Eureka Math

Eureka Math Answer Key for Grade 3 aids teachers to differentiate instruction, building, and reinforcing foundational mathematics skills that alter from the classroom to real life.
With the help of the Eureka Primary School Grade 3 Answer Key, You can think deeply regarding what you are learning, and you will really learn math easily just like that. So teachers and students can find this Eureka Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students.

Engage NY Eureka Math 3rd Grade Module 4 Lesson 10 Answer Key

Students of Grade 3 can get a strong foundation on mathematics concepts by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka’s Math Grade 3 Book.

Eureka Math Grade 3 Module 4 Lesson 10 Problem Set Answer Key

Question 1.
Label the side lengths of the shaded and unshaded rectangles when needed. Then, find the total area of the large rectangle by adding the areas of the two smaller rectangles.
a.

8 × 7 = (5 + 3) × 7
= (5 × 7) + (3 × 7)
= ___35___ + ___21___
= __56____
Area: ___56___ square units

Answer:
The area of the larger rectangle = 56 sq unit.
the area of the small rectangle A = 35 sq unit.
the area of the small rectangle B = 21 sq unit.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 56 sq unit.
area = length x breadth.
area = l x b.
area = 8 x 7.
area = 56.
the area of the rectangle A = 35 sq unit.
area = length x breadth.
area = l x b.
area = 5 x 7.
area = 35.
the area of the rectangle B = 21 sq unit.
area = length x breadth.
area = l x b.
area = 3 x 7.
area = 21.

b.

12 × 4 = (___10___ + 2) × 4
= (__10____ × 4) + (2 × 4)
= ___40___ + 8
= ___48___
Area: __48____ square units

Answer:
The area of the larger rectangle = 48 sq unit.
the area of the small rectangle A = 40 sq unit.
the area of the small rectangle B = 8 sq unit.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 48 sq unit.
area = length x breadth.
area = l x b.
area = 12 x 4.
area = 48.
the area of the rectangle A = 40 sq unit.
area = length x breadth.
area = l x b.
area = 10 x 4.
area = 40.
the area of the rectangle B = 8 sq unit.
area = length x breadth.
area = l x b.
area = 2 x 4.
area = 8.

c.

6 × 13 = 6 × (___10___ + 3)
= (6 ×___10___) + (6 × 3)
= __60____ + ___18___
= ___78___
Area: __78____ square units

Answer:
The area of the larger rectangle = 78 sq unit.
the area of the small rectangle A = 60 sq unit.
the area of the small rectangle B = 18 sq unit.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 78 sq unit.
area = length x breadth.
area = l x b.
area = 6 x 13.
area = 78.
the area of the rectangle A = 60 sq unit.
area = length x breadth.
area = l x b.
area = 10 x 6.
area = 60.
the area of the rectangle B = 8 sq unit.
area = length x breadth.
area = l x b.
area = 6 x 3.
area = 18.

d.

8 × 12 = 8 × (___10___ + ___2___)
= (8 × __10____) + (8 × ___2___)
= ___80___ + __16____
= __96____
Area: __96____ square units

Answer:
The area of the larger rectangle = 96 sq unit.
the area of the small rectangle A = 80 sq unit.
the area of the small rectangle B = 16 sq unit.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 96 sq unit.
area = length x breadth.
area = l x b.
area = 8 x 12.
area = 96.
the area of the rectangle A = 80 sq unit.
area = length x breadth.
area = l x b.
area = 10 x 8.
area = 80.
the area of the rectangle B = 16 sq unit.
area = length x breadth.
area = l x b.
area = 8 x 2.

Question 2.
Vince imagines 1 more row of eight to find the total area of a 9 × 8 rectangle. Explain how this could help him solve 9 × 8.

Answer:
The area of the rectangle = 72 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = length and b = breadth.
area = 9 x 8.
area = 72 sq cm.
so the area of the rectangle = 72 sq cm.

Question 3.
Break the 15 × 5 rectangle into 2 rectangles by shading one smaller rectangle within it. Then, find the sum of the areas of the 2 smaller rectangles and show how it relates to the total area. Explain your thinking.

Answer:
The area of the rectangle = 40 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = length and b = breadth.
area = 5 x 8.
area = 40 sq cm.
so the area of the rectangle = 40 sq cm.

Answer:
The area of the rectangle = 35 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = length and b = breadth.
area = 5 x 7.
area = 35 sq cm.
so the area of the rectangle = 35 sq cm.

Eureka Math Grade 3 Module 4 Lesson 10 Exit Ticket Answer Key

Label the side lengths of the shaded and unshaded rectangles. Then, find the total area of the large rectangle by adding the areas of the 2 smaller rectangles.

Question 1.

8 × 7 = 8 × (___5___ + __2____)
= (8 ×___5___) + (8 ×___2___)
= __40____ + __16____
= ___56___
Area: __56____ square units

Answer:
The area of the larger rectangle = 56 sq unit.
the area of the small rectangle A = 40 sq unit.
the area of the small rectangle B = 16 sq unit.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 56 sq unit.
area = length x breadth.
area = l x b.
area = 8 x 7.
area = 56.
the area of the rectangle A = 40 sq unit.
area = length x breadth.
area = l x b.
area = 8 x 5.
area = 40.
the area of the rectangle B = 16 sq unit.
area = length x breadth.
area = l x b.
area = 8 x 2.
area = 16.

Question 2.

9 × 13 = 9 × (___10___+___3___)
= (___9___ × ___10___) + (__9____×___3___)
= __90____ + ___27___
= __117____
Area: ___117___ square units

Answer:
The area of the larger rectangle = 117 sq unit.
the area of the small rectangle A = 90 sq unit.
the area of the small rectangle B = 27 sq unit.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 117 sq unit.
area = length x breadth.
area = l x b.
area = 9 x 13.
area = 117.
the area of the rectangle A = 90 sq unit.
area = length x breadth.
area = l x b.
area = 9 x 10.
area = 90.
the area of the rectangle B = 27 sq unit.
area = length x breadth.
area = l x b.
area = 9 x 3.
area = 27.

Eureka Math Grade 3 Module 4 Lesson 10 Homework Answer Key

Question 1.
Label the side lengths of the shaded and unshaded rectangles. Then, find the total area of the large rectangle by adding the areas of the 2 smaller rectangles.
a.

9 × 8 = (5 + 4) × 8
= (5 × 8) + (4 × 8)
= ___40___ + __32____
= __72____
Area: ___72___ square units

Answer:
The area of the larger rectangle = 72 sq unit.
the area of the small rectangle A = 40 sq unit.
the area of the small rectangle B = 32 sq unit.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 78 sq unit.
area = length x breadth.
area = l x b.
area = 9 x 8.
area = 72.
the area of the rectangle A = 40 sq unit.
area = length x breadth.
area = l x b.
area = 5 x 8.
area = 40.
the area of the rectangle B = 32 sq unit.
area = length x breadth.
area = l x b.
area = 4 x 8.
area = 32.

b.

12 × 5 = (__10____ + 2) × 5
= (___10___ × 5) + (2 × 5)
= ___50___ + 10
= ___60___
Area: __60____ square units

Answer:
The area of the larger rectangle = 60 sq unit.
the area of the small rectangle A = 50 sq unit.
the area of the small rectangle B = 10 sq unit.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 60 sq unit.
area = length x breadth.
area = l x b.
area = 12 x 5.
area = 60.
the area of the rectangle A = 50 sq unit.
area = length x breadth.
area = l x b.
area = 10 x 5.
area = 50.
the area of the rectangle B = 10 sq unit.
area = length x breadth.
area = l x b.
area = 2 x 5.
area = 10.

c.

7 × 13 = 7 × (___10___+ 3)
= (7 × ___10___) + (7 × 3)
= __70____ + __21____
= __91____
Area: __91____ square units

Answer:
The area of the larger rectangle = 91 sq unit.
the area of the small rectangle A = 70 sq unit.
the area of the small rectangle B = 21 sq unit.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 91 sq unit.
area = length x breadth.
area = l x b.
area = 7 x 13.
area = 91.
the area of the rectangle A = 70 sq unit.
area = length x breadth.
area = l x b.
area = 7 x 10.
area = 70.
the area of the rectangle B = 21 sq unit.
area = length x breadth.
area = l x b.
area = 7 x 3.
area = 21.

d.

9 × 12 = 9 × (___10___ + __2____)
= (9 × ___10___) + (9 × __2____)
= __90____ + ___18___
= __108____
Area: __108____ square units

Answer:
The area of the larger rectangle = 108 sq unit.
the area of the small rectangle A = 90 sq unit.
the area of the small rectangle B = 18 sq unit.

Explanation:
In the above-given question,
given that,
the area of the larger rectangle = 108 sq unit.
area = length x breadth.
area = l x b.
area = 9 x 12.
area = 108.
the area of the rectangle A = 90 sq unit.
area = length x breadth.
area = l x b.
area = 9 x 10.
area = 90.
the area of the rectangle B = 18 sq unit.
area = length x breadth.
area = l x b.
area = 9 x 2.
area = 18.

Question 2.
Finn imagines 1 more row of nine to find the total area of 9 × 9 rectangle. Explain how this could help him solve 9 × 9.

Answer:
The area of the rectangle = 81 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = length and b = breadth.
area = 9 x 9.
area = 81 sq cm.
so the area of the rectangle = 81 sq cm.

Question 3.
Shade an area to break the 16 × 4 rectangle into 2 smaller rectangles. Then, find the sum of the areas of the 2 smaller rectangles to find the total area. Explain your thinking.

Answer:
The area of the rectangle = 40 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = length and b = breadth.
area = 10 x 4.
area = 40 sq cm.
so the area of the rectangle = 40 sq cm.

Answer:
The area of the rectangle = 24 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = length and b = breadth.
area = 6 x 4.
area = 24 sq cm.
so the area of the rectangle = 24 sq cm.

Eureka Math Grade 3 Module 4 Lesson 10 Template Answer Key

____24__sq__cm______
tiling
Answer:
The area of the rectangle = 16 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 4.
area = 16 sq cm.
so the area of the rectangle = 16 sq cm.

Answer:
The area of the rectangle = 8 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 2.
area = 8 sq cm.
so the area of the rectangle = 8 sq cm.

Fun learning activities are the best option to educate primary school students and make them understand the basic mathematical concepts like addition, subtraction, multiplication, division, etc. Grade 3 primary school students can find these fun-learning exercises for all math concepts through the Eureka Math Answers Grade 3 Common Core Curriculum.

Engage NY Eureka Math 3rd Grade Module 4 Lesson 9 Answer Key

You may have diverse opportunities to develop math skills and problem-solving skills but practicing with Eureka Math 3rd Grade Answer Key for better and efficient learning. Eureka Math Grade 3 provided Free Access Student Edition of Eureka Math Grade 3 Answers are enough to practice more and get a good grip on the subject. The diverse opportunities will develop problem-solving skills among the primary school kids Practising.

Eureka Math Grade 3 Module 4 Lesson 9 Problem Set Answer Key

Question 1.
Cut the grid into 2 equal rectangles.
a. Draw and label the side lengths of the 2 rectangles.

Answer:
The side lengths of the two rectangles = 4 x 4 and 4 x 4.

Explanation:
In the above-given question,
given that,
cut the grid into two equal rectangles.
area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 4.
area = 16.
so the side lengths of 2 rectangles = 4 x 4.

b. Write an equation to find the area of 1 of the rectangles.

Answer:
The area of the 1 of the rectangle = length x breadth.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = l x b.

c. Write an equation to show the total area of the 2 rectangles.

Answer:
The total area of the 2 rectangles = 16 sq cms.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 4.
area = 16.

Question 2.
Place your 2 equal rectangles side by side to create a new, longer rectangle.
a. Draw an area model to show the new rectangle. Label the side lengths.

Answer:

The side lengths of the two rectangles = 4 cm x 8 cm.

Explanation:
In the above-given question,
given that,
cut the grid into two equal rectangles.
area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 8.
area = 32.
so the side lengths of 2 rectangles = 4 x 8.

b. Find the total area of the longer rectangle.

Answer:
The total area of the longer rectangle = 32 sq cms.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 8.
area = 32 sq cms.

Question 3.
Furaha and Rahema use square tiles to make the rectangles shown below.

a. Label the side lengths on the rectangles above, and find the area of each rectangle.

Answer:
The side length of the Rahema rectangle = 4 cms x 6 cms.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 6.
area = 24.

Answer:
The side length of the Rahema rectangle = 4 cms x 7 cms.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 7.
area = 28.

b. Furaha pushes his rectangle next to Rahema’s rectangle to form a new, longer rectangle. Draw an area model to show the new rectangle. Label the side lengths.

Answer:
The side length of the Rahema rectangle = 4 cms x 8 cms.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 8.
area = 32.

c. Rahema says the area of the new, longer rectangle is 52 square units. Is she right? Explain your answer.

Answer:
No, she was not correct.

Explanation:

given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 8.
area = 32.
so the area of the rectangle = 32 sq units.

Question 4.
Kiera says she can find the area of the long rectangle below by adding the areas of Rectangles A and B. Is she right? Why or why not?

Answer:
Yes, she was correct.

Explanation:
In the above-given question,
given that,
Kiera says that she can find the area of the long rectangle below by adding the areas of the rectangles A and B.
area = l x b.
area of the rectangles A + B = rectangle C.
so she was correct.

Eureka Math Grade 3 Module 4 Lesson 9 Exit Ticket Answer Key

Lamar uses square tiles to make the 2 rectangles shown below.

Question 1.
Label the side lengths of the 2 rectangles.

Answer:
The side lengths of rectangle A = 6 cm x 6 cm.
the side lengths of  rectangle B = 6 cm x 3 cm.

Explanation:
In the above-given question,
given that,
area of the rectangle A = l x b.
where l = length and b = breadth.
area = 6 x 6.
area of the rectangle B = l x b.
where l = length and b = breadth.
area = 6 x 3.

Question 2.
Write equations to find the areas of the rectangles.
Area of Rectangle A: ______36_sq__cm______
Area of Rectangle B: ___18__sq__cm________

Answer:
The area of rectangle A = 36 sq cm.
the area of rectangle B = 18 sq cm.

Explanation:
In the above-given question,
given that,
area of the rectangle A = l x b.
where l = length and b = breadth.
area = 6 x 6.
area = 36 sq cm.
area of the rectangle B = l x b.
where l = length and b = breadth.
area = 6 x 3.
area = 18 sq cm.

Question 3.
Lamar pushes Rectangle A next to Rectangle B to make a bigger rectangle. What is the area of the bigger rectangle? How do you know?

Answer:
The area of the bigger rectangle = 6 cms x 9 cms.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 6 x 9.
area = 54.
so the area of the bigger rectangle = 54 sq cms.

Eureka Math Grade 3 Module 4 Lesson 9 Homework Answer Key

Question 1.
Use the grid to answer the questions below.

a. Draw a line to divide the grid into 2 equal rectangles. Shade in 1 of the rectangles that you created.

Answer:
The area of the rectangle = 32 sq cms.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 8 x 4.
area = 32 sq cm.

b. Label the side lengths of each rectangle.

Answer:
The side lengths of rectangle A = 8 cm x 4 cm.
the side lengths of rectangle B = 8 cm x 4 cm.

Explanation:
In the above-given question,
given that,
area of the rectangle A = l x b.
where l = length and b = breadth.
area = 8 x 4.
area = 32 sq cm.
area of the rectangle B = l x b.
where l = length and b = breadth.
area = 8 x 4.
area = 32 sq cm.

c. Write an equation to show the total area of the 2 rectangles.

Answer:
The area of rectangle A = 32 sq cm.
the area of rectangle B = 32 sq cm.

Explanation:
In the above-given question,
given that,
area of the rectangle A = l x b.
where l = length and b = breadth.
area = 8 x 4.
area = 32 sq cm.
area of the rectangle B = l x b.
where l = length and b = breadth.
area = 8 x 4.
area = 32 sq cm.

Question 2.
Alexa cuts out the 2 equal rectangles from Problem 1(a) and puts the two shorter sides together.
a. Draw Alexa’s new rectangle and label the side lengths below.

Answer:
The side lengths of the new rectangle = 4 cm x 4cm.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 4.
area = 16 sq cm.

b. Find the total area of the new, longer rectangle.

Answer:
The area of the new rectangle = 16 sq cm.

Explanation:
In the above-given question,
given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 4 x 4.
area = 16 sq cm.

c. Is the area of the new, longer rectangle equal to the total area in Problem 1(c)? Explain why or why not.

Answer:
No, the longer rectangle does not equal the total area in the problem.

Explanation:
In the above-given question,
given that,
the area of the longer rectangle = l x b.
where l = length and b = breadth.
area = 4 x 4.
area = 16 sq cm.

Eureka Math Grade 3 Module 4 Lesson 9 Template Answer Key

________64_sq_cm.____
small centimeter grid

Answer:
The area of the rectangle = 64 sq cm.

Explanation:

given that,
area of the rectangle = l x b.
where l = length and b = breadth.
area = 8 x 8.
area = 64.
so the area of the rectangle = 64 sq cm.

Teachers and students can find this Eureka Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Eureka Math Answer Key for Grade 3 aids teachers to differentiate instruction, building and reinforcing foundational mathematics skills that alter from the classroom to real life. With the help of Eureka’s primary school Grade 3 Answer Key, you can think deeply regarding what you are learning, and you will really learn math easily just like that.

Engage NY Eureka Math 3rd Grade Module 4 Lesson 8 Answer Key

Students of Grade 3 Module 4 can get a strong foundation on mathematics concepts by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka’s Grade 3 Textbook.

Eureka Math Grade 3 Module 4 Lesson 8 Pattern Sheet Answer Key

Multiply

Answer:
6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 6 x 9 = 54, 6 x 10 = 60, 6 x 5 = 30, 6 x 6 = 36, 6 x 5 = 30, 6 x 7 = 42, 6 x 5 = 30, 6 x 8 = 48, 6 x 5 = 30, 6 x 9 = 54, 6 x 5 = 30, 6 x 10 = 60, 6 x 6 = 36, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 6 = 36, 6 x 8 = 48, 6 x 6 = 36, 6 x 9 = 54, 6 x 6 = 36, 6 x 7 = 42, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 6 x 7 = 42, 6 x 9 = 54, 6 x 7 = 42, 6 x 8 = 48, 6 x 6 = 36, 6 x 8 = 48, 6 x 7 = 42, 6 x 8 = 48, 6 x 9 = 54, 6 x 9 = 54, 6 x 6 = 36, 6 x 9 = 54, 6 x 7 = 42, 6 x 9 = 54, 6 x 8 = 48, 6 x 9 = 54, 6 x 8 = 48, 6 x 6 = 36, 6 x 9 = 54, 6 x 7 = 42, 6 x 9 = 54, 6 x 6 = 36, 6 x 8 = 48, 6 x 9 = 54, 6 x 7 = 42, 6 x 6 = 36, 6 x 8 = 48.

Explanation:
In the above-given question,
given that,
multiply with 6.
6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 6 x 9 = 54, 6 x 10 = 60, 6 x 5 = 30, 6 x 6 = 36, 6 x 5 = 30, 6 x 7 = 42, 6 x 5 = 30, 6 x 8 = 48, 6 x 5 = 30, 6 x 9 = 54, 6 x 5 = 30, 6 x 10 = 60, 6 x 6 = 36, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 6 = 36, 6 x 8 = 48, 6 x 6 = 36, 6 x 9 = 54, 6 x 6 = 36, 6 x 7 = 42, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 6 x 7 = 42, 6 x 9 = 54, 6 x 7 = 42, 6 x 8 = 48, 6 x 6 = 36, 6 x 8 = 48, 6 x 7 = 42, 6 x 8 = 48, 6 x 9 = 54, 6 x 9 = 54, 6 x 6 = 36, 6 x 9 = 54, 6 x 7 = 42, 6 x 9 = 54, 6 x 8 = 48, 6 x 9 = 54, 6 x 8 = 48, 6 x 6 = 36, 6 x 9 = 54, 6 x 7 = 42, 6 x 9 = 54, 6 x 6 = 36, 6 x 8 = 48, 6 x 9 = 54, 6 x 7 = 42, 6 x 6 = 36, 6 x 8 = 48.

Eureka Math Grade 3 Module 4 Lesson 8 Problem Set Answer Key

Question 1.
Write a multiplication equation to find the area of each rectangle.
a.

__7_____ × ____4___ = ___28_sqft___

Answer:
The area of the rectangle = 28 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 7.
area = 4 x 7.
area = 28.

b.

__8_____ × ____7___ = ___56___

Answer:
The area of the rectangle = 56 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 8 and b = 7.
area = 8 x 7.
area = 56.

c.

___6____ × ___6____ = ___36___

Answer:
The area of the rectangle = 36 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 6.
area = 6 x 6.
area = 36.

Question 2.
Write a multiplication equation and a division equation to find the unknown side length for each rectangle.

a.

___9____ × __8_____ = __72____
____72___ ÷ __9_____ = ___8____

Answer:
The unknown side length of the rectangle = 8 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 72 and b = 8.
72 = l x 8.
l = 8 x 9 = 72.
l = 72/9 = 8.

b.

___5____ × ___3____ = ___15___
___15____ ÷ ____5___ = ___3____

Answer:
The unknown side length of the rectangle = 5 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 15 and b = 3.
15 = l x 3.
l = 15 / 3 = 5.

c.

___4____ × ____7___ = ___28___
___28____ ÷ ____4___ = ___7____

Answer:
The unknown side length of the rectangle = 7 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 28 and l = 4.
28 = b x 4.
b = 28 / 4 = 7.

Question 3.
On the grid below, draw a rectangle that has an area of 42 square units. Label the side lengths.

Answer:
The area of the rectangle = 42 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 42 and b = 6.
42 = l x 6.
l = 42 / 6 = 7.

Question 4.
Ursa draws a rectangle that has side lengths of 9 centimeters and 6 centimeters. What is the area of the rectangle? Explain how you found your answer.

Answer:
The area of the rectangle = 56 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 9 and b = 6.
area = 9 x 6.
area = 54.

Question 5.
Eliza’s bedroom measures 6 feet by 7 feet. Her brother’s bedroom measures 5 feet by 8 feet. Eliza says their rooms have the same exact floor area. Is she right? Why or why not?

Answer:
No, their rooms do not have the same exact floor area.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 7.
area = 6 x 7.
area = 42.
the area of the rectangle = l x b.
where l = 5 and b = 8.
area = 5 x 8.
area = 40.

Question 6.
Cliff draws a rectangle with a side length of 6 inches and an area of 24 square inches. What is the other side length? How do you know?

Answer:
The unknown side length of the rectangle = 4 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 24 and l = 6.
24 = b x 6.
b = 24 / 6 = 4.

Eureka Math Grade 3 Module 4 Lesson 8 Exit Ticket Answer Key

Question 1.
Write a multiplication equation to find the area of the rectangle below.

___9___ × ___3____ = ___27___

Answer:
The area of the rectangle = 27 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 9 and b = 3.
area = 9 x 3.
area = 27.

Question 2.
Write a multiplication equation and a division equation to find the unknown side length for the rectangle below.

___6____ × ___9____ = ___54___
__54_____ ÷ ___6____ = ____9___

Answer:
The unknown side length of the rectangle = 9 sq in.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 54 and b = 6.
54 = l x 6.
l = 54 / 6 = 9.

Eureka Math Grade 3 Module 4 Lesson 8 Homework Answer Key

Question 1.
Write a multiplication equation to find the area of each rectangle.
a.

___3____ × ___8____ = ___24___

Answer:
The area of the rectangle = 24 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 8 and b = 3.
area = 8 x 3.
area = 24.

b.

____8___ × ___6____ = ___48___

Answer:
The area of the rectangle = 48 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 8 and b = 6.
area = 8 x 6.
area = 48.

c.

____4___ × ____4___ = ___16___

Answer:
The area of the rectangle = 16 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 4.
area = 4 x 4.
area = 16.

d.

___7____ × ____4___ = ___28___

Answer:
The area of the rectangle = 28 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 7 and b = 4.
area = 7 x 4.
area = 28.

Question 2.
Write a multiplication equation and a division equation to find the unknown side length for each rectangle.
a.

__8_____ × ___3____ = __24____
__24_____ ÷ __3_____ = ___8____

Answer:
The unknown side length of the rectangle = 8 sq in.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 24 and b = 3.
24 = l x 3.
l = 24 / 3 = 8.

b.

____9___ × __4_____ = ____36__
___36____ ÷ ___9____ = ___4____

Answer:
The unknown side length of the rectangle = 4 sq ft.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 36 and l = 9.
36 = b x 9.
b = 36 / 9 = 4.

Question 3.
On the grid below, draw a rectangle that has an area of 32 square centimeters. Label the side lengths.

Answer:
The area of the rectangle = 32 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 32 and b = 4.
32 = l x 4.
l = 32 / 4 = 8.

Question 4.
Patricia draws a rectangle that has side lengths of 4 centimeters and 9 centimeters. What is the area of the rectangle? Explain how you found your answer.

Answer:
The area of the rectangle = 54 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 9.
area = 4 x 9.
area = 36.

Question 5.
Charles draws a rectangle with a side length of 9 inches and an area of 27 square inches. What is the other side length? How do you know?

Answer:
The unknown side length of the rectangle = 3 sq in.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 27 and l = 9.
27 = b x 9.
b = 27 / 9 = 3.

Eureka Math Grade 3 Module 4 Lesson 8 Template Answer Key

_____27 ___sq cm__________
grid

Answer:
The unknown side length of the rectangle = 3 cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where area = 27 and l = 9.
27 = b x 9.
b = 27 / 9 = 3.

Students of Grade 3 Module 4 can get a strong foundation on mathematics concepts by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka’s Grade 3 Textbook.

Engage NY Eureka Math 3rd Grade Module 4 Lesson 7 Answer Key

Teachers and students can find this Eureka Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Eureka Math Answer Key for Grade 3 aids teachers to differentiate instruction, building and reinforcing foundational mathematics skills that alter from the classroom to real life. With the help of Eureka’s primary school Grade 3 Answer Key, you can think deeply regarding what you are learning, and you will really learn math easily just like that.

Eureka Math Grade 3 Module 4 Lesson 7 Problem Set Answer Key

Question 1.
Use a straight edge to draw a grid of equal size squares within the rectangle. Find and label the side lengths. Then, multiply the side lengths to find the area.

a. Area A:
____3____ units × ___4_____ units = ____12____ square units

Answer:
a. The area of the rectangle = 12 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 4.
area = 3 x 4.
area = 12.

b. Area B:
__5______ units × ___4_____ units = ___20_____ square units

Answer:
b. The area of the rectangle = 20 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 4.
area = 5 x 4.
area = 20.

c. Area C:
____2____ units × ___7_____ units = ___14_____ square units

Answer:
c. The area of the rectangle = 14 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 2 and b = 7.
area = 2 x 7.
area = 14.

d. Area D:
___7_____ units × ___4_____ units = ___28_____ square units

Answer:
d. The area of the rectangle = 28 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 7 and b = 4.
area = 7 x 4.
area = 28.

e. Area E:
___1_____ units × ___3_____ units = ___3_____ square units

Answer:
e. The area of the rectangle = 30 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 6.
area = 5 x 6.
area = 30.

f. Area F:
___4_____ units × ___2_____ units = ___8_____ square units

Answer:
f. The area of the rectangle = 8 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 2.
area = 4 x 2.
area = 8.

Question 2.
The area of Benjamin’s bedroom floor is shown on the grid to the right. Each represents 1 square foot. How many total square feet is Benjamin’s floor?

a. Label the side lengths.

Answer:
a. The side lengths of the rectangle = 9 x 11.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 9 and b = 11.
area = 9 x 11.
area = 99.

b. Use a straight edge to draw a grid of equal size squares within the rectangle.

Answer:
b. The area of the rectangle = 99 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 9 and b = 11.
area = 9 x 11.
area = 11.

c. Find the total number of squares.

Answer:
c. The area of the rectangle = 99 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 9 and b = 11.
area = 9 x 11.
area = 99.

Question 3.
Mrs. Young’s art class needs to create a mural that covers exactly 35 square feet. Mrs. Young marks the area for the mural as shown on the grid. Each represents 1 square foot. Did she mark the area correctly? Explain your answer.

Answer:
No, she did not mark the area correctly.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 7 and b = 6.
area = 7 x 6.
area = 42 square feet.

Question 4.
Mrs. Barnes draws a rectangular array. Mila skip-counts by fours and Jorge skip-counts by sixes to find the total number of square units in the array. When they give their answers, Mrs. Barnes says that they are both right.
a. Use pictures, numbers, and words to explain how Mila and Jorge can both be right.

Answer:
The area of the rectangular array = 24 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 6.
area = 4 x 6.
area = 24.

b. How many square units might Mrs. Barnes’ array have had?

Answer:
The area of the rectangular array = 24 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 6.
area = 4 x 6.
area = 24.

Eureka Math Grade 3 Module 4 Lesson 7 Exit Ticket Answer Key

Question 1.
Label the side lengths of Rectangle A on the grid below. Use a straight edge to draw a grid of equal size squares within Rectangle A. Find the total area of Rectangle A.

Area: ___36_____ square units

Answer:
The area of the rectangular array = 36 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 6.
area = 6 x 6.
area = 36.

Question 2.
Mark makes a rectangle with 36 square centimeter tiles. Gia makes a rectangle with 36 square inch tiles. Whose rectangle has a bigger area? Explain your answer.

Answer:
The Gia rectangle has a bigger area.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 6.
area = 6 x 6.
area = 36.

Eureka Math Grade 3 Module 4 Lesson 7 Homework Answer Key

Question 1.
Find the area of each rectangular array. Label the side lengths of the matching area model, and write a multiplication equation for each area model.

Answer:
a.The area of the rectangular array = 6 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 2.
area = 3 x 2.
area = 6.

Answer:
b.The area of the rectangular array = 10 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 2 and b = 5.
area = 2 x 5.
area = 10.

Answer:
c.The area of the rectangular array = 12 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 4.
area = 3 x 4.
area = 12.

Answer:
d.The area of the rectangular array = 16 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 4.
area = 4 x 4.
area = 16.

Question 2.
Jillian arranges square pattern blocks into a 7 by 4 array. Draw Jillian’s array on the the grid below. How many square units are in Jillian’s rectangular array?
a.

Answer:
The area of the rectangular array = 28 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 7 and b = 4.
area = 7 x 4.
area = 28.

b. Label the side lengths of Jillian’s array from Part (a) on the rectangle below. Then, write a multiplication sentence to represent the area of the rectangle.

Answer:
The area of the rectangular array = 28 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 6.
area = 7 x 4.
area = 28.

Question 3.
Fiona draws a 24 square centimeter rectangle. Gregory draws a 24 square inch rectangle. Whose rectangle is larger in area? How do you know?

Answer:
Gregory’s rectangle is larger in area.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 4.
area = 6 x 4.
area = 24.

Eureka Math Grade 3 Module 4 Lesson 7 Template Answer Key

____8__sq__inches_______
area of model

Answer:
The area of the rectangular array = 8 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 2.
area = 4 x 2.
area = 8.

Teachers and students can find this Eureka Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Eureka Math Answer Key for Grade 3 aids teachers to differentiate instruction, building and reinforcing foundational mathematics skills that alter from the classroom to real life. With the help of Eureka’s primary school Grade 3 Answer Key, you can think deeply regarding what you are learning, and you will really learn math easily just like that.

Engage NY Eureka Math 3rd Grade Module 4 Lesson 6 Answer Key

Students of Grade 3 Module 4 can get a strong foundation on mathematics concepts by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka’s Grade 3 Textbook.

Eureka Math Grade 3 Module 4 Lesson 6 Problem Set Answer Key

Question 1.
Each represents 1 square centimeter. Draw to find the number of rows and columns in each array. Match it to its completed array. Then, fill in the blanks to make a true equation to find each array’s area.

Answer:
a. The area of the rectangle = 30 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 6.
area = 5 x 6.
area = 30.

Answer:
b. The area of the rectangle = 21 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 7.
area = 3 x 7.
area = 21.

Answer:
c. The area of the rectangle = 15 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 5.
area = 3 x 5.
area = 15.

Answer:
d. The area of the rectangle = 20 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 4.
area = 5 x 4.
area = 20.

Answer:
e. The area of the rectangle = 12 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 2 and b = 6.
area = 2 x 6.
area = 12.

Answer:
The area of the rectangle = 12 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 3.
area = 4 x 3.
area = 12.

Question 2.
Sheena skip-counts by sixes to find the total square units in the rectangle below. She says there are 42 square units. Is she right? Explain your answer.

Answer:
No, she was not correct.

Explanation:
In the above-given question,
given that,
Sheena skip-count by sixes to find the total square units in the rectangle below.
she says there are 42 square units.
6 x 8 = 48.
No, she was not correct.

Question 3.
The tile floor in Brandon’s living room has a rug on it as shown below. How many square tiles are on the floor, including the tiles under the rug?

Answer:
The number of square tiles on the floor = 90.

Explanation:
In the above-given question,
given that,
The tile floor in Brandon’s living room has a rug on it as shown below.
9 x 10 = 90
the area of the rectangle = l x b.
where l = 9 and b = 10.
area = 9 x 10.
area = 90.

Question 4.
Abdul is creating a stained glass window with square inch glass tiles as shown below. How many more square inch glass tiles does Abdul need to finish his glass window? Explain your answer.

Answer:
The area of the rectangle = 30 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 5.
area = 6 x 5.
area = 30.
so the area of the rectangle = 30 sq inches.

Eureka Math Grade 3 Module 4 Lesson 6 Exit Ticket Answer Key

The tiled floor in Cayden’s dining room has a rug on it as shown below. How many square tiles are on the floor, including the tiles under the rug?

Answer:
The area of the rectangle = 80 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 8 and b = 10.
area = 8 x 10
area = 80.
so the area of the rectangle = 80 sq cms.

Eureka Math Grade 3 Module 4 Lesson 6 Homework Answer Key

Question 1.
Each represents 1 square centimeter. Draw to find the number of rows and columns in each array. Match it to its completed array. Then, fill in the blanks to make a true equation to find each array’s area.

Answer:
a. The area of the rectangle = 36 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 6.
area = 6 x 6.
area = 36.

Answer:
b. The area of the rectangle = 24 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 8.
area = 3 x 8.
area = 24.

Answer:
c. The area of the rectangle = 18 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 6.
area = 3 x 6.
area = 18.

Answer:
d. The area of the rectangle = 25 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 5.
area = 5 x 5.
area = 25.

Answer:
e. The area of the rectangle = 16 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 2 and b = 8.
area = 2 x 8.
area = 16.

Answer:
f. The area of the rectangle = 36 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 3.
area = 4 x 3.
area = 12.

Question 2.
Minh skip-counts by sixes to find the total square units in the rectangle below. She says there are 36 square units. Is she correct? Explain your answer.

Answer:
Yes, she was correct.

Explanation:
In the above-given question,
given that,
the number of rows = 6.
the number of columns = 6.
area of the rectangle = l x b.
where l = 6 and b = 6.
area = 6 x 6.
area = 36.

Question 3.
The tub in Paige’s bathroom covers the tile floor as shown below. How many square tiles are on the floor, including the tiles under the tub?

Answer:
The area of the rectangle = 90 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 9 and b = 10.
area = 9 x 10.
area = 90.

Question 4.
Frank sees a book on top of his chessboard. How many squares are covered by the book? Explain your answer.

Answer:
a. The area of the rectangle = 30 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 6.
area = 5 x 6.
area = 30.

Eureka Math Grade 3 Module 4 Lesson 6 Template 1 Answer Key

____24 sq__cms__________
array 1

Answer:
The area of the rectangle = 24 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 4.
area = 6 x 4.
area = 24.

Eureka Math Grade 3 Module 4 Lesson 6 Template 2 Answer Key

__30__sq__cms__________
array 2

Answer:
a. The area of the rectangle = 30 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 6.
area = 5 x 6.
area = 30.

Students of Grade 3 Module 4 can get a strong foundation on mathematics concepts by referring to the Eureka Math Book. It was developed by highly professional mathematics educators and the solutions prepared by them are in a concise manner for easy grasping. To achieve high scores in Grade 3, students need to solve all questions and exercises included in Eureka’s Grade 3 Textbook.

Engage NY Eureka Math 3rd Grade Module 4 Lesson 5 Answer Key

Teachers and students can find this Eureka Answer Key for Grade 3 more helpful in raising students’ scores and supporting teachers to educate the students. Eureka Math Answer Key for Grade 3 aids teachers to differentiate instruction, building and reinforcing foundational mathematics skills that alter from the classroom to real life. With the help of Eureka’s primary school Grade 3 Answer Key, you can think deeply regarding what you are learning, and you will really learn math easily just like that.

Eureka Math Grade 3 Module 4 Lesson 5 Problem Set Answer Key

Question 1.
Use the centimeter side of a ruler to draw in the tiles, and then skip-count to find the unknown area. Write a multiplication sentence for each tiled rectangle.
a. Area: 18 square centimeters.

  3    × ___6_____ =   18   

Answer:
The area of the rectangle = 18 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 6.
area = 3 x 6.
area = 18.

b. Area: __20___ square centimeters.

____5____ × ___4_____ = __20______

Answer:
The area of the rectangle = 20 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 4.
area = 5 x 4.
area = 20.

c. Area: 18 square centimeters

____3____ × ___6_____ = ____18_sq_cms__

Answer:
The area of the rectangle = 18 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 6.
area = 3 x 6.
area = 18.

d. Area: 24 square centimeters.

___8_____ × ___3_____ = __24_sq_cms___

Answer:
The area of the rectangle = 24 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 8 and b = 3.
area = 8 x 3.
area = 24.

e. Area: 20 square centimeters.

____4____ × ___5_____ = ___20_sq_cms___

Answer:
The area of the rectangle = 20 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 5.
area = 4 x 5.
area = 20.

f. Area: ___9__ square centimeters.

____3____ × ___3_____ = ___9__sq_cms__

Answer:
The area of the rectangle = 9 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 2.
area = 3 x 3.
area = 9.

Question 2.
Lindsey makes a rectangle with 35 square inch tiles. She arranges the tiles in 5 equal rows. What are the side lengths of the rectangle? Use words, pictures, and numbers to support your answer.

Answer:
The area of the rectangle = 35 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 7.
area = 5 x 7.
area = 35.

Question 3.
Mark has a total of 24 square inch tiles. He uses 18 square inch tiles to build one rectangular array. He uses the remaining square inch tiles to build a second rectangular array. Draw two arrays that Mark might have made. Then, write multiplication sentences for each.

Answer:
The area of the rectangle = 18 sq inch.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 3.
area = 6 x 3.
area = 18.

Answer:
The area of the rectangle = 6 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 2.
area = 3 x 2.
area = 6.

Question 4.
Leon makes a rectangle with 32 square centimeter tiles. There are 4 equal rows of tiles.
a. How many tiles are in each row? Use words, pictures, and numbers to support your answer.

Answer:
The area of the rectangle = 32 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 8.
area = 4 x 8.
area = 32.

b. Can Leon arrange all of his 32 square centimeter tiles into 6 equal rows? Explain your answer.

Answer:
No, he cannot arrange all of his 32 square centimeters tiles into 6 rows.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 8.
area = 4 x 8.
area = 32.

Eureka Math Grade 3 Module 4 Lesson 5 Exit Ticket Answer Key

Darren has a total of 28 square centimeter tiles. He arranges them into 7 equal rows. Draw Darren’s rectangle. Label the side lengths, and write a multiplication sentence to find the total area.

Answer:
The area of the rectangle = 28 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 7 and b = 4.
area = 7 x 4.
area = 28.

Eureka Math Grade 3 Module 4 Lesson 5 Homework Answer Key

Question 1.
Use the centimeter side of a ruler to draw in the tiles, and then skip-count to find the unknown area. Write a multiplication sentence for each tiled rectangle.
a. Area: 24 square centimeters.

  4    × ___6_____ =   24  

Answer:
The area of the rectangle = 24 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 6.
area = 4 x 6.
area = 24.

b. Area: 24 square centimeters.

____4____ × ___6_____ = __24_sq_cms____

Answer:
The area of the rectangle = 24 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 6.
area = 4 x 6.
area = 24.

c. Area: 15 square centimeters.

____3____ × ___5_____ = ___15_____

Answer:
The area of the rectangle = 15 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 5.
area = 3 x 5.
area = 15.

d. Area: 15 square centimeters.

____5____ × ____3____ = ____15____

Answer:
The area of the rectangle = 15 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 3.
area = 5 x 3.
area = 15.

Question 2.
Ally makes a rectangle with 45 square inch tiles. She arranges the tiles in 5 equal rows. How many square inch tiles are in each row? Use words, pictures, and numbers to support your answer.

Answer:
The area of the rectangle = 45 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 9.
area = 5 x 9.
area = 45.

Question 3.
Leon makes a rectangle with 36 square centimeter tiles. There are 4 equal rows of tiles.
a. How many tiles are in each row? Use words, pictures, and numbers to support your answer.

Answer:
The area of the rectangle = 36 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 9.
area = 4 x 9.
area = 36.

b. Can Leon arrange all of his 36 square centimeter tiles into 6 equal rows? Use words, pictures, and numbers to support your answer.

Answer:
Yes, Leon can arrange all of his 36 sq cm tiles into 6 equal rows.
The area of the rectangle = 36 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 6.
area = 6 x 6.
area = 36.

c. Do the rectangles in Parts (a) and (b) have the same total area? Explain how you know.

Answer:
Yes, the rectangles have the same area.
The area of the rectangle = 36 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 6.
area = 6 x 6.
area = 36.

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Engage NY Eureka Math 3rd Grade Module 4 Lesson 4 Answer Key

Grade 3 Eureka Math Answer Key is provided by subject experts as per the Common Core curriculum. Grade 3 Eureka Math Solutions provided educates the primary school Kids on all Math concepts of the chapter efficiently. Eureka Math Grade 3 Textbook Answers makes it easy for kids to Grasp the Concepts as well as solve any problem from chapter Tests, Practice Tests, Performance tests, cumulative practice, etc.

Eureka Math Grade 3 Module 4 Lesson 4 Problem Set Answer Key

Question 1.
Use a ruler to measure the side lengths of the rectangle in centimeters. Mark each centimeter with a point and connect the points to show the square units. Then, count the squares you drew to find the total area.

Total area: _____12__sq_units.___________

Answer:
The area of the rectangle = 12 sq units.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 2.
area = 6 x 2.
area = 12.

Question 2.
Use a ruler to measure the side lengths of the rectangle in inches. Mark each inch with a point and connect the points to show the square units. Then, count the squares you drew to find the total area.

Total area: _______12_sq_inches__________

Answer:
The area of the rectangle = 12 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 4.
area = 3 x 4.
area = 12.

Question 3.
Mariana uses square centimeter tiles to find the side lengths of the rectangle below. Label each side length. Then, count the tiles to find the total area.

Total area: ___12__sq_cms_____________

Answer:
The area of the rectangle = 12 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 3.
area = 4 x 3.
area = 12.

Question 4.
Each is 1 square centimeter. Saffron says that the side length of the rectangle below is 4 centimeters. Kevin says the side length is 5 centimeters. Who is correct? Explain how you know.

Answer:
Kevin says the side length is 5 centimeters.

Explanation:
In the above-given question,
given that,
5 x 4 = 20.
area = 20 cms.
Saffron was wrong.
Kevin says the side length is 5 centimeters.

Question 5.
Use both square centimeter and square inch tiles to find the area of the rectangle below. Which works best? Explain why.

Answer:
The area of the rectangle = 12 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 2.
area = 6 x 2.
area = 12.

Answer:
The area of the rectangle = 3 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 1.
area = 3 x 1.
area = 3.

Question 6.
How does knowing side lengths A and B help you find side lengths C and D on the rectangle below?

Answer:
The Opposite sides are equal in the rectangle.

Explanation:
In the above-given question,
given that,
the sidelengths AB = CD.
that means opposite sides are equal.

Eureka Math Grade 3 Module 4 Lesson 4 Exit Ticket Answer Key

Label the side lengths of each rectangle. Then, match the rectangle to its total area.

Answer:
The area of the rectangle = 6 sq cm.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 2.
area = 3 x 2.
area = 6.

Answer:
The area of the rectangle = 12 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 2.
area = 6 x 2.
area = 12.

Answer:
The area of the rectangle = 5 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 1.
area = 5 x 1.
area = 5.

Eureka Math Grade 3 Module 4 Lesson 4 Homework Answer Key

Question 1.
Ella placed square centimeter tiles on the rectangle below, and then labeled the side lengths. What is the area of her rectangle?

Total area: ____8__cm_____________

Answer:
The area of the rectangle = 8 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 2.
area = 4 x 2.
area = 8.

Question 2.
Kyle uses square centimeter tiles to find the side lengths of the rectangle below. Label each side length. Then, count the tiles to find the total area.

Total area: ______20 __sq_cms__________

Answer:
The area of the rectangle = 20 sq cms.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 4.
area = 5 x 4.
area = 20.

Question 3.
Maura uses square inch tiles to find the side lengths of the rectangle below. Label each side length. Then, find the total area.

Total area: ______14_sq__inches._________

Answer:
The area of the rectangle = 14 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 7 and b = 2.
area = 7 x 2.
area = 14.

Question 4.
Each square unit below is 1 square inch. Claire says that the side length of the rectangle below is 3 inches. Tyler says the side length is 5 inches. Who is correct? Explain how you know.

Total area: ____15_sq_inch_____________

Answer:
Yes, both of them are correct.

Explanation:
In the above-given question,
given that,
Clarie says that the side length of the rectangle below is 3 inches.
Tyler says that the side length is 5 inches.
5 x 3 = 15 inches.
area of the rectangle = 15 sq inches.

Question 5.
Label the unknown side lengths for the rectangle below, and then find the area. Explain how you used the lengths provided to find the unknown lengths and area.

Total area: _____8 _sq_inches.____________

Answer:
The area of the rectangle = 8 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 2.
area = 4 x 2.
area = 8.

Grade 3 Eureka Math Answer Key is provided by subject experts as per the Common Core curriculum. Grade 3 Eureka Math Solutions provided educates the primary school Kids on all Math concepts of the chapter efficiently. Eureka Math Grade 3 Textbook Answers makes it easy for kids to Grasp the Concepts as well as solve any problem from chapter Tests, Practice Tests, Performance tests, cumulative practice, etc.

Engage NY Eureka Math 3rd Grade Module 4 Lesson 3 Answer Key

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Eureka Math Grade 3 Module 4 Lesson 3 Problem Set Answer Key

Question 1.
Each is 1 square unit. What is the area of each of the following rectangles?

A: _________6 sq units.____________

B: ________12 sq units.__________

C: ________12 sq units.________

D: _______20 sq units._______

Answer:
The area of shape A = 6 sq units.
the area of shape B = 12 sq units.
the area of shape C = 12 sq units.
the area of shape D = 20 sq units.

Explanation:
In the above-given question,
given that,
the area of shape A = 6 sq units.
area = l x b.
where l = length and b = breadth.
3 x 2 = 6.
the area of shape B = 12 sq units.
area = l x b.
where l = length and b = breadth.
6 x 2 = 12.
the area of shape C = 12 sq units.
area = l x b.
where l = length and b = breadth.
4 x 3 = 12.
the area of shape D = 20 sq units.
area = l x b.
where l = length and b = breadth.
4 x 5 = 20.

Question 2.
Each is 1 square unit. What is the area of each of the following rectangles?
a.
________6 sq unit.________

Answer:
The area of the rectangle = 6 sq unit.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 2 and b = 3.
area = 2 x 3.
area = 6.

b.

______9 sq_units._________

Answer:
The area of the rectangle = 9 sq unit.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 3.
area = 3 x 3.
area = 9.

c.

_______16__sq __units_____

Answer:
The area of the rectangle = 16 sq unit.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 4.
area = 4 x 4.
area = 16.

d.

_______12_________

Answer:
The area of the rectangle = 12 sq unit.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 2.
area = 6 x 2.
area = 12.

Question 3.
a. How would the rectangles in Problem 1 be different if they were composed of square inches?

Answer:
Yes, they are different.

Explanation:
In the above-given question,
given that,
the rectangles in problem 1 are different.
because if it is converted into square inches.
so they are different.

b. Select one rectangle from Problem 1 and recreate it on square inch and square centimeter grid paper.

Answer:
The area of the rectangle = 16 sq unit.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 4.
area = 4 x 4.
area = 16.

Question 4.
Use a separate piece of square centimeter grid paper. Draw four different rectangles that each has an area of 8 square centimeters.

Answer:
The area of the rectangle = 8 sq unit.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 2.
area = 4 x 2.
area = 8.

Eureka Math Grade 3 Module 4 Lesson 3 Exit Ticket Answer Key

Question 1.
Each is 1 square unit. Write the area of Rectangle A. Then, draw a different rectangle with the same area in the space provided.

Answer:
The area of the rectangle = 12 sq unit.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 3.
area = 4 x 3.
area = 12.

Question 2.
Each is 1 square unit. Does this rectangle have the same area as Rectangle A? Explain.

Answer:
No, the rectangle does not have the same area as Rectangle A.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 4 and b = 4.
area = 4 x 4.
area = 16.

Eureka Math Grade 3 Module 4 Lesson 3 Homework Answer Key

Question 1.
Each is 1 square unit. What is the area of each of the following rectangles?

A: ________5__sq__units______

B: _____15 __sq__units_________

C: ____12___sq__units_________

D: ______20_sq_units__________

Answer:
The area of shape A = 5 sq units.
the area of shape B = 15 sq units.
the area of shape C = 12 sq units.
the area of shape D = 20 sq units.

Explanation:
In the above-given question,
given that,
the area of shape A = 5 sq units.
area = l x b.
where l = length and b = breadth.
1 x 5 = 5.
the area of shape B = 15 sq units.
area = l x b.
where l = length and b = breadth.
5 x 3 = 15.
the area of shape C = 12 sq units.
area = l x b.
where l = length and b = breadth.
3 x 4 = 12.
the area of shape D = 20 sq units.
area = l x b.
where l = length and b = breadth.
5 x 4 = 20.

Question 2.
Each  is 1 square unit. What is the area of each of the following rectangles?
a.

______9_sq__units_________

Answer:
The area of the rectangle = 9 sq unit.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 3.
area = 3 x 3.
area = 9.

b.

____9_sq__units___________

Answer:
The area of the rectangle = 9 sq unit.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 3.
area = 3 x 3.
area = 9.

c.

___8_sq_units._____________

Answer:
The area of the rectangle = 8 sq unit.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 2 and b = 4.
area = 2 x 4.
area = 8.

d.

_____18__sq_units__________

Answer:
The area of the rectangle = 18 sq unit.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 3.
area = 6 x 3.
area = 18.

Question 3.
Each is 1 square unit. Write the area of each rectangle. Then, draw a different rectangle with the same area in the space provided.

Answer:
The area of the rectangle A = 10 sq unit.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 5 and b = 2.
area = 5 x 2.
area = 10.

Answer:
The area of the rectangle B = 9 sq unit.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 3.
area = 3 x 3.
area = 9.

Answer:
The area of the rectangle = 12 sq unit.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 3 and b = 4.
area = 3 x 4.
area = 12.

Eureka Math Grade 3 Module 4 Lesson 3 Template 1 Answer Key

______12 cms________
centimeter grid

Answer:
The area of the rectangle = 12 sq unit.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 2.
area = 6 x 2.
area = 12.

Eureka Math Grade 3 Module 4 Lesson 3 Template 2 Answer Key

___12_sq__inch________
inch grid

Answer:
The area of the rectangle = 12 sq inches.

Explanation:
In the above-given question,
given that,
the area of the rectangle = l x b.
where l = 6 and b = 2.
area = 6 x 2.
area = 12.

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Engage NY Eureka Math 3rd Grade Module 4 Lesson 2 Answer Key

Grade 3 Eureka Math Answer Key is provided by subject experts as per the Common Core curriculum. Grade 3 Eureka Math Solutions provided educates the primary school Kids on all Math concepts of the chapter efficiently. Eureka Math Grade 3 Textbook Answers makes it easy for kids to Grasp the Concepts as well as solve any problem from chapter Tests, Practice Tests, Performance tests, cumulative practice, etc.

Eureka Math Grade 3 Module 4 Lesson 2 Pattern Sheet Answer Key

Multiply

Answer:
4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 4 x 4 = 16, 4 x 5 = 20, 4 x 6 = 24, 4 x 7 = 28, 4 x 8 = 32, 4 x 9 = 36, 4 x 10 = 40, 4 x 6 = 24, 4 x 7 = 28, 4 x 6 = 24, 4 x 8 = 32, 4 x 6 = 24, 4 x 9 = 36, 4 x 6 = 24, 4 x 10 = 40, 4 x 6 = 24, 4 x 7 = 28, 4 x 6 = 24, 4 x 7 = 28, 4 x 8 = 32, 4 x 7 = 28, 4 x 9 = 36, 4 x 7 = 28, 4 x 10 = 40, 4 x 7 = 28, 4 x 8 = 32, 4 x 6 = 24, 4 x 8 = 32, 4 x 7 = 28, 4 x 8 = 32, 4 x 9 = 36, 4 x 8 = 32, 4 x 10 = 40, 4 x 8 = 32, 4 x 9 = 36, 4 x 6 = 24, 4 x 9 = 36, 4 x 7 = 28, 4 x 9 = 36, 4 x 10 = 40, 4 x 6 = 24, 4 x 10 = 40, 4 x 7 = 28, 4 x 10 = 40, 4 x 8 = 32, 4 x 10 = 40, 4 x 9 = 36, 4 x 10 = 40, 4 x 6 = 24, 4 x 8 = 32, 4 x 10 = 40, 4 x 7 = 28, 4 x 9 = 36.

Explanation:
In the above-given question,
given that,
multiply by 4.
4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 4 x 4 = 16, 4 x 5 = 20, 4 x 6 = 24, 4 x 7 = 28, 4 x 8 = 32, 4 x 9 = 36, 4 x 10 = 40, 4 x 6 = 24, 4 x 7 = 28, 4 x 6 = 24, 4 x 8 = 32, 4 x 6 = 24, 4 x 9 = 36, 4 x 6 = 24, 4 x 10 = 40, 4 x 6 = 24, 4 x 7 = 28, 4 x 6 = 24, 4 x 7 = 28, 4 x 8 = 32, 4 x 7 = 28, 4 x 9 = 36, 4 x 7 = 28, 4 x 10 = 40, 4 x 7 = 28, 4 x 8 = 32, 4 x 6 = 24, 4 x 8 = 32, 4 x 7 = 28, 4 x 8 = 32, 4 x 9 = 36, 4 x 8 = 32, 4 x 10 = 40, 4 x 8 = 32, 4 x 9 = 36, 4 x 6 = 24, 4 x 9 = 36, 4 x 7 = 28, 4 x 9 = 36, 4 x 10 = 40, 4 x 6 = 24, 4 x 10 = 40, 4 x 7 = 28, 4 x 10 = 40, 4 x 8 = 32, 4 x 10 = 40, 4 x 9 = 36, 4 x 10 = 40, 4 x 6 = 24, 4 x 8 = 32, 4 x 10 = 40, 4 x 7 = 28, 4 x 9 = 36.

Eureka Math Grade 3 Module 4 Lesson 2 Problem Set Answer Key

Question 1.
Use all of Paper Strip 1, which you cut into 12 square inches, to complete the chart below.

Answer:
The area of Rectangle A = 12.
the area of Rectangle B = 14.
The area of Rectangle C = 16.

Explanation:
In the above-given question,
given that,
the length of the rectangle A = 6.
the breadth of the rectangle A = 2.
Area of the rectangle = l x b.
where l = length, b = bredth.
6 x 2 = 12.
the length of the rectangle B = 7.
the breadth of the rectangle B = 2.
Area = 7 x 2 = 14.
the length of the rectangle C = 8.
the breadth of the rectangle C = 2.
Area = 8 x 2 = 16.

Question 2.
Use all of Paper Strip 2, which you cut into 12 square centimeters, to complete the chart below.

Answer:
The area of the rectangle A = 12 square centimeters.
the area of Rectangle B = 10.
The area of Rectangle C = 16.

Explanation:
In the above-given question,
given that,
the length of the rectangle A = 6.
the breadth of the rectangle A = 2.
Area of the rectangle = l x b.
where l = length, b = bredth.
6 x 2 = 12.
the length of the rectangle B = 5.
the breadth of the rectangle B = 2.
Area = 5 x 2 = 10.
the length of the rectangle C = 8.
the breadth of the rectangle C = 2.
Area = 8 x 2 = 16.

Question 3.
Compare the areas of the rectangles you made with Paper Strip 1 and Paper Strip 2. What changed? Why did it change?

Answer:
The area of Rectangle B is changed.

Explanation:
In the above-given question,
given that,
the area of rectangle B in paper Strip 1 = 14.
7 x 2 = 14.
the area of the rectangle B in paper Strip 2 = 10.
5 x 2 = 10.
so the area of Rectangle B is changed.

Question 4.
Maggie uses square units to create these two rectangles. Do the two rectangles have the same area? How do you know?

Answer:
Yes, the two rectangles have the same area.

Explanation:
In the above-given question,
given that,
Maggie uses square units to create these two rectangles.
the area of the rectangle A = 6.
2 x 3 = 6.
where length = 2, and breadth = 3.
the area of the rectangle B = 6.
3 x 2 = 6.
where l = 3, and b = 2.
so the area of the two rectangles is same.

Question 5.
Count to find the area of the rectangle below. Then, draw a different rectangle that has the same area.

Answer:
The area of the rectangle = 8.

Explanation:
In the above-given figure.
given that,
only the length is given.
8.

Eureka Math Grade 3 Module 4 Lesson 2 Exit Ticket Answer Key

Question 1.
Each is a square unit. Find the area of the rectangle below. Then, draw a different rectangle with the same number of square units.

Answer:
The area of the rectangle = 16.

Explanation:
In the above-given figure.
given that,
l = 8, and b = 2.
8 x 2 = 16.
so the area = 16.

Question 2.
Each creates a rectangle with an area of 6 square inches. Luke makes a rectangle with an area of 6 square centimeters. Do the two rectangles have the same area? Why or why not?

Answer:
No, the two rectangles do not have the same area.

Explanation:
In the above-given question,
given that,
Each creates a rectangle with an area of 6 square inches.
Luke makes a rectangle with an area of 6 square centimeters.
so both of them are not same.

Eureka Math Grade 3 Module 4 Lesson 2 Homework Answer Key

Question 1.
Each is a square unit. Count to find the area of each rectangle. Then, circle all the rectangles with an area of 12 square units.
a.

Area = ____12___ square units

Answer:
The area of the rectangle = 12.

Explanation:
In the above-given figure.
given that,
l = 6, and b = 2.
6 x 2 = 12.
so the area = 12.

b.

Area = ___9____ square units

Answer:
The area of the rectangle = 9.

Explanation:
In the above-given figure.
given that,
l = 3, and b = 3.
3 x 3 = 9.
so the area = 9.

c.

Area = ____12___ square units

Answer:
The area of the rectangle = 12.

Explanation:
In the above-given figure.
given that,
l = 6, and b = 2.
6 x 2 = 12.
so the area = 12.

d.

Area = ___12____ square units

Answer:
The area of the rectangle = 12.

Explanation:
In the above-given figure.
given that,
l = 4, and b = 3.
4 x 3 = 12.
so the area = 12.

e.

Area = ____5___ square units

Answer:
The area of the rectangle = 5.

Explanation:
In the above-given figure.
given that,
l = 5, and b = 1.
5 x 1 = 5.
so the area = 5.

f.

Area = ___8____ square units

Answer:
The area of the rectangle = 8.

Explanation:
In the above-given figure.
given that,
l = 2, and b = 4.
2 x 4 = 8.
so the area = 8.

Question 2.
Colin uses square units to create these rectangles. Do they have the same area? Explain.

Answer:
No, they do not have the same area.

Explanation:
In the above-given question,
given that,
the area of the shape A = 8.
4 x 2 = 8.
the area of the shape B = 6.
6 x 1 = 6.
so they do not have the same area.

Question 3.
Each is a square unit. Count to find the area of the rectangle below. Then, draw a different rectangle that has the same area.

Answer:
The area of the rectangle = 16.

Explanation:
In the above-given figure.
given that,
l = 4, and b = 4.
4 x 4= 16.
so the area = 16.

Grade 3 Eureka Math Answer Key is provided by subject experts as per the Common Core curriculum. Grade 3 Eureka Math Solutions provided educates the primary school Kids on all Math concepts of the chapter efficiently. Eureka Math Grade 3 Textbook Answers makes it easy for kids to Grasp the Concepts as well as solve any problem from chapter Tests, Practice Tests, Performance tests, cumulative practice, etc.

Engage NY Eureka Math 3rd Grade Module 4 Lesson 1 Answer Key

Eureka Grade 3 ensures students with the learning targets and success criteria. The Diverse opportunities will develop problem-solving skills among the primary school kids practicing Bigideas Math Grade 3 Solutions. Eureka Textbook Grade 3 answers help Students Master the subject on Consistent practice.

Eureka Math Grade 3 Module 4 Lesson 1 Problem Set Answer Key

Question 1.
Use triangle pattern blocks to cover each shape below. Draw lines to show where the triangles meet. Then, write how many triangle pattern blocks it takes to cover each shape.

Answer:
The number of triangles in shape A = 2.
the number of triangles in shape B= 6.

Explanation:
In the above-given question,
given that,
In the parallelogram, there are 2 triangles.
in the hexagon, there are 6 triangles.
so the number of triangles in shape A = 2.
so the number of triangles in shape B= 6.

Question 2.
Use rhombus pattern blocks to cover each shape below. Draw lines to show where the rhombuses meet. Then, write how many rhombus pattern blocks it takes to cover each shape

Answer:
The number of rhombuses in shape A = 2.
the number of rhombuses in shape B= 3.

Explanation:
In the above-given question,
given that,
In the parallelogram, there are 2 rhombuses.
in the hexagon, there are 3 rhombuses.
so the number of rhombuses in shape A = 2.
so the number of rhombuses in shape B= 6.

Question 3.
Use trapezoid pattern blocks to cover each shape below. Draw lines to show where the trapezoids meet. Then, write how many trapezoid pattern blocks it requires to cover each shape.

Answer:
The number of trapezoids in shape A = 2.
the number of trapezoids in shape B= 2.

Explanation:
In the above-given question,
given that,
In the parallelogram, there is 2 trapezoid.
in the hexagon, there are 2 trapezoids.
so the number of trapezoids in shape A = 2.
so the number of trapezoids in shape B= 2.

Question 4.
How is the number of pattern blocks needed to cover the same shape related to the size of the pattern blocks?

Answer:
The number of square pattern blocks used to cover the rectangle = 40.

Explanation,
In the above-given question,
given that,
the number of rows in rectangle = 5.
the number of columns in rectangle = 8.
5 x 8 = 40.

Question 5.
Use square pattern blocks to cover the rectangle below. Draw lines to show where the squares meet. Then, write how many square pattern blocks it requires to cover the rectangle.

___40_____ squares

Answer:
The number of square pattern blocks used to cover the rectangle = 40.

Explanation,
In the above-given question,
given that,
the number of rows in rectangle = 5.
the number of columns in rectangle = 8.
5 x 8 = 40.

Question 6.
Use trapezoid pattern blocks to cover the rectangle in Problem 5. Can you use trapezoid pattern blocks to measure the area of this rectangle? Explain your answer.

Answer:
The number of trapezoid pattern blocks used to cover the rectangle = 4.

Explanation,
In the above-given question,
given that,
the number of rows in rectangle = 2.
the number of columns in rectangle = 2.
2 x 2 = 4.

Eureka Math Grade 3 Module 4 Lesson 1 Exit Ticket Answer Key

Each is 1 square unit. Do both rectangles have the same area? Explain how you know.

Answer:
Yes, both have the same area = 12.

Explanation,
In the above-given question,
given that,
the number of rows in rectangle = 4.
the number of columns in rectangle = 3.
4 x 3 = 12.
the number of rows in rectangle = 2.
the number of columns in rectangle = 6.
2 x 6 = 12.
so both have the same area = 12.

Eureka Math Grade 3 Module 4 Lesson 1 Homework Answer Key

Question 1.
Magnus covers the same shape with triangles, rhombuses, and trapezoids.
a. How many triangles will it take to cover the shape?

____12___ triangles

Answer:
The number of triangles will it take to cover the shape = 12.

Explanation,
In the above-given question,
given that,
the number of rows in parallelogram = 2.
the number of columns in parallelogram = 6.
2 x 6 = 12.
so the number of triangles will it take to cover the shape = 12 triangles.

b. How many rhombuses will it take to cover the shape?

____6___ rhombuses

Answer:
The number of rhombuses will it take to cover the shape = 6.

Explanation,
In the above-given question,
given that,
the number of rows in parallelogram = 2.
the number of columns in parallelogram = 3.
2 x 3 = 6.
so the number of rhombuses will it take to cover the shape = 6.

c. Magnus notices that 3 triangles from Part (a) cover 1 trapezoid. How many trapezoids will you need to cover the shape below? Explain your answer.

___4____ trapezoids

Answer:
The number of trapezoids will it take to cover the shape = 4.

Explanation,
In the above-given question,
given that,
the number of rows in parallelogram = 2.
the number of columns in parallelogram = 2.
2 x 2 = 14.
so the number of trapezoids will it take to cover the shape = 4 trapezoids.

Question 2.
Angela uses squares to find the area of a rectangle. Her work is shown below.
a. How many squares did she use to cover the rectangle?

____12___ squares

Answer:
The number of squares to find the rectangle = 12.

Explanation,
In the above-given question,
given that,
the number of rows in rectangle = 4.
the number of columns in rectangle = 3.
4 x 3 = 12.
so the number of squares = 12.

b. What is the area of the rectangle in square units? Explain how you found your answer.

Answer:
The number of squares to find the rectangle = 12.

Explanation,
In the above-given question,
given that,
the number of rows in rectangle = 4.
the number of columns in rectangle = 3.
4 x 3 = 12.
so the number of squares = 12.

Question 3.
Each is 1 square unit. Which rectangle has the largest area? How do you know?

Answer:
Rectangle A has the largest area.

Explanation:
In the above-given question,
given that,
the number of rows in rectangle A = 3.
the number of columns in rectangle A = 6.
3 x 6 = 18.
the number of rows in rectangle B = 4.
the number of rows in rectangle B = 2.
4 x 2 = 8.
the number of rows in rectangle C = 10.
the number of rows in rectangle C = 0.
10.
so rectangle A has the largest area.

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Engage NY Eureka Math 3rd Grade Module 3 Lesson 18 Answer Key

Grade 3 Eureka Math Answer Key is provided by subject experts as per the Common Core curriculum. Grade 3 Eureka Math Solutions provided educates the primary school Kids on all Math concepts of the chapter efficiently. Eureka Math Grade 3 Textbook Answers makes it easy for kids to Grasp the Concepts as well as solve any problem from chapter Tests, Practice Tests, Performance tests, cumulative practice, etc.

Eureka Math Grade 3 Module 3 Lesson 18 Sprint Answer Key

Multiply and Divide with 1 and 0

Answer:
2 x 1 = 2, 3 x 1 = 3, 4 x 1 = 4, 9 x 1 = 9, 8 x 0 = 0, 9 x 0 = 0, 4 x 0 = 0, 5 x 1 = 5, 6 x 1 = 6, 7 x 1 = 7, 3 x 1 = 3, 0 / 1 = 0, 0 / 2 = 0, 0 / 3 = 3, 0 / 6 = 0, 1 x 1 = 1, 4 , 1 = 4, 5 / 1 = 5, 6 / 1 = 6, 5 x 1 = 5, 3 x 0 = 0, 9 / 1 = 9, 8 x 1 = 8, 1 x 1 = 1, 0 / 3 = 0, 7 x 1 = 7, 6 x 0 = 0, 4 x 1 = 4, 0 / 8 = 0, 0 x 0 = 0, 1 / 1 = 1, 24 x 1 = 24, 17 x 0 = 0, 32 x 1 = 32, 0/ 19 = 0, 46 x 0 = 0, 0 / 51 = 0, 64 x 1 = 64, 79 x 1 = 79, 0 / 82 = 0, 96 x 1 = 96, 27 x 1 = 27, 43 x 0 = 0.

Explanation:
In the above-given question,
given that,
multiply and divide with 1 and 0.
2 x 1 = 2, 3 x 1 = 3, 4 x 1 = 4, 9 x 1 = 9, 8 x 0 = 0, 9 x 0 = 0, 4 x 0 = 0, 5 x 1 = 5, 6 x 1 = 6, 7 x 1 = 7, 3 x 1 = 3, 0 / 1 = 0, 0 / 2 = 0, 0 / 3 = 3, 0 / 6 = 0, 1 x 1 = 1, 4 , 1 = 4, 5 / 1 = 5, 6 / 1 = 6, 5 x 1 = 5, 3 x 0 = 0, 9 / 1 = 9, 8 x 1 = 8, 1 x 1 = 1, 0 / 3 = 0, 7 x 1 = 7, 6 x 0 = 0, 4 x 1 = 4, 0 / 8 = 0, 0 x 0 = 0, 1 / 1 = 1, 24 x 1 = 24, 17 x 0 = 0, 32 x 1 = 32, 0/ 19 = 0, 46 x 0 = 0, 0 / 51 = 0, 64 x 1 = 64, 79 x 1 = 79, 0 / 82 = 0, 96 x 1 = 96, 27 x 1 = 27, 43 x 0 = 0.

Answer:
3 x 1 = 3, 4 x 1 = 4, 5 x 1 = 5, 8 x 1 = 8, 7 x 0 = 0, 8 x 0 = 0, 3 x 0 = 0, 4 x 1 = 4, 5 x 1 = 5, 6 x 1 = 6, 2 x 1 = 2, 0 / 2 = 0, 0 / 3 = 0, 0 / 4 = 0, 0 / 7 = 0, 1 x 1 = 1, 3 / 1 = 3, 4 / 1 = 4, 5 / 1 = 5, 7 / 1 = 7, 6 x 1 = 6, 4 x 0 = 0, 8 / 1 = 8, 7 x 1 = 7, 1 x 1 = 1, 0 / 5 = 0, 9 x 1 = 9, 0 / 6 = 0, 1 / 1 = 1, 0 x 0 = 0, 34 x 1 = 34, 16 x 0 = 0, 31 x 1 = 31, 0 / 18 = 0, 45 x 0 = 0, 0 / 52 = 0, 63 x 1 = 63, 78 x 1 = 78, 0 / 81 = 0, 97 x 1 = 97, 26 x 1 = 26, 42 x 0 = 0.

Explanation:
In the above-given question,
given that,
multiply and divide with 1 and 0.
3 x 1 = 3, 4 x 1 = 4, 5 x 1 = 5, 8 x 1 = 8, 7 x 0 = 0, 8 x 0 = 0, 3 x 0 = 0, 4 x 1 = 4, 5 x 1 = 5, 6 x 1 = 6, 2 x 1 = 2, 0 / 2 = 0, 0 / 3 = 0, 0 / 4 = 0, 0 / 7 = 0, 1 x 1 = 1, 3 / 1 = 3, 4 / 1 = 4, 5 / 1 = 5, 7 / 1 = 7, 6 x 1 = 6, 4 x 0 = 0, 8 / 1 = 8, 7 x 1 = 7, 1 x 1 = 1, 0 / 5 = 0, 9 x 1 = 9, 0 / 6 = 0, 1 / 1 = 1, 0 x 0 = 0, 34 x 1 = 34, 16 x 0 = 0, 31 x 1 = 31, 0 / 18 = 0, 45 x 0 = 0, 0 / 52 = 0, 63 x 1 = 63, 78 x 1 = 78, 0 / 81 = 0, 97 x 1 = 97, 26 x 1 = 26, 42 x 0 = 0.

Eureka Math Grade 3 Module 3 Lesson 18 Problem Set Answer Key

Use the RDW process for each problem. Explain why your answer is reasonable.

Question 1.
Rose has 6 pieces of yarn that are each 9 centimeters long. Sasha gives Rose a piece of yarn. Now, Rose has a total of 81 centimeters of yarn. What is the length of the yarn that Sasha gives Rose?

Answer:
The length of the yarn that Sasha gives Rose = 27 centimeters.

Explanation:
In the above-given question,
given that,
Rose has 6 pieces of yarn that are each 9 centimeters long.
Sasha gives Rose a piece of yarn.
Now, Rose has a total of 81 centimeters of yarn.
6 x 9 = 54.
81 – 54 = 27.
so the length of the yarn = 27.

Question 2.
Julio spends 29 minutes doing his spelling homework. He then completes each math problem in 4 minutes. There are 7 math problems. How many minutes does Julio spend on his homework in all?

Answer:
The number of minutes does Julio spends on his homework in all = 57 minutes.

Explanation:
In the above-given question,
given that,
Julio spends 29 minutes doing his spelling homework.
He then completes each math problem in 4 minutes.
there are 7 math problems.
7 x 4 = 28.
28 + 29 = 57.
so the number of minutes Julio spends on his homework in all = 57.

Question 3.
Pearl buys 125 stickers. She gives 53 stickers to her little sister. Pearl then puts 9 stickers on each page of her album. If she uses all of her remaining stickers, on how many pages does Pearl put stickers?

Answer:
The number of pages pearl put stickers = 8 pages.

Explanation:
In the above-given question,
given that,
Pearl buys 125 stickers. She gives 53 stickers to her little sister.
Pearl then puts 9 stickers on each page of her album.
125 – 53 = 72.
72 / 9 = 8.
so the number of pages pearl put stickers = 8.

Question 4.
Tanner’s beaker had 45 milliliters of water in it at first. After each of his friends poured in 8 milliliters, the beaker contained 93 milliliters. How many friends poured water into Tanner’s beaker?

Answer:
The number of friends who poured water into Tanner’s beaker = 8.

Explanation:
In the above-given question,
given that,
Tanner’s beaker had 45 milliliters of water in it at first.
After each of his friends poured in 8 milliliters, the beaker contained 93 milliliters.
93 – 45 = 48.
48 / 8 = 6.
so the number of friends who poured water into Tanner’s beaker = 8.

Question 5.
Cora weighs 4 new, identical pencils and a ruler. The total weight of these items is 55 grams. She weighs the ruler by itself and it weighs 19 grams. How much does each pencil weigh?

Answer:
The weight of each pencil = 9 grams.

Explanation:
In the above-given question,
given that,
Cora weighs 4 new, identical pencils and a ruler.
the total weight of these items is 55 grams.
55 – 19 = 36.
36 / 4 = 9.
so the weight of each pencil = 9 grams.

Eureka Math Grade 3 Module 3 Lesson 18 Exit Ticket Answer Key

Use the RDW process to solve. Explain why your answer is reasonable.

On Saturday, Warren swims laps in the pool for 45 minutes. On Sunday, he runs 8 miles. It takes him 9 minutes to run each mile. How long does Warren spend exercising over the weekend?

Answer:
The Warren spend exercising over the weekend = 117 minutes.

Explanation:
In the above-given question,
given that,
On, Saturday, Warren swims laps in the pool for 45 minutes.
On, Sunday, he runs 8 miles.
It takes him 9 minutes to run each mile.
9 x 8 = 72.
72 + 45 = 117.
so the Warren spend over the weekend = 117 minutes.

Eureka Math Grade 3 Module 3 Lesson 18 Homework Answer Key

Use the RDW process for each problem. Explain why your answer is reasonable.

Question 1.
Mrs. Portillo’s cat weighs 6 kilograms. Her dog weighs 22 kilograms more than her cat. What is the total weight of her cat and dog?

Answer:
The total weight of her cat and dog = 34 kilograms.

Explanation:
In the above-given question,
given that,
Mrs. Portillo’s cat weighs 6 kilograms.
Her dog weighs 22 kilograms more than her cat.
6 + 22 = 28.
28 + 6 = 34.
so the total weight of her cat and dog = 34.

Question 2.
Darren spends 39 minutes studying for his science test. He then does 6 chores. Each chore takes him 3 minutes. How many minutes does Darren spend studying and doing chores?

Answer:
The number of minutes does Darren spends studying and doing chores = 57 minutes.

Explanation:
In the above-given question,
given that,
Darren spends 39 minutes studying for his science test.
He then does 6 chores.
Each chore takes him 3 minutes.
6 x 3 = 18.
18 + 39 = 57.
so the number of minutes = 57.

Question 3.
Mr. Abbot buys 8 boxes of granola bars for a party. Each box has 9 granola bars. After the party, there are 39 bars left. How many bars were eaten during the party?

Answer:
The number of bars was eaten during the party= 33.

Explanation:
In the above-given question,
given that,
Mr. Abbot buys 8 boxes of granola bars for a party.
Each box has 9 granola bars.
After the party, there are 39 bars left.
8 x 9 = 72.
72 – 39 = 33.
so the number of bars was eaten during the party = 33.

Question 4.
Leslie weighs her marbles in a jar, and the scale reads 474 grams. The empty jar weighs 439 grams. Each marble weighs 5 grams. How many marbles are in the jar?

Answer:
The number of marbles in the jar = 35.

Explanation:
In the above-given question,
given that,
Leslie weighs her marbles in a jar and the scale reads 474 grams.
The empty jar weighs 439 grams.
Each marble weighs 5 grams.
474 – 439 = 35.
so the number of marbles in the jar = 35.

Question 5.
Sharon uses 72 centimeters of ribbon to wrap gifts. She uses 24 centimeters of her total ribbon to wrap a big gift. She uses the remaining ribbon for 6 small gifts. How much ribbon will she use for each small gift if she uses the same amount on each?

Answer:
The length of ribbon she uses for each small gift = 8 centimeters.

Explanation:
In the above-given question,
given that,
Sharon uses 72 centimeters of ribbon to wrap gifts.
She uses 24 centimeters of her total ribbon to wrap a big gift.
she uses the remaining ribbon for 6 small gifts.
72 – 24 = 48.
48 / 6 = 8.
so the length of ribbon = 8 centimeters.

Question 6.
Six friends equally share the cost of a gift. They pay $90 and receive $42 in change. How much does each friend pay?

Answer:
Each friend pays = $8.

Explanation:
In the above-given question,
given that,
Six friends equally share the cost of a gift.
They pay $90 and receive $42 in change.
90 – 42 = 48.
48 / 6 = 8
so the esch friend pays = $8.

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Engage NY Eureka Math 3rd Grade Module 3 Lesson 17 Answer Key

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Eureka Math Grade 3 Module 3 Lesson 17 Problem Set Answer Key

Question 1.
Write the products into the squares as fast as you can.

a. Color all the squares with even products orange. Can an even product ever have an odd factor?

Answer:
1 x 1 = 1, 1 x 2 = 2, 1 x 3 = 3, 1 x 4 = 4, 1 x 5 = 5, 1 x 6 = 6, 1 x 7 = 8, 1 x 8 = 8, 2 x 1 = 2, 2 x 2 = 4, 2 x 3 = 6, 2 x 4 = 8, 2 x 5 = 10, 2 x 6 = 12, 2 x 7 = 14, 2 x 8 = 16, 3 x 1 = 3, 3 x 2 = 6, 3 x 3 = 9, 3 x 4 = 12, 3 x 5 = 15, 3 x 6 = 18, 3 x 7 = 21, 3 x 8 = 24, 4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 4 x 4 = 16, 4 x 5 = 20, 4 x 6 = 24, 4 x 7 = 28, 4 x 8 = 32, 5 x 1 = 5, 5 x 2 = 10, 5 x 3 = 15, 5 x 4 = 20, 5 x 5 = 25, 5 x 6 = 30, 5 x 7 = 35, 5 x 8 = 40, 6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 7 x 1 = 7, 7 x 2 = 14, 7 x 3 = 21, 7 x 4 = 28, 7 x 5 = 35, 7 x 6 = 42, 7 x 7 = 49, 7 x 8 = 56, 8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 4 = 32, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64.

Explanation:
In the above-given question,
given that,
1 x 1 = 1, 1 x 2 = 2, 1 x 3 = 3, 1 x 4 = 4, 1 x 5 = 5, 1 x 6 = 6, 1 x 7 = 8, 1 x 8 = 8, 2 x 1 = 2, 2 x 2 = 4, 2 x 3 = 6, 2 x 4 = 8, 2 x 5 = 10, 2 x 6 = 12, 2 x 7 = 14, 2 x 8 = 16, 3 x 1 = 3, 3 x 2 = 6, 3 x 3 = 9, 3 x 4 = 12, 3 x 5 = 15, 3 x 6 = 18, 3 x 7 = 21, 3 x 8 = 24, 4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 4 x 4 = 16, 4 x 5 = 20, 4 x 6 = 24, 4 x 7 = 28, 4 x 8 = 32, 5 x 1 = 5, 5 x 2 = 10, 5 x 3 = 15, 5 x 4 = 20, 5 x 5 = 25, 5 x 6 = 30, 5 x 7 = 35, 5 x 8 = 40, 6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 7 x 1 = 7, 7 x 2 = 14, 7 x 3 = 21, 7 x 4 = 28, 7 x 5 = 35, 7 x 6 = 42, 7 x 7 = 49, 7 x 8 = 56, 8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 4 = 32, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64.

b. Can an odd product ever have an even factor?

Answer:
No, an odd product ever has an even factor.

Explanation:
In the above-given question,
given that,
1 x 1 = 1, 1 x 2 = 2, 1 x 3 = 3, 1 x 4 = 4, 1 x 5 = 5, 1 x 6 = 6, 1 x 7 = 8, 1 x 8 = 8, 2 x 1 = 2, 2 x 2 = 4, 2 x 3 = 6, 2 x 4 = 8, 2 x 5 = 10, 2 x 6 = 12, 2 x 7 = 14, 2 x 8 = 16, 3 x 1 = 3, 3 x 2 = 6, 3 x 3 = 9, 3 x 4 = 12, 3 x 5 = 15, 3 x 6 = 18, 3 x 7 = 21, 3 x 8 = 24, 4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 4 x 4 = 16, 4 x 5 = 20, 4 x 6 = 24, 4 x 7 = 28, 4 x 8 = 32, 5 x 1 = 5, 5 x 2 = 10, 5 x 3 = 15, 5 x 4 = 20, 5 x 5 = 25, 5 x 6 = 30, 5 x 7 = 35, 5 x 8 = 40, 6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 7 x 1 = 7, 7 x 2 = 14, 7 x 3 = 21, 7 x 4 = 28, 7 x 5 = 35, 7 x 6 = 42, 7 x 7 = 49, 7 x 8 = 56, 8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 4 = 32, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64.
No, an odd product ever has an even factor.

c. Everyone knows that 7 × 4 = (5 × 4) + (2 × 4). Explain how this is shown in the table.

Answer:
7 x 4 = 28.
5 x 4 = 20.
2 x 4 = 8.
20 + 8 = 28.

Explanation:
In the above-given question,
given that,
7 x 4 = 28.
5 x 4 = 20.
2 x 4 = 8.
20 + 8 = 28.

d. Use what you know to find the product of 7 × 16 or 8 sevens + 8 sevens.

Answer:
7 x 16 = 112.

Explanation:
In the above-given question,
given that,
7 x 6 = 112.
8 sevens + 8 sevens.
8 x 7 + 8 x 7.
56 + 56.
112.

Question 2.
In the table, only the products on the diagonal are shown.

a. Label each product on the diagonal.

Answer:
1 x 2 = 2, 1 x 3 = 3, 1 x 4 = 4, 1 x 5 = 5, 1 x 6 = 6, 2 x 1 = 2, 2 x 3 = 6, 2 x 4 = 8, 2 x 5 = 10, 2 x 6 = 12, 3 x 1 = 3, 3 x 2 = 6, 3 x 4 = 12, 3 x 5 = 15, 3 x 6 = 18, 4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 4 x 5 = 20, 4 x 6 = 24, 5 x 1 = 5, 5 x 2 = 1, 5 x 3 = 15, 5 x 4 = 20, 5 x 6 = 30, 6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24, 6 x 5 = 30.

Explanation:
In the above-given question,
given that,
1 x 2 = 2, 1 x 3 = 3, 1 x 4 = 4, 1 x 5 = 5, 1 x 6 = 6, 2 x 1 = 2, 2 x 3 = 6, 2 x 4 = 8, 2 x 5 = 10, 2 x 6 = 12, 3 x 1 = 3, 3 x 2 = 6, 3 x 4 = 12, 3 x 5 = 15, 3 x 6 = 18, 4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 4 x 5 = 20, 4 x 6 = 24, 5 x 1 = 5, 5 x 2 = 1, 5 x 3 = 15, 5 x 4 = 20, 5 x 6 = 30, 6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24, 6 x 5 = 30.

b. Draw an array to match each expression in the table below. Then, label the number of squares you added to make each new array. The first two arrays have been done for you.

Answer:
1 + 2 = 3.
3 + 6 = 9.
6 + 10 = 16.
10 + 15 = 25.
15 + 21 = 36.

Explanation:
In the above-given question,
given that,
1 + 2 = 3.
3 + 6 = 9.
6 + 10 = 16.
10 + 15 = 25.
15 + 21 = 36.

c. What pattern do you notice in the number of squares that are added to each new array?

Answer:
1 + 3 = 4.
4 + 6 = 9.
6 + 10 = 16.
10 + 15 = 25.
15 + 21 = 36.

Explanation:
In the above-given question,
given that,
1 + 3 = 4.
4 + 6 = 9.
6 + 10 = 16.
10 + 15 = 25.
15 + 21 = 36.

d. Use the pattern you discovered in Part (b) to prove this: 9 × 9 is the sum of the first 9 odd numbers.

Answer:
9 x 9 = 81.

Explanation:
In the above-given question,
given that,
9 x 9 = 81.
the sum of the first 9 odd numbers is 81.
9 x 9 = 81.

Eureka Math Grade 3 Module 3 Lesson 17 Exit Ticket Answer Key

Question 1.
Use what you know to find the product of 8 × 12 or 6 eights + 6 eights.

Answer:
8 x 12 = 96.

Explanation:
In the above-given question,
given that,
8 x 12 = 96.
6 eights + 6 eights.
6 x 8 + 6 x 8.
48 + 48.
96.

Question 2.
Luis says 3 × 233 = 626. Use what you learned about odd times odd to explain why Luis is wrong.

Answer:
3 x 233 = 626.

Explanation:
In the above-given question,
given that,
3 x 233 = 626.
odd x odd = odd.
but in the given question,
Luis is wrong.
3 x 233 = 626.
625 + 1.

Eureka Math Grade 3 Module 3 Lesson 17 Homework Answer Key

Question 1.
a. Write the products into the chart as fast as you can.

Answer:
1 x 1 = 1, 1 x 2 = 2, 1 x 3 = 3, 1 x 4 = 4, 1 x 5 = 5, 1 x 6 = 6, 1 x 7 = 8, 1 x 8 = 8, 2 x 1 = 2, 2 x 2 = 4, 2 x 3 = 6, 2 x 4 = 8, 2 x 5 = 10, 2 x 6 = 12, 2 x 7 = 14, 2 x 8 = 16, 3 x 1 = 3, 3 x 2 = 6, 3 x 3 = 9, 3 x 4 = 12, 3 x 5 = 15, 3 x 6 = 18, 3 x 7 = 21, 3 x 8 = 24, 4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 4 x 4 = 16, 4 x 5 = 20, 4 x 6 = 24, 4 x 7 = 28, 4 x 8 = 32, 5 x 1 = 5, 5 x 2 = 10, 5 x 3 = 15, 5 x 4 = 20, 5 x 5 = 25, 5 x 6 = 30, 5 x 7 = 35, 5 x 8 = 40, 6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 7 x 1 = 7, 7 x 2 = 14, 7 x 3 = 21, 7 x 4 = 28, 7 x 5 = 35, 7 x 6 = 42, 7 x 7 = 49, 7 x 8 = 56, 8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 4 = 32, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64.

Explanation:
In the above-given question,
given that,
1 x 1 = 1, 1 x 2 = 2, 1 x 3 = 3, 1 x 4 = 4, 1 x 5 = 5, 1 x 6 = 6, 1 x 7 = 8, 1 x 8 = 8, 2 x 1 = 2, 2 x 2 = 4, 2 x 3 = 6, 2 x 4 = 8, 2 x 5 = 10, 2 x 6 = 12, 2 x 7 = 14, 2 x 8 = 16, 3 x 1 = 3, 3 x 2 = 6, 3 x 3 = 9, 3 x 4 = 12, 3 x 5 = 15, 3 x 6 = 18, 3 x 7 = 21, 3 x 8 = 24, 4 x 1 = 4, 4 x 2 = 8, 4 x 3 = 12, 4 x 4 = 16, 4 x 5 = 20, 4 x 6 = 24, 4 x 7 = 28, 4 x 8 = 32, 5 x 1 = 5, 5 x 2 = 10, 5 x 3 = 15, 5 x 4 = 20, 5 x 5 = 25, 5 x 6 = 30, 5 x 7 = 35, 5 x 8 = 40, 6 x 1 = 6, 6 x 2 = 12, 6 x 3 = 18, 6 x 4 = 24, 6 x 5 = 30, 6 x 6 = 36, 6 x 7 = 42, 6 x 8 = 48, 7 x 1 = 7, 7 x 2 = 14, 7 x 3 = 21, 7 x 4 = 28, 7 x 5 = 35, 7 x 6 = 42, 7 x 7 = 49, 7 x 8 = 56, 8 x 1 = 8, 8 x 2 = 16, 8 x 3 = 24, 8 x 4 = 32, 8 x 5 = 40, 8 x 6 = 48, 8 x 7 = 56, 8 x 8 = 64.

b. Color the rows and columns with even factors yellow.

Answer:
The even factors are color with yellow.

Explanation:
In the above-given question,
given that,
so the even factors are color with yellow.

c. What do you notice about the factors and products that are left unshaded

Answer:
The factors that are left unshaded is odd numbers.

Explanation:
In the above-given question,
given that,
the factors that are left unshaded is odd.
the factors that are in diagonals is even.

d. Complete the chart by filling in each blank and writing an example for each rule.

Answer:
odd times odd equals = odd.
even times even equals = even.
even times odd equals = even.

Explanation:
In the above-given question,
given that,
odd times odd equals = odd.
even times even equals = even.
even times odd equals = even.
9 x 9 = 81.
2 x 2 = 4.
4 x 3 = 12.

e. Explain how 7 × 6 = (5 × 6) + (2 × 6) is shown in the table

Answer:
7 x 6 = 42.

Explanation:
In the above-given question,
given that,
7 x 6 = 42.
5 x 6 = 30.
2 x 6 = 12.
( 5 x 6 ) + (2 x 6 ).
30 + 12 = 42.

f. Use what you know to find the product of 4 × 16 or 8 fours + 8 fours.

Answer:
4 x 16 = 64.

Explanation:
In the above-given question,
given that,
4 x 16 = 64.
8 fours + 8 fours.
8 x 4 + 8 x 4.
32 + 32.
64.

Question 2.
Today in class, we found that n × n is the sum of the first n odd numbers. Use this pattern to find the value of n for each equation below. The first is done for you.
a. 1 + 3 + 5 = n × n

9 = 3 × 3

b. 1 + 3 + 5 + 7 = n × n

Answer:
16 = 4 x 4.

Explanation:
In the above-given question,
given that,
16 = 4 x 4.
1 + 3 + 5 + 7 = n x n.
n = 4.
4 x 4 = 16.
1 + 3 + 5 + 7 = 16.

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Engage NY Eureka Math 3rd Grade Module 3 End of Module Assessment Answer Key

Grade 3 Eureka Math Answer Key is provided by subject experts as per the Common Core curriculum. Grade 3 Eureka Math Solutions provided educates the primary school Kids on all Math concepts of the chapter efficiently. Eureka Math Grade 3 Textbook Answers makes it easy for kids to Grasp the Concepts as well as solve any problem from chapter Tests, Practice Tests, Performance tests, cumulative practice, etc.

Eureka Math Grade 3 Module 3 End of Module Assessment Answer Key

Question 1.
Aunt Korina and her 3 friends decide to share a cab to go to the mall. If they each spent $6, how much did the cab ride cost altogether? Write an equation using a letter to represent the unknown. Solve.

Answer:
The amount the cab ride costs altogether = $24.

Explanation:
In the above-given question,
given that,
Aunt Korina and her 3 friends decide to share a cab to go to the mall.
If they each spent $6.
3 + 1 = 4.
$6 x c = 4.
c = 4 x 6.
c = 24.
so the amount of cab ride costs altogether = $24.

Question 2.
Aunt Korina’s 3 friends each order pasta and a lemonade for lunch. Aunt Korina orders only chicken salad.

a. Use the menu to find how much they spend altogether. Write equations using letters to represent the unknown. Solve.

Answer:
The amount they spend altogether =$36.

Explanation:
In the above-given question,
given that,
Aunt Korina’s friends each ordered pasta and lemonade for lunch.
pasta = $7.
Chicken Salad = $9.
Lemonade = $2.
7 x 3 = 21.
2 x 3 = 6.
21 + 6 = 27.
27 – c = 9.
c = 27 + 9 = 36.
so the amount they spend altogether = $36.

b. Aunt Korina mentally checks the total using 4 × $9. Explain her strategy.

Answer:
4 x $9 = 36.

Explanation:
In the above-given question,
given that,
Aunt Korina mentally checks the total using 4 x $9.
27 + 9 = 36.
7 x 3 = 21.
2 x 3 = 6.
21 + 6 = 27.
4 x $9 = 36.

Question 3.
After lunch, the friends notice a sale. Compare the crossed out prices to the new sale prices. If all sale prices are calculated in the same way, what would the sale price be on an item that originally cost $24? Use words and equations to explain how you know.

Answer:
The sale price is on an item that originally cost $24 = $8.

Explanation:
In the above-given question,
given that,
After lunch, the friends notice a sale.
they had given a discount of 4%.
4 x 3 = 12.
7 x 3 = 21.
9 x 3 = 27.
1 x 3 = 3.
8 x 3 = 24.
so the sale price is on an item that originally cost $24 = $8.

Question 4.
a. A shopkeeper in the bookstore arranges the boxed sets of books as shown to the right.
If each box contains 9 books, how many books are there?

• Write an equation using a letter to represent the unknown, and then solve.
• Explain how you know your answer is reasonable.

Answer:
The number of books = 90.

Explanation:
In the above-given question,
given that,
A shopkeeper in the bookstore arranges the boxed sets of books as shown to the right.
if each box contains 9 books.
b = 9 x 10.
b = 90.
so the number of books = 90.

b. Aunt Korina figures out how many books are in the arrangement. Her work is shown below.
Explain Aunt Korina’s strategy.
10 × 10 – 10 = 90

Answer:
Yes, Aunt Korina was right.

Explanation:
In the above-given question,
given that,
Aunt Korina figures out how many books are in the arrangement.
9 x 10 = 90.
10 x 10 – 10.
100 – 10.
90.

c. In the book store, Aunt Korina buys 3 boxes of pens. Each box contains 2 bundles of 10 gray pens. Her friend buys 6 packs of pens. Each pack contains 10 black pens. Explain how the equation below shows how Aunt Korina and her friend buy the same number of pens.
6 × 10 = 3 × 2 × 10

Answer:
Yes, Aunt Korina and her friend buy the same number of pens.

Explanation:
In the above-given question,
given that,
In the book store, Aunt Korina buys 3 boxes of pens.
Each box contains 2 bundles of 10 gray pens.
6 x 10 = 60.
3 x 2 x 10.
6 x 10 = 60.
Her friend buys 6 packs of pens.
Each pack contains 10 black pens.
6 x 10 = 60.
so both of them buy the same number of pens.

Question 5.
Complete as many problems as you can in 100 seconds. The teacher will time you and tell you when to stop.

Answer:
2 x 1 = 2, 2 x 6 = 12, 5 x 3 = 15, 9 x 4 = 36, 7 x 5 = 35, 9 x 6 = 54, 7 x 7 = 49, 24 / 3 = 8, 4 / 2 = 2, 21 / 7 = 3, 8 / 2 = 4, 7 x 5 = 35, 54 / 9 = 6, 49 / 7 = 7, 9 x 7 = 63, 81 / 9 = 9, 10 / 5 = 2, 8 x 3 = 24, 4 x 3 = 12, 40 / 8 = 5, 6 x 6 = 36, 8 x 7 = 56, 64 / 8 = 8, 63 / 7 = 9, 3 x 3 = 9, 9 x 3 = 27, 16 / 4 = 4, 3 x 5 = 15, 8 x 6 = 48, 6 x 7 = 42, 6 x 8 = 48, 8 x 9 = 72, 2 x 2 = 4, 30 / 10 = 3, 6 x 4 = 24, 5 x 4 = 20, 24 / 4 = 6, 21 / 3 = 7, 8 x 4 = 32, 9 x 9 = 81.

Explanation:
In the above-given question,
given that,
the multiplication and division of 2, 4, 5, 6, 7, 8, and 9.
2 x 1 = 2, 2 x 6 = 12, 5 x 3 = 15, 9 x 4 = 36, 7 x 5 = 35, 9 x 6 = 54, 7 x 7 = 49, 24 / 3 = 8, 4 / 2 = 2, 21 / 7 = 3, 8 / 2 = 4, 7 x 5 = 35, 54 / 9 = 6, 49 / 7 = 7, 9 x 7 = 63, 81 / 9 = 9, 10 / 5 = 2, 8 x 3 = 24, 4 x 3 = 12, 40 / 8 = 5, 6 x 6 = 36, 8 x 7 = 56, 64 / 8 = 8, 63 / 7 = 9, 3 x 3 = 9, 9 x 3 = 27, 16 / 4 = 4, 3 x 5 = 15, 8 x 6 = 48, 6 x 7 = 42, 6 x 8 = 48, 8 x 9 = 72, 2 x 2 = 4, 30 / 10 = 3, 6 x 4 = 24, 5 x 4 = 20, 24 / 4 = 6, 21 / 3 = 7, 8 x 4 = 32, 9 x 9 = 81.

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Engage NY Eureka Math 3rd Grade Module 3 Lesson 21 Answer Key

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Eureka Math Grade 3 Module 3 Lesson 21 Sprint Answer Key

Multiply by Multiples of 10

Answer:
2 x 3 = 6, 2 x 30 = 60, 20 x 3 = 60, 2 x 2 = 4, 2 x 20 = 40, 20 x 2 = 40, 4 x 2 = 8, 4 x 20 = 80, 40 x 2 = 80, 5 x 3 = 15, 50 x 3 = 150, 3 x 50 = 150, 4 x 4 = 16, 40 x 4 = 160, 4 x 40 = 160, 6 x 3 = 18, 6 x 30 = 180, 60 x 3 = 180, 7 x 5 = 35, 70 x 5 = 350, 7 x 50 = 350, 8 x 4 = 32, 8 x 40 = 320, 4 x 80 = 320, 9 x 6 = 54, 90 x 6 = 540, 2 x 5 = 10, 2 x 50 = 100, 3 x 90 = 270, 40 x 7 = 280, 5 x 40 = 200, 6 x 60 = 360, 70 x 6 = 420, 8 x 70 = 560, 80 x 6 = 480, 9 x 70 = 630, 50 x 6 = 300, 8 x 80 = 640, 9 x 80 = 720, 60 x 8 = 480, 70 x 7 = 490, 5 x 80 = 400, 60 x 9 = 540, 9 x 90 = 810.

Explanation:
In the above-given question,
given that,
multiply by multiple 0f 10.
2 x 3 = 6, 2 x 30 = 60, 20 x 3 = 60, 2 x 2 = 4, 2 x 20 = 40, 20 x 2 = 40, 4 x 2 = 8, 4 x 20 = 80, 40 x 2 = 80, 5 x 3 = 15, 50 x 3 = 150, 3 x 50 = 150, 4 x 4 = 16, 40 x 4 = 160, 4 x 40 = 160, 6 x 3 = 18, 6 x 30 = 180, 60 x 3 = 180, 7 x 5 = 35, 70 x 5 = 350, 7 x 50 = 350, 8 x 4 = 32, 8 x 40 = 320, 4 x 80 = 320, 9 x 6 = 54, 90 x 6 = 540, 2 x 5 = 10, 2 x 50 = 100, 3 x 90 = 270, 40 x 7 = 280, 5 x 40 = 200, 6 x 60 = 360, 70 x 6 = 420, 8 x 70 = 560, 80 x 6 = 480, 9 x 70 = 630, 50 x 6 = 300, 8 x 80 = 640, 9 x 80 = 720, 60 x 8 = 480, 70 x 7 = 490, 5 x 80 = 400, 60 x 9 = 540, 9 x 90 = 810.

Multiply by Multiples of 10

Answer:
4 x 2 = 8, 4 x 20 = 80, 40 x 2 = 80, 3 x 3 = 9, 3 x 30 = 90, 30 x 3 = 90, 3 x 2 = 6, 3 x 20 = 60, 30 x 2 = 60, 5 x 5 = 25, 50 x 5 = 250, 5 x 50 = 250, 4 x 3 = 12, 40 x 3 = 120, 4 x 30 = 120, 7 x 3 = 21, 7 x 30 = 210, 70 x 3 = 210, 6 x 4 = 24, 60 x 4 = 240, 6 x 40 = 240, 9 x 4 = 36, 9 x 40 = 360, 90 x 4 = 360, 8 x 6 = 48, 80 x 6 = 480, 5 x 2 = 10, 5 x 20 = 100, 3 x 80 = 240, 40 x 8 = 320, 4 x 50 = 200, 8 x 80 = 640, 90 x 6 = 540, 6 x 70 = 420, 60 x 6 = 360, 7 x 70 = 490, 60 x 5 = 300, 6 x 80 = 480, 7 x 80 = 560, 80 x 6 = 480, 90 x 7 = 630, 8 x 50 = 400, 80 x 9 = 720, 7 x 90 = 630.

Explanation:
In the above-given question,
given that,multiply by multiples of 10.
4 x 2 = 8, 4 x 20 = 80, 40 x 2 = 80, 3 x 3 = 9, 3 x 30 = 90, 30 x 3 = 90, 3 x 2 = 6, 3 x 20 = 60, 30 x 2 = 60, 5 x 5 = 25, 50 x 5 = 250, 5 x 50 = 250, 4 x 3 = 12, 40 x 3 = 120, 4 x 30 = 120, 7 x 3 = 21, 7 x 30 = 210, 70 x 3 = 210, 6 x 4 = 24, 60 x 4 = 240, 6 x 40 = 240, 9 x 4 = 36, 9 x 40 = 360, 90 x 4 = 360, 8 x 6 = 48, 80 x 6 = 480, 5 x 2 = 10, 5 x 20 = 100, 3 x 80 = 240, 40 x 8 = 320, 4 x 50 = 200, 8 x 80 = 640, 90 x 6 = 540, 6 x 70 = 420, 60 x 6 = 360, 7 x 70 = 490, 60 x 5 = 300, 6 x 80 = 480, 7 x 80 = 560, 80 x 6 = 480, 90 x 7 = 630, 8 x 50 = 400, 80 x 9 = 720, 7 x 90 = 630.

Eureka Math Grade 3 Module 3 Lesson 21 Problem Set Answer Key

Use the RDW process to solve each problem. Use a letter to represent the unknown.

Question 1.
There are 60 seconds in 1 minute. Use a tape diagram to find the total number of seconds in 5 minutes and 45 seconds.

Answer:
The total number of seconds = 345 seconds.

Explanation:
In the above-given question,
given that,
There are 60 seconds in 1 minute.
60 x 5 = 300.
300 + 45 = 345.

Question 2.
Lupe saves $30 each month for 4 months. Does she have enough money to buy the art supplies below? Explain why or why not.

Answer:
No, she does not have enough money to buy the art supplies.

Explanation:
In the above-given question,
given that,
Lupe saves $30 each month for 4 months.
30 x 4 = 120.
but the Art Supplies cost is $142.
120 is less than 142.
so she does not buy.

Question 3.
Brad receives 5 cents for each can or bottle he recycles. How many cents does Brad earn if he recycles 48 cans and 32 bottles?

Answer:
The number of cents he recycles = 400 cents.

Explanation:
In the above-given question,
given that,
Brad receives 5 cents for each can or bottle he recycles.
48 x 5 = 240.
32 x 5 = 150.
240 + 150 = 400.

Question 4.
A box of 10 markers weighs 105 grams. If the empty box weighs 15 grams, how much does each marker weigh?

Answer:
Each marker weight= 9.

Explanation:
In the above-given question,
given that,
A box of 10 markers weighs 105 grams.
If the empty box weighs 15 grams.
9 x 10 = 90.
105 – 15 = 90.

Question 5.
Mr. Perez buys 3 sets of cards. Each set comes with 18 striped cards and 12 polka dot cards. He uses 49 cards. How many cards does he have left?

Answer:
The number of cards he left = 51 cards.

Explanation:
In the above-given question,
given that,
Mr. Perez buys 3 sets of cards.
Each set comes with 18 striped cards and 12 polka dot cards.
He uses 49 cards.
18 + 12 = 30.
30 x 3 = 90.
90 – 49 = 51.
so the number of cards he left = 51.

Question 6.
Ezra earns $9 an hour working at a book store. She works for 7 hours each day on Mondays and Wednesdays. How much does Ezra earn each week?

Answer:
The amount does Ezra earns = $126.

Explanation:
In the above-given question,
given that,
Ezra earns $9 an hour working at a book store.
She works for 7 hours each day on Mondays and Wednesdays.
7 + 7 = 14.
14 x 9 = 126.
so the amount Ezra earns = $126.

Eureka Math Grade 3 Module 3 Lesson 21 Exit Ticket Answer Key

Use the RDW process to solve. Use a letter to represent the unknown.

Frederick buys a can of 3 tennis balls. The empty can weighs 20 grams, and each tennis ball weighs 60 grams. What is the total weight of the can with 3 tennis balls?

Answer:
The total weight of the can with 3 tennis balls = 160 grams.

Explanation:
In the above-given question,
given that,
Frederick buys a can of 3 tennis balls.
The empty can weighs 20 grams, and each ball weighs 60 grams.
60 x 3 = 180.
180 – 20 = 160.

Eureka Math Grade 3 Module 3 Lesson 21 Homework Answer Key

Use the RDW process for each problem. Use a letter to represent the unknown.

Question 1.
There are 60 minutes in 1 hour. Use a tape diagram to find the total number of minutes in 6 hours and
15 minutes.

Answer:
The total number of minutes in 6 hours and 15 minutes = 375 minutes.

Explanation:
In the above-given question,
given that,
There are 60 minutes in 1 hour.
60 / n = 360.
360 / 60 = n.
n = 60 + 15.

Question 2.
Ms. Lemus buys 7 boxes of snacks. Each box has 12 packets of fruit snacks and 18 packets of cashews. How many snack packets does she buy altogether?

Answer:
The number of snack packets = 210.

Explanation:
In the above-given question,
given that,
Ms. Lemus buys 7 boxes of snacks.
Each box has 12 packets of fruit snacks and 18 packets of cashews.
12 + 18 = 30.
30 x 7 = 210.
so the number of snack packets = 210.

Question 3.
Tamara wants to buy a tablet that costs $437. She saves $50 a month for 9 months. Does she have enough money to buy the tablet? Explain why or why not.

Answer:
Yes, she has enough money.

Explanation:
In the above-given question,
given that,
Tamara wants to buy a table that costs $437.
she saves $50 a month for 9 months.
50 x 9 = 450.
so she has enough money to buy.

Question 4.
Mr. Ramirez receives 4 sets of books. Each set has 16 fiction books and 14 nonfiction books. He puts 97 books in his library and donates the rest. How many books does he donate?

Answer:
The number of books he donates = 23.

Explanation:
In the above-given question,
given that,
Mr. Ramirez receives 4 sets of books.
Each set has 16 fiction books and 14 nonfiction books.
He puts 97 books in his library and donates the rest.
16 + 14 = 30.
30 x 4 = 120.
120 – 97 = 23.
so the number of books he donates = 23.

Question 5.
Celia sells calendars for a fundraiser. Each calendar costs $9. She sells 16 calendars to her family members and 14 calendars to the people in her neighborhood. Her goal is to earn $300. Does Celia reach her goal? Explain your answer.

Answer:
No, she does not reach her goal.

Explanation:
In the above-given question,
given that,
Celia sells calendars for a fundraiser.
Each calendar costs $9.
she sells 16 calendars to her family members and 14 calendars to the people in her neighborhood.
16 + 14 = 30.
30 x 9 = 270.
so she does not reach her goal.

Question 6.
The video store sells science and history movies for $5 each. How much money does the video store make if it sells 33 science movies and 57 history movies?

Answer:
The video store makes = $450.

Explanation:
In the above-given question,
given that,
The video store sells science and history movies for $5 each.
33 + 57 = 90.
90 x 5 = 450.
so the video store makes = $450.

Eureka Math Grade 3 Module 3 Lesson 21 Template Answer Key

Answer:
30 x 6 = 180, 9 x 60 = 540, 40 x 2 = 80, 10 x 6 = 60, 70 x 3 = 210, 50 x 6 = 300, 80 x 9 = 720, 20 x 5 = 100, 8 x 30 = 240, 3 x 30 = 90, 5 x 50 = 250, 4 x 40 = 160, 6 x 80 = 480, 70 x 7 = 490, 20 x 7 = 140, 10 x 7 = 70, 90 x 7 = 630, 2 x 60 = 120, 50 x 7 = 350, 80 x 5 = 400, 60 x 6 = 360, 9 x 50 = 450, 30 x 9 = 270, 4 x 80 = 320.

Explanation:
In the above-given table,
given that,
the multiplication of 6, 7, 8, and 9 are given.
30 x 6 = 180, 9 x 60 = 540, 40 x 2 = 80, 10 x 6 = 60, 70 x 3 = 210, 50 x 6 = 300, 80 x 9 = 720, 20 x 5 = 100, 8 x 30 = 240, 3 x 30 = 90, 5 x 50 = 250, 4 x 40 = 160, 6 x 80 = 480, 70 x 7 = 490, 20 x 7 = 140, 10 x 7 = 70, 90 x 7 = 630, 2 x 60 = 120, 50 x 7 = 350, 80 x 5 = 400, 60 x 6 = 360, 9 x 50 = 450, 30 x 9 = 270, 4 x 80 = 320.

Eureka Grade 3 ensures students with the learning targets and success criteria. The Diverse opportunities will develop problem-solving skills among the primary school kids practicing Bigideas Math Grade 3 Solutions. Eureka Textbook Grade 3 answers help Students Master the subject on Consistent practice.

Engage NY Eureka Math 3rd Grade Module 3 Mid Module Assessment Answer Key

Grade 3 Eureka Math Answer Key is provided by subject experts as per the Common Core curriculum. Grade 3 Eureka Math Solutions provided educates the primary school Kids on all Math concepts of the chapter efficiently. Eureka Math Grade 3 Textbook Answers makes it easy for kids to Grasp the Concepts as well as solve any problem from chapter Tests, Practice Tests, Performance tests, cumulative practice, etc.

Eureka Math Grade 3 Module 3 Mid Module Assessment Answer Key

Question 1.
The carnival is in town for 21 days. How many weeks is the carnival in town? (There are 7 days in 1 week.) Write an equation, and solve.

Answer:
The number of weeks carnival in town = 3 weeks.

Explanation:
In the above-given equation,
given that,
The carnival is in town for 21 days.
1 week = 7 days.
7 / n = 21.
n = 21 / 7.
n = 3.

Question 2.
There are 48 liters of water needed to finish filling the dunk tank at the carnival. Each container holds 8 liters of water. How many containers are needed to finish filling the dunk tank? Represent the problem using multiplication and division sentences and a letter for the unknown. Solve.
____8___ × ____6___ = ____48___
___48____ ÷ ___8____ = ____6___

Answer:
The containers needed to finish filling the dunk tank = 6.

Explanation:
In the above-given question,
given that,
There are 48 liters of water needed to finish filling the dunk tank at the carnival.
Each container holds 8 liters of water.
8 / c = 48.
c = 48 / 8.
c = 6.
48 x c = 8.
c = 6 x 8.
c = 48.

Question 3.
There are 4 rows of 7 chairs setup for the Magic Show. A worker sees the large number of people lined up and doubles the number of rows of chairs. They are shown below.
Explain and label to show how the array represents both 8 × 7 and 2 × (4 × 7).

Answer:
8 x 7 = 56.

Explanation:
In the above-given question,
given that,
The number of rows = 8.
the number of columns = 7.
8 x 7 = 2 x (4 x 7).
(2 x 4 ) x 7.
8 x 7 = 56.

Question 4.
a. Fabrizio wins a bumblebee doll with 6 stripes. He notices that 5 other children in line for the Magic Show won the same doll. How many stripes are on 6 bumblebee dolls? Write an equation using a letter to represent the unknown. Solve.

Answer:
The number of stripes on bumblebee dolls = 30.

Explanation:
In the above-given question,
given that,
Fabrizio wins a bumblebee doll with 6 stripes.
He notices that 5 other children in line for the magic show won the same doll.
6 x n = 5.
n = 6 x 5.
n = 30.

The magician uses a magic box. Every time he puts an object in, it gets multiplied. Fabrizio writes down what happens each time and tries to find a pattern. Look at his notes to the right.

b. Use the pattern to fill in the number of bean bags.

Answer:
6 x 7 = 42.

Explanation:
In the above-given question,
given that,
6 x 7 = 42 bean bags.

c. What does the magic box do? Explain how you know.

Answer:
2 x 7 = 14.
3 x 7 = 21.
4 x 7 = 28.
5 x 7 = 35.
6 x 7 = 42.

Explanation:
In the above-given question,
given that,
Every time he put an object in, it gets multiplied.
2 x 7 = 14.
3 x 7 = 21.
4 x 7 = 28.
5 x 7 = 35.
6 x 7 = 42.

d. The magician puts 12 rings into the magic box. Fabrizio draws a number bond to find the total number of rings after they are multiplied in the magic box. Use the number bond to show how Fabrizio might have solved the problem.

Answer:
12 x 7 = 84.

Explanation:
In the above-given question,
given that,
6 x 7 = 42 and 6 x 7 = 42.
42 + 42 = 84.

e. After the show, Fabrizio and 5 friends equally share the cost of a $54 magic set. They use the equation 6 × n = $54 to figure out how much each person pays. How much does Fabrizio pay?

Answer:
The amount each person pays = $9.

Explanation:
In the above-given question,
given that,
Fabrizio and 5 friends equally share the cost of a $54 magic set.
They use the equation 6 x n = $54.
n = 54 / 6.
n = 9.