13 Times Table | How to Read & Write Multiplication Table of 13 | Tips to Remember 13 Table Chart

13 Times Table

Learning tables from 1 to 20 is the most important part of elementary education. Every student is supposed to study 13 table as mathematics have most of the problems depending on it. Become perfect with all math tables by going through our complete article. Some of the students may feel it is very difficult to remember the multiplication table of 13 as the values are hard to remember. Get the tricks and tips to memorize the 13 times table, know how to read and write Thirteen Times Table.

13 Times Table Chart

13 times multiplication tables in table format and image format is given here. So, it makes it easy for you to remember the values. Download 13 table charts for free and prepare well. The 13th table is helpful to perform the multiplication of numbers easily. You can save your time in competitive eams by learning these multiplication tables.

13 times table 1

How to Read 13 Table?

Check the reading of the 13 multiplication table here.

One time thirteen is 13.

Two times thirteen is 26.

Three times thirteen is 39.

Four times thirteen is 52.

Five times thirteen is 65.

Six times thirteen is 78.

Seven times thirteen is 91.

Eight times thirteen is 104.

Nine times thirteen is 117.

Ten times thirteen is 130.

Importance of Multiplication Tables

Multiplication tables play an essential role in mathematics. It is the foundation of elementary maths. By learning the table chart, you will get self-confidence while doing multiplications. You can keep the information at your fingertips that help you to solve the questions quickly. Multiplication tables will enhance your memory power and improve the calculations speed.

Tables from 2 to 20 help in performing the simple arithmetic operations. So that you can save time and do calculations easily. Without learning the 13 times table, you can also calculate the multiplicative of 13 by performing the arithmetic multiplication operations.

Multiplication Table of 13 up to 20

Studying 13 Multiplication Table is an essential skill to solve the division and multiplication questions. Check out the below table to know how to write a 13 times table chart.

13x1=13
13x2=26
13x3=39
13x4=52
13x5=65
13x6=78
13x7=91
13x8=104
13x9=117
13x10=130
13x11=143
13x12=156
13x13=169
13x14=182
13x15=195
13x16=208
13x17=221
13x18=234
13x19=247
13x20=260

Tips and Tricks to Learn 13 Times Table

Here we are giving the easy tips that are helpful to remember the 13th table. Follow the below tricks and learn the multiplication tables quickly.

  • To remember the 13 times table, first, we need to memorize the 3 times table. So, the multiples of 3 are 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, . . .
  • For getting the multiples of 13, add natural numbers to the ten’s digit of the 3 multiples. Therefore, 13 times table is obtained as (1 + 0)3 = 13, (2 + 0)6 = 26 , (3 + 0)9 = 39, (4 + 1)2 = 52, (5 + 1)5 = 65, (6 + 1)8 = 78, (7 + 2)1 = 91, (8 + 2)4 = 104, (9 + 2)7 = 117, (10 + 3)0 = 130, . . .
  • 13 does not have any rules that make the multiplication of 13 table easier to memorize, then there is a structure for every 10 multiples of 13. They are 13, 26, 39, 52, 65, 78, 91, 104, 117, 130. In all these multiples, the last digit i.e units place digit is repeating. So, one can remember this logic to memorize the table.

Get More Math Tables:

0 Times Table1 Times Table2 Times Table
3 Times Table4 Times Table5 Times Table
6 Times Table7 Times Table8 Times Table
9 Times Table10 Times Table11 Times Table
12 Times Table14 Times Table15 Times Table
16 Times Table17 Times Table18 Times Table
19 Times Table20 Times Table21 Times Table
22 Times Table23 Times Table24 Times Table
25 Times Table

Solved Examples on 13 Times Table Multiplication

Example 1:

Using the table of 13, calculate 13 times 13 plus 13?

Solution:

From the given data

We can express the given data in the form of Mathematical Expression

= (13 x 13) + 13

= 169 + 13

= 182

Therefore, 13 times 13 plus 13 is 182.

Example 2:

If David’s father has to pay the amount “12 less than 13 times 15” in dollars. Using the table of 13, find how much he needs to pay?

Solution:

From the given data,

The mathematical expression of 12 less than 13 times 15 = (13 x 15) – 12

= 195 – 12

= 183

therefore, David’s father is required to pay $183.

Example 3: 

Families in a colony are going on a picnic. If 13 people ride in each car and there are 5 cars, then how many people are going on a picnic?

Solution:

Given that,

The number of people going on picnic = 13

Number of cars = 5

Then, multiply the number of people on each car, total number of cars on the picnic to get the total number of persons going for the picnic.

The number of persons going on the picnic = 13 x 5

= 65

Therefore, 65 people going on a picnic.

Example 4:

Using the 13 times table, check whether 13 times 7 minus 1 plus 10 is 100?

Solution:

Firstly, let us express the given statement in the form of mathematical expression

13 times 7 minus 1 plus 10 = (13 x 7) – 1 + 10

= (91) + 9

= 100

Hence, 13 times 7 minus 1 plus 10 is 100.

Math Tables 0 to 25 | Multiplication Tables of 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25 | Tips to Learn Multiplication Tables

Math Tables

Memorizing the Math Tables 0 to 25 you can do quick computations and save a lot of time. It is advised for Students to by heart the Multiplication Tables to have a stronger foundation of basics right from an early age. Refer to the complete guide and learn the Tips & Tricks to Memorize the Multiplication Tables. Know why one should learn these Math Tables as a part of their learning.

Multiplication Tables for 0 to 25

Below is the list of Math Tabes for 0 to 25 to make your math calculations easier and faster. These Time Tables from 0 to 25 help your child to skillfully tackle complex problems too with ease. Remembering the Multiplication Tables not just brings out self-confidence in you but also keeps information prepared at your fingertips so that you can use it whenever required. On Mastering the 0 to 25 Multiplication Charts children can enhance their speed and accuracy.

Maths Tables 0 to 25
0 Times Table1 Times Table
2 Times Table3 Times Table
4 Times Table5 Times Table
6 Times Table7 Times Table
8 Times Table9 Times Table
10 Times Table11 Times Table
12 Times Table13 Times Table
14 Times Table15 Times Table
16 Times Table17 Times Table
18 Times Table19 Times Table
20 Times Table21 Times Table
22 Times Table23 Times Table
24 Times Table25 Times Table

Importance of Math Tables or Multiplication Tables

Math Tables are the basic blocks of arithmetic calculations. Learning these Multiplication Tables can stimulate the memory power in kids and develop observation skills. Things learned at an early age can be retained for a long time. Refer to the below modules to know why one should learn Maths Tables and they are as such

  • Multiplication Tables are quite important as they support in student’s mathematical learning.
  • Students can get a strong grasp of facts associated with multiplication.
  • Makes it easier to solve problems in Mathematics.
  • The one who tends to be good at these Times Tables will be self-confident while learning new math concepts.

Tips to Memorize Multiplication Times Tables

Most of you might struggle to memorize the math tables. However, we have curated few effective tips that help you to learn the Math Times Tables easily. They are in the following fashion

  • Practice Skip Counting i.e. if you start with a number 2 keep adding 2 every time you count. That is you would say 2, 4, 6, 8, 10, 12, 14…..
  • Recite the multiplication tables in order at least once a day until you remember them. Also, learn reverse recitation of tables.
  • If you have any difficulty in remembering you can always opt for writing and memorizing. Make it a habit in your daily routine and try to memorize once.
  • Apply multiplication tables to real life and try to understand them using real-life scenarios.
  • Identify the Multiplication Table Patterns so that you can remember them much faster.

Learn 2 to 9 Times Multiplication Tricks

FAQs on Maths Times Tables

1. What is the easiest way to memorize the multiplication tables?

One of the easiest ways to memorize the Math Tables is through addition. We know the number of times a number is multiplied with another number it is added to itself the same number of times repeatedly.

2. How to memorize Multiplication Times Table?

In order to memorize the Multiplication Times Table start reciting it verbally on a regular basis or write it down on paper. In fact, you can solve questions involving multiplication charts to retain them for a long time.

 3. How Can I Learn Tables Fast?

Start with the easiest ones and then work on them until you feel confident. Learn the Tips & Tricks to memorize the Math Tables easily. Recite them as many times as possible or write to remember them fast.

3 Times Table Multiplication Chart | Learn How to Read & Write 3 Times Multiplication Table | Tips to Memorize Table of Three

3 Times Table

Students are advised to learn the Multiplication Table of 3 for quick calculations. 3 Times Table is the multiplication table of prime number 3 with other whole numbers. Table of 3 can be easily found using the repeated addition. Math Tables proves to be an excellent brain activity for kids right from an early age. Check How to Read and Write 3 Times Multiplication Chart, Tips to Remember the Three Table. Learn to solve problems involving Multiplication Table of 3 by referring to the complete article.

3 Times Multiplication Chart

Learning Table of 3 is quite essential to do your math calculations in a much faster way. Utilize the Table of 3 to understand and gain a deeper insight into the multiplication operation. For your idea, we have given the 3 Times Multiplication Table in image format. You can download and save it without paying us a single penny. Use this Table of 3 Chart for quick reference and try to recite it every day and memorize it easily.

Multiplication Chart of Three

How to Read Three Times Multiplication Table?

One time three is 3

Two times three is 6

Three times three is 9

Four times three is 12

Five times three is 15

Six times three is 18

Seven times three is 21

Eight times three is 24

Nine times three is 27

Ten times three is 30

Eleven times three is 33

Twelve times three is 36

How to write a Multiplication Table of 3? | Three Times Table upto 20

Learn how to write Table of 3 by checking out the below table. We have outlined the 3 Times Table up to 20 natural numbers so that you can get deeper knowledge on the multiplication which would be beneficial in the long run.

3x1=3
3x2=6
3x3=9
3x4=12
3x5=15
3x6=18
3x7=21
3x8=24
3x9=27
3x10=30
3x11=33
3x12=36
3x13=39
3x14=42
3x15=45
3x16=48
3x17=51
3x18=54
3x19=57
3x20=60

Why should you Learn the Multiplication Table of 3?

Go through the below lines to know the importance of the Three Table. They are along the lines

  • Learning the Table of 3 is a necessary skill to solve problems on long division and multiplication.
  • You can perform your metal math calculations right in your head and improve your problem-solving skills.
  • By Learning the Multiplication Table of 3, you can understand the pattern of multiples.
  • Ensures faster calculations and saves a lot of time.

Tips to Memorize 3 Times Table

Follow the below-listed tips & tricks to keep in mind to learn and memorize the Multiplication Table of 3. They are in the below fashion

        • Apparently, there are any rules that make the table of 3 easy to remember. However, there is a pattern for every 10 multiples of 3 i.e. 3, 6, 9, 12, 15, 18, 21, 24, 27, 30.
        • The last digit of these multiples will always repeat. You can remember these digits to memorize the multiples of 3 easily.
        • Another way to learn 3 up to 10 is through skip counting.

      Tips for 3 Times Table

By referring to the above image you can understand that the units digit are nothing but counting numbers written three in one column in descending order from right to left. 0 is left outside the grid. Later, place the digit 0 before the units digit in row 1 and digit 1 in the second row and digit 2 in the third row. Also, place 3 before the digit 0 outside the grid. That’s it you have got the first ten multiples of 3.

Get More Math Tables:

0 Times Table1 Times Table2 Times Table
4 Times Table5 Times Table6 Times Table
7 Times Table8 Times Table9 Times Table
10 Times Table11 Times Table12 Times Table
13 Times Table14 Times Table15 Times Table
16 Times Table17 Times Table 18 Times Table
19 Times Table20 Times Table21 Times Table
22 Times Table23 Times Table24 Times Table
25 Times Table

Solved Examples Involving 3 Times Table

1. Using 3 times table, evaluate 3 times 6 minus 3?

Solution:

From the given statement we can write the mathematical expression as follows

= 3*6-3

= 18-3

=15

Thus, 3 times 6 minus 3 is 15

2. Using the table of 3, Find the value of 3 plus 3 times 7 minus 5?

Solution:

First, let us write 3 plus 3 times 7 minus 5 mathematically

= 3+3*7-5

= 3+21-5

= 24-5

= 19

Hence, 3 plus 3 times 7 minus 5 is 19

3. Find the value of 4 plus 3 times 6?

Solution:

Let us write the given statement mathematically

= 4+3*6

= 4+18

= 22

Hence, 4 plus 3 times 6 is 22

4. Using the table of 3, find the value of 3 times 5 minus 3 times 2?

Solution:

Let us write the given statement mathematically

= 3*5-3*2

= 15-6

=9

Hence, 3 times 5 minus 3 times 2 is 9.

2 Times Table | Learn Multiplication Table of Two | Tips & Tricks to Remember Table of 2

2 Times Table

Maths is completely tips and tricks and Multiplication Table of Two is no more different. Learning Multiplication Chart of 2 is important as it makes mental maths easier. You can attempt complex problems too easily with confidence if you know the Table of Two. Learn the Tips & Tricks to Memorize the Multiplication Table of 2, How to Read and Write 2 Times Table. Also, Read Solved Examples Involving 2 Table for a better understanding of the concept.

Multiplication Table of 2

Here is the Multiplication Chart of Two in image format. Use it as a quick reference to make your mental math calculations much easier. Learning Table of 2 Promotes a better understanding of the multiplication operation. Knowing the basic math tables you can solve the maths problems in no time. You can save a lot of time in your competitive exams by learning the 2 Times Multiplication Table.

2 Times Table Multiplication Chart

How to Read Table of Two?

One time two is 2

Two times two is 4

Three times two is 6

Four times two is 8

Five times two is 10

Six times two is 12

Seven times two is 14

Eight times two is 16

Nine times two is 18

Ten times two is 20

Eleven times two is 22

Twelve times two is 24

Multiplication Table of Two upto 20 | How to Write 2 Times Table?

Below is the Table of 2 up to 20 Natural Numbers. You can avail the Multiplication Table of Two here and use it whenever you need to perform quick calculations. Refer to the 2 Times Table over here to memorize it quickly and recite it on a regular basis so that you can retain it for a long time.

2x1=2
2x2=4
2x3=6
2x4=8
2x5=10
2x6=12
2x7=14
2x8=16
2x9=18
2x10=20
2x11=22
2x12=24
2x13=26
2x14=28
2x15=30
2x16=32
2x17=34
2x18=36
2x19=38
2x20=40

Get More Math Tables:

0 Times Table1 Times Table3 Times Table
4 Times Table5 Times Table6 Times Table
7 Times Table8 Times Table9 Times Table
10 Times Table11 Times Table12 Times Table
13 Times Table14 Times Table15 Times Table
16 Times Table17 Times Table18 Times Table
 19 Times Table20 Times Table21 Times Table
22 Times Table23 Times Table24 Times Table
25 Times Table

How to Learn Multiplication Table of Two?

Table of 2 is quite basic and one of the easiest tables to learn and memorize. Let us learn how to obtain and memorize the multiplication table of 2 in the below sections. Basic things to observe in the Multiplication Table of Two are as such

  • 2 Times Table follows the pattern 2, 4, 6, 8, 0 in the units place.
  • It will always have even numbers
  • It is simple as we can learn using skip counting i.e. 2, 4, 6, 8, 10, 12……

Tips to Memorize Two Times Table

Follow the tips & tricks to memorize the multiplication table of 2 by referring to the below modules. They are along the lines

  • Two Times Table always follows the pattern of the even numbers i.e. 2, 4, 6, 8, 10, ….
  • Another simple way to memorize the Table of Two is through addition.
  • You can memorize the Two Table taking the help of the 1 Times Table. All you have to do is simply add the natural numbers to multiples of 1 to get the Two Table.
    • 1×1+1 = 2
    • 1×2+2 =4
    • 1×3+3 =6
    • 1×4+4 =8
    • 1×5+5=10
    • 1×6+6 =12
    • 1×7+7=14
    • 1×8+8=16
    • 1×9+9=18
    • 1×10+10=20 and so on.

Solved Examples Involving Multiplication Table of 2

1. If Reethu eats 2 chocolates per day, Using the table of 2 find how many chocolates will she have eaten at the end of the 5th day?

Solution:

Reetu eats a number of chocolates per day = 2

Number of Chocolates Reethu eats at the end of the 5th day = 2*5

= 10

Therefore, Reethu eats 10 chocolates at the end of the 5th day.

2. Using 2 times table, find 2 times 3 times 4 times 2?

Solution:

Expressing the given statement in the form of mathematical expression we have

= 2*3*4*2

= 48

Therefore, 2 times 3 times 4 times 2 is 48.

3. James wants to buy 6 Pencils. If the cost of one Pencil is $2, using the table of 2, find the cost of 6 Pencils?

Solution:

The Cost of one Pencil is $2

No. of Pencils James wants to buy = 6

Cost of 6 Pencils = $2*6

= $12

Therefore, the cost of 6 Pencils is $12.

Mensuration – Definition, Introduction, Formulas, Solved Problems

In Maths Mensuration is nothing but a measurement of 2-D and 3-D Geometrical Figures. Mensuration is the study of the measurement of shapes and figures. We can measure the area, perimeter, and volume of geometrical shapes such as Cube, Cylinder, Cone, Cuboid, Sphere, and so on.

Keep reading this page to learn deeply about the mensuration. We can solve the problems easily, if and only we know the formulas of the particular shape or figure. This article helps to learn the mensuration formulae with examples. Learn the difference between the 2-D and 3-D shapes from here. Understand the concept of Mensuration by using various formulas.

Definition of Mensuration

Mensuration is the theory of measurement. It is the branch of mathematics that is used for the measurement of various figures like the cube, cuboid, square, rectangle, cylinder, etc. We can measure the 2 Dimensional and 3 Dimensional figures in the form of Area, Perimeter, Surface Area, Volume, etc.

What is a 2-D Shape?

The shape or figure with two dimensions like length and width is known as the 2-D shape. An example of a 2-D figure is a Square, Rectangle, Triangle, Parallelogram, Trapezium, Rhombus, etc. We can measure the 2-D shapes in the form of Area (A) and Perimeter (P).

What is 3-D Shape?

The shape with more or than two dimensions such as length, width, and height then it is known as 3-D figures. Examples of 3-Dimensional figures are Cube, Cuboid, Sphere, Cylinder, Cone, etc. The 3D figure is determined in the form of Total Surface Area (TSA), Lateral Surface Area (LSA), Curved Surface Area (CSA), and Volume (V).

Introduction to Mensuration

The important terminologies that are used in mensuration are Area, Perimeter, Volume, TSA, CSA, LSA.

  • Area: The Area is an extent of two-dimensional figures that measure the space occupied by the closed figure. The units for Area is square units. The abbreviation for Area is A.
  • Perimeter: The perimeter is used to measure the boundary of the closed planar figure. The units for Perimeter is cm or m. The abbreviation for Perimeter is P.
  • Total Surface Area: The total surface area is the combination or sum of both lateral surface area and curved surface area. The units for the total surface area is square cm or m. The abbreviation for the total surface area is TSA.
  • Lateral Surface Area: It is the measure of all sides of the object excluding top and base. The units for the lateral surface area is square cm or m. The abbreviation for the lateral surface area is LSA.
  • Curved Surface Area: The area of a curved surface is called a Curved Surface Area. The units of the curved surface area are square cm or m. The abbreviation for the curved surface area is CSA.
  • Volume: Volume is the measure of the three dimensional closed surfaces. The units for volume is cubic cm or m. The abbreviation for Volume is V.

Mensuration Formulas for 2-D Figures

Check out the formulas of 2-dimensional figures from here. By using these mensuration formulae students can easily solve the problems of 2D figures.

1. Rectangle:

  • Area = length × width
  • Perimeter = 2(l + w)

2. Square:

  • Area = side × side
  • Perimeter = 4 × side

3. Circle:

  • Area = Πr²
  • Circumference = 2Πr
  • Diameter = 2r

4. Triangle:

  • Area = 1/2 × base × height
  • Perimeter = a + b + c

5. Isosceles Triangle:

  • Area = 1/2 × base × height
  • Perimeter = 2 × (a + b)

6. Scalene Triangle:

  • Area = 1/2 × base × height
  • Perimeter = a + b + c

7. Right Angled Triangle:

  • Area = 1/2 × base × height
  • Perimeter = b + h + hypotenuse
  • Hypotenuse c = a²+b²

8. Parallelogram:

  • Area = a × b
  • Perimeter = 2(l + b)

9. Rhombus:

  • Area = 1/2 × d1 × d2
  • Perimeter = 4 × side

10. Trapezium:

  • Area = 1/2 × h(a + b)
  • Perimeter = a + b + c + d

11. Equilateral Triangle:

  • Area = √3/4 × a²
  • Perimeter = 3a

Mensuration Formulas of 3D Figures

The list of the mensuration formulae for 3-dimensional shapes is given below. Learn the relationship between the various parameters from here.

1. Cube:

  • Lateral Surface Area = 4a²
  • Total Surface Area = 6a²
  • Volume = a³

2. Cuboid:

  • Lateral Surface Area = 2h(l + b)
  • Total Surface Area = 2(lb + bh + lh)
  • Volume = length × breadth × height

3. Cylinder:

  • Lateral Surface Area = 2Πrh
  • Total Surface Area = 2Πrh + 2Πr²
  • Volume = Πr²h

4. Cone:

  • Lateral Surface Area = Πrl
  • Total Surface Area = Πr(r + l)
  • Volume = 1/3 Πr²h

5. Sphere:

  • Lateral Surface Area = 4Πr²
  • Total Surface Area = 4Πr²
  • Volume = (4/3)Πr³

6. Hemisphere:

  • Lateral Surface Area = 2Πr²
  • Total Surface Area = 3Πr²
  • Volume = (2/3)Πr³

Solved Problems on Mensuration

Here are some questions that help you to understand the concept of Mensuration. Use the Mensuration formulas to solve the problems.

1. Find the Length of the Rectangle whose Perimeter is 24 cm and Width is 3 cm?

Solution:

Given that,
Perimeter = 24 cm
Width = 3 cm
Perimeter of the rectangle = 2(l + w)
24 cm = 2(l + 3 cm)
2l + 6 = 24
2l + 6 = 24
2l = 24 – 6 = 18
2l = 18
l = 9 cm
Thus length of the rectangle = 9 cm

2. Calculate the volume of the Cuboid whole base area is 60 cm² and height is 5 cm.

Solution:

Given,
Base area = 60 cm²
Height = 5 cm
Volume of the Cuboid = base area × height
V = 60 cm² × 5 cm
V = 300 cm³
Thus the volume of the cuboid is 300 cm³.

3. Find the area of the Cube whose side is 10 centimeters.

Solution:

Given, side = 10 cm
Lateral Surface Area = 4a²
LSA = 4 × 10 × 10 = 400 cm²
Total Surface Area = 6a²
= 6 × 10 × 10 = 600 cm²
Volume of the cube = a³
V = 10 × 10 × 10 = 1000 cm³
Therefore the volume of the cube is 1000 cubic centimeters.

4. What is the lateral surface area of the sphere if the radius is 5 cm.

Solution:

Given,
The radius of the sphere = 5 cm
The formula for LSA of sphere = 4Πr²
Π = 3.14 or 22/7
LSA = 4 × 3.14 × 5 cm × 5 cm
LSA = 314 sq. cm
Thus the lateral surface area of the sphere is 314 sq. cm

5. What is the area of the parallelogram if the base is 15 cm and height is 10 cm.

Solution:

Given, Base = 15 cm
Height = 10 cm
We know that,
Area of parallelogram = bh
A = 15 cm × 10 cm
A = 150 sq. cm
Therefore the area of the parallelogram is 150 sq. cm.

FAQs on Mensuration

1. What is the use of Mensuration?

Mensuration is used to find the length, area, perimeter, and volume of the geometric figures.

2. What is the difference between 2D and 3D figures?

In 2D we can measure the area and perimeter. In 3D we can measure LSA, TSA, and Volume.

3. What is Mensuration in Math?

Mensuration is the branch of mathematics that studies the theory of measurement of 2D and 3D geometric figures or shapes.

శ్రీ వెంకటేశ్వర అష్టోత్తర శతనామ స్తోత్రం

Area and Perimeter Definition, Formulas | How to find Area and Perimeter?

Area and Perimeter is an important and basic topic in the Mensuration of 2-D or Planar Figures. The area is used to measure the space occupied by the planar figures. The perimeter is used to measure the boundaries of the closed figures. In Mathematics, these are two major formulas to solve the problems in the 2-dimensional shapes.

Each and every shape has two properties that are Area and Perimeter. Students can find the area and perimeter of different shapes like Circle, Rectangle, Square, Parallelogram, Rhombus, Trapezium, Quadrilateral, Pentagon, Hexagon, and Octagon. The properties of the figures will vary based on their structures, angles, and size. Scroll down this page to learn deeply about the area and perimeter of all the two-dimensional shapes.

Area and Perimeter Definition

Area: Area is defined as the measure of the space enclosed by the planar figure or shape. The Units to measure the area of the closed figure is square centimeters or meters.

Perimeter: Perimeter is defined as the measure of the length of the boundary of the two-dimensional planar figure. The units to measure the perimeter of the closed figures is centimeters or meters.

Formulas for Area and Perimeter of 2-D Shapes

1. Area and Perimeter of Rectangle:

  • Area = l × b
  • Perimeter = 2 (l + b)
  • Diagnol = √l² + b²

Where, l = length
b = breadth

2. Area and Perimeter of Square:

  • Area = s × s
  • Perimeter = 4s

Where s = side of the square

3. Area and Perimeter of Parallelogram:

  • Area = bh
  • Perimeter = 2( b + h)

Where, b = base
h = height

4. Area and Perimeter of Trapezoid:

  • Area = 1/2 × h (a + b)
  • Perimeter = a + b + c + d

Where, a, b, c, d are the sides of the trapezoid
h is the height of the trapezoid

5. Area and Perimeter of Triangle:

  • Area = 1/2 × b × h
  • Perimeter = a + b + c

Where, b = base
h = height
a, b, c are the sides of the triangle

6. Area and Perimeter of Pentagon:

  • Area = (5/2) s × a
  • Perimeter = 5s

Where s is the side of the pentagon
a is the length

7. Area and Perimeter of Hexagon:

  • Area = 1/2 × P × a
  • Perimeter = s + s + s + s + s + s = 6s

Where s is the side of the hexagon.

8. Area and Perimeter of Rhombus:

  • Area = 1/2 (d1 + d2)
  • Perimeter = 4a

Where d1 and d2 are the diagonals of the rhombus
a is the side of the rhombus

9. Area and Perimeter of Circle:

  • Area = Πr²
  • Circumference of the circle = 2Πr

Where r is the radius of the circle
Π = 3.14 or 22/7

10. Area and Perimeter of Octagon:

  • Area = 2(1 + √2) s²
  • Perimeter = 8s

Where s is the side of the octagon.

Solved Examples on Area and Perimeter

Here are some of the examples of the area and perimeter of the geometric figures. Students can easily understand the concept of the area and perimeter with the help of these problems.

1. Find the area and perimeter of the rectangle whose length is 8m and breadth is 4m?

Solution:

Given,
l = 8m
b = 4m
Area of the rectangle = l × b
A = 8m × 4m
A = 32 sq. meters
The perimeter of the rectangle = 2(l + b)
P = 2(8m + 4m)
P = 2(12m)
P = 24 meters
Therefore the area and perimeter of the rectangle is 32 sq. m and 24 meters.

2. Calculate the area of the rhombus whose diagonals are 6 cm and 5 cm?

Solution:

Given,
d1 = 6cm
d2 = 5 cm
Area = 1/2 (d1 + d2)
A = 1/2 (6 cm + 5cm)
A = 1/2 × 11 cm
A = 5.5 sq. cm
Thus the area of the rhombus is 5.5 sq. cm

3. Find the area of the triangle whose base and height are 11 cm and 7 cm?

Solution:

Given,
Base = 11 cm
Height = 7 cm
We know that
Area of the triangle = 1/2 × b × h
A = 1/2 × 11 cm × 7 cm
A = 1/2 × 77 sq. cm
A = 38.5 sq. cm
Thus the area of the triangle is 38.5 sq. cm.

4. Find the area of the circle whose radius is 7 cm?

Solution:

Given,
Radius = 7 cm
We know that,
Area of the circle = Πr²
Π = 3.14
A = 3.14 × 7 cm × 7 cm
A = 3.14 × 49 sq. cm
A = 153.86 sq. cm
Therefore the area of the circle is 153.86 sq. cm.

5. Find the area of the trapezoid if the length, breadth, and height is 8 cm, 4 cm, and 5 cm?

Solution:

Given,
a = 8 cm
b = 4 cm
h = 5 cm
We know that,
Area of the trapezoid = 1/2 × h(a + b)
A = 1/2 × (8 + 4)5
A = 1/2 × 12 × 5
A = 6 cm× 5 cm
A = 30 sq. cm
Therefore the area of the trapezoid is 30 sq. cm.

6. Find the perimeter of the pentagon whose side is 5 meters?

Solution:

Given that,
Side = 5 m
The perimeter of the pentagon = 5s
P = 5 × 5 m
P = 25 meters
Therefore the perimeter of the pentagon is 25 meters.

FAQs on Area and Perimeter

1. How does Perimeter relate to Area?

The perimeter is the boundary of the closed figure whereas the area is the space occupied by the planar.

2. How to calculate the perimeter?

The perimeter can be calculated by adding the lengths of all the sides of the figure.

3. What is the formula for perimeter?

The formula for perimeter is the sum of all the sides.

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Constants and Variables Definitions | Difference Between Constants and Variables with Examples

Constants and Variables

Constants and Variables are the popular terms used in algebra. Every expression or equation will be implemented with a combination of constants and variables. Constant is a fixed value in every expression and the variables are not fixed values. Learn different problems on Constants and Variables and get a grip on the complete concept.
Example:
x^2 + 2xy + 6 is an algebraic equation.
Here, 6 cannot be changed and it is the constant number in the equation, and x^2, 2xy values are varied depends on the values. So, x^2 and 2xy are variables in the equation.

Constant & Variables – Definitions

Constant: A Constant is defined as a fixed value in algebraic expressions or equations. Constant will not change with time and has a fixed value. For instance, Shoe Size will not vary at any point.

In an algebraic expression, x+y = 5, 5 is a constant value, and will not be changed.

Variables: Variables are terms that can change or differ over time. It will not have a fixed value unlike a constant. For example, the Height and Weight of a Person will not remain constant and will vary with time.

In an algebraic expression, x+y = 5, x and y are the variables and can be varied. Go through the below modules to know more about the key differences between Constants and Variables.

Difference Between Constants and Variables

See the main differences between Constants and Variables here. ?They are along the lines

  • The main difference between the constants and variables, constant is a fixed value and a variable is not a fixed value.
  • Constants are indicated by the numerical values and the variables are indicated by any alphabetical values like a, b, c, d, ………..z.

Examples of Constants and Variables

Find the Constants and Variables of Given Expressions.

1. x + y + 2 =0.

Solution:
The given expression is x + y + 2 = 0.
Here, x and y are variables.
2 is a constant number.

2. x^2 + y^2 + 20 = 0.

Solution:
The given expression is x^2 + y^2 + 20 = 0.
Here, x^2 and y^2 are variables.
20 is a constant number.

3. xy + x^2 + 15 = 0.

Solution:
The given expression is xy + x^2 + 15 = 0.
Here, xy and x^2 are variables.
15 is a constant number.

4. 2xy + 6 = x^2y.

Solution:
The given expression is 2xy + 6 = x^2y.
Here, 2xy and x^2y are variables.
6 is a constant number.

5. x^3 + y^3 = 2xy + 8.

Solution:
The given expression is x^3 + y^3 = 2xy + 8.
Here, x^3, y^3, and 2xy are variables.
8 is a constant number.

6. Find out the constants and variables in the below questions

(i) In 5m, 5 is a constant and m is a variable.
(ii) In -3ab, -3 is a constant and a and b are variables.
(iii) In 4b, 4 is constant and b is variable but together 4b is a variable.
(iv) If 2 is a constant and a is a variable, then 2 + a, 2 – a, 2/a, 2a, a/2, etc., are also variables.

FAQs on Constants and Variables

1. What is the main difference between variables and constant?
The major difference between variables and constants is variable is a varying quantity, and a constant is a fixed value.

2. What are the variables?
The variables are the terms in an algebraic equation that can be changed or that are not fixed. Example: a + b = 8, where a and b are the variables, and 8 is a constant.

3. What are constants? 
The constants are the value in an algebraic expression that cannot be modified or changed. For example, in an equation x + y = 9, 9 is the constant value.

4. What is an algebraic expression?
The algebraic expression is a combination of constants, variables, integers, and mathematical operations.

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Common Factors Definition, Examples | How to Find Common Factors?

Common Factors

A factor is a number that is the exact multiplicand of another number. Every number factor is less than or equal to the given number but it cannot be greater than the given number. Every number has at least 2 factors. Common factors are also the factors that are common to two or more numbers. Fet the detailed steps to find the common factors of 2 or more numbers, solved examples, and applications in the below sections.

What are Common Factors?

Common Factors are defined as the factors that are common to two or more numbers. You can also say that a common factor is a number with which a set of two or more numbers will be divided exactly.

To find the common factors of two numbers, you need to list the factors of each number separately and then compare them. Now write the factors which are common and those are called common factors for the given numbers.

How to find Common Factors?

Factors are the numbers that divide the original number. Here are the steps to check whether two or more numbers have common factors or not.

  • Get the factors of each number separately.
  • Compare the factors of two numbers.
  • If you find common numbers then those are common factors between two numbers.

Example:

Common Factors of 4, 12

Find the factors of given numbers

4 = 1, 2, 4

12 = 1, 2, 3, 4, 6, 12

The common factors between 4 and 12 are 1, 2, 4.

Read More Articles,

Common Factors Examples

Example 1:

Find the common factors of 2, 16?

Solution:

The given numbers are 2, 16

Factors of 2 = 1, 2

Factors of 16 = 1, 2, 4, 8, and 16

Therefore, common factors of 2 and 16 = 1, 2.

Example 2:

Calculate the common factors of 14, 21?

Solution:

The given numbers are 14, 21

Factors of 14 = 1, 2, 7, 14

Factors of 21 = 1, 3, 7, 21

Therefore, common factors of 14 and 21 = 1, 7.

Example 3:

Find the common factors of 15, 45?

Solution:

The given numbers are 15, 45

Factors of 15 = 1, 3, 5, 15

Factors of 45 = 1, 3, 15, 5, 9, 45

Therefore, common factors of 15 and 45 = 1, 3, 5, 15.

Example 4:

Find the common factors of 36 and 63.

Solution:

The given numbers are 36, 63

The factors of 36 are

1 × 36 = 36

2 × 18 = 36

3 × 12 = 36

4 × 9 = 36

6 × 6 = 36

Stop here, since the number 6 is repeated.

So, 1, 2, 3, 4, 6, 9, 12, 18, and 36 are factors of 36.

The factors of 63 are

1 × 63 = 63

3 × 21 = 63

7 × 9 = 63

9 × 7 = 63

Stop here, since the numbers 7 and 9 are repeated.

So, 1, 3, 7, 9, 21, and 63 are factors of 63.

1, 3, and 9 are common in both lists.

Hence, the common factors of 36 and 63 are 1, 3, 9.

Calculate Profit and Profit Percent – Formula, Examples | How to find Profit from Profit Percent?

Calculate Profit and Profit Percent

Calculate Profit and Profit Percent using Profit formula. Easily calculate the profit gained for a product by selling it. All the business or financial transactions are used the profit formula. The profit is calculated when the selling price of any product sold is greater than the cost price. Check out how the profit is calculated and know the profit gained by your business. We have included solved problems along with explanations.

Also, Read:

Formulas to Calculate Profit

If the selling price is more than the cost price (S.P. > C.P.), there is a profit. Various formulas to calculate profit are given below. Remember all of them for better learning.

  • Formula for Profit Profit = S.P – C.P.
  • Formula for Profit Percentage = Profit Percent Formula = (Profit x 100)/C.P.
  • Gross Profit Formula = Gross Profit = Revenue – Cost of Goods Sold
  • Profit Margin Formula = Profit Margin = (Total Income/Net Sales) x 100
  • Gross Profit Margin Formula = Gross Profit Margin = (Gross Profit/Net Sales) x 100

Notation Used in Profit Formula

  • S.P. = Selling Price i.e. the cost at which the product is sold
  • C.P. = Cost price i.e. the cost at which the product is originally bought

Profit and Profit Percent Examples

Example 1.

Ram purchased 300 calculators at $100 each. He spent $5 on packing each calculator, paid $50 to the carrying for loading, and $500 on transportation. He sold 200 at a rate of $180 each and 100 at the rate of $80 each. Find his profit or loss percent in the whole transportation.

Solution:
Given that Ram purchased 300 calculators at $100 each.
C.P. of 1 calculator = $100
C.P. of 300 calculators = $100 x 300 = $30000
Money spent on packing 1 calculator = $5
Money spent on packing 300 calculators = $300 x 5 = $1500
Overhead expenses = $(1500 + 50 + 500) = $2050
C.P. of 300 calculators = Actual C.P. + Overhead expenses
C.P. of 300 calculators = $30000 + $2050 = $32050
S.P. of 300 calculators = S.P. of 200 calculators + S.P. of 100 calculators
S.P. of 1 calculator = $180
S.P. of 200 calculators = $180 x 200 = $36000
S.P. of 1 calculator = $80
S.P. of 100 calculators = $80 x 100 = $8000
S.P. of 300 calculators = $36000 + $8000 = $44000
S. P. > C. P., there is profit, therefore, profit – S.P. – C.P.
Profit = $44000 – $32050 = $11950
Profit% = P/C.P. x 100%
Profit% = $11950/$32050 x 100%
Profit% = 37.28%

The profit percentage is 37.28%.

Example 2.

A cloth merchant bought 25 shirts, each at a price of Rs 280. He sold each of them for Rs. 300. Find his percentage profit.

Solution:
Given that a cloth merchant bought 25 shirts, each at a price of Rs 280. He sold each of them for Rs. 300.
The profit percentage remains the same for one unit as well for all the units. Thus the calculations should be done for one unit only.
The Cost Price = Rs 280
Selling Price = Rs. 300
Profit = Selling Price – Cost Price
Substitute Selling Price and Cost Price in the above formula.
Profit = Rs. 300 – Rs 280 = Rs 20.
Now, find out the profit percentage formula.
Profit percentage = P/C.P. x 100%
Profit percentage = 100 × 20/280 = 7.14%

Therefore, the profit percentage is 7.14%

Example 3.

A retail fruit vendor buys pineapples at a score of Rs. 200/-,  and retails them at a dozen for Rs 156. Did he gain or lose in the transaction and what % was his gain or loss?

Solution:
Given that a retail fruit vendor buys pineapples at a score of Rs 200, and retails them at a dozen for Rs 156.
The cost price = Rs 220
C.P/Pineapple = 200/20 = 10
1 score = 20 nos
S.P = Rs.156/dozen
S.P/Pineapple = 156/12 = 13.
Profit = Rs. 13 – Rs. 10 = Rs. 3.
% Profit = 100 × 3/10 = 30%

Therefore, the profit percentage is 30%

FAQs on Profit and Profit Percent

1. How do I calculate profit percentage?

The profit percentage can be calculated using the below formula.
Formula for Profit Percentage = Profit Percent Formula = (Profit x 100)/C.P.

2. Is profit and profit percent different?

Yes, Profit is the difference between the Selling price and the Cost price when the Selling price is more than the Cost price.
P = SP – CP; SP>CP
Profit percent will obtain by dividing the Profit with Cost price and multiplying the resultant with the 100.
Profit percent = (Profit x 100)/C.P

3. What is the formula of Selling Price?

Selling Price can be found when the Profit Percentage and Cost Price are given is
SP = {(100 + P%)/100} x CP where SP is Selling Price, P% is Profit Percentage, and CP is Cost Price.

4. How to Calculate the Percentage Gain on an Investment?

  • In calculating the percentage gain on an investment, first, determine the original cost.
  • Next, Subtract the Cost Price from the Selling price of the investment.
  • Take the gain from the investment and divide it by the original amount of the investment.
  • Finally, multiply the result by 100 to get the percentage change in the investment.

Calculate Cost Price using Sell Price and Loss Percent – Formula, Examples

Calculate Cost Price using Sell Price and Loss Percent

Loss and Loss Percent is raised when the cost price is higher than the selling price. We can calculate the Cost Price when Sell Price and Loss Percent are given. Improve your preparation by referring to the complete article. Check out how to find the Cost Price and different solved examples on finding the Cost Price using Sell Price and Loss Percent from the below article. Also, find out the different formulas to use to find the cost price.

Also, See:

How to Calculate Cost Price using Sell Price and Loss Percent?

To find out the Cost Price using Sell Price and Loss Percent, use the below formula.
Cost price = selling price + loss
Cost price = selling price + loss% × cost price/100
The Cost price – loss% × cost price/100 = selling price
Cost price(1 – loss%)/100 = selling price
Cost price(100 – loss%)/100 = selling price
Also, Cost price = selling price × 100/100 – loss% (on cross multiplication)

Examples for finding Cost Price using Sell Price and Loss Percent

1. By selling a bicycle for $145, a shopkeeper loses 10%. How much percent would he gain or lose by selling it for $175?

Solution:
Given that by selling a bicycle for $145, a shopkeeper loses 10%.
The selling price = $145
Loss Percentage = 10%
We know that cost price = selling price × 100/100 – loss%
Substitute the selling price and the loss% in the above formula.
Cost price = $145 × 100/100-10
Cost price = $145 × 100/90
The Cost price = $14500/90
Cost price = $161.11
Therefore, cost price of the bicycle = $161.11
Now, if the selling price = $175, then gain = $175 – $161.11  = $13.89
Therefore, gain% = gain/cost price × 100
= 13.89/161.11 × 100
= 1500/150
= 8.62%

Therefore, he would have gained 8.62%.

2. If the selling price of a pen is $9 and the loss percent is 2%, then what is the cost price?

Solution:
Given that the selling price of a pen is $9 and the loss percent is 2%.
The selling price of a pen = $9
The loss percent is 2%.
Cost price = selling price × 100/100 – loss%
Substitute the selling price and the loss% in the above formula.
Cost price = $9 × 100/100 – 2
Cost price = $9 × 100/98
The Cost price = $900/98 = $9.18

Therefore, the cost price of the pen is $9.18.

3. Find out the cost price of the vehicle if the selling price is $3350 and the Loss is $154.

Solution:
Given that the selling price is $3350 and the Loss is $154.
The selling price of a pen = $3350
The loss = $154
Loss = Cost Price – Selling Price
Cost Price = Loss + Selling Price
Substitute the selling price and the loss in the above formula.
Cost Price = $154 + $3350
Cost Price = $3504

Therefore, the cost price of the vehicle is $3504.

FAQs on finding C.P using S.P and Loss%

1. What Does Cost Price Mean?

The cost price is the original price of an item. The cost is the total amount need to produce a product or carry out a service.

2. What is the Formula for the Cost Price?

The formula for Cost Price when the SP and L% are given
CP = {100/(100 – L%)} x SP where SP is the Selling Price and L is the Loss.

3. What are the types of Cost Prices?

Cost Price (CP) is the amount paid to buy the product is known as Cost Price. It is denoted by CP. Also, the cost price classified into two different categories. They are
Fixed Cost: The fixed cost is constant and it doesn’t vary under any circumstances.
Variable Cost: It could change depending on the number of units.

4. How to Calculate Cost Price?

Follow the below steps and find out the process to calculate cost price when the selling price and loss% are given.
1. Note down the selling price and loss%.
2. Write the formula of cost price i.e, CP = {100/(100 – L%)} x SP
3. Substitute the SP and L% in the above formula.
4. Calculate and find the Cost Price of the product.

Calculate Loss and Loss Percent – Definition, Formulas, Examples | How to Calculate Loss Percent?

Calculate Loss and Loss Percent

Loss and Loss Percent are used for calculating the loss that occurred in a business. The loss is the difference between the cost price and the selling price. Loss Percent is the percent of loss in terms of actual cost price. The loss will occur when the selling price is less than the cost price. We have given how to Calculate Loss and Loss Percent and the formula of loss. Know the process to find them and learn how to apply them in your real life. Also, check the solved examples for a better understanding.

Do Read:

Formula to Calculate Loss and Loss Percent

The loss occurs when a cost price is more than the selling price of a product in a business. The loss is calculated by subtracting the selling price from a cost price. The formula to calculate loss and loss percentage are

  • Loss = Cost Price – Selling Price when the Cost Price is higher than the Selling Price.
    or
    Loss = C.P. – S.P. (C.P.>S.P.)
  • Loss percentage = (Loss × 100) / C.P
  • Selling Price: The Selling Price is the price of a product that was sold by the shopkeeper to the customer for a particular price. Selling price is denoted by S.P.
    Selling Price(SP)= Cost Price(CP) – Loss(L)
  • Cost Price: The cost price is the price of a product it is the original cost of a product that was brought from the retailer. Cost Price is denoted by C.P.
    Cost Price(CP)= Selling Price(SP) + Loss(L)

Loss and Loss Percent Examples

Example 1.

A shirt was bought for $300 and sold for $250. Find the loss and loss percent.

Solution:
Given that a shirt was bought for $300 and sold for $250.
The cost price = $300
Also, the selling price = $250
Since, S. P. < C. P., there is loss.
Therefore, loss = cost price – selling price
Substitute the cost price and selling price in the above formula.
Loss = $300 – $250 = $50.
So, loss% = loss/cost price × 100%
Substitute the cost price and loss in the above formula.
loss% = $50/$300 × 100% = 16.66%

Therefore, the loss is $50 and the loss% is 16.66%

Example 2.

If the cost price of 30 pens is equal to the selling price of 35 pens, find a loss percent?

Solution:
Given that the cost price of 30 pens is equal to the selling price of 35 pens.
Let cost price of 1 pen = $1
Then cost price of 30 pens = $30
Also, cost price of 35 pens = $35
Since, selling price of 35 pens = cost price of 30 pens
Therefore, the selling price of 25 pens = $30
Therefore, loss = cost price – selling price
Loss = $35 – $30 = $5.
Therefore, loss% = loss/cost price × 100
loss% = $5/$35 × 100
loss% = 14.28%

Therefore, the loss is $5 and the loss% is 14.28%

Example 3.

Find the loss and loss percentage provided that the cost price is Rs. 60 and the selling price is Rs. 55.

Solution:
Given that the cost price is Rs. 60 and the selling price is Rs. 55.
The cost price = Rs. 60
Also, the selling price = Rs. 55
Since, S. P. < C. P., there is loss.
Therefore, loss = cost price – selling price
Substitute the cost price and selling price in the above formula.
Loss = Rs. 60 – Rs. 55 = Rs. 5.
So, loss% = loss/cost price × 100%
Substitute the cost price and loss in the above formula.
loss% = Rs. 5/Rs. 60 × 100% = 8.33%

Therefore, the loss is Rs. 5 and the loss% is 8.33%

Example 4.

If a house was bought by a man for Rupees 60 Lakhs and he sold it in 40 Lakhs. What is a loss percentage from this business?

Solution:
Given that a house was bought by a man for Rupees 60 Lakhs and he sold it in 40 Lakhs.
The cost price = Rs. 60 Lakhs
Also, the selling price = Rs. 40 Lakhs
Since, S. P. < C. P., there is loss.
Therefore, loss = cost price – selling price
Substitute the cost price and selling price in the above formula.
Loss = Rs. 60 Lakhs – Rs. 40 Lakhs = Rs. 20 Lakhs.
So, loss% = loss/cost price × 100%
Substitute the cost price and loss in the above formula.
loss% = Rs. 20 Lakhs/Rs. 60 Lakhs × 100% = 33.33%

Therefore, the loss is Rs. 20 Lakhs and the loss% is 33.33%

FAQs on Loss and Loss Percent

1. How do you calculate percentage loss?

Follow the below steps to find the percentage loss.
1. Note down the cost price.
2. Then, check out the Selling Price, and calculate the loss.
3. Substitute the Loss and cost price in the Loss percentage formula.
4. Finally, find the Loss percentage.
Loss percentage = (Loss × 100) / C.P

2. What are the Loss and Loss Percent Formulas?

The formula for Loss and Loss Percent are
Loss = C.P. – S.P. (C.P.>S.P.)
Loss percentage = (Loss × 100) / C.P where C.P. is cost price and S.P. is selling price.

3. What is the formula for S.P when Loss and C.P. are given?

The formula for Loss = C.P. – S.P.
Therefore, S.P. = C.P. – Loss

4. How to find the C.P. when Loss and S.P. are given?

The formula for Loss = C.P. – S.P.
Therefore, C.P. = Loss + S.P.

5. How to find loss from loss percentage?

The Loss percentage = (Loss × 100) / C.P
Firstly, multiply C.P with Loss percentage and then divide it by 100 to get a Loss from the loss percentage.
Loss = (Loss percentage × C.P)/100

Calculate Cost Price using Sell Price and Profit Percent – Formula, Examples

Calculate Cost Price using Sell Price and Profit Percent

Calculate Cost Price using Sell Price and Profit Percent when the inputs are Sell Price and Profit Percent and the output is Cost Price. By simply using the Cost Price formula, one can find out the Cost Price of a product. The cost price is always less than the selling price when the profit percent is given. We have detailed explanations and solved examples are included in this article. All the different methods to find Cost Prices using Sell Price and Profit Percent are given below.

Also, Check:

How to Calculate Cost Price Using Sell Price and Profit Percent?

Follow the below process to find out the Cost Price Using Sell Price and Profit Percent. Also, get the Cost Price Formula to solve all the problems.

1. Write down the Sell Price and Profit Percent.
2. Note Down the Cost Price Formula.
3. Substitute the Sell Price and Profit Percent in the Cost Price Formula.
4. Finally, find out the Cost Price Using Sell Price and Profit Percent.

Cost Price Formula

Use the below formulas according to the problem and get the cost price easily.

Cost price = selling price – profit
Cost price = selling price – profit% × cost price/100
The Cost price + profit% × cost price/100 = selling price
Cost price(1 – profit%)/100 = selling price
Cost price(100 + profit%)/100 = selling price
Also, cost price = selling price × 100/100 + profit% (on cross multiplication);
Here, selling price and loss% is known.

Finding Cost Price Using Sell Price and Profit Percent Examples

1. A box was sold for $428 thereby gaining 8%. Find the cost price of the bag?

Solution:

Given that a box was sold for $428 thereby gaining 8%.
The selling price = $428
Gain Percentage = 8%
We know that cost price = selling price × 100/100 + gain%
Substitute the selling price and the gain% in the above formula.
Cost price = $428 × 100/(100 + 8)
Cost price = $428 × 100/108
The Cost price = $42800/108 = $396.29

Therefore, the cost price of the bag is $396.29

2. A fan was sold for $625 thereby gaining 15%. Find the cost price of the fan.

Solution:

Given that a fan was sold for $625 thereby gaining 15%.
The selling price = $625
Gain Percentage = 15%
We know that cost price = selling price × 100/100 + gain%
Substitute the selling price and the gain% in the above formula.
Cost price = $625 × 100/(100 + 15)
Cost price = $625 × 100/115
The Cost price = $62500/115= $543.47

Therefore, the cost price of the fan is $543.47

3. By selling a mobile for $1,240, a trader gains 10%. Find the cost price of the mobile?

Solution:

Given that by selling a mobile for $1,240, a trader gains 10%.
The selling price = $1,240
Gain Percentage = 10%
We know that cost price = selling price × 100/100 + gain%
Substitute the selling price and the gain% in the above formula.
Cost price = $1240 × 100/(100 + 10)
Cost price = $1240 × 100/110
The Cost price = $124000/110 = $1127.27

Therefore, the cost price of the mobile is $1127.27

Calculate Selling Price using Cost and Loss Percent – Formula, Worked Out Problems

Calculate Selling Price using Cost and Loss Percent

The amount of a thing that can be sold is known as the Selling Price. It is denoted by SP. Also, the Selling Price is also called the sale price. The selling price can be calculated when the Cost price and Loss Percent are given. Solve all the given related to Selling price problems to get a complete grip on the concept. Also, check out the given explanation of problems to find the Selling Price using Cost and Loss Percent in the later modules.

Also, See:

How to Calculate Selling Price Using Cost and Loss Percent?

Follow the complete process to find out the Selling Price Using Cost and Loss Percent. Also, know the Cost Price Formula to solve all the problems easily.

1. Note down the Cost Price and Loss Percent.
2. Write Down the Selling Price Formula.
3. Substitute the Cost Price and Loss Percent in the Selling Price Formula.
4. Finally, find out the Selling Price Using Cost Price and Loss Percent.

Selling Price Formula when Cost and Loss Percent are Known

You can use the below formula to find the Selling Price of a product when you know the Cost and Loss Percent of that product. The formulas for Selling Price Formula when Cost and Loss Percent Known are

  • Selling price = cost price – loss
  • Selling price = cost price – loss% × cost price/100
  • Selling price = 100 × cost price – loss% × cost price/100
  • Selling price = (100 – loss%)cost price/100, [Here, cost price and loss% are known.]

Solved Examples to Find Selling Price using Cost and Loss Percent

1. Sam bought a dress for $250 and sold it to Olivia thereby suffering a loss of 10%. Find the selling price of the dress?

Solution:
Given that Sam bought a dress for $250 and sold it to Olivia thereby suffering a loss of 10%.
The cost price = $250
Loss Percentage = 10%
We know that selling price = (100 – loss%) cost price/100
Substitute the cost price and the loss% in the above formula.
Selling price = (100 – 10)250/100
Selling price = 90 × 250/100
The Selling price = $22500/100 = $225

Therefore, the Selling price of the dress is $225

2. Alex bought a laptop for $600 and sold it to Jack thereby suffering a loss of 12%. Find the selling price of the laptop?

Solution:
Given that Alex bought a laptop for $600 and sold it to Jack thereby suffering a loss of 12%.
The cost price = $600
Loss Percentage = 12%
We know that selling price = (100 – loss%) cost price/100
Substitute the cost price and the loss% in the above formula.
Selling price = (100 – 12)600/100
Selling price = 88 × 600/100
The Selling price = $52800/100 = $528

Therefore, the Selling price of the dress is $528

3. By selling a table for $630, Daisy loses 7%. At what price must she sell it to gain 10%.

Solution:
Given that By selling a table for $630, Daisy loses 7%.
Given that the selling price = $ 630
Loss % = 7%
We know, cost price = selling price × 100/100 – loss%
Substitute the selling price and the loss% in the above formula.
Therefore, cost price = 630 × 100/(100 – 7)
= 630 × 100/93
= $677.41
Now cost price = $677.41
Gain% = 10%
Therefore, selling price = (100 + gain%)cost price/100
= (100 + 10)677.41/100
= 110 × 6.77
= $744.7

At $744.7 price she can sell it to gain 10%.

Circumference and Area of Circle | How to Calculate Circumference and Area of a Circle?

In Mensuration the circumference and area of a circle are defined as the length of the boundary of the circle and region occupied by the circle in 2-D Geometry. Let us discuss in detail the area and circumference of the circle using the formulas and solved example problems. We provide a detailed explanation of how to calculate the circumference and area of the circle.

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What is Circumference and Area of Circle?

Circumference of Circle:

The circumference of the circle is the measure of the boundary of the circle. The circumference of the circle is also known as the perimeter of the circle. The perimeter or circumference of the circle is measured in units.
C = Πd or 2Πr

Area of Circle:

The area of the circle is the region covered by the circle or sphere in two-dimensional mensuration. The units to measure the area of the circle is square units.
A = Πr²
Where,
A is the area of the circle
r is the radius of the circle

What is the radius of the circle?

The radius of the circle is the distance from the center to the outline of the circle. Radius plays an important role in calculating the area and perimeter of the circle.

Properties of Circle

The properties of the circle are given below,

  • The diameter of the circle is the longest chord of the circle.
  • The circle is said to be congruent if it has the same radii.
  • A circle can confine rectangle, square, trapezium, etc.
  • If the tangents are drawn at the end of the diameter they are parallel to each other.

Area and Circumference of Circle Formula

Circumference:
The circumference of the circle is the measure of the boundary of the circle. The formula for the circumference of the circle is given below,
C = Πd
Where,
C is the circumference of the circle
Π is the mathematical constant
The approximate value of pi is 3.14 or 22/7
d is the diameter of the circle
C = 2Πr
Where,
C is the circumference of the circle
Π is the mathematical constant
The approximate value of pi is 3.14 or 22/7
r is the radius of the circle
Area: 
The formula for the area of the circle is as follows,
A = Πr²
A is an area of the circle
Π is the mathematical constant
The approximate value of pi is 3.14 or 22/7
r is the radius of the circle
Area of Semi-Circle:
The area of the semicircle is the region covered by the 2D figure. The formula for the area of the semi-circle is as follows,
A = Πr²/2
Perimeter of the Semi-circle:
The formula for the perimeter of the semi-circle is given below,
P = 2Πr/2 = Πr

Solved Examples on Circumference and Area of a Circle?

Get the step by step explanation on the formula of Area and Circumference of Circle here.

1. What is the circumference of the circle with a radius of 7cm?

Solution:

Given,
r = 7cm
We know that,
Circumference of the circle = 2Πr
C = 2 × 22/7 × 7 cm
C = 44 cm
Thus the circumference of the circle is 44 cm.

2. What is the circumference of the circle with a diameter of 21 cm?

Solution:

Given,
d = 21 cm
We know that,
Circumference of the circle = 2Πr
C = Πd
C = 22/7 × 21cm
C = 22 × 3cm
C = 66 cm
Therefore the circumference of the circle is 66 cm.

3. Find the area of the circle with a radius of 14m?

Solution:

Given,
r = 14m
We know that,
Area of Circle = Πr²
A = 22/7 × 14 × 14 sq.m
A = 22 × 2 × 14 m²
Thus the area of the circle is 616m²

4. Find the area of the circle if its circumference is 124m?

Solution:

Given,
Circumference of the circle = 124m
We know that,
Circumference of the circle = 2Πr
124m = 2Πr
Πr = 124/2
Πr = 62
r = 62 × 7/22
r = 19.72 m
Now find the area of the circle using the radius.
Area of Circle = Πr²
A = 3.14 × (19.72)²
A = 1221 sq. m
Therefore the area of the circle is 1221 sq. meters.

5. Find the area and circumference of the circle of radius 14m?

Solution:

Given,
radius = 14m
We know that,
Circumference of the circle = 2Πr
C = 2 × 22/7 × 14m
C = 2 × 22 × 2m
C = 88m
Now find the area of the circle using the radius.
Area of Circle = Πr²
A = Π(14)²
A = 22/7 × 14 × 14 sq.m
A = 22 × 2 × 14
A = 44 × 14 sq.m
A = 616 sq.m
Thus the area of the circle is 616 sq.m

FAQs on Circumference and Area of Circle

1. How to calculate the area of a circle?

The area of the circle can be calculated by the product of pi and radius squared.

2. What is the diameter of the circle?

The diameter of the circle is 2r.

3. How to calculate the circumference of the circle?

The circumference of the circle can be calculated by multiplying the diameter with pi.

Perimeter and Area of Square | How to Calculate the Perimeter and Area of a Square?

The Perimeter and Area of the Square are used to measure the length of the boundary and space occupied by the square. These are two important formulas used in Mensuration. Perimeter and Area of the Square formulas are used in the 2-D geometry.

Square is a regular quadrilateral where are the sides and angles are equal. The concepts of the Perimeter and Area Square formula, Derivation, Properties, are explained here. The solved examples with clear cut explanations are provided in this article. Students can understand how and where to use the formulas of Area and Perimeter of Square.

What is the Area and Perimeter of the Square?

Area of a square: The area of the square is defined as the region covered by the two-dimensional shape. The units of the area of the square are measured in square units i.e., sq. cm or sq. m.

Perimeter of a square: The perimeter of the square is a measure of the length of the boundaries of the square. The units of the perimeter are measured in cm or m.

Area of Square Formula

The area of the square is equal to the product of the side and side.
Area = Side ×  Side sq. units
A = s² sq. units

Perimeter of Square Formula

The perimeter of the square is the sum of the lengths.
P = s + s + s +s
P = 4s units
Where s is the side of the square.

Diagonal of Square Formula

The square has two diagonals with equal lengths. The diagonal of the square is greater than the sides of the square.

  • The relationship between d and s is d = a√2
  • The relationship between d and Area is d = √2A

What is Square?

A square is a regular polygon in which all four sides are equal. The measurement of the angles of the square is also equal.

Properties of Squares

The properties of the square are similar to the properties of the rectangle. Go through the properties of squares from the below section.

  • All sides of the squares are equal.
  • It has 4 sides and 4 vertices.
  • The interior angles of the square are equal to 90º
  • The diagonlas of square bisect at 90º
  • The diagonals of the square are divided into two isosceles triangles.
  • The opposite sides of the squares are parallel to each other.
  • Each half of the square is equal to two rectangles.

Solved Problems on Perimeter and Area of Square

Below we have provided the solved examples of perimeter and area of a square with a brief explanation. Scroll down this page to check out the formulas of Area and Perimeter of Square.

1. What is the Area and Perimeter of the square if one of its sides is 4 meters?

Solution:

Given the side of the square is 4 meters.
Area of the square = s × s
A = 4 m × 4 m
A = 16 sq. meters
The perimeter of the square = 4s
P = 4 × 4 m
P = 16 meters.
Therefore the area and perimeter of the square are 16 sq. meters and 16 meters.

2. Find the area of the square if the side is 10 cm?

Solution:

Given,
s = 10 cm
Area of the square = s × s
A = 10 cm × 10 cm
A = 100 sq. cm
Therefore the area of the square is 100 sq. cm

3. The perimeter of the square is 64 cm. Find the area of the square?

Solution:

Given,
The perimeter of the square is 64 cm
P = 4s
64 cm = 4s
s = 64/4 = 16 cm
Thus the side of the square is 16 cm.
Now the find the area of the square.
Area of the square = s × s
A = 16 cm × 16 cm
A = 256 sq. cm
Therefore the area of the square is 256 sq. cm.

4. If the area of the square is 81 cm², then what is the length of the square?

Solution:

Given,
A = 81 cm²
Area of the square = s × s
81 sq. cm = s²
s² = 81 sq. cm
s = √81 sq. cm
s = 9 cm
Thus the length of the square is 9 cm.

5. The length of the square is 25 cm. What is the area of the square?

Solution:

Given,
The length of the square is 25 cm
Area of the square = s × s
A = 25 × 25
A = 625 sq. cm
Therefore the area of the square is 625 sq. cm.

FAQs on Perimeter and Area of Square

1. How to find the perimeter of the square?

Add all the sides of the square to find the perimeter of the square.

2. What is the formula for the perimeter of a square?

The Perimeter of Square formula is sum of the lengths i.e, side + side + side + side = 4s

3. What is the formula for the area of the square?

The area of the square formula is the product of side and side. A = s × s.

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