rows if you want to add extra circular or rectangular items to your robot’s environment.

LetterItemShapePerimeter

Width and Length

Jsuncircleabout 25 cm
Khouserectangle82 cm__________ cm by __________cm
Ltree topcircleabout 30 cm
Mtree trunkrectangle30 cm__________ cm by __________cm
Ntree topcircleabout 20 cm
Otree trunkrectangle20 cm__________ cm by __________cm
P
Q
My robot’s environment has 6 to 8 items.  Number of items:  _______

Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 24 Problem Set Answer Key-1

Eureka Math Grade 3 Module 7 Lesson 24 Exit Ticket Answer Key

Estimate to draw three different rectangles with a perimeter of 16 centimeters. Label the width and length of each rectangle.
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 24 Exit Ticket Answer Key

Explanation:
Using the Perimeter of 16 cm we can draw three rectangles ABCD, EFGH, IJKL with different lengths and width.

 

Eureka Math Grade 3 Module 7 Lesson 24 Homework Answer Key

Question 1.
Brian draws a square with a perimeter of 24 inches. What is the length of the side of the square?
Answer:
Length of the side of the square = 6 inches.

Explanation:
Perimeter of the Square = 24 inches
Number of sides in the square = 4
Length of the side of the square = Perimeter of the Square  ÷ Number of sides in the square
= 24 inches ÷ 4
= 6 inches.

Question 2.
A rectangle has a perimeter of 18 centimeters.
a. Estimate to draw as many different rectangles as you can that have a perimeter of 18 centimeters. Label the width and length of each rectangle.
b. How many different rectangles did you find?
c. Explain the strategy you used to find the rectangles.
Answer:
a. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 24 Homework Answer Key-2a

b. I could find three different rectangles having perimeter as 18 centimeters.

c. The strategy which I used to find the rectangles is that :
Step 1:  Considered the Perimeter formula 2 ( Length + Width ) and its perimeter value 18 centimeters.
Step 2: Calculated the Length and width values.
Step 3: Keeping in mind highest value as length and lesser as Width.

Explanation:
a. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 24 Homework Answer Key-2a
b. I could find three different rectangles having perimeter as 18 centimeters.
c. The strategy which I used to find the rectangles is that :
Step 1:  Considered the Perimeter formula 2 ( Length + Width ) and its perimeter value 18 centimeters.
Step 2: Calculated the Length and width values.
Step 3: Keeping in mind highest value as length and lesser as Width.

 

Question 3.
The chart below shows the perimeters of three rectangles.
a. Write possible widths and lengths for each given perimeter.

RectanglePerimeter

Width and Length

A6 cm__________ cm by __________ cm
B10 cm__________ cm by __________ cm
C14 cm__________ cm by __________ cm

b. Double the perimeters of the rectangles in part (a). Then, find possible widths and lengths.

RectanglePerimeter

Width and Length

A12 cm__________ cm by __________ cm
B__________ cm by __________ cm
C__________ cm by __________ cm

Answer:
a. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 24 Homework Answer Key-3
b. Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-24-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 24 Homework Answer Key-3b
Explanation:
a. For the perimeter of 6cm, we have a rectangle length as 2cm and width as 1cm.
For the perimeter of 10cm, we have a rectangle length as 2cm and width as 3cm.
For the perimeter of 14cm, we have a rectangle length as 3cm and width as 4cm.

b. For the perimeter of 12cm, we have a rectangle length as 2cm and width as 4cm.

 

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