Eureka Math

Engage NY Eureka Math 3rd Grade Module 1 Lesson 4 Answer Key

Eureka Math Grade 3 Module 1 Answer Key

Eureka Math Grade 3 Module 1 Lesson 4 Sprint Answer Key

A
Repeated Addition as Multiplication

Question 1.
5 + 5 + 5 =
5 + 5 + 5 = 15,

Explanation:
Given 5 + 5 + 5 we add 5 by 3 times
we get 15, So 5 + 5 + 5 = 15.

Question 2.
3 × 5 =
3 X 5 = 15,

Explanation:
Given 3 X 5 we multiply 3 with 5,
we get 15 as 3 X 5 = 15.

Question 3.
5 × 3 =
5 X 3 = 15,

Explanation:
Given 5 X 3 we multiply 5 with 3,
we get 15 as 5 X 3 = 15.

Question 4.
2 + 2 + 2 =
2 + 2 + 2 = 6,

Explanation:
Given 2 + 2 + 2 we add 2 by 3 times
we get 6, So 2 + 2 + 2 = 6.

Question 5.
3 × 2 =
3 X 2 = 6,

Explanation:
Given 3 X 2 we multiply 3 with 2,
we get 6 as 3 X 2 = 6.

Question 6.
2 × 3 =
2 X 3 = 6,

Explanation:
Given 2 X 3 we multiply 2 with 3,
we get 6 as 2 X 3 = 6.

Question 7.
5 + 5 =
5 + 5 = 10,

Explanation:
Given 5 + 5 we add 5 by 2 times
we get 10, So 5 + 5 = 10.

Question 8.
2 × 5 =
2 X 5 = 10,

Explanation:
Given 2 X 5 we multiply 2 with 5,
we get 10 as 2 X 5 = 10.

Question 9.
5 × 2 =
5 X 2 = 10,

Explanation:
Given 5 X 2 we multiply 5 with 2,
we get 10 as 5 X 2 = 10.

Question 10.
2 + 2 + 2 + 2 =
2 + 2 + 2 + 2 = 8,

Explanation:
Given 2 + 2 + 2 + 2 we add 2 by 4 times
we get 8, So 2 + 2 + 2 + 2= 8.

Question 11.
4 × 2 =
4 X 2 = 8,

Explanation:
Given 4 X 2 we multiply 4 with 2,
we get 8 as 4 X 2 = 8.

Question 12.
2 × 4 =
2 X 4 = 8,

Explanation:
Given 2 X 4 we multiply 2 with 4,
we get 8 as 2 X 4 = 8.

Question 13.
2 + 2 + 2 + 2 + 2 =
2 + 2 + 2 + 2 + 2 = 10,

Explanation:
Given 2 + 2 + 2 + 2 + 2 we add 2 by 5 times
we get 10, So 2+ 2 + 2 + 2 + 2= 10.

Question 14.
5 × 2 =
5 X 2 = 10,

Explanation:
Given 5 X 2 we multiply 5 with 2,
we get 10 as 5 X 2 = 10.

Question 15.
2 × 5 =
2 X 5 = 10,

Explanation:
Given 2 X 5 we multiply 2 with 5,
we get 10 as 2 X 5 = 10.

Question 16.
3 + 3 =
3 + 3 = 6,

Explanation:
Given 3 + 3 we add 3 by 2 times
we get 6, So 3 + 3 = 6.

Question 17.
2 × 3 =
2 X 3 = 6,

Explanation:
Given 2 X 3 we multiply 2 with 3,
we get 6 as 2 X 3 = 6.

Question 18.
3 × 2 =
3 X 2 = 6,

Explanation:
Given 3 X 2 we multiply 3 with 2,
we get 6 as 3 X 2 = 6.

Question 19.
5 + 5 + 5+ 5 =
5 + 5 + 5 + 5 = 20,

Explanation:
Given 5 + 5 + 5 + 5 we add 5 by 4 times
we get 20, So 5 + 5 + 5 + 5 = 20.

Question 20.
4 × 5 =
4 X 5 = 20,

Explanation:
Given 4 X 5 we multiply 4 with 5,
we get 20 as 4 X 5 = 20.

Question 21.
5 × 4 =
5 X 4 = 20,

Explanation:
Given 5 X 4 we multiply 5 with 4,
we get 20 as 5 X 4 = 20.

Question 22.
2 × 2 =
2 X 2 = 4,

Explanation:
Given 2 X 2 we multiply 2 with 2,
we get 4 as 2 X 2 = 4.

Question 23.
3 + 3 + 3 + 3 =
3 + 3 + 3 + 3 = 12,

Explanation:
Given 3 + 3 + 3 + 3 we add 3 by 4 times
we get 12, So 3 + 3 + 3 + 3 = 12.

Question 24.
4 × 3 =
4 X 3 = 12,

Explanation:
Given 4 X 3 we multiply 4 with 3,
we get 12 as 4 X 3 = 12.

Question 25.
3 × 4 =
3 X 4 = 12,

Explanation:
Given 3 X 4 we multiply 3 with 4,
we get 12 as 3 X 4 = 12.

Question 26.
3 + 3 + 3 =
3 + 3 + 3 = 9,

Explanation:
Given 3 + 3 + 3 we add 3 by 3 times
we get 9, So 3 + 3 + 3 = 9.

Question 27.
3 × 3 =
3 X 3 = 9,

Explanation:
Given 3 X 3 we multiply 3 with 3,
we get 9 as 3 X 3 = 9.

Question 28.
3 + 3 + 3 + 3 + 3 =
3 + 3 + 3 + 3 + 3 = 15,

Explanation:
Given 3 + 3 + 3 + 3 + 3 we add 3 by 5 times
we get 15, So 3 + 3 + 3 + 3 + 3 = 15.

Question 29.
5 × 3 =
5 X 3 = 15,

Explanation:
Given 5 X 3 we multiply 5 with 3,
we get 15 as 5 X 3 = 15.

Question 30.
3 × 5 =
3 X 5 = 15,

Explanation:
Given 3 X 5 we multiply 3 with 5,
we get 15 as 3 X 5 = 15.

Question 31.
7 + 7 =
7 + 7 = 14,

Explanation:
Given 7 + 7 we add 7 by 2 times
we get 14, So 7 + 7 = 14.

Question 32.
2 × 7 =
2 X 7 = 14,

Explanation:
Given 2 X 7 we multiply 2 with 7,
we get 14 as 2 X 7 = 14.

Question 33.
7 × 2 =
7 X 2 = 14,

Explanation:
Given 7 X 2 we multiply 7 with 2,
we get 14 as 7 X 2 = 14.

Question 34.
9 + 9 =
9 + 9 = 18,

Explanation:
Given 9 + 9 we add 9 by 2 times
we get 18, So 9 + 9 = 18.

Question 35.
2 × 9 =
2 X 9 = 18,

Explanation:
Given 2 X 9 we multiply 2 with 9,
we get 18 as 2 X 9 = 18.

Question 36.
9 × 2 =
9 X 2 = 18,

Explanation:
Given 9 X 2 we multiply 9 with 2,
we get 18 as 9 X 2 = 18.

Question 37.
6 + 6 =
6 + 6 = 12,

Explanation:
Given 6 + 6 we add 6 by 2 times
we get 12, So 6 + 6 = 12.

Question 38.
6 × 2 =
6 X 2 = 12,

Explanation:
Given 6 X 2 we multiply 6 with 2,
we get 12 as 6 X 2 = 12.

Question 39.
2 × 6 =
2 X 6 = 12,

Explanation:
Given 2 X 6 we multiply 2 with 6,
we get 12 as 2 X 6 = 12.

Question 40.
8 + 8 =
8 + 8 = 16,

Explanation:
Given 8 + 8 we add 8 by 2 times
we get 16, So 8 + 8 = 16.

Question 41.
2 × 8 =
2 X 8 = 16,

Explanation:
Given 2 X 8 we multiply 2 with 8,
we get 16 as 2 X 8 = 16.

Question 42.
8 × 2 =
8 X 2 = 16,

Explanation:
Given 8 X 2 we multiply 8 with 2,
we get 16 as 8 X 2 = 16.

Question 43.
7 + 7 + 7 + 7 =
7 + 7 + 7 + 7 = 28,

Explanation:
Given 7 + 7 + 7 + 7 we add 7 by 4 times
we get 28, So 7 + 7 + 7 + 7 = 28.

Question 44.
4 × 7 =
4 X 7 = 28,

Explanation:
Given 4 X 7 we multiply 4 with 7,
we get 28 as 4 X 7 = 28.

B
Repeated Addition as Multiplication

Question 1.
2 + 2 + 2 =
2 + 2 + 2 = 6,

Explanation:
Given 2 + 2 + 2 we add 2 by 3 times
we get 6, So 2 + 2 + 2 = 6.

Question 2.
3 × 2 =
3 X 2 = 6,
Explanation:
Given 3 X 2 we multiply 3 with 2,
we get 6 as 3 X 2 = 6.

Question 3.
2 × 3 =
2 X 3 = 6,
Explanation:
Given 2 X 3 we multiply 2 with 3,
we get 6 as 2 X 3 = 6.

Question 4.
5 + 5 + 5 =
5 + 5 + 5 = 15,
Explanation:
Given 5 + 5 + 5 we add 5 by 3 times
we get 15, So 5 + 5 + 5 = 15.

Question 5.
3 × 5 =
3 X 5 = 15,
Explanation:
Given 3 X 5 we multiply 3 with 5,
we get 15 as 3 X 5 = 15.

Question 6.
5 × 3 =
5 X 3 = 15,
Explanation:
Given 5 X 3 we multiply 5 with 3,
we get 15 as 5 X 3 = 15.

Question 7.
2 + 2 + 2 + 2 =
2 + 2 + 2 + 2 = 8,

Explanation:
Given 2 + 2 + 2 + 2 we add 2 by 4 times
we get 8, So 2 + 2 + 2 + 2= 8.

Question 8.
4 × 2 =
4 X 2 = 8,
Explanation:
Given 4 X 2 we multiply 4 with 2,
we get 8 as 4 X 2 = 8.

Question 9.
2 × 4 =
2 X 4 = 8,
Explanation:
Given 2 X 4 we multiply 2 with 4,
we get 8 as 2 X 4 = 8.

Question 10.
5 + 5 =
5 + 5 = 10,
Explanation:
Given 5 + 5 we add 5 by 2 times
we get 10, So 5 + 5 = 10.

Question 11.
2 × 5 =
2 X 5 = 10,
Explanation:
Given 2 X 5 we multiply 2 with 5,
we get 10 as 2 X 5 = 10.

Question 12.
5 × 2 =
5 X 2 = 10,
Explanation:
Given 5 X 2 we multiply 5 with 2,
we get 10 as 5 X 2 = 10.

Question 13.
3 + 3 =
3 + 3 = 6,

Explanation:
Given 3 + 3 we add 3 by 2 times
we get 6, So 3 + 3 = 6.

Question 14.
2 × 3 =
2 X 3 = 6,

Explanation:
Given 2 X 3 we multiply 2 with 3,
we get 6 as 2 X 3 = 6.

Question 15.
3 × 2 =
3 X 2 = 6,

Explanation:
Given 3 X 2 we multiply 3 with 2,
we get 6 as 3 X 2 = 6.

Question 16.
2 + 2 + 2 + 2 + 2 =
2 + 2 + 2 + 2 + 2 = 10,
Explanation:
Given 2 + 2 + 2 + 2 + 2 we add 2 by 5 times
we get 10, So 2+ 2 + 2 + 2 + 2= 10.

Question 17.
5 × 2 =
5 X 2 = 10,

Explanation:
Given 5 X 2 we multiply 5 with 2,
we get 10 as 5 X 2 = 10.

Question 18.
2 × 5 =
2 X 5 = 10,
Explanation:
Given 2 X 5 we multiply 2 with 5,
we get 10 as 2 X 5 = 10.

Question 19.
5 + 5 + 5 + 5 =
5 + 5 + 5 + 5 = 20,

Explanation:
Given 5 + 5 + 5 + 5 we add 5 by 4 times
we get 20, So 5 + 5 + 5 + 5 = 20.

Question 20.
4 × 5 =
4 X 5 = 20,
Explanation:
Given 4 X 5 we multiply 4 with 5,
we get 20 as 4 X 5 = 20.

Question 21.
5 × 4 =
5 X 4 = 20,

Explanation:
Given 5 X 4 we multiply 5 with 4,
we get 20 as 5 X 4 = 20.

Question 22.
2 × 2 =
2 X 2 = 4,
Explanation:
Given 2 X 2 we multiply 2 with 2,
we get 4 as 2 X 2 = 4.

Question 23.
4 + 4 + 4 =
4 + 4 + 4 = 12,

Explanation:
Given 4 + 4 + 4 we add 4 by 3 times
we get 12, So 4 + 4 + 4 = 12.

Question 24.
3 × 4 =
3 X 4 = 12,

Explanation:
Given 3 X 4 we multiply 3 with 4,
we get 12 as 3 X 4 = 12.

Question 25.
4 × 3 =
4 X 3 = 12,

Explanation:
Given 4 X 3 we multiply 4 with 3,
we get 12 as 4 X 3 = 12.

Question 26.
4 + 4 + 4 + 4 =
4 + 4 + 4 + 4 = 16,

Explanation:
Given 4 + 4 + 4 + 4 we add 4 by 4 times
we get 16, So 4 + 4 + 4 +4 = 16.

Question 27.
4 × 4 =
4 X 4 = 16,

Explanation:
Given 4 X 4 we multiply 4 with 4,
we get 14 as 4 X 4 = 16.

Question 28.
4 + 4 + 4 + 4 + 4 =
4 + 4 + 4 + 4 + 4 = 20,

Explanation:
Given 4 + 4 + 4 + 4 + 4 we add 4 by 5 times
we get 20, So 4 + 4 + 4 + 4 + 4 = 20.

Question 29.
4 × 5 =
4 X 5 = 20,

Explanation:
Given 4 X 5 we multiply 4 with 5,
we get 20 as 4 X 5 = 20.

Question 30.
5 × 4 =
5 X 4 = 20,

Explanation:
Given 5 X 4 we multiply 5 with 4,
we get 20 as 5 X 4 = 20.

Question 31.
6 + 6 =
6 + 6 = 12,

Explanation:
Given 6 + 6 we add 6 by 2 times
we get 12, So 6 + 6 = 12.

Question 32.
6 × 2 =
6 X 2 = 12,

Explanation:
Given 6 X 2 we multiply 6 with 2,
we get 12 as 6 X 2 = 12.

Question 33.
2 × 6 =
2 X 6 = 12,

Explanation:
Given 2 X 6 we multiply 2 with 6,
we get 12 as 2 X 6 = 12.

Question 34.
8 + 8 =
8 + 8 = 16,

Explanation:
Given 8 + 8 we add 8 by 2 times
we get 16, So 8 + 8 = 16.

Question 35.
2 × 8 =
2 X 8 = 16,

Explanation:
Given 2 X 8 we multiply 2 with 8,
we get 16 as 2 X 8 = 16.

Question 36.
8 × 2 =
8 X 2 = 16,

Explanation:
Given 8 X 2 we multiply 8 with 2,
we get 16 as 8 X 2 = 16.

Question 37.
7 + 7 =
7 + 7 = 14,

Explanation:
Given 7 + 7 we add 7 by 2 times
we get 14, So 7 + 7 = 14.

Question 38.
2 × 7 =
2 X 7 = 14,

Explanation:
Given 2 X 7 we multiply 2 with 7,
we get 14 as 2 X 7 = 14.

Question 39.
7 × 2 =
7 X 2 = 14,

Explanation:
Given 7 X 2 we multiply 7 with 2,
we get 14 as 7 X 2 = 14.

Question 40.
9 + 9 =
9 + 9 = 18,

Explanation:
Given 9 + 9 we add 9 by 2 times
we get 18, So 9 + 9 = 18.

Question 41.
2 × 9 =
2 X 9 = 18,

Explanation:
Given 2 X 9 we multiply 2 with 9,
we get 18 as 2 X 9 = 18.

Question 42.
9 × 2 =
9 X 2 = 18,

Explanation:
Given 9 X 2 we multiply 9 with 2,
we get 18 as 9 X 2 = 18.

Question 43.
6 + 6 + 6 + 6 =
6 + 6 + 6 + 6 = 24,

Explanation:
Given 6 + 6 + 6 + 6 we add 6 by 4 times
we get 24, So 6 + 6 + 6 + 6 = 24.

Question 44.
4 × 6 =
4 X 6 = 24,

Explanation:
Given 4 X 6 we multiply 4 with 6,
we get 24 as 4 X 6 = 24.

Eureka Math Grade 3 Module 1 Lesson 4 Problem Set Answer Key

Question 1.

14 flowers are divided into 2 equal groups.
There are ____7_____ flowers in each group.

There are 7 flowers in each group,

Explanation:
Given 14 flowers are divided into 2 equal groups,
So there are 14 ÷ 2 = 7 flowers in 2 equal groups.

Question 2.

28 books are divided into 4 equal groups.
There are _____7____ books in each group.

There are 7 books in each group.

Explanation:
Given 28 books are divided into 4 equal groups,
So there are 28 ÷ 4 = 7 books in 4 equal groups.

Question 3.

30 apples are divided into ___3___ equal groups.
There are ____10_____ apples in each group.

30 apples are divided into 3 equal groups.
There are 10 apples in each group.

Explanation:
Given in the picture there are30 apples divided into
3 equal groups. So there are 30 ÷ 3 = 10 apples
in each group.

Question 4.

___12____ cups are divided into ___2____ equal groups.
There are ____6_____ cups in each group.
12 ÷ 2 = ___6______

12 cups are divided into 2 equal groups.
There are 6 cups in each group. 12 ÷ 2 = 6 cups,

Explanation:
As given in the picture there are 12 cups divided
into 2 equal groups, There are 6 cups  in each group
as 12 ÷ 2 = 6 cups.

Question 5.

There are ____15_____ toys in each group.
15 ÷ 3 = ____5_____

There are ____15_____ toys in each group,

Explanation:
As given in the picture there are 15 toys divided
as 15 ÷ 3 = 5 toys in each group, So, there are
15 toys in 3 equal groups.

Question 6.

9 ÷ 3 = ____3______

There are 3 cars in each group,

Explanation:
As given in the picture there are 9 cars divided
as 9 ÷ 3 = 3 cars in each group, So, there are
3 cars in 3 equal groups.

Question 7.
Audrina has 24 colored pencils. She puts them in
4 equal groups. How many colored pencils are in each group?

There are ___6____ colored pencils in each group.
24 ÷ 4 = ___6____

There are 6 colored pencils in each group,

Explanation:
Given Audrina has 24 colored pencils. She puts them in
4 equal groups. So number of  colored pencils in each group
are 24 ÷ 4 = 6 pencils in 4 equal groups.

Question 8.
Charlie picks 20 apples. He divides them equally
between 5 baskets. Draw the apples in each basket.

There are _____4______ apples in each basket.
20 ÷ ____5____ = ____4______

There are 4 apples in each basket,

Explanation:
Given Charlie picks 20 apples. He divides them equally
between 5 baskets. Drawn the apples in each basket as
20 ÷ 5 = 4 apples in 5 equal groups.

Question 9.
Chelsea collects butterfly stickers. The picture shows
how she placed them in her book. Write a division sentence
to show how she equally grouped her stickers.
There are ______3______ butterflies in each row.
____15______ ÷ _____5_____ = ____3______

Division sentence : 15 ÷ 5 = 3,
Chelsea equally grouped 3 butterflies
in her stickers.

Explanation:
Given Chelsea collects butterfly stickers.
The picture is showing 15 butterflies she placed
them in her book. Wrote a division sentence as
15 ÷ 5 = 3 butterflies to show how she equally
grouped 3 butterflies in her stickers.

Eureka Math Grade 3 Module 1 Lesson 4 Exit Ticket Answer Key

Question 1.
There are 16 glue sticks for the class. The teacher divides them into 4 equal groups. Draw the number of glue sticks in each group.

There are _____16______ glue sticks in each group.
16 ÷ ___4_____ = ____4______

There are 16 glue sticks in each group.

Explanation:
Given there are 16 glue sticks for the class.
The teacher divides them into 4 equal groups.
Drawn the number of glue sticks in each group as
16 ÷ 4 =  4 glue sticks in 4 equal groups.

Question 2.
Draw a picture to show 15 ÷ 3. Then, fill in the blank to make a true division sentence.
15 ÷ 3 = ____5______

Drawn a picture to show division sentence as
15 ÷ 3 = 5,
Filled in the blank to make a true division sentence as
15 ÷ 3 = ____5____,

Explanation:
Drawn 15 dogs and wrote division sentence as
15 ÷ 3 = 5 as shown above and filled in the blank to
make a true division sentence as 15 ÷ 3 = ____5__ or 5 X 3 = 15.

Eureka Math Grade 3 Module 1 Lesson 4 Homework Answer Key

Question 1.

12 chairs are divided into 2 equal groups.
There are ____6_____ chairs in each group.

There are 6 chairs in each group,

Explanation:
As given in the picture there are 12 chairs divided
as 12 ÷ 2 = 6 chairs in each group, So, there are
6 chairs in 2 equal groups.

Question 2.

21 triangles are divided into 3 equal groups.
There are ____7_____ triangles in each group.

There are 7 triangles in each group,

Explanation:
As given in the picture there are 21 triangles divided
as 21 ÷ 3 =7 triangles in each group, So, there are
7 triangles in 3 equal groups.

Question 3.

25 erasers are divided into ___5___ equal groups.
There are ____5_____ erasers in each group.

25 erasers are divided into 5 equal groups.
There are 5 erasers in each group as 25 ÷ 5 = 5 erasers,

Explanation:
As given in the picture there are 25 erasers divided
into 5 equal groups, There are 5 erasers in each group
as 25 ÷ 5 = 25 erasers.

Question 4.

___9____ chickens are divided into ___3____ equal groups.
There are ____3_____ chickens in each group.
9 ÷ 3 = ____3______

9 chickens are divided into 3 equal groups.
There are 3 chickens in each group as 9 ÷ 3 = 3 chickens,

Explanation:
As given in the picture there are 9 chickens divided
into 3 equal groups, There are 3 chickens in each group
as 9 ÷ 3 = 3 chickens.

Question 5.

There are ____3_____ buckets in each group.
12 ÷ 4 = ____3____

12 buckets are divided into 4 equal groups.
There are 3 buckets in each group as 12 ÷ 4 = 3 buckets,

Explanation:
As given in the picture there are 12 buckets divided
into 4 equal groups, There are 3 buckets in each group
as 12 ÷ 4 = 3 buckets.

Question 6.

16 ÷ 4 = _4_

16 bricks are divided into 4 equal groups.
There are 4 bricks in each group as 16 ÷ 4 = 4 bricks,

Explanation:
As given in the picture there are 16 bricks divided
into 4 equal groups, There are 4 bricks in each group
as 16 ÷ 4 = 4 bricks.

Question 7.
Andrew has 21 keys. He puts them in 3 equal groups.
How many keys are in each group?

There are ___7____ keys in each group.
21 ÷ 3 = ____7______

21 keys are divided into 3 equal groups.
There are 7 keys in each group.

Explanation:
Given Andrew has 21 keys. He puts them in 3
equal groups. So, number of keys in each group
are 7 keys as 21 ÷ 3 = 7 keys in each group.

Question 8.
Mr. Doyle has 20 pencils. He divides them equally
between 4 tables. Draw the pencils on each table.

There are _____5_____ pencils on each table.
20 ÷ ___4_____ = ____5______

There are 5 pencils on each table,

Explanation:
Given Mr. Doyle has 20 pencils and he divides them equally
between 4 tables. Drawn the pencils on each table as
20 ÷ 4= 5 pencils on each table as shown above.

Question 9.
Jenna has markers. The picture shows how she placed
them on her desk. Write a division sentence to represent
how she equally grouped her markers.
There are ______4______ markers in each row.

____20______ ÷ ___5_______ = ____4____

Division sentence to represent Jenna is
20 ÷ 5 = 4 markers equally grouped in each row,

Explanation:
Given Jenna has markers and the picture shows
how she placed them on her desk. Wrote a
division sentence 20 ÷ 5 = 4 markers to represent
how Jenna equally grouped 4 markers in each row.

Engage NY Eureka Math 3rd Grade Module 7 Lesson 10 Answer Key

Eureka Math Grade 3 Module 7 Lesson 10 Pattern Sheet Answer Key

Multiply

multiply by 7 (1–5)
Answer:

Explanation:
7 × 1 = 7
7 × 2 = 14
7 × 3 = 21
7 × 4 = 28
7 × 5 = 35.

Eureka Math Grade 3 Module 7 Lesson 10 Problem Set Answer Key

Question 1.
Use a 2-inch square to answer the questions below.
a. Trace the square in the space below with a red crayon.

Answer:

Explanation:
ABCD is a Square of having side as 2cm each.

b. Trace the new shape you made with the square in the space below with a red crayon.
Answer:

Explanation:
ABCD is a square transformed into a new shape with red crayon.

c. Which shape has a greater perimeter? How do you know?
Answer:
My new shape has a greater perimeter than the square because when I used my string to mark the both perimeters of the shapes, new shape was down the string.

Explanation:
My new shape has a greater perimeter than the square because when I used my string to mark the both perimeters of the shapes, new shape was down the string. So, new shape perimeter is greater than the square.

d. Color the inside of the shapes in Problem 1 (a) and (b) with a blue crayon.
Answer:

Explanation:
First, shape is square.
Second, shape is the new shape.

e. Which color represents the perimeters of the shapes? How do you know?
Answer:
Red color represents the Perimeter of the square.

Explanation:
The perimeter of a square is the length that its boundary covers. The perimeter of a square is obtained by adding all the sides together.

f. What does the other color represent? How do you know?
Answer:
Blue color represents the Area of the square.
Red color represents the Perimeter of the square.

Explanation:
The area is defined as the region occupied inside the boundary of a flat object or 2d figure.
Area of the square = Side × Side.
The perimeter of a square is the length that its boundary covers. The perimeter of a square is obtained by adding all the sides together.
Perimeter of the square = 4 × side.

g. Which shape has a greater area? How do you know?
Answer:
Neither, shape has greater area because the look of the shape of the square has been changed not the area.

Explanation:
Neither shapes have the greater area among themselves. the look of the square has just changed yet not the area.

Question 2.
a. Outline the perimeter of the shapes below with a red crayon.

Answer:

Explanation:
Rhombus ABCD, Triangle EFG, Parallelogram HIJK shapes are outlined the perimeter with red crayon.

b. Explain how you know you outlined the perimeters of the shapes above.
Answer:
The perimeter of any figure is the length that its boundary covers.

Explanation:

Question 3.
Outline the perimeter of this piece of paper with a highlighter.
Answer:

Explanation:
The Perimeter of this all figures is highlighted with a light blue crayon.

Eureka Math Grade 3 Module 7 Lesson 10 Exit Ticket Answer Key

Jason paints the outside edges of a rectangle purple. Celeste paints the inside of the rectangle yellow.
Question 1.
Use your crayons to color the rectangle that Jason and Celeste painted.

Answer:

Explanation:
ABCD is a rectangle.
Jason paints the outside edges of a rectangle purple. Celeste paints the inside of the rectangle yellow.

Question 2.
Which color represents the perimeter of the rectangle? How do you know?
Answer:
Purple Color represents the perimeter of the rectangle because it is the boundary color of the rectangle.

Explanation:

The perimeter of any figure is the length that its boundary covers.

Eureka Math Grade 3 Module 7 Lesson 10 Homework Answer Key

Question 1.
Trace the perimeter of the shapes below.

a. Explain how you know you traced the perimeters of the shapes above.

Answer:
The perimeter of any figure is the length that its boundary covers. The color used to trace the perimeter of the figures is Red color.

Explanation:

b. Explain how you could use a string to figure out which shape above has the greatest perimeter.
Answer:
Perimeter of any figure is calculated by adding its all sides. Place the string on all the sides of each figure and later add all sides of each figure to calculate the Perimeter of the figures to know which above figure as the greatest perimeter among all.

Explanation:
The perimeter of any figure is the length that its boundary covers.
Perimeter of any figure is calculated by adding its all sides.

Question 2.
Draw a rectangle on the grid below.

a. Trace the perimeter of the rectangle.

Answer:

Explanation:
ABCD is the rectangle drawn in the grid.
The perimeter of any figure is the length that its boundary covers.

b. Shade the area of the rectangle.

Answer:

Explanation:
The area is defined as the region occupied inside the boundary of a flat object or 2d figure.
Area of the rectangle is the inside part, which is shaded with yellow color.

c. How is the perimeter of the rectangle different from the area of the rectangle?
Answer:
The perimeter and the Area of the rectangle are two different topics.
They have different units for perimeter and area. The perimeter has the same units as its the length of the sides whereas the area’s unit are squared.

Explanation:
The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle, you have to add the lengths of all the four sides.
Perimeter of the rectangle = 2(Length + Width) = 2(L + W)

The area is measurement of the surface of a shape. To find the area of a rectangle  you need to multiply the length and the width of a rectangle.
Area of the rectangle = Length × Width = L × W.

Question 3.
Maya draws the shape shown below. Noah colors the inside of Maya’s shape as shown. Noah says he colored the perimeter of Maya’s shape. Maya says Noah colored the area of her shape. Who is right? Explain your answer.

Answer:
Maya is  correct not Noah because she colored inside part of the figure, which is area not perimeter.

Explanation:
The area is defined as the region occupied inside the boundary of a flat object or 2d figure.
Area of the figure is the inside color, which Noah colored.
The perimeter of a figure is the length that its boundary covers.
Perimeter of the figure is the boundaries.

Engage NY Eureka Math 3rd Grade Module 7 Lesson 9 Answer Key

Eureka Math Grade 3 Module 7 Lesson 9 Pattern Sheet Answer Key

Multiply.

multiply by 6 (6─10)
Answer:

Explanation:
6 × 5 = 30
6 × 6 = 36
6 × 7 = 42
6 × 8 = 48
6 × 9 = 54
6 × 10 = 60

Eureka Math Grade 3 Module 7 Lesson 9 Problem Set Answer Key

Question 1.
Use at least two tangram pieces to make and draw two of each of the following shapes. Draw lines to show where the tangram pieces meet.
a. A rectangle that does not have all equal sides.
Answer:

Explanation:
ABCD is an rectangle of different length size sides, folded half pointing EF.
After folding, they meet at BGC.

b. A triangle.
Answer:

Explanation:
ABC is a triangle, folded half pointing D.
After the folding EF is where they meet.

c. A parallelogram.
Answer:

Explanation:
ABCD is a parallelogram, half folded.
After folding, at BE and FD they meet.

d. A trapezoid.
Answer:

Explanation:
ABCD is a trapezium, folded at CE.
After the folding, they meet at BF and CG.

Question 2.
Use your two smallest triangles to create a square, a parallelogram, and a triangle. Show how you created them below.
Answer:

Explanation:
ABCD  is a square formed by joining two small triangles.
EFGH is a parallelogram formed by joining two small triangles.
IJK is a triangle formed by joining two small triangles.

Question 3.
Create your own shape on a separate sheet of paper using all seven pieces. Describe its attributes below.
Answer:

Explanation:
The figure which I have drawn using the seven pieces is having six sides known as a Hexagon. It has a pair of parallel sides. My figure does not have any right angles in it. It is not a regular hexagon because it does not have any equal sides in it.

Question 4.
Trade your outline with a partner to see if you can re-create her shape using your tangram pieces. Reflect on your experience below. What was easy? What was challenging?
Answer:

Explanation:
My partner has recreated the figure of mine into a trapezium. I have found it to be easy in identifying the figure by its outer size. It was challenging for me to identify how the pieces are kept to figure out the trapezium.

Eureka Math Grade 3 Module 7 Lesson 9 Exit Ticket Answer Key

Nancy uses her tangram pieces to make a trapezoid without using the square piece. Below, sketch how she might have created her trapezoid.
Answer:

Explanation:
Nancy uses her tangram pieces to make a trapezoid without using the square piece. She uses her five triangles to make a shape that has four sides with different size of sides, named as trapezium ADEG.

Eureka Math Grade 3 Module 7 Lesson 9 Homework Answer Key

Question 1.
Use at least two tangram pieces to make and draw each of the following shapes. Draw lines to show where the tangram pieces meet.
a. A triangle.
Answer:

Explanation:
ABC is a triangle formed by joining two triangle and they meet at CD.

b. A square.
Answer:

Explanation:
ABCD is a square, formed by joining two triangles joining at BD.

c. A parallelogram.
Answer:

Explanation:
ABCD is a parallelogram, formed by joining two triangles meeting at BD.

d. A trapezoid.
Answer:

Explanation:
ABCD is a trapezium formed by joining two triangles meeting at AC.

Question 2.
Use your tangram pieces to create the cat below. Draw lines to show where the tangram pieces meet.

Answer:

Explanation:
ABGE and  FQDC are two rectangles joined together to form the shape of the cat, they meet at B.
CHIP  Trapezium and PGKL  rectangle and RJK triangle are used to form the shape of the body, meeting at P.
NMOL is a combination of two triangle used together to form the shape of the cat’s tail meeting at OM.

Question 3.
Use the five smallest tangram pieces to make a square. Sketch your square below, and draw lines to show where the tangram pieces meet.
Answer:

Explanation:
ABCD is a square formed by combining five different sizes of triangles, meeting at A,B,C,D.

Engage NY Eureka Math 3rd Grade Module 1 Lesson 2 Answer Key

Eureka Math Grade 3 Module 1 Answer Key

Eureka Math Grade 3 Module 1 Lesson 2 Sprint Answer Key

A
Add or Subtract Using 2

Question 1.
0 + 2 =
0 + 2 = 2,

Explanation:
Given 0 + 2 we add 0 with 2,
we get 2 as 0 + 2 = 2.

Question 2.
2 + 2 =
2 + 2 = 4,

Explanation:
Given 2 + 2 we add 2 with 2,
we get 4 as 2 + 2 = 4.

Question 3.
4 + 2 =
4 + 2 = 6,

Explanation:
Given 4 + 2 we add 4 with 2,
we get 6 as 4 + 2 = 6.

Question 4.
6 + 2 =
6 + 2 = 8,

Explanation:
Given 6 + 2 we add 6 with 2,
we get 8 as 6 + 2 = 8.

Question 5.
8 + 2 =
8 + 2 = 10,

Explanation:
Given 8 + 2 we add 8 with 2,
we get 10 as 8 + 2 = 10.

Question 6.
10 + 2 =
10 + 2 = 12,

Explanation:
Given 10 + 2 we add 10 with 2,
we get 12 as 10 + 2 = 12.

Question 7.
12 + 2 =
12 + 2 = 14,

Explanation:
Given 12 + 2 we add 12 with 2,
we get 14 as 12 + 2 = 14.

Question 8.
14 + 2 =
14 + 2 = 16,

Explanation:
Given 14 + 2 we add 14 with 2,
we get 16 as 14 + 2 = 16.

Question 9.
16 + 2 =
16 + 2 = 18,

Explanation:
Given 16 + 2 we add 16 with 2,
we get 18 as 16 + 2 = 18.

Question 10.
18 + 2 =
18 + 2 = 20,

Explanation:
Given 18 + 2 we add 18 with 2,
we get 20 as 18 + 2 = 20.

Question 11.
20 – 2 =
20 – 2 = 18,

Explanation:
Given 20 – 2 we subtract 2 from 20,
we get 18 as 20 – 2 = 18.

Question 12.
18 – 2 =
18 – 2 = 16,

Explanation:
Given 18 – 2 we subtract 2 from 18,
we get 16 as 18 – 2 = 16.

Question 13.
16 – 2 =
16 – 2 = 14,

Explanation:
Given 16 – 2 we subtract 2 from 16,
we get 14 as 16 – 2 = 14.

Question 14.
14 – 2 =
14 – 2 = 12,

Explanation:
Given 14 – 2 we subtract 2 from 14,
we get 12 as 14 – 2 = 12.

Question 15.
12 – 2 =
12 – 2 = 10,

Explanation:
Given 12 – 2 we subtract 2 from 12,
we get 10 as 12 – 2 = 10.

Question 16.
10 – 2 =
10 – 2 = 8,

Explanation:
Given 10 – 2 we subtract 2 from 10,
we get 8 as 10 – 2 = 8.

Question 17.
8 – 2 =
8 – 2 = 6,

Explanation:
Given 8 – 2 we subtract 2 from 8,
we get 6 as 8 – 2 = 6.

Question 18.
6 – 2 =
6 – 2 = 4,

Explanation:
Given 6 – 2 we subtract 2 from 6,
we get 4 as 6 – 2 = 4.

Question 19.
4 – 2 =
4 – 2 = 2,

Explanation:
Given 4 – 2 we subtract 2 from 4,
we get 2 as 4 – 2 = 2.

Question 20.
2 – 2 =
2 – 2 = 0,

Explanation:
Given 2 – 2 we subtract 2 from 2,
we get 0 as 2 – 2 = 0.

Question 21.
2 + 0 =
2 + 0 = 2,

Explanation:
Given 2 + 0 we add 2 with 0,
we get 2 as 2 + 0 = 2.

Question 22.
2 + 2 =
2 + 2 = 4,

Explanation:
Given 2 + 2 we add 2 with 2,
we get 4 as 2 + 2 = 4.

Question 23.
2 + 4 =
2 + 4 = 6,

Explanation:
Given 2 + 4 we add 2 with 4,
we get 6 as 2 + 4 = 6.

Question 24.
2 + 6 =
2 + 6 = 8,

Explanation:
Given 2 + 6 we add 2 with 6,
we get 8 as 2 + 6 = 8.

Question 25.
2 + 8 =
2 + 8 = 10,

Explanation:
Given 2 + 8 we add 2 with 8,
we get 10 as 2 + 8 = 10.

Question 26.
2 + 10 =
2 + 10 = 12,

Explanation:
Given 2 + 10 we add 2 with 10,
we get 12 as 2 + 10 = 12.

Question 27.
2 + 12 =
2 + 12 = 14,

Explanation:
Given 2 + 12 we add 2 with 12,
we get 14 as 2 + 12 =14.

Question 28.
2 + 14 =
2 + 14 = 16,

Explanation:
Given 2 + 14 we add 2 with 14,
we get 16 as 2 + 14 =16.

Question 29.
2 + 16 =
2 + 16 = 18,

Explanation:
Given 2 + 16 we add 2 with 16,
we get 16 as 2 + 16 =18.

Question 30.
2 + 18 =
2 + 18 = 20,

Explanation:
Given 2 + 18 we add 2 with 18,
we get 20 as 2 + 18 =20.

Question 31.
0 + 22 =
0 + 22 = 22,

Explanation:
Given 0 + 22 we add 0 with 22,
we get 22 as 0 + 22 =22.

Question 32.
22 + 22 =
22 + 22 = 44,

Explanation:
Given 22 + 22 we add 22 with 22,
we get 44 as 22 + 22 =44.

Question 33.
44 + 22 =
44 + 22 = 66,

Explanation:
Given  44 + 22 we add 44 with 22,
we get 66 as 44 + 22 =66.

Question 34.
66 + 22 =
66 + 22 = 88,

Explanation:
Given 66 + 22 we add 66 with 22,
we get 88 as 66 + 22 = 88.

Question 35.
88 – 22 =
88 – 22 = 66,

Explanation:
Given 88 – 22 we subtract 22 from 88,
we get 66 as 88 – 22 = 66.

Question 36.
66 – 22 =
66 – 22 = 44,

Explanation:
Given 66 – 22 we subtract 22 from 66,
we get 44 as 66 – 22 = 44.

Question 37.
44 – 22 =
44 – 22 = 22,

Explanation:
Given 44 – 22 we subtract 22 from 44,
we get 22 as 44 – 22 = 22.

Question 38.
22 – 22 =
22 – 22 = 0,

Explanation:
Given 22 – 22 we subtract 22 from 22,
we get 0 as 22 – 22 = 0.

Question 39.
22 + 0 =
22 + 0 = 22,

Explanation:
Given 22 + 0 we add 22 with 0,
we get 22 as 22 + 0 = 22.

Question 40.
22 + 22 =
22 + 22 = 44,

Explanation:
Given 22 + 22 we add 22 with 22,
we get 44 as 22 + 22 =44.

Question 41.
22 + 44 =
22 + 44 = 66,

Explanation:
Given 22 + 44 we add 22 with 44,
we get 66 as 22 + 44 = 66.

Question 42.
66 + 22 =
66 + 22 = 88,

Explanation:
Given 66 + 22 we add 66 with 22,
we get 88 as 66 + 22 = 88.

Question 43.
888 – 222 =
888 – 222 = 666,

Explanation:
Given 888 – 222 we subtract 222 from 888,
we get 666 as 888 – 222 = 666.

Question 44.
666 – 222 =
666 – 222 = 444,

Explanation:
Given 666 – 222 we subtract 222 from 666,
we get 444 as 666 – 222 = 444.

B
Add or Subtract Using 2

Question 1.
2 + 0 =
2 + 0 = 2,

Explanation:
Given 2 + 0 we add 2 with 0,
we get 2 as 2 + 0 = 2.

Question 2.
2 + 2 =
2 + 2 = 4,

Explanation:
Given 2 + 2 we add 2 with 2,
we get 4 as 2 + 2 = 4.

Question 3.
2 + 4 =
2 + 4 = 6,

Explanation:
Given 2 + 4 we add 2 with 4,
we get 6 as 2 + 4 = 6.

Question 4.
2 + 6 =
2 + 6 = 8,

Explanation:
Given 2 + 6 we add 2 with 6,
we get 8 as 2 + 6 = 8.

Question 5.
2 + 8 =
2 + 8 = 10,

Explanation:
Given 2 + 8 we add 2 with 8,
we get 10 as 2 + 8 = 10.

Question 6.
2 + 10 =
2 + 10 = 12,

Explanation:
Given 2 + 10 we add 2 with 10,
we get 12 as 2 + 10 = 12.

Question 7.
2 + 12 =
2 + 12 = 14,

Explanation:
Given 2 + 12 we add 2 with 12,
we get 14 as 2 + 12 =14.

Question 8.
2 + 14 =
2 + 14 = 16,

Explanation:
Given 2 + 14 we add 2 with 14,
we get 16 as 2 + 14 =16.

Question 9.
2 + 16 =
2 + 16 = 18,

Explanation:
Given 2 + 16 we add 2 with 16,
we get 16 as 2 + 16 =18.

Question 10.
2 + 18 =
2 + 18 = 20,

Explanation:
Given 2 + 18 we add 2 with 18,
we get 20 as 2 + 18 =20.

Question 11.
20 – 2 =
20 – 2 = 18,

Explanation:
Given 20 – 2 we subtract 2 from 20,
we get 18 as 20 – 2 = 18.

Question 12.
18 – 2 =
18 – 2 = 16,

Explanation:
Given 18 – 2 we subtract 2 from 18,
we get 16 as 18 – 2 = 16.

Question 13.
16 – 2 =
16 – 2 = 14,

Explanation:
Given 16 – 2 we subtract 2 from 16,
we get 14 as 16 – 2 = 14.

Question 14.
14 – 2 =
14 – 2 = 12,

Explanation:
Given 14 – 2 we subtract 2 from 14,
we get 12 as 14 – 2 = 12.

Question 15.
12 – 2 =
12 – 2 = 10,

Explanation:
Given 12 – 2 we subtract 2 from 12,
we get 10 as 12 – 2 = 10.

Question 16.
10 – 2 =
10 – 2 = 8,

Explanation:
Given 10 – 2 we subtract 2 from 10,
we get 8 as 10 – 2 = 8.

Question 17.
8 – 2 =
8 – 2 = 6,

Explanation:
Given 8 – 2 we subtract 2 from 8,
we get 6 as 8 – 2 = 6.

Question 18.
6 – 2 =
6 – 2 = 4,

Explanation:
Given 6 – 2 we subtract 2 from 6,
we get 4 as 6 – 2 = 4.

Question 19.
4 – 2 =
4 – 2 = 2,

Explanation:
Given 4 – 2 we subtract 2 from 4,
we get 2 as 4 – 2 = 2.

Question 20.
2 – 2 =
2 – 2 = 0,

Explanation:
Given 2 – 2 we subtract 2 from 2,
we get 0 as 2 – 2 = 0.

Question 21.
0 + 2 =
0 + 2 = 2,
Explanation:
Given 0 + 2 we add 0 with 2,
we get 2 as 0 + 2 = 2.

Question 22.
2 + 2 =
2 + 2 = 4,
Explanation:
Given 2 + 2 we add 2 with 2,
we get 4 as 2 + 2 = 4.

Question 23.
4 + 2 =
4 + 2 = 6,
Explanation:
Given 4 + 2 we add 4 with 2,
we get 6 as 4 + 2 = 6.

Question 24.
6 + 2 =
6 + 2 = 8,

Explanation:
Given 6 + 2 we add 6 with 2,
we get 8 as 6 + 2 = 8.

Question 25.
8 + 2 =
8 + 2 = 10,
Explanation:
Given 8 + 2 we add 8 with 2,
we get 10 as 8 + 2 = 10.

Question 26.
10 + 2 =
10 + 2 = 12,
Explanation:
Given 10 + 2 we add 10 with 2,
we get 12 as 10 + 2 = 12.

Question 27.
12 + 2 =
12 + 2 = 14,
Explanation:
Given 12 + 2 we add 12 with 2,
we get 14 as 12 + 2 = 14.

Question 28.
14 + 2 =
14 + 2 = 16,
Explanation:
Given 14 + 2 we add 14 with 2,
we get 16 as 14 + 2 = 16.

Question 29.
16 + 2 =
16 + 2 = 18,
Explanation:
Given 16 + 2 we add 16 with 2,
we get 18 as 16 + 2 = 18.

Question 30.
18 + 2 =
18 + 2 = 20,
Explanation:
Given 18 + 2 we add 18 with 2,
we get 20 as 18 + 2 = 20.

Question 31.
0 + 22 =
0 + 22 = 22,
Explanation:
Given 0 + 22 we add 0 with 22,
we get 22 as 0 + 22 =22.

Question 32.
22 + 22 =
22 + 22 = 44,

Explanation:
Given 22 + 22 we add 22 with 22,
we get 44 as 22 + 22 =44.

Question 33.
22 + 44 =
22 + 44 = 66,

Explanation:
Given 22 + 44 we add 22 with 44,
we get 66 as 22 + 44 = 66.

Question 34.
66 + 22 =
66 + 22 = 88,

Explanation:
Given 66 + 22 we add 66 with 22,
we get 88 as 66 + 22 = 88.

Question 35.
88 – 22 =
88 – 22 = 66,

Explanation:
Given 88 – 22 we subtract 22 from 88,
we get 66 as 88 – 22 = 66.

Question 36.
66 – 22 =
66 – 22 = 44,

Explanation:
Given 66 – 22 we subtract 22 from 66,
we get 44 as 66 – 22 = 44.

Question 37.
44 – 22 =
44 – 22 = 22,
Explanation:
Given 44 – 22 we subtract 22 from 44,
we get 22 as 44 – 22 = 22.

Question 38.
22 – 22 =
22 – 22 = 0,

Explanation:
Given 22 – 22 we subtract 22 from 22,
we get 0 as 22 – 22 = 0.

Question 39.
22 + 0 =
22 + 0 = 22,

Explanation:
Given 22 + 0 we add 22 with 0,
we get 22 as 22 + 0 = 22.

Question 40.
22 + 22 =
22 + 22 = 44,
Explanation:
Given 22 + 22 we add 22 with 22,
we get 44 as 22 + 22 =44.

Question 41.
22 + 44 =
22 + 44 = 44,

Explanation:
Given 22 + 44 we add 22 with 44,
we get 66 as 22 + 44 = 66.

Question 42.
66 + 22 =
66 + 22 = 88,

Explanation:
Given 66 + 22 we add 66 with 22,
we get 88 as 66 + 22 = 88.

Question 43.
666 – 222 =
666 – 222 = 444,

Explanation:
Given 666 – 222 we subtract 222 from 666,
we get 444 as 666 – 222 = 444.

Question 44.
888 – 222 =
888 – 222 = 666,

Explanation:
Given 888 – 222 we subtract 222 from 888,
we get 666 as 888 – 222 = 666.

Eureka Math Grade 3 Module 1 Lesson 2 Problem Set Answer Key

Use the arrays below to answer each set of questions.

Question 1.
a. How many rows of cars are there? ___4_______
b. How many cars are there in each row? ___2_______

a. There are 4 number of rows of cars,

Explanation:
As shown in the picture there are
4 number of rows of cars.

b. There are 2 cars are there in each row,

Explanation:
As shown in the picture there are
2 cars are there in each row.

Question 2.
a. What is the number of rows? ____3______
b. What is the number of objects in each row? _____6_____

a. There are 3 number of rows of objects,

Explanation:
As shown in the picture there are
3 number of rows of objects.

b. There are 6 objects are there in each row,

Explanation:
As shown in the picture there are
6 objects are there in each row.

Question 3.
a. There are 4 spoons in each row. How many spoons are in 2 rows? ____8______
b. Write a multiplication expression to describe the array.
_____4 x 2 = 8___

a. There are 8 spoons in 2 rows,

Explanation:
Given there are 4 spoons in each row.
Number of spoons in 2 rows are 4 X 2 = 8 spoons,

b. Multiplication expression : 4 X 2 = 8 spoons,

Explanation:
Given there are 4 spoons in each row.
Multiplication expression to describe the array is
4 X 2 = 8.

Question 4.
a. There are 5 rows of triangles.
How many triangles are in each row? ___4______
b. Write a multiplication expression to describe the total number of triangles. _____5 x 4 = 20 _________________

a. There are 4 triangles in each row,

Explanation:
Given there are 5 rows of triangles,
As shown in the picture there are 4
number of triangles in each row.

b. Multiplication expression : 5 X 4 = 20 triangles,

Explanation:
Given there are 5 rows of triangles,
Wrote a multiplication expression to
describe the total number of triangles as
5 X 4 = 20 triangles.

Question 5.
The dots below show 2 groups of 5.
a. Redraw the dots as an array that shows 2 rows of 5.

b. Compare the drawing to your array.
Write at least 1 reason why they are the same and
1 reason why they are different.

Redrawn the dots as an array that shows 2 rows of 5.

Explanation:
Given the dots below show 2 groups of 5.
So, redrawn the dots as an array that shows
2 rows of 5 as shown above in the picture.

b. Same : Both have the same number of dots,
Different : Drawing is not in any order but my array
has an order of 2 rows of 5,

Explanation:
Comparing the drawing to my array.
Wrote at least 1 reason why they are the same and
1 reason why they are different as
Same : Both have the same number of dots,
Different : Drawing is not in some order but my array
has an order of 2 rows of 5.

Question 6.
Emma collects rocks. She arranges them in 4 rows of 3.
Draw Emma’s array to show how many rocks
she has altogether. Then, write a multiplication
equation to describe the array.

Emma has 12 number of rocks altogether,
Multiplication equation : 4 X 3 = 12 rocks,

Explanation:
Given Emma collects rocks. She arranges them in 4 rows of 3.
Drawn Emma’s array to show how many rocks
she has altogether as shown above in the picture,
Then, wrote a multiplication equation to describe
the array as multiplication equation : 4 X 3 = 12 rocks.

Question 7.
Joshua organizes cans of food into an array.
He thinks, “My cans show 5 × 3!” Draw Joshua’s
array to find the total number of cans he organizes.

The total number of cans Joshua organizes are 15,

Explanation:
Given Joshua organizes cans of food into an array.
He thinks, “My cans show 5 × 3!” Drawn Joshua’s
array to find the total number of cans he organizes is
5 X 3 = 15 food cans.

Eureka Math Grade 3 Module 1 Lesson 2 Exit Ticket Answer Key

Question 1.
a. There are 4 rows of stars. How many
stars are in each row? _____3_____
b. Write a multiplication equation to
describe the array. ______4 x 3= 12_________

a. There are 3 number of stars in each row,

Explanation:
As shown in the picture there are
3 number of stars in each row.

b. Multiplication equation : 4 X 3 = 12,

Explanation:
As shown in the picture multiplication equation to
describe the array is 4 X 3 = 12 stars.

Question 2.
Judy collects seashells. She arranges them in 3 rows of 6.
Draw Judy’s array to show how many seashells
she has altogether. Then, write a multiplication equation
to describe the array.

Judy’s has 18 seashells altogether,
Multiplication Equation : 3 X 6 = 18,

Explanation:
Given Judy collects seashells. She arranges them
in 3 rows of 6.
Drawn Judy’s array to show 18 seashells
she has altogether. Then, wrote a multiplication equation
to describe the array as 3 X 6 = 18 seashells.

Eureka Math Grade 3 Module 1 Lesson 2 Homework Answer Key

Use the arrays below to answer each set of questions.

Question 1.
a. How many rows of erasers are there? ____3______
b. How many erasers are there in each row? ____2______

a. There are 3 rows of erasers,

Explanation:
In the given picture there are 3 rows are erasers.

b. There are 2 erasers in each row,

Explanation:
In the given picture there are 2 erasers in each row.

Question 2.
a. What is the number of rows? _____4_____
b. What is the number of objects in each row? ____3______

a. There are 4 rows of ducks,

Explanation:
In the given picture there are 4 rows of ducks.

b. There are 3 objects in each row,

Explanation:
In the given picture there are 3 objects in each row.

Question 3.
a. There are 3 squares in each row. How many squares are in 5 rows? ____15____
b. Write a multiplication expression to describe the array.
_5 X 3 = 15___

a. There are 15 squares in 5 rows,

Explanation:
Given there are 3 squares in each row,
So, number of squares in 5 rows are 5 X 3 = 15 squares.

b. Multiplication expression : 5 X 3 = 15,

Explanation:
Given there are 3 squares in each row,
So, multiplication expression to describe the array is
5 X 3 = 15 squares.

Question 4.
a. There are 6 rows of stars. How many stars are
in each row? ____4______
b. Write a multiplication expression to describe
the array. ____6 x 4 = 24______

a. There are 4 stars in each row,

Explanation:
In the picture there are 6 rows of stars and
in each row there are 4 stars.

b. Multiplication expression : 6 X 4 = 24,

Explanation:
In the picture there are 6 rows and each row
has 4 stars, So, multiplication expression to describe
the array is 6 X 4 = 24 stars.

Question 5.
The triangles below show 3 groups of four.
a. Redraw the triangles as an array that shows 3 rows of four.
b. Compare the drawing to your array. How are they the same? How are they different?

a.

Shown triangles as an array that shows 3 rows of four.

Explanation:
Given the triangles as 3 groups of four.
a. Redrawn the triangles as an array that
shows 3 rows of four as shown in the picture above.

b. Same : Both have same number of triangles,
Different : Drawing is not in any order but my array
has an order of 3 rows of 4.

Question 6.
Roger has a collection of stamps.
He arranges the stamps into 5 rows of four.
Draw an array to represent Roger’s stamps.
Then, write a multiplication equation to
describe the array.

Drawn an array to represent Roger’s stamps.
Multiplication equation to describe the array is 5 X 4 = 20 stamps,

Explanation:
Given Roger has a collection of stamps.
He arranges the stamps into 5 rows of four.
Drawn an array to represent Roger’s stamps
as shown above then wrote a multiplication equation
to describe the array as 5 X 4 = 20 stamps.

Question 7.
Kimberly arranges her 18 markers as an array.
Draw an array that Kimberly might make.
Then, write a multiplication equation to describe your array.

Drawn an array that Kimberly might make,
Multiplication equation to describe the array is 3 X 6 = 18,

Explanation:
Given Kimberly arranges her 18 markers as an array,
may be of 3 rows of 6 markers each, Drawn an array
that Kimberly might make as shown in the picture above,
Then, wrote a multiplication equation to describe
my array as 3 X 6 = 18 markers.

Engage NY Eureka Math 3rd Grade Module 7 Lesson 8 Answer Key

Eureka Math Grade 3 Module 7 Lesson 8 Pattern Sheet Answer Key

Multiply.

multiply by 6 (1─5)
Answer:

Explanation:
6 × 1 = 6
6 × 2 = 12
6 × 3 = 18
6 × 4 = 24
6 × 5 = 30.

Eureka Math Grade 3 Module 7 Lesson 8 Problem Set Answer Key

Question 1.
Fold and cut the square on the diagonal. Draw and label your 2 new shapes below.
Answer:

Explanation:
ABCD is a Square.
ABC is the half part of the square when folded and cut.
DEF  is the other half part of the square when folded and cut.

Question 2.
Fold and cut one of the triangles in half. Draw and label your 2 new shapes below.
Answer:

Explanation:
ABC is an Triangle.
ABD is the half part of of the Triangle when folded and cut.
CEF is the other half part of of the Triangle when folded and cut.

Question 3.
Fold twice, and cut your large triangle. Draw and label your 2 new shapes below.
Answer:

Explanation:
ABC Triangle is twice folded and cut into two halves.
ADEC is first half part of twice folded Triangle.
CFG is the second half part of twice folded Triangle.

Question 4.
Fold and cut your trapezoid in half. Draw and label your 2 new shapes below.
Answer:

Explanation:
ABCD is a Trapezium, folded and cut.
ABFE and CDHG are two parts of them formed.
We can call ABFE and CDHG  as Quadrilaterals.

Question 5.
Fold and cut one of your trapezoids. Draw and label your 2 new shapes below.
Answer:

Explanation:
GDCH is a half part of Trapezium.
When folded the Trapezium, we get a  GDIJ Square and a CHK Triangle  are formed.

Question 6.
Fold and cut your second trapezoid. Draw and label your 2 new shapes below.
Answer:

Explanation:
AEFB is the second Trapezium.
When the AEFB Trapezium is folded and cut, we get a AEOP Parallelogram  and a BFN Triangle .

Question 7.
Reconstruct the original square using the seven shapes.
a. Draw lines inside the square below to show how the shapes go together to form the square. The first one has been done for you.

Answer:

Explanation:
ABCD is the Square.
AC is the first line used to divide the Square.
EB is the second line drawn, AEB and BEC Triangles are formed.
GF is the third line drawn, GFC Triangle is formed.
GI is the fourth line drawn, DGI Triangle is formed.
IJ is the fifth line drawn, IJA Triangle is formed.
HE is the sixth line drawn, IJEH Rectangle  and HEFG Rectangle are formed.
We can reconstruct this seven shapes together to form the original square.

b. Describe the process of forming the square. What was easy, and what was challenging?
Answer:
I first put the two big triangles to form the Square, which was quiet easy. Later one by one shape I joined to put on the square, this process was challenging .

Explanation:
Firstly, dividing the square into two Triangle was the easy one. Later on forming other shapes which are smaller in size than the first step, was quiet difficult one because while reconstructing it back to original shape was little messy and challenging. Overall, it made me to go back to my problem and check the shapes in the list one by one, which finally gave me my original shape of square to rejoin with all seven different shapes.

Eureka Math Grade 3 Module 7 Lesson 8 Exit Ticket Answer Key

Choose three shapes from your tangram puzzle. Trace them below. Label the name of each shape, and describe at least one attribute that they have in common.
Answer:

Explanation:
ABJ, BJC, CIF, FED, KHG are the triangles in the ABCD square.
AEKG is a Parallelogram in the ABCD square.
KFIH is the Rectangle in the ABCD square.
They all are having one right angle in common in KHG, KFIH and AEKG shapes.

Eureka Math Grade 3 Module 7 Lesson 8 Homework Answer Key

Question 1.
Draw a line to divide the square below into 2 equal triangles.

Answer:

Explanation:
EFGH is a square.
EG is the line drawn in the square, making EFG and GHE two triangles into equal halves.

Question 2.
Draw a line to divide the triangle below into 2 equal, smaller triangles.

Answer:

Explanation:
ABC is the Triangle.
CD is the line drawn, which divides the triangle into two equal triangle ADC and BDC triangles.

Question 3.
Draw a line to divide the trapezoid below into 2 equal trapezoids.

Answer:

Explanation:
ABCD is the trapezoids
EF is the line drawn, dividing the trapezoids into two equal trapezoids AEFD and BEFC. trapezoids.

Question 4.
Draw 2 lines to divide the quadrilateral below into 4 equal triangles.

Answer:

Explanation:
EFGH is the quadrilateral.
Lines are drawn in the quadrilateral joining EG and HF center O, making EOF, FOG, GOH and HOE four equal triangles.

Question 5.
Draw 4 lines to divide the square below into 8 equal triangles.

Answer:

Explanation:
ABCD is a Square.
AC and BD are joined by drawing two lines.
EF and GH are another two lines drawn making center O.
AOH, HOB, BOF, FOC, COG, GOD, DOE, EOA  equal triangles are formed.

Question 6.
Describe the steps you took to divide the square in Problem 5 into 8 equal triangles.
Answer:
I have drawn two lines dividing the square into two equal triangles.
I  have later drawn two lines in between the two triangles formed.

Explanation:
I have drawn two lines dividing the square into two equal triangles.
ABC, ABD, BCD, CDA  Triangles are formed.
I  have later drawn two lines in between the two triangles formed.
AOH, HOB, BOF, FOC, COG, GOD, DOE, EOA eight equal triangles are formed having Center O.

Engage NY Eureka Math 3rd Grade Module 7 Lesson 1 Answer Key

Eureka Math Grade 3 Module 7 Answer Key

Eureka Math 3 Module 7 Lesson 1 Pattern Sheet Answer Key

Multiply

multiply by 3(1 – 5)
Answer:

Explanation:
3 × 1 = 3
3 × 2 = 6
3  × 3 = 9
3 × 4 = 12
3  × 5 = 15.

Eureka Math Grade 3 Module 7 Lesson 1 Problem Set Answer Key

Lena’s family visits Little Tree Apple Orchard. Use the RDW process to solve the problems about Lena’s visit to the orchard. Use a letter to represent the unknown in each problem.

Question 1.
The sign below shows information about hayrides at the orchard.

a. Lena’s family buys 2 adult tickets and 2 child tickets for the hayride. How much does it cost Lena’s family to go on the hayride?
Answer:
Total cost of tickets for Lena’s family to go on the hayride = $22.

Explanation:
Cost of each adults tickets = $7
=> Cost of Two adults tickets = $7 × 2 = $14.
Cost of Each child ticket = $4
=> Cost of Two Child tickets = $4 × 2 = $8
Total cost of tickets for Lena’s family to go on the hayride = Cost of Two adults tickets + Cost of Two Child tickets
= $14 + $8
= $22.

b. Lena’s mom pays for the tickets with $5 bills. She receives $3 in change. How many $5 bills does Lena’s mom use to pay for the hayride?

Answer:
Number of $5 bills she uses to pay the bill = 5.

Explanation:
Total cost of tickets for Lena’s family to go on the hayride = $22
Amount of change she receives = $3
Total amount paid for tickets = Total cost of tickets for Lena’s family to go on the hayride + Amount of change she receives
= $22 + $3
= $25
Number of $5 bills she uses to pay the bill = Total amount paid for tickets  ÷ 5
= $25 ÷ 5
= 5.

c. Lena’s family wants to go on the fourth hayride of the day. It’s 11:38 now. How many minutes do they have to wait for the fourth hayride?

Answer:
Time left for Lena’s family to wait for their fourth hayride = 7 minutes.

Explanation:
Time of their hayride of the day now = 11:38
Leaves every 15minutes hayride starting from 11:00.
Number of hayride lens family going = Fourth of the day
=> Time of first hayride = 11:00 to 11:15
=> Time of Second hayride = 11:15 to 11.30
=> Time of Third hayride = 11:30 to 11:45
=> Time of Fourth hayride = 11:45 to 12:00.
Time left for Lena’s family to wait for their fourth hayride = Time of Fourth hayride  – Time of their hayride of the day now
= 11:45 – 11:38
= 7 minutes.

Question 2.
Lena picked 17 apples, and her brother picked 19. Lena’s mom has a pie recipe that requires 9 apples. How many pies can Mom make with the apples that Lena and her brother picked?
Answer:
Number of pies Mom can make with the apples that Lena and her brother picked = 4.

Explanation:
Number of Apples Lena picked = 17
Number of Apples Lena’s brother picked = 19
Number of Apples Lena’s mom needs to prepare a pie = 9
Number of Apples Lena and her brother picked = Number of Apples Lena picked + Number of Apples Lena’s brother picked
= 19 + 17
= 36
Number of pies Mom can make with the apples that Lena and her brother picked = Number of Apples Lena and her brother picked  ÷ Number of Apples Lena’s mom needs to prepare a pie
= 36 ÷ 9
= 4.

Question 3.
Lena’s dad gives the cashier $30 to pay for 6 liters of apple cider. The cashier gives him $6 in change. How much does each liter of apple cider cost?
Answer:
Cost  for the a liter of apple cider = $4.

Explanation:
Amount of money Lena’s dad gives to the cashier to pay for 6 liters of apple cider = $30
Amount of money Lena’s dad gets in change = $6
Cost  for the 6 liters of apple cider = Amount of money Lena’s dad gives to the cashier to pay for 6 liters of apple cider  – Amount of money Lena’s dad gets in change
= $30 – $6
= $24.
Number of liters of apple cider purchased = 6
Cost  for the a liter of apple cider = Cost  for the 6 liters of apple cider  ÷ Number of liters of apple cider purchased
= $24 ÷ 6
= $4.

Question 4.
The apple orchard has 152 apple trees. There are 88 trees with red apples. The rest of the trees have green apples. How many more trees have red apples than green apples?
Answer:
Number of Green apple trees = 64.
Number of Red apples more than Green apples = 24.

Explanation:
Number of Apple trees the Apple orchard has = 152
Number of Red apple trees = 88
Number of Green apple trees = Number of Apple trees the Apple orchard has – Number of Red apple trees
= 152 – 88
= 64.
Number of Red apples more than Green apples = Number of Red apple trees – Number of Green apple trees
= 88 – 64
= 24.

Eureka Math Grade 3 Module 7 Lesson 1 Exit Ticket Answer Key

Use the RDW process to solve the problem below. Use a letter to represent the unknown.
Sandra keeps her sticker collection in 7 albums. Each album has 40 stickers in it. She starts a new album that has 9 stickers in it. How many total stickers does she have in her collection?
Answer:
Total number of stickers Sandra has in each album = 640.

Explanation:
Number of stickers Sandra has in each album of 7albums = 40 × 7 = 280.
Number of stickers Sandra has in each album of 9albums = 40 × 9 = 360
Total number of stickers Sandra has in each album = Number of stickers Sandra has in each album of 7albums  + Number of stickers Sandra has in each album of 9albums
= 280 + 360
= 640.

Eureka Math Grade 3 Module 7 Lesson 1 Homework Answer Key

Max’s family takes the train to visit the city zoo. Use the RDW process to solve the problems about Max’s trip to the zoo. Use a letter to represent the unknown in each problem.
Question 1.
The sign below shows information about the train schedule into the city.

a. Max’s family buys 2 adult tickets and 3 child tickets. How much does it cost Max’s family to take the train into the city?
Answer:
Total amount for the Max’s family to take the train into the city = $34.

Explanation:
Amount of money for Adult ticket = $8
=> Amount of money for 2 Adult ticket = $8 × 2 = $16.
Amount of money for Child ticket = $6
=> Amount of money for 3 Child ticket =$6 × 3 = $18.
Total amount for the Max’s family to take the train into the city = Amount of money for 2 Adult ticket + Amount of money for 3 Child ticket
= $16 + $18
= $34.

b. Max’s father pays for the tickets with $10 bills. He receives $6 in change. How many $10 bills does Max’s father use to pay for the train tickets?
Answer:
Number of $10 bills Max’s father used to make the payment for the tickets = 4.

Explanation:
Amount of money paid by Max’s father for the tickets with $10 bills.
Amount of money received as change = $6
Total amount for the Max’s family to take the train into the city = $34
Number of $10 bills Max’s father used to make the payment for the tickets = Total amount for the Max’s family to take the train into the city + Amount of money received as change  ÷ 6
= $34 + $6 ÷ 10
= $40 ÷ 10
=4.

c. Max’s family wants to take the fourth train of the day. It’s 6:38 a.m. now. How many minutes do they have to wait for the fourth train?
Answer:
Time left for Max’s family to wait for their fourth train = 7 minutes.

Explanation:
Time of their Fourth train of the day now = 6:38 a.m.
Leaves every 15minutes train starting from 6:00 a.m.
Number of the train Max’s family to go = Fourth of the day
=> Time of first train  = 6:00 to 6:15
=> Time of Second train  = 6:15 to 6.30
=> Time of Third train  = 6:30 to 6:45
=> Time of Fourth train = 6:45 to 7:00.
Time left for Max’s family to wait for their fourth train = Time of Fourth train – Time of their train of the day now
= 6:45 – 6:38
= 7 minutes.

Question 2.
At the city zoo, they see 17 young bats and 19 adult bats. The bats are placed equally into 4 areas. How many bats are in each area?
Answer:
Number of Bats in each area = 9.

Explanation:
Number of Young bats in the zoo = 17
Number of Adults bats in the zoo = 19
The bats are placed equally into 4 areas.
=> Number of areas bats placed equally = 4
Number of Bats in each area = (Number of Adults bats in the zoo + Number of Young bats in the zoo) ÷ Number of areas bats placed  equally
= (19 + 17) ÷ 4
= 36 ÷ 4
= 9.

Question 3.
Max’s father gives the cashier $20 to pay for 6 water bottles. The cashier gives him $8 in change. How much does each water bottle cost?
Answer:
Cost of each water bottle = $2.

Explanation:
Amount of money given to cashier by Max’s father to pay for 6 water bottles = $20
Amount of money received as change = $8
Total number of water bottles purchased  = 6
Cost of each water bottle = Amount of money given to cashier by Max’s father to pay for 6 water bottles  – Amount of money received as change ÷ Total number of water bottles purchased
= $20 – $8 ÷ 6
= $12 ÷ 6
= $2.

Question 4.
The zoo has 112 types of reptiles and amphibians in their exhibits. There are 72 types of reptiles, and the rest are amphibians. How many more types of reptiles are there than amphibians in the exhibits?
Answer:
Number of Amphibians in the zoo = 40.
Number of Reptiles more than Amphibians in the exhibits in the zoo = 32.

Explanation:
Number of Reptiles in the zoo = 72
Number of Reptiles and Amphibians in their exhibits in the zoo = 112
Number of Amphibians in the zoo = Number of Reptiles and Amphibians in their exhibits in the zoo – Number of Reptiles in the zoo
= 112 – 72
= 40.
Number of Reptiles more than Amphibians in the exhibits in the zoo = Number of Reptiles in the zoo  – Number of Amphibians in the zoo
= 72 – 40
= 32.

Engage NY Eureka Math 3rd Grade Module 7 Lesson 2 Answer Key

Eureka Math Grade 3 Module 7 Answer Key

Eureka Math Grade 3 Module 7 Lesson 2 Pattern Sheet Answer Key

Multiply.

multiply by 3 (6–10)
Answer:

Explanation:
Explanation:
3 × 1 = 3
3 × 2 = 6
3 × 3 = 9
3 × 4 = 12
3 × 5 = 15
3 × 6 = 18
3 × 7 = 21
3 × 8 = 24
3 × 9 = 27
3 × 10 = 30.

Eureka Math Grade 3 Module 7 Lesson 2 Problem Set Answer Key

Use the RDW process to solve. Use a letter to represent the unknown in each problem.
Question 1.
Leanne needs 120 tiles for an art project. She has 56 tiles. If tiles are sold in boxes of 8, how many more boxes of tiles does Leanne need to buy?
Answer:
Number of boxes of 8 tiles needed to buy more = 8.

Explanation:
Number of tiles needed for an project = 120
Number of tiles Leanne has = 56
Number of more tiles needed to buy by Leanne = Number of tiles needed for an project – Number of tiles Leanne has
= 120 – 56
= 64.
If tiles are sold in boxes of 8.
=>Number of tiles a box consist = 8
Number of boxes of 8 tiles needed to buy more = Number of more tiles needed to buy by Leanne ÷ Number of tiles a box consist
= 64 ÷ 8
= 8.

Question 2.
Gwen pours 236 milliliters of water into Ravi’s beaker. Henry pours 189 milliliters of water into Ravi’s beaker. Ravi’s beaker now contains 800 milliliters of water. How much water was in Ravi’s beaker to begin with?

Answer:
Total number of milliliters of water was in Ravi’s beaker to begin with = 425.

Explanation:
Number of  milliliters of water Gwen pours  into Ravi’s beaker = 236
Number of  milliliters of water Henry pours  into Ravi’s beaker = 189
Ravi’s beaker now contains 800 milliliters of water.
Total number of milliliters of water was in Ravi’s beaker to begin with = Number of  milliliters of water Gwen pours  into Ravi’s beaker + Number of  milliliters of water Henry pours  into Ravi’s beaker
= 236 + 189
= 425.

Question 3.
Maude hung 3 pictures on her wall. Each picture measures 8 inches by 10 inches. What is the total area of the wall covered by the pictures?
Answer:
Total area of the wall covered by the pictures = 240  inches.

Explanation:
Maude hung 3 pictures on her wall.
=> Number of pictures hung on the wall = 3
Length of the each picture = 10 inches
Width of the each picture = 8 inches
Area of the each picture = Length of the each picture  × Width of the each picture
= 10 × 8
= 80 inches.
Total area of the wall covered by the pictures = Area of the each picture ×Number of pictures hung on the wall
= 80 × 3
= 240  inches.

Question 4.
Kami scored a total of 21 points during her basketball game. She made 6 two-point shots, and the rest were three-point shots. How many three-point shots did Kami make?

Answer:
Number of three-point shots she made = 15.

Explanation:
Total score point of Kami during her basketball game = 21
Number of two-point shots she made = 6
Number of three-point shots she made = Total score point of Kami during her basketball game – Number of two-point shots she made
= 21 – 6
= 15.

Question 5.
An orange weighs 198 grams. A kiwi weighs 85 grams less than the orange. What is the total weight of the fruit?
Answer:
Total weight of the fruits = 311 grams.

Explanation:
Weight of Orange fruit = 198 grams
A kiwi weighs 85 grams less than the orange.
=> Weight of Kiwi fruit =  Weight of Orange fruit  – 85
=> Weight of Kiwi fruit = 198 – 85
=> Weight of Kiwi fruit =  113 grams
Total weight of the fruits = Weight of Orange fruit + Weight of Kiwi fruit
=  198 + 113
= 311 grams.

Question 6.
The total amount of rain that fell in New York City in two years was 282 centimeters. In the first year, 185 centimeters of rain fell. How many more centimeters of rain fell in the first year than in the second year?

Answer:
Amount of Rain fell in the first year than in the second year = 88 centimeters.

Explanation:
Total amount of rain that fell in New York City in two years = 282 centimeters
Amount of rain fell in the First year = 185 centimeters
Amount of rain fell in the Second year = Total amount of rain that fell in New York City in two years – Amount of rain fell in the First year
= 282 – 185
= 97 centimeters.
Amount of Rain fell in the first year than in the second year = Amount of rain fell in the First year – Amount of rain fell in the Second year
= 185 – 97
= 88 centimeters.

Eureka Math Grade 3 Module 7 Lesson 2 Exit Ticket Answer Key

Use the RDW process to solve the problem below. Use a letter to represent the unknown.
Jaden’s bottle contains 750 milliliters of water. He drinks 520 milliliters at practice and then another 190 milliliters on his way home. How many milliliters of water are left in Jaden’s bottle when he gets home?

Answer:
Amount of water left in Jaden’s bottle when he gets home = 40 milliliters.

Explanation:
Total amount of water Jaden’s bottle contains = 750 milliliters
Amount of water he drinks at practice = 520 milliliters
Amount of water he drinks on his way home = 190 milliliters
Amount of water left in Jaden’s bottle when he gets home = Total amount of water Jaden’s bottle contains  – ( Amount of water he drinks at practice  + Amount of water he drinks on his way home)
= 750 – ( 520 + 190)
= 750 – 710
= 40 milliliters.

Eureka Math Grade 3 Module 7 Lesson 2 Homework Answer Key

Use the RDW process to solve. Use a letter to represent the unknown in each problem.
Question 1.
A box containing 3 small bags of flour weighs 950 grams. Each bag of flour weighs 300 grams. How much does the empty box weigh?
Answer:
Weight of the empty box = 50 grams.

Explanation:
Weight of a box containing 3 small bags of flour weighs = 950 grams
Weight of each bag of flour = 300 grams
Weight of 3 bag of flour = 300 × 3 = 900 grams
Weight of the empty box = Weight of a box containing 3 small bags of flour weighs – Weight of 3 bag of flour
= 950 – 900
= 50 grams.

Question 2.
Mr. Cullen needs 91 carpet squares. He has 49 carpet squares. If the squares are sold in boxes of 6, how many more boxes of carpet squares does Mr. Cullen need to buy?
Answer:
Number of squares boxes of 6  he needs to buy more = 7.

Explanation:
Number of carpet square Mr. Cullen needs = 91
Number of carpet square he has = 49
Number of carpet square he needs more = Number of carpet square Mr. Cullen needs – Number of carpet square he has
= 91 – 49
= 42.
Number of squares in the box = 6
Number of squares boxes of 6  he needs to buy more = Number of carpet square he needs more ÷ Number of squares in the box
= 42 ÷ 6
= 7.

Question 3.
Erica makes a banner using 4 sheets of paper. Each paper measures 9 inches by 10 inches. What is the total area of Erica’s banner?
Answer:
Total area of Erica’s banner = 360 inches.

Explanation:
Number of sheets of paper Erica makes a banner = 4
Length of the each paper = 10 inches
Width of the each paper = 9 inches
Area of the each paper = Length of the each paper × Width of the each paper
= 10 × 9
= 90 inches.
Total area of Erica’s banner = Area of the each paper  × Number of sheets of paper Erica makes a banner
= 90 × 4
= 360 inches.

Question 4.
Monica scored 32 points for her team at the Science Bowl. She got 5 four-point questions correct, and the rest of her points came from answering three-point questions. How many three-point questions did she get correct?
Answer:
Number of points scored by her for answering three-point questions correct = 27.

Explanation:
Number of points scored by Monica  for her team at the Science Bowl = 32
Number of points scored by her for four-point questions correct = 5
Number of points scored by her for answering three-point questions correct = Number of points scored by Monica  for her team at the Science Bowl  – Number of points scored by her for four-point questions correct
= 32 – 5
= 27.

Question 5.
Kim’s black kitten weighs 175 grams. Her gray kitten weighs 43 grams less than the black kitten. What is the total weight of the two kittens?
Answer:
Total weight of Kim’s black kitten and gray kitten = 307 grams.

Explanation:
Weight of the Kim’s black kitten = 175 grams
Her gray kitten weighs 43 grams less than the black kitten.
=> Weight of the Kim’s gray kitten = Weight of the Kim’s black kitten – 43
= 175 – 43
= 132 grams.
Total weight of Kim’s black kitten and gray kitten = Weight of the Kim’s black kitten + Weight of the Kim’s gray kitten
= 175 + 132
= 307 grams.

Question 6.
Cassias and Javier’s combined height is 267 centimeters. Cassias is 128 centimeters tall. How much taller is Javier than Cassias?
Answer:
Height of Javier’s more than Cassias height = 11 centimeters.

Explanation:
Height of Cassias and Javier’s combined = 267 centimeters.
Height of Cassias = 128 centimeters
Height of Javier = Height of Cassias and Javier’s combined – Height of Cassias
= 267 – 128
= 139.
Height of Javier’s more than Cassias height = Height of Javier  – Height of Cassias
= 139 – 128
= 11 centimeters.

Engage NY Eureka Math 3rd Grade Module 7 Lesson 3 Answer Key

Eureka Math Grade 3 Module 7 Answer Key

Eureka Math Grade 3 Module 7 Lesson 3 Pattern Sheet Answer Key

Multiply.

multiply by 4 (1–5)

Answer:

Explanation:
4 × 1 = 4
4 × 2 = 8
4 × 3 = 12
4 × 4 = 16
4 × 5 = 20

Eureka Math Grade 3 Module 7 Lesson3 Problem Set Answer Key

Use the RDW process to solve the problems below. Use a letter to represent the unknown in each problem. When you are finished, share your solutions with a partner. Discuss and compare your strategies with your partner’s strategies.

Question 1.
Monica measures 91 milliliters of water into 9 tiny beakers. She measures an equal amount of water into the first 8 beakers. She pours the remaining water into the ninth beaker. It measures 19 milliliters. How many milliliters of water are in each of the first 8 beakers?

Answer:
Amount of water Monica pours into each of the first 8 beakers = 9 milliliters.

Explanation:
Amount of water Monica measures into 9 tiny beakers = 91 milliliters
Amount of water in ninth beaker = 19 milliliters
Amount of water Monica measures into 8 tiny beakers = Amount of water Monica measures into 9 tiny beakers – Amount of water in ninth beaker
= 91 – 19
= 72 milliliters.
Amount of water Monica pours into each of the first 8 beakers = Amount of water Monica measures into 8 tiny beakers  ÷ 8
= 72 ÷ 8
= 9 milliliters.

Question 2.
Matthew and his dad put up 8 six-foot lengths of fence on Monday and 9 six-foot lengths on Tuesday. What is the total length of the fence?

Answer:
Total Length of the six-foot fence Matthew and his dad put up on Monday and Tuesday = 17.

Explanation:
Length of the six-foot fence Matthew and his dad put up on Monday = 8
Length of the six-foot fence Matthew and his dad put up on Tuesday = 9
Total Length of the six-foot fence Matthew and his dad put up on Monday and Tuesday = Length of the six-foot fence Matthew and his dad put up on Monday + Length of the six-foot fence Matthew and his dad put up on Tuesday
= 8 + 9
= 17.

Question 3.
The total weight of Laura’s new pencils is 112 grams. One pencil rolls off the scale. Now the scale reads 105 grams. What is the total weight of 7 new pencils?

Answer:
Total weight of 7 new pencils = 98 grams.

Explanation:
Total weight of Laura’s new pencils = 112 grams
Weight of the pencils scale reads now = 105 grams
Weight of One pencil rolls off the scale = Total weight of Laura’s new pencils – Weight of the pencils scale reads now
= 112 – 105
= 7 grams.
Total weight of 7 new pencils = Weight of the pencils scale reads now – Weight of One pencil rolls off the scale
= 105 – 7
= 98 grams.

Question 4.
Mrs. Ford’s math class starts at 8:15. They do 3 fluency activities that each last 4 minutes. Just when they finish all of the fluency activities, the fire alarm goes off. When they return to the room after the drill, it is 8:46. How many minutes did the fire drill last?

Answer:
Time taken for the fire drill last = 19 minutes.

Explanation:
Time of the Mrs. Ford’s math class starts = 8:15.
Time of the Mrs. Ford’s returning to the room after the drill = 8:46
They do 3 fluency activities that each last 4 minutes.
=> Time taken for 3 fluency activities = 4 × 3 = 12 minutes.
Time taken for the Mrs. Ford’s math class to end = Time of the Mrs. Ford’s math class starts + Time taken for 3 fluency activities
= 8:15 + 0:12
= 8:27.
Time taken for the fire drill last = Time of the Mrs. Ford’s returning to the room after the drill  – Time taken for the Mrs. Ford’s math class to end
= 8:46 -8:27
= 19 minutes.

Question 5.
On Saturday, the baker bought a total of 150 pounds of flour in five-pound bags. By Tuesday, he had 115 pounds of flour left. How many five-pound bags of flour did the baker use?

Answer:
Amount of five-pound bags of flour used by the baker = 35 pounds.

Explanation:
Amount of total flour bought on Saturday in five-pound bags = 150 pounds.
Amount of flour left by Tuesday = 115 pounds
Amount of five-pound bags of flour used by the baker = Amount of total flour bought on Saturday in five-pound bags  – Amount of flour left by Tuesday
= 150 – 115
= 35 pounds.

Question 6.
Fred cut an 84-centimeter rope into 2 parts and gave his sister 1 part. Fred’s part is 56 centimeters long. His sister cut her rope into 4 equal pieces. How long is 1 of his sister’s pieces of rope?

Answer:
Length of each piece of rope Fred’s sister makes = 7 centimeters.

Explanation:
Total length of the Fred rope had= 84 centimeter
Length of Fred’s rope part= 56 centimeters
Length of Fred’s sister part rope = Total length of the Fred rope had – Length of Fred’s rope part
= 84 – 56
= 28.
His sister cut her rope into 4 equal pieces.
=> Number of pieces of rope Fred’s sister makes = 4
=> Length of each piece of rope Fred’s sister makes = Length of Fred’s sister part rope  ÷ Number of pieces of rope Fred’s sister makes
= 28 ÷ 4
= 7 centimeters.

Eureka Math Grade 3 Module 7 Lesson 3 Exit Ticket Answer Key

Use the RDW process to solve the problem below. Use a letter to represent the unknown.
Twenty packs of fruit snacks come in a box. Each pack weighs 6 ounces. Students eat some. There are 48 ounces of fruit snacks left in the box. How many ounces of fruit snacks did the students eat?

Answer:
Weight of packs of fruit snacks students ate = 72 ounces.

Explanation:
Weight of each pack = 6 ounces.
Number of fruit snacks come in a box = 20
Weight of 20 pack of fruit snacks = 20 × 6 = 120 ounces.
Weight of packs of fruit snacks left over in the box = 48 ounces
Weight of packs of fruit snacks students ate = Weight of 20 pack of fruit snacks + Weight of packs of fruit snacks left over in the box
= 120 – 48
= 72 ounces.

Eureka Math Grade 3 Module 7 Lesson 3 Homework Answer Key

Use the RDW process to solve the problems below. Use a letter to represent the unknown in each problem.
Question 1.
Jerry pours 86 milliliters of water into 8 tiny beakers. He measures an equal amount of water into the first 7 beakers. He pours the remaining water into the eighth beaker. It measures 16 milliliters. How many milliliters of water are in each of the first 7 beakers?

Answer:
Amount of water he pours equally into the each first seven beakers = 10 milliliters.

Explanation:
Amount of water Jerry pours into 8 tiny beakers = 86 milliliters
Amount of water he pours into the eighth beaker = 16 milliliters
Amount of water he pours  into the first seven beakers = Amount of water Jerry pours into 8 tiny beakers  – Amount of water he pours into the eighth beaker
= 86 – 16
= 70 milliliters.
Number of first beakers = 7
Amount of water he pours equally into the each first seven beakers = Amount of water he pours  into the first seven beakers  ÷ Number of beakers
= 70 ÷ 7
= 10 milliliters.

Question 2.
Mr. Chavez’s third graders go to gym class at 11:15. Students rotate through three activities for 8 minutes each. Lunch begins at 12:00. How many minutes are there between the end of gym activities and the beginning of lunch?

Answer:
Time taken between the end of gym activities and the beginning of lunch = 21 minutes.

Explanation:
Time of Mr. Chavez’s third graders go to gym class = 11:15
Time of they Lunch begins = 12:00
Students rotate through three activities for 8 minutes each.
=> Time taken for three activities = 8 × 3 = 24 minutes.
Time totally taken for the gym activities = Time of Mr. Chavez’s third graders go to gym class + Time taken for three activities
= 11:15 + 24
= 11:39.
Time taken between the end of gym activities and the beginning of lunch =  Time of they Lunch begins  – Time totally taken for the gym activities
=12:00 – 11.39
= 21 minutes.

Question 3.
A box contains 100 pens. In each box there are 38 black pens and 42 blue pens. The rest are green pens. Mr. Cane buys 6 boxes of pens. How many green pens does he have in total?

Answer:
Number of Green pens Mr. Cane  has = 120.

Explanation:
Number of pens a box contains = 100
Number of Black pens present in each box = 38
Number of Blue pens present in each box = 42
Number of Green pens present in each box = Number of pens a box contains  – ( Number of Black pens present in each + Number of Blue pens present in each box )
= 100 – ( 38 + 42)
= 100 – 80
= 20.
Number of boxes of pens Mr. Cane buys = 6
Number of Green pens Mr. Cane  has = Number of Green pens present in each box  × Number of boxes of pens Mr. Cane buys
= 20 × 6
= 120.

Question 4.
Greg has $56. Tom has $17 more than Greg. Jason has $8 less than Tom.
a. How much money does Jason have?
b. How much money do the 3 boys have in total?

Answer:
a. Amount of money Jason has = $65.
b. Total amount of money 3 boys have =  $194.

Explanation:
Amount of money Greg has = $56
Tom has $17 more than Greg.
=> Amount of money Tom has = Amount of money Greg has + $17
= $56 + $17
= $73.
a)    Jason has $8 less than Tom.
=> Amount of money Jason has = Amount of money Tom has  – $8
= $73 – $8
= $65.

b)    Amount of money Greg has = $56
Amount of money Tom has = $73
Amount of money Jason has = $65.
Total amount of money 3 boys have = Amount of money Greg has + Amount of money Tom has + Amount of money Jason has
= $56 + $73 + $65
= $129 + $ 65
= $194.

Question 5.
Laura cuts 64 inches of ribbon into two parts and gives her mom one part. Laura’s part is 28 inches long. Her mom cuts her ribbon into 6 equal pieces. How long is one of her mom’s pieces of ribbon?

Answer:
Length of the each pieces her moms cut her ribbon part  = 6 inches.

Explanation:
Total Length of ribbon Laura has = 64 inches
Length of Ribbon Laura’s part = 28 inches
Length of Ribbon Laura’s mom’s part = Total Length of ribbon Laura has – Length of Ribbon Laura’s part
= 64 – 28
= 36
Number of equal pieces her moms cut her ribbon part = 6
Length of the each pieces her moms cut her ribbon part  = Length of Ribbon Laura’s mom’s part ÷ Number of equal pieces her moms cut her ribbon part
= 36 ÷ 6
= 6 inches.

Engage NY Eureka Math 3rd Grade Module 7 Lesson 4 Answer Key

Eureka Math Grade 3 Module 7 Answer Key

Eureka Math Grade 3 Module 7 Lesson 4 Pattern Sheet Answer Key

Multiply.

multiply by 4 (6─10)

Answer:

Explanation:
4 × 1 = 4
4 × 2 = 8
4 × 3 = 12
4 × 4 = 16
4 × 5 = 20
4 × 6 = 24
4 × 7 = 28
4 × 8 = 32
4 × 9 = 36
4 × 10 = 40.

Eureka Math Grade 3 Module 7 Lesson 4 Problem Set Answer Key

Question 1.
Cut out all the polygons (A–L) in the Template. Then, use the polygons to complete the following chart.

Answer:

Explanation:

Question 2.
Write the letters of the polygons that are quadrilaterals. Explain how you know these polygons are quadrilaterals.
Answer:
ABCD are the letters of the polygons that are quadrilaterals because they are straight and are four-sided figure.

Explanation:
Quadrilateral means a four-sided figure.
A polygon is any shape made up of straight lines that can be drawn on a flat surface, like a piece of paper.

Question 3.
Sketch a polygon below from the group that has 2 sets of parallel sides. Trace 1 pair of parallel sides red. Trace the other pair of parallel sides blue. What makes parallel sides different from sides that are not parallel?
Answer:

Explanation:
Parallel sides are different from sides that are not parallel because the parallel sides will never meet each other whereas sides meet each other.

Question 4.
Draw a diagonal line from one corner to the opposite corner of each polygon you drew in the chart using a straight edge. What new polygon(s) did you make by drawing the diagonal lines?
Answer:

Explanation:
By drawing the diagonal lines, to the polygons in the chart it is observed that the figures are divided into two-semi part polygons.

Eureka Math Grade 3 Module 7 Lesson 4 Exit Ticket Answer Key

List as many attributes as you can to describe each polygon below.
Question 1.

Answer:
Attributes of the given polygon are as below:
Square.
Two sets parallel sides.
Polygon with all equal sides.
4 right angles.
Rhombus.

Question 2.

Answer:
Attributes of the given polygon are as below:
1 sets of parallel sides.
Quadrilateral.
4 Angles.
2 sets of sides.

Eureka Math Grade 3 Module 7 Lesson 4 Homework Answer Key

Question 1.
Complete the chart by answering true or false.


Answer:

Question 2.
a. Each quadrilateral below has at least 1 set of parallel sides. Trace each set of parallel sides with a colored pencil.

Answer:

b. Using a straightedge, sketch a different quadrilateral with at least 1 set of parallel sides.
Answer:

Explanation:
Answers may differ.
WXYZ is a polygon with four sides.
WXYZ is a Quadrilateral.

Engage NY Eureka Math 3rd Grade Module 7 Lesson 5 Answer Key

Eureka Math Grade 3 Module 7 Answer Key

Eureka Math Grade 3 Module 7 Lesson 5 Pattern Sheet Answer Key

Multiply.

multiply by 5 (1─5)
Answer:

Explanation:
5  × 1 = 5
5  ×  2 = 10
5  × 4 = 20
5  ×  5 = 25.

Eureka Math Grade 3 Module 7 Lesson 5 Problem Set Answer Key

Question 1.
Cut out all the polygons (M–X) in the Template. Then, use the polygons to complete the following chart.


Answer:

Question 2.
Compare Polygon M and Polygon X. What is the same? What is different?
Answer:
Polygon M and Polygon X are same as they have same number of sides and are different has they does not same angles.

Explanation:

Question 3.
Jenny says, “Polygon N, Polygon R, and Polygon S are all regular quadrilaterals!” Is she correct? Why or why not?
Answer:
No, Jenny is not correct because polygon N, polygon R nor polygon S are not having four equal sides nor 4 equal angles to be said as regular quadrilaterals.

Explanation:

Question 4.
“I have six equal sides and six equal angles. I have three sets of parallel lines. I have no right angles.”
a. Write the letter and the name of the polygon described above.
b. Estimate to draw the same type of polygon as in part (a), but with no equal sides.
Answer:
a) ‘I have six equal sides and six equal angles. I have three sets of parallel lines. I have no right angles.”
Polygon U is said to be a regular hexagon.

Explanation:

b)

Explanation:
In part a, the figure is having six sides of equal length of sides.
The figure drawn, is having six sides of different lengths of sides.

Eureka Math Grade 3 Module 7 Lesson 5 Exit Ticket Answer Key

Jonah draws the polygon below. Use your ruler and right angle tool to measure his polygon. Then, answer the questions below.

Question 1.
Is Jonah’s polygon a regular polygon? Explain how you know.
Answer:
No, its not a regular polygon because does not have all sides equal nor the angles are same.

Explanation:
A polygon having equal sides and equal angles is called as a regular polygon.

Question 2.
How many right angles does his polygon have? Circle the right angles on his polygon.
Answer:
The polygon given in the figure has 2 right angles.

Explanation:

Question 3.
How many sets of parallel lines does his polygon have?
Answer:
The polygon given in the figure has 1 set of parallel lines.

Explanation:

Question 4.
What is the name of Jonah’s polygon?
Answer:
The name of Jonah’s polygon is Pentagon.

Explanation:
Jonah’s figure is having five sides. A figure with five sides is called as Pentagon.

Eureka Math Grade 3 Module 7 Lesson 5 Homework Answer Key

Question 1.
Match the polygons with their appropriate clouds. A polygon can match to more than 1 cloud.


Answer:

Explanation:
Every figure has its own attributes, which are different.
Every polygon is matched according to its attributes.

Question 2.
The two polygons below are regular polygons. How are these polygons the same? How are they different?

Answer:
They are same because each polygon drawn is made up of same sides.
They are different because they have different angles.

Explanation:

Given figures are Hexagon and Triangle.

Question 4.
Lucia drew the polygons below. Are any of the polygons she drew regular polygons? Explain how you know.

Answer:
Figure Pentagon which Lucia drawn is regular polygon because a regular polygon is a polygon that is equiangular (all angles are equal in measure) and equilateral (all sides have the same length).

Explanation:
Figures given are different in terms of sides and angles.
First and Second figures drawn are having different lengths of sides.
Third figure drawn is having same sides of equal lengths. It is said as regular polygon.

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