Eureka Math

Engage NY Eureka Math 3rd Grade Module 7 Lesson 2 Answer Key

Eureka Math Grade 3 Module 7 Answer Key

Eureka Math Grade 3 Module 7 Lesson 2 Pattern Sheet Answer Key

Multiply.

multiply by 3 (6–10)
Answer:

Explanation:
Explanation:
3 × 1 = 3
3 × 2 = 6
3 × 3 = 9
3 × 4 = 12
3 × 5 = 15
3 × 6 = 18
3 × 7 = 21
3 × 8 = 24
3 × 9 = 27
3 × 10 = 30.

Eureka Math Grade 3 Module 7 Lesson 2 Problem Set Answer Key

Use the RDW process to solve. Use a letter to represent the unknown in each problem.
Question 1.
Leanne needs 120 tiles for an art project. She has 56 tiles. If tiles are sold in boxes of 8, how many more boxes of tiles does Leanne need to buy?
Answer:
Number of boxes of 8 tiles needed to buy more = 8.

Explanation:
Number of tiles needed for an project = 120
Number of tiles Leanne has = 56
Number of more tiles needed to buy by Leanne = Number of tiles needed for an project – Number of tiles Leanne has
= 120 – 56
= 64.
If tiles are sold in boxes of 8.
=>Number of tiles a box consist = 8
Number of boxes of 8 tiles needed to buy more = Number of more tiles needed to buy by Leanne ÷ Number of tiles a box consist
= 64 ÷ 8
= 8.

Question 2.
Gwen pours 236 milliliters of water into Ravi’s beaker. Henry pours 189 milliliters of water into Ravi’s beaker. Ravi’s beaker now contains 800 milliliters of water. How much water was in Ravi’s beaker to begin with?

Answer:
Total number of milliliters of water was in Ravi’s beaker to begin with = 425.

Explanation:
Number of  milliliters of water Gwen pours  into Ravi’s beaker = 236
Number of  milliliters of water Henry pours  into Ravi’s beaker = 189
Ravi’s beaker now contains 800 milliliters of water.
Total number of milliliters of water was in Ravi’s beaker to begin with = Number of  milliliters of water Gwen pours  into Ravi’s beaker + Number of  milliliters of water Henry pours  into Ravi’s beaker
= 236 + 189
= 425.

Question 3.
Maude hung 3 pictures on her wall. Each picture measures 8 inches by 10 inches. What is the total area of the wall covered by the pictures?
Answer:
Total area of the wall covered by the pictures = 240  inches.

Explanation:
Maude hung 3 pictures on her wall.
=> Number of pictures hung on the wall = 3
Length of the each picture = 10 inches
Width of the each picture = 8 inches
Area of the each picture = Length of the each picture  × Width of the each picture
= 10 × 8
= 80 inches.
Total area of the wall covered by the pictures = Area of the each picture ×Number of pictures hung on the wall
= 80 × 3
= 240  inches.

Question 4.
Kami scored a total of 21 points during her basketball game. She made 6 two-point shots, and the rest were three-point shots. How many three-point shots did Kami make?

Answer:
Number of three-point shots she made = 15.

Explanation:
Total score point of Kami during her basketball game = 21
Number of two-point shots she made = 6
Number of three-point shots she made = Total score point of Kami during her basketball game – Number of two-point shots she made
= 21 – 6
= 15.

Question 5.
An orange weighs 198 grams. A kiwi weighs 85 grams less than the orange. What is the total weight of the fruit?
Answer:
Total weight of the fruits = 311 grams.

Explanation:
Weight of Orange fruit = 198 grams
A kiwi weighs 85 grams less than the orange.
=> Weight of Kiwi fruit =  Weight of Orange fruit  – 85
=> Weight of Kiwi fruit = 198 – 85
=> Weight of Kiwi fruit =  113 grams
Total weight of the fruits = Weight of Orange fruit + Weight of Kiwi fruit
=  198 + 113
= 311 grams.

Question 6.
The total amount of rain that fell in New York City in two years was 282 centimeters. In the first year, 185 centimeters of rain fell. How many more centimeters of rain fell in the first year than in the second year?

Answer:
Amount of Rain fell in the first year than in the second year = 88 centimeters.

Explanation:
Total amount of rain that fell in New York City in two years = 282 centimeters
Amount of rain fell in the First year = 185 centimeters
Amount of rain fell in the Second year = Total amount of rain that fell in New York City in two years – Amount of rain fell in the First year
= 282 – 185
= 97 centimeters.
Amount of Rain fell in the first year than in the second year = Amount of rain fell in the First year – Amount of rain fell in the Second year
= 185 – 97
= 88 centimeters.

Eureka Math Grade 3 Module 7 Lesson 2 Exit Ticket Answer Key

Use the RDW process to solve the problem below. Use a letter to represent the unknown.
Jaden’s bottle contains 750 milliliters of water. He drinks 520 milliliters at practice and then another 190 milliliters on his way home. How many milliliters of water are left in Jaden’s bottle when he gets home?

Answer:
Amount of water left in Jaden’s bottle when he gets home = 40 milliliters.

Explanation:
Total amount of water Jaden’s bottle contains = 750 milliliters
Amount of water he drinks at practice = 520 milliliters
Amount of water he drinks on his way home = 190 milliliters
Amount of water left in Jaden’s bottle when he gets home = Total amount of water Jaden’s bottle contains  – ( Amount of water he drinks at practice  + Amount of water he drinks on his way home)
= 750 – ( 520 + 190)
= 750 – 710
= 40 milliliters.

Eureka Math Grade 3 Module 7 Lesson 2 Homework Answer Key

Use the RDW process to solve. Use a letter to represent the unknown in each problem.
Question 1.
A box containing 3 small bags of flour weighs 950 grams. Each bag of flour weighs 300 grams. How much does the empty box weigh?
Answer:
Weight of the empty box = 50 grams.

Explanation:
Weight of a box containing 3 small bags of flour weighs = 950 grams
Weight of each bag of flour = 300 grams
Weight of 3 bag of flour = 300 × 3 = 900 grams
Weight of the empty box = Weight of a box containing 3 small bags of flour weighs – Weight of 3 bag of flour
= 950 – 900
= 50 grams.

Question 2.
Mr. Cullen needs 91 carpet squares. He has 49 carpet squares. If the squares are sold in boxes of 6, how many more boxes of carpet squares does Mr. Cullen need to buy?
Answer:
Number of squares boxes of 6  he needs to buy more = 7.

Explanation:
Number of carpet square Mr. Cullen needs = 91
Number of carpet square he has = 49
Number of carpet square he needs more = Number of carpet square Mr. Cullen needs – Number of carpet square he has
= 91 – 49
= 42.
Number of squares in the box = 6
Number of squares boxes of 6  he needs to buy more = Number of carpet square he needs more ÷ Number of squares in the box
= 42 ÷ 6
= 7.

Question 3.
Erica makes a banner using 4 sheets of paper. Each paper measures 9 inches by 10 inches. What is the total area of Erica’s banner?
Answer:
Total area of Erica’s banner = 360 inches.

Explanation:
Number of sheets of paper Erica makes a banner = 4
Length of the each paper = 10 inches
Width of the each paper = 9 inches
Area of the each paper = Length of the each paper × Width of the each paper
= 10 × 9
= 90 inches.
Total area of Erica’s banner = Area of the each paper  × Number of sheets of paper Erica makes a banner
= 90 × 4
= 360 inches.

Question 4.
Monica scored 32 points for her team at the Science Bowl. She got 5 four-point questions correct, and the rest of her points came from answering three-point questions. How many three-point questions did she get correct?
Answer:
Number of points scored by her for answering three-point questions correct = 27.

Explanation:
Number of points scored by Monica  for her team at the Science Bowl = 32
Number of points scored by her for four-point questions correct = 5
Number of points scored by her for answering three-point questions correct = Number of points scored by Monica  for her team at the Science Bowl  – Number of points scored by her for four-point questions correct
= 32 – 5
= 27.

Question 5.
Kim’s black kitten weighs 175 grams. Her gray kitten weighs 43 grams less than the black kitten. What is the total weight of the two kittens?
Answer:
Total weight of Kim’s black kitten and gray kitten = 307 grams.

Explanation:
Weight of the Kim’s black kitten = 175 grams
Her gray kitten weighs 43 grams less than the black kitten.
=> Weight of the Kim’s gray kitten = Weight of the Kim’s black kitten – 43
= 175 – 43
= 132 grams.
Total weight of Kim’s black kitten and gray kitten = Weight of the Kim’s black kitten + Weight of the Kim’s gray kitten
= 175 + 132
= 307 grams.

Question 6.
Cassias and Javier’s combined height is 267 centimeters. Cassias is 128 centimeters tall. How much taller is Javier than Cassias?
Answer:
Height of Javier’s more than Cassias height = 11 centimeters.

Explanation:
Height of Cassias and Javier’s combined = 267 centimeters.
Height of Cassias = 128 centimeters
Height of Javier = Height of Cassias and Javier’s combined – Height of Cassias
= 267 – 128
= 139.
Height of Javier’s more than Cassias height = Height of Javier  – Height of Cassias
= 139 – 128
= 11 centimeters.

 

Engage NY Eureka Math 3rd Grade Module 7 Lesson 3 Answer Key

Eureka Math Grade 3 Module 7 Answer Key

Eureka Math Grade 3 Module 7 Lesson 3 Pattern Sheet Answer Key

Multiply.

multiply by 4 (1–5)

Answer:

Explanation:
4 × 1 = 4
4 × 2 = 8
4 × 3 = 12
4 × 4 = 16
4 × 5 = 20

Eureka Math Grade 3 Module 7 Lesson3 Problem Set Answer Key

Use the RDW process to solve the problems below. Use a letter to represent the unknown in each problem. When you are finished, share your solutions with a partner. Discuss and compare your strategies with your partner’s strategies.

Question 1.
Monica measures 91 milliliters of water into 9 tiny beakers. She measures an equal amount of water into the first 8 beakers. She pours the remaining water into the ninth beaker. It measures 19 milliliters. How many milliliters of water are in each of the first 8 beakers?

Answer:
Amount of water Monica pours into each of the first 8 beakers = 9 milliliters.

Explanation:
Amount of water Monica measures into 9 tiny beakers = 91 milliliters
Amount of water in ninth beaker = 19 milliliters
Amount of water Monica measures into 8 tiny beakers = Amount of water Monica measures into 9 tiny beakers – Amount of water in ninth beaker
= 91 – 19
= 72 milliliters.
Amount of water Monica pours into each of the first 8 beakers = Amount of water Monica measures into 8 tiny beakers  ÷ 8
= 72 ÷ 8
= 9 milliliters.

 

Question 2.
Matthew and his dad put up 8 six-foot lengths of fence on Monday and 9 six-foot lengths on Tuesday. What is the total length of the fence?

Answer:
Total Length of the six-foot fence Matthew and his dad put up on Monday and Tuesday = 17.

Explanation:
Length of the six-foot fence Matthew and his dad put up on Monday = 8
Length of the six-foot fence Matthew and his dad put up on Tuesday = 9
Total Length of the six-foot fence Matthew and his dad put up on Monday and Tuesday = Length of the six-foot fence Matthew and his dad put up on Monday + Length of the six-foot fence Matthew and his dad put up on Tuesday
= 8 + 9
= 17.

Question 3.
The total weight of Laura’s new pencils is 112 grams. One pencil rolls off the scale. Now the scale reads 105 grams. What is the total weight of 7 new pencils?

Answer:
Total weight of 7 new pencils = 98 grams.

Explanation:
Total weight of Laura’s new pencils = 112 grams
Weight of the pencils scale reads now = 105 grams
Weight of One pencil rolls off the scale = Total weight of Laura’s new pencils – Weight of the pencils scale reads now
= 112 – 105
= 7 grams.
Total weight of 7 new pencils = Weight of the pencils scale reads now – Weight of One pencil rolls off the scale
= 105 – 7
= 98 grams.

Question 4.
Mrs. Ford’s math class starts at 8:15. They do 3 fluency activities that each last 4 minutes. Just when they finish all of the fluency activities, the fire alarm goes off. When they return to the room after the drill, it is 8:46. How many minutes did the fire drill last?

Answer:
Time taken for the fire drill last = 19 minutes.

Explanation:
Time of the Mrs. Ford’s math class starts = 8:15.
Time of the Mrs. Ford’s returning to the room after the drill = 8:46
They do 3 fluency activities that each last 4 minutes.
=> Time taken for 3 fluency activities = 4 × 3 = 12 minutes.
Time taken for the Mrs. Ford’s math class to end = Time of the Mrs. Ford’s math class starts + Time taken for 3 fluency activities
= 8:15 + 0:12
= 8:27.
Time taken for the fire drill last = Time of the Mrs. Ford’s returning to the room after the drill  – Time taken for the Mrs. Ford’s math class to end
= 8:46 -8:27
= 19 minutes.

Question 5.
On Saturday, the baker bought a total of 150 pounds of flour in five-pound bags. By Tuesday, he had 115 pounds of flour left. How many five-pound bags of flour did the baker use?

Answer:
Amount of five-pound bags of flour used by the baker = 35 pounds.

Explanation:
Amount of total flour bought on Saturday in five-pound bags = 150 pounds.
Amount of flour left by Tuesday = 115 pounds
Amount of five-pound bags of flour used by the baker = Amount of total flour bought on Saturday in five-pound bags  – Amount of flour left by Tuesday
= 150 – 115
= 35 pounds.

 

Question 6.
Fred cut an 84-centimeter rope into 2 parts and gave his sister 1 part. Fred’s part is 56 centimeters long. His sister cut her rope into 4 equal pieces. How long is 1 of his sister’s pieces of rope?

Answer:
Length of each piece of rope Fred’s sister makes = 7 centimeters.

Explanation:
Total length of the Fred rope had= 84 centimeter
Length of Fred’s rope part= 56 centimeters
Length of Fred’s sister part rope = Total length of the Fred rope had – Length of Fred’s rope part
= 84 – 56
= 28.
His sister cut her rope into 4 equal pieces.
=> Number of pieces of rope Fred’s sister makes = 4
=> Length of each piece of rope Fred’s sister makes = Length of Fred’s sister part rope  ÷ Number of pieces of rope Fred’s sister makes
= 28 ÷ 4
= 7 centimeters.

Eureka Math Grade 3 Module 7 Lesson 3 Exit Ticket Answer Key

Use the RDW process to solve the problem below. Use a letter to represent the unknown.
Twenty packs of fruit snacks come in a box. Each pack weighs 6 ounces. Students eat some. There are 48 ounces of fruit snacks left in the box. How many ounces of fruit snacks did the students eat?

Answer:
Weight of packs of fruit snacks students ate = 72 ounces.

Explanation:
Weight of each pack = 6 ounces.
Number of fruit snacks come in a box = 20
Weight of 20 pack of fruit snacks = 20 × 6 = 120 ounces.
Weight of packs of fruit snacks left over in the box = 48 ounces
Weight of packs of fruit snacks students ate = Weight of 20 pack of fruit snacks + Weight of packs of fruit snacks left over in the box
= 120 – 48
= 72 ounces.

Eureka Math Grade 3 Module 7 Lesson 3 Homework Answer Key

Use the RDW process to solve the problems below. Use a letter to represent the unknown in each problem.
Question 1.
Jerry pours 86 milliliters of water into 8 tiny beakers. He measures an equal amount of water into the first 7 beakers. He pours the remaining water into the eighth beaker. It measures 16 milliliters. How many milliliters of water are in each of the first 7 beakers?

Answer:
Amount of water he pours equally into the each first seven beakers = 10 milliliters.

Explanation:
Amount of water Jerry pours into 8 tiny beakers = 86 milliliters
Amount of water he pours into the eighth beaker = 16 milliliters
Amount of water he pours  into the first seven beakers = Amount of water Jerry pours into 8 tiny beakers  – Amount of water he pours into the eighth beaker
= 86 – 16
= 70 milliliters.
Number of first beakers = 7
Amount of water he pours equally into the each first seven beakers = Amount of water he pours  into the first seven beakers  ÷ Number of beakers
= 70 ÷ 7
= 10 milliliters.

Question 2.
Mr. Chavez’s third graders go to gym class at 11:15. Students rotate through three activities for 8 minutes each. Lunch begins at 12:00. How many minutes are there between the end of gym activities and the beginning of lunch?

Answer:
Time taken between the end of gym activities and the beginning of lunch = 21 minutes.

Explanation:
Time of Mr. Chavez’s third graders go to gym class = 11:15
Time of they Lunch begins = 12:00
Students rotate through three activities for 8 minutes each.
=> Time taken for three activities = 8 × 3 = 24 minutes.
Time totally taken for the gym activities = Time of Mr. Chavez’s third graders go to gym class + Time taken for three activities
= 11:15 + 24
= 11:39.
Time taken between the end of gym activities and the beginning of lunch =  Time of they Lunch begins  – Time totally taken for the gym activities
=12:00 – 11.39
= 21 minutes.

Question 3.
A box contains 100 pens. In each box there are 38 black pens and 42 blue pens. The rest are green pens. Mr. Cane buys 6 boxes of pens. How many green pens does he have in total?

Answer:
Number of Green pens Mr. Cane  has = 120.

Explanation:
Number of pens a box contains = 100
Number of Black pens present in each box = 38
Number of Blue pens present in each box = 42
Number of Green pens present in each box = Number of pens a box contains  – ( Number of Black pens present in each + Number of Blue pens present in each box )
= 100 – ( 38 + 42)
= 100 – 80
= 20.
Number of boxes of pens Mr. Cane buys = 6
Number of Green pens Mr. Cane  has = Number of Green pens present in each box  × Number of boxes of pens Mr. Cane buys
= 20 × 6
= 120.

Question 4.
Greg has $56. Tom has $17 more than Greg. Jason has $8 less than Tom.
a. How much money does Jason have?
b. How much money do the 3 boys have in total?

Answer:
a. Amount of money Jason has = $65.
b. Total amount of money 3 boys have =  $194.

Explanation:
Amount of money Greg has = $56
Tom has $17 more than Greg.
=> Amount of money Tom has = Amount of money Greg has + $17
= $56 + $17
= $73.
a)    Jason has $8 less than Tom.
=> Amount of money Jason has = Amount of money Tom has  – $8
= $73 – $8
= $65.

b)    Amount of money Greg has = $56
Amount of money Tom has = $73
Amount of money Jason has = $65.
Total amount of money 3 boys have = Amount of money Greg has + Amount of money Tom has + Amount of money Jason has
= $56 + $73 + $65
= $129 + $ 65
= $194.

Question 5.
Laura cuts 64 inches of ribbon into two parts and gives her mom one part. Laura’s part is 28 inches long. Her mom cuts her ribbon into 6 equal pieces. How long is one of her mom’s pieces of ribbon?

Answer:
Length of the each pieces her moms cut her ribbon part  = 6 inches.

Explanation:
Total Length of ribbon Laura has = 64 inches
Length of Ribbon Laura’s part = 28 inches
Length of Ribbon Laura’s mom’s part = Total Length of ribbon Laura has – Length of Ribbon Laura’s part
= 64 – 28
= 36
Number of equal pieces her moms cut her ribbon part = 6
Length of the each pieces her moms cut her ribbon part  = Length of Ribbon Laura’s mom’s part ÷ Number of equal pieces her moms cut her ribbon part
= 36 ÷ 6
= 6 inches.

Engage NY Eureka Math 3rd Grade Module 7 Lesson 4 Answer Key

Eureka Math Grade 3 Module 7 Answer Key

Eureka Math Grade 3 Module 7 Lesson 4 Pattern Sheet Answer Key

Multiply.

multiply by 4 (6─10)

Answer:

Explanation:
4 × 1 = 4
4 × 2 = 8
4 × 3 = 12
4 × 4 = 16
4 × 5 = 20
4 × 6 = 24
4 × 7 = 28
4 × 8 = 32
4 × 9 = 36
4 × 10 = 40.

Eureka Math Grade 3 Module 7 Lesson 4 Problem Set Answer Key

Question 1.
Cut out all the polygons (A–L) in the Template. Then, use the polygons to complete the following chart.

Answer:

Explanation:

Question 2.
Write the letters of the polygons that are quadrilaterals. Explain how you know these polygons are quadrilaterals.
Answer:
ABCD are the letters of the polygons that are quadrilaterals because they are straight and are four-sided figure.

Explanation:
Quadrilateral means a four-sided figure.
A polygon is any shape made up of straight lines that can be drawn on a flat surface, like a piece of paper.

 

Question 3.
Sketch a polygon below from the group that has 2 sets of parallel sides. Trace 1 pair of parallel sides red. Trace the other pair of parallel sides blue. What makes parallel sides different from sides that are not parallel?
Answer:

Explanation:
Parallel sides are different from sides that are not parallel because the parallel sides will never meet each other whereas sides meet each other.

 

Question 4.
Draw a diagonal line from one corner to the opposite corner of each polygon you drew in the chart using a straight edge. What new polygon(s) did you make by drawing the diagonal lines?
Answer:

 

Explanation:
By drawing the diagonal lines, to the polygons in the chart it is observed that the figures are divided into two-semi part polygons.

Eureka Math Grade 3 Module 7 Lesson 4 Exit Ticket Answer Key

List as many attributes as you can to describe each polygon below.
Question 1.

Answer:
Attributes of the given polygon are as below:
Square.
Two sets parallel sides.
Polygon with all equal sides.
4 right angles.
Rhombus.

Question 2.

Answer:
Attributes of the given polygon are as below:
1 sets of parallel sides.
Quadrilateral.
4 Angles.
2 sets of sides.

Eureka Math Grade 3 Module 7 Lesson 4 Homework Answer Key

Question 1.
Complete the chart by answering true or false.


Answer:

 

Question 2.
a. Each quadrilateral below has at least 1 set of parallel sides. Trace each set of parallel sides with a colored pencil.

Answer:

b. Using a straightedge, sketch a different quadrilateral with at least 1 set of parallel sides.
Answer:

Explanation:
Answers may differ.
WXYZ is a polygon with four sides.
WXYZ is a Quadrilateral.

 

Engage NY Eureka Math 3rd Grade Module 7 Lesson 5 Answer Key

Eureka Math Grade 3 Module 7 Answer Key

Eureka Math Grade 3 Module 7 Lesson 5 Pattern Sheet Answer Key

Multiply.

multiply by 5 (1─5)
Answer:

Explanation:
5  × 1 = 5
5  ×  2 = 10
5  × 4 = 20
5  ×  5 = 25.

Eureka Math Grade 3 Module 7 Lesson 5 Problem Set Answer Key

Question 1.
Cut out all the polygons (M–X) in the Template. Then, use the polygons to complete the following chart.


Answer:

 

Question 2.
Compare Polygon M and Polygon X. What is the same? What is different?
Answer:
Polygon M and Polygon X are same as they have same number of sides and are different has they does not same angles.

Explanation:

 

Question 3.
Jenny says, “Polygon N, Polygon R, and Polygon S are all regular quadrilaterals!” Is she correct? Why or why not?
Answer:
No, Jenny is not correct because polygon N, polygon R nor polygon S are not having four equal sides nor 4 equal angles to be said as regular quadrilaterals.

Explanation:

 

Question 4.
“I have six equal sides and six equal angles. I have three sets of parallel lines. I have no right angles.”
a. Write the letter and the name of the polygon described above.
b. Estimate to draw the same type of polygon as in part (a), but with no equal sides.
Answer:
a) ‘I have six equal sides and six equal angles. I have three sets of parallel lines. I have no right angles.”
Polygon U is said to be a regular hexagon.

Explanation:

b)

Explanation:
In part a, the figure is having six sides of equal length of sides.
The figure drawn, is having six sides of different lengths of sides.

 

Eureka Math Grade 3 Module 7 Lesson 5 Exit Ticket Answer Key

Jonah draws the polygon below. Use your ruler and right angle tool to measure his polygon. Then, answer the questions below.

Question 1.
Is Jonah’s polygon a regular polygon? Explain how you know.
Answer:
No, its not a regular polygon because does not have all sides equal nor the angles are same.

Explanation:
A polygon having equal sides and equal angles is called as a regular polygon.

 

Question 2.
How many right angles does his polygon have? Circle the right angles on his polygon.
Answer:
The polygon given in the figure has 2 right angles.

Explanation:

 

Question 3.
How many sets of parallel lines does his polygon have?
Answer:
The polygon given in the figure has 1 set of parallel lines.

Explanation:

Question 4.
What is the name of Jonah’s polygon?
Answer:
The name of Jonah’s polygon is Pentagon.

Explanation:
Jonah’s figure is having five sides. A figure with five sides is called as Pentagon.

Eureka Math Grade 3 Module 7 Lesson 5 Homework Answer Key

Question 1.
Match the polygons with their appropriate clouds. A polygon can match to more than 1 cloud.


Answer:

Explanation:
Every figure has its own attributes, which are different.
Every polygon is matched according to its attributes.

 

Question 2.
The two polygons below are regular polygons. How are these polygons the same? How are they different?

Answer:
They are same because each polygon drawn is made up of same sides.
They are different because they have different angles.

Explanation:

Given figures are Hexagon and Triangle.

 

Question 4.
Lucia drew the polygons below. Are any of the polygons she drew regular polygons? Explain how you know.

Answer:
Figure Pentagon which Lucia drawn is regular polygon because a regular polygon is a polygon that is equiangular (all angles are equal in measure) and equilateral (all sides have the same length).

Explanation:
Figures given are different in terms of sides and angles.
First and Second figures drawn are having different lengths of sides.
Third figure drawn is having same sides of equal lengths. It is said as regular polygon.

 

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