Eureka Math Grade 6 Module 6 Answer Key | Engage NY Math 6th Grade Module 6 Answer Key

eureka-math-grade-6-module-6-answer-key

EngageNY Math Grade 6 Module 6 Answer Key | Eureka Math 6th Grade Module 6 Answer Key

Eureka Math Grade 6 Module 6 Statistics

Eureka Math Grade 6 Module 6 Topic A Understanding Distributions

Eureka Math 6th Grade Module 6 Topic B Summarizing a Distribution that is Approximately Symmetric Using the Mean and Mean Absolute Deviation

Eureka Math Grade 6 Module 6 Mid Module Assessment Answer Key

Engage NY Math 6th Grade Module 6 Topic C Summarizing a Distribution that is Skewed Using the Median and the Interquartile Range

EngageNY Math Grade 6 Module 6 Topic D Summarizing and Describing Distributions

Eureka Math Grade 6 Module 6 End of Module Assessment Answer Key

Eureka Math Grade 6 Module 5 Answer Key | Engage NY Math 6th Grade Module 5 Answer Key

eureka-math-grade-6-module-5-answer-key

EngageNY Math Grade 6 Module 5 Answer Key | Eureka Math 6th Grade Module 5 Answer Key

Eureka Math Grade 6 Module 5 Area, Surface Area, and Volume Problems

Eureka Math Grade 6 Module 5 Topic A Area of Triangles, Quadrilaterals, and Polygons

Eureka Math 6th Grade Module 5 Topic B Polygons on the Coordinate Plane

Eureka Math Grade 6 Module 5 Mid Module Assessment Answer Key

Engage NY Math 6th Grade Module 5 Topic C Volume of Right Rectangular Prisms

EngageNY Math Grade 6 Module 5 Topic D Nets and Surface Area

Eureka Math Grade 6 Module 5 End of Module Assessment Answer Key

Eureka Math Grade 6 Module 4 Answer Key | Engage NY Math 6th Grade Module 4 Answer Key

eureka-math-grade-6-module-4-answer-key

EngageNY Math Grade 6 Module 4 Answer Key | Eureka Math 6th Grade Module 4 Answer Key

Eureka Math Grade 6 Module 4 Expressions and Equations

Eureka Math Grade 6 Module 4 Topic A Relationships of the Operations

Eureka Math 6th Grade Module 4 Topic B Special Notations of Operations

Engage NY Math 6th Grade Module 4 Topic C Replacing Letters and Numbers

EngageNY Math Grade 6 Module 4 Topic D Expanding, Factoring, and Distributing Expressions

6th Grade Eureka Math Module 4 Topic E Expressing Operations in Algebraic Form

Eureka Math Grade 6 Module 4 Mid Module Assessment Answer Key

Engage NY Grade 6 Module 4 Topic F Writing and Evaluating Expressions and Formulas

EngageNY 6th Grade Math Module 4 Topic G Solving Equations

Great Minds Eureka Math Grade 6 Module 4 Topic H Applications of Equations

Eureka Math Grade 6 Module 4 End of Module Assessment Answer Key

Eureka Math Grade 6 Module 3 Answer Key | Engage NY Math 6th Grade Module 3 Answer Key

eureka-math-grade-6-module-3-answer-key

EngageNY Math Grade 6 Module 3 Answer Key | Eureka Math 6th Grade Module 3 Answer Key

Eureka Math Grade 6 Module 3 Rational Numbers
Eureka Math Grade 6 Module 3 Topic A Understanding Positive and Negative Numbers on the Number Line

Eureka Math 6th Grade Module 3 Topic B Order and Absolute Value

Eureka Math Grade 6 Module 3 Mid Module Assessment Answer Key

Engage NY Math 6th Grade Module 3 Topic C Rational Numbers and the Coordinate Plane

Eureka Math Grade 6 Module 3 End of Module Assessment Answer Key

Eureka Math Grade 6 Module 2 Answer Key | Engage NY Math 6th Grade Module 2 Answer Key

eureka-math-grade-6-module-2-answer-key

EngageNY Math Grade 6 Module 2 Answer Key | Eureka Math 6th Grade Module 2 Answer Key

Eureka Math Grade 6 Module 2 Arithmetic Operations Including Division of Fractions
Eureka Math Grade 6 Module 2 Topic A Dividing Fractions by Fractions

Eureka Math 6th Grade Module 2 Topic B Multi-Digit Decimal Operations—Adding, Subtracting, and Multiplying

Eureka Math Grade 6 Module 2 Mid Module Assessment Answer Key

Engage NY Math 6th Grade Module 2 Topic C Dividing Whole Numbers and Decimals

EngageNY Math Grade 6 Module 2 Topic D Number Theory—Thinking Logically About Multiplicative Arithmetic

Eureka Math Grade 6 Module 2 End of Module Assessment Answer Key

Eureka Math Grade 6 Module 1 Answer Key | Engage NY Math 6th Grade Module 1 Answer Key

eureka-math-grade-6-module-1-answer-key

EngageNY Math Grade 6 Module 1 Answer Key | Eureka Math 6th Grade Module 1 Answer Key

Eureka Math Grade 6 Module 1 Ratios and Unit Rates
Eureka Math Grade 6 Module 1 Topic A Representing and Reasoning About Ratios

Eureka Math 6th Grade Module 1 Topic B Collections of Equivalent Ratios

Eureka Math Grade 6 Module 1 Mid Module Assessment Answer Key

Engage NY Math 6th Grade Module 1 Topic C Unit Rates

EngageNY Math Grade 6 Module 1 Topic D Percent

8th Grade Eureka Math Module 1 Topic E The Commutative Property of Addition and the Equal Sign
Eureka Math Grade 6 Module 1 End of Module Assessment Answer Key

Eureka Math Grade 4 Module 1 Lesson 15 Answer Key

Engage NY Eureka Math 4th Grade Module 1 Lesson 15 Answer Key

Eureka Math Grade 4 Module 1 Lesson 15 Problem Set Answer Key

Question 1.
Use the standard subtraction algorithm to solve the problems below.
a. Eureka Math Grade 4 Module 1 Lesson 15 Problem Set Answer Key 1
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Problem-Set-Answer-Key-Question-1-a
Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 101,660 is the minuend, the number 91,680 is the subtrahend and the number 9,980 is the difference.
b. Eureka Math Grade 4 Module 1 Lesson 15 Problem Set Answer Key 2
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Problem-Set-Answer-Key-Question-1-b
Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 101,660 is the minuend, the number 9,980 is the subtrahend and the number 91,680 is the difference.
c. Eureka Math Grade 4 Module 1 Lesson 15 Problem Set Answer Key 3
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Problem-Set-Answer-Key-Question-1-c

Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 242,561 is the minuend, the number 44,702 is the subtrahend and the number 197,859 is the difference.
d. Eureka Math Grade 4 Module 1 Lesson 15 Problem Set Answer Key 4
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Problem-Set-Answer-Key-Question-1-d
Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 242,561 is the minuend, the number 74,987 is the subtrahend and the number 167,574 is the difference.

e. Eureka Math Grade 4 Module 1 Lesson 15 Problem Set Answer Key 5
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Problem-Set-Answer-Key-Question-1-e
Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 1,000,000 is the minuend, the number 592,000 is the subtrahend and the number 408,000 is the difference.

f. Eureka Math Grade 4 Module 1 Lesson 15 Problem Set Answer Key 6
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Problem-Set-Answer-Key-Question-1-f
Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 1,000,000 is the minuend, the number 592,500 is the subtrahend and the number 407,500 is the difference.

g. Eureka Math Grade 4 Module 1 Lesson 15 Problem Set Answer Key 7
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Problem-Set-Answer-Key-Question-1-g
Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 600,658 is the minuend, the number 592,569 is the subtrahend and the number 8,089 is the difference.

h. Eureka Math Grade 4 Module 1 Lesson 15 Problem Set Answer Key 8

Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Problem-Set-Answer-Key-Question-1-h

Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 600,000 is the minuend, the number 592,569 is the subtrahend and the number 7,431 is the difference.

Use tape diagrams and the standard algorithm to solve the problems below. Check your answers.

Question 2.
David is flying from Hong Kong to Buenos Aires. The total flight distance is 11,472 miles. If the plane has 7,793 miles left to travel, how far has it already traveled?
Answer:
Total flight distance = 11,472 miles
Number of more miles Flight has to travel is = 7,793.
Number of miles the flight has traveled = ?
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Problem-Set-Answer-Key-Question-2

Question 3.
Tank A holds 678,500 gallons of water. Tank B holds 905,867 gallons of water. How much less water does Tank A hold than Tank B?
Answer:
Answer:
Total gallons of water Tank A holds = 678,500 gallons
Total gallons of water Tank B holds = 905,867 gallons
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Problem-Set-Answer-Key-Question-3

Question 4.
Mark had $25,081 in his bank account on Thursday. On Friday, he added his paycheck to the bank account, and he then had $26,010 in the account. What was the amount of Mark’s paycheck?
Answer:
Money in Mark bank account on Thursday = $25,081
After adding the paycheck to the bank account on Friday he have = $26,010
The amount on the Mark’s paycheck = ? = 26,010 – 25,081
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Problem-Set-Answer-Key-Question-4

Eureka Math Grade 4 Module 1 Lesson 15 Exit Ticket Answer Key

Draw a tape diagram to model each problem and solve.

Question 1.
956,204 – 780,169 =_______________
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Exit-Ticket-Answer-Key-Question-1
Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 956,204 is the minuend, the number 780,169 is the subtrahend and the number 176,035 is the difference.

Question 2.
A construction company was building a stone wall on Main Street. 100,000 stones were delivered to the site. On Monday, they used 15,631 stones. How many stones remain for the rest of the week? Write your answer as a statement.
Answer:
Total stones delivered to the site = 100,000 stones
Number of stones used on Monday = 15,631 stones.
Number of stones remaining for rest of the week = 100,000 – 15,631
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Exit-Ticket-Answer-Key-Question-2

Eureka Math Grade 4 Module 1 Lesson 15 Homework Answer Key

Question 1.
Use the standard subtraction algorithm to solve the problems below.
a. Eureka Math 4th Grade Module 1 Lesson 15 Homework Answer Key 9
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Homework-Answer-Key-Question-1-a

Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 9,656 is the minuend, the number 838 is the subtrahend and the number 8,818 is the difference.

b. Eureka Math 4th Grade Module 1 Lesson 15 Homework Answer Key 10
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Homework-Answer-Key-Question-1-b

Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 59,656 is the minuend, the number 5,880 is the subtrahend and the number 53,776 is the difference.

c. Eureka Math 4th Grade Module 1 Lesson 15 Homework Answer Key 11
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Homework-Answer-Key-Question-1-c

Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 759,656 is the minuend, the number 579,989 is the subtrahend and the number 179,667 is the difference.

d. Eureka Math 4th Grade Module 1 Lesson 15 Homework Answer Key 12
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Homework-Answer-Key-Question-1-d
Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 294,150 is the minuend, the number 166,370 is the subtrahend and the number 127,780 is the difference.

e. Eureka Math 4th Grade Module 1 Lesson 15 Homework Answer Key 13
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Homework-Answer-Key-Question-1-e
Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 294,150 is the minuend, the number 239,089 is the subtrahend and the number 55,061 is the difference.

f. Eureka Math 4th Grade Module 1 Lesson 15 Homework Answer Key 14
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Homework-Answer-Key-Question-1-f
Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 294,150 is the minuend, the number 96,400 is the subtrahend and the number 197,750 is the difference.

g. Eureka Math 4th Grade Module 1 Lesson 15 Homework Answer Key 15
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Homework-Answer-Key-Question-1-g
Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 800,500 is the minuend, the number 79,989 is the subtrahend and the number 720,511 is the difference.

h. Eureka Math 4th Grade Module 1 Lesson 15 Homework Answer Key 16
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Homework-Answer-Key-Question-1-h
Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 800,500 is the minuend, the number 45,500 is the subtrahend and the number 755,000 is the difference.

i. Eureka Math 4th Grade Module 1 Lesson 15 Homework Answer Key 17

Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Homework-Answer-Key-Question-1-i

Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 800,500 is the minuend, the number 276,664 is the subtrahend and the number 523,836 is the difference.

Use tape diagrams and the standard algorithm to solve the problems below. Check your answers.

Question 2.
A fishing boat was out to sea for 6 months and traveled a total of 8,578 miles. In the first month, the boat traveled 659 miles. How many miles did the fishing boat travel during the remaining 5 months?
Answer:
Total distance traveled by a fishing boat in 6 months = 8,578 miles
The distance traveled by the fishing boat in the 1st month = 659 miles
The distance traveled by the fishing boat in 5 months = ? = 8,578 – 659
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Homework-Answer-Key-Question-2

Question 3.
A national monument had 160,747 visitors during the first week of September. A total of 759,656 people visited the monument in September. How many people visited the monument in September after the first week?
Answer:
Number of visitors during the first week of September  at a national monument = 160,747
Total number of people visited the monument in September = 759,656
Number of people visited the monument in September after the first week = 759,656 – 160,747
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Homework-Answer-Key-Question-3

Question 4.
Shadow Software Company earned a total of $800,000 selling programs during the year 2012. $125,300 of that amount was used to pay expenses of the company. How much profit did Shadow Software Company make in the year 2012?
Answer:
Total amount earned by the Shadow Software Company by selling the programs during the year 2012 = $800,000
The amount payed for the expenses of he company = $125,300
Profit made by the Shadow Software Company in the year 2012 = $800,000 – $125,300
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Homework-Answer-Key-Question-4

Question 5.
At the local aquarium, Bubba the Seal ate 25,634 grams of fish during the week. If, on the first day of the week, he ate 6,987 grams of fish, how many grams of fish did he eat during the remainder of the week?
Answer:
At the Local aquarium
The amount of fish ate by Bubba the seal during the week = 25,634 grams
The amount of fish he ate on the first day of the week = 6,987 grams.
The amount of fish did he eat during the remaining week= 25,634 – 6,987
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-15-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-15-Homework-Answer-Key-Question-5

Eureka Math Grade 4 Module 1 Lesson 14 Answer Key

Engage NY Eureka Math 4th Grade Module 1 Lesson 14 Answer Key

Eureka Math Grade 4 Module 1 Lesson 14 Problem Set Answer Key

Question 1.
Use the standard algorithm to solve the following subtraction problems.
a. Eureka Math Grade 4 Module 1 Lesson 14 Problem Set Answer Key 1
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Problem-Set-Answer-Key-Question-1-a
b. Eureka Math Grade 4 Module 1 Lesson 14 Problem Set Answer Key 2
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Problem-Set-Answer-Key-Question-1-b
Explanation:
The rules of subtraction we first write the greater number at the top. Then subtract the digits column-wise ones from ones, tens from tens, hundreds from hundreds, thousands from thousands and so on.
Ones = 0 – 0 = 0.
Tens =  6 – 7 = 16 – 7 = 9.
6 is less than 7 so we borrow  1 from the 4 hundred  place  and make 4 hundred  as 3 hundred  and make 6  ten  as 16 ten and we subtract 7 from 16.
Hundreds = After borrowing 1 from hundred 4 becomes 3 . 3 – 4 = 13 – 4 = 9.
3 is less than 4 so we again borrow  1 from the 2 Thousands  place  and make 2 Thousands   as 1 Thousands and make 3 hundreds  as 13 hundreds and we subtract 4 from 13.
Thousands = 1 – 1 = 0
The number 2,460 is the minuend, the number 1,470 is the subtrahend and the number 990 is the difference.
c. Eureka Math Grade 4 Module 1 Lesson 14 Problem Set Answer Key 3
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Problem-Set-Answer-Key-Question-1-c
Explanation:
The rules of subtraction we first write the greater number at the top. Then subtract the digits column-wise ones from ones, tens from tens, hundreds from hundreds, thousands from thousands and so on.
Ones = 4 – 0 = 4.
Tens =  8 – 0 = 8.
Hundreds = 6 – 7 = 16 – 7 = 9.
6 is less than 7 so we borrow  1 from the 7 thousands  place  and make 7 thousands  as 6 thousands  and make 6  hundreds  as 16 hundreds and we subtract 7 from 16.
Thousands =After borrowing 1 from thousands place 7 becomes 6. 6 – 9 = 16 – 9 = 7.
6 is less than 9 so we again borrow  1 from the 9 ten thousands place  and make 9 ten thousands  as 8 ten thousands and make 6  thousands as 16 thousands and we subtract 9 from 16.
Ten Thousands = 8 – 4 = 4.
The number 97,684 is the minuend, the number 49,700 is the subtrahend and the number 47,984 is the difference.
d. Eureka Math Grade 4 Module 1 Lesson 14 Problem Set Answer Key 4
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Problem-Set-Answer-Key-Question-1-d

Explanation:
The rules of subtraction we first write the greater number at the top. Then subtract the digits column-wise ones from ones, tens from tens, hundreds from hundreds, thousands from thousands and so on.
Ones = 0 – 2 = 10 – 2 = 8.
0 is less than 2 so we borrow  1 from the 6 tens  place  and make 6 tens  as 5 tens  and make 0 ones  as 10 ones and we subtract 2 from 10.
Tens =After borrowing 1 from tens place 6 becomes 5.  5 – 7 = 15 – 7 = 8.
5 is less than 7 so we borrow  1 from the 4 hundred  place  and make 4 hundred  as 3 hundred  and make 5  tens  as 15 tens and we subtract 7 from 15.
Hundreds = After borrowing 1 from hundred 4 becomes 3 . 3 – 4 = 13 – 4 = 9.
3 is less than 4 so we borrow  1 from the 2 Thousands  place  and make 2 Thousands   as 1 Thousands and make 3 hundreds  as 13 hundreds and we subtract 4 from 13.
Thousands = 1 – 1 = 0
The number 2,460 is the minuend, the number 1,472 is the subtrahend and the number 988 is the difference.
e. Eureka Math Grade 4 Module 1 Lesson 14 Problem Set Answer Key 5
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Problem-Set-Answer-Key-Question-1-e

Explanation:
The rules of subtraction we first write the greater number at the top. Then subtract the digits column-wise ones from ones, tens from tens, hundreds from hundreds, thousands from thousands and so on.
Since, ones place and tens place values are less then the subtrahend we borrow 1 from the hundreds place and increase the value of tens.
Tens =After borrowing 1 from hundreds place 0 ten becomes 10 ten. So, After borrowing  1 from the 3 hundred  place. 3 hundred becomes 2 hundred .
Ones = 6 – 7 = 16 – 7 = 9.
6 is less than 7 so we borrow  1 from the 10 tens  place  and make 10 tens  as 9 tens  and make 6 ones  as 16 ones and we subtract 7 from 16.
Tens : After borrowing 1 from tens place. 10 becomes 9. 9 – 1 = 8.
Hundreds = After borrowing 1 from hundred 3 becomes 2 . 2 – 1 = 1.
Thousands : 4 – 1 = 3.
Ten Thousand : 2 – 3 = 12 – 3 = 9.
2 is less than 3 so we borrow  1 from the 1 hundred Thousands  place  and make 1 hundred Thousands   as 0  hundred Thousands and make 2 thousand  as 12 thousand and we subtract 3 from 12.
Hundred thousands = 0.
The number 124,306 is the minuend, the number 31,117 is the subtrahend and the number 93,189 is the difference.
f. Eureka Math Grade 4 Module 1 Lesson 14 Problem Set Answer Key 6
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Problem-Set-Answer-Key-Question-1-f

Explanation:
The rules of subtraction we first write the greater number at the top. Then subtract the digits column-wise ones from ones, tens from tens, hundreds from hundreds, thousands from thousands and so on.
Ones = 4 – 5 = 14 – 5 = 9.
4 is less than 5 so we borrow  1 from the 8 hundred  place  and make 8 hundred  as 7 hundred  and make 4  ten  as 14 ten and we subtract 5 from 14.
Tens =  7 – 0 = 7
Hundreds =6 – 7 = 16 – 7 = 9
6 is less than 7 so we borrow  1 from the 7 Thousands  place  and make 7 Thousands   as 6 Thousands and make 6 hundreds  as 16 hundreds and we subtract 7 from 16.
Thousands = 6 – 4  = 2
Ten Thousand = 9.
The number 97,684 is the minuend, the number 4,705 is the subtrahend and the number 92,979 is the difference.
g. Eureka Math Grade 4 Module 1 Lesson 14 Problem Set Answer Key 7
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Problem-Set-Answer-Key-Question-1-g

Explanation:
The rules of subtraction we first write the greater number at the top. Then subtract the digits column-wise ones from ones, tens from tens, hundreds from hundreds, thousands from thousands and so on.
The minuend ones , tens , hundreds all the three places are less then the subtrahend.
First
Ones = 6 – 7 = 16 – 7 = 9.
6 is less than 7 so we borrow  1 from the 0 ten place  and make 0 tens as 9 tens  and make 6  ones  as 16 ones and we subtract 7 from 16.
Tens = After borrowing 1 from hundred 0 becomes 9. 9 -1 = 8.
Hundreds = After borrowing 1 from thousand 0 becomes 9 . 9 – 1 = 8.
Thousands = 3 – 1 =  2.
Ten thousand = 2 – 2 = 0.
Hundred thousand = 1 – 1 = 0.
The number 124,006 is the minuend, the number 121,117 is the subtrahend and the number 2,889 is the difference.

h. Eureka Math Grade 4 Module 1 Lesson 14 Problem Set Answer Key 8
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Problem-Set-Answer-Key-Question-1-h

Explanation:
The rules of subtraction we first write the greater number at the top. Then subtract the digits column-wise ones from ones, tens from tens, hundreds from hundreds, thousands from thousands and so on.
Ones = 4 – 5 = 14 – 5 = 9.
4 is less than 5 so we borrow  1 from the 8 Tens place  and make 8 Tens  as 7 Tens  and make 6  ones  as 16 ones and we subtract 5 from 14.
Tens =  7 – 0 = 7.
Hundreds = 6 – 7 = 16 – 7 = 9.
6 is less than 7 so we borrow  1 from the 7 Thousands  place  and make 7 Thousands   as 6 Thousands and make 6 hundreds  as 16 hundreds and we subtract 7 from 16.
Thousands = 6 – 7 = 16 – 7 = 9.
6 is less than 7 so we borrow  1 from the 9 ten Thousands  place  and make 9  ten Thousands   as 8 ten Thousands and make 6 hundreds  as 16 hundreds and we subtract 7 from 16.
ten thousand = 8 – 4 = 4.
The number 97,684 is the minuend, the number 47,705 is the subtrahend and the number  49,979 is the difference.
i. Eureka Math Grade 4 Module 1 Lesson 14 Problem Set Answer Key 9
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Problem-Set-Answer-Key-Question-1-i

Explanation:
The rules of subtraction we first write the greater number at the top. Then subtract the digits column-wise ones from ones, tens from tens, hundreds from hundreds, thousands from thousands and so on.
Ones = 0 – 7 = 10 – 7 = 3.
0 is less than 7 so we borrow  1 from the 6 Tens place  and make 6 Tens  as 5 Tens  and make 0  ones  as 10 ones and we subtract 7 from 10.
Tens =  5 – 1 = 4.
Hundreds =0 – 1 = 1 – 1 = 9.
0 is less than 1 so we borrow  1 from the 4 Thousands  place  and make 4 Thousands   as 3 Thousands and make 0 hundreds  as 10 hundreds and we subtract 1 from 10.
Thousands = 3 – 1 = 2.
Ten thousand= 2 – 3 = 12 – 3 = 9.
2 is less than 3 so we borrow  1 from the 1 hundred Thousands  place  and make 1 hundred Thousands   as 0  hundred Thousands and make 2 ten thousand as 12 ten thousand and we subtract 3 from 12.
The number 124,060 is the minuend, the number 31,117 is the subtrahend and the number 92,943 is the difference.

Draw a tape diagram to represent each problem. Use numbers to solve, and write your answer as a statement. Check your answers.

Question 2.
There are 86,400 seconds in one day. If Mr. Liegel is at work for 28,800 seconds a day, how many seconds a day is he away from work?
Answer:
Total seconds in one day = 86,400
Number of seconds Mr. Liegel at work in a day = 28,800
Number of seconds Mr. Leigel away from work = 86,400 – 28,800
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Problem-Set-Answer-Key-Question-2

Question 3.
A newspaper company delivered 240,900 newspapers before 6 a.m. on Sunday. There were a total of 525,600 newspapers to deliver. How many more newspapers needed to be delivered on Sunday?
Answer:
Number of newspapers delivered by the company on Sunday before 6 a.m = 240,900
Total number of newspapers to be delivered = 525,600.
How many more newspaper to be delivered= ?
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Problem-Set-Answer-Key-Question-3

Question 4.
A theater holds a total of 2,013 chairs. 197 chairs are in the VIP section. How many chairs are not in the VIP section?
Total number of chairs a theater holds = 2,013
Number of chairs in the VIP Section = 197
Number of chairs which are not in the VIP section = B
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Problem-Set-Answer-Key-Question-4

Question 5.
Chuck’s mom spent $19,155 on a new car. She had $30,064 in her bank account. How much money does Chuck’s mom have after buying the car?
Answer:
Money spent by Chuck’s mom on new car = $19,155
Total money she had in her bank account = $30,064
Money left with her after buying the car = 30,064 – 19,155
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Problem-Set-Answer-Key-Question-5

Eureka Math Grade 4 Module 1 Lesson 14 Exit Ticket Answer Key

Use the standard algorithm to solve the following subtraction problems.

Question 1.
Engage NY Math 4th Grade Module 1 Lesson 14 Exit Ticket Answer Key 9.1
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Exit-Ticket-Answer-Key-Question-1

Question 2.
32,010 – 2,546
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Exit-Ticket-Answer-Key-Question-2

Draw a tape diagram to represent the following problem. Use numbers to solve, and write your answer as a statement. Check your answer.

Question 3.
A doughnut shop sold 1,232 doughnuts in one day. If they sold 876 doughnuts in the morning, how many doughnuts were sold during the rest of the day?
Answer:
Total doughnut sold by the doughnut shop in one day  = 1,232
Number of doughnuts sold in the morning = 876
Number of doughnuts sold during the rest of the day = A
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Exit-Ticket-Answer-Key-Question-3

Eureka Math Grade 4 Module 1 Lesson 14 Homework Answer Key

Question 1.
Use the standard algorithm to solve the following subtraction problems.
a. Eureka Math 4th Grade Module 1 Lesson 14 Homework Answer Key 10
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Homework-Answer-Key-Question-1-a

Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 71,989 is the minuend, the number 21,492 is the subtrahend and the number 50,497 is the difference.

b. Eureka Math 4th Grade Module 1 Lesson 14 Homework Answer Key 11
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Homework-Answer-Key-Question-1-b

Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 371,989 is the minuend, the number 96,492 is the subtrahend and the number 275,497 is the difference.
c. Eureka Math 4th Grade Module 1 Lesson 14 Homework Answer Key 12
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Homework-Answer-Key-Question-1-c

Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 371,089 is the minuend, the number 25,192 is the subtrahend and the number 345,897 is the difference.

d. Eureka Math 4th Grade Module 1 Lesson 14 Homework Answer Key 13
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Homework-Answer-Key-Question-1-d

Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 879,989 is the minuend, the number 721,492 is the subtrahend and the number 158,497 is the difference.

e. Eureka Math 4th Grade Module 1 Lesson 14 Homework Answer Key 14
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Homework-Answer-Key-Question-1-e

Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 879,009 is the minuend, the number 788,492 is the subtrahend and the number 90,517 is the difference.
f. Eureka Math 4th Grade Module 1 Lesson 14 Homework Answer Key 15
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Homework-Answer-Key-Question-1-f

Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 879,989 is the minuend, the number 21,070 is the subtrahend and the number 858,919 is the difference.
g. Eureka Math 4th Grade Module 1 Lesson 14 Homework Answer Key 16
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Homework-Answer-Key-Question-1-g

Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 879,000 is the minuend, the number 21,989 is the subtrahend and the number 857,011 is the difference.
h. Eureka Math 4th Grade Module 1 Lesson 14 Homework Answer Key 17
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Homework-Answer-Key-Question-1-h

Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 279,389 is the minuend, the number 191,492 is the subtrahend and the number 87,897 is the difference.
i. Eureka Math 4th Grade Module 1 Lesson 14 Homework Answer Key 18

Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Homework-Answer-Key-Question-1-i

Explanation:
In subtraction if the minuend place values are less than the subtrahend then 1 is borrowed from the higher place value like
ones borrow from tens
tens borrow from hundreds
hundreds borrow  from thousands
thousands borrow from ten thousands
ten thousands borrow from hundred thousands
hundred thousands borrow from million.
if there are successive place values less  than the subtrahend we borrow from the highest place value whose value is higher than the subtrahend.
The number 500,989 is the minuend, the number 242,000 is the subtrahend and the number 258,989 is the difference.

Draw a tape diagram to represent each problem. Use numbers to solve, and write your answer as a statement. Check your answers.

Question 2.
Jason ordered 239,021 pounds of flour to be used in his 25 bakeries. The company delivering the flour showed up with 451,202 pounds. How many extra pounds of flour were delivered?
Answer:
Total flour ordered by Jason to use in his 25 bakeries = 239,021 pounds
Total flour showed by the company at delivering = 451,202 pounds.
Extra pounds of flour delivered by the company =  A = 451,202 – 239,021
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Homework-Answer-Key-Question-2

Question 3.
In May, the New York Public Library had 124,061 books checked out. Of those books, 31,117 were mystery books. How many of the books checked out were not mystery books?
Answer:
Number of books checked out from the New York Public Library = 124,061 books
Out of the checked out books the Number of Mystery books are =  31,117 books
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Homework-Answer-Key-Question-3

Question 4.
A Class A dump truck can haul 239,000 pounds of dirt. A Class C dump truck can haul 600,200 pounds of dirt. How many more pounds can a Class C truck haul than a Class A truck?
Answer:
Number of pounds of dust A Class A dump truck can haul = 239,000 pounds
Number of pounds of dust A Class C dump truck can haul = 600,200 pounds
The number of more pounds of dust A Class C truck can haul than a Class A truck = ?
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-14-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-14-Homework-Answer-Key-Question-4

Eureka Math Grade 4 Module 1 Lesson 12 Answer Key

Engage NY Eureka Math 4th Grade Module 1 Lesson 12 Answer Key

Eureka Math Grade 4 Module 1 Lesson 12 Problem Set Answer Key

Estimate and then solve each problem. Model the problem with a tape diagram. Explain if your answer is reasonable.

Question 1.
For the bake sale, Connie baked 144 cookies. Esther baked 49 more cookies than Connie.
a. About how many cookies did Connie and Esther bake? Estimate by rounding each number to the nearest ten before adding.
Answer:
Number of cookies Connie baked = 144 cookies
Number of cookies  Esther baked = 49 more than Connie = 49 + 144 = 193 cookies
Total number of cookies baked by both  = 144 + 193
rounding each number to the nearest ten = 144 ~ 140  and  193 ~ 190.
Adding both 140 + 190 = 330 cookies.
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-12-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-12-Problem-Set-Answer-Key-Question-1-a
b. Exactly how many cookies did Connie and Esther bake?
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-12-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-12-Problem-Set-Answer-Key-Question-1-b
They both Baked 337 cookies exactly.
c. Is your answer reasonable? Compare your estimate from (a) to your answer from (b). Write a sentence to explain your reasoning.
Answer:
In the (a) bit the estimate answer was 330 cookies  but the answer in (b)  is 337 cookies on rounding it the nearest ten it would be 340 cookies.

Queens 2.
Raffle tickets were sold for a school fundraiser to parents, teachers, and students. 563 tickets were sold to teachers. 888 more tickets were sold to students than to teachers. 904 tickets were sold to parents.
a. About how many tickets were sold to parents, teachers, and students? Round each number to the nearest hundred to find your estimate.
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-12-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-12-Problem-Set-Answer-Key-Question-2-a
b. Exactly how many tickets were sold to parents, teachers, and students?
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-12-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-12-Problem-Set-Answer-Key-Question-2-b
c. Assess the reasonableness of your answer in (b). Use your estimate from (a) to explain.
Answer:
In (b) the answer is 2,918 on rounding it ti nearest hundred we get 2,900. But in (a) the answer is 3,000 on rounding to the nearest hundred. The difference is 100 tickets .

Queens 3.
From 2010 to 2011, the population of Queens increased by 16,075. Brooklyn’s population increased by 11,870 more than the population increase of Queens.
a. Estimate the total combined population increase of Queens and Brooklyn from 2010 to 2011.
(Round the addends to estimate.)
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-12-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-12-Problem-Set-Answer-Key-Question-3-a
b. Find the actual total combined population increase of Queens and Brooklyn from 2010 to 2011.
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-12-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-12-Problem-Set-Answer-Key-Question-3-b
c. Assess the reasonableness of your answer in (b). Use your estimate from (a) to explain.
Answer:
The answer in (b) is 44,020 population but on rounding to the nearest thousand the value is 44,000 in (a). There is a difference of 20 between the both value. Both the values are relatively closed.

Question 4.
During National Recycling Month, Mr. Yardley’s class spent 4 weeks collecting empty cans to recycle.

Week

Number of Cans Collected

1

10,827

2

3

10,522

4

20,011

a. During Week 2, the class collected 1,256 more cans than they did during Week 1. Find the total number of cans Mr. Yardley’s class collected in 4 weeks.
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-12-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-12-Problem-Set-Answer-Key-Question-4-a
b. Assess the reasonableness of your answer in (a) by estimating the total number of cans collected.
Answer:
On rounding the number to the nearest thousand we get 53,000 as total and the difference will be of 443 cans. both my estimation and actual are relatively close.

Engage NY Math 4th Grade Module 1 Lesson 12 Exit Ticket Answer Key

Model the problem with a tape diagram. Solve and write your answer as a statement.

In January, Scott earned $8,999. In February, he earned $2,387 more than in January. In March, Scott earned the same amount as in February. How much did Scott earn altogether during those three months? Is your answer reasonable? Explain.
Answer:
In January Scott earned = $8,999
In February Scott earned = $2,387
In March Scott earned same amount as February = $2,387
Total earnings in the three months =
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-12-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-12-Exit-Ticket-Answer-Key
Yes my answer is  reasonable. Because my actual and estimation both are relatively close.

Eureka Math 4th Grade Module 1 Lesson 12 Homework Answer Key

Estimate and then solve each problem. Model the problem with a tape diagram. Explain if your answer is reasonable.

Question 1.
There were 3,905 more hits on the school’s website in January than February. February had 9,854 hits. How many hits did the school’s website have during both months?
Answer:
In February there were 9,854 hits on school’s website
In January  there were more hits than February = 3,905 + 9,854 = 13,759
a. About how many hits did the website have during January and February?
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-12-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-12-Homework-Answer-Answer-Key-Question-1-a
b. Exactly how many hits did the website have during January and February?
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-12-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-12-Homework-Answer-Answer-Key-Question-1-b
c. Is your answer reasonable? Compare your estimate from (a) to your answer from (b). Write a sentence to explain your reasoning.
Answer:
The actual number of hits 23,613 is reasonable because it is relatively close to the estimation 24,000.

Question 2.
On Sunday, 77,098 fans attended a New York Jets game. The same day, 3,397 more fans attended a New York Giants game than attended the Jets game. Altogether, how many fans attended the games?
Answer:
Number of fans attended a New York Jets game = 77,098
Number of fans attended the Giants game = 3,397 more than New York Jets = 3,397 + 77,098
a. What was the actual number of fans who attended the games?
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-12-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-12-Homework-Answer-Answer-Key-Question-2-a
b. Is your answer reasonable? Round each number to the nearest thousand to find an estimate of how many fans attended the games.
Answer:
Rounding each number to the nearest thousand
80,495 ~ 90,000               77,098 ~ 77,000
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-12-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-12-Homework-Answer-Answer-Key-Question-2-b
Yes my answer is reasonable. The real value and the estimation values are close .

Question 3.
Last year on Ted’s farm, his four cows produced the following number of liters of milk:

Cow

Liters of Milk Produced

Daisy

5,098

Betsy

Mary

9,980

Buttercup

7,087

a. Betsy produced 986 more liters of milk than Buttercup. How many liters of milk did all 4 cows produce?
Answer:
Number of liters of milk produced by Daisy = 5,098
Number of liters of milk produced by Mary = 9,980
Number of liters of milk produced by Buttercup = 7,087
Number of liters of milk produced by Betsy = 986 more liters of milk than Buttercup =986 + 7,087
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-12-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-12-Homework-Answer-Answer-Key-Question-3-a
b. Is your answer reasonable? Explain.
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-12-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-12-Homework-Answer-Answer-Key-Question-3-b

Eureka Math Grade 4 Module 1 Lesson 13 Answer Key

Engage NY Eureka Math 4th Grade Module 1 Lesson 13 Answer Key2ureka Math Grade 4 Module 1 Lesson 13 Problem Set Answer Key

Question 1.
Use the standard algorithm to solve the following subtraction problems.
a. Eureka Math Grade 4 Module 1 Lesson 13 Problem Set Answer Key 1
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Problem-Set-Answer-Key-Question-1-a
Explanation:
The rules of subtraction we first write the greater number at the top. Then subtract the digits column-wise ones from ones, tens from tens, hundreds from hundreds, thousands from thousands and so on.
Ones =  5 – 2 = 3.
Tens =  2 – 0 = 2.
Hundreds = 5 – 5 = 0.
Thousands = 7 – 3 = 4.
The number 7,525 is the minuend, the number 3,502 is the subtrahend and the number 4,023 is the difference.
b. Eureka Math Grade 4 Module 1 Lesson 13 Problem Set Answer Key 2
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Problem-Set-Answer-Key-Question-1-b
Explanation:
The rules of subtraction we first write the greater number at the top. Then subtract the digits column-wise ones from ones, tens from tens, hundreds from hundreds, thousands from thousands and so on.
Ones =  5 – 2 = 3.
Tens =  2 – 0 = 2.
Hundreds = 5 – 5 = 0.
Thousands = 7 – 3 = 4.
Ten thousands = 1 – 1 = 0.
The number 17,525 is the minuend, the number 13,502 is the subtrahend and the number 04,023 is the difference.

c. Eureka Math Grade 4 Module 1 Lesson 13 Problem Set Answer Key 3
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Problem-Set-Answer-Key-Question-1-c
Explanation:
The rules of subtraction we first write the greater number at the top. Then subtract the digits column-wise ones from ones, tens from tens, hundreds from hundreds, thousands from thousands and so on.
Ones =  5 – 7 = 8.
5 is less than 7 so we borrow  1 from the 2 tens place and make 2 tens as 1 tens and make 5 ones as 15 ones and we subtract 7 from 15.
Tens =  1 – 1 = 0.
Hundreds = 6 – 4 = 2.
Thousands = 6 – 4 = 2.
The number 6,625 is the minuend, the number 4,417 is the subtrahend and the number 2,208 is the difference.
d. Eureka Math Grade 4 Module 1 Lesson 13 Problem Set Answer Key 4
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Problem-Set-Answer-Key-Question-1-d
Explanation:
The rules of subtraction we first write the greater number at the top. Then subtract the digits column-wise ones from ones, tens from tens, hundreds from hundreds, thousands from thousands and so on.
Ones =  5 – 5 = 0.
Tens =  2 – 3 =  12 – 3 = 9.
2 is less than 3 so we borrow  1 from the 6 hundreds place  and make 6 hundreds as 5 hundreds and make 2 tens as 12 tens and we subtract 3 from 12.
Hundreds = 5 – 4 = 1.
Thousands = 4 – 0 = 4.
The number 4,625 is the minuend, the number 435 is the subtrahend and the number 4,190 is the difference.
e. Eureka Math Grade 4 Module 1 Lesson 13 Problem Set Answer Key 5
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Problem-Set-Answer-Key-Question-1-e
Explanation:
The rules of subtraction we first write the greater number at the top. Then subtract the digits column-wise ones from ones, tens from tens, hundreds from hundreds, thousands from thousands and so on.
Ones =  0 – 0 = 0.
Tens =  0 – 7 =  10 – 7 = 3.
0 is less than 7 so we borrow  1 from the 5 hundreds place  and make 5 hundreds as 4 hundreds and make 0 tens as 10 tens and we subtract 7 from 10.
Hundreds = 4 – 4 = 0 .
Thousands = 6 – 0 = 6.
The number 6,500 is the minuend, the number 470 is the subtrahend and the number 6,030 is the difference.
f. Eureka Math Grade 4 Module 1 Lesson 13 Problem Set Answer Key 6
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Problem-Set-Answer-Key-Question-1-f
Explanation:
The rules of subtraction we first write the greater number at the top. Then subtract the digits column-wise ones from ones, tens from tens, hundreds from hundreds, thousands from thousands and so on.
Ones =  5 – 2 = 3.
Tens =  2 – 0 =  2.
Hundreds = 0 – 5 = 10 – 5 = 5.
0 is less than 5 so we borrow  1 from the 6 Thousands place  and make 6 Thousands as 5 Thousands and make 0 hundreds as 10 hundreds and we subtract 5 from 10.
Thousands = 5 – 3 = 2.
The number 6,025 is the minuend, the number 3,502 is the subtrahend and the number 2,502 is the difference.
g. Eureka Math Grade 4 Module 1 Lesson 13 Problem Set Answer Key 7
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Problem-Set-Answer-Key-Question-1-g
Explanation:
The rules of subtraction we first write the greater number at the top. Then subtract the digits column-wise ones from ones, tens from tens, hundreds from hundreds, thousands from thousands and so on.
Ones =  0 – 0  = 0.
Tens =  4 – 3 = 1
Hundreds = 6 – 6 = 0.
Thousands = 3 – 4 = 13 – 4 = 9.
3 is less than 4 so we borrow  1 from the 2 ten Thousands place  and make 2 Thousands as 1 ten Thousands and make 3 hundreds as 13 hundreds and we subtract 4 from 13.
Ten Thousands = 1 – 1 = 0
The number 23,640 is the minuend, the number 14,630 is the subtrahend and the number 09,010 is the difference.
h. Eureka Math Grade 4 Module 1 Lesson 13 Problem Set Answer Key 8
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Problem-Set-Answer-Key-Question-1-h
Explanation:
The rules of subtraction we first write the greater number at the top. Then subtract the digits column-wise ones from ones, tens from tens, hundreds from hundreds, thousands from thousands and so on.
Ones =  5 – 5 = 0.
Tens =  2 – 1 =  1.
2 is less than 3 so we borrow  1 from the 6 hundreds place  and make 6 hundreds as 5 hundreds and make 2 tens as 12 tens and we subtract 3 from 12.
Hundreds = 9 – 8 = 1.
Thousands = 1 – 4 = 11 – 4 = 7.
1 is less than 4 so we borrow  1 from the 3 ten thousands place  and make 3 ten thousands as 2 ten thousands and make 1 thousands as 11 thousands and we subtract 4 from 11.
Ten thousand =2 – 0 = 2.
Hundred thousand = 4 – 2 = 2.
The number 431,925 is the minuend, the number 204,815 is the subtrahend and the number 227,110 is the difference.
i. Eureka Math Grade 4 Module 1 Lesson 13 Problem Set Answer Key 9
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Problem-Set-Answer-Key-Question-1-i
Explanation:
The rules of subtraction we first write the greater number at the top. Then subtract the digits column-wise ones from ones, tens from tens, hundreds from hundreds, thousands from thousands and so on.
Ones =  5 – 5 = 0.
Tens =  2 – 0 =  2.
Hundreds = 9 – 7 = 2.
Thousands = 9 – 1 = 8
Ten thousand =1 – 2 = 11 – 2 = 9.
1 is less than 2 so we borrow  1 from the 2 hundred thousands place  and make 2 hundred thousands as 1 hundred thousands and make 1  ten thousands as 11 ten thousands and we subtract 2 from 11.
Hundred thousand = 1 – 1 = 0.
The number 219,925 is the minuend, the number 121,705 is the subtrahend and the number 098,220 is the difference.

Draw a tape diagram to represent each problem. Use numbers to solve, and write your answer as a statement. Check your answers.

Question 2.
What number must be added to 13,875 to result in a sum of 25,884?
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Problem-Set-Answer-Key-Question-2
12,009 must be added to 13,875 to get the sum of 25,884.

Question 3.
Artist Michelangelo was born on March 6, 1475. Author Mem Fox was born on March 6, 1946. How many years after Michelangelo was born was Fox born?
Answer:
Artist Michelangelo was born on March 6, 1475.
Artist Mem Fox was born on March 6, 1946
The difference between the their years = 1946 – 1475 = 471 years.
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Problem-Set-Answer-Key-Question-3

Question 4.
During the month of March, 68,025 pounds of king crab were caught. If 15,614 pounds were caught in the first week of March, how many pounds were caught in the rest of the month?
Answer:
Number of pounds of king crabs caught in the month of March = 68,025 pounds.
Number of pounds of king crabs caught in the first week of March = 15,614 pounds.
Number of pounds were caught in the rest of the month = 68,025 – 15,614 = 52,411.
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Problem-Set-Answer-Key-Question-4

Question 5.
James bought a used car. After driving exactly 9,050 miles, the odometer read 118,064 miles. What was the odometer reading when James bought the car?
Answer:
James bought a used car after driving exactly = 9,050 miles.
The reading of the Odometer  = 118,064 miles.
The odometer reading when James bought the car = 118,064 – 9,050 =
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Problem-Set-Answer-Key-Question-5

Eureka Math Grade 4 Module 1 Lesson 13 Exit Ticket Answer Key

Question 1.
Use the standard algorithm to solve the following subtraction problems.
a. Engage NY Math 4th Grade Module 1 Lesson 13 Exit Ticket Answer Key 10
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Exit-Ticket-Answer-Key-Question-1-a

Explanation:
The rules of subtraction we first write the greater number at the top. Then subtract the digits column-wise ones from ones, tens from tens, hundreds from hundreds, thousands from thousands and so on.
Ones =  2 – 1 = 1.
Tens =  1 – 0 = 1.
Hundreds = 5 – 5 = 0.
Thousands = 8 – 2 = 6.
The number 8,512 is the minuend, the number 2,501 is the subtrahend and the number 6,011 is the difference.

b. Engage NY Math 4th Grade Module 1 Lesson 13 Exit Ticket Answer Key 11
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Exit-Ticket-Answer-Key-Question-1-b

Explanation:
The rules of subtraction we first write the greater number at the top. Then subtract the digits column-wise ones from ones, tens from tens, hundreds from hundreds, thousands from thousands and so on.
Ones =  2 – 2 = 0.
Tens =  4 – 2 =  2.
Hundreds = 0 – 1 = 10 – 1 = 9.
0 is less than 1 so we borrow  1 from the 8 thousands place  and make 8 thousands as 7 thousands and make 0 hundred as 10 hundred and we subtract 1 from 10.
Thousands = 7 – 4 = 3.
Ten thousand =1.
The number 18,042 is the minuend, the number 4,122 is the subtrahend and the number 13,920 is the difference.
c. Engage NY Math 4th Grade Module 1 Lesson 13 Exit Ticket Answer Key 12
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Exit-Ticket-Answer-Key-Question-1-c
Explanation:
The rules of subtraction we first write the greater number at the top. Then subtract the digits column-wise ones from ones, tens from tens, hundreds from hundreds, thousands from thousands and so on.
Ones =  2 – 1 = 1.
Tens =  7- 6 =  1.
Hundreds = 0 – 5 = 10 – 5 = 5.
0 is less than 5 so we borrow  1 from the 8 thousands place  and make 8 thousands as 7 thousands and make 0 hundred as 10 hundred and we subtract 5 from 10.
Thousands = 7 – 1 = 6.
The number 8,072 is the minuend, the number 1,561 is the subtrahend and the number 6,511 is the difference.

Draw a tape diagram to represent the following problem. Use numbers to solve. Write your answer as a statement. Check your answer.

Question 2.
What number must be added to 1,575 to result in a sum of 8,625?
Answer:
Sum = 8,625
One Addend = 1,575
Second Addend = sum –  one addend = 8,625 – 1,575 =
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Exit-Ticket-Answer-Key-Question-2

Eureka Math Grade 4 Module 1 Lesson 13 Homework Answer Key

Question 1.
Use the standard algorithm to solve the following subtraction problems.

a. Eureka Math 4th Grade Module 1 Lesson 13 Homework Answer Key 13
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Homework-Answer-Key-Question-1-a
b. Eureka Math 4th Grade Module 1 Lesson 13 Homework Answer Key 14
Answer:

Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Homework-Answer-Key-Question-1-b
c. Eureka Math 4th Grade Module 1 Lesson 13 Homework Answer Key 15
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Homework-Answer-Key-Question-1-c
d. Eureka Math 4th Grade Module 1 Lesson 13 Homework Answer Key 16
Answer:

Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Homework-Answer-Key-Question-1-d
e. Eureka Math 4th Grade Module 1 Lesson 13 Homework Answer Key 17
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Homework-Answer-Key-Question-1-e
f. Eureka Math 4th Grade Module 1 Lesson 13 Homework Answer Key 18
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Homework-Answer-Key-Question-1-f
g. 2,431 – 920 =
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Homework-Answer-Key-Question-1-g
h. 892,431 – 520,800 =
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Homework-Answer-Key-Question-1-h

Question 2.
What number must be added to 14,056 to result in a sum of 38,773?
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Homework-Answer-Key-Question-2

Draw a tape diagram to model each problem. Use numbers to solve, and write your answers as a statement. Check your answers.

Question 3.
An elementary school collected 1,705 bottles for a recycling program. A high school also collected some bottles. Both schools collected 3,627 bottles combined. How many bottles did the high school collect?
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Homework-Answer-Key-Question-3
The High School have collected 1,922 bottles.

Question 4.
A computer shop sold $356,291 worth of computers and accessories. It sold $43,720 worth of accessories. How much did the computer shop sell in computers?
Answer:
Total worth of computers and accessories a computer shop = $356,291
The worth of  accessories = $43,720.
The worth of computers  = A
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Homework-Answer-Key-Question-4

Question 5.
The population of a city is 538,381. In that population, 148,170 are children.
a. How many adults live in the city?
b. 186,101 of the adults are males. How many adults are female?
Answer:
Total population of the city = 538,381
Number of children in the city = 148,170
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-13-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-13-Homework-Answer-Key-Question-5

Eureka Math Grade 4 Module 1 Lesson 11 Answer Key

Engage NY Eureka Math 4th Grade Module 1 Lesson 11 Answer Key

Eureka Math Grade 4 Module 1 Lesson 11 Problem Set Answer Key

Question 1.
Solve the addition problems below using the standard algorithm.
a. Eureka Math Grade 4 Module 1 Lesson 11 Problem Set Answer Key 1
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Problem-Set-Answer-Key-Question-1-a
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 6,311 and 268
first adding the ones place = 1 + 8 = 9.
ten place : 1 + 6 = 7
hundreds place = 3 + 2 = 5
thousands place = 6
Sum = 6,579
b. Eureka Math Grade 4 Module 1 Lesson 11 Problem Set Answer Key 2
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Problem-Set-Answer-Key-Question-1-b
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 6,311 and 1,268
first adding the ones place = 1 + 8 = 9.
ten place : 1 + 6 = 7
hundreds place = 3 + 2 = 5
thousands place = 6 + 1 = 7
Sum = 7,579
c. Eureka Math Grade 4 Module 1 Lesson 11 Problem Set Answer Key 3
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Problem-Set-Answer-Key-Question-1-c
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 6,314 and 1,268
first adding the ones place =  4 + 8 = 12. 12 is represented as 10 ones + 2 ones  that’s 10 ones make 1 ten and 2 ones. So 1 is carried to the tens place and added to the tens place values.
ten place : 1 + 6 + 1 = 8
hundreds place = 3+ 2 = 5
thousands place = 6 + 1 = 7
Sum = 7,582.
d. Eureka Math Grade 4 Module 1 Lesson 11 Problem Set Answer Key 4
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Problem-Set-Answer-Key-Question-1-d
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 6,314 and 2,493
first adding the ones place =  4 + 3 = 7.
ten place : 1 + 9  = 10. 10 tens make 1 hundred . So 1 is carried to the hundreds place and added to the hundreds place values and 0 is represented in tens place
hundreds place = 3+ 4 + 1 = 8
thousands place = 6 + 2 = 8
Sum = 8,807
e. Eureka Math Grade 4 Module 1 Lesson 11 Problem Set Answer Key 5
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Problem-Set-Answer-Key-Question-1-e
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 8,314 and 2,493
first adding the ones place = 4 + 3 = 7.
ten place : 1 + 9 = 10. 10 tens make 1 hundred . So 1 is carried to the hundreds place and added to the hundreds place values and 0 is represented in tens place
hundreds place = 3 + 4 + 1 = 8
thousands place = 8 + 2 = 10. 10 thousands make 1 ten thousands . So 1 is carried to the ten thousands place and added to the ten thousands place values and 0 is represented in thousands place
ten thousands = 1
Sum = 10,807.
f. Eureka Math Grade 4 Module 1 Lesson 11 Problem Set Answer Key 6
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Problem-Set-Answer-Key-Question-1-f

Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 12,378 and 5,463
first adding the ones place = 8 + 3 = 11. 10 ones + 1 ones = 11. 10 ones make 1 ten . So 1 is carried to the tens place and added to the tens place values and 1 is represented in ones place
ten place : 7 + 6 + 1(carry on) = 14. 10 ten and 4 tens = 14 .10 tens make 1 hundred . So 1 is carried to the hundreds place and added to the hundreds place values and 4 is represented in tens place
hundreds place = 3 + 4 + 1(carry on) = 8
thousands place = 2 + 5 = 7
ten thousands = 1
Sum = 17,841

g. Eureka Math Grade 4 Module 1 Lesson 11 Problem Set Answer Key 7
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Problem-Set-Answer-Key-Question-1-g
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 52,098 and 6,048
first adding the ones place = 8 + 8 = 16. 10 ones + 6 ones = 16. 10 ones make 1 ten . So 1 is carried to the tens place and added to the tens place values and 6 is represented in ones place
ten place : 9 + 4 + 1(carry on) = 14. 10 ten and 4 tens = 14 .10 tens make 1 hundred . So 1 is carried to the hundreds place and added to the hundreds place values and 4 is represented in tens place
hundreds place = 0 + 0 + 1(carry on) = 1
thousands place = 2 + 6 = 8
ten thousands = 5
Sum = 58,146

h. Eureka Math Grade 4 Module 1 Lesson 11 Problem Set Answer Key 8
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Problem-Set-Answer-Key-Question-1-h
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 34,698 and 71,840
first adding the ones place = 8 + 0 = 8.
ten place : 9 + 4 = 13. 10 tens + 3 tens = 13 .10 tens make 1 hundred . So 1 is carried to the hundreds place and added to the hundreds place values and 3 is represented in tens place
hundreds place = 6 +8 + 1(carried number) = 15 = 10 hundred + 5 hundred . 10 hundreds make 1 thousands . So 1 is carried to the thousands place and added to the thousands place values and 5 is represented in hundreds place
thousands place = 4 + 1 + 1(carried number) = 6.
ten thousands = 3 + 7 = 10 .10  ten thousands make 1 hundred thousands . So 1 is carried to the hundred thousands place and added to the hundred thousands place values and 0 is represented in ten thousands place
Hundred thousands = 1(carried number) = 1
Sum = 106,538.
i. Eureka Math Grade 4 Module 1 Lesson 11 Problem Set Answer Key 9
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Problem-Set-Answer-Key-Question-1-i
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 34,698 and 71,840
first adding the ones place = 1 + 5 = 6.
ten place : 1 + 4 = 5.
hundreds place = 8 + 4 = 12 = 10 hundred + 2 hundred . 10 hundreds make 1 thousands . So 1 is carried to the thousands place and added to the thousands place values and 2 is represented in hundreds place
thousands place = 4 + 6 + 1(carried number) = 11 =10 thousand + 1 thousand. 10   thousands make 1 ten thousands . So 1 is carried to the ten thousands place and added to the ten thousands place values and 1 is represented in  thousands place
ten thousands = 4 + 5 + 1(carried number) = 10 .10  ten thousands make 1 hundred thousands . So 1 is carried to the hundred thousands place and added to the hundred thousands place values and 0 is represented in ten thousands place
Hundred thousands = 1(carried number) = 5 + 3 + 1(carried number) = 9
Sum = 901,256.
j. 527 + 275 + 752
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Problem-Set-Answer-Key-Question-1-j
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 527 , 275 and 752
first adding the ones place = 7 + 5 + 2 = 14 = 10 ones + 4 ones . 10 ones make 1 tens . So 1 is carried to the tens place and added to the tens place values and 4 is represented in ones place
ten place : 2 + 7 + 5 + 1(carried number) = 15 = 10 tens + 5 tens.  10 tens make 1 hundred . So 1 is carried to the hundreds place and added to the hundreds place values and 5 is represented in tens place
hundreds place = 5 +2 + 7 + 1(carried number)= 15 = 10 hundred + 5 hundred . 10 hundreds make 1 thousands . So 1 is carried to the thousands place and added to the thousands place values and 5 is represented in hundreds place
thousands place = 4 + 6 + 1(carried number) = 11 =10 thousand + 1 thousand. 10   thousands make 1 ten thousands . So 1 is carried to the ten thousands place and added to the ten thousands place values and 1 is represented in  thousands place
ten thousands = 4 + 5 + 1(carried number) = 10 .10  ten thousands make 1 hundred thousands . So 1 is carried to the hundred thousands place and added to the hundred thousands place values and 0 is represented in ten thousands place
Hundred thousands = 1(carried number) = 5 + 3 + 1(carried number) = 9
Sum = 1,554
k. 38,193 + 6,376 + 241,457
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Problem-Set-Answer-Key-Question-1-k
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 38,193 + 6,376 + 241,457
first adding the ones place = 3 + 6 + 7= 16 = 10 ones + 6 ones . 10 ones make 1 tens . So 1 is carried to the tens place and added to the tens place values and 6 is represented in ones place
ten place : 9 + 7 + 5 + 1(carried number) = 22 = 20 tens + 2 tens.  20 tens make 2 hundred . So 1 is carried to the hundreds place and added to the hundreds place values and 2 is represented in tens place
hundreds place = 1 + 3 + 4  + 1(carried number)= 10. 10 hundreds make 1 thousands . So 1 is carried to the thousands place and added to the thousands place values and 0 is represented in hundreds place
thousands place = 8 + 6 + 1 +1(carried number) = 16 =10 thousand + 6 thousand. 10   thousands make 1 ten thousands . So 1 is carried to the ten thousands place and added to the ten thousands place values and 6 is represented in  thousands place
ten thousands =3 + 4 + 1(carried number) = 8 .
Hundred thousands = 2
Sum = 286,026.

Draw a tape diagram to represent each problem. Use numbers to solve, and write your answer as a statement.

Question 2.
In September, Liberty Elementary School collected 32,537 cans for a fundraiser. In October, they collected 207,492 cans. How many cans were collected during September and October?
Answer:
Number of cans collected by the Liberty Elementary School for a fundraiser in September are = 32,537
Number of cans collected by the Liberty Elementary School for a fundraiser in October are = 207,492
Total number of cans collected during September and October are = 32,537 + 207,492 =
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Problem-Set-Answer-Key-Question-2

Question 3.
A baseball stadium sold some burgers. 2,806 were cheeseburgers. 1,679 burgers didn’t have cheese. How many burgers did they sell in all?
Answer:
Number of cheeseburgers sold at baseball stadium = 2,806
Number of burgers without cheese sold at baseball stadium are = 1,679
Total number of burgers sold in all are = 2,806 + 1,679
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Problem-Set-Answer-Key-Question-3

Question 4.
On Saturday night, 23,748 people attended the concert. On Sunday, 7,570 more people attended the concert than on Saturday. How many people attended the concert on Sunday?
Answer:
Number of people attended the concert on Saturday night = 23,748
Number of people attended the concert on Sunday are =  7,570 more than on Saturday
Total people attended the concert on Sunday = 23,748 + 7, 570
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Problem-Set-Answer-Key-Question-4

Eureka Math Grade 4 Module 1 Lesson 11 Exit Ticket Answer Key

Question 1.
Solve the addition problems below using the standard algorithm.
a. Engage NY Math 4th Grade Module 1 Lesson 11 Exit Ticket Answer Key 10
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Exit-Ticket-Answer-Key-Question-1-a
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 23,607 and 2,307
first adding the ones place = 7 + 7 = 14. 14 is represented as 10 + 4 that’s 1 ten and 4 ones. So 1 is carried to the tens place and added to the tens place values.
ten place : 0 + 0 + 1 = 1
hundreds place = 6 + 3 = 9
thousands place = 3 + 2 = 5
ten thousands place = 2
Sum = 25,914.

b. Engage NY Math 4th Grade Module 1 Lesson 11 Exit Ticket Answer Key 11
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Exit-Ticket-Answer-Key-Question-1-b
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 3,948 and 278
first adding the
ones place = 8 + 8 = 16. 16 is represented as 10 + 6 that’s 1 ten and 6 ones. So 1 is carried to the tens place and added to the tens place values and 6 is represented in ones place.
ten place : 4 + 7 + 1(carried number) = 12 = 10 + 2 that’s 1 hundred and 2 tens. So 1 is carried to the hundreds place and added to the hundreds place values and 2 is represented in tens place.
hundreds place = 9 + 2 + 1(carried number) = 12 = 10 + 2 that’s 1 thousand and 2 hundred. So 1 is carried to the thousands place and added to the thousands place values and 2 is represented in hundreds place.
thousands place = 3 + 1(carried number) = 4
Sum = 4,226.
c. 5,983 + 2,097
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Exit-Ticket-Answer-Key-Question-1-c
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 5,983 and 2,097
first adding the
ones place = 3 + 7 = 10. 10 is represented as 10 + 0 that’s 1 ten and 0 ones. So 1 is carried to the tens place and added to the tens place values and 0 is represented in ones place.
ten place : 8 + 9 + 1(carried number) = 18 = 10 + 8 that’s 1 hundred and 8 tens. So 1 is carried to the hundreds place and added to the hundreds place values and 8 is represented in tens place.
hundreds place = 9 + 0 + 1(carried number) = 10 = 10 + 0 that’s 1 thousand and 0 hundred. So 1 is carried to the thousands place and added to the thousands place values and 0 is represented in hundreds place.
thousands place = 5 + 2 + 1(carried number) = 8
Sum = 8,080

Question 2.
The office supply closet had 25,473 large paper clips, 13,648 medium paper clips, and 15,306 small paper clips. How many paper clips were in the closet?
Answer:
Number of large paper clips = 25,473
Number of medium paper clips = 13,648
Number of small paper clips = 15,306
Total number of paper clips = 25,473 + 13,648 + 15,306
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Exit-Ticket-Answer-Key-Question-2

Eureka Math Grade 4 Module 1 Lesson 11 Homework Answer Key

Question 1.
Solve the addition problems below using the standard algorithm.
a. Eureka Math 4th Grade Module 1 Lesson 11 Homework Answer Key 12
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Homework-Answer-Key-Question-1-a
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 7,909 and 1,044
first adding the ones place = 9 + 4 = 13 = 10 ones + 3 ones . 10 ones make 1 tens . So 1 is carried to the tens place and added to the tens place values and 3 is represented in ones place
ten place : 0 + 4 + 1(carried number) = 5
hundreds place = 9 + 0 = 9.
thousands place = 7 + 1 = 8.
Sum = 8,953.
b. Eureka Math 4th Grade Module 1 Lesson 11 Homework Answer Key 13
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Homework-Answer-Key-Question-1-b
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 27,909 and 9,740
first adding the ones place = 9 + 0 = 9
ten place : 0 + 4 = 4.
hundreds place = 9 + 7 = 16. 10 hundreds make 1 thousands . So 1 is carried to the thousands place and added to the thousands place values and 6 is represented in hundreds place
thousands place = 7 + 9 +1(carried number) = 17 =10 thousand + 7 thousand. 10   thousands make 1 ten thousands . So 1 is carried to the ten thousands place and added to the ten thousands place values and 7 is represented in  thousands place.
ten thousands =2 + 1(carried number) = 3 .
Sum = 37,649.
c. Eureka Math 4th Grade Module 1 Lesson 11 Homework Answer Key 14
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Homework-Answer-Key-Question-1-c
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 827,909 and 42,989
first adding the ones place = 9 + 9= 18 = 10 ones + 8 ones . 10 ones make 1 tens . So 1 is carried to the tens place and added to the tens place values and 8 is represented in ones place
ten place : 0 + 8  + 1(carried number) = 8.
hundreds place = 9 + 9 = 18. 10 hundreds make 1 thousands . So 1 is carried to the thousands place and added to the thousands place values and 8 is represented in hundreds place
thousands place = 7 + 2 +1(carried number) = 10 =10 thousand + 0 thousand. 10   thousands make 1 ten thousands . So 1 is carried to the ten thousands place and added to the ten thousands place values and 0 is represented in  thousands place
ten thousands =2+ 4 + 1(carried number) = 7 .
Hundred thousands = 8
Sum = 870,898.
d. Eureka Math 4th Grade Module 1 Lesson 11 Homework Answer Key 15
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Homework-Answer-Key-Question-1-d
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 289,205 and 11,845
first adding the ones place = 5 + 5 = 10 = 10 ones + 0 ones . 10 ones make 1 tens . So 1 is carried to the tens place and added to the tens place values and 0 is represented in ones place
ten place : 0 + 4 + 1(carried number) = 5.
hundreds place = 2 + 8 = 10. 10 hundreds make 1 thousands . So 1 is carried to the thousands place and added to the thousands place values and 0 is represented in hundreds place
thousands place = 9 + 1 +1(carried number) = 11 =10 thousand + 1 thousand. 10   thousands make 1 ten thousands . So 1 is carried to the ten thousands place and added to the ten thousands place values and 1 is represented in  thousands place
ten thousands =8 + 1 + 1(carried number) =10. 10 ten thousands make 1 hundred thousands . So 1 is carried to the hundred thousands place and added to the hundred thousands place values and 1 is represented in  ten thousands place
Hundred thousands = 2 + 1(carried over number) = 3
Sum = 301,050.
e. Eureka Math 4th Grade Module 1 Lesson 11 Homework Answer Key 16
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Homework-Answer-Key-Question-1-e
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 547,982 and 114,849
first adding the ones place = 2 + 9 = 11 = 10 ones + 1 ones . 10 ones make 1 tens . So 1 is carried to the tens place and added to the tens place values and 1 is represented in ones place
ten place : 8 + 4 + 1(carried number) = 13. 10 tens make 1 hundred . So 1 is carried to the hundreds place and added to the hundreds place values and 3 is represented in tens place
hundreds place = 9 + 8 + 1(carried number)= 18. 10 hundreds make 1 thousands . So 1 is carried to the thousands place and added to the thousands place values and 8 is represented in hundreds place
thousands place = 7 + 4 +1(carried number) = 12 =10 thousand + 2 thousand. 10   thousands make 1 ten thousands . So 1 is carried to the ten thousands place and added to the ten thousands place values and 2 is represented in  thousands place
ten thousands =4 + 1 + 1(carried number) = 6.
Hundred thousands = 5 + 1 = 6.
Sum = 662,831.
f. Eureka Math 4th Grade Module 1 Lesson 11 Homework Answer Key 17
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Homework-Answer-Key-Question-1-f
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 258,983 and 121,897.
first adding the ones place = 3 + 7 = 10 = 10 ones + 0 ones . 10 ones make 1 tens . So 1 is carried to the tens place and added to the tens place values and 0 is represented in ones place
ten place : 8 + 9+ 1(carried number) = 18. 10 tens make 1 hundred . So 1 is carried to the hundreds place and added to the hundreds place values and 8 is represented in tens place
hundreds place = 9 + 8 + 1(carried number)= 18. 10 hundreds make 1 thousands . So 1 is carried to the thousands place and added to the thousands place values and 8 is represented in hundreds place
thousands place = 8 + 1 +1(carried number) = 10 =10 thousand + 0 thousand. 10   thousands make 1 ten thousands . So 1 is carried to the ten thousands place and added to the ten thousands place values and 0 is represented in  thousands place
ten thousands =5 + 2 + 1(carried number) = 8.
Hundred thousands = 2 + 1 = 3.
Sum = 380,880.
g. Eureka Math 4th Grade Module 1 Lesson 11 Homework Answer Key 18
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Homework-Answer-Key-Question-1-g
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 83,906 and 35,808
first adding the ones place = 6 + 8  = 14 = 10 ones + 4 ones . 10 ones make 1 tens . So 1 is carried to the tens place and added to the tens place values and 4 is represented in ones place
ten place : 0 + 0 + 1(carried number) = 1.
hundreds place = 9 + 8 = 17. 10 hundreds make 1 thousands . So 1 is carried to the thousands place and added to the thousands place values and 7 is represented in hundreds place
thousands place = 3 + 5 +1(carried number) = 9.
ten thousands =8 + 3 = 11. 10 ten thousands make 1 hundred thousands . So 1 is carried to the hundred thousands place and added to the hundred thousands place values and 1 is represented in  ten thousands place
Hundred thousands = 1(carried number) = 1.
Sum = 119,714.
h. Eureka Math 4th Grade Module 1 Lesson 11 Homework Answer Key 19
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Homework-Answer-Key-Question-1-h
Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 289,999 and 91,849
first adding the ones place = 9 + 9  = 18 = 10 ones + 8 ones . 10 ones make 1 tens . So 1 is carried to the tens place and added to the tens place values and 8 is represented in ones place
ten place : 9 + 4 + 1(carried number) = 14. 10 tens make 1 hundreds . So 1 is carried to the hundreds place and added to the hundreds place values and 4 is represented in tens place
hundreds place = 9 + 8 +1(carried number)= 18 . 10 hundreds make 1 thousands . So 1 is carried to the thousands place and added to the thousands place values and 8 is represented in hundreds place
thousands place = 9 + 1 +1(carried number) = 11. 10  thousands make 1 ten thousands . So 1 is carried to the ten thousands place and added to the ten thousands place values and 1 is represented in  thousands place.
ten thousands =8 + 9 +1(carried number) = 18. 10 ten thousands make 1 hundred thousands . So 1 is carried to the hundred thousands place and added to the hundred thousands place values and 8 is represented in  ten thousands place
Hundred thousands = 2 +1(carried number) = 3.
Sum = 381,848
i. Eureka Math 4th Grade Module 1 Lesson 11 Homework Answer Key 20
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Homework-Answer-Key-Question-1-i

Explanation:
While adding two numbers we add the numbers according to the place values individually. We add number from ones place to the largest place value.
given number 289,999 and 91,849
first adding the ones place = 0 + 0  = 0.
ten place : 0 + 0 = 0.
hundreds place = 9+1= 10 . 10 hundreds make 1 thousands . So 1 is carried to the thousands place and added to the thousands place values and 0 is represented in hundreds place
thousands place = 4 + 5  +1(carried number) = 10. 10  thousands make 1 ten thousands . So 1 is carried to the ten thousands place and added to the ten thousands place values and 0 is represented in  thousands place.
ten thousands =5 + 4 +1(carried number) = 10. 10 ten thousands make 1 hundred thousands . So 1 is carried to the hundred thousands place and added to the hundred thousands place values and 0 is represented in  ten thousands place
Hundred thousands = 7 + 2 +1(carried number) = 1. 10 hundred thousands make 1 million . So 1 is carried to the millions place and added to the millions place values and 0 is represented in  hundred thousands place.
Millions = 1 (carried over number) = 1.
Sum = 1,000,000.

Draw a tape diagram to represent each problem. Use numbers to solve, and write your answer as a statement.

Question 2.
At the zoo, Brooke learned that one of the rhinos weighs 4,897 pounds, one of the giraffes weighs 2,667 pounds, one of the African elephants weighs 12,456 pounds, and one of the Komodo dragons weighs 123 pounds.
Answer:
Given
One of the rhinos weights at the zoo = 4,897 pounds.
One of the giraffes weights at the zoo  = 2,667 pounds
One of the African elephants weights at the zoo = 12, 456 pounds.
One of the Komodo dragons at the zoo weighs = 123 pounds.
a. What is the combined weight of the zoo’s African elephant and the giraffe?
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Homework-Answer-Key-Question-2-a
b. What is the combined weight of the zoo’s African elephant and the rhino?
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Homework-Answer-Key-Question-2-b
c. What is the combined weight of the zoo’s African elephant, the rhino, and the giraffe?
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Homework-Answer-Key-Question-2-c
d. What is the combined weight of the zoo’s Komodo dragon and the rhino?
Answer:
Engage-NY-Eureka-Math-4th-Grade-Module-1-Lesson-11-Answer-Key-Eureka-Math-Grade-4-Module-1-Lesson-11-Homework-Answer-Key-Question-2-d

Eureka Math Grade 4 Module 7 End of Module Assessment Answer Key

Engage NY Eureka Math 4th Grade Module 7 End of Module Assessment Answer Key

Eureka Math Grade 4 Module 7 End of Module Assessment Task Answer Key

Question 1.
Solve for the following conversions. Draw tape diagrams to model the equivalency.
a. 1 gal = ______ qt
b. 3 qt 1 pt = ______ pt
Answer:

a. 1 gal =  4 qt


b. 3 qt 1 pt = 7 pt

 

Question 2.
Complete the following tables:
a.

Pounds

Ounces

116
232
696
10160
13208

The rule for converting pounds to ounces is _____________.

To convert pounds into ounces, multiply pounds x 16

b.

Hours

Minutes

160
3180
7420
10600
14840

The rule for converting hours to minutes is _____________.
Answer:

To convert hours into minutes, multiply hours x 60

Question 3.
Answer true or false for the following statements. Explain how you know using pictures, numbers, or words.
a. 68 ounces < 4 pounds _____________ b. 920 minutes > 17 hours _____________
c. 38 inches = 3 feet 2 inches _____________
Answer:

a. False, 4 pounds = 16 x 4 = 64 ounces

So, 68 ounces > 4 pounds

b. False, 17 hours = 17 x 60 = 1,020 minutes

So, 920 minutes < 1,020 minutes

c. True.

3 feet = 36 inches  and 2 inches

Total : 36 + 2 = 38 inches

So, 38 inches = 3 feet 2 inches.

Question 4.
Convert the following measurements.
a. Express the length of a 9 kilometre trip in meters. _______________
b. Express the capacity of a 3 liter 240 millilitre container in millilitres. ______________
c. Express the length of a 3 foot 5 inch fish in inches. _______________
d. Express the length of a 2\(\frac{1}{4}\) hour movie in minutes. _______________
e. Express the weight of a 24\(\frac{3}{8}\) pound wolverine in ounces. _______________
Answer:

a. Express the length of a 9 kilometre trip in meters. 9000 meters
b. Express the capacity of a 3 liter 240 millilitre container in millilitres. 3240 millilitres
c. Express the length of a 3 foot 5 inch fish in inches. 41 inches
d. Express the length of a 2\(\frac{1}{4}\) hour movie in minutes. 135 minutes
e. Express the weight of a 24\(\frac{3}{8}\) pound wolverine in ounces. 390 ounces

Question 5.
Find the following sums and differences. Show your work.
a. 4 gal 2 qt + 5 gal 3 qt = _______ gal _______ qt
b. 6 ft 2 in – 9 inches = _______ ft _______ in
c 3 min 34 sec + 7 min 46 sec = _______ min _______ sec
d. 24 lb 9 oz – 3 lb 11 oz = _______ lb _______ oz
Answer:

a. 4 gal 2 qt + 5 gal 3 qt = 10 gal 1 qt
b. 6 ft 2 in – 9 inches = 5 ft 5 in
c 3 min 34 sec + 7 min 46 sec = 11 min 20 sec
d. 24 lb 9 oz – 3 lb 11 oz = 20 lb 14 oz

Question 6.
a. Complete the table.

Length

yards

inches

136
272
3108
4144
5180
10360

b. Describe the rule for converting yards to inches.
c. How many inches are in 15 yards?
d. Jacob says that he can find the number of inches in 15 yards by tripling the number of inches in 5 yards. Does his strategy work? Why or why not?
e. A blue rope in Garret’s camping backpack is 6 yards long. The blue rope is 3 times as long as a red rope. A yellow rope is 2 feet 7 inches shorter than the red rope. What is the difference in length between the blue rope and the yellow rope?
Answer:

B.

To convert yards into inches

Multiply the number of yards x 36

c.

1 yard = 36 inches

15 yards = 15 x 36 = 540

Therefore, 15 yards = 540 inches.

d.

Yes, Jacob strategy is right.

15 yards can be shown as 5 yards x 3

1 yard = 36 inches

15 yards = 540 inches

5 yards tripling by 3 =

5 yards = 5 x 36 = 180

5 yards = 180 inches

180 inches x 3 = 540

e.

Given, the length of blue rope = 6 yards long

6 yards = 18 feet

Also given, the blue rope is 3 times as long as a red rope

so, length of red rope = 2 yards = 6 feet

A yellow rope is 2 feet 7 inches shorter than red rope

So, 6 feet – 2 feet 7 inches

= 3 feet 5 inches

Now,

18 feet – 3 feet 5 inches = 14 feet 7 inches.

 

Therefore, the length difference between the blue rope and the yellow rope is 14 feet 7 inches.

Eureka Math Grade 4 Module 7 Lesson 18 Answer Key

Engage NY Eureka Math 4th Grade Module 7 Lesson 18 Answer Key

Eureka Math Grade 4 Module 7 Lesson 18 Reflection Answer Key

Question 1.
Why do you think vocabulary was such an important part of fourth-grade math? How does vocabulary help you in math?
Answer:

Yes, Vocabulary is important in mathematics.

Vocabulary helps in understanding and communication. It helps to solve complex and real problems.

Question 2.
Which vocabulary terms do you know well, and which would you like to improve upon?
Answer:

I came across several vocabulary words like Area, data, absolute value, ratio etc…. I would like improve more on vocabulary terms by practicing.

Eureka Math Grade 4 Module 7 Lesson 17 Answer Key

Engage NY Eureka Math 4th Grade Module 7 Lesson 17 Answer Key

Eureka Math Grade 4 Module 7 Lesson 17 Reflection Answer Key

Question 1.
What are you able to do now in math that you were not able to do at the beginning of Grade 4?
Answer:

I am able to solve some critical problems related to areas and calculations which I am not able to do before

Question 2.
Which activities would you like to practice this summer in order to keep fluent or become more fluent?
Answer:

The activities I would like to practice are reading some books, I think they  will keep me more productive and useful for my studies too

Question 3.
What type of practice would help you build your fluency with these concepts?
Answer:

I think practicing some more critical problems and reasoning will help me to build fluency.

Eureka Math Grade 4 Module 7 Lesson 17 Homework Answer Key

Question 1.
Decimal Fraction Review: Plot and label each point on the number line below, and complete the chart. Only solve the portion above the dotted line.
Eureka Math Grade 4 Module 7 Lesson 17 Homework Answer Key 1

PointUnit FormDecimal FormMixed Number (ones and fraction form)

How much more to get to the next whole number?

A2 ones and 9 tenths
B4.44\(\frac{4}{10}\)
C\(\frac{2}{10}\) or 0.2

Answer:

 

Question 2.
Complete the chart. Create your own problem for B, and plot the point.
Eureka Math Grade 4 Module 7 Lesson 17 Homework Answer Key 2


Point

Unit FormDecimal FormMixed Number (ones and fraction form)

How much more to get to the next whole number?

A2 ones and 9 tenths2.92 9/10 1/10
B3 ones and 4 tenths3.43 8/102/10

Answer:

Question 3.
Complete the chart. The first one has been done for you. Only solve the top portion above the dotted line.

Decimal

Mixed NumberTenths

Hundredths

3.23\(\frac{2}{10}\)32 tenths    or \(\frac{32}{10}\)320 hundredths    or \(\frac{320}{100}\)
8.6 

 

11.7 

 

4.8

Answer:

Question 4.
Complete the chart. Create your own problem in the last row.

Decimal

Mixed NumberTenths

Hundredths

3.2
8.6 

 

11.7 

 

Answer:

 

Eureka Math Grade 4 Module 7 Lesson 16 Answer Key

Engage NY Eureka Math 4th Grade Module 7 Lesson 16 Answer Key

Eureka Math Grade 4 Module 7 Lesson 16 Problem Set Answer Key

Work with your partner to create each floor plan on a separate piece of paper, as described below.
You should use a protractor and a ruler to create each floor plan and be sure each rectangle you create has two sets of parallel lines and four right angles.
Be sure to label each part of your model with the correct measurement.
Question 1.
The bedroom in Samantha’s dollhouse is a rectangle 26 centimetres long and 15 centimetres wide. It has a rectangular bed that is 9 centimetres long and 6 centimetres wide. The two dressers in the room are each 2 centimetres wide. One measures 7 centimetres long, and the other measures 4 centimetres long. Create a floor plan of the bedroom containing the bed and dressers. Find the area of the open floor space in the bedroom after the furniture is in place.
Answer:

Total area = length x width

= 26 x 15

= 390 sq. cm.

Bedroom + dresser + dresser =

54 + 14 +14 = 76 sq. cm.

Now, Room furniture =

390 – 76 = 314 sq. cm.

Therefore, The area of the open floor space in the bedroom after furniture is placed = 314 sq. cm.

Question 2.
A model of a rectangular pool is 15 centimeters long and 10 centimeters wide. The walkway around the pool is 5 centimeters wider than the pool on each of the four sides. In one section of the walkway, there is a flowerbed that is 3 centimeters by 5 centimeters. Create a diagram of the pool area with the surrounding walkway and flowerbed. Find the area of the open walkway around the pool.
Answer:

Total area = 25 x 20 = 500 sq. cm

Pool + flower bed =

150 + 15 = 165 sq. cm.

Total area = 500 – 165 = 335 sq. cm.

Therefore, The area of the open walkway around the pool = 335 sq. cm.

 

Eureka Math Grade 4 Module 7 Lesson 16 Reflection Answer Key

In the table below are skills that you learned in Grade 4 and that you used to complete today’s lesson. These skills were originally introduced in earlier grades, and you will continue to work on them as you go on to later grades. Choose three topics from the chart, and explain how you think you might build on and use them in Grade 5.

Multiply 2-digit by
2-digit numbers
Use the area formula to
find the area of
composite figures
Create composite figures from a set of specifications
Subtract multi-digit numbersAdd multi-digit numbersSolve multi-step word problems
Construct parallel and perpendicular linesMeasure and construct
90° angles
Measure in centimeters

Eureka Math Grade 4 Module 7 Lesson 16 Homework Answer Key

For homework, complete the top portion of each page. This will become an answer key for you to refer to when completing the bottom portion as a mini-personal white board activity during the summer.

Use a ruler and protractor to create and shade a figure according to the directions. Then, find the area of the unshaded part of the figure.
Question 1.
Draw a rectangle that is 18 cm long and 6 cm wide. Inside the rectangle, draw a smaller rectangle that is 8 cm long and 4 cm wide. Inside the smaller rectangle, draw a square that has a side length of 3 cm. Shade in the smaller rectangle, but leave the square unshaded. Find the area of the unshaded space.
Answer:

The area of unshaded part =

( 4 x 8 ) – ( 3 x 3 )

32 – 9

= 23 sq. cm

Therefore, the area of unshaded part = 23 sq. cm.

Question 2.
Emanuel’s science project display board is 42 inches long and 48 inches wide. He put a 6-inch border around the edge inside the board and placed a title in the center of the board that is 22 inches long and 6 inches wide. How many square inches of open space does Emanuel have left on his board?
Answer:

The square inches of open space Emanuel have left on his board.

(42 x 48)-{(6 x 42)+(6 x 42)+(6 x 32 )+( 6 x 32 ) + (6 x 22)}

= 2016 – { 252 + 252 + 216 + 216+ 132 }

= 2016 – 1068

= 948 sq. inches.

Challenge: Replace the given dimensions with different measurements, and solve again.