Eureka Math

Teachers and students can find this Eureka Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Eureka Math Answer Key for Grade 3 aids teachers to differentiate instruction, building and reinforcing foundational mathematics skills that alter from the classroom to real life. With the help of Eureka’s primary school Grade 3 Answer Key, you can think deeply regarding what you are learning, and you will really learn math easily just like that.

Engage NY Eureka Math 3rd Grade Module 3 Lesson 3 Answer Key

Teachers and students can find this Eureka Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Eureka Math Answer Key for Grade 3 aids teachers to differentiate instruction, building and reinforcing foundational mathematics skills that alter from the classroom to real life. With the help of Eureka’s primary school Grade 3 Answer Key, you can think deeply regarding what you are learning, and you will really learn math easily just like that.

Eureka Math Grade 3 Module 3 Lesson 3 Problem Set Answer Key

Question 1.
Each equation contains a letter representing the unknown. Find the value of the unknowns, and then write the letters that match the answers to solve the riddle.

Answer:
e = 20, i = 1/ 6, s = 4, n = 10, k = 6, a = 2.6, l = 7, c = 3, t = 0.7, b = 2, h = 5.

Explanation:
In the above-given question,
given that,
The equation contains the letter representing unknown.
5 x 4 = e , e = 20.
24/ i = 4, i = 4/ 24 = 1/6.
32 = s x 8, s = 32/ 8, s = 4.
8 = 80 / n, n = 10.
8 = a / 3, a = 2.6.
21 / 3 = l, l = 7.
21 = c x 7, c = 3.
t / 10 = 7, t = 0.7.
24/b = 12, b = 24/ 12, b = 2.
35 = 7 x h, h = 5.

Which tables do you NOT have to learn?

Answer:
The tables not have to learn is 10, 20, and 70.

Explanation:
In the above-given question,
given that,
The tables are 9, 6, 3, 5, 70, 20, 10, 24, 2, 7, and 4.
out of all the tables 10 and 20 are very easy.
so we need not to learn.

Question 2.
Lonna buys 3 t-shirts for $8 each.
a. What is the total amount Lonna spends on 3 t-shirts? Use the letter m to represent the total amount of money Lonna spends, and then solve the problem.

Answer:
The total amount of money Lonna spends = 24$.

Explanation:
In the above-given question,
given that,
Lonna buys 3 t-shirts for $8 each.
m x 3 = $8.
m = 8 x 3.
m = $24.
so the total amount of money Lonna spends = $24.

b. If Lonna hands the cashier 3 ten dollar bills, how much change will she receive? Use the letter c in an equation to represent the change, and then find the value of c.

Answer:
The change she received = $6.

Explanation:
In the above-given question,
given that,
Lonna hands the cashier 3 ten dollar bills.
c x 30 = 24.
c = 30 – 24.
c = $6.
so the change Lonna received = $6.

Question 3.
Miss Potts used a total of 28 cups of flour to bake some bread. She used 4 cups of flour for each loaf of bread. How many loaves of bread did she bake? Represent the problem using multiplication and division sentences and a letter for the unknown. Then, solve the problem.
__7___ × ___4__ = __28____
__28___ ÷ __4___ = ___7___

Answer:
The number of loaves of bread did she bake = 7.

Explanation:
In the above-given question,
given that,
Miss potts used a total of 28 cups of flour to bake some bread.
she used 4 cups of flour for each loaf of bread.
7 x 4 = 28.
28 / 4 = 7.
so the number of loaves of bread did she bake = 7.

Question 4.
At a table tennis tournament, two games went on for a total of 32 minutes. One game took 12 minutes longer than the other. How long did it take to complete each game? Use letters to represent the unknowns. Solve the problem.

Answer:
The other game takes to complete = 10 minutes.

Explanation:
In the above-given question,
given that,
At a table tennis tournament, two games went on for a total of 32 minutes.
one game took 12 minutes longer than the other.
32 + t = 12.
t = 32 – 12.
t = 20.
so the other game takes to complete = 10 minutes.

Eureka Math Grade 3 Module 3 Lesson 3 Exit Ticket Answer Key

Find the value of the unknown in Problems 1 – 4.

Question 1.
z = 5 × 9
z = ___45___

Answer:
z = 45.

Explanation:
In the above-given question,
given that,
the equation z = 5 x 9.
z = 45.

Question 2.
30 ÷ 6 = v
v = ___5___

Answer:
v = 5.

Explanation:
In the above-given question,
given that,
the equation 30/ 6 = v.
v = 5.

Question 3.
8 × w = 24
w = ____3__

Answer:
w = 3.

Explanation:
In the above-given question,
given that,
the equation 8 x w = 24.
w = 24/8.
w = 3.

Question 4.
y ÷ 4 = 7
y = __1.75____

Answer:
y = 1.75.

Explanation:
In the above-given question,
given that,
y / 4 = 7.
y = 7 / 4.
y = 1.75.

Question 5.
Mr. Strand waters his rose bushes for a total of 15 minutes. He waters each rose bush for 3 minutes. How many rose bushes does Mr. Strand water? Represent the problem using multiplication and division sentences and a letter for the unknown. Then, solve the problem.
__3___ × __5___ = __15___
__15___ ÷ __3___ = ___5__

Answer:
The number of rose bushes Mr. strand water = 15.

Explanation:
In the above-given question,
given that,
Mr. Strand waters his rose bushes for a total of 15 minutes.
He waters each rose bush for 3 minutes.
3 x 5 = 15.
15 / 3 = 5.
so the number of rose bushes Mr. Strand water = 15.

Eureka Math Grade 3 Module 3 Lesson 3 Homework Answer Key

Question 1.
a. Complete the pattern.

Answer:
The missing numbers in the pattern are 40, 50, 70, 80, and 100.

Explanation:
In the above-given question,
given that,
the pattern with numbers.
the missing numbers are 40, 50, 70, 80, and 100.

b. Find the value of the unknown.

10 × 2 = d   d = __20___
3 × 10 = e   e = __30___
f = 4 × 10   f = ___40__
p = 5 × 10  p = __50___
10 × 6 = w  w = ___60__
10 × 7 = n  n = __70___
g = 8 × 10  g = __80___

Answer:
d = 20.
e = 30.
f = 40.
p = 50.
w = 60.
n = 70.
g = 80.

Explanation:
In the above-given question,
given that,
the equations 10 x 2 = d, d = 20.
3 x 10 = e, e = 30.
f = 4 x 10, f = 40.
p = 5 x 10, p = 50.
10 x 6 = w, w = 60.
10 x 7 = n, n = 70.
g = 8 x 10, g = 80.

Question 2.
Each equation contains a letter representing the unknown. Find the value of the unknown.

Answer:
n = 4.
a = 4.
p = 5.
c = 3.
d = 6.
h = 1.4.
f = 18.
y = 8.

Explanation:
In the above-given question,
given that,
the equations 8 / 2 = n, n = 4.
3 x a = 12, a = 12 / 3, a = 4.
p x 8 = 40, p = 40 / 8, p = 5.
18 / 6 = c, c = 3.
d x 4 = 24, d = 24 / 4, d = 6.
h / 7 = 5, h = 1.4.
6 x 3 = f, f = 18.
32 / y = 4. y = 8.

Question 3.
Pedro buys 4 books at the fair for $7 each.
a. What is the total amount Pedro spends on 4 books? Use the letter b to represent the total amount Pedro spends, and then solve the problem.

Answer:
The total amount Pedro spends on 4 books = $28.

Explanation:
In the above-given question,
given that,
Pedro buys 4 books at the fair for $7 each.
b x 4 = 7.
b = 7 x 4.
b = $28.
so the total amount Pedro spends on 4 books = $28.

b. Pedro hands the cashier 3 ten dollar bills. How much change will he receive? Write an equation to solve. Use the letter c to represent the unknown.

Answer:
The change Pedro receives = $2.

Explanation:
In the above-given question,
given that,
Pedro hands the cashier 3 ten dollar bills.
c + 30 = 28.
c = 30 – 28.
c = $2.

Question 4.
On field day, the first-grade dash is 25 meters long. The third-grade dash is twice the distance of the first-grade dash. How long is the third-grade dash? Use a letter to represent the unknown and solve.

Answer:
The third-grade dash = 75 meters long.

Explanation:
In the above-given question,
given that,
On field day, the first-grade dash is 25 meters long.
The third-grade dash is twice the distance of the first-grade dash.
g = 25 + 50.
g = 75.
so the third-grade dash = 75 meters long.

Students of Grade 3 Module 3 can get a strong foundation on mathematics concepts by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka’s Grade 3 Textbook.

Engage NY Eureka Math 3rd Grade Module 3 Lesson 6 Answer Key

So teachers and students can find this Eureka Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Eureka Math Answer Key for Grade 3 aids teachers to differentiate instruction, building and reinforcing foundational mathematics skills that alter from the classroom to real life. With the help of Eureka’s primary school Grade 3 Answer Key, you can think deeply regarding what you are learning, and you will really learn math easily just like that.

Eureka Math Grade 3 Module 3 Lesson 6 Pattern Sheet Answer Key

Multiply

Answer:
6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 6 x 9 = 54, 6 x 10 = 60, 6 x 5 = 30, 6 x 6 = 36, 6 x 5 = 30, 6 x 7 = 35, 6 x 5 = 30, 6 x 8 = 40, 6 x 5 = 30, 6 x 9 = 54, 6 x 5 = 30, 6 x 10 = 60, 6 x 6 = 36, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 6 = 36, 6 x 8 = 48, 6 x 6 = 36, 6 x 9 = 54, 6 x 6 = 36, 6 x 7 = 42, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 6 x 7 = 42, 6 x 9 = 54, 6 x 7 = 42, 6 x 8 = 48, 6 x 6 = 36, 6 x 8 = 48, 6 x 7 = 42, 6 x 8 = 48, 6 x 9 = 54, 6 x 9 = 54, 6 x 6 = 36, 6 x 9 = 54, 6 x 8 = 48, 6 x 6 = 36, 6 x 9 = 54, 6 x 7 = 42, 6 x 9 = 54, 6 x 6 = 36, 6 x 8 = 48, 6 x 9 = 54, 6 x 7 = 42, 6 x 6 = 36, 6 x 8 = 48.

Explanation:
In the above-given question,
given that,
the table of 6.
6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 6 x 9 = 54, 6 x 10 = 60, 6 x 5 = 30, 6 x 6 = 36, 6 x 5 = 30, 6 x 7 = 35, 6 x 5 = 30, 6 x 8 = 40, 6 x 5 = 30, 6 x 9 = 54, 6 x 5 = 30, 6 x 10 = 60, 6 x 6 = 36, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 6 = 36, 6 x 8 = 48, 6 x 6 = 36, 6 x 9 = 54, 6 x 6 = 36, 6 x 7 = 42, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 6 x 7 = 42, 6 x 9 = 54, 6 x 7 = 42, 6 x 8 = 48, 6 x 6 = 36, 6 x 8 = 48, 6 x 7 = 42, 6 x 8 = 48, 6 x 9 = 54, 6 x 9 = 54, 6 x 6 = 36, 6 x 9 = 54, 6 x 8 = 48, 6 x 6 = 36, 6 x 9 = 54, 6 x 7 = 42, 6 x 9 = 54, 6 x 6 = 36, 6 x 8 = 48, 6 x 9 = 54, 6 x 7 = 42, 6 x 6 = 36, 6 x 8 = 48.

Eureka Math Grade 3 Module 3 Lesson 6 Problem Set Answer Key

Question 1.
Label the tape diagrams. Then, fill in the blanks below to make the statements true.
a. 6 × 6 = __36___

(6 × 6) = (5 + 1) × 6
= (5 × 6) + (1 × 6)
=    30    + __6____
= ____6__

Answer:
5 x 6 = 30.
1 x 6 = 6.
30 + 6 = 36.

Explanation:
In the above-given question,
given that,
6 x 6 = (5 + 1) x 6.
(5 x 6) + (1 x 6).
30 + 6.
36.

b. 7 × 6 = __42___

(7 × 6) = (5 + 2) × 6
= (5 × 6) + (2 × 6)
=   30     + __12____
= ____42__

Answer:
5 x 6 = 30.
2 x 6 = 12.
30 + 12 = 42.

Explanation:
In the above-given question,
given that,
7 x 6 = (5 + 2) x 6.
(5 x 6) + (2 x 6).
30 + 12.
42.

c. 8 × 6 = ___48__

8 × 6 = (5 + ___3__ ) × 6
= (5 × 6) + ( __3__ × 6)
=   30    + __18____
= __48____

Answer:
5 x 6 = 30.
3 x 6 = 18.
30 + 18 = 48.

Explanation:
In the above-given question,
given that,
8 x 6 = (5 + 3) x 6.
(5 x 6) + (3 x 6).
30 + 18.
48.

d. 9 × 6 = __54___

9 × 6 = (5 + __4___ ) × 6
= (5 × 6) + ( _4___ × 6)
=   30    + __24____
= __54____

Answer:
5 x 6 = 30.
4 x 6 = 24.
30 + 24 = 54.

Explanation:
In the above-given question,
given that,
9 x 6 = (5 + 4) x 6.
(5 x 6) + (4 x 6).
30 + 24.
54.

Question 2.
Break apart 54 to solve 54 ÷ 6.

54 ÷ 6 = (30 ÷ 6) + ( __24________ ÷ 6)
= 5 + ______4______
= ____9_______

Answer:
54 / 6 = 9.

Explanation:
In the above-given question,
given that,
54 / 6 is divided into two parts.
30 / 6 and 24 / 6.
30 / 6 = 5 and 24 / 6 = 4.
5 + 4 = 9.

Question 3.
Break apart 49 to solve 49 ÷ 7.

49 ÷ 7 = (35 ÷ 7) + ( ___14_______ ÷ 7)
= 5 + _______2_____
= _____7______

Answer:
49 / 7 = 7.

Explanation:
In the above-given question,
given that,
49 / 7 is divided into two parts.
35 / 7 and 14 / 7.
35 / 7 = 5 and 14 / 7 = 2.
5 + 2 = 7.

Question 4.
Robert says that he can solve 6 × 8 by thinking of it as (5 × 8) + 8. Is he right? Draw a picture to help explain your answer.

Answer:
Yes, he was right.

Explanation:
In the above-given question,
given that,
Robert says that he can solve 6 x 8 by thinking of it as (5 x 8) + 8.
6 x 8 = 48.
(5 x 8) + 8 = 40 + 8 = 48.
so he was correct.

Question 5.
Kelly solves 42 ÷ 7 by using a number bond to break apart 42 into two parts. Show what her work might look like below.

Answer:
42 / 7 = 6.

Explanation:
In the above-given question,
given that,
42 / 7 is divided into two parts.
28 / 7 and 14 / 7.
28 / 7 = 4 and 14 / 7 = 2.
4 + 2 = 6.

Eureka Math Grade 3 Module 3 Lesson 6 Exit Ticket Answer Key

Question 1.
A parking lot has space for 48 cars. Six cars can park in 1 row. Break apart 48 to find how many rows there are in the parking lot.

Answer:
48 / 6 = 8.

Explanation:
In the above-given question,
given that,
48 / 6 is divided into two parts.
30 / 6 and 18 / 6.
30 / 6 = 5 and 18 / 6 = 3.
5 + 3 = 8.

Question 2.
Malia solves 6 × 7 using (5 × 7) + 7. Leonidas solves 6 × 7 using (6 × 5) + (6 × 2). Who is correct? Draw a picture to help explain your answer.

Answer:
Yes, both of them are correct.

Explanation:
In the above-given question,
given that,
6 x 7 = 42.
(5 x 7) + 7 = 35 + 7 = 42.
(6 x 5) + (6 x 2) = 30 + 12 = 42.

Eureka Math Grade 3 Module 3 Lesson 6 Homework Answer Key

Question 1.
Label the tape diagrams. Then, fill in the blanks below to make the statements true.
a. 6 × 7 = __42___

(6 × 7) = (5 + 1) × 7
= (5 × 7) + (1 × 7)
=   35     + ___7___
= ___42___

Answer:
5 x 7 = 35.
1 x 7 = 7.
35 + 7 = 42.

Explanation:
In the above-given question,
given that,
6 x 7 = (5 + 1) x 7.
(5 x 7) + (1 x 7).
35 + 7.
42.

b. 7 × 7 = __49___

(7 × 7) = (5 + 2) × 7
= (5 × 7) + (2 × 7)
=   35     + __14___
= ___49___

Answer:
5 x 7 = 35.
2 x 7 = 14.
35 + 14 = 49.

Explanation:
In the above-given question,
given that,
6 x 7 = (5 + 2) x 7.
(5 x 7) + (2 x 7).
35 + 14.
49.

c. 8 × 7 = __56___

8 × 7 = (5 + ___3__ ) × 7
= (5 × 7) + ( __3__ × 7)
=   35     + ___21___
= __56____

Answer:
5 x 7 = 35.
3 x 7 = 21.
35 + 21 = 56.

Explanation:
In the above-given question,
given that,
8 x 7 = (5 + 3) x 7.
(5 x 7) + (3 x 7).
35 + 21.
56.

d. 9 × 7 = __63___

9 × 7 = (5 + __4___ ) × 7
= (5 × 7) + ( __4__ × 7)
=   35    + ___28___
= ___63___

Answer:
5 x 7 = 35.
4 x 7 = 28.
35 + 28 = 63.

Explanation:
In the above-given question,
given that,
9 x 7 = (5 + 4) x 7.
(5 x 7) + (4 x 7).
35 + 28.
63.

Question 2.
Break apart 54 to solve 54 ÷ 6.

54 ÷ 6 = (30 ÷ 6) + ( ____24_______ ÷ 6)
= 5 + _______4_____
= _____9______

Answer:
54 / 6 = 9.

Explanation:
In the above-given question,
given that,
54 / 6 is divided into two parts.
30 / 6 and 24 / 6.
30 / 6 = 5 and 24 / 6 = 4.
5 + 4 = 9.

Question 3.
Break apart 56 to solve 56 ÷ 7

56 ÷ 7 = ( __35___ ÷ ___7__ ) + ( __21___ ÷ ___7__ )
= 5 + ____3____
= ____8______

Answer:
56 / 7 = 8.

Explanation:
In the above-given question,
given that,
56 / 7 is divided into two parts.
35 / 7 and 21 / 7.
35 / 7 = 5 and 21 / 7 = 3.
5 + 3 = 8.

Question 4.
Forty-two third grade students sit in 6 equal rows in the auditorium. How many students sit in each row? Show your thinking.

Answer:
The number of students sits in each row = 7.

Explanation:
In the above-given question,
given that,
42 third-grade students sit in 6 equal rows in the auditorium.
42 / 6 = 7.
7 x 6 = 42.

Question 5.
Ronaldo solves 7 × 6 by thinking of it as (5 × 7) + 7. Is he correct? Explain Ronaldo’s strategy.

Answer:
Yes, he was correct.

Explanation:
In the above-given question,
given that,
Ronaldo solves 7 x 6 = 42.
(5 x 7) + 7 = 42.
so he was correct.

Teachers and students can find this Eureka Book Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Learning activities are the best option to educate elementary school kids and make them understand the basic mathematical concepts like addition, subtraction, multiplication, division, etc. Grade 3 elementary school students can find these fun-learning exercises for all math concepts through the Eureka Book.

Engage NY Eureka Math 3rd Grade Module 3 Lesson 7 Answer Key

Students of Grade 3 can get a strong foundation by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka Grade 3 Book.

Eureka Math Grade 3 Module 3 Lesson 7 Pattern Sheet Answer Key

Multiply

Answer:
7 x 1 = 7, 7 x 2 = 14, 7 x 3 = 21, 7 x 4 = 28, 7 x 5 = 35, 7 x 1 = 7, 7 x 2 = 14, 7 x 1 = 7, 7 x 3 = 21, 7 x 1 = 7, 7 x 4 = 28, 7 x 1 = 7, 7 x 5 = 35, 7 x 1 = 7, 7 x 2 = 14, 7 x 3 = 21, 7 x 2 = 14, 7 x 4 = 28, 7 x 5 = 35, 7 x 2 = 14, 7 x 2 = 14, 7 x 1 = 7, 7 x 2 = 14, 7 x 3 = 21, 7 x 1 = 7, 7 x 3 = 21, 7 x 2 = 14, 7 x 3 = 21, 7 x 4 = 28, 7 x 3 = 21, 7 x 5 = 35, 7 x 3 = 21, 7 x 4 = 28, 7 x 1 = 7, 7 x 4 = 28, 7 x 2 = 14, 7 x 4 = 28, 7 x 3 = 21, 7 x 4 = 28, 7 x 5 = 35, 7 x 4 = 28, 7 x 5 = 35, 7 x 1 = 7, 7 x 5 = 35, 7 x 2 = 14, 7 x 5 = 35, 7 x 3 = 21, 7 x 5 = 35, 7 x 4 = 28, 7 x 2 = 14, 7 x 4 = 28, 7 x 3 = 21, 7 x 5 = 35, 7 x 3 = 21, 7 x 2 = 14, 7 x 4 = 28, 7 x 3 = 21, 7 x 5 = 35, 7 x 2 = 14, 7 x 4 = 28.

Explanation:
In the above-given question,
given that,
the table of 7 and multiply.
7 x 1 = 7, 7 x 2 = 14, 7 x 3 = 21, 7 x 4 = 28, 7 x 5 = 35, 7 x 1 = 7, 7 x 2 = 14, 7 x 1 = 7, 7 x 3 = 21, 7 x 1 = 7, 7 x 4 = 28, 7 x 1 = 7, 7 x 5 = 35, 7 x 1 = 7, 7 x 2 = 14, 7 x 3 = 21, 7 x 2 = 14, 7 x 4 = 28, 7 x 5 = 35, 7 x 2 = 14, 7 x 2 = 14, 7 x 1 = 7, 7 x 2 = 14, 7 x 3 = 21, 7 x 1 = 7, 7 x 3 = 21, 7 x 2 = 14, 7 x 3 = 21, 7 x 4 = 28, 7 x 3 = 21, 7 x 5 = 35, 7 x 3 = 21, 7 x 4 = 28, 7 x 1 = 7, 7 x 4 = 28, 7 x 2 = 14, 7 x 4 = 28, 7 x 3 = 21, 7 x 4 = 28, 7 x 5 = 35, 7 x 4 = 28, 7 x 5 = 35, 7 x 1 = 7, 7 x 5 = 35, 7 x 2 = 14, 7 x 5 = 35, 7 x 3 = 21, 7 x 5 = 35, 7 x 4 = 28, 7 x 2 = 14, 7 x 4 = 28, 7 x 3 = 21, 7 x 5 = 35, 7 x 3 = 21, 7 x 2 = 14, 7 x 4 = 28, 7 x 3 = 21, 7 x 5 = 35, 7 x 2 = 14, 7 x 4 = 28.

Eureka Math Grade 3 Module 3 Lesson 7 Problem Set Answer Key

Question 1.
Match the words to the correct equation.

Answer:
n x 7 = 21.
n x 6 = 30.
6 x 7 = n.
7 x n = 42,
36 / n = 6.
63 / n = 9.

Explanation:
In the above-given question,
given that,
the equations of the products and divisions.
n x 7 = 21.
n x 6 = 30.
6 x 7 = n.
7 x n = 42,
36 / n = 6.
63 / n = 9.

Question 2.
Write an equation to represent the tape diagram below, and solve for the unknown.

Equation: __48__/___k___=_8._____

Answer:
48 / k = 8.
k = 6.

Explanation:
In the above-given question,
given that,
There are 6 eights.
6 x 8 = 48.
48 / k = 8.
k = 6.

Question 3.
Model each problem with a drawing. Then, write an equation using a letter to represent the unknown, and solve for the unknown.

a. Each student gets 3 pencils. There are a total of 21 pencils. How many students are there?

Answer:
The number of students = 7.

Explanation:
In the above-given question,
given that,
Each student gets 3 pencils.
There are a total of 21 pencils.
21 x p = 3.
21 / 3 = p.
so p = 7.

b. Henry spends 24 minutes practicing 6 different basketball drills. He spends the same amount of time on each drill. How much time does Henry spend on each drill?

Answer:
Henry spends on each drill = 4 minutes.

Explanation:
In the above-given question,
given that,
Henry spends 24 minutes practicing 6 different basketball drills.
He spends the same amount of time on each drill.
24 / m = 6.
m = 24 / 6 .
m = 4 minutes.

c. Jessica has 8 pieces of yarn for a project. Each piece of yarn is 6 centimeters long. What is the total length of the yarn?

Answer:
The total length of the yarn = 48 centimeters.

Explanation:
In the above-given question,
given that,
Jessica has 8 pieces of yarn for a project.
Each piece of yarn is 6 centimeters long.
8 x y = 6.
y = 6 x 8.
y = 48.

d. Ginny measures 6 milliliters of water into each beaker. She pours a total of 54 milliliters. How many beakers does Ginny use?

Answer:
The number of beakers does Ginny uses = 9.

Explanation:
In the above-given question,
given that,
Ginny measures 6 millimeters of water into each beaker.
she pours a total of 54 milliliters.
6 / b = 54.
b = 54 / 6.
b = 9.

Eureka Math Grade 3 Module 3 Lesson 7 Exit Ticket Answer Key

Model each problem with a drawing. Then, write an equation using a letter to represent the unknown, and solve for the unknown.

Question 1.
Three boys and three girls each buy 7 bookmarks. How many bookmarks do they buy all together?

Answer:
The total number of bookmarks = 42.

Explanation:
In the above-given question,
given that,
Three boys and three girls each buy 7 bookmarks.
3 + 3 = 6.
6 x b = 7.
b = 7 x 6.
b = 42.

Question 2.
Seven friends equally share the cost of a $56 meal. How much does each person pay?

Answer:
The number of dollars each person pays = $8.

Explanation:
In the above-given question,
given that,
seven friends equally share the cost of a $56 meal.
7 / p = 56.
p = 56 / 7.
p = 8.

Eureka Math Grade 3 Module 3 Lesson 7 Homework Answer Key

Question 1.
Match the words on the arrow to the correct equation on the target.

Answer:
n x 7 = 21 = A number times 7 equals 21.
7 x n = 42 = 7 times a number equals 42.
63 / n = 9 = 63 divided by a number equals 9.
36 / n = 6 = 36 divided by a number equals 6.

Explanation:
In the above-given question,
given that,
the equations that multiply and divide.
n x 7 = 21 = A number times 7 equals 21.
7 x n = 42 = 7 times a number equals 42.
63 / n = 9 = 63 divided by a number equals 9.
36 / n = 6 = 36 divided by a number equals 6.

Question 2.
Ari sells 6 boxes of pens at the school store.
a. Each box of pens sells for $7. Draw a tape diagram, and label the total amount of money he makes as m. Write an equation, and solve for m.

Answer:
The total amount of money = 42.

Explanation:
In the above-given question,
given that,
Ari sells 6 boxes of pens at the school store.
Each box of pens sells for $7.
6 x m = $7.
m = 6 x 7.
m = 42.

b. Each box contains 6 pens. Draw a tape diagram, and label the total number of pens as p. Write an equation, and solve for p.

Answer:
The total number of pens = 36.

Explanation:
In the above-given question,
given that,
Each box contains 6 pens.
6 x p = 6.
p = 6 x 6.
p = 36.

Question 3.
Mr. Lucas divides 28 students into 7 equal groups for a project. Draw a tape diagram, and label the number of students in each group as n. Write an equation, and solve for n.

Answer:
The number of students in each group = 4.

Explanation:
In the above-given question,
given that,
Mr. Lucas divides 28 students into 7 equal groups for a project.
28 / s = 7.
s = 28 / 7.
s = 4.

Students of Grade 3 can get a strong foundation by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka Grade 3 Book.

Engage NY Eureka Math 3rd Grade Module 3 Lesson 8 Answer Key

Teachers and students can find this Eureka Book Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Learning activities are the best option to educate elementary school kids and make them understand the basic mathematical concepts like addition, subtraction, multiplication, division, etc. Grade 3 elementary school students can find these fun-learning exercises for all math concepts through the Eureka Book.

Eureka Math -Grade 3 Module 3 Lesson 8 Pattern Sheet Answer Key

Multiply

Answer:
7 x 1 = 7, 7 x 2 = 14, 7 x 3 = 21, 7 x 4 = 28, 7 x 5 = 35, 7 x 6 = 42, 7 x 7 = 49, 7 x 8 = 56, 7 x 9 = 63, 7 x 10 = 70, 7 x 5 = 35, 7 x 6 = 42, 7 x 5 = 35, 7 x 7 = 49, 7 x 5 = 35, 7 x 8 = 56, 7 x 5 = 35, 7 x 9 = 63, 7 x 5 = 35, 7 x 10 = 70, 7 x 6 = 42, 7 x 5 = 35, 7 x 6 = 42, 7 x 7 = 49, 7 x 6 = 42, 7 x 8 = 56, 7 x 6 = 42, 7 x 9 = 63, 7 x 6 = 42, 7 x 7 = 49, 7 x 6 = 42, 7 x 7 = 49, 7 x 8 = 56, 7 x 7 = 49, 7 x 9 = 63, 7 x 7 = 49, 7 x 8 = 56, 7 x 6 = 42, 7 x 8 = 56, 7 x 7 = 49, 7 x 8 = 56, 7 x 9 = 63, 7 x 9 = 63, 7 x 6 = 42, 7 x 9 = 63, 7 x 7 = 49, 7 x 9 = 63, 7 x 8 = 56, 7 x 9 = 63, 7 x 8 = 56, 7 x 6 = 42, 7 x 9 = 63, 7 x 7 = 49, 7 x 9 = 63, 7 x 6 = 42, 7 x 8 = 56, 7 x 9 = 63, 7 x 7 = 49, 7 x 6 = 42, 7 x 8 = 56.

Explanation:
In the above-given question,
given that,
the table of 6 is given.
7 x 1 = 7, 7 x 2 = 14, 7 x 3 = 21, 7 x 4 = 28, 7 x 5 = 35, 7 x 6 = 42, 7 x 7 = 49, 7 x 8 = 56, 7 x 9 = 63, 7 x 10 = 70, 7 x 5 = 35, 7 x 6 = 42, 7 x 5 = 35, 7 x 7 = 49, 7 x 5 = 35, 7 x 8 = 56, 7 x 5 = 35, 7 x 9 = 63, 7 x 5 = 35, 7 x 10 = 70, 7 x 6 = 42, 7 x 5 = 35, 7 x 6 = 42, 7 x 7 = 49, 7 x 6 = 42, 7 x 8 = 56, 7 x 6 = 42, 7 x 9 = 63, 7 x 6 = 42, 7 x 7 = 49, 7 x 6 = 42, 7 x 7 = 49, 7 x 8 = 56, 7 x 7 = 49, 7 x 9 = 63, 7 x 7 = 49, 7 x 8 = 56, 7 x 6 = 42, 7 x 8 = 56, 7 x 7 = 49, 7 x 8 = 56, 7 x 9 = 63, 7 x 9 = 63, 7 x 6 = 42, 7 x 9 = 63, 7 x 7 = 49, 7 x 9 = 63, 7 x 8 = 56, 7 x 9 = 63, 7 x 8 = 56, 7 x 6 = 42, 7 x 9 = 63, 7 x 7 = 49, 7 x 9 = 63, 7 x 6 = 42, 7 x 8 = 56, 7 x 9 = 63, 7 x 7 = 49, 7 x 6 = 42, 7 x 8 = 56.

Eureka Math Grade 3 Module 3 Lesson 8 Problem Set Answer Key

Question 1.
Solve.
a. (12 – 4) + 6 = __14____

Answer:
(12 – 4) + 6 = 14.

Explanation:
In the above-given question,
given that,
(12 – 4) = 8.
8 + 6 = 14.

b. 12 – (4 + 6) = ___2___

Answer:
12 – (4 + 6) = 2.

Explanation:
In the above-given question,
given that,
4 + 6 = 10.
12 – 10 = 2.

c. __5____ = 15 – (7 + 3)

Answer:
15 – (7 + 3) = 5.

Explanation:
In the above-given question,
given that,
7 + 3 = 10.
15 – 10 = 5.

d. __11____ = (15 – 7) + 3

Answer:
(15 – 7) + 3 = 11.

Explanation:
In the above-given question,
given that,
15 – 7 = 8.
8 + 3 = 11.

e. ___30___ = (3 + 2) × 6

Answer:
(3 + 2 ) x 6 = 30.

Explanation:
In the above-given question,
given that,
3 + 2 = 5.
5 x 6 = 30.

f. __15____ = 3 + (2 × 6)

Answer:
3 + ( 2  x 6 ) = 15.

Explanation:
In the above-given question,
given that,
2 x 6 = 12.
3 + 12 = 15.

g. 4 × (7 – 2) = __20____

Answer:
4 x ( 7  – 2 ) = 20.

Explanation:
In the above-given question,
given that,
7 – 2 = 5.
5 x 4 = 20.

h. (4 × 7) – 2 = __26____

Answer:
(4 x 7) – 2 = 26.
Explanation:
In the above-given question,
given that,
4 x 7 = 28.
28 – 2 = 26.

i. ___10___ = (12 ÷ 2) + 4

Answer:
4 + ( 12  / 2 ) = 10.

Explanation:
In the above-given question,
given that,
12 / 2 = 6.
4 + 6 = 10.

j. __2____ = 12 ÷ (2 + 4)

Answer:
12 / ( 2  + 4 ) = 2.

Explanation:
In the above-given question,
given that,
12 / 6 = 2.
2 + 4 = 6.

k. 9 + (15 ÷ 3) = __14____

Answer:
9 + ( 15  / 3 ) = 14.

Explanation:
In the above-given question,
given that,
15 / 3 = 5.
9 + 5 = 14.

l. (9 + 15) ÷ 3 = ___8___

Answer:
(9 + 15) / 3 = 8.

Explanation:
In the above-given question,
given that,
9 + 15 = 24.
24 / 3 = 8.

m. 60 ÷ (10 – 4) = __10____

Answer:
60 / (10 – 4) = 10.
Explanation:
In the above-given question,
given that,
10 – 4 = 6.
60 / 6 = 10.

n. (60 ÷ 10) – 4 = __2____

Answer:
(60 / 10) – 4 = 2.

Explanation:
In the above-given question,
given that,
(60 / 10) = 6.
6 – 4 = 2.

o. __37____ = 35 + (10 ÷ 5)

Answer:
35 + ( 10 / 5 ) = 37.

Explanation:
In the above-given question,
given that,
10 / 5 = 2.
35 + 2 = 37.

p. ___9___ = (35 + 10) ÷ 5

Answer:
(35 + 10) / 5 = 9.

Explanation:
In the above-given question,
given that,
35 + 10 = 45.
45 / 5 = 9.

Question 2.
Use parentheses to make the equations true.
Answer:

Question 3.
The teacher writes 24 ÷ 4 + 2 = __4 , __8__ on the board. Chad says it equals 8. Samir says it equals 4. Explain how placing the parentheses in the equation can make both answers true.

Answer:
Yes, both the answers are true.

Explanation:
In the above-given question,
given that,
The teacher writes 24 / 4 + 2 = 8 and 4 on the board.
24 / 4 = 6.
6 + 2 = 8.
4 + 2 = 6.
24 / 6 = 4.
so both answers are true.

Question 4.
Natasha solves the equation below by finding the sum of 5 and 12. Place the parentheses in the equation to show her thinking. Then, solve.
12 + 15 ÷ 3 = __17______

Answer:
12 + 15 / 3 = 17.

Explanation:
In the above-given question,
given that,
Natasha solves the equation below by finding the sum of 5 and 12.
15 / 3 = 5.
12 + 5 = 17.

Question 5.
Find two possible answers to the expression 7 + 3 × 2 by placing the parentheses in different places.

Answer:
The two possible answers are 20 and 13.

Explanation:
In the above-given question,
given that,
7 + 3 x 2.
7 + 3 = 10.
10 x 2 = 20.
3 x 2 = 6.
7 + 6 = 13.

Eureka Math Grade 3 Module 3 Lesson 8 Exit Ticket Answer Key

Question 1.
Use parentheses to make the equations true.
a. 24 = 32 – 14 + 6

Answer:
24 = (32 – 14) + 6.

Explanation:
In the above-given question,
given that,
24 = 32 – 14 + 6.
32 – 14 = 18.
18 + 6 = 24.

b. 12 = 32 – 14 + 6

Answer:
12 = 32 – (14 + 6).

Explanation:
In the above-given question,
given that,
12 = 32 – 14 + 6.
14 + 6 = 20.
32 – 20 = 12.

c. 2 + 8 × 7 = 70

Answer:
70 = 70.

Explanation:
In the above-given question,
given that,
2 + 8 x 7.
2 + 8 = 10.
10 x 7 = 70.

d. 2 + 8 × 7 = 58

Answer:
58 = 58.

Explanation:
In the above-given question,
given that,
2 + 8 x 7.
7 x 8 = 56.
56 + 2 = 58.

Question 2.
Marcos solves 24 ÷ 6 + 2 = ___6 and 3___. He says it equals 6. Iris says it equals 3. Show how the position of parentheses in the equation can make both answers true.

Answer:
Yes, both the answers are true.

Explanation:
In the above-given question,
given that,
Marcos solves 24 / 6 + 2.
24 / 6 = 4.
4 + 2 = 6.
6 + 2 = 8.
24 / 8 = 3.
so both answers are true.

Eureka Math Grade 3 Module 3 Lesson 8 Homework Answer Key

Question 1.
Solve.
a. 9 – (6 + 3) = __0____

Answer:
9 – ( 6 + 3) = 0.

Explanation:
In the above-given question,
given that,
6 + 3 = 9.
9 – 9 = 0.

b. (9 – 6) + 3 = __6____

Answer:
(9 – 6) + 3 = 6.

Explanation:
In the above-given question,
given that,
(9 – 6) = 3.
3 + 3 = 6.

c. __8___ = 14 – (4 + 2)

Answer:
14 – (4 + 2) = 8.

Explanation:
In the above-given question,
given that,
(4 + 2) = 6.
14 – 6 = 8.

d. ___12__ = (14 – 4) + 2

Answer:
(14 – 4) + 2 = 12.

Explanation:
In the above-given question,
given that,
(14 – 4) = 10.
10 + 2 = 12.

e. _42____ = (4 + 3) × 6

Answer:
(4 + 3) x 6 = 42.

Explanation:
In the above-given question,
given that,
(4 + 3) = 7.
7 x 6 = 42.

f. __22___ = 4 + (3 × 6)

Answer:
(3 x 6) + 4 = 22.

Explanation:
In the above-given question,
given that,
(3 x 6) = 18.
18 +  4 = 22.

g. (18 ÷ 3) + 6 = __12___

Answer:
(18 / 3) + 6 = 12.

Explanation:
In the above-given question,
given that,
(18 / 3) = 6.
6 + 6 = 12.

h. 18 ÷ (3 + 6)= __2___

Answer:
18 / (3 + 6) = 2.

Explanation:
In the above-given question,
given that,
(3 + 6) = 9.
18 / 9 = 2.

Question 2.
Use parentheses to make the equations true
a. 14 – 8 + 2 = 4

Answer:
14 – (8 + 2) = 4.
Explanation:
In the above-given question,
given that,
4 = 14 – 8 + 2.
8 + 2 = 10.
14 – 10 = 4.

b. 14 – 8 + 2 = 8

Answer:
8 = 8.

Explanation:
In the above-given question,
given that,
14 – 8 + 2 = 8.
14 – 8 = 6.
6 + 2 = 8.

c. 2 + 4 × 7 = 30

Answer:
30 = 30.

Explanation:
In the above given question,
given that,
30 = 2 + 4 x 7.
4 x 7 = 28.
28 + 2 = 30.

d. 2 + 4 × 7 = 42

Answer:
42 = 42.

Explanation:
In the above given question,
given that,
42 = 2 + 4 x 7.
2 + 4 = 6.
6 x 7 = 42.

e. 12 = 18 ÷ 3 × 2

Answer:
12 = 12.

Explanation:
In the above-given question,
given that,
12 = 18 / 3 x 2.
18 / 3 = 6.
6 x 2 = 12.

f. 3 = 18 ÷ 3 × 2

Answer:
3 = 3.

Explanation:
In the above-given question,
given that,
3 = 18 / 3 x 2.
3 x 2 = 6.
18 / 6 = 3.

g. 5 = 50 ÷ 5 × 2

Answer:
5 = 5.

Explanation:
In the above-given question,
given that,
5 = 50 / 5 x 2.
5 x 2 = 10.
50 / 10 = 5.

h. 20 = 50 ÷ 5 × 2

Answer:
20 = 20.

Explanation:
In the above-given question,
given that,
20 = 50 / 5 x 2.
50 / 5 = 10.
10 x 2 = 20.

Question 3.
Determine if the equation is true or false.

Answer:
a. true.
b. true.
c. false.
d. true.
e. false.

Explanation:
In the above-given question,
given that,
(15 – 3) / 2 = 6.
(10 – 7) x 6 = 18.
(35 – 7) / 4 = 7.
28 = 4 x (20 – 13).
2.8 = (22 – 8) / 5.

Question 4.
Jerome finds that (3 × 6) ÷ 2 and 18 ÷ 2 are equal. Explain why this is true.

Answer:
Yes, it is true.

Explanation:
In the above-given question,
given that,
Jerome finds that (3 x 6) / 2 and 18 / 2 are equal.
3 x 6 = 18.
so both of them are true.

Question 5.
Place parentheses in the equation below so that you solve by finding the difference between 28 and 3. Write the answer
4 × 7 – 3 = __25______

Answer:
The difference between 28 and 3 is 25.

Explanation:
In the above-given question,
given that,
4 x 7 – 3 = 25.
4 x 7 = 28.
28 – 3 = 25.

Question 6.
Johnny says that the answer to 2 × 6 ÷ 3 is 4 no matter where he puts the parentheses. Do you agree? Place parentheses around different numbers to help you explain his thinking.

Answer:
( 2 x 6 ) / 3 = 4.

Explanation:
In the above-given question,
given that,
2 x 6 = 12.
12 / 3 = 4.

Teachers and students can find this Eureka Book Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Learning activities are the best option to educate elementary school kids and make them understand the basic mathematical concepts like addition, subtraction, multiplication, division, etc. Grade 3 elementary school students can find these fun-learning exercises for all math concepts through the Eureka Book.

Engage NY Eureka Math 3rd Grade Module 3 Lesson 9 Answer Key

Students of Grade 3 can get a strong foundation by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka Grade 3 Book.

Eureka Math Grade 3 Module 3 Lesson 9 Application Problems Answer Key

Solve the following pairs of problems. Circle the pairs where both problems have the same answer.

Question 1.
a. 7 + (6 + 4)
b. (7 + 6) + 4

Answer:
a. 17.
b. 17.

Explanation:
In the above-given question,
given that,
a. 7 + (6 + 4)
6 + 4 = 10.
7 + 10 = 17.
b. (7 + 6) + 4.
7 + 6 = 13.
13 + 4 = 17.

Question 2.
a. (3 × 2) × 4
b. 3 × (2 × 4)

Answer:
a. 24.
b. 24.

Explanation:
In the above-given question,
given that,
a. 4 x (3 x 2)
3 x 2 = 6.
6 x 4 = 24.
b. (2 x 4) x 3.
2 x 4 = 8.
8 x 3 = 24.

Question 3.
a. (2 × 1) × 5
b. 2 × (1 × 5)
Answer:
a. 10.
b. 10.

Explanation:
In the above-given question,
given that,
a. 5 x (2 x 1)
2 x 1 = 2.
5 x 2 = 10.
b. (1 x 5) x 2.
5 x 1 = 5.
5 x 2 = 10.

Question 4.
a. (4 × 2) × 2
b. 4 × (2 × 2)

Answer:
a. 16.
b. 16.

Explanation:
In the above-given question,
given that,
a. 2 x (4 x 2)
4 x 2 = 8.
8 + 2 = 16.
b. (2 x 2) x 4.
2 x 2 = 4.
4 x 4 = 16.

Question 5.
a. (3 + 2) × 5
b. 3 + (2 × 5)

Answer:
a. 25.
b. 13.

Explanation:
In the above-given question,
given that,
a. 5 x (3 + 2)
3 + 2 = 5.
5 x 5 = 25.
b. (2 x 5) + 3.
2 x 5 = 10.
10 + 3 = 13.

Question 6.
a. (8 ÷ 2) × 2
b. 8 ÷ (2 × 2)

Answer:
a. 8.
b. 2.

Explanation:
In the above-given question,
given that,
a. 2 x (8 / 2)
8 / 2 = 4.
2 x 4 = 8.
b. (2 x 2) / 8.
2 x 2 = 4.
8 / 4 = 2.

Question 7.
a. (9 – 5) + 3
b. 9 – (5 + 3)

Answer:
a. 7.
b. 1.

Explanation:
In the above-given question,
given that,
a. 3 + (9 – 5)
9 – 5 = 4.
4 + 3 = 7.
b. (5 + 3) – 9.
5 + 3 = 8.
9 – 8 = 1.

Question 8.
a. (8 × 5) – 4
b. 8 × (5 – 4)

Answer:
a. 36.
b. 8.

Explanation:
In the above-given question,
given that,
a. 4 – (8 x 5)
8 x 5 = 40.
40 – 4 = 36.
b. (5 – 4) x 8.
5 – 4 = 1.
1 x 8 = 8.

Eureka Math Grade 3 Module 3 Lesson 9 Problem Set Answer Key

Question 1.
Use the array to complete the equation.
a.

3 × 12 =___36______

Answer:
The number of rows = 3.
the number of columns = 12.

Explanation:
In the above-given question,
given that,
The number of rows = 3.
the number of columns = 12.
3 x 12 = 36.

b.

(3 × 3) × 4
= __9___ × 4
= __36___

Answer:
The number of rows = 3.
the number of columns = 12.

Explanation:
In the above-given question,
given that,
The number of rows = 3.
the number of columns = 12.
(3 x 3) x 4.
9 x 4 = 36.

c.

3 × 14 = __42___

Answer:
The number of rows = 3.
the number of columns = 14.

Explanation:
In the above-given question,
given that,
The number of rows = 3.
the number of columns = 14.
3 x 14 = 42.

d.

(___2__ × __3___) × 7
= ___6__ × __7___
= __42___

Answer:
The number of rows = 3.
the number of columns = 14.

Explanation:
In the above-given question,
given that,
The number of rows = 3.
the number of columns = 14.
(2 x 3) x 7.
6 x 7 = 42.

Question 2.
Place parentheses in the equations to simplify. Then, solve. The first one has been done for you.
a.

Answer:
3 x 16 = 3 x (2 x 8)
(3 x 2) x 8.
6 x 8 = 48.

Explanation:
In the above-given question,
given that,
the equation 3 x 16.
3 x ( 2 x 8 )
( 3 x 2 ) x 8.
6 x 8 = 48.

b.

Answer:
2 x 14 = 2 x (2 x 7)
(2 x 2) x 7.
4 x 7 = 28.

Explanation:
In the above-given question,
given that,
the equation 2 x 14.
2 x ( 2 x 7 )
( 2 x 2 ) x 7.
4 x 7 = 28.

c.

Answer:
3 x 12 = 3 x (3 x 4)
(3 x 3) x 4.
9 x 4 = 36.

Explanation:
In the above-given question,
given that,
the equation 3 x 12.
3 x ( 3 x 4 )
( 3 x 3 ) x 4.
9 x 4 = 36.

d.

Answer:
3 x 14 = 3 x (2 x 7)
(3 x 2) x 7.
6 x 7 = 42.

Explanation:
In the above-given question,
given that,
the equation 3 x 14.
3 x ( 2 x 7 )
( 3 x 2 ) x 7.
6 x 7 = 42.

e.

Answer:
15 x 3 = 5 x 3 x 3
(5 x 3) x 3.
15 x 3 = 45.

Explanation:
In the above-given question,
given that,
the equation 3 x 15.
3 x ( 5 x 3 )
( 3 x 5 ) x 3.
15 x 3 = 45.

f.

Answer:
2 x 15 = 2 x (5 x 3)
(5 x 3) x 2.
15 x 2 = 30.

Explanation:
In the above-given question,
given that,
the equation 2 x 15.
2 x ( 5 x 3)
( 5 x 3 ) x 2.
15 x 2 = 30.

Question 3.
Charlotte finds the answer to 16 × 2 by thinking about 8 × 4. Explain her strategy.

Answer:
16 x 2 = 32.
8 x 4 = 32.

Explanation:
In the above-given question,
given that,
16 x 2 = 8 x 4.
16 x 2 = 32.
8 x 4 = 32.

Eureka Math Grade 3 Module 3 Lesson 9 Exit Ticket Answer Key

Simplify to find the answer to 18 × 3. Show your work, and explain your strategy.

Answer:
18 x 3 = 54.

Explanation:
In the above-given question,
given that,
18 x 3 = 54.
3 x 18 = 54.

Eureka Math Grade 3 Module 3 Lesson 9 Worksheet Answer Key

Question 1.
Use the array to complete the equation.
a.

3 × 16 = ____48_____

Answer:
The number of rows = 3.
the number of columns = 16.

Explanation:
In the above-given question,
given that,
The number of rows = 3.
the number of columns = 16.
3 x 16 = 48.

b.

(3 × __2__) × 8
= __6___ × ___8__
= __48___

Answer:
The number of rows = 3.
the number of columns = 16.

Explanation:
In the above-given question,
given that,
The number of rows = 3.
the number of columns = 16.
(3 x 2) x 8.
6 x 8 = 48.

c.

4 × 18 = __72___

Answer:
The number of rows = 4.
the number of columns = 18.

Explanation:
In the above-given question,
given that,
The number of rows = 4.
the number of columns = 18.
4 x 18 = 72.

d.

(4 × __2__) × 9
= ___8__ × ___9__
= __72___

Answer:
The number of rows = 4.
the number of columns = 18.

Explanation:
In the above-given question,
given that,
The number of rows = 4.
the number of columns = 18.
(4 x 2) x 9.
8 x 9 = 72.

Question 2.
Place parentheses in the equations to simplify and solve.
a.

Answer:
14 x 3 = 2 x 7 x 3
(3 x 2) x 7.
6 x 7 = 42.

Explanation:
In the above-given question,
given that,
the equation 3 x 14.
3 x ( 2 x 7 )
( 3 x 2 ) x 7.
6 x 7 = 42.

b.

Answer:
12 x 3 = 4 x 3 x 3
(3 x 3) x 4.
9 x 4 = 36.

Explanation:
In the above-given question,
given that,
the equation 3 x 12.
3 x ( 3 x 4 )
( 3 x 3 ) x 4.
9 x 4 = 36.

Question 3.
Solve. Then, match the related facts.

Answer:
20 x 2 = 40.
30 x 2 = 60.
35 x 2 = 70.
40 x 2 = 80.

Explanation:
In the above-given question,
given that,
the equations are 20 x 2 = 40.
30 x 2 = 60.
35 x 2 = 70.
40 x 2 = 80.

Students of Grade 3 can get a strong foundation by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka Grade 3 Book.

Engage NY Eureka Math 3rd Grade Module 3 Lesson 10 Answer Key

Teachers and students can find this Eureka Book Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Learning activities are the best option to educate elementary school kids and make them understand the basic mathematical concepts like addition, subtraction, multiplication, division, etc. Grade 3 elementary school students can find these fun-learning exercises for all math concepts through the Eureka Book.

Eureka Math Grade 3 Module 3 Lesson 10 Problem Set Answer Key

Question 1.
Label the arrays. Then, fill in the blanks below to make the statements true.
a. 8 × 8 = __64___

8 × 8 = 8 × (5 + __3___)
= (8 × 5) + (8 × __3___)
=   40     + ___24___
= ____64__

Answer:
8 x 8 = 64.

Explanation:
In the above-given question,
given that,
the number of rows = 8.
the number of columns = 8.
8 x 8 = 8 x ( 5 + 3 ).
(8 x 5 ) + ( 8 x 3)
40 + 24.
64.

b. 8 × 9 = 9 × 8 = __72___

9 × 8 = 8 × (5 + __4___)
= (8 × 5) + (8 × __4__ )
=   40    + __32____
= __72____

Answer:
9 x 8 = 72.

Explanation:
In the above-given question,
given that,
the number of rows = 8.
the number of columns = 9.
8 x 9 = 8 x ( 5 + 4 ).
(8 x 5 ) + ( 8 x 4)
40 + 32.
72.

Question 2.
Break apart and distribute to solve 56 ÷ 8.

56 ÷ 8 = (40 ÷ 8) + ( ____16_____ ÷ 8)
= 5 + _____2_______
= _____7_______

Answer:
56 / 8 = 7.

Explanation:
In the above-given question,
given that,
56 / 8 = (40 / 8 ) + ( 16 / 8 )
40 / 8 = 5.
16 / 8 = 2.
5 + 2 = 7.

Question 3.
Break apart and distribute to solve 72 ÷ 8.

72 ÷ 8 = (40 ÷ 8) + ( ___32______ ÷ 8)
= 5 + ______4______
= _______9_____

Answer:
72 / 8 = 9.

Explanation:
In the above-given question,
given that,
72 / 8 = (40 / 8 ) + ( 32 / 8 )
40 / 8 = 5.
32 / 8 = 4.
5 + 4 = 9.

Question 4.
An octagon has 8 sides. Skip-count to find the total number of sides on 9 octagons.

Nine octagons have a total of _____72____ sides.

Answer:
8 x 9 = 72.

Explanation:
In the above-given question,
given that,
An octagon has 8 sides.
the total number of sides o 9 octagons.
8 x 9 = 72.

Question 5.
Multiply.

Answer:
8 x 6 = 48, 3 x 8 = 24, 8 x 10 = 80, 8 x 8 = 64, 7 x 8 = 56.

Explanation:
In the above-given question,
given that,
the tables of 7 and 8.
8 x 6 = 48.
3 x 8 = 24.
8 x 10 = 80.
8 x 8 = 64.
7 x 8 = 56.

Question 6.
Match

Answer:
24 / 8 = 3.
32 / 8 = 4.
16 / 8 = 2.
64 / 8 = 8.
48 / 8 = 6.
72 / 8 = 9.

Explanation:
In the above-given question,
given that,
8 x 3 = 24, 8 x 4 = 32, 8 x 2 = 16, 8 x 8 = 64, 8 x 6 = 48, 8 x 9 = 72.
24 / 8 = 3.
32 / 8 = 4.
16 / 8 = 2.
64 / 8 = 8.
48 / 8 = 6.
72 / 8 = 9.

Eureka Math Grade 3 Module 3 Lesson 10 Exit Ticket Answer Key

Use the break apart and distribute strategy to solve the following problem. You may choose whether or not to draw an array.
7 × 8 =__56___

Answer:
7 x 8 = 56.

Explanation:
In the above-given question,
given that,
the number of rows = 7.
the number of columns = 8.
7 x 8 = 7 x ( 5 + 3 ).
(7 x 5 ) + ( 7 x 3)
35 + 21.
56.

Eureka Math Grade 3 Module 3 Lesson 10 Homework Answer Key

Question 1.
Label the array. Then, fill in the blanks to make the statements true.
8 × 7 = 7 × 8 =__56___

8 × 7 = 7 × (5 + __3___)
= (7 × 5) + (7 × __3__)
=    35     + ___21___
= __56____

Answer:
7 x 8 = 56.

Explanation:
In the above-given question,
given that,
the number of rows = 7.
the number of columns = 8.
7 x 8 = 7 x ( 5 + 3 ).
(7 x 5 ) + ( 7 x 3)
35 + 21.
56.

Question 2.
Break apart and distribute to solve 72 ÷ 8.

72 ÷ 8 = (40 ÷ 8) + ( ____32_____ ÷ 8)
= 5 + ______4______
= ______9______

Answer:
72 / 8 = 9.

Explanation:
In the above-given question,
given that,
72 / 8 = (40 / 8 ) + ( 32 / 8 )
40 / 8 = 5.
32 / 8 = 4.
5 + 4 = 9.

Question 3.
Count by 8. Then, match each multiplication problem with its value.
8 , ___16____, ___24____, ____32___, ____40___, ___48____, ___56____, ____64___, ___72____, ___80____

Answer:
8 x 2 = 16, 8 x 3 = 24, 8 x 4 = 32, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64, 8 x 9 = 72, and 8 x 10 = 8.

Explanation:
In the above-given question,
given that,
the table of 8 and match it with the given equations.
8 x 2 = 16, 8 x 3 = 24, 8 x 4 = 32, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64, 8 x 9 = 72, and 8 x 10 = 8.

Question 4.
Divide

Answer:
16 / 8 = 2.
40 / 8 = 5.
32 / 8 = 4.
48 / 8 = 6.
56 / 8 = 7.
72 / 8 = 9.

Explanation:
In the above-given question,
given that,
the division of 8.
16 / 8 = 2.
40 / 8 = 5.
32 / 8 = 4.
48 / 8 = 6.
56 / 8 = 7.
72 / 8 = 9.

Teachers and students can find this Eureka Book Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Learning activities are the best option to educate elementary school kids and make them understand the basic mathematical concepts like addition, subtraction, multiplication, division, etc. Grade 3 elementary school students can find these fun-learning exercises for all math concepts through the Eureka Book.

Engage NY Eureka Math 3rd Grade Module 3 Lesson 11 Answer Key

Students of Grade 3 can get a strong foundation by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka Grade 3 Book.

Eureka Math Grade 3 Module 3 Lesson 11 Pattern Sheet Answer Key

Multiply.

Answer:
8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 4 = 8 x 5 = 40, 8 x 1 = 8, 8 x 2 = 16, 8 x 1 = 8, 8 x 3 = 24, 8 x 1 = 8,  8 x 4 = 32, 8 x 1 = 8, 8 x 5 = 40, 8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 2 = 16, 8 x 4 = 32, 8 x2 = 16, 8 x 5 = 40, 8 x 2 = 16, 8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 1 = 8, 8 x 3 = 24, 8 x 2 = 16, 8 x 3 = 24, 8 x 4 = 32, 8 x 3 = 24, 8 x 5 = 40, 8 x 3 = 24, 8 x 4 = 32, 8 x 1 = 8, 8 x 4 = 32, 8 x 2 = 16, 8 x 4 = 32, 8 x 3 = 24, 8 x 4 = 32, 8 x 5 = 40, 8 x 4 = 32, 8 x 5 = 40, 8 x 1 = 8, 8 x 5 = 40, 8 x 2 = 16, 8 x 5 = 40, 8 x 3 = 24, 8 x 5 = 40, 8 x 4 = 32, 8 x 2 = 16, 8 x 4 = 32, 8 x 3 = 24, 8 x 5 = 40, 8 x 3 = 24, 8 x 2 = 16, 8 x 4 = 32, 8 x 3 = 24, 8 x 5 = 40, 8 x 2 = 16, 8 x 4 = 32.

Explanation:
In the above-given question,
given that,
the tables of 8.
8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 4 = 8 x 5 = 40, 8 x 1 = 8, 8 x 2 = 16, 8 x 1 = 8, 8 x 3 = 24, 8 x 1 = 8,  8 x 4 = 32, 8 x 1 = 8, 8 x 5 = 40, 8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 2 = 16, 8 x 4 = 32, 8 x2 = 16, 8 x 5 = 40, 8 x 2 = 16, 8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 1 = 8, 8 x 3 = 24, 8 x 2 = 16, 8 x 3 = 24, 8 x 4 = 32, 8 x 3 = 24, 8 x 5 = 40, 8 x 3 = 24, 8 x 4 = 32, 8 x 1 = 8, 8 x 4 = 32, 8 x 2 = 16, 8 x 4 = 32, 8 x 3 = 24, 8 x 4 = 32, 8 x 5 = 40, 8 x 4 = 32, 8 x 5 = 40, 8 x 1 = 8, 8 x 5 = 40, 8 x 2 = 16, 8 x 5 = 40, 8 x 3 = 24, 8 x 5 = 40, 8 x 4 = 32, 8 x 2 = 16, 8 x 4 = 32, 8 x 3 = 24, 8 x 5 = 40, 8 x 3 = 24, 8 x 2 = 16, 8 x 4 = 32, 8 x 3 = 24, 8 x 5 = 40, 8 x 2 = 16, 8 x 4 = 32.

Eureka Math Grade 3 Module 3 Lesson 11 Problem Set Answer Key

Question 1.
Ms. Santor divides 32 students into 8 equal groups for a field trip. Draw a tape diagram, and label the number of students in each group as n. Write an equation, and solve for n.

Answer:
32 / n = 8.
n = 4.

Explanation:
In the above-given question,
given that,
Ms. Santor divides 32 students into 8 equal groups for a field trip.
the number of students in each group as n.
32 / n = 8.
n = 4.

Question 2.
Tara buys 6 packs of printer paper. Each pack of paper costs $8. Draw a tape diagram, and label the total amount she spends as m. Write an equation, and solve for m.

Answer:
The total amount she spends = $48.

Explanation:
In the above-given question,
given that,
Tara buys 6 packs of printer paper.
Each pack of paper costs $8.
6 x m = $8.
m = 6 x 8 = $48.

Question 3.
Mr. Reed spends $24 on coffee beans. How many kilograms of coffee beans does he buy? Draw a tape diagram, and label the total amount of coffee beans he buys as c. Write an equation, and solve for c.

Answer:
The total amount of coffee beans he buys = 3 kg.

Explanation:
In the above-given question,
given that,
Mr. Reed spends $24 on coffee beans.
$24 / c = 8.
c = 24 / 8.
c = 3.

Question 4.
Eight boys equally share 4 packs of baseball cards. Each pack contains 10 cards. How many cards does each boy get?

Answer:
The number of cards each boy gets = 40.

Explanation:
In the above-given question,
given that,
Eight boys equally share 4 packs of baseball cards.
each pack contains 10 cards.
10 x 4 = 40.
so the number of cards each boy gets = 40.

Question 5.
There are 8 bags of yellow and green balloons. Each bag contains 7 balloons. If there are 35 yellow balloons, how many green balloons are there?

Answer:
The number of green balloons = 21.

Explanation:
In the above-given question,
given that,
There are 8 bags of yellow and green balloons.
each bag contains 7 balloons.
if there are 35 yellow balloons.
8 x 7 = 56.
56 – 35 = 21.
so the number of green balloons = 21.

Question 6.
The fruit seller packs 72 oranges into bags of 8 each. He sells all the oranges at $4 a bag. How much money did he receive?

Answer:
The amount of money he receives = 40.

Explanation:
In the above-given question,
given that,
The fruit seller packs 72 oranges into bags of 8 each.
He sells all the oranges at $4 a bag.
8 x 4 = 32.
72 – 32 = 40.
so the amount of money he receives = 40.

Eureka Math Grade 3 Module 3 Lesson 11 Exit Ticket Answer Key

Erica buys some packs of rubber bracelets. There are 8 bracelets in each pack.

a. How many packs of rubber bracelets does she buy if she has a total of 56 bracelets? Draw a tape diagram, and label the total number of packages as p. Write an equation, and solve for p.

Answer:
The total amount of packages = 7.

Explanation:
In the above-given question,
given that,
Erica buys some packs of rubber bracelets.
There are 8 bracelets in each pack.
8 / p = 56.
p = 56 / 8.
p = 7.
so the total amount of packages = 7.

b. After giving some bracelets away, Erica has 18 left. How many bracelets did she give away?

Answer:
The number of bracelets did she give away = 9.

Explanation:
In the above-given question,
given that,
After giving some bracelets away, Erica has 18 left.
18 / 2 = 9.
so the number of bracelets did she give away = 9.

Eureka Math Grade 3 Module 3 Lesson 11 Homework Answer Key

Question 1.
Jenny bakes 10 cookies. She puts 7 chocolate chips on each cookie. Draw a tape diagram, and label the total amount of chocolate chips as c. Write an equation, and solve for c.

Answer:
The total amount of chocolate chips = 70.

Explanation:
In the above-given question,
given that,
Jenny bakes 10 cookies.
she puts 7 chocolate chips on each cookie.
10 x 7 = c.
c = 70.

Question 2.
Mr. Lopez arranges 48 dry erase markers into 8 equal groups for his math stations. Draw a tape diagram, and label the number of dry erase markers in each group as v. Write an equation, and solve for v.

Answer:
The number of dry erase markers in each group = 6.

Explanation:
In the above-given question,
given that,
Mr. Lopez arranges 48 dry erase markers into 8 equal groups for his math stations.
48 / v = 8.
v = 48 / 8.
v = 6.

Question 3.
There are 35 computers in the lab. Five students each turn off an equal number of computers.
How many computers does each student turn off? Label the unknown as m, and then solve.

Answer:
The number of computers does each student turn off = 7.

Explanation:
In the above-given question,
given that,
There are 35 computers in the lab.
Five students each turn off an equal number of computers.
5 / m = 35.
m = 35 / 5.
m = 7.

Question 4.
There are 9 bins of books. Each bin has 6 comic books. How many comic books are there altogether?

Answer:
The number of comic books is there altogether = 54.

Explanation:
In the above-given question,
given that,
There are 9 bins of books.
Each bin has 6 comic books.
9 x 6 = 54.
so the number of comic books is there altogether = 54.

Question 5.
There are 8 trail mix bags in one box. Clarissa buys 5 boxes. She gives an equal number of bags of trail mix to 4 friends. How many bags of trail mix does each friend receive?

Answer:
The bags of trail mix does each friend receives = 40.

Explanation:
In the above-given question.
given that,
There are 8 trail mix bags in one box.
Clarissa buys 5 boxes.
she gives an equal number of bags of trail mix to 4 friends.
8 x 5 = 40.

Question 6.
Leo earns $8 each week for doing chores. After 7 weeks, he buys a gift and has $38 left. How much money does he spend on the gift?

Answer:
The amount he spends on the gift = $18.

Explanation:
In the above-given question,
given that,
Leo earns $8 each week for doing chores.
After 7 weeks, he buys a gift and has $38 left.
7 x 8 = 56.
56 – 38 = $18.
so the amount he spends on the gift = $18.

Students of Grade 3 can get a strong foundation by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka Grade 3 Book.

Engage NY Eureka Math 3rd Grade Module 3 Lesson 12 Answer Key

Teachers and students can find this Eureka Book Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Learning activities are the best option to educate elementary school kids and make them understand the basic mathematical concepts like addition, subtraction, multiplication, division, etc. Grade 3 elementary school students can find these fun-learning exercises for all math concepts through the Eureka Book.

Eureka Math Grade 3 Module 3 Lesson 12 Pattern Sheet Answer Key

Multiply

Answer:
8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64, 8 x 9 = 72, 8 x 10 = 80, 8 x 5 = 40, 8 x 6 = 48, 8 x 5 = 40, 8 x 7 = 56, 8 x 5 = 40, 8 x 6 = 48, 8 x 5 = 40, 8 x 7 = 56, 8 x 5 = 40, 8 x 8 = 64, 8 x 5 = 40, 8 x 9 = 72, 8 x 5 = 40, 8 x 10 = 80, 8 x 6 = 48, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 6 = 48, 8 x 8 = 64, 8 x 6 = 48, 8 x 9 = 72, 8 x 6 = 48, 8 x 7 = 56, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64, 8 x 7 = 56, 8 x 9 = 72, 8 x 7 = 56, 8 x 8 = 64, 8 x 6 48, 8 x 8 = 64, 8 x 7 = 56, 8 x 8 = 64, 8 x 9 = 72, 8 x 9 = 72, 8 x 6 = 48, 8 x 9 = 72, 8 x 7 = 56, 8 x 9 = 72, 8 x 8 = 64, 8 x 9 = 72, 8 x 8 = 64, 8 x 6 = 48, 8 x 9 = 72, 8 x 7 = 56, 8 x 9 = 72, 8 x 6 = 48, 8 x 8 = 64, 8 x 9 = 72, 8 x 7 = 56, 8 x 6 = 48, 8 x 8 = 64.

Explanation:
In the above-given question,
given that,
the table of 8 and multiply.
8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64, 8 x 9 = 72, 8 x 10 = 80, 8 x 5 = 40, 8 x 6 = 48, 8 x 5 = 40, 8 x 7 = 56, 8 x 5 = 40, 8 x 6 = 48, 8 x 5 = 40, 8 x 7 = 56, 8 x 5 = 40, 8 x 8 = 64, 8 x 5 = 40, 8 x 9 = 72, 8 x 5 = 40, 8 x 10 = 80, 8 x 6 = 48, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 6 = 48, 8 x 8 = 64, 8 x 6 = 48, 8 x 9 = 72, 8 x 6 = 48, 8 x 7 = 56, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64, 8 x 7 = 56, 8 x 9 = 72, 8 x 7 = 56, 8 x 8 = 64, 8 x 6 48, 8 x 8 = 64, 8 x 7 = 56, 8 x 8 = 64, 8 x 9 = 72, 8 x 9 = 72, 8 x 6 = 48, 8 x 9 = 72, 8 x 7 = 56, 8 x 9 = 72, 8 x 8 = 64, 8 x 9 = 72, 8 x 8 = 64, 8 x 6 = 48, 8 x 9 = 72, 8 x 7 = 56, 8 x 9 = 72, 8 x 6 = 48, 8 x 8 = 64, 8 x 9 = 72, 8 x 7 = 56, 8 x 6 = 48, 8 x 8 = 64.

Eureka Math Grade 3 Module 3 Lesson 12 Problem Set Answer Key

Question 1.
Each has a value of 9. Find the value of each row. Then, add the rows to find the total.

a. 6 × 9 = ___54____

6 × 9 = (5 + 1) × 9
= (5 × 9) + (1 × 9)
= 45 + ___9__
= __54___

Answer:
6 x 9 = 54.

Explanation:
In the above-given question,
given that,
6 x 9 = ( 5 + 1 ) x 9.
( 5 x 9 ) + ( 1 x 9 )
45 + 9
54.

b. 7 × 9 = ____63___

7 × 9 = (5 + __2__) × 9
= (5 × 9) + (__2__ × 9)
= 45 + __18___
= ___63__

Answer:
7 x 9 = 63.

Explanation:
In the above-given question,
given that,
7 x 9 = ( 5 + 2 ) x 9.
( 5 x 9 ) + ( 2 x 9 )
45 + 18.
63.

c. 8 × 9 = ___72____

8 × 9 = (5 + ___3__) × 9
= (5 × 9) + (___3__ × __9___)
= 45 + __27___
= __72___

Answer:
8 x 9 = 72.

Explanation:
In the above-given question,
given that,
8 x 9 = ( 5 + 3 ) x 9.
( 5 x 9 ) + ( 3 x 9 )
45 + 27.
72.

d. 9 × 9 = ____81___

9 × 9 = (5 + ___4__) × 9
= (5 × 9) + (__4___ × ___9__)
= 45 + __36___
= __81___

Answer:
9 x 9 = 81.

Explanation:
In the above-given question,
given that,
9 x 9 = ( 5 + 4 ) x 9.
( 5 x 9 ) + ( 4 x 9 )
45 + 36.
81.

Question 2.
Find the total value of the shaded blocks.

a. 9 × 6 = 54

9 sixes = 10 sixes – 1 six
=__60___ – 6
= __54___

Answer:
9 x 6 = 54.

Explanation:
In the above-given equation,
given that,
9 sixes = 10 sixes – 1 six.
60 – 6.
54.

b. 9 × 7 = 63

9 sevens = 10 sevens – 1 seven
= __70___ – 7
= __63___

Answer:
9 x 7 = 63.

Explanation:
In the above-given equation,
given that,
9 sevens = 10 sevens – 1 seven.
70 – 7.
63.

c. 9 × 8 = 72.

9 eights = 10 eights – 1 eight
= __80___ – 8
= __72___

Answer:
9 x 8 = 72.

Explanation:
In the above-given equation,
given that,
9 eights = 10 eights – 1 eight.
80 – 8.
72.

d. 9 × 9 = 81.

9 nines = 10 nines – 1 nine
= __90___ – __9___
= __81___

Answer:
9 x 9 = 81.

Explanation:
In the above-given equation,
given that,
9 nines = 10 nines – 1 nine.
90 – 9.
81.

Question 3.
Matt buys a pack of postage stamps. He counts 9 rows of 4 stamps. He thinks of 10 fours to find the total number of stamps. Show the strategy that Matt might have used to find the total number of stamps.

Answer:
9 x 4 = 36.

Explanation:
In the above-given equation,
given that,
9 fours = 10 fourss – 1 four.
40 – 4.
36.

Question 4.
Match

Answer:
3 x 9 = 27, 45 / 9 = 5.
9 x 9 = 81, 9 / 9 = 1.
8 x 9 = 72, 90 / 9 = 10.
9 x 4 = 36, 72 / 9 = 8.
2 x 9 = 18, 54 / 9 = 6.

Explanation:
In the above-given question,
given that,
the multiplication and division of 9.
3 x 9 = 27, 45 / 9 = 5.
9 x 9 = 81, 9 / 9 = 1.
8 x 9 = 72, 90 / 9 = 10.
9 x 4 = 36, 72 / 9 = 8.
2 x 9 = 18, 54 / 9 = 6.

Eureka Math Grade 3 Module 3 Lesson 12 Exit Ticket Answer Key

Question 1.
Each has a value of 9. Complete the equations to find the total value of the tower of blocks.

___5__ × 9 = (5 + __1__ ) × 9
= (5 × ___9__ ) + ( __1___ × __9___ )
= 45 + __9___
= __54___

Answer:
6 x 9 = 54.

Explanation:
In the above-given question,
given that,
5 x 9 = ( 5 + 1 ) x 9.
( 5 x 9 ) + ( 1 x 9 )
45 + 9.
54.

Question 2.
Hector solves 9 × 8 by subtracting 1 eight from 10 eights. Draw a model, and explain Hector’s strategy.

Answer:
9 x 8 = 72.

Explanation:
In the above-given question,
given that,
9 x 8 = 72.
10 eights – 1 eight.
80 – 8.
72.

Eureka Math Grade 3 Module 3 Lesson 12 Homework Answer Key

Question 1.
Find the value of each row. Then, add the rows to find the total.

a. Each has a value of 6.
9 × 6 = ___54_____

9 × 6 = (5 + 4) × 6
= (5 × 6) + (4 × 6)
= 30 + __24___
= __54___

Answer:
6 x 9 = 54.

Explanation:
In the above-given question,
given that,
6 x 9 = ( 5 + 4 ) x 6.
( 5 x 6 ) + ( 4 x 6 )
30 + 24.
54.

b. Each has a value of 7.
9 × 7 = ___63_____

9 × 7 = (5 + __4___) × 7
= (5 × 7) + (__4___ × 7)
= 35 + __28___
= ___63__

Answer:
9 x 7 = 63.

Explanation:
In the above-given question,
given that,
9 x 7 = ( 5 + 4 ) x 7.
( 5 x 7 ) + ( 4 x 9 )
35 + 28.
63.

c. Each has a value of 8.
9 × 8 = ____72____

9 × 8 = (5 + __4___) × 8
= (5 × 8) + (__4___ × ___8__)
= 40 + ___32__
= __72___

Answer:
9 x 8 = 72.

Explanation:
In the above-given question,
given that,
9 x 8 = ( 5 + 4 ) x 8.
( 5 x 8 ) + ( 4 x 8 )
40 + 32.
72.

d. Each has a value of 9.
9 × 9 = ____81____

9 × 9 = (5 + _____) × 9
= (5 × 9) + (__4___ × __9___)
= 45 + ___36__
= __81___

Answer:
9 x 9 = 81.

Explanation:
In the above-given question,
given that,
9 x 9 = ( 5 + 4 ) x 9.
( 5 x 9 ) + ( 4 x 9 )
45 + 36.
81.

Question 2.
Match

Answer:
50 – 5 = 45, 9 x 5 = 45.
60 – 6 = 54, 9 x 6 = 54.
70 – 7 = 63, 9 x 7 = 63.
80 – 8 = 72, 9 x 8 = 72.
90 – 9 = 81, 9 x 9 = 81.
40 – 4 = 36, 9 x 4 = 36.

Explanation:
In the above-given question,
given that,
the multiplication and division of 9 is given.
50 – 5 = 45, 9 x 5 = 45.
60 – 6 = 54, 9 x 6 = 54.
70 – 7 = 63, 9 x 7 = 63.
80 – 8 = 72, 9 x 8 = 72.
90 – 9 = 81, 9 x 9 = 81.
40 – 4 = 36, 9 x 4 = 36.

Teachers and students can find this Eureka Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Eureka Math Answer Key for Grade 3 aids teachers to differentiate instruction, building and reinforcing foundational mathematics skills that alter from the classroom to real life. With the help of Eureka’s primary school Grade 3 Answer Key, you can think deeply regarding what you are learning, and you will really learn math easily just like that.

Engage NY Eureka Math 3rd Grade Module 3 Lesson 1 Answer Key

Students of Grade 3 Module 3 can get a strong foundation on mathematics concepts by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka’s Grade 3 Textbook.

Eureka Math Grade 3 Module 3 Lesson 1 Sprint Answer Key

Mixed Multiplication

Answer:
2 x 1 = 2, 2 x 2 = 4, 2 x 3 = 6, 4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 1 x 6 = 6, 2 x 6 = 12, 1 x 8 = 8, 2 x 8 = 16, 3 x 1 = 3, 3 x 2 = 6, 3 x 3 = 9, 5 x 1 = 5, 5 x 2 = 10, 5 x 3 = 15, 1 x 7 = 7, 2 x 7 = 14, 1 x 9 = 9, 2 x 9 = 18, 2 x 5 = 10, 2 x 6 = 12,
2 x 7 = 14, 5 x 5 = 25, 5 x 6 = 30, 5 x 7 = 35, 4 x 5 = 20, 4 x 6 = 24, 4 x 7 = 28, 3 x 5 = 15, 3 x 6 = 18, 3 x 7 = 21, 2 x 7 = 14, 2 x 8 = 16, 2 x 9 = 18, 5 x 7 = 35, 5 x 8 = 40, 5 x 9 = 45, 4 x 7 = 28, 4 x 8 = 32, 4 x 9 = 36, 3 x 7 = 21, 3 x 8 = 24, 3 x 9 = 27.

Explanation:
In the above-given question,
given that,
The tables of 1, 2, 3, 4, and 5.

2 x 1 = 2, 2 x 2 = 4, 2 x 3 = 6, 4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 1 x 6 = 6, 2 x 6 = 12, 1 x 8 = 8, 2 x 8 = 16, 3 x 1 = 3, 3 x 2 = 6, 3 x 3 = 9, 5 x 1 = 5, 5 x 2 = 10, 5 x 3 = 15, 1 x 7 = 7, 2 x 7 = 14, 1 x 9 = 9, 2 x 9 = 18, 2 x 5 = 10, 2 x 6 = 12,
2 x 7 = 14, 5 x 5 = 25, 5 x 6 = 30, 5 x 7 = 35, 4 x 5 = 20, 4 x 6 = 24, 4 x 7 = 28, 3 x 5 = 15, 3 x 6 = 18, 3 x 7 = 21, 2 x 7 = 14, 2 x 8 = 16, 2 x 9 = 18, 5 x 7 = 35, 5 x 8 = 40, 5 x 9 = 45, 4 x 7 = 28, 4 x 8 = 32, 4 x 9 = 36, 3 x 7 = 21, 3 x 8 = 24, 3 x 9 = 27.

Answer:
5 x 1 = 5, 5 x 2 = 10, 5 x 3 = 15, 3 x 1 = 3, 3 x 2 = 6, 3 x 3 = 9, 1 x 7 = 7, 2 x 7 = 14, 1 x 9 = 9, 2 x 9 = 18, 2 x 1 = 2, 2 x 2 = 4, 2 x 3 = 6, 4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 1 x 6 = 6, 2 x 6 = 12, 1 x 8 = 8, 2 x 8 = 16, 5 x 5 = 25, 5 x 6 = 30,
5 x 7 = 35, 2 x 5 = 10, 2 x 6 = 12, 2 x 7 = 14, 3 x 5 = 15, 3 x 6 = 18, 3 x 7 = 21, 4 x 5 = 20, 4 x 6 = 24, 4 x 7 = 28, 5 x 7 = 35, 5 x 8 = 40, 5 x 9 = 45, 2 x 7 = 14, 2 x 8 = 16, 2 x 9 = 18, 3  x 7 = 21, 3 x 8 = 24, 3 x 9 = 27, 4 x 7 = 28, 4 x 8 = 32, 4 x 9 = 36.

Explanation:
In the above-given question,
given that,
the tables of 1, 2, 3, 4, and 5.
5 x 1 = 5, 5 x 2 = 10, 5 x 3 = 15, 3 x 1 = 3, 3 x 2 = 6, 3 x 3 = 9, 1 x 7 = 7, 2 x 7 = 14, 1 x 9 = 9, 2 x 9 = 18, 2 x 1 = 2, 2 x 2 = 4, 2 x 3 = 6, 4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 1 x 6 = 6, 2 x 6 = 12, 1 x 8 = 8, 2 x 8 = 16, 5 x 5 = 25, 5 x 6 = 30,
5 x 7 = 35, 2 x 5 = 10, 2 x 6 = 12, 2 x 7 = 14, 3 x 5 = 15, 3 x 6 = 18, 3 x 7 = 21, 4 x 5 = 20, 4 x 6 = 24, 4 x 7 = 28, 5 x 7 = 35, 5 x 8 = 40, 5 x 9 = 45, 2 x 7 = 14, 2 x 8 = 16, 2 x 9 = 18, 3  x 7 = 21, 3 x 8 = 24, 3 x 9 = 27, 4 x 7 = 28, 4 x 8 = 32, 4 x 9 = 36.

Eureka Math Grade 3 Module 3 Lesson 1 Problem Set Answer Key

Question 1.
a. Solve. Shade in the multiplication facts that you already know. Then, shade in the facts for sixes, sevens, eights, and nines that you can solve using the commutative property

Answer:
The facts of 6 are 2, 3, and 12.
the facts of 7 are 7, 1, 14.
the facts of 8 are 8, 16.
the facts of 9 are 18.

Explanation:
In the above-given question,
given that,
the facts of 6, 7, 8, and 9.
The facts of 6 are 2, 3, and 12.
the facts of 7 are 7, 1, 14.
the facts of 8 are 8, 16.
the facts of 9 are 18.

b. Complete the chart. Each bag contains 7 apples.

Answer:
The number of bags is 2, the total number of apples = 14.
The number of bags is 3, the total number of apples = 21.
The number of bags is 4, the total number of apples = 28.
The number of bags is 5, the total number of apples = 35.
The number of bags is 6, the total number of apples = 42.

Explanation:
In the above-given question,
given that,
Each bag contains 7 apples.
The number of bags is 2, the total number of apples = 14.
The number of bags is 3, the total number of apples = 21.
The number of bags is 4, the total number of apples = 28.
The number of bags is 5, the total number of apples = 35.
The number of bags is 6, the total number of apples = 42.

Question 2.
Use the array to write two different multiplication sentences.

Answer:
The number of rows is 4, the number of columns = 6.
6 x 4 = 24.
4 x 6 = 24.

Explanation:
In the above-given question,
given that,
the array contains the number of rows and number of columns.
The number of rows is 4, the number of columns = 6.
6 x 4 = 24.
4 x 6 = 24.

Question 3.
Complete the equations.

a. 2 sevens = __seven_____ twos
= ____14____

Answer:
2 sevens = seven twos.
14 = 14.

Explanation:
In the above-given question,
given that,
2 sevens = seven twos.
2 x 7 = 7 x 2.
14 = 14.

b. 3 ___sixs_____ = 6 threes
= ___18_____

Answer:
3 sixs = 6 threes.
18 = 18.

Explanation:
In the above-given question,
given that,
3 sixs = 6 threes.
3 x 6 = 6 x 3.
18 = 18.

c. 10 eights = 8 __tens______
= ___80_____

Answer:
10 eights = 8 tens.
80 = 80.

Explanation:
In the above-given question,
given that,
10 eights = 8 tens.
10 x 8 = 80 and 8 x 10 = 80.

d. 4 × __six_____ = 6 × 4
= ___24_____

Answer:
4 x six = 6 x 4.
24 = 24.

Explanation:
In the above-given question,
given that,
4 x six = six x 4.
4 x 6 = 6 x 4.
24 = 24.

e. 8 × 5 = ____five____ × 8
= __40______

Answer:
8 x 5 = five x 8.
40 = 40.

Explanation:
In the above-given question,
given that,
8 x 5 = 5 x 8.
40 = 40.

f. ___5____ × 7 = 7 × ___five____
= __35______

Answer:
5 x 7 = 7 x five.
35 = 35.

Explanation:
In the above-given question,
given that,
5 x 7 = 7 x five.
35 = 35.

g. 3 × 9 = 10 threes – ___1____ three
= __27______

Answer:
3 x 9 = 10 threes – 1 three.
27 = 30 – 3.

Explanation:
In the above-given question,
given that,
3 x 9 = 10 threes – 1 three.
27 = 30 – 3.
27 = 27.

h. 10 fours – 1 four = __9_____ × 4
= ____36____

Answer:
10 fours – 1 four = 9 x 4.
40 – 4 = 36.

Explanation:
In the above-given question,
given that,
10 fours – 1 four = 9 x 4.
40 – 4 = 36.
36 = 36.

i. 8 × 4 = 5 fours + __3_____ fours
= ____32____

Answer:
8 x 4 = 5 fours + 3 fours.
32 = 20 + 12.

Explanation:
In the above-given question,
given that,
8 x 4 = 5 fours + 3 fours.
32 = 20 + 12.
32 = 32.

j. __six_____ fives + 1 five = 6 × 5
= ____35____

Answer:
six fives + 1 five = 6 x 5.
30 + 5 = 35.

k. 5 threes + 2 threes = __7___ × __3___
= ___21_____

Answer:
5 threes + 2 threes = 7 x 3.
21 = 21.

Explanation:
In the above-given question,
given that,
5 threes + 2 threes = 7 x 3.
15 + 6 = 21.
21 = 21.

l. ____5__ twos + __five____ twos = 10 twos
= ___20_____

Answer:
5 twos + 5 twos.
20 = 20.

Explanation:
In the above-given question,
given that,
5 twos + five twos = 10 twos.
10 + 10 = 10 twos.
20 = 20.

Eureka Math Grade 3 Module 3 Lesson 1 Exit Ticket Answer Key

Question 1.
Use the array to write two different multiplication facts.

Answer:
The number of rows is 4, the number of columns = 7.
7 x 4 = 28.
4 x 7 = 28.

Explanation:
In the above-given question,
given that,
the array contains the number of rows and number of columns.
The number of rows is 4, the number of columns = 7.
7 x 4 = 28.
4 x 7 = 28.

Question 2.
Karen says, “If I know 3 × 8 = 24, then I know the answer to 8 × 3.” Explain why this is true.

Answer:
3 x 8 = 24.
8 x 3 = 24.

Explanation:
In the above-given question,
given that,
3 x 8 = 24.
8 x 3 = 24.
24 = 24.

Eureka Math Grade 3 Module 3 Lesson 1 Homework Answer Key

Question 1.
Complete the charts below.
a. A tricycle has 3 wheels.

Answer:
The number of tricycles is 3, the total number of wheels = 9.
The number of tricycles is 4, the total number of wheels = 12.
The number of tricycles is 5, the total number of wheels = 15.
The number of tricycles is 6, the total number of wheels = 18.
The number of tricycles is 7, the total number of wheels = 21.

Explanation:
In the above-given question,
given that,
A tricycle has 3 wheels.
The number of tricycles is 3, the total number of wheels = 9.
The number of tricycles is 4, the total number of wheels = 12.
The number of tricycles is 5, the total number of wheels = 15.
The number of tricycles is 6, the total number of wheels = 18.
The number of tricycles is 7, the total number of wheels = 21.

b. A tiger has 4 legs.
Number of Tigers

Answer:
The number of tigers is 5, the total number of legs = 20.
The number of tigers is 6, the total number of legs = 24.
The number of tigers is 7, the total number of legs = 28.
The number of tigers is 8, the total number of legs = 32.
The number of tigers is 9, the total number of legs = 36.

Explanation:
In the above-given question,
given that,
A tiger has 4 legs.
The number of tigers is 5, the total number of legs = 20.
The number of tigers is 6, the total number of legs = 24.
The number of tigers is 7, the total number of legs = 28.
The number of tigers is 8, the total number of legs = 32.
The number of tigers is 9, the total number of legs = 36.

c. A package has 5 erasers.
Number of Packages 6

Answer:
The number of packages is 6, the total number of Erasers = 30.
The number of packages is 7, the total number of Erasers = 35.
The number of packages is 8, the total number of Erasers = 40.
The number of packages is 9, the total number of Erasers = 45.
The number of packages is 10, the total number of Erasers = 50.

Explanation:
In the above-given question,
given that,
A package has 5 erasers.
the number of packages = 6.
The number of packages is 6, the total number of Erasers = 30.
The number of packages is 7, the total number of Erasers = 35.
The number of packages is 8, the total number of Erasers = 40.
The number of packages is 9, the total number of Erasers = 45.
The number of packages is 10, the total number of Erasers = 50.

Question 2.
Write two multiplication facts for each array.

Answer:
The number of rows is 4, the number of columns = 6.
6 x 4 = 24.
4 x 6 = 24.

Explanation:
In the above-given question,
given that,
the array contains the number of rows and number of columns.
The number of rows is 4, the number of columns = 6.
6 x 4 = 24.
4 x 6 = 24.

Answer:
The number of rows is 3, the number of columns = 8.
3 x 8 = 24.
8 x 3 = 24.

Explanation:
In the above-given question,
given that,
the array contains the number of rows and number of columns.
The number of rows is 3, the number of columns = 8.
3 x 8 = 24.
8 x 3 = 24.

Question 3.
Match the expressions.

Answer:
The expressions 3 x 6 = 6 x 3.
3 sevens = 7 threes.
2 eights = 8 x 2.
5 x 9 = 9 x 5.
10 twos = 2 x 10.

Explanation:
In the above-given question,
given that,
The expressions 3 x 6 = 6 x 3.
3 sevens = 7 threes.
2 eights = 8 x 2.
5 x 9 = 9 x 5.
10 twos = 2 x 10.

Question 4.
Complete the equations.

a. 2 sixes = ___six___ twos
= ____12___

Answer:
2 sixes = six twos.
12 = 12.

Explanation:
In the above-given question,
given that,
2 sixes = six twos.
12 = 12.

b. ___3__ × 6 = 6 threes
= ____18___

Answer:
3 x 6 = 6 x 3.
18 = 18.

Explanation:
In the above-given question,
given that,
3 x 6 = 6 x3.
18 = 18.

c. 4 × 8 = _8____ × 4
= __32_____

Answer:
4 x 8 = 8 x 4.
32 = 32.

Explanation:
In the above-given question,
given that,
4 x 8 = 8 x 4.
32 = 32.

d. 4 × _8____ = _8____ × 4
= ___32____

Answer:
4 x 8 = 8 x 4.
32 = 32.

Explanation:
In the above-given question,
given that,
4 x 8 = 8 x 4.
32 = 32.

e. 5 twos + 2 twos = _7____ × ___2__
= __14_____

Answer:
5 twos + 2 twos = 14.

Explanation:
In the above-given question,
given that,
5 twos + 2 twos = 7 x 2.
10 + 4 = 14.
14 = 14.

f. __5___ fives + 1 five = 6 × 5
= ____30___

Answer:
5 fives + 1 five.
30 = 30.

Explanation:
In the above-given question,
given that,
5 fives + 1 five = 6 x 5.
25 + 5 = 30.
30 = 30.