Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations

Big Ideas Math Answers Grade 8 Chapter 4

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Big Ideas Math Book 8th Grade Answer Key Chapter 4 Graphing and Writing Linear Equations

Make the most out of the handy resources available for Big Ideas Math Ch 4 Graphing and Writing Linear Equations and stand out from the rest of the crowd. BIM Book 8th Grade Chapter 4 Solutions include questions belonging to Lessons 4.1 to 4.7, Cumulative Practice, Assessment Tests, Review Tests, etc. Big Ideas Math 8th Grade Chapter 4 Solution Key is given by subject experts after extensive research. Access the quick links over here during your preparation and get the assistance needed at the comfort of your home.

Performance Task

Lesson: 1 Graphing Linear Equations

Lesson: 2 Slope of a Line

Lesson: 3 Graphing Proportional Relationships

Lesson: 4 Graphing Linear Equations in Slope-Intercept Form

Lesson: 5 Graphing Linear Equations in Standard Form

Lesson: 6 Writing Equations in Slope-Intercept Form

Lesson: 7 Writing Equations in Point-Slope Form

Chapter: 4 – Graphing and Writing Linear Equations

Graphing and Writing Linear Equations STEAM Video/Performance Task

STEAM Video

“Hurricane
A hurricane is a storm with violent winds. How can you prepare your home for a hurricane?
Watch the STEAM Video “Hurricane!” Then answer the following questions.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 1
1. Robert says that the closer you are to the eye of a hurricane, the stronger the winds become. The wind speed on an island is 50 miles per hour when the eye of a hurricane is 140 miles away.
a. Describe the wind speed on the island when the eye of the hurricane is 100 miles away.
b. Describe the distance of the island from the eye of the hurricane when the wind speed on the island is 25 miles per hour.
c. Sketch a line that could represent the wind speed y (in miles per hour) on the island when the eye of x the hurricane is miles away from the island. Wind speed
2. A storm dissipates as it travels over land. What does this mean?

Performance Task

Anatomy of a Hurricane
After completing this chapter, you will be able to use the concepts you learned to answer the questions in the STEAM Video Performance Task. You will be given information about the atmospheric pressure inside a hurricane.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 2
You will be asked to use a model to find the strength of a hurricane after x hours of monitoring. Why is it helpful to predict how strong the winds of a hurricane will become?

Graphing and Writing Linear Equations Getting Ready for Chapter 4

Chapter Exploration
1. Work with a partner.
a. Use the equation y = \(\frac{1}{2}\)x + 1 to complete the table. (Choose any two x-values and find the y-values.)
b. Write the two ordered pairs given by the table. These are called solutions of the equation.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 3.1
c. PRECISION Plot the two solutions. Draw a line exactly through the points.
d. Find a different point on the line. Check that this point is a solution of the equation y = \(\frac{1}{2}\)x + 1.
e. LOGIC Do you think it is true that any point on the line is a solution of the equation y = \(\frac{1}{2}\)x + 1? Explain.
f. Choose five additional x-values for the table below. (Choose both positive and negative x-values.) Plot the five corresponding solutions. Does each point lie on the line?
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 3
g. LOGIC Do you think it is true that any solution of the equation y = \(\frac{1}{2}\)x + 1 is a point on the line? Explain.
h. Why do you think y = ax + b is called a linear equation?

Vocabulary
The following vocabulary terms are defined in this chapter. Think about what each term might mean and record your thoughts.
linear equation
slope
y-intercept
solution of a linear equation
x-intercept

Lesson 4.1 Graphing Linear Equations

EXPLORATION 1

Creating Graphs
Work with a partner. It starts snowing at midnight in Town A and Town B. The snow falls at a rate of 1.5 inche sper hour.
a. In Town A, there is no snow on the ground at midnight. How deep is the snow at each hour between midnight and 6 A.M.? Make a graph that represents this situation.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.1 1
b. Repeat part(a) for TownB, which has 4 inches of snow on the ground at midnight.
c. The equations below represent the depth y(in inches) of snow x hours after midnight in Town C and Town D. Graph each equation.
Town C y = 2x + 3
Town D y = 8
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.1 2
d. Use your graphs to compare the snowfall in each town.
Answer:

Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.1 3

Try It

Graph the linear equation.
Question 1.
y = 3x
Answer:
Make to table of values
Replace x with a number and find the value of y
Big ideas math answers grade 8 chapter 4 img_1
Plot the values of x and y obtained above, on the graph
Big ideas math answers grade 8 chapter 4 img_1.1

Draw the line through the points

Big ideas math answers grade 8 chapter 4 img_1.2

Question 2.
y = – 2x – 1
Answer:
Big ideas math answers grade 8 chapter 4 img_2.1
Plot the values of x and y
Big ideas math answers grade 8 chapter 4 img_2.2
Now the line through the points
Big ideas math answers grade 8 chapter 4 img_2.3

Question 3.
y = –\(\frac{1}{2}\)x + 2
Answer:
Big ideas math answers grade 8 chapter 4 img_3.1
Plot the ordered pairs
Big ideas math answers grade 8 chapter 4 img_3.2

Graph the linear equation.
Question 4.
y = 3
Answer:
The graph of y = 3 is a horizontal like passing through (0, 3)
Draw a horizontal line through this point.
Big ideas math answer key grade 8 chapter 4 img_4

Question 5.
y = – 1.5
Answer:
The graph of y = -1.5 is a horizontal line passing through (0, -1.5)
Draw a horizontal line through this point.
Big ideas math answer key grade 8 chapter 4 img_5

Question 6.
x = – 4
Answer:
The graph of x = – 4 is a vertical line passing through (-4, 0)
Draw a vertical line through this point.
BIM Grade 8 Answers Chapter 4 img_6

Question 7.
x = \(\frac{1}{2}\)
Answer:
The graph of x = \(\frac{1}{2}\) is a vertical line passing through (\(\frac{1}{2}\), 0)
Draw a vertical line through this point.
Big Ideas Math 8th Grade Solution Key Chapter 4 img_7

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

GRAPHING A LINEAR EQUATION Graph the linear equation.
Question 8.
y = – x + 1
Answer:
Make of a table of values
Replace x with a number and find the value of y
Big Ideas Math 8th Grade Solution Key Chapter 4 img_8.1
Plot the values of x and y obtained, on the graph,
Big Ideas Math 8th Grade Solution Key Chapter 4 img_8.2

Question 9.
y = 0.8x – 2
Answer:
Replace x with a number and find the value of y
Big Ideas Math 8th Grade Solution Key Chapter 4 img_9.1
Big Ideas Math 8th Grade Solution Key Chapter 4 img_9.2

Question 10.
x = 2.5
Answer:
The graph of x = 2.5 is a vertical line passing through (2.5, 0)
Draw a vertical line through this point.
Big Ideas Math Answers Grade 8 Chapter 4 img_10.1

Question 11.
y = \(\frac{2}{3}\)
Answer:
The graph of y = \(\frac{2}{3}\) is a horizontal line passing through (0, \(\frac{2}{3}\))
Draw a horizontal line through this point.
BIM Grade 8 Answer Key Chapter 4 img_11

Question 12.
WHICH ONE DOESN’T BELONG?
Which equation does not belong with the other three? Explain your reasoning.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.1 4
Answer:
y = x – 2
4x + 3 = y
y = x² + 6
x + 5 = y

Self-Assessment for Problem Solving
Solve each exercise. The rate your understanding of the success criteria in your journal.

Question 13.
A game show contestant earns y dollars for completing a puzzle in x minutes. This situation is represented by the equation y = – 250x + 5000. How long did a contestant who earned $500 take to complete the puzzle? Justify your answer.
Answer:
Given,
A game show contestant earns y dollars for completing a puzzle in x minutes.
This situation is represented by the equation y = – 250x + 5000.
y = -250x + 5000
500 = -250x + 5000
500 – 5000 = -250x + 5000 – 5000
-4500 = -250x
x = 18

Question 14.
The total cost y (in dollars) to join a cheerleading team and attend x competitions is represented by the equation y = 10x + 50.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.1 5
a. Graph the linear equation.

Answer:
Big Ideas Math Answers 8th Grade Chapter 4 img_14

b. You have $75 to spend. How many competitions can you attend?
Answer:
75 ≤ 10x + 50
75 – 50 ≤ 10x
25 ≤ 10x
2.5 ≥ x
By this I can say that I can attend 2 competitions if I have $75 to spend.

Question 15.
The seating capacity for a banquet hall is represented by y = 8x + 56, where x is the number of extra tables you need. How many extra tables do you need to double the original seating capacity?
Answer:
Given,
The seating capacity for a banquet hall is represented by y = 8x + 56, where x is the number of extra tables you need.
y = 8x + 56
2 × 56 = 8x + 56
112 = 8x + 56
8x = 112 – 56
8x = 56
x = 7 tables

Graphing Linear Equations Homework & Practice 4.1

Review & Refresh

Tell whether the triangles are similar. Explain.
Question 1.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.1 6
Answer:
x° + 46° + 95° = 180°
x° + 141° = 180°
x° = 180° – 141°
x° = 39°
Thus the angles of the triangle are 39°, 46°, 95°
y° + 39° + 46° = 180°
y° + 75° = 180°
y° = 180° – 75°
y° = 95°
Three angles of the triangle are 39°, 46°, 95°
The triangles have two pairs of congruent angles.

Question 2.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.1 7
Answer:
x° + 40° + 51° = 180°
x° + 91° = 180°
x° = 180° – 91°
x° = 89°
Three angles of the triangle are 40°, 51°, 89°
y° + 40° + 79° = 180°
y° + 119° = 180°
y° = 180° – 119°
y° = 61°

Describe the translation of the point to its image.
Question 3.
(1, – 4) → (3, 0)
Answer:
A(1, -4) = A'(1 + 2, -4) = (3, -4)
A'(3, 4) = B(3, -4 + 4) = (3, 0)
Translate 2 units right and 4 units up.

Question 4.
(6, 4) → (- 4, – 6)
Answer:
We are given the points
(6, 4) → (- 4, – 6)
A(6, 4) = A'(6 – 10, 4) = (-4, 4)
A'(-4, -4) = B(-4, 4 – 10) = (-4, -6)

Question 5.
(4, – 2) → (- 9, 3)
Answer:
We are given the points
A(4, -2)
B(-9, 3)
A(4, -2) = A'(4 – 13, -2) = (-9, -2)
A'(-9, -2) = B(-9, -2 + 4) = (-9, 3)

Concepts, Skills, & Problem Solving

CREATING GRAPHS Make a graph of the situation. (See Exploration 1, p. 141.)
Question 6.
The equation y = – 2x + 8 represents the amount (in fluid ounces) of dish detergent in a bottle after x days of use.
Answer:
Bigideas math answers grade 8 chapter 4 img_15

Question 7.
The equation y = 15x + 20 represents the cost (in dollars) of a gym membership after x months.
Answer:
Bigideas math answers grade 8 chapter 4 img_16

PRECISION Copy and complete the table with two solutions. Plot the ordered pairs and draw the graph of the linear equation. Use the graph to find a third solution of the equation.
Question 8.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.1 8
Answer:
Bigideas math answers grade 8 chapter 4 img_17
(x, y) = (2, 5)
Bigideas math answers grade 8 chapter 4 img_18

Question 9.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.1 9
Answer:
Bigideas math answers grade 8 chapter 4 img_19
(x, y) = (3, 3)
Bigideas math answers grade 8 chapter 4 img_20

GRAPHING A LINEAR EQUATION Graph the linear equation.
Question 10.
y = – 5x
Answer:
Bigideas math answers grade 8 chapter 4 img_21

Question 11.
y = 9x
Answer:
Bigideas math answers grade 8 chapter 4 img_22

Question 12.
y = 5
Answer:
The graph of y = 5 is a horizontal line passing through (0, 5)
Draw a horizontal line through this point.
Bigideas math answers grade 8 chapter 4 img_23

Question 13.
x = – 6
Answer:
Bigideas math answers grade 8 chapter 4 img_24

Question 14.
y = x – 3
Answer:
Bigideas math answers grade 8 chapter 4 img_25

Question 15.
y = – 7x – 1
Answer:
Bigideas math answers grade 8 chapter 4 img_26

Question 16.
y = – \(\frac{x}{8}\) + 4
Answer:
Bigideas math answers grade 8 chapter 4 img_27

Question 17.
y = 0.75x – 0.5
Answer:
Bigideas math answers grade 8 chapter 4 img_28

Question 18.
y = – \(\frac{2}{3}\)
Answer:
Bigideas math answers grade 8 chapter 4 img_29

Question 19.
y = 6.75
Answer:
Bigideas math answers grade 8 chapter 4 img_30

Question 20.
x = – 0.5
Answer:
The graph of x = -0.5 is a vertical line passing through (-0.5, 0)
Draw a vertical line through this point.
Big Ideas Math Answers Grade 8 Ch 4 img_26

Question 21.
x = \(\frac{1}{4}\)
Answer:
The graph of x = \(\frac{1}{4}\) is a vertical line passing through (\(\frac{1}{4}\), 0)
Draw a vertical line through this point.
Big Ideas Math Answers Grade 8 Ch 4 img_27

Question 22.
YOU BE THE TEACHER
Your friend graphs the equation y = 4. Is your friend correct? Explain your reasoning.
Answer:
Big Ideas Math Answers Grade 8 Ch 4 img_28
No my friend is not correct because the graph for the equation y = 4 is a  horizontal line not a vertical line, and it passes through the point (0, 4) not (4, 0)

Question 23.
MODELING REAL LIFE
The equation y = 20 represents the cost y (in dollars) for sending x text messages in a month. Graph the linear equation. What does the graph tell you about your texting plan?
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.1 10
Answer:
Big Ideas Math Answers Grade 8 Ch 4 img_29

Question 24.
MODELING REAL LIFE
The equation y = 2x + 3 represents the cost y (in dollars) of mailing a package that weighs x pounds.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.1 11
a. Use a graph to estimate how much it costs to mail the package.
b. Use the equation to find exactly how much it costs to mail the package.
Answer:
Given the equation y = 2x + 3
The ordered pairs will be (0, 3), (2,7), (4, 11)
Now plot the ordered pairs
Big Ideas Math Answers Grade 8 Ch 4 img_30
y = 2(1.126) + 3
= 5.252 ≈ 5.25

SOLVING A LINEAR EQUATION Solve for y. Then graph the linear equation.
Question 25.
y – 3x = 1
Answer:
y – 3x = 1
y = 3x + 1
Big Ideas Math Answers Grade 8 Ch 4 img_31
Draw a line through the points
Big Ideas Math Answers Grade 8 Ch 4 img_32

Question 26.
5x + 2y = 4
Answer:
5x + 2y = 4
2y = 4 – 5x
y = – \(\frac{5}{2}\)x + 2
BIM 8th Grade Solution Key Chapter 4 img_33

Question 27.
– \(\frac{1}{3}\)y + 4x = 3
Answer:
– \(\frac{1}{3}\)y + 4x = 3
– \(\frac{1}{3}\)y = 3 – 4x
y = 12x – 9
BIM 8th Grade Solution Key Chapter 4 img_34

Question 28.
x + 0.5y = 1.5
Answer:
x + 0.5y = 1.5
0.5y = -x + 1.5
y = -2x + 3
Big Ideas Math Grade 8 Answers Chapter 4 img_35

Question 29.
MODELING REAL LIFE
The depth y (in inches) of a lake after x years is represented by the equation y = 0.2x + 42. How much does the depth of the lake increase in four years? Use a graph to justify your answer.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.1 12
Answer:
y = 0.2x + 42
Depth of the lake now: y = 0.2(0) + 42 = 42
Depth of the lake after 4 years: y = 0.2(4) + 42 = 42.8
Big Ideas Math Grade 8 Answers Chapter 4 img_36
42.8 – 42 = 0.8 inches

Question 30.
MODELING REAL LIFE
The amount y (in dollars) of money in your savings account after x months is represented by the equation y = 12.5x + 100.
a. Graph the linear equation.

Answer:
Big Ideas Math Grade 8 Answers Chapter 4 img_37
b. How many months will it take you to save a total of $237.50?
Answer:
y = 12.5x + 100
237.5 = x + 100
237.5 – 100 = 12.5x + 100 – 100
12.5x = 137.5
x = 11

Question 31.
PROBLEM SOLVING
The radius y (in millimeters) of a chemical spill after x days is represented by the equation y = 6x + 50.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.1 13
a. Graph the linear equation.

Answer:
Big Ideas Math Grade 8 Answers Chapter 4 img_38
b. The leak is noticed after two weeks. What is the area of the leak when it is noticed? Justify your answer.
Answer:
y = 6(14) + 50
y = 84 + 50
y = 134 mm
2πr = 2π = 841.95 sq. mm

Question 32.
GEOMETRY
The sum S of the interior angle measures of a polygon with n sides is S = (n – 2) • 180°.
a. Plot four points (n, S) that satisfy the equation. Is the equation a linear equation? Explain your reasoning.

Answer:
Big Ideas Math 8th Grade Answer Key for Chapter 4 img_39
b. Does the value n = 3.5 make sense in the context of the problem? Explain your reasoning.
Answer:
The value n = 3.5 does not make sense because the number of angles cannot be other than integer greater or equal to 2.

Question 33.
DIG DEEPER!
One second of video on your cell phone uses the same amount of memory as two pictures. Your cell phone can store 2500 pictures.
a. Create a graph that represents the number y of pictures your cell phone can store when you take x seconds of video.

Answer:
Big Ideas Math 8th Grade Answer Key for Chapter 4 img_40
b. How many pictures can your cell phone store in addition to a video that is one minute and thirty seconds long?
Answer:
Determine the number of pictures you can store in addition to a video of 1 min 30 seconds.
1 min 30 seconds = (60 + 90) 3 seconds = 90 seconds
2500 – (2 . 90)
2500 – 180 = 2320 pictures

Lesson 4.2 Slope of a Line

EXPLORATION 1

Measuring the Steepness of a Line
Work with a partner. Draw any nonvertical line in a coordinate plane.
a. Develop a way to measure the steepness of the line. Compare your method with other pairs.
b. Draw a line that is parallel to your line. What can you determine about the steepness of each line? Explain your reasoning.
Answer:

EXPLORATION 2

Using Right Triangles
Work with a partner. Use the figure shown.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 1
a. △ABC is a right triangle formed by drawing a horizontal line segment from point A and a vertical line segment from point B. Use this method to draw another right triangle, △DEF, with its longest side on the line
b. What can you conclude about the two triangles in part(a)? Justify your conclusion. Compare your results with other pairs.
c. Based on your conclusions in part(b), what is true about \(\frac{BC}{AC}\) and the corresponding measure in △DEF? Explain your reasoning. What do these values tell you about the line?
Answer:

Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 2

Try It

Find the slope of the line.
Question 1.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 3
Answer:
(x1, y1) = (-2, 3)
(x2, y2) = (3, 2)
m = (y2 – y1)/(x2 – x1)
m = (2 -3)/(3 – (-2))
m = -1/5
Thus slope = -1/5

Question 2.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 4
Answer:
(x1, y1) = (-4, -1)
(x2, y2) = (2, 1)
m = (y2 – y1)/(x2 – x1)
m = (1 – (-1))/(2 – (-4))
m = 2/6
Thus slope = 1/3

Find the slope of the line through the given points.
Question 3.
(1, -2), (7, -2)
Answer:
(x1, y1) = (1, -2)
(x2, y2) = (7, -2)
m = (y2 – y1)/(x2 – x1)
m = (-2 – (-2))/(7 – 1)
m = 0/6
Thus slope = 0

Question 4.
(-3, -3), (-3, -5)
Answer:
(x1, y1) = (-3, -3)
(x2, y2) = (-3, -5)
m = (y2 – y1)/(x2 – x1)
m = (-5 + 3)/(-3 + 3)
m = -2/0
Thus slope = undefined

Question 5.
WHAT IF
The blue line passes through (-4, -3) and (-3, 2). Are any of the lines parallel? Explain.
Answer:
(x1, y1) = (-4, -3)
(x2, y2) = (-3, 2)
m = (y2 – y1)/(x2 – x1)
m = (2 + 3)/(-3 + 4)
m = 5/1
m = 5
The slpe of the blue line is 5 and the slope of the red line is also 5.
The blue lines and red lines have same slopes so they are parallel.

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 6.
VOCABULARY
What does it mean for a line to have a slope of 4?
Answer:
If a line have a slope of 4 it means that the line rises 4 units for every 1 units it runs.

FINDING THE SLOPE OF A LINE Find the slope of the line through the given points.
Question 7.
(1, -1), (6, 2)
Answer:
(x1, y1) = (1, -1)
(x2, y2) = (6, 2)
m = (y2 – y1)/(x2 – x1)
m = (2 – (-1))/(6 – 1)
m = 3/5

Question 8.
(2, -3), (5, -3)
Answer:
(x1, y1) = (2, -3)
(x2, y2) = (5, -3)
m = (y2 – y1)/(x2 – x1)
m = (5 – 2)/(-3 + 3)
m = 3/0
m = undefined

Question 9.
FINDING SLOPE
Are the lines parallel? Explain your reasoning.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 5
Answer:
Red line:
(x1, y1) = (-1, 0)
(x2, y2) = (1, -2)
m = (y2 – y1)/(x2 – x1)
m = (-2 – 0)/1 – (-1))
m = -2/2
m = -1
Blue Line:
(x1, y1) = (-1, 3)
(x2, y2) = (1, -1)
m = (y2 – y1)/(x2 – x1)
m = (-1 – 3)/(1 – (-1))
m = -4/2
m = -2
The slope of the blue line and red line are not the same. So they are not parallel.

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 10.
The table shows the lengths (in inches) of your hair months after your last haircut. The points in the table lie on a line. Find and interpret the slope of the line. After how many months is your hair 4 inches long?
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 6
Answer:
Determine the slope of the line using two points from the table:
(2, 1), (4, 2)
m = (2 – 1)/4 – 2
m = 1/2
m = 0.5
This means that each month the hair grows 0.5 inches
As the hair grows 0.5 inches/ month, it will be 4 inches long after 4/0.5 = 8 months.

Question 11.
A customer pays an initial fee and a daily fee to rent a snowmobile. The total payment for 3 days is 92 dollars. The total payment for 5 days is 120 dollars. What is the daily fee? Justify your answer.
Answer:
Given,
A customer pays an initial fee and a daily fee to rent a snowmobile.
The total payment for 3 days is 92 dollars. The total payment for 5 days is 120 dollars.
m = (120 – 92)/5 – 3
m = 28/2
m = 14

Question 12.
You in-line skate from an elevation of 720 feet to an elevation of 750 feet in 30 minutes. Your friend in-line skates from an elevation of 600 feet to an elevation of 690 feet in one hour. Compare your rates of change in elevation.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 7
Answer:
Given,
You in-line skate from an elevation of 720 feet to an elevation of 750 feet in 30 minutes.
Your friend in-line skates from an elevation of 600 feet to an elevation of 690 feet in one hour.
(750 – 720)/30 = 30/30 = 1 ft/min
(690 – 600)/60 = 90/60 = 1.5 ft/min

Slope of a Line Homework & Practice 4.2

Review & Refresh

Graph the linear equation.
Question 1.
y = 4x – 3
Answer:
Big Ideas Math Grade 8 Chapter 4 Solution Key img_41

Question 2.
x = -3
Answer:
Big Ideas Math Grade 8 Chapter 4 Solution Key img_42

Question 3.
y = 2
Answer:
Big Ideas Math Grade 8 Chapter 4 Solution Key img_43

Question 4.
y = \(\frac{3}{2}\)x – \(\frac{1}{2}\)
Answer:
Big Ideas Math Grade 8 Chapter 4 Solution Key img_44

Find the missing values in the ratio table.
Question 5.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 8
Answer:
Big-Ideas-Math-Answers-8th-Grade-Chapter-4-Graphing-and-Writing-Linear-Equations-4.2-8
x/10 = 1/3
x = 10/3
x = 3.33
1/3 = 5/y
y = 5 × 3
y = 15
1/3 = 7/z
z = 3 × 7
z = 21

Question 6.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 9
Answer:
Big-Ideas-Math-Answers-8th-Grade-Chapter-4-Graphing-and-Writing-Linear-Equations-4.2-9

Concepts, Skills, &Problem Solving

USING RIGHT TRIANGLES Use the figure shown (See Exploration 2, p. 147.)
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 10
Question 7.
Find the slope of the line.
Answer:
(x1, y1) = B(-4, 2)
(x2, y2) = A(-2, 1)
m = (y2 – y1)/(x2 – x1)
m = (1 – 2)/(-2 – (-4))
m = -1/2
Thus the slope m = -1/2

Question 8.
Let point D be at (-4, 1). Use the sides of △BDA to find the slope of the line.
Answer:
Big Ideas Math Grade 8 Chapter 4 Answers img_45
m = -BD/DA = -1/2

FINDING THE SLOPE OF A LINE Find the slope of the line.
Question 9.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 11
Answer:
(x1, y1) = (-2, 0)
(x2, y2) = (2, 3)
m = (y2 – y1)/(x2 – x1)
m = (3 – 0)/(2 – (-2))
m = 3/4

Question 10.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 11
Answer:
(x1, y1) = (-2, 5)
(x2, y2) = (2, 0)
m = (y2 – y1)/(x2 – x1)
m = (0 – 5)/(2 – (-2))
m = -5/4

Question 11.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 13
Answer:
(x1, y1) = (-4, 1)
(x2, y2) = (1, -2)
m = (y2 – y1)/(x2 – x1)
m = (-2 – 1)/(1 + 2)
m = -3/5

Question 12.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 14
Answer:
(x1, y1) = (-5, -4)
(x2, y2) = (1, -3)
m = (y2 – y1)/(x2 – x1)
m = (-3 – (-4))/(1 – (-5))
m = 1/6

Question 13.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 15
Answer:
(x1, y1) = (-1, 3)
(x2, y2) = (3, 3)
m = (y2 – y1)/(x2 – x1)
m = (3 – 3)/(3 – (-1))
m = 0/4
m = 0

Question 14.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 16
Answer:
(x1, y1) = (1, 3)
(x2, y2) = (1, -2)
m = (y2 – y1)/(x2 – x1)
m = (-2 – 3)/(1 – 1)
m = -5/0
m = undefined

FINDING THE SLOPE OF A LINE Find the slope of the line through the given points.
Question 15.
(4, -1), (-2, -1)
Answer:
(x1, y1) = (4, -1)
(x2, y2) = (-2, -1)
m = (y2 – y1)/(x2 – x1)
m = (-1 – (-1))/(-2 – 4)
m = 0/-6
m = 0

Question 16.
(5, -3), (5, 8)
Answer:
(x1, y1) = (5, -3)
(x2, y2) = (5, 8)
m = (y2 – y1)/(x2 – x1)
m = (8 – 3)/(5 – 5)
m = 5/0
m = undefined

Question 17.
(-7, 0), (-7, -6)
Answer:
(x1, y1) = (-7, 0)
(x2, y2) = (-7, -6)
m = (y2 – y1)/(x2 – x1)
m = (-6 – 0)/(-7 – (-7))
m = -6/0
m = undefined

Question 18.
(-3, 1), (-1, 5)
Answer:
(x1, y1) = (-3, 1)
(x2, y2) = (-1, 5)
m = (y2 – y1)/(x2 – x1)
m = (5 – 1)/(-1 + 3)
m = 4/2
m = 2

Question 19.
(10, 4), (4, 15)
Answer:
(x1, y1) = (10, 4)
(x2, y2) = (4, 15)
m = (y2 – y1)/(x2 – x1)
m = (15 – 4)/(4 – 10)
m = 11/-6
m = -11/6

Question 20.
(-3, 6), (2, 6)
Answer:
(x1, y1) = (-3, 6)
(x2, y2) = (2, 6)
m = (y2 – y1)/(x2 – x1)
m = (6 – 6)/(2 – (-3))
m = 0/5
m = 0

Question 21.
REASONING
Draw a line through each point using slope of m = \(\frac{1}{4}\). Do the lines intersect? Explain.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 17
Answer:
Big Ideas math Grade 8 Answer Key Chapter 4 img_46
The 2 lines are parallel because they have the same slope and they do not intersect.

Question 22.
YOU BE THE TEACHER
Your friend finds the slope of the line shown. Is your friend correct? Explain your reasoning.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 18
Answer:
Big Ideas math Grade 8 Answer Key Chapter 4 img_47
No my friend is not correct because the denominator should be 2 – 4
(x1, y1) = (2, 3)
(x2, y2) = (4, 1)
m = (y2 – y1)/(x2 – x1)
m = (1 – 3)/(4 – 2)
m = -2/2
m = -1

IDENTIFYING PARALLEL LINES Which lines are parallel? How do you know?
Question 23.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 19
Answer:
Blue line:
(x1, y1) = (-5, 2)
(x2, y2) = (-4, -1)
m = (y2 – y1)/(x2 – x1)
m = (-1 – 2)/(-4 – (-5))
m = -3/1
m = -3
Red line:
(x1, y1) = (-2, 1)
(x2, y2) = (-1, -2)
m = (y2 – y1)/(x2 – x1)
m = (-2 – 1)/(-1 – (-2))
m = -3/1
m = -3
Green Line:
(x1, y1) = (1, 3)
(x2, y2) = (2, -1)
m = (y2 – y1)/(x2 – x1)
m = (-1 – 3)/(2 – 1)
m = -4/1
m = -4
Blue line and red line have slope of -3, so they are parallel.

Question 24.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 20
Answer:
Blue line:
(x1, y1) = (-2, 3)
(x2, y2) = (-5, -2)
m = (y2 – y1)/(x2 – x1)
m = (-2 – 3)/(-5 – (-2))
m = -5/-3
m = 5/3
Red line:
(x1, y1) = (1, 2)
(x2, y2) = (-2, -2)
m = (y2 – y1)/(x2 – x1)
m = (-2 – 2)/(-2 – 1)
m = -4/-3
m = 4/3
Green Line:
(x1, y1) = (4, 1)
(x2, y2) = (1, -3)
m = (y2 – y1)/(x2 – x1)
m = (-3 – 1)/(1 – 4)
m = -4/-3
m = 4/3
Red line and green line have slope of 4/3 by this we can say that they are parallel.

IDENTIFYING PARALLEL LINES Are the given lines parallel? Explain your reasoning.
Question 25.
y = -5, y = 3
Answer:
8th Grade Big Ideas Math Answers Chapter 4 img_47
Both lines are horizontal and have slope = 0

Question 26.
y = 0, x = 0
Answer:
8th Grade Big Ideas Math Answers Chapter 4 img_48
The line y = 0 have slope = 0 and are horizontal lines.
The line x = 0 have slope = undefined and are vertical lines.
So, they are not parallel.

Question 27.
x = -4, x = 1
Answer:
8th Grade Big Ideas Math Answers Chapter 4 img_49
Both lines are vertical and have an undefined slope.

FINDING SLOPE The points in the table lie on a line. Find the slope of the line.
Question 28.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 21
Answer:
m = (y2 – y1)/(x2 – x1)
m = (10 – 2)/(3 – 1) = (18 – 10)/(5 – 3) = (26 – 18)/(7 – 5)
m = 8/2 = 8/2 = 8/2
m = 4 = 4 = 4
Slope = 4

Question 9.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 22
Answer:
m = (y2 – y1)/(x2 – x1)
m = (2 – 0)/(2 – (-3)) = (4 – 2)/(7 – 2) = (6 – 4)/(12 – 7)
m = 2/5 = 2/5 = 2/5
m = 2/5

Question 30.
MODELING REAL LIFE
Carpenters refer to the slope of a roof as the pitch of the roof. Find the pitch of the roof.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 23
Answer:
Pitch of the roof = rise/run
= 4/12 = 1/3

Question 31.
PROJECT
The guidelines for a wheelchair ramp suggest that the ratio of the rise to the run be no greater than 1 : 12.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 24
a. CHOOSE TOOLS Find a wheelchair ramp in your school or neighborhood. Measure its slope. Does the ramp follow the guidelines?

Answer:
rise/run < 1/12
m = 0.06
1/12 = 0.0833
0.06 < 0.0833
As m < 1/12 the wheelchair ramp follows the guides.

b. Design a wheelchair ramp that provides access to a building with a front door that is 2.5 feet above the sidewalk. Illustrate your design.
Answer:
AC/AB = 1/12
2.5/AB = 1/12
AB = 2.5 × 12
AB = 30
So the end of the ramp should be placed at least 30 feet from the front door.

USING AN EQUATION Use an equation to find the value of k so that the line that passes through the given points has the given slope.
Question 32.
(1, 3), (5, k); m = 2
Answer:
A(1, 3)
B(5, k)
m = 2
2 = (k – 3)/(5 – 1)
2 × 4 = k – 3
8 = k – 3
k = 8 + 3
k = 11

Question 33.
(-2, k), (2, 0); m = -1
Answer:
Given,
A(-2, k)
B(2, 0)
m = -1
-1 = (0 – k)/2 – (-2)
-1 = -k/4
-4 = -k
k = 4

Question 34.
(-4, k), (6, -7); m = –\(\frac{1}{5}\)
Answer:
Given,
A(-4, k)
B(6, -7)
m = –\(\frac{1}{5}\)
–\(\frac{1}{5}\) = (-7 – k)/6 – (-4)
-2 = -7 – k
-2 + 7 = -k
5 = -k
k = -5

Question 35.
(4, -4), (k, -1); m = \(\frac{3}{4}\)
Answer:
\(\frac{3}{4}\) = (-1 – (-4))/(k – 4)
4 = k – 4
k = 4 + 4
k = 8

Question 36.
MODELING REAL LIFE
The graph shows the numbers of prescriptions filled over time by a pharmacy.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 25
a. Find the slope of the line.
Answer:
(0, 0), (20, 5)
m = (5 – 0)/(20 – 0)
m = 5/20
m = 1/4
b. Explain the meaning of the slope as a rate of change.
Answer:
This means that every 4 minutes a prescription is filled.

Question 37.
CRITICAL THINKING
Which is steeper: the boatramp, or a road with a 12% grade? Note: Explain. (Road grade is the vertical increase divided by the horizontal distance.)
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 26
Answer:
Mramp = rise/run = 6/36 = 1/6
Mroad = 12% = 12/100 = 0.12
0.16 = 0.166… > 0.12
Mramp > Mroad
Therefore the slope of the ramp is steeper than the slope of the road.

Question 38.
REASONING
Do the points A(-2, -1), B(1, 5), and C(4, 11) lie on the same line? Without using a graph, how do you know?
Answer:
Given,
A(-2, -1), B(1, 5), and C(4, 11)
mAB = (5 – (-1))/(1 – (-2)) = 6/3 = 2
mBC = (11 – 5)/(4 – 1) = 6/3 = 2
By seeing the slopes we can say that the points A, B, C lie on the same line.

Question 39.
PROBLEM SOLVING
A small business earns a profit of $6500 in January and $17,500 in May. What is the rate of change in profit for this time period? Justify your answer.
Answer:
Pjan = 6500
Pmay = 17,500
Pmay – Pjan/5 – 1
= (17,500 – 6500)/4
= 11,000/4 = 2750

Question 40.
STRUCTURE
Choose two points in the coordinate plane. Use the slope formula to find the slope of the line that passes through the two points. Then find the slope using the formula \(\frac{y_{1}-y_{2}}{x_{1}-x_{2}}\). Compare your results.
Answer:
P1(2, 5)
P2(3, 10)
m1 = (10 – 5)/(3 – 2) = 5/1 = 5
m2 = (5 – 10)/(1 – 3) = -5/-1 = 5
m1 = m2

Question 41.
DIG DEEPER!
The top and the bottom of the slide are level with the ground, which has a slope of 0.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.2 27
a. What is the slope of the main portion of the slide?
b. Describe the change in the slope when the bottom of the slide is only 12 inches above the ground. Explain your reasoning.
Answer:
18 inches = 1.5 feet
mMC = rise/run = (8 – 1.5)/(12 – 1 – 1) = 6.5/10 = 0.65
AD = 1
mMC = CR/MR
= (8 – 1)/(12 – 1 – 1) = 7/10 = 0.7
The slope increases from 0.65 to 0.70 because the rise increasses, while the run stays the same.

Lesson 4.3 Graphing Proportional Relationships

EXPLORATION 1

Using a Ratio Table to Find Slope
Work with a partner. The graph shows amounts of vinegar and water that can be used to make a cleaning product.
a. Use the graph to make a ratio table relating the quantities. Explain how the slope of the line is represented in the table.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.3 1
b. Make a ratio table that represents a different ratio of vinegar to water. Use the table to describe the slope of the graph of the new relationship.
Answer:

EXPLORATION 2

Deriving an Equation
Work with a partner. Let (x, y) represent any point on the graph of a proportional relationship.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.3 2
a. Describe the relationship between the corresponding side lengths of the triangles shown in the graph. Explain your reasoning.
b. Use the relationship in part(a) to write an equation relating y, m, and x. Then solve the equation for y. How can you find the side lengths of the triangles in the graph?
c. What does your equation in part(b) describe? What does represent? Explain your reasoning.
Answer:

Try It

Question 1.
WHAT IF
The cost of frozen yogurt is represented by y = 0.75x. Graph the equation and interpret the slope.
Answer:
The equation shows that the slope m is 0.75. So the graph passes through the points (0, 0) and (1, 0.75).
Plot the ordered pairs and draw the graph.
Big Ideas Math Grade 8 Answer Key Chapter 4 img_48
The slope indicates that the unit cost is $0.75 per ounce.

Question 2.
How much would a spacecraft that weighs 3500 kilograms on Earth weigh on Titan?
Answer:
y = 1/7 x
y = 1/7 × 3500
y = 500 kg
So a spacecraft would weigh 500 kg on Titan.

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

GRAPHING A PROPORTIONAL RELATIONSHIP Graph the equation.
Question 3.
y = 4x
Answer:
Big Ideas Math Grade 8 Answer Key Chapter 4 img_49

Question 4.
y = -3x
Answer:
Big Ideas Math Grade 8 Answer Key Chapter 4 img_50

Question 5.
y = 8x
Answer:
Big Ideas Math Grade 8 Answer Key Chapter 4 img_51

Question 6.
WRITING AND USING AN EQUATION
The number of objects a x machine produces is proportional to the time (in minutes) that the machine runs. The machine produces five objects in four minutes.
a. Write an equation that represents the situation.

Answer:
As 5 objects are produced in 4 minutes, the slope of the line is m = 5/4.
The equation that represents the situation is
y = 5/4 x
y = 1.25 x

b. Graph the equation in part (a) and interpret the slope.

Answer:
Use the slope. The equation shows that the slope m is 1.25. So the graph passes through the points (0, 0) and (1, 1.25)

c. How many objects does the machine produce in one hour?
Answer:
Big Ideas Math Grade 8 Answer Key Chapter 4 img_52

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 7.
The amount y (in liters) of water that flows over a natural waterfall in x seconds is represented by the equation y = 500x. The graph shows the number of liters of water that flow over an artificial waterfall. Which waterfall has a greater flow? Justify your answer.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.3 3
Answer:
Given the equation y = 500x
15000 – 3000 = 12000
12000/4 = 3000
Mnatural = 500
3000 > 500
Therefore the artificial waterfall has greater flow.

Question 8.
The speed of sound in air is 343 meters per second. You see lightning and hear thunder 12 seconds later.
a. Is there a proportional relationship between the amount of time that passes and your distance from a lightning strike? Explain.

Answer:
y = kx
where k is the speed of sound, x the time and y the distance.
Yes, there is a proportional relationship between the amount of time that passes and your distance from the lightning strike as the further you are, the more time will pass until the sound reaches you.

b. Estimate your distance from the lightning strike.
Answer:
y = 343 × 12
= 4116 meters

Graphing Proportional Relationships Homework & Practice 4.3

Review & Refresh

Find the slope of the line.
Question 1.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.3 4
Answer:
(x1, y1) = (0, -3)
(x2, y2) = (3, 0)
m = (y2 – y1)/(x2 – x1)
m = (0 – (-3))/(3 – 0)
m = (0 + 3)/(3 – 0)
m = 3/3
m = 1

Question 2.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.3 5
Answer:
(x1, y1) = (0, 1)
(x2, y2) = (3, -5)
m = (y2 – y1)/(x2 – x1)
m = (-5 – 1)/(3 – 0)
m = -6/3
m = -2

Question 3.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.3 6
Answer:
(x1, y1) = (0, 0)
(x2, y2) = (2, 8)
m = (y2 – y1)/(x2 – x1)
m = (8 – 0)/(2 – 0)
m = 8/2
m = 4

Solve the equation. Check your solution.
Question 4.
2x + 3x = 10
Answer:
Given the equation
2x + 3x = 10
5x = 10
x = 10/5
x = 2

Question 5.
x + \(\frac{1}{6}\) = 4 – 2x
Answer:
Given the equation
x + \(\frac{1}{6}\) = 4 – 2x
x + 2x = 4 – \(\frac{1}{6}\)
3x = 4 – \(\frac{1}{6}\)
3x = \(\frac{23}{6}\)
x = \(\frac{23}{18}\)

Question 6.
2(1 – x) = 11
Answer:
2(1 – x) = 11
2 – 2x = 11
2 – 11 = 2x
2x = -9
x = -9/2

Concepts, Skills, & Problem Solving

USING EQUIVALENT RATIOS The graph shows amounts of water and flour that can be used to make dough. (See Exploration 1, p. 155.)
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.3 7
Question 7.
Use the graph to make a ratio table relating the quantities. Explain how the slope of the line is represented in the table.
Answer:
BIM Grade 8 Solution Key Chapter 4 img_53
m = rise/run
= (10 – 5)/(6 – 3)
= 5/3
That means to every 5 cups of flour there is an increase of 3 cups of water.
The slope m is 5/3.

Question 8.
Make a ratio table that represents a different ratio of flour to water. Use the table to describe the slope of the graph of the new relationship.
Answer:
BIM Grade 8 Solution Key Chapter 4 img_54
From the table we find that for every increase of 7 cups of flour there is an increase of 4 cups of water.
The slope is 7/4.

Question 9.
GRAPHING AN EQUATION
The amount y(in dollars) that you raise by selling fundraiser tickets is represented by the equation y = 5x. Graph the equation and interpret the slope.
Answer:
BIM Grade 8 Solution Key Chapter 4 img_55
The slope indicates that the unit cost is $5 per ticket.

IDENTIFYING PROPORTIONAL RELATIONSHIPS Tell whether and are in a proportional relationship. Explain your reasoning. If so, write an equation that represents the relationship.
Question 10.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.3 8
Answer:
The graph doesn’t represent a proportional relationship because it doesn’t pass through the point (0, 0).

Question 11.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.3 9
Answer:
The graph represents a proportional relationship because it is linear and passes through the point (0, 0)
(0, 0), (2, 8)
m = (8 – 0)/(2 – 0)
m = 8/2
m = 4
The equation is y = 4x

Question 12.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.3 10
Answer:
(2 – 1)/(6 – 3) = 1/3
(3 – 2)/(9 – 6) = 1/3
(4 – 3)/(12 – 9) = 1/3
As the rate of change is constant, it means that the graph is a line.
(1 – y)/(3 – 0) = 1/3
(1 – y)/3 = 1/3
1 – y = 1
y = 1 – 1
y = 0
Therefore the point (0, 0) belomgs to the graph.
So the table represents a proportional relationship
y = 1/3 x

Question 13.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.3 11
Answer:
(8 – 4)/(5 – 2) = 4/3
(13 – 8)/(8 – 5) = 5/3
(23 – 13)/10 – 8 = 10/2 = 5

Question 14.
MODELING REAL LIFE
The cost y (in dollars) to rent a kayak is proportional to the number x of hours that you rent the kayak. It costs $27 to rent the kayak for 3 hours.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.3 12
a. Write an equation that represents the situation.
b. Interpret the slope of the graph of the equation.
c. How much does it cost to rent the kayak for 5 hours? Justify your answer.
Answer:
y = kx
27 = k × 3
k = 27/3
k = 9
The equation is k = 9x
b. The slope k = 3 shows that the cost of renting the kayak per hour is $9.
c. y = 9 × 5
y = 45

Question 15.
MODELING REAL LIFE
The distance y (in miles) that a truck travels on x gallons of gasoline is represented by the equation y = 18x. The graph shows the distance that a car travels.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.3 13
a. Which vehicle gets better gas mileage? Explain how you found your answer.

Answer:
y = 18x
(0, 0), (2, 50)
m = (50 – 0)/(2 – 0)
m = 50/2
m = 25
25 > 18
Therefore the car has better mileage.

b. How much farther can the vehicle you chose in part(a) travel on 8 gallons of gasoline?
Answer:
y = 25 × 8 – 18 × 8
= 200 – 144
= 56 miles

Question 16.
PROBLEM SOLVING
Toenails grow about 13 millimeters per year. The table shows fingernail growth.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.3 14
a. Do fingernails or toenails grow faster? Explain.

Answer:
y = 0.25x
m = (1.4 – 0.7)/(2 – 1)
m = 0.7
y = 0.7x
Because 0.7 > 0.25, the fingernails grow faster.

b. In the same coordinate plane, graph equations that represent the growth rates of toenails and fingernails. Compare and interpret the steepness of each graph.
Answer:
BIM Answer Key Grade 8 Chapter 4 img_57

Question 17.
REASONING
The quantities and are in a proportional relationship. What do you know about the ratio of y to x for any point (x, y) on the graph of x and y?
Answer:
y = kx
where k is constant
y/x = k
This means the ratio of y to x is constant.

Question 18.
DIG DEEPER!
The graph relates the temperature change y (in degrees Fahrenheit) to the altitude change x (in thousands of feet).
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.3 15
a. Is the relationship proportional? Explain.

Answer: The relationship is proportional because the graph is linear and passes through the origin.

b. Write an equation of the line. Interpret the slope.

Answer:
(0,0), (10, -35)
m = (-35 – 0)/(10 – 0)
= -35/10
= -3.5
y = -3.5x

c. You are at the bottom of a mountain where the temperature is 74°F. The top of the mountain is 5500 feet above you. What is the temperature at the top of the mountain? Justify your answer.
Answer:
x = 5.5 – 0 = 5.5 thousand feet
y = -3.5x = -3.5(5.5) = -19.25
74 – 19.25 = 54.75°F

Question 19.
CRITICAL THINKING
Consider the distance equation d = rt, where d is the distance (in feet), r is the rate (in feet per second), and t is the time (in seconds). You run for 50 seconds. Are the distance you run and the rate you run at proportional? Use a graph to justify your answer.
Answer:
d = rt
d = 50r
Having the form y = kx the equation represents a proportional relationship.
BIM Answer Key Grade 8 Chapter 4 img_58

Lesson 4.4 Graphing Linear Equations in Slope-Intercept Form

EXPLORATION 1

Deriving an Equation
Work with a partner. In the previous section, you learned that the graph of a proportional relationship can be represented by the equation y = mx, where m is the constant of proportionality.
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation 4.4 1
a. You translate the graph of a proportional relationship 3 units up as shown below. Let (x, y) represent any point on the graph. Make a conjecture about the equation of the line. Explain your reasoning.
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation 4.4 2
b. Describe the relationship between the corresponding side lengths of the triangles. Explain your reasoning.
c. Use the relationship in part(b) to write an equation relating y, m, and x. Does your equation support your conjecture in part(a)? Explain.
d. You translate the graph of a proportional relationship b units up. Write an equation relating y, m, x, and b. Justify your answer.
Answer:

Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation 4.4 3

Try It

Find the slope and the y-intercept of the graph of the linear equation.
Question 1.
y = 3x – 7
Answer:
Given the equation
y = 3x – 7
Write the equation in slope – intercept form: y = mx + b
The slope of the line is m and the y – intercept of the line is b.
y = 3x – 7
Slope = 3 and y – intercept = -7

Question 2.
y – 1 = –\(\frac{2}{3}\)x
Answer:
Write the equation in slope – intercept form: y = mx + b
The slope of the line is m and the y – intercept of the line is b.
y – 1 = –\(\frac{2}{3}\)x
y = –\(\frac{2}{3}\)x + 1
Slope = –\(\frac{2}{3}\) and y – intercept = 1

Graph the linear equation. Identify the x-intercept.
Question 3.
y = x – 4
Answer:
y = x – 4
Comparing the above equation with slope – intercept equation.
slope = 1, y-intercept = -4
Ploy y – intercept and slope
slope = rise/run = 1/1
Plot the point that is 1 unit right and 1 unit up from (0, -4) = (1, -3)
Grade 8 BIM Answers Chapter 4 img_59
Thus the intercept is 4.

Question 4.
y = –\(\frac{1}{2}\)x + 1
Answer:
y = –\(\frac{1}{2}\)x + 1
Comparing the above equation with slope – intercept equation.
Slope = –\(\frac{1}{2}\), y-intercept = 1
y-intercept = 1. So plot (0, 1)
Slope = rise/run = -1/2
Plot the point that is 2 units right and 1 unit down from (0, -4) = (2, 0)
Grade 8 BIM Answers Chapter 4 img_60
So, the x-intercept is 2.

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 5.
IN YOUR OWN WORDS
Consider the graph of the equation y = mx + b.
a. How does changing the value of m affect the graph of the equation?

Answer:
The value of m is the slope of the graph. If the value of m changes it means the slope of the graph is changing, whether it will rise or fall from left or right is dependent on the value of m.

b. How does changing the value of b affect the graph of the equation?
Answer:
The value of b is the y-intercept of the graph. If the value of b changes it means it affects where the graph crosses the y – axis.

IDENTIFYING SLOPE AND y-INTERCEPT Find the slope and the y-intercept of the graph of the linear equation.
Question 6.
y = -x + 0.25
Answer:
y = mx + c
slope = -1 and y – intercept = 0.25

Question 7.
y – 2 = –\(\frac{3}{4}\)x
Answer:
Given the equation
y – 2 = –\(\frac{3}{4}\)x
y = –\(\frac{3}{4}\)x + 2
slope = –\(\frac{3}{4}\) and y – intercept = 2

GRAPHING A LINEAR EQUATION Graph the linear equation. Identify the x-intercept.
Question 8.
y = x – 7
Answer:
Grade 8 BIM Answers Chapter 4 img_61
The line crosses the x-axis at (7, 0)
So, the x – intercept is 7.

Question 9.
y = 2x + 8
Answer:
Grade 8 BIM Answers Chapter 4 img_62
The line crosses the x – axis at (-4, 0)
So, the x – intercept is -4.

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 10.
The height y (in feet) of a movable bridge after rising for seconds is represented by the equation y = 3x + 6. Graph the equation. Interpret the y-intercept and slope. How many seconds does it take the bridge to reach a height of 76 feet? Justify your answer.
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation 4.4 4
Answer:
Given,
y = 3x + 6.
slope = 3, y – intercept = 16
Grade 8 BIM Answers Chapter 4 img_63
The y – intercept is 16. So, the initial height of the bridge is 16 feet.
The slope is 3. So, the bridge rises 3 feet per second.
The bridge will reach a height of 76 feet in 20 seconds.

Question 11.
The number of perfume bottles in storage after x months is represented by the equation y = -20x + 460. Graph the equation. Interpret the y-intercept and the slope. In how many months will there be no perfume bottles left in storage? Justify your answer.
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation 4.4 5.1
Answer:
Given the equation
y = -20x + 460
Slope = -20, y-intercept = 460
Grade 8 BIM Answers Chapter 4 img_64
The y-intercept is 460. So, the initial number of perfume in the storage is 460.
The slope is -20. So, the number of perfume bottle decrease with 20 bottles per months.
There will be no perfume bottle left in the storage in 23 months.

Graphing Linear Equations in Slope-Intercept Form Homework & Practice 4.4

Review & Refresh

Tell whether x and y are in a proportional relationship. Explain your reasoning. If so, write an equation that represents the relationship.
Question 1.
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation 4.4 5
Answer:
(8 – 6)/(2 – 1) = 2/1 = 2
(10 – 8)/(3 – 2) = 2/1 = 2
(12 – 10)/(4 – 3) = 2/1 = 2
The rate of change in the table is constant.
(6 – y)/(1 – 0) = 2
6 – y = 2
y = 6 – 2
y = 4
Therefore the graph does not pass through the origin.
So x and y are not proportional.

Question 2.
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation 4.4 6
Answer:
(4 – 0)/(-8 – 0) = 4/-8 = -1/2 = -0.5
(2 – 4)/(-4 – (-8)) = -2/4 = -1/2 = -0.5
(-2 – 2)/(4 – (-4)) = -4/8 = -1/2 = -0.5
(-4 – (-2))/(8 – 4) = -2/4 = -1/2 = -0.5
As the rate of change is constant, x and y are in a proportional relationship.
y = -0.5x

Solve the equation for y.
Question 3.
x = 4y – 2
Answer:
Given the equation
x = 4y – 2
x – 2 = 4y
y = x/4 + 1/2

Question 4.
3y = -6x + 1
Answer:
Given the equation
3y = -6x + 1
y = -2x + 1/3

Question 5.
1 + y = –\(\frac{4}{5}\)x – 2
Answer:
Given the equation
1 + y = –\(\frac{4}{5}\)x – 2
y = –\(\frac{4}{5}\)x – 3

Question 6.
2.5y = 5x – 5
Answer:
Given the equation
2.5y = 5x – 5
y = 2x – 2

Question 7.
1.3y + 5.2 = -3.9x
Answer:
Given the equation
1.3y + 5.2 = -3.9x
1.3y = -3.9x – 5.2
y = -3x – 4

Question 8.
y – \(\frac{2}{3}\)x = -6
Answer:
Given the equation
y – \(\frac{2}{3}\)x = -6
y = \(\frac{2}{3}\)x -6

Concepts, Skills, &Problem Solving

GRAPHING A LINEAR EQUATION Graph the equation. (See Exploration 1, p. 161.)
Question 9.
The graph of y = 3.5x is translated up 2 units.
Answer:
Given the equation
y = 3.5x
The line obtained by translating the graph of the line y = 3.5x up 2 units has the same slope (3.5) and y – intercept 2 units greater, which means b = 0 + 2 = 2
Big Ideas Math Grade 8 Answer Key Chapter 4 img_60

Question 10.
The graph of y = -5x is translated down 3 units.
Answer:
y = -5x
The line obtained by translating the graph of the line y = -5x down 3 units has the same slope and the y – intercept 3 units smaller, which means b = 0 – 3 = -3
Big Ideas Math 8th Grade Answer Key for Chapter 4 img_61

MATCHING EQUATIONS AND GRAPHS Match the equation with its graph. Identify the slope and the y-intercept.
Question 11.
y = 2x + 1
Answer:
Given the eqation
y = 2x + 1
slope = 2 and y – intercept = 1
Big Ideas Math 8th Grade Answer Key for Chapter 4 img_62

Question 12.
y = \(\frac{1}{3}\)x – 2
Answer:
slope = 1/3 and y – intercept = -2
Big Ideas Math 8th Grade Answer Key for Chapter 4 img_63

Question 13.
y = –\(\frac{2}{3}\)x + 1
Answer:

Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation 4.4 7

Answer:
Slope = -2/3 and y – intercept = 1
The graph which passes through the point (0, 1) and has a negative slope is the matching graph of the given equation.

IDENTIFYING SLOPES AND y-INTERCEPTS Find the slope and the y-intercept of the graph of the linear equation.
Question 14.
y = 4x – 5
Answer:
y = mx + b
slope = 4 and y — intercept = -5

Question 15.
y = -7x + 12
Answer:
y = -7x + 12
y = mx + b
slpoe = -7 and y – intercept = 12

Question 16.
y = –\(\frac{4}{5}\)x – 2
Answer:
y = mx + b
slope = -4/5
y – intercept = -2

Question 17.
y = 2.25x + 3
Answer:
y = mx + b
slope = 2.25 and y – intercept = 3

Question 18.
y + 1 = \(\frac{4}{3}\)x
Answer:
y = mx + b
y + 1 = \(\frac{4}{3}\)x
y = \(\frac{4}{3}\)x – 1
slope = \(\frac{4}{3}\), y – intercept = -1

Question 19.
y – 6 = \(\frac{3}{5}\)x
Answer:
y = mx + b
y – 6 = \(\frac{3}{5}\)x
y = \(\frac{3}{5}\)x + 6
slope = 3/8 and y – intercept = 6

Question 20.
y – 3.5 = -2x
Answer:
y = mx + b
y – 3.5 = -2x
y = -2x + 3.5
slope = -2 and y – intercept = 3.5

Question 21.
y = -5 – \(\frac{1}{2}\)x
Answer:
y = mx + b
y = -5 – \(\frac{1}{2}\)x
y =- \(\frac{1}{2}\)x – 5
slope = – \(\frac{1}{2}\) and y – intercept = -5

Question 22.
y = 11 + 1.5x
Answer:
y = mx + b
y = 1.5x + 11
slope = 1.5 and y – intercept = 11

Question 23.
YOU BE THE TEACHER
Your friend finds the slope and y-intercept of the graph of the equation y = 4x – 3. Is your friend correct? Explain your reasoning.
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation 4.4 8
Answer:
y = 4x – 3
No my friend is not correct because the y – intercept is -3.

Question 24.
MODELING REAL LIFE
The number y of seasonal allergy shots available at a facility x days after receiving a shipment is represented by y = -15x + 375.
a. Graph the linear equation.
b. Interpret the slope and the y-intercept.
Answer:
y = -15x + 375
x = 0
y = -15(0) + 375 = 375
y = 0
0 = -15x + 375
15x = 375
x = 375/15
x = 25
BIM Grade 8 Solution Key Chapter 4 img_64
The slope shows that the number of seasonal allergy shots decrease by 15 shots each day.
The y – intercept shows that the number of shots immediately after receiving a shipment is 375.

GRAPHING AN EQUATION Graph the linear equation. Identify the x-intercept.
Question 25.
y = x + 3
Answer:
Given the equation
y = x + 3
slope = 1 and y – intercept = 3
Slope = rise/run = 1/1
Plot the point that is 1 unit right and 1 unit up from (0, 3) = (1, 4)
BIM Grade 8 Solution Key Chapter 4 img_65
So, the x – intercept is -3.

Question 26.
y = 4x – 8
Answer:
y = 4x – 8
Comparing the above equation with slope – intercept equation.
slope = 4 and y – intercept = -8
Slope = rise/run = 4/1 = 4
Plot the point that is 1 unit right and 4 unit up from (0, -8) = (1, -4)
BIM Grade 8 Solution Key Chapter 4 img_66

Question 27.
y = -3x + 9
Answer:
y = -3x + 9
slope = -3 and y – intercept = 9
slope rise/run = -3/1 = -3
BIM Grade 8 Solution Key Chapter 4 img_67

So, the intercept is 3.

Question 28.
y = -5x – 5
Answer:
y = -5x – 5
slope = -5 and y – intercept = -5
slope = rise/run = -5/1
Plot the point that is 1 unit right and 5 unit up from (0, -5) = (1, -10)
BIM Grade 8 Solution Key Chapter 4 img_68
So, the x – intercept is -1.

Question 29.
y + 14 = -7x
Answer:
y + 14 = -7x
y = -7x – 14
slope = -7 and y – intercept = -14
Slope = rise/run = -7/1
Plot the point that is 1 unit right and 7 unit down from (0, -14) = (1, -21)
BIM Grade 8 Solution Key Chapter 4 img_69
So, the x – intercept is -2.

Question 30.
y = 8 – 2x
Answer:
Given the equation
y = 8 – 2x
y = -2x + 8
slope = -2 and y – intercept = 8
slope = rise/run = -2/1
Plot the point 1 unit right and 2 units down from (0, 8) = (1, 6)
BIM Grade 8 Solution Key Chapter 4 img_70
So, the x – intercept is 4.

Question 31.
PRECISION
You go to a harvest festival and pick apples.
a. Which equation represents the cost (in dollars) of going to the festival and picking x pounds of apples? Explain.
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation 4.4 9
b. Graph the equation you chose in part(a).
Answer:
Picking a pound of apples costs $0.75, therefore x pounds cost 0.75 × x = 0.75x
y = 0.75x + 5
BIM Grade 8 Solution Key Chapter 4 img_71

Question 32.
REASONING
Without graphing, identify the equations of the lines that are parallel. Explain your reasoning.
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation 4.4 10
Answer:
The lines which area parallel are those having the same slope.
y = 2x + 4
y = 2x – 3
y = 2x + 1
y = 1/2x + 1
y = 1/2x + 2

Question 33.
PROBLEM SOLVING
A skydiver parachutes to the ground. The height y (in feet) of the skydiver after x seconds is y = -10x + 3000.
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation 4.4 11
a. Graph the linear equation.
b. Interpret the slope, y-intercept, and x-intercept.
Answer:
y = -10x + 3000
x = 0
y = -10(0) + 3000 = 3000
y = 0
0 = -10 + 3000
10x = 3000
x = 3000/10 = 300
BIM Grade 8 Solution Key Chapter 4 img_72
b. The slope shows that each second the skydiver descends 10 feet.
The y – intercept shows that the skydiver begins its dive from 3000 feet.
The x – intercept shows that he reaches the ground after 300 seconds.

Question 34.
DIG DEEPER!
Six friends create a website. The website earns money by selling banner ads. It costs $120 a month to operate the website.
a. A banner ad earns $0.005 per click. Write a linear equation that represents the monthly profit after paying operating costs.
b. Graph the equation in part(a). On the graph, label the number of clicks needed for the friends to start making a profit. Explain.
Answer:
y = 0.005x – 120
x = 0
y = 0.005(0) – 120
y = -120
y = 0
0 = 0.005x – 120
0.005x = 120
x = 24000
BIM Grade 8 Solution Key Chapter 4 img_73
x > 24,000

Lesson 4.5 Graphing Linear Equations in Standard Form

EXPLORATION 1

Using Intercepts
Work with a partner. You spend $150 on fruit trays and vegetable trays for a party.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.5 1
a. You buy x fruit trays and y vegetable trays. Complete the verbal model. Then use the verbal model to write an equation that relates x and y.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.5 2
b. What is the greatest number of fruit trays that you can buy? vegetable trays? Can you use these numbers to graph your equation from part (a) in the coordinate plane? Explain.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.5 3
c.Use a graph to determine the different combinations of fruit trays and vegetable trays that you can buy. Justify your answers algebraically.
d. You are given an extra $50 to spend. How does this affect the intercepts of your graph in part(c)? Explain your reasoning.
Answer:

Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.5 4

Try It

Graph the linear equation.
Question 1.
x + y = -2
Answer:
Given the equation
y = mx + b
x + y = -2
y = -x – 2
Comparing the value of b and m from y = mx + b
m = -1 and b = -2
Plot y – intercept = (0, b) = (0, -2)
Slope = -1
run/rise = -1/1
Plot the point 1 unit down and 1 unit to the right = (1, -3)
Now plot the points and draw the graph
BIM Grade 8 Solution Key Chapter 4 img_74

Question 2.
–\(\frac{1}{2}\)x + 2y = 6
Answer:
–\(\frac{1}{2}\)x + 2y = 6
2y = 6 + \(\frac{1}{2}\)x
y = 0.25x + 3
Comparing the value of b and m from y = mx + b
m = 0.25 and b = 3
Plot y – intercept = (0, b) = (0, 3)
Slope = 0.25
run/rise = 0.25/1
Plot the point 0.25 unit up and 1 unit to the right = (1, 3.25)
Now plot the points and draw the graph

BIM Grade 8 Solution Key Chapter 4 img_75

Question 3.
–\(\frac{2}{3}\)x + y = 0
Answer:
–\(\frac{2}{3}\)x + y = 0
y = \(\frac{2}{3}\)x
Comparing the value of b and m from y = mx + b
m = \(\frac{2}{3}\) and b = 0
Plot y – intercept = (0, b) = (0, 0)
Slope =\(\frac{2}{3}\)
run/rise = \(\frac{2}{3}\)
Plot the point 0.25 unit up and 1 unit to the right = (3, 2)
Now plot the points and draw the graph
BIM Grade 8 Solution Key Chapter 4 img_76

Question 4.
2x + y = 5
Answer:
2x + y = 5
y = -2x + 5
Comparing the value of b and m from y = mx + b
m = -2 and b = 5
Plot y – intercept = (0, b) = (0, 5)
Slope = -2
run/rise = \(\frac{-2}{1}\)
Plot the point 0.25 unit up and 1 unit to the right = (1, 3)
Now plot the points and draw the graph
BIM Grade 8 Solution Key Chapter 4 img_77

Graph the linear equation using intercepts.
Question 5.
2x – y = 8
Answer:
y = 0
2x – y = 8
2x – 0 = 8
2x = 8
x = 4
The x – intercept is (4, 0)
Y – intercept :
x = 0
2x – y = 8
2(0) – y = 8
y = -8
BIM Grade 8 Solution Key Chapter 4 img_78

Question 6.
x + 3y = 6
Answer:
X-intercept:
y = 0
x + 3y = 6
x + 3(0) = 6
x + 0 = 6
x = 6
The x – intercept is (6, 0)
Y – intercept:
x = 0
x + 3y = 6
0 + 3y = 6
y = 2
The y – intercept is (0, 2)
BIM Grade 8 Solution Key Chapter 4 img_79

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

STRUCTURE Determine whether the equation is in standard form. If not, rewrite the equation in standard form.
Question 7.
y = x – 6
Answer:
y = x – 6
The standard form of equation is: Ax + By = C
The given equation is not in the standard form.
y = x – 6
x – y = 6

Question 8.
y – \(\frac{1}{6}\)x + 5 = 0
Answer:
The standard form of equation is: Ax + By = C
The given equation is not in the standard form.
y – \(\frac{1}{6}\)x + 5 = 0
\(\frac{1}{6}\)x – y = 5

Question 9.
4x + y = 5
Answer:
The standard form of equation is: Ax + By = C
The given equation is in the form of the standard form.

Question 10.
WRITING
Describe two ways to graph the equation 4x + 2y = 6.
Answer:
The two ways to graph the equation:
1. Graph the equation using standard form
2. Graph the equation using intercept.

GRAPHING A LINEAR EQUATION Graph the linear equation.
Question 11.
4x + y = 5
Answer:
Given the equation
4x + y = 5
y = -4x + 5
Comparing the value of b and m from y = mx + b
m = -4 and b = 5
Plot y – intercept = (0, b) = (0, 5)
Slope = -4
run/rise = \(\frac{-4}{1}\)
Plot the point 4 unit down and 1 unit to the right = (1, 1)
Now plot the points and draw the graph
BIM Grade 8 Solution Key Chapter 4 img_81

Question 12.
\(\frac{1}{3}\)x + 2y = 8
Answer:
X – intercept:
y = 0
\(\frac{1}{3}\)x + 2y = 8
\(\frac{1}{3}\)x + 2(0) = 8
\(\frac{1}{3}\)x = 8
x = 24
The x – intercept is (24, 0)
Y – intercept:
x = 0
\(\frac{1}{3}\)x + 2y = 8
\(\frac{1}{3}\)(0) + 2y = 8
2y = 8
y = 4
The y – intercept is (0, 4)
BIM Grade 8 Solution Key Chapter 4 img_82

Question 13.
5x – y = 10
Answer:
X – intercept:
y = 0
5x – 0 = 10
5x = 10
x = 2
The x-intercept is (2, 0)
Y – intercept:
x = 0
5x – y = 10
5(0) – y = 10
-y = 10
y = -10
The y – intercept is (0, -10)
BIM Grade 8 Solution Key Chapter 4 img_83

Question 14.
x – 3y = 9
Answer:
X – intercept:
y = 0
x – 3(0) = 9
x = 9
The x – intercept is (9, 0)
Y – intercept:
x = 0
0 – 3y = 9
-3y = 9
y = -3
The y – intercept is (0, -3)
BIM Grade 8 Solution Key Chapter 4 img_84

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 15.
You have $30 to spend on paint and clay. The equation 2x + 6y = 30 represents this situation, where x is the number of paint bottles and y is the number of tubs of clay. Graph the equation. Interpret the intercepts. How many bottles of paint can you buy if you buy 3 tubs of clay? Justify your answer.
Answer:
Given,
You have $30 to spend on paint and clay.
The equation 2x + 6y = 30 represents this situation,
where x is the number of paint bottles and y is the number of tubs of clay.
X – intercept:
y = 0
2x + 6y = 30
2x + 6(0) = 30
2x = 30
x = 15
The x – intercept is (15, 0)
Y – intercept:
x = 0
2x + 6y = 30
2(0) + 6y = 30
6y = 30
y = 5
The y – intercept is (0, 5)
BIM Grade 8 Solution Key Chapter 4 img_85
From the graph, I can buy 6 bottles of point if I buy 3 tubs of clay.
BIM Grade 8 Solution Key Chapter 4 img_86

Question 16.
You complete two projects for a class in 60 minutes. The equation x + y = 60 represents this situation, where x is the time (in minutes) you spend assembling a birdhouse and y is the time (in minutes) you spend writing a paper.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.5 5
a. Graph the equation. Interpret the intercepts.

Answer:
x + y = 60
y = -x + 60
BIM Grade 8 Solution Key Chapter 4 img_87

b. You spend twice as much time assembling the birdhouse as you do writing the paper. How much time do you spend writing the paper? Justify your answer.
Answer:
We are given,
y = 2x
2x = -x + 60
2x + x = 60
3x = 60
x = 20
y = 2 (20)
y = 40

Graphing Linear Equations in Standard Form Homework & Practice 4.5

Review & Refresh

Find the slope and the y-intercept of the graph of the linear equation.
Question 1.
y = x – 1
Answer:
y = mx + b
Slope = -1 and y – intercept = -1

Question 2.
y = -2x + 1
Answer:
y = -2x + 1
y = mx + b
Slope = -2 and y – intercept = 1

Question 3.
y = \(\frac{8}{9}\)x – 8
Answer:
y = \(\frac{8}{9}\)x – 8
y = mx + b
Slope = \(\frac{8}{9}\) and y – intercept = -8

Tell whether the blue figure is a reflection of the red figure.
Question 4.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.5 6
Answer:
The blue figure is not a reflection of the red figure because, for example the reflection of the upper leg of the upper leg of the red triangle across the y-axis is the top vertex of the blue triangle, not a point.

Question 5.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.5 7
Answer:
The blue figure is a reflection of the red figure because to each point in the red figure corresponds a symmetrical point in the blue figure.

Question 6.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.5 8
Answer:
The blue figure is a reflection of the red figure because to each point in the red figure corresponds a symmetrical point in the blue figure.

Concepts, Skills, &Problem Solving

USING INTERCEPTS Define two variables for the verbal model. Write an equation in slope-intercept form that relates the variables. Graph the equation using intercepts. (See Exploration 1, p. 167.)
Question 7.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.5 9
Answer:
x = amount of peaches (in pounds)
y = the amount of apples (in pounds)
2x + 1.5y = 15
y = 0 = 2x + 1.5(0) = 15
2x = 15
x = 7.5
x = 0
2(0) + 1.5y = 15
1.5y =15
y = 10
BIM Grade 8 Solution key Chapter 4 img_88

Question 8.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.5 10
Answer:
x = the biked distance (in miles)
y = the walked distance (in miles)
y = 0
16x + 2(0) = 32
16x = 32
x = 2
x = 0
16(0) + 2y = 32
2y = 32
y = 16
BIM Grade 8 Solution key Chapter 4 img_89

REWRITING AN EQUATION Write the linear equation in slope-intercept form.
Question 9.
2x + y = 17
Answer:
Given the equation
2x + y = 17
y = 17 – 2x
y = -2x + 17

Question 10.
5x – y = \(\frac{1}{4}\)
Answer:
Given the equation
5x – y = \(\frac{1}{4}\)
-y = \(\frac{1}{4}\) – 5x
y = 5x – \(\frac{1}{4}\)

Question 11.
–\(\frac{1}{2}\)x + y = 10
Answer:
Given the equation
–\(\frac{1}{2}\)x + y = 10
y = \(\frac{1}{2}\)x + 10

GRAPHING AN EQUATION Graph the linear equation.
Question 12.
-18x + 9y = 72
Answer:
Given the equation
-18x + 9y = 72
X – intercept:
y = 0
-18x + 9(0) = 72
-18x = 72
x = -4
The x – intercept is (-4, 0)
Y – intercept:
x = 0
-18x + 9y = 72
-18(0) + 9y = 72
9y = 72
y = 8
BIM Grade 8 Answers Chapter 4 img_90

Question 13.
16x – 4y = 2
Answer:
Given the equation
16x – 4y = 2
X – intercept:
y = 0
16x – 4y = 2
16x – 4(0) = 2
16x = 2
x = 0.125
The X – intercept is (0.125, 0)
Y – intercept:
x = 0
16(0) – 4y = 2
-4y = 2
y = -2
BIM Grade 8 Answers Chapter 4 img_91

Question 14.
\(\frac{1}{4}\)x + \(\frac{3}{4}\)y = 1
Answer:
Given the equation
\(\frac{1}{4}\)x + \(\frac{3}{4}\)y = 1
x + 3y = 4
y = 0
x + 3(0) = 4
x = 4
x = 0
0 + 3y = 4
3y = 4
y = 4/3
BIM Grade 8 Answers Chapter 4 img_93

MATCHING Match the equation with its graph.
Question 15.
15x – 12y = 60
Answer:
y = 0
15x – 12(0) = 60
15x = 60
x = 60/15
x = 4
x = 0
15(0) – 12y = 60
-12y = 60
y = -5
The graph having the x – intercept 4 and y – intercept -5

Question 16.
5x + 4y = 20
Answer:
Given the linear equation
5x + 4y = 20
y = 0
5x + 4(0) = 20
5x = 20
x = 4
x = 0
5(0) + 4y = 20
4y = 20
y = 5

Question 17.
10x + 8y = -40
Answer:

Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.5 11
10x + 8y = -40
y = 0
10x + 8(0) = -40
10x = -40
x = -4
x = 0
10(0) + 8y = -40
8y = -40
y = -5

Question 18
YOU BE THE TEACHER
Your friend finds the x-intercept of -2x + 3y = 12. Is your friend correct? Explain your reasoning.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.5 12
Answer:
-2x + 3y = 12
y = 0
-2x + 3(0) = 12
-2x = 12
x = -6
Your friend is not correct because the x – intercept is the value of x corresponding to y = 0.
Your friend computed the y – intercept.

Question 19.
MODELING REAL LIFE
A charm bracelet costs $65, plus $25 for each charm. The equation -25x + y = 65 represents the cost y (in dollars) of the bracelet, where x is the number of charms.
a. Graph the equation.
b. How much does a bracelet with three charms cost?
Answer:
BIM Grade 8 Answers Chapter 4 img_94
y = 25x + 65
Substitute the value of x in the equation
y = 25(3) + 65
y = 75 + 65
y = 140

USING INTERCEPTS TO GRAPH Graph the linear equation using intercepts.
Question 20.
3x – 4y = -12
Answer:
Given the equation
3x – 4y = -12
3x – 4(0) = -12
3x = -12
x = -4
The x – intercept is (-4, 0)
Y – intercept:
x = 0
3(0) – 4y = -12
-4y = -12
y = 3
The y – intercept is (0, 3)
BIM Grade 8 Answers Chapter 4 img_95

Question 21.
2x + y = 8
Answer:
X – intercept:
y = 0
2x + y = 8
2x + 0 = 8
2x = 8
x = 4
The x – intercept is (4, 0)
Y – intercept:
x = 0
2x + y = 8
2(0) + y = 8
y = 8
The y – intercept is (0, 8)
BIM Grade 8 Answers Chapter 4 img_96

Question 22.
\(\frac{1}{3}\)x – \(\frac{1}{6}\)y = –\(\frac{2}{3}\)
Answer:
X – intercept:
y = 0
\(\frac{1}{3}\)x – \(\frac{1}{6}\)(0) = –\(\frac{2}{3}\)
\(\frac{1}{3}\)x = –\(\frac{2}{3}\)
x = -2
The x – intercept is (-2, 0)
Y – intercept:
x = 0
\(\frac{1}{3}\)(0) – \(\frac{1}{6}\)y = –\(\frac{2}{3}\)
y = 4
The y – intercept is (0, 4)
BIM Grade 8 Answers Chapter 4 img_97

Question 23.
MODELING REAL LIFE
Your cousin has $90 to spend on video games and movies. The equation 30x + 15y = 90 represents this situation, where x is the number of video games purchased and y is the number of movies purchased. Graph the equation. Interpret the intercepts.
Answer:
30x + 15y = 90
x = 0
30(0) + 15y = 90
15y = 90
y = 6
y = 0
30x + 15(0) = 90
30x = 90
x = 3
BIM Grade 8 Answers Chapter 4 img_98
The x – intercept shows that 3 video games are purchased when no movies are purchased.
The y – intercept shows that 6 movies are purchased when no video games are purchased.

Question 24.
PROBLEM SOLVING
A group of friends go scuba diving. They rent a boat for x days and scuba gear for y people, represented by the equation 250x + 50y = 1000.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.5 13
a. Graph the equation and interpret the intercepts.
b. How many friends can go scuba diving if they rent the boat for 1 day? 2 days?
c. How much money is spent in total?
Answer:
250x + 50y = 1000
x = 0
250(0) + 50y = 1000
50y = 1000
y = 20
when y = 0
250x + 50(0) = 1000
250x = 1000
x = 4
BIM Grade 8 Answers Chapter 4 img_99
b.
250(1) + 50y = 1000
250 + 50y = 1000
50y = 1000 – 250
50y = 750
y = 15
when x = 2
250(2) + 50y = 1000
500 + 50y = 1000
50y = 1000 – 500
50y = 500
y = 500/50
y = 10

Question 25.
DIG DEEPER!
You work at a restaurant as a host and a server. You earn $9.45 for each hour you work as a host and $3.78 for each hour you work as a server.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.5 14
a. Write an equation in standard form that models your earnings.
b. Graph the equation.
Answer:
You earn $9.45 for each hour you work as a host and $3.78 for each hour you work as a server.
Number of hours worked as host + $3.78.
Number of hours worked as server = $113.40
9.45x + 3.78y = 113.40
x = 0
9.45(0) + 3.78y = 113.40
3.78y = 113.40
y = 30
when y = 0
9.45x + 3.78(0) = 113.40
9.45x = 113.40
x = 12
BIM Grade 8 Answers Chapter 4 img_100

Question 26.
LOGIC
Does the graph of every linear equation have an x-intercept? Justify your reasoning.
Answer:
y = mx + b
y = 0
0 = mx + b
mx = -b
x = -b/m for m ≠ 0
If m = 0 the equation has no solution. Therefore the equation y = b has no x – intercept.

Question 27.
CRITICAL THINKING
For a house call, a veterinarian charges $70, plus $40 per hour.
Big Ideas Math Answer Key Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.5 15
a. Write an equation that represents the total fee y (in dollars) the veterinarian charges for a visit lasting x hours.

b. Find the x-intercept. Does this value make sense in this context? Explain your reasoning.
c. Graph the equation.
Answer:
Total fee = fixed charge + number of hours . cost per hour
y = 70 + 40x
y = 0
0 = 70 + 40x
-70 = 40x
x = -1.75
x = 0
y = 70 + 40(0)
y = 70
BIM Grade 8 Solutions Chapter 4 img_101

Lesson 4.6 Writing Equations in Slope-Intercept Form

EXPLORATION 1

Writing Equations of Lines
Work with a partner.For each part, answer the following questions.

  • What are the slopes and the y-intercepts of the lines?
  • What are equations that represent the lines?
  • What do the lines have in common?

Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 1
Answer:

EXPLORATION 2

Interpreting the Slope and the y-Intercept
Work with a partner. The graph represents the distance y (in miles) of a car from Phoenix after t hours of a trip.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 2
a. Find the slope and the y-intercept of the line. What do they represent in this situation?
b. Write an equation that represents the graph.
c. How can you determine the distance of the car from Phoenix after 11 hours?
Answer:

Try It

Write an equation in slope-intercept form of the line that passes through the given points.
Question 1.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 3
Answer:
m = (y2 – y1)/(x2 – x1)
= (4 – 2)/(1 – 0)
= 2/1
= 2
Because the line crosses the y – axis at (0, 2)
y = mx + b
y = 2x + 2

Question 2.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 4
Answer:
m = (y2 – y1)/(x2 – x1)
= (-1 – 3)/(0 – (-3))
= -4/3
Because y = -1 when x = 0, the y – intercept is -1
y = mx + b
y = -4/3 x – 1

Write an equation of the line that passes through the given points.
Question 3.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 5
Answer:
m = (y2 – y1)/(x2 – x1)
= (5 – 5)/(0 – (-4))
= 0/4
Because y = 5 when x = 0, the y – intercept is 5
y = mx + b
y = (0)x + 5
y = 5

Question 4.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 6
Answer:
m = (y2 – y1)/(x2 – x1)
= (1 – 1)/(3 – 0)
= 0/3
= 0
Because the line crosses the y – axis at (0, 1) the y – intercept is 1
y = mx + b
y = (0)x + 1
y = 1

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

WRITING EQUATIONS IN SLOPE-INTERCEPT FORM Write an equation in slope-intercept form of the line that passes through the given points.
Question 5.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 7
Answer:
m = (y2 – y1)/(x2 – x1)
= (5 – 2)/(1 – 0)
= 3/1
= 3
Because y = 2 when x = 0, the y – intercept is 2
y = mx + b
y = (3)x + 2
y = 3x + 2

Question 6.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 8
Answer:
m = (y2 – y1)/(x2 – x1)
= (-1 – 5)/(1 – (-1))
= -6/2
= -3
Because the line crosses the y – axis at (0, 2) the y – intercept is 2
y = mx + b
y = -3x + 2

Question 7.
WRITING AN EQUATION
Write an equation of the line that passes through (0, -5) and (2, -5).
Answer:
m = (y2 – y1)/(x2 – x1)
= (-5 – (-5))/(2 – 0)
= 0/2
= 0
Because y = -5 when x = 0, the y – intercept is -5
y = mx + b
y = (0)x + -5
y = -5

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 8.
You load boxes onto an empty truck at a constant rate. After 3 hours, there are 100 boxes on the truck. How much longer do you work if you load a total of 120 boxes? Justify your answer.
Answer:
Let x be the number of hours you work if you load a total of 120 boxes.
100/3 = 120/x
100x = 3 × 120
x = 360/100
x = 3.6 hours
3.6 – 3 = 0.6 hours

Question 9.
The table shows the amounts (in tons) of waste left in a landfill after x months of waste relocation. Interpret the slope and the y-intercept of the line that passes through the given points. How many months does it take to empty the landfill? Justify your answer.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 9
Answer:
m = (12 – 15)/ (6 – 0)
m = -3/6
m = -0.5
b = 15
The y – intercept shows that there are 150 tons of waste in the beginning.
y = -0.5x + 15
y = 0
0 = -0.5x + 15
x = 30
So the ladfill will be emptied after 30 months.

Question 10.
DIG DEEPER!
A lifetime subscription to a website costs $250. A monthly subscription to the website costs $10 to join and $15 per month. Write equations to represent the costs of each plan. If you want to be a member for one year, which plan is less expensive? Explain.
Answer:
Given,
A lifetime subscription to a website costs $250. A monthly subscription to the website costs $10 to join and $15 per month.
Total cost for plan 1 = the lifetime subscription
y = 250
Total cost for Plan 2 = Fixed tax + Number of months . monthly cost
y = 10 + 15x
Plan 1: y = 250
Plan 2: y = 10 + 15(12) = 190
As 190 < 250, plan 1 is less expensive.

Writing Equations in Slope-Intercept Form Homework & Practice 4.6

Review & Refresh

Write the linear equation in slope-intercept form.
Question 1.
4x + y = 1
Answer:
Given the equation
4x + y = 1
y = -4x + 1

Question 2.
x – y = \(\frac{1}{5}\)
Answer:
Given the equation
x – y = \(\frac{1}{5}\)
x – \(\frac{1}{5}\) = y

Question 3.
–\(\frac{2}{3}\)x + 2y = -7
Answer:
Given the equation
–\(\frac{2}{3}\)x + 2y = -7
2y = -7 + \(\frac{2}{3}\)x
y = \(\frac{1}{3}\)x – \(\frac{7}{2}\)

Plot the ordered pair in a coordinate plane.
Question 4.
(1, 4)
Answer:
8th Grade BIM Answers Chapter 4 img_102

Question 5.
(-1, -2)
Answer:
8th Grade BIM Answers Chapter 4 img_103

Question 6.
(0, 1)
Answer:
8th Grade BIM Answers Chapter 4 img_104

Question 7.
(2, 7)
Answer:
8th Grade BIM Answers Chapter 4 img_105

Concepts, Skills, & Problem Solving

INTERPRETING THE SLOPE AND THE y-INTERCEPT The graph y represents the cost (in dollars) to open an online gaming account and buy x games. (See Exploration 2, p. 173.)
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 10
Question 8.
Find the slope and the y-intercept of the line. What do they represent in this situation?
Answer:
(0, 15), (3, 45)
m = (45 – 15)/(3 – 0)
m = 30/3 10
Thus the slope of the line is m – 3.
b = 15
The slope represents the cost of one game, while the y – intercept is the cost of opening the gaming account.

Question 9.
Write an equation that represents the graph.
Answer:
m = 10
b = 15
y = mx + b
y = 10x + 15

Question 10.
How can you determine the total cost of opening an account and buying 6 games?
Answer:
y = 10x + 15
y = 10(6) + 15
y = 60 + 15
y = 75

WRITING EQUATIONS IN SLOPE-INTERCEPT FORM Write an equation in slope-intercept form of the line that passes through the given points.
Question 11.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 11
Answer:
m = (y2 – y1)/(x2 – x1)
= (4 – 3)/(0 – (-1))
= 1/1
= 1
Because the line crosses the y – axis at (0, 4) the y – intercept is 4
y = mx + b
y = (1)x + 4
y = x + 4

Question 12.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 12
Answer:
m = (y2 – y1)/(x2 – x1)
= (6 – 0)/(-3 – 0)
= 6/-3
= -2
Because the line crosses the y – axis at (0, 2) the y – intercept is 2
y = mx + b
y = -2x + 0
y = -2x

Question 13.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 13
Answer:
m = (y2 – y1)/(x2 – x1)
= (2 – 1)/(4 – 0)
= 1/4
Because the line crosses the y – axis at (0, 1) the y – intercept is 1
y = mx + b
y = 1/4 x + 1

Question 14.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 14
Answer:
m = (y2 – y1)/(x2 – x1)
= (1 – 2)/(0 – (-2))
= -1/2
Because y = 1 when x = 0, the y – intercept is 1
y = mx + b
y = -1/2 x + 2

Question 15.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 15
Answer:
m = (y2 – y1)/(x2 – x1)
= (-3 – (-4))/(0 – (-3))
= 1/3
Because y = -3 when x = 0, the y – intercept is -3
y = mx + b
y = 1/3 x – 3

Question 16.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 16
Answer:
m = (y2 – y1)/(x2 – x1)
= (-1 -4)/(0 – (-2))
= -5/2
Because y = -1 when x = 0, the y – intercept is -1
y = mx + b
y = -5/2 x – 1

WRITING EQUATIONS Write an equation of the line that passes through the given points.
Question 17.
(-1, 4), (0, 2)
Answer:
m = (y2 – y1)/(x2 – x1)
= (2 – 4)/(0 – (-1))
= -2/1
= -2
Because y = 2 when x = 0, the y – intercept is 2
y = mx + b
y = -2x + 2

Question 18.
(-1, 0), (0, 0)
Answer:
m = (y2 – y1)/(x2 – x1)
= (0 – 0)/(0 – (-1))
= 0/1
= 0
Because y = 0 when x = 0, the y – intercept is 0
y = mx + b
y = 0

Question 19.
(0, 4), (0, -3)
Answer:
Both points belong to the y-axis. Therefore the equation of the line passing through them is
x = 0

Question 20.
YOU BE THE TEACHER
Your friend writes an equation of the line shown. Is your friend correct? Explain your reasoning.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 17
Answer:
Because in the given graph, y = -2 when x = 0, so the y – intercept is -2. The equation of the line should be: y = 1/2 x – 2
No my friend is NOT correct.

Question 21.
MODELING REAL LIFE
A boa constrictor is 18 inches long at birth and grows 8 inches per year. Write an equation in slope y-intercept form that represents the length (in feet) of a boa constrictor that is x years old.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 18
Answer:
Given,
A boa constrictor is 18 inches long at birth and grows 8 inches per year.
Length after x years = birth length + number of years . Growth per year
y = 18 + 8x
y = 8x + 18
Convert it into feet
y = 2/3 x + 3/2

Question 22.
MODELING REAL LIFE
The table shows the speeds y (in miles per hour) of a car after x seconds of braking. Write an equation of the line that passes through the points in the table. Interpret the slope and the y-intercept of the line.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 19
Answer:
m = (y2 – y1)/(x2 – x1)
= (60 – 70)/(1 – 0)
= -10/1
= -10
Because y = 70 when x = 0, the y – intercept is 70
y = mx + b
y = -10x + 70
Slope = -10 represents the decrease in the speed of the car each seconds after breaking.
The y – intercept of 70 represents the initial speed of the car.

Question 23.
MODELING REAL LIFE
A dentist charges a flat fee for an office visit, plus an additional fee for every tooth removed. The graph shows the total cost y (in dollars) for a patient when the dentist removes x teeth. Interpret the slope and the y-intercept.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 20
Answer:
(2, 500), (4, 900)
m = (900 – 500)/(4 – 2)
m = 400/2
m = 200
y = mx + b
500 = 200(2) + b
500 = 400 + b
b = 500 – 400
b = 100
The slope shows that the amount charged for each removed tooth is $200.
The y – intercept shows that the flat fee for an office visit is $100.

Question 24.
MODELING REAL LIFE
One of your friends gives you $10 for a charity walkathon. Another friend gives you an amount per mile. After 5 miles, you have raised $13.50 total. Write an equation that represents the amount y of money you have raised after x miles.
Answer:
Given,
One of your friends gives you $10 for a charity walkathon.
Another friend gives you an amount per mile. After 5 miles, you have raised $13.50 total.
y = mx + b
b = 10
13.50 = 5m + 10
13.50 – 10 = 5m
3.50 = 5m
m = 3.50/5
m = 0.7
y = 0.7x + 10

Question 25.
PROBLEM SOLVING
You have 500 sheets of notebook paper. After 1 week, you have 72% of the sheets left. You use the same number of sheets each week. Write an equation that represents the number y of sheets remaining after x weeks.
Answer:
y = mx + b
500 – 0.72 × 500 = 500 – 360 = 140 sheets
m = -140
b = 500
y = -140x + 500

Question 26.
DIG DEEPER!
The palm tree on the left is 10 years old. The palm tree on the right is 8 years old. The trees grow at the same rate.
Big Ideas Math Answers 8th Grade Chapter 4 Graphing and Writing Linear Equations 4.6 21
a. Estimate the height y (in feet) of each tree.
b. Plot the two points (x, y), where x is the age of each tree and y is the height of each tree.
c. What is the rate of growth of the trees?
d. Write an equation that represents the height of a palm tree in terms of its age.
Answer:
a. estimate
left: 18
right: 12
plot y = 1.8x

Lesson 4.7 Writing Equations in Point-Slope Form

EXPLORATION 1

Deriving an Equation
Work with a partner. Let (x1, y1) represent a specific point on a line. Let (x, y) represent any other point on the line.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 1
a. Write an equation that represents the slope m of the line. Explain your reasoning.
b. Multiply each side of your equation in part(a) by the expression in the denominator. What does the resulting equation represent? Explain your reasoning.
Answer:

EXPLORATION 2

Writing an Equation
Work with a partner.
For 4 months, you saved $25 a month. You now have $175 in your savings account.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 2
a. Draw a graph that shows the balance in your account after t months.
b.Use your result from Exploration 1 to write an equation that represents the balance A after t months.
Answer:

Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 3

Try It
Write an equation in point -slope form of the line that passes through the given point and has the given slope.
Question 1.
(1, 2); m = -4
Answer:
y – y1 = m(x – x1)
y – 2 = -4(x – (1))
y – 2 = -4(x – 1)

Question 2.
(7, 0); m = 1
Answer:
y – y1 = m(x – x1)
y – 0 = 1(x – (7))
y – 0 = 1(x – 7)

Question 3.
(-8, -5); m = –\(\frac{3}{4}\)
Answer:
y – y1 = m(x – x1)
y – (-5) = –\(\frac{3}{4}\)(x – (-8))
y + 5 = –\(\frac{3}{4}\)(x + 8)

Write an equation in slope-intercept form of the line that passes through the given points.
Question 4.
(-2, 1), (3, -4)
Answer:
Slope(m) = (-4 – 1)/(3 – (-2))
= -5/5
m = -1
y – y1 = m(x – x1)
y – 1 = -1(x – (-2))
y – 1 = -1(x + 2)
y – 1 = -x – 2
y = -x – 1

Question 5.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 4
Answer:
Slope(m) = (3 – 5)/(-3 – (-5))
= -2/2
m = -1
y – y1 = m(x – x1)
y – 1 = -1(x – (-1))
y – 1 = -1(x + 1)
y – 1 = -x – 1
y = -x – 1 + 1
y = -x

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

WRITING AN EQUATION Write an equation in point-slope form of the line that passes through the given point and has the given slope.
Question 6.
(2, 0); m = 1
Answer:
y – y1 = m(x – x1)
y – 0 = 1(x – (2))
y – 0 = 1(x – 2)

Question 7.
(-3, -1); m = –\(\frac{1}{3}\)
Answer:
y – y1 = m(x – x1)
y – (-1) = –\(\frac{1}{3}\)(x – (-3))
y + 1 = –\(\frac{1}{3}\)(x + 3)

Question 8.
(5, 4); m = 3
Answer:
y – y1 = m(x – x1)
y – 4 = 3(x – (5))
y – 4 = 3(x – 5)

Question 9.
WRITING AN EQUATION
Write an equation of the line that passes through the points given in the table.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 5
Answer:
Slope(m) = (-2 – 1)/(5 – 3)
= -3/2
m = -1
y – y1 = m(x – x1)
y – (-5) = -3/2(x – 7)
y + 5 = -3/2(x – 7)
y + 5 = -3/2 x + 21/2
y = -3/2 x + 11/2

Question 10.
DIFFERENT WORDS, SAME QUESTION
Which is different? Sketch “both” graphs.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 6
Answer:
y – 7 = 4x – 4
y = 4x + -4 + 7
y = 4x + 3
Graph line passes through the points (4, 5) and (5, 9)

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 11.
A writer finishes a project that a coworker started at a rate of 3 pages per hour. After 3 hours,25% of the project is complete.
a. The project is 200 pages long. Write and graph an equation for the total number y of pages that have been finished after the writer works for x hours.
b. The writer has a total of 45 hours to finish the project. Will the writer meet the deadline? Explain your reasoning.
Answer:
m = 3
y = 3x + b
b + 9 = 25%(200)
b + 9 = 0.25(200)
b + 9 = 50
b = 50 – 9
b = 41
y = 3x + 41
BIM 8th Grade Solution Key Ch 4 img_106
y = 3x + 41
y = 3(45) + 41 = 176 pages
As 176 < 200, the writer will not meet the deadline.

Question 12.
DIG DEEPER!
You and your friend begin to run along a path at different constant speeds.After 1 minute,your friend is 45 meters ahead of you. After 3 minutes, your friend is 105 meters ahead of you.
a. Write and graph an equation for the distance y (in meters) your friend is ahead of you after x minutes. Justify your answer.

Answer:
y = mx + b
45 = m + b
105 = 3m + b
105 – 45 = (3m + b) – (m + b)
60 = 2m
m = 30
45 = 30 + b
b = 45 – 30
b = 15
y = 30x + 15
BIM 8th Grade Solution Key Ch 4 img_107

b. Did you and your friend start running from the same spot? Explain your reasoning.
Answer:
The distance between you and your friend in the initial moment is b = 15 meters. So you are ahead your friend by 15 meters at the starting point.

Writing Equations in Point-Slope Form Homework & Practice 4.7

Review & Refresh

Write an equation in slope-intercept form of the line that passes through the given points.
Question 1.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 7
Answer:
Slope(m) = (5 – 4)/(0 – (-2))
= 1/2
m = 1/2
Because y = 5 when x = 0, the y – intercept is 5.
y = mx + b
y = 1/2 x + 5

Question 2.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 8
Answer:
Slope(m) = (5 – (-1))/(2 – (-2))
= (5 + 1)/(2 + 2)
m = 6/4
m = 3/2
From the graph, the line crosses the y – axis at (0, 2)
y = mx + b
y = 3/2 x + 2

Solve the equation. Check your solution, if possible.
Question 3.
2x + 3 = 2x
Answer:
Given the equation
2x + 3 = 2x
3 = 2x – 2x
3 ≠ 0

Question 4.
6x – 7 = 1 – 3x
Answer:
Given the equation
6x – 7 = 1 – 3x
6x + 3x = 1 + 7
9x = 8
x = 8/3

Question 5.
0.1x – 1 = 1.2x – 5.4
Answer:
Given the equation
0.1x – 1 = 1.2x – 5.4
0.1x – 1.2x = 1 – 5.4
-1.1x = -4.4
x = 4

Concepts, Skills, &Problem Solving

WRITING AN EQUATION The value of a new car decreases $4000 each year. After 3 years, the car is worth $18,000. (See Exploration 2, p. 179.)
Question 6.
Draw a graph that shows the value of the car after t years.
Answer:
BIM 8th Grade Solution Key Chapter 4 img_111

Question 7.
Write an equation that represents the value V of the car after t years.
Answer:
y = -4000t + b
where b is the original price
18,000 = -4000(3) + b
18,000 + 12,000 = b
b = 30,000
y = -4000t + 30,000

WRITING AN EQUATION Write an equation in point-slope form of the line that passes through the given point and has the given slope.
Question 8.
(3, 0); m = –\(\frac{2}{3}\)
Answer:
y – y1 = m(x – x1)
y – (0) = -2/3(x – 3)
y – 0 = -2/3(x – 3)

Question 9.
(4, 8); m = \(\frac{3}{4}\)
Answer:
y – y1 = m(x – x1)
y – (8) = 3/4(x – 4)
y – 8 = 3/4(x – 4)

Question 10.
(1, -3); m = 4
Answer:
y – y1 = m(x – x1)
y – (-3) = 4(x – 1)
y + 3 = 4(x – 1)

Question 11.
(7, -5); m = –\(\frac{1}{7}\)
Answer:
y – y1 = m(x – x1)
y – (-5) = –\(\frac{1}{7}\)(x – 7)
y + 5 = –\(\frac{1}{7}\)(x – 7)

Question 12.
(3, 3); m = \(\frac{5}{3}\)
Answer:
y – y1 = m(x – x1)
y – (3) = \(\frac{5}{3}\)(x – 3)
y – 3 = \(\frac{5}{3}\)(x – 3)

Question 13.
(-1, -4); m = -2
Answer:
y – y1 = m(x – x1)
y – (-4) = -2(x – (-1))
y + 4 = -2(x + 1)

WRITING AN EQUATION Write an equation in slope-intercept form of the line that passes through the given points.
Question 14.
(-1, -1), (1, 5)
Answer:
Slope(m) = (5 – (-1))/(2 – (-1))
= (5 + 1)/(1 + 1)
m = 6/2
m = 3
y – y1 = m(x – x1)
y – (5) = 3(x – (1))
y – 5 = 3x – 3
y = 3x + 2

Question 15.
(2, 4), (3, 6)
Answer:
Slope(m) = (6 – 4)/(3 – 2)
m = 2/1
m = 2
y – y1 = m(x – x1)
y – (4) = 2(x – (2))
y – 4 = 2x – 4
y = 2x

Question 16.
(-2, 3), (2, 7)
Answer:
Slope(m) = (7 – (3))/(2 – (-2))
= (7 – 3)/(2 + 2)
m = 4/4
m = 1
y – y1 = m(x – x1)
y – (3) = 1(x – (-2))
y – 3 = x + 2
y = x + 5

Question 17.
(4, 1), (8, 2)
Answer:
Slope(m) = (2 – (1))/(8 – (4))
= (2 – 1)/(8 – 4)
m = 1/4
y – y1 = m(x – x1)
y – (1) = 1/4(x – (4))
y – 1 = 1/4 x – 1
y = 1/4 x

Question 18.
(-9, 5), (-3, 3)
Answer:
Slope(m) = (3 – (5))/(-3 – (-9))
= (3 – 5)/(-3 + 9)
m = -2/6
m = -1/3
y – y1 = m(x – x1)
y – (3) = -1/3(x + 3)
y – 3 = -1/3 x – 1
y = -1/3 x + 2

Question 19.
(1, 2), (-2, -1)
Answer:
Slope(m) = (2 – (1))/(8 – (4))
= (-1 – 2)/(-2 – 1)
m = -3/-3
m = 1
y – y1 = m(x – x1)
y – (2) = 1(x – (1))
y – 2 = x – 1
y = x + 1

Question 20.
MODELING REAL LIFE
At 0° C, the volume of a gas is 22 liters. For each degree the temperature T (in degrees Celsius) increases, the volume V (in liters) of the gas increases by \(\frac{2}{25}\). Write an equation that represents the volume of the gas in terms of the temperature.
Answer:
The equation modeling the situation has the form:
V = mT + b
m = 2/25
22 = 2/25(0) + b
b = 22
V = 2/25 T + 22

WRITING AN EQUATION Write an equation of the line that passes through the given points in any form. Explain your choice of form.
Question 21.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 9
Answer:
m = (y2 – y1)/(x2 – x1)
= (2.5 – 1.5)/(0 – (-1))
= 1/1
= 1
Because the line crosses the y – axis at (0, 2.5), the y – intercept is 2.5
y = mx + b
y = (1)x + 2.5
y = x + 2.5

Question 22.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 10
Answer:
m = (y2 – y1)/(x2 – x1)
= (3.5 – 1.5)/(2 – (1))
= 2/1
= 2
y – y1 = m(x – x1)
y – (1.5) = 2(x – (1))
y – 1.5 = 2x – 2
y = 2x – 0.5

Question 23.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 11
Answer:
m = (y2 – y1)/(x2 – x1)
= (-1.5 – 4.5)/(1 – (-1))
= -6/2
= -3
y – y1 = m(x – x1)
y – (-1.5) = -3(x – (1))
y + 1.5 = -3x + 3
y = -3x + 1.5

Question 24.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 12
Answer:
m = (y2 – y1)/(x2 – x1)
= (-0.5 – 3.5)/(1 – (-1))
= -4/2
= -2
y – y1 = m(x – x1)
y – (-0.5) = -2(x – (1))
y + 0.5 = -2x – 2
y = -2x – 2.5

Question 25.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 13
Answer:
m = (y2 – y1)/(x2 – x1)
= (1 – (-1))/(0 – (-3))
= (1 + 1)/(0 + 3)
= 2/3
Because y = 1 when x = 0, the y – intercept is 1.
y = mx + b
y = 2/3 x + 1

Question 26.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 14
Answer:
m = (y2 – y1)/(x2 – x1)
= (4 – 6)/(-3 – (-7))
= -2/4
= -1/2
y – y1 = m(x – x1)
y – (2) = -1/2(x – (1))
y – 2 = -1/2x + 1/2
y = -1/2 x + 5/2

Question 27.
REASONING
Write an equation of the line that passes through the point (8, 2) and is parallel to the graph of the equation y = 4x – 3.
Answer:
y = 4x – 3
Comparing the given equation with y = mx + b, we get
m = 4
y – y1 = m(x – x1)
y – 2 = 4(x – 8)
y – 2 = 4x – 32
y = 4x – 32 + 2
y = 4x – 30

Question 28.
MODELING REAL LIFE
The table shows the amount y (in fluid ounces) of carpet cleaner in a tank after x minutes of cleaning.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 15
a. Write an equation that represents the amount of cleaner x in the tank after minutes.
b. How much cleaner is in the tank when the cleaning begins?
c. After how many minutes is the tank empty? Justify your answer.
Answer:

Question 29.
DIG DEEPER!
According to Dolbear’s law, you can predict the temperature T (in degrees Fahrenheit) by counting the number x of chirps made by a snowy tree cricket in 1 minute.When the temperature is 50°F, a cricket chirps 40 times in 1 minute. For each rise in temperature of 0.25°F, the cricket makes an additional chirp each minute.
a. You count 100 chirps in 1 minute. What is the temperature?
b. The temperature is 96°F.How many chirps do you expect the cricket to make? Justify your answer.
Answer:

Question 30.
PROBLEM SOLVING
The Leaning Tower of Pisa in Italy was built between 1173 and 1350.
a. Write an equation that represents the yellow line.
b. The tower is 56 meters tall. How far from the center is the top of the tower? Justify your answer.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 16
Answer:

Graphing and Writing Linear Equations Connecting Concepts

Using the Problem-Solving Plan
Question 1.
Every item in a retail store is on sale for 40% off. Write and graph an equation that represents the sale price of an item that has an original price of x dollars.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 cc 1
Understand the problem.
You know the percent discount of items in a retail store.You are asked to write and graph an equation that represents the sale price of an item that has an original price of x dollars.
Make a plan.
Selling an item for 40% off is the same as selling an item for 60% of its original price. Use this information to write and graph an equation that represents the situation.
Solve and check.
Use the plan to solve the problem. Then check your solution.
Answer:
40% = 0.40 and to find a percent of a number you multiply the number by the percent in decimal form.
So, the equation is d = 0.4p
BIM 8th Grade Answers img_111

Question 2.
Two supplementary angles have angle measures of x° and y°. Write and graph an equation that represents the relationship between the measures of the angles.
Answer:

Question 3.
A mechanic charges a diagnostic fee plus an hourly rate. The table shows the numbers of hours worked and the total costs for three customers.A fourth customer pays $285. Find the number of hours that the mechanic worked for the fourth customer.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 cc 2
Answer:

Performance Task

Anatomy of a Hurricane
At the beginning of this chapter, you watched a STEAM Video called “Hurricane!” You are now ready to complete the performance task related to this video, available at BigIdeasMath.com. Be sure to use the problem-solving plan as you work through the performance task.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 cc 3

Graphing and Writing Linear Equations Chapter Review

Review Vocabulary
Write the definition and give an example of each vocabulary term.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations cr 1

Graphic Organizers
You can use a Definition and Example Chart to organize information about a concept. Here is an example of a Definition and Example Chart for the vocabulary term linear equation.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations cr 2

Choose and complete a graphic organizer to help you study the concept.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations cr 3
1. slope
2. slope of parallel lines
3. proportional relationship
4. slope-intercept form
5. standard form
6. point-slope form

Chapter Self-Assessment

As you complete the exercises, use the scale below to rate your understanding of the success criteria in your journal.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 cr 1

4.1 Graphing Linear Equations (pp. 141–146)
Learning Target: Graph linear equations.Graph the linear equation.

Question 1.
y = \(\frac{3}{5}\)x
Answer:
Bigideas Math Answers 8th Grade chapter 4 img_112

Question 2.
y = -2
Answer:
Bigideas Math Answers 8th Grade chapter 4 img_113

Question 3.
y = 9 – x
Answer:
Bigideas Math Answers 8th Grade chapter 4 img_114

Question 4.
y = -0.25x + 4
Answer:
Bigideas Math Answers 8th Grade chapter 4 img_115

Question 5.
y = \(\frac{2}{3}\)x + 2
Answer:
Bigideas Math Answers 8th Grade chapter 4 img_116

Question 6.
x = -5
Answer:
Bigideas Math Answers 8th Grade chapter 4 img_117

Question 7.
The equation y = 0.53x + 3 represents the cost y (in dollars) of riding in a taxi x miles.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 cr 2
a. Use a graph to estimate how much it costs to ride 5.25 miles in a taxi.
b. Use the equation to find exactly how much it costs to ride 5.25 miles in a taxi.
Answer:
Bigideas Math Answers 8th Grade chapter 4 img_118
y = 0.5x + 3
y = 0.5(5.25) + 3
y ≈ 5.6

Question 8.
The equation y = 9.5x represents the earnings y (in dollars) of an aquarium gift shop employee that works x hours.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 cr 8
a. Graph the linear equation.
b. How much does the employee earn for working 40 hours?
Answer:
Bigideas Math Answers 8th Grade chapter 4 img_119
Determine y for x = 40:
y = 9.5x
y = 9.5(40) = 380

Question 9.
Is y = x2 a linear equation? Explain your reasoning.
Answer:
y = x2
The graph of the given equation passes through the origin, but is not linear, therefore it is not a linear equation.
So, the answer is no.

Question 10.
The sum S of the exterior angle measures of a polygon with n sides is S = 360°.
a. Plot four points (n, S) that satisfy the equation. Is the equation a linear equation? Explain your reasoning.
b. Does the value n = 2 make sense in the context of the problem? Explain your reasoning.
Answer:
8th Grade Big Ideas Math Answer Key Chapter 4 img_120
The value n = 2 does not make sense in the context of the problem because a polygon has at least 3 sides.

4.2 Slope of a Line (pp. 147–154)
Learning Target: Find and interpret the slope of a line.

Describe the slope of the line. Then find the slope of the line.
Question 11.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 cr 11
Answer:
(x1, y1) = (3, 1)
(x2, y2) = (-3, -3)
m = (y2 – y1)/(x2 – x1)
m = (-3 – 1)/(-3 – 3)
m = -4/-6
m = 2/3

Question 12.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 cr 12
Answer:
(x1, y1) = (0, 4)
(x2, y2) = (2, -2)
m = (y2 – y1)/(x2 – x1)
m = (-2 – 4)/(2 – 0)
m = -6/2
m = -3
The slope is negative

Find the slope of the line through the given points.
Question 13.
(-5, 4), (8, 4)
Answer:
(x1, y1) = (-5, 4)
(x2, y2) = (8, 4)
m = (y2 – y1)/(x2 – x1)
m = (4 – 4)/(8 – (-5))
m = 0/13
m = 0

Question 14.
(-3, 5), (-3, 1)
Answer:
(x1, y1) = (-3, 5)
(x2, y2) = (-3, 1)
m = (y2 – y1)/(x2 – x1)
m = (1 – 5)/(-3 + 3)
m = -4/0
m = undefined

The points in the table lie on a line. Find the slope of the line.
Question 15.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 cr 15
Answer:
(x1, y1) = (0, -1)
(x2, y2) = (1, 0)
m = (y2 – y1)/(x2 – x1)
m = (0 – (-1))/(1 – 0)
m = 1/1
m = 1

Question 16.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 cr 16
Answer:
(x1, y1) = (-2, 3)
(x2, y2) = (0, 4)
m = (y2 – y1)/(x2 – x1)
m = (4 – 3)/(0 – (-2))
m = 1/2

Question 17.
How do you know when two lines are parallel? Use an example to justify your answer.
Answer:
Two lines are parallel when their slopes are the same. In order for the two lines not to coincide, we must add the condition that their y – intercepts.
Example 1:
d1: y = 3x – 6
d2: 3x – y = 6
The lines d1 and d2 have the same slope and the same y – intercept, therefore they coincide.

Question 18.
Draw a line through the point (-1, 2) that is parallel to the graph of the line in Exercise 11.
Answer:
y = 2/3 x – 1
A (-1, 2)
y = 2/3 x + b
y = 2/3 (-1) + b
b = 8/3
The equation of d1 is:
y = 2/3 x + 8/3
Determine the x intercept of d1:
0 = 2/3 x + 8/3
0 = 2x + 8
2x = -8
x = -8/2
x = -4
Bigideas math answers grade 8 ch 4 img_121

4.3 Graphing Proportional Relationships (pp. 155–160)
Learning Target: Graph proportional relationships.

Tell whether x and y are in a proportional relationship. Explain your reasoning. If so, write an equation that represents the relationship.
Question 19.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 cr 19
Answer:
x and y are not in a proportional relationship because the line does not pass through the origin.

Question 20.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 cr 20
Answer:
x and y are in a proportional relationship because the line does passes through the origin.
Determine the slope k using two points from the graph
k = (10 – 0)/(2 – 0)
k = 10/2
k = 5x

Question 21.
The cost y (in dollars) to provide food for guests at a dinner party is proportional to the number x of guests attending the party. It costs $30 to provide food for 4 guests.
a. Write an equation that represents the situation.
b. Interpret the slope of the graph of the equation.
c. How much does it cost to provide food for 10 guests? Justify your answer.
Answer:
y = kx
30 = 4k
k = 30/4
k = 7.5
y = 7.5x
b. The slope 7.5 represents the unit cost for a guest.
y = 7.5 × 10
y = 75
c. Determine y for x = 10
So it costs $75 to provide food for 10 guests.

Question 22.
The distance y (in miles) you run after weeks is represented by the equation y =8x. Graph the equation and interpret the slope.
Answer:
y = 8x
Big Ideas Math 8th Grade Answer Key for Chapter 4 img_122

Question 23.
You research that hair grows 15 centimeters per year on average. The table shows your friend’s hair growth.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 cr 23
a. Does your friend’s hair grow faster than average? Explain.

Answer:
The rate of growth on average is
15/12 = 1.25 cm/month
The slope/rate of growth for your friend is
(6 – 3)/(4 – 2) = 3/2 = 1.5 cm/month
As 1.5 > 1.25, your friends hair grows faster than average.

b. In the same coordinate plane, graph the average hair growth and the hair growth of your friend. Compare and interpret the steepness of each of the graphs.
Answer:
The equation for the average growth is
y = 1.25x
The equation for the friends growth is
y = 1.5 x
Big Ideas Math 8th Grade Answer Key for Chapter 4 img_123

4.4 Graphing Linear Equations in Slope-Intercept Form (pp. 161–166)
Learning Target: Graph linear equations in slope-intercept form.

Find the slope and the -intercept of the graph of the linear equation.
Question 24.
y = -4x + 1
Answer:
y = mx + b
slope = -4 and y – intercept = 1

Question 25.
y = \(\frac{2}{3}\)x – 12
Answer:
y = mx + b
slope = \(\frac{2}{3}\) and y – intercept = -12

Question 26.
y – 7 = 0.5x
Answer:
Given the equation
y – 7 = 0.5x
y = 0.5x + 7
slope = 0.5 and y – intercept = 7

Graph the linear equation. Identify the -intercept.
Question 27.
y = 2x – 6
Answer:
Given the equation
y = 2x – 6
Comparing the above equation with slope – intercept equation
slope = 2, y – intercept = -6
Slope = rise/run = 2/1
Plot the point that is 1 unit right and 2 units up from (0, -6) = (1, -4)
BIM Grade 8 Answers Chapter 4 img_124
The line crosses the x – axis at (3, 0)
So, the x – intercept is 3.
BIM Grade 8 Answers Chapter 4 img_125

Question 28.
y = -4x + 8
Answer:
y = -4x + 8
slope = -4 and y – intercept = 8
So plot (0, 8)
Slope = rise/run = -4/1
plot the point that is 1 unit right and 4 units down from (0, 8) = (1, 4)
BIM Grade 8 Answers Chapter 4 img_126
The line crosses the x- axis at (2, 0)
So the x – intercept is 2.
BIM Grade 8 Answers Chapter 4 img_127

Question 29.
y = -x – 8
Answer:
Given the equation
y = -x – 8
comparing the above equation with sloope – intercept equation.
Slope = -1 and y – intercept = -8
Slope = rise/run = -1/1
Plot the point that is 1 unit right and 1 unit down from (0, -8) = (1, -9)
BIM Grade 8 Answers Chapter 4 img_128
The line crosses the x-axis at (-8, 0)
So, the intercept is -8.
BIM Grade 8 Answers Chapter 4 img_129BIM Grade 8 Answers Chapter 4 img_129

Question 30.
The cost y (in dollars) of one person buying admission to a fair and going on x rides is y = x + 12.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 cr 30
a. Graph the equation.
b. Interpret the y-intercept and the slope.
Answer:
y = x + 12
Comparing the above equation with slope – intercept equation.
Slope = 1 and y – intercept = 12
So plot (0, 20)
Slope = rise/run = 1/1
Plot the point that is 1 unit right and 1 unit up from (0, 12) = (1, 13)
BIM Grade 8 Answers Chapter 4 img_130
The y – intercept is 12 so the initial cost of admission is $12.
The slope is 1 so for each ride the cost of the person increases $1 per ride.

Question 31.
Graph the linear equation with slope -5 and y-intercept 0.
Answer:
y – intercept = 0. So plot (0, 0)
Plot the point that is 1 unit right and 5 unit down from (0, 0) = (1, -5)
BIM Grade 8 Answers Chapter 4 img_131

4.5 Graphing Linear Equations in Standard Form (pp. 167–172)
Learning Target: Graph linear equations in standard form.

Write the linear equation in slope-intercept form.
Question 32.
4x + 2y = -12
Answer:
4x + 2y = -12
2y = -12 – 4x
y = -6 – 2x
y = -2x – 6

Question 33.
x – y = \(\frac{1}{4}\)
Answer:
Given the equation
x – y = \(\frac{1}{4}\)
y = x – \(\frac{1}{4}\)

Graph the linear equation.
Question 34.
\(\frac{1}{4}\)x + y = 3
Answer:
\(\frac{1}{4}\)x + y = 3
y = 3 – \(\frac{1}{4}\)x
y = –\(\frac{1}{4}\)x + 3
Slope = –\(\frac{1}{4}\) and y – intercept = 3
So plot (0, 3)
Slope = rise/run = –\(\frac{1}{4}\)
Plot the point that is 4 units right and 1 unit down from (0, 3) = (4, 2)
Big Ideas Math Answers 8th Grade Chapter 4 img_132

Question 35.
-4x + 2y = 8
Answer:
-4x + 2y = 8
2y = 8 + 4x
y = 2x + 4
Slope = 2 and y – intercept = 4
So plot (0, 4)
Slope = rise/run = 2/1
Plot the point that is 1 unit right and 2 units up from (0, 4) = (1, 6)
Big Ideas Math Answers 8th Grade Chapter 4 img_133

Question 36.
x + 5y = 10
Answer:
x + 5y = 10
5y = -x + 10
y = -1/5 x + 2
Slope = -1/5 and y – intercept = 2
So, plot (0, 2)
Slope = rise/run = -1/5
Plot the point that is 5 unit right and 1 unit down from (0, 2) = (5, 1)
Big Ideas Math Answers 8th Grade Chapter 4 img_134

Question 37.
–\(\frac{1}{2}\)x + \(\frac{1}{8}\)y = \(\frac{3}{4}\)
Answer:
–\(\frac{1}{2}\)x + \(\frac{1}{8}\)y = \(\frac{3}{4}\)
\(\frac{1}{8}\)y = \(\frac{3}{4}\)  + \(\frac{1}{2}\)x
y = 4x + 6
Slope = 4 and y – intercept = 6
So plot (0, 6)
Slope = rise/run = 4/1
Plot the point that is 1 unit right and 4 units up from (0, 6) = (1, 10)
Big Ideas Math Answers 8th Grade Chapter 4 img_135

Question 38.
A dog kennel charges $30 per night to board your dog and $6 for each hour of playtime. The amount of money you spend is given by 30x + 6y = 180, where x is the number of nights and y is the number of hours of playtime. Graph the equation and interpret the intercepts.
Answer:
Given,
A dog kennel charges $30 per night to board your dog and $6 for each hour of playtime.
The amount of money you spend is given by 30x + 6y = 180,
where x is the number of nights and y is the number of hours of playtime.
30x + 6y = 180
6y = -30x + 180
y = -5x + 30
BIM Answers Grade 8 Chapter 4 img_136
The x – intercept is 6, which means that the dog can stay for 6 nights when there is no playtime.
The y – intercept is 30, which means the dog can play for 30 hours when he does not spend any night at the kennel.

4.6 Writing Equations in Slope-Intercept Form (pp. 173–178)
Learning Target: Write equations of lines in slope-intercept form.

Write an equation in slope-intercept form of the line that passes through the given points.
Question 39.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 cr 39
Answer:
m = (y2 – y1)/(x2 – x1)
m = (1 – (-2))/(3 – 0)
m = (1 + 2)/(3 – 0)
m = 3/3
m = 1
We have to find the y – intercept because the line crosses the y – axis at (0, -2)
y = mx + b
y = x – 2

Question 40.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 cr 40
Answer:
m = (y2 – y1)/(x2 – x1)
m = (4 – 2)/(0 – 4)
m = 2/-4
m = -1/2
We have to find the y – intercept because the line crosses the y – axis at (0, 4)
y = mx + b
y =-1/2 x + 4

Question 41.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 cr 41
Answer:
m = (y2 – y1)/(x2 – x1)
m = (-2 – 1)/(2 – 0)
m = -3/2
We have to find the y – intercept because y = 1 when x = 0, the y – intercept is 1.
y = mx + b
y = -3/2 x + 1

Question 42.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 cr 42
Answer:
m = (y2 – y1)/(x2 – x1)
m = (-1 – (-3))/(1 – 0)
m = 2/1
m = 2
We have to find the y – intercept because y = -3 when x = 0, the y – intercept is -3.
y = mx + b
y = 2x + (-3)
y = 2x – 3

Question 43.
Write an equation of the line that passes through (0, 8) and (6, 8).
Answer:
m = (y2 – y1)/(x2 – x1)
m = (8 – 8)/(6 – 0)
m = 0/6
m = 0
We have to find the y – intercept because y = 8 when x = 0, the y – intercept is 8.
y = mx + b
y = (0) x + 8
y = 8

Question 44.
Write an equation of the line that passes through (0, -5) and (-5, -5).
Answer:
m = (y2 – y1)/(x2 – x1)
m = (-5 – (-5))/(-5 – 0)
m = 0/-5
m = 0
We have to find the y – intercept because y = -5 when x = 0, the y – intercept is -5
y = mx + b
y = (0) x + (-5)
y = -5

Question 45.
A construction crew is extending a highway sound barrier that is 13 miles long. The crew builds \(\frac{1}{2}\) of a mile per week. Write an equation in slope -intercept form that represents the length y (in miles) of the barrier after x weeks.
Answer:
Given,
A construction crew is extending a highway sound barrier that is 13 miles long.
The crew builds \(\frac{1}{2}\) of a mile per week.
y = mx + b
m = \(\frac{1}{2}\)
b = 13
y = \(\frac{1}{2}\)x + 13

4.7 Writing Equations in Point-Slope Form (pp. 179–184)
Learning Target: Write equations of lines in point-slope form.

Write an equation in point-slope form of the line that passes through the given point and has the given slope.
Question 46.
(4, 4); m = 3
Answer:
y – y1 = m(x – x1)
Substitute m value, x and y value in the equation
y – (4) = 3(x – 4)
y – 4 = 3(x – 4)

Question 47.
(2, -8); m = –\(\frac{2}{3}\)
Answer:
y – y1 = m(x – x1)
Substitute m value, x and y value in the equation
y – (-8) = –\(\frac{2}{3}\)(x – 2)
y + 8 = –\(\frac{2}{3}\)(x – 2)

Write an equation in slope-intercept form of the line that passes through the given points.
Question 48.
(-4, 2), (6, -3)
Answer:
m = (y2 – y1)/(x2 – x1)
m = (-3 – 2)/(6 – (-4))
m = -5/10
m = -1/2
y – y1 = m(x – x1)
Substitute m value, x and y value in the equation
y – 2 = –\(\frac{1}{2}\)(x – (-4))
y – 2 = –\(\frac{1}{2}\)(x + 4)
y = –\(\frac{1}{2}\)x

Question 49.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 cr 49
Answer:
m = (y2 – y1)/(x2 – x1)
m = (5 – 1)/(3 – 2)
m = 4/1
m = 4
y – y1 = m(x – x1)
Substitute m value, x and y value in the equation
y – (-3) = 4(x – 1)
y + 3 = 4x – 4
y = 4x – 7

Question 50.
The table shows your elevation y (in feet) on a ski slope after x minutes.
Big Ideas Math Answers Grade 8 Chapter 4 Graphing and Writing Linear Equations 4.7 cr 50
a. Write an equation that represents your elevation after x minutes.

Answer:
m = (600 – 800)/(2 – 1)
m = -200
800 = -200(1) + b
800 = -200 + b
800 + 200 = b
b = 1000 feet

b. What is your starting elevation?

Answer:
The starting elevation is the y – intercept
b = 1000 feet

c. After how many minutes do you reach the bottom of the ski slope? Justify your answer.
Answer:
0 = -200x + 1000
0 – 1000 = -200x
-1000 = -200x
200x = 1000
x = 5 minutes

Question 51.
A company offers cable television at$29.95 per month plus a one-time installation fee. The total cost for the first six months of service is $214.70. a. Write an equation in point-slope form that represents the total cost you pay for cable television after x months.
b. How much is the installation fee? Justify your answer.
Answer:
y – y1 = m(x – x1)
m = 29.95
y – 214.70 = 29.95(x – 6)
y – 214.70 + 214.70 = 29.95x – 179.97 + 2147.70
y = 29.95x + 35
b = 35

Question 52.
When might it be better to represent an equation in point-slope form rather than slope-intercept form? Use an example to justify your answer.
Answer:
When we are given the slope and a point that is the y – intercept, then the easiest way is to use the slope – intercept form y = mx + b
Example:
m = 2
(0, 5)
y = 2x + 5
m = 2
(1, 3)
y – 3 = 2(x – 1)
Easier when given the slope and a point that is not the y – intercept.

Graphing and Writing Linear Equations Practice Test

Find the slope and the -intercept of the graph of the linear equation.
Question 1.
y = 6x – 5
Answer:
y = 6x – 5
Slope = 6 and y – intercept = -5

Question 2.
y – 1 = 3x + 8.4
Answer:
Given the equation
y – 1 = 3x + 8.4
y = 3x + 8.4 + 1
y = 3x + 9.4
Slope = 3 and y – intercept = 9.4

Question 3.
–\(\frac{1}{2}\)x + 2y = 7
Answer:
Given the equation
–\(\frac{1}{2}\)x + 2y = 7
y = \(\frac{1}{4}\)x + \(\frac{7}{2}\)
Slope = \(\frac{1}{4}\) and y – intercept = \(\frac{7}{2}\)

Graph the linear equation.
Question 4.
y = –\(\frac{1}{2}\)x – 5
Answer:
Given the equation
y = –\(\frac{1}{2}\)x – 5
Slope = –\(\frac{1}{2}\) and y – intercept = -5
So plot (0, -5)
Plot the point that is 2 units right and 1 unit down from (0, -5) = (2, -6)
Draw a line through the two points.
BIM Grade 8 Answers Chapter 4 img_108

Question 5.
-3x + 6y = 12
Answer:
Given the equation
-3x + 6y = 12
6y = 3x + 12
y = \(\frac{1}{2}\)x + 2
Slope = \(\frac{1}{2}\), y – intercept = 2
Slope = rise/run = \(\frac{1}{2}\)
Plot the point that is 2 units right and 1 unit up from (0, 2) = (2, 3)
BIM Grade 8 Answers Chapter 4 img_109

Question 6.
y = \(\frac{2}{3}\)x
Answer:
Given the equation
y = \(\frac{2}{3}\)x
Slope = \(\frac{2}{3}\), y – intercept = 0
Slope = rise/run = \(\frac{2}{3}\)
Plot the point that is 3 units right and 2 unit up from (0, 0) = (3, 2)
Big Ideas Math Answers Grade 8 Ch 4 img_109

Question 7.
Which lines are parallel? Explain.
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation pt 7
Answer:
Red line:
(x1, y1) = (-4, 1)
(x2, y2) = (2, 4)
m = (y2 – y1)/(x2 – x1)
m = (4 – 1)/(2 – (-4))
m = 3/6
m = 1/2
Blue line:
(x1, y1) = (-4, -1)
(x2, y2) = (2, 0.5)
m = (y2 – y1)/(x2 – x1)
m = (0.5 – (-1))/(2 – (-4))
m = 1.5/6
m = 1/4
Green Line:
(x1, y1) = (-2, -4)
(x2, y2) = (2, -2)
m = (y2 – y1)/(x2 – x1)
m = (-2 – (-4))/(2 – (-2))
m = 2/4
m = 1/2
Red lines and Green lines are parallel because both have same slope = 1/2

Question 8.
The points in the table lie on a line. Find the slope of the line.
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation pt 8
Answer:
(x1, y1) = (-1, -4)
(x2, y2) = (0, -1)
m = (y2 – y1)/(x2 – x1)
m = (-1 – (-4))/(0 – (-1))
m = 3/1
m = 3

Write an equation in slope-intercept form of the line that passes through the given points.
Question 9.
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation pt 9
Answer:
(x1, y1) = (-4, 1)
(x2, y2) = (2, 4)
m = (y2 – y1)/(x2 – x1)
m = (-5 – (-1))/(3 – 0)
m = -4/3
Because the line crosses the y – axis at (0, -1), the y – intercept is -1.
y = mx + b
y = -4/3x – 1

Question 10.
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation pt 10
Answer:
m = (y2 – y1)/(x2 – x1)
m = (2 – 2)/(0 – (-2))
m = 0/2
m = 0
Because y = 2 when x =0, the y – intercept is 2.
y = mx + b
y = 2

Question 11.
Write an equation in point-slope form of the line that passes through (-4, 1) and (4, 3).
Answer:
m = (y2 – y1)/(x2 – x1)
m = (3 – 1)/(4 – (-4))
m = 2/8
m = 1/4
y – y1 = m(x – x1)
y – 1 = 1/4(x – (-4))
y – 1 = 1/4(x + 4)

Question 12.
The number y of new vocabulary words that you learn after x weeks is represented by the equation y = 15x.
a. Graph the equation and interpret the slope.
b. How many new vocabulary words do you learn after 5 weeks?
c. How many more vocabulary words do you learn after 6 weeks than after 4 weeks?
Answer:
a. 8th Grade Big Ideas Math Answer Key Chapter 4 img_109
b. y = 15 . 5
y = 75 words
c. 15 . 6 – 15 . 4 = 90 – 60 = 30 words

Question 13.
You used $90 worth of paint for a school float. The amount of money you spend is given by 18x + 15y = 90, where x is the number of gallons of blue paint and y is the number of gallons of white paint. Graph the equation and interpret the intercepts.
Answer:
Given,
18x + 15y = 90
15y = -18x + 90
y = -6/5 x + 6
8th Grade Big Ideas Math Answer Key Chapter 4 img_110
The x – intercept is 5 and shows that 5 gallons of blue paint might be bought when no gallon of the white pants is bought.
The y – intercept is 6 and shows that 6 gallons of white paint might be bought when no gallon of blue is bought.

Graphing and Writing Linear Equations Cumulative Practice

Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation cp 1
Question 1.
Which equation matches the line shown in the graph?
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation cp 2
A. y =2x – 2
B. y = 2x + 1
C. y = x – 2
D. y = x + 1
Answer:
m = (-2 – 0)/(0 – 1)
m = 2
y = 2x – 2
Thus the correct answer is option A.

Question 2.
Which point lies on the graph of 6x – 5y = 14?
F. (-4, -1)
G. (-2, 4)
H. (-1, -4)
I. (4, -2)
Answer:
6x – 5y = 14
F. 6(-4) – 5(-1) = 14
-24 + 5 = 14
-19 ≠ 14
G. 6(-2) – 5(4) = 14
-12 – 20 = 14
-32 ≠ 14
H. 6(-1) – 5(-4) = 14
-6 + 20 = 14
14 = 14
Thus the correct answer is option H.

Question 3.
You reflect the triangle in the x-axis. What are the coordinates of the image?
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation cp 3
A. X'(4, 1), Y'(2, 3), Z'(-2, 1)
B. X'(4, -1), Y'(2, -3), Z'(-2, -1)
C. X'(-4, -1), Y(-2, -3), Z'(2, -1)
D. X'(1, 4), Y'(3, 2), Z'(1, -2)
Answer:
BIM 8th Grade Solution Key ch 4 img_108
Thus the correct answer is option C.

Question 4.
Which of the following is the equation of a line parallel to the line shown in the graph?
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation cp 4
Answer:
m = (-4 – 2)/(6 – 4)
m = -6/2
m = -3
Two lines parallel if they have the same slope.
From the given equations, the one having the slope -3 is y = -3x + 5
Thus the correct answer is option H.

Question 5.
What is the value of x?
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation cp 5
Answer:
122 = 47 + x
47 + x = 122
x = 122 – 47
x = 75

Question 6.
An emergency plumber charges $49.00 plus $70.00 per hour of the repair. A bill to repair your sink is $241.50. This can be modeled by 70.00 h + 49.00 = 241.50, where h represents the number of hours for the repair. How many hours did it take to repair your sink?
A. 2.75 hours
B. 3.45 hours
C. 4.15 hours
D. 13,475 hours
Answer:
70.00 h + 49.00 = 241.50
70h = 241.50 – 49
70h = 192.5
h = 2.75 hours
Thus the correct answer is option A.

Question 7.
It costs $40 to rent a car for one day. In addition, the rental agency charges you for each mile driven, as shown in the graph.
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation cp 7
Part A Determine the slope of the line joining the points on the graph.
Part B Explain what the slope represents.
Answer:
m = (50 – 40)/(100 – 0)
m = 10/100
m = 0.1

Question 8.
What value of makes the equation true?
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation cp 8
7 + 2x = 4x – 5
Answer:
7 + 2x = 4x – 5
2x – 4x = -5 – 7
-2x = -12
x = 6

Question 9.
Trapezoid KLMN is graphed in the coordinate plane shown.
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation cp 9
Rotate Trapezoid KLMN 90° clockwise about the origin. What are the coordinates of point M’, the image of point M after the rotation?
F. (-3, -2)
G. (-2, -3)
H. (-2, 3)
I. (3, 2)
Answer: M'(-3, -2)
Thus the correct answer is option F.

Question 10.
Solve the formula K = 3M – 7.
A. M = K + 7
B. M = \(\frac{K+7}{3}\)
C. M = \(\frac{K}{3}\) + 7
D. M = \(\frac{K-7}{3}\)
Answer:
K = 3M – 7
K + 7 = 3M
M = \(\frac{K+7}{3}\)
Thus the correct answer is option B.

Question 11.
What is the distance across the canyon?
Big Ideas Math Solutions Grade 8 Chapter 4 Exponents and Scientific Notation cp 11
F. 3.6 ft
G. 12 ft
H. 40 ft
I. 250 ft
Answer:
100/30 = d/12
3d = 12 × 10
3d = 120
d = 40 feet
Thus the correct answer is option H.

Conclusion:

All the solutions in the above article are beneficial for all the students of middle school students. All the solutions are prepared by the math professionals. The solutions are given clearly with step by step explanations. If you have any doubts regarding the chapter we are always ready to clarify your doubts. All you have to do is to post the comments in the below comment box.

Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles

Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles

Get Big Ideas Math Answer Key for Grade 7 Chapter 9 Geometric Shapes and Angles Pdf here. We are providing free download links to all problems in the upcoming sections. You can understand the concept easily as we are explaining the concept with so many real-time examples. Candidates can improve their problem-solving skills and analytical thinking with the help of Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles.

BIM Grade 7 Chapter 9 Geometric Shapes and Angles Answer Key pdf. Download all the pdf links from here for free of cost and kickstart your exam preparation. Follow the various concepts and solve as many problems as before going to the exam. We are providing the preparatory material for the candidates to score better marks in the exam. Grade 7 Big Ideas Math Answers is providing amazing tips and tricks in the next sections. Check it out!!

Big Ideas Math Book 7th Grade Answer Key 9 Geometric Shapes and Angles

If it is some theory, then you can easily learn it but if it is problematic, then you must have perfection and grip on the subject. Therefore, we are providing a lot of practice material with solutions. First, read the question and try to solve the problems without looking at the solutions. Then refer to the solution and know if it is correct or not. Also, check if it the easiest process or not. With the help of professionals and math experts, we gave the solution to the problems in the easiest methods.

You need not be the expert in all the topics but you must check the easy topics like Geometric Shapes and Angles and prepare perfectly. These topics act as a scoring factor because they are easy to understand and solve. If you have any further doubts, go through Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles, you will get a clear idea about every detail.

Performance Task

Lesson: 1 Circle and Circumference

Lesson: 2 Areas of Circles

Lesson: 3 Perimeters and Areas of Composite Figures

Lesson: 4 Constructing Polygons

Lesson: 5 Finding Unknown Angle Measures

Chapter 9 – Geometric Shapes and Angles

Geometric Shapes and Angles STEAM Video/Performance Task

STEAM Video

Track and Field
Different lanes on a race track have different lengths. How can competitors run in different lanes and have the same finish line?

Watch the STEAM Video “Track and Field.” Then answer the following questions.
1. A track consists of a rectangle and two semicircles. The dimensions of the rectangle formed by the innermost lane are shown. What is the distance around each semicircle on the 400-meter, innermost lane?
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 1
2. How does the width of the rectangle, 63.7 meters, compare to the distance around each semicircle? Explain.

Answer:
1. The distance around each semicircle on the 400-meter, innermost lane = 488 m
2. The distance around each semicircle = 90π + 320

Explanation:
1. The inside perimeter of the track = 400 m
the total length of the two straight portions = 90 + 90 = 180
therefore the length of the remaining portion = 400-180 = 220 m
circumference of the two remaining semi-circular portions = πr + πr = 2πr
2πr = 220
2 x 3.14 x r = 220
r = 35 m
Area of the track = 2 x 90 x 14 +3.14 x (49) x (49) – (35) x (35)
area of the track = 6216 square meter
length of the outer running track = 488 m
2. The perimeter of the track is the two circumferences of the circumferences.
The diameters of the circle and the width of the rectangle = 90 m
90 π + 320
Performance Task.
Finding the Area and Perimeter of a Track
After completing this chapter, you will be able to use the concepts you learned to answer the questions in the STEAM Video Performance Task. You will be given the dimensions of a race track.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 2
You will be asked to solve various perimeter and area problems about the track. Given a race track, what measures do you need to find the outer perimeter?

Answer:
The outer perimeter = 11,2610 sq m

Explanation:
perimeter of the semicircle = (π + 2 ) r
p = (3.14 + 2)36.5
p= (3.16) 36.5
p = 11,2610 sq m

Geometric Shapes and Angles Getting Ready for Chapter 9

Chapter Exploration
Work with a partner.
Question 1.
Perform the steps for each of the figures.

  • Measure the perimeter of the larger polygon to the nearest millimeter.
  • Measure the diameter of the circle to the nearest millimeter.
  • Measure the perimeter of the smaller polygon to the nearest millimeter.
  • Calculate the value of the ratio of the two perimeters to the diameter.
  • Take the average of the ratios. This average is the approximation of π(the Greek letter ).
    Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 3

Question 2.
Based on the table, what can you conclude about the value of π? Explain your reasoning.

Answer:
The value of π = 3.14

Explanation:
We can consider 3 values for the π.
they are (22/7) or 3.14
so i am considering the 3.14

Question 3.
The Greek mathematician Archimedes used the above procedure to approximate the value of π. He used polygons with 96 sides. Do you think his approximation was more or less accurate than yours? Explain your reasoning.
Answer:
The greek mathematician used polygons with the side of polygons as 12,14,48, and finally 96 sides.

Explanation:
The greek mathematician used polygons with the side of polygons as 12,14,48, and finally 96 sides.
yes the accuration is more than i think.

Vocabulary
The following vocabulary terms are defined in this chapter. Think about what each term might mean and record your thoughts.
diameter of a circle
semi circle
adjacent angles
circumference
composite figure
vertical angles

Answer:
The diameter of the circle = the diameter is the length of the line through the center that touches two points on the edge of the circle.
semi circle =  semicircle is a one-dimensional locus of points that forms half of the circle.
adjacent angles = adjacent angles are two angles that have a common vertex and a common side but do not overlap.
circumference = the circumference is the perimeter of the circle. the circumference would be the arc length of the circle.
composite figure = a figure that consists of two or more geometric shapes.
vertical angles = a pair of non-adjacent angles form when two lines intersect.

Explanation:
The diameter of the circle = the diameter is the length of the line through the center that touches two points on the edge of the circle.
semi circle =  semicircle is a one-dimensional locus of points that forms half of the circle.
adjacent angles = adjacent angles are two angles that have a common vertex and a common side but do not overlap.
circumference = the circumference is the perimeter of the circle. the circumference would be the arc length of the circle.
composite figure = a figure that consists of two or more geometric shapes.
vertical angles = a pair of non-adjacent angles form when two lines intersect.

Lesson 9.1 Circles and Circumference

EXPLORATION 1

Using a Compass to Draw a Circle
Work with a partner. Set a compass to 2 inches and draw a circle.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 1
a. Draw a line from one side of the circle to the other that passes through the center. What is the length of the line? This is called the diameter of the circle.
b. Estimate the distance around the circle. This is called the circumference of the circle. Explain how you found your answer.

Answer:
a. the length of the line = 4 inches
b.  The circumference of the circle = 12.56 inch

Explanation:
a. In the question they said that 2 inches
the length of the line = 4 in
b. the circumference of the circle = 2π r
circle = 2 x 3.14 x 2
circle = 12.56 in

EXPLORATION 2

Exploring Diameter and Circumference
Work with a partner.
a. Roll a cylindrical object on a flat surface to find the circumference of the circular base.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 2
b. Measure the diameter of the circular base. Which is greater, the diameter or the circumference? how many times greater?
c. Compare your answers in part(b) with the rest of the class. What do you notice?
d. Without measuring, how can you find the circumference of a circle with a given diameter? Use your method to estimate the circumference of the circle in Exploration 1.

Answer:
a. The circumference of the circle = 2πr
b. The circumference of the circle is 3.14 times greater than the diameter of the circle.
c. The circumference of the circle is greater than the diameter of the circle.
d. The diameter of the circle = 2r and the circumference of the circle = 2πr

Explanation:
a. The circumference of the circle = 2πr
b. The circumference of the circle is 3.14 times greater than the diameter of the circle.
c. The circumference of the circle is greater than the diameter of the circle.
d. The diameter of the circle = 2r and the circumference of the circle = 2πr

Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 3

Try It

Question 1.
The diameter of a circle is 16 centimeters. Find the radius.

Answer:
radius = 8 cm

Explanation:
The diameter of the circle = 2r
16 = 2r
r = 8 cm

Question 2.
The radius of a circle is 9 yards. Find the diameter.

Answer:
The diameter = 18 yds

Explanation:
The diameter of the circle = 2r
diameter = 2 x 9
r = 18 yds

Find the circumference of the object. Use 3.14 or \(\frac{22}{7}\) for π.
Question 3.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 4

Answer:
circumference = 12.56 cm

Explanation:
circumference of the circle =2πr
circle = 2 x 3.14 x 2 where r = 2cm given
circle = 6.28 x 2
circle = 12.56 cm

Question 4.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 5

Answer:
circumference =43.96 square feet

Explanation:
circumference of the circle =2πr
circle = 2 x 3.14 x 7 where r = 7 ft given
circle = 6.28 x 7
circle = 43.96 square feet

Question 5.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 6

Answer:
circumference =28.26 square in

Explanation:
circumference of the circle =2πr
circle = 2 x 3.14 x 4.5 where r = 4.5 is given
circle = 6.28 x 4.5
circle =28.26 in

Find the perimeter of the semicircular region.
Question 6.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 7

Answer:
perimeter of the semicircle =  5.14 ft

Explanation:
perimeter of the semicircle = (π + 2 ) r
perimeter = (3.14 + 2) 1 diameter = 2 given r= 1
perimeter = 5.14 feet

Question 7.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 8

Answer:
perimeter of the semicircle =  17.99 cm

Explanation:
perimeter of the semicircle = (π + 2 ) r
perimeter = (3.14 + 2) 3.5 diameter = 7 given r= 3.5
perimeter = 17.99 cm

Question 8.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 9

Answer:
the perimeter of the semicircle =  33.14 in

Explanation:
perimeter of the semicircle = (π + 2 ) r
perimeter = (3.14 + 2) 15 given r= 15
perimeter = 33.14 in

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 9.
WRITING
Are there circles for which the value of the ratio of circumference to diameter is not equal to π? Explain.

Answer:
circumference to diameter is equal to π

Explanation:
d. The diameter of the circle = 2r and the circumference of the circle = 2πr
circumference to diameter is equal to π

Question 10.
FINDING A PERIMETER
Find the perimeter of a semicircular region with a straight side that is 8 yards long.

Answer:
perimeter = 11.14 yd

Explanation:
perimeter of the semicircle = (π + 2 ) r
perimeter = (3.14 + 2) 4 given r= 4
perimeter = 11.14 yd
Question 11.
DIFFERENT WORDS, SAME QUESTION
Which is different? Find “both” answers.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 10

Answer:
What is π times the radius?
What is π times the diameter?

Explanation:
the radius of the circle = (c/2 π )
the diameter of the circle =  2r
Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 12.
The wheels of a monster truck are 66 inches tall. Find the distance the monster truck travels when the tires make one 360-degree rotation.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 11

Answer:
The distance = 207.35 inches

Explanation:
The wheel is in the shape of a circle.
diameter = 66 given
radius = (66/2)
radius = 33
The circumference = 2πr
c = 2 x 3.14 x 33
c = 6.28 x 33
c = 207.24 in

Question 13.
DIG DEEPER!
The radius of a dog’s collar should be at least 0.5 inch larger than the radius of the dog’s neck. A dog collar adjusts to a circumference of 10 to 14 inches. Should the collar be worn by a dog with a neck circumference of 12.5 inches? Explain.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 12

Answer:
No, the collar should not be worn by this dog.

Explanation:
Given that the collar should be at least 0.5 inches.
dog collar adjusts to a circumference of 10 to 14 inches.

Question 14.
You resize a picture so that the radius of the midday Sun appears four times larger. How much larger does the circumference of the Sun appear? Explain.

Answer:
4 times larger

Explanation:
they said that if they resize it for 4 times.
therefore the sun appears 4 times larger.

Circles and Circumference Homework & Practice 9.1

Review & Refresh

Two jars each contain 1000 numbered tiles. The double box-and-whisker plot represents a random sample of 10 numbers from each jar.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 13
Question 1.
Compare the samples using measures of center and variation.

Answer:
a. Jar A = median 3, starting 2.
b. Jar B = median  6, starting 2

Explanation:
In the above-given figure, the jar A is starting from 2
jar A contains median = 3
the jar B is starting from 2
jar B contains median = 6

Question 2.
Can you determine which jar contains greater numbers? Explain.

Answer:
Jar B

Explanation:
jar B contains the numbers from 4 to 9
Question 3.
Find the percent of change from 24 to 18.
A. 25% decrease
B. 25% increase
C. 75% increase
D. 75% decrease

Answer:
option A is correct

Explanation:
if the percent of jar changes from 24 to 18
the decrease in the percent = 25

Concepts, Skills, & Problem Solving
EXPLORING DIAMETER AND CIRCUMFERENCE Estimate the circumference of the circular base of the object. (See Exploration 2, p. 361.)
Question 4.
tube of lip balm with radius 0.5 mm

Answer:
c = 3.14 mm

Explanation:
circumference of the circle =2πr
circle = 2 x 3.14 x 0.5 where r = 0.5 mm given
circle = 6.28 x 0.5
circle =3.14 mm

Question 5.
D battery with radius 0.65 in.

Answer:
c = 4.082 in

Explanation:
circumference of the circle =2πr
circle = 2 x 3.14 x 0.65 where r = 0.65 ingiven
circle = 6.28 x 0.65
circle =4.082 in

FINDING A RADIUS Find the radius of the button.
Question 6.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 14

Answer:
radius =2.5 cm

Explanation:
radius = (5/2)
radius = 2.5 cm

Question 7.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 15

Answer:
radius =14 mm

Explanation:
radius = (28/2)
radius = 14 mm

Question 8.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 16

Answer:
radius =1.75 in

Explanation:
radius = (3.5/2)
radius = 1.75 in

FINDING A DIAMETER Find the diameter of the object.
Question 9.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 17

Answer:
diameter = 4 in

Explanation:
diameter of the circle = 2r
where r = 2 given
d = 4 in

Question 10.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 18

Answer:
diameter = 0.64 ft

Explanation:
diameter of the circle = 2r
where r = 0.8 given
d = 0.64 ft

Question 11.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 19

Answer:
diameter = 1.2 cm

Explanation:
diameter of the circle = 2r
where r = 0.6 given
d = 1.2 cm

FINDING A CIRCUMFERENCE Find the circumference of the object. Use 3.14 or \(\frac{22}{7}\) for π.
Question 12.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 20

Answer:
c = 43.96 in

Explanation:
circumference of the circle =2πr
circle = 2 x 3.14 x 7 where r = 7 ingiven
circle = 6.28 x 7
circle =43.96 in

Question 13.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 21

Answer:
c = 18.84 cm

Explanation:
circumference of the circle =2πr
circle = 2 x 3.14 x 7 where r = 3 cmgiven
circle = 6.28 x 3
circle =18.84 cm

Question 14.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 22

Answer:
c = 6.28 mm

Explanation:
circumference of the circle =2πr
circle = 2 x 3.14 x 1where r = 1mgiven
circle = 6.28 x 1
circle =6.28 m

FINDING THE PERIMETER OF A SEMICIRCULAR REGION Find the perimeter of the window.
Question 15.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 23

Answer:
perimeter = 7.71 ft

Explanation:
perimeter of the semicircle = (π + 2 ) r
perimeter = (3.14 + 2) 1.5 given d =3 ,r = (d/2)
perimeter = 7.71 ft

Question 16.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 24

Answer:
perimeter = 64.8 cm

Explanation:
perimeter of the semicircle = (π + 2 ) r
perimeter = (3.14 + 2) 20 given  ,r = 20 cm
perimeter = 64.8 cm

ESTIMATING A RADIUS Estimate the radius of the object.
Question 17.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 25

Answer:
Radius = 1.417 mm

Explanation:
radius of the circle = (c/2π )
r = (8.9/6.28)
r = 1.417 mm

Question 18.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 26

Answer:
Radius = 19.426 in

Explanation:
radius of the circle = (c/2π )
r = (122/6.28)
r = 19.426 in

Question 19.
MODELING REAL LIFE
A circular sinkhole has a circumference of 75.36 meters. A week later, it has a circumference of 150.42 meters.
a. Estimate the diameter of the sinkhole each week.
b. How many times greater is the diameter of the sinkhole a week later?

Answer:
a. The diameter of the sinkhole each week = 4 in
b. 2 times greater is the diameter of the sinkhole a week later

Explanation:
a. The diameter of the sinkhole each week = 75.36 m
b. 2 times greater is the diameter of the sinkhole a week later
75.36 x 75.36 = 150.42 m
Question 20.
REASONING
Consider the circles A, B, C, and D.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 27
a. Without calculating, which circle has the greatest circumference? Explain.
b. Without calculating, which circle has the least circumference? Explain.

Answer:
a. option D has the greatest circumference.
b. option C has the least circumference.

Explanation:
D. circumference of the circle =2πr
circle = 2 x 3.14 x 50where r =50 ingiven
circle = 6.28 x 50
circle =314 in
Explanation:
C. circumference of the circle =2πr
circle = 2 x 3.14 x 1where r = 1given
circle = 6.28 x1
circle = 6.28
Explanation:
A. circumference of the circle =2πr
circle = 2 x 3.14 x 4 where r = 4given
circle = 6.28 x 4
circle = 25.12
Explanation:
A. circumference of the circle =2πr
circle = 2 x 3.14 x 10 where r = 10given
circle = 6.28 x 10
circle = 62.8

FINDING CIRCUMFERENCES Find the circumferences of both circles.
Question 21.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 28

Answer:
circumference of inside circle  =31.4 square cm
circumference of outside circle = 62.8  square cm

Explanation:
circumference of the inside circle =2πr
circle = 2 x 3.14 x 5 where r = 5 cm given
circle = 6.28 x 5
circle = 31.4 square cm
circumference of the outside circle =2πr
circle = 2 x 3.14 x 2 where r = 2 cm given
circle = 6.28 x 2
circle = 62.8 square cm

Question 22.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 29

Answer:
circumference of inside circle  =28.26 ft
circumference of outside circle = 31.4 square cm

Explanation:
circumference of the inside circle =2πr
circle = 2 x 3.14 x 4.5 where r = 4.5 feet given
circle = 6.28 x 4.5
circle = 28.26 ft
circumference of the outsideside circle =2πr
circle = 2 x 3.14 x 2.5 where r = 2.5 ft given
circle = 6.28 x 2.5
circle = 15.7 square ft

Question 23.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 30

Answer:
circumference of inside circle  =69.08  m
circumference of outside circle = 138.16 m

Explanation:
circumference of the inside circle =2πr
circle = 2 x 3.14 x 5.5 where r = 5.5 feet given
circle = 6.28 x 5.5
circle = 69.08 m
circumference of the outsideside circle =2πr
circle = 2 x 3.14 x 22 where r = 22given
circle = 6.28 x 22
circle = 138.16 m

Question 24.
MODELING REAL LIFE
A satellite is in an approximately circular orbit 36,000 kilometers from Earth’s surface. The radius of Earth is about 6400 kilometers. What is the circumference of the satellite’s orbit?
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 31

Answer:
c = 40,192 km

Explanation:
circumference of the  satellite orbit =2πr
circle = 2 x 3.14 x 6400where r = 6400kmgiven
circle = 6.28 x 6400
circle =40,192km

Question 25.
STRUCTURE
The ratio of circumference to diameter is the same for every circle. Is the ratio of circumference to radius the same for every circle? Explain.

Answer:
The ratio of circumference to radius is  same for every circle.

Explanation:
c/r = 2πr/r
where r get canceled in both numerator and denominator.
c/r = 2π
radius = (c/2π)
the radius is same for every circle.

Question 26.
PROBLEM SOLVING
A wire is bent to form four semicircles. How long is the wire? Justify your answer.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 32

Answer:
The wire is 128 cm long

Explanation:
Given that the four semicircles are 32 cm
32 + 32 + 32 + 32 = 64

Question 27.
CRITICAL THINKING
Explain how to draw a circle with a circumference of π2 inches. Then draw the circle.

Answer:

Explanation:
circumference of circle = 2πr
c = π2

Question 28.
DIG DEEPER!
“Lines” of latitude on Earth are actually circles. The Tropic of Cancer is the northernmost line of latitude at which the Sun appears directly overhead at noon. The Tropic of Cancer has a radius of 5854 kilometers.
To qualify for an around-the-world speed record, a pilot must cover a distance no less than the circumference of the Tropic of Cancer, cross all meridians, and land on the same air field where the flight began.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 33
a. What is the minimum distance that a pilot must fly to qualify for an around-the-world speed record?
b. RESEARCH Estimate the time it will take for a pilot to qualify for the speed record. Explain your reasoning.

Answer:
a. The minimum distance that a pilot must fly to qualify for an around the world-speed record = 18.3376 km
b. The pilot will take for the speed record = 18.3376 km

Explanation:
a. The minimum distance that a pilot must fly to qualify for an around the world-speed record = 18.3376 km
b. The pilot will take for the speed record = 18.3376 km
Question 29.
PROBLEM SOLVING
Bicycles in the late 1800s looked very different than they do today.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 34
a. How many rotations does each tire make after traveling 600 feet? Round your answers to the nearest whole number.
b. Would you rather ride a bicycle made with two large wheels or two small wheels? Explain.

Answer:
a. The rotations each tire make after traveling 600 feet = 188.4 in in
b. two large wheels = 376.8 in
two small wheels = 113.04 in

Explanation:
the rotations each tire make after travelling = 2 x 3.14 x 30  = 188.4 in
b. two large wheels = 188.4 x 2 = 376.8 in
for two small wheels = 113.04 in

Question 30.
LOGIC
The length of the minute hand is 150% of the length of the hour hand.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.1 35
a. What distance will the tip of the minute hand move in 45 minutes? Justify your answer.
b. In 1 hour, how much farther does the tip of the minute hand move than the tip of the hour hand? Explain how you found your answer.

Answer:
The distance will the tip of minute hand move in 45 minutes = 140 %
b. the tip of the minute hand moves 60 times faster than hour hand.

Explanation:
The distance will the tip of minute hand move in 45 minutes = 140 %
b. the tip of the minute hand moves 60 times faster than hour hand.

Lesson 9.2 Areas of Circles

EXPLORATION 1

Estimating the Area of a Circle
Work with a partner. Each grid contains a circle with a diameter of 4 centimeters. Use each grid to estimate the area of the circle. Which estimate should be closest to the actual area? Explain.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 1

Answer:
Area of 1st circle = 200.96 cm
Area of 2nd circle =803.84 cm
Area of 3rd circle =3215.36 cm

Explanation:
area of 1st circle = πr x r
area = 3.14 x 8 x 8
a = 200.96 cm
area of 2nd circle = πr x r
area= 3.14 x 16 x 16
a = 803.84 cm
area of 3rd circle = πr x r
area= 3.14 x 32 x 32
a = 3215.36
EXPLORATION 2

Writing a Formula for the Area of a Circle
Work with a partner. A student draws a circle with radius and divides the circle into 24 equal sections. The student cuts out each section and arranges the sections to form a shape that resembles a parallelogram.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 2
a. Use the diagram to write a formula for the area of a circle in terms of the radius r. Explain your reasoning.Describe the relationship between the radius and the area of a circle.
b. Use the formula to check your estimates in Exploration 1.

Answer:
a. the area of the circle = 1808.64
b. the area of the circle in terms of radius r = 0.0084 cm

Explanation:
The area  of circle = πr x r
a = 3.14 x 24 x 24
a = 1808.64 cm
The radius of the circle = (c/2 π)
circumference = 2πr
c = 2 x 3.14 x 24
c = 150.72 cm
area = (150.72/6.28)
area = 0.0084 cm

Try It
Question 1.
Find the area of a circle with a radius of 6 feet. Use 3.14 for π.

Answer:
The area  of circle = 113.04 sq ft

Explanation:
The area  of circle = πr x r
a = 3.14 x 6 x 6
a = 113.04 square feet
Question 2.
Find the area of a circle with a diameter of 28 meters.Use \(\frac{22}{7}\) for π.

Answer:
The area  of circle = 175.84 sq meters

Explanation:
The area  of circle = πr x r
a = 3.14 x 14 x 14 where d = 28 so r = 14
a = 175.84 square meters

Find the area of the semicircle.
Question 3.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 3

Answer:
Area of semicircle =62.07 sq cm

Explamation:
Area of semicircle =( π+r x r/2)
area =( 3.14 +121/2)
area =(121.14/2)
area = 62.07 sq cm

Question 4.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 4

Answer:
Area of semicircle =9.57 sqm

Explamation:
Area of semicircle =( π+r x r/2)
area =( 3.14 +16/2)
area =(19.14/2)
area = 9.57 sq m

Question 5.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 5

Answer:
Area of semicircle =4.695 sq yd

Explanation:
Area of semicircle =( π+r x r/2)
area =( 3.14 +6.25/2)
area =(9.39/2)
area = 4.695 sq yd

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 6.
ESTIMATING AN AREA
The grid contains a circle with a diameter of 2 centimeters. Use the grid to estimate the area of the circle. How can you change the grid to improve your estimate? Explain.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 6

Answer:
The area  of circle = 50.24 sq centi meters

Explanation:
The area  of circle = πr x r
a = 3.14 x 4 x 4 where d = 8 so r = 4
a = 50.24 square centimeters

Question 7.
WRITING
Explain the relationship between the circumference and area of a circle.

Answer:
The area  of circle = πr x r
circumference of circle = 2πr

Explanation:
The circumference of the circle is 2 times greater than the area of the circle.
The area  of circle = πr x r
circumference of circle = 2πr

Question 8.
DIFFERENT WORDS, SAME QUESTION
Which is different? Find “both” answers.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 7

Answer:
What is area of a circle with a radius of 100 cm?
What is the area of a circle with a radius  of 500 mm?

Explanation:
The area  of circle = πr x r
area = 3.14 x 100 x 100
area = 31400 sq cm
The area  of circle = πr x r
area = 3.14 x 500 x 500
area = 785000 sq mm
Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 9.
A local event planner wants to cover a circular region with mud for an obstacle course. The region has a circumference of about 157 feet. The cost to cover 1 square foot with mud is $1.50. Approximate the cost to cover the region with mud.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 8

Answer:
Cost to cover =

Question 10.
DIG DEEPER!
A manufacturer recommends that you use a frying pan with a radius that is within 1 inch of the radius of your stove top burner. The area of the bottom of your frying pan is 25π square inches. The circumference of your cook top burner is 9π inches. Does your frying pan meet the manufacturer’s recommendation?

Answer:
no the frying pan does not meet the manufacture

Explanation:
Given that frying pan has radius = 1 inch
area of frying pan = 25π square inches
circumference = 9π  inches

Areas of Circles Homework & Practice 9.2

Review & Refresh

Find the circumference of the object. Use 3.14 or \(\frac{22}{7}\) for π.
Question 1.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 9

Answer:
c = 28.26cm

Explanation:
circumference of the circle =2πr
circle = 2 x 3.14 x 4.5where r = 4.5cmgiven
circle = 6.28 x 4.5
circle =28.26 cm

Question 2.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 10

Answer:
c = 21.98 sq in

Explanation:
circumference of the circle =2πr
circle = 2 x 3.14 x 3.5where r = 3.5ingiven
circle = 6.28 x 3.5
circle =21.98 sq in

You spin the spinner shown.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 11
Question 3.
How many possible outcomes are there?

Answer:
3 possible outcomes

Explanation:
There are 3 possible outcomes.
3 numbers are there in the spin.

Question 4.
In how many ways can spinning an odd number occur?

Answer:
2 ways the spinning an odd number occur.

Explanation:
There are 2 possible ways that the odd numbers can occur.

Concepts, Skills, & Problem Solving
ESTIMATING AN AREA Use the grid to estimate the area of the circle. (See Exploration 1, p. 369.)

Question 5.
diameter of 3 centimeters
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 12

Answer:
area of the circle = 6.75 sq cm

Explanation:
The area  of circle = πr x r
area = 3.14 x 1.5 x 1.5
area = 6.75 sq cm

Question 6.
diameter of 1.6 inches
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 13

Answer:
area of the circle = 141.41 sq in

Explanation:
The area  of circle = πr x r
area = 3.14 x 6.4 x 6.4
area = 141.41 sq in

FINDING AN AREA Find the area of the circle. Use 3.14 or \(\frac{22}{7}\) for π.
Question 7.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 14

Answer:
The area  of circle = 254.34 sq milli meters

Explanation:
The area  of circle = πr x r
a = 3.14 x 4 x 4 where d = 8 so r = 4
a = 254.34 square millimeters

Question 8.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 15

Answer:
The area  of circle = 615.44 sq centi meters

Explanation:
The area  of circle = πr x r
a = 3.14 x 14 x 14 where r = 14
a = 615.44 square centimeters

Question 9.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 16

Answer:
The area  of circle = 314 sq inches

Explanation:
The area  of circle = πr x r
a = 3.14 x 10 x 10 where r = 10
a = 314 square inches

Question 10.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 17

Answer:
The area  of circle = 7.065 sq inches

Explanation:
The area  of circle = πr x r
a = 3.14 x 1.5 x 1.5 where r = 1.5
a = 7.065 square inches

Question 11.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 18

Answer:
The area  of circle = 3.14 sq cm

Explanation:
The area  of circle = πr x r
a = 3.14 x 1 x 1 where r = 1
a = 3.14 square cm

Question 12.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 19

Answer:
area  of circle = 1.76625sq ft

Explanation:
The area  of circle = πr x r
a = 3.14 x 0.75 x 0.75 where r = 0.75
a = 1.76625 square ft

Question 13.
YOU BE THE TEACHER
Your friend finds the area of a circle with a diameter of 7 meters. Is your friend correct? Explain.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 20

Answer:
No, my friend is not correct.

Explanation:
The area  of circle = πr x r
a = 3.14 x 3.5 x 3.5 where r = 0.75
a = 38.465 square meters
Question 14.
MODELING REAL LIFE
The diameter of a flour tortilla is 12 inches. What is the total area of two tortillas?

Answer:
The area  of tortilla = 226.08 sq inches

Explanation:
The area  of tortilla = πr x r
a = 3.14 x 6 x 6 where r = 6
a = 113.04 square inches
for 2 tortilla = 226.08 sq inches

Question 15.
MODELING REAL LIFE
The diameter of a coaster is 7 centimeters. What is the total area of five coasters?

Answer:
The  total area  of coaster = 192.325 cm

Explanation:
The area  of tortilla = πr x r
a = 3.14 x 3.5 x 3.5 where r = 3.5
a = 38.465 square cm
for 5 tortilla = 192.325 centimeters

Question 16.
PROBLEM SOLVING
The HillsboroInlet Lighthouse lights up how much more area than the Jupiter Inlet Lighthouse?
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 21

Answer:
The HillsboroInlet Lighthouse lights are 2 times greater than the Jupiter Inlet Lighthouse.

Explanation:
Hillsboro inlet Lighthouse = 3.14 x 28 x 28
area = 2,461.76 sq mi
jupiter inlet Lighthouse = 3.14 x 18 x 18
area = 1,017.36 sq mi

FINDING THE AREA OF A SEMICIRCLE Find the area of the semicircle.
Question 17.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 22

Answer:
Area of semicircle = 628 sq cm

Explanation:
Area of semicircle =( π+r x r/2)
area =( 3.14 +400/2)
area =(403.14/2)
area = 628 sq cm

Question 18.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 23
Answer:
Area of semicircle =201.57 sq cm

Explanation:
Area of semicircle =( π+r x r/2)
area =( 3.14 +400/2)
area =(403.14/2)
area = 201.57 sq cm

Question 19.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 24

Answer:
Area of semicircle =1.57 sq ft

Explanation:
Area of semicircle =( π+r x r/2)
area =( 3.14 +1/2)
area =(3.14/2)
area = 1.57 sq ft

Question 20.
MODELING REAL LIFE
The plate for a microscope has a circumference of 100π millimeters. What is the area of the plate?

Answer:
Area of the plate = 200π mm

Explanation:
Area of the plate = π x r x r
area = 3.14 x 200 x 200

Question 21.
MODELING REAL LIFE
A dog is leashed to the corner of a house. How much running area does the dog have? Explain how you found your answer.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 25

Answer:
Area of the circle = 942 sq ft

Explanation:
Area of the circle = π x r x r
area = 3.14 x 20 x 20
area = 942 sq ft
The running area is 3/4 the area of a circle with a radius of 20 feet.

Question 22.
REASONING
Target A has a circumference of 20 feet. Target B has a diameter of 3 feet. Both targets are the same distance away. Which target is easier to hit? Explain your reasoning.

Answer:
Target B is easier to hit

Explanation:
Target A =2  π x r
A  = 2 x 3.14 x 3.18
A = 19.9704

Target B = 1.5

Question 23.
DIG DEEPER!
A circular oil spill has a radius of 2 miles. After a day, the radius of the oil spill increases by 3 miles. By how many square miles does the area of the oil spill increase?

Answer:
The area of oil spill increases by 65.94 miles.

Explanation:
Given that the circular oil spill has a radius of 2 miles.
The radius of the oil spill increases by 65.94 sq miles.

Question 24.
FINDING AN AREA
Find the area of the circle in square yards.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles 9.2 26

Answer:
Area of the circle = 7.057935 sq yd

Explanation:
Area of the circle = π x r x r
area = 3.14 x 4.5 x 4.5
area = 63.585 sq ft
area = 7.057935 sq yd

Question 25.
REPEATED REASONING
What happens to the circumference and the area of a circle when you double the radius? triple the radius? Justify your answer.

Answer:
If we double the radius ,area  = π x r x r x r x r
If we double the radius, circumference  = 2πr x r x r
If we triple the radius ,area  = π x r x r x r x r x r
If we triple the radius, circumference  = 2πr x r x r x r x r

Explanation:
circumference doubles and area quadruples;
circumference triples and area is 9 times greater;
double the radius: circumference = 2π2r = 4πr
4πr /2πr  = 2 times larger, area =π (2r) x r =4πrx r
4πrx r/ πrx r = 4 times larger.

Question 26.
CRITICAL THINKING
Is the area of a semicircle with a diameter of x greater than, less than, or equal to the area of a circle with a diameter of \(\frac{1}{2}\)x? Explain.

Answer:
The area of a semicircle with a diameter of x is greater than the area of a circle with a diameter of (0.5)

Explanation:
Area of semicircle = (3.14 + (0.5 x 0.5)/2)
area = 1.695
Area of circle = (3.14 x 0.5 x 0.5)
area = 0.785

Lesson 9.3 Perimeters and Areas of Composite Figures

EXPLORATION 1

Submitting a Bid
Work with a partner. You want to bid on a project for the pool shown. The project involves ordering and installing the brown tile that borders the pool, and ordering a custom-made tarp to cover the surface of the pool. In the figure, each grid square represents 1 square foot. You pay $5 per linear foot for the tile.

  • You pay $4 per square foot for the tarp.
  • It takes you about 15 minutes to install each foot of tile.

a. Estimate the total cost for the tile and the tarp.
b. Write a bid for how much you will charge for the project.Include the hourly wage you will receive.Estimate your total profit.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 1

Answer:

Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 2

Try It

Question 1.
Estimate the perimeter and the area of the figure.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 3

Answer:
50.24 sq mm

Explanation:
The above-given figure is about  50.24 sq mm
Question 2.
Find the perimeter and the area of the figure.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 4

Answer:
perimeter of the figure = 3.16 sq in
area of the figure = 3.14 sq in

Explanation:
perimeter of the semicircle = ( π + 2) r
p = (3.14 + 2 ) 1
p = 3.16 in
area of the figure = π x r x r
area = 3.14 x 1 x1
area = 3.14 in

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 3.
ESTIMATING PERIMETER AND AREA
Estimate the perimeter and area of the figure at the right.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 5

Answer:
The perimeter  and area = 30 ft
area =  π  x r x r

Explanation:

The perimeter = ( π + 2) r
area =  π  x r x r

Question 4.
FINDING PERIMETER AND AREA
Identify the shapes that make up the figure at the left. Then find the perimeter and area of the figure.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 6

Answer:
The perimeter = 9.48 sq ft
area =  27.36 sq ft

Explanation:
The perimeter = ( π + 2) r
perimeter = 3.14 +2 x 3
perimeter = 9.48 sq ft
area = 3.14 x 3 x 3
area = 27.36 sq feet

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 5.
A farmer wants to seed and fence a section of land. Fencing costs $27 per yard. Grass seed costs $2 per square foot. How much does it cost to fence and seed the pasture?
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 7

Answer:
1 m

Explanation:
Given that farmer has the fencing cost = $ 27
seed cost = $ 2
5.10 $ is used to cost for  grass seed
$ 27 is used to fence = 1 m

Question 6.
DIG DEEPER!
In each room shown, you plan to put down carpet and add a wallpaper border around the ceiling. Which room needs more carpeting? more wallpaper?
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 8

Answer:
Room A needs more carpeting.

Explanation:
Room A =  10 x 11
where length = 11 , breadth = 10 given
Room A = 110
Room B = 12 x 8
B = 96

Perimeters and Areas of Composite Figures Homework & Practice 9.3

Review & Refresh

Find the area of the circle. Use 3.14 or \(\frac{22}{7}\) for π.
Question 1.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 9

Answer:
Area of the circle = 50.24 sq mm

Explanation:
Area of the circle = π x r x r
area = 3.14 x 4 x 4
area = 3.14 x 16
area = 50.24 sq mm

Question 2.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 10

Answer:
Area of the circle = 63.585 sq ft

Explanation:
Area of the plate = π x r x r
area = 3.14 x 4.5 x 4.5
area = 3.14 x
area = 63.585 sq ft

Find the missing dimension. Use the scale 1 : 5.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 11

Answer:
3. Height = 30 ft
4. Length = 6 ft
5. Depth = 100 cm
6. Diameter = 2 in

Explanation:
3. house : height = 6 ft , height = 30 ft given that scale = 1 : 5
4. garden hose : length = 6 ft , length = 20 yd
4. fountain : depth = 20 cm, depth = 100 cm
5. bicycle wheel :  = diameter = 2 in  diameter = 2 ft

Concepts, Skills, & Problem Solving

ESTIMATING PERIMETER AND AREA You build a patio with a brick border. (See Exploration 1, p. 375.)
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 12
Question 7.
Estimate the perimeter of the patio.

Answer:
The perimeter of a patio = 24 units

Explanation:
In the above-given figure,
the perimeter of the patio = 24

Question 8.
Estimate the area of the patio.

Answer:
area of the patio = π r

ESTIMATING PERIMETER AND AREA Estimate the perimeter and the area of the shaded figure.
Question 9.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 13

Answer:
Perimeter = 19.5 units
area =13.5 units

Explanation:
given figure is trapezoid
Perimeter = a + b + c + d
area =( (a + b) x h /2)

Question 10.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 14

Answer:
area =(  3 √ 3/2) a square
perimeter = 6 a

Explanation:
given figure is hexagon
area =(  3 √ 3/2) a square
perimeter = 6 a

Question 11.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 15

Answer:
The perimeter = 24.6 units
Area of the plate = 41.1 sq units

Explanation:
given figure is semicircle
The perimeter = ( π + 2) r
Area of the plate = π x  r x r

Question 12.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 16

Answer:
Perimeter = a + b + c + d
area =( (a + b) x h /2)

Explanation:
given figure is trapezoid
Perimeter = a + b + c + d
area =( (a + b) x h /2)

Question 13.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 17

Answer:
Perimeter = 19 units
area = 24  squnits

Explanation:
given figure is pentagon
Perimeter = 5 a
area = (  perimeter x apotherm /2 )

Question 14.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 18

Answer:
Perimeter = a + b + c
area = (  height x breadth /2 )

Explanation:
given figure is triangle
Perimeter = a + b + c
area = (  height x breadth /2 )

FINDING PERIMETER AND AREA Find the perimeter and the area of the figure.
Question 15.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 19

Answer:
area = 137 sq m
perimeter = 56 m

Explanation:
area of the rectangle = l x w
l = length, w = width
area = 12 x 11
area = 137 sq m
perimeter of the rectangle = 2 ( l + w)
perimeter = 2 (28)
perimeter = 56 m

Question 16.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 20

Answer:
area = 114.07 sq ft
perimeter = 47.4 sq ft

Explanation:
Area of semicircle =( π+r x r/2)
area =( 3.14 +225/2)
area =(228.14/2)
area = 114.07 sq ft
perimeter of the semicircle = (π + 2 ) r
perimeter = (3.14 + 2) 15 given r= 15
perimeter = 3.16 x 15
perimeter = 47.4 sq ft

Question 17.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 21

Answer:
area = 49.5 cm
perimeter = 29 cm

Explanation:
area of the rectangle = l x w
l = length, w = width
area = 7 x 7
area = 49 cm
perimeter of the rectangle = 2 ( l + w)
perimeter = 2 (14)
perimeter = 29 cm

Question 18.
YOU BE THE TEACHER
Your friend finds the perimeter of the figure. Is your friend correct? Explain your reasoning.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 22

Answer:
Yes my friend is correct.

Explnation:
perimeter = length + side +  height + breadth + width + base
p = 4 + 3 + 4 + 5 + 4 + 5
p = 25 in

Question 19.
LOGIC
A running track has six lanes. Explain why the starting points for the six runners are staggered. Draw a diagram as part of your explanation.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 23

Answer:

Explanation:
The starting points for the six runners are staggered because each runner can run the same distance.

Explanation:
The starting points are staggered so that each runner can run the same distance and use the same finish line.
this is necessary because the circumference is different for each lane.
the above-diagram shows this because the diameter is greater n the outer lanes.

Question 20.
PROBLEM SOLVING
You run around the perimeter of the baseball field at a rate of 9 feet per second. How long does it take you to run around the baseball field?
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 24

Answer:
It take to run around the baseball field = 1,58,962.5 sq feet

Explanation:
The area of the circle = π x r x r
area = 3.14 x 225 x 225
area = 1,58,962.5 sq feet

Question 21.
STRUCTURE
The figure at the right is made up of a square and a rectangle. Find the area of the shaded region.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 25

Answer:
The area of the shaded region =24 sq m

Ex planation:
Area of triangle = ( b x h )/2
area =( 8 x 7)/ 2
area = 48/2
area = 24 sq m
Question 22.
DIG DEEPER!
Your friend makes a two-dimensional model of a dividing cell as shown. The total area of the dividing cell is 350 square inches. What is the area of the shaded region?
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles 9.3 26

Answer:
The area of the shaded region = 1.89 sq in

Explanation :
area of semicircle = (π + r x r/2)
area = (3.14 + 64/2)
area = ( 3.78 / 2)
area = 1.89 sq in
Question 23.
CRITICAL THINKING
How can you add a figure to a composite figure without increasing its perimeter? Can this be done for all figures? Draw a diagram to support your answer.

Answer:

Explanation:
The perimeter does not increases.

Lesson 9.4 Constructing Polygons

EXPLORATION 1

Using Technology to Draw Polygons
Work with a partner.
a. Use geometry software to draw each polygon with the given side lengths or angle measures, if possible. Complete the table.
Big Ideas Math Solutions Grade 7 Chapter 9 Geometric Shapes and Angles 9.4 1
b. Without constructing, how can you tell whether it is possible to draw a triangle given three angle measures? three side lengths? Explain your reasoning.
c. Without constructing, how can you tell whether it is possible to draw a quadrilateral given four angle measures? four side lengths? Explain your reasoning.

Answer:
b. Yes it is possible to draw a triangle with the given three angles measures, three side lengths.
c. yes it is possible to draw a quadrilateral with the given 4 angle measures, four side lengths.

Explanation:
1. given that sides = 4 cm , 6 cm , 7cm

2. given that sides = 2 cm , 3 cm , 3 cm, 5 cm

Try It

Draw a triangle with the given angle measures, if possible.
Question 1.
45°, 45°, 90°

Answer:

Explanation:
The above triangle is an equilateral triangle.
it forms with the given angles 45°, 45°, 90°.

Question 2.
100°, 55°, 25°

Answer:

Explanation:
The above triangle is scalene  triangle.
it forms with the given angles 100°, 55°, 25°.

Question 3.
60°, 60°, 80°

Answer:

Explanation:
The above triangle is an equilateral triangle.
it forms with the given angles60°, 60°, 80°

Question 4.
Draw a triangle with side lengths of 1 inch and 2 inches that meet at a 60° angle.

Answer:

Explanation:
The above triangle is a scalene triangle.
it forms with the given angles 60° , 1 inch and 2 inch.

Draw a triangle with the given side lengths, if possible.
Question 5.
2 cm, 2 cm, 5 cm

Answer:

Explanation:
given the sides of a triangle 2cm , 2 cm , 5 cm

Question 6.
4 cm, 3 cm, 3 cm

Answer:

Explanation:
given that 2 sides are same and one side is different.

Question 7.
1 cm, 4 cm, 5 cm

Answer:

Draw a quadrilateral with the given angle measures, if possible.
Question 8.
100°, 90°, 65°, 105°

Answer:

Explanation:
The quadrilateral formed with the given angles 100°, 90°, 65°, 105°.

Question 9.
100°, 40°, 20°, 20°

Answer:

Explanation:
The quadrilateral formed with the given angles 100°, 40°, 20°, 20°.

Question 9.

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

DRAWING POLYGONS Draw a polygon with the given side lengths or angle measures, if possible.
Question 10.
25 mm, 36 mm, 38 mm

Answer:

Explanation:
The polygon formed with the given sides is a triangle.

Question 11.
10°, 15°, 155°

Answer:

Explanation:
The polygon formed with the given sides is a triangle.

Question 12.
20°, 45°, 50°, 65°

Answer:

Explanation:
The polygon formed with the given sides is a  hexagon.

Question 9.
100°, 40°, 20°, 20°

Answer:

Explanation:
The polygon formed with the given sides is a  hexagon.
Question 9.
100°, 40°, 20°, 20°
Answer:

Question 9.
100°, 40°, 20°, 20°
Answer:

Explanation:
The polygon formed with the given sides is a  quadrilateral.

Question 13.
50°, 90°, 110°, 110°

Answer:

Question 14.
USING SIDE LENGTH
Can you construct one, many, or triangle(s) with side lengths of 3 inches, 4 inches, and 8 inches? Explain.
Answer:
We can construct only one triangle

Explanation:
Given the side lengths of 3 inches, 4 inches, and 8 inches.

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 15.
A triangular pen has fence lengths of 6 feet, 8 feet, and 10 feet. Create a scale drawing of the pen.
Answer:

Question 16.
The front of a cabin is the shape of a triangle. The angles of the triangle are 40°, 70°, and 70°. Can you determine the height of the cabin? If not, what information do you need?
Answer:

Question 17.
DIG DEEPER!
Two rooftops have triangular patios. One patio has side lengths of 9 meters,10 meters, and 11 meters.e other has side lengths of 6 meters,10 meters, and 15 meters. Which patio has a greater area? Explain.
Big Ideas Math Solutions Grade 7 Chapter 9 Geometric Shapes and Angles 9.4 2
Answer:
The patio which has a side length of 6 meters, 10 meters, and 15 meters.

Explanation:
The patio has a greater side length.

Constructing Polygons Homework & Practice 9.4

Review & Refresh

Find the perimeter and area of the figure.
Question 1.
Big Ideas Math Solutions Grade 7 Chapter 9 Geometric Shapes and Angles 9.4 3
Answer:
area = 12 in
perimeter = 14 in

Explanation:
area of the rectangle = l x w
l = length, w = width
area = 4 x 3
area = 12 in
perimeter of the rectangle = 2 ( l + w)
perimeter = 2 (7)
perimeter = 14 in

Question 2.
Big Ideas Math Solutions Grade 7 Chapter 9 Geometric Shapes and Angles 9.4 4
Answer:

perimeter of the figure = 9.48 sq cm
area of the figure = 28.26 sq cm

Explanation:
perimeter of the semicircle = ( π + 2) r
p = (3.14 + 2 ) 3
p = 9.48 cm
area of the figure = π x r x r
area = 3.14 x 3 x3
area = 28.26 sq cm

Use a tree diagram to find the sample space and the total number of possible outcomes of the indicated event.
Big Ideas Math Solutions Grade 7 Chapter 9 Geometric Shapes and Angles 9.4 5
Question 3.
choosing a toothbrush
Big Ideas Math Solutions Grade 7 Chapter 9 Geometric Shapes and Angles 9.4 6
Answer:
Extra soft, soft, Medium

Explanation:
In the above given figure the strength of the toothbrush = extra soft , soft , meedium

Question 4.
Big Ideas Math Solutions Grade 7 Chapter 9 Geometric Shapes and Angles 9.4 7
Answer:
The size of the toy hop is small, medium , large.

Explanation:
given that the colour of the toy hoop is blue , green , orange, pink, purple , yellow.

Concepts, Skills, & Problem Solving

USING TECHNOLOGY TO DRAW POLYGONS Use geometry software to draw the polygon with the given side lengths or angle measures, if possible. (See Exploration 1, p. 381.)
Question 5.
30°, 65°, 85°
Answer:

Question 6.
2 in., 3 in., 5 in.
Answer:

Question 7.
80°, 90°, 100°, 110°
Answer:
Not possible.

Question 8.
2 cm, 2 cm, 5 cm, 5 cm
Answer:

CONSTRUCTING TRIANGLES USING ANGLE MEASURES Draw a triangle with the given angle measures, if possible.
Question 9.
40°, 50°, 90°
Answer:

Question 10.
20°, 40°, 120°
Answer:

Question 11.
38°, 42°, 110°
Answer:

Question 12.
54°, 60°, 66°
Answer:

Question 13.
YOU BE THE TEACHER
Your friend determines whether he can draw a triangle with angle measures of 10°, 40°, and 130°. Is your friend correct? Explain your reasoning.
Big Ideas Math Solutions Grade 7 Chapter 9 Geometric Shapes and Angles 9.4 8
Answer:
Yes .

Explanation:
yes we cannot draw the triangle with the angle measures of 10, 40, 130

CONSTRUCTING TRIANGLES USING ANGLES AND SIDES Draw a triangle with the given description.
Question 14.
side lengths of 1 inch and 2 inches meet at a 50° angle
Answer:
yes.

Explanation:
we can draw a triangle with 1 inch 2 inch that meets at  50 degrees.

Question 15.
side lengths of 7 centimeters and 9 centimeters meet at a 120° angle
Answer:
yes.

Explanation:
we can draw a triangle with 7 cm 9 cm that meets at  120 degrees.

Question 16.
a 95° angle connects to a 15° angle by a side of length 2 inches
Answer:
no.

Explanation:
we cannot draw a triangle with 2 inches 15 degrees that meets at  120 degrees.

Question 17.
a 70° angle connects to a 70° angle by a side of length 4 centimeters
Answer:
yes.

Explanation:
we can draw an angle with 4 cm  70 degrees that meets at  120 degrees.

CONSTRUCTING TRIANGLES USING SIDE LENGTHS Draw a triangle with the given side lengths, if possible.
Question 18.
4 in., 5 in., 10 in.
Answer:

Question 19.
10 mm, 30 mm, 50 mm
Answer:

Question 20.
5 cm, 5 cm, 8 cm
Answer:

Question 21.
8 mm, 12 mm, 13 mm
Answer:

Question 22.
MODELING REAL LIFE
Can you construct a triangular case using two pieces of wood that are 12 inches long and one piece of wood that is 25 inches long? Explain.
Answer:
Yes we can construct a triangle .

Explanation:
We can costruct the triangle by using two pieces of wood that are 12 inches long and the one piece of wood is 25 inches.

Question 23.
MODELING REAL LIFE
Can you construct a warning triangle using three pieces of plastic that are each 6 inches long? Explain.
Big Ideas Math Solutions Grade 7 Chapter 9 Geometric Shapes and Angles 9.4 9
Answer:
Yes.

Explanation:
we can construct the three pieces of plastic by using 3 6 inches long.

Question 24.
LOGIC
You are constructing a triangle. You draw the first angle, as shown. Your friend says that you must be constructing an acute triangle. Is your friend correct? Explain your reasoning.
Big Ideas Math Solutions Grade 7 Chapter 9 Geometric Shapes and Angles 9.4 10
Answer:
Yes my friend is correct.

Explanation:
it is a acute angle triangle.

USING ANGLES AND SIDES Determine whether you can construct one, many, or no triangle(s) with the given description. Explain your reasoning.
Question 25.
a triangle with one angle measure of 60and one side length of 4 centimeters
Answer:

Explanation:
we cannot construct one trinangle with the help of given sidelengths.

Question 26.
a scalene triangle with side lengths of 3 centimeters and 7 centimeters
Answer:

Question 27.
an isosceles triangle with two side lengths of 4 inches that meet at an 80° angle
Answer:

Question 28.
a triangle with one angle measure of 60°, one angle measure of 70°, and a side length of 10 centimeters between the two angles
Answer:

Question 29.
a triangle with one angle measure of 20°, one angle measure of 35°, and a side of length 3 inches that is between the two angles
Answer:

Question 29.
REASONING
A triangle is shown.
Big Ideas Math Solutions Grade 7 Chapter 9 Geometric Shapes and Angles 9.4 11
a. Construct a triangle with side lengths twice those of the triangle shown. Does the new triangle have the same angle measures?
b. How can you change the side lengths of the triangle so that the measure of ∠A increases?
Answer:
a. Yes the new triangle have the same angle.
b. angle A increases .

Explanation:
Given that the triangle with side lengths twice those of the triangle shown.
If we can change the side lengths of triangle .

CONSTRUCTING QUADRILATERALS Draw a quadrilateral with the given angle measures, if possible.
Question 31.
60°, 60°, 120°, 120°
Answer:

Question 32.
50°, 60°, 110°, 150°
Answer:

Question 33.
20°, 30°, 150°, 160°
Answer:

Question 34.
10°, 10°, 10°, 150°
Answer:

Explanation:
Given angles are 10 degrees, 10 degrees, 10 degrees, 10 degrees.

CONSTRUCTING SPECIAL QUADRILATERALS Construct a quadrilateral with the given description.
Question 35.
a rectangle with side lengths of 1 inch and 2 inches
Answer:

Question 36.
a kite with side lengths of 4 centimeters and 7 centimeters
Answer:

Question 37.
a trapezoid with base angles of 40°
Answer:
Answer

Question 38.
a rhombus with side lengths of 10 millimeters
Answer:

Question 39.
REASONING
A quadrilateral has side lengths of 6 units, 2 units, and 3 units as shown. How many quadrilaterals can be formed given a fourth side with a fixed length? Explain.
Big Ideas Math Solutions Grade 7 Chapter 9 Geometric Shapes and Angles 9.4 12
Answer:
2 quadrilaterals can be formed.

Explanation:
Given that the quadrilateral has side lengths of 6 units, 2 units, and 3 units.
so 2 quadrilaterals can be formed.

Question 40.
REASONING
What types of quadrilaterals can you form using four side lengths of 7 units? Use drawings to support your conclusion.
Answer:

Question 41.
MODELING REAL LIFE
A triangular section of a farm is enclosed by fences that are 2 meters, 6 meters, and 7 meters long. Estimate the area of the section.
Answer:
Area of the section = 12 sq meters.

Question 42.
MODELING REAL LIFE
A chemical spill expert sets up a triangular caution zone using cones. Cones A and B are 14 meters apart. Cones B and C are 22 meters apart. Cones A and C are 34 meters apart. Estimate the area of the caution zone.
Big Ideas Math Solutions Grade 7 Chapter 9 Geometric Shapes and Angles 9.4 13
Answer:
Area of the area of the caution Zone = 308 sq meters.

Explanation:
Area of the triangle = l x b
area = 22 x 14
area = 308 sq meters.

Question 43.
MODELING REAL LIFE
A search region is in the shape of an equilateral triangle. The measure of one side of the region is 20 miles. Make a scale drawing of the search region. Estimate the area of the search region.
Answer:

Explanation:
Given that the equilateral triangle .

Question 44.
REASONING
A triangle has fixed side lengths of 2 and 14.
a. How many triangles can you construct? Use the figure below to explain your reasoning.
Big Ideas Math Solutions Grade 7 Chapter 9 Geometric Shapes and Angles 9.4 14
b. Is the unknown side length of the triangle also fixed? Explain.
Answer:
We can construct 14 triangles.
b. No the side length of the triangle cannot fixed.

Explanation:
a. We can construct 14 triangles.
b. No the side length of the triangl cannot fixed.

Lesson 9.5 Finding Unknown Angle Measures

EXPLORATION 1

Using Rules About Angles
Work with a partner. The diagram shows pairs of angles and vertical angles. Vertical angles cannot be adjacent.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 1
a. Which pair(s) of angles are adjacent angles? Explain.
b. Which pair(s) of angles are vertical angles? Explain.
c. Without using a protractor, find the values of x, y, and z. Explain your reasoning.
d. Make a conjecture about the measures of any two vertical angles.
e. Test your conjecture in part(d) using the diagram below. Explain why your conjecture is or is not true.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 2
Answer:
A. ∠ACD, ∠AEB
b. ∠ACD, ∠AEB
c. 125
d. ∠ACD, ∠AEB
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 3

Try It

Question 1.
Name a pair of (a) adjacent angles, (b) complementary angles, (c) supplementary angles, and (d) vertical angles in the figure.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 4
Answer:
a. ∠JKL, ∠JKQ, . ∠MNJ,. ∠PJN
b. ∠JKQ
c. ∠JNK, ∠ JPL. ∠JMQ
D. ∠JMQ, ∠JPL.

Explanation:
The above angles are adjacent, vertical, supplementary,complementary.

Classify the pair of angles. Then find the value of x.
Question 2.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 5
Answer:
x = 95 ˚

Explanation:
x = (180 – 85)
x = 95 ˚

Question 3.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 6
Answer:
x =  180 ˚

Explanation:
x = 180 ˚

Question 4.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 7
Answer:
x = 30 ˚

Explanation:
(2x – 3) = 60
2x = (60/3)
2x = 20
x = 10

Find the measure of the indicated angle in the diagram.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 8.1
Question 5.
∠NJM
Answer:
12 x ˚

Question 6.
∠KJP
Answer:
16 x ˚

Question 7.
∠KJM
Answer:
6x ˚

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 8.
NAMING ANGLES
Name a pair of (a) adjacent angles, (b) complementary angles, (c) supplementary angles, and (d) vertical angles in the figure at the left.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 8
Answer:
a. ∠ABC
b. ∠ABD
c. ∠ABE
d. ∠ABE

Explanation:
The above angles are adjacent, vertical, supplementary,complementary.

FINDING ANGLE MEASURES Find the value of x.
Question 9.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 9
Answer:
x = 60˚

Explanation:
4x = x
4x – x = 180
3x = 180
x = 60˚

Question 10.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 10
Answer:
x = 12.5˚

Explanation:
2x  – 10= 2x + 40
4x  = 50
x = 12.5˚

Question 11.
WHICH ONE DOESN’T BELONG?
Which pair of angles does not belong with the other three? Explain your reasoning.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 11
Answer:
∠FBA, ∠EBD does not belong with the other three.

Explanation:
the 3 angles are different measures,

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 12.
What is the angle between any two windmill blades in the windmill at the left? Justify your answer.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 12

Answer:
The angle between any two wind mills blades in the windmill at the left = 60 °

Explanation:
60 + 60 + 60 = 180

Question 13.
A hockey puck strikes a wall at an angle of 30°. The puck then travels away from the wall at the same angle. Find the value of y. Explain your reasoning.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 13
Answer:
y = 150 °

Explanation:
In the above figure said that hockey puck strikes a wall at an angle of 30 °.
so 180 – 30 = 150

Question 14.
DIG DEEPER!
The laptop screen turns off when the angle between the keyboard and the screen is less than 20°. How many more degrees can the laptop screen close before the screen turns off?
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 14
Answer:
The laptop screen close before the screen turns off = 60 degrees.

Explanation:
(z + 40) = (z – 20)
z – z = (-  20 -40)
z = -60

Finding Unknown Angle Measures Homework & Practice 9.5

Review & Refresh

Draw a triangle with the given side lengths, if possible.
Question 1.
1 in., 3 in., 4 in.
Answer:

Explanation:
In the above question , they said to draw 1 in, 3 in, 4 in.

Question 2.
4 cm, 4 cm, 7 cm
Answer:

Solve the inequality. Graph the solution.
Question 3.
– 8y ≤ 40
Answer:

Explanation:
– 8y ≤ 40
y = (40/8)
y = 5

Question 4.
1.1z > – 3.3
Answer:

Explanation:
z = 3.3

Question 5.
\(\frac{1}{3}\)x ≥ 2.5
Answer:

Concepts, Skills, & Problem Solving

USING RULES ABOUT ANGLES The diagram shows pairs of adjacent vertical angles and angles. B(See Exploration 1, p. 389.)
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 15
Question 6.
Which pair(s) of angles are adjacent angles? Explain.
Answer:
angle AEC, angle ABD.

Explanation:
In the above given figure angle AEC, angle ABD are adjacent.

Question 7.
Which pair(s) of angles are vertical angles? Explain.
Answer:
angle ABC, angle ADE

Explanation:
In the above given figure angle AEC, angle ABD are adjacent.

NAMING ANGLES Use the figure shown.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 16
Question 8.
Name a pair of adjacent angles.
Answer:
∠ADC, ∠AEF, ∠ABC

Question 9.
Name a pair of complementary angles.
Answer:
∠ADE, ∠ABD

Question 10.
Name a pair of supplementary angles.
Answer:
∠ABE, ∠ACF

Question 11.
Name a pair of vertical angles.
Answer:
∠AEF, ∠ABC

Question 12.
YOU BE THE TEACHER
Your friend names a pair of angles with the same measure. Is your friend correct? Explain your reasoning.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 17
Answer:
yes my friend is correct

Explanation:
The angles both have the same measure.

ADJACENT AND VERTICAL ANGLES Tell whether the angles are adjacent, vertical, or neither. Explain.
Question 13.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 18
Answer:
vertical.

Explanation:
The given angles are vertical.

Question 14.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 19
Answer:
Adjacent.

Explanation:
The given angles are adjacent.

Question 15.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 20

Answer:
Adjacent, vertical

Explanation:
The given angles are adjacent, vertical.

COMPLEMENTARY AND SUPPLEMENTARY ANGLES Tell whether the angles are complementary supplementary, or neither. Explain.
Question 16.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 21
Answer:
The angles are neither complementary nor supplementary.

Explanation:
complementary = 90 degree
supplementary = 180 degree

Question 17.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 22
Answer:
The angles are complementary.

Explanation:
complementary = 90 degree
supplementary = 180 degree

Question 18.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 23
Answer:
The angles are complementary.

Explanation:
complementary = 90 degree
supplementary = 180 degree

Question 19.
YOU BE THE TEACHER
Your friend names a pair of supplementary angles. Is your friend correct? Explain.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 24
Answer:
yes my friend is correct.

Explanation:
angle LMN and angle PMQ are supplementary angles.

USING PAIRS OF ANGLES Classify the pair of angles. Then find the value of x.
Question 20.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 25
Answer:
Acute angle.
x = 145

Explanation:
x = (180 – 35)
x = 35

Question 21.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 26
Answer:
verticle angle.
x = 52

Explanation:
x = (180 – 128)
x = 52

Question 22.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 27
Answer:
obtuse angle.
x = 63

Explanation:
x = (180 – 117)
x = 63

Question 23.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 28
Answer:
intersection angles
x = 25

Explanation:
(4x – 25) = 75
4x = 75 + 25
4x = 100
x = (100/4)
x = 25

Question 24.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 29
Answer:
x = 15

Explanation:
2x = 30
x = (30/2)
x = 15
4x = 60
x = (60/4)
x = 15

Question 25.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 30
Answer:
x = 3.33

Explanation:
(x + 20 ) = 7 x
20 = 7x – x
20 = 6x
x = (20/6)
x = 3.33

Question 26.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 31
Answer:
x = 15

Explanation:
3x = 45
x = (45/3)
x = 15

Question 27.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 32
Answer:
x = 20

Explanation:
(x – 20 ) = x
20 = x – x
x = 20

Question 28.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 33
Answer:
x = 25

Explanation:
(3x + 25) = 2x
3x – 2x = 25
x = 25

Question 29.
MODELING REAL LIFE
What is the measure of each angle formed by the intersection? Explain.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 34
Answer:
angle 2 = 50°
angle 3 = 40°
angle 1 = 40°

Explanation:
In the above figure the angle 4 is given.

Question 30.
MODELING REAL LIFE
A tributary joins a river at an angle x. Find the value of x. Explain.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 35
Answer:
x = 21

Explanation:
(2x + 21 ) = x
2x – x = 21
x = 21

Question 31.
MODELING REAL LIFE
The iron cross is a skiing trick in which the tips of the skis are crossed while the skier is airborne. Find the value of x in the iron cross shown.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 36
Answer:
The value of x in the iron cross = 43

Explanation:
(2x + 41) = 127
2x = 127 – 41
2x = 86
x = 43

FINDING ANGLE MEASURES Find all angle measures in the diagram.
Question 32.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 37
Answer:
x = 90˚

Question 33.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 38
Answer:
23.33

Explanation:
(3x + 5) = 75
3x = 75 – 5
3x = 70
x = (70/3)
x = 23.33

Question 34.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 39
Answer:
x = 68
x = 67

Explanation:
(2x + 4) = 140
2x = (140 – 4)
2x = 136
x = (136/2)
x = 68
(2x + 6) = 140
2x = (140 – 6)
2x = 134
x = (134/2)
x = 67

OPEN-ENDED Draw a pair of adjacent angles with the given description.
Question 35.
Both angles are acute.
Answer:

Question 36.
One angle is acute, and one is obtuse.
Answer:

Question 37.
The sum of the angle measures is 135°.
Answer:

REASONING Copy and complete each sentence with always, sometimes, or never.
Question 38.
If x and y are complementary angles, then both x and y are________ acute.
Answer:
Right acute.

Explanation:
if x and y are complimentary then the x and y are right acute.

Question 39.
If x and y are supplementary angles, then is x ________ acute.
Answer:
left acute.

Explanation:
if x and y are complimentary then the x and y are right acute.

Question 40.
If x is a right angle, then is x ________ acute.
Answer:
Right acute.

Explanation:
if x and y are complimentary then the x and y are right acute.

Question 41.
If x and y are complementary angles, then x and y are ________ adjacent.
Answer:
Right adjacent.

Explanation:
if x and y are complimentary then the x and y are right adjacent.

Question 42.
If x and y are supplementary angles, then x and y are _______ vertical.
Answer:
left vertical.

Explanation:
if x and y are supplementary then the x and y are left vertical.

Question 43.
REASONING
Draw a figure in which ∠1 and ∠2 are acute vertical angles, ∠3 is a right angle adjacent to ∠2, and the sum of the measure of ∠1 and the measure of ∠4 is 180°.
Answer:

Question 44.
STRUCTURE
Describe the relationship between the two angles represented by the graph shown at the right.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 40
Answer:
90°

Explanation:
The relationship between the two angles represented by the graph =90°

Question 45.
STRUCTURE
Consider the figure shown at the left. Use a ruler to extend both rays into lines. What do you notice about the three new angles that are formed?
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 41
Answer:
The 3 angles that are formed = 30°, 60°, 90°

Explanation:
The given angles are right angles.

Question 46.
OPEN-ENDED
Give an example of an angle that can be a supplementary angle but cannot be a complementary angle to another angle. Explain.
Answer:
Acute angle

Question 47.
MODELING REAL LIFE
The vanishing point of the picture is represented by point B.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 42
a. The measure of ∠ABD is 6.2 times greater than the measure of ∠CBD. Find the measure of ∠CBD.
b. ∠FBE and ∠EBD are congruent. Find the measure of ∠FBE.
Answer:
a. The measure of  ∠CBD = 30°
b. The measure of ∠FBE = 60°

Explanation:
Given that the measure of ∠ABD is 6.2 times greater than the measure of ∠CBD  = 30°
∠FBE and ∠EBD are congruent so ∠FBE = 60°

Question 48.
CRITICAL THINKING
The measures of two complementary angles have a ratio of 3 : 2. What is the measure of the larger angle?
Answer:
The measure of the larger angle = 3

Explanation:
given that, the measures of two complementary angles have a ratio = 3 : 2

Question 49.
REASONING
Two angles are vertical angles. What are their measures if they are also complementary angles? supplementary angles?
Answer:
when two angles are vertical.
complementary angles = Two angles are called complementary when their measures add to 90°
supplementary angles = two angles are called supplementary when their measures add to 180°

Question 50.
PROBLEM SOLVING
Find the values of x and y.
Big Ideas Math Answer Key Grade 7 Chapter 9 Geometric Shapes and Angles 9.5 43
Answer:
x = 2.857
y = 2
x = 4

Explanation:
7  x = 20
x = (20/7)
x = 2.857
2y = 20
y = (20/10)
y  = 2
5x = 20
x = (20/5)
x = 4

Geometric Shapes and Angles Connecting Concepts

Using the Problem-Solving Plan
Question 1.
A dart is equally likely to hit any point on the board shown. Find the theoretical probability that a dart hitting the board scores 100 points.
Understand the problem.
You are given the dimensions of a circular dartboard. You are asked to find the theoretical probability of hitting the center circle.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cc 1
Make a plan.
Find the area of the center circle and the area of the entire dart board. To find the theoretical probability of scoring 100 points, divide the area of the center circle by the area of the entire dart board.
Solve and check.
Use the plan to solve the problem. Then check your solution.
Answer:
Area of center =31,400 sq in
area of entire dart board = 1,962.5 sq in

Explanation:
Area of center circle = π r ²
a = 3.14 x 100 x 100
a = 31,400  sq in
area of entire dart board =  π r ²
a = 3.14 x 25 x 25
a = 3.14 x 625
a = 1,962.5 sq in

Question 2.
A scale drawing of a window is shown. Find the perimeter and the area of the actual window. Justify your answer.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cc 2
Answer:
Area of semicircle = 1.695sq ft
perimeter of semicircle = 1.58 sq ft

Explanation:
area of the semicircle = ( π + r x r /2)
s . c = (3.14 + 0.5 x 0.5 /2)
s. c = (3.14 + 0.25 /2)
s . c = (3.39 /2
s. c = 1.695 sq ft
perimeter of the semicircle = (π + 2 ) x r
p= 3.14 + 2 x 0.5
p = 3.16 x 0.5
p = 1.58 sq ft

Question 3.
∠CAD makes up 20% of a pair of supplementary angles. Find the measure of ∠DAE. Justify your answer.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cc 3
Answer:
∠DAE = 30 %

Explanation:
Given that ∠CAD = 20%
so
∠DAE = 30 %

Performance Task

Finding the Area and Perimeter of a Track
At the beginning of the this chapter, you watched a STEAM video called “Track and Field”. You are now ready to complete the performance task related to this video, available at BigIdeasMath.com. Be sure to use the problem-solving plan as you work through the performance task.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cc 4

Geometric Shapes and Angles Chapter Review

Review Vocabulary

Write the definition and give an example of each vocabulary term.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 1

Graphic Organizers

You can use a Four Square to organize information about a concept. Each of the four squares can be a category, such as definition, vocabulary, example, non-example, words, algebra, table, numbers, visual, graph, or equation. Here is an example of a Four Square for circumference.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 2

Choose and complete a graphic organizer to help you study each topic.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 3
1. area of a circle
2. semicircle
3. composite figure
4. constructing triangles
5. constructing quadrilaterals
6. complementary angles
7. supplementary angles
8. vertical angles

Answer:
1. area of a circle = π r ²
2. semicircle = ( π  +  r ²/2)
3. composite figure = The figure that consists of two or more geometric shapes.
4. constructing triangles = A triangle is a 3 – sided polygon made up of three sides having 3 angles.
5. constructing quadrilateral = quadrilateral can be categorized by the lengths of its sides and the size of its angles.
6. complementary angles = Two angles are called complimentary when their measures add to 90°
7. supplementary angles = two angles are called supplementary when their measures add to 180°
8. vertical angles = The angles opposite each other when two lines cross.

Chapter Self-Assessment

As you complete the exercises, use the scale below to rate your understanding of the success criteria in your journal.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 4

9.1 Circles and Circumference (pp. 361–368)
Learning Target: Find the circumference of a circle.

Question 1.
What is the radius of a circular lid with a diameter of 5 centimeters?
Answer:
radius = 50 mm

Explanation:
radius  = ( d / 2)
radius  = (5/ 2) cm
r = 2.5  cm

Question 2.
The radius of a circle is 25 millimeters. Find the diameter.
Answer:
Diameter = 50 mm

Explanation:
diameter = 2 x radius
diameter = 2 x 25  mm
d = 50 mm

Find the circumference of the object. Use 3.14 or \(\frac{22}{7}\) for π.
Question 3.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 5
Answer:
circumference of the object = 37.68 sq mm

Explanation:
D. circumference of the circle =2πr
circle = 2 x 3.14 x 6 where r =6 given
circle = 6.28 x  6
circle =37.68 sq mm

Question 4.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 6
Answer:
circumference of the object = 4.71 sq ft

Explanation:
D. circumference of the circle =2πr
circle = 2 x 3.14 x 0.75 where r =0.75 given
circle = 6.28 x  0.75
circle =4.71 sq ft

Question 5.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 7
Answer:
circumference of the object = 4.71 sq cm

Explanation:
D. circumference of the circle =2πr
circle = 2 x 3.14 x 3 .5 where r =3.5 given
circle = 6.28 x  3.5
circle =21.98  sq cm

Question 6.
You are placing non-slip tape along the perimeter of the bottom of a semicircle-shaped doormat. How much tape will you save applying the tape to the perimeter of the inside semicircle of the doormat? Justify your answer.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 8
Answer:
the tape saved = 47 .4 sq in
Explanation:
perimeter of the semicircle = ( π + 2 ) r
p = ( 3.14 + 2) 15
p = (3 .16 ) 15
p = 47.4 sq in

Question 7.
You need to carry a circular cake through a 32-inch wide doorway without tilting it. The circumference of the cake is 100 inches. Will the cake fit through the doorway? Explain.
Answer:
yes the cake fit through the doorway.
Explanation:
radius of the circle = (c/2π)
r= (100/6.28)
r = 15.923 sq in

Question 8.
Estimate the radius of the Big Ben clock face in London.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 9
Answer:
Radius of the Big Ben clock = 7.0063 m

Explanation:
radius of the circle = (c/2π)
r= (44/6.28)
r = 7.0063 m

Question 9.
Describe and solve a real-life problem that involves finding the circumference of a circle.
Answer:
The circumference of a circle = 2 π r

Explanation:
circle = 2 π r
where r = radius , π = 3.14

9.2 Areas of Circles (pp. 369-374)
Learning Target: Find the area of a circle.

Find the area of the circle. Use 3.14 or \(\frac{22}{7}\) for π.
Question 10.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 10
Answer:
The area of the circle = 50.24 sq in

Explanation:
Area of the circle = π x r x r
area = 3.14 x 4 x 4
area = 3.14 x 16
area = 50.24 sq in

Question 11.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 11
Answer:
The area of the circle = 379.94 sq cm

Explanation:
Area of the circle = π x r x r
area = 3.14 x 11 x 11
area = 3.14 x 121
area = 379.94 sq cm

Question 12.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 12
Answer:
The area of the circle = 1384.74 sq mm

Explanation:
Area of the circle = π x r x r
area = 3.14 x 21 x 21
area = 3.14 x 441
area = 1384.74 sq mm

Question 13.
A desktop is shaped like a semicircle with a diameter of 28 inches. What is the area of the desktop?
Answer:
The area of the desktop = 615.44 sq in

Explanation:
Area of the desktop = π x r x r
area = 3.14 x 14 x 14
area = 3.14 x 196
area = 615.44 sq in

Question 14.
An ecologist is studying an algal bloom that has formed on the entire surface of a circular pond. What is the area of the surface of the pond covered by the algal bloom?
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 14
Answer:
The area of the surface of the pond covered by the algol bloom = 615.44 ft

Explanation:
Area of the pond = π x r x r
area = 3.14 x 14 x 14
area = 3.14 x 196
area = 615.44 sq ft

Question 15.
A knitted pot holder is shaped like a circle. Its radius is 3.5 inches. What is its area?
Answer:
The area of the pot holder = 38.465 sq in

Explanation:
Area of the pot holder = π x r x r
area = 3.14 x 3.5 x 3.5
area = 3.14 x 12.25
area = 38.465 sq in

9.3 Perimeters and Areas of Composite Figures (pp. 375–380)
Learning Target: Find perimeters and areas of composite figures.

Find the perimeter and the area of the figure.
Question 16.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 16
Answer:
Area of semicircle = 1.695 sq in
perimeter of semicircle = 15.8 sq in

Explanation:
area of the semicircle = ( π + r x r /2)
s . c = (3.14 + 5 x 5 /2)
s. c = (3.14 + 25/2)
s . c = (3.39 /2 )
s. c = 1.695 sq in
perimeter of the semicircle = (π + 2 ) x r
p= 3.14 + 2 x 5
p = 3.16 x 5
p = 15.8 sq in

Question 17.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 17
Answer:
Area of semicircle = 6.07 sq ft
perimeter of semicircle = 9.48 sqft

Explanation:
area of the semicircle = ( π + r x r /2)
s . c = (3.14 + 3 x 3 /2)
s. c = (3.14 + 9/2)
s . c = (12.14 /2 )
s. c = 6.07 sq ft
perimeter of the semicircle = (π + 2 ) x r
p= 3.14 + 2 x 3
p = 3.16 x 3
p = 9.48 sq ft

Question 18.
GARDEN
You want to fence part of a yard to make a vegetable garden. How many feet of fencing do you need to surround the garden?
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 18
Answer:
The fencing need to surround the garden = 32 sq feet

Explanation:
area  of the rectangle = l + b
area = 18 + 14
area = 32 sq feet

9.4 Constructing Polygons (pp. 381-388)

Learning Target: Construct a polygon with given measures.

Draw a triangle with the given description, if possible.
Question 19.
a triangle with angle measures of 15°, 75°, and 90°
Answer:

Explanation:
Given triangle with angle measures.

Question 20.
a triangle with a 3-inch side and a 4-inch side that meet at a 30° angle
Answer:

Question 21.
a triangle with side lengths of 5 centimeters, 8 centimeters, and 2 centimeters
Answer:

Draw a quadrilateral with the given angle measures, if possible.
Question 22.
110°, 80°, 70°, 100°
Answer:

Question 23.
105°, 15°, 20°, 40°
Answer:

9.5 Finding Unknown Angle Measures (pp. 389–396)
Learning Target: Use facts about angle relationships to find unknown angle measures.

Use the figure shown.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 24
Question 24.
Name a pair of adjacent angles.
Answer:
x , y , v , w .

Explanation:
In the above-given figure, the adjacent angles are x, y, v, w.

Question 25.
Name a pair of complementary angles.
Answer:
u and z

Explanation:
complementary angles = u , z

Question 26.
Name a pair of supplementary angles.
Answer:
x , y , v , z

Explanation:
supplementary are x , y , v , z
Question 27.
Name a pair of vertical angles.
Answer:
x , y , v, w

Explanation:
pair of vertical angles are x , y , v , w

Classify the pair of angles. Then find the value of x.
Question 28.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 28
Answer:
x = 111 degrees.

Explanation :
x = 56
x =180  – 69
x = 111 degree

Question 29.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 29
Answer:
x = 81 degrees.

Explanation :
x + 3  = 84
x =84   – 3
x = 81  degree

Question 30.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 30
Answer:
x = 3.33degrees.

Explanation :
(4x + 10) = x
10 = x – 4 x
3 x = 10
x = 3.33  degree

Question 31.
Describe two ways to find the measure of ∠2.
Big Ideas Math Answers 7th Grade Chapter 9 Geometric Shapes and Angles cr 31
Answer:
angle 2 = 65

Explanation:
x = 180 – 115
x = 65
2 = 65

Question 32.
Using the diagram from Exercises 24–27, find all the angle measures when ∠XUY = 40°.
Answer:

Geometric Shapes and Angles Practice Test

Question 1.
Find the radius of a circle with a diameter of 17 inches.
Answer:
radius of a circle = 8.5 in

Explanation:
radius of a circle = (d / 2)
radius =( 17 / 2)
radius = 8.5 in
Find (a) the circumference and (b) the area of the circle. Use 3.14 or \(\frac{22}{7}\) for π.
Question 2.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles pt 2
Answer:
Area of the circle = 3.14 m
circumference of the circle = 6.28 m

Explanation:
Area of the circle = π x r x r
area = 3.14 x 1 x 1
area = 3.14 m
circumference of the circle = 2 x π x r
c = 2 x 3.14 x 1
c = 6.28 m

Question 3.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles pt 3
Answer:
Area of the circle = 3846.5 sq in
circumference of the circle = 219. 8 sq in

Explanation:
Area of the circle = π x r x r
area = 3.14 x 35 x 35
area = 3.14 x 1,225 sq in
area = 3846.5 sq in
circumference of the circle = 2 x π x r
c = 2 x 3.14 x 35
c = 6.28 x 35
c = 219.8 sq in

Find (a) the perimeter and (b) the area of the figure. Use 3.14 or \(\frac{22}{7}\) for π.
Question 4.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles pt 4
Answer:
Area of semicircle = 2.695 sq ft
perimeter of semicircle = 4. 74 sq ft

Explanation:
area of the semicircle = ( π + r x r /2)
s . c = (3.14 + 1.5 x 1.5 /2)
s. c = (3.14 + 2.25 /2)
s . c = (5.39 /2 )
s. c = 2.695 sq ft
perimeter of the semicircle = (π + 2 ) x r
p= 3.14 + 2 x 1.5
p = 3.16 x 1.5
p = 4. 74 sq ft

Question 5.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles pt 5
Answer:
Area of semicircle = 9.57 sq ft
perimeter of semicircle = 12.64 sq ft

Explanation:
area of the semicircle = ( π + r x r /2)
s . c = (3.14 + 4 x 4 /2)
s. c = (3.14 + 16 /2)
s . c = (19.14 /2 )
s. c = 9.57  sq ft
perimeter of the semicircle = (π + 2 ) x r
p= 3.14 + 2 x 4
p = 3.16 x 4
p = 12.64 sq ft

Draw a figure with the given description, if possible.
Question 6.
a triangle with sides of length 5 inches and 6 inches that meet at a 50° angle.
Answer:

Question 7.
a triangle with side lengths of 3 inches, 4 inches, and 5 inches
Answer:

Question 8.
a quadrilateral with angle measures of 90°, 110°, 40°, and 120°
Answer:

Classify each pair of angles. Then find the value of x.
Question 9.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles pt 9
Answer:
x = 9 degrees.

Explanation:
(8x + 2) = 74
8x = 74 – 2
8x = 72
x = (72/8)
x = 9

Question 10.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles pt 10
Answer:
x = 50 degrees.

Explanation:
(x + 6) = 56
x = 56 – 6
x = 50
Question 11.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles pt 11
Answer:
x = 67 degrees.

Explanation:
x = 180 – 113
x = 67 degrees.

Question 12.
A museum plans to rope off the perimeter of the 60 ftL-shaped exhibit. How much rope does it need?
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles pt 12
Answer:
Area of the museum = 2,826 sq ft

Explanation:
Area of the museum  = π x r x r
area = 3.14 x 30 x 30
area = 3.14 x 900
area =  2,826 sq ft

Geometric Shapes and Angles Cumulative Practice

Question 13.
Draw a pair of adjacent angles that are neither complementary nor supplementary.
Answer:

Question 14.
The circumference of a circle is 36.2 centimeters. What is the length of the diameter of the circle?
Answer:
Diameter of the circle = 11.52866 cm

Explanation:
Diameter of the circle = 2 x r
radius of the circle = (c / 2 π )
circumference = 36.2 cm
radius = (36.2 / 6.28)
radius = 5.7643
daimeter = 2 x r
diameter = 5.7643 x 2
diameter = 11.52866 cm

Question 15.
The circular rug is placed on a square floor. The rug touches all four walls. How much of the floor space is not covered by the rug?
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles pt 15
Answer:
Area of the circle = 176.625sq ft

Explanation:
Area of the circle  = π x r x r
area = 3.14 x 7.5 x 7.5
area = 3.14 x 56.25
area =  176.625 sq ft

Geometric Shapes and Angles Cumulative Practice

Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles cp 1
Question 1.
To make 6 servings of soup, you need 5 cup of chicken broth. You want to know how many servings you can make with 2 quarts of chicken broth. Which proportion should you use?
A. \(\frac{6}{5}=\frac{2}{x}\)
B. \(\frac{6}{5}=\frac{x}{2}\)
C. \(\frac{6}{5}=\frac{x}{8}\)
D. \(\frac{5}{6}=\frac{x}{8}\)
Answer:
option B is correct.

Explanation:
Given that in the question to make 6 servings of soup you need 5 cup of chicken broth.

Question 2.
What is the value of x?
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles cp 2
Answer:
x = 42 degrees.

Explanation:
(2x + 1) = 85
2x = 85 – 1
2x = 84
x = (84/2)
x = 42

Question 3.
Your mathematics teacher described an inequality in words.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles cp 3
Which inequality matches your mathematics teacher’s description?
F. 7n – 5 < 42 G. (7 – 5)n > 42
H. 5 – 7n > 42
I. 7n – 5 > 42
Answer:
option G is correct.

Explanation:
5 is less than the product of 7 and an unknown number is greater than 42.
(7 – 5)n > 42

Question 4.
What is the approximate area of the circle below? (Use \(\frac{22}{7}\) for π).
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles cp 4
A. 132 cm2
B. 264 cm2
C. 5544 cm2
D. 22,176 cm2
Answer:
Area of the circle = 63.585 sq ft

Explanation:
Area of the circle  = π x r x r
area = 3.14 x 42 x 42
area = 3.14 x 1,764
area =  5,538.96 cm

Question 5.
You have a 50% chance of selecting a blue marble from Bag A and a 20% chance of selecting a blue marble from Bag B. Use the provided simulation to answer the question, “What is the estimated probability of selecting a blue marble from both bags?”
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles cp 5
F. 12%
G. 16%
H. 24%
I. 88%
Answer:
option F is correct.

Explanation:
The digits 1 and 2 in the ones place represent selecting a blue marble from bag B.
The digits 1 through 5  in the tens place represent selecting a blue marble from bag A.

Question 6.
Which proportion represents the problem?
“What number is 12% of 125?”
A. \(\frac{n}{125}=\frac{12}{100}\)
B. \(\frac{12}{125}=\frac{n}{100}\)
C. \(\frac{125}{n}=\frac{12}{100}\)
D. \(\frac{12}{n}=\frac{125}{100}\)
Answer:
option B is correct.

Explanation:
(12/125 ) x 100
(12/5) x 4
Question 7.
What is the approximate perimeter of the figure below? (Use 3.14 for π)
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles cp 7
Answer:
The perimeter of the semicircle = 18. 84

Explnation:
perimeter = ( π + 2 x r)
perimeter = (6.28 x 3 )
perimeter = 18 . 84

Question 8.
A savings account earns 2.5% simple interest per year. The principal is $850. What is the balance after 3 years?
F. $63.75
G. $871.25
H. $913.75
J. $7225
Answer:

Question 9.
Two ponds each contain about 400 fish. The double box-and-whisker plot represents the weights of a random sample of 12 fish from each pond. Which statement about the measures of center and variation is true?
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles cp 9
A. The variation in the samples is about the same, but the sample from Pond A has a greater median.
B. The variation in the samples is about the same, but the sample from Pond B has a greater median.
C. The measures of center and variation are about the same for both samples.
D. Neither the measures of center nor variation are the same for the samples.
Answer:
option D is correct.

Explanation:
Neither the measures of center nor variation are same for the samples.

Question 10.
A lawn sprinkler sprays water onto part of a circular region, as shown below.
Big Ideas Math Answers Grade 7 Chapter 9 Geometric Shapes and Angles cp 11
Part A What is the area, in square feet, of the region that the sprinkler sprays with water? Explain your reasoning. (Use 3.14 for π.)
Part B What is the perimeter, in feet, of the region that the sprinkler sprays with water? Explain your reasoning. (Use 3.14 for π.)
Answer:
part A The region that sprinkler sprays with water = 1,256 ft
part B The region that sprinkler sprays with water = 125 .6 ft

Explanation:
area of the circle = π x r x r
area = 3.14 x 20 x 20
area = 1256 ft
perimeter of the circle =  2 x π x r
perimeter = 2 x 3.14 x 20
perimeter = 125. 6 ft

Question 11.
What is the least value of x for which x – 12 ≥ – 8 is true?
F. – 20
G. – 4
H. 4
I. 5
Answer:
option F is correct.

Explanation:
x – 12 ≥ – 8
x = -20

Final Words:

Access Big Ideas Math Book 7th Grade Answer Key 9 Geometric Shapes and Angles from the direct links presented above. Hit the direct links and prepare yourself for the exam. With the help of the problems, you can test yourself and your capability of solving the problems. Cumulative practice, Chapter review, the Practice test will help you throughout your preparation.

Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data

Big Ideas Math Answers Grade 2 Chapter 13

Do you feel maths is a difficult subject and worried about the test? If yes, then don’t worry we are here to help you out to overcome the difficulties in maths. Get free access to download Big Ideas Math Answers 2nd Grade 13th Chapter Represent and Interpret Data pdf from this page. Students can find various tricks to solve the questions. Learn how to represent data in different ways with the help of BIM Book Grade 2 Chapter 13 Represent and Interpret Data Answers.

Big Ideas Math Book Grade 2 Answer Key Chapter 13 Represent and Interpret Data

It is necessary for the students to go through the topics included in this chapter before starting their preparation. The list of lessons in Chapter 13 Represent and Interpret Data are Sort and Organize Data, Real and Interpret Picture Graphs, Make Picture Graphs, Real and Interpret Bar Graphs, Make Bar Graphs, Make Line Plots, and Measure Objects and Make Line Plots.

You can understand the concepts quickly and easily by referring to Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data. The quick links are attached at the end for the reference of students.

Vocabulary

Lesson: 1 Sort and Organize Data

Lesson: 2 Real and Interpret Picture Graphs

Lesson: 3 Make Picture Graphs

Lesson: 4 Real and Interpret Bar Graphs

Lesson: 5 Make Bar Graphs

Lesson: 6 Make Line Plots

Lesson: 7 Measure Objects and Make Line Plots

Chapter- 13: Represent and Interpret Data

Represent and Interpret Data Vocabulary

Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data v1
Organize It
Use the review words to complete the graphic organizer.
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data v2

Answer:
The number of students who choose math = 6.
The number of students who choose science = 5

Explanation:
In the above-given figure,
the number of students who choose math = 6
the number of students who choose science = 5
the more number of students choose maths than science.

.Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13-1

Organize It
Use your vocabulary cards to identify the word.
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data v3

Answer:
1. The pencil lengths of each student = 4, 5, 6, and 7.

Explanation:
The number of pencil lengths of all students = 4, 5, 6, and 7.
the max length of the pencil = 5
In the above-given figure is a line plot.
given that the pencil lengths in inches = 4, 5, 6, and 7.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13-2

Answer:
2. The more number of students whose favorite hobby is singing = 7.

Explanation:
In the above-given figure,
the total number of students = 8
the number of students whose favorite hobby dancing = 6.
the number of students whose favorite hobby running = 5.
the number of students whose favorite hobby singing = 7.
The more number of students whose favorite hobby is singing = 7.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13-3

Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data v4.1
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data v4
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data v5.1
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data v5

Lesson 13.1 Sort and Organize Data

Explore and Grow

Look at your color tiles. Complete the tally chart.
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data 13.1 1
Answer:
The tile colors are blue, green, red, and yellow.

Explanation:
In the above-given figure,
given the tile, colors are blue, green, red, and yellow.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.1-1

Write and answer a question about your tally chart.

Answer:
The more number of students they choose yellow = 5.

Explanation:
In the above-given figure,
the number of students who choose blue = 2.
the number of students who choose green = 3.
the number of students who choose red = 4.
the number of students who choose yellow = 5.
the more number of students who choose yellow = 5.

Show and Grow

Question 1.
Use the data to complete the tally chart.
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data 13.1 2
How many students chose math? ________
Which subject is the most favorite? _________

Answer:
The students who choose math = 7.
The most favorite subject = math.

Explanation:
The students who choose math = 7.
The students who choose science = 4.
The students who choose social studies = 2.
The students who choose language arts = 3.

Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.1-2

Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.1-3

Apply and Grow: Practice

Question 2.
Use the data to complete the tally chart.
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data 13.1 3
Which animal is the least favorite? ________
How many students did not choose fox? How do you know?

Answer:
The least favorite animal = owl
the students did not choose fox = 12.

Explanation:
In the above-given figure,
the least favorite animal = owl.
the students did not choose fox = 12.
the total number of students = 18
18 – 6 = 12
12 students did not choose fox.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.1-4

Did more students choose fox or owl?
_______
How many more? ______ more

Did fewer students choose reindeer or polar bear?
________
How many fewer? ______ fewer

Answer:
The more students choose fox = 7.
the more students = 7
the fewer students choose a polar bear.
fewer = 3

Explanation:
The students who choose fox = 7.
the students who choose more = 7
the students who choose fewer = polar bear
polar bear = 3
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.1-4

Question 3.
Reasoning
Which sentences are correct?
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data 13.1 4
You survey 30 students.
11 students chose whale.
4 more students chose seal than penguin.
20 students did not choose seal.

Answer:
4 more students choose seal than penguin is correct.

Explanation:
In the above-given figure,
the penguin = 14
whale = 6
seal = 10

Think and Grow: Modeling Real Life

Newton wants to survey25 students. How many more students does he need to survey?
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data 13.1 5
Addition equation:

_______ students

Answer:
The more students does he need to survey = 6 students.

Explanation:
In the above-given figure,
the total number of students = 19.
newton wants 25 students.
19 + 6 = 25
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.1-5

Show and Grow

Question 4.
Descartes wants to survey 20 students. How many more students does he need to survey?
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data 13.1 6
_______ students

Answer:
The more students do he need to survey = 2 students.

Explanation:
In the above-given figure,
the total number of students = 18.
Descartes wants 20 students.
18 + 2 = 20.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.1-6

How many more students need to choose sneakers so that the numbers of students who choose sneakers and sandals are equal?
______ students

Answer:
The students need to choose sneakers so that the number of students who choose sneakers and sandals is equal = 2 students.

Explanation:
In the above-given figure,
the sandals = 6
sneakers = 4
6 – 4 = 2
2 students.

Sort and Organize Data Homework & Practice 13.1

Question 1.
Use the data to complete the tally chart.
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data 13.1 7
Which activity is the most favorite? _______
Did more students choose catch or sidewalk chalk? _______
How many more?
______ more

Answer:
The activity the most favorite = tag.
The more students choose catch than sidewalk chalk.
0ne more.

Explanation:
The most favorite activity = tag.
Most students choose catch than the sidewalk.
sidewalk = 2
catch = 4
bubbles are more.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.1-7

Question 2.
Modeling Real Life
Newton wants to survey 15 friends. How many more friends does he need to survey?
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data 13.1 8

Answer:
The more friends he needs to survey = 4.

Explanation:
Given that newton wants 15 friends to survey.
but in the figure, he has only 11 friends.
11 + 4 = 15
the more friends he wants to survey = 4
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.1-8

Question 3.
Writing
In Exercise 2, what question did Newton ask?
__________________
__________________

Answer:
Newton wants to survey 15 friends.

Explanation:
In the above-given question, he wants to survey more friends.
the more friends = 4
in the figure given that 11 friends.
11 + 4 = 15.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.1-9

Question 4.
Modeling Real Life
You want to survey 30 students. How many more students do you need to survey?
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data 13.1 9
______ students
How many more students need to choose coloring so that the numbers of students who choose coloring and puppets are equal?
______ students

Answer:
The more students you need to survey = 10 students.

Explanation:
In the above-given figure,
The total number of students = 20
The more number of students you need to survey = 10.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.1-10
Review & Refresh

Question 5.
153 − 10 = ______

Answer:
153 – 10 = 143

Explanation:
153 – 10 = 143
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.1-12

Question 6.
978 − 10 = ______

Answer:
978 – 10 = 968

Explanation:
978 – 10 = 968
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.1-13

Question 7.
642 − 100 = ______

Answer:
642 – 100 = 542

Explanation:
642 – 100 = 542
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.1-14

Question 8.
1,000 −100 = ______

Answer:
1000 – 100 = 900

Explanation:
1000 – 100 = 900
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.1-15

Lesson 13.2 Real and Interpret Picture Graphs

Explore and Grow

How are the tally chart and the picture graph the same? How are they different?
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.2 1
__________________
___________________

Answer:
Yes, the tally chart and picture graph represents the same.

Explanation:
The favorite bird = 2.
cat = 4
dog = 7.
So in the tally chart and the picture graph represents the same.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.2-1

Show and Grow

Question 1.
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.2 2
How many students chose butterfly? _______
Which insect is the most favorite? ______
Which insect is the least favorite? _______

Answer:
The students who choose butterfly = 7
The most favorite insect= 8
The least favorite insect = 2

Explanation:
In the above-given figure,
The insects bumblebee = 2
ladybug = 8
grasshopper = 6
butterfly = 7
The students who choose butterfly = 7
The most favorite insect= 8
The least favorite insect = 2
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.2-2

Apply and Grow: Practice

Question 2.
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.2 3
How many students chose sporting event? _______
Which school trip is the least favorite? _______
How many more students chose science center than the park? _______

Answer:
The students who choose sporting event = 8
The least favorite school trip = park
The more students who choose science center than the park = 3

Explanation:
In the above-given figure,
the science center = 5
park = 2
sporting event = 8
museum = 3
The students who choose sporting event = 8
The least favorite school trip = park
The more students who choose science center than the park = 3
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.2-3

Question 3.

Number Sense
Use the numbers to complete the sentences.
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.2 4
Newton has ______ siblings.
Your friend has _______ siblings.
Your friend has ______ more siblings than your cousin.

Answer:
Newton has 2 siblings.
your friend has 4 siblings.
your friend has 3 more siblings than your cousin.

Explanation:
In the above-given figure,
your cousin has 1 sibling.
your friend has 4 siblings.
newton has 2 siblings.
Descartes has 3 siblings.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.2-4

Think and Grow: Modeling Real Life

Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.2 5
Do more students like crabs and sea turtles or octopuses and jellyfish?
Addition equations:
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.2 6
More students like ______ and _______.

Answer:
The more students like sea turtle = 9
More students like octopus and sea turtle.

Explanation:
In the above-given figure,
the students like crab = 6
the students who like octopus = 8
the students who like jellyfish = 3
the students who like sea turtle = 9
The more students like sea turtle = 9
More students like octopus and sea turtle.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.2-5

Show and Grow

Question 4.
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.2 7
Do you see more cars and motorcycles or vans and trucks?
You see more _______ and ______.

Answer:
We see more cars.

Explanation:
In the above-given figure,
the cars = 9
vans = 8
truck  4
motorcycles = 2
we see more cars than other vehicles.

Real and Interpret Picture Graphs Homework & Practice 13.2

Question 1.
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.2 8
Which fruit do exactly 7 students like most? _______
How many students like the fruit with the fewest votes? _______
How many more students chose banana than pear? _____

Answer:
The fruits exactly 7 students like most = banana.
the students who like the fewest = apple.
the more students choose banana than pears = 3

Explanation:
In the above-given figure,
The students who like apple = 4
the students who like pears = 5
The students who like grapes = 7
the students who like banana = 8
The fruits exactly 7 students like most = banana.
the students who like the fewest = apple.
the more students choose banana than pears = 3
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.2-6

Question 2.
Writing
Use the picture graph.
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.2 9
Write two true statements about the picture graph.
____________________
____________________

Answer:
The students who choose bus = 6
The students who choose walk= 4
The students who choose car = 2
The students who choose subway = 5

Explanation:
In the above- given figure,
the students who choose bus = 6
The students who choose walk= 4
The students who choose car = 2
The students who choose subway = 5
the more students choose the bus.
fewer students choose cars.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.2-7

Question 3.
Modeling Real Life
Use the picture graph.
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.2 10
Do more students like to play video games and read or play outside and watch TV?
More students like to ______ and ______.

Answer:
The more students like to play video games.

Explanation:
In the above-given figure,
the students who like to play outside = 6
the students who like to play video games = 9
the students who like to watch tv= 7
the students who like to read = 3
the more students like to play videogames and watching tv
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.2-8
Review & Refresh

Question 4.
What is the best estimate of the length of a keyboard?
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.2 11
Answer: 18 inches

Lesson 13.3 Make Picture Graphs

Explore and Grow

Look at your color tiles. Complete the tally chart and the picture graph.
Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data 13.3 1

Answer:
The number of students who like blue = 2
The number of students who like green = 3
The number of students who like red = 4
The number of students who like yellow = 5
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.3-1

Show and Grow

Question 1.
Complete the picture graph.
Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data 13.3 2
Which fruit is the most favorite? ______
Which fruit is the least favorite? ________
How many more students chose apple than banana? _________

Answer:
The favorite fruit = apple.
the least favorite = strawberry
The students choose apple than banana = 1

Explanation:
In the above-given figure,
The students who choose orange = 4
The students who choose strawberry = 2
The students who choose apple = 6
The students who choose banana = 5
The favorite fruit = apple.
the least favorite = strawberry
The students choose apple than banana = 1
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.3-2

Apply and Grow: Practice

Question 2.
Complete the picture graph.
Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data 13.3 3
How many students chose the most favorite bird? ________
How many students chose flamingo or penguin? _______

Answer:
The students who choose penguin = 7
the students who choose flamingo or penguin = 6 or 7

Explanation:
In the above-given figure,
the students who choose penguin = 7
the students who choose flamingo = 5
the students who choose own = 3
the students who choose parrot = 2
The students who choose penguin = 7
the students who choose flamingo or penguin = 6 or 7

Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.3-3

Question 3.
Complete the picture graph.
Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data 13.3 4
Newton gives 4 coins to Descartes. How many coins does Newton have now? How do you know?
____________________
____________________

Answer:
Newton has zero coins.

Explanation:
In the above-given figure,
the newton has 4 coins.
Descartes has 6 coins.
I have 6 coins.
Given that newton gives 4 coins to Descartes.
so newton has 0 coins.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.3-4

Think and Grow: Modeling Real Life

You ask 20 students to name their eye colors. 9 have brown eyes. 3 more students have brown eyes than blue eyes. The rest have green eyes. Complete the picture graph.
Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data 13.3 5

Answer:
The students who have green eyes = 8

Explanation:
In the above-given question, given that
9 have brown eyes.
3 students have blue eyes.
the students who have green = 8
20 – 8 = 12
9 + 3 = 12.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.3-5

Show and Grow

Question 4.
You ask 15 students which community helper is their favorite. 6 choose police officer. 2 fewer students choose doctor than police officer. The rest choose firefighter. Complete the picture graph.
Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data 13.3 6
How did you find how many students chose firefighter?

Answer:
The students who choose firefighter = 5

Explanation:
The students who choose police officer = 6
The students who choose doctor = 2
The students who choose fire fighter= 5
8 + 5 = 15
15 – 10 = 5
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.3-6

Make Picture Graphs Homework & Practice 13.3

Question 1.
Complete the picture graph.
Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data 13.3 7
Who has the least medals? _______
How many more medals do you have than your friend? _________
How many medals do Newton and Descartes have in all? ________

Answer:
Your friend has the least medals.
the medals I have more than my friend = 2
Newton and Descartes have all the medals = 11

Explanation:
In the above-given figure,
I have 4 medals.
my friend has 2 medals.
Newton has 5 medals.
descartes have 6 medals.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.3-10

Question 2.
Complete the picture graph.
Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data 13.3 8

2 more students chose tomato soup. How many students chose tomato now? How do you know?

Answer:
The students who choose tomato soup = 8

Explanation:
In the above-given figure,
The students who choose alphabet = 7
The students who choose vegetable = 3
the students who choose tomato = 6
given that 2 more students choose tomato soup.
6 + 2 = 8
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.3-11

Question 3.
Modeling Real Life
You ask 20 students about their favorite way to exercise. 4 like to walk. 6 like to swim. The rest like to bike. Complete the picture graph.
Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data 13.3 9
How did you find how many students like to bike?

Answer:
The students who like to walk = 4.
The students who like to swim = 6.
Rest of the students who like bike = 10

Explanation:
In the above-given figure,
The students who like to walk = 4.
The students who like to swim = 6.
Rest of the students who like bike = 10
20 – 4 + 6
20 – 10
10
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.3-12

Review & Refresh

Question 4.
Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data 13.3 10

Answer:
415 – 273 = 142

Explanation:
415 – 273 = 142
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.3-7

Question 5.
Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data 13.3 11

Answer:
583 – 127 = 456

Explanation:
583 – 127 = 456
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.3-8

Question 6.
Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data 13.3 12

Answer:
892 – 105 = 787

Explanation:
892 – 105 = 787
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.3-9

Lesson 13.4 Real and Interpret Bar Graphs

Explore and Grow

How are the tally chart and the bar graph the same? How are they different?
Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data 13.4 1
Based on the given values they are the same.
If they give different values they are different.

Answer:

The number of students who choose baseball = 6
The number of students who choose basketball = 5
The number of students who choose soccer = 7

Explanation:
In the above-given figure,
The number of students who choose baseball = 6
The number of students who choose basketball = 5
The number of students who choose soccer = 7
The students whose favorite spot = soccer.

Show and Grow

Question 1.
Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data 13.4 2
How many students chose computer? _______
Which activity is the least favorite? ________

Answer:
The students who choose computer = 8.
The least favorite activity = reading.

Explanation:
In the above-given figure,
The students who choose painting = 4
the students who choose computer = 8
the students who choose reading = 3
the students who choose games = 6
The students who choose computer = 8.
The least favorite activity = reading
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.4-1

Apply and Grow: Practice

Question 2.
Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data 13.4 3.1
How many students chose breakfast? _______
Which meal is the most favorite? ________
How many students chose the meal that is least favorite? ________
How many more students chose snack than lunch? _______

Answer:
The students who choose breakfast = 7.
the most favorite meal = Dinner.
The students chose the meal that is least favorite = 4
The students choose snack than lunch = 2

Explanation:
The students who choose breakfast = 7.
The students who choose lunch = 4.
The students who choose dinner = 9.
The students who choose snack = 6.
The students who choose breakfast = 7.
the most favorite meal = Dinner.
The students chose the meal that is least favorite = 4
The students choose snack than lunch = 2
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.4-2

Question 3.
DIG DEEPER!
Order the meals in Exercise 2 from the least favorite to the most favorite.
______, ______, ________, ________

Answer:
Lunch, snack, breakfast, and dinner.

Explanation:
In the above-given figure
given that order the meals from least favorite to the most favorite.
the least favorite = lunch.
the most favorite = dinner.
lunch, snack, breakfast, dinner.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.4-3

Think and Grow: Modeling Real Life

Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data 13.4 3
A student chooses a food that has 1 more vote than eggs and toast combined. Which food does the student choose?
The student chooses ________.

Answer:
The students who choose 1 more than eggs = toast.

Explanation:
In the above-given figure,
The students who choose cereal = 9
The students who choose toast = 5
The students who choose pancakes = 8
The students who choose eggs = 3
The students who choose 1 more than eggs = toast.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.4-4

Show and Grow

Question 4.
Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data 13.4 4
A student chooses an activity that has the same number of votes as crafts and hiking combined. Which activity does the student choose?
The student chooses ________

Answer:
The student who chooses an activity that has the same number of votes as crafts and hiking combined = Archery.

Explanation:
In the above-given figure,
the student who chooses archery = 6
the student who chooses crafts = 4
the student who chooses Hiking = 2
the student who chooses swimming = 7
The student who chooses an activity that has the same number of votes as crafts and hiking combined = Archery.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.4-5

Real and Interpret Bar Graphs Homework & Practice 13.4

Question 1.
Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data 13.4 5
How many students chose police officer? _________
How many more students chose teacher than nurse? _________

Answer:
The students who choose police officer = 7.
The more students choose teacher than nurse = 1

Explanation:
In the above-given figure,
The students who choose teacher job = 5
The students who choose police officer job = 7
The students who choose sports player job = 8
The students who choose nurse job = 4
The students who choose police officer = 7.
The more students choose teacher than nurse = 1
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.4-6

Question 2.
Writing
How can you use a bar graph to find how many students were surveyed?
__________________
__________________

Answer:
The number of students surveyed = 24 students.

Explanation;
In the above-given graph
The students who choose teacher job = 5
The students who choose police officer job = 7
The students who choose sports player job = 8
The students who choose nurse job = 4
The total number of students were surveyed = 24 students.

Question 3.
Modeling Real Life
Use the bar graph.
Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data 13.4 6
A student chooses a writing tool that has 3 fewer votes than crayon and marker combined. Which writing tool does the student choose?
The student chooses ______.

Answer:
The student chooses a writing tool that has 3 fewer votes than crayon and marker combined = pen.

Explanation:
In the above-given graph,
the student who chooses pencil = 4
the student who chooses pen = 6
the student who chooses crayon = 2
the student who chooses marker = 5
The student chooses a writing tool that has 3 fewer votes than crayon and marker combined = pen.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.4-7

Review & Refresh

Find the missing number.
Question 4.
Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data 13.4 7
Answer:
576 + 153  = 729

Explanation:
729 – 576 = 153
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.4-8

Question 5.
Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data 13.4 8
Answer:
431 + 389 = 820

Explanation:
820 – 431 = 389
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.4-9

Question 6.
Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data 13.4 9

Answer:
128 + 521 = 649

Explanation:
649 – 128 = 521
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.4-10

Lesson 13.5 Make Bar Graphs

Explore and Grow

Look at your Instrument Cards. Complete the tally chart and the bar graph.
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data 13.5 1
Answer:
The students who choose drum = 2
The students who choose trumpet = 3
The students who choose tuba = 4

Explanation:
In the above-given figure,
The students who choose drum = 2
The students who choose trumpet = 3
The students who choose tuba = 4
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.5-1

Show and Grow

Question 1.
Complete the bar graph.
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data 13.5 2
Which book type is the least favorite? _________
How many more students chose fiction than history? _______

Answer:
The least favorite book = history
The more students choose fiction than history = 3

Explanation:
In the above-given figure,
The students who choose history = 3
The students who choose fiction = 7
The students who choose science = 5
The students who choose poetry = 6
The least favorite book = history
The more students choose fiction than history = 3
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.5-2

Apply and Grow: Practice

Question 2.
Complete the bar graph.
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data 13.5 3
How many raisins are there? _________
How many more almonds are there than dried fruit? _______

Answer:
The raisins are = 6
The more almonds are there than dried fruit = 3

Explanation:
In the above-given figure,
The number of peanuts = 9
the number of raisins = 6
The number of almonds = 7
the number of dried fruit = 4
The raisins are 6
the more almonds are there than dried fruits = 3
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.5-3

Question 3.
Complete the bar graph.
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data 13.5 4
Which drink was chosen the most? _______
How many more people chose iced tea than water? _______

Answer:
The number of people who choose the drink most = Lemonade
The people who choose iced tea over water = 3

Explanation:
The number of people who choose water = 5
The number of people who chose fruit punch = 2
The number of people who choose lemonade = 9
The number of people who choose  iced tea 8
The number of people who choose the drink most = Lemonade
The people who choose iced tea over water = 3
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.5-4

Think and Grow: Modeling Real Life

You classify 30 animals as fish, mammals, or reptiles.11 are fish. 7 are reptiles. The rest are mammals. Complete the bar graph.
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data 13.5 5

Answer:
The mammals = 12.

Explanation:
In the above-given figure,
Given that the fishes are 11.
reptiles = 7
mammals = 12
11 + 7 = 18
30 – 18 = 12
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.5-5

Show and Grow

Question 4.
You ask 29 students if they want to collect seashells, fossils, or stickers. 8 said fossils. 12 said stickers. The rest said seashells. Complete the bar graph.
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data 13.5 6

DIG DEEPER!
You ask 3 more students which object they want to collect. 1 said fossils. 2 said seashells. How many fewer students chose fossils than seashells now?
_______ students

Answer:
The fewer students choose fossils than seashells now = 2.

Explanation:
In the above-given figure,
The number of students who choose seashells = 9
The number of students who choose fossils = 8
The number of students who choose stickers = 12
given that 29 students.
11 + 9 = 20
29 – 20 = 9
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.5-6
Make Bar Graphs Homework & Practice 13.5

Question 1.
Complete the bar graph.
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data 13.5 7
How many more votes did Spot receive than Sparkle? ______

Answer:
The more votes did spot receive than sparkle = 7

Explanation:
In the above-given figure,
The number of votes for spot = 9
The number of votes for sparkle = 2
The number of votes for flip = 7
The number of votes for star = 6
The more votes did spot receive than sparkle = 7
the spot receives 7 more votes than sparkle.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.5-7

Question 2.
Complete the bar graph.
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data 13.5 8
How many total animals are in the pet store? _______

Answer:
The total animals in the pet store = 20.

Explanation:
In the above-given figure,
Given that fish = 7
hamster = 5
snake = 4
rabbit = 4
total animals in the pet = 20 animals.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.5-8

Question 3.
Modeling Real Life
You, your friend, and your cousin hand out a total of 25 flyers. You hand out 12. Your friend hands out 9. Your cousin hands out the rest. Complete the bar graph.
Big Ideas Math Answer Key Grade 2 Chapter 13 Represent and Interpret Data 13.5 9
DIG DEEPER!
You hand out 1 more flyer. Your friend hands out4 more. How many fewer flyers does your cousin hand out than your friend now?
_______ flyers

Answer:
The many fewer flyers do your cousin hand out than your friend now = 9

Explanation:
In the above-given figure,
The flyers handed out by me = 12.
The flyers handed out by my friend = 9.
The flyers handed out by my cousin = 4.
given that flyers handed out by me = 12
totally there are 25 flyers.
12 + 9 = 25
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.5-9
Review & Refresh

Question 4.
861 − 410 = ______

Answer:
861 – 410 = 451

Explanation:
861 – 410 = 451
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.5-10

Question 5.
624 − 320 = ______

Answer:
624 – 320 = 304

Explanation:
624 – 320 = 304
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.5-11

Lesson 13.6 Make Line Plots

Explore and Grow

How are the thumb lengths shown on the number line?
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.6 1
Answer:
The thumb lengths for thumb 1, thumb 4, thumb 7 = 4 cms.
thumb 2 , thumb 6 = 5 cms.
thumb 3 = 3 cm
thumb 5 = 6cm

Explanation:
In the above-given figure,
given the thumb lengths.
The thumb lengths for thumb 1, thumb 4, thumb 7 = 4 cms.
thumb 2 , thumb 6 = 5 cms.
thumb 3 = 3 cm
thumb 5 = 6cm

Show and Grow

Question 1.
Complete the line plot.
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.6 2
How many long jumps are 43 inches long? _____
What is the most common long jump length? ______ inches

Answer:
One long-jump is 43 inches long = child 3.
the most common long jump length = child 1 and child 4.

Explanation:
In the above-given figure,
given that the long jump lengths.
child 1 and child 4 = 41
child 2 = 44
child 5 = 45
One long-jump is 43 inches long = child 3.
the most common long jump length = child 1 and child 4.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.6-1

Apply and Grow: Practice

Question 2.
Complete the line plot.
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.6 3
What is the most common puppy length? ______ inches
How many fewer puppies are 11 inches long than 10 inches long? ______
How many puppies are 8 or 9 inches long? ______
How many puppies are shorter than 11 inches? How do you know?
_____________________
____________________

Answer:
The most common puppy length = puppy 2, 3, 5, 6, and 7.
The fewer puppies are 11 inches longer than 10 inches long = puppy 1.
The puppies which are 8 or 9 inches long = 3 puppies.
The puppies which are shorter than 11 inches = 6 puppies.

Explanation:
In the above-given figure,
given the puppy lengths.
the puppy lengths with puppy 1 = 11 inches.
puppy 2 = 9 inches.
puppy 3 = 10 inches.
puppy 4 = 12 inches.
puppy 5 = 9 inches.
puppy 6 = 10 inches.
puppy 7 = 10 inches.
puppy 8 = 8 inches.
The most common puppy length = puppy 2, 3, 5, 6, and 7.
The fewer puppies are 11 inches longer than 10 inches long = puppy 1.
The puppies which are 8 or 9 inches long = 3 puppies.
The puppies which are shorter than 11 inches = 6 puppies.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.6-2

Think and Grow: Modeling Real Life

9 people measure the length of a guitar. The line plot shows the measured lengths. How long do you think the guitar is? Explain.
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.6 4.2
______ inches

Answer:
The length of the guitar = 35 inches.

Explanation:
In the above-given figure,
the number of inches in guitar lengths are:
the guitar length with 34 inches.
the guitar length with 35 inches.
the guitar length with 36 inches.

Show and Grow

Question 3.
8 people measure the length of a playground. The line plot shows the measured lengths.How long do you think the playground is? Explain.
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.6 5
______ meters
DIG DEEPER!
Why are the measurements different?

Answer:
The length o the playground = 51 meters.

Explanation:
In the above-given figure,
the number of meters of playgrounds is:
given that 8 people measure the length of the playground.
6 people choose 50 meters.
1 people choose 49 meters.
1 people choose 48 meters.

Make Line Plots Homework & Practice 13.6

Question 1.
Complete the line plot.
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.6 6
How many leaves are 13 centimeters long? _______
What is the most common leaf length? _______ centimeters
How many more leaves are 14 centimeters long than 12 centimeters long? ______
How many leaves are 14 or 15 centimeters? ________

Answer:
No leaves are 13 centimeters long.
the most common leaf lengths are leaf 2, leaf 3, and leaf 6.
the more leaves are 14 centimeters long than 12 centimeters long = leaf 1 and leaf 4.
The leaves are 14 or 15 centimeters = 5 leaves.

Explanation:
In the above-given figure,
given that, the leaf lengths.
the leaf 1 = 14 centimeters.
the leaf 2 = 15 centimeters
the leaf 3 = 15 centimeters
the leaf 4 = 14 centimeters
the leaf 5 = 12 centimeters
the leaf 6 = 15 centimeters
No leaves are 13 centimeters long.
the most common leaf lengths are leaf 2, leaf 3, and leaf 6.
the more leaves are 14 centimeters long than 12 centimeters long = leaf 1 and leaf 4.
The leaves are 14 or 15 centimeters = 5 leaves.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.6-3
Question 2.
Complete the line plot.
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.6 7
How many sharks are longer than 14 feet? How do you know?
____________

Answer:
The sharks which are longer than 14 feet = 3 sharks.

Explanation:
In the above-given figure,
given that the shark lengths in feets.
shark 1 = 14
shark 2 = 15
shark 3 = 16
shark 4 = 14
shark 5 = 12
shark 6 = 16
The sharks which are longer than 14 feet = 3 sharks.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.6-4

Question 3.
Modeling Real Life
8 people measure the length of a bus. The line plot shows the measured lengths. How long do you think the school bus is? Explain.
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.6 8
______ meters

Answer:
The length of the school bus = 105 meters.

Explanation:
In the above-given figure,
the lengths of the school bus is given.
given that 8 people measure the length of a bus.
the lone plot shows the measured lengths.
2 people measure the 14 meters.
1 people measure the 12 inches.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.6-5

Review & Refresh

Question 4.
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.6 9
Answer:
127.

Explanation:
36 + 4 + 22 + 65
40 + 22 + 65
62 + 65
127
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.6-5

Question 5.
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.6 10
Answer:
208.

Explanation:
95 + 68 + 45
163 + 45
208
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.6-6

Question 6.
Big Ideas Math Answers 2nd Grade Chapter 13 Represent and Interpret Data 13.6 11
Answer:
226.

Explanation:
76 + 50 + 18 + 82
126 + 18 + 82
144 + 82
226
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.6-7

Lesson 13.7 Measure Objects and Make Line Plots

Explore and Grow

Use a ruler to measure the caterpillars on Lengths of Caterpillars. Use the lengths to complete the chart and the line plot.
Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data 13.7 1

Answer:
The long length of the caterpillar = 9.

Explanation:
We have to assume the lengths of the cater pillars.
cater pillar 1 = 6 cms.
cater pillar 2 = 7 cms.
cater pillar 3 = 9 cms.
cater pillar 4 = 9 cms.
cater pillar 5 = 7 cms.
cater pillar 6 = 10 cms.
cater pillar 7 = 8 cms.
cater pillar 8 = 7 cms.
The long length of the caterpillar = 9
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.6-8

Show and Grow

Question 1.
Measure the lengths of 4 pencils. Complete the line plot.
Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data 13.7 2
What is the length of the longest pencil? _______ inches
How much longer is the longest pencil than the shortest pencil? _______ inches

Answer:
The length of the longest  pencil = 10 inches.
The longer is the longest pencil than the shortest penccil = 5 inches.

Explanation:
In the above-given figure,
given that the length of the 4 pencils.
the length of the pencil 1 = 5 inches.
pencil 2 = 6 inches.
pencil 3 = 8 inches.
pencil 4 = 10 inches.
The length of the longest  pencil = 10 inches.
The longer is the longest pencil than the shortest penccil = 5 inches.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.6-9

Apply and Grow: Practice

Question 2.
Measure the lengths of 8 shoes. Complete the line plot.
Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data 13.7 3
What is the length of the longest shoe? ______ inches
What is the length of the shortest shoe? _______ inches
How much shorter is the shortest shoe than the longest shoe? _______ inches
You measure 5 more shoes and they are each6 inches long. How does the line plot change?
_________________________
_________________________

Answer:
The length of the longest shoe = 10 inches.
The length of the shortest shoe = 6 inches.
The shorter is the shortest shoe than the longest shoe = 5 inches.
The line plot changes.

Explanation:
In the above-given figure,
we have to assume  the examples.
length of the shoe 1 = 6 inches.
length of the shoe 2 = 7 inches.
length of the shoe 3 = 6 inches.
length of the shoe 4 = 7 inches.
length of the shoe 5 = 8 inches.
length of the shoe 6 = 9 inches.
length of the shoe 7 = 10 inches.
length of the shoe 8 = 8 inches.
The length of the longest shoe = 10 inches.
The length of the shortest shoe = 6 inches.
The shorter is the shortest shoe than the longest shoe = 5 inches.
The line plot changes.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.6-10

Think and Grow: Modeling Real Life

A fire station is building a new garage for emergency vehicles. Complete the sentence. Explain.
Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data 13.7 4
The garage should be more than _______ meters long.
____________________

Answer:
The garage should be more than 16 meters long.

Explanation:
In the above-given figure,
Given that the fire station is building a new garage for emergency vehicles.
the garage should be more than 6 meters long and the shorter than 16 meters long.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.6-11

Show and Grow

Question 3.
You want to put some school supplies in a pencil box. Complete the sentence. Explain.
Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data 13.7 5
The pencil box should be more than _______ centimeters long.
______________________
Answer:
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.6-11

Measure Objects and Make Line Plots Homework & Practice 13.7

Question 1.
Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data 13.7 6
Measure the lengths of 5 socks. Complete the line plot.
What is the length of the longest sock? ______ inches
What is the length of the shortest sock? _______ inches
How much longer is the longest sock than the shortest sock? _______ inches

Answer:
The length of the longest sock = 10 inches.
The length of the shortest sock = 7 inches.
The longer is the longest sock than the shortest sock = 3 inches.

Explanation:
In the above-given figure,
we have to assume the:
sock 1 = 7
sock 2 = 8
sock 3 = 8
sock 4 = 9
sock 5 = 10
The length of the longest sock = 10 inches.
The length of the shortest sock = 7 inches.
The longer is the longest sock than the shortest sock = 3 inches.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.6-12

Question 2.
Measure the lengths of 4 hands. Complete the line plot.
Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data 13.7 7
How many hands are longer than 5 inches? How do you know?
__________________________
___________________________

Answer:
The hands that are longer than 5 inches = 3

Explanation:
We have to assume the hands in inches.
given that hand 1 = 7 inches.
hand 2 = 6 inches.
hand 3 = 5 inches.
hand 4 = 6 inches.
The hands that are longer than 5 inches = 3
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.6-13

Question 3.
Modeling Real Life
Newton wants to put his dog bones in a box. Complete the sentence. Explain.
Big Ideas Math Answers Grade 2 Chapter 13 Represent and Interpret Data 13.7 8
The box should be more than ______ inches long.
____________________

Answer:
The bo should be more than 11 inches.

Explanation:
In the above-given figure,
Given that newton wants to put his dog bones in a box.
the box should be more than 11 inches.
the box should be less than 4 inches.
Review & Refresh

Question 4.
10 more than 347 is _______.

Answer:
357

Explanation:
Given that,
10 more than 347 = 357.
347 + 10 = 357

Question 5.
100 less than 926 is _________.

Answer:
826

Explanation:
Given that 100 less than 926 = 826
926 – 100 = 826

Represent and Interpret Data Performance Task

You measure the lengths of 8 writing tools. The tools and their lengths are shown.
Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data 1
Question 1.
Organize the writing tool lengths on the line plot.
Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data 2

Answer:
The maximum length of the pencil = 12cms.

Explanation:
In the above-given figure,
given that
pencil 1 = 9 cm
pencil 2 = 9 cm
pencil 3 = 6 cm
pencil 4 = 9 cm
pencil 5 = 12 cm
pencil 6 = 12 cm
pencil 7 = 12 cm
pencil  8 = 12 cm
the maximum length of the pencil = 12 cms
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.7-1

Question 2.
Use the line plot to complete the equation. Why is the sum 8?
_____ + ______ + ______ = 8

Answer:
2 + 2 + 4 = 8

Question 3.
Measure your pencil. Add the length of your pencil to the line plot in Exercise 1.

Answer:
My pencil length is = 11 cms.

Explanation:
In the above-given figure,
given that
pencil 1 = 9 cm
pencil 2 = 9 cm
pencil 3 = 6 cm
pencil 4 = 9 cm
pencil 5 = 12 cm
pencil 6 = 12 cm
pencil 7 = 12 cm
pencil  8 = 12 cm
the maximum length of the pencil = 12 cms
Assuming my pencil length = 11 cms
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.7-2

Question 4.
Compare the lengths of your pencil and one of the writing tools above.

Answer:
The length of my pencil = 11 cms.

Explanation:
In the above-given figure,
given that
pencil 1 = 9 cm
pencil 2 = 9 cm
pencil 3 = 6 cm
pencil 4 = 9 cm
pencil 5 = 12 cm
pencil 6 = 12 cm
pencil 7 = 12 cm
pencil  8 = 12 cm
the maximum length of the pencil = 12 cms
Assuming my pencil length = 11 cms
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.7-2

Represent and Interpret Data Activity

Spin and Graph
To Play: Spin 10 times. Complete the tally chart. Then complete the bar graph. Answer the Spin and Graph Questions about your graph.
Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data 3

Represent and Interpret Data Chapter Practice

13.1 Sort and Organize Data

Question 1.
Use the data to complete the tally chart.
Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data chp 1
How many students chose magic show? _______
Which event is the least favorite? __________

Answer:
The students who choose the magic show = 5 students.
The last favorite = dancing.

Explanation:
In the above-given figure,
The students who choose magic show = 5
The students who choose face painting = 4
The students who choose games = 2
The students who choose dancing = 1
The students who choose the magic show = 5 students.
The last favorite = dancing.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.7-3

Question 2.
Modeling Real Life
You want to survey30 students. How many more students do you need to ask?
Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data chp 2
______ students
How many more students need to have red hair so that the numbers of students with red hair and blonde hair are equal?
______ students

Answer:
The more students need to ask = 3 students.
The more students need to have red hair so that the numbers of students with red hair and blonde hair are equal = 7 students.

Explanation:
In the above-given figure,
the hair color which is in red = 2
the hair color which is in black = 5
the hair color which is brown = 10
the hair color which is in blonde = 9
The more students need to ask = 3 students.
The more students need to have red hair so that the numbers of students with red hair and blonde hair are equal = 7 students.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.7-4

13.2 Read and Interpret Picture Graphs

Question 3.
Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data chp 3
Which type of book do exactly 7 students like best? _______
How many more students chose magazine than fiction? ________

Answer:
The type of book does exactly 7 students like best = comics.
The more students choose magazine than fiction = 4.

Explanation:
In the above-given figure,
The students who choose comics = 7
The students who choose fiction = 4
The students who choose nonfiction = 5
The students who choose magazine = 8
The type of book does exactly 7 students like best = comics.
The more students choose magazine than fiction = 4.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.7-5

13.3 Make Picture Graphs

Question 4.
Complete the picture graph.
Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data chp 4
How many fewer students chose tiger than cheetah? ______
How many students chose the least favorite cat? _______
How many students chose panther or lion? __________

Answer:
The fewer students choose tiger than cheetah = 4
The students who choose least favorite cat = tiger
the students who choose panther = 5
the students who choose lion = 4

Explanation:
In the above-given figure,
Given that,
The fewer students choose tiger than cheetah = 4
The students who choose least favorite cat = tiger
the students who choose panther = 5
the students who choose lion = 4
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.7-6

13.4 Read and Interpret Bar Graphs

Question 5.
Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data chp 5
How much rain fell on Tuesday? ______
Which day did it rain the least? _______
How much more rain fell on Monday than Wednesday? _________

Answer:
The rain fell on Tuesday = 3 inches.
The day it rains the least = thursday.
the more rain fell on Monday than Wednesday = 1 inch.

Explanation:
In the above-given graph,
the rain fell on Monday = 5 inches.
the rain fell on Tuesday = 3 inches.
the rain fell on Wednesday = 4 inches.
the rain fell on Thursday = 2 inches.
The rain fell on Tuesday = 3 inches.
The day it rains the least = Thursday.
the more rain fell on Monday than Wednesday = 1 inch.

Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.7-7
13.5 Make Bar Graphs

Question 6.
Complete the bar graph.
Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data chp 6
How many hurricanes were there in 2012 and 2013? _______

Answer:
The hurricanes were there in 2012 and 2013 = 12.

Explanation:
In the above-given figure,
given that the hurricanes in the north Atlantic.
in 2012 = 10
2013 = 2
2014 = 5
2015 = 4
The hurricanes were there in 2012 and 2013 = 12.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.7-8

13.6 Read and Interpret Line Plots

Question 7.
Complete the line plot.
Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data chp 7
How many feathers are longer than 13 centimeters? How do you know?
__________________
__________________

Answer:
The feathers which are longer than 13 centimeters = 2 feathers.

Explanation:
In the above-given figure,
The feathers with the lengths in centimeters.
feather 1 = 14 cms.
feather 2 = 13 cms.
feather 3 = 15 cms.
feather 4 = 12 cms.
The feathers which are longer than 13 centimeters = 2 feathers.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.7-9

13.7 Measure Objects and Make Line Plots

Question 8.
Use an inch ruler to measure the lengths of 5 toys to the nearest inch. Then complete the line plot.
Big Ideas Math Solutions Grade 2 Chapter 13 Represent and Interpret Data chp 8
What is the length of the longest toy? _______ inches

Answer:
The length of the longest toy = 9inches.

Explanation:
In the above-given figure,
we have to assume that
the length of the toy 1 = 6 inches.
the length of the toy 2 = 7 inches.
the length of the toy 3 = 6 inches
the length of the toy 4 = 8 inches.
the length of the toy 5 = 9 inches.
The length of the longest toy = 9inches.
Big-Ideas-Math-Solutions-Grade-2-Chapter-13-Represent and Interpret Data-13.7-10

Conclusion:

I hope that the solutions explained here are helpful for the students while preparing for the exams. So, download Big Ideas Math 2nd Grade 13th Chapter Represent and Interpret Data Answer Key pdf for free of cost and begin preparation. Students can clear their doubts by writing a comment in the below comment section. Also, bookmark our site to get the latest edition solutions for Big Ideas Math Book Grade 2 Chapters.

Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays

Big Ideas Math Answers Grade 8 Chapter 6

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Big Ideas Math Book 8th Grade Answer Key Chapter 6 Data Analysis and Displays

Test your preparation standards taking the help of these handy resources for Big Ideas Math Book 8th Grade Ch 6 Data Analysis and Displays Solutions and improve on the areas of need. Achieve Learning Targets and succeed in your math journey easily. Download the 8th Grade Big Ideas Math Book Ch 6 Data Analysis and Displays Answers in PDF Format via quick links and prepare anywhere and anytime.

Performance Task

Lesson: 1 Scatter Plots

Lesson: 2 Lines of Fit

Lesson: 3 Two-Way Tables

Lesson: 4 Choosing a Data Display

Chapter: 6 – Data Analysis and Displays 

Data Analysis and Displays STEAM Video/Performance Task

STEAM Video

Fuel Economy
The fuel economy of a vehicle is a measure of the effciency of the vehicle’s engine. What are the benefits of using a car with high fuel economy?
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 1
Watch the STEAM Video “Fuel Economy.” Then answer the following questions.
1. Tory says that the footprint of a vehicle is the area of the rectangle formed by the wheel base and the track width. What is the footprint of a car with a wheel base of 106 inches and a track width of 61 inches?
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 2
2. The graph shows the relationship between the fuel economy and the footprint for four vehicles.
a. What happens to the fuel economy as the footprint increases?
b. Plot the point (50, 40) on the graph. What does this point represent? Does the point fit in with the other points? Explain.

Answer:
1.The footprint of a car = 6,466 sq inches.

Explanation:
In the above-given question,
Tory says that the footprint of a vehicle is the area of the rectangle formed by the wheelbase and the track width.
area of rectangle = length  x width
Given that the footprint of a car = 106 inches.
width with 61 inches.
area = 106 x 61
footprint = 6,466 sq inches.

Answer:
2. a.The fuel economy increases when the footprint increases.

Explanation:
In the above-shown video,
tory says that whenever the footprint increases the fuel economy also increases.
whenever the footprint decreases the fuel economy decreases.

Answer:
2.b.The point (50, 40) represents the outlier.

Explanation:
In the above-given graph,
the point (50, 40) lies in the graph.
it represents the outlier of the graph.
Big-Ideas-Math-Solutions-Grade-8-Chapter-6-Data Analysis and Displays-6-1

Performance Task

Cost vs. Fuel Economy
After completing this chapter, you will be able to use the STEAM concepts you learned to answer the questions in the Video Performance Task. You will be given fuel economies and purchase prices of hybrid and non hybrid car models.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 3
You will be asked to create graphs to compare car models. Why might you want to know the relationship between the fuel economy and the purchase price of a vehicle?

Answer:
The relationship between the fuel economy and the purchase price of a vehicle is proportional.

Explanation:
In the above-given figure,
Given that the city fuel Economy and the purchase price of the cars.
for car A (21.8, 24)
for car B(22.4, 22)
for car C(40.1, 18)
if the fuel economy increases the purchase price also increases.
whenever the economy decreases the purchase price also decreases.

Data Analysis and Displays Getting Ready for Chapter 6

Chapter Exploration
1. Work with a partner. The table shows the number of absences and the final grade for each student in a sample.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 4
a.Write the ordered pairs from the table. Then plot them in a coordinate plane.
b. Describe the relationship between absences and final grade.
c. MODELING A student has been absent6 days. Use the data to predict the student’s final grade. Explain how you found your answer.

Answer:
a. (0, 95), (3, 88), (2, 90), (5, 83), (7, 79), (9, 70), (4, 85), (1, 94), (10, 65), (8, 75).
b. the relationships between the absences and the final grade is decreasing when the absences increases.
c. The student’s final grade is 80.

Explanation:
a. From the above-given figure,
The ordered pairs are:
(0, 95), (3, 88), (2, 90), (5, 83), (7, 79), (9, 70), (4, 85), (1, 94), (10, 65), (8, 75).
Big-Ideas-Math-Solutions-Grade-8-Chapter-6-Data Analysis and Displays-6-2

B. whenever the final grade is decreasing the absences also decrease.
whenever the final grade increases the absence also increases.
c. Given that the student has been absent for 6 days.
The student’s final grade is 80.

2. Work with a partner. Match the data sets with the most appropriate scatter plot. Explain your reasoning.
a. month of birth and birth weight for infants at a day care
b. quiz score and test score of each student in a class
c. age and value of laptop computers
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 5

Vocabulary
The following vocabulary terms are defined in this chapter. Think about what each term might mean and record your thoughts.
scatter plot
two-way table
line of fit
joint frequency

Answer:
Scatter plot = A scatter plot uses dots to represent values for two different numeric variables. The position of each dot on the horizontal and vertical axis indicates values for an individual data point.
Two-way table = A two-way table is a way to display frequencies or relative frequencies for two categorical variables.
Line of fit = Line of fit refers to a line through a scatter plot of data points that best expresses the relationship between those points.
Joint frequency = Joint frequency is joining one variable from the row and one variable from the column.

Explanation:
Scatter plot = A scatter plot uses dots to represent values for two different numeric variables. The position of each dot on the horizontal and vertical axis indicates values for an individual data point.
Two-way table = A two-way table is a way to display frequencies or relative frequencies for two categorical variables.
Line of fit = Line of fit refers to a line through a scatter plot of data points that best expresses the relationship between those points.
Joint frequency = Joint frequency is joining one variable from the row and one variable from the column.

Lesson 6.1 Scatter Plots

EXPLORATION 1

Work with a partner. The weights and circumferences of several sports balls are shown.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 6.1 1
a. Represent the data in the coordinate plane. Explain your method.
b. Is there a relationship between the size and the weight of a sports ball? Explain your reasoning.
c. Is it reasonable to use the graph to predict the weights of the sports balls below? Explain your reasoning.
Kickball : circumference = 26 in.
Bowling ball : circumference = 27 in.
Answer:
a.(21, 30), (5, 9), (1.6, 5.3), (16, 28), (2, 8), (1.4, 7), (7, 12), (10, 26).

Explanation:
Big-Ideas-Math-Solutions-Grade-8-Chapter-6-Data Analysis and Displays-6.1-1

Answer:
b. The weight is measured in inches and size is measured in ounces.

Explanation:
In the above-given figure,
the size and the weight of the balls are given.
size and weight of basketball = (21, 30).
size and weight of baseball = (5, 9).
size and weight of golfball = (1.6, 5.3).
size and weight of soccerball = (16, 28).
size and weight of tennis = (2, 8).
size and weight of racquetball = (1.4, 7).
size and weight of softball = (7, 12).
size and weight of volleyball = (10, 26)

Answer:
c. No, it is not reasonable to use the graph.

Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 6.1 2

Try It

Question 1.
Make a scatter plot of the data. Identify any outliers, gaps, or clusters.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 6.1 3

Answer:
outliers = (120, 70)
gaps =(10, 62) to (45, 85)
clusters =(80, 95), (90, 97), (80, 91)

Explanation:
outliers =(120, 70)
gaps = (10, 62) to (45, 85)
clusters = (80, 95), (90, 97), (80, 91)

Big-Ideas-Math-Solutions-Grade-8-Chapter-6-Data Analysis and Displays-6.1-2

Question 2.
Describe the relationship between the data in Example 1.

Answer:
Linear relationship.

Explanation:
In the above-given graph,
the relationship used is a linear relationship.

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 3.
SCATTER PLOT
Make a scatter plot of the data. Identify any outliers, gaps, or clusters. Then describe the relationship between the data.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 6.1 4
Answer:
outliers = (3,24)
clusters = 22 to 36
gaps = (4, 27), (8, 36)

Explanation:
outliers = (3,24)
clusters = 22 to 36
gaps = (4, 27), (8, 36)

Big-Ideas-Math-Solutions-Grade-8-Chapter-6-Data Analysis and Displays-6.1-3

Question 4.
WHICH ONE DOESN’T BELONG?
Using the scatter plot, which point does not belong with the other three? Explain your reasoning.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 6.1 5

Answer:
The point (3.5, 3) does not belong with the other three.

Explanation:
In the above-given figure
The points (1,8),  (3, 6.5), and (8, 2) lies in the coordinate plane.
the point (3.5, 3) does not belong with the other three.
the point (3.5, 3) is an outlier.
Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 5.
The table shows the high school and college grade point averages (GPAs) of 10 students. What college GPA do you expect for a high school student with a GPA of 2.7?
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 6.1 6

Answer:
The college GPA I expect for a high school student with a GPA of 2.7 is 2.45.

Explanation:
In the above-given points,
given that the college GPA for high school students.
college GPA for 2.4 = high school students of 2.6
so I am expecting the 2.45 for 2.7.

Question 6.
The scatter plot shows the ages of 12 people and the numbers of pets each person owns. Identify any outliers, gaps, or clusters. Then describe the relationship between the data.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 6.1 7

Answer:
outliers = (40, 6)
clusters = (20, 2) to (70, 1)
gaps = (0, 30), (1, 35), (2, 50) and so on.

Explanation:
Given that,
the person’s age (years) in the x-axis.
a number of pets owned in the y-axis.
outliers = (40, 6)
clusters = (20, 2) to (70, 1)
gaps = (0, 30), (1, 35), (2, 50) and so on.

Scatter Plots Homework & Practice 6.1

Review & Refresh

Solve the system. Check your solution.
Question 1.
y = – 5x + 1
y = – 5x – 2

Answer:
There is no solution for the given equation.

Explanation:
Given that y = – 5x + 1
y = – 5x – 2
so there is no solution for the given equation.

Question 2.
2x + 2y = 9
x = 4.5 – y

Answer:
9 = 9

Explanation:
Given that,
2x + 2y = 9
x = 4.5 – y
2(4.5 – y) + 2y = 9
9 – 2y + 2y = 9
-2y and + 2y get cancelled on both sides.
9 = 9

Question 3.
y = – x
6x + y = 4

Answer:
x = (4/5 , -4/5)

Explanation:
Given that y = -x
6x + y = 4
6x + (-x) = 4
6x – x = 4
5x = 4
x = (4/5)

Question 4.
When graphing a proportional relationship represented by y = mx, which point is not on the graph?
A. (0, 0)
B. (0, m)
C. (1, m)
D. (2, 2m)

Answer:
Point A is not on the graph.

Explanation:
In the above question,
given that the points are:
(0, 0)
(0, m)
(1, m)
(2, 2m)
the point (0, 0) is not in the graph.

Concepts, Skills, &Problem Solving

USING A SCATTER PLOT The table shows the average prices (in dollars) of jeans sold at different stores and the numbers of pairs of jeans sold at each store in one month. (See Exploration 1, p. 237.)

Question 5.
Represent the data in a coordinate plane.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 6.1 8

Answer:
The points are (22, 152), (40, 94), (28, 134), (35, 110), and (46, 81)

Explanation:
In the above-given figure,
The points are (22, 152), (40, 94), (28, 134), (35, 110), and (46, 81)
Big-Ideas-Math-Solutions-Grade-8-Chapter-6-Data Analysis and Displays-6.1-4

Question 6.
Is there a relationship between the average price and the number sold? Explain your reasoning.

Answer:
The linear relationship.

Explanation:
In the above-given figure,
the relationship given is linear relationship.

MAKING A SCATTER PLOT Make a scatter plot of the data. Identify any outliers, gaps, or clusters.
Question 7.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 6.1 9

Answer:
Outliers = (102, 63)
gaps = x from 40 to 44
clusters = 82 to 89

Explanation:
outliers = (102, 63)
gaps = x from 40 to 44
clusters = 82 to 89
Big-Ideas-Math-Solutions-Grade-8-Chapter-6-Data Analysis and Displays-6.1-5

Question 8.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 6.1 10

Answer:
Outliers = (0, 5.5)
gaps = x from 4.5 to 5.5
clusters = 1.5 to 2.5

Explanation:
outliers = (0, 5.5)
gaps = x from 4.5 to 5.5
clusters = 1.5 to 2.5
Big-Ideas-Math-Solutions-Grade-8-Chapter-6-Data Analysis and Displays-6.1-6

IDENTIFYING RELATIONSHIPS Describe the relationship between the data. Identify any outliers, gaps, or clusters.
Question 9.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 6.1 11

Answer:
Outliers = (15, 10)
gaps = from x = 15 to x = 25
clusters = 0
Negative linear relationship.

Explanation:
Outliers = (15, 10)
gaps = from x = 15 to x = 25
clusters = 0
There are no clusters.

Question 10.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 6.1 12

Answer:
There are no clusters.
gaps = from x = 4 to x = 36
outliers.

Explanation:
In the above-given figure,
there are no clusters.
gaps = from x = 4 to x = 36
no outliers.

Question 11.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 6.1 13

Answer:
There is no relationship.
there are no clusters.
no gaps.
no outliers.

Explanation:
In the above-given graph,
there are no clusters.
no gaps.
no clusters.
there is no relationship.

Question 12.
CRITICAL THINKING
The table shows the average price per pound for honey at a store from 2014 to 2017. Describe the relationship between the data.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 6.1 14

Answer:
The relationship is a positive linear relationship.

Explanation:
In the above-figure,
given points are:
(2014, $4.65), (2015, $5.90), (2016, $6.50), and (2017, $7.70)
so the above given is a positive linear relationship.

Question 13.
MODELING REAL LIFE
The scatter plot shows the amount of rainfall and the amount of corn produced by a farm over the last 10 years. Describe the relationship between the amount of rainfall and the amount of corn produced.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 6.1 15

Answer:
The relationship is a positive linear relationship.

Explanation:
In  the above-given figure,
outliers = (49, 80)
clusters = from x = 190 to 220.

Question 14.
OPEN-ENDED
Describe a set of real-life data that has a negative linear relationship.
Answer:

Question 15.
MODELING REAL LIFE
The scatter plot shows the total earnings (wages and tips) of a food server during one day.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 6.1 16
a. About how many hours must the server work to earn $70?
b. About how much does the server earn for 5 hours of work?
c. Describe the relationship shown by the data.

Answer:
a. 3.5 h
b. 85 $
c. positive linear relationship.

Explanation:
In the above-given graph,
given that,
a. the hours must server work to earn $70 = 3.5 h
b. The server earns for 5 hours of work = $ 85.
c. the relationship is shown by the data = positive linear relationship.

Question 16.
PROBLEM SOLVING
The table shows the memory capacities (in gigabytes) and prices (in dollars) of tablet computers. (a) Make a scatter plot of the data. Then describe the relationship between the data. (b) Identify any outliers, gaps, or clusters. Explain why they might exist.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 6.1 17

Answer:
Outliers =(16, 50)
gaps = 128 on x.
clusters = 64, 32, 64

Explanation:
Outliers =(16, 50)
gaps =128 on x.
clusters = 64, 32, 64.

Big-Ideas-Math-Solutions-Grade-8-Chapter-6-Data Analysis and Displays-6.1-7

Question 17.
PATTERNS
The scatter plot shows the numbers of drifting scooters sold by a company.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays 6.1 18
a. In what year were1000 scooters sold?
b. About how many scooters were sold in 2015?
c. Describe the relationship shown by the data.
d. Assuming this trend continues, in what year are about 500 drifting scooters sold?

Answer:
a. 2014
b. about 950 scooters.
c. negative linear relationship.
d. 2019.

Explanation:
In the above-given figure,
Given that the number of vehicles sold in the year.
a. 2014
b. about 950 scooters.
c. negative linear relationship.
d. 2019

Question 18.
DIG DEEPER!
Sales of sunglasses and beach towels at a store show a positive linear relationship in the summer. Does this mean that the sales of one item cause the sales of the other item to increase? Explain.

Answer:
Yes.

Explanation:
In the above-figure,
given that the sales of the sunglasses and beach towels at a store show a positive linear relationship.
yes the sales of one item cause the sales of the other item to increase.

Lesson 6.2 Lines of Fit

EXPLORATION 1

Representing Data by a Linear Equation
Work with a partner. You have been working on a science project for 8 months. Each month, you measured the length of a baby alligator.
Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays 6.2 1
a. Use a scatter plot to draw a line that you think best describes the relationship between the data.
b. Write an equation for your line in part(a).
c. MODELING Use your equation in part(b) to predict the length of the baby alligator next September.

Answer:
a. The relation is a linear relationship.

Explanation:
Big-Ideas-Math-Solutions-Grade-8-Chapter-6-Data Analysis and Displays-6.1-8

Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays 6.2 2

Try It

Question 1.
The table shows the numbers of people who attend a festival over an eight-year period. (a) Make a scatter plot of the data and draw a line of fit. (b) Write an equation of the line of fit. (c) Interpret the slope and the y-intercept of the line of fit.
Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays 6.2 3

Answer:
The order pairs (1, 420), (2, 500), (3, 650), (4, 900), (5, 1100), (6, 1500), (7, 1750), (8, 2400)

Explanation:
Big-Ideas-Math-Solutions-Grade-8-Chapter-6-Data Analysis and Displays-6.2-2

Question 2.
Find an equation of the line of best fit for the data in Example 1. Identify and interpret the correlation coefficient.
Answer:

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 3.
FINDING A LINE OF FIT
The table shows the numbers of days spent training and the race times for several people in a race.
Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays 6.2 4
a. Make a scatter plot of the data and draw a line of fit.
b. Write an equation of the line of fit.
c. Interpret the slope and the y-intercept of the line of fit.

Answer:

Question 4.
IDENTIFYING RELATIONSHIPS
Find an equation of the line of best fit for the data at the left. Identify and interpret the correlation coefficient
Answer:

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 5.
The ordered pairs show amounts y (in inches) of rainfall equivalent x to inches of snow. About how many inches of rainfall are equivalent to 6 inches of snow? Justify your answer.
(16, 1.5) (12, 1.3) (18, 1.8) (15, 1.5) (20, 2.1) (23, 2.4)
Answer:

Question 6.
The table shows the heights (in feet) of a high jump bar and the number of people who successfully complete each jump. Identify and interpret the correlation coefficient.
Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays 6.2 5
Answer:

Lines of Fit Homework & Practice 6.2

Review & Refresh

Describe the relationship between the data. Identify any outliers, gaps, or clusters.
Question 1.
Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays 6.2 6

Answer:
Negative linear relationship.
outliers = (6, 10)
clusters = 0
gaps = 0

Explanation:
In the above-given figure,
The relationship is negative linear relationship.
outliers = (6, 10)
cluster = 0
gaps = 0
there are no clusters and no gaps.

Question 2.
Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays 6.2 7

Answer:

Question 3.
Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays 6.2 8

Answer:

positive linear relationships.
outliers = 0
gaps = 0
clusters = x = 11 to x = 15

Explanation:
In the above-given figure,
given that
positive linear relationship.
outliers = 0
gaps = 0
clusters = x = 11 to x = 15

Write the fraction as a decimal and a percent.
Question 4.
\(\frac{29}{100}\)

Answer:
Decimal = 0.29
percent = 29 %

Explanation:
Given that
(29/100)
0.29
percent = 29%
decimal = 0.29

Question 5.
\(\frac{7}{25}\)

Answer:
Decimal = 0.28
percent = 28%

Explanation:
Given that
(7/25) = 0.28
decimal = 0.28
percent = 28

Question 6.
\(\frac{35}{50}\)

Answer:
Decimal = 0.7
percent = 0.007

Explanation:
Given that
(35/50) = 0.7
decimal = 0.7
percent = 0.007

Concepts, Skills, &Problem Solving
REPRESENTING DATA BY A LINEAR EQUATION Use a scatter plot to draw a line that you think best describes the relationship between the data. (See Exploration 1, p. 243.)
Question 7.
Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays 6.2 9

Answer:
The points are (0,0), (1, 0.8), (2, 1.50), (3, 2.20), (4, 3.0), (5, 3.75)

Explanation:
In the above-given figure,
Given that :
the points are (0, 0), (1, 0.8), (2, 1.50), (3, 2.20), (4, 3.0), (5, 3.75)
The blue berries are in the x-axis.
weight is measured in pounds.
weight is shown in the y-axis.
Big-Ideas-Math-Solutions-Grade-8-Chapter-6-Data Analysis and Displays-6.2-3
Question 8.
Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays 6.2 10

Answer:
The given points are (0,91), (2, 82), (4, 74), (6, 65), (8, 55), (10, 43).

Explanation:
In the above-given figure,
Given that :
the points are (0, 91, (2, 82), (4, 74), (6, 65), (8, 55), (10, 43)
The Age is given on the x-axis.
value is measured in dollars.
value is given in the y-axis.
Big-Ideas-Math-Solutions-Grade-8-Chapter-6-Data Analysis and Displays-6.2-4
Question 9.
FINDING A LINE OF FIT
The table shows the daily high temperatures (°F)and the numbers of hot chocolates sold at a coffee shop for eight randomly selected days.
Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays 6.2 11
a. Make a scatter plot of the data and draw a line of fit.
b.Write an equation of the line of fit.
c. Interpret the slope and the y-intercept of the line of fit.

Answer:
a.The given points are (30, 45), (36, 43), (44, 36), (51, 35), (60, 30), (68, 27), (75, 23), (82, 17).
b. y = -0.5x + 60
c. you could expect that 60 hot chocolates are sold when the temperature is 0 degree f, and the sales decrease by 1 hot chocolate for every 2 degrees f increase in temperature.

Explanation:
a.The given points are (30, 45), (36, 43), (44, 36), (51, 35), (60, 30), (68, 27), (75, 23), (82, 17).
b. y = -0.5x + 60
c. you could expect that 60 hot chocolates are sold when the temperature is 0 degree f, and the sales decrease by 1 hot chocolate for every 2 degrees f increase in temperature.

Big-Ideas-Math-Solutions-Grade-8-Chapter-6-Data Analysis and Displays-6.2-5

Question 10.
NUMBER SENSE
Which correlation coefficient indicates a stronger relationship: – 0.98 or 0.91? Explain.

Answer:
0.91 indicates a stronger correlation coefficient.

Explanation:
In the above-given question,
-0.98 is a negative value and 0.91 is a positive value.
So 0.91 indicates a stronger correlation coefficient.

Question 11.
IDENTIFYING RELATIONSHIPS
The table shows the admission costs (in dollars) and the average number of daily visitors at an amusement park each year for the past 8 years. Find an equation of the line of best fit. Identify and interpret the correlation coefficient.
Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays 6.2 12

Answer:
The equation for the line of best fit is Y = -4.9x + 1042
about -0.969.
strong negative correlation.

Explanation:
In the above-given figure,
The given points are (20, 940), (21, 935), (22, 940), (24, 925), (25, 920), (27, 905), (28, 910), and (30, 890)
The equation for the line of best fit is y = -4.9x + 1042.
about -0.969.
strong negative correlation.

Question 12.
REASONING
The table shows the weights(in pounds) and the prescribed dosages (in milligrams) of medicine for six patients.
Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays 6.2 13
a. Find an equation of the line of best fit. Identify and interpret the correlation coefficient.
b. Interpret the slope of the line of best fit.
c. A patient who weighs 140 pounds is prescribed 135 milligrams of medicine. How does this affect the line of best fit?
Answer:

Question 13.
MODELING REAL LIFE
The table shows the populations (in millions) and the numbers of electoral votes assigned for eight states in the 2016 presidential election.
Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays 6.2 14
a. Find an equation of the line of best fit. Identify and interpret the correlation coefficient.
b. Interpret the slope of the line of best fit.
c. Interpret the y-intercept of the line of best fit.
d. RESEARCH Research the Electoral College to explain the meaning of your answer in part(c).

Answer:
a. y = 1.3 x + 2; about 0.9995; strong positive correlation.
b. The number of electoral votes increases by 1.3 for every increase of 1  million people in the state.
c. A state with a population of 0 has 2 electoral votes.
d. The number of electoral votes a state has is based on the number of members that the state has in congress. Each state has 2 senators, plus a number of members of the House of Representatives based on its population. so, the y-intercept is 2 because a hypothetical state with no population would still have 2 senators.

Explanation:
a. y = 1.3 x + 2; about 0.9995; strong positive correlation.
b. The number of electoral votes increases by 1.3 for every increase of 1  million people in the state.
c. A state with a population of 0 has 2 electoral votes.
d. The number of electoral votes a state has is based on the number of members that the state has in congress. Each state has 2 senators, plus a number of members of the House of Representatives based on its population. so, the y-intercept is 2 because a hypothetical state with no population would still have 2 senators.

Question 14.
MODELING REAL LIFE
The table shows the numbers (in millions) of active accounts for two social media websites over the past five years. Assuming this trend continues, how many active accounts will Website B have when Website A has 280 million active accounts? Justify your answer.
Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays 6.2 15

Answer:

Question 15.
DIG DEEPER!
The table shows the heights y(in feet) of a baseball x seconds after it was hit.
Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays 6.2 16
a. Predict the height after 5 seconds.
b. The actual height after 5 seconds is about 3 feet. Why might this be different from your prediction?

Answer:
a. 251 ft.
b. The height of the baseball is not linear.

Explanation:
a. The height after 5 seconds is 251 feet.
Given that the seconds on the x-axis and height on the y-axis.
the points are (0, 3), (0.5, 39), (1, 67), (1.5, 87), and (2, 99).
b. The actual height after 5 seconds is about 3 feet.

Lesson 6.3 Two-Way Tables

EXPLORATION 1

Analyzing Data
Work with a partner. You are the manager of a sports shop. The table shows the numbers of soccer T-shirts that your shop has left in stock at the end of a soccer season.
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays 6.3 1
a. Complete the table.
b. Are there any black-and-gold XL T-shirts in stock? Justify your answer.
c. The numbers of T-shirts you ordered at the beginning of the soccer season are shown below. Complete the table.
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays 6.3 2
d. REASONING How would you alter the numbers of T-shirts you order for the next soccer season?
Answer:

Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays 6.3 3

Try It

Question 1.
How many students in the survey above studied for the test and failed?
Answer:

Question 2.
You randomly survey students in a cafeteria about their plans for a football game and a school dance. The two-way table shows the results. Find and interpret the marginal frequencies for the survey.
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays 6.3 4
Answer:

Question 3.
You randomly survey students about whether they buy a school lunch or pack a lunch. The results are shown. Make a two-way table that includes the marginal frequencies.
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays 6.3 5
Answer:

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 4.
READING A TWO-WAY TABLE
The results of a music survey are shown in the two-way table. How many students dislike both country and jazz? How many students like country but dislike jazz?
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays 6.3 6
Answer:

Question 5.
MAKING A TWO-WAY TABLE
You randomly survey students about their preference for a class field trip. The results are shown in the tally sheets. Make a two-way table that includes the marginal frequencies.
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays 6.3 7
Answer:

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 6.
The results of a voting survey are shown in the two-way table. For each age group, what percent of voters prefer Candidate A? Candidate B? Determine whether there is a relationship between age and candidate preference.
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays 6.3 8
Answer:

Question 7.
You randomly survey 40 students about whether they play an instrument. You find that8 males play an instrument and 13 females do not play an instrument. A total of 17 students in the survey play an instrument. Make a two-way table that includes the marginal frequencies.
Answer:

Question 8.
Collect data from each student in your math class about whether they like math and whether they like science. Is there a relationship between liking math and liking science? Justify your answer.
Answer:

Two-Way Tables Homework & Practice 6.3

Review & Refresh

Find an equation of the line of best fit for the data.
Question 1.
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays 6.3 9

Answer:
The line y = 12.6x + 75.8 best fit for the data.

Explanation:
In the above-given figure,
Given that the points are (0,75), (1, 91), (2, 101), (3, 109) and (4, 129).
The line y = 12.6x + 75.8 is the best fit for the data.

Question 2.
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays 6.3 10
Answer:

The vertices of a triangle are A (1, 2), B (3, 1), and C (1, – 1). Draw the figure and its image after the translation.
Question 3.
4 units left
Answer:

Question 4.
2 units down
Answer:

Question 5.
(x – 2, y + 3)
Answer:

Concepts, Skills, &Problem Solving

ANALYZING DATA In Exploration 1, determine how many of the indicated T-shirt are in stock at the end of the soccer season. (See Exploration 1, p. 249.)
Question 6.
black-and-white M

Answer:
4 T-shirts are in stock at the end of the soccer season.

Explanation:
In the above-given Exploration 1,
Given that The T-shirts are in stock.
4 T-shirts are in stock at the end of the soccer season.

Question 7.
blue-and-gold XXL

Answer:
0 shirts.

Explanation:
In the above-given Exploration 1,
Given that The T-shirts are in stock.
0 T-shirts are in stock at the end of the soccer season.

Question 8.
blue-and-white L

Answer:
1 T-shirt.

Explanation:
In the above-given Exploration 1,
Given that the T-shirts are in stock.
1 T-shirt is in stock at the end of the soccer season.

READING A TWO-WAY TABLE You randomly survey students about participating in a yearly fundraiser. The two-way table shows the results.
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays 6.3 11
Question 9.
How many female students participateFundraiserin the fundraiser?

Answer:
51 students participate.

Explanation:
In the above-given table,
Given that male and female students are participated in the fundraiser.
so 51 female students participate.

Question 10.
How many male students do not participate in the fundraiser?

Answer:
30 male students do not participate.

Explanation:
In the above-given table,
Given that male and female students are participated in the fundraiser.
so 30 male students do not participate.

FINDING MARGINAL FREQUENCIES Find and interpret the marginal frequencies.
Question 11.
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays 6.3 12

Answer:
71 students are juniors.
75 students are seniors.
93 students will attend the school play.
53 students will not attend the school play.
146 students were surveyed.

Explanation:
In the above-given table,
Given that students of the class participate in the school play.
71 students are juniors.
75 students are seniors.
93 students will attend the school play.
53 students will not attend the school play.
146 students were surveyed.

Question 12.
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays 6.3 13

Answer:
The data plan of 78 people is limited for the cell phone company A.
The data plan of  94 people is limited for the cell phone company B.
The data plan of 175 people is unlimited for the cell phone company A.
The data plan of 135 people is unlimited for the cell phone company B.
482 people were surveyed.

Explanation:
In the above-given table,
The data plan of the cell phone company are given.
The data plan of 78 people is limited for the cell phone company A.
The data plan of  94 people is limited for the cell phone company B.
The data plan of 175 people is unlimited for the cell phone company A.
The data plan of 135 people is unlimited for the cell phone company B.
482 people were surveyed.

Question 13.
MAKING A TWO-WAY TABLE
A researcher randomly surveys people with a medical condition about whether they received a treatment and whether their condition improved. The results are shown. Make a two-way table that includes the marginal frequencies.
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays 6.3 14

Answer:
The people who improved with treatment = 34.
The people who did not improve with treatment = 10
The people who improved with no treatment = 12.
The people who did not improve with no treatment = 29
Totally are about 85 people.

Explanation:
The people who improved with treatment = 34.
The people who did not improve with treatment = 10
The people who improved with no treatment = 12.
The people who did not improve with no treatment = 29
Totally are about 85 people.

Question 14.
MODELING REAL LIFE
You randomly survey students in your school about the color of their eyes. The results are shown in the tables.
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays 6.3 15
a. Make a two-way table.
b. Find and interpret the marginal frequencies for the survey.
c. For each eye color, what percent of the students in the survey are male? female? Organize the results in a two-way table.
Answer:

Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays 6.3 16
Question 15.
REASONING
Use the information from Exercise 14. For each gender, what percent of the students in the survey have green eyes? blue eyes? brown eyes? Organize the results in a two-way table.
Answer:

Question 16.
CRITICAL THINKING
What percent of students in the survey in Exercise 14 are either female or have green eyes? What percent of students in the survey are males who do not have green eyes? Find and explain the sum of these two percents.
Answer:

Question 17.
MODELING REAL LIFE
You randomly survey people in your neighborhood about whether they have at least $1000 in savings. The results are shown in the tally sheets. For each age group, what percent of the people have at least $1000 in savings? do not have at least $1000 in savings? Determine whether there is a relationship between age and having at least $1000 in savings.
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays 6.3 17
Answer:

Question 18.
DIG DEEPER!
The three-dimensional bar graph shows information about the numbers of hours students at a high school work at part-time jobs during the school year.
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays 6.3 18
a. Make a two-way table that represents the data. Use estimation to find the entries in your table.
b. A newspaper article claims that more males than females drop out of high school to work full-time. Do the data support this claim? Explain your reasoning.
Answer:

Lesson 6.4 Choosing a Data Display

EXPLORATION 1

Displaying Data
Work with a partner. Analyze and display each data set in a way that best describes the data. Explain your choice of display.

a. NEW ENGLAND ROADKILL A group of schools in New England participated in a two-month study. They reported 3962 dead animals.
Birds: 307
Mammals: 2746
AmphibiAnswer: 145
Reptiles: 75
Unknown: 689
Big Ideas Math Solutions Grade 8 Chapter 6 Data Analysis and Displays 6.4 1
b. BLACK BEAR ROADKILL The data below show the numbers of black bears killed on a state’s roads each year for 20 years.
Big Ideas Math Solutions Grade 8 Chapter 6 Data Analysis and Displays 6.4 2
c. RACCOON ROADKILL A one-week study along a four-mile section of road found the following weights (in pounds) of raccoons that had been killed by vehicles.
Big Ideas Math Solutions Grade 8 Chapter 6 Data Analysis and Displays 6.4 3
d. What can be done to minimize the number of animals killed by vehicles?
Answer:

Try It

Choose an appropriate data display for the situation. Explain your reasoning.
Question 1.
the population of the United States divided into age groups
Answer:

Question 2.
the number of students in your school who play basketball, football, soccer, or lacrosse
Answer:

Tell whether the data display is appropriate for representing the data in Example 2. Explain your reasoning.
Question 3.
dot plot
Answer:

Question 4.
circle graph
Answer:

Question 5.
stem-and-leaf plot
Answer:

Question 6.
Which bar graph is misleading? Explain.
Big Ideas Math Solutions Grade 8 Chapter 6 Data Analysis and Displays 6.4 4
Answer:

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

CHOOSING A DATA DISPLAY Choose an appropriate data display for the situation. Explain your reasoning.
Question 7.
the percent of band students playing each instrument
Answer:

Question 8.
a comparison of the amount of time spent using a tablet computer and the remaining battery life
Answer:

Question 9.
IDENTIFYING A MISLEADING DISPLAY
Is the box-and-whisker plot misleading? Explain.
Big Ideas Math Solutions Grade 8 Chapter 6 Data Analysis and Displays 6.4 5
Answer:

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 10.
An employee at an animal shelter creates the histogram shown. A visitor concludes that the number of 7-year-old to 9-year-old dogs is triple the number of 1-year-old to 3-year-old dogs. Determine whether this conclusion is accurate. Explain.
Big Ideas Math Solutions Grade 8 Chapter 6 Data Analysis and Displays 6.4 6
Answer:

Question 11.
DIG DEEPER!
A business manager creates the line graph shown. (a) How do the data appear to change over time? Explain why this conclusion may not be accurate. (b) Why might the business manager want to use this line graph?
Big Ideas Math Solutions Grade 8 Chapter 6 Data Analysis and Displays 6.4 7
Answer:

Choosing a Data Display Homework & Practice 6.4

Review & Refresh

You randomly survey students about whether they recycle. The two-way table shows the results.
Big Ideas Math Solutions Grade 8 Chapter 6 Data Analysis and Displays 6.4 8
Question 1.
How many male students recycle? How many female students do not recycle?
Answer:

Question 2.
Find and interpret the marginal frequencies.
Answer:

Find the slope and the y-intercept of the graph of the linear equation.
Question 3.
y = 4x + 10
Answer:

Question 4.
y = – 3.5x – 2
Answer:

Question 5.
y – 8 = – x
Answer:

Concepts, Skills, & Problem Solving

Question 6.
DISPLAYING DATA
Analyze and display the data in a way that best describes the data. Explain your choice of display. (See Exploration 1, p. 255.)
Big Ideas Math Solutions Grade 8 Chapter 6 Data Analysis and Displays 6.4 9

Answer:

CHOOSING A DATA DISPLAY Choose an appropriate data display for the situation. Explain your reasoning.
Question 7.
a student’s test scores and how the scores are spread out

Answer:
stem and leaf plot shows how data is distributed.

Question 8.
the prices of different televisions and the numbers of televisions sold
Answer:

Question 9.
the outcome of rolling a number cube
Answer:

Question 10.
the distance a person drives each month
Answer:

Question 11.
IDENTIFYING AN APPROPRIATE DISPLAY
A survey asked 800 students to choose their favorite school subject. The results are shown in the table. Tell whether each data display is appropriate for representing the portion of students who prefer math. Explain your reasoning.
Big Ideas Math Solutions Grade 8 Chapter 6 Data Analysis and Displays 6.4 10
Answer:

Question 12.
IDENTIFYING AN APPROPRIATE DISPLAY
The table shows how many hours you worked as a lifeguard from May to August. Tell whether each data display is appropriate for representing how the number of hours worked changed during the 4 months. Explain your reasoning.
Big Ideas Math Solutions Grade 8 Chapter 6 Data Analysis and Displays 6.4 11
Answer:

Question 13.
WRITING
When should you use a histogram instead of a bar graph to display data? Use an example to support your answer.
Answer:

IDENTIFYING MISLEADING DISPLAYS Which data display is misleading? Explain.
Question 14.
Big Ideas Math Solutions Grade 8 Chapter 6 Data Analysis and Displays 6.4 12
Answer:

Question 15.
Big Ideas Math Solutions Grade 8 Chapter 6 Data Analysis and Displays 6.4 13
Answer:

Question 16.
REASONING
What type of data display is appropriate for showing the mode of a data set?
Answer:

Question 17.
CRITICAL THINKING
The director of a music festival creates the data display shown. A customer concludes that the ticket price for Group C is more than double the ticket price for Group A. Determine whether this conclusion is accurate. Explain.
Big Ideas Math Solutions Grade 8 Chapter 6 Data Analysis and Displays 6.4 14
Answer:

Question 18.
PATTERNS
A scientist gathers data about a decaying chemical compound and creates the scatter plot shown.
Big Ideas Math Solutions Grade 8 Chapter 6 Data Analysis and Displays 6.4 15
a.The scientist concludes that there is a negative linear relationship between the data. Determine whether this conclusion is accurate. Explain.
b. Estimate the amount of the compound remaining after 1 hour, 3 hours, 5 hours, and 7 hours.
Answer:

Question 19.
REASONING
A survey asks 100 students to choose their favorite sports. The results are shown in the circle graph.
Big Ideas Math Solutions Grade 8 Chapter 6 Data Analysis and Displays 6.4 16
a. Explain why the graph is misleading.
b. What type of data display is more appropriate for the data? Explain.
Answer:

Question 20.
STRUCTURE
With the help of computers, mathematicians have computed and analyzed trillions of digits of the irrational number π. One of the things they analyze is the frequency of each of the numbers 0 through 9. The table shows the frequency of each number in the first 100,000 digits of π.
a. Display the data in a bar graph.
b. Display the data in a circle graph.
c. Which data display is more appropriate? Explain.
d. Describe the distribution.
Big Ideas Math Solutions Grade 8 Chapter 6 Data Analysis and Displays 6.4 17
Answer:

Data Analysis and Displays Connecting Concepts

Using the Problem-Solving Plan
Question 1.
You randomly survey middle school students about whether they prefer action, comedy, or animation movies. The two-way table shows the results. Estimate the probability that a randomly selected middle school student prefers action movies.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays cc 1
Understand the problem.
You know the results of a survey about movie preference. You are asked to estimate the probability that a randomly selected middle school student prefers action movies.

Make a plan.
Find the marginal frequencies for the data. Then use the marginal frequencies to find the probability that a randomly selected middle school student prefers action movies.

Solve and check.
Use the plan to solve the problem. Then check your solution.
Answer:

Question 2.
An equation of the line of best fit for a data set is y = – 0.68x + 2.35. Describe what happens to the slope and the y-intercept of the line when each y-value in the data set increases by 7.
Answer:

Question 3.
On a school field trip, there must be 1 adult chaperone for every 16 students. There are 8 adults who are willing to be a chaperone for the trip, but only the number of chaperones that are necessary will attend. Ina class of 124 students, 80 attend the trip. Make a two-way table that represents the data.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays cc 2
Answer:

Performance Task

Cost vs. Fuel Economy
At the beginning of this chapter, you watched a STEAM Video called “Fuel Economy.” You are now ready to complete the performance task related to this video, available at BigIdeasMath.com. Be sure to use the problem-solving plan as you work through the performance task.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays cc 3

Data Analysis and Displays Chapter Review

Review Vocabulary

Write the definition and give an example of each vocabulary term.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays cr 1

Graphic Organizers

You can use Information Frame an to help organize and remember a concept. Here is an example of an Information Frame for scatter plots.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays cr 2

Choose and complete a graphic organizer to help you study the concept.
1. lines of fit
2. two-way tables
3. data displays
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays cr 3

Chapter Self-Assessment

As you complete the exercises, use the scale below to rate your understanding of the success criteria in your journal.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays cr 4

6.1 Scatter Plots   (pp. 237–242)
Learning Target: Use scatter plots to describe patterns and relationships between two quantities.

Question 1.
Make a scatter plot of the data. Identify any outliers, gaps, or clusters.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays cr 5
Answer:

Describe the relationship between the data. Identify any outliers, gaps, or clusters.
Question 2.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays cr 6
Answer:

Question 3.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays cr 7
Answer:

Question 4.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays cr 8
Answer:

Question 5.
Your school is ordering custom T-shirts. The scatter plot shows the numbers of T-shirts ordered and the cost per shirt. Describe the relationship between the numbers of T-shirts ordered and the cost per T-shirt.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays cr 9.1
Answer:

Question 6.
Describe a set of real-life data that has each relationship.
a. positive linear relationship
b. no relationship
Answer:

Question 7.
The table shows the numbers of hours a waitress works and the amounts she earns in tips. How many hours do you expect the waitress to work when she earns $42 in tips?
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays cr 9
Answer:

6.2 Lines of Fit   (pp. 243–248)
Learning Target: Use lines of fit to model data.

Question 8.
The table shows the numbers of students at a middle school over a 10-year period.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays cr 10
a. Make a scatter plot of the data and draw a line of fit.
b. Write an equation of the line of fit.
c. Interpret the slope and the y-intercept of the line of fit.
d. Predict the number of students in year 11.
Answer:

Question 9.
Find an equation of the line of best fit for the data in Exercise 8. Identify and interpret the correlation coefficient.
Answer:

Question 10.
The table shows the revenue (in millions of dollars) for a company over an eight-year period. Assuming this trend continues, how much revenue will there be in year 9?
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays cr 11.1
Answer:

6.3 TwoWay Tables   (pp. 249–254)
Learning Target: Use two-way tables to represent data. You randomly survey students about participating in the science fair. The two-way table shows the results.

Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays cr 11
Question 11.
How many male students participate in the science fair?
Answer:

Question 12.
How many female students do not participate in the science fair?
Answer:

Question 13.
You randomly survey students in your school about whether they liked a recent school play. The two-way table shows the results. Find and interpret the marginal frequencies.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays cr 13
Answer:

Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays cr 14
You randomly survey people at a mall about whether they like the new food court. The results are shown.
Question 14.
Make a two-way table that includes the marginal frequencies.
Answer:

Question 15.
For each group, what percent of the people surveyed like the food court? dislike the food court? Organize your results in a two-way table.
Answer:

Question 16.
Does your table in Exercise 15 show a relationship between age and whether people like the food court?
Answer:

6.4 Choosing a Data Display (pp. 255–262)

Learning Target: Use appropriate data displays to represent situations.

Choose an appropriate data display for the situation. Explain your reasoning.
Question 17.
the numbers of pairs of shoes sold by a store each week
Answer:

Question 18.
the percent of votes that each candidate received in an election.
Answer:

Question 19.
Bird banding is attaching a tag to a bird’s wing or leg to track the movement of the bird. This provides information about the bird’s migration patterns and feeding behaviors. The table shows the numbers of robins banded in Pennsylvania over 5 years. Tell whether each data display is appropriate for representing how the number of bandings changed during the 5 years. Explain your reasoning.
Big Ideas Math Answer Key Grade 8 Chapter 6 Data Analysis and Displays cr 19
Answer:

Question 20.
Give an example of a bar graph that is misleading. Explain your reasoning.
Answer:

Question 21.
Give an example of a situation where a dot plot is an appropriate data display. Explain your reasoning.
Answer:

Data Analysis and Displays Practice Test

Question 1.
The graph shows the population (in millions) of the United States from 1960 to 2010.
Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays pt 1
a. In what year was the population of the United States about 180 million?
b. What was the approximate population of the United States in 1990?
c. Describe the relationship shown by the data.
Answer:

Question 2.
The table shows the weight of a baby over several months.
Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays pt 2
a. Make a scatter plot of the data and draw a line of fit.
b. Write an equation of the line of fit.
c. Interpret the slope and the y-intercept of the line of fit.
Answer:

Question 3.
You randomly survey students at your school about what type of books they like to read. The two-way table shows your results. Find and interpret the marginal frequencies.
Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays pt 3
Answer:

Choose an appropriate data display for the situation. Explain your reasoning.
Question 4.
magazine sales grouped by price range
Answer:

Question 5.
the distance a person hikes each week
Answer:

Question 6.
The table shows the numbers of AP exams (in thousands) taken from 2012 to 2016, where x = 12 represents the year 2012. Find an equation of the line of best fit. Identify and interpret the correlation coefficient.
Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays pt 6
Answer:

Question 7.
You randomly survey shoppers at a supermarket about whether they use reusable bags. Of 60 male shoppers,15 use reusable bags. Of 110 female shoppers,60 use reusable bags. Organize your results in a two-way table. Include the marginal frequencies. Estimate the probability that a randomly selected male shopper uses reusable bags.
Big Ideas Math Answers 8th Grade Chapter 6 Data Analysis and Displays pt 7
Answer:

Data Analysis and Displays Cumulative Practice

Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays cp 1
Question 1.
What is the solution of the system of linear equations?
y = 2x – 1
y = 3x + 5
A. ( 13, 6)
B. (- 6, – 13)
C. (- 13, 6)
D. (- 6, 13)
Answer:

Question 2.
The diagram shows parallel lines cut by a transversal. Which angle is the corresponding angle for ∠6 ?
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays cp 2
F. ∠2
G. ∠3
H. ∠4
I. ∠8
Answer:

Question 3.
You randomly survey students in your school. You ask whether they have jobs. You display your results in the two-way table. How many male students do not have a job?
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays cp 3
Answer:

Question 4.
Which scatter plot shows a negative relationship between x and y?
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays cp 4
Answer:

Question 5.
A system of two linear equations has no solution. What can you conclude about the graphs of the two equations?
F. The lines have the same slope and the same y-intercept.
G. The lines have the same slope and different y-intercepts.
H. The lines have different slopes and the same y-intercept.
I. The lines have different slopes and different y-intercepts.
Answer:

Question 6.
What is the solution of the equation?
0.22(x + 6) = 0.2x + 1.8
A. x = 2.4
B. x = 15.6
C. x = 24
D. x = 156
Answer:

Question 7.
A person who is 5\(\frac{1}{2}\) feet tall casts a 3\(\frac{1}{2}\) -foot-long shadow. A nearby flagpole casts a 28-foot-long shadow. What is the height (in feet) of the flag pole?
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays cp 7
Answer:

Question 8.
A store records total sales (in dollars) each month for three years. Which type of graph can best show how sales increase over this time period?
F. circle graph
G. line graph
H. histogram
I. stem-and-leaf plot
Answer:

Question 9.
Trapezoid KLMN is graphed in the coordinate plane shown.
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays cp 9
Rotate Trapezoid 90° clockwise about the origin. What are the M’, coordinates of point, the image of point M after the rotation?
A. (- 3, – 2)
B. (- 2, – 3)
C. (- 2, 3)
D. (3, 2)
Answer:

Question 10.
The table shows the numbers of hours students spent watching television from Monday through Friday for one week and their scores on a test that Friday.
Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays cp 10
Part A Make a scatter plot of the data.
Part B Describe the relationship between the hours of television watched and the test scores.
Part C Explain how to justify your answer in PartB using the linear regression feature of a graphing calculator.
Answer:

Conclusion:

Get the free access to Download Big Ideas Math Answers Grade 8 Chapter 6 Data Analysis and Displays from here. All the solutions are prepared in a simple manner. Test yourself by answering the questions given at the end of the chapter. Keep in touch with us to get the Solutions of all Big Ideas Math Grade 8 Chapters.

Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10

Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10

Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 is the best material for your child to score good marks in the exams. Refer to Big Ideas Math Book K Grade Answer Key Chapter 5 Compose and Decompose Numbers to 10 and try to solve all the problems. You can understand the concepts deeply with the help of the Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10. In order to excel in the exam, we suggest the students of K standard refer to the BIM Text Book Kth Grade Chapter 5 Compose and Decompose Numbers to 10 Solution Key.

Big Ideas Math Book Grade K Answer Key Chapter 5 Compose and Decompose Numbers to 10

We provide the step by step explanations for all the questions by using the images in Bigideas Math Kth Grade Answer Key Chapter 5 Compose and Decompose Numbers to 10. Students who feel difficulty in solving the math problems can quickly understand the concepts with the help of our Big Ideas Math Book K Grade Solution Key Chapter 5 Compose and Decompose  Numbers to 10. As per your convenience, we have provided the Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 in the pdf format.

Vocabulary

Lesson: 1 Partner Numbers to 5

Lesson: 2 Use Number Bonds to Represent Numbers to 5

Lesson: 3 Compose and Decompose 6

Lesson: 4 Compose and Decompose 7

Lesson: 5 Compose and Decompose 8

Lesson: 6 Compose and Decompose 9

Lesson: 7 Compose and Decompose 10

Lesson: 8 Compose and Decompose Using a Group of 5

Chapter 5: Compose and Decompose Numbers to 10

Compose and Decompose Numbers to 10 Vocabulary

Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 1
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 2

Directions:
Count the animals in each group. Write each number. Draw a line through the number that is less than the other number.

Answer:
There are 2 groups of animals.
They are squirrels and parrots.
There are 3 squirrels and 5 parrots in the group.

Chapter 5 Vocabulary Cards

Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 3
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 4

Lesson 5.1 Partner Numbers to 5

Explore and Grow

Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 5

Directions:
Drop 3 two-color counters in the box. Move the counters to the correct frame. Name the parts and the whole. Repeat this process using 4 and 5 counters.

Think and Grow

Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 6

Directions:
Count each type of object. Write each number. Count all of the objects. Write the number for the whole.

Answer:
cat = 2
tiger =1
rabbit(white) = 5
rabbit (brown) = 0

Explanation:
In the above-given figures ,
There are 2 cats.
The number of cats = 2
There are 1 tigers.
The number of tigers = 1
There are 5 white color rabbits.
The number of rabbits which are in white color = 5
There is one brown color rabbit.
The number of rabbits which are in brown color =0
Big-Ideas-Math-Solutions-Grade-K-Chapter-5-Compose and Decompose Numbers to 10-5.1-01

Apply and Grow: Practice

Question 1.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 7

Answer:
dogs (white) = 1
dog( yellow) = 3

Explanation:
In the above-given figures ,
There are  4  dogs.
The number of  dogs which are in white color = 1
The number of dogs which are in yellow color = 3
Big-Ideas-Math-Solutions-Grade-K-Chapter-5-Compose and Decompose Numbers to 10-5.1-02

Question 2.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 8

Answer:
The number of dogs  = 2
The  number of cats= 3
Big-Ideas-Math-Solutions-Grade-K-Chapter-5-Compose and Decompose Numbers to 10-5.1-03

Question 3.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 9

Directions:
1 – 3 Count each type of animal. Write each number. Count all of the animals. Write the number for the whole.
Answer:
a. bears = 1 + 1 + 1
bears = 3
b. bears = 4
deers = 0
The number for the whole = 3
Big-Ideas-Math-Solutions-Grade-K-Chapter-5-Compare and Decompose Numbers to 10-5.1-4

Think and Grow: Modeling Real Life

Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 10

Answer:
1.The number of spots on the left side = 2
The number of spots on the right side = 2

Explanation:
Given that show one way to draw  4 spots on the ladybug.
The number of spots on the left side = 2
The number of spots on the right side = 2
the number of spots on each wing = 4

Answer:
2.The number of spots on the left side = 3
The number of spots on the right side = 2

Explanation:
Given that show one way to draw  4 spots on the ladybug.
The number of spots on the left side = 3
The number of spots on the right side = 2
the number of spots on each wing = 5

Answer:
3.The number of spots on the left side = 2
The number of spots on the right side = 3

Explanation:
Given that show one way to draw  4 spots on the ladybug.
The number of spots on the left side = 2
The number of spots on the right side = 3
the number of spots on each wing = 5
Big-Ideas-Math-Solutions-Grade-K-Chapter-5-Compare and Decompose Numbers to 10-5.1-5

Directions:

  • Show one way to draw 4 spots on the ladybug. Write the number of spots on each wing.
  • Show two ways to draw 5 spots on the ladybug. Write the number of spots on each wing.

Partner Numbers to 5 Homework & Practice 5.1

Question 1.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 11

Answer:
yellow color = 1
red color = 1

Explanation:
In the above-given figure,
There are 2 colors.
They are yellow and red in color.
The number of red color = 1
The number of yellow color = 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-5-Compare and Decompose Numbers to 10-5.1-6

Question 2.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 12

Answer:
white color dogs = 2
brown color dogs = 2

Explanation:
In the above-given figure,
There are dogs.
They are white and brown in color.
The number of white color dogs = 2
The number of brown color dogs = 2
2 + 2 = 4
Big-Ideas-Math-Solutions-Grade-K-Chapter-5-Compare and Decompose Numbers to 10-5.1-7

Directions:
1 and 2 Count each type of object. Write each number. Count all of the objects. Write the number for the whole.

Question 3.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 13

Answer:
red color dogs = 4
1 + 1 + 1 + 1
blue color dogs = 1
1
The number for the whole =5
1 + 1 + 1+ 1 + 1

Explanation:
In 1 there are 4 red color dogs.
1 + 1 + 1 + 1
There is one blue color dog.
1
The number of all dogs which are red and blue = 5
Big-Ideas-Math-Solutions-Grade-K-Chapter-5-Compare and Decompose Numbers to 10-5.1-8

Question 4.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 14

Answer:
white color dogs = 2
black color = 0
The number of dogs for whole = 2

Explanation:
In 1 there are 2 white color dogs
1 + 1 = 2
The number for the whole = 2
The total number of dogs = 2
1 + 1 = 2
Big-Ideas-Math-Solutions-Grade-K-Chapter-5-Compare and Decompose Numbers to 10-5.1-9

Question 5.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 15

Answer:
The number of spots on the left side = 2
The number of spots on the right side = 1

Explanation:
Given that show one way to draw  3 spots on the ladybug.
The number of spots on the left side = 2
The number of spots on the right side = 1
the number of spots on each wing = 3
Big-Ideas-Math-Solutions-Grade-K-Chapter-5-Compare and Decompose Numbers to 10-5.1-10

Directions:
3 and 4 Count each type of dog. Write each number. Count all of the dogs. Write the number for the whole. 5 Show one way to draw 3 spots on the ladybug. Write the number of spots on each wing.

Lesson 5.2 Use Number Bonds to Represent Numbers to 5

Explore and Grow

Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 16

Answer:
The number of berries on the bushes = 5

Explanation:
Given that use, counters to show  3 berries on one bush and 2 berries on the other bush.
the number of berries on the left = 3
the number of berries on the right = 2
the total number of berries on the bushes = 5

Big-Ideas-Math-Solutions-Grade-K-Chapter-5-Compare and Decompose Numbers to 10-5.2-1

Directions:
Use counters to show 3 berries on one bush and 2 berries on the other bush. Slide the counters to the bottom to show the whole. Name the parts and the whole.

Think and Grow

Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 17

Answer:
There are 2 blue color berries.
There are 3 green color berries.
The whole = 5

Explanation:
In the above-given figure,
there are 5 berries.
In them, there are 2 blue color berries.
there are 3 green color berries.
Number bond

Big-Ideas-Math-Solutions-Grade-K-Chapter-5-Compare and Decompose Numbers to 10-5.2-2

Answer:
There is 1 yellow color peach.
There is 1 green color peach.
The whole = 2

Explanation:
In the above-given figure,
there are 2 peaches.
In them, there is 1 yellow color peach.
there is 1 green color peach
The whole = 1 + 1 = 2.
Number bond

Directions:
Name the parts and the whole for the group. Then complete the number bond.

Apply and Grow: Practice

Question 1.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 18.1

Answer:
There are 4 blue color strawberries.
There is 1 red color strawberry.
The whole = 5

Explanation:
In the above-given figure,
there are 5 strawberries.
In them, there is 1 red color strawberry.
there is 4 blue color strawberries.
The whole = 4+ 1 = 5.
1 + 1 + 1 + 1 + 1 = 5
Number bond
Big-Ideas-Math-Solutions-Grade-K-Chapter-5-Compare and Decompose Numbers to 10-5.2-3

Question 2.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 18.2

Answer:
There are 2 yellow color lemons.
There are 2 green color lemons.
The whole = 4

Explanation:
In the above-given figure,
there are 4 lemons.
In them, there are 2 green color lemons.
there are 2 yellow color lemons.
The whole = 2 + 2 = 4.
1 + 1 + 1 + 1 = 4
Number bond
Big-Ideas-Math-Solutions-Grade-K-Chapter-5-Compare and Decompose Numbers to 10-5.2-4

Question 3.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 18.3

Answer:
There are 2 bananas which are not opened.
There is 1 banana which is opened.
The whole = 3

Explanation:
In the above-given figure,
there are 3 bananas.
In them, there are 2 bananas which are not opened.
there is 1 banana which is opened.
The whole = 3.
1 + 1 + 1  = 3
Number bond
Big-Ideas-Math-Solutions-Grade-K-Chapter-5-Compare and Decompose Numbers to 10-5.2-5

Directions:
1 – 3 Name the parts and the whole for the group. Then complete the number bond.

Think and Grow: Modeling Real Life

Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 19
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 20

Answer:
The number of cherries = 3

Explanation:
In the above-given question,
draw three cherries on the picture.
draw some of the cherries in the tree and some of the cherries on the ground.
the number of cherries on the tree = 2
the number of cherries on the ground = 1
The number of cherries = 3

Answer:
The number of cherries = 4

Explanation:
In the above-given question,
draw three cherries on the picture.
draw some of the cherries in the tree and some of the cherries on the ground.
the number of cherries on the tree = 2
the number of cherries on the ground = 2
The number of cherries = 4

Big-Ideas-Math-Solutions-Grade-K-Chapter-5-Compare and Decompose Numbers to 10-5.2-6

Directions:

  • Draw 3 cherries on the picture. Draw some of the cherries in the tree and some of the cherries on the ground. Complete the number bond to match your picture.
  • Draw 4 cherries on the picture. Draw some of the cherries in the tree and some of the cherries on the ground. Complete the number bond to match your picture.

Use Number Bonds to Represent Numbers to 5 Homework & Practice 5.2

Question 1.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 21

Answer:
There is 1 red color.
There is 1 yellow color.
The whole = 2

Explanation:
In the above-given figure,
there are 2 colors.
In them, there is 1 red color.
there is  1 yellow color
The whole = 2.
1 + 1   = 3
Number bond

Directions:
1 Name the parts and the whole for the group. Then complete the number bond.

Question 2.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 22

Answer:
There are 3 red color Apples.
There is 1 yellow color Apple.
The whole = 4

Explanation:
In the above-given figure,
there are 2 colors of apples.
In them, there are 3 red color Apples
there is  1 yellow color Apple.
The whole = 4.
1 + 1 + 1 + 1   = 4
Number bond

Question 3.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 23

Answer:
There are 2 oranges which are not opened.
There are 3 oranges which are opened.
The whole = 5

Explanation:
In the above-given figure,
there are 5 oranges.
In them, there are 2 oranges which are not opened.
there are 3 oranges which are opened.
The whole = 5.
1 + 1 + 1 + 1 + 1  = 5
Number bond

Question 4.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 24

Directions:
2 and 3 Name the parts and the whole for the group. Then complete the number bond. 4 Draw 5 cherries on the picture. Draw some of the cherries in the tree and some of the cherries on the ground. Complete the number bond to match your picture.

Lesson 5.3 Compose and Decompose 6

Explore and Grow

Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 25

Directions:
Use counters to show 2 vegetables in one basket and 4 vegetables in the other basket. Slide the counters to the top to show the whole. Name the parts and the whole.

Answer:
The whole = 6

Explanation:
2 vegetables in one basket and 4 vegetables in another basket.
tomatoes, brinjal, cucumber, beans.
Whole = 2 + 4 = 6
2 = 1 + 1
4 = 1 + 1 + 1 + 1

Think and Grow

Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 26

Answer:
There are 3 yellow color capsicums.
There are 3 green color capsicums.
The whole = 6

Explanation:
In the above-given figure,
there are 2 colors of capsicums.
In them, there are 3  yellow color capsicums.
there are  3  green color capsicums.
The whole = 6.
1 + 1 + 1 + 1 +1 + 1  = 6
Number bond

Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 27

Answer:
There are 4 white color broccoli.
There are 2 green color broccoli.
The whole = 6

Explanation:
In the above-given figure,
there are 2 colors of broccoli.
In them, there are 4  white color broccoli.
there are  2  green color broccoli.
The whole = 6.
1 + 1 + 1 + 1 +1 + 1  = 6
Number bond

Directions:
Name the parts and the whole for the group. Then complete the number bond.

Apply and Grow: Practice

Question 1.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 28

Answer:
There are 5 red color chilies.
There is 1 yellow color chilies.
The whole = 6

Explanation:
In the above-given figure,
there are 2 colors of chilies.
In them, there are 5  red color chilies
there is 1  yellow color chilies.
The whole = 6.
1 + 1 + 1 + 1 +1 + 1  = 6
Number bond

Question 2.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 29

Answer:
There are 3 red color onions.
There are 3 orange color onions.
The whole = 6

Explanation:
In the above-given figure,
there are 2 colors of onions.
In them, there are 3  red color onions.
there are 3 orange color onions.
The whole = 6.
1 + 1 + 1 + 1 +1 + 1  = 6
Number bond

 

Question 3.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 30

Answer:
There are 4 corns which are not opened.
There are 2 corns which are opened.
The whole = 6

Explanation:
In the above-given figure,
there are 6 corns
In them, there are 4 corns which are not opened.
there are 2 corns which are opened.
The whole = 6.
1 + 1 + 1 +1 +1 + 1 = 6
Number bond

Directions:
1 – 3 Name the parts and the whole for the group. Then complete the number bond.

Think and Grow: Modeling Real Life

Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 31

Answer:
Newton buys 2 tomatoes.
Descartes buys 4 tomatoes
whole = 6

Explanation:
In the above-given question
they said that newton uses fewer tomatoes than descarrtes.
Newton buys 2 tomatoes.
Descartes buys 4 tomatoes
whole = 2 + 4
6 = 1 + 1 + 1 + 1 + 1 + 1
Number bond

Directions:
There are 6 tomatoes at a farm stand. Newton and Descartes buy all of them. Newton buys fewer tomatoes than Descartes.

  • Draw tomatoes in the wagons to show how many tomatoes Newton and Descartes could buy. Then complete the number bond to match your picture.
  • Draw another way to show how many tomatoes Newton and Descartes could buy. Then complete the number bond to match your
  • picture.

Compose and Decompose 6 Homework & Practice 5.3

Question 1.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 32

Answer:
There are 5 red color buttons.
There is 1yellow color button.
The whole = 6

Explanation:
In the above-given figure,
there are 2 colors of buttons.
In them, there are 5  red color buttons.
there is 1yellow color button..
The whole = 6.
1 + 1 + 1 + 1 +1 + 1  = 6
Number bond

Directions:
1 Name the parts and the whole for the group. Then complete the number bond.

Question 2.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 33

Answer:
There are 4 green color roses.
There are 2 pink color roses.
The whole = 6

Explanation:
In the above-given figure,
there are 2 colors of roses.
In them, there are 4 green color roses.
there are 2 pink color roses.
The whole = 6.
1 + 1 + 1 + 1 +1 + 1  = 6
Number bond

Question 3.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 34

Answer:
There are 3 pumpkins that are not opened.
There are 3 pumpkins which are opened.
The whole = 6

Explanation:
In the above-given figure,
there are 6 pumpkins.
In them, there are 3 pumpkins that are not opened.
there are 3 pumpkins which are opened.
The whole = 6.
1 + 1 + 1 +1 +1 + 1 = 6
Number bond

Question 4.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 35

Answer:
2 + 3 = 5
2 = 1 + 1
3 = 1 + 1 + 1

Newton and Descartes buy all of them.
Newton buys more tomatoes than Descartes.
Newton buys 4 tomatoes and Descartes buys 2 tomatoes.
Number bond

Directions:
2 and 3 Name the parts and the whole for the group. Then complete the number bond. 4 There are 6 tomatoes at a farm stand. Newton and Descartes buy all of them. Newton buys more tomatoes than Descartes. Drawtomatoes in the wagons to show how many tomatoes Newton and Descartes could buy. Then complete the number bond to match your picture.

Lesson 5.4 Compose and Decompose 7

Explore and Grow

Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 36

Directions:
Use counters to show 7 flowers. Slide the counters to the bottom to show 2 groups. Name the parts and the whole.

Answer:
There are 7 flowers shown in the figure.
7 = 4 + 3
whole = 7

Explanation:
There are 7 flowers shown in the figure.
7 = 1 + 1 + 1 + 1 + 1 + 1 +1
4 =1 + 1 + 1 + 1
3 = 1 + 1 + 1
whole = 7

Think and Grow

Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 37

Answer:
There are 6 white color roses.
There is 1 yellow color roses.
The whole = 7

Explanation:
In the above-given figure,
there are 2 colors of roses.
In them, there are.6 white color roses
there are is 1 yellow color roses
The whole = 7.
1 + 1 + 1 + 1 +1 + 1 + 1  = 7
Number bond

Answer:
There are 5 sky blue color arrows.
There are 2 purple color arrows.
The whole = 7

Explanation:
In the above-given figure,
there are 2 colors of arrows.
In them, there are. 5 sky blue color arrows
there are 2 purple color arrows
The whole = 7.
1 + 1 + 1 + 1 +1 + 1 + 1  = 7
Number bond

Directions:
Name the parts and the whole for the group. Then complete the number bond.

Apply and Grow: Practice

Question 1.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 38

Answer:
There are 5 pink color roses.
There are 2 yellow color roses.
The whole = 7

Explanation:
In the above-given figure,
there are 2 colors of roses.
In them, there are. 5 pink color roses.
there are 2 yellow color roses.
The whole = 7.
1 + 1 + 1 + 1 +1 + 1 + 1  = 7
Number bond

Question 2.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 39

Answer:
There are 4 sky blue color water sprinklers.
There are. 3 purple color water sprinklers.
The whole = 7

Explanation:
In the above-given figure,
there are 2 colors of water sprinklers.
In them, there are.4 sky blue color water sprinklers
there are 3 purple color water sprinklers.
The whole = 7.
1 + 1 + 1 + 1 +1 + 1 + 1  = 7
Number bond

Question 3.
Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 40

Answer:
There are 6 pots with sand.
There is 1 pot with sand is poured out.
The whole = 7

Explanation:
In the above-given figure,
there are 2 types of pots.
In them, there are 6 pots with sand.
there 1 pot with sand is poured out.
The whole = 7.
1 + 1 + 1 + 1 +1 + 1 + 1  = 7
Number bond

Directions:
1 – 3 Name the parts and the whole for the group. Then complete the number bond.

Think and Grow: Modeling Real Life

Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 41

Answer:
There are 4 purple color flowers.
There are 3 yellow color flowers.
The whole = 7

Explanation:
In the above-given figure,
there are 2 color of flowers.
In them, there are 4 purple color flowers.
there 3 yellow color flowers.
The whole = 7.
1 + 1 + 1 + 1 +1 + 1 + 1  = 7
Number bond

Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 42

Answer:
There are 3 purple color flowers.
There are 4 yellow color flowers.
The whole = 7

Explanation:
In the above-given figure,
there are 2 color of flowers.
In them, there are 3 purple color flowers.
there 4 yellow color flowers.
The whole = 7.
1 + 1 + 1 + 1 +1 + 1 + 1  = 7
Number bond

Directions:

  • Color some of the flowers purple and some of the flowers yellow. Complete the number bond to match your picture.
  • Color to show another way. Complete the number bond to match your picture.

Compose and Decompose 7 Homework & Practice 5.4

Question 1.
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 43

Directions:
1 Name the parts and the whole for the group. Then complete the number bond.

Answer:
There are 6 red color buttons.
There is 1yellow color button.
The whole = 7

Explanation:
In the above-given figure,
there are 2 colors of buttons.
In them, there are 6  red color buttons.
there is 1yellow color button..
The whole = 7.
1 + 1 + 1 + 1 +1 + 1 + 1  = 7
Number bond

Question 2.
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 44

Answer:
There are 4 blue color houses.
There are 3 purple color houses
The whole = 7

Explanation:
In the above-given figure,
there are 2 colors of houses.
In them, there are 4 blue color houses.
there are 3 purple color houses
The whole = 7.
1 + 1 + 1 + 1 +1 + 1 + 1  = 7
Number bond

Question 3.
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 45

Answer:
There are  5 birds which are flying.
There are 2 birds that are not flying.
The whole = 7

Explanation:
In the above-given figure,
there are 2 colors of birds.
In them, there are 5 birds which are flying.
there are 2 birds which are not flying.
The whole = 7.
1 + 1 + 1 + 1 +1 + 1 + 1  = 7
Number bond

Question 4.
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 46

Directions:
2 and 3 Name the parts and the whole for the group. Then complete the number bond. 4 Color some of the flowers yellow and some of the flowers purple. Complete the number bond to match your picture.

Lesson 5.5 Compose and Decompose 8

Explore and Grow

Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 47

Directions:
Use counters to show 5 toys on the top shelf and 3 toys on the bottom shelf. Slide the counters to the side to show the whole. Name the parts and the whole.

Answer:
The number of toys on the top shelf = 5 toys
The number of toys on the bottom shelf = 3 toys
whole = 5 + 3 = 8

Explanation:
Given that,
The number of toys on the top shelf = 5 toys
The number of toys on the bottom shelf = 3 toys
whole = 5 + 3 = 8
5 = 1 +  1 + 1 + 1 + 1
3 = 1+ 1 + 1
8 = 1 + 1 + 1 + 1 + 1 + 1 + 1 +1
Number bond =

Think and Grow

Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 48

Answer:
There are 5 blue color ropes.
There are 3 orange color ropes.
The whole = 8

Explanation:
In the above-given figure,
there are 2 colors of ropes.
In them, there are 4 blue color ropes
there are 3 orange color ropes
The whole = 8.
1 + 1 + 1 + 1 +1 + 1 + 1 + 1  = 8
Number bond

Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 49

Directions:
Name the parts and the whole for the group. Then complete the number bond.

Answer:
There are 4 blue color teddybears.
There are 4 brown color teddybears.
The whole = 8

Explanation:
In the above-given figure,
there are 2 colors of teddy bears.
In them, there are 4 blue color teddybears.
there are 4 brown color teddybears.
The whole = 8.
1 + 1 + 1 + 1 +1 + 1 + 1 + 1  = 8
Number bond

Apply and Grow: Practice

Question 1.
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 50

Answer:
There are 2 blue color balls.
There are 6 red color balls.
The whole = 8

Explanation:
In the above-given figure,
there are 2 colors of balls.
In them, there are 2 blue color balls.
there are 6 red color balls.
The whole = 8.
1 + 1 + 1 + 1 +1 + 1 + 1 + 1  = 8
Number bond

Question 2.
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 51

Answer:
There are 3 green color flowers.
There are 5 pink color flowers.
The whole = 8

Explanation:
In the above-given figure,
there are 2 colors of flowers.
In them, there are 3 green color flowers.
there are 5 pink color flowers.
The whole = 8
1 + 1 + 1 + 1 +1 + 1 + 1 + 1  = 8
Number bond


Question 3.
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 52

Answer:
There are 6 boxes which are not opened.
There are 2 boxes which are opened.
The whole = 8

Explanation:
In the above-given figure,
there are 8 boxes.
In them, there are 6 boxes which are not opened
there are 2 boxes which are opened..
The whole = 8.
1 + 1 + 1 +1 +1 + 1 + 1 + 1 = 8
Number bond

Directions:
1 – 3 Name the parts and the whole for the group. Then complete the number bond.

Think and Grow: Modeling Real Life

Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 53
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 54

Answer:
There are 6 boxes in  Group A
There are 2 boxes in Group B.
The whole = 8

Explanation:
In the above-given figure,
there are 8 boxes.
In them, there are 6 boxes in Group A.
there are 2 boxes in Group B.
The whole = 8.
1 + 1 + 1 +1 +1 + 1 + 1 + 1 = 8
Number bond

Answer:
There are 4 boxes in  Group A
There are 4 boxes in Group B.
The whole = 8

Explanation:
In the above-given figure,
there are 8 boxes.
In them, there are 4 boxes in Group A.
there are 4 boxes in Group B.
The whole = 8.
1 + 1 + 1 +1 +1 + 1 + 1 + 1 = 8
Number bond

Answer:
There are 2 boxes in  Group A
There are 6 boxes in Group B.
The whole = 8

Explanation:
In the above-given figure,
there are 8 boxes.
In them, there are 2 boxes in Group A.
there are 6 boxes in Group B.
The whole = 8.
1 + 1 + 1 +1 +1 + 1 + 1 + 1 = 8
Number bond

Directions:

  • Put the marbles into 2 groups. Circle the groups. Then complete the number bond to match your picture.
  • Show 2 other ways you can put the marbles into 2 groups. Then complete the number bonds to match your pictures.

Compose and Decompose 8 Homework & Practice 5.5

Question 1.
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 55

Directions:
1 Name the parts and the whole for the group. Then complete the number bond.

Answer:
There are 5 red color buttons.
There is 3 yellow color button.
The whole = 8

Explanation:
In the above-given figure,
there are 2 colors of buttons.
In them, there are 5  red color buttons.
there is 3 yellow color button..
The whole = 8.
1 + 1 + 1 + 1 +1 + 1 + 1 + 1 = 8
Number bond

Question 2.
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 56

Answer:
There are 4 red color cups.
There is 4 blue color cups.
The whole = 8

Explanation:
In the above-given figure,
there are 2 colors of buttons.
In them, there are 4 red color cups.
there is 4 blue color cups.
The whole = 8.
1 + 1 + 1 + 1 +1 + 1 + 1 + 1 = 8
Number bond

Question 3.
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 57

Answer:
There are 7 bands that are not opened.
There is 1 band which is opened.
The whole = 8

Explanation:
In the above-given figure,
there are 8 boxes.
In them, there are  7 bands that are not opened
there is 1 band which is opened..
The whole = 8.
1 + 1 + 1 +1 +1 + 1 + 1 + 1 = 8
Number bond

Question 4.
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 58

Directions:
2 and 3 Name the parts and the whole for the group. Then complete the number bond. 4 Put the marbles into 2 equal groups. Circle the groups. Then complete the number bond to match your picture.

Answer:
There are 8 blue color balls.
whole = 8

Explanation:
In the above-question given that,
put the marbles into 2 equal groups.
group A = 4 balls
group B = 4 balls
whole = 8
4 = 1+ 1 + 1 + 1
4 = 1 + 1 + 1 + 1
whole = 8
Number bond

Lesson 5.6 Compose and Decompose 9

Explore and Grow

Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 59

Directions:
Use counters to show 3 fish in one scene of underwater vegetation and 6 fish in the other scene of underwater vegetation. Slide the counters to the side to show the whole. Name the parts and the whole.

Answer:
There are 3 fish in one scene of underwater vegetation.
There are 6 fish in other scene of underwater vegetation.
whole = 9

Explanation:
In the above-question given that,
put the fishes into 2 equal groups.
group A = 3 fishees.
group B = 6 fishs.
whole = 9
3 = 1+ 1 + 1
6 = 1 + 1 + 1 + 1 + 1 + 1
whole = 9
Number bond

Think and Grow

Big Ideas Math Answer Key Grade K Chapter 5 Compose and Decompose Numbers to 10 60

Answer:
There are 4 yellow color helicopters
There are 5 blue color helicopters.
The whole = 9

Explanation:
In the above-given figure,
there are 2 colors of helicopters.
In them, there are 4 yellow color helicopters
there are 5 blue color helicopters.
The whole = 9.
1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1= 9
Number bond

Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 61

Directions:
Name the parts and the whole for the group. Then complete the number bond.

Answer:
There are 7 red color frogs.
There are 2 blue color frogs.
The whole = 9

Explanation:
In the above-given figure,
there are 2 colors of frogs
In them, there are 7 red color frogs.
there are 2 blue color frogs.
The whole = 9.
1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1= 9
Number bond

Apply and Grow: Practice

Question 1.
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 62

Answer:
There are 8 yellow color seahorses.
There is 1 green color seahorses.
The whole = 9

Explanation:
In the above-given figure,
there are 2 colors of frogs
In them, there are 8 yellow color seahorses.
there is 1 green color seahorse.
The whole = 9.
1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1= 9
Number bond

Question 2.
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 63

Answer:
There are 6 purple colo snails.
There are 3 orange color snails.
The whole = 9

Explanation:
In the above-given figure,
there are 2 colors of snails.
In them, there are 6 purple colo snails.
there are 3 orange color snails.
The whole = 9.
1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1= 9
Number bond

Question 3.
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 64

Answer:
There are 4 boxes that are not opened.
There are  5 boxes which are opened.
The whole = 9

Explanation:
In the above-given figure,
there are 9 boxes.
In them, there are 4 boxes that are not opened..
there are5 boxes which are opened.
The whole = 9.
1 + 1 + 1 +1 +1 + 1+ 1 + 1+ 1 = 9
Number bond

Directions:
1 – 3 Name the parts and the whole for the group. Then complete the number bond.

Think and Grow: Modeling Real Life

Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 65
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 66

Answer:
There are 6 fish in Group A
There are 3 fish in Group A
whole = 9

Explanation:
In the above-question given that,
put the fishes into 2 unequal groups.
group A = 6 fishees.
group B = 3 fishs.
whole = 9
6= 1+ 1 + 1 +1 + 1+ 1
3 = 1 + 1 + 1
whole = 9
Number bond

Answer:
There are 5 fish in Group A
There are 4 fish in Group A
whole = 9

Explanation:
In the above-question given that,
put the fishes into 2 unequal groups.
group A = 5 fishes.
group B = 4 fishes.
whole = 9
5= 1+ 1 + 1 +1 + 1
4 = 1 + 1 + 1 + 1
whole = 9
Number bond

Directions:
You buy 9 fish for your fish tank. You buy more orange fish than yellow fish.

  • Color to show how many orange fish and yellow fish you could buy. Then complete the number bond to match your picture.
  • Color to show another way. Then complete the number bond to match your picture.

Compose and Decompose 9 Homework & Practice 5.6

Question 1.
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 67

Directions:
1 Name the parts and the whole for the group. Then complete the number bond.

Answer:
There is 1 red color button.
There are 8 yellow color buttons.
The whole = 9

Explanation:
In the above-given figure,
there are 2 colors of buttons.
In them, there is 1 red color button.
there are 8 yellow color buttons.
The whole = 9.
1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1= 9
Number bond

Question 2.
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 68

Answer:
There are 3 purple color octopus.
There are 6 orange color octopus.
The whole = 9

Explanation:
In the above-given figure,
there are 2 colors of octopus.
In them, there are 3 purple color octopus
there are 6 orange color octopus
The whole = 9.
1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1= 9
Number bond

Question 3.
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 69

Answer:
There are 5 fishes that do not eat.
There are 4 fishes that eat.
The whole = 9

Explanation:
In the above-given figure,
there are 2 colors of fishes.
In them, there are 5 fishes that do not eat.
there are 4 fishes that eat.
The whole = 9.
1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1= 9
Number bond

Question 4.
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 70

Directions:
2 and 3 Name the parts and the whole for the group. Then complete the number bond. 4 You buy 9 fish for your fish tank. You buy fewer red fish than purple fish. Color to show how many red fish and purple fish you could buy. Then complete the number bond to match your picture.

Answer:
There are 3 red color fishes.
There are 6 purple color fishes.
The whole = 9

Explanation:
Given that fewer are red and some are purple.
In the above-given figure,
there are 2 colors of fishes.
In them, there are 3 red color fishes.
there are 6 purple color fishes.
The whole = 9.
1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1= 9
Number bond

Lesson 5.7 Compose and Decompose 10

Explore and Grow

Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 71

Directions:
Use counters to show 10 paint spots. Slide the counters to the side to show 2 groups. Name the parts and the whole.

Think and Grow

Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 73

Answer:
There are 9 green colored pencils.
There is 1 blue color pencil.
The whole = 10

Explanation:
Given that fewer are red and some are purple.
In the above-given figure,
there are 2 colors of pencils.
In them, there are 9 green colored pencils.
there 1 blue color pencil..
The whole = 10.
1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1= 9
1 = 1
Number bond

Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 73.1

Directions:
Name the parts and the whole for the group. Then complete the number bond.

Answer:
There are 4 yellow-colored brushes.
There are 6 orange color brushes.
The whole = 10

Explanation:
Given that fewer are red and some are purple.
In the above-given figure,
there are 2 colors of brushes.
In them, there are 4 yellow-colored brushes.
there are 6 orange color brushes.
The whole = 10.
6 = 1 + 1 + 1 + 1 +1 + 1
4 = 1 + 1 + 1 + 1
Number bond

Apply and Grow: Practice

Question 1.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 74

Answer:
There are 5 red-colored bags.
There are 5 ash color bags.
The whole = 10

Explanation:
Given that fewer are red and some are purple.
In the above-given figure,
there are 2 colors of bags.
In them, there are 5 red-colored bags.
there are 5 ash color bags.
The whole = 10.
5 = 1 + 1 + 1 + 1 +1
5 = 1 + 1 + 1 + 1 + 1
Number bond

Question 2.
Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 75

Answer:
There are 6 green-colored bottles.
There are 4 blue color bottles.
The whole = 10

Explanation:
Given that fewer are red and some are purple.
In the above-given figure,
there are 2 colors of bottles.
In them, there are 6 green-colored bottles..
there are 4 blue color bottles.
The whole = 10.
6 = 1 + 1 + 1 + 1 +1 + 1
4 = 1 + 1 + 1 + 1
Number bond

Question 3.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 76

Directions:
1 – 3 Name the parts and the whole for the group. Then complete the number bond.

Answer:
There are 2 bottles which are poured out.
There are 8 bottles that are not poured.
The whole = 10

Explanation:
In the above-given figure,
there are 2 colors of bottles.
In them, there 2 bottles which are poured out.
there are 8 bottles that are not poured.
The whole = 10.
8 = 1 + 1 + 1 + 1 +1 + 1 + 1+1
2 = 1 + 1
Number bond

Think and Grow: Modeling Real Life

Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 77

Answer:
There are 4 red color buttons.
There are 6 blue color buttons.
The whole = 10

Explanation:
In the above-given figure,
there are 2 colors of buttons.
In them, there 4 red color buttons.
there are 6 blue color buttons.
The whole = 10.
6 = 1 + 1 + 1 + 1 +1 + 1
4 = 1 + 1 +1 + 1
Number bond

Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 78

Answer:
There are 5 red color buttons.
There are 5 blue color buttons.
The whole = 10

Explanation:
In the above-given figure,
there are 2 colors of buttons.
In them, there 5 red color buttons.
there are 5 blue color buttons.
The whole = 10.
5= 1 + 1 + 1 + 1 +1
5 = 1 + 1 +1 + 1+ 1
Number bond

Answer:
There are 6 red color buttons.
There are 4 blue color buttons.
The whole = 10

Explanation:
In the above-given figure,
there are 2 colors of buttons.
In them, there 6 red color buttons.
there are 4 blue color buttons.
The whole = 10.
6= 1 + 1 + 1 + 1 +1+ 1
4 = 1 + 1 +1 + 1
Number bond

Directions:

  • You have 10 buttons. Classify the buttons into 2 categories. Circle the groups. Then complete the number bond to match your picture.
  • Show 2 other ways you can classify the buttons into 2 categories. Then complete the number bonds to match your pictures.

Compose and Decompose 10 Homework & Practice 5.7

Question 1.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 79

Answer:
There are 4  red color buttons.
There are 6 yellow color buttons.
The whole = 10

Explanation:
In the above-given figure,
there are 2 colors of buttons.
In them, there are 4 red color buttons.
there are 6 yellow color buttons.
The whole = 10.
1 +1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1= 10
Number bond

Directions:
1 Name the parts and the whole for the group. Then complete the number bond.

Question 2.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 80

Answer:
There are 2 green color bottles.
There are 8 orange color bottles.
The whole = 10

Explanation:
In the above-given figure,
there are 2 colors of bottles.
In them, there are 2 green color bottles.
there are 8 orange color bottles.
The whole = 10.
1 +1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1= 10
Number bond

Question 3.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 81

Answer:
There are 7 boxes that are not opened.
There are  3 boxes which are opened.
The whole = 10

Explanation:
In the above-given figure,
there are 10 boxes.
In them, there are 7 boxes that are not opened..
there are 3 boxes which are opened.
The whole = 10.
1 +1 + 1 + 1 +1 +1 + 1+ 1 + 1+ 1 = 9
Number bond

Question 4.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 82

Answer:
There are 5  purple color buttons.
There are 5 yellow color buttons.
The whole = 10

Explanation:
In the above-given figure,
there are 2 colors of buttons.
In them, there are 5 purple color buttons.
there are 5 yellow color buttons.
The whole = 10.
1 +1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1= 10
Number bond

Directions:
2 and 3 Name the parts and the whole for the group. Then complete the number bond. 4 You have 10 buttons. Classify the buttons into 2 categories. Circle the groups. Then complete the number bond to match your picture.

Lesson 5.8 Compose and Decompose Using a Group of 5

Explore and Grow

Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 83

Directions:
How many frogs are on the log? Place a counter on each frog. Use more counters to show 9 frogs. Slide the counters to the bottom to show the 2 groups. Name the parts and the whole.

Answer:
There are 5 frogs in Group A
There are 4 frogs in Group B
whole = 9

Explanation:
In the above-question given that,
put the fishes into 2 unequal groups.
group A = 5 frogs
group B = 4 frogs.
whole = 9
5= 1+ 1 + 1 +1 + 1
4 = 1 + 1 + 1 + 1
whole = 9
Number bond

Think and Grow

Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 84

Answer:
Whole = 6
5 = 1 + 1 + 1 + 1 + 1
1 = 1

Explanation:
In the above-given figure,
whole = 6
5 + 1 = 6
we have to add 1 and we have to color it.
Number bond

Answer:
Whole = 9
5 = 1 + 1 + 1 + 1 + 1
4 = 1 + 1 + 1 + 1

Explanation:
In the above-given figure,
whole = 9
5 + 4 = 9
we have to add 4 dots and we have to color it.
Number bond

Directions:
Draw dots in the ten frame to make the whole. Use the ten frame to complete the number bond.

Apply and Grow: Practice

Question 1.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 85

Answer:
Whole = 10
5 = 1 + 1 + 1 + 1 + 1
5 = 1 + 1 + 1 + 1 + 1

Explanation:
In the above-given figure,
whole = 10
5 + 5 = 10
we have to add 5 dots and we have to color it.
Number bond

Question 2.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 86

Answer:
Whole = 8
5 = 1 + 1 + 1 + 1 + 1
3 = 1 + 1 + 1

Explanation:
In the above-given figure,
whole = 8
5 + 3 = 8
we have to add 3 dots and we have to color it.
Number bond

Question 3.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 87

Answer:
Whole = 7
5 = 1 + 1 + 1 + 1 + 1
2 = 1 + 1

Explanation:
In the above-given figure,
whole = 7
5 + 2 = 7
we have to add 2 dots and we have to color it.
Number bond

Directions:
1 – 3 Draw dots in the ten frame to make the whole. Use the ten frame to complete the number bond.

Think and Grow: Modeling Real Life

Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 88

Answer:
Whole = 7
5 = 1 + 1 + 1 + 1 + 1
2 = 1 + 1

Explanation:
In the above-given figure,
whole = 7
5 + 2 = 7
we have to add 2 dots and we have to color it.
Number bond

Answer:
Whole = 7
4 = 1 + 1 + 1 + 1
3 = 1 + 1 + 1

Explanation:
In the above-given figure,
whole = 7
4 + 3 = 7
we have to add 3 dots and we have to color it.
Number bond

Directions:
Newton has 5 balloons. Descartes has fewer balloons than Newton.

  • Draw Descarte’s balloons. Complete the number bond to match your picture.
  • Draw to show another way. Then complete the number bond to match your picture.

Compose and Decompose Using a Group of 5 Homework & Practice 5.8

Question 1.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 89

Directions:
1 Draw dots in the ten frame to make the whole. Use the ten frame to complete the number bond.

Answer:
Whole = 10
5 = 1 + 1 + 1 + 1 + 1
5 = 1 + 1 + 1+ 1 + 1

Explanation:
In the above-given figure,
whole = 10
5 + 5 = 10
we have to add 5 dots and we have to color it.
Number bond

Question 2.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 90

Answer:
Whole = 7
5 = 1 + 1 + 1 + 1 + 1
2 = 1 + 1

Explanation:
In the above-given figure,
whole = 7
5 + 2 = 7
we have to add 2 dots and we have to color it.
Number bond

 

Question 3.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 91

Answer:
Whole = 9
5 = 1 + 1 + 1 + 1 + 1
4 = 1 + 1 + 1 + 1

Explanation:
In the above-given figure,
whole = 9
5 + 4 = 9
we have to add 4 dots and we have to color it.
Number bond

Question 4.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 92

Directions:
2 and 3 Draw dots in the ten frame to make the whole. Use the ten frame to complete the number bond. 4 Newton has 5 balloons. Descartes has the same number of balloons as Newton. Draw Descartes’s balloons. Complete the number bond to match your picture.

Answer:
Whole = 10
5 = 1 + 1 + 1 + 1 + 1
5 = 1 + 1 + 1 + 1 + 1

Explanation:
In the above-given figure,
whole = 10
5 + 5 = 10
we have to add 5 dots and we have to color it.
Number bond

Compose and Decompose Numbers to 10 Performance Task 5

Question 1.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 93

Question 2.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 94

Answer:
Whole = 8
5 = 1 + 1 + 1 + 1 + 1
3 = 1 + 1 + 1

Explanation:
In the above-given figure,
whole = 8
5 + 3 = 8
we have to add 3 dots and we have to color it.
Number bond

Question 3.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 95

Answer:
Whole = 8
4 = 1 + 1 + 1 + 1
4 = 1 + 1 + 1 + 1

Explanation:
In the above-given figure,
whole = 8
4 + 4 = 8
we have to add 4 dots and we have to color it.
Number bond

Directions:
1 Color to show fewer red ladybugs than yellow ladybugs. Then complete the number bond to match your picture. 2 Use the number bond to classify the butterflies. Then complete the number bond. 3 Classify the butteries another way. Then complete the number bond.

Compose and Decompose Numbers to 10 Activity

Number Bond Spin and Cover

Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 95.1

Directions:
Take turns using the spinner to nd your partner number with 5. Use your partner numbers to find the whole on the game board. Cover the whole with a counter. Repeat this process until you have covered all of the numbers.

Compose and Decompose Numbers to 10 Chapter Practice

5.1 Partner Numbers to 5

Question 1.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 96

Answer:
There are 2 red color buttons.
There is 2 yellow color button.
The whole = 4

Explanation:
In the above-given figure,
there are 2 colors of buttons.
In them, there are 2  red color buttons.
there is  2 yellow color button..
The whole = 4
1 + 1 + 1 + 1   = 4

Question 2.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 97

Answer:
dogs= 1
puppies =4
whole = 5

Explanation:
In the above-given figures,
There are 4 dogs.
The number of puppies = 4
There is 1 dog.
The number of dogs  = 1
whole = 5
5.2 Use Number Bonds to Represent Numbers to 5

Question 3.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 98

Directions:
1 and 2 Count each type of object. Write each number. Count all of the objects. Write the number for the whole. 3 Name the parts and the whole for the group. Then complete the number bond.

Answer:
There are 4 red color buttons.
There is 1yellow color button.
The whole = 5

Explanation:
In the above-given figure,
there are 2 colors of buttons.
In them, there are 4 red color buttons.
there is 1yellow color button..
The whole = 5.
1 + 1 + 1 + 1 +1   = 5
Number bond

5.3 Compose and Decompose 6

Question 4.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 99

Answer:
There are 3 blue color plates.
There are 3 green color plates.
The whole = 6

Explanation:
In the above-given figure,
there are 2 colors of plates.
In them, there are 3 blue color plates.
there are 3 green color plates.
The whole = 6.
1 + 1 + 1 + 1 +1 + 1 = 6
Number bond

5.4 Compose and Decompose 7

Question 5.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 100

Answer:
There are 3 pink color flowers.
There are 4 blue color flowers.
The whole = 7

Explanation:
In the above-given figure,
there are 2 colors of flowers.
In them, there are 3 pink color flowers.
there are 3 blue color flowers.
The whole = 7.
1 + 1 + 1 + 1 +1 + 1+ 1 = 6
Number bond

5.5 Compose and Decompose 8

Question 6.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 101

Directions:
4 – 6 Name the parts and the whole for the group. Then complete the number bond.

Answer:
There are 4 brown color teddybears.
There are 4 blue color teddybears.
The whole = 8

Explanation:
In the above-given figure,
there are 2 colors of teddybears.
In them, there are 4 brown color teddybears.
there are 4 blue color teddybears.
The whole = 8.
1 + 1 + 1 + 1 +1 + 1+ 1 + 1= 8
Number bond

5.6 Compose and Decompose 9

Question 7.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 102

Answer:
There are 3 green color teddybears.
There are 6 blue color teddybears.
The whole = 9

Explanation:
In the above-given figure,
there are 2 colors of teddy bears.
In them, there are 3 green color teddybears.
there are 6 blue color teddybears.
The whole = 9.
1 +1 + 1 + 1 + 1 +1 + 1+ 1 + 1= 8
Number bond

5.7 Compose and Decompose 10

Question 8.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 103

Answer:
There are 4 flowers which are opened.
There are 6 flowers which are not opened.
The whole = 10

Explanation:
In the above-given figure,
there are 2 colors of flowers.
In them, there are 4 flowers which are opened.
there are 6 6 flowers which are not opened
The whole = 10.
1 +1 +1 + 1 + 1 + 1 +1 + 1+ 1 + 1= 8
Number bond

Question 9.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 104

Directions:
7 and 8 Name the parts and the whole for the group. Then complete the number bond. 9 You have 10 buttons. Classify the buttons into 2 categories. Circle the groups. Then complete the number bond to match your picture.

Answer:
There are 4  green color buttons.
There are 6 yellow color buttons.
The whole = 10

Explanation:
In the above-given figure,
there are 2 colors of buttons.
In them, there are 4 green color buttons.
there are 6 yellow color buttons.
The whole = 10.
1 +1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1= 10
Number bond

5.8 Compose and Decompose Using a Group of 5

Question 10.

Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 105

Answer:
Whole = 9
5 = 1 + 1 + 1 + 1 + 1
4 = 1 + 1 + 1+ 1

Explanation:
In the above-given figure,
whole = 9
5 + 4 = 19
we have to add 4 dots and we have to color it.
Number bond

Question 11.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 106

Answer:
Whole = 7
5 = 1 + 1 + 1 + 1 + 1
2= 1 + 1

Explanation:
In the above-given figure,
whole = 7
5 + 2 = 7
we have to add 2 dots and we have to color it.
Number bond

 

Question 12.
Big Ideas Math Solutions Grade K Chapter 5 Compose and Decompose Numbers to 10 107

Directions:
10 and 11 Draw dots in the ten frame to make the whole. Use the ten frame to complete the number bond. 12 Newton has 5 balloons. Descartes has fewer balloons than Newton. Draw Descartes’s balloons. Complete the number bond to match your picture.

Answer:
Whole = 7
5 = 1 + 1 + 1 + 1 + 1
2= 1 + 1

Explanation:
In the above-given figure,
whole = 7
5 + 2 = 7
we have to add 2 dots and we have to color it.
Number bond

Conclusion:
Hope Big Ideas Math Answers Grade K Chapter 5 Compose and Decompose Numbers to 10 is helpful for you to gain knowledge over the subject. Test yourself by solving the problems given at the end of the chapter. For any doubts please post the comments in the below given comment box. We are always ready to clarify your doubts without any delay and in a simple manner.

Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19

Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19

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Big Ideas Math Book Grade K Answer Key Chapter 8 Represent Numbers 11 to 19

Enhance your performance skills by solving the Big Ideas Math Book Grade K Answers Chapter 8 Represent Numbers 11 to 19. Students can get a good knowledge on the subject with the help of Big Ideas Math Book Grade K Answer Key Chapter 8 Represent Numbers 11 to 19. Mathematical students can construct the meaning of core concepts and principles by addressing the  Big Ideas Math Grade K Solution Key. Just click on the below links which are prepared topic wise and kickstart your preparation.

Vocabulary

Lesson: 1 Identify Groups of 10

Lesson: 2 Count and Write 11 and 12

Lesson: 3 Understand 11 and 12

Lesson: 4 Count and Write 13 and 14

Lesson: 5 Understand 13 and 14

Lesson: 6 Count and Write 15

Lesson: 7 Understand 15

Lesson: 8 Count and Write 16 and 17

Lesson: 9 Understand 16 and 17

Lesson: 10 Count and Write 18 and 19

Lesson: 11 Understand 18 and 19

Chapter: 8 – Represent Numbers 11 to 19

Represent Numbers 11 to 19 Vocabulary

Directions:
Count the shooting stars in the sky. Write the number. You see 2 more shooting stars in the sky. Draw the shooting stars. Then write an addition sentence to tell how many shooting stars there are in all.

Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 v 1

Answer:
There are 48 shooting stars in the sky.

Explanation:
Given that, there are 2 more shooting stars in the sky.
Totally there are 48 stars in the sky.
46 + 2 = 48
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.1-1

Vocabulary Cards
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 v 2
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 v 3

Vocabulary Cards
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 v 4

Answer:
The vocabulary cards are 12, 13, 14, 15, 16, 17, 18, and 19.

Explanation:
In the above-given question,
given the vocabulary cards.
The vocabulary cards are 12, 13, 14, 15, 16, 17, 18, and 19.

Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 v 5

Answer:
The vocabulary cards are 12, 13, 14, 15, 16, 17, 18, and 19.

Explanation:
In the above-given question,
given the vocabulary cards.
The vocabulary cards are 12, 13, 14, 15, 16, 17, 18, and 19.

Lesson 8.1 Identify Groups of 10

Explore and Grow

Directions:
Count and circle 10 linking cubes. Color the extra linking cubes.

Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.1 1

Answer:
The number of cubes = 15

Explanation:
Given that, circle the 10 linking cubs.
color that extra linking cubs.
The total number of cubes = 15
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.1-01

Think and Grow

Directions:
Circle 10 objects. Tell how many more objects there are. Then write the numbers.

Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.1 2

Answer:
The total number of objects is 18.

Explanation:
Given that, circle the 10 objects.
There are 8 more objects.
The total number of objects is 18.
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.1-2

Apply and Grow: Practice

Directions:
1 and 2 Circle 10 objects. Tell how many more objects there are. Then write the numbers.

Question 1.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.1 3

Answer:
The total number of objects is 17.

Explanation:
Given that, circle the 10 objects.
There are 7 more objects.
The total number of objects is 17.

Question 2.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.1 4

Answer:
The total number of objects is 14.

Explanation:
Given that, circle the 10 objects.
There are 3 more objects.
The total number of objects is 14.
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.1-03

Think and Grow: Modeling Real Life

Directions:
Draw beads on the string to show how many beads there are in all. Circle 10 beads

Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.1 5

Answer:
The total number of beads is 11 in the first figure.

Explanation:
Given that, circle the 10 objects.
There are 1 more objects.
The total number of objects is 11.
The total number of beads is 11 in the first figure.
Given that, circle the 10 objects.
There are 6 more objects.
The total number of objects is 16.

Identify Groups of 10 Homework & Practice 8.1

Directions:
1 Circle 10 paintbrushes. Tell how many more paintbrushes there are. Then write the numbers.

Question 1.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.1 6

Answer:
The total number of paintbrushes is 13.

Explanation:
Given that, circle the 10 paintbrushes.
There are 3 more objects.
The total number of paintbrushes is 13.
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.1-05
Directions:
2 and 3 Circle 10 objects. Tell how many more objects there are. Then write the numbers. 4 Draw beads on the string to show how many beads there are in all. Circle 10 beads.

Question 2.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.1 7

Answer:
The total number of objects is 15.

Explanation:
Given that, circle the 10 objects.
There are 5 more objects.
The total number of objects is 15.

Question 3.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.1 8

Answer:
The total number of objects is 11.

Explanation:
Given that, circle the 10 objects.
There are 1 more objects.
The total number of objects is 11.

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.1-07

Question 4.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.1 9

Answer:
The total number of beads is 17 figure.

Explanation:
Given that, circle the 10 beads.
There are 7 more beads.
The total number of beads is 17.

Lesson 8.2 Count and Write 11 and 12

Explore and Grow

Directions:
Place a linking cube on each strawberry. Slide cubes to fill the ten frame. Slide the extra cubes to the five frame.

Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.2 1
Answer:
The number of strawberries.

Explanation:
Given that there are 11 strawberries.
place the cubes in 10 frame and 1 cube in 1 frame.
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.2-01

Think and Grow

Directions:

  • Count the fruit. Say the number. Trace and write the number.
  • Count the fruit. Say the number. Write the number

Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.2 2

Answer:
a. The number of bananas = 12.
b. The number of watermelons = 11.

Explanation:
Given that, count the fruit.
bananas = 12
water melons = 11
12 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
11 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.2-1

Apply and Grow:

Practice

Directions:
1 – 4 Count the objects. Say the number. Write the number.

Question 1.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.2 3

Answer:
The total number of objects is 11.

Explanation:
Given that, count the objects.
There are 11 objects.
The total number of objects is 11.
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.2-2

Question 2.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.2 4

Answer:
The total number of objects is 11.

Explanation:
Given that, count the objects.
There are 11 objects.
The total number of objects is 11.
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.2-3

Question 3.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.2 5

Answer:
The total number of objects is 12.

Explanation:
Given that, count the objects.
There are 12 objects.
The total number of objects is 12.
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.2-4

Question 4.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.2 6

Answer:
The total number of objects is 12.

Explanation:
Given that, count the objects.
There are 12 objects.
The total number of objects is 12.
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.2-5

Think and Grow: Modeling Real Life

Directions:
You have 12 oranges in your cart. There are 11 apples in the bin. Draw the oranges in the cart and the apples in the bin. Then write the numbers.

Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.2 7

Answer:
The number of oranges = 12.
The number of apples = 11.

Explanation:
Given that, there are 12 oranges in the cart.
there are 11 apples in the bin.
The number of oranges = 12.
The number of apples = 11.
11 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
12 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.2-6
Count and Write 11 and 12 Homework & Practice 8.2

Directions:
1 and 2 Count the objects. Say the number. Write the number.

Question 1.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.2 8

Answer:
The number of objects = 12.

Explanation:
Given that, count the objects.
there are 12 objects.
The number of objects = 12.
12 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.2-7

Question 2.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.2 9

Answer:
The number of objects = 11.

Explanation:
Given that, count the objects.
there are 11 objects.
The number of objects = 11.
11 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.2-8

Directions:
3 and 4 Count the fruit. Say the number. Write the number. 5 Draw 12 cherries on the tree. Write the number.

Question 3.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.2 10

Answer:
The number of bananas = 10.

Explanation:
Given that, count the fruits.
there are 10 bananas.
The number of fruits = 10.
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.2-9

Question 4.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.2 11

Answer:
The number of berries = 11.

Explanation:
Given that, count the fruits.
there are 11 berries.
The number of berries = 11.
11 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.2-10

Question 5.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.2 12

Answer:
The number of cherries = 12.

Explanation:
Given that, draw the cherries on the tree.
there are 12 cherries.
The number of cherries = 12.
12 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1+ 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.2-11

Lesson 8.3 Understand 11 and 12

Explore and Grow

Directions:
Place the 10 and 1 cards as the parts on the number bond. Slide the cards and hide the zero with the 1 card to make the whole. Write the parts and the whole.

Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.3 1

Answer:
10 + 1 = 11
The whole = 11

Explanation:
Given that, place the 10 and 1 cards as the parts on the number bond.
slide the cards and hide the zero with the one card to make the whole.
10 + 1 = 11
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
1 = 1
whole = 11
11 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1.
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.3-1

Think and Grow

Directions:
Circle 10 objects. Draw dots in the ten frame to show how many objects are circled. Draw dots in the five frame to show how many more objects there are. Use the frames to write an addition sentence.

Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.3 2

Answer:
The number of cars = 12

Explanation:
Given that, there are 12 cars in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
12 = 10 + 2
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
2 = 1 + 1
12 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.2-02

Apply and Grow: Practice

Directions:
1 and 2 Circle 10 vehicles. Draw dots in the ten frame to show how many vehicles are circled. Draw dots in the five frame to show how many more vehicles there are. Use the frames to write an addition sentence.

Question 1.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.3 3

Answer:
The number of bikes = 12

Explanation:
Given that, there are 12 bikes in the figure.
circle 10 vehicles.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
12 = 10 + 2
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
2 = 1 + 1
12 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.2-03

Question 2.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.3 4

Answer:
The number of cars = 12

Explanation:
Given that, there are 11 cars in the figure.
circle 10 vehicles.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
11 = 10 + 1
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
1 = 1
11 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.2-04

Think and Grow: Modeling Real Life

Directions:

  • You have blue trucks. Your friend has red trucks. Circle your trucks. Write an addition sentence to match the picture. How many trucks do you have? Circle the number.
  • You have yellow trains. Your friend has green trains. Circle your trains. Write an addition sentence to match the picture. How many trains does your friend have? Circle the number.

Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.3 5

Answer:
a. The number of trucks = 11
blue color trucks = 10
red color truck = 1

Explanation:
Given that, there are 11 trucks in the figure.
circle 10 trucks.
blue color trucks = 10
red color trucks = 1
the number of trucks = 11
11 = 10 + 1
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
1 = 1
11 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1+ 1
b. The number of trains = 12
yellow color trains = 10
green color trains= 2
Explanation:
Given that, there are 12 trains in the figure.
circle 10 trains.
yellow color trains = 10
green color trucks = 2
the number of trains = 12
12 = 10 + 2
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
2 = 1 + 1
12 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1+ 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.2-05

Understand 11 and 12 Homework & Practice 8.3

Directions:
1 Circle 10 trucks. Draw dots in the ten frame to show how many trucks are circled. Draw dots in the five frame to show how many more trucks there are. Use the frames to write an addition sentence.

Question 1.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.3 6

Answer:
The number of cars = 11.

Explanation:
Given that, there are 11 cars in the figure.
circle 10 vehicles.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
11 = 10 + 1
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
1 = 1
11 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.3-011

Directions:
2 Circle 10 bicycles. Draw dots in the ten frame to show how many bicycles are circled. Draw dots in the five frame to show how many more bicycles there are. Use the frames to write an addition sentence. 3 You have red cars. Your friend has blue cars. Circle your cars. Write an addition sentence to match your picture. How many cars does your friend have? Circle the number.

Question 2.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.3 7
Answer:
The number of bicycles = 12.

Explanation:
Given that, there are 12 bicycles in the figure.
circle 10 bicycles.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
12 = 10 + 2
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
2 = 1 + 1
12 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.3-012

Question 3.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.3 8

Answer:
a. The number of cars = 12
blue color cars = 2
red color cars = 10

Explanation:
Given that, there are 12 cars in the figure.
circle 10 cars.
blue color cars = 2
red color cars = 10
the number of carss = 12
12 = 10 + 2
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
2 = 1 + 1
12 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1+ 1 + 1

Lesson 8.4 Count and Write 13 and 14

Explore and Grow

Directions:
Place a linking cube on each carrot. Slide cubes to fill the ten frame. Slide the extra cubes to the five frame.

Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.4 1

Answer:
The number of carrots = 13.

Explanation:
Given that, there are 13 carrots in the figure.
circle 13 carrots.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
13 = 10 + 3
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
3 = 1 + 1 + 1
13 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.4-01

Think and Grow

Directions:

  • Count the vegetables. Say the number. Trace and write the number.
  • Count the vegetables. Say the number. Write the number.

Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.4 2

Answer:
a. The number of chilies = 13.
b. The number of capsicums = 14.

Explanation:
Given that, count the fruit.
chillies = 13
capsicums = 14
13 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
14 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.3-2

Apply and Grow: Practice

Directions:
1 – 4 Count the objects. Say the number. Write the number.

Question 1.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.4 3

Answer:
The number of objects = 13.

Explanation:
Given that, count the objects.
there are 13 objects.
The number of objects = 13.
13 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.3-3

Question 2.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.4 4

Answer:
The number of objects = 14.

Explanation:
Given that, count the objects.
there are 14 objects.
The number of objects = 14.
14 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1+ 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.3-4

Question 3.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.4 5

Answer:
The number of objects = 13.

Explanation:
Given that, count the objects.
there are 13 objects.
The number of objects = 13.
13 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.3-5

Question 4.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.4 6

Answer:
The number of objects = 14.

Explanation:
Given that, count the objects.
there are 14 objects.
The number of objects = 14.
14 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.3-6

Think and Grow: Modeling Real Life

Directions:
A store has 14 cucumbers and 13 ears of corn in the bins. Draw the cucumbers and the ears of corn. Then write the numbers.

Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.4 7

Answer:
The number of cucumbers = 14.
The number of corns = 13.

Explanation:
Given that, there are 14 cucumbers in the bins.
there are 13 corns in the bin.
The number of cucumbers = 12.
The number of corns = 13
13 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
14 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.3-7

Count and Write 13 and 14 Homework & Practice 8.4

Directions:
1 and 2 Count the objects. Say the number. Write the number.

Question 1.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.4 8

Answer:
The number of objects = 14.

Explanation:
Given that, count the objects.
there are 14 objects.
The number of objects = 14.
14 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.3-8

Question 2.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.4 9

Answer:
The number of objects = 13.

Explanation:
Given that, count the objects.
there are 13 objects.
The number of objects = 13.
13 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.3-9

Directions:
3 and 4 Count the vegetables. Say the number. Write the number. 5 Draw 14 heads of lettuce in the dirt. Write the number.

Question 3.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.4 10

Answer:
The number of objects = 12.

Explanation:
Given that, count the objects.
there are 12 objects.
The number of objects = 12.
12 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.3-10

Question 4.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.4 11

Answer:
The number of objects = 13.

Explanation:
Given that, count the objects.
there are 13 objects.
The number of objects = 13.
13 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.3-11

Question 5.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.4 12

Answer:
The number of objects = 14.

Explanation:
Given that, draw the 14 heads of lettuce in the dirt.
there are 14 objects.
The number of objects = 14.
14 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.3-12

Lesson 8.5 Understand 13 and 14

Explore and Grow

Directions:
Place the 10 and 3 cards as the parts on the number bond. Slide the cards and hide the zero with the 3 card to make the whole. Write the parts and the whole.

Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.5 1

Answer:
10 + 3 = 13
The whole = 13

Explanation:
Given that, place the 10 and 3 cards as the parts on the number bond.
slide the cards and hide the zero with the one card to make the whole.
10 + 3 = 13
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
3 = 1 + 1 + 1
whole = 13
13 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.4-1

Think and Grow

Directions:
Circle 10 objects. Draw dots in the ten frame to show how many objects are circled. Draw dots in the five frame to show how many more objects there are. Use the frames to write an addition sentence.

Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.5 2

Answer:
The number of caps = 14

Explanation:
Given that, there are 14 caps in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
14 = 10 + 4
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
4 = 1 + 1 + 1 + 1
14 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1 + 1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.5-01

Apply and Grow: Practice

Directions:
1 and 2 Circle 10 hats. Draw dots in the ten frame to show how many hats are circled. Draw dots in the five frame to show how many more hats there are. Use the frames to write an addition sentence.

Question 1.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.5 3

Answer:
The number of caps = 13

Explanation:
Given that, there are 13 caps in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
13 = 10 + 3
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
3 = 1 + 1 + 1
13 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.5-02

Question 2.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.5 4

Answer:
The number of caps = 14

Explanation:
Given that, there are 14 caps in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
14 = 10 + 4
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
4 = 1 + 1 + 1 + 1
14 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.5-03

Think and Grow: Modeling Real Life

Directions:

  • You have striped party hats. Your friend has polka-dot party hats. Circle your hats. Write an addition sentence to match the picture. How many hats do you and your friend have in all? Circle the number.
  • You have red party hats. Your friend has blue party hats. Circle your hats. Write an addition sentence to match the picture. How many hats do you have? Circle the number.

Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.5 5

Answer:
a. The number of hats = 14
mixed color hats = 10
yellow color hats = 4
b. The number of red color = 10
blue color = 3

Explanation:
Given that, there are 14 trucks in the figure.
circle 10 trucks.
mixed color hats = 10
yellow color hats = 4
the number of hats = 14
14 = 10 + 4
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
4 = 1 + 1 + 1 + 1
14 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1+ 1 + 1 + 1
b. The number of hats = 13
blue color hats = 3
red color hats = 10
Given that, there are 13 hats in the figure.
circle 10 hats.
blue color hatss = 3
red color hats = 10
the number of hats = 13
13 = 10 + 3
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
3 = 1 + 1 + 1
13 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1+ 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.5-04

Understand 13 and 14 Homework & Practice 8.5

Directions:
1 Circle 10 hats. Draw dots in the ten frame to show how many hats are circled. Draw dots in the five frame to show how many more hats there are. Use the frames to write an addition sentence.

Question 1.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.5 6

Answer:
The number of caps = 13

Explanation:
Given that, there are 13 caps in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
13 = 10 + 3
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
3 = 1 + 1 + 1
13 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.5-02

 

Directions:
2 Circle 10 hats. Draw dots in the ten frame to show how many hats are circled. Draw dots in the five frame to show how many more hats there are. Use the frames to write an addition sentence. 3 You have green party hats. Your friend has purple party hats. Circle your hats. Write an addition sentence to match the picture. How many hats do you have? Circle the number.

Question 2.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.5 7

Answer:
The number of caps = 14

Explanation:
Given that, there are 14 caps in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 4 frames to show how many more objects there are.
14 = 10 + 4
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
4 = 1 + 1 + 1 + 1
14 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1 + 1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.5-03

Question 3.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.5 8

Answer:
The number of hats = 14
blue color hats = 4
green color hats = 10
Given that, there are 13 hats in the figure.
circle 10 hats.
blue color hats = 4
green color hats = 10
the number of hats = 14
14 = 10 + 4
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
4 = 1 + 1 + 1 + 1
14 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1+ 1 + 1 + 1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.5-005

Lesson 8.6 Count and Write 15

Explore and Grow

Directions:
Place a linking cube on each dolphin. Slide cubes to fill the top ten frame. Slide the extra cubes to the bottom ten frame.

Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.6 1

Answer:
The number of objects = 15.

Explanation:
Given that, there are 15 objects in the figure.
circle 15 carrots.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
15 = 10 + 5
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
5 = 1 + 1 + 1+ 1 + 1
15 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1 + 1 + 1

Think and Grow

Directions:

  • Count the fish. Say the number. Trace and write the number.
  • Count the fish. Say the number. Write the number.

Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.6 2

Answer:
a. The number of fishes = 15.

Explanation:
Given that, count the objects.
there are 15 objects.
The number of fishes = 15.
15 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1+ 1 +1
b. The number of fishes = 15.
Given that, count the objects.
there are 15 objects.
The number of fishes = 15.
15 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1+ 1 +1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.4-2

Apply and Grow: Practice

Directions:
1 – 4 Count the objects. Say the number. Write the number.

Question 1.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.6 3

Answer:
The number of objects = 15.

Explanation:
Given that, count the objects.
there are 15 objects.
The number of fishes = 15.
15 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1+ 1 +1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.4-3

Question 2.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.6 4

Answer:
The number of objects = 13.

Explanation:
Given that, count the objects.
there are 13 objects.
The number of fishes = 13.
13 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1

Question 3.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.6 5

Answer:
The number of objects = 15.

Explanation:
Given that, count the objects.
there are 15 objects.
The number of fishes = 15.
15 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1+ 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.4-5

Question 4.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.6 6

Answer:
The number of objects = 15.

Explanation:
Given that, count the objects.
there are 15 objects.
The number of fishes = 15.
15 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1+ 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.4-6
Think and Grow: Modeling Real Life

Directions:
11 blue fish swim near the top of the water. 15 red fish swim near the shipwreck. Draw the fish. Then write the numbers.

Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.6 7

Answer:
The number of fishes = 26
blue color fishes = 11
red color fishes = 15

Explanation:
Given that, there are 11 trucks in the figure.
blue color fishess = 10
red color fishes = 15
the number of blue color fishes = 11
the number of red color fishes = 15
11 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1
15 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1 + 1+ 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.4-7
Count and Write 15 Homework & Practice 8.6

Directions:
1 and 2 Count the objects. Say the number. Write the number.

Question 1.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.6 8

Answer:
The number of objects = 15.

Explanation:
Given that, count the objects.
there are 15 objects.
The number of fishes = 15.
15 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.4-8

Question 2.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.6 9

Answer:
The number of objects = 13.

Explanation:
Given that, count the objects.
there are 13 objects.
The number of objects = 13.
13 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.4-9

Directions:
3 and 4 Count the sea creatures. Say the number. Write the number. 5 Draw 15 bubbles in the water. Write the number.

Question 3.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.6 10

Answer:
The number of objects = 11.

Explanation:
Given that, count the objects.
there are 11 objects.
The number of objects = 11.
11 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.4-10

Question 4.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.6 11

Answer:
The number of objects = 15.

Explanation:
Given that, count the objects.
there are 15 objects.
The number of objects = 15.
15 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.4-11

Question 5.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.6 12

Answer:
The number of bubbles = 15.

Explanation:
Given that, count the objects.
there are 15 objects.
The number of objects = 15.
15 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.4-12

Lesson 8.7 Understand 15

Explore and Grow

Directions:
Place the 10and 5 cards as the parts on the number bond. Slide the cards and hide the zero with the 5 card to make the whole. Write the parts and the whole.

Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.7 1

Answer:
The number of cards = 15

Explanation:
Given that, there are 15 caps in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
15 = 10 + 5
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
5 = 1 + 1 + 1 + 1 + 1
15 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.7-01

Think and Grow

Directions:
Circle 10 objects. Draw dots in the top ten frame to show how many objects are circled. Draw dots in the bottom ten frame to show how many more objects there are. Use the ten frames to write an addition sentence.

Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.7 2

Answer:

The number of objects = 15

Explanation:
Given that, there are 15 caps in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
15 = 10 + 5
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
5 = 1 + 1 + 1 + 1 + 1
15 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+ 1+1 + 1 + 1

Apply and Grow: Practice

Directions:
1 and 2 Circle 10owers. Draw dots in the top ten frame to show how many flowers are circled. Draw dots in the bottom ten frame to show how many more flowers there are. Use the ten frames to write an addition sentence.

Question 1.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.7 3

Answer:
The number of objects = 15

Explanation:
Given that, there are 15 caps in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
15 = 10 + 5
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
5 = 1 + 1 + 1 + 1 + 1
15 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+ 1+1 + 1 + 1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.5-007

Question 2.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.7 4

Answer:
The number of objects = 15

Explanation:
Given that, there are 15 caps in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
15 = 10 + 5
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
5 = 1 + 1 + 1 + 1 + 1
15 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+ 1+1 + 1 + 1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.5-008

Think and Grow: Modeling Real Life

Directions:

  • You have pink flowers. Your friend has yellow flowers. Circle your flowers. Write an addition sentence to match the picture. How many flowers does your friend have? Circle the number.
  • You have blue flowers. Your friend has orange flowers. Circle your flowers. Write an addition sentence to match the picture. How many flowers do you and your friend have in all? Circle the number.

Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.7 5

Answer:
a. The number of flowers = 15
pink color flowers = 10
yellow color flowers = 5
b. The number of red color = 4
blue color = 10

Explanation:
Given that, there are 15 figures in the figure.
circle 10 flowers.
pink color hats = 10
yellow color hats = 5
the number of hats = 15
15 = 10 + 5
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
5 = 1 + 1 + 1 + 1+ 1
15 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1+ 1 + 1 + 1 + 1
b. The number of flowers = 13
blue color flowers = 10
red color flowers = 4
Given that, there are 14 flowers in the figure.
circle 10 flowers.
blue color flowers = 4
red color flowers = 10
the number of flowers = 14
14 = 10 + 4
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
4 = 1 + 1 + 1+ 1
14 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1+ 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.5-009

Understand 15 Homework & Practice 8.7

Directions:
1 Circle 10 flowers. Draw dots in the top ten frame to show how many flowers are circled. Draw dots in the bottom ten frame to show how many more flowers there are. Use the ten frames to write an addition sentence.

Question 1.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.7 6

Answer:
The number of objects = 15

Explanation:
Given that, there are 15 caps in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
15 = 10 + 5
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
5 = 1 + 1 + 1 + 1 + 1
15 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+ 1+1 + 1 + 1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.5-0010

Directions:
2 Circle 10 flowers. Draw dots in the top ten frame to show how many flowers are circled. Draw dots in the bottom ten frame to show how many more flowers there are. Use the ten frames to write an addition sentence. 3 You have yellow flowers. Your friend has red flowers. Circle your flowers. Write an addition sentence to match the picture. How many flowers do you and your friend have in all? Circle the number.

Question 2.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.7 7

Answer:
The number of objects = 14

Explanation:
Given that, there are 14 flowers in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
14 = 10 + 4
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
4 = 1 + 1 + 1 + 1
14 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+ 1+1 + 1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.5-0011

Question 3.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.7 8

Answer:
The number of flowers = 15
yellow color flowers = 10
red color flowers = 5
Given that, there are 15 flowers in the figure.
circle 10 flowers.
yellow color flowers = 10
red color flowers = 5
the number of flowers = 15
15 = 10 + 5
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
5 = 1 + 1 + 1+ 1 + 1
15 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1+ 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.5-0012

Lesson 8.8 Count and Write 16 and 17

Explore and Grow

Directions:
Place a linking cube on each football. Slide cubes to fill the top ten frame. Slide the extra cubes to the bottom ten frames.

Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.8 1

Answer:
The number of objects = 16.

Explanation:
Given that, there are 16 objects in the figure.
circle 16 carrots.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
16 = 10 + 6
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
6 = 1 + 1 + 1+ 1 + 1 + 1
16 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.8-01

Think and Grow

Directions:

  • Count the objects. Say the number. Trace and write the number.
  • Count the objects. Say the number. Write the number.

Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.8 2

Answer:
a.The number of objects = 17.

Explanation:
Given that, count the objects.
there are 17 objects.
The number of objects = 17.
17 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
b.The number of objects = 16.
Given that, count the objects.
there are 16 objects.
The number of objects = 16.
16 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1+ 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.7-02

Apply and Grow: Practice

Directions:
1 – 4 Count the objects. Say the number. Write the number.

Question 1.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.8 3

Answer:
The number of objects = 16.

Explanation:
Given that, count the objects.
there are 16 objects.
The number of objects = 16.
16 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1+ 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.7-03

Question 2.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.8 4

Answer:
The number of objects = 17.

Explanation:
Given that, count the objects.
there are 17 objects.
The number of objects = 17.
17 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1+ 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.7-04

Question 3.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.8 5

Answer:
The number of objects = 17.

Explanation:
Given that, count the objects.
there are 17 objects.
The number of objects = 17.
17 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1+ 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.7-05

Question 4.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.8 6

Answer:
The number of objects = 16.

Explanation:
Given that, count the objects.
there are 16 objects.
The number of objects = 16.
16 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1+ 1 + 1 + 1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.7-06

Think and Grow: Modeling Real Life

Directions:
There are 17 blocks on the floor and 16 books on the shelves. Draw the blocks and the books. Then write the numbers.

Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.8 7

Answer:
The number of blocks = 17
The number of books = 16

Explanation:
Given that, there are 17 blocks on the floor and 16 books on the shelves.
the number of blocks = 17
the number of books = 16
16 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
17 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.7-07

Count and Write 16 and 17 Homework & Practice 8.8

Directions:
1 and 2 Count the objects. Say the number. Write the number.

Question 1.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.8 8

Answer:
The number of objects = 16.

Explanation:
Given that, count the objects.
there are 16 objects.
The number of objects = 16.
16 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1+ 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.7-03

Question 2.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.8 9

Answer:
The number of objects = 17.

Explanation:
Given that, count the objects.
there are 17 objects.
The number of objects = 17.
17 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1+ 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.8-02
Directions:
3 and 4 Count the objects. Say the number. Write the number. 5 Draw 17 balls on the ball rack. Write the number.

Question 3.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.8 10

Answer:
The number of objects = 16.

Explanation:
Given that, count the objects.
there are 16 objects.
The number of objects = 16.
16 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1+ 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.8-03

Question 4.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.8 11

Answer:
The number of objects = 14.

Explanation:
Given that, count the objects.
there are 14 objects.
The number of objects = 14.
14 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1+ 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.8-04

Question 5.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.8 12

Answer:
The number of objects = 17.

Explanation:
Given that, count the objects.
there are 17 objects.
The number of objects = 17.
17 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1+ 1+ 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.8-05

Lesson 8.9 Understand 16 and 17

Explore and Grow

Directions:
Place the 10and 6 cards as the parts on the number bond. Slide the cards and hide the zero with the 6 card to make the whole. Write the parts and the whole.

Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.9 1

Answer:
The number of cards = 16

Explanation:
Given that, there are 16 caps in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 6 frames to show how many more objects there are.
16 = 10 + 6
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
6 = 1 + 1 + 1 + 1 + 1 + 1
16 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.9-01

Think and Grow

Directions:
Circle 10 objects. Draw dots in the top ten frame to show how many objects are circled. Draw dots in the bottom ten frame to show how many more objects there are. Use the ten frames to write an addition sentence.

Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.9 2

Answer:
The number of cards = 17

Explanation:
Given that, there are 17 caps in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 7 frames to show how many more objects there are.
17 = 10 + 7
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
7 = 1 + 1 + 1 + 1 + 1 + 1 + 1
17 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.8-02

Apply and Grow: Practice

Directions:
1 and 2 Circle 10 objects. Draw dots in the top ten frame to show how many objects are circled. Draw dots in the bottom ten frame to show how many more objects there are. Use the ten frames to write an addition sentence.

Question 1.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.9 3

Answer:
The number of cards = 16

Explanation:
Given that, there are 16 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 6 frames to show how many more objects there are.
16 = 10 + 6
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
6 = 1 + 1 + 1 + 1 + 1 + 1
16 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.8-03

Question 2.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.9 4

Answer:
The number of cards = 17

Explanation:
Given that, there are 17 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 7 frames to show how many more objects there are.
17 = 10 + 7
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
7 = 1 + 1 + 1 + 1 + 1 + 1 + 1
17 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1 + 1 + 1 + 1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.9-01

Think and Grow: Modeling Real Life

Directions:

  • You put yellow stickers on a page. Your friend puts red stickers on the same page. Circle your stickers. Write an addition sentence to match the picture. How many stickers does your friend put on the page? Circle the number.
  • You put blue stickers on a page. Your friend puts green stickers on the same page. Circle your stickers. Write an addition sentence to match the picture. How many stickers does your friend put on the page? Circle the number.

Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.9 5

Answer:
a. The number of stickers = 16
red color stickers = 6
yellow color stickers = 10
b. The number of green color = 7
blue color = 10

Explanation:
Given that, there are 16 figures in the figure.
circle 10 stickers..
red color stickers= 6
yellow color sickers= 10
the number of stickers = 16
16 = 10 + 6
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
6 = 1 + 1 + 1 + 1+ 1+ 1
16 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1+ 1 + 1 + 1 + 1 + 1
b. The number of stickers = 17
blue color stickers = 10
green color stickers = 7
Given that, there are 17 flowers in the figure.
circle 10 stickerss.
blue color stickerss = 4
green color flowers = 7
the number of flowers = 10
17 = 10 + 7
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
7 = 1 + 1 + 1+ 1 + 1 + 1 + 1
17 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1+ 1 + 1 + 1

Understand 16 and 17 Homework & Practice 8.9

Directions:
1 Circle 10 stars. Draw dots in the top ten frame to show how many stars are circled. Draw dots in the bottom ten frame to show how many more stars there are. Use the ten frames to write an addition sentence.

Question 1.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.9 6

Answer:
The number of stars = 16

Explanation:
Given that, there are 16 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 6 frames to show how many more objects there are.
16 = 10 + 6
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
6 = 1 + 1 + 1 + 1 + 1 + 1
16 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.9-03

Directions:
2 Circle 10 butterflies. Draw dots in the top ten frame to show how many butterflies are circled. Draw dots in the bottom ten frame to show how many more butterflies there are. Use the ten frames to write an addition sentence. 3 You put orange stickers on a page. Your friend puts blue stickers on the next page. Circle your stickers. Write an addition sentence to match the picture. How many stickers does your friend put on the next page? Circle the number.

Question 2.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.9 7

Answer:
The number of butterflies = 16

Explanation:
Given that, there are 16 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 6 frames to show how many more objects there are.
16 = 10 + 6
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
6 = 1 + 1 + 1 + 1 + 1 + 1
16 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.9-04

Question 3.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 8.9 8

Answer:
The number of stickers = 17
yellow color stickers = 10
blue color flowers = 7

Explanation:
Given that, there are 17 stickers in the figure.
circle 10 stickers.
yellow color stickers = 10
blue color stickers = 7
the number of stickers = 17
17 = 10 + 7
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
7 = 1 + 1 + 1+ 1 + 1 + 1 + 1

Lesson 8.10 Count and Write 18 and 19

Explore and Grow

Directions:
Place a linking cube on each leaf. Slide cubes to fill the top ten frame. Slide the extra cubes to the bottom ten frame.

Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.10 1

Answer:
The number of objects = 18.

Explanation:
Given that, there are 18 objects in the figure.
circle 18 carrots.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
18 = 10 + 8
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
8 = 1 + 1 + 1+ 1 + 1 + 1+ 1 + 1
18 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.9-05

Think and Grow

Directions:

  • Count the objects. Say the number. Trace and write the number.
  • Count the objects. Say the number. Write the number.

Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.10 2

Answer:
a.The number of objects = 19.
b. The number of objects = 18.

Explanation:
Given that, count the objects.
there are 19 objects.
The number of objects = 19.
19 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1.
b.The number of objects = 18.
Given that, count the objects.
there are 18 objects.
The number of objects = 18.
18 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1+ 1 + 1 + 1.
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.10-01

Apply and Grow: Practice

Directions:
1 – 4 Count the objects. Say the number. Write the number.

Question 1.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.10 3

Answer:
The number of objects = 18.

Explanation:
Given that, count the objects.
there are 18 objects.
The number of objects = 18.
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
8 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.10-02

Question 2.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.10 4

Answer:
The number of objects = 18.

Explanation:
Given that, count the objects.
there are 18 objects.
The number of objects = 18.
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
8 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.10-03

Question 3.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.10 5

Answer:
The number of objects = 19.

Explanation:
Given that, count the objects.
there are 19 objects.
The number of objects = 19
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
9 = 1 + 1 + 1 + 1 + 1 + 1 +1

Question 4.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.10 6

Answer:
The number of objects = 19.

Explanation:
Given that, count the objects.
there are 19 objects.
The number of objects = 19
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
9 = 1 + 1 + 1 + 1 + 1 + 1 +1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.10-04

Think and Grow: Modeling Real Life

Directions:
There are 19 red leaves on the ground. There are 18 orange leaves left on the tree. Draw the leaves on the ground and the leaves on the tree. Write the numbers.

Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.10 7

Answer:
The number of red  leaves = 19
The number of green leaves = 18
green color leaves = 18
red color leaves = 19

Explanation:
Given that, there are 18 , 19trucks in the figure.
green color leaves = 18
red color leaves = 19
the number of green color leaves= 18
the number of red color leaves = 19
18 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
19 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1 + 1+ 1 + 1 + 1 + 1 +1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.10-05

Count and Write 18 and 19 Homework & Practice 8.10

Directions:
1 and 2 Count the objects. Say the number. Write the number.

Question 1.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.10 8

Answer:
The number of objects = 19.

Explanation:
Given that, count the objects.
there are 19 objects.
The number of objects = 19.
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
9 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.10-06

Question 2.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.10 9

Answer:
The number of objects = 18.

Explanation:
Given that, count the objects.
there are 18 objects.
The number of objects = 18.
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
8 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.10-03

Directions:
3 and 4 Count the objects. Say the number. Write the number. 5 Draw 18 acorns on the ground. Write the number.

Question 3.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.10 10

Answer:
The number of objects = 19.

Explanation:
Given that, count the objects.
there are 19 objects.
The number of objects = 19.
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
9 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.10-07

Question 4.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.10 11

Answer:
The number of objects = 17.

Explanation:
Given that, count the objects.
there are 17 objects.
The number of objects = 17.
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
7 = 1 + 1 + 1 + 1 + 1 + 1 + 1

Question 5.
Big Ideas Math Answer Key Grade K Chapter 8 Represent Numbers 11 to 19 8.10 12

Answer:
The number of objects = 18.

Explanation:
Given that, count the objects.
there are 18 objects.
The number of objects = 18.
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
8 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1

Lesson 8.11 Understand 18 and 19

Explore and Grow

Directions:
Place the 10 and 8 cards as the parts on the number bond. Slide the cards and hide the zero with the 8 card to make the whole. Write the parts and the whole.

Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.11 1

Answer:
The number of cards = 18

Explanation:
Given that, there are 18 caps in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 8 frames to show how many more objects there are.
18 = 10 + 8
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
8 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
18 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.11-1

Think and Grow

Directions:
Circle 10 objects. Draw dots in the top ten frame to show how many objects are circled. Draw dots in the bottom ten frame to show how many more objects there are. Use the ten frames to write an addition sentence.

Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.11 2

Answer:
The number of object = 19

Explanation:
Given that, there are 19 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 9 frames to show how many more objects there are.
19 = 10 + 9
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
9 = 1 + 1 + 1 + 1 + 1 + 1  + 1 + 1 + 1
19 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1 + 1 + 1 +1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.10-01

Apply and Grow: Practice

Directions:
1 and 2 Circle 10 gemstones. Draw dots in the top ten frame to show how many gemstones are circled. Draw dots in the bottom ten frame to show how many more gemstones there are. Use the ten frames to write an addition sentence.

Question 1.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.11 3

Answer:
The number of objects= 18.

Explanation:
Given that, there are 18 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 8 frames to show how many more objects there are.
18 = 10 + 8
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
8 = 1 + 1 + 1 + 1 + 1 + 1  + 1 + 1
18 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1 + 1 + 1 +1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.10-01

Question 2.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.11 4

Answer:
The number of objects= 19.

Explanation:
Given that, there are 19 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 9 frames to show how many more objects there are.
19 = 10 + 9
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
9 = 1 + 1 + 1 + 1 + 1 + 1  + 1 + 1 + 1
19 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1 + 1 + 1 +1 + 1 + 1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.10-02

Think and Grow: Modeling Real Life

Directions:

  • You have pink gemstones and blue gemstones. Your friend has silver gemstones and gold gemstones. Circle your gemstones. Write an addition sentence to match the picture. How many gemstones do you have? Circle the number.
  • You have gold gemstones and silver gemstones. Your friend has purple gemstones and green gemstones. Circle your gemstones. Write an addition sentence to match the picture. How many gemstones does your friend have? Circle the number.

Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.11 5

Answer:
a. The number of objects = 19
pink  and blue color flowers = 10
yellow and silver color flowers = 9
b.The number of objects = 18
The number of gold and silver color = 10
blue and green  color = 8

Explanation:
Given that, there are 15 figures in the figure.
circle 10 flowers.
pink color hats = 19
yellow color hats = 9
the number of hats = 10
19 = 10 + 9
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
9 = 1 + 1 + 1 + 1+ 1 + 1 + 1 + 1 + 1
19 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1+ 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
b. The number of flowers = 18
blue color flowers = 10
red color flowers = 8
Given that, there are 18 flowers in the figure.
circle 10 flowers.
pink color hats = 18
yellow color hats = 8
the number of hats = 10
18 = 10 + 8
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
8 = 1 + 1 + 1 + 1+ 1 + 1 + 1 + 1
18 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1+ 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.11-01

Understand 18 and 19 Homework & Practice 8.11

Directions:
1 Circle 10 gemstones. Draw dots in the ten frame to show how many gemstones are circled. Draw dots in the bottom ten frame to show how many more gemstones there are. Use the ten frames to write an addition sentence.

Question 1.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.11 6

Answer:
The number of objects= 18.

Explanation:
Given that, there are 18 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 8 frames to show how many more objects there are.
18 = 10 + 8
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
8 = 1 + 1 + 1 + 1 + 1 + 1  + 1 + 1 + 1
18 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1 + 1 + 1 +1 + 1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.10-02

Directions:
2 Circle 10 gemstones. Draw dots in the top ten frame to show how many gemstones are circled. Draw dots in the bottom ten frame to show how many more gemstones there are. Use the ten frames to write an addition sentence. 3 You have red gemstones and blue gemstones. Your friend has yellow gemstones and silver gemstones. Circle your gemstones. Write an addition sentence to match the picture. How many gemstones does your friend have? Circle the number.

Question 2.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.11 7

Answer:
The number of objects= 18.

Explanation:
Given that, there are 18 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 8 frames to show how many more objects there are.
18 = 10 + 8
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
8 = 1 + 1 + 1 + 1 + 1 + 1  + 1 + 1 + 1
18 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1 + 1 + 1 +1 +
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.11-02

Question 3.
Big Ideas Math Answers Grade K Chapter 8 Represent Numbers 11 to 19 8.11 8

Answer:
The number of objects= 19.

Explanation:
Given that, there are 19 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 9 frames to show how many more objects there are.
19 = 10 + 9
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
9 = 1 + 1 + 1 + 1 + 1 + 1  + 1 + 1 + 1+ 1
19 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1 + 1 + 1 +1 +1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.11-03

Represent Numbers 11 to 19 Performance Task

Directions:
1 Classify the stars into 2 categories. Circle to show each group. Then write an addition sentence to tell how many stars there are in all. 2 There are red stars and blue stars in the sky. The number of red stars is 1 more than 9. The number of blue stars is greater than 5, but less than the number of red stars. Draw and color the stars. Then write an addition sentence to tell how many stars there are in all.

Question 1.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 1

Answer:
The number of objects= 15.

Explanation:
Given that, there are 15 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
15 = 10 + 5
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
5 = 1 + 1 + 1 + 1 + 1
15 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.11-04

Question 2.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 2
Answer:
The number of objects= 18.

Explanation:
Given that, there are 18 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 8 frames to show how many more objects there are.
18 = 10 + 8
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
8 = 1 + 1 + 1 + 1 + 1 + 1  + 1 + 1 + 1
18 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1 + 1 + 1 + 1 +1 +

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.11-05

Represent Numbers 11 to 19 Activity

Number Flip and Find
Directions:
Place the Number Flip and Find Cards face down in the boxes. Take turns flipping 2 cards. If your cards show the same number, keep the cards. If your cards show different numbers, flip the cards back over. Repeat this until all cards are gone.

Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 3

Represent Numbers 11 to 19 Chapter Practice

Directions:
1 and 2 Circle 10 objects. Tell how many more objects there are. Then write the numbers.

8.1 Identify Groups of 10

Question 1.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 chp 1

Answer:
The number of objects = 16.

Explanation:
Given that, circle the objects.
there are 16 objects.
The number of objects = 16.
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
6 = 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.11-06

Question 2.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 chp 2

Answer:
The number of objects = 13.

Explanation:
Given that, circle the objects.
there are 13 objects.
The number of objects = 13.
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
3 = 1 + 1 + 1

Directions:
3 and 4 Count the fruit. Say the number. Write the number. Circle 10 buses. Draw dots in the ten frame to show how many buses are circled. Draw dots in the five frame to show how many more buses there are. Use the frames to write an addition sentence.

8.2 Count and Write 11 and 12

Question 3.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 chp 3

Answer:
The number of objects= 12.

Explanation:
Given that, there are 12 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 2 frames to show how many more objects there are.
12 = 10 + 2
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
2 = 1 + 1
12 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1+1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.11-2

Question 4.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 chp 4

Answer:
The number of objects= 11.

Explanation:
Given that, there are 11 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 1 frames to show how many more objects there are.
11 = 10 + 1
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
1 = 1
11 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.11-3

8.3 Understand 11 and 12

Question 5.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 chp 5

Answer:
The number of objects= 12.

Explanation:
Given that, there are 12 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 2 frames to show how many more objects there are.
12 = 10 + 2
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
2 = 1 + 1
12 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1 + 1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.3-012

Directions:
6 and 7 Count the vegetables. Say the number. Write the number. 8 Circle 10 hats. Draw dots in the ten frame to show how many hats are circled. Draw dots in the five frame to show how many more hats there are. Use the frames to write an addition sentence.

8.4 Count and Write 13 and 14

Question 6.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 chp 6

Answer:
The number of objects= 14.

Explanation:
Given that, there are 14 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 4 frames to show how many more objects there are.
14 = 10 + 4
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
4 = 1 + 1 + 1 + 1
14 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.11-4

Question 7.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 chp 7

Answer:
The number of objects= 13.

Explanation:
Given that, there are 13 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 3 frames to show how many more objects there are.
13 = 10 + 3
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
3 = 1 + 1 + 1
13 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.11-5

8.5 Understand 13 and 14

Question 8.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 chp 8

Answer:
The number of objects= 11.

Explanation:
Given that, there are 11 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 1 frame to show how many more objects there are.
11 = 10 + 1
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
1 = 1
11 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.5-02

Directions:
9 Count the fish. Say the number. Write the number. 10 Circle 10 flowers. Draw dots in the top ten frame to show how many flowers are circled. Draw dots in the bottom ten frame to show how many more flowers there are. Use the ten frames to write an addition sentence.

8.6 Count and Write 15

Question 9.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 chp 9
Answer:
The number of objects= 15.

Explanation:
Given that, there are 15 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
15 = 10 + 5
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
5 = 1 + 1 + 1 + 1 + 1
15 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.5-0012

8.7 Understand 15

Question 10.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 chp 10

Answer:
The number of objects= 15.

Explanation:
Given that, there are 15 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 5 frames to show how many more objects there are.
15 = 10 + 5
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
5 = 1 + 1 + 1 + 1 + 1
15 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.11-08

Directions:
11 Count the yo-yos. Say the number. Write the number. 12 Circle 10 stickers. Draw dots in the top ten frame to show how many stickers are circled. Draw dots in the bottom ten frame to show how many more stickers there are. Use the ten frames to write an addition sentence.

8.8 Count and Write 16 and 17

Question 11.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 chp 11

Answer:
The number of objects = 16.

Explanation:
Given that, count the objects.
there are 16 objects.
The number of objects = 16.
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
6 = 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.11-7

8.9 Understand 16 and 17

Question 12.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 chp 12

Answer:
The number of objects= 17.

Explanation:
Given that, there are 17 objects in the figure.
circle 10 objects.
draw dots in 10 frames to show how many objects are circled.
draw dots in 7 frames to show how many more objects there are.
17 = 10 + 7
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
7 = 1 + 1 + 1 + 1 + 1 + 1 + 1
17 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1

Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.11-09

Directions:
13 Count the leaves. Say the number. Write the number. 14 You have blue gemstones and orange gemstones. Your friend has purple gemstones and green gemstones. Circle your gemstones. Write an addition sentence to match the picture. How many gemstones do you and your friend have in all? Circle the number.

8.10 Count and Write 18 and 19

Question 13.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 chp 13

Answer:
The number of objects = 19.

Explanation:
Given that, circle the objects.
there are 19 objects.
The number of objects = 19.
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
9 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.11-6

8.11 Understand 18 and 19

Question 14.
Big Ideas Math Solutions Grade K Chapter 8 Represent Numbers 11 to 19 chp 14

Answer:
The number of gemstones = 18
red color stickers = 3
sky blue color stickers = 7
The number of green color = 2
blue color = 6

Explanation:
Given that, there are 18 figures in the figure.
circle 10 stickers..
red  and skyblue color stickers= 10
green and blue color sickers= 8
the number of gemstones = 18
18 = 10 + 8
10 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1
8 = 1 + 1 + 1 + 1+ 1+ 1 + 1 + 1
18 = 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 +1 + 1+ 1 + 1 + 1 + 1 + 1 + 1 + 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-8-Represent Numbers 11 to 19-8.11-07

Conclusion:

Score top in the exams by referring Big Ideas Math Book Grade K Answer Key Chapter 8 Represent Numbers 11 to 19. The solutions seen in Big Ideas Math Grade K Chapter 8 Represent Numbers 11 to 19 are prepared by the math experts. First, you have to understand the concepts and then solve the problems. Stay tuned to our site to get the Answer Key for all Big Ideas Math Grade K Chapters from 1 to 13.

Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids

Big Ideas Math Answers Grade 8 Chapter 10

Big Ideas Math Answers 8th Grade Ch 10 Volume and Similar Solids helps you to have strong fundamentals of concepts underlying. Learn the associated lessons of Volume and Similar Solids easily and quickly taking the help of the BIM Book Grade 8 Chapter 10 Answers. All the Big Ideas Math Grade 8 Answers Chapter 10 Concepts are sequenced as per the BIM Textbooks. Resolve all your queries taking the help of the Step by Step Solutions provided for Big Ideas Math 8th Grade Questions and attempt the exam with utmost confidence.

Big Ideas Math Book 8th Grade Answer Key Chapter 10 Volume and Similar Solids

Big Ideas Math Book Grade 8 Answer Key Chapter 10 Volume and Similar Solids is given by subject experts after extensive research and meets the Common Core State Standards Curriculum. Refer to the below links available for BIM Textbook 8th Grade Ch 10 Volume and Similar Solids Solution Key and clear all your concerns in no time. Download the Volume and Similar Solids Big Ideas Math 8th Grade Answers for free of cost.

Performance Task

Lesson: 1 Volumes of Cylinders

Lesson: 2 Volumes of Cones

Lesson: 3 Volumes of Spheres

Lesson: 4 Surface Areas and Volumes of Similar Solids

Chapter: 10 – Volume and Similar Solids

Volume and Similar Solids STEAM Video/Performance Task

STEAM Video

Canning Salsa
You can estimate the volumes of ingredients to predict the total volume of a finished recipe. In what other real-life situations is it helpful to know the volumes of objects?
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 1
Watch the STEAM Video “Canning Salsa.” Then answer the following questions.
1. You can approximate the volumes of foods by comparing them to common solids. A cube of cheese has side lengths of 3 centimeters. What is the volume of the cheese?
2. The table shows the amounts x (in cubic inches) of tomato used to make y cubic inches of salsa.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 2
a. Is there a proportional relationship between x and y? Justify your answer.
b. How much tomato do you need to make 15 cubic inches of salsa?

Answer:
1. The volume of the cheese = 27 cubic centimeters.
2. a = 1: 3 relationship.
b. 5 tomatoes are used to make 15 cubic inches of salsa.

Explanation:
1. Given that a cube of cheese has a side length of 3 centimeters.
the volume of cube = s³
volume = side x side x side
volume = 3 x 3 x 3
volume = 27 cubic centimeters.
2. The relationship given in the above table is a 1: 3  ratio.
1 x 3 = 3
2 x 3 = 6
3 x 3 = 9
4 x 3 = 12.
b. The tomatoes  used to make 15 cubic inches of salsa = 5
5 x 3 = 15

Performance Task

Packaging Salsa
After completing this chapter, you will be able to use the concepts you learned to answer the questions in the STEAM Video Performance Task. You will be given the dimensions of a jar and a shipping box.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 3
You will be asked questions about how to package jars of salsa. Why is it helpful to know how many jars of salsa fit in one box?

Volume and Similar Solids Getting Ready for Chapter 10

Chapter Exploration
1. Work with a partner.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 4
a. How does the volume of the stack of dimes compare to the volume of a single dime?
b. How does the volume of the stack of nickels compare to the volume of the stack of dimes? Explain your reasoning. (The height of each stack is identical.)
c. How does the volume of each stack change when you double the number of coins?
d. LOGIC Your friend adds coins to both stacks so that the volume of the stack of dimes is greater than the volume of the stack of nickels. What can you conclude about the number of coins added to each stack? Explain your reasoning.

Vocabulary

The following vocabulary terms are defined in this chapter. Think about what each term might mean and record your thoughts.
cone
hemisphere
sphere
similar solids

Answer:
cone = A solid or hollow object which tapers from a circular or roughly circular base to a point.
hemisphere = a half of the celestial sphere as divided into two halves by the horizon.
sphere = a round solid figure, or its surface, with every point on its surface equidistant from its center.
similar solids = two solids are similar if they are the same type of solid and their corresponding radii, heights, base lengths, widths, etc. are proportional.

Lesson 10.1 Volumes of Cylinders

EXPLORATION 1

Exploring Volume
Work with a partner.
a. Each prism shown has a height of h units and bases with areas of B square units. Write a formula that you can use to find the volume of each prism.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 1
b. How can you find the volume of a prism with bases that each have 100 sides?
c. Make a conjecture about how to find the volume of a cylinder. Explain your reasoning.

Answer:
a. Volume of triangular prism = (bhl/2)
rectangular prism = lwh
pentagonal prism =(1/2)(5 s x a) h
Hexagonal prism = BH
octagonal prism = (A x H)/2
b. volume of prism = 5,00,000
c. volume of cylinder = πr² h

Explanation:
a. volume of traingular prism = (bhl/2)
where b = base, h = height, l= length.
rectangular prism = lwh
where l = length, w= width, h= height.
pentagonal prism = (1/2) x (5 s x a) h
where s = side , a= area , h= height.
hexagonal prism = BH
where b = base h = height
octagonal prism = (A X H)/2
A = area , H = height
volume of triangular prism = (bhl/2)
volume = (100 x 100 x 100/2)
volume = (100x 100 x 50)
volume = 5,00,000
volume of cylinder =πr² h
where r = radius and h = height.

EXPLORATION 2

Finding Volume Experimentally
Work with a partner. Draw a net for a cylinder. Then cut out the net and use tape to form an open cylinder. Repeat this process to form an open cube. The edge length of the cube should be greater than the diameter and the height of the cylinder.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 2
a.Use your conjecture in Exploration 1 to find the volume of the cylinder.
b. Fill the cylinder with rice. Then pour the rice into the open cube. Find the volume of rice in the cube. Does this support your answer in part(a)? Explain your reasoning.

Answer:
a. volume of cylinder = πr² h
b. we did not find the volume of rice in the cube.

Explanation:
a. volume of cylinder  = πr² h
where r = radius , h = height
b. we did not find the volume of rice in the cube because they did not give the value for the volume of rice.

Try It

Question 1.
Find the volume of a cylinder with a radius of 4 feet and a height of 15 feet. Round your answer to the nearest tenth.

Answer:
volume of cylinder =  753.6 cubic feet.

Explanation:
volume of cylinder =πr² h
where r = radius and h = height.
r = 4 feet , h = 15 feet π = 3.14 given.
v = π x 4 x 4 x 15
v = 3.14 x 16 x 15
v = 753.6 cubic feet.

Question 2.
Find the height of the cylinder at the left. Round your answer to the nearest tenth.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 3

Answer:
height of the cylinder =0.28545 cm

Explanation:
volume of cylinder =πr² h
where r = radius and h = height.
r = 4 cm , v = 176  π = 3.14 given.
176= π x 4  x 4 x h
176= 3.14 x 16 h
176 = 50.24 h
h = (50.24/176)
h = 0.28545 cm

Find the radius of the cylinder. Round your answer to the nearest tenth.
Question 3.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 4

Answer:
radius of the cylinder = 0.2242 m²

Explanation:
volume of cylinder =πr² h
where r = radius and h = height.
h = 4 m , v = 28  π = 3.14 given.
28= π x r  x r x 4
28= 3.14 x 4 r²
28 = 12.56 r²
r² = (12.56/28)
r² = 0.44857143 m⁴
r = 0.2242 m²

Question 4.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 5

Answer:
radius of the cylinder =0.01183067 mm²

Explanation:
volume of cylinder =πr² h
where r = radius and h = height.
h = 4.25mm , v = 564  π = 3.14 given.
564= π x r  x r x 4.25
564= 3.14 x 4.25 r²
564= 13.345 r²
r² = (13.345/564)
r² = 0.02366135.
r = 0.01183067 mm²

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 5.
FINDING THE VOLUME OF A CYLINDER
Find the volume of the cylinder at the left. Round your answer to the nearest tenth.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 6

Answer:
volume of cylinder = 43.96 cu yds

Explanation:
volume of cylinder = πr² h
where π = 3.14  diameter = 4 given
so radius = (d/2)
r = (4/2)
r = 2 , h = 3.5
v = 3.14 x 2 x 2 x 3.5
v = 6.28 x 2 x 3.5
v = 12.56 x 3.5
v = 43.96 cu yds

Question 6.
FINDING THE HEIGHT OF A CYLINDER
Find the height of the cylinder at the right. Round your answer to the nearest tenth.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 7

Answer:
volume of cylinder = 43.96 cu yds

Explanation:
volume of cylinder = πr² h
where π = 3.14  diameter = 4 given
so radius = (d/2)
r = (4/2)
r = 2 , h = 3.5
v = 3.14 x 2 x 2 x 3.5
v = 6.28 x 2 x 3.5
v = 12.56 x 3.5
v = 43.96 cu yds

Question 7.
DIFFERENT WORDS, SAME QUESTION
Which is different? Find “both” answers.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 8

Answer:
volume of cylinder = 942 cu cm

Explanation:
volume of cylinder = πr² h
where π = 3.14  r = 5 cm
r = 5 , h = 12 given
v = 3.14 x 5 x 5 x 12
v = 3.14 x 25 x 12
v = 78.5 x 12
v = 942 cu cm

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 8.
How much salsa is missing from the jar? Explain your reasoning.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 9

Answer:
The salsa missing from the jar = 6 cm

Explanation:
Given that the jar height = 10 cm
salsa filled is 4 cm
salsa missing from the jar = 10 – 4
salsa missing from the jar = 6 cm

Question 9.
A cylindrical swimming pool has a circumference of 18π feet and a height of 4 feet. About how many liters of water are needed to fill the swimming pool to 85% of its total volume? Justify your answer. (1 ft3 ≈ 28.3 L)
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 10

Answer:
The total amount of water needed to fill the swimming pool = 9 feet

Explanation:
No of liters of water = volume of cylinder = πr² h
h = 4 feet given,
circumference = 18 π feet given
2 πr = 18 π
π get canceled on both sides.
2r = 18
r = 9 feet

Question 10.
DIG DEEPER!
A company creates two designs for a cylindrical soup can. Can A has a diameter of 3.5 inches and a height of 3.6 inches. Can B has a height of 4.9 inches. Each can holds the same amount of soup. Which can requires less material to make? Explain your reasoning.

Answer:
can B requires less material to make.

Explanation:
volume of the cylinder = πr² h
volume of can A = πr² h
h = 3.6 in,diameter = 3.5 in given where r = (d/2)
r = (3.5/2) = 1.75 in
v = 3.14 x 1.75 x 1.75 x 3.6
v = 3.14 x 3.0625 x 3.6
v = 3.14 x 11.025
v = 34.6185 cu in
volume of can B = πr² h
h = 4.9 in,diameter = 3.5 in given where r = (d/2)
r = (3.5/2) = 1.75 in
v = 3.14 x 3.5 x 3.5 x 3.6
v = 3.14 x 12.25 x 3.6
v = 3.14 x 44.1
v = 138.474 cu in

Volumes of Cylinders Homework & Practice 10.1

Review & Refresh

Tell whether the triangle with the given side lengths is a right triangle.
Question 1.
20 m, 21 m, 29 m

Answer:
Yes, the given side lengths form a right triangle.

Explanation:
The length of any sides of right triangle = a² + b² = c²
a² + b² = c² = a² + 2b= c²
a = 20 , b = 21, c = 29
400 + 441 = 841
841 is equal to 841

Question 2.
1 in., 2.4 in., 2.6 in.

Answer:
the given side lengths is not a right triangle.

Explanation:
The length of any sides of right triangle = a² + b² = c²
a² + b² = c² = a² + 2b= c²
a = 1 , b = 2.4, c = 2.6
1+ 2.4 x 2 = 6.76
5.8 = 6.76
5.8 is not equal to 6.76

Question 3.
5.6 ft, 8 ft, 10.6 ft

Answer:
the given side lengths is not a right triangle.

Explanation:
The length of any sides of right triangle = a² + b² = c²
a² + b² = c² = a² + 2b= c²
a = 5.6 , b = 8, c = 10.6
5.6 x 5.6 + 8 x 2 = 10.6 x 10.6
31.36 + 16 = 112.36
47.36 = 112.36
47.36 is not equal to 112.36

Write the number in standard form.
Question 4.
3.9 × 106

Answer:
3.9000000

Explanation:
3.9 x 10⁶
3.9 x (10⁵ x 10⁶)
3.9 x (10 ⁵⁺⁶)
using aᵐx aᵑ = aᵐ⁺ᵑ
3.9 x (10 ¹¹)
3.9 x 10¹¹
3.900000000000

Question 5.
6.7 × 10-5

Answer:
0.000067

Explanation:
6.7x 10-5
6.7 x 10-⁴ x 10-5
6.7 x (10-⁴- ⁵)
6.7 x 10-⁹
0.000067

Question 6.
6.24 × 1010

Answer:
6.240000000000

Explanation:
6.24 x 10¹⁰
6.24 x (10⁹ x 10¹⁰)
6.24 x (10⁹ ⁺¹⁰)
using aᵐx aᵑ = aᵐ⁺ᵑ
6.24 x (10 ¹⁹ )
6.24 x 10¹⁹
6.240000000000000000000

Question 7.
Which ordered pair is the solution of the linear system 3x + 4y = -10 and 2x – 4y = 0?
A. (6, 2)
B. (2, 6)
C. (2, 1)
D. (1, 2)

Answer:
option c is correct.

Explanation:
3x + 4y = -10
3 (2) + 4 (1) = -10
6 + 4 = -10
2x – 4y = 0
2 (2) – 4 (1) = 0
4 – 4 = 0

Concepts, Skills, &Problem Solving

FINDING VOLUME The height h and the base area B of a cylinder are given. Find the volume of the cylinder. Write your answer in terms of π. (See Explorations 1 and 2, p. 427.)
Question 8.
h = 5 units
B = 4π square units

Answer:
volume of cylinder = 251.2 π cubic units

Explanation:
volume of cylinder = πr² h
where π = 3.14  r = 4π
r = 4π , h = 5 given
v = 3.14 x 4 x 4 x 5
v = 3.14 x 16 x 5
v = 251.2
v = 251.2 π cubic  units

Question 9.
h = 2 units
B = 25π square units

Answer:
volume of cylinder = 50 π cubic units

Explanation:
volume of cylinder = πr² h
where π = 3.14  r = 25π
r = 25π , h = 2 given
v = 3.14 x 25x 25 x 2
v = 3.14 x 25 x 2
v = 3.14 x 50
v = 50 π cu. units

Question 10.
h = 4.5 units
B = 16π square units

Answer:
volume of cylinder = 3,617.28 π cu. units

Explanation:
volume of cylinder = πr² h
where π = 3.14  r = 16π
r = 16π , h = 4.5 given
v = 3.14 x 16 x 16 x 4.5
v = 3.14 x 256 x 4.5
v = 3.14 x 1152
v = 3,617.28  π cu. units

FINDING THE VOLUME OF A CYLINDER Find the volume of the cylinder. Round your answer to the nearest tenth.
Question 11.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 11

Answer:
volume of cylinder = 1,526.04 cu. feet

Explanation:
volume of cylinder = πr² h
where π = 3.14  r = 9
r = 9 , h = 6 given
v = 3.14 x 9 x 9 x 6
v = 3.14 x 81 x 6
v = 3.14 x 486
v = 1,526.04 cu. feet

Question 12.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 12

Answer:
volume of cylinder = 791.28 cu. in

Explanation:
volume of cylinder = πr² h
where π = 3.14  r = 6
r = 6 , h = 7 given
v = 3.14 x 6 x 6 x 7
v = 3.14 x 36 x 7
v = 3.14 x 252
v = 791.28 cu. in

Question 13.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 13

Answer:
volume of cylinder = 769.3 cu feet

Explanation:
volume of cylinder = πr² h
where π = 3.14  r = 7
r = 7 , h = 5 given
v = 3.14 x 7 x 7 x 5
v = 3.14 x 49 x 5
v = 3.14 x 245
v = 769.3 cu feet

Question 14.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 14

Answer:
volume of cylinder = 785 cu. feet

Explanation:
volume of cylinder = πr² h
where π = 3.14  r = 5 ft
r = 5 , h = 10 given
v = 3.14 x 5 x 5 x 10
v = 3.14 x 25 x 10
v = 3.14 x 250
v = 785 cu. feet

Question 15.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 15

Answer:
volume of cylinder = 804.2 cu. cm

Explanation:
volume of cylinder = πr² h
where π = 3.14  r = 8 cm
r = 8 , h = 16 given
v = 3.14 x 8 x 8 x 16
v = 3.14 x 64 x 16
v = 3.14 x 1,024
v = 804.2 cu. cm

Question 16.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 16

Answer:
volume of cylinder = 883.125 cu. m

Explanation:
volume of cylinder = πr² h
where π = 3.14  d = 15 r = (d/2)
r = 7.5 , h = 5 given
v = 3.14 x 7.5 x 7.5 x 5
v = 3.14 x 56.25 x 5
v = 3.14 x 281.25
v = 883.125 cu. m

Question 17.
REASONING
Without calculating, which of the solids has the greater volume? Explain.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 17

Answer:
the cube has a greater volume.

Explanation:
the volume of square prism = s³
v = side x side x side
v = 8 x 8 x 8
v = 64 x 8
v = 512 cubic inches
volume of cylinder = πr² h
where π = 3.14  r = 4 cm
r = 4 , h = 8 given
v = 3.14 x 4 x 4 x 8
v = 3.14 x 16 x 8
v = 3.14 x 128
v = 401.92 cu. in

FINDING A MISSING DIMENSION Find the missing dimension of the cylinder. Round your answer to the nearest whole number.
Question 18.
Volume = 10,000 π in.3
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 18

Answer:
height of cylinder = 0.080384 in

Explanation:
volume of cylinder = πr² h
where π = 3.14  d = 32 r = (d/2)
r = 16 , v = 10,000
10,000 = 3.14 x 16 x 16 x h
10,000 = 3.14 x 256 h
10,000= 803.84  h
h = (803.84/10,000)
h = 0.080384 in

Question 19.
Volume = 3785 cm3
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 19

Answer:
radius of cylinder = 8 cm

Explanation:
volume of cylinder = πr² h
where π = 3.14  h = 19
v = 3785
3785 = 3.14 x r x r x 19
3785 = 3.14 x 19r²
3785= 59.66 r²
r² = (3785/59.66)
r² =64
r = 8 cm

Question 20.
Volume = 600,000 cm3
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 20

Answer:
Radius of cylinder = 0.00198867 cm

Explanation:
Volume of cylinder = πr² h
where π = 3.14  h = 76 cm given
, v = 600,000
600,000 = 3.14 x r x r x 76
600,000 = 3.14 x 76r²
600,000= 238.64r²
r² = (238.64/600,000)
r² = 0.00397733
r = 0.00198867 cm

Question 21.
MODELING REAL LIFE
A cylindrical hazardous waste container has a diameter of 1.5 feet and a height of 1.6 feet. About how many gallons of hazardous waste can the container hold? (1 ft3 ≈ 7.5 gal)

Answer:
Hazardous waste can hold the container = 21.195 gal

Explanation:
volume of cylinder = πr² h
where π = 3.14  d = 1.5 r = (d/2)
r = 0.75 , h = 1.6 feet
v = 3.14 x 0.75 x 0.75 x 1.6
v = 3.14 x 0.5625 x 1.6
v= 3.14 x 0.9
h = 2.826
h = 2.826 x 7.5
h = 21.195 gal

Question 22.
CRITICAL THINKING
How does the volume of a cylinder change when its diameter is halved? Explain.

Answer:
the volume of the cylinder change when its diameter is halved.

Explanation:
If the diameter is halved it is the same as a radius.
d = (r/2)
(d/2)
so the volume of the cylinder change when its diameter is halved.

Question 23.
PROBLEM SOLVING
A traditional “square” bale of hay is actually in the shape of a rectangular prism. Its dimensions are 2 feet by 2 feet by4 feet. How many square bales contain the same amount of hay as one large “round” bale?
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 21

Answer:
The square bales contain the same amount of hay as one large round bale = 4 squares bale

Explanation:
The surface area of rectangular prism = 2(lw + lh +wh)
given that l = 2, w=2 h = 4
area = 2(2 x 2 + 2 x 4 +4 x 2)
area = 2(4 + 8 + 8)
area = 2(2)
area = 4 sq ft

Question 24.
MODELING REAL LIFE
A tank on a road roller is filled with water to make the roller heavy. The tank is a cylinder that has a height of 6 feet and a radius of 2 feet. About how many pounds of water can the tank hold? (One cubic foot of water weighs about 62.5 pounds.)
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 22

Answer:
The pounds of water can hold the tank = 4,710 pounds

Explanation:
Volume of cylinder = πr² h
where π = 3.14  h = 6 ft given
r = 2 ft
v = 3.14 x 2 x 2 x 6
v = 3.14 x 4 x 6
v= 3.14 x 24
v = 75.36 cu. feet
v = 75.36 x 62.5
v = 4,710 pounds

Question 25.
REASONING
A cylinder has a surface area of 1850 square meters and a radius of 9 meters. Estimate the volume of the cylinder to the nearest whole number.

Answer:
Volume of the cylinder = 6035 cubic meters.

Explanation:
volume of the cylinder= πr²h
volume = 3.14 x 9 x 9 x 1850
volume = 8325 – 729 π
v = 8325 – 729 x 3.14
v = 8325 – 102.06
v = 8222.94
the nearest whole number to the 8222.94 is 6035 cubic meters.

Question 26.
DIG DEEPER!
Water flows at 2 feet per second through a cylindrical pipe with a diameter of 8 inches. A cylindrical tank with a diameter of 15 feet and a height of 6 feet collects the water.
a. What is the volume (in cubic inches) of water flowing out of the pipe every second?
b. What is the height (in inches) of the water in the tank after 5 minutes?
c. How many minutes will it take to fill 75% of the tank?

Answer:
a. Volume of water flowing out of the pipe every second = 100.48 cu. in
b. The height of the water in tank after 5 minutes = 1,059.75 sq ft
c. 75% of water to fill tank = 25

Explanation:
a. Volume of cylinder = πr² h
where π = 3.14  h = 2 ft given
r = 4
v = 3.14 x 4 x 4 x 2
v = 3.14 x 16 x 2
v= 3.14 x 32
v = 100.48 cu. in
b. Volume of cylinder = πr² h
where π = 3.14  h = 6 ft given
r = 7.5
v = 3.14 x 7.5 x 7.5 x 6
v = 3.14 x 56.25 x 6
v= 3.14 x 337.5
v = 1,059.75 cu. ft
c. 100 – 75
25 %

Question 27.
PROJECT
You want to make and sell three different sizes of cylindrical candles. You buy 1 cubic foot of candle wax for $20 to make 8 candles of each size.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids 10.1 23
a. Design the candles. What are the dimensions of each size of candle?
b. You want to make a profit of $100. Decide on a price for each size of candle. Explain how you set your prices.

Answer:
a. The dimensions of each size of candle = 20cm
b. price for each size of candle = $ 30

Explanation:
$ x 80 candles given
20 x 3 = 60
each candle has a dimension of 20 cm
b. price for each side = $ 30

Lesson 10.2 Volumes of Cones

You already learned how the volume of a pyramid relates to the volume of a cone prism. In this exploration, you will discover how the volume of a relates to the volume of a cylinder.
A cone is a solid that has one circular base and one vertex.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 1

EXPLORATION 1

Finding a Formula Experimentally
Work with a partner.Use a paper cup that is shaped like a cone. Measure the height of the cup and the diameter of the circular base. Use these measurements to draw a net for a cylinder with the same base and height as the paper cup. Then cut out the net and use tape to form an open cylinder.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 2
a. Find the volume of the cylinder.
b. Fill the paper cup with rice. Then pour the rice into the cylinder. Repeat this until the cylinder is full. How many cones does it take to fill the cylinder?
c. Use your result to write a formula for the volume of a cone.
d. Use your formula in part(c) to find the volume of the cone. How can you tell whether your answer is correct?
e. Do you think your formula for the volume of a cone oblique is also true for cones? Explain your reasoning.

Answer:
a. volume of cylinder = πr² h
b. 2 cones will take to fill the cylinder.
c. volume of cone = πr²( h/3)
d. yes the answer is correct.
e. volume of cone oblique is true for cones.

Explanation:
a.volume of cylinder = πr² h
where r = radius , h= height
b. 2 cones = 1 cylinder
c. . volume of cone = πr²( h/3)
where r = radius , h= height
d. Yes the answer is correct.

Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 3

Try It

Question 1.
Find the volume of a cone with a radius of 6 centimeters and a height of 15 centimeters. Round your answer to the nearest tenth.

Answer:
volume of cone = 565.2 cu. cm

Explanation:
volume of cone =πr² (h/3)
given that r = 6 ,h=15
v = 3.14 x 6 x 6 x (15/3)
v = 3.14 x 36 x 5
v=3.14 x 180
v= 565.2 cu. cm

Question 2.
Find the height of the cone at the left. Round your answer to the nearest tenth.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 4

Answer:
height of cone = 0.03270833 yd

Explanation:
volume of cone =πr² (h/3)
given that r = 15 ,v = 7200
7200 = 3.14 x 15 x 15 x (h/3)
7200 = 3.14 x 15 x 5h
7200=3.14 x 75h
7200= 235.5 h
h = (235.5/7200)
h = 0.03270833

Find the radius of the cone. Round your answer to the nearest whole number.
Question 3.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 5

Answer:
radius of cone = 12.4887397 feet

Explanation:
volume of cone =πr² (h/3)
given that h = 7 ,v = 183
183 = 3.14 x r x r x (7/3)
183 = 3.14 x r² x 2.33
183=3.14 x 2.33 r²
183= 7.32666 r²
r² = (183/7.32666)
r²  = 24.97747
r=12.4887397 feet

Question 4.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 6

Answer:
radius of cone = 1.78594585 meter

Explanation:
volume of cone =πr² (h/3)
given that h = 2.75 ,v = 46
46 = 3.14 x r x r x (2.75/3)
46 = 3.14 x r² x 0.9166
46 = 12.87833 r²
r² = (46/12.87833)
r²  = 3.57189
r=1.78594585 meter

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 5.
FINDING THE VOLUME OF A CONE
Find the volume of a cone with a diameter of 10 yards and a height of 12 yards. Round your answer to the nearest tenth.

Answer:
volume of cone = 314 cu. yards.

Explanation:
volume of cone =πr² (h/3)
given that d = 10 r=(d/2) r = (10/2) r = 5 ,h=12
v = 3.14 x 5 x 5 x (12/3)
v = 3.14 x 25 x 4
v=3.14 x 100
v= 314 cu. yards

FINDING A MISSING DIMENSION OF A CONE Find the missing dimension of the cone. Round your answer to the nearest tenth.
Question 6.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 7

Answer:
height of cone = 66.6666 in

Explanation:
volume of cone =πr² (h/3)
given that r = 6 ,v = 2,512
2512 = 3.14 x 6 x 6 x (h/3)
2512 = 3.14 x 6 x 2h
2512 =3.14 x 12h
2512= 37.68h
h = (2512/37.68)
h = 66.6666 in

Question 7.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 8

Answer:
radius of cone = 25.12 centimeter

Explanation:
volume of cone =πr² (h/3)
given that h = 5 ,v = 16.5
16.5 = 3.14 x r x r x (5/3)
16.5 = 3.14 x r² x 1.666
16.5 = 5.23333 r²
r² = (16.5/5.23333)
r²  = 3.152868
r= 8π centimeter

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 8.
A stalactite is a mineral formation that hangs from the ceiling of a cave. A cone-shaped stalactite has a height of 48 centimeters and a base circumference of 3.5π centimeters. What is the volume of the stalactite?
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 9

Answer:
volume of cone = 615.44 cu. cm

Explanation:
volume of cone =πr² (h/3)
given that r =3.5 ,h=48
v = 3.14 x 3.5 x 3.5 x (48/3)
v = 3.14 x 12.25 x 16
v=3.14 x 196
v= 615.44 cu. cm

Question 9.
A store sells two cone-shaped funnels. What is the height of each funnel? (1 pt = 28.875 in.3)
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 10

Answer:
height of ist funnel =2.72469922 in
height of 2nd funnel = 3.06528662 in

Explanation:
volume of 1st cone =πr² (h/3)
given that r= (d/2)r = (4.5/2) r = 2.25 ,v = 0.5
0.5 = 3.14 x 2.25 x 2.25 x (h/3)
0.5 = 3.14 x 5.0625 x (h/3)
0.5 =3.14 x 1.6875h
0.5= 5.29875 h
h = (0.5/5.29875)
h = 0.09436188
h = 0.09436188 x 28.875
h = 2.72469922
volume of 2nd cone =πr² (h/3)
given that r= (d/2)r = (6/2) r=3 ,v = 1
1 = 3.14 x 3 x 3 x (h/3)
1 = 3.14 x 3x h
1 =3.14 x 3h
1= 9.42 h
h = (1/9.42)
h = 0.10615711 x 28.875
h = 3.0652866

Question 10.
You fill cone-shaped pastry bags with icing to a height of 1 foot and a diameter of 3.5 inches. You use about 1.35 cubic inches of icing per cupcake. About how many cupcakes can you decorate with 2 bags of icing?

Answer:
Cupcakes can decorate with 2 bags of icing = 6.410833 sq in

Explanation:
volume of  cone =πr² (h/3)
given that r= (d/2)r = (3.5/2) r=1.75 ,h = 1
v = 3.14 x 1.75 x 1.75 x (1/3)
v = 3.14 x 3.0625 x (1/3)
v =3.14 x 3.0625 x 0.333
v= 3.14 x 1.0208333
v = 3.20541667 inches
for 2 bags of icing = 6.4108333

Volumes of Cones Homework & Practice 10.2

Review & Refresh

Find the volume of the cylinder. Round your answer to the nearest tenth.
Question 1.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 11

Answer:
volume of  cone = 65.94 cu. cm

Explanation:
volume of  cone =πr² (h/3)
given that r=3 ,h = 7
v = 3.14 x 3 x 3 x (7/3)
v = 3.14 x 9 x (7/3)
v =3.14 x 9 x 2.33
v= 3.14 x 21
v = 65.94 cu. cm

Question 2.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 12

Answer:
volume of  cone = 16.7466 cu. ft

Explanation:
volume of  cone =πr² (h/3)
given that r=2 ,h = 4
v = 3.14 x 2 x 2 x (4/3)
v = 3.14 x 4 x (4/3)
v =3.14 x 4 x 1.33
v= 3.14 x 5.333
v = 16.7466 cu. ft

Question 3.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 13

Answer:
volume of  cone = 523.333 cu. yds

Explanation:
volume of  cone =πr² (h/3)
given that r=10 ,h = 5
v = 3.14 x 10 x 10 x (5/3)
v = 3.14 x 100 x (5/3)
v =3.14 x 100 x 1.666
v= 3.14 x 166.66
v = 523.333 cu. yds

Solve the equation.
Question 4.
x3 = 27

Answer:
x = 3

Explanation:
x³ = 27
x³ = 3³
when power are equal exponents must be equal.
x = 3

Question 5.
– 6 = y3 + 2

Answer:
y = – 2

Explanation:
-6 = y³ + 2
y³ = 2 + 6
y³ = 8
y³ = 2³
y = -2

Question 6.
2h3 – 33 = 95

Answer:
h = 4

Explanation:
2h³ – 33 = 95
2h³ = 95 + 33
2h³ = 128
h³ = (128/2)
h³ = 64
h³ = 4³
h = 4

Concepts, Skills, & Problem Solving

FINDING A VOLUME The height h and the base B area of a cone are given. Find the volume of the cone. Write your answer in terms of π. (See Exploration 1, p. 433.)
Question 7.
h = 6 units
B = 4π square units

Answer:
volume of  cone = 8 π cubic units

Explanation:
volume of  cone =πr² (h/3)
given that r=4 ,h = 6
v = 3.14 x 4 x 4 x (6/3)
v = 3.14 x 16 x (6/3)
v =3.14 x 4 x 2
v= 8 x π
v = 25.12 cubic units

Question 8.
h = 9 units
B = 5π square units

Answer:
volume of  cone = 235.5 cubic units

Explanation:
volume of  cone =πr² (h/3)
given that r=5 ,h = 9
v = 3.14 x 5 x 5 x (9/3)
v = 3.14 x 25 x (9/3)
v =3.14 x 25 x 3
v= 3.14 x 75
v = 235.5 cubic units

FINDING THE VOLUME OF A CONE Find the volume of the cone. Round your answer to the nearest tenth.
Question 9.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 14

Answer:
volume of  cone = 16.7466 cu. in

Explanation:
volume of  cone =πr² (h/3)
given that r=2 ,h = 4
v = 3.14 x 2 x 2 x (4/3)
v = 3.14 x 4 x (4/3)
v =3.14 x 4 x 1.33
v= 3.14 x 5.33
v = 16.7466 cu. in

Question 10.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 15

Answer:
volume of  cone = 28.26 cu. m

Explanation:
volume of  cone =πr² (h/3)
given that r=(d/2) (6/2)=3 ,h = 3
v = 3.14 x 3 x 3 x (3/3)
v = 3.14 x 9 x (3/3)
v =3.14 x 9 x 1
v= 3.14 x 9
v = 28.26 cu. m

Question 11.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 16

Answer:
volume of  cone =261.66 cu. mm

Explanation:
volume of  cone =πr² (h/3)
given that r = 5 ,h = 10
v = 3.14 x 5 x 5 x (10/3)
v = 3.14 x 25 x (10/3)
v =3.14 x 25 x 3.33
v= 3.14 x 83.333
v = 261.66 cu. mm

Question 12.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 17

Answer:
volume of  cone =2.093333 cu. ft

Explanation:
volume of  cone =πr² (h/3)
given that r = 1 ,h = 2
v = 3.14 x 1 x 1 x (2/3)
v = 3.14 x 1 x (2/3)
v =3.14 x 1 x 0.6666
v= 3.14 x 0.666
v = 2.093333 cu. ft

Question 13.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 18

Answer:
volume of  cone = 804.2 cubic cm

Explanation:
volume of  cone =πr² (h/3)
given that r = 5 ,h = 8
v = 3.14 x 5 x 5 x (8/3)
v = 3.14 x 25 x (8/3)
v =3.14 x 25 x 2.6666
v= 3.14 x 256
v = 804.2 cubic cm

Question 14.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 19

Answer:
volume of  cone = 115.395 cu. yd

Explanation:
volume of  cone =πr² (h/3)
given that r =(d/2) = (7/2) = 3. 5 ,h = 9
v = 3.14 x 3.5 x 3.5 x (9/3)
v = 3.14 x 12.25 x (9/3)
v =3.14 x 12.25 x 3
v= 3.14 x 36.75
v = 115.395 cu. yd

Question 15.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 20

Answer:
volume of  cone =117.226667 cu. ft

Explanation:
volume of  cone =πr² (h/3)
given that r = 4 ,h = 7
v = 3.14 x 4 x 4 x (7/3)
v = 3.14 x 16 x (7/3)
v =3.14 x 16 x 2.3333
v= 3.14 x 37.33333
v = 117.226667 cu. ft

Question 16.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 21

Answer:
volume of  cone =65.416666 cu. in

Explanation:
volume of  cone =πr² (h/3)
given that r = 2.5 ,h = 10
v = 3.14 x 2.5 x 2.5 x (10/3)
v = 3.14 x 6.25 x (10/3)
v =3.14 x 6.25 x 3.33
v= 3.14 x 20.8333
v = 65.416666 cu. in

Question 17.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 22

Answer:
volume of  cone =1.5 cu. cm

Explanation:
volume of  cone =πr² (h/3)
given that r = 2 ,h = 8
v = 3.14 x 2 x 2x (8/3)
v = 3.14 x 4 x (8/3)
v =3.14 x 4 x 2.666
v= 3.14 x 10.6666
v = 1.5 cu. cm

Question 18.

STRUCTURE
The inside of each glass is shaped like a cone. Which glass can hold more liquid? How much more?
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 23

Answer:
Glass A can hold more liquid than glass B.

Explanation:
volume of  Glass A =πr² (h/3)
given that r = 4 ,h = 8
v = 3.14 x 4 x 4 x (8/3)
v = 3.14 x 16 x (8/3)
v =3.14 x 16 x 2.666
v= 3.14 x 42.656
v = 42.656 cu. cm
volume of  Glass A =πr² (h/3)
given that r = 3 ,h = 10
v = 3.14 x 3 x 3 x (10/3)
v = 3.14 x 9 x (10/3)
v =3.14 x 9 x 3.33
v= 3.14 x 30
v = 94.2 cu. cm

FINDING A MISSING DIMENSION OF A CONE Find the missing dimension of the cone. Round your answer to the nearest tenth.
Question 19.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 24

Answer:
volume of cone = 9203 cubic cm

Explanation:
volume of  cone =πr² (h/3)
given that  r=0.33 ,v = (1/18) ,v = 0.055
0.055 = 3.14 x 0.33 x 0.33 x (h/3)
0.055 = 3.14 x 0.1089h
0.055 =0.341946 h
h =(8788/3) x 3.14
h = 2929.33 x 3.14
h = 9203 cubic cm

Question 20.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 25

Answer:
volume of cone = 0.1162963 cu. cm

Explanation:
volume of  cone =πr² (h/3)
given that  r=5 ,v = 225
225 = 3.14 x 5 x 5 x (h/3)
225 = 3.14 x 5 x 1.666 h
225 =8.3333 x 3.14 h
225 = 26.1666666 h
h = (26.1666666/225)
h = 0.1162963 sq cm

Question 21.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 26

Answer:
radius of cone =  3.15 cubic in

Explanation:
volume of  cone =πr² (h/3)
given that  h= 4.2 ,v = 3.6
3.6 = 3.14 x r x r x (4.2/3)
3.6 = 3.14 x r²   x 1.4
3.6  =( 4.396 / r² )
r²  = 3/4 x h
r = 0.75 x 4.12
r = 3.15  cubic in

Question 22.
FINDING A MISSING DIMENSION OF A CONE
The volume of a cone with a height of 10 meters is 20π cubic meters. What is the diameter of the cone?

Answer:
diameter of cone = 0.333 meters

Explanation:
volume of  cone =πr² (h/3)
given that  h= 10 ,v = 20
20 = 3.14 x r x r x (10/3)
20 = 3.14 x r²   x3.33
20  = 10.46666 r²
r²  = 0.1665  x 2
r = 0.333 meters.

Question 23.
MODELING REAL LIFE
Water leaks from a crack in a cone-shaped vase at a rate of 0.5 cubic inch per minute. The vase has a height of 10 inches and a diameter of 4.8 inches. How long does it take for 20% of the water to leak from the vase when it is full of water?

Answer:
20% of water to leak from the vase when it is full of water = 1206.4

Explanation:
volume of  cone  =πr² (h/3)
given that r = 2.4 ,h = 10
v = 3.14 x 2.4 x 2.4 x (10/3)
v = 3.14 x 5.76  x (10/3)
v =3.14 x 5.76 x 3.33
v= 3.14 x 384
v = 1206.4
20% of water to leak from the vase when it was full of water
1206.4

Question 24.
DIG DEEPER!
You have 10 gallons of lemonade to sell. (1 gal ≈ 3785 cm3)
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 27
a. Each customer uses 1 paper cup. The cups are sold in packages of 50. How many packages should you buy?
b. How many cups will be left over if you sell 80% of the lemonade?

Answer:
a. the no of packages should buy = 25
b. 20 cups will be left over if we sell 80% of lemonade.

Explanation:
a. the no of packages = 25
In the question given that the cups are sold in the packages of 50
b. 80% of cups will be left in the lemonade = 20
100 – 80 =  20

Question 25.
STRUCTURE
The cylinder and the cone have the same volume. What is the height of the cone?
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 28

Answer:
The height of the cone = 54 π

Explanation:
Given that the cone and the cylinder have the same volume.
The height of the cone = 54 π
54 x 3.14
169.56
170 cubic cm

Question 26.
CRITICAL THINKING
In Example 4, you use a different timer with the same dimensions. The sand in this timer has a height of 30 millimeters. How much time do you have to answer the question?

Answer:
300 minutes will take to answer the question.

Explanation:
The sand in this timer has a height of 30 mm
time to answer the question = 5 x 6
5 hrs
300 minutes will take to answer the question.

Question 27.
REASONING
A vapor cone is a cloud of condensed water that forms when an aircraft breaks the sound barrier. How does doubling both the diameter and the height affect the volume of the vapor cone?
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids 10.2 29

Answer:
The volume of the vapor cone is changed.

Explanation:
the volume of the cone = 4/3 πr³
v =4/3 πr³
r = 3√ 435,750,000
3200 + 3√ 435,750,000
3958

Lesson 10.3 Volumes of Spheres

A sphere is the set of all points in space that are the same distance from a point called the center. The radius r is the distance from the center to any point on the sphere. A sphere is different from the other solids you have studied so far because it does not have a base.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 1

EXPLORATION 1

Finding a Formula Experimentally
Work with a partner. Use a plastic ball similar to the one shown. Draw a net for a cylinder with a diameter and a height equal to the diameter of the ball. Then cut out the net and use tape to form an open cylinder.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 2
a. How is the height h of the cylinder related to the radius r of the ball?
b. Cover the ball with aluminum foil or tape. Leave one hole open. Fill the ball with rice. Then pour the rice into the cylinder. What fraction of the cylinder is filled with rice?
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 3
c. Use your result in part(b) and the formula for the volume of a cylinder to write a formula for the volume of a sphere. Explain your reasoning.

Answer:
a. Height of the cylinder is proportional to the radius of the ball.
c. volume of cylinder = πr²h
volume of sphere = (4/3) πr² x r

Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 4

Try It

Find the volume of the sphere. Round your answer to the nearest tenth.
Question 1.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 5

Answer:
volume of the sphere = 33.49333 cubic mm

Explanation:
volume of sphere = (4/3) πr² x r
v = (4/3) x 3.14 x 2 x 2 x2
where r = 2 given
v = 1.33 x 3.14 x 8
v= 4.18666 x 8
v = 33.49333 cubic mm

Question 2.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 6

Answer:
volume of the sphere =2,138.2144 sq ft

Explanation:
volume of sphere = (4/3) πr² x r
v = (4/3) x 3.14 x 8 x 8 x8
where r = 8  given
v = 1.33 x 3.14 x 512
v= 1.33 x 1,607.68
v = 2,138.2144 cu. ft

Find the radius of the sphere. Round your answer to the nearest tenth if necessary.
Question 3.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 7

Answer:
radius of the sphere=0.333055310396 m

Explanation:
volume of sphere = (4/3) πr² x r
36  = (4/3) x 3.14 x r³
where v = 36
36 = 1.33r³
r³ = (1.33/36)
r³ = 0.036944
r =0.333055310396 m

Question 4.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 8

Answer:
radius of the sphere= 0.6681660696 in

Explanation:
volume of sphere = (4/3) πr² x r
14  = (4/3) x 3.14 x r³
where v = 14
14 = 1.33 x 3.14 r³
14 = 4.1762 r³
r³ = (4.1762/14)
r³ = 0.2983 cubic in
r = 0.6681660696 in

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 5.
FINDING THE VOLUME OF A SPHERE
Find the volume of the sphere. Round your answer to the nearest tenth.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 9

Answer:
volume of the sphere =17,105.7552 cu. cm

Explanation:
volume of sphere = (4/3) πr² x r
v = (4/3) x 3.14 x 16 x 16 x 16
where r = 16  given
v = 1.33 x 3.14 x 4,096
v= 1.33 x 12,861.44
v = 17,105.7552 cu. cm

Question 6.
FINDING THE RADIUS OF A SPHERE
Find the radius of a sphere with a volume of 4500π cubic yards.

Answer:
radius of the sphere= 0.00029556 sq yds

Explanation:
volume of sphere = (4/3) πr² x r
4500  = (4/3) x 3.14 x r³
where v = 4500
4500 = 1.33 x 3.14 r³
4500 = 1.33 r³
r³ = (1.33/4500)
r³ = 0.00029556

Question 7.
WHICH ONE DOESN’T BELONG?
Which figure does not belong with the other three? Explain your reasoning.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 10

Answer:
sphere does not belong with the other three.

Explanation:
pyramid, prism, cylinder have bases.
sphere does not have a base.

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 8.
In sphering, a person is secured inside a small, hollow sphere that is surrounded by a larger sphere. The space between the spheres is inflated with air. What is the volume of the inflated space? Explain.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 11

Answer:
The volume of the inflated surface = 79.54649 cu. m

Explanation:
The volume of larger sphere = (4/3) πr³
v = (4/3) x 3.14 x 3³
v = 1.333 x 3.14 x 27
v = 4.18666 x 27
v = 113.03982 cu. m
The volume of hollow sphere = (4/3) πr³
v = (4/3) x 3.14 x 2³
v = 1.333 x 3.14 x 8
v = 4.18666 x 8
v = 33.49333 cu. m
inflated space = larger sphere – hollow sphere
inflated space = 79.54649

Question 9.

DIG DEEPER!
A vendor sells cones filled with frozen yogurt, as shown. The vendor has 4 cylindrical containers of frozen yogurt, each with a diameter of 18 centimeters and a height of 15 centimeters. About how much money will the vendor make when all of the frozen yogurt is sold? Justify your answer.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 12

Answer:
volume of  cone= 113.04 cu. cm

Explanation:
the volume of  cone  =πr² (h/3)
given that r = 3 ,h = 12
v = 3.14 x 3 x 3 x (12/3)
v = 3.14 x 9  x (12/3)
v =3.14 x 9 x 4
v= 3.14 x 36
v = 113.04 cu. cm

Volumes of Spheres Homework & Practice 10.3

Review & Refresh

Find the volume of the cone. Round your answer to the nearest tenth.
Question 1.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 13

Answer:
volume of  cone= 25.12 cu. ft

Explanation:
volume of  cone  =πr² (h/3)
given that r = 2 ,h = 6
v = 3.14 x 2 x 2 x (6/3)
v = 3.14 x 4  x (6/3)
v =3.14 x 4 x 2
v= 3.14 x 8
v = 25.12 cu. ft

Question 2.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 14

Answer:
volume of  cone= 47.1 cu. cm

Explanation:
volume of  cone  =πr² (h/3)
given that r = 3 ,h = 5
v = 3.14 x 3 x 3 x (5/3)
v = 3.14 x 9  x (5/3)
v =3.14 x 9 x 1.666
v= 3.14 x 15
v = 47.1 cu. cm

Question 3.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 15

Answer:
volume of  cone=84.78 cu. m

Explanation:
volume of  cone  =πr² (h/3)
given that r = 4.5 ,h = 4
v = 3.14 x 4.5 x 4.5 x (4/3)
v = 3.14 x 20.25 x (4/3)
v =3.14 x 20.25 x 1.333
v= 3.14 x 27
v = 84.78 cu. m

Evaluate the expression. Write your answer in scientific notation.
Question 4.
(4.6 × 109) + (3.9 × 109)

Answer:
85,00,00,00000

Explanation:
(4.6 × 109) + (3.9 × 109)
4.6 x 1000000000 + 3.9 x 1000000000
85,00,00,00000

Question 5.
(1.4 × 10-4) ÷ (2.8 × 106)

Answer:
5e – 12

Explanation:
0.00014 / 28000000
5e – 12

Question 6.
A person who is 5 feet tall casts a 6-foot-long shadow. A nearby flag pole casts a 30-foot-long shadow. What is the height of the flagpole?
A. 25 ft
B. 29 ft
C. 36 ft
D. 40 ft
Answer:
Option B is correct.

Explanation:
Given that person who is 5 feet tall casts a 6-foot-long shadow.
A nearby flag pole casts a 30-foot-long shadow.
the height of the flagpole is 29 ft

Concepts, Skills, &Problem Solving

FINDING VOLUME The radius of a sphere is given. Find the volume of the sphere. Write your answer in terms of π. (See Exploration 1, p. 439.)
Question 7.
r = 6 units

Answer:
volume of the sphere= 902.0592 units

Explanation:
volume of sphere = (4/3) πr² x r
v  = (4/3) x 3.14 x r³
where r =6
v = 1.33 x 3.14  x 6 x 6 x 6
v = 1.33 x 3.14 x 216
v = 1.33 x 678.24
v = 902.0592 units

Question 8.
r = 12 units

Answer:
volume of the sphere= 7,216.4736 units

Explanation:
volume of sphere = (4/3) πr² x r
v  = (4/3) x 3.14 x r³
where r =12
v = 1.33 x 3.14  x 12 x 12 x 12
v = 1.33 x 3.14 x 1,728
v = 1.33 x 5,425.92
v = 7,216.4736 units

Question 9.
r = 10 units

Answer:
volume of the sphere=4,176.2 units

Explanation:
volume of sphere = (4/3) πr² x r
v  = (4/3) x 3.14 x r³
where r =10
v = 1.33 x 3.14  x 10 x 10 x 10
v = 1.33 x 3.14 x 1000
v = 1.33 x 3140
v = 4,176.2 units

FINDING THE VOLUME OF A SPHERE Find the volume of the sphere. Round your answer to the nearest tenth.
Question 10.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 16

Answer:
volume of the sphere= 522.025 cu. units

Explanation:
volume of sphere = (4/3) πr² x r
v  = (4/3) x 3.14 x r³
where r =5
v = 1.33 x 3.14  x 5 x 5 x 5
v = 1.33 x 3.14 x 125
v = 1.33 x 3.92.5
v = 522.025 cu. units

Question 11.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 17

Answer:
volume of the sphere=1,432.4366 cu. units

Explanation:
volume of sphere = (4/3) πr² x r
v  = (4/3) x 3.14 x r³
where r =7
v = 1.33 x 3.14  x 7 x 7 x 7
v = 1.33 x 3.14 x 343
v = 1.33 x 1,077.02
v = 1,432.4366 cu. units

Question 12.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 18

Answer:
volume of the sphere= 3,044.4498 units

Explanation:
volume of sphere = (4/3) πr² x r
v  = (4/3) x 3.14 x r³
where r =9
v = 1.33 x 3.14  x 9 x 9 x 9
v = 1.33 x 3.14 x 729
v = 1.33 x 2,289.06
v = 3,044.4498 cu. units

Question 13.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 19

Answer:
volume of the sphere= 300.6864 cu. units

Explanation:
volume of sphere = (4/3) πr² x r
v  = (4/3) x 3.14 x r³
where r =6
v = 1.33 x 3.14  x 6 x 6 x 6
v = 1.33 x 3.14 x 72
v = 1.33 x 226.08
v = 300.6864 cu. units

Question 14.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 20

Answer:
volume of the sphere= 112.7574 cu. units

Explanation:
volume of sphere = (4/3) πr² x r
v  = (4/3) x 3.14 x r³
where r =3
v = 1.33 x 3.14  x 3 x 3 x 3
v = 1.33 x 3.14 x 27
v = 1.33 x 84.78
v = 112.7574 cu. units

Question 15.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 21

Answer:
volume of the sphere=11,459.4928 cu. units

Explanation:
volume of sphere = (4/3) πr² x r
v  = (4/3) x 3.14 x r³
where r =14
v = 1.33 x 3.14  x 14 x 14 x 14
v = 1.33 x 3.14 x 2744
v = 1.33 x 8,616.16
v = 11,459.4928 cu. units

FINDING THE RADIUS OF A SPHERE Find the radius of a sphere with the given volume. Round your answer to the nearest tenth if necessary.
Question 16.
Volume = 972π mm3

Answer:
radius of the sphere= 0.0004561 cubic mm

Explanation:
volume of sphere = (4/3) πr² x r
972  = (4/3) x 3.14 x r³
where v = 972
972 = 1.33 x 3.14 r³
972 = 1.33 r³
r³ = (1.33/972)
r³ = 0.00136831 cubic mm
r = 0.0004561

Question 17.
Volume = 4.5π cm3

Answer:
radius of the sphere= 0.09851852 cubic cm

Explanation:
volume of sphere = (4/3) πr² x r
4.5  = (4/3) x 3.14 x r³
where v = 4.5
4.5 = 1.33 x 3.14 r³
4.5 = 1.33 r³
r³ = (1.33/4.5)
r³ = 0.29555555 cubic mm
r = 0.09851852 cubic cm

Question 18.
Volume = 180 ft3

Answer:
radius of the sphere=0.0077337 cubic ft

Explanation:
volume of sphere = (4/3) πr² x r
180 = (4/3) x 3.14 x r³
where v = 180
180 = 1.33 x 3.14 r³
180 = 1.33  x 3.14r³
180 = 4.1762 r³
r³ = (4.1762/180)
r³ = 0.02320111 cubic ft
r = 0.0077337 cubic ft

Question 19.
MODELING REAL LIFE
The globe of the moon has a radius of 13 centimeters. Find the volume of the globe. Round your answer to the nearest whole number.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 22

Answer:
Volume of the globe =9,175.1114 cu. cm

Explanation:
volume of the globe=11,459.4928 units

Explanation:
volume of sphere = (4/3) πr² x r
v  = (4/3) x 3.14 x r³
where r =13
v = 1.33 x 3.14  x 13 x 13 x 13
v = 1.33 x 3.14 x 2,197
v = 1.33 x 6,898.58
v = 9,175.1114 cu. cm

Question 20.
MODELING REAL LIFE
A softball has a volume of about 29 cubic inches. Find the radius of the softball. Round your answer to the nearest tenth.

Answer:
radius of the softball= 0.0480023 ft

Explanation:
volume of sphere = (4/3) πr² x r
29= (4/3) x 3.14 x r³
where v = 29
29 = 1.33 x 3.14 r³
29 = 1.33  x 3.14r³
29 = 4.1762 r³
r³ = (4.1762/29)
r³ = 0.1440069 cubic ft
r = 0.0480023 ft

Question 21.
REASONING
A sphere and a right cylinder have the same radius and volume. Find the radius r in terms of the height h of the cylinder.

Answer:
The volume of sphere = (4/3) π h³
the volume of cylinder = πr²  r

Explanation:
volume of sphere = (4/3) π r³
They said to find the radius r in terms of height h.
the volume of sphere = (4/3) π h³
the volume of cylinder = πr² r

FINDING VOLUME Find the volume of the composite solid. Round your answer to the nearest tenth.
Question 22.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 23

Answer:
volume = 256 cubic cm

Explanation:
volume of rectangular prism = lwh
where l= length, w = weight, h= height
l = 8 ,w = 8 , h = 8 given
v= 8 x 8 x 8
v = 64 x 4
v =  256 cubic cm

Question 23.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 24

Answer:
volume = 192 cubic feet

Explanation:
volume of triangular prism = (bhl/2)
b = 16 , h = 6 , l = 4 given
v = (16 x 6 x 4/2)
v = (16 x 24/2)
v = 16 x 12
v = 192 cubic feet

Question 24.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 25

Answer:
volume of cylinder = 310.86 cu. in

Explanation:
volume of cylinder = πr² h
v = 3.14 x 3 x 3 x 11
v = 3.14 x 9 x 11
v = 3.14 x 99
v = 310.86 cu. in

Question 25.
PROBLEM SOLVING
A cylindrical container of three rubber balls has a height of 18 centimeters and a diameter of 6 centimeters. Each ball in the container has a radius of 3 centimeters. Find the amount of space in the container that is not occupied by rubber balls. Round your answer to the nearest whole number.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 26
Answer:
The amount of space in the container that is not occupied by the rubber balls = 2,034.72 cu. cm

Explanation:
volume of cylinder = πr² h
v = 3.14 x 6 x 6 x 18
v = 3.14 x 36 x 18
v = 3.14 x 648
v =2,034.72 cu. cm

Question 26.
DIG DEEPER!
The basketball shown is packaged in a box that is in the shape of a cube. The edge length of the box is equal to the diameter of the basketball. What are the surface area and the volume of the box?
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 27

Answer:
The volume of sph0.01646091 cubic in

Explanation:
the volume of sphere = 4 πr²
121.5 π = 4 π r²
121.5 = 4 r²
r² = (4/121.5)
r² = 0.03292181
r = 0.01646091 cubic in

Question 27.
PROBLEM SOLVING
The inner core of Earth begins about 3200 miles below the surface of Earth and has a volume of about 581,000,000π cubic miles. Approximate the radius of Earth. Justify your answer.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids 10.3 28

Answer:
radius  of earth = 0.00240199 miles.

Explanation:
volume of sphere = (4/3) π r³
581,000,000 π  = (4/3) x 3.14 x r³
581,000,000= 1.3333 x 3.14 x r³
581,000,000= 4.18666667  r³
r³ = (4.18666667/581.000,000)
r³ = 0.00720597
r = 0.00240199 miles,

Question 28.
LOGIC
Your friend says that the volume of a sphere with radius r is four times the volume of a cone with radius r. When is this true? Justify your answer.
Answer:
No my friend is wrong.

Explanation:
volume of cone = πr² (h/3)
volume of sphere = (4/3) πr² x r
when the radius is equal to the height h
then the volume of a sphere with radius r is four times the volume of a cone with a radius r.

Lesson 10.4 Surface Areas and Volumes of Similar Solids

EXPLORATION 1

Comparing Similar Solids
Work with a partner.
a.You multiply the dimensions of the smallest cylinder by different factors to create the other four cylinders. Complete the table. Compare the surface area and volume of each cylinder with the surface area and volume of the smallest cylinder.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 1
b. Repeat part(a) using the square pyramids and table below.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 2

Answer:
a.  surface area of cylinder  1 = 12.56
b. surface area of cylinder  2 = 50.24
c. surface area of cylinder  3 = 113.04
d. surface area of cylinder  4 = 200.96
e.. surface area of cylinder  5 = 314

Explanation:
a. surface area of cylinder  1 = 2 πr² + 2 πrh
A = 2 x 3.14 x 1 + 2 x 3.14 x 1 x 1
A = 6.28 + 6.28
A = 12.56
volume of cylinder = πr²h
v = 3.14 x 1 x 1
v = 3.14
b. surface area of cylinder  2 = 2 πr² + 2 πrh
A = 2 x 3.14 x 2 x 2 + 2 x 3.14 x 2 x 2
A = 6.28 x 4 + 6.28 x 4
A = 25.12 + 25.12
A = 50.24
volume of cylinder = πr²h
v = 3.14 x 2 x 2
v = 3.14 x 4
v = 12.56
c. surface area of cylinder  1 = 2 πr² + 2 πrh
A = 2 x 3.14 x 3 x 3 + 2 x 3.14 x 3 x 3
A = 6.28 x 9 + 6.28 x 9
A = 56.52 +56.52
A = 113.04
volume of cylinder = πr²h
v = 3.14 x 3 x 3
v = 3.14 x 9
v = 28.26
d. surface area of cylinder  1 = 2 πr² + 2 πrh
A = 2 x 3.14 x 4 x 4 + 2 x 3.14 x 4 x 4
A = 6.28 x 16 + 6.28 x 16
A = 100.48 + 100.48
A = 200.96
volume of cylinder = πr²h
v = 3.14 x 4 x 4
v = 3.14 x 16
v = 50.24
e. surface area of cylinder  1 = 2 πr² + 2 πrh
A = 2 x 3.14 x 5 x 5 + 2 x 3.14 x 5 x 5
A = 6.28 x 25 + 6.28 x 25
A = 157 + 157
A = 314
volume of cylinder = πr²h
v = 3.14 x 5 x 5
v = 3.14 x 25
v = 78.5

Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 3

Try It

Question 1.
Cylinder D has a radius of 7.5 meters and a height of 4.5 meters. Which cylinder in Example 1 is similar to Cylinder D?

Answer:
volume of cylinder = 794.8125 cu. meters.

Explanation:
volume of cylinder = πr²h
v = 3.14 x 7.5 x 7.5 x 4.5
v = 3.14 x 56.25 x 4.5
v = 3.14 x 253.125
v = 794.8125 cu. meters.

Question 2.
The prisms at the right are similar. Find the missing width and length.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 4

Answer:
volume = 1760 cubic in

Explanation:
the volume of rectangular prism = lwh
where l= length, w = weight, h= height
l = 11,w = 8 , h = 20 given
v= 11 x 8 x 20
v = 88 x 20
v =  1760 cubic in

The solids are similar. Find the surface area of the red solid. Round your answer to the nearest tenth.
Question 3.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 5

Answer:
volume = 440 cubic m

Explanation:
volume of rectangular prism = lwh
where l= length, w = weight, h= height
l  = 11,w = 8 , h = 5 given
v= 11 x 8x 5
v = 11 x 40
v =  440 cubic m

Question 4.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 6

Answer:
Volume of cylinder= 0.17840909 cu. cm

Explanation:
Volume of cylinder = πr² h
where π = 3.14
r = 2.5
110 = 3.14 x 2.5 x 2.5 x h
110 = 3.14 x 6.25 h
110= 19.625 h
h = (19.625/110)
h = 0.17840909 sq cm

Question 5.
The pyramids at the left are similar. Find the volume of the red pyramid. Round your answer to the nearest tenth.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 7

Answer:
volume of red pyramid = 0.444 cubic in

Explanation:
the volume of the pyramid =( l x w x h/3)
v = 9 given, width = 4 h = 3
9=( 4 x 3h /3)
9 = 4h
h = (4/9)
h = 0.444 cubic in

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 6.
IDENTIFYING SIMILAR SOLIDS
Cone A and Cone B are right cones. Cone B has a radius of 1.25 feet and a height of 3 feet. Are the cones similar?
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 8

Answer:
No the cones are not similar.

Explanation:
volume of  cone  A =πr² (h/3)
given that r = 5 ,h = 12
v = 3.14 x 5 x 5 x (12/3)
v = 3.14 x 25 x (12/3)
v =3.14 x 25 x 4
v= 3.14 x100
v = 314  cu. ft
volume of  cone  B =πr² (h/3)
given that r = 1.25 ,h = 3
v = 3.14 x 1.25 x 1.25 x (3/3)
v = 3.14 x 1.5625 x (3/3)
v =3.14 x 1.5625 x 1
v= 3.14 x1.5625
v = 4.90625 cu. ft

Question 7.
FINDING A MISSING MEASURE
A cylinder with a radius of 4 inches r and a height of 6 inches is similar to a cylinder with a radius of r inches and a height of 9 inches. What is the value of r?
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 9

Answer:
The value of r = 3 yds

Explanation:
volume of  cylinder  =πr² (h/3)
given that r = 4 ,h = 6
v = 3.14 x 4 x 4 x (6/3)
v = 3.14 x 16 x (6/3)
v =3.14 x 16 x 2
v= 3.14 x 32
v = 100.48

Question 8.
FINDING SURFACE AREA AND VOLUME
The rectangular prisms shown are similar. Find the surface area and volume of the red rectangular prism .

Answer:
The surface area of rectangular prism =2(lw +lh +wh)
the volume of rectangular prism = lwh

Explanation:
The surface area of rectangular prism =2(lw +lh +wh)
where h = height, w = width, l = length
the volume of rectangular prism = lwh

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 9.
Two snails have shells that are similar in shape. The younger snail has a shell with a height of 3.9 centimeters and a volume of 3 cubic centimeters. The older snail has a shell with a volume of 10 cubic centimeters. Estimate the height of the older snail’s shell.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 10

Answer:
The height of the older snails shell = 0.942 cm

Explanation:
the volume of  cylinder  =πr² (h/3)
given that r = 3 ,v = 10
10 = 3.14 x 3 x 3 x (h/3)
10 = 3.14 x 3 x h
10 =3.14 x 3h
10= 9.42 h
h = (9.42/10)
h = 0.942 cm

Question 10.
Two barrels filled with sand are similar in shape. The smaller barrel has a height of 4 feet and a volume of 4.5 cubic feet. The larger barrel has a height of 6 feet. What is the weight of the sand in the larger barrel? Round your answer to the nearest tenth.(One cubic foot of sand weighs about 110 pounds.)

Answer:
The weight of the sand in the larger barrel  = 18 cubic feet

Explanation:
Given that the smaller barrel h = 4 ft and v = 4.5 cubic ft
weight = 4 x 4.5
weight = 18 cubic feet
larger barrel h =  6feet, v= 3 cubic feet,
weight = 3 x 6
weight = 18 cubic feet
1 cubic ft = 110 pounds

Question 11.
Two trunks are similar in shape. The larger trunk has a length of 6 feet and a surface area of 164.25 square feet. The smaller trunk has a length of 4 feet. The materials needed to manufacture each trunk cost $0.60 per square foot. What is the total cost of the materials needed to manufacture the smaller trunk?
Answer:

Surface Areas and Volumes of Similar Solids Homework & Practice 10.4

Review & Refresh

Find the volume of the sphere. Round your answer to the nearest tenth.
Question 1.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 11

Answer:
volume of the sphere= 5,558.52222 cubic cm

Explanation:
volume of sphere = (4/3) πr² x r
v  = (4/3) x 3.14 x r³
where r =11
v = 1.33 x 3.14  x 11 x 11 x 11
v = 1.33 x 3.14 x 1,331
v = 1.33 x 4,179.34
v = 5,558.52222 cubic cm

Question 2.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 12

Answer:
volume of the sphere= 380.556225 cubic ft

Explanation:
volume of sphere = (4/3) πr² x r
v  = (4/3) x 3.14 x r³
where r =4.5
v = 1.33 x 3.14  x 4.5 x 4.5 x 4.5
v = 1.33 x 3.14 x 91.125
v = 1.33 x 286.1325
v = 380.556225 cubic ft

Question 3.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 13

Answer:
volume of the sphere=902.0592 cubic mm

Explanation:
volume of sphere = (4/3) πr² x r
v  = (4/3) x 3.14 x r³
where r =6
v = 1.33 x 3.14  x 6 x 6 x 6
v = 1.33 x 3.14 x 216
v = 1.33 x 678.24
v = 902.0592 cubic mm

Question 4.
Which system of linear equations has no solution?
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 14
Answer:
Option c has no solution.

Explanation:
if we take x = 2
A. y = 4x + 1 = 4(2) + 1= 9 , y = – 4x + 1 = -8 + 1= -7
b. Y = 2x – 7 = 4 – 7 = -3 , y = 2x + 7 = 4 + 7 = 11
c. 3x + y = 1 , y = 1 – 6 y = -5 , 6x + 2y = 2 = 12 + 2y = 2,2y =- 10  y = -5
Concepts, Skills, & Problem Solving

COMPARING SIMILAR SOLIDS All of the dimensions of the solid are multiplied by a factor of k. How many times greater is the surface area of the new solid? How many times greater is the volume of the new solid? (See Exploration 1, p. 445.)
Question 5.
k = 5
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 15

Answer:
25 times greater.
volume of new solid = 125 cubic ft

Explanation:
volume of  prism = lwh
where l= length, w = weight, h= height
l = 5 ,w = 5 , h = 5 given
v= 5 x 5 x 5
v = 5 x 25
v =  125  cubic ft

Question 6.
k = 10
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 16

Answer:
volume of  new cone= 1,046.666 cubic cm

Explanation:
volume of  cone  =πr² (h/3)
given that r = 10 ,h = 10
v = 3.14 x 10 x 10 x (10/3)
v = 3.14 x 100 x (10/3)
v =3.14 x 100 x 3.33
v= 3.14 x 333.33
v = 1,046.666 cubic cm

IDENTIFYING SIMILAR SOLIDS Determine whether the solids are similar.
Question 7.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 17

Answer:
The solida are  similar

Explanation:
volume of  small prism = lwh
where l= length, w = weight, h= height
l = 2 ,w = 1 , h = 3 given
v= 2 x 1 x 3
v = 2 x 3
v =  6  cubic in
volume of  large prism = lwh
where l= length, w = weight, h= height
l = 6 ,w = 3 , h = 9 given
v= 6 x 3 x 9
v = 2 x 27
v =  54 cubic in

Question 8.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 18

Answer:
The solida are not similar

Explanation:
surface area  of  large prism =2 (lw + wh +1h)
where l= length, w = weight, h= height
l = 4 ,w = 2 , h = 4 given
v=2( 4 x 2 + 2 x 4 + 4 x 4)
v = 2 (8 + 8+ 16)
v =  2( 32)
v = 64 cubic in
surface area  of small prism =2 (lw + wh +1h)
where l= length, w = weight, h= height
l = 2 ,w = 1 , h = 4 given
v=2( 2 x 1 + 1 x 4 + 2 x 4)
v = 2 (2 + 4+ 8)
v =  2( 16)
v = 32 cubic in

Question 9.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 19

Answer:
The pyramids are  similar.

Explanation:
surface area of triangular pyramid 1 = area of faces + base
area of face 1 = 5
area of face 2 = 5
area of face 3 = 6.5
area of face 4 = 6
area of base = 5
A= 5 + 5 + 6.5 + 6 + 5
A = 10 + 6.5 + 11
A = 21 + 6.5
A = 27.5
surface area of triangular pyramid 2 = area of faces + base
area of face 1 = 10
area of face 2 = 10
area of face 3 = 13
area of face 4 = 12
area of base = 10
A= 10 + 10 + 13 + 12 + 10
A = 20 + 13 + 22
A = 42 + 13
A = 55

Question 10.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 20

Answer:
Two solids are not similar.

Explanation:
volume of  cone 1 =πr² (h/3)
given that  r=9 ,h = 12
v = 3.14 x 9 x 9 x (12/3)
v = 3.14 x 9 x9 x 4
v =3.14 x 81 x 4
v = 3.14 x 324
h = 1,017.36sq m
volume of  cone 2 =πr² (h/3)
given that  r=20 ,h = 21
v = 3.14 x 20 x 20 x (21/3)
v = 3.14 x20 x 20 x 7
v =3.14 x 400 x 7
v = 3.14 x 2800
h =  8,792 sq m

FINDING MISSING MEASURES IN SIMILAR SOLIDS The solids are similar. Find the missing measure(s).
Question 11.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 21

Answer:
volume of the sphere=2.5 cu. feet

Explanation:
volume of sphere = (4/3) πr² x r
v  = (4/3) x 3.14 x r³
where r =5
v = 1.33 x 3.14  x 5 x 5 x 5
v = 1.33 x 3.14 x 125
v = 1.33 x 392.5
v = 2.5 cu. feet

Question 12.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 22

Answer:
surface area of triangular pyramid  = 54 cubic m

Explanation:
surface area of triangular pyramid  = area of faces + base
area of face 1 = 12
area of face 2 = 6
area of face 3 = 13
area of face 4 = 5
area of base = 18
A= 12 + 6 + 13 + 5 + 18
A = 18 + 13 + 23
A = 18 + 36
A = 54  cubic m

Question 13.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 23

Answer:
volume = 11.5 cu. mm

Explanation:
volume of triangular prism = (bhl/2)
b = 4.6 , h = 4.6 , l = 6.4 given
v = (4.6 x 4.6 x 6.4/2)
v = (21.16 x 6.4/2)
v = (135.424/2)
v = 11.5 cu. mm

Question 14.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 24

Answer:
volume of cone = 8.0384 cu. in

Explanation:
volume of  cone  =πr² (h/3)
given that  r=1.6 ,h = 3
v = 3.14 x 1.6 x 1.6 x (3/3)
v = 3.14 x 1.6  x1.6  x 1
v =3.14 x 2.56 x 1
v = 3.14 x 2.56
v = 8.0384 cu. in

FINDING SURFACE AREA The solids are similar. Find the surface area of the red solid. Round your answer to the nearest tenth if necessary.
Question 15.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 25
Answer:
The surface area of the red solid = 90 sq m

Explanation:
Given that the surface area of blue solid = 40 sq m
s0 the surface area of the red solid = 60 sq m
4  x 10 = 40
9 x 10 = 90 sq m

Question 16.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 26

Answer:
volume of the sphere= 14,094 cu. in

Explanation:
volume of sphere = (4/3) πr² x r
v  = (4/3) x 3.14 x r³
where r =15
v = 1.33 x 3.14  x 15 x 15 x 15
v = 1.33 x 3.14 x 3375
v = 1.33 x 10,597.5
v = 14,094.675 cu. in

Question 17.
FINDING SURFACE AREA
The ratio of the corresponding linear measures of two similar cans is 4 to 7. The smaller can has a surface area of 220 square centimeters. Find the surface area of the larger can.

Answer:
The surface area of larger can = 55 sq cm

Explanation:
Given that the smaller can has a surface area of 220 sq cm
The ratio of two similar cans is 4: 7
(220/5) = 55 sq cm

FINDING VOLUME The solids are similar. Find the volume of the red solid.
Question 18.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 27

Answer:
The volume of red soil =  70 cu. mm

Explanation:
surface area of triangular pyramid  = area of faces + base
area of face 1 = 21
area of face 2 = 21
area of face 3 = 7
area of face 4 = 7
area of base = 14
A= 21 + 21 + 7 + 7 + 14
A = 42 + 14 + 14
A = 42 + 28
A = 70 cu. mm

Question 19.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 28

Answer:
height  of cylinder=13,564.8 ft

Explanation:
Volume of cylinder = πr² h
where π = 3.14
r = 12
v = 3.14 x 12 x 12 x h
7850 = 3.14 x 144 h
7850= 452.16 h
h = (452.16/7850)
h = 13,564.8 sq ft

Question 20.
YOU BE THE TEACHER
The ratio of the corresponding linear measures of two similar solids is 3:5. The volume of the smaller solid is 108 cubic inches. Your friend finds the volume of the larger solid. Is your friend correct? Explain your reasoning.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 29

Answer:
Yes my friend is correct.

Explanation:
the volume of smaller solid is 108 cubic inches.
(108/v) = (3/5) x (3/5)
(108/v) = (9/25)
v = 300 cubic in

Question 21.
MODELING REAL LIFE
A hemisphere-shaped mole has a diameter of 5.7 millimeters and a surface area of about 51 square millimeters. The radius of the mole doubles. Estimate the new surface area of the mole.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 30

Answer:
The new surface area of the mole = 19.742 sq. mm

Explanation:
surface area of sphere = (4/3) πr² x r
A = (4/3) x 3.14 x r³
where r = 2.85
A = 1.33 x 3.14  x 2.85 x 2.85
A= 1.33 x 3.14 x 8.1225
A = 1.33 x 25.50465
A = 19.742 sq. mm

Question 22.
REASONING
The volume of a 1968 Ford Mustang GT engine is 390 cubic inches. Which scale model of the Mustang has the greater engine volume, a 1 : 18 scale model or a 1 : 24 scale model? How much greater is it?
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 31
Answer:

Question 23.
DIG DEEPER!
You have a small marble statue of Wolfgang Mozart. It is 10 inches tall and weighs 16 pounds. The original marble statue is 7 feet tall.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 32
a. Estimate the weight of the original statue. Explain your reasoning.
b. If the original statue were 20 feet tall, how much would it weigh?

Answer:
a. The weight of the original statue = 84/10 cubic pounds
b. The original statue weight = 221 lb

Explanation:
a. The weight of the original statue = 7 ft
1 ft = 12 pounds
7 x 12 / 10 = 84/10 cubic pounds.
b. given that the original statue was 20 ft
221,184 lb

Question 24.
REPEATED REASONING
The nesting dolls are similar. The largest doll is 7 inches tall. Each of the other dolls is 1 inch shorter than the next larger doll. Make a table that compares the surface areas and the volumes of the seven dolls.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 33

Answer:

Explanation:
In the above given figure the larger doll is 7 inches tall.
Each of the other doll is 1 inch shorter than the next larger doll.

Question 25.
PRECISION
You and a friend make paper cones to collect beach glass. You cut out the largest possible three-fourths circle from each piece of paper.
Big Ideas Math Solutions Grade 8 Chapter 10 Volume and Similar Solids 10.4 34
a. Are the cones similar? Explain your reasoning.
b. Your friend says that because your sheet of paper is twice as large, your cone will hold exactly twice the volume of beach glass. Is this true? Explain your reasoning.

Answer:
a. Yes, the cones are similar.
b.No my friend is correct.

Explanation:
a. all circles are similar, the slant height and the circumference of the base of the cones are proportional .
b. my cone holds about 2 times as much my friend cone.

Volume and Similar Solids Connecting Concepts

Using the Problem-Solving Plan
Question 1.
A yurt is a dwelling traditionally used in Mongolia and surrounding regions. The yurt shown is made of a cylinder and a cone. What is the volume of the yurt?
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cc 1
Understand the problem
You know that the yurt is made of a cylinder and a cone. You also know several dimensions. You are asked to find the volume of the yurt.
Make a plan.
Use the Pythagorean Theorem to find the height of the cone. Then use the formulas for the volume of a cylinder and the volume of a cone to find the volume of the yurt.
Solve and check.
Use the plan to solve the problem. Then check your solution.

Answer:
volume of hurt = 4855 cu. ft

Explanation:
volume of  cone  =πr² (h/3)
given that  r = 15 ,h = 7
v = 3.14 x 15 x 15 x (17/3)
v = 3.14 x 225  x (17/3)
v =3.14 x 225 x 5.666
v = 3.14 x 1275
v = 4,003
volume of cylinder = πr² h
where π = 3.14  d =
r = 3 , h = 30
v = 3.14 x 3 x 3 x 30
v = 3.14 x 9 x 30
v= 3.14 x 270
h = 847.8
4008 +847 =4855

Question 2.
supervoidA spherical , a region in space that is unusually empty, has a diameter of 1.8 × 19 0light-years. What is the volume of the supervoid? Use 3.14 for π. Write your answer in scientific notation.

Answer:
volume of supervoid =3.75858000000000 light years

Explanation:
volume of sphere = (4/3) πr³
v = (4/3) x 3.14 x r³
v = 1.33 x 3.14 x 0.9
v = 2.826 x 1.33
v = 3.75858000000000 light years

Question 3.
The cylinders are similar. The volume of Cylinder A is \(\frac{8}{27}\) times the volume of Cylinder B. Find the volume of each cylinder. Round your answers to the nearest tenth.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cc 2

Answer:
volume of cylinder = 452.16 cu. cm

Explanation:
the volume of cylinder = πr² h
where π = 3.14
r = 4 , h = 9
v = 3.14 x 4 x 4 x 9
v = 3.14 x 16 x 9
v= 3.14 x 144
h = 452.16 sq cm

Performance Task

Packaging Salsa
At the beginning of this chapter, you watched a STEAM Video called “Canning Salsa.” You are now ready to complete the performance task related to this video, available at BigIdeasMath.com. Be sure to use the problem-solving plan as you work through the performance task.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cc 3

Volume and Similar Solids Chapter Review

Review Vocabulary

Write the definition and give an example of each vocabulary term.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 1

Graphic Organizers

You can use a Summary Triangle to explain a concept. Here is an example of a Summary Triangle for volume of a cylinder.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 2

Choose and complete a graphic organizer to help you study the concept.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 3
1. volume of a cone
2. volume of a sphere
3. volume of a composite solid
4. surface areas of similar solids
5. volumes of similar solids

Answer:
cone = A solid or hollow object which tapers from a circular or roughly circular base to a point.
hemisphere = a half of the celestial sphere as divided into two halves by the horizon.
sphere = a round solid figure, or its surface, with every point on its surface equidistant from its center.
similar solids = two solids are similar if they are the same type of solid and their corresponding radii, heights, base lengths, widths, etc. are proportional.

Chapter Self-Assessment

As you complete the exercises, use the scale below to rate your understanding of the success criteria in your journal.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 4

10.1 Volumes of Cylinders (pp. 427–432)
Learning Target: Find the volume of a cylinder. Find the volume of the cylinder. Round your answer to the nearest tenth.
Question 1.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 5

Answer:
volume of cylinder =1,236.375 cu. ft

Explanation:
volume of cylinder = πr² h
where π = 3.14  d = 15 r = (d/2)
r = 7.5 , h = 7 given
v = 3.14 x 7.5 x 7.5 x 7
v = 3.14 x 56.25 x 7
v = 3.14 x 393.75
v = 1,236.375 cu. ft

Question 2.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 6

Answer:
volume of cylinder =62.8 cu. cm

Explanation:
volume of cylinder = πr² h
where π = 3.14
r = 2 , h = 5 given
v = 3.14 x 2 x 2 x 5
v = 3.14 x 4 x 5
v = 3.14 x 20
v = 62.8 cu. cm

Find the missing dimension of the cylinder. Round your answer to the nearest whole number.
Question 3.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 7

Answer:
height of cylinder = 0.25232143 sq in

Explanation:
volume of cylinder = πr² h
where π = 3.14
r = 1.5 , v = 28 given
28 = 3.14 x 1.5 x 1.5 x h
28= 3.14 x 2.25h
28 = 7.065 h
h = 7.065/28
h = 0.25232143 sq in

Question 4.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 8

Answer:
radius of cylinder =60.501 sq m

Explanation:
volume of cylinder = πr² h
where π = 3.14
h = 20 m, v = 7599 given
7599= 3.14 x r x r x 20
7599= 3.14 x 20 r²
7599 = 62.8 r²
r² = 7599/62.8
r² = 121.00 m
r = 60.501 sq m

Question 5.
You are buying two cylindrical cans of juice. Each can holds the same amount of juice.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 9
a. What is the height of Can B?
b. About how many cups of juice does 3≈each can hold? (1 in.3 ≈ 0.07 cup)

Answer:
a.The height of can B = 0.074 in
b. The cups of juice does 3 each can hold = 21 cups

Explanation:
volume of cylinder = πr² h
where π = 3.14
h = 6, r = 3given
v = 3.14 x 3 x 3 x 6
v= 3.14 x 9 x 6
v = 3.14 x 54
v = 169.56 sq in
volume of cylinder = πr² h
where π = 3.14
v = 169.56, r = 2given
169.56 = 3.14 x 2 x 2 h
169.56= 3.14 x 4 h
169.56= 12.56 h
h = 0.074 in
b. 3 x 0.07
0.21
21 cups.

Question 6.
You triple the radius of a cylinder. How many times greater is the volume of the new cylinder? Explain.

Answer:
3 times greater than the volume of the new cylinder.

Explanation:
Given that the radius is tripled.
volume of cylinder = πr⁵ h

10.2 Volumes of Cones (pp. 433–438)
Learning Target: Find the volume of a cone.

Find the volume of the cone. Round your answer to the nearest tenth.
Question 7.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 10

Answer:

volume of  cone= 803.84 cu. m

Explanation:
volume of  cone  =πr² (h/3)
given that r = 8 ,h = 12
v = 3.14 x 8 x 8 x (12/3)
v = 3.14 x 64 x (12/3)
v =3.14 x 64 x 4
v= 3.14 x 256
v = 803.84 cu. m

Question 8.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 11

Answer:
volume of  cone= 41.8666 cu. cm

Explanation:
volume of  cone  =πr² (h/3)
given that r = 2 ,h = 10
v = 3.14 x 2 x 2 x (10/3)
v = 3.14 x 4 x (10/3)
v =3.14 x 4 x 3.33
v= 3.14 x 13.33
v = 41.8666 cu. cm

Find the missing dimension of the cone. Round your answer to the nearest tenth.
Question 9.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 12

Answer:
radius of  cone= 0.006173  in

Explanation:
volume of  cone  =πr² (h/3)
given that ,h = 36
3052= 3.14 x r x r (36/3)
3052 = 3.14 x 12 r²
3052 =37.68 r²
r²= 0.012346
v = 0.006173 cu. in

Question 10.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 13

Answer:
height of  cone=0.041866 sq mm

Explanation:
volume of  cone  =πr² (h/3)
given that ,r =6
900= 3.14 x 6 x 6 (h/3)
900 = 3.14 x 12 h
900 =37.68 h
h= (37.68/900)
h  = 0.041866 sq mm

Question 11.
The paper cup can hold 84.78 cubic centimeters of water. What is the height of the cup?
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 14

Answer:
height of  cone=  0.111111 cm

Explanation:
volume of  cone  =πr² (h/3)
given that ,r =3
84.78= 3.14 x 3 x 3 (h/3)
84.78 = 3.14 x 3 h
84.78 =9.42 h
h= (9.42/84.78)
h  = 0.111111 cm

10.3 Volumes of Spheres (pp. 439–444)
Learning Target: Find the volume of a sphere.

Find the volume of the sphere. Round your answer to the nearest tenth.
Question 12.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 15

Answer:
volume of the sphere=7,216.4736 cubic ft

Explanation:
volume of sphere = (4/3) πr² x r
v  = (4/3) x 3.14 x r³
where r =12
v = 1.33 x 12  x 12 x 12 x 3.14
v = 1.33 x 3.14 x 1728
v = 1.33 x 5,425.92
v = 7,216.4736 cubic ft

Question 13.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 16

Answer:
volume of the sphere= 5,558.52222 cu. cm

Explanation:
volume of sphere = (4/3) πr² x r
v  = (4/3) x 3.14 x r³
where r =11
v = 1.33 x 11  x 11 x 11 x 3.14
v = 1.33 x 3.14 x 1331
v = 1.33 x 4,179.34
v = 5,558.52222 cu. cm

Question 14.
The volume of a water walking ball is \(\frac{4}{3}\)π cubic meters. Find the diameter of the water walking ball.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 17
Answer:

Find the volume of the composite solid. Round your answer to the nearest tenth if necessary.
Question 15.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 18

Answer:
volume of  cone=  452.16 cu. m

Explanation:
volume of  cone  =πr² (h/3)
given that ,r = 6, h = 12
v= 3.14 x 6 x 6 (12/3)
v = 3.14 x 36 x (12/3)
v =3.14 x 36 x 4
v= 3.14 x 144
v  = 452.16 cu. m

Question 16.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 19

Answer:
The volume of solid=  31 cu. ft

Explanation:
surface area of triangular pyramid  = area of faces + base
area of face 1 = 6
area of face 2 = 6
area of face 3 = 2
area of face 4 = 5
area of base = 12
A= 6 + 6 + 2 + 5 + 12
A = 12 + 7 + 12
A = 24 + 7
A = 31   sq ft

Question 17.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 20.1

Answer:
volume of cylinder =50.24 cu. cm

Explanation:
volume of cylinder = πr² h
where π = 3.14
r = 2 , h = 4 given
v = 3.14 x 2 x 2 x 4
v = 3.14 x 16
v= 50.24 cu. cm

Question 18.
The volume of water that a submerged object displaces is equal to the volume of the object. Find the radius of the sphere. Round your answer to the nearest tenth.(1 mL = 1 cm3)
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 20
Answer:

10.4 Surface Areas and Volumes of Similar Solids (pp. 445–452)
Learning Target: Find the surface areas and volumes of similar solids.

Question 19.
Determine whether the solids are similar.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 21

Answer:
Volume of cylinder= 0.17840909 cu. cm

Explanation:
Volume of cylinder = πr² h
where π = 3.14
r = 2.5
110 = 3.14 x 2.5 x 2.5 x h
110 = 3.14 x 6.25 h
110= 19.625 h
h = (19.625/110)
h = 0.17840909 sq cm

Question 20
The prisms are similar. Find the missing measures.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 22

Answer:

Question 21.
The prisms are similar. Find the surface area of the red prism. Round your answer to the nearest tenth.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 23
Answer:
volume = 67.712 cubic cm

Explanation:
volume of triangular prism = (bhl/2)
b = 4.6 , h = 4.6 , l = 6.4 given
v = (4.6 x 4.6 x 6.4/2)
v = (21.16 x 6.4/2)
v = (135.424/2)
v = 67.712 cubic  cm

Question 22.
The pyramids are similar. Find the volume of the red pyramid.
Big Ideas Math Answer Key Grade 8 Chapter 10 Volume and Similar Solids cr 24

Answer:
The volume of red soil =  70 cu. mm

Explanation:
surface area of triangular pyramid  = area of faces + base
area of face 1 = 21
area of face 2 = 21
area of face 3 = 7
area of face 4 = 7
area of base = 14
A= 21 + 21 + 7 + 7 + 14
A = 42 + 14 + 14
A = 42 + 28
A = 70  sqmm

Question 23.
The ratio of the corresponding linear measures of two similar jewelry boxes is 2 to 3. The larger jewelry box has a volume of 162 cubic inches. Find the volume of the smaller jewelry box.

Answer:
volume of the jewelry box = 36.4 cubics in

Explanation:
given that 2: 3 ratio
(162/v) = (2/3) x (2/3)
(162/v) = (4/9)
4v = 1458
v = (1458/4)
v = 36.4 cubic in

Volume and Similar Solids Practice Test

Find the volume of the solid. Round your answer to the nearest tenth.
Question 1.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids pt 1

Answer:
volume of the sphere=33,409.6 cu. mm

Explanation:
volume of sphere = (4/3) πr² x r
v  = (4/3) x 3.14 x r³
where r =20
v = 1.33 x 20 x 20 x 20 x 3.14
v = 1.33 x 3.14 x 8000
v = 1.33 x 25,120
v = 33,409.6 cu. mm

Question 2.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids pt 2

Answer:
volume of  cone=  452.16 cu. m

Explanation:
volume of  cone  =πr² (h/3)
given that ,r = 6, h = 12
v= 3.14 x 6 x 6 (12/3)
v = 3.14 x 36 x (12/3)
v =3.14 x 36 x 4
v= 3.14 x 144
v  = 452.16 cu. m

Question 3.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids pt 3

Answer:
volume of the sphere=33,409.6 cu. mm

Explanation:
volume of sphere = (4/3) πr² x r
v  = (4/3) x 3.14 x r³
where r =20
v = 1.33 x 20 x 20 x 20 x 3.14
v = 1.33 x 3.14 x 8000
v = 1.33 x 25,120
v = 33,409.6 cu. mm

Question 4.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids pt 4
Answer:
volume of  cone=  452.16 cu. m

Explanation:
volume of  cone  =πr² (h/3)
given that ,r = 6, h = 12
v= 3.14 x 6 x 6 (12/3)
v = 3.14 x 36 x (12/3)
v =3.14 x 36 x 4
v= 3.14 x 144
v  = 452.16 cu. m

Question 5.
The pyramids are similar.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids pt 5
a. Find the missing measures.
b. Find the surface area of the red pyramid.

Answer:
The volume of red soil =  70 cu. mm

Explanation:
surface area of triangular pyramid  = area of faces + base
area of face 1 = 21
area of face 2 = 21
area of face 3 = 7
area of face 4 = 7
area of base = 14
A= 21 + 21 + 7 + 7 + 14
A = 42 + 14 + 14
A = 42 + 28

Question 6.
You are making smoothies. You will use either the cone-shaped glass or the cylindrical glass. Which glass holds more? About how much more?
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids pt 6
Answer:
volume of  cone=  452.16 cu. m

Explanation:
volume of  cone  =πr² (h/3)
given that ,r = 6, h = 12
v= 3.14 x 6 x 6 (12/3)
v = 3.14 x 36 x (12/3)
v =3.14 x 36 x 4
v= 3.14 x 144
v  = 452.16 cu. m

Question 7.
The ratio of the corresponding linear measures of two similar waffle cones is 3 to 4. The smaller cone has a volume of about 18 cubic inches. Find the volume of the larger cone. Round your answer to the nearest tenth.

Answer: 24 cubic inches.

Explanation:
(18/v) = (3/4)
3v = 18 x 4
3v = 72
v = 24 cubic in

Question 8.
Draw two different composite solids that have the same volume but different surface areas.Explain your reasoning.
Answer:

Question 9.
There are 13.5π cubic inches of blue sand and 9π cubic inches of red sand in the cylindrical container. How many cubic inches of white sand are in the container? Round your answer to the nearest tenth.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids pt 9
Answer:
v = 169.56 cu. in
Explanation:
volume of cylinder = πr² h
where π = 3.14
h = 6, r = 3given
v = 3.14 x 3 x 3 x 6
v= 3.14 x 9 x 6
v = 3.14 x 54
v = 169.56 cu. in

Question 10.
Without calculating, determine which solid has the greater volume. Explain your reasoning.
Big Ideas Math Answers 8th Grade Chapter 10 Volume and Similar Solids pt 10

Answer:
prism has great volume.

Explanation:
the volume of the sphere is less than the volume of a prism.

Volume and Similar Solids Cumulative Practice

Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids cp 1
Question 1.
What is the value of 14 – 2\(\sqrt [ 3 ]{ 64 } \) ?
A. – 50
B. – 2
C. 6
D. 48
Answer:
option A Is correct

Explanation:
14 – 2 (3/64 x 100)
12 (150/32)
12 x (75/16)
-50

Question 2.
What is the volume of the cone? (Use \(\frac{22}{7}\) for π.)
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids cp 2

Answer:
volume of  cone=  4098. 8304 cubic cm

Explanation:
volume of  cone  =πr² (h/3)
given that ,r = 14, h = 20
v= 3.14 x 14 x 14 (20/3)
v = 3.14 x196 x (20/3)
v =3.14 x 196 x 6.66
v= 3.14 x 1305.36
v  = 4098. 8304

Question 3.
The cylinders are similar. What is the volume of the red cylinder?
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids cp 3
A. 6 cm
B. 150.75 cm3
C. 301.5 cm3
D. 603 cm3

Answer:
option D is correct.

Explanation:
(1206/2 ) = 603
large cylinder is 2 times greater than small cylinder.

Question 4.
A rectangle is graphed in the coordinate plane.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids cp 4.1
Which of the following shows Rectangle E’F’G’H’, the image of Rectangle EFGH after it is reflected in the -axis?
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids cp 4

Answer:
option  I is correct.

Explanation:
EFGH  is reflected in the -ve axis.

Question 5.
What are the ordered pairs shown in the mapping diagram?
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids cp 5
A. (2, 5), (4, – 2), (6, – 7), (8, 1)
B. (2, – 7), (4, – 2), (6, 1), (8, 5)
C. (2, 5), (4, 1), (6, – 2), (8, – 7)
D. (5, 2), (- 2, 4), (- 7, 6), (1, 8)

Answer:
option A is correct.

Explanation:
(2, 5)
(4, -2)
(6, -7)
(8, 1)

Question 6.
What is \(0 . \overline{75}\) written as a fraction?
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids cp 6

Answer:

Question 7.
Solve the formula A = P + PI for I.
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids cp 7

Answer:
option I is correct.

Explanation:
A = P + PI
I = (A – P/P)
A = P + P (A – P/P)
A = A.

Question 8.
A cylinder has a volume of 1296 cubic inches. If you divide the radius of the cylinder by 12, what is the volume (in cubic inches) of the smaller cylinder?
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids cp 6

Answer:
The volume =0.1162963 cubic in

Explanation:
volume of  cylinder  =πr² (h/3)
given that r = 12 , v = 1296
1296 = 3.14 x 12 x 12 x (h/3)
1296 = 3.14 x 12x 4h
1296 =3.14 x  48 h
1296= 150.72 h
h =(150.72/1296)
h = 0.1162963 cubic in

Question 9.
The cost y (in dollars) for pounds of grapes is represented by y = 2x. Which graph represents the equation?
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids cp 9

Answer:
Option c is correct.

Explanation:
y = 2x
on the x axis the graph represents the straight line on x – axis.

Question 10.
You are making a giant crayon. What is the volume (in cubic centimeters) of the entire crayon? Show your work and explain your reasoning. (Use 3.14 for π.)
Big Ideas Math Answers Grade 8 Chapter 10 Volume and Similar Solids cp 10
Answer:
The volume = =75.34116 cubic cm

Explanation:
the volume of  cylinder  =πr² (h/3)
given that r = 3 ,h = 8
v = 3.14 x 3 x 3 x (8/3)
v = 3.14 x 9 x (8/3)
v =3.14 x 9 x 2.666
v= 3.14 x 23.994
v = 75.34116 cubic cm

Conclusion

We wish the knowledge shared regarding the Big Ideas Math Answers Grade 8 Ch 10 Volume and Similar Solids has helped you in your preparation. In case of any queries, do leave us your suggestions via the comment section and we will get back to you.

Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations

Big Ideas Math Answers Grade 8 Chapter 5

Big Ideas Math Answers Grade 8 Chapter 5 include questions on System of Linear Equations by Graphing, Substitution, Elimination, Connecting Concepts, etc. All the Problems in the Big Ideas Grade 8 Ch 5 System of Linear Equations are provided in a simple and easy-to-understand language. Learn the problem-solving methods used by referring to our Big Ideas Math Grade 8 Answers Chapter 5 System of Linear Equations and apply them to similar kinds of problems. Download the BIM Chapter 5 System of Linear Equations Answer Key and understand the related concepts in no time.

Big Ideas Math Book 8th Grade Answer Key Chapter 5 Systems of Linear Equations

Big Ideas Math Answers Grade 8 Ch 5 is curated by subject experts adhering to the latest syllabus guidelines. Practice as many times as possible and attempt the exams with utmost confidence and score well. Enhance your subject knowledge and gain a deeper understanding of concepts at the surface level. Simply click on the direct links available and begin preparing the respective topics in no time.

Performance

Lesson: 1 Solving Systems of Linear Equations by Graphing

Lesson: 2 Solving Systems of Linear Equations by Substitution

Lesson: 3 Solving Systems of Linear Equations by Elimination

Lesson: 4 Solving Special Systems of Linear Equations

Chapter: 5 – Systems of Linear Equations

Systems of Linear Equations STEAM Video/Performance

STEAM Video

Gold Alloys

An alloy is a mixture of different metals melted together at high temperatures. A dental filling is created using a gold alloy. What are other uses of alloys?
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 1.1

Watch the STEAM Video “Gold Alloys.” Then answer the following questions.

Question 1.
Enid says that the proportion of gold in an alloy can be measured in karats. For example, 24 karats represent 100% gold and 18 karats represent 75% gold.
a. A dental filling is 9 karats. What percent of the filling is gold?
b. A watch is 60% gold. How many karats is the watch?

Answer:
a. 37.5% of the filling is gold.
b. 14.4 karats are the watch

Explanation:
a. A dental filling is 9 karats.
24 karats represent 100% gold
So, 9 karats = (100 * 9)/24
= 900/24
= 37.5%
37.5% of the filling is gold.
b. A watch is 60% gold
24 karats represent 100% gold
So, watch = (60 * 24)/100
= 1440/100
= 14.4
14.4 karats are the watch

Question 2.
What percent gold is each described alloy?
a. A mixture of 2 grams 10-karat gold and 2 grams 14-karat gold
b. A mixture of 6 grams 24-karat gold and 4 grams 9-karat gold

Answer:
a. 200%
b. 750%

Explanation:
a. 24 karats represents 100% gold
10 karat gold is 125/3 %
14 -karat gold gold is 175/3 %
2 grams 10-karat gold = 2(125/3) = 250/3
2 grams 14-karat gold = 2(175/3) = 350/3
The alloy mixture = (250 + 350)/3
= 600/3 = 200
b. 6 grams 24-karat gold
6 grams = 600%
9-karat gold = 75/2
4 grams 9-karat gold = 4(75)/2 = 150%
The alloy mixture = 600% + 150% = 750%

Performance Task

Mixing Alloys

After completing this chapter, you will be able to use the concepts you learned to answer the questions in the STEAM Video Performance Task. You will be given a list of gold alloys available at a jewelry store.
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 1
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 2
You will use a system of equations to determine the amounts of the given alloys that a jeweler needs to create a new alloy. Why might a jeweler need to create a mixture with a specific proportion of gold?

Systems of Linear Equations Getting Ready for Chapter 5

Getting Ready for Chapter 5

Chapter Exploration

Question 1.
Work with a partner. Your family starts a bed-and-breakfast. You spend $500 fixing up a bedroom to rent. The cost for food and utilities is $10 per night. Your family charges $60 per night to rent the bedroom.
a. Write an equation that represents the costs.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 3
b. Write an equation that represents the revenue (income).
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 4
c. A set of two (or more) linear equations is called a system of linear equations. Write the system of linear equations for this problem.

Answer:
a. C = 10x + 500
b. R = 60x
c. The system of linear equations are
C = 10x + 500
R = 60x

Explanation:
a. Cost, C = $10 per night . Number of nights, x + $500
C = 10x + 500
b.
Revenue, R = $60 per night . Number of nights x
R = 60x
c. The system of linear equations are
C = 10x + 500
R = 60x

Question 2.
Work with a partner. Use a graphing calculator to solve the system.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 5
a. Enter the equations into your calculator. Then graph the equations. What is an appropriate window?
b. On your graph, how can you determine which line is the graph of which equation? Label the equations on the graph shown.
c. Visually estimate the point of intersection of the graphs.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 6
d. To find the solution, use the intersect feature to find the point of intersection. The solution is Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 7

Answer:
The solution is (10, 600)

Explanation:
 Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations
The solution is (10, 600)

Vocabulary

The following vocabulary terms are defined in this chapter. Think about what each term might mean and record your thoughts.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 7.1

Lesson 5.1 Solving Systems of Linear Equations by Graphing

EXPLORATION 1
Work with a partner. You charge your headphones and your phone. The equations below represent the battery powers p% of the devices after x minutes of charging.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 8
a. You check the battery power of each device every 10 minutes. Copy and complete the table. How do the devices’ battery powers compare?
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 8.1
b. After how much time do the devices have the same battery power? What is the battery power at that time? Justify your answer.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 9
c. The solutions of a linear equation are all the points on its graph. How many solutions can two linear equations share? Explain your reasoning.
d. Graph the battery power equations in the same coordinate plane. What do you notice?
e. Use a graphing calculator to check your answers in part(b). Explain your method.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 10

Answer:
a. Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 30
d. The solution is (75/2, 125/2)

Explanation:
a. Headphones equation is p = 5/3 x
p1 = 5/3 (10) = 50/3, p2 = 5/3 (20) = 100/3, p3 = 5/3 (30) = 50, p4 = 5/3 (40) = 200/3, p5 = 5/3 (50) = 250/3
p6 = 5/3 (60) = 100
Phone equation is p = x + 25
p1 = 10 + 25 = 35, p2 = 20 + 25 = 45, p3 = 30 + 25 = 55, p4 = 40 + 25 = 65
p5 = 50 + 25 = 75, p6 = 60 + 25 = 85
b. Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 31
The solution is (75/2, 125/2)
p = 5/3 x, p = x + 25
Put x = 75/2
p = 5/3 (75/2)
= 125/2
p = 75/2 + 25
= 125/2

5.1 Lesson

Try It

Solve the system by graphing.

Question 1.
y = x – 1
y  = -x + 3

Answer:
The solution is (1, 2).

Explanation:
The given systems of linear equations are y = x – 1, y  = -x + 3
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 1
The graphs appear to intersect at (1, 2)
So, the solution is (1, 2)

Question 2.
y = -5x + 14
y = x – 10

Answer:
The solution is (4, -6)

Explanation:
The given systems of linear equations are y = -5x + 14, y = x – 10
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 2
The lines intersect at (4, -6)
So, the solution is (4, -6)

Question 3.
y = x
y = 2x + 1

Answer:
The solution is (-1, -1)

Explanation:
The given systems of linear equations are y = x, y = 2x + 1
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 3
The lines intersect at (-1, -1)
So, the solution is (-1, -1)

Question 4.
y = -4x – 7
x + y = 2

Answer:
The solution is (-3, 5)

Explanation:
The given systems of linear equations are y = -4x – 7, x + y = 2
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 4
The lines intersect at (-3, 5)
So, the solution is (-3, 5)

Question 5.
x – y = 5
-3x +  y = -1

Answer:
The solution is (-2, -7)

Explanation:
The given systems of linear equations are x – y = 5, -3x +  y = -1
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 5
The lines intersect at (-2, -7)
So, the solution is (-2, -7)

Question 6.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 16

Answer:
The solution is (4, -8)

Explanation:
The given systems of linear equations are 1/2 x + y = -6, 6x + 2y = 8
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 7
The lines intersect at (4, -8)
So, the solution is (4, -8)

Self-Assessment for Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

SOLVING A SYSTEM OF LINEAR EQUATIONS
Solve the system by graphing.

Question 7.
y = x + 1
y = 4x +1

Answer:
The solution is (0, 1).

Explanation:
The given systems of linear equations are y = x + 1, y = 4x +1
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 8
The lines intersect at (0, 1)
So, the solution is (0, 1)

Question 8.
3x – y = -1
y = -x + 5

Answer:
The solution is (1, 4).

Explanation:
The given systems of linear equations are 3x – y = -1, y = -x + 5
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 9
The lines intersect at (1, 4)
So, the solution is (1, 4).

Question 9.
x + 2y = 3
-x + 3y = 7

Answer:
The solution is (-1, 2).

Explanation:
The given systems of linear equations are x + 2y = 3, -x + 3y = 7
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 10
The lines intersect at (-1, 2)
So, the solution is (-1, 2).

Question 10.
WRITING
Explain why the solution of a system of linear equations is the point of intersection of their graphs.

Answer:
The solution of a system of linear equations in two variables is an ordered pair that is a solution of each equation in the system. The ordered pair is obtained by drawing a graph for two equations and the point of intersection.

Question 11.
DIFFERENT WORDS, SAME QUESTION
Which is different? Find “both” answers.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 20

Answer:
The solution of the system is (1, 6)
The graphs of the equations intersect at (1, 6)
Ordered pair (1, 6) makes both equations true

Explanation:
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 32
The point of intersection is the solution.
The solution is (1, 6).

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 12.
Your family attends a comic convention. Each autograph costs $20 and each photograph costs $50. Your family buys a total of 5 autographs and photographs for $160. How many photographs does your family buy?
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 21

Answer:
The number of photographs the family buys will be 2.

Explanation:
Each autograph costs $20 and photograph costs $50
According to the question, the family buys a total of 5 items including both autographs and photographs for $160.
Let’s assume the number of autographs bought be x, while the number of photographs is 5 – x
Thus, cost to buy autographs will be 20* x = 20x and photographs will be 50(5 – x) = 250 – 50x
now, total cost becomes 20x + 250 – 50x, which will be equal to 160. lets find number of each items x
20x + 250 – 50x = 160
-30x = 160 – 250
-30x = -90
x = 3
Hence, the cost of buying autographs will be $20 * 3 = $60 and the cost to buy photographs will be (250 – 50) * 3 = 250 – 150 = $100
The number of photographs the family buys will be 5 – 3 = 2

Question 13.
DIG DEEPER!
Two apps on your phone take away points for using your phone at school. You have 140 points on the first app and 80 points on the second app when a school day begins. Each time you check your phone, you lose 10 points on your first app and p points on your second app. After you check your phone ten times, you have the same number of points on each app. Find the value of p.

Answer:
p = 4

Explanation:
App one has 140 points and 80 points on the second app
As per the question, app one loses 10 points for each check while app second loses p points. We check the phone 10 times
So, total points lost by app 1 will be 10 * 10 = 100, and points lost by app 2 will be p * 10 = 10p
After 10 times both apps are left with the same points.
So let’s find the value of p
Thus, points left in the first app will be 140 – 100 = 40 while in the second app will be 80 – 10p
40 = 80 – 10p
10p = 80 – 40
10p = 40
p = 40/10
p = 4

Solving Systems of Linear Equations by Graphing Homework & Practice 5.1

Review & Refresh

Write an equation in point-slope form of the line that passes through the given point and has the given slope.

Question 1.
(3, -4); m = 1

Answer:
y = x – 7

Explanation:
Given that,
(3, -4); m = 1
x₁ = 3, y₁ = -4
Slope intercept form of a line is (y – y₁) = m(x – x₁)
Therefore, (y – (-4)) = 1(x – 3)
(y + 4) = (x – 3)
y = x – 3 – 4
y = x – 7

Question 2.
(5, 6); m = \(\frac{3}{5}\)

Answer:
5y = 3x + 15

Explanation:
Given that,
(5, 6); m = \(\frac{3}{5}\)
x₁ = 5, y₁ = 6
Slope intercept form of a line is (y – y₁) = m(x – x₁)
Therefore, (y – 6) = 3/5(x – 5)
5(y – 6) = 3(x – 5)
5y – 30 = 3x – 15
5y = 3x – 15 + 30
5y = 3x + 15

Question 3.
(1, 10); m = –\(\frac{1}{4}\)

Answer:
4y = 41 – x

Explanation:
Given that,
(1, 10); m = –\(\frac{1}{4}\)
x₁ = 1, y₁ = 10
Slope intercept form of a line is (y – y₁) = m(x – x₁)
Therefore, (y – 10) = -1/4(x – 1)
4(y – 10) = -1(x – 1)
4y – 40 = -x + 1
4y = -x + 1 + 40
4y = 41 – x

Solve the equation. Check your solution

Question 4.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 21.1

Answer:
c = 8

Explanation:
Given equation is 3/4 c – 1/4 c + 3 = 7
2/4 c + 3 = 7
1/2 c = 7 – 3
1/2 c = 4
c = 4 * 2
c = 8
Substituting c = 8 in 3/4 c – 1/4 c + 3 = 7
3/4 (8) – 1/4 (8) + 3 = 6 – 2 + 3
= 9 – 2 = 7

Question 5.
5(2 – y) + y = -6

Answer:
y = 4

Explanation:
Given equation is 5(2 – y) + y = -6
10 – 5y + y = -6
10 – 4y = -6
10 + 6 = 4y
4y = 16
y = 16/4
y = 4
Substituting y = 4 in 5(2 – y) + y = -6
5(2 – 4) + 4 = 5(-2) + 4
= -10 + 4 = -6

Question 6.
6x – 3(x + 8) = 9

Answer:
x = 11

Explanation:
Given equation is 6x – 3(x + 8) = 9
6x – 3x – 24 = 9
3x – 24 = 9
3x = 9 + 24
3x = 33
x = 33/3
x = 11
Substituting x = 11 in 6x – 3(x + 8) = 9
6(11) – 3(11 + 8) = 66 – 3(19)
= 66 – 57 = 9

Concepts, Skills, &Problem Solving
USING A GRAPH TO SOLVE A PROBLEM
The equations below represent the numbers y of tickets sold after x weeks for two different local music festivals. (See Exploration 1, p. 199.)
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 22

Question 7.
You check the ticket sales for both festivals each week for 10 weeks. Create a table for the ticket sales each week. How do the festivals’ ticket sales compare?

Answer:
We can say that tickets for the country Music Festival sold more by mid the 4th week. After the mid of 4th-week tickets for the Pop Music Festival sold more than the country music festival.

Explanation:
Ticket sales for a country music festival and pop music festival are calculated in the tables below for 10 weeks
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 33
From the above tables, we can say that tickets for the country Music Festival sold more by mid of the 4th week. After the mid of 4th-week tickets for the Pop Music Festival sold more than the country music festival.

Question 8.
After how much time have the same number of tickets been sold for both festivals? What is the number of tickets sold at that time?

Answer:
The number of tickets sold for both festivals each is 185.

Explanation:
Country music festival y = 10x + 150
Pop musuic festival y = 20x + 115
As per the question, we will equate both the equation to get x value
10x + 150 = 20x + 115
10x – 20x = 115 – 150
-10x = -35
x = 35/10
x = 3.5
Thus, we get 3.5 weeks after which both festivals would sold equal number of tickets.
Let us find the number of tickets at that time
Put x = 3.5 in y = 10x + 150
y = 10(3.5) + 150
= 35 + 150 = 185
Hence, the number of tickets sold for both festivals each are 185.

SOLVING A SYSTEM OF LINEAR EQUATIONS
Solve the system by graphing.

Question 9.
y = 2x + 9
y = 6 – x

Answer:
The solution is (-1, 7)

Explanation:
The given systems of linear equations are y = 2x + 9, y = 6 – x
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 11
The lines intersect at (-1, 7)
So, the solution is (-1, 7)

Question 10.
y = -x – 4
y = \(\frac{3}{5}\)x + 4

Answer:
The solution is (-5, 1).

Explanation:
The given systems of linear equations are y = -x – 4, y = \(\frac{3}{5}\)x + 4
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 12
The lines intersect at
So, the solution is (-5, 1)

Question 11.
y = 2x + 5
y = \(\frac{1}{2}\)x – 1

Answer:
The solution is (-4, -3).

Explanation:
The given systems of linear equations are y = 2x + 5, y = \(\frac{1}{2}\)x – 1
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 13
The lines intersect at (-4, -3)
So, the solution is (-4, -3).

Question 12.
x + y = 27
y = x + 3

Answer:
The solution is (12, 15).

Explanation:
The given systems of linear equations are x + y = 27, y = x + 3
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 14
The lines intersect at (12, 15)
So, the solution is (12, 15).

Question 13.
y – x = 17
y = 4x + 2

Answer:
The solution is (5, 22)

Explanation:
The given systems of linear equations are y – x = 17, y = 4x + 2
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 15
The lines intersect at (5, 22)
So, the solution is (5, 22)

Question 14.
x – y = 7
0.5x + y =5

Answer:
The solution is (8, 1).

Explanation:
The given systems of linear equations are x – y = 7, 0.5x + y =5
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 16
The lines intersect at (8, 1)
So, the solution is (8, 1)

USING A GRAPHING CALCULATOR
Use a graphing calculator to solve the system.

Question 15.
2.2x + y = 12.5
1.4x – 4y =1

Answer:
The solution is (5, 1.5).

Explanation:
The given systems of linear equations are 2.2x + y = 12.5, 1.4x – 4y = 1
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 17
The lines intersect at (5, 1.5)
So, the solution is (5, 1.5)

Question 16.
2.1x + 4.2y = 14.7
-5.7x – 1.9y = -11.4

Answer:
The solution is (1, 3)

Explanation:
The given systems of linear equations are 2.1x + 4.2y = 14.7, -5.7x – 1.9y = -11.4
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 18
The lines intersect at (1, 3)
So, the solution is (1, 3)

Question 17.
-1.1x – 5.5y = -4.4
0.8x – 3.2y = -11.2

Answer:
The solution is (-6, 2)

Explanation:
The given systems of linear equations are -1.1x – 5.5y = -4.4, 0.8x – 3.2y = -11.2
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 19
The lines intersect at (-6, 2)
So, the solution is (-6, 2)

Question 18.
YOU BE THE TEACHER
Your friend solves the system of linear equations below. Is your friend correct? Explain your reasoning.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 23
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 24

Answer:
Correct.

Explanation:
The given system of equations are y = 0.5x + 1, y = – + 7
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 34
The point of intersection is (4, 3)
So, the solution is (4, 3)

Question 19.
MODELING REAL LIFE
You have a total of 42 math and science problems for homework. You have 10 more math problems than science problems. How many problems do you have in each subject? Use a system of linear equations to justify your answer.

Answer:
26 math and 16 science problems.

Explanation:
Write the system of equations where m and s are the number of math and science problems
m + s = 42 —- (1)
m = 10 + s —- (2)
Substitute equation (2) in equation (1)
10 + s + s = 42
10 + 2s = 42
2s = 42 – 10
2s = 32
s = 32/2
s = 16
Put s = 16 in equation (2)
m = 10 + 16
m = 26
So, 26 math and 16 science problems.

Question 20.
PROBLEM SOLVING
A generator contains 60 gallons of fuel and uses 2.5 gallons per hour. A more efficient power generator contains 40 gallons of fuel and uses 1.5 gallons per hour. After how many hours do the generators have the same amount of fuel? Which generator runs longer? Justify your answers.

Answer:
After 20 hours both generators will be having an equal amount of fuel. The generator has 40 gallons of fuel that will run for a longer time.

Explanation:
A generator contains 60 gallons of fuel and uses 2.5 gallons per hour. A more efficient power generator contains 40 gallons of fuel and uses 1.5 gallons per hour
Let’s assume that after x hours, both generate will have an equal amount of fuel
Thus, fuel consumed by the first generator will be 2.5x gallons and for the more efficient generator will be 1.5x gallons
Fuel left in the less efficient generator will be (60 – 2.5x) gallons. Fuel left in a more efficient generator will be (40 – 1.5x) gallons.
60 – 2.5x = 40 – 1.5x
-2.5x + 1.5x = 40 – 60
-x = -20
x = 20
Thus, fuel left in each generator will be 60 – 2.5 * 20 = 10 gallons
Now lets find which generator will run longer.
The number of hours less efficient generator would run is equal to 60/2.5 = 24 hours
The number of hours more efficient generator would run is equal to 40/1.5 = 26.66 hours
Hence, After 20 hours both generators will be having an equal amount of fuel.
The generator has 40 gallons of fuel that will run for a longer time.

Question 21.
PROBLEM SOLVING
You and your friend are in a canoe race. Your friend is a half-mile in front of you and paddling 3 miles per hour. You are paddling 3.4 miles per hour.
a. You are 8.5 miles from the finish line. How long will it take you to catch up with your friend? your friend
b. You both maintain your paddling rates for the remainder of the race. How far ahead of your friend will you be when you cross the finish line?
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 25

Answer:
a. It takes 1 hour 25 minutes for you to catch up to your friend.
b. You 0.5 miles ahead of your friend when you finish the race.

Explanation:
a. Let d be the distance traveled by your friend, h=then you have to travel d + 0.5 to catch up since you are currently 0.5 miles behind your friends.
distance = rate * time
you is d + 0.5 = 3.4t
a friend is d = 3t
Substitute the equation for your friend into the equation for y to solve d
3t + 0.5 = 3.4t
0.5 = 3.4t – 3t
0.4t = 0.5
t = 0.5/0.4
t = 1.25
b. Time it takes you to complete the race
8.5 = 3.4t
t = 8.5/3.4
t = 2.5
Distance traveled by a friend in that time 3(2.5) = 7.5
Your friend started 8 miles from the finishing line so you will be 8 – 7.5 = 0.5 miles ahead of your friend when you finish the race.

OPEN-ENDED
Write a system of linear equations that fits the description. Use a graph to justify your answer.

Question 22.
The solution of the system is a point on the line y = -9x + 1.

Answer:
The equations have infinitely many solutions.

Explanation:
The given equation is y = -9x + 1
Multiply both sides by 2
2y = 2(-9x + 1)
2y = -18x + 2
Draw a graph for the system of equations y = -9x + 1, 2y = -18x + 2
The equations have infinitely many solutions.

Question 23.
The solution of the system is (3, -1).

Answer:
m = -1/3

Explanation:
The slope intercept form is y = mx + c
-1 = 3m
m = -1/3

Question 24.
DIG DEEPER!
A graph of a system of two linear equations is shown. Write the system of linear equations represented by the graph. What is the solution to the system?
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 25.1

Answer:
The systems of linear equations are y = -x + 2, y = 2x – 1
The solution is (1, 1)

Explanation:
for line 1,
x₁ = 0, y₁ = 2, x₂ = 2, y₂ = 0
Slope m = (y₂ – y₁)/(x₂ – x₁)
= (0 – 2)/(2 – 0)
= -2/2 = -1
Slope intercept form of a line is y = mx + b
The line passes through (0, 2)
2 = 0(x) + b
b = 2
y = -1(x) + 2
y = -x + 2
For line 2
x₁ = 2, y₁ = 3, x₂ = 0, y₂ = -1
Slope m = (-1 – 3)/(0 – 2)
= -4/-2
= 2
y = 2x + b
The line passes through (0, -1)
-1 = 2(0) + b
n = -1
The slope intercept form of a line is y = 2x – 1
So, the systems of linear equations are y = -x + 2, y = 2x – 1
The point of intersection in the graph is (1, 1)

Question 25.
CRITICAL THINKING
Your friend is trying to grow her hair as long as her cousin’s hair. The table shows their hair lengths (in inches) in different months.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 26
a. Write a system of linear equations that represents this situation. Let x = 1 represent January.
b. Will your friend’s hair ever be as long as her cousin’s hair? If so, in what month?

Answer:
a. The equation of the line for a friend’s hair is y = 1/2 x + 5/2, the equation of the line for a friend’s cousin hair is y =2/5x + 29/5
b. After 33 months length of hair of both girls would be the same.

Explanation:
a. The length of hair is represented by y coordinate and month is represented as x coordinate
The slope formula when we know two points is m = (y₂ – y₁)/(x₂ – x₁)
x₁ = 3, y₁ = 4, x₂ = 8, y₂ = 6.5
m = (6.5 – 4)/(8 -3)
= 2.5/5
m = 1/2
The slope form of a line is (y – y₁) = m(x – x₁)
y – 4 = 1/2 (x – 3)
2(y – 4) = (x – 3)
2y – 8 = x – 3
2y = x – 3 + 8
2y = x + 5
y = 1/2 x + 5/2
Hence, the equation of line for friend’s hair is y = 1/2 x + 5/2
Equations of line for friend’s cousin hair
x₁ = 3, y₁ = 7, x₂ = 8, y₂ = 9
m = (y₂ – y₁)/(x₂ – x₁)
= (9 – 7)/(8 – 3)
= 2/5
Now to find the equation of line for friends cousin hair
(y – y₁) = m(x – x₁)
(y – 7) = 2/5 (x – 3)
5(y – 7) = 2(x – 3)
5y – 35 = 2x – 6
5y = 2x – 6 + 35
5y = 2x + 29
y = 2/5x + 29/5
Hence, the equation of line for friend’s cousin hair is y =2/5x + 29/5
b.
2/5x x + 29/5 = 1/2 x + 5/2
2/5 x – 1/2x =5/1 – 29/5
(4x – 5x)/10 = (25 – 58)/10
-x/10 = -33/10
x = 33
Hence, after 33 months length of hair of both girls would be same.

Question 26.
REASONING
Is it possible for a system of two linear equations to have multiple solutions? Explain your reasoning.

Answer:
No, it is not possible for a system of two linear equations to have multiple solutions. Because the system of linear equations is the straight lines and those lines intersect at only one point.

Question 27.
GEOMETRY
The length of a rectangle is 8 feet more than its width. The perimeter of the rectangle is 72 feet. Find the width of the rectangle.

Answer:
The width of the rectangle is 14 ft.

Explanation:
Let us say rectangle length is l, its width is l – 8
Rectangle perimeter = 2(l + b)
72 = 2(l + l – 8)
72/2 = 2l – 8
36 = 2l – 8
2l = 36 + 8
2l = 44
l = 44/2
l = 22
rectangle width is 22 – 8 = 14 ft

Lesson 5.2 Solving Systems of Linear Equations by Substitution

EXPLORATION 1
Work with a partner.
a. Find the value of each symbol in the systems below. Compare your solution methods with other pairs of students.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 26.1
b. Use a method similar to your method in part(a) to solve the system below. Then explain how to solve a system of linear equations in two variables algebraically.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 27
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 28

EXPLORATION 2
Writing and Solving Systems of Equations
Work with a partner. Roll two number cubes that are different colors. Then write the ordered pair shown by the number cubes.
a. Write a system of linear equations that has your ordered pair as its solution. Explain how you found your system.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 29
b. Exchange systems with another pair of students. Use a method from Exploration 1 to solve the system.

5.2 Lesson

Try It

Solve the system by substitution. Check your solution.

Question 1.
y = 2x + 3
y = 5x

Answer:
The solution is (1, 1)

Explanation:
The given systems of linear equations are
y = 2x + 3 —- (i)
y = 5x —– (ii)
Substitute equation (ii) in equation (i)
5x = 2x + 3
5x – 2x = 3
3x = 3
x = 3/3
x = 1
Substitute x = 1 in equation (ii)
y = 5(1)
y = 1
So, the solution is (1, 1)

Question 2.
4x + 2y = 0
y = \(\frac{1}{2}\)x – 5

Answer:
The solution is (0, -5)

Explanation:
The given systems of linear equations are
4x + 2y = 0 —– (i)
y = \(\frac{1}{2}\)x – 5 —– (ii)
Substitute equation (ii) in equation (i)
4x + 2(1/2 x) = 0
4x + x = 0
5x = 0
x = 0
putting x = 0 in equation (ii)
y = 1/2 (0) – 5
y = -5
So, the solution is (0, -5)

Question 3.
x = 5y + 3
2x + 4y = -1

Answer:
The solution is (1/2, -1/2)

Explanation:
The given systems of linear equations are
x = 5y + 3 —- (i)
2x + 4y = -1 —- (ii)
Substitute equation (i) in equation (ii)
2(5y + 3) + 4y = -1
10y + 6 + 4y = -1
14y = -1 – 6
14y = -7
y = -7/14
y = -1/2
Put y = -1/2 in equation (i)
x = 5(-1/2) + 3
= -5/2 + 3
= 1/2
So, the solution is (1/2, -1/2)

Try It

Solve the system. Explain your choice of method.

Question 4.
y = -3x + 2
y = 2

Answer:
The solution set is (0, 2)

Explanation:
The given systems of linear equations are
y = -3x + 2 —- (1)
y = 2 —- (2)
substitute equation (2) in (1)
2 = -3x + 2
2 – 2 = -3x
-3x = 0
x = 0
So, the solution set is (0, 2)

Question 5.
4y = x
x + 4y = -8

Answer:
T4y = x
x + 4y = -8

Explanation:
The given systems of linear equations are
4y = x —– (i)
x + 4y = -8 —– (ii)
Substitute x = 4y in equation (ii)
4y + 4y = 8
8y = 8
y = 1
Put y = 1 in equation (i)
4(1) = x
x = 4
So, the solution set is (4, 1)

Question 6.
2x + 2y = 1
-x + 2y = -3

Answer:
The solution set is (4/3, -5/6)

Explanation:
The given systems of linear equations are
2x + 2y = 1 —- (i)
-x + 2y = -3
2y + 3 = x —- (ii)
Substitute equation (ii) in equation (i)
2(2y + 3) + 2y = 1
4y + 6 + 2y = 1
6y + 6 = 1
6y = 1 – 6
6y = -5
y = -5/6
Put y = -5/6 in equation (ii)
2(-5/6) + 3 = x
x = -5/3 +3
x = 4/3
So, the solution set is (4/3, -5/6)

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 7.
REASONING
Does solving a system of linear equations by graphing give the same solution as solving by substitution? Explain.

Answer:
Yes.

SOLVING A SYSTEM OF LINEAR EQUATIONS
Solve the system by substitution. Check your solution.

Question 8.
y = x – 8
y = 2x – 14

Answer:
The solution set is (6, -2)

Explanation:
The given systems of linear equations are
y = x – 8 —- (i)
y = 2x – 14 —- (ii)
Substitute equation (i) in (ii)
x – 8 = 2x – 14
-8 + 14 = 2x – x
x = 6
Putting x = 6 in equation (i)
y = 6 – 8
y = -2
Substitute x = 6, y = -2 in equation (i)
-2 = 6 – 8
So, the solution set is (6, -2)

Question 9.
x = 2y + 2
2x – 5y = 1

Answer:
The solution set is (8, 3)

Explanation:
The given systems of linear equations are
x = 2y + 2 —- (i)
2x – 5y = 1 —- (ii)
Substituting equation (i) in (ii)
2(2y + 2) – 5y = 1
4y + 4 – 5y = 1
4 – 1 = y
y = 3
Put y = 3 in equation (i)
x = 2(3) + 2
x = 8
Substitute x = 8, y = 3 in 2x – 5y = 1
2(8) – 5(3) = 16 – 15 = 1
So, the solution set is (8, 3)

Question 10.
x – 5y = 1
-2x + 9y = -1

Answer:
The solution is (-4, -1)

Explanation:
The given systems of linear equations are
x – 5y = 1
x = 1 + 5y —– (i)
-2x + 9y = -1 —- (ii)
Substitute equation (i) in (ii)
-2(1 + 5y) + 9y = -1
-2 – 10y + 9y = -1
-2 – y = -1
y = -2 + 1
y = -1
Put y = -1 in (i)
x = 1 + 5(-1)
x = 1 – 5
x = -4
Put x = -4, y = -1 in (ii)
-2(-4) + 9(-1) = 8 – 9 = -1
So, the solution is (-4, -1)

CHOOSING A SOLUTION METHOD

Solve the system. Explain your choice of method.

Question 11.
y = -x + 3
y = 2x

Answer:
The solution set is (1, 2).

Explanation:
The given systems of linear equations are
y = -x + 3
y = 2x
Equating both equations
-x + 3 = 2x
3 = 2x + x
3x = 3
x = 1
Substitute x = 1 in y = 2x
y = 2(1)
y = 2
So, the solution set is (1, 2).

Question 12.
0.5x + y = 2
0.5x = 1 + y

Answer:
The solution set is (3, 1/2).

Explanation:
The given systems of linear equations are
0.5x + y = 2 —— (i)
0.5x = 1 + y
x = 1/0.5 + y/0.5
x = 2 + 2y —- (ii)
Substitute equation (ii) in (i)
0.5(2 + 2y) + y = 2
1 + y + y = 2
2y + 1 = 2
2y = 2 – 1
2y = 1
y = 1/2
Put y = 1/2 in equation (i)
0.5x + 1/2 = 2
0.5x = 2 – 0.5
0.5x = 1.5
x = 1.5/0.5
x = 3
So the solution set is (3, 1/2).

Question 13.
x = 5y
y = 22 – 2x

Answer:
The solution set is (10, 2)

Explanation:
The given systems of linear equations are
x = 5y —- (i)
y = 22 – 2x —– (ii)
Substitute x = 5y in equation (ii)
y = 22 – 2(5y)
y = 22 – 10y
y + 10y = 22
11y = 22
y = 2
Put y = 2 in x = 5y
x = 5(2)
x = 10
So, the solution set is (10, 2)

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 14.
To stock your school store, you buy a total of 25 sweatshirts and hats for $172.50. You pay $8.00 per sweatshirt and $2.50 per hat. How many of each item do you buy?

Answer:
The number of sweatshirts you buy would be 20 and the hat you buy would be 5.

Explanation:
Let’s assume the number of sweatshirts bought be x, while the number of hats will be 25 – x
Thus, cost to buy sweatshirts is 8 * x = 8x, and for hats will be 2.5 * (25 – x) = 62.50 – 2.50x
Therefore, total cost is 8x + 62.50 – 2.5x which is equal to 172.50
8x + 62.50 – 2.5x = 172.50
5.5x = 172.50 – 62.50
5.5x = 110
x = 110/5.5
x = 20
Hence, the cost of buying sweatshirts will be $20 * 8 = $160 and the cost to buy hats will be (25 – 20)2.50 = 12.5
The number of sweatshirts you buy would be 20 and the hat you buy would be (25 – 20) = 5

Question 15.
DIG DEEPER!
The length of a volleyball court is twice its width. The perimeter of the court is 180 feet. Find the area of the volleyball court. Justify your answer.

Answer:
The area of the rectangle will be 1800 sq ft.

Explanation:
The perimeter of the volleyball court is 180 feet. The length of the court is twice its width
Let us take the length and width of the court be 2x, x
Perimeter = 2(l + b)
As per the question
2(l + b) = 180
2x + x = 90
3x = 90
x = 90/3
x = 30
Thus, the length of court is 2 . 30 = 60 and width is 30 ft
Area = length * width
= 60 * 30
= 1800
Hence, the area of the rectangle will be 1800 sq ft.

Solving Systems of Linear Equations by Substitution Homework & Practice 5.2

Review & Refresh

Solve the system by graphing.

Question 1.
y = 2x – 3
y = -x + 9

Answer:
The solution is (4, 5)

Explanation:
The given systems of linear equations are y = 2x – 3, y = -x + 9
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 20
The lines intersect at (4, 5)
So, the solution is (4, 5)

Question 2.
6x + y = -2
y = -3x + 1

Answer:
The solution is (-1, 4)

Explanation:
The given systems of linear equations are 6x + y = -2, y = -3x + 1
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 21
The lines intersect at (-1, 4)
So, the solution is (-1, 4)

Question 3.
4x + 2y = 2
3x = 4 – y

Answer:
The solution is (3, -5).

Explanation:
The given systems of linear equations are 4x + 2y = 2, 3x = 4 – y
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 22
The lines intersect at (3, -5)
So, the solution is (3, -5)

Question 4.
Use the figure to find the measure of ∠2
A. 17°
B. 73°
C. 83°
D. 107°

Answer:
B. 73°

Explanation:
Given that,
∠1 = 107 degrees
∠1 + ∠2 = 180
107 + ∠2 = 180
∠2 = 180 – 107
= 73 degrees

Concepts, Skills, &Problem Solving
SOLVING A SYSTEM ALGEBRAICALLY
Find the value of each symbol in the system. (See Exploration 1, p. 205.)

Question 5.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 30

Question 6.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 31

SOLVING A SYSTEM OF LINEAR EQUATIONS
Solve the system by substitution. Check your solution.

Question 7.
y = x – 4
y = 4x – 10

Answer:
The solution set is (2, -2).

Explanation:
The given systems of linear equations are
y = x – 4 —- (i)
y = 4x – 10 —– (ii)
Substitute (ii) in (i)
4x – 10 = x – 4
4x – x = -4 + 10
3x = 6
x = 2
Put x = 2 in (i)
y = 2 – 4
y = -2
Substitute x = 2, y = -2 in equation (ii)
-2 = 4(2) – 10
= 8 – 10
So, the solution set is (2, -2).

Question 8.
y = 2x + 5
y = 3x – 1

Answer:
The solution set is (6, 17).

Explanation:
The given systems of linear equations are
y = 2x + 5 —– (i)
y = 3x – 1 —— (ii)
Substitute (ii) in (i)
3x – 1 = 2x + 5
3x – 2x = 5 + 1
x = 6
Substitute x = 6 in (i)
y = 2(6) + 5
y = 12 + 5
y = 17
Put x = 6, y = 17 in (ii)
17 = 3(6) – 1
= 18 – 1
So, the solution set is (6, 17)

Question 9.
x = 2y + 7
3x – 2y = 3

Answer:
The solution set is (-2, -9/2).

Explanation:
The given systems of linear equations are
x = 2y + 7 —– (i)
3x – 2y = 3  —– (ii)
Substitute (i) in (ii)
3(2y + 7) – 2y = 3
6y + 21 – 2y = 3
4y = 3 – 21
4y = -18
y = -9/2
Substitute y = -9/2 in (i)
x = 2(-9/2) + 7
x = -9 + 7
x = -2
Put x = -2, y = -9/2 in (ii)
3(-2) – 2(-9/2) = -6 + 9 = 3
So, the solution set is (-2, -9/2)

Question 10.
4x – 2y =14
y = \(\frac{1}{2}\)x – 1

Answer:
The solution set is (4, 1)

Explanation:
The given systems of linear equations are
4x – 2y =14 —– (i)
y = \(\frac{1}{2}\)x – 1 —– (ii)
Substitute equation (i) in (ii)
4x – 2(0.5x – 1) = 14
4x – x + 2 = 14
3x = 14 – 2
3x = 12
x = 4
Substitute x = 4 in (i)
4(4) – 2y = 14
16 – 14 = 2y
2 = 2y
y = 1
Put x = 4, y = 1 in (ii)
1 = 1/2 (4) – 1
= 2 – 1
So, the solution set is (4, 1)

Question 11.
2x = y – 10
2x + 7 = 2y

Answer:
The solution set is (-13/2, -3)

Explanation:
The given systems of linear equations are
2x = y – 10
y = 2x + 10 —- (i)
2x + 7 = 2y —— (ii)
Substitute (i) in (ii)
2x + 7 = 2(2x + 10)
2x + 7 = 4x + 20
4x – 2x = 7 – 20
2x = -13
x = -13/2
Substitute x = -13/2 in (i)
y = 2(-13/2) + 10
= -13 + 10
= -3
Put x = -13/2, y = -3 in (ii)
2(-13/2) + 7 = 2(-3)
-13 + 7 = -6
So, the solution set is (-13/2, -3)

Question 12.
8x – \(\frac{1}{3}\)y = 0
12x + 3 =y

Answer:
The solution set is (1/4, 6).

Explanation:
The given systems of linear equations are
8x – \(\frac{1}{3}\)y = 0 —– (i)
12x + 3 =y —— (ii)
Substitute (ii) in (i)
8x – 1/3(12x + 3) = 0
8x – 4x – 1 = 0
4x – 1 = 0
4x = 1
x = 1/4
Substitute x = 1/4 in (ii)
12(1/4) + 3 = y
3 + 3 = y
y = 6
Put x = 1/4, y = 6 in (ii)
12(1/4) + 3 = 3 + 3 = 6
So, the solution set is (1/4, 6).

Question 16.
MODELING REAL LIFE
There are a total of 64 students in a film making club and a yearbook club. The filmmaking club has 14 more students than the yearbook club.
a. Write a system of linear equations that represents this situation.
b. How many students are in the film making club? the yearbook club?
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 32

Answer:
a. x + y = 64, x = y + 14
b. The number of students in the filmmaking club and yearbook club are 39 and 25 respectively.

Explanation:
a. Let us take the number of students in film making club to be x and the number of students in the yearbook club be y
x + y = 64 —- (i)
It is given that the number of students in the filmmaking club is greater than students in the yearbook club by 14
So, x = y + 14 —- (ii)
b. Put equation (ii) in (i)
y + 14 + y = 64
2y + 14 = 64
2y = 64 – 14
2y = 50
y = 25
Substitute y = 25 in (i)
x + 25 = 64
x = 64 – 25
x = 39
Hence, the number of students in filmmaking club and yearbook club are 39 and 25 respectively.

Question 17.
MODELING REAL LIFE
A drama club earns $1040 from production by selling 64 adult tickets and 132 student tickets. An adult ticket costs twice as much as a student ticket.
a. Write a system of linear equations that represents this situation.
b. What is the cost of each ticket?

Answer:
a. 64a + 132s = 1040, a = 2s
b. The price of a student ticket is $4, adult ticket is $8.

Explanation:
Write the system of equations that models the problem where a is the price of an adult ticket and s is the price of a student ticket
64a + 132s = 1040
a = 2s
b. Substitute a = 2s in 64a + 132s = 1040
64(2s) + 132s = 1040
128s + 132s = 1040
260s = 1040
s = 1040/260
s = $4 per student ticket
a = 2(4) = $8 per adult ticket.

Question 18.
OPEN-ENDED
Write a system of linear equations that has the ordered pair (1, 6) as its solution.

Answer:
The system of linear equations that pass through (1, 6) is y – 6 = m(x – 1)

Explanation:
We know that the equation of a line that passes through a point is (y – y₁) = m(x – x₁)
The line pass through (1,6 )
So, y – 6 = m(x – 1)
We can get system of linear equations by inserting different values of m in above equation
If we put m = 1, then equation is y – 6 = 1(x – 1)
y – 6 = x – 1
y = x – 1 + 6
y = x + 5
Hence, the system of linear equation is y – 6 = m(x – 1) that pass through (1, 6).

CHOOSING A SOLUTION METHOD
Solve the system. Explain your choice of method.

Question 19.
y – x = 4
x + y = 6

Answer:
The solution set is (1, 5)

Explanation:
The given system of linear equations are
y – x = 4
y = 4 + x —– (i)
x + y = 6 —– (ii)
Substitute (i) in (ii)
x + 4 + x = 6
2x + 4 = 6
2x = 6 – 4
2x = 2
x = 1
Substitute x = 1 in (i)
y = 4 + 1
y = 5
So, the solution set is (1, 5)

Question 20.
0.5x + y = 4
0.5x – y =-1

Answer:
The solution set is (3, 2.5)

Explanation:
The given system of linear equations are
0.5x + y = 4 —- (i)
0.5x – y =-1
0.5x + 1 = y —- (ii)
Substitute (ii) in (i)
0.5x + 0.5x + 1 = 4
x + 1 = 4
x = 4 – 1
x = 3
Substitute x = 3 in (ii)
y = 0.5(3) + 1
= 2.5
So, the solution set is (3, 2.5)

Question 21.
y = 2x + 5
y = -3x

Answer:
The solution set is (-1, 3)

Explanation:
The given system of linear equations are
y = 2x + 5 —- (i)
y = -3x —– (ii)
Substitute (i) in (ii)
-3x = 2x + 5
-3x – 2x = 5
-5x = 5
x = -1
Substitute x = -1 in (i)
y = 2(-1) + 5
y = -2 + 5
y = 3
So, the solution set is (-1, 3)

Question 22.
CRITICAL THINKING
A system consists of two different proportional relationships. What is the solution to the system? Justify your answer.

Answer:
The solution is (0, 0).

Explanation:
The proportional relationships in the system of linear equations mean that there is no constant available in the equation.
Therefore, the lines will always pass through the origin (0, 0)
Hence, the solution is (0, 0).

Question 23.
GEOMETRY
The measure of the obtuse angle in the isosceles triangle is two and a half times the measure of one of the acute angles. Write and solve a system of linear equations to find the measure of each angle.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 33

Answer:
The systems of linear equations are x + 2y = 180°, x = 2.5y
x = 100°, y = 40°

Explanation:
In an isosceles triangle, there are two angles that are the same and one that is different. We know there is one angle that is more than 90° because that is the definition of an obtuse angle. We also know that the sum of all the angles of a triangle equals 180°.
Let’s put all this together and find the measures of the angles.
x + 2y = 180°
x = 2.5y
Put x = 2.5 y in x + 2y = 180°
2.5y + 2y = 180°
4.5y = 180
y = 180/4.5
y = 40
Put y = 40 in x = 2.5y
x = 2.5(40)
x = 100

Question 24.
NUMBER SENSE
The sum of the digits of a two-digit number is 8. When the digits are reversed, the number increases by 36. Find the original number.

Answer:
The original number is 26.

Explanation:
Let the two-digit number be xy
The sum of the digits of a two-digit number is 8
x + y = 8
y = 8 – x —- (i)
So, the number is 10x + y
When the digits are reversed, the number increases by 36
10y + x = 36 + 10x + y
10y – y = 36 + 10x – x
9y = 36 + 9x
Put y = 8 – x
9(8 – x) = 36 + 9x
72 – 9x = 36 + 9x
72 – 36 = 18x
18x = 36
x = 36/18
x = 2
Put x = 2 in equation (i)
y = 8 – 2
y = 6
So, the original number is 26.

Question 25.
DIG DEEPER!
A hospital employs a total of 77 nurses and doctors. The ratio of nurses to doctors is 9 : 2. How many nurses are employed at the hospital? How many doctors are employed at the hospital?

Answer:
There are 63 nurses, 14 doctors are employed at the hospital.

Explanation:
Let x be the number of nurses and y be the number of doctors
A hospital employs a total of 77 nurses and doctors
x + y = 77 —- (i)
The ratio of nurses to doctors is 9:2.
x/y = 9/2
x = 9/2y
Put x = 9/2y in (i)
9/2 y + y = 77
11/2 y = 77
11y = 77 * 2
y = 14
x = 9/2 (14)
y = 63
So, there are 63 nurses, 14 doctors are employed at the hospital.

Question 26.
REPEATED REASONING
A DJ has a total of 1075 dance, rock, and country songs on her system. The dance selection is three times the rock selection. The country selection has 105 more songs than the rock selection. How many songs on the system is dance? rock? country?
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 34

Answer:
582 dance, 299 countries, and 194 ock songs on the system.

Explanation:
Let d, r, c be the number of dance, rock and country songs
A DJ has a total of 1075 dance, rock, and country songs on her system
d + r + c = 1075 —- (i)
The dance selection is three times the size of the rock selection
d = 3r —- (ii)
The country selection has 105 more songs than the rock selection
c = 105 + r —– (iii)
Put (ii), (iii) in (i)
3r + r + 105 + r = 1075
5r = 1075 – 105
5r = 970
r = 194
d = 3(194) = 582
c = 105 + 194 = 299
So, 582 dance, 299 country, and 194 ock songs on the system.

Lesson 5.3 Solving Systems of Linear Equations by Elimination

EXPLORATION 1
Work with a partner. A student found the value of in the system using substitution as shown.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 35
a. Find another way to obtain the equation 4x = -4 from the original system. Does your method produce an equation in one variable for any system? Explain.
b. Can you use your method in part(a) to solve each system below? If so, solve the system. If not, replace one of the equations with an equivalent equation that allows you to use your method in part(a). Then solve the system.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 36
c. Compare your solution methods in part(b) with other pairs of students.

5.3 Lesson

Try It

Solve the system by elimination. Check your solution.

Question 1.
2x – y = 9
4x + y =21

Answer:
The solution set is (5, 1).

Explanation:
The given system of linear equations are
2x – y = 9 —- (i)
4x + y =21 —– (ii)
Add both equations
2x – y + 4x + y = 9 + 21
6x = 30
x = 30/6
x = 5
Put x = 5 in (i)
2(5) – y = 9
10 – y = 9
10 – 9 = y
y = 1
Substitute x = 5, y = 1 in (ii)
4(5) + 1 = 20 + 1 = 21
So, the solution set is (5, 1).

Question 2.
-5x + 2y = 13
5x + y = -1

Answer:
The solution set is (-1, 4).

Explanation:
The given system of linear equations are
-5x + 2y = 13 —– (i)
5x + y = -1 —— (ii)
Add both equations
-5x + 2y + 5x + y = 13 – 1
3y = 12
y = 4
Substitute y = 4 in (ii)
5x + 4 = -1
5x = -1 – 4
5x = -5
x = -1
Substitute x = -1, y = 4 in (i)
-5(-1) + 2(4) = 5 + 8 = 13
So, the solution set is (-1, 4).

Question 3.
3x + 4y = -6
7x + 4y = -14

Answer:
The solution set is (-2, 0).

Explanation:
The given system of linear equations are
3x + 4y = -6 —- (i)
7x + 4y = -14 —– (ii)
Subtract (ii) from (i)
3x + 4y – (7x + 4y) = -6 + 14
3x + 4y – 7x – 4y = 8
-4x = 8
x = -8/4
x = -2
Substitute x = -2 in (i)
3(-2) + 4y = -6
-6 + 4y = -6
4y = -6 + 6
y = 0
Substitute x = -2, y = 0 in (ii)
7(-2) + 4(0) = -14
So, the solution set is (-2, 0).

Try It

Solve the system by elimination. Check your solution.

Question 4.
3x + y = 11
6x + 3y = 24

Answer:
The solution set is (3, 2)

Explanation:
The given system of linear equations are
3x + y = 11 —— (i)
6x + 3y = 24 ——- (ii)
Divide equation (ii) by 1/3
1/3(6x + 3y = 24)
2x + y = 8 —- (iii)
Subtract (iii) from (i)
3x + y – (2x + y) = 11 – 8
3x + y – 2x – y = 3
x = 3
Put x = 3 in (i)
3(3) + y = 11
9 + y = 11
y = 11 – 9
y = 2
Substitute x = 3, y = 2 in (iii)
2(3) + 2 = 6 + 2 = 8
So, the solution set is (3, 2)

Question 5.
4x – 5y = -19
-x – 2y = 8

Answer:
The solution set is (-6, -1)

Explanation:
The given system of linear equations are
4x – 5y = -19 —– (i)
-x – 2y = 8 —— (ii)
Multiply both sides of equation (ii) by 4
4(-x – 2y = 8)
-4x – 8y = 32 —- (iii)
Add (i) & (iii)
4x – 5y – 4x – 8y = -19 + 32
-13y = 13
y = -1
Substitute y = -1 in (ii)
-x – 2(-1) = 8
-x + 2 = 8
-x = 8 – 2
x = -6
Substitute x = -6, y = -1 in (ii)
-(-6) – 2(-1) = 6 + 2 = 8
So, the solution set is (-6, -1)

Question 6.
5y = 15 – 5x
y = -2x + 3

Answer:
The solution set is (0, 3)

Explanation:
The given system of linear equations are
5y = 15 – 5x —– (i)
y = -2x + 3 —– (ii)
Divide equation (i) by 1/5
1/5(5y = 15 – 5x)
y = 3 – x —– (iii)
Subtract (iii) from (ii)
y – y = -2x + 3 – (3 – x)
0 = -2x + 3 – 3 + x
-x = 0
x = 0
Substitute x = 0 in (iii)
y = 3 – 0
y = 3
Substitute x = 0, y = 3 in (ii)
3 = -2(0) + 3
So, the solution set is (0, 3)

Try It

Question 7.
Change one word in Choice B so that it represents an efficient approach to solving the system.

Answer:
Multiply equation (i) by -1 and subtract the equations.

Explanation:
The given system of linear equations are
x – 2y = 6 —- (i)
-x + 4y = 6 —- (ii)
multiply equation (i) by -1 and subtract the equations.
-1(x – 2y = 6)
-x + 2y = -6
-x + 2y – (-x + 4y) = -6 – 6
-x + 2y + x – 4y = -12
-2y = -12
y = 6
Put y = 6 in (i)
x – 2(6) = 6
x – 12 = 6
x = 6 + 12
x = 18

Self-Assessment for Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

SOLVING A SYSTEM OF LINEAR EQUATIONS
Solve the system by elimination. Check your solution.

Question 8.
2x + y = 4
-2x + 2y = 5

Answer:
The solution set is (1/2, 3)

Explanation:
The given system of linear equations are
2x + y = 4 —— (i)
-2x + 2y = 5 —– (ii)
Add equations
2x + y – 2x + 2y = 4 + 5
3y = 9
y = 3
Substitute y = 3 in (i)
2x + 3 = 4
2x = 4 – 3
2x = 1
x = 1/2
Substitute x = 1/2, y = 3 in (ii)
-2(1/2) + 2(3) = -1 + 6 = 5
So, the solution set is (1/2, 3)

Question 9.
-x + y = 1
-3x + y =7

Answer:
The solution set is (-3, -2).

Explanation:
The given system of linear equations are
-x + y = 1 —- (i)
-3x + y =7 —– (ii)
Subtract equations
-x + y – (-3x + y) = 1 – 7
-x + y + 3x – y = -6
2x = -6
x = -3
Substitute x = -3 in (ii)
-3(-3) + y = 7
9 + y = 7
y = 7 – 9
y = -2
Substitute x = -3, y = -2 in (i)
-(-3) – 2 = 3 – 2 = 1
So, the solution set is (-3, -2).

Question 10.
y = -2x + 3
4x – 5y = 13

Answer:
The solution set is (2, -1).

Explanation:
The given system of linear equations are
y = -2x + 3
2x + y = 3 —– (i)
4x – 5y = 13 —– (ii)
Multiply equation (i) by 2 and subtract
2(2x + y = 3)
4x + 2y = 6
4x + 2y – (4x – 5y) = 6 – 13
4x + 2y – 4x + 5y = -7
7y = -7
y = -1
Substitute y = -1 in (i)
2x – 1 = 3
2x = 4
x = 2
Substitute x = 2, y = -1 in (ii)
4(2) – 5(-1) = 8 + 5 = 13
So, the solution set is (2, -1).

CHOOSING A SOLUTION METHOD
Solve the system. Explain your choice of method.

Question 11.
y = 6x – 1
y = 3x – 4

Answer:
The solution set is (-1, -7)

Explanation:
The given system of linear equations are
y = 6x – 1 —- (i)
y = 3x – 4 —– (ii)
Equating both the equations
6x – 1 = 3x – 4
6x – 3x = -4 + 1
3x = -3
x = -3/3
x = -1
Substitute x = -1 in equation (i)
y = 6(-1) – 1
y = -7
So, the solution set is (-1, -7)

Question 12.
3x = y + 2
3x + 2y = 5

Answer:
The solution set is (1, 1).

Explanation:
The given system of linear equations are
3x = y + 2 —- (i)
3x + 2y = 5 —– (ii)
Substitute equation (i) in (ii)
y + 2 + 2y = 5
3y = 5 – 2
3y = 3
y = 1
Substitute y = 1 in (i)
3x = 1 + 2
3x = 3
x = 1
So, the solution set is (1, 1).

Question 13.
2x – y = 7
x + y = 5

Answer:
The solution set is (4, 1).

Explanation:
The given system of linear equations are
2x – y = 7 —- (i)
x + y = 5 —- (ii)
Add equations
2x – y + x + y = 7 + 5
3x = 12
x = 4
Substitute x = 4 in (ii)
4 + y = 5
y = 5 – 4
y = 1
So, the solution set is (4, 1).

Question 14.
WHICH ONE DOESN’T BELONG?
Which system does not belong with the other three? Explain your reasoning.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 37

Answer:
2x + 3y = 11, 3x – 2y = 10 is does not belong to other three.

Explanation:
1. 3x + 3y = 3 —- (i)
2x – 3y = 7 —- (ii)
Add equations
3x + 3y + 2x – 3y = 3 + 7
5x = 10
x = 2
Substitute x = 2 in (ii)
2(2) – 3y = 7
4 – 3y = 7
-3y = 7 – 4
-3y = 3
y = -1
The solution set is (2, -1).
2. -2x + y = 6 — (i)
2x – 3y = -10 — (ii)
Add equations
-2x + y + 2x – 3y = 6 – 10
-2y = -4
y = 2
Substitute y = 2 in (i)
-2x + 2 = 6
-2x = 4
x = -2
The solution set is (-2, 2)
3. 2x + 3y = 11 —- (i)
3x – 2y = 10
3x = 10 + 2y
x = (10 + 2y)/3
Substitute x = (10 + 2y)/3 in (i)
2(10 + 2y)/3 + 3y = 11
20 + 4y + 9y = 33
20 + 13y = 33
13y = 33 – 20
y = 1
Put y = 1 in (i)
2x + 3 = 11
2x = 11 – 3
2x = 8
x = 4

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 15.
A fitness instructor purchases exercise bikes and treadmills for two gyms. For the first gym, 2 exercise bikes and 3 treadmills cost $2200. For the second gym, 3 exercise bikes and 4 treadmills cost $3000. How much does a treadmill cost?

Answer:
The cost of a treadmill is $600.

Explanation:
Let x and y be the price of exercise bikes and treadmills, respectively
Using the fact that
Total cost = cost of exercise bike . Number of bikes in a gym + Cost of treadmill . Number of treadmills in a gym
2x + 3y = 2200 —- (i)
3x + 4y = 3000 —– (ii)
Multiply (i) by 3 and (ii) by 2
3(2x + 3y = 2200)
6x + 9y = 6600 —- (iii)
2(3x + 4y = 3000)
6x + 8y = 6000 —– (iv)
Subtract equations
6x + 9y – 6x – 8y = 6600 – 6000
y = 600
The cost of treadmill is $600.

Question 16.
DIG DEEPER!
At your school, cooking club members raise $5 per member for a charity, and woodshop club members raise $10 per member for a different charity. The cooking club has three times as many members as the woodshop club. The difference in the number of members in the two clubs is 12 members. How much does each club raise?
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 38

Answer:
Money raised for charity by the cooking club is $90, Money raised for charity by the woodshop club $60.

Explanation:
Let x and y be the number of members of the cooking club and woodshop club
The cooking club has three times as many members as the woodshop club.
x = 3y
The difference in the number of members in the two clubs is 12 members.
x – y = 12
3y – y = 12
2y = 12
y = 6
So, x = 3(6) = 18
Money raised for charity by cooking club = Number of members in a cooking club. Charity per member of cooking club
= x . 5
= 18 . 5
= $90
Money raised for charity by woodshop club = Number of members in woodshop club. Charity per member of woodshop club
= y . 10
= 6 . 10
= $60

Solving Systems of Linear Equations by Elimination Homework & Practice 5.3

Review & Refresh

Solve the system by substitution. Check your solution.

Question 1.
x = 5 – y
x – y = 3

Answer:
The solution set is (4, 1).

Explanation:
The given system of linear equations are
x = 5 – y —- (i)
x – y = 3 —- (ii)
Substitute equation (i) in (ii)
5 – y – y = 3
5 – 2y = 3
5 – 3 = 2y
2 = 2y
y = 1
Substitute y = 1 in (i)
x = 5 – 1
x = 4
Substitute x = 4, y = 1 in (ii)
4 – 1 = 3
So, the solution set is (4, 1).

Question 2.
x – 5y = 1
-x + y = 7

Answer:
The solution set is (-9, -2)

Explanation:
The given system of linear equations are
x – 5y = 1
x = 1 + 5y —- (i)
-x + y = 7 —- (ii)
Substitute (i) in (ii)
-1 – 5y + y = 7
-1 – 4y = 7
-4y = 7 + 1
-4y = 8
y = -2
Substitute y = -2 in (i)
x = 1 + 5(-2)
x = 1 – 10
x = -9
Substitute x = -9, y = -2
-(-9) – 2 = 9 – 2 = 7
So, the solution set is (-9, -2)

Question 3.
x + 6y = -2
-x = 3y – 10

Answer:
The solution set is (22, -4).

Explanation:
The given system of linear equations are
x + 6y = -2 —- (i)
-x = 3y – 10 —- (ii)
Substitute (ii) in (i)
-3y + 10 + 6y = -2
3y + 10 = -2
3y = -2 – 10
3y = -12
y = -4
Substitute y = -4 in (ii)
-x = 3(-4) – 10
-x = -12 – 10
-x = -22
x = 22
Substitute x = 22, y = -4 in (i)
22 + 6(-4) = 22 – 24 = -2
So, the solution set is (22, -4).

The vertices of a triangle are given. Draw the triangle and its image after a dilation with the given scale factor. Identify the type of dilation.

Question 4.
A(1, 1), B(1, 3), C(3, 1); k = 2

Answer:
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 35
The new triangle is larger than the original triangle so it’s an increase.

Explanation:
The vertices of a triangle are A(1, 1), B(1, 3), C(3, 1)
Multiply the coordinates by 2 and then graph the original and new coordinates.
New coordinates are D(2, 2), E(2, 6), F(6, 2)
The new triangle is larger than the original triangle so it’s an increase.

Question 5.
D(-8, -4), E(-4, 8), F(0, 0); k = 0.5

Answer:
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 36
The new triangle is smaller than the original triangle so it’s a reduction.

Explanation:
The vertices of a triangle are D(-8, -4), E(-4, 8), F(0, 0)
Multiply the coordinates by 0.5 and then graph the original and new coordinates
The new coordinates are A(-4, -2), B(-2, 4), C(0, 0)
The new triangle is smaller than the original triangle so it’s a reduction.

Concepts, Skills, &Problem Solving
SOLVING A SYSTEM ALGEBRAICALLY
Explain how to obtain the equation 3x = 6 from the given system. (See Exploration 1, p. 211.)

Question 6.
2x + y = 5
x – y = 1

Answer:
Add both equations

Explanation:
The given system of linear equations are
2x + y = 5 —– (i)
x – y = 1 —– (ii)
Add both equations
2x + y + x – y = 5 + 1
3x = 6

Question 7.
5x + 2y = 2
x + y = -2

Answer:
Multiply the equation 2 by 2 and Subtract equation obtained equation from (i)

Explanation:
The given system of linear equations are
5x + 2y = 2 —– (i)
x + y = -2 —— (ii)
Multiply the equation 2 by 2
2(x + y) = 2(-2)
2x + 2y = -4
Subtract equation obtained equation from (i)
5x + 2y – 2x – 2y = 2 + 4
3x = 6

Question 8.
-x + y = -3
6x – 3y =15

Answer:
Multiply the equation (i) by 3, Add equations (i) & (iii)

Explanation:
The given system of linear equations are
-x + y = -3 —- (i)
6x – 3y =15 —- (ii)
Multiply the equation (i) by 3
3(-x + y = -3)
-3x + 3y = -9 —- (ii)
Add equation (i) & (iii)
6x – 3y – 3x + 3y = 15 – 9
3x = 6

SOLVING A SYSTEM OF LINEAR EQUATIONS
Solve the system by elimination. Check your solution.

Question 9.
x + 3y = 5
-x – y = -3

Answer:
The solution set is (2, 1).

Explanation:
The given system of linear equations are
x + 3y = 5 —- (i)
-x – y = -3 —– (ii)
Add equations (i) & (ii)
x + 3y – x – y = 5 – 3
2y = 2
y = 1
Substitute y = 1 in (ii)
-x – 1 = -3
-x = -3 + 1
-x = -2
x = 2
Substitute x = 2, y = 1 in (i)
2 + 3(1) = 2 + 3 = 5
So, the solution set is (2, 1).

Question 10.
x – 2y = -7
3x + 2y = 3

Answer:
The solution set is (-1, 3).

Explanation:
The given system of linear equations are
x – 2y = -7 —- (i)
3x + 2y = 3 —- (ii)
Add equations (i), (ii)
x – 2y + 3x + 2y = -7 + 3
4x = -4
x = -1
Substitute x = -1 in (i)
-1 – 2y = -7
-2y = -7 + 1
-2y = -6
y = 3
Substitute x = -1, y = 3 in (i)
-1 – 2(3) = -1 – 6 = -7
So, the solution set is (-1, 3).

Question 11.
4x + 3y = -5
-x + 3y = -10

Answer:
The solution set is(1, -3).

Explanation:
The given system of linear equations are
4x + 3y = -5 —- (i)
-x + 3y = -10 —- (ii)
Subtract equations (i), (ii)
4x + 3y – (-x + 3y) = -5 – (-10)
4x + 3y + x – 3y = -5 + 10
5x = 5
x = 1
Substitute x = 1 in (ii)
-1 + 3y = -10
3y = -10 + 1
3y = -9
y = -3
Substitute x = 1, y = -3 in (i)
4(1) + 3(-3) = 4 – 9 = -5
So, the solution set is(1, -3).

Question 12.
2x + 7y = 1
2x – 4y = 12

Answer:
The solution set is (4, -1).

Explanation:
The given system of linear equations are
2x + 7y = 1 —- (i)
2x – 4y = 12 —– (ii)
Subtract equations (i), (ii)
2x – 4y – (2x + 7y) = 12 – 1
2x – 4y – 2x – 7y = 11
-11y = 11
y = -1
Substitute y = -1 in (ii)
2x – 4(-1) = 12
2x + 4 = 12
2x = 12 – 4
2x = 8
x = 4
Substitute x = 4, y = -1 in (i)
2(4) + 7(-1) = 8 – 7 = 1
So, the solution set is (4, -1).

Question 13.
2x + 5y = 16
3x – 5y = -1

Answer:
The solution set is (3, 2).

Explanation:
The given system of linear equations are
2x + 5y = 16 —- (i)
3x – 5y = -1 —– (ii)
Add both equations
2x + 5y + 3x – 5y = 16 – 1
5x = 15
x = 3
Substitute x = 3 in (i)
2(3) + 5y = 16
5y = 16 – 6
5y = 10
y = 2
Substitute x = 3, y = 2 in (ii)
3(3) – 5(2) = 9 – 10 = -1
So, the solution set is (3, 2).

Question 14.
3x – 2y = 4
6x – 2y = -2

Answer:
The solution set is (-2, -5).

Explanation:
The given system of linear equations are
3x – 2y = 4 —– (i)
6x – 2y = -2 —– (ii)
Subtract equations
3x – 2y – (6x – 2y) = 4 – (-2)
3x – 2y – 6x + 2y = 4 + 2
-3x = 6
x = -2
Substitute x = -2 in (i)
3(-2) – 2y = 4
-6 – 2y = 4
-2y = 4 + 6
-2y = 10
y = -5
Substitute x = -2, y = -5 in (ii)
6(-2) – 2(-5) = -12 + 10 = -2
So, the solution set is (-2, -5).

Question 15.
YOU BE THE TEACHER
Your friend solves the system. Is your friend correct? Explain your reasoning.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 39

Answer:
Wrong.

Explanation:
The given equations are 5x + 2y = 9 —- (i)
3x – 2y = -1 —- (ii)
Add both equations
5x + 2y + 3x – 2y = 9 – 1
8x = 8
x = 1
Put x = 1 in (ii)
3(1) – 2y = -1
3 – 2y = -1
-2y = -1 – 3
-2y = -4
y = 2
So, the solution set is (1, 2).

Question 16.
MODELING REAL LIFE
You and your friend are selling raffle tickets for a new laptop. You sell 14 more tickets than your friend sells. Together, you and your friend sell 58 tickets.
a. Write a system of linear equations that represents this situation.
b. How many tickets do each of you sell?

Answer:
a. x = 14 + y, x + y = 58
b. The number of tickers you sell is 36, the number of tickets your friend sells is 22.

Explanation:
a. Let x be the number of tickets you sell and let y be the number of tickets your friend sells.
You sell 14 more tickets than your friend sells
x = 14 + y —- (i)
Together, you and your friend sell 58 tickets.
x + y = 58 —- (ii)
b. Substitute equation (i) in (ii)
14 + y + y = 58
14 + 2y = 58
2y = 58 – 14
2y = 44
y = 44/2
y = 22
Substitute y = 22 in (i)
x = 14 + 22
x = 36
So, The number of tickers you sell is 36, the number of tickets your friend sells is 22.

Question 17.
MODELING REAL LIFE
You can jog around your block twice and the park once in 10 minutes. You can jog around your block twice and the park 3 times in 22 minutes. Write a system of linear equations that represents this situation. How long does it take you to jog around the park?
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 40

Answer:
The system of linear equations are 2x + y = 10, 2x + 3y = 22
It takes 6 minutes to jog around the park.

Explanation:
Let x be the number of minutes it takes to jog around the block and y be the number of minutes it takes to jog around the park
You can jog around your block twice and the park once in 10 minutes
2x + y = 10 —- (i)
You can jog around your block twice and the park 3 times in 22 minutes
2x + 3y = 22 —- (ii)
Subtract equations
2x + y – 2x – 3y = 10 – 22
-2y = -12
y = 6
Substitute y = 6 in (i)
2x + 6 = 10
2x = 10 – 6
2x = 4
x = 2
So, it takes 6 minutes to jog around the park.

SOLVING A SYSTEM OF LINEAR EQUATIONS
Solve the system by elimination. Check your solution.

Question 18.
2x – y = 0
3x – 2y = -3

Answer:
The solution set is (3, 6).

Explanation:
The systems of linear equations are
2x – y = 0 —- (i)
3x – 2y = -3 —– (ii)
Multiply equation (i) by 2
2(2x – y = 0)
4x – 2y = 0 —- (iii)
Subtract equation (ii) from (iii)
4x – 2y – (3x – 2y) = 0 – (-3)
4x – 2y – 3x + 2y = 3
x = 3
Substitute x = 3 in (i)
2(3) – y = 0
6 – y = 0
y = 6
Substitute x = 3, y = 6 in (i)
2(3) – 6 = 6 – 6 = 0
So, the solution set is (3, 6).

Question 19.
x + 4y = 1
3x + 5y = 10

Answer:
The solution set is (5, -1).

Explanation:
The systems of linear equations are
x + 4y = 1 —- (i)
3x + 5y = 10 —- (ii)
Multiply equation (i) by 3
3(x + 4y = 1)
3x + 12y = 3 —- (iii)
Subtract equation (iii) from (ii)
3x + 5y – (3x + 12y) = 10 – 3
3x + 5y – 3x – 12y = 7
-7y = 7
y = -1
Substitute y = -1 in (i)
x + 4(-1) = 1
x – 4 = 1
x = 1 + 4
x = 5
Substitute x = 5, y = -1 in (i)
5 + 4(-1) = 5 – 4 = 1
So, the solution set is (5, -1).

Question 20.
-2x + 3y = 7
5x + 8y = -2

Answer:
The solution set is (-2, 1).

Explanation:
The systems of linear equations are
-2x + 3y = 7 —- (i)
5x + 8y = -2 —– (ii)
Multiply equation (i) by 5 and equation (ii) by 2
5(-2x + 3y = 7)
-10x + 15y = 35 —- (iii)
2(5x + 8y = -2)
10x + 16y = -4 —- (iv)
Add equations (iii) & (iv)
-10x + 15y + 10x + 16y = 35 – 4
31y = 31
y = 1
Substitute y = 1 in (i)
-2x + 3(1) = 7
-2x = 7 – 3
-2x = 4
x = -2
Substitute x = -2, y = 1 in (ii)
5(-2) + 8(1) = -10 + 8 = -2
So, the solution set is (-2, 1).

Question 21.
3x + 3 = 3y
2x – 6y = 2

Answer:
The solution set is (-2, -1).

Explanation:
The systems of linear equations are
3x + 3 = 3y —- (i)
2x – 6y = 2 —- (ii)
Multiply equation (i) by 2
2(3x + 3 = 3y)
6x + 6 = 6y
6x – 6y = -6 —- (iii)
Subtract equations (ii) & (iii)
2x – 6y – 6x + 6y = 2 + 6
-4x = 8
x = -2
Substitute x = -2 in (i)
3(-2) + 3 = 3y
-6 + 3 = 3y
-3 = 3y
y = -1
Substitute x = -2, y = -1 in (i)
3(-2) + 3 = 3(-1)
-6 + 3 = -3
So, the solution set is (-2, -1).

Question 22.
2x – 6 = 4y
7y =-3x + 9

Answer:
The solution set is (3, 0).

Explanation:
The systems of linear equations are
2x – 6 = 4y
2x – 4y = 6 —- (i)
7y = -3x + 9
3x + 7y = 9 —- (ii)
Multiply (i) by 7 and (ii) by 4
7(2x – 4y = 6)
14x – 28y = 42 —- (iii)
4(3x + 7y = 9)
12x + 28y = 36 —- (iv)
Add equations (iii) & (iv)
14x – 28y + 12x + 28y = 42 + 36
26x = 78
x = 78/26
x = 3
Substitute x = 3 in (i)
2(3) – 4y = 6
6 – 4y = 6
6 – 6 = 4y
y = 0
Substitute x = 3, y = 0 in (i)
2(3) – 4(0) = 6 – 0 = 6
So, the solution set is (3, 0).

Question 23.
5x = 4y + 8
3y = 3x – 3

Answer:
The solution set is (4, 3).

Explanation:
The systems of linear equations are
5x = 4y + 8
5x – 4y = 8 — (i)
3y = 3x – 3
3x – 3y = 3 —- (ii)
Multiply (i) by 3 and (ii) by 4
3(5x – 4y = 8)
15x – 12y = 24 — (iii)
4(3x – 3y = 3)
12x – 12y = 12 —- (iv)
Subtract obtained equations
15x – 12y – 12x + 12y = 24 – 12
3x = 12
x = 4
Substitute x = 4 in (ii)
3(4) – 3y = 3
12 – 3y = 3
-3y = 3 – 12
-3y = -9
y = 3
Substitute x = 4, y = 3 in (ii)
3(4) – 3(3) = 12 – 9 = 3
So, the solution set is (4, 3).

Question 24.
YOU BE THE TEACHER
Your friend solves the system. Is your friend correct? Explain your reasoning.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 41

Answer:
Wrong.

Explanation:
Given equations are
x + y = 1 — (i)
5x + 3y = -3 (ii)
Multiply equation (i) by -5
-5(x + y = 1)
-5x – 5y = -5 — (iii)
Add equations (iii) & (ii)
-5x – 5y + 5x + 3y = -3 – 5
-2y = -8
y = 4
Put y = 4 in (i)
x + 4 = 1
x = 1 – 4 = -3
So, the solution set is (-3, 4).

CHOOSING A SOLUTION METHOD
Solve the system. Explain your choice of method.

Question 25.
x + y = 4
x – y = 4

Answer:
The solution set is (4, 0).

Explanation:
The systems of linear equations are
x + y = 4 — (i)
x – y = 4 — (ii)
Add equations
x + y + x – y = 4 + 4
2x = 8
x = 4
Substitute x = 4 in (i)
4 + y = 4
y = 4 – 4
y = 0
So, the solution set is (4, 0).

Question 26.
y = x – 3
y = -2x + 3

Answer:
The solution set is (2, -1).

Explanation:
The systems of linear equations are
y = x – 3 — (i)
y = -2x + 3 — (ii)
Equate both equations
x – 3 = -2x + 3
x + 2x = 3 + 3
3x = 6
x = 2
Substitute x = 2 in (i)
y = 2 – 3
y = -1
So, the solution set is (2, -1).

Question 27.
x + 2y = 0
2x – y = 4

Answer:
The solution set is (8/5, -4/5)

Explanation:
The systems of linear equations are
x + 2y = 0 —- (i)
2x – y = 4 —- (ii)
y = 2x – 4
Substitute y = 2x – 4 in (i)
x + 2(2x – 4) = 0
x + 4x – 8 = 0
5x = 8
x = 8/5
Substitute x = 8/5 in (i)
8/5 + 2y = 0
2y = -8/5
y = -4/5
So, the solution set is (8/5, -4/5)

Question 28.
y + 5x = 1
5y – x = 5

Answer:
The solution set is (0, 1).

Explanation:
The systems of linear equations are
y + 5x = 1 —- (i)
5y – x = 5 —- (ii)
5y – 5 = x
Substitute x = 5y – 5 in (i)
y + 5(5y – 5) = 1
y + 25y – 25= 1
26y = 1 + 25
26y = 26
y = 1
Substitute y = 1 in (i)
1 + 5x = 1
5x = 0
x = 0
So, the solution set is (0, 1).

Question 29.
2 = x – 3y
-2x + y = 4

Answer:
The solution set is (-14/5, -8/5)

Explanation:
The systems of linear equations are
2 = x – 3y
x = 2 + 3y — (i)
-2x + y = 4 —- (ii)
Substitute (i) in (ii)
-2(2 + 3y) + y = 4
-4 – 6y + y = 4
-5y = 4 + 4
y = -8/5
Substitute y = -8/5 in (i)
x = 2 + 3(-8/5)
x = 2 – 24/5
x = -14/5
So, the solution set is (-14/5, -8/5)

Question 30.
8x + 5y = 6
8x = 3 – 2y

Answer:
The solution set is (1/8, 1).

Explanation:
The systems of linear equations are
8x + 5y = 6 —- (i)
8x = 3 – 2y —- (ii)
Substitute (ii) in (i)
3 – 2y + 5y = 6
3y = 6 – 3
3y = 3
y = 1
Substitute y = 1 in (ii)
8x = 3 – 2(1)
8x = 1
x = 1/8
So, the solution set is (1/8, 1).

NUMBER SENSE
For what value of a might you choose to solve the system by elimination? Explain.

Question 31.
4x – y = 3
ax + 10y = 6

Answer:
If a is 4 or -4 it is easy to solve the systems of linear equations using the elimination method as by just subtracting or adding the equations, we can eliminate x.

Explanation:
The systems of linear equations are
4x – y = 3
ax + 10y = 6
If a is 4 or -4 it is easy to solve the systems of linear equations using the elimination method as by just subtracting or adding the equations, we can eliminate x.

Question 32.
x – 7y = 6
-6x + ay = 9

Answer:
If a is 7 or -7 it is easy to solve the systems of linear equations using the elimination method as by just adding or subtracting the equations, we can eliminate x.

Explanation:
The systems of linear equations are
x – 7y = 6
-6x + ay = 9
If a is 7 or -7 it is easy to solve the systems of linear equations using the elimination method as by just adding or subtracting the equations, we can eliminate x.

CRITICAL THINKING
Determine whether the line through the first pair of points intersects the line through the second pair of points. Explain.

Question 33.
Line 1: (-2, 1), (2, 7)
Line 2: (-4, -1), (0, 5)

Answer:
No

Explanation:
Equation of a line passing through points (x₁, y₁) and (x₂, y₂) is y – y₁ = (y₂ – y₁)/(x₂ – x₁) (x – x₁)
So, equation of line 1 is
y – 1 = (7 – 1)/(2 + 2)(x + 2)
y – 1 = 6/4 (x + 2)
y – 1 = 3/2 (x + 2)
2(y – 1) = 3(x + 2)
2y – 2 = 3x + 6
3x – 2y = -2 – 6
3x – 2y = -8
Equation of line 2 is
y + 1 = (5 + 1)/(0 + 4) (x + 4)
y + 1 = 6/4 (x + 4)
y + 1 = 3/2 (x + 4)
2(y + 1) = 3(x + 4)
2y + 2 = 3x + 12
3x – 2y = 2 – 12
3x – 2y = -10
As the slope of the lines are same, but the consant is different, the lines are parallek to each other and there is no point of intersection.

Question 34.
Line 1: (-2, 8), (0, 2)
Line 2: (3, -2), (6, 4)

Answer:
Yes

Explanation:
Equation of a line passing through points (x₁, y₁) and (x₂, y₂) is y – y₁ = (y₂ – y₁)/(x₂ – x₁) (x – x₁)
So, line 1 is
y – 8 = (2 – 8)/(0 + 2) (x + 2)
y – 8 = -6/2 (x + 2)
y – 8 = -3(x + 2)
y – 8 = -3x – 6
3x + y = -6 + 8
3x + y = 2
Line 2 is
y + 2 = (4 + 2)/(6 – 3) (x – 3)
y + 2 = 6/3 (x – 3)
y + 2 = 2(x – 3)
y + 2 = 2x – 6
2x – y = 8
As the slopes are different, so the lines intesect each other.

Question 35.
REASONING
Two airplanes are flying to the same airport. Their positions are shown in the graph. Write a system of linear equations that represents this situation. Solve the system by elimination to justify your answer.
Big Ideas Math Answer Key Grade 8 Chapter 5 Systems of Linear Equations 42

Answer:
x = 6, y = 12.

Explanation:
To write the system we need the slope of each line and at least one point on the line. The two lines to consider will be the lines connecting the location of each plane to the airport they are flying to. It is also worth noting that the coordinates of the airport represent the point of intersection of the two lines and thus the solution to the system.
Airport (6, 12), Airplane 1 (2, 4), Airplane 2 (15, 9)
the slope of the line connecting airplane 1 and the airport = (4 – 12)/(2- 6)
= -8/-4 = 2
The line equation is y – 4 = 2(x -4)
2x – y = 0
slope of the line connecting airplane 2 and the airport = (4 – 9)/(2 – 15)
= -5/-13 = 5/13
The line equation is y – 9 = 5/13 (x – 15)
x + 3y = 42
So, the system of linear equations are
2x – y = 0 —- (i)
x + 3y = 42 —– (ii)
Multiply (ii) by 2
2(x + 3y = 42)
2x + 6y = 84 — (iii)
Subtract (iii) & (i)
2x – y – 2x – 6y = 0 – 84
-7y = -84
y = 12
Put y = 12 in (i)
2x – 12 = 0
x = 6
We have proven that the location of the airport is in fact the solution to our system.

Question 36.
MODELING REAL LIFE
A laboratory uses liquid nitrogen tanks of two different sizes. The combined volume of 3 large tanks and 2 small tanks is 24 liters. The combined volume of 2 large tanks and 3 small tanks is 21 liters. What is the volume of each size of tank? Justify your answer.

Answer:
The volume of the large tank is 6 lit, the volume of the small tank is 3 lit.

Explanation:
Let x and y be the volume of the large and small tank
The combined volume of 3 large tanks and 2 small tanks is 24 liters. The combined volume of 2 large tanks and 3 small tanks is 21 liters
Combined volume = No of large tanks x volume of large tank + No of small tanks x volume of small tank
3x + 2y = 24 — (i)
2x + 3y = 21 —- (ii)
Multiply (i) by -2 and (ii) by 3
-2(3x + 2y = 24)
-6x – 4y = -48
3(2x + 3y = 21)
6x + 9y = 63
Add obtained equations
-6x – 4y + 6x + 9y = -48 + 63
5y = 15
y = 3
Put y = 3 in (i)
3x + 6 = 24
3x = 24 – 6
3x = 18
x = 6
So, the volume of the large tank is 6 lit, volume of the small tank is 3 lit.

Question 37.
PROBLEM SOLVING
The table shows the numbers of correct answers on a practice standardized test. You score 86 points on the test and your friend scores 76 points. How many points is each type of question worth?
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 43

Answer:
The marks for correct multiple choice questions, short response questions are 2 and 4.

Explanation:
Let x, y be the marks of multiple choice & short response questions
Total marks = no of correct MCQs x marks for correct MCQs + no of short response questions x marks for short response questions
23x + 10y = 86 — (i)
28x + 5y = 76 —- (ii)
Multiply (ii) by 2
2(28x + 5y = 76)
56x + 10y = 152 —- (iii)
Subtract (i) & (iii)
23x + 10y – 56x – 10y = 86 – 152
-33x = -66
x = 2
Put x = 2 in (i)
23(2) + 10y = 86
10y = 86 – 46
10y = 40
y = 4
So, the marks for correct multiple choice questions, short response questions are 2 and 4.

Question 38.
LOGIC
You solve a system of equations in which x represents the number of adult memberships sold and y represents the number of student memberships sold. Can (-6, 24) be the solution to the system? Explain your reasoning.

Answer:
If x represents the number of adult tickets sold, then x must be a non-negative number since there can’t be a negative number of tickets sold.
Therefore (-6, 24) can’t be a solution since that would give x = 6.

Explanation:
If x represents the number of adult tickets sold, then x must be a non-negative number since there can’t be a negative number of tickets sold.
Therefore (-6, 24) can’t be a solution since that would give x = 6.

Question 39.
PROBLEM SOLVING
The table shows the activities of two tourists at a vacation resort. You want to go parasailing for 1 hour and horseback riding for 2 hours. How much do you expect to pay?
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 44
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 44.1

Answer:
The cost of parasailing for 1 hour and horseback riding for hours is $90.

Explanation:
Let x and y represent per hour price for parasailing and horseback riding
Total cost = no of hours of parasailing x per hour price for parasailing + no of hours of horseback riding x per hour price for horseback riding
2x + 5y = 205 —- (i)
3x + 3y = 240 — (ii)
Multiply (i) by 3 and (ii) by 2
3(2x + 5y = 205)
6x + 15y = 615 — (iii)
2(3x + 3y = 240)
6x + 6y = 480 —- (iv)
Subtract (iii) & (iv)
6x + 15y – 6x – 6y = 615 – 480
9y = 135
y = 15
Put y = 15 in (i)
2x + 15(5) = 205
2x = 205 – 75
2x = 130
x = 65
So, the Cost of parasailing for 1 hour and harseback riding for hours is x + 2y
= 65 + 2(15)
= $95.

Question 40.
REASONING
Write a system of linear equations containing 2x + y = 0 and that has the solution (2, -4).

Answer:
The system of linear equations are 2x + y = 0, x – y = 6.

Explanation:
The equation of a line that passes through (2, -4) is y = mx + b
-4 = 2m + b
Let us take m slope as 1
-4 = 2 + b
b = -4 – 2
b = -6
So, line is y = x – 6
So, the system of linear equations are 2x + y = 0, x – y = 6.

Question 41.
REASONING
A metal alloy is a mixture of two or more metals. A jeweler wants to make 8 grams of 18-karat gold, which is 75% gold. The jeweler has an alloy that is 90% gold and an alloy that is 50% gold. old. How much of each alloy should the jeweler use?
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 45

Answer:
The jeweler should use 5, 3 grams of first and second alloy.

Explanation:
Let x, y be the amount of first & second alloy
Amount of gold = percentage of gold in first alloy x amount of first alloy + percentage of gold in second alloy x amount of the second alloy
x + y = 8
0.9x + 0.5y = 6
y = 8 – x
0.9x + 0.5(8 – x) = 6
0.4x + 4 = 6
0.4x = 2
x = 5
y = 8 – 5
y = 3
The jeweler should use 5, 3 grams of first and second alloy.

Question 42.
PROBLEM SOLVING
It takes a powerboat traveling with the current 30 minutes to go 10 miles. The return trip takes 50 minutes traveling against the current. What is the speed of the current?

Answer:
The current speed is 4 miles per hour.

Explanation:
Let r be the speed of the boat and w be the speed of water current
downstream 10 = (r + w)30
1 = 3(r + w)
3r + 3w = 1 — (i)
Upstream 10 = (r – w)50
1 = 5(r – w)
5r – 5w = 1 —- (ii)
Multiply (i) by 5 and (ii) by 3 and add them
15r + 15w + 15r – 15w = 5 + 3
30r = 8
r = 4/15
substitute r = 4/15 in (ii)
5(4/15) – 5w = 1
4/3 – 5w = 1
-5w = -1/3
w = 1/15 miles per inute
= 1/15 (60) = 4 miles per hour
The current speed is 4 miles per hour.

Question 43.
DIG DEEPER!
Solve the system of equations by elimination.
2x – y + 3z = -1
x + 2y – 4z = -1
y – 2z = 0

Answer:
The solution set is (-1, 2, 1).

Explanation:
The given systems of linear equations are
2x – y + 3z = -1 —– (i)
x + 2y – 4z = -1 —- (ii)
y – 2z = 0 —– (iii)
Substitute y = 2z in (i) & (ii)
2x – 2z + 3z = -1
2x+ z = -1 —- (iv)
x + 4z – 4z = -1
x = -1
Substitute x = -1 in (iv)
2(-1) + z = -1
z = -1 + 2
z = 1
Substitute z = 1 in (iii)
y – 2 = 0
y = 2
So, the solution set is (-1, 2, 1).

Lesson 5.4 Solving Special Systems of Linear Equations

EXPLORATION 1
Exploring Solutions of Systems
Work with a partner. You spend $50 on a sewing machine to makedog backpacks. Each backpack costs you $15 for materials.
a. Represent the cost (in dollars) to make backpacks in the coordinate plane.
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 46
b. You charge $25 per backpack. How many backpacks do you have to break even sell to ? Use a graph to justify your answer.
c. Can you break even when you sell each backpack for $20? $15? Use graphs to justify your answers.
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 47
d. Explain whether it is possible for a system of linear equations to have the numbers of solutions below.

  • no solution
  • exactly one solution
  • exactly two solutions
  • infinitely many solutions

Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 48

5.4 Lesson

Try It

Solve the system. Explain your choice of method.

Question 1.
y = -x + 3
y = -x + 5

Answer:
There is no solution.

Explanation:
The given systems of linear equations are
y = -x + 3
y = -x + 5
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 37
The two lines are parallel to each other.
So, there is no solution.

Question 2.
y = -5x – 2
5x + y = 0

Answer:
The system has no solution.

Explanation:
The given systems of linear equations are y = -5x – 2, 5x + y = 0
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 38
The two lines are parallel to each other.
So, the system has no solution.

Question 3.
x = 2y + 10
2x + 3y = -1

Answer:
The solution set is (4, -3)

Explanation:
The given systems of linear equations are x = 2y + 10, 2x + 3y = -1
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 39
The point of intersection of two lines is (4, -3)
So, the solution set is (4, -3)

Try It

Solve the system. Explain your choice of method.

Question 4
x + y = 3
x = y – 3

Answer:
The solution set is (0, 3).

Explanation:
The given systems of linear equations are
x + y = 3 — (i)
x = y – 3 —- (ii)
Substitute (ii) in (i)
y – 3 + y = 3
2y = 6
y = 3
Substitute y = 3 in (ii)
x = 3 – 3
x = 0
So, the solution set is (0, 3).

Question 5.
2x + y = 5
4x + 2y = 0

Answer:
The system has no solution.

Explanation:
The given systems of linear equations are
2x + y = 5 —- (i)
4x + 2y = 0 —- (ii)
Solve by graphing
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 40
The lines are parallel so the system has no solution.

Question 6.
2x – 4y = 10
-12x + 24y = -60

Answer:
The system has infinitely many solutions.

Explanation:
The given systems of linear equations are
2x – 4y = 10 —- (i)
-12x + 24y = -60 — (ii)
Multiply (i) by 6
6(2x – 4y = 10)
12x – 24y = 60 — (iii)
Add (ii) & (iii)
-12x + 24y + 12x – 24y = -60 + 60
0 = 0
So, the system has infinitely many solutions.

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

STRUCTURE
Without graphing or solving, determine the number of solutions of the system. Explain your reasoning.

Question 7.
y = 5x – 9
y = 5x + 9

Answer:
The system has infinitely many solutions.

Explanation:
The given systems of linear equations are
y = 5x – 9
y = 5x + 9
the slope of the two lines are the same i.e 5
So, the system has infinitely many solutions.

Question 8.
y = 6x + 2
y = 3x + 1

Answer:
The system has one solution.

Explanation:
The given systems of linear equations are
y = 6x + 2
slope1 = 6
y = 3x + 1
slope2 = 3
Slopes are different
So, the system has one solution.

Question 9.
y = 8x – 2
y – 8x = -2

Answer:
The system has infinitely many solutions.

Explanation:
The given systems of linear equations are
y = 8x – 2
slope 1 = 8
y – 8x = -2
y = -2 + 8x
slope 2 = 8
the slope of the two lines are the same i.e 8
So, the system has infinitely many solutions.

CHOOSING A METHOD
Solve the system. Explain your choice of method.

Question 10.
2x + y = 6
x – y = 3

Answer:
The solution set is (3, 0).

Explanation:
The given systems of linear equations are
2x + y = 6 —- (i)
x – y = 3 — (ii)
Add equations
2x + y + x – y = 3 + 6
3x = 9
x = 3
Substitute x = 3 in (ii)
3 – y = 3
y = 0
So, the solution set is (3, 0).

Question 11.
4y – 4x = 8
y = x + 2

Answer:
The system has infinitely many solutions.

Explanation:
The given systems of linear equations are
4y – 4x = 8 — (i)
y = x + 2 —- (ii)
Substitute 2 in 1
4(x + 2) – 4x = 8
4x + 8 – 4x = 8
8 = 8
So, the system has infinitely many solutions.

Question 12.
5x – 4y = 12
7.5x = 6(y – 1)

Answer:
The system has no solution.

Explanation:
The given systems of linear equations are
5x – 4y = 12
7.5x = 6(y – 1)
By graphing
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 41
The lines are parrel
So, the system has no solution.

Question 13.
-6x = 9
6x – y = 3

Answer:
The solution set is (-3/2, -12)

Explanation:
The given systems of linear equations are
-6x = 9
6x – y = 3
-6x = 9
x = -9/6
x = -3/2
Substitute x = -3/2 in 6x – y = 3
6(-3/2) – y = 3
-18/2 – 3 = y
y = -24/2
y = -12
So, the solution set is (-3/2, -12)

Question 14.
0.5x + 4y = -11
-1.5x – 12y = 33

Answer:
The system has infinitely many solutions.

Explanation:
The given systems of linear equations are
0.5x + 4y = -11
-1.5x – 12y = 33
By graphing
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 42
Two equations are on the same line.
So, the system has infinitely many solutions.

Question 15.
x = y + 2
3x = 6(y + 2)

Answer:
The solution set is (0, -2).

Explanation:
The given systems of linear equations are
x = y + 2
3x = 6(y + 2)
By graphing
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 43
The point of intersection of two equations is (0, -2)
so, the solution set is (0, -2).

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 16.
Your friend wants to sell painted rocks. He spends $10.00 on startup costs, and each painted rock costs him $0.75 to make. A store offers to pay your friend’s startup costs and buy his painted rocks for $0.75 each. How many painted rocks does your friend need to sell to make a profit?

Answer:
No profit.

Explanation:
The cost on startup is $10 and each painted rock costs around $0.75 to make
A store pays startup cost and buys his painted rocks for $0.75 each
There will be no profit because the cost price and selling price is the same. He buys for $0.75 and sells the same for $0.75.

Question 17.
DIG DEEPER!
The difference in age of two orangutans is 6 years. In 4 years, is it possible for the older orangutan to be twice as old as the younger orangutan? three times as old? Justify your answers.
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 49

Answer:
Both are possible

Explanation:
Let us take the age of two orangutans as x and y
The difference in age of two orangutans is 6 years
x – y = 6
So, x is the older one
x = 6 + y
If the older orangutan to be twice as old as the younger orangutan
x = 2y
2y – y = 6
y = 6
If the older orangutan to be three times as old as the younger orangutan
x = 3y
3y – y = 6
2y = 6
y = 3
Both are possible, the older orangutan to be twice as old as the younger orangutan when younger age is 6 years and the older orangutan to be three times as old as the younger orangutan when the younger age is 3 years.

Solving Special Systems of Linear Equations Homework & Practice 5.4

Review & Refresh

Solve the system by elimination. Check your solution.

Question 1.
x + 2y = 4
-x – y = 2

Answer:
The solution set is (-8, 6)

Explanation:
The given systems of linear equations are
x + 2y = 4 — 1
-x – y = 2 — 2
Add both equations
x + 2y – x – y = 4 + 2
y = 6
Substitute y = 6 in 2
-x – 6 = 2
-x = 2 + 6
x = -8
Substitute x = -8, y = 6 in 2
8 – 6 = 2
So, the solution set is (-8, 6)

Question 2.
2x – y = 1
x + 3y – 4 = 0

Answer:
The solution set is (1, 1).

Explanation:
The given systems of linear equations are
2x – y = 1 —- (i)
x + 3y – 4 = 0 —- (ii)
Multiply (i) by 3
3(2x – y = 1)
6x – 3y = 3 —- (iii)
Add (iii) & (ii)
6x – 3y + x + 3y – 4 = 3
7x = 3 + 4
7x = 7
x = 1
Substitute x = 1 in (i)
2(1) – y = 1
2 – y = 1
2 – 1 = y
y = 1
Substitute x = 1, y = 1 in (i)
2(1) – 1 = 2 – 1 = 1
So, the solution set is (1, 1).

Question 3.
3x = -4y + 10
4x + 3y = 11

Answer:
The solution set is (2, 1).

Explanation:
The given systems of linear equations are
3x = -4y + 10
3x + 4y = 10 —- (i)
4x + 3y = 11—- (ii)
Multiply (i) by 4 and (ii) by 3
4(3x + 4y = 10)
12x + 16y = 40 —- (iii)
3(4x + 3y = 11)
12x + 9y = 33 —- (iv)
Subtract (iii) from (iv)
12x + 16y – 12x – 9y = 40 – 33
7y = 7
y = 1
Substitute y = 1 in (i)
3x + 4 = 10
3x = 6
x = 2
Substitute x = 2, y = 1 in (i)
3(2) + 4 = 6 + 4 = 10
So, the solution set is (2, 1).

Write an equation of the line that passes through the given points.

Question 4.
(0, 0), (2, 6)

Answer:
y = 3x

Explanation:
The equation of a line when two points given is
(y – y₁) = [(y₂ – y₁)/(x₂ – x₁)](x – x₁)
x₁ = 0, y₁ = 0, x₂ = 2, y₂ = 6
So, (y – 0) = [(6 – 0)/(2 – 0)] (x – 0)
y = 3x

Question 5.
(0, -3), (3, 3)

Answer:
y = 2x – 3

Explanation:
The equation of a line when two points given is
(y – y₁) = [(y₂ – y₁)/(x₂ – x₁)](x – x₁)
x₁ = 0, y₁ = -3, x₂ = 3, y₂ = 3
So, (y + 3) = [(3 + 3)/(3 – 0)](x – 0)
(y + 3)  = 2x
y = 2x – 3

Question 6.
(-6, 5), (0, 2)

Answer:
x + 2y = 6

Explanation:
The equation of a line when two points are given is
(y – y₁) = [(y₂ – y₁)/(x₂ – x₁)](x – x₁)
x₁ = -6, y₁ = 5, x₂ = 0, y₂ = 2
So, (y – 5) = [(2 – 5)/(0 + 6)](x + 6)
y – 6 = -3/6 (x + 6)
y – 6 = -1/2 (x + 6)
2(y – 6) = -1(x + 6)
2y – 12 = -x – 6
2y = -x – 6 + 12
x + 2y = 6

Concepts, Skills, &Problem Solving
EXPLORING SOLUTIONS OF SYSTEMS
Use a graph to determine the number of solutions of the system. (See Exploration 1, p. 219.)

Question 7.
y = 2x + 1
y = 2x + 5

Answer:
The system has no solution.

Explanation:
The given systems of linear equations are y = 2x + 1, y = 2x + 5
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 44
The lines are parallel
So, the system has no solution.

Question 8.
y + 8 = 0
y = 8

Answer:
The system has no solution.

Explanation:
The given systems of linear equations are y + 8 = 0, y = 8
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 45
The lines are parallel
So, the system has no solution.

Question 9.
x + y = 2
5x + y = 9

Answer:
The solution is (7/4, 1/4)

Explanation:
The given systems of linear equations are x + y = 2, 5x + y = 9
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 46
The lines intersect at (7/4, 1/4)
So, the solution is (7/4, 1/4)

SOLVING A SYSTEM
Solve the system. Explain your choice of method.

Question 10.
y = 2x – 2
y = 2x + 9

Answer:
The system has no solution.

Explanation:
The given systems of linear equations are
y = 2x – 2 — (i)
y = 2x + 9 — (ii)
Equate equations
2x – 2 = 2x + 9
So, the system has no solution.

Question 11.
y = 3x + 1
-x + 2y = -3

Answer:
The solution is (-1, -2).

Explanation:
The given systems of linear equations are y = 3x + 1, -x + 2y = -3
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 47
The lines intersect at (-1, -2)
So, the solution is (-1, -2).

Question 12.
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 50

Answer:
The system has no solution.

Explanation:
The given systems of linear equations are
y = π/3 x + π —- (i)
-πx + 3y = -6π —- (ii)
Substitute (i) in (ii)
-πx + 3(π/3 x + π) = -6π
-πx + πx + 3π = -6π
So, the system has no solution.

Question 13.
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 51

Answer:
The system has infinitely many solutions.

Explanation:
The given systems of linear equations are
y = -1/6 x + 5 —-(i)
x + 6y = 30 —- (ii)
Substitute (i) in (ii)
x + 6(-1/6 x + 5) = 30
x – x + 30 = 30
So, the system has infinitely many solutions.

Question 14.
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 52

Answer:
The system has infinitely many solutions.

Explanation:
The given systems of linear equations are
1/3 x + y = 1 —- (i)
2x + 6y = 6 —- (ii)
Divide (ii) by 1/6
1/6(2x + 6y = 6)
1/3 x + y = 1 —- (iii)
equation (i) & (iii) are same
So, the system has infinitely many solutions.

Question 15.
-2x + y = 1.3
2(0.5x – y) = 4.6

Answer:
The solution is (-2.4, -3.5)

Explanation:
The given systems of linear equations are -2x + y = 1.3, 2(0.5x – y) = 4.6
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 48
The lines intersect at (-2.4, -3.5)
So, the solution is (-2.4, -3.5)

Question 16.
2(x + y) = 9
1 = -4(x + y)

Answer:
The system has no solution.

Explanation:
The given systems of linear equations are 2(x + y) = 9, 1 = -4(x + y)
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 49
The lines are parallel
So, the system has no solution.

Question 17.
y = 9x
x + y = 1

Answer:
The solution is (1/10, 9/10)

Explanation:
The given systems of linear equations are y = 9x, x + y = 1
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 50
The lines intersect at (1/10, 9/10)
So, the solution is (1/10, 9/10)

Question 18.
0.2y = 4.6x + 1.2
-2.3x = -0.1y + 0.6

Answer:
The system has infinitely many solutions

Explanation:
The given systems of linear equations are 0.2y = 4.6x + 1.2, -2.3x = -0.1y + 0.6
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 51
Two equations lies on the same line
So, the system has infinitely many solutions

Question 19.
YOU BE THE TEACHER
Your friend finds the number of solutions of the system. Is your friend correct? Explain your reasoning.
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 53

Answer:
Correct.

Explanation:
The given systems of linear equations are
y = -2x + 4
y = -2x + 6
Two equations have the same slope
So, the system has infinitely many solutions.

Question 20.
REASONING
In a pig race, your pig has a head start of 3 feet and runs at a rate of 2 feet per second. Your friend’s pig also runs at a rate of 2 feet per second. A system of linear equations that represents this situation is y = 2x + 3 and y = 2x. Does your friend’s pig catch up to your pig? Explain.
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 54

Answer:
No.

Explanation:
y = 2x + 3 and y = 2x
Substitute y = 2x in y = 2x + 3
2x = 2x + 3
2x – 2x = 3
0 = 3
The system has no solution
Your friend’s pig never catch up to your pig

Question 21.
REASONING
One equation in a system of linear equations has a slope of 3. The other equation has a slope of 4. How many solutions does the system have? Explain.

Answer:
The system has one solution.

Explanation:
One equation in a system of linear equations has a slope of 3. The other equation has a slope of 4
As the slopes are different. The system has one solution.

Question 22.
LOGIC
How can you use the slopes and the y-intercepts of equations in a system one solution, infinitely many solutions, or no solution?

Answer:
The slope-intercept form of a line is y = mx + c
If the slope is the same, different y-intercept for the two equations, then the system has no solution.
If the slope is different for two equations, then the system has one solution.
If the slope is the same, the same y-intercept for two equations, then the system has infinitely many solutions.

Question 23.
PROBLEM SOLVING
You and a friend both work two different jobs. The system of linear equations represents the total earnings (in dollars) for x hours worked at the first job and y hours worked at the second job. Your friend earns twice as much as you.
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 55
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 56
a. One week, both of you work 4 hours at the first job. How many hours do you and your friend work at the second job?
b. Both of you work the same number of hours at the second job. Compare the number of hours you and your friend work at the first job.

Answer:
a. 16 hours you and your friend work at the second job
b. If both work the same y hours at a second job, then both will same x hours at the first job.

Explanation:
Let x represent the first job and y represents the second job
The system of linear equations for the total number of hours for the first job & second job for you & your friend is
4x + 8y = 64
8x + 16y = 128
a. If x = 4
8(4) + 16y = 128
32 + 16y = 128
16y = 128 – 32
16y = 96
y = 16 hours
b. If both work the same y hours at the second job, then both will same x hours at the first job.

Question 24.
MODELING REAL LIFE
You download a digital album for $10.00. Then you and your friend each download the same number of individual songs for $0.99 each. Write a system of linear equations that represents this situation. Will you and your friend spend the same amount of money? Explain.

Answer:
No

Explanation:
Write the equations for you and your friends’ total cost y where x is the number of songs
you y = 10 + 0.99x
your friend y = 0.99x
The two equations have the same slope but different y-intercepts so the system has no solution.

Question 25.
MODELING REAL LIFE
The table shows the research activities of two students at an observatory. How much does a student pay to use the telescope for one hour?
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 57

Answer:
A student must pay $7.5 for using a telephone per hour and $11 for using a supercomputer per hour.

Explanation:
Let the cost of telephonic use be x, supercomputer use be y. The system of equations are
5x + 3y = 70.50 — (i)
6x + 2y = 67 —- (ii)
Multiply (i) by 2 and (ii) by 3 and subtract them
10x + 6y = 141
18x + 6y = 201
10x + 6y – 18x – 6y = 141 – 201
-8x = -60
x = 7.5
Substitute x = 7.5 in (ii)
6(7.5) + 2y = 67
45 + 2y = 67
2y = 67 – 45
2y = 22
y = 11
So, a student must pay $7.5 for using telephone per hour and $11 for using supercomputer per hour.

Question 26.
REASONING
Does the system shown always, sometimes, or never have a solution when a = b? a ≥ b? a < b? Explain your reasoning.
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 58

Answer:
If a = b, the system will always have no solution
If a ≥ b, the system will sometimes have no solution.
If a < b, the system will never have no solution.

Explanation:
If a = b, then two linear equations will have the same slope but different y-intercepts. So, they will always have no solution
If a ≥ b, then the slopes may be different or the same so they may intersect once or not at all. Therefore, they will sometimes have no solution.
If a < b, then the equations have a different slope so they will intersect once. so, they will never have no solution.

Question 27.
LOGIC
The table shows the numbers of lift tickets and ski rentals sold to different groups. Is it possible to determine how much each lift ticket costs using the information for Groups 1 and 2? Groups 1 and 3? Justify your answers.
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 89

Answer:
a. It is not possible to find out the cost of lift tickets using the given information.
b. The cost of a lift ticket is $14, cost of ski rental is $10.

Explanation:
Let the cost for lift tickets and cost for sky rentals be y. The system of equations are
36x + 18y = 684 — (i)
24x + 12y = 456 —- (ii)
18x + 18y = 432 —-(iii)
3(12x + 6y) = 684
12x + 6y = 228
2(12x + 6y) = 456
12x + 6y = 228
Both the equations are same. So, they have infinately many solutions.
Hence, it is not possible to find out the cost of lift tickets using the given information.
b. Subtract 1 from 2
36x + 18y – 18x – 18y = 684 – 432
18x = 252
x = 14
Put x = 14
36(14) + 18y = 684
504 + 18y = 684
18y = 180
y = 10
The cost of lift ticket is $14, cost of ski rentaks is $10.

Question 28.
DIG DEEPER!
Find the values of a and b so the system is shown has the solution (2, 3). Does the system have any other solutions for these values of a and b? Explain.
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 90

Answer:
(a, b) = (2, 2)

Explanation:
Given that,
12x – 2by = 12
3ax – by = 6
The value of a, b if (x, y) = (2, 3)
12(2) – 2b(3) = 12
24 – 6b = 12
6b = 24 – 12
6b = 12
b = 2
3a(2) – 3b = 6
6a – 3(2) = 6
6a – 6 = 6
6a = 12
a = 2
The system of equations are
12x – 4y = 12
2(6x – 2y) = 12
6x – 2y = 6 — (i)
6x – 2y = 6 — (ii)
As both the equations are same, they have infinately many solutions
(a, b) = (2, 2)

Systems of Linear Equations Connecting Concepts

Connecting Concepts

Using the Problem-Solving Plan

Question 1.
An animal shelter has a total of 65 cats and dogs. The ratio of cats to dogs is 6:7. Find the number of cats and the number of dogs in the shelter.
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 91
Understand the problem.
You know the total number of cats and dogs in an animal shelter, and the ratio of cats to dogs. You are asked to find the number of cats and the number of dogs in the shelter.
Make a plan.
Write a system of equations. Use the total number of cats and dogs to write an equation relating the number of cats and the number of dogs. Use the ratio of cats to dogs to write a second equation. Then solve the system.
Solve and check.
Use the plan to solve the problem. Then check your solution.

Answer:
The number of cats in the shelter is 30, the number of dogs are 35.

Explanation:
Let us take the number of dogs as x, cats as y
An animal shelter has a total of 65 cats and dogs.
x + y = 65 — (i)
The ratio of cats to dogs is 6:7
x : y = 6 : 7
6x = 7y
x = 7y/6
Substitute x = 7y/6 in (i)
7y/6 + y = 65
7y + 6y = 65(6)
13y = 390
y = 30
Substitute y = 30 in (i)
x + 30 = 65
x = 65 – 30
x = 35
So, the number of cats in the shelter are 30, number of dogs are 35.

Question 2.
The measure of ∠1 is 15 degrees less than two times the measure of ∠2. Find the measure of each of the four angles formed by the intersecting lines. Justify your answer.
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 92

Answer:
The angles are ∠1 = 125, ∠2 = 55, ∠3 = 125, ∠4 = 55.

Explanation:
The measure of ∠1 is 15 degrees less than two times the measure of ∠2.
∠1 – 15 = 2(∠2) — (i)
∠1 + ∠2 = 180 degrees — (ii)
∠1 = 180 – ∠2
180 – ∠2 – 15 = 2(∠2)
165 = 2∠2 + ∠2
165 = 3∠2
∠2 = 55 degrees
Substitute ∠2 = 55 in (i)
∠1 – 15 = 2(55)
∠1 = 110 + 15
∠1 = 125 degrees
So, the angles are ∠1 = 125, ∠2 = 55, ∠3 = 125, ∠4 = 55.

Question 3.
A landscaper plants grass seed over the entire area of two parks that are similar in shape. The ratio of the perimeter of Park A to the perimeter of Park B is 2 : 1. The parks have a combined area of 9000 square feet. How many square feet does the landscaper cover with grass seed at ParkA? Park B? Justify your answer.
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 93

Answer:
The landscaper cover with grass seed at ParkA is 60√2 at park B is 30√2.

Explanation:
let the side of park A is x, park b is y.
The ratio of the perimeter of Park A to the perimeter of Park B is 2 : 1
x : y = 2 : 1
x = 2y — (i)
The parks have a combined area of 9000 square feet
x² + y² = 9000 —- (ii)
Substitute x = 2y in (ii)
(2y)² + y² = 9000
4y² + y² = 9000
5y² = 9000
y² = 1800
y = 30√2
Substitute y = 30√2 in (i)
x = 2(30√2)
= 60√2
The landscaper cover with grass seed at ParkA is 60√2 at park B is 30√2.

Performance Task

Mixing Alloys

At the beginning of this chapter, you watched a STEAM Video called “Gold Alloys.” You are now ready to complete the performance task related to this video, available at BigIdeasMath.com. Be sure to use the problem-solving plan as you work through the performance task.
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 94

Systems of Linear Equations Chapter Review

Review Vocabulary

Write the definition and give an example of each vocabulary term.
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 95

Graphic Organizers

You can use a Four Square to organize information about a concept. Each of the four squares can be a category, such as definition, vocabulary, example, non-example, words, algebra, table, numbers, visual, graph, or equation. Here is an example of a Four Square for solving systems of linear equations by graphing.
Big Ideas Math Answers 8th Grade Chapter 5 Systems of Linear Equations 96

Choose and complete a graphic organizer to help you study the concept.

  1. solving systems of linear equations by substitution
  2. solving systems of linear equations by elimination
  3. systems of linear equations with no solution
  4. systems of linear equations with infinitely many solutions

Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 97

Chapter Self-Assessment

As you complete the exercises, use the scale below to rate your understanding of the success criteria in your journal.
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 98

5.1 Solving Systems of Linear Equations by Graphing (pp. 199-204)

Solve the system by graphing.

Question 1.
y = 2x – 3
y = x + 2

Answer:
The solution is (5, 7)

Explanation:
The given systems of linear equations are y = 2x – 3, y = x + 2
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 24
The lines intersect at (5, 7)
So, the solution is (5, 7)

Question 2.
y = -x + 4
x + 2y = 0

Answer:
The solution is (8, -4)

Explanation:
The given systems of linear equations are y = -x + 4, x + 2y = 0
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 25
The lines intersect at (8, -4)
So, the solution is (8, -4)

Question 3.
x – y = -2
2x – 3y = -2

Answer:
The solution is (-4, -2).

Explanation:
The given systems of linear equations are x – y = -2, 2x – 3y = -2
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 26
The lines intersect at (-4, -2)
So, the solution is (-4, -2)

Use a graphing calculator to solve the system.

Question 4.
y = -0.5x
y = 0.75x + 1.25

Answer:
The solution is (-1, 0.5)

Explanation:
The given systems of linear equations are y = -0.5x, y = 0.75x + 1.25
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 27
The lines intersect at (-1, 0.5)
So, the solution is (-1, 0.5)

Question 5.
y = 0.2x – 3
10x + 3y = 5

Answer:
The solution is (1.3, -2.7)

Explanation:
The given systems of linear equations are y = 0.2x – 3, 10x + 3y = 5
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 28
The lines intersect at (1.3, -2.7)
So, the solution is (1.3, -2.7)

Question 6.
2.6x + 1.3y = 7.8
1.2x – 3.6y = 12

Answer:
The solution is (4, -2)

Explanation:
The given systems of linear equations are 2.6x + 1.3y = 7.8, 1.2x – 3.6y = 12
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 29
The lines intersect at (4, -2)
So, the solution is (4, -2)

Question 7.
The sum of the two numbers is 38. Find each number when one number is 8 more than the other number. Use a system of linear equations to justify your answer.

Answer:
The numbers are 15, 28.

Explanation:
Let the two numbers be x, y
The sum of two numbers is 38
x + y = 38 — (i)
One number is 8 more than the other number
x + 8 = y — (ii)
Substitute y = x + 8 in (i)
x + x + 8  = 38
2x + 8 = 38
2x = 38 – 8
2x = 30
x = 15
Substitute x = 15 in (ii)
y = 15 + 8
y = 23
So, the numbers are 15, 28.

Question 8.
You observe the heights of two plants for an experiment. Plant A has a height of 8 centimeters and grows 1 centimeter each week. Plant B has a height of 4 centimeters and grows 2 centimeters each week.
a. Write a system of linear equations that represents this situation.
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 99
b. Will the plants ever have the same height? If so, what is the height?

Answer:
a. y = x + 8, y = 2x + 4
b. The same height will be 12 cm after4 weeks.

Explanation:
Let the total height be y, growth of the plant each week be x.
Plant A has a height of 8 centimeters and grows 1 centimeter each week. Plant B has a height of 4 centimeters and grows 2 centimeters each week.
a. y = x + 8 — (i)
y = 2x + 4 —- (ii)
b. If plants ever have the same height
x + 8 = 2x + 4
2x – x = 8 – 4
x = 4
y = 4 + 8
y = 12
The same height will be 12 cm after4 weeks.

Question 9.
Write a system of linear equations containing the equation y = -3x + 2 and that has a solution of (-1, 5). Use a graph to justify your answer.

Answer:
The equation is y = x + 6

Explanation:
Equation is y = -3x + 2
The point is (-1, 5)
The slope intercept form is y = mx + c
5 = -m + c
If m = 1
then c = 5 = -1 + c
c = 6
Then the equation is y = x + 6
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 52

5.2 Solving Systems of Linear Equations by Substitution (pp. 205–210)

Solve the system by substitution. Check your solution.

Question 10.
y = -3x – 7
y = x + 9

Answer:
The solution set is (-4, 5).

Explanation:
The given system of linear equations are
y = -3x – 7 —- (i)
y = x + 9 —- (ii)
Substitute (i) in (ii)
-3x – 7 = x + 9
-3x – x = 9 + 7
-4x = 16
x = -4
Substitute x = -4 in (i)
y = -3(-4) – 7
y = 12 – 7
y = 5
Substitute x = -4, y = 5 in (i)
5 = -3(-4) – 7 = 12 – 7
So, the solution set is (-4, 5).

Question 11.
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 100

Answer:
The solution set is (-8, 0)

Explanation:
The given system of linear equations are
1/2 x + y = -4 —- (i)
y = 2x + 16 —-(ii)
Substitute (ii) in (i)
1/2 x + 2x + 16 = -4
2.5x = -4 – 16
2.5x = -20
x = -8
Substitute x = -8 in (ii)
y = 2(-8) + 16
y = -16 + 16
y = 0
Substitute x = -8, y = 0 in (ii)
0 = 2(-8) + 16 = -16 + 16
So, the solution set is (-8, 0)

Question 12.
-x + 5y = 28
x + 3y = 20

Answer:
The solution set is (2, 6)

Explanation:
The given system of linear equations are
-x + 5y = 28
x + 3y = 20 —- (ii)
x = 5y – 28 —- (i)
Substitute (i) in (ii)
5y – 28 + 3y = 20
8y – 28 = 20
8y = 48
y = 6
Substitute y = 6 in (i)
x = 5(6) – 28
= 30 – 28
x = 2
Substitute y = 6, x = 2 in (ii)
2 + 3(6) = 2 + 18 = 20
So, the solution set is (2, 6)

Question 13.
Zoo admission costs $6 for children and $9 for adults. On Monday, 2200 people visit the zoo and the zoo collects $14,850 in admissions.
a. Write a system of linear equations that represents this situation.
b. How many zoo visitors are children? adults?
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 101

Answer:
a. 6x + 9y = 14850, x + y = 2200
b. There are 1650 child visitors and 550 adult visitors.

Explanation:
The cost for the zoo is $6 for children & $9 for adults. On Monday, 2200 people visit the zoo and the zoo collects $14,850 in admissions.
a. The system of equations are
6x + 9y = 14850 — (i)
x + y = 2200 — (ii)
b. Multiply (ii) by 6
6x + 6y = 13200
6x + 6y – 6x – 9y = 13200 – 14850
-3y = -1650
y = 550
Substitute y = 550 in (ii)
x + 550 = 2200
x = 2200 – 550
x = 1650
There are 1650 child visitors and 550 adult visitors.

Solve the system. Explain your choice of method.

Question 14.
y = x – 2
y = -2x + 1

Answer:
The solution set is (1, -1).

Explanation:
The given system of linear equations are
y = x – 2 — (i)
y = -2x + 1 — (ii)
x – 2 = -2x + 1
x + 2x = 1 + 2
3x = 3
x = 1
Substitute x = 1 in (i)
y = 1 – 2
y = -1
So, the solution set is (1, -1).

Question 15.
3y + 9 = 3x
y = –\(\frac{1}{3}\)x + 1

Answer:
The solution set is (3, 0).

Explanation:
The given system of linear equations are
3y + 9 = 3x — (i)
y = –\(\frac{1}{3}\)x + 1 —- (ii)
Substitute (ii) in (i)
3(-1/3 x + 1) + 9 = 3x
-x + 3 + 9 = 3x
4x = 12
x = 3
Substitute x = 3 in (i)
9 = 9 + 3y
y = 0
So, the solution set is (3, 0).

Question 16.
-x + 2y = -4
4y = x

Answer:
The solution set is (8, 2).

Explanation:
The given system of linear equations are
-x + 2y = -4 —- (i)
4y = x —- (ii)
Substitute (ii) in (i)
-4y + 2y = -4
-2y = -4
y = 2
Substitute y = 2 in (ii)
x = 4(2)
x = 8
So, the solution set is (8, 2).

Question 17.
The measure of an acute angle in a right triangle is one-fourth the measure of the other acute angle. Write a system of linear equations that represents this situation and use it to find the measures of the acute angles of the triangle.

Answer:
x = 72 degrees, y = 18 degrees

Explanation:
Let two acute angles be x, y
The measure of an acute angle in a right triangle is one-fourth the measure of the other acute angle
x + y = 90 — (i)
y = 1/4 x — (ii)
Substitute (ii) in (i)
x + 1/4 = 90
5/4 x = 90
x = 90 . (4/5)
x = 72 degrees
So, y = 1/4 (72)
y = 18 degrees

5.3 Solving Systems of Linear Equations by Elimination (pp. 211–218)

Solve the system by elimination. Check your solution.

Question 18.
2x + 5y = 60
2x – 5y = -20

Answer:
The solution set is (10, 8).

Explanation:
The given system of linear equations are
2x + 5y = 60 — (i)
2x – 5y = -20 — (ii)
Add both equations
2x + 5y + 2x – 5y = 60 – 20
4x = 40
x = 10
Substitute x = 10 in (i)
2(10) + 5y = 60
20 + 5y = 60
5y = 60 – 20
5y = 40
y = 8
Substitute x = 10, y = 8 in (i)
2(10) + 5(8) = 20 + 40 = 60
So, the solution set is (10, 8).

Question 19.
4x – 3y = 15
2x + y = -5

Answer:
The solution set is (3/2, -3).

Explanation:
The given system of linear equations are
4x – 3y = 15 —- (i)
2x + y = -5 —- (ii)
Multiply (ii) by 3
6x + 3y = -15 —- (iii)
Add (ii) & (i)
4x – 3y + 6 + 3y = 15 – 15
4x – 6 = 0
4x = 6
x = 3/2
Substitute x = 3/2 in (i)
4(3/2) – 3y = 15
6 – 3y = 15
-3y = 15 – 6
-3y = 9
y = -3
Substitute x = 3/2, y = -3 in (i)
4(3/2) – 3(-3) = 6 + 9 = 15
So, the solution set is (3/2, -3).

Question 20.
A gift basket that contains jars of jam and packages of bread mix costs $45. There are 8 items in the basket. Jars of jam cost $6 each, and packages of bread mix cost $5 each. Write and solve a system of linear equations to find the number of each item in the gift basket.

Answer:
5 jars of jam and 3 packages of bread mix.

Explanation:
Let j be the no of jars of jam, b bethe no of packages of bread mix
j + b = 8
6j + 5b = 45
5j + 5b = 40
6j + 5b – 5j – 5b = 45 – 40
j = 5
5 + b = 8
b = 3
So, 5 jars of jam and 3 packages of bread mix.

Question 21.
When might it be easier to solve a system by elimination instead of graphing?

Answer:
Substitution is easier to solve a system by elimination instead of graphing.

Question 22.
You have a total of 10 coins consisting of nickels and dimes in your pocket. The value of the coins is $0.70. Write and solve a system of linear equations to find the numbers of nickels and dimes in your pocket.

Answer:
There are 6 nickels and 4 dimes.

Explanation:
The no of coins of nickles and dimes 10.
x + y = 10 — (i)
0.05x + 0.1y = 0.70 — (ii)
Multiply (i) by 0.05
0.05x + 0.05y = 0.5
0.05x + 0.1y – 0.05x – 0.05y = 0.70 – 0.50
0.05y = 0.2
y = 4
x + 4 = 10
x = 6
There are 6 nickles and 4 dimes.

5.4 Solving Special Systems of Linear Equations (pp. 219–224)

Solve the system. Explain your choice of method.

Question 23.
x + 2y = -5
x – 2y = -5

Answer:
The solution set is (-5, 0)

Explanation:
The given system of linear equations are
x + 2y = -5
x – 2y = -5
add both equations
x + 2y + x – 2y = -5 – 5
2x = -10
x = -5
Substitute x = -5 in x – 2y = -5
-5 – 2y = -5
-2y = 0
y = 0
So, the solution set is (-5, 0)

Question 24.
3x – 2y = 1
9x – 6y = 3

Answer:
The system has infinitely many solutions.

Explanation:
The given system of linear equations are
3x – 2y = 1 —- (i)
9x – 6y = 3 —- (ii)
Multiply (ii) by 1/3
3x – 2y = 1 —- (iii)
Both (iii) & (ii) are samem so the system has infinitely many solutions.

Question 25.
8x – 2y = 16
-4x + y = 8

Answer:
The system has no solution.

Explanation:
The given system of linear equations are
8x – 2y = 16 — (i)
-4x + y = 8 — (ii)
Multiply (i) by 1/2
4x – y = 8 — (iii)
Add (iii) & (ii)
-4x + y – 4x + y = 8 + 8
So, the system has no solution.

Question 26.
4y = x – 8
–\(\frac{1}{4}\)x + y = -1

Answer:
The system has no solution.

Explanation:
The given system of linear equations are
4y = x – 8
–\(\frac{1}{4}\)x + y = -1
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 53
Lines are parallel
So, the system has no solution.

Question 27.
-2x + y = -2
3x + y = 3

Answer:
The solution set is (1, 0).

Explanation:
The given system of linear equations are
-2x + y = -2 —(i)
3x + y = 3 — (ii)
Subtract equations
-2x + y – 3x – y = -2 – 3
-5x = -5
x = 1
Substitute x = 1 in (i)
-2(1) + y = -2
-2 + y = -2
y = 0
Substitute x = 1, y = 0 in (i)
-2(1) + 0 = -2
So, the solution set is (1, 0).

Question 28.
3x = \(\frac{1}{3}\)y + 2
9x – y =-6

Answer:
The system has no solution.

Explanation:
The given system of linear equations are
3x = \(\frac{1}{3}\)y + 2
9x – y =-6
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 54
The lines are parallel
So, the system has no solution.

Question 29.
You have $50 in your savings account and plan to deposit $10 each week. Your friend has $25 in her savings account and plans to also deposit $10 each week.
a. Write a system of linear equations that represents this situation.
b. Will your friend’s account ever have the same amount of money as your account? Explain.
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 102

Answer:
a. y = 10x + 50, y = 10x + 25
b. No, the amount will never be equal.

Explanation:
Let the total amount be y and the number of weeks is x
a. You have $50 in your savings account and plan to deposit $10 each week.
y = 10x + 50
Your friend has $25 in her savings account and plans to also deposit $10 each week.
y = 10x + 25
b. No, the account will never have the same amounts. By inspection, the lines are parallel and have the same slopes but different y-intercepts. So, the amount will always be $25 greater than the friend account but will not be the same.

Write a system of linear equations that fits the description. Use a graph to justify your answer.

Question 30.
The system has no solution.

Answer:
The possible systems of linear equations can be y = -5x – 2, 5x + y = 0.

Explanation:
The conditions where two equations have no solution are The lines should be parallel having the same slopes but different y-intercepts.
So, let us consider the slope as -5 and different y-intercepts.
Then, the possible systems of linear equations can be y = -5x – 2, 5x + y = 0.
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 38

Question 31.
The system has infinitely many solutions.

Answer:
The system of linear equations can be 0.5x + 4y = -11, -1.5x – 12y = 33.

Explanation:
The condition is lines are the same and have the same slope, y-intercepts.
So, the system of linear equations can be 0.5x + 4y = -11, -1.5x – 12y = 33
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 42

Question 32.
The system has one solution.

Answer:
The system of linear equations can be -2x + y = 1.3, 2(0.5x – y) = 4.6

Explanation:
The system has only one solution means the lines intersect and have different slopes.
So, the system of linear equations can be -2x + y = 1.3, 2(0.5x – y) = 4.6
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 48

Question 33.
Solve the system by graphing, by substitution, and by elimination. Which method do you prefer? Explain your reasoning.
5x + y = 8
2y = -10x + 8

Answer:
The system has no solution.
Out of all methods, I feel graphing is easier.

Explanation:
The given system of linear equations are
5x + y = 8 —- (i)
2y = -10x + 8 —- (ii)
Graph the above equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 55
The lines are parallel. So, the system has no solution.
Using substitution method
Multiply equation (ii) by 1/2
2y = -10x + 8
y = -5x + 4
Substitute y = -5x + 4 in (i)
5x + -5x + 4 = 8
4 = 8
So, the system has no solution
Using elimination method
y = -5x + 4
5x + y = 4 — (iii)
Subtract (i) & (iii)
5x + y – -5x – y = 8 – 4
0 = 4
So, the system has no solution.

Question 34.
Your friend chooses to solve the system of equations by graphing. Would you choose the same method? Why or why not?
5x + 2y = 12
y = x – 8

Answer:
The solution set is (4, -4).

Explanation:
The given system of linear equations are
5x + 2y = 12, y = x – 8
Yes, I will also choose graphing to solve the equations.
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 56
The solution set is (4, -4).

Systems of Linear Equations Practice Test

5 Practice Test

Question 1.
Solve the system by graphing.
Big Ideas Math Solutions Grade 8 Chapter 5 Systems of Linear Equations 103

Answer:
The solution is (4, 12).

Explanation:
The given systems of linear equations are y = 1/2 x + 10, y = 4x – 4
Graph the equations
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 23
The lines intersect at (4, 12)
So, the solution is (4, 12)

Question 2.
Solve the system by substitution.
-3x + y = 2
-x + y – 4 = 0

Answer:
The solution set is (1, 5)

Explanation:
The given system of linear equations are
-3x + y = 2
y = 2 + 3x —- (i)
-x + y – 4 = 0 —- (ii)
Substitute (i) in (ii)
-x + 2 + 3x – 4 = 0
2x – 2 = 0
2x = 2
x = 1
Substitute x = 1 in (i)
y = 2 + 3(1)
y = 2 + 3
y = 5
So, the solution set is (1, 5)

Question 3.
Solve the system by elimination. Solve the system. Check your solution.
x + y = 12
3x = 2y + 6

Answer:
The solution set is (-18, 30)

Explanation:
The given system of linear equations are
x + y = 12 —- (i)
3x = 2y + 6
3x – 2y = 6 —- (ii)
Multiply equation (i) by 2
2(x + y = 12)
2x + 2y = 24 —- (iii)
Subtract (ii) from (iii)
3x – 2y – 2x – 2y = 6 – 24
x = -18
Substitute x = -18 in (i)
-18 + y = 12
y = 12 + 18
y = 30
So, the solution set is (-18, 30)

Question 4.
Solve the system. Explain your choice of method.
-2x + y + 3 = 0
3x + 4y = -1

Answer:
The solution set is (1, -1).

Explanation:
The given system of linear equations are
-2x + y + 3 = 0
3x + 4y = -1
By graphing
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 57
The solution set is (1, -1).

Without graphing or solving, determine whether the system of linear equations has one solution, infinitely many solutions, or no solution. Explain your reasoning.

Question 5.
y = 4x + 8
y = 5x + 1

Answer:
The system has one solution.

Explanation:
The given system of linear equations are
y = 4x + 8 — (i)
y = 5x + 1 —- (ii)
Equate both equations
4x + 8 = 5x + 1
5x – 4x = 8 – 1
x = 7
Substitute x = 7 in (i)
y = 4(7) + 8
y = 28 + 8
y = 36
So, the system has one solution.

Question 6.
2y = 16x – 2
y = 8x – 1

Answer:
The system has infinitely many solutions

Explanation:
The given system of linear equations are
2y = 16x – 2 — (i)
y = 8x – 1 — (ii)
Substitute (ii) in (i)
2(8x – 1) = 16x – 2
16x – 2 = 16x – 2
So, the system has infinitely many solutions.

Question 7.
y = -3x + 2
6x + 2y = 10

Answer:
The system has  no solution.

Explanation:
The given system of linear equations are
y = -3x + 2 — (i)
6x + 2y = 10 — (ii)
Substitute (i) in (ii)
6x + 2(-3x + 2) = 10
6x – 6x + 4 = 10
4 = 10
So, the system has  no solution.

Question 8.
In the diagram, the measure of ∠1 is three times the measure of ∠2. Find the measure of each angle.
Big Ideas Math Solutions Grade 8 Chapter 5 Systems of Linear Equations 104

Answer:
∠1 = 3(∠2) = ∠6
∠3 = 180 – ∠2 = ∠5 = ∠7
∠4 = ∠2

Explanation:
The measure of ∠1 is three times the measure of ∠2
∠1 = 3(∠2)
∠5 + ∠2 = 180
∠5 = 180 – ∠2
∠6 + ∠1 = 180
∠6 + 3(∠2) = 180
∠6 = 180 – 3(∠2)
∠2 + ∠3 = 180
∠3 = 180 – ∠2 = ∠5
So, ∠4 = ∠2

Question 9.
The price of 2 pears and 6 apples is $14. The price of 3 pears and 9 apples is $21. Can you determine the unit prices for pears and apples? Explain.

Answer:
They have infinitely many solutions.

Explanation:
Let the price of 1 pears be x, price of 1 apple be y
The price of 2 pears and 6 apples is $14
2x + 6y = 14 — (i)
x + 3y = 7
The price of 3 pears and 9 apples is $21
3x + 9y = 21 —- (ii)
x + 3y = 7
Both the equations are the same. So they have infinitely many solutions.

Question 10.
A bouquet of lilies and tulips has 12 flowers. Lilies cost $3 each, and tulips cost $2 each. The bouquet costs $32. Write and solve a system of linear equations to find the numbers of lilies and tulips in the bouquet.
Big Ideas Math Solutions Grade 8 Chapter 5 Systems of Linear Equations 105

Answer:
8 lilies and 4 tulips.

Explanation:
Let l be the no of lilies, t be the no of tulips
A bouquet of lilies and tulips has 12 flowers
l + t = 12 —- (i)
Lilies cost $3 each, and tulips cost $2 each. The bouquet costs $32.
3l + 2t = 32 — (ii)
Multiply (i) by 3
3(l + t = 12)
3l + 3t = 36 — (iii)
Subtract (iii) from (ii)
3l + 3t – (3l + 2t) = 36 – 32
3l + 3t – 3l – 2t = 4
t = 4
Substitute t = 4 in (i)
l + 4 = 12
l = 12 – 4
l = 8
8 lilies and 4 tulips.

Question 11.
How much does it cost for 2 specials and 2 glasses of milk?
Big Ideas Math Solutions Grade 8 Chapter 5 Systems of Linear Equations 106

Answer:
The cost of 2 specials & 2 glasses of milk is $16.1.

Explanation:
Let specials be x and glasses of milk be y
4x + 2y = 28 — (i)
3x + 4y = 26.25 — (ii)
2(4x + 2y = 28)
8x + 4y = 56
subtract equations
8x + 4y – (3x + 4y) = 56 – 26.25
8x + 4y – 3x – 4y = 29.75
5x = 29.75
x = 5.95
Substitute x = 5.95 in (i)
4(5.95) + 2y = 28
23.8 + 2y = 28
2y = 28 – 23.8
2y = 4.2
y = 2.1
The cost of 2 specials & 2 glasses of milk is 2x + 2y
= 2(5.95) + 2(2.1)
= 11.9 + 4.2
= 16.1
The cost of 2 specials & 2 glasses of milk is $16.1.

Systems of Linear Equations Cumulative Practice

Question 1.
What is the solution of the system of equations?
Big Ideas Math Solutions Grade 8 Chapter 5 Systems of Linear Equations 107
B. (0, -1)
C. no solution
D. infinitely many solutions

Big Ideas Math Solutions Grade 8 Chapter 5 Systems of Linear Equations 108

Answer:
B. (0, -1)

Explanation:
The given system of linear equations are
y = 2/3 x – 1
4x + 6y = -6
By graphing
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 58
so, the solution set is (-1, 0)

Question 2.
What is the value of x?
Big Ideas Math Solutions Grade 8 Chapter 5 Systems of Linear Equations 109

Answer:
x = 40 degrees

Explanation:
x + 140 = 180
x = 180 – 140
x = 40 degrees

Question 3.
Which of the following shows Rectangle E’F’G’H’, the image of Rectangle EFGH after it is translated 4 units down?
Big Ideas Math Solutions Grade 8 Chapter 5 Systems of Linear Equations 110
Big Ideas Math Solutions Grade 8 Chapter 5 Systems of Linear Equations 111

Answer:
F.

Explanation:
By observing all the images we can say that F is the answer.

Question 4.
Which point is a solution of the system of equations?
x + 3y = 10
x = 2y – 5
A. (1, 3)
B. (3, 1)
C. (55, -15)
D. (-35, -15)

Answer:
The solution set is (1, 3).

Explanation:
The given system of linear equations are
x + 3y = 10
x = 2y – 5
Substitute x = 2y – 5 in x + 3y = 10
2y – 5 + 3y = 10
5y = 10 + 5
5y = 15
y = 3
Substitute y = 3 in x = 2y – 5
x = 2(3) – 5
x = 6 – 5
x = 1
So, the solution set is (1, 3).

Question 5.
The graph of a system of two linear equations is shown. Which point is the solution of the system?
F. (-1, 2)
G. (0, 4)
H. (2, -1)
I. (0, 0)
Big Ideas Math Solutions Grade 8 Chapter 5 Systems of Linear Equations 112

Answer:
F. (-1, 2)

Explanation:
From the graph, the point of intersection of two equations is (-1, 2)
So, the solution set is (-1, 2).

Question 6.
A scenic train ride has one price for adults and one price for children. One family of two adults and two children pays $62 for the train ride. Another family of one adult and four children pays $70. Which system of linear equations can you use to find the price x for an adult and the price y for a child?
A. 2x + 2y = 70
x + 4y = 62
B. x + y = 62
x + y = 70
C. 2x + 2y = 62
4x + y = 70
D. 2x + 2y = 62
x + 4y = 70

Answer:
D. 2x + 2y = 62
x + 4y = 70

Explanation:
If x is the cost of an adult ticket, y is the cost of a child ticket, then
One family of two adults and two children pays $62 for the train ride.
2x + 2y = 62
Another family of one adult and four children pays $70.
x + 4y = 70.

Question 7.
Which of the following is true about the graph of the linear equation y =-7x + 5?
F. The slope is 5, and the y-intercept is -7.
G. The slope is -5, and the y-intercept is -7.
H. The slope is -7, and the y-intercept is -5.
I. The slope is -7, and the y-intercept is 5.

Answer:
H. The slope is -7, and the y-intercept is -5.

Explanation:
The given equation is y =-7x + 5
The equation in the form of y = mx + c
So, slope m = -7, y-intercept c = 5

Question 8.
What is the measure (in degrees) of the exterior angle of the triangle?
Big Ideas Math Solutions Grade 8 Chapter 5 Systems of Linear Equations 113

Answer:
The exterior angle of the triangle is 127 degrees

Explanation:
The Sum of angles of a triangle is 180
x + 64 + y = 180
x + y = 180 – 64
x + y = 116
y = 116 – x — (i)
Sum of unknown angle and exterior angle is 180
y + 2x + 1 = 180
y + 2x = 180 – 1
2x + y = 179 —(ii)
Substitute (i) in (ii)
2x + 116 – x = 179
x + 116 = 179
x = 179 – 116
x = 63
So, the exterior angle is (2x + 1) = 2(63) + 1
= 126 + 1 = 127 degrees

Question 9.
The graph of which equation is parallel to the line that passes through the points (-1, 5) and (4, 7)?
Big Ideas Math Solutions Grade 8 Chapter 5 Systems of Linear Equations 114

Answer:
c.

Explanation:
The equation of a line pass through two points is (y – y₁) = [ =(y₂ – y₁)/(x₂ – x₁)](x – x₁)
x₁ = -1, y₁ = 5, x₂ = 4, y₂ = 7
So, (y – 5) = (7 – 5)/(4 + 1)(x + 1)
y – 5 = 2/5(x + 1)
5(y – 5) = 2(x + 1)
5y – 25 = 2x + 2
5y = 2x + 2 + 25
5y = 2x + 27
y = 2/5 x + 27/5

Question 10.
You buy 3 T-shirts and 2 pairs of shorts for $42.50. Your friend buys 5 T-shirts and 3 pairs of shorts for $67.50. Use a system of linear equations to find the cost of each T-shirt. Show your work and explain your reasoning.
Big Ideas Math Solutions Grade 8 Chapter 5 Systems of Linear Equations 115

Answer:
The cost of each T-shirt is $7.5.

Explanation:
Let t be the price of a t-shirt, s be the price of a pair of shorts
You buy 3 T-shirts and 2 pairs of shorts for $42.50.
3t + 2s = 42.50
Your friend buys 5 T-shirts and 3 pairs of shorts for $67.50
5t + 3s = 67.50
Multiply the first equation by 3 and second by 2 and then subtract two equations
3(3t + 2s = 42.50) ➝ 9t + 6s = 127.50
2(5t + 3s = 67.50) ➝ 10t + 6s = 135
10t + 6s – 9t – 6s = 135 – 127.50
t = 7.5
The cost of each T-shirt is $7.5.

Question 11.
The red figure is congruent to the blue figure. Which of the following is a sequence of rigid motions between the figures?
F.Translate the red triangle 6 units left and then 4 units down.
G. Reflect the red triangle in the x-axis, and then translate 4 units down.
H. Reflect the red triangle in the y-axis, and then translate 4 units down.
I. Rotate the red triangle 180° clockwise about the origin.
Big Ideas Math Solutions Grade 8 Chapter 5 Systems of Linear Equations 116

Answer:
I. Rotate the red triangle 180° clockwise about the origin.

Explanation:
The vertices of the red triangle is (1, 1), (4, 1), (3, 4)
The vertices of the blue triangle are (-1, -3), (-4, -3), (-3, 0)

Question 12.
Which of the following is true about the graph of the linear equation y = 2?
A. The graph is a vertical line that passes through (2, 0).
B. The graph is a vertical line that passes through (0, 2).
C. The graph is a horizontal line that passes through (2, 0).
D. The graph is a horizontal line that passes through (0, 2).

Answer:
C. The graph is a horizontal line that passes through (2, 0).

Explanation:
The graph for the linear equation y = 2 is
Big Ideas Math Answers Grade 8 Chapter 5 Systems of Linear Equations 59

Question 13.
The sum of one-third of a number and 10 is equal to 13. What is the number?
F. \(\frac{8}{3}\)
G. 9
H. 29
I. 69

Answer:
G. 9

Explanation:
Let the number be n
The sum of one-third of a number and 10 is equal to 13
1/3 n + 10 = 13
1/3 n = 13 – 10
1/3 n = 3
n = 3 x 3
n = 9

Question 14.
Solve the equation 4x + 7y = 16 for x.
A. x = 4 + \(\frac{7}{4}\)y
B. x = 4 – \(\frac{7}{4}\)y
C. x = 4 + \(\frac{4}{7}\)y
D. x = 16 – 7y

Answer:
B. x = 4 – \(\frac{7}{4}\)y

Explanation:
The given equation is 4x + 7y = 16
4x = 16 – 7y
x = (16 – 7y)/4
x = 4 – 7y/4

Conclusion:

The solutions given in this Big Ideas Math Grade 8 Chapter 5 are prepared by the subject experts. So, don’t worry about the answers just go through the answers and try to solve the problems. Test your knowledge by practicing the questions in the practice test section. After solving them cross check the answers. Follow our ccssmathanswers.com to get the latest updates regarding all Grade 8 Chapters.

Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume

Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume

Wanna get the best preparatory material of Big Ideas Math 6th Grade Chapters? If yes, then you have hit the exact page. Here, in this article, we are providing in-depth concepts of area, surface area, and volume. You can understand all the concepts with the help of Big Ideas Math Book Solutions. We are providing the step-by-step procedure and its explanations for all the problems using the tips and figures. Follow Big Ideas Math Book  6th Grade Answer Key Chapter 7 and know shortcuts, time management, etc. Understand all the concepts of area, surface area, and volume in Big Ideas Math Book Solution Key. Click on the below-given pdf links of Big Ideas Math Answers Grade 6 Chapter 7 and get the solutions here.

Big Ideas Math Book 6th Grade Answer Key Chapter 7 Area, Surface Area, and Volume

To excel in the exam, candidates of 6th standard have to refer to the important preparatory material of Big Ideas Math Book Answer Key Grade 6 Chapter 7 Area, Surface Area, and Volume. If you facing difficulty in solving or calculating the problems, you can easily understand them with the help of Big Ideas Math Book Answer Key Chapter 7. Check the below sections to know the performance, various chapters involved in this concept. You can find the various chapters like area of parallelograms, area of triangles, areas of trapezoids, three-dimensional figures, and so on.

Performance

Lesson: 1 Areas of Parallelograms

Lesson: 2 Areas of Triangles

Lesson: 3 Areas of Trapezoids and Kites

Lesson: 4 Three-Dimensional Figures

Lesson: 5 Surface Areas of Prisms

Lesson: 6 Surface Areas of Pyramids

Lesson: 7 Volumes of Rectangular Prisms

Chapter 7 – Area, Surface Area, and Volume

Area, Surface Area, and Volume STEAM Video/Performance

Packaging Design

Surface area can be used to determine amounts of materials needed to create objects. Describe another situation in which you need to find the surface area of an object.

Watch the STEAM Video “Packaging Design.” Then answer the following questions. Alex is cutting a design out of paper and folding it to form a box.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 1

Question 1.
Tory says that the length of the design is 47 inches and the width is 16 inches. Show several ways that you can arrange three of the designs on a roll of paper that is 48 inches wide. You can make the length of the paper as long as is needed.

Answer:
We can make the length of the paper = 15.6666 inches

Explanation:
Given that the length of the design = 47 inches
that the width of the design = 16 inches
area of the design = 752 inches
They can arrange the three of the design on a roll of paper that = 48 inches
(752/48)
15.6666 inches
Question 2.
Tory says that the cut-out design has an area of 619 square inches. What is the least possible amount of paper that is wasted when you cut out three of the designs?

Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 2

Answer:
The least amount of paper that is wasted when you cut out three of the designs = 12.89

Explanation:
The area of the rectangle = breadth x height
619 square inches = 48 in x length
619 = 48l
l = 619/48
l = 12.89

Performance Task

Maximizing the Volumes of Boxes

After completing this chapter, you will be able to use the concepts you learned to answer the questions in the STEAM Video Performance Task. You will be given the dimensions of a small box and two larger boxes.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 3
You will be asked to determine how many small boxes can be placed in each larger box. When a company is deciding on packaging for a product, why should the surface area of the packaging also be considered?
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 4

Area, Surface Area, and Volume Gettig Ready for chapter 7

Chapter Exploration

The formulas for the areas of polygons can be derived from one area formula, the area of a rectangle.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 5

Work with a partner. Find (a) the dimensions of the figures and (b) the areas of the figures. What do you notice?

Question 1.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 6

Answer:
The area of the rectangle = The product of the length and the product of the width
The area of the parallelogram = the product of the width and the product of the height

Explanation:
The area of the rectangle is equal to the area of the parallelogram
The area of the rectangle = the product of the length and the product of the width
The area of the rectangle = length x width
area = l x w
The area of the parallelogram = the product of the base and the product of the width
area = base x height
area = b x h

Question 2.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 7

Answer:
The  area of the rectangle = the product of the length and the product of the width
The area of the parallelogram = (1/2) x the product of the base and the product of the height

Explanation:
The area of the rectangle is equal to the area of the parallelogram
The area of the rectangle = the product of the length and the product of the width
The area of the rectangle = length x width
area = l x w
The area of the triangle =(1/2) x  the product of the base and the product of the width
area =(1/2) base x height
area =(1/2) b x h

Question 3.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 8

Answer:
The  area of the rectangle = the product of the length and the product of the width
The area of the trapezoid = (1/2) x height x (base 1 + base 2)

Explanation:
The area of the rectangle is equal to the area of the parallelogram
The area of the rectangle = the product of the length and the product of the width
The area of the rectangle = length x width
area = l x w
The area of the trapezoid =(1/2) x product of the height  and the product of the bases
area =(1/2) x height x bases
area =(1/2) x height (b1 + b2)

Vocabulary

The following vocabulary terms are defined in this chapter. Think about what each term might mean and record your thoughts.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 9

Lesson 7.1 Areas of Parallelograms

A polygon is a closed figure in a plane that is made up of three or more line segments that intersect only at their endpoints. Several examples of polygons are parallelograms, rhombuses, triangles, trapezoids, and kites.
The formula for the area of a parallelogram can be derived from the definition of the area of a rectangle. Recall that the area of a rectangle is the product of its length ℓ and its width w. The process you use to derive this and other area formulas in this chapter is called deductive reasoning.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 10

EXPLORATION 1
Deriving the Area Formula of a Parallelogram
Work with a partner.
a. Draw any rectangle on a piece of centimeter grid paper. Cut the rectangle into two pieces that can be arranged to form a parallelogram. What do you notice about the areas of the rectangle and the parallelogram?
b. Copy the parallelogram below on a piece of centimeter grid paper. Cut the parallelogram and rearrange the pieces to find its area.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 11
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 12
c. Draw any parallelogram on a piece of centimeter grid paper and find its area. Does the area change when you use a different side as the base? Explain your reasoning.
d. Use your results to write a formula for the area A of a parallelogram.

Answer:
c : The area of the parallelogram = the product of the width and the product of the height
area = width x height
area = w x h
Yes the area changes.
We use the bases as equal length and width as equal length
d : the area of the parallelogram = the product of the width and the product of the height

c : The area of the parallelogram = the product of the width and the product of the height
area = width x height
area = w x h
Yes the area changes.
We use the bases as equal length and width as equal length
d : the area of the parallelogram = the product of the width and the product of the height

7.1 Lesson

The area of a polygon is the amount of surface it covers. You can find the area of a parallelogram in much the same way as you can find the area of a rectangle.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 13

Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 13.1

Try It

Find the area of the parallelogram.

Question 1.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 14

Answer:
Area = 500 m

Explanation:
The area of the parallelogram = the product of the base b and its height h.
area = b x h
b = 20 m, h = 25 m
So the Area of the parallelogram = 500 m

Question 2.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 15

Answer;
Area = 126 in

Explanation:
The area of the parallelogram = the product of base b and its height h
area = b x h
b = 7 in , h = 18 in
So area = 126 in

Question 3.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 16

Answer:
615 yd

Explanation:
The area of the parallelogram = the product of base b and its height h
area = b x h
b = 30 yd, h = 20.5 yd
So area = 615 yd

When finding areas, you may need to convert square units. The diagrams at the left show that there are 9 square feet per square yard.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 17
1 yd2 = (1 yd)(1 yd) = (3 ft)(3 ft) = 9 ft2
You can use a similar procedure to convert other square units.

Try It

Question 4.
Find the area of the parallelogram in square centimeters.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 18

Answer:
The area of the parallelogram = the product of the base and the product of the height
Area = 400 cms

Explanation:
The area of the parallelogram = the product of the base and the product of the height
area = base x height
area = 4 m x 10 m
area = 40 m
1 meter = 100 centimeters
40 meter = 400 centimeters
area = 400 cm

Self-Assessment for Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 5.
WRITING
Explain how to use the area of a rectangle to find the area of a parallelogram

Answer:
Area of the rectangle = length x breadth
Area of the parallelogram =   base x height

Explanation:
Area of the rectangle = length x breadth
area = l x b
Area of the parallelogram =   base x height
area =  b x h
area =  bh

FINDING AREA
Find the area of the parallelogram.

Question 6.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 19

Answer:
area = 80 ft

Explanation:
The area of the parallelogram = the product of the base and the product of the height
area = base x height
area = b x h
b = 16 ft and h = 5 ft given
area = 16 x 5
area = 80 ft

Question 7.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 20

Answer:
The area of the parallelogram = 14 . 4 km

Explanation:
The area of the parallelogram = the product of the base and the product of the height
area = base x height
area = b x h
b = 3 km and h = 4.8 km given
area = 3 x 4.8
area = 14.4 km

Question 8.
REASONING
Draw a parallelogram that has an area of 24 square inches.

Answer:
We have to assume that the base = 4 square inches and the height = 6 square inches

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 9.
The side of an office building in Hamburg, Germany, is in the shape of a parallelogram. The area of the side of the building is about 2150 square meters. What is the length x of the portion of the building that extends over the river?
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 21

Answer:
The length of the portion of the building that extends over the river = 45 m

Explanation:
The area of the parallelogram = the product of the bases and the product of the bases
area = 2150 square meters given
area = 25 m x (39 +47) given that height = 25 and base = 39
area = 25 x (86)
area = 2150
Thus the length of the portion of the building that extends over the river = 45 m

Question 10.
You make a photo prop for a school fair. You cut a 10-inch square out of a parallelogram-shaped piece of wood. What is the area of the photo prop?
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 22

Answer:
The area of the photo prop = 32

Explanation:
the area of the photo prop = the product of the base and the product of the height
area = h x b
area = 8 x 4
area = 32 ft

Question 11.
DIG DEEPER!
A galaxy contains a parallelogram-shaped dust field. The dust field has a base of 150 miles. The height is 14% of the base. What is the area of the dust field?

Answer:
The area of the dust field =3,150

Explanation:
The area of the parallelogram = the product of the height and the product of the base
area = h x b given that height = 14% = (14/100) x 150 = 21, base = 150 miles
area = 3150

Areas of Parallelograms Homework & Practice 7.1

Review & Refresh

Graph the equation.

Question 1.
y = 4x

Answer:
:

Explanation:
The given equation = y = 4x
for suppose x = 0, then y = 0
x = 1 , then y = 4 that means (1,4) y = 4 x 1 = 4
x = 2 , then y = 8 that means (2,8) y = 4 x 2 = 8
x = 3 , then y = 12 that means (3,12) y = 4 x 3 = 12

Question 2.
y = x + 3

Answer:

Explanation:
The given equation = y = x + 3
for suppose x = 0, then y = 3
x = 1 , then y = 4 that means (1,4) y = 1 + 3 = 4
x = 2 , then y = 5 that means (2, 5) y = 2 + 3  = 5
x = 3 , then y = 6 that means (3,16) y = 3 + 3 = 6
x = 4 , then y = 7 that means (4, 7) y = 4 + 3 = 7

Question 3.
y = 2x + 5

Answer:

Explanation:
The given equation = y = 2x + 5
for suppose x = 0, then y = 5
x = 1 , then y = 7 that means (1,7) y = 2 + 5 = 7
x = 2 , then y = 9 that means (2, 9) y = 4 + 5  = 9
x = 3 , then y = 11 that means (3,11) y = 6 + 5 = 11
x = 4 , then y = 13 that means (4, 13) y = 8 + 5 = 13

Represent the ratio relationship using a graph.

Question 4.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 23

Answer:
1: 2 ratio

Explanation:

Question 5.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 24

Answer:
1 : 2 ratio

Explanation:

Write the prime factorization of the number.

Question 6.
55

Answer:
5 . 11

Explanation:
5 x 11 = 55
S0 5,11

Question 7.
60

Answer:
2 x 2 x 3 x 5

Explanation:
2 x 30 = 60
2 x 15 = 30
5 x 3 = 15
3 x 1 = 3

Question 8.
150

Answer:
3 . 5 . 5 . 2

Explanation:
3 x 50 = 150
5 x 10 = 50
5 x 2 = 10
2 x 1 = 2

Question 9.
126

Answer:
2 . 3 . 3 . 7

Explanation:
2 x 63 = 126
3 x 21 = 63
3 x 7 = 21
7 x 1 = 7

Add or subtract.

Question 10.
2.36 + 15.71

Answer:
2.36 + 15.71 = 18.07

Explanation:


Question 11.
9.035 – 6.144

Answer:
9.035 – 6.144 = 2.891

Explanation:

Question 12.
28.351 – 19.3518

Answer:
28.351 = 19.3518 = 8.9992

Explanation:

Concepts, Skills, & Problem Solving
USING TOOLS
Rearrange the parallelogram as a rectangle. Then find the area. (See Exploration 1, p. 285.)

Question 13.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 25

Answer:

Question 14.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 26

Answer:

Question 15.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 27

Answer:

FINDING AREA
Find the area of the parallelogram.

Question 16.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 28

Answer:
The area of the parallelogram = 18 ft

Explanation:
The area of the parallelogram = the product of the base and the height
area = b x h given that base = 6 ft height = 3 ft
area = 18 ft
Question 17.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 29

Answer:
The area of the parallelogram = 840 mm

Explanation:
The area of the parallelogram = the product of the base and the height
area = b x h given that base = 20 mm height = 42 ft
area = 840 mm

Question 18.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 30

Answer:
The area of the parallelogram = 187 km

Explanation:
The area of the parallelogram = the product of the base and the height
area = b x h given that base = 17 km height = 11km
area = 187 km

Question 19.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 31

Answer:
The area of the parallelogram = 3750 cm

Explanation:
The area of the parallelogram = the product of the base and the height
area = b x h given that base = 75 cm  height = 50 cm
area = 3750 cm

Question 20.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 32

Answer:
The area of the parallelogram = 243 in

Explanation:
The area of the parallelogram = the product of the base and the height
area = b x h given that base = 13.5 in  height = 18 in
area = 243 in

Question 21.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 33

Answer:
The area of the parallelogram = 894 mi

Explanation:
The area of the parallelogram = the product of the base and the height
area = b x h given that base = 24 in, height = 37 x (1/4)
area = 24 x 37.25
area = 894 mi

Question 22.
YOU BE THE TEACHER
Your friend finds the area of the parallelogram. Is your friend correct? Explain your reasoning.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 34

Answer:
Yes my friend is correct

Explanation:
The area of the parallelogram = the product of the base and the product of the height
area = 8 m x 15 m
Given that base = 8m and height = 15 m
area = base x height
area = 8 m x 15 m
area = 120 m

Question 23.
MODELING REAL LIFE
A ceramic tile in the shape of a parallelogram has a base of 4 inches and a height of 1.5 inches. What is the area of the tile?

Answer:
The area of the tile =  6 inches

Explanation:
The area of the parallelogram = the product of the base and the product of the height
area = base x height
area = 4 x 1.5
area = 6 inches

FINDING AREA
Find the area of the parallelogram. Round to the nearest hundredth if necessary.

Question 24.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 35

Answer:
4800 cm

Explanation:
The area of the parallelogram = the product of the base and the product of the height
area = base x height
area = 6 x 8
area = 48 m
1 meter = 100 centimeter
48 m = 4800 cm

Question 25.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 36

Answer:
1,121.64096

Explanation:
The area of the parallelogram = the product of the base and the product of the height
area = base x height
area = 1320 yd x 1496 yd
area = 1974720yd
1 yard = 0.000568 mile
1974720 yd = 1,121.64096 miles

Question 26.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 37

Answer:
67.4 ft

Explanation:
The area of the parallelogram = the product of the base and the product of the height
area = base x height
area = 5 m x 4 m
area = 20 m
1 meter = 3 feet 3.37 inches
20 m = 67 . 4 ft

Question 27.
OPEN-ENDED
Your deck has an area of 128 square feet. After adding a section, the area will be (s2 + 128) square feet. Draw a diagram of how this can happen.

Answer:

Question 28.
MODELING REAL LIFE
You use the parallelogram-shaped sponge to create the T-shirt design. The area of the design is 66 square inches. How many times do you use the sponge to create the design? Draw a diagram to support your answer.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 37.1

Answer:
33 times is used to the sponge to create the design = 33
Explanation:
The area of the parallelogram = base x height
area = 3 x 1
area = 3  inches
The area of the design = 66 inches
66/3 = 33

FINDING A MISSING DIMENSION
Find the missing dimension of the parallelogram described.

Question 29.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 38

Answer:
height = 9 ft
Explanation:
area of the parallelogram = the product of the base and the product of the height
area = base x height
area = 6 ft  x 9 ft
area = 54 ft
So height = 54

Question 30.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 39

Answer:
base = 6.5 cm

Explanation:
area of the parallelogram = the product of the base and the product of the height
area = base x height
area = 6 . 5 cm  x 2.5 cm
area = 16 .25
So height = 2.5 cm

Question 31.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 40

Answer:
height = 4 yd

Explanation:
5(x + 4) = 5x + 20

Question 32.
DIG DEEPER!
The staircase has three identical parallelogram-shaped panels. The horizontal distance between each panel is 4.25 inches. The area of each panel is 287 square inches. What is the value of x?
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 41

Answer:
The value of x = 14

Explanation:
(1/2)bx = 287
(1/2) x 14 x x = 287
7x = 287
x = 287/7
x = 41
50.5 -8
42.5 x 2 = 8.50

Question 33.
LOGIC
Each dimension of a parallelogram is multiplied by a positive number n. Write an expression for the area of the new parallelogram.

Answer:
The area of the parallelogram = (1/2) x b x h
area = (1/2)bn x hn
(1/2) bhn

Question 34.
CRITICAL THINKING
Rearrange the rhombus shown to write a formula for the area of a rhombus in terms of its diagonals.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 42

Answer:
The area of the rhombus = (1/2) ab
area = (1/2) x ab

Explanation:
The area of the rhombus = (1/2) ab
area = (1/2) x ab

Lesson 7.2 Areas of Triangles

EXPLORATION 1

Deriving the Area Formula of a Triangle
Work with a partner.
a. Draw any parallelogram on a piece of centimeter grid paper. Cut the parallelogram into two identical triangles. How can you use the area of the parallelogram to find the area of each triangle?
b. Copy the triangle below on a piece of centimeter grid paper. Find the area of the triangle. Explain how you found the area.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 43
c. Draw any acute triangle on a piece of centimeter grid paper and find its area. Repeat this process for a right triangle and an obtuse triangle.
d. Do the areas change in part(c) when you use different sides as the base? Explain your reasoning.

Answer:
a : The area of the parallelogram = (1/2) x b x h
The area of the triangle = base x height
b : The area of the triangle = base x height
area = b x h
c : The area of the acute-angled triangle = (1/2) x b x h
The area of the right-angled triangle = (1/2) x base x perpendicular
The area of the obtuse-angled triangle =(1/2) x b x h

Explanation:
a :
b :
c :



Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 44
e. Use your results to write a formula for the area A of a triangle. Use the formula to find the area of the triangle shown.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 45

Answer:
15 m

Explanation:
The area of the triangle = half x the product of the base b and the product of the height h
area = (1/2) x b x h given that b= 6 m ,h = 5 m
area = (1/2) x 30
area = 15 m

7.2 Lesson

Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 46

Try It

Find the area of the triangle

Question 1.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 47

Answer:
22 ft

Explanation:
The area of the triangle = (1/2) x bh
The area of the triangle = (1/2) x the product of base and the product of the height
b = 11 ft , h = 4 ft
area = (1/2) x bh
area = (1/2) x 11 x 4
area = (1/2) x 44
area = 22 ft

Question 2.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 48

Answer:
Area = 60 cm

Explanation:
The area  of the triangle = (1/2) x the product of the base b and the product of the height h
b = 15 cm, h = 8cm
area = (1/2) x 15 x 8
area = (1/2) x 120
area = 60

Question 3.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 49

Answer:
area = 110 m

Explanation:
The area of the triangle = (1/2) x the product of the base b and the product of the height h
So the b = 22m ,h= 10 m
area= (1/2) x 10 x 22
area = (1/2) x 220
area = 110 m

Question 4.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 50

Answer:
6.5 yd

Explanation:
The area of the triangle = (1/2) x the product of base b and the product of the height h
So the b = (13/2) yd h = 2 yd
area = (1/2) x b x h
area = (1/2) x 6.5 x 2
area = (1/2) x 13
area = 6.5

Try It

Find the missing dimension of the triangle.

Question 5.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 51

Answer:
Base = 8 cm

Explanation:
The area of the triangle =(1/2) x  the product of the base b and the product of height h
area of the triangle = 24 cm given
So the height = 6cm given
area =  (1/2) x b x h
area = (1/2) x 8 x 6
area = (1/2) x 48
area = 24
So base = 8 cm

Question 6.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 52

Answer:
height = 17.5ft

Explanation:
The area of the triangle =(1/2) x  the product of the base b and the product of the height h
area of the triangle = 175 ft given,
So we have to find the height?
area = (1/2) x 20 x 17.5
area = (1/2) x 350
area = 175
So the height = 17.5 ft

Self-Assessment for Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 7.
FINDING AREA
Find the area of the triangle at the left.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 53

Answer:
The area of the triangle = 12

Explanation:
The area of the triangle = (1/2) x the product of base and the product of the height
b = 8 , h = 3
area = (1/2) x bh
area = (1/2) x 8 x 3
area = (1/2) x 24
area = 12

Question 8.
WRITING
Explain how to use the area of a parallelogram to find the area of a triangle.

Answer:
The area of the parallelogram = the product of the base and the product of the height
The area of the triangle = half x  the product of the base b and the product of the height h

Explanation:
The area of the parallelogram = the product of the base and the product of the height
area = b x h
The area of the triangle = half x the product of the base and the height
area = (1/2) x b x h
FINDING A MISSING DIMENSION
Find the missing dimension of the triangle.

Question 9.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 54

Answer:
base = 10 mm

Explanation:
The area of the triangle = (1/2) the product of the base and the product of the height
area = (1/2) x base x height
area = (1/2) x 10 mm x 6 mm
area = (1/2) x 60 mm
area = 30 mm
So base = 10 mm
Question 10.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 55

A composite figure is made up of triangles, squares, rectangles, and other two-dimensional figures. To find the area of a composite figure, separate it into figures with areas you know how to find. This is called decomposition.

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 11.
A wildlife conservation group buys the 9 square miles of land shown. What is the distance from Point A to Point B?
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 56

Answer:
The distance from point A to point B = 3 miles

Explanation:
The  area of the triangle = (1/2) ab
Given that  the land shown = 9 square miles
(1/2)bh = triangle ABC + triangle BCD
(3/2)b + (3/2)b = 9
(6/2)b = 9
3 b = 9
b = 3 miles
Question 12.
DIG DEEPER!
Find the area of the side of the chimney. Explain how you found the area.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 57

Answer:
The area of the chimney = 31.5 sq. ft

Explanation:
The area of the chimney = (1/2) x base x height
area = (1/2)  x 3 x 21
area = 31.5 sq. ft

Areas of Triangles Homework & Practice 7.2

Review & Refresh

Find the area of the parallelogram.

Question 1.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 58

Answer:  
The area of the parallelogram = 72 in

Explanation:
The area of the parallelogram = product of the height h and the product of the base b
b = 12 in, h = 6 in given
area =  12 x 6
area = 72 in

Question 2.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 59

Answer:
The area of the parallelogram = 10.5 km

Explanation:
The area of the parallelogram = the product of the base b and the product of the height h
b = 3.5 km, h = 3km given
area = 3.5 x 3
area = 10.5 km

Question 3.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 60

Answer:
The area of the parallelogram = 255 mi

Explanation:
The area of the parallelogram = the product of the base b and the product of the height h
b = 17 mi, h = 15 mi given
area = 17 x 15
area = 255 mi

Tell which property the statement illustrates.

Question 4.
n . 1 = n

Answer:
The product of x = the product of y

Explanation:
The product of x = n x 1 = n
the product of y = n
n = n

Question 5.
4 . m = m . 4

Answer:
The product of x = the product of y

Explanation:
The product of x = m x 4 = 4 m
the product of y = m x 4 = 4 m
4 . m = m . 4

Question 6.
(x + 2) + 5 = x + (2 + 5)

Answer:
The product of x = the product of y

Explanation:
The product of x = (x + 2) + 5
the product of y =  x + (2 +5)
(x +2) +5 = x + (2 +5)

Question 7.
What is the first step when using order of operations?
A. Multiply and divide from left to right.
B. Add and subtract from left to right.
C. Perform operations in grouping symbols.
D. Evaluate numbers with exponents.

Answer:
Evaluate numbers with exponents

Concepts, Skills, & Problem Solving

USING TOOLS
Find the area of the triangle by forming a parallelogram. (See Exploration 1, p. 291.)

Question 8.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 61

Answer:
The area of the right angled triangle = (1/2) x ab

Explanation:

Question 9.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 62

Answer:
obtused angled triangle = (1/2) x b xh

Explanation:

Question 10.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 63

Answer:
acute angled triangle

Explanation:

FINDING AREA
Find the area of the triangle.

Question 11.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 64

Answer:
The area of the triangle = 6 cm

Explanation:
Area of the triangle = (1/2) x the product of the base b and the product of the height h
area = (1/2) x b x h
So b = 3 cm , h = 4 cm
area = (1/2) x 3 x 4
area = (1/2) x 12
area = 6 cm

Question 12.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 65

Answer:
The area of the triangle = 90 mi

Explanation:
Area of the triangle = (1/2) x the product of the base b and the product of the height h
area = (1/2) x b x h
So b = 20 mi  , h = 9 mi
area = (1/2) x 20 x 9
area = (1/2) x 180
area = 90 sq. miles

Question 13.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 66

Answer:
The area of the triangle =1620 in

Explanation:

Area of the triangle = (1/2) x the product of the base b and the product of the height h
area = (1/2) x b x h
So b =60 in , h = 54 in
area = (1/2) x 3240
area = 1620 in

Question 14.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 67

Answer:

The area of the triangle = 189 mm

Explanation:
Area of the triangle = (1/2) x the product of the base b and the product of the height h
area = (1/2) x b x h
So b =21 mm , h = 18 mm
area = (1/2) x 378
area = 189 mm

Question 15.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 68

Answer:
The area of the triangle = 1125 cm

Explanation:
Area of the triangle = (1/2) x the product of the base b and the product of the height h
area = (1/2) x b x h
So b =75 cm , h = 30 cm
area = (1/2) x 2250
area = 1125 cm

Question 16.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 69

Answer:
The area of the triangle = 132 m

Explanation:
Area of the triangle = (1/2) x the product of the base b and the product of the height h
area = (1/2) x b x h
So b =8 m , h = 33 m
area = (1/2) x 264
area = 132 m

Question 17.
YOU BE THE TEACHER
Your friend finds the area of the triangle. Is your friend correct? Explain your reasoning.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 70

Answer:
Yes my friend is correct

Explanation:
Area of the triangle = (1/2) x the product of the base b and the product of the height h
area = (1/2) x b x h
Sob =10 m , h = 12 m
area = (1/2) x 120
area = 60 m

Question 18.
MODELING REAL LIFE
Estimate the area of the cottonwood leaf.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 71

Answer:
The area of the cottonwood leaf = 10 in

Explanation:
Area of the triangle = (1/2) x the product of the base b and the product of the height h
area = (1/2) x b x h
Sob = 5 in , h =  4 in
area = (1/2) x 20
area = 10 in

Question 19.
MODELING REAL LIFE
A shelf has the shape of a triangle. The base of the shelf is 36 centimeters, and the height is 18 centimeters. Find the area of the shelf in square inches.

Answer:
The shape of the triangle = 324

Explanation:
Area of the triangle = (1/2) x the product of the base b and the product of the height h
area = (1/2) x b x h
Sob = 36 cm , h =  18 cm
area = (1/2) x 648
area = 324 sq. cm

Question 19.

FINDING A MISSING DIMENSION
Find the missing dimension of the triangle.

Question 20.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 72

So base = 7 m

Question 21.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 73

Answer:
Base of the triangle = 4.66 ft

Explanation:
The area of the triangle =(1/2) x  the product of the base b and the product of height h
area of the triangle = 14 ft given
So the height = 6 ft given
area =  (1/2) x b x h
area = (1/2) x 4.66 x 6
area = (1/2) x 27.96
area = 14
soo base = 4.66 ft

Question 22.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 74

Answer:
Height = 2.66 in

Explanation:
The area of the triangle = (1/2) x the product of the base and the product of the height
area = (1/2) x 1.5 x h given that area = 2 in
2 = (1/2) x 1.5h
1.5 h = 4
h = (4/1.5)
h = 2.66 in
COMPOSITE FIGURES
Find the area of the figure.

Question 23.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 75

Answer:
The area of the figure = 44 ft

Explanation:
The area of the rectangle = 2 x(length + breadth)
area = 2 x (12 +10)
area = 2 x (22)
area = 44 sq. ft

Question 24.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 76

Answer:
The area of the figure = 52 cm

Explanation:
The area of the rectangle = 2 x(length + breadth)
area = 2 x (11 +15)
area = 2 x (26)
area = 52 cm

Question 25.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 77

Answer:
The area of the perimeter = 5/2 x a x b

Explanation:
The area of the perimeter = (5/2) x a x b
where a = middle point
b = sides

Question 26.
WRITING
You know the height and the perimeter of an equilateral triangle. Explain how to find the area of the triangle. Draw a diagram to support your reasoning.

Answer:
The perimeter of the equilateral triangle = a  x a x a = 3a

Explanation:
The perimeter of the equilateral triangle = 3a
height of the equilateral triangle = h
the area of the triangle = (1/2) x product of base b and the product of the height h
area = (1/2) x bh

Question 27.
CRITICAL THINKING
The total area of the polygon is 176 square feet. What is the value of x?
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 78

Answer:
The value of x = 6

Explanation:
The area of the polygon = 176 square feet given
area = 16 x 8 = 128
area = 176 – 128 = 48
The area of the right angle triangle = (a x b )/2
area = (8 x X)/2
48 = 4x + 4x
8x = 48
x = (48/8)
x = 6 ft

Question 28.
REASONING
The base and the height of Triangle A are one-half the base and the height of Triangle B. How many times greater is the area of Triangle B?

Answer:
2 times

Explanation:
The triangle B is 2 times greater than the triangle A

Question 29.
STRUCTURE
Use what you know about finding areas of triangles to write a formula for the area of a rhombus in terms of its diagonals. Compare the formula with your answer to Section 7.1 Exercise 34.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 79

Answer:
The area of the triangle = (1/2) ab
The area of the rhombus = (1/2) ab

Explanation:
The area of the triangle is equal to the area of the rhombus
area of the triangle = (1/2) ab
area of the rhombus = (1/2) ab

Lesson 7.3 Areas of Trapezoids and Kites

EXPLORATION 1
Deriving the Area Formula of a Trapezoid
Work with a partner.
a. Draw any parallelogram on a piece of centimeter grid paper. Cut the parallelogram into two identical trapezoids. How can you use the area of the parallelogram to find the area of each trapezoid?
b. Copy the trapezoid below on a piece of centimeter grid paper. Find the area of the trapezoid. Explain how you found the area.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 80
c. Draw any trapezoid on a piece of centimeter grid paper and find its area.
d. Use your results to write a formula for the area A of a trapezoid. Use the formula to find the area of the trapezoid shown.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 81
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 82

7.3 Lesson

Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 83
You can use decomposition to find areas of trapezoids and kites. A kite is a quadrilateral that has two pairs of adjacent sides with the same length and opposite sides with different lengths.

Try It
Find the area of the figure.

Question 1.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 87

Answer:
76.5 in

Explanation:
The area of the trapezoid = one half the product of its height h and the sum of its bases b1 and b2.
area = (1/2) x h x( b1 + b2)
area =(1/2) x h (5 + 12). Given that b1 = 5 and b2 = 12
area = (1/2) x 9(17) given that h = 9
area = (1/2) x 153
area = 76.5 sq. in

Question 2.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 88

Answer:
65.45 sq. mi

Explanation:
The area of the trapezoid = one half the product of its height h and the sum of its bases b1 and b2.
area = (1/2) x h x( b1 + b2)
area =(1/2) x h (3 + 3). Given that b1 = 3 and b2 = 3
area = (1/2) x 7.7(17) given that h = 7.7
area = (1/2) x 130.9
area = 65.45 sq. mi

In Example 1(a), you could have used a copy of the trapezoid to form a parallelogram. As you may have discovered in the exploration, this leads to the following formula for the area of a trapezoid.

Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 89

Try It
Find the area of the trapezoid.

Question 3.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 90

Answer:
The area of the trapezoid = 22.5 sq. mm

Explanation:
The area of the trapezoid = one half the product of its height h and the sum of its bases b1 and b2.
area = (1/2) x h x( b1 + b2)
area =(1/2) x h (5 + 4). Given that b1 = 5 and b2 = 4
area = (1/2) x 8(9) given that h = 8
area = (1/2) x 45
area = 22.5 sq. mm

Question 4.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 91

Answer:
The area of the trapezoid = 30 sq. in

Explanation:
The area of the trapezoid = one half the product of its height h and the sum of its bases b1 and b2.
area = (1/2) x h x( b1 + b2)
area =(1/2) x h (7.7 + 2.3). Given that b1 = 7.7 and b2 = 2.3
area = (1/2) x 6(10) given that h = 6 in
area = (1/2) x 60
area = 30 sq. in

Try It
Find the area of the figure.

Question 5.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 92

Answer:
The area of the trapezoid1 = 60 sq. m
The area of the trapezoid2= 88 sq. m

Explanation:
The area of the trapezoid1 = one half the product of its height h and the sum of its bases b1 and b2.
area = (1/2) x h x( b1 + b2)
area =(1/2) x h (5 + 5). Given that b1 = 5  and b2 = 5
area = (1/2) x 12(10) given that h = 6 m
area = (1/2) x  120
area = 60 sq. m
The area of the trapezoid2 = one half the product of its height h and the sum of its bases b1 and b2.
area = (1/2) x h x( b1 + b2)
area =(1/2) x h (8 + 8). Given that b1 = 8  and b2 = 8
area = (1/2) x 11(16) given that h = 6 m
area = 88 sq. m
Question 6.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 93

Answer:
The area of the trapezoid = 112 sq. in

Explanation:
The area of the trapezoid = one half the product of its height h and the sum of its bases b1 and b2.
area = (1/2) x h x( b1 + b2)
area =(1/2) x h (6+ 10). Given that b1 = 6 and b2 = 10
area = (1/2) x 14(16) given that h = 14 in
area = (1/2) x 224
area = 112 sq. in

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 7.
WRITING
Explain how to use the area of a parallelogram to find the area of a trapezoid.

Answer:
The area of the parallelogram = product of the height h and the product of the base b
The area of the trapezoid = one half the product of its height h and the sum of its bases b1 and b2.

Question 8.
REASONING
What measures do you need to find the area of a kite?

Answer:
Rhombus is used to find the area of the kite

Explanation:
The area of the rhombus = (1/2) x side x height
area = (1/2) x s x h
area = (1/2) sh
kite is also same as the rhombus

FINDING AREA
Find the area of the figure.

Question 9.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 94

Answer:
Area = 52.5 sq. yd

Explanation:
The area of the trapezoid = (1/2) x height x the product of the base 1 and the base 2
area = (1/2) x height x (b1 + b2)
area = (1/2) x 5 x (9 + 12)
area = (1/2) x 5 x 21
area = (1/2) x 105
area = 52.5 sq. yd

Question 10.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 95

Answer:
Area = 55 sq. m

Explanation:
The area of the trapezoid = (1/2) x height x the product of the base 1 and the base 2
area = (1/2) x height x (b1 + b2)
area = (1/2) x 10 x (7 + 4)
area = (1/2) x 10x 11
area = (1/2) x 110
area = 55 sq. m

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 11.
DIG DEEPER!
An archaeologist estimates that the manuscript shown was originally a rectangle with a length of 20 inches. Estimate the area of the fragment that is missing.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 96

Answer:
144 square inches

Explanation:
The area of the right angle triangle = a x b where a = height b = base
area = a x b a=12 b = 18 – 6 = 12
area = 12 x 12
area = 144 sq. in

Question 12.
The stained-glass window is made of identical kite-shaped glass panes. The approximate dimensions of one pane are shown. The glass used to make the window costs $12.50 per square foot. Find the total cost of the glass used to make the window.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 97

Answer:
The total cost of the glass used to make the window is 14.4375 $
Explanation:
The area of the rhombus = (1/2) x the product of the side s and the product of height h
area  = (1/2) x2 ft x 2.31ft
area = ( 4.62/2)
Area = 2.31 x 12.50$
area = 14.4375$

Areas of Trapezoids and Kites Homework & Practice 7.3

Review & Refresh

Find the area of the triangle.

Question 1.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 98

Answer:
Area =63 in

Explanation:
The area of the triangle = half the product of the base and the product of the height
area = (1/2)bh
area = (1/2) x 18 x 7
area = (126/2)
area = 63 in

Question 2.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 99

Answer:
Area =26 sq. km

Explanation:
The area of the triangle = half the product of the base and the product of the height
area = (1/2)bh
area = (1/2) x 8 x 6.5
area = (52/2)
area = 26 sq. km

Question 3.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 100

Answer:
Area =25 sq. ft

Explanation:
The area of the triangle = half the product of the base and the product of the height
area = (1/2)bh
area = (1/2) x 4 x 12.5
area = (50/2)
area = 25 sq. ft

Classify the quadrilateral./

Question 4.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 101

Answer:
The above quadrilateral look similar to the rectangle

Explanation:
Rectangle
the area of the rectangle = length x width
area = l x w

Question 5.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 102

Answer:
The above diagram is  similar to the trapezoid

Explanation:
The area of the trapezoid = half the product of the base and the product of the height
area = (1/2) x b x h
Question 6.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 103

Answer:
The above figure is similar to the parallelogram

Explanation:
The area of the parallelogram = the product of the height and the product of the base b
area = b x h

Question 7.
On a normal day, 12 airplanes arrive at an airport every 15 minutes. Which rate does not represent this situation?
A. 24 airplanes every 30 minutes
B. 4 airplanes every 5 minutes
C. 6 airplanes every 5 minutes
D. 48 airplanes each hour

Answer:
B

Explanation:
4 airplanes every 5 minutes
Concepts, Skills, & Problem Solving
USING TOOLS
Find the area of the trapezoid by forming a parallelogram. (See Exploration 1, p. 297.)

Question 8.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 104

Answer:
The area of the trapezoid = (1/2) x b x l x h

Explanation:
The area of the trapezoid = (1/2) x b x l x h
area = (1/2) x b x h x l
area = (lxb/2)x h

Question 9.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 105

Answer:
The area of the trapezoid = (1/2) x b x l x h

Explanation:
The area of the trapezoid = (1/2) x b x l x h
area = (1/2) x b x h x l
area = (lxb/2)x h

Question 10.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 106

Answer:
The area of the trapezoid = (1/2) x b x l x h

Explanation:
The area of the trapezoid = (1/2) x b x l x h
area = (1/2) x b x h x l
area = (lxb/2)x h

FINDING AREA
Use decomposition to find the area of the figure.

Question 11.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 107

Answer:
25 cm

Explanation:
The area of the triangle = (1/2) b x h
base value = 2, height = 5 given
area = (1/2) x 5 x 2
area = 5
the area of another triangle = 5
the remaining = rectangle
area of rectangle = length x breadth
area = 15 + 5 + 5 = 25 cm

Question 12.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 108

Answer:
92 sq. yd

Explanation:
The area of the triangle = (1/2) b x h
base value = 2, height = 5 given
area = (1/2) x 8 x 2=3
area = 12
the remaining = rectangle
area of rectangle = length x breadth
area = 80 + 12 yd
area = 92 yd

Question 13.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 109

Answer:
125 m

Explanation:
The area of the triangle = (1/2) b x h
base value = 2, height = 5 given
area = (1/2) x 8 x 5= 20
area = 20
The area of the triangle = (1/2) b x h
base value = 17, height = 5 given
area = (1/2) x 17 x 5= 20
area = 42.5
area  = 20 + 20+ 42.5 + 42.5
area = 125 m

Question 14.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 110

Answer:
The area of the figure = 44 inches

Explanation:
The area of the triangle = (1/2) b x h
base value = 9, height = 4 given
area = (1/2) x 9 x 4= 18
area = 18
the remaining = rectangle
area of rectangle = length x breadth
area = 18 + 18 + 4 +
area = 44 inches
Question 15.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 111

Answer:
The area of the figure = 55  miles

Explanation:
The area of the triangle = (1/2) b x h
base value = 10, height = 7 given
area = (1/2) x 10 x 7= 35
area = 35 mi
The area of the triangle = (1/2) b x h
base value = 10, height = 4 given
area = (1/2) x 10 x 4= 20
area = 20 mi
area =  20 + 35 = 55
area = 55 mi

Question 16.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 112

Answer:
The area of the figure = 17.68 miles

Explanation:
The area of the triangle = (1/2) b x h
base value = 3.2, height = 3.8 given
area = (1/2) x 3.2 x 3.8= 35
area = 6.08
The area of the triangle = (1/2) b x h
base value = 3.2, height = 1.6given
area = (1/2) x 3.2 x 1.6= 20
area = 2.56
area =  2.56 + 2.56 + 6.08 + 6.08 = 17.68 kms
area = 17.68 miles

FINDING AREA
Find the area of the trapezoid.

Question 17.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 113

Answer:
28 in

Explanation:
Area of trapezoid = half the product of the height and the product  of the bases
area = (1/2) x h x (b1 +b2)
area = (1/2) x 4 x  (6 + 8)/
area = (1/2) x 4 x 14
area = 28 sq. in

Question 18.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 114

Answer:
10 sq. cm

Explanation:
Area of trapezoid = half the product of the height and the product  of the bases
area = (1/2) x h x (b1 +b2)
area = (1/2) x 4 x  (3.5 + 1.5)
area = (1/2) x 4 x 5
area = 10 sq. cm

Question 19.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 115

Answer:
105 sq. ft

Explanation:
Area of trapezoid = half the product of the height and the product  of the bases
area = (1/2) x h x (b1 +b2)
area = (1/2) x 10 x  (13.5 + 7.5)
area = (1/2) x 10 x 21
area = 105 sq. ft

Question 20.
YOU BE THE TEACHER
Your friend finds the area of the trapezoid. Is your friend correct? Explain your reasoning.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 116

Answer:
No my friend is not correct

Explanation:
Area of trapezoid = half the product of the height and the product  of the bases
area = (1/2) x h x (b1 +b2)
area = (1/2) x 8 x  (6 +14)
area = (1/2) x 160
area = 80 sq. m

Question 21.
MODELING REAL LIFE
Light shines through a window. What is the area of the trapezoid-shaped region created by the light?
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 117

Answer:
16 sq. ft
Explanation:
Area of trapezoid = half the product of the height and the product  of the bases
area = (1/2) x h x (b1 +b2) given that b1 = 3 and b2 = 5
area = (1/2) x 4 x  (5 +3)
area = (1/2) x 32
area = 16 sq. ft

COMPOSITE FIGURES
Find the area of the figure.

Question 22.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 118

Answer:
178.5 sq. ft
Explanation:
Area of trapezoid = half the product of the height and the product  of the bases
area = (1/2) x h x (14 +7) given that b1 = 14 and b2 = 7
area = (1/2) x 17 x  (14 +7)
area = (1/2) x 357
area = 178.5 sq. ft

Question 23.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 119

Question 24.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 120

FINDING A MISSING DIMENSION
Find the height of the trapezoid.

Question 25.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 121

Answer:
The height of the trapezoid = square root of height and bases

Question 26.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 122

Question 27.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 123

FINDING AREA
Find the area (in square feet) of a trapezoid with height hand bases b1 and b2.

Question 28.
h = 6 in.
b1 = 9 in.
b2 = 12 in.

Answer:
The area of the trapezoid = 0.43722 square feet

Explanation:
Area of trapezoid = half the product of the height and the product  of the bases
area = (1/2) x h x (9 +12) given that b1 = 9 and b2 = 12
area = (1/2) x 6 x  (9 + 12)
area = (1/2) x 126
area = 63 in
1 inch = 0.00694 sq feet
so 0.43722sq ft

Question 29.
h = 12 yd
b1 = 5 yd
b2 = 7 yd

Answer:
The area of the trapezoid = 648 square feet

Explanation:
Area of trapezoid = half the product of the height and the product  of the bases
area = (1/2) x h x (5 +7) given that b1 = 5 and b2 = 7
area = (1/2) x 12 x  (5 + 7)
area = (1/2) x 144
area =72 yd
1 yard = 9 sq feet
so 72 yd = 72 x 9 sq ft
area = 648 sq ft

Question 30.
h = 6 m
b1 = 3 m
b2 = 8 m

Answer:
The area of the trapezoid = 355.212 square feet

Explanation:
Area of trapezoid = half the product of the height and the product  of the bases
area = (1/2) x h x (3 +8) given that b1 = 3 and b2 = 8
area = (1/2) x 6 x  (3 + 8)
area = (1/2) x 66
area =33 m
1 m  = 10.764 sq feet
so 33 m = 33 x 10.764sq ft
area = 355.212 sq ft

Question 31.
OPEN-ENDED
The area of the trapezoidal student election sign is 5 square feet. Find two possible values for each base length.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 123.1

Answer:
The area of the trapezoid = 4 ft

Explanation:
Area of trapezoid = half the product of the height and the product  of the bases
area = (1/2) x h x (4 +4) given that b1 = 4 and b2 = 4
area = (1/2) x 2 x  (4 + 4)
area = (1/2) x 8
area = 4 sq. ft

Question 32.
REASONING
How many times greater is the area of the floor covered by the larger speaker than by the smaller speaker?
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 124

Answer:
2 times

Explanation:
The larger speaker is 2 times greater than that of the smaller speaker

Question 33.
REASONING
The rectangle and the trapezoid have the same area. What is the length ℓ of the rectangle?
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 125

Question 34.

Answer:
The area of the triangle =36
Explanation:
In the above given trapezoid the bases b1 = 12 and b2 = 24 height = 9 ft
So the area of the trapezoid = (1/2) x h x(b1 + b2)
area = (1/2) x 9 x (12 +24)
area = (1/2) x 324
area = 162
The length of the triangle = length X w
162 = 9l
length = 36 ft

CRITICAL THINKING
In the figureshown, the area of the trapezoid is less than twice the area of the triangle. Find the possible values of x. Can the trapezoid have the same area as the triangle? Explain your reasoning.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 126

Answer:
The possible value of x = 15 in

Explanation:
In the above statement they said that the area of the trapezoid is less than twice the area of the triangle
area of the triangle = (1/2) x b x h
area = (1/2)  x 15 x 10
area = (150/2) =75
Area of trapezoid = (1/2) x h x (b1 + b2)
area = (1/2) x 10 x (15 +15)
area = (300/2)
area = 150
So the area of the trapezoid is 2 times less than the area of the triangle.

Question 35.
STRUCTURE
In Section 7.1 Exercise 34 and Section 7.2 Exercise 29, you wrote a formula for the area of a rhombus in terms of its diagonals.
a. Use what you know about finding areas of figures to write a formula for the area of a kite in terms of its diagonals.
b. Are there any similarities between your formula in part(a) and the formula you found in Sections 7.1 and 7.2? Explain why or why not.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 127

Answer:
The area of the rhombus = (1/2) x side x height

Explanation:
The kite is looking the same as the rhombus
area of the rhombus = (1/2) x side x height

Lesson 7.4 Three-Dimensional Figures

EXPLORATION 1
Exploring Faces, Edges and Vertices

Work with a partner. Use the rectangular prism shown.
a. Prisms have faces, edges, and vertices. What does each of these terms mean?
b. What does it mean for lines or planes to be parallel or perpendicular in three dimensions? Use drawings to identify one pair of each of the following.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 128

  • parallel faces
  • parallel edges
  • edge parallel to a face
  • perpendicular faces
  • perpendicular edges
  • edge perpendicular to a face

Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 128.1

EXPLORATION 2

Drawing Views of a Solid
Work with a partner. Draw the front, side, and top views of each stack of cubes. Then find the number of cubes in the stack. An example is shown at the left.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 129
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 129.1

Answer:
a: the number of cubes = 4
b: the number of cubes = 4
c: the number of cubes = 5
d: the number of cubes = 6

Explanation:
a:
b::
c:
d:

7.4 Lesson

A solid is a three-dimensional figure that encloses a space. A polyhedron is a solid whose faces are all polygons.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 130

Try It

Question 1.
Find the numbers of faces, edges, and vertices of the solid.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 131

Answer:
faces = 5
edges = 12
vertices = 6

Explanation:
The number of faces = 5
the number of edges = 12
the number of vertices = 6

Key Ideas

Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 132

Try It

Draw the solid.

Question 2.
square prism

Answer:

Question 3.
pentagonal pyramid

Answer:

Self-Assessment for Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 132.1

Question 4.
FACES, EDGES, AND VERTICES
Find the numbers of faces, edges, and vertices of the solid at the left.

Answer:
faces : 3
edges : 6
vertices : 3

Explanation:
The number of faces of solid at the left = 3
edges = 6
vertices = 3

Question 5.
DRAWING A SOLID
Draw an octagonal prism.

Answer:

Question 6.
WHICH ONE DOESN’T BELONG?
Which figuredoes not belong with the other three? Explain your reasoning.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 133

Answer:
The 3rd figure is different from the other 3 figures

Explanation:
The 3rd figure is the same as the square prism
the other 3 figures are triangular prisms

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 7.
The Flatiron Building in New York City is in the shape of a triangular prism. Draw a sketch of the building.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 134

Answer:

Question 8.
The Pyramid of the Niches is in El Tajín, an archaeological site in Veracruz, Mexico. Draw the front, side, and top views of the pyramid. Explain.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 135

Answer:
Front = 2
side = 1
top = 1

Explanation:

Question 9.
Use the point-cut diamond shown.
a. Find the numbers of faces, edges, and vertices of the diamond.
b. Draw the front, side, and top views of the diamond.
c. How can a jeweler transform the point-cut diamond into a table-cut diamond as in Example 3?
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 136

Answer:
a : the number of faces = 8,edges = 16,vertices = 6
b : front = 2 , side = 2,top = 1

Explanation:
a : faces = 8
edges = 16
vertices = 6
b :

Three-Dimensional Figures Homework & Practice 7.4

Review & Refresh

Find the area of the figure.

Question 1.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 137

Answer:
The area of the triangle = 15 ft
Explanation:
In the above given trapezoid the bases b1 = 12 and b2 = 24 height = 9 ft
So the area of the trapezoid = (1/2) x h x(b1 + b2)
area = (1/2) x 3 x (4 +6)
area = (1/2) x 30
area = 15
Question 2.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 138

Answer:
The area of the triangle = 18 km
Explanation:
In the above given trapezoid the bases b1 = 12 and b2 = 24 height = 9 ft
So the area of the trapezoid = (1/2) x h x(b1 + b2)
area = (1/2) x 3 x (5 +7)
area = (1/2) x 36
area = 18 km

Question 3.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 139

Answer:
The area of the triangle = 18 km
Explanation:
In the above given trapezoid the bases b1 = 12 and b2 = 24 height = 9 ft
So the area of the trapezoid = (1/2) x h x(b1 + b2)
area = (1/2) x 18 x (6 +6)
area = (1/2) x 216
area = 18 k

Find the LCM of the numbers.

Question 4.
8, 12

Answer:
24

Explanation:
Factors of 8 = 2 x 2 x2
factors of 12 = 2 x 2x 3
l.c.m. = 2 x 2 x 2x 3
l.c.m = 24

Question 5.
15, 25

Answer:
75

Explanation:
Factors of 15 = 5 x 3
factors of 25 = 5 x 5
l.c.m. = 5 x 3 x5
l.c.m = 75

Question 6.
32, 44

Answer:
352

Explanation:
Factors of 32 = 8 x 4
factors of 44 = 11 x 4
l.c.m. = 4 x 11 x 8
l.c.m = 352

Question 7.
3, 7, 10

Answer:
210

Explanation:
Factors of 3 = 3 x 1
factors of 7 = 7 x 1
factors of 10 =5 x 2
l.c.m. = 3 x 7 x 5 x 2
l.c.m = 210

A bucket contains stones and seashells. You are given the number of seashells in the bucket and the ratio of stones to seashells. Find the number of stones in the bucket.

Question 8.
18 seashells; 2 to 1

Answer:
No of stones = 12
No of seashells = 6

Explanation:
(18/3) = 6
2 : 1 = 12 : 6

Question 9.
30 seashells; 4 : 3

Answer:
No of stones = 17.14
No of seashells = 12.6

Explanation:
(30/7) = 4.2
4 : 3 = 17.4 : 12.6

Question 10.
40 seashells; 7 : 4

Answer:
No of stones = 25.45
No of seashells = 14.54

Explanation:
(40/11) = 3.63
7 : 4 = 25.45 : 14.54

Concepts, Skills, & Problem Solving

DRAWING VIEWS OF A SOLID
Draw the front, side, and top views of the stack of cubes. Then find the number of cubes in the stack. (See Exploration 2, p. 305.)

Question 11.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 140

Answer:
front = 10
side = 3
top = 4

Explanation:

Question 12.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 141

Answer:
front = 9
side = 3
top = 5

Explanation:

Question 13.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 142

Answer:
front = 5
side = 5
top = 8

Explanation:

FACES, EDGES, AND VERTICES
Find the numbers of faces, edges, and vertices of the solid.

Question 14.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 143

Answer:
faces = 10
edges = 24
vertices = 9

Explanation:
The number of faces = 10
the number of edges = 24
the number of vertices =9

Question 15.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 144

Answer:
faces = 17
edges = 34
vertices = 13

Explanation:
The number of faces = 17
the number of edges = 34
the number of vertices =13

Question 16.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 145

Answer:
faces = 10
edges = 20
vertices = 7

Explanation:
The number of faces = 10
the number of edges = 20
the number of vertices =7

DRAWING SOLIDS
Draw the solid.

Question 17.
triangular prism

Answer:

Question 18.
pentagonal prism

Answer:

Question 19.
rectangular pyramid

Question 20.
hexagonal pyramid

Answer:

Question 21.
MODELING REAL LIFE
The Pyramid of Cestius in Rome, Italy, is in the shape of a square pyramid. Draw a sketch of the pyramid.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 146

Answer:

Question 22.
RESEARCH
Use the Internet to find a picture of the Washington Monument. Describe its shape.

DRAWING VIEWS OF A SOLID
Draw the front, side, and top views of the solid.

Question 23.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 147

Answer:
front = 1
side = 2
top = 1

Explanation:

Question 24.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 148

Answer:
front =2
side = 2
top = 1

Explanation:

Question 25.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 149

Answer:
front =2
side = 2
top = 1

Explanation:

Question 26.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 150

Answer:
front =2
side = 2
top = 2

Explanation:

Question 27.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 151

Answer:
front = 1
side = 2
top = 1

Explanation:

Question 28.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 152

Answer:
front = 1
side = 1
top = 1

Explanation:

DRAWING SOLIDS
Draw a solid with the following front, side, and top views.

Question 29.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 153

Answer:

Explanation:
front = 2 top = 1 side = 2

Question 30.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 154

Question 31.
MODELING REAL LIFE
Design and draw a house. Name the different solids that you can use to make a model of the house.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 155

Question 32.
DIG DEEPER!
Two of the three views of a solid are shown.
a. What is the greatest number of cubes in the solid?
b. What is the least number of cubes in the solid?
c. Draw the front views of both solids in parts (a) and (b).
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 156

Answer:
a: The greatest number of cubes in the solid = 3
b : The least number of cubes in the solid = 2
c :

Question 33.
OPEN-ENDED
Draw two different solids with five faces.
a. Write the numbers of vertices and edges for each solid.
b. Explain how knowing the numbers of edges and vertices helps you draw a three-dimensional figure.

Question 34.
CRITICAL THINKING
The base of a pyramid has n sides. Find the numbers of faces, edges, and vertices of the pyramid. Explain your reasoning.

Lesson 7.5 Surface Areas of Prisms

EXPLORATION 1
Using Grid Paper to Construct a Solid
Work with a partner. Copy the figure shown below onto grid paper.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 157
a. Cut out and fold the figure to form a solid. What type of solid does the figure form?
b. What is the area of the entire surface of the solid?

EXPLORATION 2
Finding the Area of the Entire Surface
Work with a partner. Find the area of the entire surface of each solid. Explain your reasoning.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 158

Answer:

Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 159

7.5 Lesson

The surface area of a solid is the sum of the areas of all of its faces. You can use a two-dimensional representation of a solid, called a net, to find the surface area of the solid. Surface area is measured in square units.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 160

Key Idea
Net of a Rectangular Prism
A rectangular prism is a prism with rectangular bases.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 161

Try It

Find the surface area of the rectangular prism.

Question 1.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 162

Answer:
258 sq. m

Explanation:
The surface area of the rectangular prism = Area of the top + area of the bottom +area of front + area of back + area of side + area of a side
surface area = 9 x 5 + 9 x 5 + 6 x 9+ 6 x 9  + 6 x 5 +6 x 5
surface area = 45 + 45 + 54 + 54 + 30 +30
surface area = 258 sq. mm

Question 2.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 163

Answer:
286 sq. ft

Explanation:
The surface area of the rectangular prism = Area of the top + area of the bottom +area of front + area of back + area of side + area of a side
surface area = 10 x 3.5 + 10 x 3.5 + 10 x 8+ 10 x 8  + 8 x 3.5 + 8 x 3.5
surface area = 35 +35+ 80 + 80 +28 +28
surface area = 286 sq. ft

Key Idea
Net of a Triangular Prism
A triangular prism is a prism with triangular bases.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 164

Try It

Find the surface area of the triangular prism.

Question 3.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 165

Answer:
67 sq. yd

Explanation:
Surface area = area of the bottom + area of the front +area of the back +area of a side + area of a side
surface area = 3 x 5 = 15+ (1/2) x 3 x 4 = 6 + (1/2) x 3 x 4 = 6 + 4 x 5 = 20 + 5 x 4 = 20
bottom = 3 x 5 , front = (1/2) x 3 x 4, back = (1/2) x 3 x 4, side = 4 x 5 , side = 5 x 4
surface  area = 15 +6 +6 +20 + 20
area = 67 sq. yd

Question 4.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 166

Answer:
510 sq. m

Explanation:
Surface area = area of the bottom + area of the front +area of the back +area of a side + area of a side
surface area = 10 x 10 = 100+ (1/2) x 10 x 16=80 + (1/2) x 10 x 16 = 80+ 9 x 10 =90 + 10 x 16=160
bottom = 10 x 10 , front = (1/2) x 10 x 16, back = (1/2) x 10 x 16, side = 9 x 10 , side = 10 x 16
surface  area = 100 +80 +80+90 +160
area = 510 sq. m

When all the edges of a rectangular prism have the same length s, the rectangular prism is a cube. The net of a cube shows that each of the 6 identical square faces has an area of s2. So, a formula for the surface area of a cube is
S = 6s2. Formula for surface area of a cube
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 167
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 168

Try It
Find the surface area of the cube.

Question 5.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 169

Answer:
96 sq. cm

Explanation:
area of the cube = 6 s2
area = 6 x side x side
area = 6 x 4  x 4
area = 96 sq. cm

Question 6.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 170

Answer:
1.5 sq. in

Explanation:
area of the cube = 6 s2
area = 6 x side x side
area = 6 x 0.5  x 0.5
area = 1.5 sq. in

Self-Assessment for Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 7.
FINDING SURFACE AREA
Find the surface area of a cube with edge lengths of 9 centimeters.

Answer:
486 sq. cm

Explanation:
area of the cube = 6 s2
area = 6 x side x side given that s = 9 cm
area = 6 x 9  x 9
area = 486 sq. cm

Question 8.
DIFFERENT WORDS, SAME QUESTION
Which is different? Find “both” answers.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 171
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 172

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 9.
Light shines through a glass prism and forms a rainbow. What is the surface area of the prism?
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 173

Answer:
93 sq. cm

Explanation:
Surface area = area of the bottom + area of the front +area of the back +area of a side + area of a side
surface area = 6 x 3 = 18+ (1/2) x 5 x 6=30 + (1/2) x 5 x 6 = 30+ 3 x 5 =15+ 5 x 6= 30
bottom = 6  x 3 , front = (1/2) x 5 x 6, back = (1/2) x 5 x 6, side = 3 x 5 , side = 5 x 6
surface  area = 18 +15 +15 +15 +30
area = 93 sq. cm

Question 10.
One pint of chalkboard paint covers 60 square feet. What is the least number of pints of paint needed to paint the walls of a room in the shape of a rectangular prism with a length of 15 feet, a width of 13 feet, and a height of 10 feet? Explain.

Question 11.
DIG DEEPER!
A flexible metamaterial is developed for use in robotics and prosthetics. A block of metamaterial is in the shape of a cube with a surface area of 600 square centimeters. What is the edge length of the block of metamaterial?

Answer:
The edge length of the block of metamaterial = 25 square centimeters

Explanation:
The surface area of the cube = 6 s square
area = 6 x 25 x4
area = 6 x100
area = 600 square centimeters

Surface Areas of Prisms Homework & Practice 7.5

Review & Refresh

Draw the front, side, and top views of the solid.

Question 1.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 174

Answer:
front = 1
side = 2
top = 1

Explanation:

Question 2.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 174.1

Answer:
front = 1
side = 1
top = 1

Explanation:

Question 3.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 174.2

Answer:
front = 1
side = 2
top = 2

Explanation:

Find the GCF of the numbers.

Question 4.
18, 72

Answer:
18

Explanation:
The factors of 18 are = 3 x 3 x 2
The factors of 72 are = 3 x 3 x 2 x 2 x 2
From the above the greatest common factors are = 3 x 3 x 2 =18

Question 5.
44, 110

Answer:
22

Explanation:
The factors of 44 are = 2 x 2 x 11
The factors of 110 are = 2  x  5 x 11
From the above the greatest common factors are = 2 x 11 = 22

Question 6.
78, 93

Answer:
3

Explanation:
The factors of 78 are = 2 x 3 x 13
The factors of 93 are = 3 x 31
From the above the greatest common factors are = 3

Question 7.
60, 96, 156

Answer :
12

Explanation:
The factors of 60 are = 2 x 2 x 3 x5
The factors of 96 are = 2 x 2 x 2x 2 x 2 x 3
The factors of 156 are =2 x 2 x 3 x 13
From the above the greatest common factors are = 2 x 2 x 3 = 12

Solve the equation.

Question 8.
s – 5 = 12

Answer:
17

Explanation:
s = 12 + 5
s = 17

Question 9.
x + 9 = 20

Answer:
11

Explanation:
x = 20  -9
x = 11

Question 10.
48 = 6r

Answer:
r = 8

Explanation:
48 = 6r
r = (48/6)
r = 8

Question 11.
\(\frac{m}{5}\) = 13

Answer:
65

Explanation:
(m/5) = 13
m = 13 x 5
m = 65

Divide.

Question 12.
496 ÷ 16

Answer:
31

Explanation:
(496/16) = 31

Question 13.
765 ÷ 45

Answer:
17

Explanation:
(765/45) = 17

Question 14.
1173 ÷ 23

Answer:
51

Explanation:
(1173/23) = 51

Concepts, Skills, & Problem Solving
USING TOOLS
Use a net to find the area of the entire surface of the solid. Explain your reasoning. (See Exploration 2, p. 311.)

Question 15.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 175

Answer:
The surface area of the rectangle = length x breadth
area = l x b

Explanation:
The above figure is same as the rectangle
The surface area of the rectangle = length x breadth
area = l x b

Question 16.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 176

Answer:
The surface area of the triangle =  (/2) x  length x breadth
area =(1/2) x l x b

Explanation:
The above figure is the same as the triangle
The surface area of the rectangle =(1/2) x length x breadth
area =(1/2) l x b

Question 17.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 177

Answer:
The surface area of the square =  (/2) x  length x breadth
area =(1/2) x l x b

Explanation:
The above figure is the same as the triangle
The surface area of the rectangle =(1/2) x length x breadth
area =(1/2) l x b

FINDING SURFACE AREA
Find the surface area of the rectangular prism.

Question 18.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 178

Answer:
130 ft

Explanation:
The surface area of the rectangular prism = Area of the top + area of the bottom +area of front + area of back + area of side + area of a side
surface area = 5 x 1 + 5 x 1 + 10 x 5 + 10 x 5 + 10 x 1 +10 x 1
surface area = 5 + 5 + 50 + 50 +10 +10
surface area = 130

Question 19.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 179

Answer:
198

Explanation:
The surface area of the rectangular prism = Area of the top + area of the bottom +area of front + area of back + area of side + area of a side
surface area = 6 x 9 + 6 x 9 + 9 x 3 + 9 x 3 + 6 x 3 +6 x 3
surface area = 54 + 54 + 27 + 27 +18 +18
surface area = 198 sq. cm

Question 20.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 180

Answer:
76

Explanation:
The surface area of the rectangular prism = Area of the top + area of the bottom +area of front + area of back + area of side + area of a side
surface area = 2 x 4+ 2 x 4 + 4 x 5 + 4 x 5 + 2 x 5 +2 x 5
surface area = 8 + 8 + 20 + 20+10+10
surface area = 76

Question 21.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 181

Answer:
52in

Explanation:
The surface area of the rectangular prism = Area of the top + area of the bottom +area of front + area of back + area of side + area of a side
surface area = 2 x 4+ 2 x 4 + 3 x 2 + 3 x 2 + 4 x 3 +4 x 3
surface area = 8 + 8 + 6 + 6 +12 +12
surface area = 52

Question 22.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 182

Answer:
116.375 m

Explanation:
The surface area of the rectangular prism = Area of the top + area of the bottom +area of front + area of back + area of side + area of a side
surface area = 5.5 x 3 + 5.5 x 3 + 3 x 7.25 + 3 x 7.25 + 5.5 x 7.25 + 5.5 x 7.25
surface area = 16.5+ 16.5 + 21.75 + 21.75 +39.875 +39.875
surface area = 116.375 m

Question 23.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 183

Answer:
48.785 mi

Explanation:
The surface area of the rectangular prism = Area of the top + area of the bottom +area of front + area of back + area of side + area of a side
surface area = 6 x2 .33 + 6 x 2.33 + 2.33 x 1.25 + 2.33 x 1.25 + 6 x 1.25 + 6 x 1.25
surface area = 13.98+ 13.98 + 2.9125 + 2.9125 +7.5 +7.5
surface area = 48.785 mi

FINDING SURFACE AREA
Find the surface area of the triangular prism.

Question 24.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 184

Answer:
102 cm

Explanation:
Surface area = area of the bottom + area of the front +area of the back +area of a side + area of a side
surface area = 3 x 4 = 12 + (1/2) x 3 x 10 = 15 + (1/2) x 3 x 10  = 15 + 4 x 5 = 20 + 4 x 10 = 40
bottom = 3 x 4 , front = (1/2) x 3 x 10, back = (1/2) x 3 x 10, side = 4 x 5 , side = 4 x 10
surface  area = 12 +15 +15+20 +40
area = 102  cm

Question 25.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 185

Answer:
822 m

Explanation:
Surface area = area of the bottom + area of the front +area of the back +area of a side + area of a side
surface area = 16 x 10 = 160+ (1/2) x 16 x 17 = 136 + (1/2) x 16 x 17 = 136+ 15 x 10=150 + 15 x 16 = 240
bottom = 16 x 10 , front = (1/2) x16 x 17, back = (1/2) x 16 x 17, side = 15 x 10 , side =15 x 16
surface  = 160 +136+ 136 + 150 + 240
area = 822 m

Question 26.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 186

Answer:
543 in

Explanation:
Surface area = area of the bottom + area of the front +area of the back +area of a side + area of a side
surface area = 12 x 9 = 108+ (1/2) x 12 x 10 = 60 + (1/2) x 12 x 10 = 60 + 15 x 9 = 135 + 9 x 20 = 180
bottom = 12 x 9 , front = (1/2) x12 x 10, back = (1/2) x 12 x 10, side = 115 x 9 , side = 9 x 20
surface  area =108 +60 +60+ 135 +180
area = 543 in

Question 27.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 187

Answer:
17.8 ft

Explanation:
Surface area = area of the bottom + area of the front +area of the back +area of a side + area of a side
surface area = 1 x 3 = 3+ (1/2) x 1 x 2.2 = 1.1 + (1/2) x 1 x 2.2 = 1.1 + 2 x 3 = 6+ 3 x 2.2 = 6.6
bottom = 1 x 3 , front = (1/2) x1 x 2.2, back = (1/2) x 1 x 2.2, side = 2 x 3 , side = 3 x 2.2
surface  area =3 + 1.1 + 1.1+ 6 + 6.6
area = 17. 8 ft

Question 28.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 188

Answer:
62 . 8 mm

Explanation:
Surface area = area of the bottom + area of the front +area of the back +area of a side + area of a side
surface area = 4 x 4 = 16+ (1/2) x 4 x 3 = 6 + (1/2) x  4 x 3 = 6 + 5.7 x 4=22.8+ 3 x 4 = 12
bottom = 4 x 4 , front = (1/2) x 4 x 3, back = (1/2) x 4 x 3, side = 5.7 x 4 , side = 3 x 4
surface  area = 16 + 6 + 6 +22.8 + 12
area = 62. 8 mm

Question 29.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 189

Answer:
3228 . 26 m

Explanation:
Surface area = area of the bottom + area of the front +area of the back +area of a side + area of a side
surface area = 10 x (17/3) = 56.6+ (1/2) x 10 x 13 = 65 + (1/2) x  10 x 13 = 65 + 12 x (17/3) = 68+ (17/3) x 13 = 73.6
bottom = 10 x (17/3) , front = (1/2) x 10 x 13, back = (1/2) x 10 x 13, side = 12 x (17/3) , side = (17/3) x 13
surface  area = 56.6 + 65 + 65 + 68 + 73.6
area = 3228. 26 m

Question 30.
MODELING REAL LIFE
A gift box in the shape of a rectangular prism measures 8 inches by 8 inches by 10 inches. What is the least amount of wrapping paper needed to wrap the gift box? Explain

Answer:
440 inches

Explanation:
The surface area of the rectangular prism = Area of the top + area of the bottom +area of front + area of back + area of side + area of a side
surface area = 8 x 8 + 8 x 8 + 10 x 8 + 10 x 8+ 8 x 10 + 8 x 10
surface area = 64 + 64+ 80 + 80 + 80 + 80
surface area = 440 in
The least amount of wrapping paper needed to wrap the gift box = 440 in

Question 31.
MODELING REAL LIFE
What is the least amount of fabric needed to make the tent?
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 190

Answer:
102 sq. ft

Explanation:
Surface area = area of the bottom + area of the front +area of the back +area of a side + area of a side
surface area = 6 x 4 = 24+ (1/2) x 6 x 5 = 15 + (1/2) x  6 x 5 = 15+ 7 x 4 = 28+ 5 x 4 = 20
bottom = 6 x 4 , front = (1/2) x 6 x 5, back = (1/2) x 6 x 5, side = 7 x 4 , side = 5 x 4
surface  area = 24 + 15 + 15 + 28 + 20
area = 20 sq. ft

FINDING SURFACE AREA

Find the surface area of the cube.

Question 32.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 191

Answer:
216 sq. km

Explanation:
area of the cube = 6 s2
area = 6 x side x side
area = 6 x 6  x 6
area = 216 sq. km

Question 33.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 192

Answer:
0.66666 sq. ft

Explanation:
area of the cube = 6 s²
area = 6 x side x side
area = 6 x (1/2)  x (1/2)
area = 6 x 0.11111
area = 0.6666 sq. ft

Question 34.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 193

Answer:
181.5 sq. yd

Explanation:
area of the cube = 6 s²
area = 6 x side x side
area = 6 x 5.5 x 5.5
area = 6 x 30.25
area = 181 .5 sq. yd

Question 35.
MODELING REAL LIFE
A piece of dry ice is in the shape of a cube with edge lengths of 7 centimeters. Find the surface area of the dry ice.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 194

Answer:
294 centimeters
Explanation:
area of the cube = 6 s2
area = 6 x side x side
area = 6 x 7 x 7
area = 6 x 49
area = 294 sq. cm

Question 36.
YOU BE THE TEACHER
Your friend finds the surface area of the prism. Is your friend correct? Explain your reasoning.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 195

Answer:
No, my friend is not correct because my friend did the surface area of the cube

Explanation:
My friend did the surface area of the cube
cube = 6s²

Question 37.
CRITICAL THINKING
A public library has the aquarium shown. The front piece of glass has an area of 24 square feet. How many square feet of glass were used to build the aquarium?
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 196

Answer:
The square feet of glass were used to build the aquarium = 12 ft

Explanation:
The square feet of glass were  used to build the aquarium = l x b
square = 6 x 2.5
square = 12

Question 38.
PROBLEM SOLVING
A cereal box has the dimensions shown.
a. Find the surface area of the cereal box.
b. The manufacturer decides to decrease the size of the box by reducing each of the dimensions by 1 inch. Find the decrease in surface area.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 197

Answer:
a : 216 in
b : 144 in

Explanation:
Surface area  of a = 6 x s x s
area = 6 x 36
area = 216
surface area of b = 6 x s x s
area = 6 x 24
area = 144 because they said that cereal box is decreased by 1 inch

Question 39.
REASONING
The material used to make a storage box costs $1.25 per square foot. The boxes have the same volume. Which box might a company prefer to make? Explain your reasoning.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 198

Question 40.
LOGIC
Which of the following are nets of a cube? Select all that apply.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 199

Question 41.
MODELING REAL LIFE
A quart of stain covers 100 square feet. How many quarts should you buy to stain the wheelchair ramp? (Assume you do not have to stain the bottom of the ramp.)
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 200

Answer:

Question 42.
DIG DEEPER!
A cube is removed from a rectangular prism. Find the surface area of the figure after removing the cube.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 201

Answer:
341 sq. ft

Explanation:
Surface area of the rectangular prism = area of the bottom + area of the front +area of the back +area of a side + area of a side
surface area =  9 x 8= 72 + (1/2) x 9 x 5=94.5 + (1/2) x 9 x 5 = 94.5 + 5 x 8 = 40+ 8 x 5 =40
bottom = 9 x 8 , front = (1/2) x 9 x 5, back = (1/2) x 9 x 5, side = 5 x 8 , side = 8 x 5
surface  area = 72 + 94.5 + 94.5 +40 +40
area = 341 sq. ft

Lesson 7.6 Surface Areas of Pyramids

EXPLORATION 1
Using a Net to Construct a Solid
Work with a partner. Copy the net shown below onto grid paper.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 202
a. Cut out and fold the net to form a solid. What type of solid does the net form?
b. What is the surface area of the solid?

EXPLORATION 2
Finding Surface Areas of Solids
Work with a partner. Find the surface area of each solid. Explain your reasoning.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 203
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 204

7.6 Lesson

Key Idea
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 205
In this book, the base of every pyramid is either a square or an equilateral triangle. So, the lateral faces are identical triangles.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 206

Try It
Find the surface area of the square pyramid.

Question 1.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 207

Answer:
16 sq. ft

Explanation:
surface area of the square pyramid = bottom + side + side + side + side
area = 4 + 3 + 3 + 3
bottom = 2 x 2= 4, side = (1/2) x 2 x 3 = 3,
area = 16 sq. ft

Question 2.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 208

Answer:
62.5 sq. cm
Explanation:
surface area of the square pyramid = bottom + side + side + side + side
area = 25 + 12.5 + 12.5 + 12.5
bottom = 5 x 5 = 25, side = (1/2) x 5 x 5 = 12.5,
area = 62.5 sq. cm

Try It
Find the surface area of the triangular pyramid.

Question 3.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 209

Answer:
area = 26 sq. cm

Explanation:
surface area of the triangular pyramid = bottom + side + side + side
area = 17 + 3 + 3 + 3
bottom = (1/2 ) x 3 x 4 = 17 , side =(1/2) x 3 x 2 = 3
area = 26 sq. cm

Question 4.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 210

Answer:
area = 26 sq. cm

Explanation:
surface area of the triangular pyramid = bottom + side + side + side
area = 17 + 3 + 3 + 3
bottom = (1/2 ) x 3 x 4 = 17 , side =(1/2) x 3 x 2 = 3
area = 26 sq. cm

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 5.
PRECISION
Explain how to find the surface area of a pyramid.

Answer:
Surface area of the pyramid = area +(1/2) x p x s

Explanation:,
The surface area of the pyramid = area + (1/2) x p x s where p = perimeter of the base, s = slant height

FINDING SURFACE AREA
Find the surface area of the pyramid.

Question 6.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 211

Answer:
Area = 21 sq. yd

Explanation:,
The surface area of the pyramid = area + (1/2) x p x s where p = perimeter of the base, s = slant height
area = 7 +(1/2) x 4 x 7
area = 7 + 14
area = 21 sq. yd

Question 7.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 212

Answer:
Area = 31.15 sq. m

Explanation:,
The surface area of the pyramid = area + (1/2) x p x s where p = perimeter of the base, s = slant height
area = 8 +(1/2) x 7 x  6.9
area = 7 + (48.3/2)
area = 7 + 24.15
area = 31.15 sq. m

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 8.
A salt lamp is shaped like a triangular pyramid. Find the surface area of each triangular face.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 213

Answer:
The surface area of the triangular pyramid = 115.5 sq. in

Explanation:

The surface area of the triangular pyramid = area of the faces + area of the base
area of the face1 = 3 in
area of the face2 = 3 in
area of the face3  = 3 in
area of the face4 = 3in
area of the base = 3.5
surface area = 12 + 3.5 = 15.5 sq. in

Question 9.
DIG DEEPER!
Originally, each triangular face of the Great Pyramid of Giza had a height of 612 feet and a base of 756 feet. Today, the height of each triangular face of the square pyramid is 592 feet. Find the change in the total surface area of the four triangular faces of the Great Pyramid of Giza.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 214

Answer:
The surface area of the  four triangular faces = 612 sq. ft

Explanation:

The surface area of the triangular pyramid = area of the faces + area of the base
area of the face1 = 612 sq. ft
area of the face2 = 612 sq. ftft
area of the face3  =612 sq. ft
area of the face4 = 612 sq. ft
area of the base = 756 sq. ft
surface area = 3204 sq. ft

Surface Areas of Pyramids Homework & Practice 7.6

Review & Refresh

Find the surface area of the prism.

Question 1.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 215

Answer:
82 sq. ft

Explanation:
The surface area of the rectangular prism = Area of the top + area of the bottom +area of front + area of back + area of side + area of a side
surface area = 7 x 2 + 7 x 2 + 7 x 3+ 7 x 3 + 3 x 2 + 3 x 2
surface area = 14 +14+ 21 + 21 +6+6
surface area = 82 sq. ft

Question 2.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 216

Answer:
82 sq. ft

Explanation:
The surface area of the rectangular prism = Area of the top + area of the bottom +area of front + area of back + area of side + area of a side
surface area =  + 7 x 2 + 7 x 3+ 7 x 3 + 3 x 2 + 3 x 2
surface area = 14 +14+ 21 + 21 +6+6
surface area = 82 sq. ft

Question 3.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 217

Answer:
384 sq. in

Explanation:
The surface area of the rectangular prism = Area of the top + area of the bottom +area of front + area of back + area of side + area of a side
surface area =8 x 8  + 8 x 8 + 8 x 8+ 8 x 8 + 8 x 8 + 8 x 8
surface area = 64 +64 + 64 + 64+ 64+64
surface area = 384 sq. in

Match the expression with an equivalent expression.

Question 4.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 218

Answer:
12n + 6
A. 12n + 12

Explanation:
3 x (4n + 2 )
12n + 6
A. 2 x (6n + 6)
12n + 12

Question 5.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 219

Answer:
12n + 18
B. 6(2n + 3)

Explanation:
6 x (2n + 3 )
12n + 18
A. 6 x (2n + 3)
12n + 18

Question 6.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 220

Answer:
12n + 16
C. 12n + 6

Explanation:
4 x (3n + 4 )
12n + 16
C.  2 x (6n + 3)
12n + 6

Question 7.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 221

Answer:
12n + 12
D. 2 x (6n +8)

Explanation:
4 x (3n + 3)
12n + 12
C.  2 x (6n + 8)
12n + 16

Write the fraction or mixed number as a percent.

Question 8.
\(\frac{17}{25}\)

Answer:
68%

Explanation:
(17/25) = (17/25 x 100)
(17 x 4)/(25 x 4)
(68/100)
(34/50)
68%

Question 9.
\(\frac{19}{20}\)

Answer:
95%

Explanation:
(19/20) = (19/20 x 100)
(19 x 5)/(20 x 5)
(95/100)
95%
Question 10.
6\(\frac{7}{8}\)

Answer:
6.875%

Explanation:
(7/8) = (7/8 x 100)
6 x (7/8) = 6 x (7/8 x 100)
(55/8)

Question 11.
\(\frac{3}{400}\)

Answer:
0.75%

Explanation:
(3/400) = (3/400 x 100)
(3/4) = 0.75%

Concepts, Skills, &Problem Solving
USING TOOLS
Use a net to find the surface area of the solid. Explain your reasoning. (See Exploration 2, p. 319.)

Question 12.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 222

Answer:
The surface area of the triangular pyramid = a+(1/2) x p x s

Explanation:
The surface area of the pyramid = area + (1/2) x p x s where p = perimeter of the base, s = slant height

Question 13.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 223

Answer:
The surface area of the triangular pyramid = a+(1/2) x p x s

Explanation:
The surface area of the pyramid = area + (1/2) x p x s where p = perimeter of the base, s = slant height

Question 14.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 224

Answer:
The surface area of the triangular pyramid = a+(1/2) x p x s

Explanation:
The surface area of the pyramid = area + (1/2) x p x s where p = perimeter of the base, s = slant height

FINDING SURFACE AREA
Find the surface area of the pyramid.

Question 15.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 225

Answer:
The surface area of the  pyramid = 27 in

Explanation:
The surface area of the triangular pyramid = area of the faces + area of the base
area of the face1 = 5 sq. in
area of the face2 = 5 sq. in
area of the face3  = 5 sq. in
area of the face4 = 5 sq. in
area of the base = 7 sq. in
surface area = 27 sq. in

Question 16.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 226

Answer:
The surface area of the  pyramid = 51 .6 sq. yd

Explanation:
The surface area of the triangular pyramid = area of the faces + area of the base
area of the face1 = 11.4 sq. yd
area of the face2 = 11.4 sq. yd
area of the face3  = 11.4 sq. yd
area of the face4 = 11.4 sq. yd
area of the base = 6 sq. yd
surface area = 51.6 sq. yd

Question 17.
Big Ideas Math Answers Grade 6 Chapter 7 Area, Surface Area, and Volume 227

Answer:
The surface area of the  pyramid = 80 sq. cm

Explanation:
The surface area of the triangular pyramid = area of the faces + area of the base
area of the face1 = 17 sq. cm
area of the face2 = 17 sq. cm
area of the face3  = 17 sq. cm
area of the face4 = 17 sq. cm
area of the base = 12 sq. cm
surface area = 80 sq. cm

Question 18.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 228

Answer:
The surface area of the  pyramid = 50.8 sq. ft

Explanation:
The surface area of the triangular pyramid = area of the faces + area of the base
area of the face1 = 10.4 sq. ft
area of the face2 = 10.4 sq. ft
area of the face3  = 9 sq. ft
area of the face4 = 9 sq. ft
area of the base = 12 sq. ft
surface area = 50.8 sq. ft

Question 19.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 229

Answer:
The surface area of the  pyramid = 49.8 sq. in

Explanation:
The surface area of the triangular pyramid = area of the faces + area of the base
area of the face1 = 6.9 sq. in
area of the face2 = 6.9 sq. in
area of the face3  = 14 sq. in
area of the face4 = 14 sq. in
area of the base = 8 sq. in
surface area = 49.8 sq. in

Question 20.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 230

Answer:
The surface area of the  pyramid = 27 sq. m

Explanation:
The surface area of the triangular pyramid = area of the faces + area of the base
area of the face1 = 8 sq. m
area of the face2 = 8 sq. m
area of the face3  = 3.5 sq. m
area of the face4 = 3.5 sq. m
area of the base = 4 sq. m
surface area = 27 sq. m

Question 21.
MODELING REAL LIFE
A paperweight is shaped like a triangular pyramid. Find the surface area of the paperweight.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 231

Answer:
The surface area of the  pyramid = 9.8 sq. in

Explanation:
The surface area of the triangular pyramid = area of the faces + area of the base
area of the face1 = 2.2 sq. in
area of the face2 = 2.2 sq. in
area of the face3  = 1.7 sq. in
area of the face4 = 1.7 sq. in
area of the base = 2 sq. in
surface area = 9.8 sq. in

Question 22.
PROBLEM SOLVING
The entrance to the Louvre Museum in Paris, France, is a square pyramid. The side length of the base is 116 feet, and the height of one of the triangular faces is 91.7 feet. Find the surface area of the four triangular faces of the entrance to the LouvreMuseum.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 232

Answer:
The surface area of the  pyramid = 48.2 sq. ft

Explanation:
The surface area of the triangular pyramid = area of the faces + area of the base
area of the face1 = 91.7 sq. ft
area of the face2 = 91.7 sq. ft
area of the face3  = 91.7 sq. ft
area of the face4 = 91.7 sq. ft
area of the base = 116 sq. ft
surface area = 482.8 sq. ft

Question 23.
MODELING REAL LIFE
A silicon wafer is textured to minimize light reflection. This results in a surface made up of square pyramids. Each triangular face of one of the pyramids has a base of 5 micrometers and a height of 5.6 micrometers.Find the surface area of the pyramid, including the base.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 233

Answer:
Area = 42 sq. micrometers

Explanation:,
The surface area of the pyramid = area + (1/2) x p x s where p = perimeter of the base, s = slant height
area = 28 +(1/2) x 5 x 5.6
area = 28+ (28/2)
area = 28+ 14
area = 42 sq. micrometers

Question 24.
REASONING
A hanging light cover made of glass is shaped like a square pyramid. The cover does not have a bottom. One square foot of the glass weighs 2.45 pounds. The chain can support 35 pounds. Will the chain support the light cover? Explain.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 234

Answer:
Yes the chain support the light cover

Explanation:
The surface area of the pyramid = area + (1/2) x p x s where p = perimeter of the base, s = slant height
area = 4+(1/2) x 2  x 2
area = 4+ 4
area = 8
area = 8 sq. ft

Question 25.
GEOMETRY
The surface area of the square pyramid shown is 84 square inches. What is the value of x?
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 235

Answer:
The value of x = 14 in

Explanation:
The surface area of the square pyramid = length x breadth
area = l x b
84 =6x
x =(84/6)
x =14 in

Question 26.
STRUCTURE
In the diagram of the base of the hexagonal pyramid, all the triangles are the same. Find the surface area of the hexagonal pyramid.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 236

Answer:
The surface area of the hexagonal pyramid = 478.32 cm

Explanation:
The surface area of the hexagonal pyramid = 3ab +3bs
area = 3 x 8 x 6.93 +3 x 8 x 13 where a = 8,b =8, s = 13
area = 166.32+312
area = 478.32 sq. cm

Question 27.
CRITICAL THINKING
Can you form a square pyramid using a square with side lengths of 14 inches and four of the triangles shown? Explain your reasoning.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 237

Answer:
yes
Explanation:
given that square has side lengths of 14 inches and four of the triangles.
so we can form the square pyramid

Lesson 7.7 Volumes of Rectangular Prisms

Recall that the volume of a three-dimensional figureis a measure of the amount of space that it occupies. Volume is measured in cubic units.

EXPLORATION 1

Using a Unit Cube
Work with a partner. A unit cube is a cube with an edge length of 1 unit. The parallel edges of the unit cube have been divided into 2, 3, and 4 equal parts to create smaller rectangular prisms that are identical.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 238
a. The volumes of the identical prisms are equal. What else can you determine about the volumes of the prisms? Explain.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 239

Answer:
The volume of the prism = 1 unit

Explanation:
The volume of the prism = Bh
where b = area of the base
volume = 1 x 1
volume = 1
b. Use the identical prisms in part(a) to find the volume of the prism below. Explain your reasoning.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 240

Answer:
The volume of the prism = 4.3125 cu. unit

Explanation:
The volume of the prism = Bh
where b = area of the base
volume = (3/4) x (2/3)
volume = 0.75 x 5.75
volume = 4.3125 cu. units

c. How can you use a unit cube to find the volume of the prism below? Explain.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 241

Answer:
The volume of the prism = 0.375 cu. m

Explanation:
The volume of the prism = Bh
where b = area of the base
volume = (1/2) x (3/4)
volume = 0.5x 0.75
volume = 0.375 cu. m

Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 242
d. Do the formulas V = Bh and V = ℓwh work for rectangular prisms with fractional edge lengths? Give examples to support your answer.

7.7 Lesson

Key Idea
Volume of a Rectangular Prism
Words
The volume V of a rectangular prism is the product of the area of the base and the height of the prism.
Algebra
V = Bh or V = lwh
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 243
When a rectangular prism is a cube with an edge length of s, you can also use the formula V = s3 to find the volume V of the cube.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 243.1

Try It
Find the volume of the prism.

Question 1.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 244

Answer:
The volume of the prism = 0.6665 cu. ft

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
volume = (1.333) x (0.5)
volume = 1.33 x 0.5
volume = 0.6665 cu. ft

Question 2.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 245

Answer:
The volume of the prism = 0.6665 cu. ft

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
volume = (1.333) x (0.5)
volume = 1.33 x 0.5
volume = 0.6665 cu. ft

Try It
Find the missing dimension of the prism.

Question 3.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 246

Answer:
The missing dimension of the prism = 6 in

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
volume = b x l x h
volume = 6x 6 x  2
volume = 72 in
so length = 6 in

Question 4.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 247

Answer:
The width of the prism = 12.5 cm

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
volume = 5 x(1/2) x 12.5 x20
volume = (11/2)x 12.5 x  20
volume = 1375 cm
so width = 12.5 cm

Self-Assessment for Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 5.
CRITICAL THINKING
Explain how volume and surface area are different.

Answer:
Volume grows exponentially and the surface area grows  with the volume
the surface area grows with the rate of volume

Question 6.
FINDING A MISSING DIMENSION
The base of a rectangular prism has an area of 24 square millimeters. The volume of the prism is 144 cubic millimeters. Make a sketch of the prism. Then find the height of the prism.

Answer:
The height of the prism = 6 millimeters

Explanation:
The volume of the rectangular prism = Bh
where b = base area and h= height
so volume = 144 cubic millimeters given
B = 24
volume = Bh
144 = 24h
h = (144/24)
h = 6 mm

FINDING VOLUME
Find the volume of the prism.

Question 7.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 278

Answer:
The volume of the prism = 0.2343 cu. m

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
volume = (3/4) x(1/2) x (5/8)
volume = 0.75 x 0.5x 0.625
volume = 0.2343 cu. m

Question 8.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 279

Answer:
The volume of the prism = 0.343 cu. in

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
volume = (7/10) x(7/10) x (7/10)
volume = 0.7 x 0.7 x 0.7
volume = 0.343 cu. in

When finding volumes, you may need to convert cubic units. The diagrams at the left show that there are 27 cubic feet per cubic yard.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 280
1 yd3 = (1 yd)(1 yd)(1 yd) = (3 ft)(3 ft)(3 ft) = 27 ft3
You can use a similar procedure to convert other cubic units.

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 9.
DIG DEEPER!
The shark cage is in the shape of a rectangular prism and has a volume of 315 cubic feet. Find a set of reasonable dimensions for the base of the cage. Justify your answer.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 281

Answer:
The base  of the prism = 4.906 ft

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
314 = (8) x(8 ) x h
314 = 64h
h = (314/64)
h = 4.906 ft

Question 10.
The hot tub is in the shape of a rectangular prism. How many pounds of water can the hot tub hold? One cubic foot of water weighs about 62.4 pounds.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 282

Answer:
The hot tub can hold = 312 pounds

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
hot tub = (2) x(2) x 1.25
hot tub = 4 x 1.25
hottub = 5
hot tub = 5
5 x 62.4 = 312 pounds

Volumes of Rectangular Prisms Homework & Practice 7.7

Review & Refresh

Find the surface area of the pyramid.

Question 1.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 283

Answer:
The surface area of the pyramid = 220.5 sq. ft

Explanation:
The surface area of the pyramid = area + (1/2) x p x s
where area = l x w
surface area =21 x (1/2) x 7 x3
surface area = 21x 10.5
surface area = 220.5 sq. ft

Question 2.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 284

Answer:
The surface area of the pyramid = 364.5 sq. m

Explanation:
The surface area of the pyramid = area + (1/2) x p x s
where area = l x w
surface area =27 x (1/2) x 4.5 x6
surface area = 27 x (27/2)=13.5
surface area = 364.5 sq. m

Question 3.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 285

Answer:
The surface area of the pyramid = 20,760 sq. yd

Explanation:
The surface area of the pyramid = area + (1/2) x p x s
where area = l x w
surface area =346 x (1/2) x 12 x 20
surface area = 346 x (120/2)=60
surface area = 20,760 sq. yd

Write the phrase as an expression. Then evaluate the expression when x = 2 and y = 12.

Question 4.
8 more than a number x

Answer:
Yes
Explanation:
8 is more than 2
where x = 2 given

Question 5.
the difference of a number y and 9

Answer:
The difference of a number y and 9 = 3

Explanation:
difference = 12 – 9
diff = 3
where y = 12 given

Concepts, Skills, & Problem Solving
STRUCTURE
The unit cube is divided into identical rectangular prisms. What is the volume of one of the identical prisms? (See Exploration 1, p. 325.)

Question 6.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 286

Answer:
(2/2),(2/4),(4/2)

Explanation:
In the above figure the base = (2/2) units
base = (2/2) units
height = (4/2) units

Question 7.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 287

Answer:
(3/3),(3/2),(2/3)

Explanation:
In the above figure the base = (3/3) units
base = (3/2) units
height = (2/3) units

Question 8.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 288

Answer:
(5/5),(5/3),(3/5)

Explanation:
In the above figure the base = (5/5) units
base = (5/3) units
height = (3/5) units

FINDING VOLUME
Find the volume of the prism.

Question 9.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 289

Answer:
The volume of the prism = 0.297 Cu. in

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
volume = (0.66) x(0.6) x (0.75)
volume = 0.297 Cu. in

Question 10.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 290

Answer:
The volume of the prism = 1.3125 Cu. cm

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
volume = (7/4) x(3/2) x (1/2)
volume = 1.75 x 1.5 x 0.5
volume = 1.3125 Cu. cm

Question 11.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 291

Answer:
The volume of the prism = 0.064 Cu. ft

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
volume = (2/5) x(2/5) x (2/5)
volume = 0.4 x 0.4 x 0.4
volume = 0.064 Cu. ft

Question 12.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 292

Answer:
The volume of the prism =0.75 Cu. m

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
volume = (5/8) x(3/4) x (2)
volume = 0.625 x 0.6 x 2
volume = 0.75 Cu. m

Question 13.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 293

Answer:
The volume of the prism =3.111255 Cu. cm

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
volume = (5/3) x(5/6) x (9/4)
volume = 1.66 x 0.833 x 2.25
volume = 3.111255 Cu. cm

Question 14.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 294

Answer:
The volume of the prism = 12.425 Cu. m

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
volume = (14/5) x(10/7) x (25/8)
volume = 2.8 x 1.42 x 3.125
volume = 12.425 Cu. m

FINDING A MISSING DIMENSION
Find the missing dimension of the prism.

Question 15.
Volume = 1620 cm3
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 295

Answer:
The missing dimension of the prism = 20 cm

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
1620 = (9) x(9) x h
1620 = 81 h
h = (1620/8)
h = 8
Question 16.
Volume = 220.5 cm3
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 296

Answer:
The missing dimension of the prism = 4.5 cm

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
220.5 = (7) x(7) x w
220.5 = 49 w
w = (220.5/49)
w = 4.5 cm

Question 17.
Volume = 532 in3
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 297

Answer:
The missing dimension of the prism = 16 in

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
532 = (7/4) x(19) x w
532 = 33.25
h = (532/33.25)
h = 16 in

Question 18.
MODELING REAL LIFE
An FBI agent orders a block of ballistics gel. The gel weighs 54 pounds per cubic foot. What is the weight of the block of gel?
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 298

Answer:
The volume of the prism = 720 in

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
volume = (6) x(20) x 6
volume = 720 in
Question 19.
MODELING REAL LIFE
a. Estimate the amount of casserole left in the dish.
b. Will the casserole fit in the storage container? Explain your reasoning.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 299

Answer:
a : The amount of casserole left in the dish = 396 in

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
volume = (2.75) x(12) x 12
volume = 396

b : The casserole will not fit in the container

Explanation:
The length of the container is less than the casserole

Question 20.
GEOMETRY
How many \(\frac{3}{4}\)-centimeter cubes do you need to create a cube with an edge length of 12 centimeters?

Answer:
16 cubes

Explanation:
16 cubes are used to create a cube with an edge length of 12 centimeters
in the above-given question (3/4) = 0.75
0.75 x 16 = 12

Question 21.
REASONING
How many one-millimeter cubes do you need to fill a cube that has an edge length of 1 centimeter? How can this result help you convert a volume from cubic millimeters to cubic centimeters? from cubic centimeters to cubic millimeters?
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 300

Answer:
10 mm cubes are needed to fill a cube that has an edge length of 1 cm

Explanation:
1 mm =0.1 cm
0.1 x 10 = 1 cm
1 cubic mm = 0.001 cubic cm
1 cubic cm = 1000 cubic mm

Question 22.
LOGIC
The container is partially filled with unit cubes. How many unit cubes fit in the container? Explain your reasoning.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 301

Answer:
6 cubes fit in the container

Explanation:
In the above diagram,6 units are filled with color
so 6 unit cubes fit in the container.

Question 23.
PROBLEM SOLVING
The area of the shaded face is 96 square centimeters. What is the volume of the rectangular prism?

Answer:
The volume of the rectangular prism = 4 x 3 x 8

Explanation:
The volume of the rectangular prism = length x width x height
volume = 4 x 3 x 8

Question 24.
DIG DEEPER!
Is the combined volume of a 4-foot cube and a 6-foot cube equal to the volume of a 10-foot cube? Use a diagram to justify your answer.

Question 25.
PROJECT
You have 1400 square feet of boards to use for a new tree house.
a. Design a tree house that has a volume of at least 250 cubic feet. Include sketches of your tree house.
b. Are your dimensions reasonable? Explain your reasoning.

Area, Surface Area, and Volume Connecting Concepts

Using the Problem-Solving Plan

Question 1.
A sports complex has two swimming pools that are shaped like rectangular prisms. The amount of water in the smaller pool is what percent of the amount of water in the larger pool?
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 302
Understand the problem.
You know the shape and the dimensions of the two swimming pools. You are asked to find the amount of water in the smaller pool as a percent of the amount of water in the larger pool.
Make a plan.
First, find the volume of each pool. Then represent the amount of water in the smaller pool as a fraction of the amount of water in the larger pool. Find an equivalent fraction whose denominator is 100 to find the percent.

Answer:
28% of water in the 1st pool is greater than that of the smaller pool

Explanation:
volume of the first pool = 25 x 3 x 50=3750
volume of the second pool = 25 x 21 x 2= 1050
1050 : 3750 = 0.28
0.28 = 28 %
Solve and Check
Use the plan to solve the problem. Then check your solution.

Question 2.
Use a graph to represent the relationship between the surface area S(in square meters) and the height h(in meters) of the triangular prism. Then find the height when the surface area is 260 square meters.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 303

Answer:
The height of the triangular prism = 43.33 meters

Explanation:
The surface area  of the triangular prism = (1/2) x b x h
area = (1/2) x 12h
260 = 6h
h =(260/6)
h = 43.33 m

Question 3.
A toy company sells two different toy chests. The toy chests have different dimensions, but the same volume. What is the width w of Toy Chest 2?
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 304

Answer:
The width of the toy chest2 = 384 in

Explanation:
In the above figure the toy chest 2 has length = 24 in and volume = 16 in
width = 24 x 16
width = 384 in

Performance Task
Maximizing the Volumes of Boxes

At the beginning of this chapter, you watched a STEAM Video called “Packaging Design.” You are now ready to complete the performance task related to this video, available at BigIdeasMath.com. Be sure to use the problem-solving plan as you work through the performance task.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 305

Area, Surface Area, and Volume Chapter Review

Review Vocabulary

Write the definition and give an example of each vocabulary term.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 306

Answer:
polygon = a polygon is a closed figure in a plane that is made up of 3 or more line segments that intersect only at their endpoints.
composite figure = composite figure is made up of triangles, squares, rectangles and other two-dimensional figures.
kite = kite is a quadrilateral that has two pairs of adjacent sides with the same length and opposite sides with different lengths.

Graphic Organizers
You can use a Four Square to organize information about a concept. Each of the four squares can be a category, such as definition, vocabulary, example, non-example, words, algebra, table, numbers, visual, graph, or equation. Here is an example of a Four Square for the area of a parallelogram.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 307
Choose and complete a graphic organizer to help you study the concept.

  1. area of a triangle
  2. area of a trapezoid
  3. area of a composite figure
  4. polyhedron
  5. surface area of a prism
  6. surface area of a pyramid
  7. volume of a rectangular prism

Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 308

Chapter Self-Assessment

As you complete the exercises, use the scale below to rate your understanding of the success criteria in your journal.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 309

7.1 Areas of Parallelograms (pp. 285–290)

Find the area of the parallelogram.

Question 1.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 310

Answer:
area = 500 yd

Explanation:
area of the parallelogram = b x h
area = 25 x 20
area = 500 yd

Question 2.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 311

Answer:
area = 242 mm

Explanation:
area of the parallelogram = b x h
area = 22 x 11
area = 242 mm

Question 3.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 312

Answer:
area = 45 cm

Explanation:
area of the parallelogram = b x h
area = 9 x 5
area = 45 cm

Question 4.
Find the area (in square inches) of the parallelogram.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 313

Answer:
area = 72 square in

Explanation:
area of the parallelogram = b x h
area = 2 x 3
area = 6 ft
1 feet = 12 inches
area = 72 square inches

Question 5.
The billboard shown is in the shape of a parallelogram with a base of 48 feet. What is the height of the billboard?
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 314

Answer:
The height of the billboard = 14 ft

Explanation:
The area of the parallelogram = b x h
672 = 48 h
h = (672/48)
h = 14 ft

Question 6.
The freeway noise barrier shown is made of identical parallelogram-shaped sections. The area of each section is 7.5 square meters, and the height of the barrier is 5 meters. How many meters wide is each section of the noise barrier?
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 315

Answer:
Each section of the noise barrier is 1.5 m

Explanation:
The area of the parallelogram = b x h
area = 1.5 x5
area = 7.5
so b = 1.5 m

Question 7.
Draw a parallelogram that has an area between 58 and 60 square centimeters.

Answer:
59 square centimeters

Explanation:

7.2 Areas of Triangles (pp. 291–296)

Find the area of the triangle.

Question 8.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 316

Answer:
The area of the triangle = 80 sq. km

Explanation:
The area of the triangle = half the product of the base and the product of the height
area = (1/2) x 16 x 10
area = (1/2) x 160
area = 80 sq. km

Question 9.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 317

Answer:
The area of the triangle = 175 sq. cm

Explanation:
The area of the triangle = half the product of the base and the product of the height
area = (1/2) x 14 x 25
area = (1/2) x 350
area = 175 sq. cm

Find the missing dimension of the triangle.

Question 10.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 318

Answer:
base = 5 mi

Explanation:
The area of the tringle = b x h
given that h = 7 mi and area = 35 mi
base = 5 mi

Question 11.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 319

Answer:
height = 5 cm

Explanation:
The area of the tringle = b x h
given that b = 4 cm and area = 5 mi
height = 5 cm

Find the area of the figure.

Question 12.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 320

Answer:
The area of the trapezoid = 112.5 sq. yd

Explanation:
The area of the trapezoid = one half the product of its height h and the sum of its bases b1 and b2.
area = (1/2) x h x( b1 + b2)
area =(1/2) x h (12 + 3). Given that b1 = 12 and b2 = 3
area = (1/2) x 15(15) given that h = 15 yd
area = (1/2) x 225
area = 112.5 sq. yd

Question 13.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 321

Answer:
The area of the trapezoid = 4 sq. mm

Explanation:
The area of the trapezoid = one half the product of its height h and the sum of its bases b1 and b2.
area = (1/2) x h x( b1 + b2)
area =(1/2) x h (8 + 8). Given that b1 = 8 and b2 = 8
area = (1/2) x 2(16) given that h = 2 yd
area = (1/2) x 8
area = 4 sq. mm

Question 14.
Draw a composite figure that has an area of less than 35 square inches.

Answer:
The area of the triangle = b x h
area = 6 x 4
area = 24 square inches

Explanation:

Question 15.
Te triangle-shaped entrance to the cavern is 2\([\frac{1}{2}/latex] feet tall and 4 feet wide. What is the area of the entrance?
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 322

Answer:
The area of the entrance = 10

Explanation:
2 x(1/2) = 5/2 = 2.5
2.5 x 4 = 10
7.3 Areas of Trapezoids and Kites (pp. 297 – 304)

Question 16.
Use decomposition to find the area of the kite.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 323

Answer:
The area of the kite = 255 sq. in

Explanation:
The area of the trapezoid = (1/2) x 10 x 9 + 10 x 21
area = (1/2) x 90 +210
area = 45 + 210
255 sq. in
Find the area of the trapezoid.

Question 17.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 324

Answer:
The area of the trapezoid = 105 sq. m

Explanation:
The area of the trapezoid = one half the product of its height h and the sum of its bases b1 and b2.
area = (1/2) x h x( b1 + b2)
area =(1/2) x h (15 + 6). Given that b1 = 15 and b2 = 6
area = (1/2) x 10(21) given that h = 10 in
area = (1/2) x 210
area = 105 sq. m

Question 18.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 325

Answer:
The area of the trapezoid = 6 sq. in

Explanation:
The area of the trapezoid = one half the product of its height h and the sum of its bases b1 and b2.
area = (1/2) x h x( b1 + b2)
area =(1/2) x h (1.5 + 2.5). Given that b1 = 1(1/2) = 1.5 and b2 = 2(1/2) = 2.5
area = (1/2) x 3(4) given that h = 10 in
area = (1/2) x 12
area = 6 sq. in

Question 19.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 326

Answer:
The area of the trapezoid =49 sq. mi

Explanation:
The area of the trapezoid = one half the product of its height h and the sum of its bases b1 and b2.
area = (1/2) x h x( b1 + b2)
area =(1/2) x h (6 + 8). Given that b1 = 6 and b2 = 8
area = (1/2) x 7(14) given that h = 7 mi
area = (1/2) x 98
area = 49 sq. mi

Find the area of the figure.

Question 20.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 327

Answer:
The area of the trapezoid = 56 sq. ft

Explanation:
The area of the trapezoid = one half the product of its height h and the sum of its bases b1 and b2.
area = (1/2) x h x( b1 + b2)
area =(1/2) x h (6 + 7). Given that b1 = 6 and b2 = 7
area = (1/2) x 8(14) given that h = 8 ft
area = (1/2) x 112
area = 56 sq ft

Question 21.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 328

Answer:
The area of the trapezoid = 48 sq. cm

Explanation:
The area of the trapezoid = one half the product of its height h and the sum of its bases b1 and b2.
area = (1/2) x h x( b1 + b2)
area =(1/2) x h (4 + 8). Given that b1 = 4 and b2 = 8
area = (1/2) x 8(12) given that h = 8 ft
area = (1/2) x 96
area = 48 sq. cm

Question 22.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 329

Answer:
The area of the trapezoid = 40 sq. in

Explanation:
The area of the trapezoid = one half the product of its height h and the sum of its bases b1 and b2.
area = (1/2) x h x( b1 + b2)
area =(1/2) x h (6 +10). Given that b1 = 6 and b2 = 10
area = (1/2) x 5(16) given that h = 80
area = (1/2) x 80
area = 40 sq. in

Question 23.
You are creating a design for the side of the soapbox car. How much area do you have for the design?
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 330

Answer:
The area of the trapezoid =240 sq. in

Explanation:
The area of the trapezoid = one half the product of its height h and the sum of its bases b1 and b2.
area = (1/2) x h x( b1 + b2)
area =(1/2) x h (6 +14). Given that b1 = 6 and b2 = 14
area = (1/2) x 24(20) given that h = 24
area = (1/2) x 480
area = 240 sq. in

Question 24.
Find the area (in square centimeters) of a trapezoid with a height of 2 meters and base lengths of 3 meters and 5 meters.

Answer:
The area of the trapezoid =240 sq. in

Explanation:
The area of the trapezoid = one half the product of its height h and the sum of its bases b1 and b2.
area = (1/2) x h x( b1 + b2)
area =(1/2) x h (3 +5). Given that b1 = 3 and b2 = 5
area = (1/2) x 2(8) given that h = 2
area = (1/2) x 16
area = 8 sq. m
1 meter = 100 cm
area = 8 x 100 = 800 sq. cm

7.4 Three-Dimensional Figures (pp. 305–310)

Find the numbers of faces, edges, and vertices of the solid.

Question 25.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 331

Answer:
faces = 6
edges = 12
vertices =7

Explanation:
The number of faces = 6
The number of edges = 12
The number of vertices =7

Question 26.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 332

Answer:
faces = 5
edges = 10
vertices =6

Explanation:
The number of faces = 5
The number of edges = 10
The number of vertices =6

Question 27.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 333

Answer:
faces = 9
edges = 20
vertices = 12

Explanation:
The number of faces = 9
The number of edges = 20
The number of vertices =12

Draw the solid.

Question 28.
square pyramid

Answer:

Question 29.
hexagonal prism

Draw the front, side, and top views of the solid.

Question 30.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 334

Answer:
front = 1
side =2
top = 1

Explanation:

Question 31.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 335

Answer:
front = 4
side =2
top = 2

Explanation:

Question 32.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 336

Answer:
front = 1
side = 1
top = 1

7.5 Surface Areas of Prisms (pp. 311–318)

Find the surface area of the prism.

Question 33.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 337

Answer:
The surface area of the prism = 100 sq. in

Explanation:
The surface area of the rectangular prism = Area of the top + area of the bottom +area of front + area of back + area of side + area of a side
surface area = 7 x 2 + 7 x 2 + 4x 7+ 4 x 7 + 4 x 2 + 4 x 2
surface area = 14 +14+ 28 + 28 +8+8
surface area = 100 sq. in

Question 34.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 338

Answer:
The surface area of the prism = 243 sq. m

Explanation:
The surface area of the rectangular prism = Area of the top + area of the bottom +area of front + area of back + area of side + area of a side
surface area = 6 x 9 + 6 x 9 + 9 x 4.5+ 9 x 4.5 + 6 x 4.5 + 6 x 4.5
surface area = 54 +54+ 40.5 + 40.5 +27+ 27
surface area = 243 sq. m

Question 35.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 339

Answer:
The surface area of the prism = 590 cm

Explanation:
The surface area of the rectangular prism = Area of the top + area of the bottom +area of front + area of back + area of side + area of a side
surface area = 8 x 7 + 8 x 7 + 15 x 8+ 15 x 8 + 17 x 7 + 17 x 7
surface area = 56 +56+ 120 + 120 +119+ 119
surface area = 590 sq. cm

Question 36.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 340

Answer:
The surface area of the triangular prism = 49 sq. ft

Explanation:
The surface area of the triangular prism = 2 b + p s
surface area = 2 x 5 +6 x 6.5
surface area = 10 + 39
surface area = 49 sq. ft

Question 37.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 341

Answer:
The volume of the prism = 1,17,649 cu. yd

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
volume = (7) x(7) x (7)
volume = 49 x 49 x 49
volume = 1,17,649 cu. yd

Question 38.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 342

Answer:
The volume of the prism = 614.125 cu. mi

Explanation:
The volume of the prism = Bh
where b = l x w
where b = area of the base
volume = (17/2) x(17/2) x (17/2)
volume = 8.5 x 8.5 x 8.5
volume = 614.125 cu. mi

Question 39.
One quart of water-resistant paint covers 75 square feet. A swimming pool is in the shape of a rectangular prism with a length of 20 feet, a width of 10 feet, and a height of 5 feet. How many quarts should you buy to paint the swimming pool with two coats of paint?

Answer:
The volume of rectangular prism = 1000 cu. ft

Explanation:
The volume of the rectangular prism = b ase x height
volume = b x h where b = l x w
volume = 20 x 10 x 5
volume = 1000 cu. ft
7.6 Surface Areas of Pyramids (pp. 319–324)

Find the surface area of the pyramid.

Question 40.
An

Question 41.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 344

Answer:
The surface area of the pyramid = 95.2 m

Explanation:
The surface area of the square pymarid = area + (1/2) x ps
surface area = 55.2 + (1/2) x 10 x 8
surface area = 55.2 + 40
surface area = 95.2 m

Question 42.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 345

Answer:
The surface area of the pyramid = 88.1 cm

Explanation:
The surface area of the square pymarid = area + (1/2) x ps
surface area = 65.8 + (1/2) x 7 x 9.4
surface area = 55.2 + 32.9
surface area = 88.1 cm

Question 43.
You make a square pyramid for a school project. Find the surface area of the pyramid.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 346

Answer:
The surface area of the pyramid = 41.25

Explanation:
The surface area of the square pyramid = area + (1/2) x ps
surface area = 27.5 + (1/2) x 5.5 x 5
surface area = 27.5 + 13.75
surface area = 41.25 in

7.7 Volumes of Rectangular Prisms (pp. 325–330)

Find volumes and missing dimensions of rectangular prisms.

Question 44.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 347

Answer:
The volume of rectangular prism = 4.875 ft

Explanation:
The volume of the rectangular prism = b ase x height
volume = b x h where b = l x w
volume = (5/2) x (3/2) x (4/3)
volume = 2.5 x 1.5 x 1.33
volume = 4.875 ft

Question 45.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 348

Answer:
The volume of rectangular prism = 0.605 cm

Explanation:
The volume of the rectangular prism = b ase x height
volume = b x h where b = l x w
volume = (1/2) x (2/3) x (11/6)
volume = 0.5 x 0.66 x 1.83
volume = 0.605 cm

Question 46.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 349

Answer:
The volume of rectangular prism = 0.05272 cu. in

Explanation:
The volume of the rectangular prism = b ase x height
volume = b x h where b = l x w
volume = (3/8) x (3/8) x (3/8)
volume = 0.375 x 0.375 x 0.375
volume = 0.05273 cu. in

Question 47.
The prism has a volume of 150 cubic feet. Find the length of the prism.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 350

Answer:
The length of rectangular prism = 7 ft

Explanation:
The volume of the rectangular prism = base x height
volume = b x h where b = l x w
volume = (5) x (4) x (7)
volume = 150
length = 7 ft

Question 48.
How many cubic inches of tissues can the box hold?
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 351

Answer:
The length of rectangular prism = 162 . 5 in

Explanation:
The volume of the rectangular prism = b ase x height
volume = b x h where b = l x w
volume = (5) x (5) x (6.5)
volume = 162.5 in

Question 49.
Draw a rectangular prism that has a volume less than 1 cubic inch.

Area, Surface Area, and Volume Practice Test

7 Practice Test

Find the area of the figure.

Question 1.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 352

Answer:
The area of the parallelogram = 13000 cm

Explanation:
The area of the parallelogram = the product of the base and the product of the height
area = 130 x 100
area = 13000 cm

Question 2.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 353

Answer:
The area of the triangle = 154 in

Explanation:
The area of the triangle = (1/2 ) x b x h
area = (1/2) x 14 x 22
area = (1/2) x 308
area = 154 in

Question 3.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 354

Find the surface area of the solid.

Question 4.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 355

Answer:
340  ft

Explanation:
Surface area = area of the bottom + area of the front +area of the back +area of a side + area of a side
surface area = 12 x 7 = 84+ (1/2) x 7 x 5 = 17.5+ (1/2) x  7 x 5 = 17.5+  13 x 5 = 65 + 12 x 13  = 156
bottom = 12 x 7 , front = (1/2) x 7 x 5, back = (1/2) x 7 x 5, side = 13 x 5 , side = 12 x 13
surface  area = 84 + 17.5 +17.5 + 65+156
area = 340 ft

Question 5.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 356

Answer:
The volume of the prism =1567.5 m

Explanation:
The volume of the prism = Bh where b = l x w
where b = area of the base
volume = (9.5) x(11) x (15)
volume = 1567.5 m

Find the volume of the prism.

Question 6.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 357

Answer:
The volume of the prism = 3.5 cm

Explanation:
The volume of the prism = b x h
volume = (3/2) x (7/3)
volume = 1.5 x 2.33
volume = 3.5 cm

Question 7.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 358

Answer:
The volume of the prism = 0.64 yd

Explanation:
The volume of the prism = b x h
volume = (4/5) x (4/5)
volume = 0.8 x 0.8
volume = 0.64 yd

Question 8.
Draw an octagonal prism.

Answer:

Question 9.
Find the numbers of faces, edges, and vertices of the solid.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 359

Answer:
faces = 8
edges = 26
vertices = 10

Explanation:
The number of faces = 8
the number of edges = 26
the number of vertices = 10

Question 10.
The area of a parallelogram is 156 square meters. What is the height of the parallelogram when the base is 13 meters?

Answer:
The base of the parallelogram = 12 square meters

Explanation:
The area of the parallelogram = b x h
area = 13 x  12
area = 156
so base = 12 square meters

Question 11.
A candle is shaped like a square pyramid. Find the surface area of the candle.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 360

Answer:
The surface area of the candle = 21.6 in

Explanation:
The area of the square pyramid = area +(1/2) x p x s
surface area = 14.4 +(1/2) x 4 x 3.6
surface area = 14.4 + 7.2
surface area = 21.6 in

Question 12.
You are wrapping the boxed DVD collection as a present. What is the least amount of wrapping paper needed to wrap the box?
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 361

Question 13.
A cube has an edge length of 4 inches. You double the edge lengths. How many times greater is the volume of the new cube?

Answer:
2 times greater

Explanation:
Given that the cube has an edge length of 4 inches
They said to double the cube
4 x 2 = 8
the volume of the new cube is 2 times greater than that of the old cube

Question 14.
The Pentagon in Arlington, Virginia, is the headquarters of the U.S. Department of Defense. The building’s center contains a pentagon-shaped courtyard with an area of about 5 acres. Find the land areas (in square feet) of the courtyard and the building.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 362

Area, Surface Area, and Volume Cumulative Practice

7 Cumulative Practice

Question 1.
A cruise ship is carrying a total of 4971 people. Each life boat can hold a maximum of 150 people. What is the minimum number of lifeboats needed to evacuate everyone on the cruise ship?
A. 33 lifeboats
B. 34 lifeboats
C. 54 lifeboats
D. 332 lifeboats

Answer:
option A is correct

Explanation:
150/33 = 4971 boats
In the above question, the lifeboat can hold a maximum of 150 people
The minimum no of lifeboats needed = 33

Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 363

Question 2.
Which number is equivalent to the expression?
3 . 42 + 6 ÷ 2
F. 27
G. 33
H. 51
I. 75

Answer:
option H is correct

Explanation:
3 . 16 + 3
48 + 3
51
Question 3.
What is the volume of the package?
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 364

Question 4.
A housing community started with 60 homes. In each of the following years, 8 more homes were built. Let represent the number of years that have passed since the first year, and let n represent the number of homes. Which equation describes the relationship between n and y?
F. n = 8y + 60
G. n = 68y
H. n = 60y + 8
I. n = 60 + 8 + y

Answer:
option I is the correct

Explanation:
n = 60 + 8 + y
where n = no of homes
y = number of years

Question 5.
What is the value of m that makes the equation true?
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 365

4m = 6

Answer:
the value of m = (6/4)

Explanation:
m = (6/4)
4m = 6
4 x (6/4) = 6
6 = 6

Question 6.
What is the surface area of the square pyramid?
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 366

Answer:
none of the options are correct

Explanation:
surface area of the pyramid = area +(1/2)x(5x 3)
area = 15+ (1/2) (15)
area = 15 + 7.5
area = 22.5 in
Question 7.
A wooden box has a length of 12 inches, a width of 6 inches, and a height of 8 inches.
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 367
Part A
Draw and label a rectangular prism with the dimensions of the wooden box.
Part B
What is the surface area, in square inches, of the wooden box? Show your work.
Part C
You have a two-fluid ounce sample of wood stain that covers 900 square inches. Is this enough to give the entire box two coats of stain? Show your work and explain your reasoning.

Answer:
The surface area of the rectangular prism = 432 in

Explanation:
The surface area of the rectangular prism = Area of the top + area of the bottom +area of front + area of back + area of side + area of a side
surface area = 12 x 6 + 12 x 6 + 6 x 8 + 6 x 8 + 12 x 8+ 12 x 8
surface area = 72+ 72 + 48 + 48 + 96 +96
surface area = 432 in
a :

Question 8.
On Saturday, you earned $35 mowing lawns. This was dollars more than you earned on Thursday. Which expression represents the amount, in dollars, you earned mowing lawns on Thursday?
F. 35x
G. x + 35
H. x – 35
I. 35 – x

Answer:
Option G is correct

Explanation:
x + 35 is correct

Question 9.
What is the area, in square yards, of the triangle?
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 368

Answer:
The area of the triangle = 20 yd

Explanation:
Area of the triangle = (1/2) x b x h
area = (1/2) x 5 x 8 where b = 5 and h = 8 given
area = (1/2) x 40
area = 20yd

Question 10.
Which expression is equivalent to [latex]\frac{12}{35}\) ?
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 369

Answer:
option b is correct

Explanation:
(2 x 6)/(7 x 5)
12 / 35
so option b is correct
Question 11.
The description below represents the area of which polygon?
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 370
F. rectangle
G. parallelogram
H. trapezoid
I. triangle

Answer:
option h is correct

Explanation:
The formula of trapezoid = 0ne half the product of its height and the sum of its bases.

Question 12.
What is the missing quantity in the double number line?
Big Ideas Math Answers 6th Grade Chapter 7 Area, Surface Area, and Volume 371
A. 25 ounces
B. 165 ounces
C. 525 ounces
D. 600 ounces

Answer:
Option b is correct

Explanation:
6 + 15 = 21
150 + 15 = 165
so option b is correct

Conclusion:

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Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5

Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5

Students of Elementary School can get the best study material to score good marks in the exams. Download Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 Pdf from this page. Improve your math skills Big Ideas Math Book K Grade Answer Key Chapter 1 Count and Write Numbers 0 to 5 and solve the problems. Students of Kth Grade can understand the concepts in-depth with the help of the Big Ideas Math Answer Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5.

Big Ideas Math Book Grade K Answer Key Chapter 1 Count and Write Numbers Numbers 0 to 5

Teachers and parents can understand the graph of the student’s performance by making them practice from Big Ideas Math Book Grade K Solution Key Chapter 1 Count and Write Numbers Numbers 0 to 5. All the answers seen on this page are prepared by the math experts. You can perform well in practice tests, Assessment tests, and chapter tests by using Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5. Make use of the below links and try to complete your homework with the time.

Vocabulary

Lesson: 1 Model and Count 1 and 2

Lesson: 2 Understand and Write 1 and 2

Lesson: 3 Model and Count 3 and 4

Lesson: 4 Understand and Write 3 and 4

Lesson: 5 Model and Count 5

Lesson: 6 Understand and Write 5

Lesson: 7 The Concept of Zero

Lesson: 8 Count and Order Numbers to 5

Chapter 1 – Count and Write Numbers 0 to 5

Count and Write Numbers Numbers 0 to 5 Vocabulary

Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 1
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 2

Answer:
The ducks are two.

Explanation:
In the above-given figure,
In the pond, there are 2 ducks.
we have to color the ducks.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1-1

Chapter 1 Vocabulary Cards

Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 3
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 4
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 5
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 6

Lesson 1.1 Model and Count 1 and 2

Explore and Grow

Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 7

Directions:

  • Place 1 counter on the blue sky. Decide which frame shows 1. Slide the counter to the frame.
  • Place 2 counters on the green grass. Decide which frame shows 2. Slide the counters to the frame.

Think and Grow

Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 8
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 8.1

Answer:
The objects are 2.

Explanation:
In the above-given figure,
The given objects are 2.
so we have to fill the color for 2 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.1-1
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 8.2

Answer:
The object is one.

Explanation:
In the above-given figure,
The given object is 1.
so we have to fill the color for 1 box.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.1-2

Directions:
Count the objects. Color the boxes to show how many

Apply and Grow: Practice

Question 1.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 9

Answer:
The objects are 2.

Explanation:
In the above-given figure,
The given objects are 2.
so we have to fill the color for 2 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.1-3
Question 2.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 10

Answer:
The object is one.

Explanation:
In the above-given figure,
The given object is 1.
so we have to fill the color for 1 box.

Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.1-4

Question 3.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 11

Answer:
The object is one.

Explanation:
In the above-given figure,
The given object is 1.
so we have to fill the color for 1 box.

Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.1-5

Question 4.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 12

Answer:
The objects are 2.

Explanation:
In the above-given figure,
The given objects are 2.
so we have to fill the color for 2 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.1-6

Directions:
1 – 4 Count the objects. Color the boxes to show how many.

Think and Grow: Modeling Real Life

Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 13

Answer:
a.The objects are 2.

Explanation:
In the above-given figure,
The given objects are 2.
so we have to fill the color for 2 boxes.

b.The object is one.

Explanation:
In the above-given figure,
The given object is 1.
so we have to fill the color for 1 box.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.1-7

Directions:
Count the objects in the picture. Color the boxes to show how many.

Model and Count 1 and 2 Homework & Practice 1.1

Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 14

Answer:
a.The object is one.

Explanation:
In the above-given figure,
The given object is 1.
so we have to fill the color for 1 box.

Answer:
b.The objects are 2.

Explanation:
In the above-given figure,
The given objects are 2.
so we have to fill the color for 2 boxes.

Question 1.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 15

Answer:
The object is one.

Explanation:
In the above-given figure,
The given object is 1.
so we have to fill the color for 1 box.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.1-9

Question 2.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 16

Answer:
The objects are 2.

Explanation:
In the above-given figure,
The given objects are 2.
so we have to fill the color for 2 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.1-10
Question 3.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 17

Answer:
The object is one.

Explanation:
In the above-given figure,
The given object is 1.
so we have to fill the color for 1 box.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.1-11

Question 4.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 18

Answer:
The objects are 2.

Explanation:
In the above-given figure,
The given objects are 2.
so we have to fill the color for 2 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.1-12

Question 5.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 19

Answer:
a.The object is one.

Explanation:
In the above-given figure,
The given object is 1.
so we have to fill the color for 1 box.

Answer:
b.The objects are 2.

Explanation:
In the above-given figure,
The given objects are 2.
so we have to fill the color for 2 boxes.

Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.1-13

Directions:
3 and 4. Count the objects. Color the boxes to show how many. 5 Count the objects in the picture. Color the boxes to show how many.

Lesson 1.2 Understand and Write 1 and 2

Explore and Grow

Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 20
Directions:
Use counters to show how many dogs and how many fish are in the story My Pets. Write how many dogs and how many fish are in the story.

Think and Grow

Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 21

Directions:
Count the objects. Say the number. Trace and write the number.

Apply and Grow: Practice

Question 1.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 22

Answer:
The object is one.

Explanation:
In the above-given figure,
there is 1 object.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.2-1

Question 2.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 23

Answer:
The objects are two.

Explanation:
In the above-given figure,
there are 2 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.2-2

Question 3.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 24

Answer:
The object is one.

Explanation:
In the above-given figure,
there is 1 object.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.2-3

Question 4.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 25

Answer:
The objects are two.

Explanation:
In the above-given figure,
there are 2 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.2-4

Question 5.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 26

Answer:
The objects are two.

Explanation:
In the above-given figure,
there are 2 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.2-5

Question 6.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 27

Answer:
The object is one.

Explanation:
In the above-given figure,
there is 1 object.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.2-6

Question 7.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 28

Answer:
The objects are two.

Explanation:
In the above-given figure,
there are 2 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.2-7

Question 8.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 29

Answer:
The object is one.

Explanation:
In the above-given figure,
there is 1 object.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.2-8

Directions:
1 – 8 Count the objects. Say the number. Write the number.

Think and Grow: Modeling Real Life

Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 30

Answer:
Lizards = one.
birds = two.
tortoise = two.
snakes = two.

Explanation:
In the above-given figure,
The lizards are one.
birds = two.
tortoise = two.
snakes = two.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.2-9

Directions: Count the objects in the picture. Say the number. Write the number.

Understand and Write 1 and 2 Homework & Practice 1.2

Question 1.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 31

Answer:
The objects are two.

Explanation:
In the above-given figure,
there are 2 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.2-10

Question 2.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 32

Answer:
The object is one.

Explanation:
In the above-given figure,
there is 1 object.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.2-11

Question 3.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 33

Answer:
The object is one.

Explanation:
In the above-given figure,
there is 1 object.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.2-12

Question 4.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 34

Answer:
The objects are two.

Explanation:
In the above-given figure,
there are 2 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.2-13

Directions:
1 – 4 Count the linking cubes. Say the number. Write the number.

Question 5.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 35

Answer:
The object is one.

Explanation:
In the above-given figure,
there is 1 object.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.2-14

Question 6.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 36

Answer:
The objects are two.

Explanation:
In the above-given figure,
there are 2 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.2-15

Question 7.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 37

Answer:
The objects are two.

Explanation:
In the above-given figure,
there are 2 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.2-16

Question 8.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 38

Answer:
The object is one.

Explanation:
In the above-given figure,
there is 1 object.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.2-17

Question 9.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 39

Answer:
snails = two.
tortoise = two.

Explanation:
In the above-given figure,
snails = two
tortoise = two.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.2-18

Directions:
5 – 8 Count the objects. Say the number. Write the number. 9 Count the objects in the picture. Say the number. Write the number.

Lesson 1.3 Model and Count 3 and 4

Explore and Grow
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 40
Directions:

  • Place 4 counters on top of the water. Decide which frame shows 4. Slide the counters to the frame.
  • Place 3 counters at the bottom of the bowl. Decide which frame shows 3. Slide the counters to the frame.

Think and Grow

Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 41

Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 42

Answer:
The objects are 4.

Explanation:
In the above-given figure,
The given objects are 4.
so we have to fill the color for 4 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.3-1

Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 43

Answer:
The objects are 3.

Explanation:
In the above-given figure,
The given objects are 3.
so we have to fill the color for 3 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.3-1

Directions:
Count the objects. Color the boxes to show how many.

Apply and Grow: Practice

Question 1.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 44

Answer:
The objects are 4.

Explanation:
In the above-given figure,
The given objects are 4.
so we have to fill the color for 4 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.3-2

Question 2.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 45

Answer:
The objects are 3.

Explanation:
In the above-given figure,
The given objects are 3.
so we have to fill the color for 3 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.3-3

Question 3.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 46

Answer:
The objects are 3.

Explanation:
In the above-given figure,
The given objects are 3.
so we have to fill the color for 3 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.3-4

Question 4.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 47

Answer:
The objects are 4.

Explanation:
In the above-given figure,
The given objects are 4.
so we have to fill the color for 4 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.3-5

Directions:
1 – 4 Count the objects. Color the boxes to show how many.

Think and Grow: Modeling Real Life

Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 48

Answer:
b.The objects are 4.

Explanation:
In the above-given figure,
The given objects are 4.
so we have to fill the color for 4 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.3-6

Answer:
a.The objects are 3.

Explanation:
In the above-given figure,
The given objects are 3.
so we have to fill the color for 3 boxes.

Directions:
Count the objects in the picture. Color the boxes to show how many.

Model and Count 3 and 4 Homework & Practice 1.3

Question 1.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 49

Answer:
The objects are 3.

Explanation:
In the above-given figure,
The given objects are 3.
so we have to fill the color for 3 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.3-7

Question 2.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 50

Answer:
The objects are 4.

Explanation:
In the above-given figure,
The given objects are 4.
so we have to fill the color for 4 boxes.

Directions:
1 and 2 Count the objects. Color the boxes to show how many.

Question 3.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 51

Answer:
The objects are 3.

Explanation:
In the above-given figure,
The given objects are 3.
so we have to fill the color for 3 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.3-4

Question 4.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 52

Answer:
The objects are 2.

Explanation:
In the above-given figure,
The given objects are 2.
so we have to fill the color for 2 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.3-9

Question 5.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 53

Answer:
a.The objects are 3.

Explanation:
In the above-given figure,
The given objects are 3.
so we have to fill the color for 3 boxes.

Answer:
b.The objects are 4.

Explanation:
In the above-given figure,
The given objects are 4.
so we have to fill the color for 4 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.3-10

Directions:
3 and 4 Count the objects. Color the boxes to show how many. 5 Count the objects in the picture. Color the boxes to show how many.

Lesson 1.4 Understand and Write 3 and 4

Explore and Grow

Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 54

Directions:
Use counters to show how many trees and how many birds are in the story We Go Camping. Write how many trees and how many birds are in the story.

Think and Grow

Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 55

Directions: Count the objects. Say the number. Trace and write the number.

Apply and Grow: Practice

Question 1.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 57

Answer:
The objects are three.

Explanation:
In the above-given figure,
there are 3 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.4-1

Question 2.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 58

Answer:
The objects are four.

Explanation:
In the above-given figure,
there are 4 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.4-2

Question 3.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 59

Answer:
The objects are four.

Explanation:
In the above-given figure,
there are 4 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.4-3

Question 4.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 60

Answer:
The objects are three.

Explanation:
In the above-given figure,
there are 3 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.4-4

Question 5.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 61

Answer:
The objects are three.

Explanation:
In the above-given figure,
there are 3 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.4-5

Question 6.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 62

Answer:
The objects are four.

Explanation:
In the above-given figure,
there are 4 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.4-6

Directions:
1 – 6 Count the objects. Say the number. Write the number.

Think and Grow: Modeling Real Life

Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 63

Answer:
a.The objects are four.

Explanation:
In the above-given figure,
there are 4 objects.
so, we have to count it and we have to write it.

Answer:
b.The objects are three.

Explanation:
In the above-given figure,
there are 3 objects.
so, we have to count it and we have to write it.

Answer:
c.The object is one.

Explanation:
In the above-given figure,
there is 1 object.
so, we have to count it and we have to write it.

Answer:
d.The objects are two.

Explanation:
In the above-given figure,
there are 2 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.4-7

Directions:
Count the objects in the picture. Say the number. Write the number.

Understand and Write 3 and 4 Homework & Practice 1.4

Question 1.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 64

Answer:
The objects are four.

Explanation:
In the above-given figure,
there are 4 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.4-8

Question 2.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 65

Answer:
The objects are three.

Explanation:
In the above-given figure,
there are 3 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.4-9

Question 3.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 66

Answer:
The objects are three.

Explanation:
In the above-given figure,
there are 3 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.4-10

Question 4.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 67

Answer:
The objects are four.

Explanation:
In the above-given figure,
there are 4 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.4-11

Directions:
1 – 4 Count the linking cubes. Say the number. Write the number.

Question 5.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 68

Answer:
The objects are three.

Explanation:
In the above-given figure,
there are 3 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.4-12

Question 6.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 69

Answer:
The objects are four.

Explanation:
In the above-given figure,
there are 4 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.4-13

Question 7.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 70

Answer:
The objects are four.

Explanation:
In the above-given figure,
there are 4 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.4-14

Question 8.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 71

Answer:
The objects are two.

Explanation:
In the above-given figure,
there are 2 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.4-15

Question 9.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 72

Answer:
a.The objects are four.

Explanation:
In the above-given figure,
there are 4 objects.
so, we have to count it and we have to write it.

Answer:
b.The objects are three.

Explanation:
In the above-given figure,
there are 3 objects.
so, we have to count it and we have to write it.

Answer:
c.The objects are one.

Explanation:
In the above-given figure,
there is 1 object.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.4-16

Directions:
5 – 8 Count the objects. Say the number. Write the number. 9 Count the objects in the picture. Say the number. Write the number.

Lesson 1.5 Model and Count 5

Explore and Grow

Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 73

Directions:
Place 5 counters on the blanket. Slide the counters to the frame.

Think and Grow

Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 74
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 74.1

Answer:
The objects are 5.

Explanation:
In the above-given figure,
The given objects are 5.
so we have to fill the color for 5 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.5-16

Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 74.2

Answer:
The objects are 5.

Explanation:
In the above-given figure,
The given objects are 5.
so we have to fill the color for 5 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.5-17

Directions:
Count the objects. Color the boxes to show how many.

Apply and Grow: Practice

Question 1.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 75

Answer:
The objects are 5.

Explanation:
In the above-given figure,
The given objects are 5.
so we have to fill the color for 5 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.5-18

Question 2.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 76

Answer:
The objects are 4.

Explanation:
In the above-given figure,
The given objects are 4.
so we have to fill the color for 4 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.5-19

Question 3.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 77

Answer:
The objects are 5.

Explanation:
In the above-given figure,
The given objects are 5.
so we have to fill the color for 5 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.5-020

Directions:
1 – 3 Count the objects. Color the boxes to show how many.

Think and Grow: Modeling Real Life
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 78

Answer:
a.The objects are 5.

Explanation:
In the above-given figure,
The given objects are 5.
so we have to fill the color for 5 boxes.

Answer:
b.The objects are 5.

Explanation:
In the above-given figure,
The given objects are 5.
so we have to fill the color for 5 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.5-021

Directions:
Count the objects in the picture. Color the boxes to show how many.

Model and Count 5 Homework & Practice 1.5

Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 78.1

Question 1.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 79

Answer:
The objects are 5.

Explanation:
In the above-given figure,
The given objects are 5.
so we have to fill the color for 5 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.5-022

Question 2.
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 80

Answer:
The objects are 3.

Explanation:
In the above-given figure,
The given objects are 3.
so we have to fill the color for 3 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.5-023

Directions:
1 and 2 Count the objects. Color the boxes to show how many.

Question 3.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 81

Answer:
The objects are 5.

Explanation:
In the above-given figure,
The given objects are 5.
so we have to fill the color for 5 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.5-024

Question 4.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 82

Answer:
b.The objects are 5.

Explanation:
In the above-given figure,
The given objects are 5.
so we have to fill the color for 5 boxes.

Answer:
a.The objects are 4.

Explanation:
In the above-given figure,
The given objects are 4.
so we have to fill the color for 4 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.5-025

Directions:
3 Count the watermelon slices. Color the boxes to show how many. 4 Count the objects in the picture. Color the boxes to show how many.

Lesson 1.6 Understand and Write 5

Explore and Grow

Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 83
Directions:
Use counters to show how many turtles are in the story. Write how many turtles are in the story.

Think and Grow

Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 84
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 84.1

Answer:
The objects are five.

Explanation:
In the above-given figure,
there are 5 objects.
so, we have to count it and we have to write it.

Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.6-1

Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 84.2

Answer:
The objects are five.

Explanation:
In the above-given figure,
there are 5 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.6-2

Directions:

  • Count the objects. Say the number. Trace and write the number.
  • Count the objects. Say the number. Write the number.

Apply and Grow: Practice

Question 1.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 85

Answer:
The objects are five.

Explanation:
In the above-given figure,
there are 5 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.6-3

Question 2.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 86

Answer:
The objects are five.

Explanation:
In the above-given figure,
there are 5 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.6-4

Question 3.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 87

Answer:
The objects are three.

Explanation:
In the above-given figure,
there are three objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.6-5

Question 4.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 88

Answer:
The objects are five.

Explanation:
In the above-given figure,
there are 5 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.6-6

Directions:
1 – 4 Count the objects. Say the number. Write the number.

Think and Grow: Modeling Real Life
Big Ideas Math Answers Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 89

Answer:
a.The objects are three.

Explanation:
In the above-given figure,
there are 3 objects.
so, we have to count it and we have to write it.

Answer:
b.The objects are five.

Explanation:
In the above-given figure,
there are 5 objects.
so, we have to count it and we have to write it.

Answer:
c.The objects are five.

Explanation:
In the above-given figure,
there are 5 objects.
so, we have to count it and we have to write it.

Answer:
d.The objects are two.

Explanation:
In the above-given figure,
there are 2 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.6-8

Directions: Count the objects in the picture. Say the number. Write the number.

Understand and Write 5 Homework & Practice 1.6

Question 1.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 90

Answer:
The objects are five.

Explanation:
In the above-given figure,
there are 5 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.6-9

Question 2.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 91

Answer:
The objects are five.

Explanation:
In the above-given figure,
there are 5 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.6-10

Question 3.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 92

Answer:
The objects are three.

Explanation:
In the above-given figure,
there are 3 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.6-11

Question 4.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 93

Answer:
The objects are five.

Explanation:
In the above-given figure,
there are 5 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.6-12

Directions: 1 – 4 Count the dots. Say the number. Write the number.

Question 5.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 94

Answer:
The objects are five.

Explanation:
In the above-given figure,
there are 5 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.6-13

Question 6.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 95

Answer:
The objects are four.

Explanation:
In the above-given figure,
there are 4 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.6-14

Question 7.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 96

Answer:
a.The objects are five.

Explanation:
In the above-given figure,
there are 5 objects.
so, we have to count it and we have to write it.

Answer:
b.The objects are four.

Explanation:
In the above-given figure,
there are 4 objects.
so, we have to count it and we have to write it.

Answer:
c.The objects are two.

Explanation:
In the above-given figure,
there are 2 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.6-15

Directions:
5 and 6 Count the objects. Say the number. Write the number. 7 Count the objects in the picture. Say the number. Write the number.

Lesson 1.7 The Concept of Zero

Explore and Grow
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 97

Answer:
The box is empty.

Explanation:
In the above-given figure,
The given objects are 0.
so we have to fill the color for 0 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.6-16

Directions: The box is empty. Show the number of toys in the box. Write the number on a box flap.

Think and Grow

Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 98

Answer:
a.The objects are 0.

Explanation:
In the above-given figure,
The given objects are 0.
so we have to fill the color for 0 boxes.

Answer:
1.a.The objects are 2.

Explanation:
In the above-given figure,
The given objects are 2.
so we have to fill the color for 2 boxes.

Answer:
1.b. The objects are 2.

Explanation:
In the above-given figure,
The given objects are 2.
so we have to fill the color for 2 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.7-1

Directions:

  • Count the leaves on the bottom branch. Say the number. Trace and write the number.
  • Count the sheep in each pen. Color the boxes to show how many.

Apply and Grow: Practice

Question 1.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 99

Answer:
The objects are zero.

Explanation:
In the above-given figure,
there are 0 objects.
so, we have to count it and we have to write it
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.7-2

Question 2.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 100

Answer:
The objects are three.

Explanation:
In the above-given figure,
there are 3 objects.
so, we have to count it and we have to write it
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.7-3

Question 3.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 101

Answer:
The objects are five.

Explanation:
In the above-given figure,
there are 5 objects.
so, we have to count it and we have to write it
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.7-4

Question 4.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 102

Answer:
The objects are zero.

Explanation:
In the above-given figure,
there are 0 objects.
so, we have to count it and we have to write it
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.7-5

Directions
1 – 4 Count the fireflies. Say the number. Write the number.

Think and Grow: Modeling Real Life
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 103

Answer:
a.The objects are two.

Explanation:
In the above-given figure,
there are 2 objects.
so, we have to count it and we have to write it

Answer:
b.The objects are five.

Explanation:
In the above-given figure,
there are 5 objects.
so, we have to count it and we have to write it

Answer:
c.The objects are zero.

Explanation:
In the above-given figure,
there are 0 objects.
so, we have to count it and we have to write it

Answer:
d.The objects are three.

Explanation:
In the above-given figure,
there are 3 objects.
so, we have to count it and we have to write it
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.7-6

Directions: Count the objects in the picture. Say the number. Write the number.

The Concept of Zero Homework & Practice 1.7

Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 104

Question 1.
Big Ideas Math Answer Key Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 105

Answer:
The objects are 2.

Explanation:
In the above-given figure,
The given objects are 2.
so we have to fill the color for 2 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.7-7

Question 2.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 106

Answer:
The objects are 0.

Explanation:
In the above-given figure,
The given objects are 0.
so we have to fill the color for 0 boxes.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 106

Directions:
1 and 2 Count the flowers. Say the number. Write the number. Color the boxes to show how many.

Question 3.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 107

Answer:
The objects are zero.

Explanation:
In the above-given figure,
there are 0 objects.
so, we have to count it and we have to write it
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.7-8

Question 4.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 108

Answer:
The objects are four.

Explanation:
In the above-given figure,
there are 4 objects.
so, we have to count it and we have to write it
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.7-9

Question 5.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 109

Answer:
a.The objects are five.

Explanation:
In the above-given figure,
there are 5 objects.
so, we have to count it and we have to write it

Answer:
b.The objects are one.

Explanation:
In the above-given figure,
there are 1 object.
so, we have to count it and we have to write it

Answer:
The objects are zero.

Explanation:
In the above-given figure,
there are 0 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.7-10

Directions: 3 and 4 Count the fireflies. Say the number. Write the number. 5 Count the objects in the picture. Say the number. Write the number.

Lesson 1.8 Count and Order Numbers to 5

Explore and Grow
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 110

Directions: Trace the numbers. Then make linking cube trains that are 0 to 5 cubes long. Order the trains to match the numbers 0 to 5.

Think and Grow

Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 111

Answer:
b.The objects are four.

Explanation:
In the above-given figure,
there are 4 objects.
so, we have to count it and we have to write it

Answer:
c.The objects are five.

Explanation:
In the above-given figure,
there are 5 objects.
so, we have to count it and we have to write it

Answer:
e.The objects are three.

Explanation:
In the above-given figure,
there are 3 objects.
so, we have to count it and we have to write it

Answer:
1, 2, 3, 4, and 5

Explanation:
The number in order are one, two, three, four, and five.
given that write the numbers in order.
1, 2, 3, 4 and 5.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-2

Directions:

  • Count the objects in each ve frame. Say the number. Write the number.
  • Write the numbers in order. Start with the number 1.

Apply and Grow: Practice

Question 1.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 112

Answer:
The objects are five.

Explanation:
In the above-given figure,
there are 5 objects.
so, we have to count it and we have to write it
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-3

Question 2.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 113

Answer:
The objects are three.

Explanation:
In the above-given figure,
there are 3 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-4

Question 3.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 114

Answer:
The objects are two.

Explanation:
In the above-given figure,
there are 2 objects.
so, we have to count it and we have to write it
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-5

Question 4.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 115

Answer:
The objects are four.

Explanation:
In the above-given figure,
there are 4 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-6

Question 5.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 116

Answer:
The objects are one.

Explanation:
In the above-given figure,
there is 1 object.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-7

Question 6.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 117

Answer:
1, 2, 3, 4, and 5.

Explanation:
the numbers in order are
one, two, three, four and five.
1, 2, 3, 4, and 5.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-8

Directions: 1 – 5 Count the objects. Say the number. 6 Write the number. Write the numbers in order. Start with the number 1.

Think and Grow: Modeling Real Life
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 118

Answer:
a.Yellow = 3
blue = 1
orange = 4
green = 5
pink = 2

Explanation:
In the above-given figure,
there are different colors of stars.

Yellow = 3
blue = 1
orange = 4
green = 5
pink = 2

Answer:
b.five
four
three
two
one

Explanation:
In the above-question, given that
write the numbers in reverse order.
five
four
three
two
one
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-9

Directions:

  • Count the stars in the picture. Say the number. Write the number.
  • Write the numbers in reverse order. Start with the number 5.

Count and Order Numbers to 5 Homework & Practice 1.8

Question 1.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 119

Answer:
The objects are two.

Explanation:
In the above-given figure,
there are 2 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-10

Question 2.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 120

Answer:
The objects are three.

Explanation:
In the above-given figure,
there are 3 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-11

Question 3.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 121

Answer:
The objects are one.

Explanation:
In the above-given figure,
there are one object.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-12

Question 4.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 122

Answer:
one
two
three

Explanation:
Given that,
write the numbers in order. start with the number 1.
one
two
three
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-13

Directions:
1 – 3 Count the birds. Say the number. Write the number. 4 Write the numbers in order. Start with the number 1.

Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 123

Question 5.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 124

Answer:
orange flag=3
yellow flag = 2
green flag = 4
blue flag = 5
pink flag = 1

Explanation:
In the above question given that,
count the flags in the picture.
orange flag=3
yellow flag = 2
green flag = 4
blue flag = 5
pink flag = 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-14

Question 6.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 125

Answer:
pink flag = 1
yellow flag = 2
orange flag = 3
green flag = 4
blue flag = 5

Explanation:
Given that write the numbers in order.
pink flag = 1
yellow flag = 2
orange flag = 3
green flag = 4
blue flag = 5
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-15

Question 7.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 126

Answer:
blue flag = 5
green flag = 4
orange flag = 3
yellow flag = 2
pink flag = 1

Explanation:
Given that write the numbers in reverse order.
blue flag = 5
green flag = 4
orange flag = 3
yellow flag = 2
pink flag = 1
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-16

Directions:
5 Count the flags in the picture. Say the number. Write the number.
6 Write the numbers in order. Start with the number 1.
7 Write the numbers in reverse order. Start with the number 5.

Count and Write Numbers 0 to 5 Performance Task

Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 127

Question 1.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 128

Answer:
a.The objects are three.

Explanation:
In the above-given figure,
there are 3 objects.
so, we have to count it and we have to write it

Answer:
b.The objects are zero.

Explanation:
In the above-given figure,
there are 0 objects.
so, we have to count it and we have to write it

Answer:
c.The objects are two.

Explanation:
In the above-given figure,
there are 2 objects.
so, we have to count it and we have to write it

Answer:
d.The objects are four.

Explanation:
In the above-given figure,
there are 4 objects.
so, we have to count it and we have to write it

Answer:
e.The objects are one.

Explanation:
In the above-given figure,
there are 1 object.
so, we have to count it and we have to write it
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-17

Question 2.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 129

Answer:
The objects are five.

Explanation:
In the above-given figure,
there are 5 objects.
so, we have to count it and we have to write it
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-18

Question 3.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 130

Answer:
The objects are three.

Explanation:
In the above-given figure,
there are 3 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-19

Directions:
1 Count the objects in the picture. Say the number. Write the number. Write the numbers in order. Start with the number 0. 2 A chicken lays five eggs. Draw to show how many eggs. 3 Show how many eggs in another way.

Count and Write Numbers 0 to 5 Activity

Number Land
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 131
Directions: Put the Subitizing Cards 0–5 into a pile. Start at Newton. Take turns drawing a card and moving your piece to the matching number. Repeat this process until you have gone around the board and back to Newton.

Count and Write Numbers 0 to 5 Chapter Practice 1

1.1 Model and Count 1 and 2

Question 1.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 132

Answer:
The objects are 2.

Explanation:
In the above-given figure,
The given objects are 2.
so we have to fill the color for 2 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-20

Question 2.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 133

Answer:
The object is one.

Explanation:
In the above-given figure,
The given object is 1.
so we have to fill the color for 1 box.

Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-21

1.2 Understand and Write 1 and 2

Question 3.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 134

Answer:
The object is one.

Explanation:
In the above-given figure,
there is 1 object.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-22

Question 4.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 135

Answer:
The objects are two.

Explanation:
In the above-given figure,
there are 2 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-23

Directions: 1 and 2 Count the objects. Color the boxes to show how many. 3 and 4 Count the objects. Say the number. Write the number.

1.3 Model and Count 3 and 4

Question 5.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 136

Answer:
The objects are 3.

Explanation:
In the above-given figure,
The given objects are 3.
so we have to fill the color for 3 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-24

Question 6.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 137

Answer:
The objects are 4.

Explanation:
In the above-given figure,
The given objects are 4.
so we have to fill the color for 4 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-25

1.4 Understand and Write 3 and 4

Question 7.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 138

Answer:
The objects are four.

Explanation:
In the above-given figure,
there are 4 objects.
so, we have to count it and we have to write it.

Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-26

Question 8.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 139

Answer:
The objects are three.

Explanation:
In the above-given figure,
there are 3 objects.
so, we have to count it and we have to write it.

Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-27

Directions: 5 and 6 Count the objects. Color the boxes to show how many. 7 and 8 Count the objects. Say the number. Write the number.

1.5 Model and Count 5

Question 9
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 140

Answer:
The objects are 5.

Explanation:
In the above-given figure,
The given objects are 5.
so we have to fill the color for 5 boxes.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-28

1.6 Understand and Write 5

Question 10.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 141

Answer:
The objects are five.

Explanation:
In the above-given figure,
there are 5 objects.
so, we have to count it and we have to write it.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-29

1.7 The Concept of Zero

Question 11.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 142

Answer:
The objects are three.

Explanation:
In the above-given figure,
there are 3 objects.
so, we have to count it and we have to write it.

Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-30

Question 12.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 143

Answer:
The objects are zero.

Explanation:
In the above-given figure,
there are 0 objects.
so, we have to count it and we have to write it.

Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-31

Directions: 9 Count the ears of corn. Color the boxes to show how many. 10 Count the beavers. Say the number. Write the number. 11 and 12 Count the owls. Say the number. Write the number.

1.8 Count and Order Numbers to 5

Directions:
13 – 17
Count the objects. Say the number. Write the number. 18 Write the numbers in order. Start with the number 1.

Question 13.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 144

Answer:
The objects are one.

Explanation:
In the above-given figure,
there is 1 object.
so, we have to count it and we have to write it.

Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-32

Question 14.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 145

Answer:
The objects are five.

Explanation:
In the above-given figure,
there are 5 objects.
so, we have to count it and we have to write it.

Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-33

Question 15.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 146

Answer:
The objects are four.

Explanation:
In the above-given figure,
there are 4 objects.
so, we have to count it and we have to write it.

Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-35

Question 16.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 147

Answer:
The objects are two.

Explanation:
In the above-given figure,
there are 2 objects.
so, we have to count it and we have to write it.

Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-36

Question 17.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 148

Answer:
The objects are three.

Explanation:
In the above-given figure,
there are 3 objects.
so, we have to count it and we have to write it.

Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-37

Question 18.
Big Ideas Math Solutions Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 149

Answer:
The numbers in order are 1, 2, 3, 4, and 5.

Explanation:
Given that 1.
write the numbers in order.
start with the number 1.
1
2
3
4
5.
Big-Ideas-Math-Solutions-Grade-K-Chapter-1-Count and Write Numbers Numbers 0 to 5-1.8-38

Conclusion:

We wish the above article i.e, Big Ideas Math Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 Answer Key is helpful for all elementary school students. Thus, the students who are unable to make their children finish homework in time can make use of the BIM Grade K Chapter 1 Count and Write Numbers Numbers 0 to 5 Solution Key pdf. Keep in touch with us to get the Solution Key of all Bigideas Math Grade K chapters.

Big Ideas Math Answers Grade 7 Chapter 3 Expressions

Big Ideas Math Answers Grade 7 Chapter 3 Expressions

Big Ideas Math 7th Grade Chapter 3 Expressions Answer Key: Download free step-by-step problem and solution pdf of Big Ideas Math Grade 7 Chapter 3 Expressions from here. Follow the various concepts and topics involved in this chapter and make your preparation easy and efficient. We are providing the free Big Ideas Math Book 7th Grade Answer Key Chapter 3 Expressions pdf links in the below sections.

Refer to the Big Ideas Math Answers Grade 7 Chapter 3 Expressions and finish your preparation and assignment. The solutions for 7th-grade chapter 3 expressions give you a clear idea of how to solve and understand the problems. With the help of experts, we have given all the problems of a chapter in a single pdf. To avoid time waste, download the pdf and start your preparation.

Big Ideas Math Book 7th Grade Answer Key Chapter 3 Expressions

There are various topics available in the Expressions Chapter. Those are Adding and Subtracting Linear Expressions, The Distributive Property, Algebraic Expressions, Factoring Expressions, and so on. Find out the solutions and problems involved in these chapters. To understand the concept more clearly, compare the problems with real-life situations.

Follow BIM 7th Grade Chapter 3 Expressions Solution Key and know your strengths and weaknesses. First of all, know the syllabus of expressions and then based on the various concepts, prepare the timetable. Involve the number of concepts, time remaining to learn all the topics, etc, and prepare the timetable according to it. Know the example problems and formulae in the below sections.

Performance

Lesson: 1 Algebraic Expressions

Lesson: 2 Adding and Subtracting Linear Expressions

Lesson: 3 The Distributive Property

Lesson: 4 Factoring Expressions

Chapter: 3 – Expressions 

Expressions STEAM VIDEO/Performance

STEAM Video

Trophic Status

In an ecosystem, energy and nutrients flow between abiotic and components. Biotic components are the living parts of an ecosystem. Abiotic components are the non-living parts of an ecosystem. What is an example of an ecosystem?
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 1

Watch the STEAM video “Trophic Status.” Then answer the following questions.

Question 1.
Give examples of both biotic and abiotic components in an ecosystem. Explain.

Answer:
Examples of biotic components are plants, animals, bacteria, fungi. Examples of abiotic components are water, soil, sunlight, gases, etc.

Explanation:
Biotic components are the living organisms in an ecosystem. Examples of biotic components are plants, animals, bacteria, fungi. Abiotic components are the non-living physical and chemical factors in the environment that affect ecosystems. Examples of abiotic components are water, soil, sunlight, gases, etc. Abiotic factors affect the ability of organisms to reproduce, survive, help determine the types and number of organisms able to exist in the environment. Limiting factors restrict growth. Biotic factors are the living things that directly or indirectly affect organisms in the environment.

Question 2.
When an organism is eaten, its energy flows into the organism that consumes it. Explain how to use an expression to represent the total energy that a person gains from eating each of the items shown.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 2

Answer:
bx + lx + fx

Explanation:
Let us take the energy gained by eating a banana is bx, by eating leaves is lx, by eating fish is fx.
So, the expression becomes the sum of all those energies.
bx + lx + fx

Performance Task

Chlorophyll in Plants

After completing this chapter, you will be able to use the STEAM concepts you learned to answer the questions in the Video Performance Task. You will be given the numbers of atoms found in molecules involved in photosynthesis.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 3
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 4
You will be asked to determine the total cost for a model of a molecule given the costs of different types of atom models. How can you find the total cost of purchasing several identical objects?

Expressions Getting Ready for Chapter 3

Chapter Exploration

Work with a partner. Rewrite the algebraic expression so that it has fewer symbols x but still has the same value when evaluated for any value of x.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 5

Answer:
1. 3x + 4
2. 3x – 1
3. 2x – 3
4. 2(1 + x)
5. 3x – 1
6. x + 5

Explanation:
1. Original expression is 2x + 4 + x
Simplified expression is 3x + 4
2. Original expression is 3(x + 1) – 4
3x + 3 – 4 = 3x – 1
Simplified expression is 3x – 1
3. Original expression is x – (3 – x)
x – 3 + x
Simplified expression is 2x – 3
4. Original expression is 5 + 2x – 3
Simplified expression is 2 + 2x = 2(1 + x)
5. Original expression is x + 3 + 2x – 4
Simplified expression is 3x – 1
6. Original expression is 2x + 2 – x + 3
Simplified expression is x + 5

Question 7.
WRITING GUIDELINES
Work with a partner. Use your answers in Exercises 1-6 to write guidelines for simplifying an expression.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 6

Answer:
First, you need to take the given original expression as it is.
If there are any braces, then eliminate them by expanding the expression
Then, add or subtract variables and constants together to get the solution

Explanation:
Let us take question 2. 3(x + 1) – 4
Expand 3
3x + 3 – 4
Simplify
3x – 1

APPLYING A DEFINITION
Work with a partner. Two expressions are equivalent if x they have the same value when evaluated for any value of x. Decide which two expressions are equivalent. Explain your reasoning.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 7

Answer:
8. x – (2x + 1) is equivalent to -x – 1
9. 2x + 3 – x + 4 is equivalent to x + 7 in expression B
10. 3 + x -2(x + 1) is equivalent to -x + 1
11. 2 – 2x – (x + 2) is equivalent to -3x

Explanation:
8. x – (2x + 1) = x – 2x – 1
= -x – 1
So, x – (2x + 1) is equivalent to -x – 1
9. 2x + 3 – x + 4 = x + 7
So, 2x + 3 – x + 4 is equivalent to x + 7 in expression B
10. 3 + x -2(x + 1) = 3 + x -2x – 2
= 1 – x
So, 3 + x -2(x + 1) is equivalent to -x + 1
11. 2 – 2x – (x + 2) = 2 – 2x – x – 2
= -3x
So, 2 – 2x – (x + 2) is equivalent to -3x

Vocabulary
The following vocabulary terms are defined in this chapter. Think about what each term might mean and record your thoughts.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 8

Lesson 3.1 Algebraic Expressions

EXPLORATION 1
Simplifying Algebraic Expressions
Work with a partner.
a. Choose a value of other than 0 or 1 for the last column in the table. Complete the table by evaluating each algebraic expression for each value of x. What do you notice?
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 9
b. How can you use properties of operations to justify your answers in part(a)? Explain your reasoning.
c. To subtract a number, you can add its opposite. Does a similar rule apply to the terms of an algebraic expression? Explain your reasoning.

Answer:
a. Big Ideas Math Answers Grade 7 Chapter 3 Expressions 1
b. Just simplify the expression and put the values of x in simplified expression
c. Yes

Explanation:
a.
A. -1/3 + x + 7/3 = (-1 + 7)/3 + x
= -6/3 + x = -2 + x
If x = 0, then -2 + 0 = -2
If x = 1, then -2 + 1 = -1
If x = 4, then -2 + 4 = 2
B. 0.5x + 3 – 1.5x – 1 = -x + 4
If x = 0, then -0 + 4 = 4
If x = 1, then -1 + 4 = 3
If x = 4, then -4 + 4 = 0
C. 2x + 6
If x = 0, then 2(0) + 6 = 6
If x = 1, then 2(1) + 6 = 8
Ifx = 4, then 2(4) + 6 = 14
D. x + 4
If x = 0, then 0 + 4 = 4
If x = 1, then 1 + 4 = 5
If x = 4, then 4 + 4 = 8
E. -2x + 2
If x = 0, then -2(0) + 2 = 2
If x = 1, then -2(1) + 2 = 0
If x = 4, then -2(4) + 2 = -6
F. 1/2 x – x + 3/2 x + 4 = 4/2 x – x + 4
= 2x – x + 4 = x + 4
If x = 0, then 0 + 4 = 4
If x = 1, then 1 + 4 = 5
If x = 4, then 4 + 4 = 8
G. -4.8x + 2 – x + 3.8x = -2x + 2
If x = 0, then -2(0) + 2 = 2
If x = 1, then -2(1) + 2 = 0
If x = 4, then -2(4) + 2 = -6
H. x + 2
If x = 0, then 0 + 2 = 2
If x = 1, then 1 + 2 = 3
If x = 4, then 4 + 2 = 6
I. -x + 2
If x = 0, then -0 + 2 = 2
If x = 1, then -1 + 2 =1
If x = 4, then -4 + 2 = -2
J. 3x + 2 – x + 4 = 2x + 6
If x = 0, then 2(0) + 6 = 6
If x = 1, then 2(1) + 6 = 8
If x = 4, then 2(4) + 6 = 14

3.1 Lesson

In an algebraic expression, are terms that have the same variables raised to the same exponents. Constant terms are also like terms. To identify terms and like terms in an expression, first write the expression as a sum of its terms.

Try It
Identify the terms and like terms in the expression.

Question 1.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 10

Answer:
Terms are 10, y, -3/2y, like terms are y, -3/2y.

Explanation:
The given expression is y + 10 – 3/2 y
Like terms are y, -3/2y
Because they have the same variable y
Terms are 10, y, -3/2y

Question 2.
2r2 + 7r – r2 – 9

Answer:
The like terms are 2r², -r², Terms are -9, 7r, 2r², -r²

Explanation:
Given expression is 2r² + 7r -r² – 9
The like terms are 2r², -r²
Terms are -9, 7r, 2r², -r²

Question 3.
7 + 4p – 5 + p + 2q

Answer:
The like terms are 4p, p
The terms are 7, -5, 2q, 4p, p

Explanation:
Given expression is 7 + 4p – 5 + p + 2q
The like terms are 4p, p
The terms are 7, -5, 2q, 4p, p

Try It
Simplify the expression.

Question 4.
-10y + 15y

Answer:
-10y + 15y = 5y

Explanation:
Given expression is -10y + 15y
5y

Question 5.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 11

Answer:
3/8 b – 3/4 b = -3/8 b

Explanation:
Given expression is 3/8 b – 3/4 b
L.C.M of 8, 4 is 8
(3 – 6)/8 b = -3/8 b

Question 6.
2.4g – 2.4g – 9.8g

Answer:
-9.8g

Explanation:
Given expression is 2.4g – 2.4g – 9.8g
-9.8g

Try It

Simplify the expression.

Question 7.
14 – 3z + 8 + z

Answer:
22 – 2z

Explanation:
Given expression is 14 – 3z + 8 + z
Add constants and like terms
22 – 2z

Question 8.
2.5x + 4.3x – 5

Answer:
6.8x – 5

Explanation:
Given expression is 2.5x + 4.3x – 5
6.8x – 5

Question 9.
2s – 9s + 8t – t

Answer:
7(t – s)

Explanation:
Given expression is 2s – 9s + 8t – t
-7s + 7t = 7(t – s)

Self-Assessment for Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 10.
WRITING
Explain how to identify the terms and like terms of 3y – 4 – 5y.

Answer:
The like terms are 3y, -5y
Terms are -4, 3y, -5y

Explanation:
Given expression is 3y – 4 – 5y
Like terms are the terms in the expression which have the same variable
The following are the like terms because each term contains a variable y and numeric coefficient
3y, -5y
Other than like terms are called the terms
Terms are -4, 3y, -5y

SIMPLIFYING ALGEBRAIC EXPRESSIONS
Simplify the expression.

Question 11.
7p + 6p

Answer:
13p

Explanation:
Given expression is 7p + 6p
13p

Question 12.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 12

Answer:
3n/2 – 3

Explanation:
Given expression is 4/5 n – 3 + 7/10 n
(8n + 7n)/10 – 3
= 15n/10 – 3
= 3n/2 – 3

Question 13.
2w – g – 7w + 3g

Answer:
-5w + 2g

Explanation:
Given expression is 2w – g – 7w + 3g
Perform the arithmetic operations between the like terms
-5w + 2g

Question 14.
VOCABULARY
Is the expression 3x + 2x – 4 in simplest form? Explain.

Answer:
The expression 3x + 2x – 4 is not in the simplest form.

Explanation:
Given expression is 3x + 2x – 4
= 5x – 4
The simplest form of 3x + 2x – 4 is 5x – 4

Question 15.
WHICH ONE DOESN’T BELONG?
Which expression does not belong with the other three? Explain your reasoning.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 13

Answer:
5x – 10 – 2x does not belong with the other three.

Explanation:
The first expression is -4 + 6 + 3x = 2 + 3x
The second expression is 3x + 9 – 7 = 3x + 2
The third expression is 5x – 10 – 2x = 3x – 10
Fourth expression is 5x – 4 + 6 – 2x = 3x + 2
So, out of all 5x – 10 – 2x does not belong with the other three.

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 16.
MODELING REAL LIFE
An exercise mat is 3.3 times as long as it is wide. Write expressions in simplest form that represent the perimeter and the area of the exercise mat.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 14

Answer:
The perimeter of the exercise mat is 8.6l, Area of the exercise mat is 3.3l²

Explanation:
Let us take the l is the length of the exercise mat
Then, the width of the exercise mat = 3.3l
Perimeter of exercise mat = 2(length + width)
= 2(l + 3.3l)
= 2(4.3l) = 8.6 l
Area of the exercise mat = length x width
= l x 3.3l
= 3.3l²
Therefore, the perimeter of the exercise mat is 8.6l, Area of the exercise mat is 3.3l²

Question 17.
DIG DEEPER!
A group of friends visits the movie theater in Example 4. Each person buys a daytime ticket and a small drink. The group shares 2 large popcorns. What is the average cost per person when there are 4 people in the group?

Answer:
The total cost for a group of 4 people is $35.

Explanation:
Number of tickets . cost per ticket + number of small drinks . cost per small drink + Number of large popcorns . Cost per large popcorn
The same number of tickets, small drinks are purchased. So, can represent the number of tickets, the number of small drinks.
5x + 1.75x + $8 = x(5 + 1.75) + $8
= 6.75x + $8
2 popcorns cost is 2 x 4 = $8
The expression 6.75x + $8 indicates that the cost per person is $6.75 + $8 = 14.75
To find the cost for a group of 4 people, evaluate the expression when x = 4
= 6.75 (4 ) + 8 = 27 + 8 = 35
The total cost for a group of 4 people is $35.

Algebraic Expressions Homework & Practice 3.1

Review & Refresh

Find the product or quotient. Write fractions in simplest form.

Question 1.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 15

Answer:
-1/2

Explanation:
Given that,
-2/7 x 7/4 = -2/4
= -1/2

Question 2.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 16

Answer:
3/5

Explanation:
Given that,
-2/3(-9/10) = 2/3 x 9/10
= 6/10 = 3/5

Question 3.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 17

Answer:
-13/6

Explanation:
Given that,
1(4/9) ÷ (-2/3) = 13/9 ÷ (-2/3)
= 13/9 x (-3/2) = -13/6

Order the numbers from least to greatest.

Question 4.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 18

Answer:
3/4, 78%, 0.85, 87%, 7/8

Explanation:
Given that
7/8 = 0.875, 0.85, 87% = 87/100 = 0.87 3/4 = 0.75, 78% = 78/100 = 0.78
So, the numbers are 0.875, 0.85, 0.87, 0.75, 0.78
Ordering from the least to the greatest is 0.75,0.78,0.85,0.87,0.875
i.e 3/4, 78%, 0.85, 87%, 7/8

Question 5.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 19

Answer:
15%, 1450%, 14.8, 15(4/5)

Explanation:
Given that,
15% = 15/100 = 0.15, 14.8, 15(4/5) = 79/5 = 15.8, 1450% = 1450/100 = 14.5
So the numbers are 0.15, 14.8, 15.8, 14.5
The order of number from least to greatest is 0.15, 14.5, 14.8, 15.8
i.e 15%, 1450%, 14.8, 15(4/5)

Question 6.
A bird’s nest is 12 feet above the ground. A mole’s den is 12 inches below the ground. What is the difference in height of these two positions?
A. 24 in.
B. 11 ft
C. 13 ft
D. 24 ft

Answer:
The difference in height of these two positions is 13 feet.

Explanation:
Given that,
The bird nest is 12 feet above the ground and a mole’s den is 12 inches below the ground.
So, the mole’s den have to travel 12 inches +12 feet to reach the bird nest
So, the difference in height of these two positions is 12 feet + 12 inches
= 12 feet + 1 feet = 13 feet

Concepts, Skills, & Problem Solving
REASONING
Determine whether the expressions are equivalent. Explain your reasoning. (See Exploration 1, p. 91.)

Question 7.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 20

Answer:
The expressions are not equivalent

Explanation:
Expression 1 is 3 – 5x
Expression 2 is 4.25 – 5x – 4.25
= -5x
So, expressions are not equivalent

Question 8.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 21

Answer:
Both the expressions are equivalent.

Explanation:
Expression 1 is 1.25x + 4 + 0.75x – 3
= 2x + 4 – 3 = 2x + 1
Expression 2 is 2x + 1
So, both the expressions are equivalent.

IDENTIFYING TERMS AND LIKE TERMS
Identify the terms and like terms in the expression.

Question 9.
t + 8 + 3t

Answer:
Like terms are t, 3t
Terms are 8, t, 3t

Explanation:
Given expression is t + 8 + 3t
Like terms are t, 3t
Terms are 8, t, 3t

Question 10.
3z + 4 + 2 + 4z

Answer:
Like terms are 3z, 4z
terms are 4, 2, 3z, 4z

Explanation:
Given expression is 3z + 4 + 2 + 4z
Like terms are 3z, 4z
terms are 4, 2, 3z, 4z

Question 11.
2n – n – 4 + 7n

Answer:
Like terms are 2n, -n, 7n
Terms are -4, 2n, -n, 7n

Explanation:
Given expression is 2n – n – 4 + 7n
Like terms are 2n, -n, 7n
Terms are -4, 2n, -n, 7n

Question 12.
-x – 9x2 + 12x2 + 7

Answer:
Like terms are -9x², 12x²
Terms are 7, -x, -9x², 12x²

Explanation:
Given expression is -x – 9x² + 12x² + 7
Like terms are -9x², 12x²
Terms are 7, -x, -9x², 12x²

Question 13.
1.4y + 5 – 4.2 – 5y2 + z

Answer:
There are no like terms
Terms are 1.4y, 5, -4.2, -5y², z

Explanation:
Given expression is 1.4y + 5 – 4.2 – 5y² + z
There are no like terms
Terms are 1.4y, 5, -4.2, -5y², z

Question 14.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 22

Answer:
Like terms are 1/2 s, 3/4 s
Terms are -4, 1/8, -s³, 1/2 s, 3/4 s

Explanation:
Given expression is 1/2 s – 4 + 3/4 s + 1/8 – s³
Like terms are 1/2 s, 3/4 s
Terms are -4, 1/8, -s³, 1/2 s, 3/4 s

Question 15.
YOU BE THE TEACHER
Your friend identifies the terms and like terms in the expression 3x – 5 – 2x + 9x. Is your friend correct? Explain your reasoning.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 23

Answer:
Wrong

Explanation:
Given expression is 3x – 5 – 2x + 9x
like terms are 3x, -2x, 9x
Terms are 3x, -2x, 9x, 5

SIMPLIFYING ALGEBRAIC EXPRESSIONS
Simplify the expression.

Question 16.
12g + 9g

Answer:
21g

Explanation:
The given expression is 12g + 9g
= 21g

Question 17.
11x + 9 – 7

Answer:
11x + 2

Explanation:
Given expression is 11x + 9 – 7
= 11x + 2

Question 18.
8s – 11s + 6s

Answer:
3s

Explanation:
Given expression is 8s – 11s + 6s
= 14s – 11s = 3s

Question 19.
4b – 24 + 19

Answer:
4b – 5

Explanation:
Given expression is 4b – 24 + 19
= 4b – 5

Question 20.
4p – 5p – 30p

Answer:
-31p

Explanation:
Given expression is 4p – 5p – 30p
= 4p – 35p = -31p

Question 21.
4.2v – 5 – 6.5v

Answer:
-2.3v – 5

Explanation:
Given expression is 4.2v – 5 – 6.5v
= -2.3v – 5

Question 22.
8 + 4a + 6.2 – 9a

Answer:
14.2 – 5a

Explanation:
Given expression is 8 + 4a + 6.2 – 9a
= 14.2 – 5a

Question 23.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 24

Answer:
3 – 1/2 y

Explanation:
Given expression is 2/5y – 4 + 7 – 9/10y
= (4 – 9)/10 y + 3
= -5/10 y + 3
= -1/2 y + 3

Question 24.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 25

Answer:
40c/3 – 3/2

Explanation:
Given expression is -2/3 c -9/5 + 14c + 3/10
= (-2 + 42)c/3 – (18 – 3)/10
= 40c/3 – 15/10
= 40c/3 – 3/2

Question 25.
MODELING REAL LIFE
On a hike, each hiker carries the items shown. Write and interpret an expression in simplest form that represents the weight carried by x hikers. How much total weight is carried when there are 4 hikers?
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 26

Answer:
When there are 4 hikers the total weight is 40.8 lb.

Explanation:
A hiker has thw following items:
A sleeping bag of 3.4 lb weight, camping bag of 4.6 lb weight, and a water bottle of 2.2 lb weight
The expression can be
3.4x + 4.6x + 2.2x = x
Here x is the weight each hiker is carrying
10.2x = x
So, each hiker carries a total weight of 10.2 pounds
When there are 4 hikes, the total weight is 10.2 x 4 = 40.8

Question 26.
STRUCTURE
Evaluate the expression -8x + 5 – 2x – 4 + 5 when x = 2 before and after simplifying. Which method do you prefer? Explain.

Answer:
-14

Explanation:
Given expression is -8x + 5 – 2x – 4 + 5
Put x = 2
-8(2) + 5 -2(2) – 4 + 5
= -16 + 5 – 4 – 4 + 5 = -14
Simplify -8x + 5 – 2x – 4 + 5
= -10x + 10 – 4 = -10x + 6
Put x = 2 in -10x + 6
= -10(2) + 6
= -20 + 6 = -14
I just prefer putting x = 2 after simplifying the expression.

Question 27.
OPEN-ENDED
Write an expression with five different terms that is equivalent 8x2 + 3x2 + 3y. Justify your answer.

Answer:
3x² + 2y + y + 7x² + x²

Explanation:
Given expression is 8x² + 3x² + 3y.
The expression which is equivalent to 8x² + 3x² + 3y and having 5 different terms can be as follows
3x² + 2y + y + 7x² + x²
by simplifying the above expression, you will get the original expression.

Question 28.
STRUCTURE
Which of the following shows a correct way of simplifying 6 + (3 – 5x)? Explain the errors made in the other choices.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 27

Answer:
C. 6 + (3 – 5x) = (6 + 3) – 5x = 9 – 5x

Explanation:
A. 6 + (3 – 5x) = (6 + 3 – 5)x
Here, x is applicable to only -5x, it is not multiplied with whole expression
B. 6 + (3 – 5x) = 6 + (3 – 5)x
Here, x is the multiple of only -5x, but you have included 3 also which is false
C. 6 + (3 – 5x) = (6 + 3) – 5x = 9 – 5x
This is true
D. 6 + (3 – 5x) = (6 + 3 + 5) – x
5 is the multiple of x, it is not constant.

Question 29.
PRECISION
Two comets orbit the Sun. One comet travels 30,000 miles per hour and the other comet travels 28,500 miles per hour. What is the most efficient way to calculate the difference of the distances traveled by the comets for any given number of minutes? Justify your answer.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 28

Answer:
The difference between those distances is 1500 miles for 60 minutes.

Explanation:
Given that,
One comet travels 30,000 miles per hour and the other comet travels 28,500 miles per hour.
Let us say, the time given for the comets is 60 minutes.
So, in 60 minutes, the first one travels 30,000 miles, and the second one travels 28,500 miles
The difference between those distances = 30,000 – 28,500 = 1500 miles

Question 30.
MODELING REAL LIFE
Find the earnings for washing and waxing 12 cars and 8 trucks. Justify your answer.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 29

Answer:
and waxing 12 cars and 8 trucks is $440

Explanation:
The earnings for washing and waxing 12 cars = 12(washing one car cost) + 12(waxing one car cost)
= 12($8) + 12($12)
= 12(8 + 12) = $240
The earnings for washing and waxing 8 trucks = 8(washing one truck cost) + 8(waxing one truck cost)
= 8($10) + 8($15)
= 8(10 + 15) = 8(25) = $200
So, the earnings for washing and waxing 12 cars and 8 trucks is $ 240 + $200 = $440

Question 31.
CRITICAL THINKING
You apply gold foil to a piece of red poster board to make the design shown.
a. Find the area of the gold foil when x = 3. Justify your answer.
b. The pattern at the right is called “St. George’s Cross.” Find a country that uses this pattern as its flag.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 30

Answer:
a. Area of the gold foil = 87 sq in
b. England

Explanation:
You apply gold foil to a piece of red poster board to make the design.
a. Area of rectangle = length x breadth
= 20 x 12 = 240 sq in.
Length of the gold foil = (12 – x) in
The breadth of gold foil = (20 – x) in
Area of horizontal gold foil = length x breadth
= 20 * x = 20x sq. in
Area of the vertical gold foil = length x breath
= 12 * x = 12x sq. in
Area of the middle gold foil = length x breadth
= x * x = x² sq. in
Area of the gold foil = Area of horizontal gold foil + Area of vertical gold foil – Area of the middle gold foil
= 20x + 12x – x²
The area of gold foil when x = 3 is 20(3) + 12(3) – (3)²
= 60 + 36 – 9
= 87 sq in
b. The pattern at the right is called “St. George’s Cross.” Find a country that uses this pattern as its flag.
England

Question 32.
GEOMETRY
Two rectangles have different dimensions. Each rectangle has a perimeter of (7x + 5) inches. Draw and label diagrams that represent possible dimensions of the rectangles.

Answer:
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 3
Rectangle 1 dimensions are 3.5x and 2.5, rectangle 2 dimensions are 1/2(5x + 1), x + 2

Explanation:
Perimeter of rectangle = (7x + 5) inches
2(length + width) = 7x + 5
length + width = (7x + 5)/2
Rectangle 1 dimensions can be 3.5x and 2.5
Rectangle 2 dimensions can be 1/2(5x + 1), x + 2

Lesson 3.2 Adding and Subtracting Linear Expressions

EXPLORATION 1

Using Algebra Tiles
Work with a partner. You can use the algebra tiles shown at the left to find sums and differences of algebraic expressions.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 31
a. How can you use algebra tiles to model a sum of terms that equals 0? Explain your reasoning.
b. Write each sum or difference modeled below. Then use the algebra tiles to simplify the expression.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 32
c. Write two algebraic expressions of the form ax + b, where a and b are rational numbers. Find the sum and difference of the expressions.

EXPLORATION 2
Using Properties of Operations
Work with a partner.
a. Do algebraic expressions, such as 2x, -3y, and 3z + 1 have additive inverses? How do you know?
b. How can you find the sums and differences modeled in Exploration 1 without using algebra tiles? Explain your reasoning.

3.2 Lesson

Try It

Find the sum.

Question 1.
(x + 3) + (2x – 1)

Answer:
(x + 3) + (2x – 1) = 3x + 2

Explanation:
The given expression is (x + 3) + (2x – 1)
Add the like terms and constant
= 3x + 3 – 1
= 3x + 2

Question 2.
(-8z + 4) + (8z – 7)

Answer:
(-8z + 4) + (8z – 7) = -3

Explanation:
The given expression is (-8z + 4) + (8z – 7)
= -8z + 4 + 8z – 7
= -3

Question 3.
(4.5 – n) + (-10n + 6.5)

Answer:
(4.5 – n) + (-10n + 6.5) = 11(1 – n)

Explanation:
The given expression is (4.5 – n) + (-10n + 6.5)
= 4.5 – n – 10n + 6.5
= 11 – 11n
= 11(1 – n)

Question 4.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 34

Answer:
(1/2w – 3) + (1/4w + 3) = 3w/4

Explanation:
The given expression is (1/2w – 3) + (1/4w + 3)
= 1/2w – 3 + 1/4w + 3
= (2w + w)/4 = 3w/4

Try It

Find the difference.

Question 5.
(m – 3) – (-m + 12)

Answer:
(m – 3) – (-m + 12) = 2m – 15

Explanation:
The given expression is (m – 3) – (-m + 12)
= m – 3 + m – 12
= 2m – 15

Question 6.
(-2c + 5) – (6.3c + 20)

Answer:
(-2c + 5) – (6.3c + 20) = -83c – 15

Explanation:
The given expression is (-2c + 5) – (6.3c + 20)
= -2c + 5 – 6.3c – 20
= -83c – 15

Self-Assessment for Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 7.
WRITING
Describe how to distinguish a linear expression from a nonlinear expression. Give an example of each.

Answer:
An example of a linear expression is 2x + 1.
An example of a non-linear expression is 2x² + 1

Explanation:
Linear expressions are the expressions where the sum of constants and products of constants and raised to a power of 0 or 1. Non-linear expressions are the expressions where the sum of constants and products of constants and raised to a power that is not 0 or 1.
So, an example of a linear expression is 2x + 1.
An example of a non-linear expression is 2x² + 1

Question 8.
DIFFERENT WORDS, SAME QUESTION
Which is different? Find “both” answers.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 35

Answer:
What is x more than 3x – 1 is different.

Explanation:
What is x more than 3x – 1 = x + 3x – 1 = 4x – 1
Find 3x – 1 decreased by x = 3x – 1 – x = 2x – 1
What is the difference of 3x – 1 and x = 3x – 1 – x = 2x – 1
Subtract (x + 1) from 3x = 3x – (x + 1) = 3x – x – 1 = 2x – 1

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 9.
DIG DEEPER!
In a basketball game, the home team scores (2m + 39) points and the away team scores (3m + 40) points, where m is the number of minutes since halftime. Who wins the game? What is the difference in the scores minutes after halftime? Explain.

Answer:
The away team wins the game. And the difference in the scores minutes after halftime is 2m + 2.

Explanation:
Given that,
The score of home team = 2m + 39 points
The score of away team = 3m + 40 points
Here, m is the number of minutes since halftime
Let us consider the teams that score the same points after the half time
The score of home team = 2m + 39 + 2m + 39 = 4m + 78
The score of away team = 3m + 40 + 3m + 40 = 6m + 80
The difference between those scores = 6m + 80 – (4m + 78)
= 6m + 80 – 4m – 78 = 2m + 2
The away team wins the game.

Question 10.
Electric guitar kits originally cost d dollars online. You buy the kits on sale for 50% of the original price, plus a shipping fee of $4.50 per kit. After painting and assembly, you sell each guitar online for (1.5d + 4.5) dollars. Find and interpret your profit on each guitar sold.

Answer:
Your profit on each electric guitar kit is d dollars

Explanation:
Electric guitar kits originally cost d dollars online.
You buy the kits on sale for 50% of the original price. So, the purchase price of kit is = d/2 + 4.50
After painting and assembly, you sell each guitar online for (1.5d + 4.5) dollars
Profit = Selling price – Purchased price
= 1.5d + 4.5 – (d/2+ 4.50)
= 1.5d + 4.5 – 0.5d – 4.50
= d dollars
Your profit on each electric guitar kit is d dollars. You pay (0.5d + 4.50) dollars for each kit. so, you are getting 4.50 dollars less than double your money.

Adding and Subtracting Linear Expressions Homework & Practice 3.2

Review & Refresh

Simplify the expression.

Question 1.
4f + 11f

Answer:
4f + 11f = 15f

Explanation:
Given expression is 4f + 11f
Add the like terms
= 15f

Question 2.
b + 4b – 9b

Answer:
b + 4b – 9b = -4b

Explanation:
Given expression is b + 4b – 9b
Perform required operations between like terms
= 5b – 9b = -4b

Question 3.
-4z – 6 – 7z + 3

Answer:
-4z – 6 – 7z + 3 = -11z- 3

Explanation:
Given expression is -4z – 6 – 7z + 3
Perform required operations between like terms and constants
= -11z- 3

Evaluate the expression when x = \(-\frac{4}{5}\) and y = \(\frac{1}{3}\).

Question 4.
x + y

Answer:
-7/15

Explanation:
Given expression is x + y
Put x = -4/5, y = 1/3
= -4/5 + 1/3
= (-12 + 5)/15 = -7/15

Question 5.
2x + 6y

Answer:
2/5

Explanation:
Given expression is 2x + 6y
Put x = -4/5, y = 1/3
= 2(-4/5) + 6(1/3) = -8/5 + 6/3
= (-24 + 30)/15 = 6/15
= 2/5

Question 6.
-x + 4y

Answer:
32/15

Explanation:
Given expression is -x + 4y
Put x = -4/5, y = 1/3
= -(-4/5) + 4(1/3)
= 4/5 + 4/3
= (12 + 20)/15
= 32/15

Question 7.
What is the surface area of a cube that has a side length of 5 feet?
A. 25 ft2
B. 75 ft2
C. 125 ft2
D. 150 ft2

Answer:
D. 150 ft²

Explanation:
Given that,
the side length of cube = 5 feet
The surface area of a cube = 6side²
= 6 x (5)² = 6 x 25
= 150 ft²

Concepts, Skills, & Problem Solving
USING ALGEBRA TILES
Write the sum or difference modeled by the algebra tiles. Then use the algebra tiles to simplify the expression. (See Exploration 1, p. 97.)

Question 8.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 36

Answer:
3x – 1

Explanation:
Convert the given algebra tiles to the expressions
(x – 1 – 1 – 1 + x – 1 – 1 – 1) + (x + 1 + 1+ 1+ 1+ 1)
= (2x – 6) +(x + 5)
= 2x – 6 + x + 5
= 3x – 1

Question 9.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 37

Answer:
11

Explanation:
Convert the given algebra tiles to the expressions
(x + 1 + 1 + 1+ 1 + 1 + x + 1 + 1) – (x – 1 – 1 – 1 – 1 + x)
= (2x + 7) – (2x – 4)
= 2x + 7 – 2x + 4
= 11

ADDING LINEAR EXPRESSIONS
Find the sum.

Question 10.
(n + 8) + (n – 12)

Answer:
(n + 8) + (n – 12) = 2n – 4

Explanation:
Given linear expression is (n + 8) + (n – 12)
= n + 8 + n – 12
= 2n – 4

Question 11.
(7 – b) + (3b + 2)

Answer:
(7 – b) + (3b + 2) = 9 + 2b

Explanation:
Given linear expression is (7 – b) + (3b + 2)
= 7 – b + 3b + 2
= 9 + 2b

Question 12.
(2w – 9) + (-4w – 5)

Answer:
(2w – 9) + (-4w – 5) = -2w – 14

Explanation:
Given linear expression is (2w – 9) + (-4w – 5)
= 2w – 9 – 4w- 5
= -2w – 14

Question 13.
(2x – 6) + (4x – 12)

Answer:
(2x – 6) + (4x – 12) = 8x – 18

Explanation:
Given linear expression is (2x – 6) + (4x – 12)
= 2x – 6 + 4x – 12
= 8x – 18

Question 14.
(-3.4k – 7) + (3k + 21)

Answer:
(-3.4k – 7) + (3k + 21) = -0.4k + 14

Explanation:
Given linear expression is (-3.4k – 7) + (3k + 21)
= -3.4k – 7 + 3k + 21
= -0.4k + 14

Question 15.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 38

Answer:
(-7/2 z+ 4) + (1/5 z- 15) = -33z/10 – 11

Explanation:
Given linear expression is (-7/2 z+ 4) + (1/5 z- 15)
= -7/2 z + 4 + 1/5 z- 15
= (-35z + 2z)/10 – 11
= -33z/10 – 11

Question 16.
(6 – 2.7h) + (-1.3j – 4)

Answer:
(6 – 2.7h) + (-1.3j – 4) = 2 – 2.7h – 1.3j

Explanation:
Given linear expression is (6 – 2.7h) + (-1.3j – 4)
= 6 – 2.7h – 1.3j – 4
= 2 – 2.7h – 1.3j

Question 17.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 39

Answer:
(7/4 x – 5) + (2y – 3.5) + (-1/4 x + 5) = 3x/2 + 2y – 3.5

Explanation:
Given linear expression is (7/4 x – 5) + (2y – 3.5) + (-1/4 x + 5)
= 7/4 x – 5 + 2y – 3.5 – 1/4x + 5
= (7x – x)/4 + 2y – 3.5
= 6x/4 + 2y – 3.5
= 3x/2 + 2y – 3.5

Question 18.
MODELING REAL LIFE
While catching fireflies, you and a friend decide to have a competition. After m minutes, you have (3m + 13) fireflies and your friend has (4m + 6) fireflies.
a. How many total fireflies do you and your friend catch? Explain your reasoning.
b. The competition lasts 3 minutes. Who has more fireflies? Justify your answer.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 40

Answer:
a. The total number of fireflies collected is 7m + 19
b. You have more fireflies when compared with your friend.

Explanation:
The number of fireflies you collected after m minutes is (3m + 13)
The number of fireflies your friend collected after m minutes is (4m + 6)
a.
The number of fireflies you collected is (3m + 13)
The number of fireflies your friend collected is (4m + 6)
The total number of fireflies collected = (3m + 13) + (4m + 6)
= 3m + 13 + 4m + 6 = 7m + 19
b. The competition lasts 3 minutes
So, The number of fireflies you collected is 3(1) + 13 = 3 + 13 = 16
The number of fireflies your friend collected is 4(1) + 6 = 4 + 6 = 10
So, you have more fireflies when compared with your friend.

SUBTRACTING LINEAR EXPRESSIONS

Find the difference.

Question 19.
(-2g + 7) – (g + 11)

Answer:
(-2g + 7) – (g + 11) = -3g – 4

Explanation:
The given linear expression is (-2g + 7) – (g + 11)
= -2g + 7 – g – 11
= -3g – 4

Question 20.
(6d + 5) – (2 – 3d)

Answer:
(6d + 5) – (2 – 3d) = 9d + 3

Explanation:
The given linear expression is (6d + 5) – (2 – 3d)
= 6d + 5 – 2 + 3d
= 9d + 3

Question 21.
(4 – 5y) – (2y – 16)

Answer:
(4 – 5y) – (2y – 16) = 20 – 7y

Explanation:
The given linear expression is (4 – 5y) – (2y – 16)
= 4 – 5y – 2y + 16
= 20 – 7y

Question 22.
(2n – 9) – (-2.4n + 4)

Answer:
(2n – 9) – (-2.4n + 4) = 4.4n – 13

Explanation:
The given linear expression is (2n – 9) – (-2.4n + 4)
= 2n – 9 + 2.4n – 4
= 4.4n – 13

Question 23.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 41

Answer:
(-1/8 c + 16) – (3/8 + 3c) = (-25c + 125)/8

Explanation:
The given linear expression is (-1/8 c + 16) – (3/8 + 3c)
= -1/8 c + 16 – 3/8 – 3c
= (-c – 24c)/8 + (128 – 3)/8
= -25c/8 + 125/8
= (-25c + 125)/8

Question 24.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 42

Answer:
(9/4 x + 6) – (-5/4 x – 24) = 7x/2 + 30

Explanation:
The given linear expression is (9/4 x + 6) – (-5/4 x – 24)
= 9x/4 + 6 + 5x/4 + 24
= (9x + 5x)/4 + 30
= 14x/4 + 30
= 7x/2 + 30

Question 25.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 43

Answer:
(1/3 – 6m) – (1/4 n – 8) = 25/4 – 6m – n/4

Explanation:
The given linear expression is (1/3 – 6m) – (1/4 n – 8)
= 1/3 – 6m – 1/4 n + 8
= (1 + 24)/3 – 6m – n/4
= 25/4 – 6m – n/4

Question 26.
(1 – 5q) – (2.5s + 8) – (0.5q + 6)

Answer:
(1 – 5q) – (2.5s + 8) – (0.5q + 6) = -5.5q – 2.5s – 13

Explanation:
The given linear expression is (1 – 5q) – (2.5s + 8) – (0.5q + 6)
= 1 – 5q – 2.5s – 8 – 0.5q – 6
= 1 – 5.5q – 2.5s – 14
= -5.5q – 2.5s – 13

Question 27.
YOU BE THE TEACHER
Your friend finds the difference (4m + 9) – (2m – 5). Is your friend correct? Explain your reasoning.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 44

Answer:
Wrong

Explanation:
The given expression is (4m + 9) – (2m – 5)
= 4m + 9 – 2m + 5
= 2m + 14

Question 28.
GEOMETRY
The expression 17n + 11 represents the perimeter of the triangle. What is the length of the third side? Explain your reasoning.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 45

Answer:
The length of the third side is 8n.

Explanation:
Perimeter of the triangle = 17n + 11
5n + 6 + 4n + 5 + third side = 17n + 11
9n + 11 + third side = 17n + 11
third side = 17n + 11 – (9n +11)
= 17n + 11 – 9n – 11
= 8n
The length of the third side is 8n.

Question 29.
LOGIC
Your friend says the sum of two linear expressions is always a linear expression. Is your friend correct? Explain.

Answer:
yes, the sum of two linear expressions is always a linear expression.

Explanation:
The sum of two linear expressions is always a linear expression. But the product of linear expressions may not be the linear expression.

Question 30.
MODELING REAL LIFE
You burn 265 calories running and then 7 calories per minute swimming. Your friend burns 273 calories running and then 11 calories per minute swimming. You each swim for the same number of minutes. Find and interpret the difference in the amounts of calories burned by you and your friend.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 46

Answer:
The difference in the amounts of calories burned by you and your friend is 8 + 4m.

Explanation:
The number of calories your burn by running and swimming is 265 + 7m
The number of calories your friend burns by running and swimming is 273 + 11m
The difference in amount of calories burn = 273 + 11m – (265 + 7m)
= 273 + 11m – 265 – 7m
= 8 + 4m
The difference in the amounts of calories burned by you and your friend is 8 + 4m.

Question 31.
DIG DEEPER!
You start a new job. After w weeks, you have (10w + 120) dollars in your savings account and (45w + 25) dollars in your checking account.
a. What is the total amount of money in the accounts? Explain.
b. How much money did you have before you started your new job? How much money do you save each week?
c. You want to buy a new phone for $150, and still have $500 left in your accounts afterwards. Explain how to determine when you can buy the phone.

Answer:
a. The total amount of money in the accounts = (55w + 145) dollars
b. You started a new job with 120 dollars savings and you earned 10 dollars savings each week.
c. You can buy the phone after 9 weeks of starting new job.

Explanation:
You have (10w + 120) dollars in your savings account and (45w + 25) dollars in your checking account.
a.
The total amount of money in the accounts = 10w + 120 + 45w + 25
= 55w + 145
b.
In the saving’s account the multiple of w is the amount earned during job and other constant is the amount you have before the new job.
So, you started a new job with 120 dollars savings and you earned 10 dollars savings each week.
c.
The total amount in accounts is (55w + 145) dollars
You want to buy a new phone for $150, and still have $500 left in your accounts afterwards
Deduct $150 from total amount so that the remaining amount should be $500.
55w + 145 – 150 = 500
55w – 5 = 500
55w = 500 + 5
55w = 505
w = $505/55
w = 9.1818
So, you can buy the phone after 9 weeks of starting new job.

Question 32.
REASONING
Write an expression in simplest form that represents the vertical distance between the two lines shown. What is the distance when x = 3? when x = -3?
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 47

Answer:
The vertical distance between the two lines is 3 units.

Explanation:
Given equations are y = x – 1, y = 2x – 4
Equating those two
x – 1 = 2x – 4
-1 + 4 = 2x – x
3 = x
So, the vertical distance between the two lines is 3 units.

Lesson 3.3 The Distributive Property

EXPLORATION 1

Using Models to Write Expressions
Work with a partner.
a. Write an expression that represents the area of the shaded region in each figure.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 48
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 48.1
b. Compare your expressions in part(a) with other groups in your class. Did other groups write expressions that look different than yours? If so, determine whether the expressions are equivalent.

3.3 Lesson

Try It
Simplify the expression.

Question 1.
-1(x + 9)

Answer:
-1(x + 9) = 9 – x

Explanation:
Given expression is -1(x + 9)
= -x + 9

Question 2.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 49

Answer:
2/3 (-3z – 6) = -2z – 4

Explanation:
Given expression is 2/3 (-3z – 6)
= 2/3(-3z) – 2/3(6)
= -2z – 2(2)
= -2z – 4

Question 3.
-1.5(8m – n)

Answer:
-1.5(8m – n) = -12m + 1.5n

Explanation:
Given expression is -1.5(8m – n)
= -1.5(8m) + 1.5(n)
= -12m + 1.5n

Try It

Simplify the expression.

Question 4.
2(-3s + 1 – 5)

Answer:
2(-3s + 1 – 5) = -6s – 8

Explanation:
Given expression is 2(-3s + 1 – 5)
= 2(-3s) + 2(1) + 2(-5)
= -6s + 2 – 10
= -6s – 8

Question 5.
Big Ideas Math Answers 7th Grade Chapter 3 Expressions 50

Answer:
-3/2 (a – 4 – 2a) = 3a/2 + 6

Explanation:
Given expression is -3/2 (a – 4 – 2a)
= -3/2 (a) + 3/2(4) + 3/2(2a)
= -3a/2 + 3(2) + 3(a)
= -3a/2 + 6 + 3a
= (-3a + 6a)/2 + 6
= 3a/2 + 6

Try It

Simplify the expression.

Question 6.
3.5m – 1.5(m – 10)

Answer:
3.5m – 1.5(m – 10) = 2m + 15

Explanation:
Given expression is 3.5m – 1.5(m – 10)
= 3.5m – 1.5(m) + 1.5(10)
= 3.5m – 1.5m + 15
= 2m + 15

Question 7.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 51

Answer:
4/5(10w – 5) – 2(w + 9) = 6w – 22

Explanation:
Given expression is 4/5(10w – 5) – 2(w + 9)
= 4/5(10w) – 4/5(5) – 2w – 18
= 4(2w) – 4 – 2w – 18
= 8w – 2w – 22
= 6w – 22

Self-Assessment for Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 8.
WRITING
Explain how to use the Distributive Property when simplifying an expression.

Answer:
Distributive property says that a(b+ c) = ab + ac and a(b – c) = ab – ac
So, you need to expand the outer number with the sum or difference inside the braces
And perform the required arithmetical operations to get the simplified expression.

USING THE DISTRIBUTIVE PROPERTY
Simplify the expression.

Question 9.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 52

Answer:
5/6 (-2y + 3) = -5y/3 + 5/2

Explanation:
Given expression is 5/6 (-2y + 3)
= 5/6(-2y) + 5/6(3)
= -10y/6 + 15/6
= -5y/3 + 5/2

Question 10.
6(3s – 2.5 – 5s)

Answer:
6(3s – 2.5 – 5s) = -15 – 12s

Explanation:
Given expression is 6(3s – 2.5 – 5s)
= 6(-2.5 – 2s)
= 6(-2.5) – 6(2s)
= -15 – 12s

Question 11.
Big Ideas Math Answers 7th Grade Chapter 3 Expressions 53

Answer:
3/10(4m – 8) + 9m = (51m – 12)/5

Explanation:
Given expression is 3/10(4m – 8) + 9m
= 3/10(4m) – 3/10(8) + 9m
= 3/5(2m) – 3/5(4) + 9m
= 6m/5 – 12/5 + 9m
= (6m + 45m)/5 – 12/5
= 51m/5 – 12/5
= (51m – 12)/5

Question 12.
2.25 – 2(7.5 – 4h)

Answer:
2.25 – 2(7.5 – 4h) = 8h – 12.75

Explanation:
Given expression is 2.25 – 2(7.5 – 4h)
= 2.25 – 2(7.5) + 2(4h)
= 2.25 – 15 + 8h
= 8h – 12.75

Question 13.
STRUCTURE
Big Ideas Math Answers 7th Grade Chapter 3 Expressions 54
Use the terms at the left to complete the expression below so that it is equivalent to 9x – 12. Justify your answer.
Big Ideas Math Answers 7th Grade Chapter 3 Expressions 55

Answer:
3/2 (4x – 8) + 3x

Explanation:
The expression can be
3/2 (4x – 8) + 3x
= 3/2(4(x – 2)) + 3x
= 3(2(x – 2)) + 3x
= 6(x – 2) + 3x
= 6x – 12 + 3x
= 9x – 12

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 14.
A rectangular room is 10 feet longer than it is wide. How many 1-foot square tiles does it take to tile along the inside walls of the room?

Answer:
The number of tiles required is 4w + 20.

Explanation:
Let the width of the rectangular room is w
The length of the rectangular room is w + 10
Perimeter of the rectangular room = 2(length + with)
= 2(w + 10 + w)
= 2(2w +10)
= 4w + 20
So, the number of tiles required is 4w + 20.

Question 15.
How many 2-foot square tiles does it take to tile the border of the pool in Example 4? Explain.

Answer:
(4s + 8) 2 foot square tiles are required.

Explanation:
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 6
The diagram shows that the tiled border can be divided into two sections that each requires s + 4 tiles and two sections that each requires s tiles. So, the number of tiles can be represented as 2(s + 4) + 2s
2(s + 4) + 2s = 2(s) + 2(4) + 2s
= 4s + 8
So, (4s + 8) 2 foot square tiles are required.

The Distributive Property Homework & Practice 3.3

Review & Refresh

Find the sum or difference.

Question 1.
(5b – 9) + (b + 8)

Answer:
(5b – 9) + (b + 8) = 6b – 1

Explanation:
Given expression is (5b – 9) + (b + 8)
= 5b – 9 + b + 8
= 6b – 1

Question 2.
(3m + 5) – (6 – 5m)

Answer:
(3m + 5) – (6 – 5m) = 8m – 1

Explanation:
Given expression is (3m + 5) – (6 – 5m)
= 3m + 5 – 6 + 5m
= 8m – 1

Question 3.
(1 – 9z) + 3(z – 2)

Answer:
(1 – 9z) + 3(z – 2) = -5 – 6z

Explanation:
Given expression is (1 – 9z) + 3(z – 2)
= 1 – 9z + 3(z) – 3(2)
= 1 – 9z + 3z – 6
= -5 – 6z

Question 4.
(7g – 6) – (-3n – 4)

Answer:
(7g – 6) – (-3n – 4) = 7g + 3n – 2

Explanation:
Given expression is (7g – 6) – (-3n – 4)
= 7g – 6 -(-3n) -(-4)
= 7g – 6 + 3n + 4
= 7g + 3n – 2

Evaluate the expression.

Question 5.
-62

Answer:
-6² = -36

Explanation:
Given expression is -62
-6 x 6 = -36

Question 6.
-92 . 3

Answer:
-9² . 3 = -243

Explanation:
Given expression is -9² . 3
= -9 . 9 . 3
= -9 . 27
= -243

Question 7.
(-7) . (-2) . (-4)

Answer:
(-7) . (-2) . (-4) = -56

Explanation:
Given expression is (-7) . (-2) . (-4)
= -7 . -2 . -4
= 14 . -4
= -56

Copy and complete the statement using <, >, or =.

Question 8.
Big Ideas Math Answers 7th Grade Chapter 3 Expressions 56

Answer:
11 = | -11 |

Explanation:
11 = | -11 |
mod of -11 is positive 11
So, they are equal.

Question 9.
Big Ideas Math Answers 7th Grade Chapter 3 Expressions 57

Answer:
| 3.5 | <  | -5.8 |

Explanation:
| 3.5 | _  | -5.8 |
3.5 < 5.8

Question 10.
Big Ideas Math Answers 7th Grade Chapter 3 Expressions 58

Answer:
| -3.5 | <  | 17/5 |

Explanation:
| -3.5 | _  | 17/5 |
3.5 < 3.4

Concepts, Skills, & Problem Solving

USING MODELS
Write two different expressions that represent the area of the shaded region. Show that the expressions are equivalent. (See Exploration 1, p. 103.)

Question 11.
Big Ideas Math Answers 7th Grade Chapter 3 Expressions 59

Answer:
6.5(2x + 2), 13x + 13

Explanation:
The length of the shaded region is 6.5
The width of the shaded region is (3x + 4) – (x + 2) = 3x + 4 – x – 2
= 2x + 2
The area of the shaded region = length . width
= 6.5 . (2x + 2)
= 6.5(2x + 2)
= 6.5(2x) + 6.5(2)
= 13x + 13
The second way is as follows
The length of bigger rectangle is 3x + 4
Width of the bigger rectangle is 6.5
Area of the bigger rectangle = length . width
= 6.5(3x + 4)
The length of unshaded region is x + 2
width of the unshaded region is 6.2
Area of the unshaded region = length . width
= 6.5(x + 2)
Area of the shaded region = Area of the bigger rectangle – area of the shaded region
= 6.5(3x + 4) – 6.5(x + 2)
= 6.5(3x + 4 -(x + 2))
= 6.5(3x + 4 – x – 2)
= 6.5(2x + 2)
= 6.5(2x) + 6.5(2)
= 13x + 13

Question 12.
Big Ideas Math Answers 7th Grade Chapter 3 Expressions 60

Answer:
2.5m² – 2m, 1.5m² + m(m – 2)

Explanation:
The first way is here.
The length of the bigger rectangle is 1.5m
The width of the bigger rectangle is 2m
The area of the bigger rectangle = length . width
= 1.5m x 2m = 3m²
Length of the unshaded region is 1.5m – (m – 2) = 1.5m – m + 2
= 0.5m + 2
Width of the unshaded region = 2m – m = m
Area of the unshaded region = length . width
= (0.5m + 2) . m
Area of the shaded region = The area of the bigger rectangle – Area of the unshaded region
= 3m² – m(0.5m + 2)
= 3m² – 0.5m² -2m
= 2.5m² – 2m
The second way is as follows
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 7
The length of the first shaded rectangle = 1.5m
The width of the first shaded rectangle = m
Area of the first shaded rectangle = length . width
= 1.5m x m
= 1.5m²
The length of the second shaded rectangle = m – 2
The width of the first shaded rectangle = 2m – m = m
Area of the second shaded rectangle = length . width
= m(m – 2)
Therefore, area of the shaded region = Area of the first shaded rectangle + Area of the second shaded rectangle
= 1.5m² + m(m – 2)
= 1.5m² + m² – 2m
= 2.5m² – 2m
Therefore, two expressions that represent the area of the shaded region is 2.5m² – 2m, 1.5m² + m(m – 2).

USING THE DISTRIBUTIVE PROPERTY
Simplify the expression.

Question 13.
3(a – 7)

Answer:
3(a – 7) = 3a – 21

Explanation:
The given expression is 3(a – 7)
= 3(a) – 3(7)
= 3a – 21

Question 14.
-6(2 + x)

Answer:
-6(2 + x) = -12 – 6x

Explanation:
The given expression is -6(2 + x)
= -6(2) +(-6)(x)
= -12 -6(x)
= -12 – 6x

Question 15.
-5(3m – 4)

Answer:
-5(3m – 4) = -15m + 20

Explanation:
The given expression is -5(3m – 4)
= -5(3m) – (-5) (4)
= -15m +5(4)
= -15m + 20

Question 16.
-9(-5 – 4c)

Answer:
-9(-5 – 4c) = 45 + 36c

Explanation:
The given expression is -9(-5 – 4c)
= -9(-5) – (-9) (4c)
= 45 + 9(4c)
= 45 + 36c

Question 17.
4.5 (3s + 6)

Answer:
4.5 (3s + 6) = 13.5s+ 27

Explanation:
The given expression is 4.5 (3s + 6)
= 4.5(3s) + 4.5(6)
= 13.5s+ 27

Question 18.
-1.4 (-5 + 7g)

Answer:
-1.4 (-5 + 7g) = 7 – 9.8g

Explanation:
The given expression is -1.4 (-5 + 7g)
= -1.4(-5) -1.4(7g)
= 7 – 9.8g

Question 19.
Big Ideas Math Answers 7th Grade Chapter 3 Expressions 61

Answer:
2/5(6 – 5p) = 12/5 – 2p

Explanation:
The given expression is 2/5(6 – 5p)
= 2/5(6) – 2/5(5p)
= 12/5 – 2p

Question 20.
Big Ideas Math Answers 7th Grade Chapter 3 Expressions 62

Answer:
-4/3 (3q – 10) = -4q + 40/3

Explanation:
The given expression is -4/3 (3q – 10)
= -4/3 (3q) + 4/3(10)
= -4q + 40/3

Question 21.
2(3 + 4y + 5)

Answer:
2(3 + 4y + 5) = 16 + 8y

Explanation:
The given expression is 2(3 + 4y + 5)
= 2(8 + 4y)
= 2(8) + 2(4y)
= 16 + 8y

Question 22.
-9(8 + 6n – 4)

Answer:
-9(8 + 6n – 4) = -36 – 54n

Explanation:
The given expression is -9(8 + 6n – 4)
= -9(4 + 6n)
= -9(4) – 9(6n)
= -36 – 54n

Question 23.
-6(-4d – 8.3 + 3d)

Answer:
-6(-4d – 8.3 + 3d) = 6d + 49.8

Explanation:
The given expression is -6(-4d – 8.3 + 3d)
= -6(-d – 8.3)
= -6(-d) + 6(8.3)
= 6d + 49.8

Question 24.
2.3h(6 – k)

Answer:
2.3h(6 – k) = 13.8h – 2.3hk

Explanation:
The given expression is 2.3h(6 – k)
= 2.3h(6) – 2.3h(k)
= 13.8h – 2.3hk

Question 25.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 63

Answer:
-3/8 (-4y + z) = 3y/2 – 3z/8

Explanation:
The given expression is -3/8 (-4y + z)
= -3/8 (-4y) – 3/8(z)
= 3y/2 – 3z/8

Question 26.
2(-2w – 1.2 + 7x)

Answer:
2(-2w – 1.2 + 7x) = -4w- 2.4 + 14x

Explanation:
The given expression is 2(-2w – 1.2 + 7x)
= 2(-2w) + 2(-1.2) + 2(7x)
= -4w- 2.4 + 14x

Question 27.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 64

Answer:
5/3(4/3 a + 9b + 2/3 a) = 10a/3 + 15b

Explanation:
The given expression is 5/3(4/3 a + 9b + 2/3 a)
= 5/3 ( 6a/3 + 9b)
= 5/3 (2a + 9b)
= 5/3 (2a) + 5/3 (9b)
= 10a/3 + 5 (3b)
= 10a/3 + 15b

YOU BE THE TEACHER
Your friend simplifies the expression. Is your friend correct? Explain your reasoning

Question 28.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 65

Answer:
Wrong.

Explanation:
-2(h + 8k) = -2(h) -2(8k)
= -2h – 16k

Question 29.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 66

Answer:
Wrong

Explanation:
-3(4 – 5b + 7) = -3(11 – 5b)
= -3(11) -3(-5b)
= -33 + 15b

SIMPLIFYING EXPRESSIONS
Simplify the expression.

Question 30.
-3(5g + 1) + 8g

Answer:
-3(5g + 1) + 8g = -7g – 3

Explanation:
The given expression is -3(5g + 1) + 8g
= -3(5g) -3(1) + 8g
= -15g – 3 + 8g
= -7g – 3

Question 31.
-6a + 7(-2a – 4)

Answer:
-6a + 7(-2a – 4) = -20a – 28

Explanation:
The given expression is -6a + 7(-2a – 4)
= -6a + 7(-2a) +7(-4)
= -6a – 14a – 28
= -20a – 28

Question 32.
9 – 3(5 – 4x)

Answer:
9 – 3(5 – 4x) = -6 + 12x

Explanation:
The given expression is 9 – 3(5 – 4x)
= 9 – 3(5) -3(-4x)
= 9 – 15 + 12x
= -6 + 12x

Question 33.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 67

Answer:
-3/4(5p – 12) + 2(8 – 1/4 p) = -17p/4 + 25

Explanation:
The given expression is -3/4(5p – 12) + 2(8 – 1/4 p)
= -3/4 (5p) -3/4(-12) + 2(8) + 2(-1/4p)
= -15p/4 + 9 + 16 – p/2
= (-15p -2p)/4 + 25
= -17p/4 + 25

Question 34.
c(4 + 3c) – 0.75(c + 3)

Answer:
c(4 + 3c) – 0.75(c + 3) = 4c + 3c² – 0.75c – 2.25

Explanation:
The given expression is c(4 + 3c) – 0.75(c + 3)
= c(4) + c(3c) – 0.75(c) – 0.75(3)
= 4c + 3c² – 0.75c – 2.25

Question 35.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 68

Answer:
-1 – 2/3(6/7 – 3/7 n) = -33/21 + 6n/21

Explanation:
The given expression is -1 – 2/3(6/7 – 3/7 n)
= -1 -2/3(6/7) – 2/3(-3/7 n)
= -1 – 12/21 + 6n/21
= (-21 – 12)/21 + 6n/21
= -33/21 + 6n/21

Question 36.
MODELING REAL LIFE
The cost (in dollars) of a custom-made sweatshirt is represented by 3.5n + 29.99, where n is the number of different colors in the design. Write and interpret a simplified expression that represents the cost of 15 sweatshirts.

Answer:
The cost of 15 sweatshirts is 52.5n + 449.85

Explanation:
The cost (in dollars) of a custom-made sweatshirt is represented by 3.5n + 29.99
To find the cost of 15 sweatshirts, we need to multiply the expression by 15
= 15(3.5n + 29.99)
= 15(3.5n) + 15(29.99)
= 52.5n + 449.85
Therefore, the cost of 15 sweatshirts is 52.5n + 449.85

Question 37.
MODELING REAL LIFE
A ski resort makes snow using a snow fan that costs $1200. The fan has an average daily operation cost of $9.50. Write and interpret a simplified expression that represents the cost to purchase and operate 6 snow fans.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 69

Answer:
The expression that represents the cost to purchase and operate 6 snow fans is 7200 + 57d.

Explanation:
Given that,
A ski resort makes snow fan that costs $1200
The fan has an average daily operation cost of $ 9.50
We have to write a simplified expression that represents the cost to purchase and operate 6 snow fans.
And variable d represents the number of days that the resort operates the fans.
Now, cost of 6 snow fans = 6 x cost of each snow fan = 6 x 1200 = 7200
The cost to operate 6 fans = 6 x number of days x cost to operate each fan
= 6 x d x 9.5 = 57d
So, the expression for total cost will be cost of fans + cost to operate = 7200 + 57d.

Question 38.
NUMBER SENSE
Predict whether the instructions below will produce equivalent expressions. Then show whether your prediction is correct.

  • Subtract 3 from n, add 3 to the result, and then triple that expression.
  • Subtract 3 from n, triple the result, and then add 3 to that expression.

Answer:
Your prediction is wrong.

Explanation:
a. Subtract 3 from n = n – 3
Add 3 to the result = n – 3 + 3 = n
And then triple that expression = n x n x n = n³.
b. Subtract 3 from n = n – 3
Triple the result = (n – 3) . (n – 3) . (n – 3) = (n – 3)³
And then add 3 to that expression = (n – 3)³ + 3
Therefore, n³ is not equivalent to (n – 3)³ + 3
Hence, the prection is wrong.

USING A MODEL
Draw a diagram that shows how the expression can represent the area of a figure. Then simplify the expression.

Question 39.
5(2 + x + 3)

Answer:
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 8

Explanation:
The area of rectangle = length . width
= 5(2 + x + 3)
= 5(5 + x)
= 5(5) + 5(x)
= 25 + 5x
Therefore, area is (25 + 5x)

Question 40.
(4 + 1)(x + 2x)

Answer:
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 9

Explanation:
Length = 4 + 1
width = x + 2x
The area of rectangle = length . width
= (4 + 1) . (x + 2x)
= 5 . (3x)
= 15x
Therefore, area is 15x.

Question 41.
DIG DEEPER!
A square firepit with a side length of s feet is bordered by 1-foot square stones as shown.
a. How many stones does it take to border the firepit with two rows of stones? Use a diagram to justify your answer.
b. You border the fire pit with rows of stones. How many stones are in the nth row? Explain your reasoning.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 70

Answer:
a. Big Ideas Math Answers Grade 7 Chapter 3 Expressions 11
The number of stones = (s + 2)² + (s + 4)²
b. The area of the nth row square is (s + 2n)² ft².

Explanation:
a. The side length of the inner sqaure is s
The area of the sqaure = side²
= s²
The side length of the 1st row square is s + 1 + 1 = s + 2 ft
The area of the 1st row square = side²
= (s + 2)² ft²
The side length of the 2nd row of the sqaure is s + 2 + 2 = s + 4 ft
The area of the 2st row square = side²
= (s + 4)² ft²
So, the number of stones = (s + 2)² + (s + 4)²
b.
The side length of the nth row is s + 2n ft
The area of the nth row square = side²
= (s + 2n)² ft²

Question 42.
PUZZLE
Your friend asks you to perform the following steps.

  1. Pick any number except 0.
  2. Add 2 to your number.
  3. Multiply the result by 3.
  4. Subtract 6 from the result.
  5. Divide the result by your original number.

Your friend says, “The final result is 3!” Is your friend correct? If so, explain how your friend knew the final result. If not, explain why not.

Answer:
Yes, my friend is correct.

Explanation:

  1. Pick any number except 0.
    I have taken 2.
  2. Add 2 to your number.
    2 + 2 = 4
  3. Multiply the result by 3.
    4 x 3 = 12
  4. Subtract 6 from the result.
    12 – 6 = 6
  5. Divide the result by your original number.
    6/2 = 3

Lesson 3.4 Factoring Expressions

Factoring Expressions

EXPLORATION 1

Finding Dimensions
Work with a partner.
a. The models show the areas (in square units) of parts of rectangles.
Use the models to find the missing values that complete the expressions. Explain your reasoning.?
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 71
b. Are the expressions you wrote in part(a) equivalent to the original expressions? Explain your reasoning.
c. Explain how you can use the Distributive Property to find rational number factors of an expression.

Try It

Factor the expression using the GCF.

Question 1.
15x + 25

Answer:
15x + 25 = 5(3x + 5)

Explanation:
Find the G.C.F of 15x and 25
15x = 3 . 5 . x
25 = 5. 5
The common prime factor is 5.
So, the GCF of 15x and 25 is 5
Use the GCF to factor the expression
15x + 25 = 5(3x) + 5(5)
= 5(3x + 5)

Question 2.
4y – 20

Answer:
4y – 20 = 4(y – 5)

Explanation:
Find the G.C.F of 4y and 20
15x = 2 . 2 . y
20 = 2 . 2 . 5
The common prime factors are 2 . 2 = 4
So, the GCF of 4y and 20 is 4
Use the GCF to factor the expression
4y – 20 = 4(y) – 4(5)
= 4(y – 5)

Question 3.
36c + 24d

Answer:
36c + 24d = 12(3c + 2d)

Explanation:
The G.C.F of 36c, 24d is
36c = 2 . 2 . 3 . 3 . c
24d = 2 . 3 . 2 . 2 . d
The common prime factors are 2 . 2 . 3 = 12
The G.C.F of 36c, 24d is 12
Use the GCF to factor the expression
36c + 24d = 12(3c) + 12(2d)
= 12(3c + 2d)

Try It

Factor out the coefficient of the variable term.

Question 4.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 72

Answer:
½n – ½ = ½(n – 1)

Explanation:
Given that,
½n – ½
½n = ½ . n
½ = ½ . 1
Use the distributive property to factor out ½.
½n – ½ = ½(n) – ½(1)
= ½(n – 1)

Question 5.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 73

Answer:
3/4 p – 3/2 = 3/2(p/2 – 1)

Explanation:
Given that,
3/4 p – 3/2
3/2 = 3/2 . 1
3/4 p = 3/2 . 1/2 . p
Use the distributive property to factor out 3/2
3/4 p – 3/2 = 3/2(1/2 p) – 3/2(1)
= 3/2(p/2 – 1)

Question 6.
5 + 2.5q

Answer:
5 + 2.5q = 2.5(2 + q)

Explanation:
Given that,
5 + 2.5q
5 = 2.5 . 2
2.5 = 2.5 . 1
Use the distributive property to factor out 2.5
5 + 2.5q = 2.5(2) + 2.5(q)
= 2.5(2 + q)

Try It

Question 7.
Factor -5 out of -5d + 30.

Answer:
-5d + 30 = -5(d – 6)

Explanation:
Given that,
-5d + 30.
-5d = -5 . d
30 = 5 . 6 = -5 . -6
-5d + 30 = -5(d) – 5(-6)
= -5(d – 6)

Question 8.
Factor -4 out of -8k – 12.

Answer:
-8k – 12 = -4(2k + 3)

Explanation:
given that,
-8k – 12
-8k = -2 . 4 . k
-12 = -4 . 3
The G.C.f of -8k, -12 is -4.
-8k – 12 = -4(2k) – 4(3)
= -4(2k + 3)

Self-Assessment for Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

FACTORING OUT THE GCF
Factor the expression using the GCF.

Question 9.
16n – 24

Answer:
16n – 24 = 8(2n – 3)

Explanation:
Find the G.C.F of 16n, 24
16n = 2 . 2 . 2 . 2 . n
24 = 2 . 2 . 2 . 3
The G.C.F of 16n, 24 is 2 . 2 . 2 = 8
Use the GCF to factor the expression
16n – 24 = 8(2n)- 8(3)
= 8(2n – 3)

Question 10.
42a + 14b

Answer:
42a + 14b = 14(3a + b)

Explanation:
Find the G.C.F of 42a, 14b
42a = 2 . 3 . 7 . a
14b = 2 . 7 . b
The greatest common factor of 42a, 14b is 2 . 7 = 14
Use the GCF to factor the expression
42a + 14b = 14(3a) + 14(b)
= 14(3a + b)

FACTORING OUT A RATIONAL NUMBER
Factor out the coefficient of the variable term.

Question 11.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 74

Answer:
1/10 k – 7/10 = 1/10(k – 7)

Explanation:
Given that,
1/10 k – 7/10
The factors of 1/10, 7/10 are
1/10 = 1/10 . 1
7/10 = 7 . 1/10
Use the distributive property to factor out 1/10
1/10 k – 7/10 = 1/10 (k) – 1/10(7)
= 1/10(k – 7)

Question 12.
42 + 3.5h

Answer:
42 + 3.5h = 3.5(12 + h)

Explanation:
Find the factors of 42, 3.5
42 = 4 . 3 . 3.5
3.5 = 3.5 . 1
Use the distributive property to factor out 3.5
42 + 3.5h = 3.5(12) + 3.5(h)
= 3.5(12 + h)

FACTORING OUT A NEGATIVE NUMBER
Factor out the indicated number.

Question 13.
Factor -8 out of -3d + 56.

Answer:
-3d + 56 = -8(3d/8  – 7)

Explanation:
Get the factors of -3d, 56
-3d = 3d/8 . -8
56 = -7 . -8
Use the distributive property to factor out -8
-3d + 56 = -8(3d/8) – 8(-7)
= -8(3d/8  – 7)

Question 14.
Factor -12 out of -24k + 120.

Answer:
-24k + 120 = -12(2k – 10)

Explanation:
Get the factors of -24k, 120
-24k = -12. 2. k
120 = -12. -10
Use the distributive property to factor out -12
-24k + 120 = -12(2k) -12(-10)
= -12(2k – 10)

Question 15.
WRITING
Describe the relationship between using the Distributive Property to simplify an expression and to factor an expression. Give an example to justify your answer.

Answer:
The distributive property tells that a(b – c) = ab – ac and a(b + c) = ab + ac. It means you can seperate the common term and represent it as the factor.

Explanation:
The relationship between using the Distributive Property to simplify an expression and to factor an expression is mentioned here.
The distributive property tells that a(b – c) = ab – ac and a(b + c) = ab + ac. It means you can seperate the common term and represent it as the factor.
Let us take one example question 12x + 40y
The factors of 12x = 3 . 4 . x, the factors of 40y = 5 . 2 . 4 . y
The common factor is 4. So, take out the common factor and use the distribuyive property.
12x + 4y = 4(3x) + 4(10y)
= 4(3x + 10y)

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 16.
An organization drills 3 wells to provide access to clean drinking water. The cost (in dollars) to drill and maintain the wells for n years is represented by 34,500 + 540n. Write and interpret an expression that represents the cost to drill and maintain one well for n years.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 75

Answer:
The cost to drill and maintain one well for n years is 10(1150 + 18n).

Explanation:
The cost to drill and maintain 3 wells for n years is 34,500 + 540n
To get the drill and maintainance cost for 1 well, you need to find the factors
34500 = 10 . 10 . 3 . 5 . 23
540n = 3. 9 . 2 . 10 . n
The G.C.F of 34500 and 540n is 10 . 3 = 30
34,500 + 540n = 30(1150) + 30(18n)
= 30(1150 + 18n)
Divide the expression by 3 to get the drill and maintainance cost for 1 well
= 30(1150 + 18n)/ 3 = 10(1150 + 18n)
So, the cost to drill and maintain one well for n years is 10(1150 + 18n)

Question 17.
A photograph is 16 inches long and has an area of (16x + 96) square inches. A custom-made frame is 2 inches wide and costs $0.50 per square inch. Write an expression that represents the cost of the frame.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 76

Answer:
The cost of frame is $0.50(4x + 104)

Explanation:
Given that,
Length of photograph = 16 inches
Area of photograph = (16x + 96) sq inches
Factor out 16 from the expression
= 16(x) + 16(6) = 16(x + 6)
So, the width of the photograph is x + 6 inches
A custom-made frame is 2 inches wide and costs $0.50 per square inch.
The length of frame and photograph is 16 + 2 + 2 = 20 inches
The bredth of the frame & photograph is (x + 6 + 4) = x + 10 inches
Area of the photograph and frame = length . width
= 20(x + 10)
The area of frame = The area of photograph and frame – Area of photograph
= 20(x + 10) – (16x + 96)
= 20x + 200 – 16x – 96
= 4x + 104 sq inches
The cost of frame is $0.50 per square inch
So, the cost of the frame is 0.50(4x + 104).

Factoring Expressions Homework & Practice 3.4

Review & Refresh

Simplify the expression.

Question 1.
8(k – 5)

Answer:
8(k – 5) = 8k – 40

Explanation:
The given expression is 8(k – 5)
= 8(k) – 8(5)
= 8k – 40

Question 2.
-4.5(-6 + 2d)

Answer:
-4.5(-6 + 2d) = 27 – 9d

Explanation:
The given expression is -4.5(-6 + 2d)
= -4.5(-6) – 4.5(2d)
= 27 – 9d

Question 3.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 77

Answer:
-1/4 (3g – 6 – 5g) = 3/2 + g/2

Explanation:
The given expression is -1/4 (3g – 6 – 5g)
= -1/4(-6 – 2g)
= -1/4(-6) – 1/4(-2g)
= 3/2 + 1/2 g

Find the difference. Write fractions in simplest form.

Question 4.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 78

Answer:
2/3 – (-5/3) = 7/3

Explanation:
Given that,
2/3 – (-5/3) = 2/3 + 5/3
= (2 + 5)/3 = 7/3

Question 5.
-4.7 – 5.6

Answer:
-4.7 – 5.6 = -10.3

Explanation:
Given that,
-4.7 – 5.6 = -10.3

Question 6.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 79

Answer:
-4(3/8) – (-2(1/4) = -17/8

Explanation:
Given that,
-4(3/8) – (-2(1/4) = -35/8 – (-9/4)
= -35/8 + 9/4 = (-35 + 18)/8
= -17/8

Evaluate the expression when x = 4, y = -6, and z = -3.

Question 7.
y ÷ z

Answer:
y ÷ z = 2

Explanation:
Given expression is y ÷ z
Put y = -6, and z = -3
y ÷ z = -6 ÷ -3
= 6 ÷ 3 = 2

Question 8.
\(\frac{4 y}{2 x}\)

Answer:
4y/2x = -3

Explanation:
Given expression is 4y/2x
Put x = 4, y = -6
4y/2x =(4 x -6)/ (2 x 4)
= -24/8 = -3

Question 9.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 80

Answer:
(3x – 2y)/z = -8

Explanation:
Given expression is (3x – 2y)/z
Put x = 4, y = -6, and z = -3
= (3 x 4 – 2(-6))/-3
= (12 + 12)/-3
= 24/-3
= -24/3
= -8

Concepts, Skills, & Problem Solving
FINDING DIMENSIONS
The model shows the area (in square units) of each part of a rectangle. Use the model to find the missing values that complete the expression. Explain your reasoning. (See Exploration 1, p. 109.)

Question 10.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 81

Answer:
2.25x + 3 = 1.5(1.5x + 2)

Explanation:
Find the factors of 2.25x, 3
2.25x = 1.5 . 1.5 . x
3 = 1.5 . 2
So, 2.25x + 3 = 1.5(1.5x) +1.5(2)
= 1.5(1.5x + 2)

Question 11.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 82

Answer:
5/6 m + 2/3 n = 1/3(5m/2 + 2n)

Explanation:
Find the factors of 5m/6, 2n/3
5m/6 = 1/3 . 5/2 . m
2n/3 = 1/3 . 2 . n
So, 5/6 m + 2/3 n = 1/3(5m/2) + 1/3(2n)
= 1/3(5m/2 + 2n)

FACTORING OUT THE GCF
Factor the expression using the GCF.

Question 12.
9b + 21

Answer:
9b + 21 = 3(3b + 7)

Explanation:
The given expression is 9b + 21
Find the factors of 9b, 21
9b = 3 . 3 . b
21= 7 . 3
G.C.F of 9b, 21 is 3
Use the GCF to factor the expression
9b + 21 = 3(3b) + 3(7)
= 3(3b + 7)

Question 13.
32z – 48

Answer:
32z – 48 = 16(2z – 3)

Explanation:
The given expression is 32z – 48
Find the factors of 32z, -48
32z = 2 . 2 . 2 . 2 . 2 . z
48 = 2 . 2 . 2 . 2 . 3
G.C.F of 32z, -48 is 2 . 2 . 2 . 2 = 16
Use the GCF to factor the expression
32z – 48 = 16(2z) – 16(3)
= 16(2z – 3)

Question 14.
8x + 2

Answer:
8x + 2 = 2(4x + 1)

Explanation:
The given expression is 8x + 2
find the factors of 8x, 2
8x = 2 . 2 . 2 . x
2 = 2. 1
G.C.F of 8x, 2 is 2
Use the GCF to factor the expression
8x + 2 = 2(4x) + 2(1)
= 2(4x + 1)

Question 15.
3y – 24

Answer:
3y – 24 = 3(y – 4)

Explanation:
The given expression is 3y – 24
Find the factors of 3y, 24
3y = 3 . y
24 = 4 . 3
G.C.F of 3y, 24 is 3
Use the GCF to factor the expression
3y – 24 = 3(y) – 3(4)
= 3(y – 4)

Question 16.
14p – 28

Answer:
14p – 28 = 14(p – 2)

Explanation:
The given expression is 14p – 28
Find the factors of 14p, 28
14p = 7 . 2 . p
28 = 7 . 2 . 2
G.C.F of 14p, 28 is 14
Use the GCF to factor the expression
14p – 28 = 14(p) – 14(2)
= 14(p – 2)

Question 17.
6 + 16k

Answer:
6 + 16k = 2(3 + 8k)

Explanation:
The given expression is 6 + 16k
Find the factors of 6, 16k
6 = 2 . 3
16k = 2 . 2 . 2 . 2 . k
G.C.F of 6, 16k is 2
Use the GCF to factor the expression
6 + 16k = 2(3) + 2(8k)
= 2(3 + 8k)

Question 18.
21 – 14d

Answer:
21 – 14d = 7(3 – 2d)

Explanation:
The given expression is 21 – 14d
Get the factors of 21, 14d
21 = 7 . 3
14d = 7 . 2 . d
G.C.F of 21, 14d is 7
Use the GCF to factor the expression
21 – 14d = 7(3) – 7(2d)
= 7(3 – 2d)

Question 19.
20z – 8

Answer:
20z – 8 = 4(5z – 2)

Explanation:
The given expression is 20z – 8
Get the factors of 20z, 8
20z = 5 . 2 . 2 . z
8 = 2 . 2 . 2
G.C.F of 20z, 8 is 4
Use the GCF to factor the expression
20z – 8 = 4(5z) – 4(2)
= 4(5z – 2)

Question 20.
15w + 65

Answer:
15w + 65 = 5(3w + 13)

Explanation:
The given expression is 15w + 65
Get the factors of 15w, 65
15w = 5 . 3 . w
65 = 5 . 13
G.C.F of 15w, 65 is 5
Use the GCF to factor the expression
15w + 65 = 5(3w) + 5(13)
= 5(3w + 13)

Question 21.
36a + 16b

Answer:
36a + 16b = 4(9a + 4b)

Explanation:
The given expression is 36a + 16b
Get the factors of 36a, 16b
36a = 3 . 2 . 3 . 2 . a
16b = 2 . 2 . 2 . 2 . b
G.C.F of 36a, 16b is 4
Use the GCF to factor the expression
36a + 16b = 4(9a) + 4(4b)
= 4(9a + 4b)

Question 22.
21m – 49n

Answer:
21m – 49n = 7(3m + 7n)

Explanation:
The given expression is 21m – 49n
Get the factors of 21m, 49n
21m = 7 . 3 . m
49n = 7 . 7 . n
G.C.F of 21m, 49n
Use the GCF to factor the expression
21m – 49n = 7(3m) + 7(7n)
= 7(3m + 7n)

Question 23.
12 + 9g – 30h

Answer:
12 + 9g – 30h = 3(4 + 3g – 10h)

Explanation:
The given expression is 12 + 9g – 30h
Get the factors of 12, 9g, 30h
12 = 3 . 2 . 2
9g = 3 . 3 . g
30h = 3 . 5 . 2 . h
G.C.F of 12, 9g, 30h is 3
Use the GCF to factor the expression
12 + 9g – 30h = 3(4) + 3(3g) – 3(10h)
= 3(4 + 3g – 10h)

FACTORING OUT A RATIONAL NUMBER
Factor out the coefficient of the variable term.

Question 24.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 83

Answer:
1/7 a + 1/7 = 1/7 (a + 1)

Explanation:
The given expression is 1/7 a + 1/7
1/7a = 1/7 . a
1/7 = 1/7 . 1
Use the distributive property to factor out 1/7
1/7 a + 1/7 = 1/7(a) + 1/7(1)
= 1/7 (a + 1)

Question 25.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 84

Answer:
1/3 b – 1/3 = 1/3(b – 1)

Explanation:
The given expression is 1/3 b – 1/3
1/3b = 1/3 . b
1/3 = 1/3 . 1
Use the distributive property to factor out 1/3
1/3 b – 1/3 = 1/3(b) – 1/3(1)
= 1/3(b – 1)

Question 26.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 85

Answer:
3/8 d + 3/4 = 3/4(d/2 + 1)

Explanation:
The given expression is 3/8 d + 3/4
3/8 d = 3/4 . 1/2 . d
3/4 = 3/4 . 1
Use the distributive property to factor out 3/4
3/8 d + 3/4 = 3/4 (d/2) + 3/4(1)
= 3/4(d/2 + 1)

Question 27.
2.2x + 4.4

Answer:
2.2x + 4.4 = 2.2(x +2)

Explanation:
The given expression is 2.2x + 4.4
2.2x = 1.1 . 2 . x
4.4 = 1.1 . 2 . 2
Use the distributive property to factor out 2.2
2.2x + 4.4 = 2.2(x) + 2.2(2)
= 2.2(x +2)

Question 28.
1.5y – 6 = 1.5(y – 4)

Answer:
1.5y – 6

Explanation:
The given expression is 1.5y – 6
1.5y = 1.5 . y
6 = 1.5 . 2 . 2
Use the distributive property to factor out 1.5
1.5y – 6 = 1.5(y) – 1.5(4)
= 1.5(y – 4)

Question 29.
0.8w + 3.6

Answer:
0.8w + 3.6 = 0.8(w + 4.5)

Explanation:
The given expression is 0.8w + 3.6
0.8w = 0.8 . w
3.6 = 0.8 . 4.5
Use the distributive property to factor out 0.8
0.8w + 3.6 = 0.8(w) + 0.8(4.5)
= 0.8(w + 4.5)

Question 30.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 86

Answer:
15/4 + 3/8 x = 3/4(5 + x/2)

Explanation:
The given expression is 15/4 + 3/8 x
15/4 = 3/4 . 5
3/8x = 3/4 . 1/2 . x
Use the distributive property to factor out 3/4
15/4 + 3/8 x = 3/4(5) + 3/4(x/2)
= 3/4(5 + x/2)

Question 31.
4h – 3

Answer:
4h – 3 = 2(2h – 1.5)

Explanation:
The given expression is 4h – 3
4h = 2 . 2 h
3 = 2 . 1.5
Use the distributive property to factor out 2
4h – 3 = 2(2h) – 2(1.5)
= 2(2h – 1.5)

Question 32.
0.15c – 0.072

Answer:
0.15c – 0.072 = 0.03(5c – 2.4)

Explanation:
The given expression is 0.15c – 0.072
0.15c = 0.03 . 5 . c
0.072 = 0.03 . 2.4
Use the distributive property to factor out 0.03
0.15c – 0.072 = 0.03(5c) – 0.03(2.4)
= 0.03(5c – 2.4)

Question 33.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 87

Answer:
3/8 z + 1 = 1/8(3z + 8)

Explanation:
The given expression is 3/8 z + 1
3/8 z = 1/8 . 3 . z
1 = 1/8 . 8
Use the distributive property to factor out 1/8
3/8 z + 1 = 1/8(3z) + 1/8(8)
= 1/8(3z + 8)

Question 34.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 88

Answer:
6s – 3/4 = 3(2s – 1/4)

Explanation:
The given expression is 6s – 3/4
6s = 3 . 2 . s
3/4 = 3 . 1/4
Use the distributive property to factor out 3
6s – 3/4 = 3(2s) – 3(1/4)
= 3(2s – 1/4)

Question 35.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 89

Answer:
5/2 k – 2 = 1/2(5k – 4)

Explanation:
The given expression is 5/2 k – 2
5/2k = 1/2 . 5 . k
2 = 1/2 . 4
Use the distributive property to factor out 1/2
5/2 k – 2 = 1/2 (5k) – 1/2(4)
= 1/2(5k – 4)

YOU BE THE TEACHER
Your friend factors the expression. Is your friend correct? Explain your reasoning.

Question 36.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 90

Answer:
Wrong

Explanation:
Factors of 16p, 28
16p = 4 . 4 . p
28 = 4 . 7
Use the distributive property to factor out 4
16p – 28 = 4(4p) – 4(7)
= 4(4p – 7)

Question 37.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 91

Answer:
Correct.

Explanation:
Find the factors of 2/3y, 14/3
2/3y = 2 . 1/3 . y
14/3 = 2 . 7 . 1/3
Use the distributive property to factor out 2/3
2/3y – 14/3 = 2/3(y) – 2/3(7)
= 2/3(y – 7)

FACTORING OUT A NEGATIVE NUMBER
Factor out the indicated number.

Question 38.
Factor -4 out of -8d + 20.

Answer:
-4(2d – 5)

Explanation:
Given expression is -8d + 20
Find factors of 8d, 20
-8d = -4 . 2 . d
20 = -4. -5
Use the distributive property to factor out -4
-8d + 20 = -4(2d) – 4(-5)
= -4(2d – 5)

Question 39.
Factor -6 out of 18z – 15.

Answer:
18z – 15 = -6(-3z + 5/2)

Explanation:
Given expression is 18z – 15
Find factors of 18z, -15
18z = -6 . -3 . z
-15 = -3 . 5/2 . 2
Use the distributive property to factor out -6
18z – 15 = -6(-3z) – 6(5/2)
= -6(-3z + 5/2)

Question 40.
Factor -0.25 out of 7g+ 3.5.

Answer:
7g+ 3.5 = -0.25(-28g – 14)

Explanation:
Given expression is 7g+ 3.5
Find factors of 7g, 3.5
7g = -0.25 x -28 x g
3.5 = -0.25 x -14
Use the distributive property to factor out -0.25
7g+ 3.5 = -0.25(-28g) -0.25(-14)
= -0.25(-28g – 14)

Question 41.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 92

Answer:
-1/2 x + 6 = -1/2(x – 12)

Explanation:
Given expression is -1/2 x + 6
Find factors of -1/2 x, 6
-1/2x = -1/2 . x
6 = -1/2 . -4 . 3
Use the distributive property to factor out -1/2
-1/2 x + 6 = -1/2(x) – 1/2(-12)
= -1/2(x – 12)

Question 42.
Factor -1.75 out of -14m – 5.25n.

Answer:
-14m – 5.25n = -1.75(8m + 3n)

Explanation:
Given expression is -14m – 5.25n
Find factors of -14m, -5.25n
-14m = -1.75 . 8 . m
-5.25n = -1.75 . 3 . n
Use the distributive property to factor out -1.75
-14m – 5.25n = -1.75(8m) -1.75(3n)
= -1.75(8m + 3n)

Question 43.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 92.1

Answer:
-1/2 x – 5/4 y = -1/4(2x + 5y)

Explanation:
Given expression is -1/2 x – 5/4 y
Find factors of -1/2 x, – 5/4 y
-1/2x = -1/4 . 2. x
-5/4y = -1/4 . 5 . y
Use the distributive property to factor out -1/4
-1/2 x – 5/4 y = -1/4(2x) -1/4(5y)
= -1/4(2x + 5y)

Question 44.
STRUCTURE
A rectangle has an area of (4x + 12) square units. Write three multiplication expressions that can represent the product of the length and the width of the rectangle.

Answer:
Three multiplication expressions that can represent the product of the length and the width of the rectangle are1/2(4x + 24), 2(2x + 6), 4(x + 3).

Explanation:
Rectangle area is (4x + 12) square units
Find the factors of 4x, 12
4x = 2 . 2 . x
12 = 2 . 2 . 3
Use the distributive property to factor out 2
(4x + 12) = 2(2x) + 2(6)
= 2(2x + 6)
Area of rectangle = length . width
= 2(2x + 6)
Use the distributive property to factor out 4 of (4x + 12)
(4x + 12) = 4(x) + 4(3)
= 4(x + 3)
4x = 1/2 . 4x
12 = 1/2 . 6 . 4
Use the distributive property to factor out 1/2
(4x + 12) = 1/2(4x) + 1/2(24)
= 1/2(4x + 24)
So, three multiplication expressions that can represent the product of the length and the width of the rectangle are1/2(4x + 24), 2(2x + 6), 4(x + 3).

Question 45.
MODELING REAL LIFE
A square wrestling mat has a perimeter of (12x – 32) feet. Explain how to use the expression to find the length (in feet) of the mat. Justify your answer.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 93

Answer:
The expression that represents the length of the side of the mat is 3x – 8 feet.

Explanation:
The wrestling mat is a sqauare
Let a is the length of the side of a square
The perimeter of mat = 4 x side = 4 . a
12x – 32 = 4a
In order to find the length of the side of te mat we have to solve the equation above for a
4a = 12x – 32
a = (12x – 32)/4
a = 3x – 8 feet
The expression that represents the length of the side of the mat is 3x – 8 feet.

Question 46.
MODELING REAL LIFE
A table is 6 feet long and 3 feet wide. You extend the length of the table by inserting two identical leaves table. The extended table is rectangular with an area of (18 + 6x) square feet. Write and interpret an expression that represents the length (in feet) of the extended table.

Answer:
The length of the extended table is 6 + 2x

Explanation:
A table is 6 feet long and 3 feet wide.
Table area = length. width
= 6 . 3 = 18 sq feet
The extended table is rectangular with an area of (18 + 6x) square feet.
Find factors of 18, 6x
18 = 3 . 6
6x = 3 . 2 . x
(18 + 6x) = 3(6) + 3(2x)
= 3(6 + 2x)
So, the length of the extended table is 6 + 2x

Question 47.
DIG DEEPER!
A three-dimensional printing pen uses heated plastic to create three-dimensional objects. A kit comes with one 3D-printing pen and packages of plastic. An art club purchases 6 identical kits for (180 + 58.5p) dollars. Write and interpret an expression that represents the cost of one kit.
Big Ideas Math Answers Grade 7 Chapter 3 Expressions 94

Answer:
The cost of one kit is (30 + 9.75) dollars.

Explanation:
Art club purchases 6 identical kits for (180 + 58.5p) dollars
Divide (180 + 58.5p) by 6 to get the cost of one kit
= (180 + 58.5p) / 6
= 180/6 + 58.5p/6
= 30 + 9.75
Hence, the cost of one kit is (30 + 9.75) dollars.

Question 48.
STRUCTURE
The area of the trapezoid is Big Ideas Math Answers Grade 7 Chapter 3 Expressions 95.1 square centimeters. Write two different pairs of expressions that represent the possible base lengths (in centimeters). Justify your answers.
Big Ideas Math Answer Key Grade 7 Chapter 3 Expressions 95

Answer:
(3x – 1)/2

Explanation:
Area of the trapezoid = height * (sum of parallel lengths)/2
= (3x/4 – 1/4)
= (3x – 1)/4
Here height is 1/2
So, base length is (3x – 1)/2

Expressions Connecting Concepts

3 Connecting Concepts

Using the Problem-Solving Plan

Question 1.
The runway shown has an area of (0.05x + 0.125) square miles. Write an expression that represents the perimeter (in feet) of the runway.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 96
Understand the problem
You know the area of the rectangular runway in square miles and the width of the runway in miles. You want to know the perimeter of the runway in feet.
Make a plan.
Factor the width of 0.05 mile out of the expression that represents the area to find an expression that represents the length of the runway. Then write an expression that represents the perimeter (in miles) of the runway. Finally, use a measurement conversion to write the expression in terms of feet.
Solve and check.
Use the plan to solve the problem. Then check your solution.

Answer:
The perimeter of the runway is 2(x + 2.55) miles.

Explanation:
The runway shown has an area of (0.05x + 0.125)
= 0.05(x) + 0.05(2.5)
= 0.05(x + 2.5)
The length of the run way is (x + 2.5) miles
Width = 0.05
Perimeter of the runway = 2(length + width)
= 2(x + 2.5 + 0.05)
= 2(x + 2.55)

Question 2.
The populations of two towns after t years can be modeled by -300t + 7000 and -200t + 5500. What is the combined population of the two towns after years? The combined population of the towns in Year 10 is what percent of the combined population in Year 0?
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 97

Answer:
The combined population of two towns after t years is -500t + 12500.
The combined population of the towns in 10 Years is 60% of the combined population in Year 0.

Explanation:
The populations of two towns after t years can be modeled by -300t + 7000 and -200t + 5500
The combined population of two towns after t years = -300t + 7000 + (-200t + 5500)
= -300t + 7000 – 200t + 5500
= -500t + 12500
The combined population of the towns in 10 Years = -500(10) + 12500
= -5000 + 12500 = 7500
The combined population in Year 0 = -500(0) + 12500
= 12500
The combined population of the towns in 10 Years is what percent of the combined population in Year 0 is 7500/12500 x 100
= 7500/125 = 60
So, The combined population of the towns in 10 Years is 60% of the combined population in Year 0.

Performance Task

Chlorophyll in Plants

At the beginning of this chapter, you watched a STEAM Video called “Tropic Status.” You are now ready to complete the performance task related to this video, available at BigIdeasMath.com. Be sure to use the problem-solving plan as you work through the performance task.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 98

Expressions Chapter Review

3 Chapter Review

Review Vocabulary

Write the definition and give an example of each vocabulary term.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 99

Graphic Organizers

You can use an Example and Non-Example Chart to list examples and non-examples of a concept. Here is an Example and Non-Example Chart for like terms.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 100

Choose and complete a graphic organizer to help you study the concept.

  1. simplest form
  2. equivalent expressions
  3. linear expression
  4. Distributive Property
  5. factoring an expression

Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 101

Chapter Self-Assessment

As you complete the exercises, use the scale below to rate your understanding of the success criteria in your journal.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 102

3.1 Algebraic Expressions (pp. 91–96)

Identify the terms and like terms in the expression.

Question 1.
z + 8 – 4z

Answer:
Like terms are z, -4z
Terms are z, 8, -4z

Explanation:
Like terms are z, -4z
Terms are z, 8, -4z

Question 2.
3n + 7 – n – 3

Answer:
Like terms are 3n, -n
Terms are 3n, 7, -n, -3

Explanation:
Like terms are 3n, -n
Terms are 3n, 7, -n, -3

Question 3.
10x2 – y + 12 – 2x2

Answer:
Like terms are10x², -2x²
Terms are 10x², -y, 12, -2x²

Explanation:
Like terms are10x², -2x²
Terms are 10x², -y, 12, -2x²

Simplify the expression.

Question 4.
4h – 8h

Answer:
4h – 8h = -4h

Explanation:
The given expression is 4h – 8h
= -4h

Question 5.
6.4r – 7 – 2.9r

Answer:
6.4r – 7 – 2.9r = 3.5r – 7

Explanation:
The given expression is 6.4r – 7 – 2.9r
= 3.5r – 7

Question 6.
2m – m – 7m

Answer:
2m – m – 7m = -6m

Explanation:
The given expression is 2m – m – 7m
= 2m – 8m = -6m

Question 7.
6y + 9 + 3y – 7

Answer:
6y + 9 + 3y – 7 = 9y + 2

Explanation:
The given expression is 6y + 9 + 3y – 7
= 9y + 2

Question 8.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 103

Answer:
3/5 x + 19 – 3/20 x – 7 = 9x/20 + 12

Explanation:
The given expression is 3/5 x + 19 – 3/20 x – 7
= 3x/5 + 19 – 3x/20 – 7
= (12x – 3x)/20 + 19 – 7
= 9x/20 + 12

Question 9.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 104

Answer:
2/3 y + 14 – 1/6 y – 8 = y/2 + 6

Explanation:
The given expression is 2/3 y + 14 – 1/6 y – 8
= (4y – y)/6 + 14 – 8
= 3y/6 + 6
= y/2 + 6

Question 10.
Write an expression with 4 different terms that is equivalent to 5x2 – 8. Justify your answer.

Answer:
5x² – 8 = 3x² + 2x² – 6 – 2

Explanation:
Given expression is 5x² – 8
= 3x² + 2x² – 6 – 2

Question 11.
Find the earnings for selling the same number of each type of sandwich. Justify your answer.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 105

Answer:
The earnings in turkey is 2.25x + 1.15y
The earnings in Ham is 1.55x + 1.30y

Explanation:
Let us take the earnings for selling pretzel roll sandwich is x, begel sandwich is y
So, The earnings in turkey is 2.25x + 1.15y
The earnings in Ham is 1.55x + 1.30y

Question 12.
You buy the same number of brushes, rollers, and paint cans.
a. Write and interpret an expression in simplest form that represents the total amount of money you spend on painting supplies.
b. How much do you spend when you buy one set of supplies for each of 3 painters?
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 106

Answer:
a. The total amount of money you spend on painting supplies is 32.67x
b. The cost of one set of supplies for each of 3 painters is $98.01.

Explanation:
a.
let us take you buy the x number of brushes, rollers, and paint cans.
So, the amount sped to buy those is 3.99x + 21.79x + 6.89x
= x(3.99 + 21.79 + 6.89)
= x(32.67)
b. The cost for 1 set of painting supplies = (3.99 + 21.79 + 6.89)
= 32.67
The cost for 3 sets of painting supplies = 3(32.67)
= 98.01

3.2 Adding and Subtracting Linear Expressions (pp. 97–102)

Find the sum.

Question 13.
(c – 4) + (3c + 9)

Answer:
(c – 4) + (3c + 9) = 4c + 5

Explanation:
The given expression is (c – 4) + (3c + 9)
= c – 4 + 3c + 9
= 4c + 5

Question 14.
(5z + 4) + (3z – 6)

Answer:
(5z + 4) + (3z – 6) = 8z- 2

Explanation:
The given expression is (5z + 4) + (3z – 6)
= 5z + 4 + 3z – 6
= 8z- 2

Question 15.
(-2.1m – 5) + (3m – 7)

Answer:
(-2.1m – 5) + (3m – 7) = 0.9m – 12

Explanation:
The given expression is (-2.1m – 5) + (3m – 7)
= -2.1m – 5 + 3m – 7
= 0.9m – 12

Question 16.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 107

Answer:
(5/4 q + 1) + (q – 4) + (-1/4 q + 2) = 2q – 1

Explanation:
The given expression is (5/4 q + 1) + (q – 4) + (-1/4 q + 2)
= 5/4 q + 1 + q – 4 -1/4 q + 2
= (5q – q)/4 + q + 3 – 4
= 4q/4 + q – 1
= q + q – 1
= 2q – 1

Find the difference.

Question 17.
(x – 1) – (3x + 2)

Answer:
(x – 1) – (3x + 2) = -2x – 3

Explanation:
The given expression is (x – 1) – (3x + 2)
= x – 1 – 3x – 2
= -2x – 3

Question 18.
(4y + 3) – (2y – 9)

Answer:
(4y + 3) – (2y – 9) = 2y + 12

Explanation:
The given expression is (4y + 3) – (2y – 9)
= 4y + 3 – 2y + 9
= 2y + 12

Question 19.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 108

Answer:
(1/2 h + 7) – (3/2 h + 9) = -h – 2

Explanation:
The given expression is  (1/2 h + 7) – (3/2 h + 9)
= 1/2 h + 7 – 3/2 h – 9
= (1 – 3)/2 h – 2
= -2h/2 – 2
= -h – 2

Question 20.
(4 – 3.7b) – (-5.4b – 4) – (1.2b + 1)

Answer:
(4 – 3.7b) – (-5.4b – 4) – (1.2b + 1) = 7 – 0.5b

Explanation:
The given expression is (4 – 3.7b) – (-5.4b – 4) – (1.2b + 1)
= 4 – 3.7b + 5.4b + 4 – 1.2b – 1
= 7 – 4.9b + 5.4b
= 7 – 0.5b

Question 21.
A basket holds apples. You pick (2n – 3) apples, and your friend picks (n + 4) apples. How many apples do you and your friend pick together? How many baskets do you need to carry all the apples? Justify your answer.

Answer:
The number of apples you and your friend picked is 3n + 1.

Explanation:
The number of apples you picked = 2n – 3
The number of apples your friend picked = n + 4
The number of apples you and your friend picked = (2n – 3) + (n + 4)
= 3n + 1
The number of apples you and your friend picked is 3n + 1

Question 22.
Greenland has a population of x people. Barbados has a population of about 4500 more than 5 times the population of Greenland. Find and interpret the difference in the populations of these two countries.

Answer:
The difference in the populations of these two countries is 4500 + 4x.

Explanation:
Greenland population = x
Barbados population = 4500 + 5x
The difference in the populations of these two countries = 4500 + 5x – x
= 4500 + 4x

3.3 The Distributive Property (pp. 103–108)

Simplify the expression.

Question 23.
2(a – 3)

Answer:
2(a – 3) = 2a – 6

Explanation:
The given expression is 2(a – 3)
= 2(a) – 2(3)
= 2a – 6

Question 24.
-3(4x – 10)

Answer:
-3(4x – 10) = -12x + 30

Explanation:
The given expression is -3(4x – 10)
= -3(4x) + 3(10)
= -12x + 30

Question 25.
-2.5(8 – b)

Answer:
-2.5(8 – b) = -20 + 2.5b

Explanation:
The given expression is -2.5(8 – b)
= -2.5(8) + 2.5(b)
= -20 + 2.5b

Question 26.
-7(1 – 3d – 5)

Answer:
-7(1 – 3d – 5) = 21d + 28

Explanation:
The given expression is -7(1 – 3d – 5)
= -7(-3d – 4)
= -7(-3d) – 7(-4)
= 21d + 28

Question 27.
9(-3w – 6.2 + 2w)

Answer:
9(-3w – 6.2 + 2w) = -9w – 55.8

Explanation:
The given expression is 9(-3w – 6.2 + 2w)
= 9(-w – 6.2)
= 9(-w) – 9(6.2)
= -9w – 55.8

Question 28.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 109

Answer:
3/4 (8g – 1/4 – 2/3 g) = 11g/2 – 3/8

Explanation:
The given expression is 3/4 (8g – 1/4 – 2/3 g)

= 3/4((24g – 2g)/3 – 1/4)
= 3/4(22g/3 – 1/4)
= 3/4(22g/3) – 3/4(1/4)
= 11g/2 – 3/8

Question 29.
Mars has m moons. The number of moons of Pluto is one more than twice the number of moons of Mars. The number of moons of Neptune is one less than 3 times the number of moons of Pluto. Write and interpret a simplified expression that represents the number of moons of Neptune.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 109.1

Answer:
The number of moons of Neptune is 6m + 2.

Explanation:
Number of moons of marks = m
The number of moons of pluto = 1 + 2m
The number of moons of Neptune = 3(1 + 2m) – 1
= 3 + 6m – 1 = 6m + 2

Simplify the expression.

Question 30.
3( 2 + q) + 15

Answer:
3( 2 + q) + 15 = 21 + 3q

Explanation:
The given expression is 3( 2 + q) + 15
= 3(2) + 3(q) + 15
= 6 + 3q + 15
= 21 + 3q

Question 31.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 110

Answer:
1/8 (16m – 8) – 17 = 2m – 18

Explanation:
The given expression is 1/8 (16m – 8) – 17
= 1/8(16m) + 1/8(-8) – 17
= 2m – 1 – 17
= 2m – 18

Question 32.
-1.5(4 – n) + 2.8

Answer:
-1.5(4 – n) + 2.8 = -3.2 + 1.5n

Explanation:
The given expression is -1.5(4 – n) + 2.8
= -1.5(4)- 1.5(-n) + 2.8
= -6 + 1.5n + 2.8
= -3.2 + 1.5n

Question 33.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 111

Answer:
2/5 (d – 10) – 2/3 (d + 6) = -4d/15 – 8

Explanation:
The given expression is 2/5 (d – 10) – 2/3 (d + 6)
= 2/5(d) + 2/5(-10) – 2/3(d) – 2/3(6)
= 2d/5 – 4 – 2d/3 – 4
= (6d – 10d)/15 – 8
= -4d/15 – 8

Question 34.
The expression for degrees Fahrenheit is Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 112 where C represents degrees Celsius. The temperature today is 5 degrees Celsius more than yesterday. Write and simplify an expression for the difference in degrees Fahrenheit for these two days.

Answer:
The difference in degrees Fahrenheit for these two days 9 degrees celsius.

Explanation:
The expression for degrees Fahrenheit is 9/5 C + 32
The temperature today is 5 degrees Celsius more than yesterday.
Today temperature = 9/5 (x + 5) + 32
Yesterday Temperature = 9/5 x + 32
The difference in degrees Fahrenheit for these two days = 9/5 (x + 5) + 32 – ( 9/5 x + 32)
= 9/5(x) + 9/5(5) + 32 – 9/5 x – 32
= 9x/5 + 9 + 32 – 9x/5 – 32
= 9

3.4 Factoring Expressions (pp. 109–114)

Factor the expression using GCF.

Question 35.
18a – 12

Answer:
18a – 12 = 6(3a – 2)

Explanation:
The G.C.F of 18a, 12 is
18a = 2 . 3 . 3 . a
12 = 3 . 2 . 2
The common prime factors are 2 . 3 = 6
The G.C.F of 18a, 12 is 6
Use the GCF to factor the expression
18a – 12 = 6(3a) – 6(2)
= 6(3a – 2)

Question 36.
2b + 8

Answer:
2b + 8 = 2(b + 3)

Explanation:
The G.C.F of 2b, 8 is
2b = 2 . b
8 = 2 . 2 . 2
The common prime factors are 2
The G.C.F of 2b, 8 is 2
Use the GCF to factor the expression
2b + 8 = 2(b) + 2(3)
= 2(b + 3)

Question 37.
9 – 15x

Answer:
9 – 15x = 3(3 – 5x)

Explanation:
The G.C.F of 9, 15x is
9 = 3 . 3
15x = 3 . 5 . x
The common prime factor is 3
The G.C.F of 9, 15x is 3
Use the GCF to factor the expression
9 – 15x = 3(3) – 3(5x)
= 3(3 – 5x)

Factor out the coefficient of the variable term.

Question 38.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 112.1

Answer:
1/4 y + 3/8 = 1/4(y + 3/2)

Explanation:
Find the factors of 1/4 y, 3/8
1/4y = 1/4 . y
3/8 = 1/4 . 1/2 . 3
Use the distributive property to factor out 1/4
1/4 y + 3/8 = 1/4(y) + 1/4(3/2)
= 1/4(y + 3/2)

Question 39.
1.7j – 3.4

Answer:
1.7j – 3.4 = 1.7(j – 2)

Explanation:
Find the factors of 1.7j, 3.4
1.7j = 1.7 . j
3.4 = 1.7 . 2
Use the distributive property to factor out 1.7
1.7j – 3.4 = 1.7(j) – 1.7(2)
= 1.7(j – 2)

Question 40.
-5p + 20

Answer:
-5p + 20 = 5(-p + 4)

Explanation:
Find the factors of 5p, 20
5p = 5 . p
20 = 5 . 4
Use the distributive property to factor out 5
-5p + 20 = 5(-p) + 5(4)
= 5(-p + 4)

Question 41.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 113

Answer:
3/2 x – 9/4y = -3/4(-2 + 3y)

Explanation:
Find the factors of 3/2 x , -9/4 y
3/2x = -3/4 . -2
-9/4 y = -3/4 . 3 . y
Use the distributive property to factor out -3/4
3/2 x – 9/4y = -3/4(-2) – 3/4(3y)
= -3/4(-2 + 3y)

Question 42.
You and 4 friends are buying tickets for a concert. The cost to buy one ticket is c dollars. If you buy all the tickets together, there is a discount and the cost is (5c – 12.5) dollars. How much do you save per ticket when you buy the tickets together?

Answer:
The amount saved by buying all tickets is 12.5 dollars.

Explanation:
The cost per 1 ticket is c
The cost to buy 5 tickets = 5c dollars
If you buy all the tickets together, there is a discount and the cost is (5c – 12.5) dollars
The amount saved by buying all tickets = 5c – (5c – 12.5) dollars
= 5c – 5c + 12.5
= 12.5 dollars

Question 43.
The rectangular pupil of an octopus is estimated to be 20 millimeters long with an area of (20x – 200) square millimeters. Write an expression that represents the perimeter (in millimeters) of the octopus pupil.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 114

Answer:
Perimeter the octopus pupil is 2x milli meters.

Explanation:
The length of an octopus pupil = 20 millimeters
Area of an octopus = (20x – 200) sq milli meters
Factor 20 out of (20x – 200)
= 20(x) – 20(10)
= 20(x – 20)
So, the width of the octopus pupil = x – 20 milli meters
The perimeter of octopus pupil = 2(length + width)
= 2(20 + (x – 20))
= 2(20 + x – 20)
= 2x milli meters
Perimeter the octopus pupil is 2x milli meters.

Question 44.
A building block has a square base that has a perimeter of (12x – 9) inches. Explain how to use the expression to find the length (in inches) of the wall shown.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 114.1

Answer:
The length of the wall is 7(3x – 9/4) inches

Explanation:
The perimeter of the square base = (12x – 9) inches
4 x length of the base = (12x – 9)
length of the base = (12x/4 – 9/4)
= (3x – 9/4) inches
The length of wall = 7(3x – 9/4)

Expressions Practice Test

3 Practice Test

Question 1.
Identify the terms and like terms in 4x + 9x2 – 2x + 2.

Answer:
The terms are 4x, 9x², -2x, 2
The like terms are 4x -2x

Explanation:
The given expression is 4x + 9x² – 2x + 2
The terms are 4x, 9x², -2x, 2
The like terms are 4x -2x

Simplify the expression.

Question 2.
8x – 5 + 2x

Answer:
8x – 5 + 2x = 10x – 5

Explanation:
The given expression is 8x – 5 + 2x
= 10x – 5

Question 3.
2.5w – 3y + 4w

Answer:
2.5w – 3y + 4w = 6.5w – 3y

Explanation:
The given expression is 2.5w – 3y + 4w
= 6.5w – 3y

Question 4.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 115

Answer:
5/7 x + 15 – 9/14 x – 9 = x/14 + 6

Explanation:
The given expression is 5/7 x + 15 – 9/14 x – 9
= (10x – 9x)/14 + 15 – 9
= x/14 + 6

Question 5.
(3j + 11) + (8j – 7)

Answer:
(3j + 11) + (8j – 7) = 11j + 4

Explanation:
The given expression is (3j + 11) + (8j – 7)
= 3j + 11 + 8j – 7
= 11j + 4

Question 6.
(2r – 13) – (-6r + 4)

Answer:
(2r – 13) – (-6r + 4) = 8r – 17

Explanation:
The given expression is (2r – 13) – (-6r + 4)
= 2r – 13 + 6r – 4
= 8r – 17

Question 7.
-2(4 – 3n)

Answer:
-2(4 – 3n) = -8 + 6n

Explanation:
The given expression is -2(4 – 3n)
= -2(4) – 2(-3n)
= -8 + 6n

Question 8.
3(5 – 2n) + 9n

Answer:
3(5 – 2n) + 9n = 15 + 3n

Explanation:
The given expression is 3(5 – 2n) + 9n
= 3(5) – 3(2n) + 9n
= 15 – 6n + 9n
= 15 + 3n

Question 9.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 116

Answer:
1/3 (6x + 9) – 2 = 2x + 1

Explanation:
The given expression is 1/3 (6x + 9) – 2
= 1/3 (6x) + 1/3(9) – 2
= 2x + 3 – 2
= 2x + 1

Question 10.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 117

Answer:
3/4 (8p + 12) + 3/8 (16p – 8) = 12p + 6

Explanation:
The given expression is 3/4 (8p + 12) + 3/8 (16p – 8)
= 3/4(8p) + 3/4(12) + 3/8(16p) + 3/8(-8)
= 3(2p) + 3(3) + 3(2p) + 3(-1)
= 6p + 9 + 6p – 3
= 12p + 6

Question 11.
-2.5(2s – 5) – 3(4.5s – 5.2)

Answer:
-2.5(2s – 5) – 3(4.5s – 5.2) = -18.5s + 28.1

Explanation:
The given expression is -2.5(2s – 5) – 3(4.5s – 5.2)
= -2.5(2s) – 2.5(-5) – 3(4.5s) – 3(-5.2)
= -5s + 12.5 – 13.5s + 15.6
= -18.5s + 28.1

Factor out the coefficient of the variable term.

Question 12.
6n – 24

Answer:
6n – 24 = 6(n – 4)

Explanation:
Find the factors of 6n, 24
6n = 6 . n
24 = 6 . 4
Use the distributive property to factor out 6
6n – 24 = 6(n) – 6(4)
= 6(n – 4)

Question 13.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 118

Answer:
1/2 q + 5/2 = 1/2(q + 5)

Explanation:
Find the factors of 1/2 q, 5/2
1/2q = 1/2 . q
5/2 = 5 . 1/2
Use the distributive property to factor out 1/2
1/2 q + 5/2 = 1/2(q) + 1/2(5)
= 1/2(q + 5)

Question 14.
-4x + 36

Answer:
-4x + 36 = 4(-x + 9)

Explanation:
Find the factors of 4x, 36
4x = 4 . x
36 = 4 . 9
Use the distributive property to factor out 4
-4x + 36 = 4(-x) + 4(9)
= 4(-x + 9)

Question 15.
Find the earnings for giving a haircut and a shampoo to m men and w women. Justify your answer.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 119

Answer:
The earnings for giving a haircut and a shampoo to women is 45w + 12w
The earnings for giving a haircut and a shampoo to men is 15m + 7m

Explanation:
The earning for giving haircut to women is 45w
The earning for giving shampoo to women is 12w
The earning for giving haircut to men is 15m
The earning for giving shampoo to men is 7m
The earnings for giving a haircut and a shampoo to women is 45w + 12w
The earnings for giving a haircut and a shampoo to men is 15m + 7m

Question 16.
The expression 15x + 11 represents the perimeter of the trapezoid. What is the length of the fourth side? Explain your reasoning.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 120

Answer:
The length of the fourth side of trapezoid is 6x + 5.

Explanation:
Perimeter of the trapezoid = 15x + 11
2x + 3 + 3x + 4 + 4x – 1 + fourth side length = 15x + 11
9x + 7 – 1 + fourth side length = 15x + 11
9x + 6 + fourth side length = 15x + 11
fourth side length = (15x + 11) – (9x + 6)
= 15x + 11 – 9x – 6
= 6x + 5

Question 17.
The maximum number of charms that will fit on a bracelet is Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 121, where d is the diameter(in centimeters) of the bracelet.
a. Write and interpret a simplified expression that represents the maximum number of charms on a bracelet.
b. What is the maximum number of charms that fit on a bracelet that has a diameter of 6 centimeters?

Answer:
a. The maximum number of charms that will fit on a bracelet = 3d – 2
b. The maximum number of charms that fit on a bracelet that has a diameter of 6 centimeters is 16.

Explanation:
a. The maximum number of charms that will fit on a bracelet = 3(d – 2/3)
= 3(d) – 3(2/3)
= 3d – 2
b. The maximum number of charms that fit on a bracelet that has a diameter of 6 centimeters is 3(6) – 2
= 18 – 2 = 16

Question 18.
You expand a rectangular garden so the perimeter is now twice the perimeter of the old garden. The expression 12w + 16 represents the perimeter of the new garden, where w represents the width of the old garden.
a. Write an expression that represents the perimeter of the old garden. Justify your answer.
b. Write an expression that represents the area of the old garden.

Answer:
a. Perimeter of old rectangular garden is 6w + 8
b. The area of the old garden is 12w.

Explanation:
a. New garden perimeter = 2 * perimeter of old garden
(12w + 16) = 2 * perimeter of old garden
(12w/2 + 16/2) = Perimeter of old garden
6w + 8 = Perimeter of old garden
b. Perimeter of old rectangular garden is 6w + 8
Find the factors of 6w, 8
6w = 2 . 3 . w
8 = 2 . 2 . 2
Use the distributive property to factor out 2
6w + 8 = 2(3w) + 2(4)
= 2(3w + 4)
Perimeter of old garden = 2(length + width) = 2(3w + 4)
So, length of the garden is 3w, width of the garden is 4
The area of old garden = length . width
= 3w . 4 = 12w

Expressions Cumulative Practice

Question 1.
What is the simplified form of the expression?
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 121.1
A. -3.6x
B. 6x – 5
C. 1.4x – 5
D. 3.7x – 7.3

Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 122

Answer:
C. 1.4x – 5

Explanation:
The given expression is 3.7x – 5 – 2.3x
= 1.4x – 5

Question 2.
What is the value of the expression when c = 0 and d = -6?
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 123
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 124

Answer:
-9.

Explanation:
The give expression is (cd – d²)/4
Put c = 0, d= -6 in above expression
= (0 . -6 – (-6)²)/4
= -(36)/4
= -9

Question 3.
What is the value of the expression?
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 125
F. -52
G. -24
H. 24
I. 52

Answer:
G. -24

Explanation:
The given expression is -38 – (-14)
= -38 + 14 = -24

Question 4.
The daily low temperatures for a week are shown.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 126
What is the mean low temperature of the week?
A. −2°F
B. 6°F
C. 8°F
D. 10°F

Answer:
The mean low temperature of the week is 6°F.

Explanation:
The list of low temperatures are -2°F, -3°F, -1°F, 8°F, 10°F, 12°F, 18°F
The mean temperature of the week = sum of the observations/ number of observations
= (-2 – 3 – 1 + 8 + 10 + 12 + 18)/7
= (-6 + 48)/7
= 42/7
= 6°F
The mean low temperature of the week is 6°F.

Question 5.
You and a friend collect seashells on a beach. After h minutes, you have collected (11 + 2h) seashells and your friend has collected (5h – 2) seashells. How many total seashells have you and your friend collected?
F. 7h + 9
G. 3h – 13
H. 16h
I. 7h + 13

Answer:
F. 7h + 9

Explanation:
The number of seashells collected by you = (11 + 2h)
The number of seashells collected by your friend = (5h – 2)
The total seashells have you and your friend collected = The number of seashells collected by you + The number of seashells collected by your friend
= 11 + 2h + 5h – 2
= 9 + 7h

Question 6.
What is the value of the expression?
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 127

Answer:
-0.28 ÷ (-0.07) = 4

Explanation:
The value of the expression is -0.28 ÷ (-0.07)
= 0.28 ÷ 0.07 = 4

Question 7.
Which list is ordered from least to greatest?
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 128

Answer:
D.

Explanation:
A. -3/4, -1/2, 3/8, -1/4, 7/8 is not in the order
B. -1/2, -1/4, 3/8, -3/4, 7/8 is not in the order
C. 7/8, 3/8, -1/4, -1/2, -3/4 is not in the order
D. -3/4, -1/2, -1/4, 3/8, 7/8 is in the order from least to greatest.

Question 8.
Which number is equivalent to the expression shown?
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 129

Answer:
H. 6(1/8)

Explanation:
-2(1/4) – (-8(3/8)) = -9/4 + 67/8
= (-18 + 67)/8 = 49/8
= 6(1/8)

Question 9.
What is the simplified form of the expression?
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 130
A. 15x + 30
B. x – 12
C. 13x + 12
D. -11x

Answer:
B. x – 12

Explanation:
The given expression is 7x – 2(3x + 6)
= 7x – 2(3x) – 2(6)
= 7x – 6x – 12
= x – 12

Question 10.
Which expression is not equivalent to the expression?
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 131
F. 6(12m – 10)
G. 4(18m – 15)
H. 12m
I. 12(6m – 5)

Answer:
I. 12(6m – 5)

Explanation:
The given expression is 72m – 60
Find the factors of 72m, 60
72m = 2 . 2 . 3 . 3 . 2 . m
60 = 2 . 2 . 3 . 5
The G.C.F of 72m, 60 is 2 . 2 . 3 = 12
72m – 60 = 12(6m) – 12(5)
= 12(6m – 5)

Question 11.
You want to buy a bicycle with your friend. You have $43.50 saved and plan to save an additional $7.25 every week. Your friend has $24.50 saved and plans to save an additional $8.75 every week.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 132
Part A
Simplify and interpret an expression that represents the amount of money you and your friend save after weeks.
Part B
After 10 weeks, you and your friend use all of the money and buy the bike. How much does the bike cost? Who pays more towards the cost of the bike? Explain your reasoning.

Answer:
A. The total amount of money you and your friend saved after x weeks is 68 + 16x
B. The cost of the bike is 228 dollars
You will pay more money towards the bike.

Explanation:
A. Let the number of weeks we need to save be x
The amount you saved 43.50 + 7.25x
The amount your friend saved = 24.50 + 8.75x
The total amount of money you and your friend saved after x weeks is 43.50 + 7.25x + 24.50 + 8.75x
= 68 + 16x
B. The amount saved after 10 weeks is
The amount you saved = 43.50 + 7.25(10) = 43.50 + 72.5 = 116
The amount your friend saved = 24.50 + 8.75(10) = 24.50 + 87.5 = 112
The cost of bike = The amount you saved + The amount your friend saved
= 116 + 112 = 228 dollars
You will pay more money towards the bike.

Question 12.
Your friend evaluated 3 + x2 ÷ y when x = 2 and y = 4.
Big Ideas Math Solutions Grade 7 Chapter 3 Expressions 133
What should your friend do to correct his error?
A. Divide 3 by 4 before subtracting.
B. Square -2, then divide.
C. Divide -2 by 4, then square.
D. Subtract 4 from 3 before dividing.

Answer:
B. Square -2, then divide.

Explanation:
The given expression is 3 + x2 ÷ y
Put x = 2 and y = 4
= 3 + 2² ÷ 4
= 3 + 4 ÷  4
= 3 + 1
= 4

Conclusion:

To help all the candidates, we have provided Chapter 3 Expressions in this article. Just click on the respective direct link and download the pdf and start your preparation and learn all the fundamentals which are included in it. Bookmark our website of Big Ideas Math Answers and get the solutions to Grade 7 chapters. If you bookmark our page, you will get instant updates of all 7th Grade chapters.

Big Ideas Math Answers Grade 6 Chapter 4 Percents

Big Ideas Math Answers Grade 6 Chapter 4 Percents

Follow our Big Ideas Math Book 6th Grade Answer key chapter 4 Percents problems and solutions. Understanding the concepts in depth is not an easy task, but if you have good practice and grip over the subject then you can easily solve all the problems. Big Ideas Math Book Answers 6th Grade solution key provides you with in-depth knowledge and concepts. You can find the step-by-step solution to all the problems of Percents. Scroll down to the below sections to check Big Ideas Math Answers Grade 6 Chapter 4 Percents and every detail of this concept.

Big Ideas Math Book 6th Grade Answer Key Chapter 4 Percents

Feeling difficulty in solving percent problems? Don’t worry! Here is the best material and guide for you to solve the problems quickly and efficiently. Big Ideas Math Book 6th Grade Answer key for Chapter 4 Percents pdf will help you to clear all your doubts and get perfection. To excel in the exam, we suggest all the aspirants to refer the Big Ideas Math Book 6th Grade Chapter 4 Percents Answer key which is given in the below sections. Follow the lesson-wise practice material here.

Performance

Lesson 1: Percents and Fractions

Lesson 2: Percents and Decimals

Lesson: 3 Comparing and Ordering Fractions, Decimals, and Percents

Lesson: 4 Solving Percent Problems

Chapter – 4: Concepts

Percents STEAM Video/Performance


Chargaff’s Rules

DNA is a molecule made up of four nucleotide bases called adenine (A), thymine (T), cytosine (C), and guanine (G). DNA contains the genetic information for a living organism. What can you learn about an organism from its DNA?
Watch the STEAM Video “Chargaff’s Rules.” Then answer the following questions.
1. Veronica says that the DNA of most mammals contains about 60 percent A and T nucleotides and 40 percent C and G nucleotides. What do you think this means?

Answer:
According to the above stated DNA structure both adenine and thymine contains 60%, cytosine and guanine contain 40%. The difference between them is 20%.

Explanation:
In the above-given DNA structure, they stated that adenine and thymine contain 60%, cytosine and guanine contain 40% and the difference is 20%.
60% – 40% = 20%

2. Use your answer in Question 1 to determine which of the following DNA samples is most likely to belong to a mammal. Explain your reasoning.
Big Ideas Math Answers Grade 6 Chapter 4 Percents 1

Big Ideas Math Answers Grade 6 Chapter 4 Percents 2

Answer:
Sample 2 satisfies the condition because the 1st question statement is near to the sample2.

Explanation:
Sample 2 is near to the 1st question.

Performance Task
Genetic Ancestry

After completing this chapter, you will be able to use the concepts you learned to answer the questions in the STEAM Video Performance Task. You will be given the results of your friend’s ancestry test.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 3
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 3.1
You will be asked to compare the portions of your friend’s ancestry from different regions of the world. How can you order the portions of your friend’s ancestry from least to greatest?

Answer:
Native American, SouthWest Asian, Mediterranean, Northern European, African.

Explanation:
Native American = (1/50) = 0.02
African = (30/40) = 0.75
Northern European = 0.10
SouthWest Asian = (3/75) = 0.04
Mediterranean = 0.06

Percents Getting Ready for Chapter 4

Chapter Exploration

Question 1.
THE MEANING OF A WORD
Work with a partner. Match the “cent” word with its definition.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 4

Answer:
one hundredth of a dollar

Explanation:
cent meaning

Question 2.
THE MEANING OF A WORD
Work with a partner. Describe a situation where you have seen the word perused and explain its use. In your own words, what do you think the word percent means? Use the word percent in a sentence.
Work with a partner. Represent the shaded portion of the square as
(a) a fraction whose denominator is 100,
(b) a fraction in the simplest form,
(c) a decimal, and
(d) a percent.

Answer:
A fraction whose denominator is 100.

Explanation:
Per meaning in percentage.
Question 3.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 6

Answer:
4%

Explanation:
The Total number of boxes is 100. In the above-given boxes, 4 boxes are filled with color.
(4/100) x 100 = 4%.

Question 4.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 7

Answer:
15%

Explanation:
The number of boxes are 100. In the above-given boxes, 15 are filled with color.
(15/100) x 100 = 15%

Question 5.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 8

Answer:
30%

Explanation:
The number of boxes are 100. In the above-given boxes, 30 are filled with color.
(30/100) x 100 = 30%

Question 6.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 9

Answer:
50%

Explanation:
The Total number of boxes are 100. In the above-given boxes, 50 boxes are filled with color.
(50/100) x 100 = 50

Question 7.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 10

Answer:
100%

Explanation:
The Total number of boxes are 100. In the above given 100 boxes are filled with color.

(100/100) x 100 = 100

Question 8.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 11

Answer:
0%

Explanation:
The number of boxes are 100. In the above given no boxes are filled with color.
(0/100) x 100 = 0

Vocabulary

The following terms are used in this chapter. Think about what each term might mean and record your thoughts.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 12

Lesson 4.1 Percents and Fractions

Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 13
Cent means one hundred, so percent means per one hundred. The symbol for percent is %.

EXPLORATION 1

Interpreting Models
Work with a partner. Write a percent, a fraction, and a ratio shown by each model. How are percents, fractions, and ratios related?
a. Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 14

Answer:
Percentage = 60%
Fraction = 6/10
Ratio = 3:5

Explanation:
In the above-given boxes, 60 boxes are filled with color.
Percentage = (60/100) x 100 = 60
Fraction = (60/100) = 6/10
Ratio = 6:10 = 3:5
The Relationship between Fractions, Percentages, Ratios is since a percent can be written as a fraction as well as a ratio. The ratio and fraction are same.

b. Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 15

Answer:
Percentage = 8%
Fraction = 8/100
Ratio = 2:25

Explanation:
In the above given boxes, 8 boxes are filled with color.
percentage = (8/100) x 100 = 8
Fraction = 2 : 25
Ratio = 2:5
The Relationship between percents, ratios, fractions are percents can be written as ratios. The ratios and fractions are the same.
c.Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 16

Answer:
Percentage = 51%
Fraction = 51/100
Ratio = 51:100

Explanation:
percentage = (51/100) x 100 = 51%
Fraction = 51 : 100
In the above given boxes 51 boxes are filled with color.

d. Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 17

Answer:
Percentage = 25%
Fraction = 1/4
Ratio = 1:4

Explanation:
percentage = (25/100)
Fraction = 0.25
In the above given boxes 51 boxes are filled with color.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 18

4.1 Lesson

Try It
Write the percent as a fraction or mixed number in simplest form.

Question 1.
5%
Answer:
1: 20

Explanation:
(5/100) = 1: 20

Question 2.
168%
Answer:
42/25

Explanation:
(168/100 )= 42: 25

Question 3.
36%
Answer:
3/25

Explanation:
(36/100) = 3: 25

Question 4.
83%

Answer:
83/100

Explanation:
(83/100) = 83: 100

Key Idea
Writing Fractions as Percents
Words Write an equivalent fraction with a denominator of 100. Then write the numerator with the percent symbol.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 19

Try It
Write the fraction or mixed number as a percent.

Question 5.
\(\frac{31}{50}\)

Answer:
62%

Explanation:
(31/50)  = (31 x 2)/(50 x 2) = 62/100 = 62%
Question 6.
\(\frac{19}{20}\)

Answer:
19/20

Explanation:
(19/20) = (19 x 5)/(20 x 5) = 95/100 = 95%

Question 7.
\(\frac{1}{200}\)

Answer:
1/200

Explanation:
(1/200) = (1 x 1)/(2 x 1) = 0.5%

Question 8.
1\(\frac{1}{2}\)

Answer:
3/2

Explanation:
(3/2) = (3 x 50)/(2 x 50) = 150%

Self-Assessment for Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 9.
WRITING A FRACTION
Write 40% as a fraction in simplest form. Draw a model that represents this fraction.

Answer:
2/5

Question 10.
WRITING A PERCENT
Write \(\frac{9}{20}\) as a percent.

Answer:
45

Explanation:
9/20 x 100 = 45

Question 11.
WHICH ONE DOESN’T BELONG?
Which number does not belong with the other three? Explain your reasoning.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 20

Answer:
0.01

Explanation:
They are in the fraction and 0.01 is in the decimal

Question 12.
OPEN-ENDED
Write three different fractions that are less than 40%.

Answer:
1/10, 1/5, 3/10

Explanation:
10%,20%,30%

Question 13.
NUMBER SENSE
Can 1\(\frac{1}{4}\) be written as a percent? Explain.

Answer:
25%

Explanation:
(1/4) x 100 = (50/2) = 25

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 14.
You and a friend fill balloons with water. Two out of every 25 balloons pop while they are being filled. What percent of the balloons do not pop while they are being filled?

Answer:
92%

Explanation:
Given that or every 25 ballons 2 ballons are popped, It means 23 ballons are not popped . For 100 ballons 92 ballons are not popped.

Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 21

Question 15.
During the month of April, it rains 2 days for every 3 days that it does not rain. What percent of the days in April does it rain?

Answer:
20 Days

Explanation:
In April month there are 30 days, so for every 3 days it rains 2 days.
3 x10 = 30 days
2 x10 = 20 days

Question 16.
DIG DEEPER!
There are 100 students in a band. Forty percent are 12 years old, \(\frac{1}{2}\) are 13 years old, and the rest are 14 years old. Write the portion of the band for each age as a fraction and a percent.

Answer:
12 years old = 40%, 2:5.
13 years old = 50%, 1:2.
14 yars old = 10%,1:10.

Explanation:
In the given quesion 40% are 12 years old ,50% are 13 years old and the rest are 14 years old.
percent = 40% , fraction = 2: 5
percent = 50% , fraction = 1:2
percent = 10% , fraction = 1: 10

Percents and Fractions Practice 4.1

Review & Refresh

Copy and complete the statement. Round to the nearest hundredth if necessary.

Question 1.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 22

Answer:
3000m

Explanation:
1 km = 1000 m so 3 x 1000 =3000m

Question 2.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 23

Answer:
112 c

Explanation:
1 gal = 6 c so 7 gal = 112 c

Question 3.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 24

Answer:
1.5 yd

Explanation:
1 Inch = 0.0277778 yds so 54 inches = 1.5 yds

Question 4.

Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 25

Answer:
6 kilometers

Explanation:
1 mile = 1.6093kms. So 4 miles = 6.4 km ~6 kms

Question 5.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 26

Answer:
1
Explanation:
1 liter = 0.2647 gal
6.5 liters = 1

Question 6.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 27

Answer:
20 kgs

Explanation:
1 lb = 0.4535 kgs so 45lb = 20 kgs

Divide

Question 7.
120 ÷ 12

Answer:
10

Explanation:
12 x 10 = 120

Question 8.
208 ÷ 4

Answer:
52

Explanation:
4×52 = 208

Question 9.
195 ÷ 15

Answer:
13

Explanation:
15×13 = 195

Question 10.
1428 ÷ 34

Answer:
42

Explanation:
34×42 = 1428

Question 11.
8528 ÷ 164

Answer:
52

Explanation:
164×52 = 8528

Question 12.
295 ÷ 8

Answer:
36.875

Explanation:
36.875 x 8 = 295

Use the table to write the ratio.

USING TOOLS
Use a 10-by-10 grid to model the percent. (See Exploration 1, p. 163)

Question 17.
10%

Answer:
1/10

Explanation:
10 x (1/100) = 1/10

Question 18.
55%

Answer:
11/20

Explanation:
55 x (1/100) = 11/20

Question 19.
45%

Answer:
9/20

Explanation:
45 x (1/100) = 9/20

WRITING PERCENTS AS FRACTIONS
Write the percent as a fraction or mixed number in simplest form.

Question 20.
45%

Answer:
9:20

Explanation:
45 x (1/100) = 9:20

Question 21.
90%

Answer:
9:10

Explanation:
90 x (1/100) = 9:10

Question 22.
15%

Answer:
3:20

Explanation:
(15/100) = 3:20

Question 23.
7%

Answer:
7:100

Explanation:
(7/100) = 7:100

Question 24.
34%

Answer:
17:50

Explanation:
(34/100) = (17/50) = 17:50

Question 25.
79%

Answer:
79:100

Explanation:
(79/100) = 79:100

Question 26.
77.5%

Answer:
151:200

Explanation:
(775/1000) = 151/200 = 151:200

Question 27.
188%

Answer:
47:25

Explanation:

(188/100) = 94/50 =47/25

Question 28.
8%

Answer:
2:25

Explanation:
(8/100) = (4/500) = 2/25

Question 29.
224%

Answer:
56:25

Explanation:
(224/100) = 112/50 = 56/25

Question 30.
0.25%

Answer:
1:400

Explanation:
(25/10000) = (5/2000) = 1/400

Question 31.
0.4%

Answer:
1:250

Explanation:
(4/1000) = (2/500) = 1/250

Question 32.
YOU BE THE TEACHER
Your friend writes 225% as a fraction. Is your friend correct? Explain your reasoning.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 28

Answer:
correct

Explanation:
(225/100) = (45/20) = 9/4

WRITING FRACTIONS AS PERCENTS
Write the fraction or mixed number as a percent.

Question 33.
\(\frac{1}{10}\)

Answer:
0.1%

Explanation:
(1/10 x 100) = (10/100) = (1/10) = 0.1%

Question 34.
\(\frac{1}{5}\)

Answer:
0.2%

Explanation:
(1/5) x 100 = (20/100) = (10/100) = (1/5) = 0.2%

Question 35.
\(\frac{11}{20}\)

Answer:
0.55%

Explanation:
(11/20) x 100 = (55/100) = 0.55%

Question 36.
\(\frac{1}{400}\)

Answer:
0.0025%

Explanation:
(1/400) x 100 = (1/400) = 0.0025%

Question 37.
\(\frac{2}{25}\)

Answer:
0.08%

Explanation:
(2/25) x 100 = (8/100) = 0.08%

Question 38.
\(\frac{27}{50}\)

Answer:
0.27

Explanation:
(27/50) x 100 = (54/200) = 0.27%

Question 39.
\(\frac{3}{250}\)

Answer:
0.3%

Explanation:
(3/250) x 100 = (12/40)  = 0.3%

Question 40.
\(\frac{18}{25}\)

Answer:
0.72%

Explanation:
(18/25) x 100 = (72/100) = 0.72%

Question 41.
1\(\frac{17}{20}\)

Answer:
0.85%

Explanation:
(17/20) x 100 = (85/100) = 0.85%

Question 42.
2\(\frac{41}{50}\)

Answer:
282%

Explanation:
2 x (41/50) =(141/50)  = 2.82 x 100 = 282%

Question 43.
3\(\frac{1}{200}\)

Answer:
300.5%

Explanation:
3 x (1/200) = (601/200) = 3.005 x 100 = 300.5

Question 44.
4\(\frac{7}{500}\)

Answer:
200700%

Explanation:
4 x (7/500) = (2007/500) = 2007 x 100 = 200700

Question 45.
YOU BE THE TEACHER
Your friend writes \(\frac{14}{25}\) as a percent. Is your friend correct? Explain your reasoning.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 29

Answer:
correct

Explanation:
(14/25) = (56/100) = 0.56%

Question 46.
MODELING REAL LIFE
During a 10-year period, 6 out of 30 Major League Baseball teams won the World Series. What percent of Major League Baseball teams won the World Series during the 10-year period?
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 30

Answer:
5%

Explanation:
Out of 30 games, 6 matches are won for 100 games 15 matches are won
(6/30) = (X/100)
X = 5

Question 47.
MODELING REAL LIFE
A doctor conducts an experiment to test new treatments for a medical condition. Of the 16 volunteers in the experiment, 4 do not receive any treatment. What percent of the volunteers do not receive any treatment?

Answer:
25%

Explanation:
In the above-given statement out of 16 volunteers in the experiment, 4 do not receive any treatment. So (4/4) = 16. If it is 100% (100/4) = 25

Question 48.
LOGIC
Of the students in your class, 12% are left-handed and the rest are right-handed. What fraction of the students are left-handed? Are there more right-handed or left-handed students? Explain.

Answer:
12% of students are left handed = 3: 25

Explanation:
Given that 12% are left handed and remaining are right handed = 100% – 12% = 88%.
There are more right-handed students.

Question 49.
NUMBER SENSE
You have 125% of the tickets required for a prize. What fraction of the required tickets do you have? Do you need more tickets for the prize? Explain.

Answer:
5:4

Explanation:
We have 125% of the tickets required for a prize. No we do not need more tickets for the prize. We have more enough 125 percent of the tickets required for a prize.

FINDING PERCENTS
Find the percent.

Question 50.
3 is what percent of 8?

Answer:
37.5

Explanation:
(3/8)  x 100 = 37.5

Question 51.
13 is what percent of 16?

Answer:
81.25

Explanation:
(13/16) x 100 = 81.25

Question 52.
9 is what percent of 16?

Answer:
56.25

Explanation:
(9/16) x 100 = 56.25

Question 53.
33 is what percent of 40?

Answer:
82.5

Explanation:
(33/40) x 100 = 82.5

Question 54.
Modeling Real Life
A survey asked students to choose their favorite social media website.
a. What fraction of the students chose Website A?
b. What percent of the students chose Website C?
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 30.1

Answer:
a = 5:20, b = 0.22

Explanation:
The fraction of students who choose website A is 35. 35 :100 = 5:20
The percent of students who choose website c is 22.(  25/100) = 0.22

Question 55.
DIG DEEPER!
The percent of the total area of the United States that is in each of four states is shown.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 31
a. Write the percents as fractions in simplest form.b. Compared to the map of Florida, is the map of Alaska the correct size? Explain your reasoning.
c. RESEARCH
Which of the 50 states are larger than Illinois?

Answer:
Alaska, California, Montana, New Mexico, Arizona, Nevada, Colorado, Oregon,

Question 56.
CRITICAL THINKING
A school fundraiser raised 120% of last year’s goal and 25% of this year’s goal. Did the fundraiser raise more money this year? Explain your reasoning.

Question 57.

Answer:
No

Explanation:
The fundraiser did not raise more money this year. Last year fundraiser raised 120% and this year fundraiser raised 25%,
CRITICAL THINKING
How can you use a 10-by-10 grid to model \(\frac{1}{2}\)?

Question 58.

Answer:

REASONING
Write \(\frac{1}{12}\) as a percent. Explain how you found your answer.

Answer:
8.33

Explanation:
(1/12) x 100 = 8.33

Lesson 4.2 Percents and Decimals

EXPLORATION 1
Interpreting Models
Work with a partner. Write a percent and a decimal shown by each model. How are percents and decimals related?

Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 32
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 33

Answer:
a :  Fraction = 100% , Decimal = 1.0
b : Fraction = 33%, Decimal = 0.33
c : Fraction = 37%, Decimal = 0.37
d : Fraction = 64%, Decimal = 0.64
e : Fraction = 50%, Decimal = 0.5
f : Fraction = 60%, Decimal = 0.6
g : Fraction = 130%, Decimal = 0.65

Explanation:
a : 100% =  (100/100) = 1 and Decimal = 1.0. The total boxes are filled.
b : 33% = (33/100) = 0.33.  So 33% boxes are filled.
c : 37% = (37/100) = 0.37. So 37 boxes are filled.
d : 64% = (64/100) = 0.64. So 64 boxes are filled.
e : 50% = (50/100) = 0.5. So 50 boxes are filled.
f : 60% = (60/100) = 0.6. So 60 boxes are filled.
g : 130% = (130/200) = 0.65. So 130 boxes are filled.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 33.1

4.2 Lesson

Try It

Write the percent as a decimal. Use a model to represent the decimal.

Question 1.
24%

Answer:
(24/100) = (6/25) = 0.24

Explanation:

Question 2.
3%

Answer:
(3/100) = 0.03

Explanation:

Question 3.
107%

Answer:
1.07 = (107/100)

Explanation:

Question 4.
92.5%

Answer:
92.5% = (925/1000) = 0.925

Explanation:

Key Idea
Writing Decimals as Percents
Words Multiply by 100, which moves the decimal point two places to the right. Then add a percent symbol.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 34

Try It
Write the decimal as a percent.

Question 5.
0.94

Answer:
94%

Explanation:
94% = (94/100) = 0.94

Question 6.
1.2

Answer:
120%

Explanation:
120% = (120/100) = 1.2

Question 7.
0.316

Answer:
31.6%

Explanation:
31.6% = (31.6/100) = 0.316

Question 8.
0.005

Answer:
5%

Explanation:
5% = (5/1000) = 0.005

Try It

Question 9.
WHAT IF? You earn 90 out of a possible 100 points on the test. Write “90 out of 100” as a fraction, a decimal, and a percent.

Answer:
Fraction = 90: 100
Decimal = 0.9
percent = 90%

Explanation:
They had given that 90 out of possible 100 points on the test. So 90% = (90/100), fraction = 90 :  100, decimal = 0.9.

Self-Assessment for Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

WRITING PERCENTS AS DECIMALS
Write the percent as a decimal. Use a model to represent the decimal.

Question 10.
32%

Answer:
32% = (32/100) = 0.32

Explanation:

Question 11.
54.5%

54.5% = (54.5/100 = 0.545

Explanation:

Question 12.
108%

Answer:
108% = (108/100) = 1.08

Explanation:

WRITING DECIMALS AS PERCENTS
Write the decimal as a percent.

Question 13.
0.71

Answer:
71%

Explanation:
(71/100) = 71%

Question 14.
0.052

Answer:
52%

Explanation:
(52/1000) = 52%

Question 15.
9.66

Answer:
966%

Explanation:
966% = (966/100) = 9.66

Question 16.
WRITING
Explain why the decimal point moves left when dividing a number by 100.

Answer:
It moves 2 digits left because it has 2 zeros.

Explanation:
It is dividing by 100 so the decimal point moves left when dividing a number by 100.

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 17.
Write the amount of occupied space on the computer as a percent.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 35

Answer:
0.18%

Explanation:
In the above given condition the total capacity is 150GB and the free space is 132GB. The remaining space is 18.

Question 18.
Salinity is a measure of the salt content of a body of water. One researcher measures the salinity of the Indian Ocean as 3.2%. Another researcher measures the salinity of the Dead Sea as 34%. A bucket of water from the Indian Ocean contains 56 grams of salt.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 36
How much salt is contained in the same amount of water from the Dead Sea? Justify your answer.

Answer:
34%

Explanation:
They have said that 34% of salt is ontained in the dead water.

Percents and Decimals Practice 4.2

Review & Refresh

Write the fraction or mixed number as a percent.

Question 1.
\(\frac{7}{50}\)

Answer:
0.14%

Explanation:
(7/50) x 100 = (7 x 2)/(50 x 2) = (14/100) = 0.14

Question 2.
\(\frac{2}{5}\)

Answer:
0.4%

Explanation:
(2/5) x 100 = (2 x 20)/(5 x 100) = (40/100) = 0.4

Question 3.
\(\frac{1}{250}\)

Answer:
0.004%

Explanation:
(1/250) x 100 = (1 x 4)/(250 x 4) = (4/1000) = 0.004

Question 4.
\(\frac{1}{500}\)

Answer:
0.002%

Explanation:
(1/500) x 100 = (1 x 1)/(500 x 1) = 0.002

Represent the ratio relationship using a graph.

Question 5.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 37

Question 6.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 38
Multiply. Write the answer in simplest form.

Question 7.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 39

Answer:
(6/63)

Explanation:
(3 x 2) = 6 ,(7 x 9) = 63

Question 8.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 40

Answer:
(5/60)

Explanation:
(5 x 1) = 5,(12 x 5) = 60

Question 9.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 41

Answer:
(126/30)

Explanation:
(14 x 9) = 126,(3 x 10) = 30

Question 10.

Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 42

Answer:
(91/12)

Explanation:
(13 x 7) = 91, (6 x 2) = 12

Concepts, Skills, & Problem Solving

INTERPRETING MODELS
Write the percent and the decimal shown by the model. (See Exploration 1, p. 169.)

Question 11.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 43

Answer:
51%, 0.51

Explanation:
In the above given box 51 boxes are filled with color. So 51% = (51/100) = 0.51

Question 12.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 44

Answer:
144%, 0.72

Explanation:
In the above given box 144 boxes are filled with color. So 144% = (144/200) = 0.72

WRITING PERCENTS AS DECIMALS
Write the percent as a decimal.

Question 13.
78%

Answer:
0.78

Explanation:
(78/100) = 0.78

Question 14.
55%

Answer:
0.55

Explanation:
(55/100) = 0.55

Question 15.
18.5%

Answer:
0.185

Explanation:
(18.5/100) = 0.185

Question 16.
57.4%

Answer:
0.574

Explanation:

(57.4 /100) = 0.574

Question 17.
33%

Answer:
0.33

Explanation:
(33/100) = 0.33

Question 18.
9%

Answer:
0.09

Explanation:
(9/100) = 0.09

Question 19.
47.63%

Answer:
0.4763

Explanation:
(47.63/100) = 0.4763

Question 20.
91.25%

Answer:
0.9125

Explanation:
(91.25/100) = 0.9125

Question 21.
166%

Answer:
1.66

Explanation:
(166/100) = 1.66

Question 22.
217%

Answer:
2.17

Explanation:
(217/100) = 2.17

Question 23.
0.06%

Answer:
6%

Explanation:
(6/100) = 0.06

Question 24.
0.034%

Answer:

WRITING DECIMALS AS PERCENTS
Write the decimal as a percent.

Question 25.
0.74

Answer:
74%

Explanation:
(74/100) = 0.74

Question 26.
0.52

Answer:
52%

Explanation:
(52/100) = 0.52

Question 27.
0.89

Answer:
89%

Explanation:
(89/100) = 0.89

Question 28.
0.768

Answer:
768%

Explanation:
(768/1000) = 0.768

Question 29.
0.99

Answer:
99%

Explanation:
(99/100) = 0.99

Question 30.
0.49

Answer:
49%

Explanation:
(49/100) = 0.49

Question 31.
0.487

Answer:
48.7%

Explanation:
48.7% = (48.7/100) = 0.487

Question 32.
0.128

Answer:
12.8%

Explanation:
12.8% = (12.8/100) = 0.128

Question 33.
3.68

Answer:
368%

Explanation:
368% = (368/100) = 3.68

Question 34.
5.12

Answer:
512%

Explanation:
512% = (512/100) = 5.12

Question 35.
0.0371

Answer:
3.71%

Explanation:
3.71% = (3.71/100) = 0.0371

Question 36.
0.0046

Answer:
46%

Explanation:
46% = (46/1000) = 0.0046

Question 37.
YOU BE THE TEACHER
Your friend writes 0.86 as a percent. Is your friend correct? Explain your reasoning.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 45

Answer:
No my friend is not correct.

Explanation:
0.86 = 0.086 = 0.0086.

MATCHING
Match the decimal with its equivalent percent.

Question 38.
0.42

Answer:
0.42 = 0.042 = 0.0042

Explanation:
(42/100) = 0.42

Question 39.
4.02

Answer:
4.02 = 4.002 = 4.0002

Explanation:

Question 40.
0.042

Answer:
0.042 = 0.0042 = 0.00042

Explanation:
(42/100000) = 0.00042

Question 41.
0.0402
A. 4.02%
B. 42%
C. 4.2%
D. 402%

Answer:
A

Explanation:
4.02% = (4.02/100) = 0.0402

Question 42.
MODELING REAL LIFE
About 80% of the precipitation that enters Crater Lake falls directly on the surface of the lake. Write this percent as a decimal.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 46

Answer:
0.8

Explanation:
(80/100) = 0.8 . In the above-given statement, they are given in percentage and said that write it in the decimal points.

Question 43.
MODELING REAL LIFE
About 0.34 of the length of a cat is its tail. Write this decimal as a percent.

Answer:
34%

Explanation:
(34/100) = 0.34. In the given question, they are given in decimal and they said that convert it in percents.

Question 44.
OPEN-ENDED
Write three different decimals that are between 10% and 20%.

Answer:
0.13,0.16,0.19

Explanation:
In the above-given question, they said to write the decimals between 10% and 20%. So 13%,16%,19% is between the 10% and 20%.

WRITING PERCENTS AS FRACTIONS AND DECIMALS
Write the percent as a fraction in simplest form and as a decimal.

Question 45.
36%

Answer:
Decimal = 0.36, Fraction = 18 : 25

Explanation:
36% = (36/100) = 0.36 , fraction = 18: 25
Question 46.
23.5%

Answer:
Decimal = 0.235, Fraction = 47: 200

Explanation:
23.5% = (23.5/100) = 0.235 , fraction = 47 : 200

Question 47.
16.24%

Answer:
Decimal = 0.1624, Fraction =

Question 48.
DIG DEEPER!
The percents of students who travel to school by car, bus, and bicycle are shown for a school of 825 students.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 47
a. Write the percents as decimals.

Answer:
car:0.2 , school bus:0.48 , bicycle:0.08

Explanation:
In the above-given figures, they have given in percents and said to write in decimals.
b. Write the percents as fractions.

Answer:

c. What percent of students use another method to travel to school?

Answer:
24%

Explanation:
They go by walk or either they go by bike.

d. RESEARCH
Make a bar graph that represents how the students in your class travel to school.

Question 49.
LOGIC
A running back was the MVP (most valuable player) in 0.14 of the first 50 Super Bowls.
a. What percent of the MVPs were running backs?
b. What fraction of the MVPs were not running backs?

Question 50.
CHOOSING A METHOD
Students in a class were asked to tell their favorite color.
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 48
a. Whatpercent said red, blue, or yellow?

Answer:
Red = 26% , blue = 40% , yellow = 4%

Explanation:
In the above given that the students who like red are 26%, blue is40%, yellow is 4%.
b. How many times more students said red than yellow?

Answer:
22

Explanation:
The students who like red color more than yellow color is 22%
c. Use two methods to find the percent of students who said green. Which method do you prefer? Explain.

Answer:
The students who said green is 16%.

Explanation:
In the above given the students who like red 26%, blue 40%, yellow 4%, purple 14%. So the total percentage is 100 and the remaining is 16. (100-84) = 16

Lesson 4.3 Comparing and Ordering Fractions, Decimals, and Percents

EXPLORATION 1
Using a Number Line to Order Numbers

Work with three partners. Create a number line on the floor. Have your group stand on the number line to represent the four numbers in each list. Use the results to order each list of numbers from least to greatest. How did you know where to stand?
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 49

Answer:
a =
b =
c =
d =
e =
f =

Explanation:
a = 0.25 = 25%
0.5 = (0.5/10) x 100 = 50%
b =  (3/4) = (3/4) x 100 = 75%
(1/20) = (1/20) x 100 = 5%
c = 0.125 = 12.5%
(3/10) = (3/10) x 100 = 30%
d = 1.02 = (1.02/100) x 100 = 102%
(1/100) = (1/100) x 100 = 1%
e = 0.3 = 30%
(1/8) = (1/8) x 100 = 5%
0.75 = (0.75/100) x 100 = 75%
f = (51/50) = (51/50) x 100 = 102%
(9/10) = 90%
1.5 = (1.5/10) x 100 = 150%
Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 50

4.3 Lesson

When comparing and ordering fractions, decimals, and percents, write the numbers as all fractions, all decimals, or all percents.

Try It
Tell which number is greater.

Question 1.
25%, \(\frac{7}{25}\)

Answer:
(7/25) is greater

Explanation:
25% = (25/100) = 0.25, (7/25) = 0.28

Question 2.
0.49, 94%

Answer:
94% is greater

Explanation:
94% = (94/100) = 0.94

Try It
Order the numbers from least to greatest.

Question 3.
\(\frac{3}{10}\), 15%, 0.2, \(\frac{3}{8}\), 0.09

Answer:
0.09, 0.15, 0.2, 0.3, 0.375

Explanation:
(3/10) = 0.3, 15% = 0.15, (3/8) = 0.375. They said to write from least to greast. So 0.09, 0.15, 0.2, 0.3, 0.375.

Question 4.
100%, 0.95, 1.2, \(\frac{5}{4}\), 110%

Answer:
0.95, 1, 1.1, 1.2,1.25

Explanation:
100% = 1, (5/4) = 1.25, 110% = 1.1 so 0.95, 1, 1.1, 1.2, 1.25.

Question 5.
WHAT IF?
Your friend makes \(\frac{3}{4}\) of his shots. Did your friend make more shots than you? your sister?

Self-Assessment for Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Big Ideas Math Answer Key Grade 6 Chapter 4 Percents 51

Answer:
72%
0.85
0.26, 26%
(31/50),62%
(9/20),0.45

Explanation:
Fraction = 18 : 25 ,decimal = 0.72, percent = 72%
Fraction = 17 : 20 , decimal = 0.85, percent = 85%
Fraction = 13 :50 , decimal = 0.26, percent = 26%
Fraction = 31 :50, decimal = 0.62, percent = 62%
Fraction = 9 : 20 , decimal = 0.45, percent = 45%

Question 6.
NUMBER SENSE
Copy and complete the table.

Answer:

Explanation:

Fraction = 18 : 25 ,decimal = 0.72, percent = 72%
Fraction = 17 : 20 , decimal = 0.85, percent = 85%
Fraction = 13 :50 , decimal = 0.26, percent = 26%
Fraction = 31 :50, decimal = 0.62, percent = 62%
Fraction = 9 : 20 , decimal = 0.45, percent = 45%

Question 7.
NUMBER SENSE
How would you decide whether \(\frac{3}{5}\) or 59% is greater? Explain.

Answer:
(3/5) is greater.

Explanation:
(3/5) = 0.6, 59% = 0.59 so 0.6 is greater than 0.59

COMPARING NUMBERS

Tell which number is greater.

Question 8.
33%, 0.34

Answer:
0.34 is greater.

Explanation:
0.34 = (34/100). 34 is greater than 33.

Question 9.
0.85, \(\frac{4}{5}\)

Answer:
0.8 is greater.

Explanation:
0.85 = (85/100)

Question 10.
\(\frac{9}{50}\), 17%

Answer:
(9/50) is greater.

Explanation:
17% = (17/100) = 0.17,(9/50) = (18/100) = 0.18. So 0.18 is greater.

ORDERING NUMBERS
Order the numbers from least to greatest.

Question 11.
12%, 0.1, \(\frac{4}{25}\)

Answer:
0.1,12%,4/25.

Explanation:
12% = 0.12, (4/25) = 0.16

Question 12.
1.35, 125%, \(\frac{6}{5}\), 1.5, 130%

Answer:
0.2, 1.25, 1.3, 1.35, 1.5.

Explanation:
125% = 1.25, (6/5) = 0.2, 130% = 1.3

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 13.
The table shows the portions of copper in three rings. Which ring has the highest portion of copper?
Big Ideas Math Answers 6th Grade Chapter 4 Percents 52

Answer:
All the 3 rings are approximately equal.

Explanation:
25% = 0.25, 0.2, (9/40) = 0.225. So the 3 rings has approximately equal values.

Question 14.
DIG DEEPER!
The table shows the results of five teams competing in a scavenger hunt. List the five teams in order by the portion of items collected from least to greatest. What is the minimum number of items in the scavenger hunt? Explain.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 53

Answer:
Team 5, team 1, team 3, team 2, team 4.

Explanation:
(13/20) = 0.65, (3/4) = 0.75, 77.5% = 0.775,  0.8, 0.825. So the minimum number of items in scavenger hunt is 5.

Comparing and Ordering Fractions, Decimals, and Percents Homework & Practice 4.3

Review & Refresh

Write the percent as a decimal.

Question 1.
12%

Answer:
0.12

Explanation:
(12/100) = 0.12

Question 2.
98.37%

Answer:
0.9837

Explanation:
(98.37/100) = 0.9837

Question 3.
0.046%

Answer:
0.00046

Explanation:
(0.046/100) = 0.00046

Find the missing value(s) in the ratio table. Then write the equivalent ratios.

Question 4.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 54

Answer:
45

Explanation:
(4 x 9) = 36, (5 x 9) = 45

Question 5.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 55

Multiply.

Question 6.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 56

Answer:
(5.3 x 6) = 31.8

Explanation:

Question 7.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 57

Answer:
162.9

Explanation:

Question 8.
12.43 × 1.51

Answer:
(12.43 x 1.51) = 18.7693

Explanation:

Question 9.
0.852 × 6.7

Answer:
(0.852 x 6.7) = 5.7084

Explanation:

Find the GCF of the numbers.

Question 10.
15, 36

Answer:
3

Explanation:
(36/15) = 6 . (15/6) =3, (6/3) = 0

Question 11.
51, 85

Answer:
17

Explanation:
(85/51) = 34,(51/34) = 17, (34/17) = 0

Question 12.
88, 112

Answer:
8

Explanation:
(112/88) = 24, (88/24) = 16, (24/16) = 8, (16/8) = 0

Concepts, Skills, & Problem Solving

USING A NUMBER LINE
Use a number line to order the numbers from least to greatest. (See Exploration 1, p. 175.)

Question 13.
80%, 0.65, \(\frac{3}{10}\), 40%

Answer:

Explanation:
(3/10) = (3/10) x 100 = (3 x 10)/(10 x 10) = (30/100) =30%
0.65 = (0.65/100) x 100 = 65%

Question 14.
0.27, 20%, \(\frac{1}{25}\), 9%

Answer:

Explanation:
0.27 = (0.27/100) x 100 = 27%
(1/25) = (1/25) x 100 = (1 x 4/25 x 4) = (4/100) = 4%

Question 15.
\(\frac{1}{8}\), 0.25, 15%, \(\frac{27}{100}\)

Answer:

Explanation:
(1/8) = (1/8) x 100 = (1 x 50/4 x 50) = (50/200) = 0.25 = 25%
0.25 = (0.25 x 100) = 25%
(27/100) = (27/100) x 100 = 27%

COMPARING NUMBERS
Tell which number is greater.

Question 16.
0.9, 95%

Answer:
95%

Explanation:
95% = (95/100) = 0.95

Question 17.
20%, 0.02

Answer:
20%

Explanation:
20% = 0.2

Question 18.
\(\frac{37}{50}\), 37%

Answer:
(37/50)

Explanation:
(37/50) = 0.74, 37% = 0.37. So (37/50) is greater.

Question 19.
50%, \(\frac{13}{25}\)

Answer:
(13/25)

Explanation:
50% = (50/100) = 0.5, (13/25) = 0.52

Question 20.
0.086, 86%

Answer:
86%

Explanation:
86% = 0.86, 0.086 so 0.86 is greater

Question 21.
76%, 0.67

Answer:
76%

Explanation:
76% = 0.76, 67% = 0.67

Question 22.
60%, \(9\frac{5}{8}\)

Answer:
(5/8)

Explanation:
(5/8) = 0.625, 60% = 0.6

Question 23.
0.12, 1.2%

Answer:
0.12

Explanation:
0.12 = 12%, 1.2%

Question 24.
17%, \(\frac{4}{25}\)

Answer:
17%

Explanation:
17% = 0.17, (4/25) = 16% = 0.16

Question 25.
140%, 0.14

Answer:
140%

Explanation:
140% = 1.4

Question 26.
\(\frac{3}{8}\), 30%

Answer:
0.375

Explanation:
30% = 0.3, (3/8) = 0.375

Question 27.
80%, \(\frac{7}{10}\)

Answer:
80%

Explanation:
80% = 0.8, (7/10) = 0.7

ORDERING NUMBERS
Order the numbers from least to greatest.

Question 28.
38%, \(\frac{8}{25}\), 0.41

Answer:
(8/25) , 38%, 0.41

Explanation:
38% = 0.38, (8/25) = 0.32, 0.41

Question 29.
68%, 0.63, \(\frac{13}{20}\)

Answer:
0.63, (13/20), 68%

Explanation:
68% = 0.68, (13/20) = 0.65

Question 30.
\(\frac{43}{50}\), 0.91, \(\frac{7}{8}\), 84%

Answer:
84%, (43/50), (7/8) , 0.91

Explana;tion:
(43/50) = 0.86, (7/8) = 0.875, 84% = (84/100) = 0.84

Question 31.
0.15%, \(\frac{3}{20}\), 0.015

Answer:
0.15%, 0.015, (3/20)

Explanation:
0.15% =(0.15/100) = 0.0015, (3/20) = 2.5

Question 32.
2.62, 2\(\frac{2}{5}\), 26.8%, 2.26, 271%

Answer:
2 x (2/5) ,26.8%, 2.26, 2.62, 2.71

Explanation:
2 x (2/5) = 0.024, 26.8% = 0.268, 271% = 2.71
So 0.024, 0.268, 2.26, 2.62, 2.71

Question 33.
\(\frac{87}{200}\), 0.44, 43.7%, \(\frac{21}{50}\)

Answer:
(21/50),0.44, 43.7%, (87/200)

Explanation:
(21/50) = 0.42, (87/200) = 0.435, 43.7% = 0.437

Question 34.
NUMBER SENSE
You answer 21 out of 25 questions correctly on a test. Do you reach your goal of answering at least 80% of the questions correctly?

Answer:
yes we reach our goal of answering .

Explanation:
We answer 21 out of 25 questions correctly on a test. Yes we reach our goal of answering 80%.

Question 35.
MODELING REAL LIFE
The table shows the approximate portions of the world population that live in four countries. Order the countries by population from least to greatest.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 58

PRECISION
Order the numbers from least to greatest.

Answer:
Russia, Brazil, India, United States.

Explanation:
Brazil = 2.8%
India = (7/40) = (7/40) x 100 = 17.5%
Russia = (1/50) = (1/50) x 100 = 2%
United States = 0.044 = (444/1000) x 100 = 44.4%

Question 36.
66.1%, 0.66, \(\frac{133}{200}\), 0.667

Answer:
0.66, 66.1%, (133/200), 0.667

Explanation:
66.1% = 0.661, (13/200) = 0.665

Question 37.
\(\frac{111}{500}\), 21%, 0.211, \(\frac{11}{50}\)

Answer:
21%, 0.211, (11/50), (111/500)

Explanation:
21% = 0.21, (11/50) = 0.22, (111/500) = 0.222

MATCHING
Tell which letter shows the graph of the number.

Question 38.
\(\frac{2}{5}\)

Question 39.
45.2%

Question 40.
0.435

Question 41.
\(\frac{89}{200}\)

Big Ideas Math Answers 6th Grade Chapter 4 Percents 59

Question 42.
PRECISION
The Tour de France is a bicycle road race. The whole race is made up of 21 small races called stages. The table shows how several stages compare to the whole Tour de France in a recent year. Order the stages by distance from shortest to longest.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 60

Answer:
Stage21, Stage 8, Stage1, Stage17, Stage7

Explanation:
Stage 1 = (11/200 x 100) = 5.5%
Stage 7 = (444/1000 x 100 )  = 44.4%
Stage 8 = (6/125 x 100) = 4.8%
Stage 17 = (6/100 x 100) = 6%
Stage 21 = 4%

Question 43.
PRECISION
The table shows the portions of the day that several animals sleep.
a. Order the animals by sleep time from least to greatest.
b. Estimate the portion of the day that you sleep.
c. Where do you fit on the ordered list?
Big Ideas Math Answers 6th Grade Chapter 4 Percents 61

Answer:
a : Dolphin, Rabbit, Lion, Squirrel,Tiger
b : 8 hours
c : Dolhpin:

Explanation:
a : dolphin = 43.3%, rabbit = (19/40 x 100) = 47.5%, squirrel = (31/50 x 100) = 62
b : I will sieep 8 hours per a day
c : Dolhpin

Question 44.
NUMBER SENSE
Tell what whole number you can substitute for a in each list so the numbers are ordered from least to greatest. If there is none, explain why.
a. \(\frac{1}{a}\), \(\frac{a}{20}\), 28%
b. \(\frac{3}{a}\), \(\frac{a}{5}\), 75%

Answer:
a : 0.1

Lesson 4.4 Solving Percent Problems

EXPLORATION 1

Using Percent Models
Work with a partner
a. Find the missing values. What does the model represent?
Big Ideas Math Answers 6th Grade Chapter 4 Percents 62

Answer:
The missing values of 15= 16.6%, (100/3) = 22.5, 40 = 62.5, 75% = 50

Explanation:
The missing value of 15 = (0+33.5)/2 = 16.6%
The missing value of 33.5 = (15 + 30)/2 = 22.5%
The missing value of 40 = (50 + 75)/2 = 62.5%
The missing value of 75 = (40 + 60)/2 = 50%

b. Label atleast three percents and their corresponding numbers on the model below. How do you know you are correct?
Big Ideas Math Answers 6th Grade Chapter 4 Percents 63

EXPLORATION 2
Solving a Percent Problem
Big Ideas Math Answers 6th Grade Chapter 4 Percents 64
Work with a partner. You purchase a national parks annual pass for 75% of the full price of the pass.
a. Suppose you know the full price or the discounted price. How can you find the other price? Compare your answers with other students in your class.
b. Suppose the full price of the pass is $80. How can you use a percent model to find the purchase price?
Big Ideas Math Answers 6th Grade Chapter 4 Percents 65

Answer:
If we purchase national parks annual pass for 75% = (75 x 80)/100 = 6
if they give 25% discount = (25 x 80)/100 = 20

Explanation:
We purchase a national parks annual pass for 75% of the full price . If the full price is 100% then the discounted price is 25% = 100%-25% = 75%
So if we purchase annual pass for 80% = (75 x 80)/100 = 6
If we purchase it for 25% = (25 x 80) /100 = 20
Big Ideas Math Answers 6th Grade Chapter 4 Percents 66

4.4 Lesson

Try It

Find the percent of the number.

Question 1.
90% of 20

Answer:
18

Explanation:
90% = (90/100) x 20 = 18

Question 2.
75% of 32

Answer:
24
Eplanation:
(75/100) x 32 = 24

Because n% means n per 100, you can also solve percent problems using part-to-whole ratios.

Try It

Find the percent of the number.

Question 3.
10% of 110

Answer:
11
Explanation:
(10/100) x 110 = 11

Question 4.
30% of 75

Answer:
22.5

Explanation:
(30/100) x 75 = 22.5

Try It

Find the whole.

Question 5.
15% of what number is 9?

Answer:
60

Explanation:
(15/100) x 60 = 9

Question 6.
5% of what number is 10?

Answer:
200

Explanation:
(5/100) x 200 = 10

Try It

Question 7.
62% of what number is 31?

Answer:
50

Explanation:
(62/100) x 50 = 31

Question 8.
125% of what number is 50?

Answer:
40

Explanation:
(120/100) x 40 = 50

Try It

Question 9.
The width of a rectangular stage is 55% of its length. The stage is 120 feet long. What is the area of the stage?

Self-Assessment for Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 10.
DIFFERENT WORDS, SAME QUESTION
Which is different? Find “both” answers.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 67

Answer:
Twenty percent of what number is 30 is different.

Explanations:
1 : (20/100) x 150 = 30
2 : (20/100) x ? = 30 then 30 x (100/20) = 150

Question 11.
FINDING THE PERCENT OF A NUMBER
Find 12% of 75.

Answer:
9
Explanation:
(12/100) x 75 = 9

Question 12.
FINDING THE WHOLE
35% of what number is 21?

Answer:
60

Explanation:
(35/100) x 60 = 21

Question 13.
NUMBER SENSE
If 52 is 130% of a number, is the number greater than or less than 52? Explain.

Answer:
The number is less than 52

Explanation:
(130/100) x 40 = 52. So 40 is less than 52

Question 14.
STRUCTURE
How can you find 10% of any number without multiplying or dividing? Explain your reasoning.

Answer:
(10/100) = (1/10) = 0.1

Explanation:
First, we have canceled zeros we got (1/10) automatically the point moves to the front then we get 0.1

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 15.
You raise $420 during a fundraising event. The amount of money that you raise is 120% of your goal. How much more did you raise than your goal?

Answer:
70$ I raise more than my goal

Explanation:
If i raise 120% of our goal for $420
So for 100% i raise more than 20%
(420 x 20)/120 = 70$

Question 16.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 68
A shirt is on sale for 60% of the original price. The original price is $28 more than the sale price. What was the original price?

Answer:
The original price is 70

Explanation:
A shirt is on sale for 60% that  means for 100% 40% is remaining.
The original price is $28 more than the sale price.
(100 x 28)/40 = 70

Question 17.
You have a meal at a restaurant. The sales tax is 8%. You leave a tip for the waitress that is 20% of the pretax price. You spend a total of $23.04. What is the pretax price of the meal?

Answer:
The pretax price of the meal =

Solving Percent Problems Homework & Practice 4.4

Review & Refresh

Order the numbers from least to greatest.

Question 1.
latex]\frac{1}{8}[/latex], 35%, 0.33

Answer:
(1/8), 0.33, 35%

Explanation:
(1/8) = 0.125, 35% = 0.35, 0.33 so 0.125, 0.33, 0.35

Question 2.
0.3, latex]\frac{9}{25}[/latex], 0.35, 33%

Answer:
0.3, 33%, 0.35, (9/25)

Explanation:
33% = 0.33, (9/25) = 0.36 . So 0.3, 0.33, 0.35, 0.36

Question 3.
latex]\frac{13}{50}[/latex], 22%, 0.28, latex]\frac{1}{5}[/latex], 0.41

Answer:
(1/5), 22%, 0.28, 0.41, (13/50)

Explanation:
(13/50) = 2.66, 22% = 0.22, (1/5) = 0.2 so (1/5), 22%, 0.28, 0.41,2.66 is from least to greatest.

Write the percent as a fraction or mixednumber in simplest form.

Question 4.
65%

Answer:
(65/100)

Explanation:
65% = (65/100)

Question 5.
0.45%

Answer:
(45/100)

Explanation:
0.45% = (45/100)

Question 6.
110%

Answer:
(110/100)

Explanation:
110% = (110/100)

Divide.

Question 7.
19.2 ÷ 1.6

Answer:
12

Explanation:
(19.2 % 1.6) = 12

Question 8.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 69

Answer:
10.2459016

Explanation:
(0.244 x 0.244) = 0.059536
0.61/0.244 = 10.2459016

Question 9.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 70

Answer:
2.89050757
Explanation:
(0.558 x 0.558) = 0.311364
0.9/0.311364 = 2.89050757

Question 10.
4.65 ÷ 0.003

Answer:
1550

Explanation:
(4.65 % 0.003) = 1550

The tape diagram represents the ratio of the time you spend online to the time your friend spends online. You are online for 30 minutes. How many minutes does your friend spend online?

Question 11.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 71

Answer:
2 hrs

Explanation:
I spend it online for 30 minutes and my friend spends it online for 2 hrs. The above diagram shows that 1:4 ratio that is 120 minutes.

Question 12.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 72

Answer:
45 minutes

Explanation:
1 spend it online for 30 minutes and my friend spends it online for 45 minutes. The above diagram shows that my friend spends 45 minutes in online.

Concepts, Skills, & Problem Solving

USING TOOLS
An annual pass to a park costs $120. Use a percent model to find the given percent of the full price of the annual pass. (See Exploration 2, p. 181.)

Question 13.
25%

Answer:
30$

Explanation:
(25/100) x 120 = 30$

Question 14.
50%

Answer::
60$

Explanation:
(50/100) x 120 = 60$

Question 15.
200%

Answer:
240$

Explanation:
(200/100) x 120 = 240$

FINDING THE PERCENT OF A NUMBER
Find the percent of the number. Explain your method.

Question 16.
20% of 60

Answer:
12

Explanation:
(20/100) x 60 = 12

Question 17.
10% of 40

Anwer:
4

Explanation:
(10/100) x 40 = 4

Question 18.
50% of 70

Answer:
35

Explanation:
(50/100) x 70 = 35

Question 19.
30% of 30

Answer:
9

Explanation:
(30/100) x 100 = 9

Question 20.
10% of 90

Answer:
9

Explanation:
(10/100) x 90 = 9

Question 21.
15% of 20

Answer:
3

Explanation:
(15/100) x 20 = 3

Question 22.
25% of 50

Answer:
12.5

Explanation:
(25/100) x 50 = 12.5

Question 23.
5% of 60

Answer:
3

Explanation:
(5/100) x 60 = 3

Question 24.
30% of 70

Answer:
21

Explanation:
(30/100) x 70 = 21

Question 25.
75% of 48

Answer:
36

Explanation:
(75/100) x 48 = 36

Question 26.
45% of 45

Answer:
20.25

Explanation:
(45/100) x 45 = 20.25

Question 27.
92% of 19

Answer:
17.48

Explanation:
(92/100) x 19 = 17.48

Question 28.
40% of 60

Answer:
24

Explanation:
(40/100) x 60 = 24

Question 29.
38% of 22

Answer:
8.36

Explanation:
(38/100) x 22 = 8.36

Question 30.
70% of 20

Answer:
14

Explanation:
(70/100) x 20 = 14

Question 31.
87% of 55

Answer:
47.85

Explanation:
(87/100) x 55 = 47.85

Question 32.
140% of 60

Answer:
84

Explanation:
(140/100) x 60 = 84

Question 33.
120% of 33

Answer:
39.6

Explanation:
(120/100) x 33 = 39.6

Question 34.
175% of 54

Answer:
94.5

Explanation:
(175/100) x 54 = 94.5

Question 35.
250% of 146

Answer:
365

Explanation:
(250/100) x 146 = 365

Question 36.
MODELING REAL LIFE
The tail of the spider monkey is 64% of the length shown. What is the length of the tail?
Big Ideas Math Answers 6th Grade Chapter 4 Percents 73

Answer:
28

Explanation:
The length of the tail is 28

Question 37.
PROBLEM SOLVING
A family pays $45 each month for cable television. The cost increases 7%.
a. How many dollars is the increase?

Answer:
3.15$

Explanation:
(7/100) x 45 = 3.15$
b. What is the new monthly cost?

Answer:
3.15$

Explanation:
The cost increases by 7% so we have to pay 3.15$ for the new month.

Question 38.
YOU BE THE TEACHER
Your friend finds 40% of 75. Is your friend correct? Explain your reasoning.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 74

Answer:
correct

Explanation:
40% = 0.4 so (40/100) x 75 = 0.4 x 75 = 30. Yes my friend is correct.

FINDING THE WHOLE
Find the whole. Explain your method.

Question 39.
10% of what number is 14?

Answer:
1.4

Explanation:
(14/10) = 1.4

Question 40.
20% of what number is 18?

Answer:
0.9

Explanation:
(18/20) = 0.9

Question 41.
25% of what number is 21?

Answer:
0.84

Explanation:
(21/25) = 0.84

Question 42.
75% of what number is 27?

Answer:
0.36

Explanation:
(27/75) = 0.36

Question 43.
15% of what number is 12?

Answer:
0.8

Explanation:
(12/15) = 0.8

Question 44.
85% of what number is 17?

Answer:
0.2

Explanation:
(17/85) = 0.2

Question 45.
140% of what number is 35?

Answer:
0.25

Explanation:
(35/140) = 0.25

Question 46.
160% of what number is 32?

Answer:
0.2

Explanation:
(32/160) = 0.2

Question 47.
125% of what number is 25?

Answer:
0.2

Explanation:
(25/125) = 0.2

Question 48.
175% of what number is 42?

Answer:
0.24

Explanation:
(42/175) = 0.24

Question 49.
YOU BE THE TEACHER
Your friend answers the question “20% of what number is 5?” Is your friend correct? Explain your reasoning.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 75

Answer:
correct

Explanation:
(5/20) = 0.25 = (1/4)

Question 50.
PROBLEM SOLVING
You have a coupon for a restaurant. You save $3 on a meal. What was the original cost of the meal?
Big Ideas Math Answers 6th Grade Chapter 4 Percents 76

Answer:
12$

Explanation:
The original cost of the meal is 12$ because they save 3$ on a meal.

Question 51.
PROBLEM SOLVING
The results of a survey are shown at the right. In the survey, 12 students said that they would like to learn French. How many of the students surveyed would like to learn Spanish?

Big Ideas Math Answers 6th Grade Chapter 4 Percents 77

Answer:
18

Explanation:
The students who would like to learn French is 12. The students who would like  to learn spanish is 18

Question 52.
MODELING REAL LIFE
A sixth grader weighs 90 pounds, which is 120% of what he weighed in fourth grade. How much did he weigh in fourth grade?

Answer:
60

Explanation:

Question 53.
LOGIC
In an asteroid field, 75% of the asteroids are carbonaceous asteroids. There are 375,000 carbonaceous asteroids in the asteroid field. How many asteroids are not carbonaceous?

Answer:
281250

Explanation:
(75/100) x  375,000 = 281250

Question 54.
DIG DEEPER!
A bottle contains 20 fluid ounces of lotion and sells for $5.80. The 20-fluid-ounce bottle contains 125% of the lotion in the next smallest size, which sells for $5.12. Which is the better buy? Explain.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 78

COMPARING PERCENTS
Copy and complete the statement using <, >, or =

Question 55.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 79

Answer:
equals to

Explanation:
80% = 0.8, (80/100) x 60 = 48
60% = 0.6, (60/100) x 80 = 48 so both the values are equal.

Question 56.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 80

Answer:
6 is less than 12

Explanation:
20% = 0.2, (20/100) x 30 = 6
30% = 0.3, (30/100) x 40 = 12 so 6 is less than 12

Question 57.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 81

Answer:
6 is greater than 2

Explanation:
120% = 1.2, (120/100) x 5 = 6
0.8% = 0.008, (0.8/100) x 250 = 2 so 6 is greater than 2.

Question 58.
Big Ideas Math Answers 6th Grade Chapter 4 Percents 82

Answer:
equals to

Explanation:
85% = 0.85, (85/100) x 40 = 34
25% = 0.25, (25/100) x 136 = 34 so both the values are equal

Question 59.
Time
How many minutes is 40% of 2 hours?

Answer:
48 minutes

Explanation:
120 x (40/100) = 48

Question 60.
LENGTH
How many inches is 78% of 3 feet?

Answer:

Explanation:

Question 61.
GEOMETRY
The width of the rectangle is 75% of its length.
a. What is the area of the rectangle?

Answer:
108

Explanation:
Area of the Rectangle = L x W, width =( 75/100) x 24 = 18, L = (25/100) x 24 = 6 so (18 x 6 ) = 108
b. The length of the rectangle is doubled. What percent of the length is the width now? Explain your reasoning.
Big Ideas Math Answers Grade 6 Chapter 4 Percents 83

Answer:

Question 62.
PRECISION
To pass inspection, a new basketball should bounce between 68% and 75% of the starting height. A new ball is dropped from 6 feet and bounces back 4 feet 1 inch. Does the ball pass inspection? Explain.

Answer:
Yes the ball passes the inspection.

Explanation:
If the ball is dropped from 6 feet and it bounces back 4 feet 1 inch so it bounces 68% then it satisfies the condition.

Question 63.
REASONING
You know that 15% of a number n is 12. How can you use this to find 30% of n? 45% of n? Explain.

Answer:
To find 30% = 24
To find 45% = 36

Explanation:
(15/100) x 80 = 12 = n
(30/100) x 80 = 24
(45/100) x 80 = 36

Question 64.
REASONING
You have a coupon for 10% off the sale price of a surfboard. Which is the better buy? Explain your reasoning.

  • 40% off the regular price
  • 30% off the regular price and then 10% off the sale price

Big Ideas Math Answers Grade 6 Chapter 4 Percents 84

Answer:
40% of the regular price is better to buy.

Explanation:
40% is the better buy because they are giving more discount than the other.

Question 65.
CRITICAL THINKING
Consider two different numbers x and y. Is x% of y the same as y% of x? Justify your answer

Answer:
same

Explanation:
X = 10 and Y = 50 then X% of Y = (10/100) x 50 = 5
Y% of X = (50/100) x 10 =5

Question 66.
GEOMETRY
Square ABCD and Square EFGH both have side lengths of 8 inches. The squares overlap and form Rectangle ABGH, which has a length of 10 inches. What percent of Rectangle ABGH is shaded purple?
Big Ideas Math Answers Grade 6 Chapter 4 Percents 85

Answer:
60%

Explanation:
In the above figure, the square ABCD and EFGH have 8 inches. The percent of Rectangle ABGH shaded purple is 60%. Total percent is 100% so 100-40 = 60

Question 67.
NUMBER SENSE
On three 150-point geography tests, you earned grades of 88%, 94%, and 90%. The final test is worth 250 points. What percent do you need on the final to earn 93% of the total points on all tests?
Big Ideas Math Answers Grade 6 Chapter 4 Percents 86

Answer:
97.2%

Explanation:
(88 + 94 +90) x 150 + p x 250 = 93 x (3 x 150 + 250)
40800 + 250p = 65100
250p = 24300
p = 24300/250
p = 97.2%

Percents Connecting Concepts

4 Connecting Concepts

Using the Problem-Solving Plan

Question 1.
During a football game, a total of 63 points are scored by the two teams. Team A scores 80% of the number of points that Team B scores. What is the final score of the game?
Big Ideas Math Answers Grade 6 Chapter 4 Percents 87

Understand the Problem
You know that Team A’s score is 80% of Team B’s score, and the total points scored is 63. You are asked to find the final score of the football game.
Make a Plan
Because 80% means 80 per 100, write the relationship between the scores of the teams as a ratio. Then represent the situation using a tape diagram. Use the total points to find the value of each part of the tape diagram and the final score of the game.
Solve and check
Use the plan to solve the problem.

Question 2.
A pen at a pet store contains male and female guinea pigs. The ratio of female guinea pigs to male guinea pigs is 7 to 3. Find the percent of guinea pigs in the pen that is male. Justify your answer.

Answer:
30

Explanation:
(7/10) x 100 =  30. 30 % of guinea pigs are male

Question 3.
You multiply two numbers. The first number, 21, is 6.25% of the product. What is the second number? Justify your answer.

Answer:
29.76

Explanation:
The first number x second number = product of two numbers.
21 x X = (625/100) x 100
X = 625/21= 29.76

Question 4.
You have a bag containing dollar coins, dimes, and pennies. The bag contains 40 coins. The number of dollar coins is 20% of the total number of coins. The number of pennies is \(\frac{7}{9}\) of the number of dimes. How much money is in the bag?
Big Ideas Math Solutions Grade 6 Chapter 4 Percents 88

Answer:
8 rs  are there in the bag

Explanation:
The bag contains 40 coins.
The number of dollar coins is 20% of the total number of coins that is 40 coins.

Performance Task

Genetic Ancestry
At the beginning of this chapter, you watched a STEAM video called “Chargaff’s Rules.” You are now ready to complete the performance task for this video, available at BigIdeasMath.com. Be sure to use the problem-solving plan as you work through the performance task.
Big Ideas Math Solutions Grade 6 Chapter 4 Percents 89

Percents Chapter Review

Review Vocabulary
Write the definition and give an example of the vocabulary term.
percent, p. 164

Answer:
A part of a whole expressed in hundredths.
(42/100) = 0.42

Graphic Organizers

You can use a Four Square to organize information about a concept. Each of the four squares can be a category, such as definition, vocabulary, example, non-example, words, algebra, table, numbers, visual, graph, or equation. Here is an example of a Four Square for finding the percent of a number.

Big Ideas Math Solutions Grade 6 Chapter 4 Percents 90

Choose and complete a graphic organizer to help you study the concept.
Big Ideas Math Solutions Grade 6 Chapter 4 Percents 91

  1. percent
  2. writing percents as fractions
  3. writing fractions as percents
  4. writing percents as decimals
  5. writing decimals as percents
  6. finding the whole

Chapter Self-Assessment

As you complete the exercises, use the scale below to rate your understanding of the success criteria in your journal.
Big Ideas Math Solutions Grade 6 Chapter 4 Percents 92

4.1 Percents and Fractions (pp. 163 – 168)

Question 1.
12%

Answer:
(12/100)

Explanation:
(12/100) = 12%

Question 2.
88%

Answer:
(88/100)

Explanation:
(88/100) = 88%

Question 3.
0.8%

Answer:
(0.8/100)

Explanation:
(0.8/100) = 0.8%

Question 4.
127%

Answer:
(127/100)

Explanation:
(127/100) = 127%

Question 5.
2.5%

Answer:
(2.5/100)

Explanation:
(2.5/100) = 2.5%

Question 6.
18%

Answer:
(18/100)

Explanation:
(18/100) = 18%

Write the fraction or mixed number as a percent.

Question 7.
\(\frac{3}{5}\)

Answer:

Question 8.
1\(\frac{18}{25}\)

Answer:
72%

Explanation:
(18/25) = 0.72 x 100 = 72

Question 9.
1\(\frac{21}{50}\)

Answer:
42%

Explanation:
(21/50) = 0.42 x 100 = 42

Question 10.
\(\frac{14}{35}\)

Answer:
0.04%

Explanation:
(14/35) = 0.4 x 100 = 0.04%

Question 11.
5\(\frac{7}{25}\)

Answer:
5.28

Explanation:
5 x (7/25) = (132/25) = 5.28

Question 12.
\(\frac{7}{400}\)

Answer:
1.75

Explanation:
(7/400) x 100 = (7/4) = 1.75

Question 13.
Write a fraction in simplest form that is greater than 43% and less than 47%.

Answer:
(9/20)

Explanation:
45% is greater than 43% and 47%
45% = (45/100) = (9/20)

Question 14.
Write a percent thatis greater than 3\(\frac{3}{4}\) and less than 3\(\frac{4}{5}\).

Question 15.
Your computer displays the progress of a downloading video. What fraction of the video is downloaded?
Big Ideas Math Solutions Grade 6 Chapter 4 Percents 93

Answer:
23:50
Explanation:
In the above figure it displays 46% and the remaining 54% is downloading. So (46/100) = (23/50).

Question 16.
You complete 40% of your homework problems before dinner. What fraction of the problems did you complete before dinner?

Answer:
2:5
Explanation:
40% = (40/100) = (2/5) = 2:5

Question 17.
There are nine different colonies of bacteria on the Petri dish. What percent of the bacteria on the Petri dish is from Colony 3?
Big Ideas Math Solutions Grade 6 Chapter 4 Percents 94

Answer:
33.3

Explanation:
(3/9) x 100 = 33.3

4.2 Percent and Decimals

Write the percent as a decimal.

Question 18.
76%

Answer:
0.76

Explanation:
76% = (76/100) = 0.76

Question 19.
6%

Answer:
0.06

Explanation:
6% = (6/100) = 0.06

Question 20.
17%

Answer:
0.17

Explanation:
17% = (17/100) = 0.17

Question 21.
0.8%

Answer:
0.008

Explanation:
0.8% = (0.8/100) = 0.008

Question 22.
0.016%

Answer:
0.00016

Explanation:
0.016 = (0.016/100) 0.00016

Question 23.
334%

Answer:
3.34

Explanation:
334% = (334/100) = 3.34

Write the decimal as a percent.

Question 24.
0.15

Answer:
15%

Explanation:
(15/100) = 0.15

Question 25.
0.77

Answer:
77%

Explanation:
(77/100) = 0.77

Question 26.
0.56

Answer:
56%

Explanation:
(56/100) = 0.56

Question 27.
1.06

Answer:
106%

Explanation:
(106/100) = 1.06

Question 28.
1.24

Answer:
124%

Explanation:
(124/100) = 1.24

Question 29.
0.097

Answer:

Question 30.
Write a decimal that is greater than 0.62% and less than 0.64%.

Answer:
63

Explanation:
0.63% is greater than 0.64% and less than 0.62%
0.63% = (0.63/100) = 63

Question 31.
Write a percent that is greater than 0.026 and less than 0.028.

Answer:
2.7

Explanation:
2.7 is greater than 0.026 and less than 0.028
(0.027/100) = 2.7

Question 32.
On a fishing trip, 38% of the fish that you catch are perch. Write this percent as a decimal.
Big Ideas Math Solutions Grade 6 Chapter 4 Percents 95

Answer:
0.38

Explanation:
(38/100) = 0.38

4.3 Comparing and Ordering Fractions, Decimals, and Percents (pp. 175 – 180)

Tell which number is greater.

Question 33.
\(\frac{1}{2}\), 52%

Answer:
52%

Explanation:
52% = (52/100) =0.52, (1/2) = 0.5. So 52% is greater

Question 34.
\(\frac{12}{5}\), 245%

Answer:
245%

Explanation:
245% = 2.45. (12/5) = 2.4 so 245% is greater

Question 35.
0.46, 43%

Answer:
0.46

Explanation:
43% = 0.43, 0.46 = 46%

Question 36.
0.023, 22%

Answer:
22%

Explanation:
22% = 0.22, 0.023

Order the numbers from least to greatest.

Question 37.
\(\frac{9}{4}\), 220%, 2.15, 218%

Answer:
220%, 2.15, 218%,(9/4)

Explanation:
220% = 2.2, (9/4) = 2.25, 218% = 2.18

Question 38.
0.88, \(\frac{7}{8}\), 92%, 0.89

Answer:
(7/8), 0.88, 0.89, 92%

Explanation:
(7/8) = 0.875, 92% = 0.92

Question 39.
Write a percent that is greater than \(\frac{13}{25}\) and less than 0.54.

Question 40.
The table shows the portions of students in your grade who participate in five activities. List the activities in order by number of students from least to greatest.
Big Ideas Math Solutions Grade 6 Chapter 4 Percents 96

4.4 Solving Percent Problems (pp. 181–188)

Find the percent of the number. Explain your method.

Question 41.
60% of 80

Answer:
48

Explanation:
60% = (60/100) x 80 = 0.6 x 80 =48

Question 42.
80% of 55

Answer:
44

Explanation:
80% = (80/100) x 55 = 0.8 x 55 = 44

Question 43.
150% of 48

Answer:
72

Explanation:
150% = (150/100) x 48 = 1.5 x 48 = 72

Question 44.
42% of 150

Answer:
63

Explanation:
42% = (42/100) x 150 = 0.42 x 150 = 63

Question 45.
112% of 75

Answer:
84

Explanation:
112% = (112/100) x 75  = 1.12 x 75 = 84

Question 46.
45% of 42

Answer:
18.9

Explanation:
45% = (45/100) x 42 = 0.45 x 42 = 18.9

Find the whole. Explain your method.

Question 47.
70% of what number is 35?

Answer:
0.5

Explanation:
(35/70) = 0.5

Question 48.
28% of what number is 21?

Answer:
0.75

Explanation:
(21/28) = 0.75

Question 49.
56% of what number is 84?

Answer:
1.5

Explanation:
(84/56) = 1.5

Question 50.
20% of what number is 96?

Answer:
4.8

Explanation:
(96/20) = 4.8

Question 51.
140% of what number is 56?

Answer:
0.4

Explanation:
(56/140) = 0.4

Question 52.
175% of what number is 112?

Answer:
0.64

Explanation:
(112/175) = 0.64

Question 53.
Each cell of a dog contains 78 chromosomes. Exactly 50% of the chromosomes are inherited from the father. How many chromosomes in each cell of the dog are inherited from the father?
Big Ideas Math Solutions Grade 6 Chapter 4 Percents 97

Answer:
39 chromosomes in each cell of the dog are inherited from the father

Explanation:
50% = (78/2) = 39

Question 54.
You went to the mall with $80. You spent 25% of your money on a pair of shorts and 65% of the remainder on sandals. How much did you spend on the sandals? Which country would you most like to visit?

Answer:

Question 55.
The results of the survey are shown at the left. In the survey, 7 students said that they would most like to visit Italy. How many of the students surveyed would most like to visit Ireland?
Big Ideas Math Solutions Grade 6 Chapter 4 Percents 98

Answer:
2 students

Explanation:
(8/4) = 2

Question 56.
You answer 24 questions on a 100-point test correctly and earn a 96%.
a. All of the questions are worth the same number of points. How many questions are on the test? How many points is each question worth?

Answer:
25 questions are on the test
b. Your friend earns a grade of 76% on the same test. How many questions did your friend answer correctly?

Answer:
19

Explanation:
My friend answer 19 questions correctly

Percents Practice Test

4 Practice Test

Write the fraction or mixed number as a percent.

Question 1.
\(\frac{21}{25}\)

Answer:
84%

Explanation:
(21/25) = 0.84 = 84

Question 2.
\(\frac{17}{20}\)

Answer:
85%

Explanation:
(17/20) = 0.85 = 85

Question 3.
1\(\frac{2}{5}\)

Answer:
0.4%

Explanation:
(2/5) = 0.4

Write the decimal as a percent.

Question 4.
0.42

Answer:
42%

Explanation:
42%  = (42/100) = 0.42

Question 5.
7.88

Answer:
788%

Explanation:
788% = (788/100) = 7.88

Question 6.
0.5854

Answer:
5854%

Explanation:
5854% = (5854/10000) = 0.5854

Write the percent as a fraction in simplest form and as a decimal.

Question 7.
0.96%

Answer:
Fraction= 24:25, Decimal = 0.0096

Explanation:
0.96% = (0.96/100) = 0.0096

Question 8.
65%

Answer:
Fraction = 13:20, Decimal = 0.65

Explanation:
65% = 0.65, (65/100) = 13:20

Question 9.
25.7%

Answer:
Fraction =

Tell which number is greater.

Question 10.
\(\frac{16}{25}\), 65%

Answer:
65% is greater

Explanation:
(16/25) = 0.64, 65% = (65/100) = 0.65. So 65% is greater

Question 11.
56%, 5.6

Answer:
5.6 is greater

Explanation:
56% = (56/100) = 0.56 . So 5.6 is greater

Order the numbers from least to greatest.

Question 12.
85%, \(\frac{7}{10}\), 0.74, \(\frac{4}{5}\)

Answer:
(7/10), 0.74, 0.8, 0.85

Explanation:
85% = 0.85, (7/10) = 0.7, (4/5) = 0.8

Question 13.
130%, 1.32, \(\frac{6}{5}\), \(\frac{5}{4}\), 1.28

Answer:
(6/5), (5/4), 1.28, 130%, 1.32

Explanation:
130% = (130/100) = 1.3, (6/5) = 1.2, (5/4) = 1.25

Question 14.
80% of 90 is what number?

Answer:
72

Explanation:
80% = (80/100) =0.8 x 90  =72

Question 15.
120% of 75 is what number?

Answer:
112.5

Explanation:
120% = (120/100) = 1.2 x 112.5

Question 16.
40% of what number is 34?

Answer:
0.34

Explanation:
(34/40) = 0.34

Question 17.
130% of what number is 52?

Answer:
0.4

Explanation:
(52/130) = 0.4

Question 18.
A goalie’s saves (.) and goals scored against (×) are shown. What percent of shots did the goalie save? Explain.
Big Ideas Math Solutions Grade 6 Chapter 4 Percents 99

Answer:
2%

Explanation:
Two dots are there. So 2%

Question 19.
About 62% of the human body is composed of water. Write this percent as a fraction in simplest form.

Answer:
31:50

Explanation:
62% = (62/100) = 31:50

Question 20.
You, your cousin, and a friend each take the same number of free throws at a basketball hoop. You make \(\frac{17}{20}\) of your free throws, your cousin makes 0.8 of her free throws, and your friend makes 87.5% of his free throws. Who made the most free throws?

Answer:

Question 21.
In a class of 20 students, 40% are boys. Twenty-five percent of the boys and 50% of the girls wear glasses. How many students in the class wear glasses?

Answer:
15 students in the class wear glasses.

Explanation:
In the above given question there are 20 students. So 75% of students wear glasses that means the students who wear glasses is 15.

Question 22.
Eighty percent of the picture frame is glass. What is the area of the moulding?
Big Ideas Math Solutions Grade 6 Chapter 4 Percents 101

Answer:
91.375

Explanation:
(17/2) = 8.5
(43/4) = 10.75
Area = l x b = 91.375

Percents Cumulative Practice

Question 1.
How many pints are in 8 quarts?
A. 2 pints
B. 4 pints
C. 16 pints
D. 32 pints

Big Ideas Math Solutions Grade 6 Chapter 4 Percents 102

Answer:
16 pints

Explanation:
16 pints = 8 quarts

Question 2.
Which fraction is not equivalent to 25%?
Big Ideas Math Solutions Grade 6 Chapter 4 Percents 103

Answer:
(2/5) is not equivalent to 25%

Explanation:
25% = (25/100), 25% = (5/20), 25% = (1/4). So (2/5) is not equivalent to 25%

Question 3.
What is the missing value in the ratio table?
Big Ideas Math Solutions Grade 6 Chapter 4 Percents 104

Answer:
28

Explanation:
In the above given table 2 x 2 x 2 = 8, 8 x 2 =16. 7 x 2 x 2 = 28, 28 x 2 = 56.  The  missing value in the ratio table is 28.

Question 4.
Your friend was finding the percent of a number in the box below.
Big Ideas Math Solutions Grade 6 Chapter 4 Percents 105
What should your friend do to correct the error?
A. Divide 24 by 25.
B. Divide \(\frac{1}{4}\) by 24.
C. Multiply 24 by 25.
D. Multiply 24 by \(\frac{1}{4}\).

Answer:
option b is correct

Explanation:
(25/100) x 24 = 6

Question 5.
Which percent is equivalent to \(\frac{4}{5}\)?
F. 20%
G. 45%
H. 80%
I. 125%

Answer:
80% is equivalent to (4/5)

Explanation:
80% = (80/100) 0.8 , (4/5) = 0.8. So 80% is equivalent to (4/5)

Question 6.
Which pair of numbers does not have a least common multiple less than 100?
A. 10, 15
B. 12, 16
C. 16, 18
D. 18, 24

Answer:
Option c is correct

Explanation:
16, 18 = 108 is least common multiple less than 100.

Question 7.
You are comparing the costs of buying bottles of water at the supermarket. Which of the following has the least cost per liter?
F. 6 one-liter bottles for $1.80
G. 1 two-liter bottle for $0.65
H. 8 half-liter bottles for $1.50
I. 12 half-liter bottles for $1.98

Answer:
one liter bottle for $1.80

Explanation:
one liter bottle for $1.80

Question 8.
What is 75% of 36?
Big Ideas Math Solutions Grade 6 Chapter 4 Percents 106

Answer:
27

Explanation:
(75/100) x 36 = 27

Question 9.
Which number is equivalent to \(\frac{5}{12}\) × \(\frac{4}{9}\) ?
A. \(\frac{5}{27}\)
B. \(\frac{3}{7}\)
C. \(\frac{15}{16}\)
D. \(\frac{5}{3}\)

Answer:
Option A is equivalent to (5/12) x (4/9)

Explanation:
(5/12) x (4/9) = 0.18518518. S0 (5/27) = 0.18518517. So both values are equal.

Question 10.
Which list of numbers is in order from least to greatest?
F. 0.8, \(\frac{5}{8}\), 70%, 0.09
G. \(\frac{5}{8}\), 70%, 0.8, 0.09
H. 0.09, \(\frac{5}{8}\), 0.8, 70%
I. 0.09, \(\frac{5}{8}\), 70%, 0.8

Answer:
0.09, (5/8) , 70%, 0.8

Explanation:
(5/8) = 0.625, 70% = 0.7

Question 11.+
Which number is equivalent to 1.32 ÷ 0.006?
A. 2.2
B. 22
C. 220
D. 2200

Answer:
220

Explanation:
(1.32 / 0.006) = 220

Question 12.
Which ratio is equivalent to 4 : 14?
F. 2 : 12
G. 10 : 35
H. 18 : 28
I. 8 : 18

Answer:
Option G is correct

Explanation:
4 : 14 = 2 : 7 , 10 : 35 = 2 :7

Question 13.
For a party, you make a gelatin dessert in a rectangular pan and cut the dessert into equal-sized pieces, as shown below.
Big Ideas Math Solutions Grade 6 Chapter 4 Percents 107
Big Ideas Math Solutions Grade 6 Chapter 4 Percents 108
The dessert consists of 5 layers of equal height. Each layer is a different flavor, as shown below by a side view of the pan.
Big Ideas Math Solutions Grade 6 Chapter 4 Percents 109
Your guests eat \(\frac{3}{5}\) of the pieces of the dessert.
Part A
Write the amount of cherry gelatin that your guests eat as a fraction of the total dessert. Justify your answer.
Part B
Write the amount of cherry gelatin that your guests eat as a percent of the total dessert. Justify your answer.

Conclusion:

I hope the information given in the Big Ideas Math Answers Grade 6 Chapter 4 Percents benefits all the candidates who are in middle school. You can get free access to Big Ideas Math Answer Key Grade 6 Chapter 4 Percents to make your preparation successful. We are here to clarify all your doubts, so you can post in the below comment box. Moreover, bookmark our page to get the preparatory material and solution key of grade 6 Big Ideas Math Answers. Get instant updates on all information regarding percents.

Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers

Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers

Get Big Ideas Math Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers Answer Key PDF here. If you are seeking help in learning math problems and various concepts, then refer to this page. The professionals and experts suggested several ways to learn Multiplying and Dividing Rational Numbers questions.

Find the best solutions and methods to solve various problems. Practice the questions of Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers to score better marks in the exam. Refer to the next sections to get the complete idea of various topics involved in Multiplying and Dividing Rational Numbers. Practice as many questions as from the material and get perfect in all ways.

Big Ideas Math Book 7th Grade Answer Key Chapter 2 Multiplying and Dividing Rational Numbers

Big Ideas Math Answers Grade 7 Chapter 2 involves various topics like dividing integers, multiplying rational numbers, dividing rational numbers, multiplying integers, dividing integers, conversion between fractions and decimals. We are providing the various Cumulative Practice material, Chapter Review material, multiplying rational numbers, dividing rational numbers, etc.

Practice all these topics and get a clear idea of what is important and what is not. Follow all the important tips and tricks to get perfection in multiplying and dividing rational numbers. Get a final conclusion on advantages, formulae, and important concepts of rational numbers. Attend many mock tests and know how to manage your time to answer all the questions in the exam.

Performance

Lesson: 1 Multiplying Integers

Lesson: 2 Dividing Integers

Lesson: 3 Converting Between Fractions and Decimals

Lesson: 4 Multiplying Rational Numbers

Lesson: 5 Dividing Rational Numbers

Chapter: 2 – Multiplying and Dividing Rational Numbers

Multiplying and Dividing Rational Numbers STEAM Video/Performance

STEAM Video

Carpenter or Joiner

Carpenters and joiners must be precise with their measurements when building structures. In what other real-life situations must measurements be precise?
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 1

Watch the STEAM Video “Carpenter or Joiner.” Then answer the following questions.

Question 1.
Robert says that changes in water content cause wood to shrink or expand across the grain more than along the grain. What does this mean?

Answer:
Robert says that changes in water content cause wood to expand across the grain. So, the carpenter has to make the measurements 1/16 inches.

Question 2.
Describe how you can cut a log so that the pieces shrink in different ways as they dry out.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 1.1

Answer:
While cutting the log, you need to take the correct measurement to avoid the pieces shrink in different ways as they dry out.

Performance Task

Precisely Perfect

After completing this chapter, you will be able to use the concepts you learned to answer the questions in the Video Performance Task. You will be given the accuracies of seven telescopes. For example:
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 2
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 3
You will be asked to compare the accuracies of the telescopes. Why do different telescopes have different accuracies?

Multiplying and Dividing Rational Numbers Getting Ready for Chapter 2

Chapter Exploration

Question 1.
Work with a partner. Use integer counters to find each product. Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 4
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 4.1

Work with a partner. Use integer counters to find the product.

Answer:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 1

Explanation:
a. (+3) x (-2) = -6
The integers have different signs, so the product is a negative value.
b. (-2) x (-2) = 4
The integers have the same sign, so the product is a positive value.
c. (-2) x (+3) = -6

Question 2.
(+3) × (+2)

Answer:
(+3) x (+2) = +6

Explanation:
The given expression is (+3) x (+2)
The integers have the same sign. So the product is a positive value.
(+3) x (+2) = +6

Question 3.
(+3) × (-1)

Answer:
(+3) × (-1) = -3

Explanation:
The given expression is (+3) × (-1)
The integers have different signs. So the product is a negative value.
(+3) × (-1) = -3

Question 4.
(+2) × (-4)

Answer:
(+2) × (-4) = -8

Explanation:
The given expression is (+2) × (-4)
The integers have different signs. So the product is a negative value.
(+2) × (-4) =-8

Question 5.
(-3) × (+2)

Answer:
(-3) × (+2) = -6

Explanation:
The given expression is
The integers have different signs. So the product is a negative value.
(-3) × (+2) = -6

Question 6.
(-2) × (-3)

Answer:
(-2) × (-3) = +6

Explanation:
The given expression is (-2) × (-3)
The integers have the same sign. So the product is a positive value.
(-2) × (-3) = +6

Question 7.
(-1) × (-4)

Answer:
(-1) × (-4) = +4

Explanation:
The given expression is (-1) × (-4)
The integers have the same sign. So the product is a positive value.
(-1) × (-4) = +4

Question 8.
(-1) × (-2)

Answer:
(-1) × (-2) = +2

Explanation:
The given expression is (-1) × (-2)
The integers have the same sign. So the product is a positive value.
(-1) × (-2) = +2

Question 9.
(+3) × (+1)

Answer:
(+3) × (+1) = 3

Explanation:
The given expression is (+3) × (+1) = 3
The integers have the same sign. So the product is a positive value.
(+3) × (+1) = 3

Question 10.
(-3) × (-2)

Answer:
(-3) × (-2) = +6

Explanation:
The given expression is (-3) × (-2)
The integers have the same sign. So the product is a positive value.
(-3) × (-2) = +6

Question 11.
(-2) × (+2)

Answer:
(-2) × (+2) = -4

Explanation:
The given expression is (-2) × (+2)
The integers have different signs. So the product is a negative value.
(-2) × (+2) = -4

Question 12.
(-2) × (+4)

Answer:
(-2) × (+4) = -8

Explanation:
The given expression is (-2) × (+4)
The integers have different signs. So the product is a negative value.
(-2) × (+4) = -8

Question 13.
(-4) × (-2)

Answer:
(-4) × (-2) = +8

Explanation:
The given expression is (-4) × (-2)
The integers have the same sign. So the product is a positive value.
(-4) × (-2) = +8

Question 14.
MAKE A CONJECTURE
Use your results in Exercises 1–13 to determine the sign of each product.
a. negative integer and a positive integer
b. two negative integers
c. two positive integers

Answer:
a. When you multiply a negative integer and a positive integer, the product is a negative integer.
b. When you multiply two negative integers, then the product is a positive integer.
c. If you multiply two positive integers, then the product is a positive integer.

Explanation:
a. negative integer and a positive integer
When you multiply a negative integer and a positive integer, the product is a negative integer.
b. two negative integers
When you multiply two negative integers, then the product is a positive integer.
c. two positive integers
If you multiply two positive integers, then the product is a positive integer.

Vocabulary

The following vocabulary terms are defined in this chapter. Think about what each term might mean and record your thoughts.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 4.2

Lesson 2.1 Multiplying Integers

EXPLORATION 1
Understanding Products Involving Negative Integers
Work with a partner.
a. The number line and integer counters model the product 3 • 2. How can you find 3 • (-2)? Explain.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 4.3
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 4.4
b. Use the tables to find -3 • 2 and -3 • (-2). Explain your reasoning.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 4.5
c.
INDUCTIVE REASONING
Complete the table. Then write general rules for multiplying

  1. two integers with the same sign and
  2. two integers with different signs.

Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 4.6

Answer:
a. 3 . 2 = 6
3 . (-2) = -6
b. Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 2
c. Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 3

Explanation:
a. The product of 3 and 2 is 6
Both the integers are positive. So, the product is also positive.
3 . (-2) = -6
The reason is one integer is positive and another integer is negative. So, the result is negative.
b. The product of two positive or negative integers is a positive integer. The product of one positive and second negative integers is a negative integer.
c. In any expression, integers are having the same sign, which means the product is positive. If the integers are having a different sign, then the product is negative.

2.1 Lesson

Try It

Find the product.

Question 1.
5 • 5

Answer:
5 . 5 = 25

Explanation:
The given expression is 5 . 5
The given integers have the same sign. So the product is a positive integer.
5 . 5 = 25

Question 2.
-1(-9)

Answer:
-1(-9) = +9

Explanation:
The given expression is -1(-9)
The given integers have the same sign. So the product is a positive integer.
-1(-9) = +9

Question 3.
-7 • (-8)

Answer:
-7 • (-8) = 56

Explanation:
The given expression is -7 • (-8)
The given integers have the same sign. So the product is a positive integer.
-7 • (-8) = 56

Question 4.
12 • (-2)

Answer:
12 • (-2) = -24

Explanation:
The given integers are 12, -2
Integers have different signs. So, the product is a negative integer.
12 • (-2) = -24

Question 5.
4(-6)

Answer:
4(-6) = -24

Explanation:
The given integers are 4, -6
Integers have different signs. So, the product is a negative integer.
4(-6) = -24

Question 6.
-25(0)

Answer:
-25(0) = 0

Explanation:
The given integers are -25, 0
Integers have different signs. So, the product is a negative integer.
-25(0) = 0
When you multiply any number with zero, the product is also zero.

Try It

Evaluate the expression.

Question 7.
8 • (-15) • 0

Answer:
8 • (-15) • 0 = 0

Explanation:
The given expression is 8 • (-15) • 0
Use the commutative property of the multiplication
= -120 . 0
= 0

Question 8.
24 – 33

Answer:
24 – 3³ = -3

Explanation:
The given expression is 24 – 3³
Write 3³ as a repeated multiplication
= 24 – (3 . 3 . 3)
= 24 – 27
= -3

Question 9.
10 – 7(3 – 5)

Answer:
10 – 7(3 – 5) = 24

Explanation:
The given expression is 10 – 7(3 – 5)
Perform the operations in the parenthesis
= 10 – 7(-2)
= 10 + 14
= 24

Self-Assessment for Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 10.
WRITING
What can you conclude about two integers whose product is (a) positive and (b) negative?

Answer:
If the product of two integers is positive, then those integers are with the same sign. If the product of two integers is negative, then those integers are having different signs.

Explanation:
The two integers product is a positive integer means those integers are with two positive signs or two negative signs.
For example 4 . 2 = 8, (-4) . (-2) = 8
The two integers is a negative integer means those are having one positive integer and negative integer irrespective of the order.
Examples are -4 . 2 = -8, 4 . -2 = -8

EVALUATING AN EXPRESSION
Evaluate the expression.

Question 11.
4(-8)

Answer:
4(-8) = -32

Explanation:
The given expression is 4(-8)
Here integers are having different signs. So the product is a negative integer.
4(-8) = -32

Question 12.
-5(-7)

Answer:
-5(-7) = 35

Explanation:
The given expression is -5(-7)
The product of two integers with the same sign is positive.
-5(-7) = 35

Question 13.
12 – 32 • (-2)

Answer:
12 – 3² • (-2) = 30

Explanation:
The given expression is 12 – 3² • (-2)
Write 3² as a repeated multiplication
= 12 – (3 . 3) . (-2)
= 12 – 9 . (-2)
The product of two integers with the same sign is positive.
= 12 + 18
= 30

REASONING
Tell whether the statement is true or false. Explain your reasoning.

Question 14.
The product of three positive integers is positive.

Answer:
True

Explanation:
The product of three positive integers is positive The reason is the product of two positive integers is positive. Again perform the product of an obtained positive integer with the third positive integer to get a positive integer.

Question 15.
The product of three negative integers is positive.

Answer:
False

Explanation:
The product of three negative integers is always a negative integer. Because the product of two negative integers is a positive integer. The product of obtained positive integer and remaining negative integer is a negative integer. So, the product of three integers is not positive.

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 16.
On a mountain, the temperature decreases by 18°F for each 5000-foot increase in elevation. At 7000 feet, the temperature is 41°F. What is the temperature at 22,000 feet? Justify your answer.

Answer:
The temperature at 22,000 feet is 95°F

Explanation:
Change in temperature over 5000 feet = 18°F
The temperature at 7000 feet = 41°F
The temperature at 22000 feet = 7000 + 5000x
22000 – 7000 = 5000x
15000 = 5000x
x = 15000/5000
x = 3
So, the temperature at 22000 feet is 41 + 3(18)
= 41 + 54 = 95°F

Question 17.
Players in a racing game earn 3 points for each coin they collect. Each player loses 5 points for each second that he or she finishes after the first-place finisher. The table shows the results of a race. List the players in order from greatest to least number of points.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 4.7
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 4.8

Answer:
Player 3, Player 2, Player 1, Player 4.

Explanation:
Players in a racing game earn 3 points for each coin they collect.
The number of coins earned by the players are listed here.
Player 2 = 18 x 3 = 54 points
Player 3 takes 3 seconds more than player 2 to finish the game.
So, player 3 number of points = (24 . 3) – (5 . 3) = 72 – 15 = 57
Player 4 takes 6 seconds more than player 2 to finish the game.
So, the number of points earned by player 4 = (27 . 3) – (5 . 6)
= 81 – 30 = 51
Player 1 takes 8 seconds more than player 2 to finish the game.
So, the number of points earned by player 1 = (31 . 3) – (5 . 8)
= 93 – 40 = 53
Hence, the number of coins earned by the players are Player 3 = 57, Player 2 = 53, Player 1 = 53, Player 4 = 51

Multiplying Integers Homework & Practice 2.1

Review & Refresh

Find the distance between the two numbers on a number line.

Question 1.
-4.3 and 0.8

Answer:
5.1

Explanation:
The distance between -4.3 and 0.8 = | 0.8 – (-4.3) |
= | 0.8 + 4.3 | = | 5.1 |
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers4

Question 2.
-7.7 and -6.4

Answer:
1.3

Explanation:
The distance between -7.7 and -6.4 = | -6.4 – (-7.7) |
= | -6.4 + 7.7 | = | 1.3 |
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 5

Question 3.
-2\(\frac{3}{5}\) and -1

Answer:
3.6

Explanation:
The distance between -2(3/5) or -13/5 and 1 = | 1 – (-13/5) |
= | 1 + 13/5 | = | (5 + 13)/5 |
= | 18/5 | = | 3.6 |
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 6

Divide.

Question 4.
27 ÷ 9

Answer:
27 ÷ 9 = 3

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 7

Question 5.
48 ÷ 6

Answer:
48 ÷ 6 = 8

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 8

Question 6.
56 ÷ 4

Answer:
56 ÷ 4 = 14

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 9

Question 7.
153 ÷ 8

Answer:
153 ÷ 8 = 19 R 1

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 10

Question 8.
What is the prime factorization of 84?
A. 22 × 32
B. 23 × 7
C. 33 × 7
D. 22 × 3 × 7

Answer:
D. 2² x 3 x 7

Explanation:
Divide 84 by 2
84/2 = 42
Divide 42 by 2
42/2 = 21
divide 21 by 3
21/3 = 7
Divide 7 by 7
7/7 = 1
So, the prime factorization of 84 is 2 x 2 x 3 x 7 = 2² x 3 x 7

Concepts, Skills, & Problem Solving
CHOOSE TOOLS
Use a number line or integer counters to find the product. (See Exploration 1, p. 49.)

Question 9.
2(-4)

Answer:
2(-4) = -8

Explanation:
2 . -4
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 11

Question 10.
-6(3) = -18

Answer:
-6(3)

Explanation:
-6. 3
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 12

Question 11.
4(-5)

Answer:
4(-5) = -20

Explanation:
4(-5)
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 13
So, 4(-5) = -20

MULTIPLYING INTEGERS
Find the product.

Question 12.
6 • 4

Answer:
6 • 4 = 24

Explanation:
The product of two integers with the same sign is positive.
6 • 4 = 24

Question 13.
7(-3)

Answer:
7(-3) = -21

Explanation:
The product of two integers with the different sign is negative.
7(-3) = -21

Question 14.
-2(8)

Answer:
-2(8) = -16

Explanation:
The product of two integers with different sign is negative.
-2(8) = -16

Question 15.
-3(-4)

Answer:
-3(-4) = 12

Explanation:
The product of two integers with the same sign is positive.
-3(-4)= 12

Question 16.
-6 • 7

Answer:
-6 • 7= -42

Explanation:
The product of two integers with different sign is negative.
-6 • 7 = -42

Question 17.
3 • 9

Answer:
3 • 9 = 27

Explanation:
The product of two integers with the same sign is positive.
3 • 9 = 27

Question 18.
8 • (-5)

Answer:
8 • (-5) = -40

Explanation:
The product of two integers with different sign is negative.
8 • (-5) = -40

Question 19.
-1 • (-12)

Answer:
-1 • (-12) = 12

Explanation:
The product of two integers with the same sign is positive.
-1 • (-12) = 12

Question 20.
-5(10)

Answer:
-5(10) = -50

Explanation:
The product of two integers with different sign is negative.
-5(10) = -50

Question 21.
-13(0)

Answer:
-13(0) = 0

Explanation:
The product of two integers with different sign is negative.
-13(0) = -0 = 0

Question 22.
-9 • 9

Answer:
-9 • 9 = -81

Explanation:
The product of two integers with different sign is negative.
-9 • 9 = -81

Question 23.
15(-2)

Answer:
15(-2) = -30

Explanation:
The product of two integers with different sign is negative.
15(-2) = -30

Question 24.
-10 • 11

Answer:
-10 • 11 = -110

Explanation:
The product of two integers with different sign is negative.
-10 • 11 = -110

Question 25.
-6 • (-13)

Answer:
-6 • (-13) = 78

Explanation:
The product of two integers with the same sign is positive.
-6 • (-13) = 78

Question 26.
7(-14)

Answer:
7(-14) = -98

Explanation:
The product of two integers with different sign is negative.
7(-14) = -98

Question 27.
-11 • (-11)

Answer:
-11 • (-11) = 121

Explanation:
The product of two integers with the same sign is positive.
-11 • (-11) = 121

Question 28.
MODELING REAL LIFE
You burn 10 calories each minute you jog. What integer represents the change in your calories after you jog for 20 minutes?

Answer:
The change in your calories after you jog for 20 minutes is 200.

Explanation:
The number of calories you burn per minute = 10
The change in your calories after you jog for 20 minutes = 20 x 10 = 200

Question 29.
MODELING REAL LIFE
In a four-year period, about 80,000 acres of coastal wetlands in the United States are lost each year. What integer represents the total change in coastal wetlands?
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 6

Answer:
The total change in coastal wetlands is 20000 acres.

Explanation:
In A 4 year period, About 80,000 acres of coastal wetlands in United States are lost each year.
so, total area =80000 acres
total time = 4 years
now, we can use formula
total change in wetlands = ( total area)/(total time)
now, we can put values
total change in wetlands = 80000/4 = 20000

EVALUATING EXPRESSIONS
Evaluate the expression.

Question 30.
(-4)2

Answer:
(-4)² = 16

Explanation:
(-4)² = -4 . -4 = 16

Question 31.
-62

Answer:
-6² = -36

Explanation:
-6² = -6. 6 = -36

Question 32.
-5 • 3 • (-2)

Answer:
-5 • 3 • (-2) = 30

Explanation:
-5 • 3 • (-2) = -15 . (-2)
= 30

Question 33.
3 • (-12) • 0

Answer:
3 • (-12) • 0 = 0

Explanation:
3 • (-12) • 0 = -36 . 0 = 0

Question 34.
-5(-7)(-20)

Answer:
-5(-7)(-20) = -700

Explanation:
-5(-7)(-20) = -5 . -7 (-20) = 35 . -20 = -700

Question 35.
5 – 82

Answer:
5 – 8² = -59

Explanation:
5 – 8² = 5 – (8 . 8)
= 5 – 64 = -59

Question 36.
-52 • 4

Answer:
-5² . 4 = -100

Explanation:
-5² . 4 = -5 . 5 . 4
= -25 . 4 = -100

Question 37.
-2 • (-3)3

Answer:
-2 • (-3)³ = 54

Explanation:
-2 • (-3)³ = -2 . (-3 . -3 . -3)
= -2 . (-3 . 9)
= -2 . -27 = 54

Question 38.
2 + 1 • (-7 + 5)

Answer:
2 + 1 • (-7 + 5) = 0

Explanation:
2 + 1 • (-7 + 5) = 2 + 1 . (-2)
= 2 – 2 = 0

Question 39.
4 – (-2)3

Answer:
4 – (-2)³ = 12

Explanation:
4 – (-2)³ = 4 – (-2 . -2 . -2)
= 4 – (-2 . 4) = 4 – (-8)
= 4 + 8 = 12

Question 40.
4 • (25 • 32)

Answer:
4 • (25 • 3²) = 900

Explanation:
4 • (25 • 3²) = 4 . (25 . 3 . 3)
= 4 . (25 . 9) = 4 . 225
= 900

Question 41.
-4(32 – 8) + 1

Answer:
-4(3² – 8) + 1 = -3

Explanation:
-4(3² – 8) + 1 = -4(3 . 3 – 8) + 1
= -4(9 – 8) + 1
= -4(1) + 1 = -4 + 1 = -3

YOU BE THE TEACHER
Your friend evaluates the expression. Is your friend correct? Explain your reasoning.

Question 42.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 7

Answer:
Wrong

Explanation:
The product of two integers with the same sign is positive.
So, -2(-7) = 14

Question 43.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 8

Answer:
Correct

Explanation:
The product of two integers with different sign is negative.
-10² = -10 . 10 = -100

PATTERNS
Find the next two numbers in the pattern.

Question 44.
-12, 60, -300, 1500, ….

Answer:
The next two numbers in the pattern are -7500, 37500

Explanation:
Multiply each integer by -5
-12 x -5 = 60
60 x -5 = -300
-300 x -5 = 1500
1500 x -5 = -7500
-7500 x -5 = 37500

Question 45.
7, -28, 112, -448,…..

Answer:
The next two numbers in the pattern are 1792, -7168

Explanation:
Multiply each integer by -4
7 x -4 = -28
-28 x -4 = 112
112 x -4 = -448
-448 x -4 = 1792
1792 x -4 = -7168

Question 46.
PROBLEM SOLVING
In a scavenger hunt, each team earns 25 points for each item that they find. Each team loses 15 points for every minute after 4:00 P.M. that they report to the city park. The table shows the number of items found by each team and the time that each team reported to the park. Which team wins the scavenger hunt? Justify your answer.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 9

Answer:
Team D wins the scavenger hunt.

Explanation:
Each team earns 25 points for each item that they find. Each team loses 15 points for every minute after 4:00 P.M
The points earned by Team A = (13 x 25) – (15 x 3) = 325 – 45 = 280
The points earned by Team B = (15 x 25) – (15 x 7) = 375 – 105 = 270
The points earned by Team C = (11 x 25) = 275
The points earned by Team D = (12 x 25) – (1 x 15) = 300 – 15 = 285
Finally, Team D scores the highest points.
Hence, Team D wins the scavenger hunt.

Question 47.
REASONING
The height of an airplane during a landing is given by 22,000 + (-480t), where t is the time in minutes. Estimate how many minutes it takes the plane to land. Explain your reasoning.

Answer:
It takes 45 minutes for the plane to land.

Explanation:
The height of an airplane during a landing = 22,000 + (-480t)
= 22,000 – 480t
After landing, the height of the airplane = 0
So, 22,000 – 480t = 0
22000 = 0 + 480t
480t = 22000
t = 22000/480
t = 2200/48
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 14
So, it takes 45 minutes for the plane to land.

Question 48.
PROBLEM SOLVING
The table shows the price of a bluetooth speaker each month for 4 months.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 10
a. Describe the change in the price of the speaker.
b. The table at the right shows the amount of money you save each month. When do you have enough money saved to buy the speaker? Explain your reasoning.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 11

Answer:
a. The Bluetooth speaker price decreased by 12 dollars every month.
b. You can buy the speaker in the month of September.

Explanation:
a. The table shows that the change in the price of the Bluetooth speaker per every month is -12. So, the Bluetooth speaker price decreased by 12 dollars per every month.
b.
The amount of money you saved in June is $35, the price of the speaker is $165.
The amount of money you saved in July is 35 + 55 = $90, the price of the speaker is 165 – 12 = $153
The amount of money you saved in august is 90 + 45 = $135, the price of the speaker is 165 – 24 = $141
The amount of money you saved in September is 135 + 18 = $153, the price of the speaker is 165 – 36 = 129
So, you can buy the speaker in the month of September.

Question 49.
DIG DEEPER!
Two integers, a and b, have a product of 24. What is the least possible sum of a and b?

Answer:
The least possible sum of a and b is -25.

Explanation:
The product of a and b = 24
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 15
The least possible sum of a and b is -25.

Question 50.
NUMBER SENSE
Consider two integers p and q. Explain why p × (-q) = (-p) × q = -pq

Answer:
We know that,
the product of two integers with the different sign is negative.
p × (-q)
Here p is a positive integer, q is a negative integer
(-p) × q
Here p is a negative integer and q is a positive integer.
So, the product is negative

Lesson 2.2 Dividing Integers

EXPLORATION 1

Understanding Quotients Involving Negative Integers
Work with a partner.
a. Discuss the relationship between multiplication and division with your partner.
b. INDUCTIVE REASONING
Complete the table. Then write general rules for dividing

  1. two integers with the same sign and
  2. two integers with different signs.

Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 12
c. Find the values of Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 13 What do you notice? Is this true for Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 14 when a and b are integers? Explain.
d. Is every quotient of integers a rational number? Explain your reasoning.

Answer:
a. Multiplication and division are two opposite operations.
b. Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 16
c. True
d. Yes

Explanation:
a. Multiplication and division are the reverse operations. When you multiply two numbers, you will get the product. Divide the product by any one of the multiplicand to get another multiplicand.
b. When two integers have the same sign then the quotient is positive. If two integers have different signs then the quotient is negative. When any one of the integers is zero, then the quotient is zero.
c. -(8/4) = -(2) = -2
-8/4 = -2
8/-4 = -2
Yes, -(8/4), 8/-4, -8/4 are true.
d. Every quotient of integers a rational number.

2.2 Lesson

Try It

Find the quotient.

Question 1.
14 ÷ 2

Answer:
14 ÷ 2 = 7

Explanation:
The quotient of two integers with the same sign is positive.
14 ÷ 2 = 7

Question 2.
-32 ÷ (-4)

Answer:
-32 ÷ (-4) = 8

Explanation:
The quotient of two integers with the same sign is positive.
-32 ÷ (-4) = 8

Question 3.
-40 ÷ (-8)

Answer:
-40 ÷ (-8) = 5

Explanation:
The quotient of two integers with the same sign is positive.
-40 ÷ (-8) = 5

Try It

Find the quotient.

Question 4.
0 ÷ (-6)

Answer:
0 ÷ (-6) = 0

Explanation:
The quotient of two integers with the different signs is negative.
0 ÷ (-6) = 0

Question 5.
\(\frac{-49}{7}\)

Answer:
-49 ÷ 7 = -7

Explanation:
The quotient of two integers with the different signs is negative.
-49 ÷ 7 = -7

Question 6.
\(\frac{21}{-3}\)

Answer:
21 ÷ -3 = -7

Explanation:
The quotient of two integers with the different signs is negative.
21 ÷ -3 = -7

Try It

Evaluate the expression when a = 18 and b = -6.

Question 7.
a ÷ b

Answer:
18 ÷ -6 = -3

Explanation:
a ÷ b
Put a = 18, b = -6
18 ÷ -6 = -3
The quotient of two integers with the different signs is negative.

Question 8.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 13.1

Answer:
8

Explanation:
The given expression is (a + 6)/3
Put a = 18
= (18 + 6)/3 = 24/3
The quotient of two integers with the same sign is positive.
24/3 = 8

Question 9.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 14.1

Answer:
-50

Explanation:
The given expression is b²/a + 4
Put a = 18, b = -6
= 18²/-6 + 4
= 324/-6 + 4
The quotient of two integers with the different signs is negative.
= -54 + 4 = -50

Self-Assessment for Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 10.
WRITING
What can you conclude about two integers whose quotient is (a) positive, (b) negative, or (c) zero?

Answer:
If the quotient of two integers is positive then the integers are having the same sign.
The quotient of two integers is negative when the integers are having different signs.
The quotient of two integers is zero when any one of the integers is zero.

DIVIDING INTEGERS
Find the quotient.

Question 11.
-12 ÷ 4

Answer:
-12 ÷ 4 = -3

Explanation:
The quotient of two integers with the different signs is negative.
-12 ÷ 4 = -3

Question 12.
\(\frac{-6}{-2}\)

Answer:
-6 ÷ -2 = 3

Explanation:
The quotient of two integers with the same sign is positive.
-6 ÷ -2 = 3

Question 13.
15 ÷ (-3)

Answer:
15 ÷ (-3) = -5

Explanation:
The quotient of two integers with the different signs is negative.
15 ÷ (-3) = -5

Question 14.
WHICH ONE DOESN’T BELONG?
Which expression does not belong with the other three? Explain your reasoning.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 15

Answer:
-10/-5

Explanation:
Out of all expressions, -10/-5 is different. Because in all remaining expressions, the negative sign is applicable to either numerator or denominator. But in -10/-5 the negative sign is applicable to both numerator and denominator.

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 15.
A female grizzly bear weighs 500 pounds. After hibernating for 6 months, she weighs only 350 pounds. What is the mean monthly change in weight?
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 15.2

Answer:
The mean change in weight per month is 50 pounds.

Explanation:
A female grizzly bear weighs 500 pounds
After hibernating for 6 months, she weighs only 200 pounds
Mean change in weight = 500 – 200 = 300
6 months = 300 pounds
Divide both sides by 6
6 months/6 = 300/6
1 month = 50 pounds
The mean change in weight per month is 50 pounds.

Question 16.
The table shows the change in the number of crimes committed in a city each year for 4 years. What is the mean yearly change in the number of crimes?
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 16

Answer:
The mean yearly change in the number of crimes are -49.

Explanation:
Mean = (sum of observations)/ number of observations
= (215 – 321 – 185 + 95)/4
= -196/4 = -49
The mean yearly change in the number of crimes are -49.

Question 17.
DIG DEEPER!
At a restaurant, when a customer buys 4 pretzels, the fifth pretzel is free. Soft pretzels cost $3.90 each. You order 12 soft pretzels. What is your mean cost per pretzel?

Answer:
The mean cost per pretzel is $2.925.

Explanation:
At a restaurant, when a customer buys 4 pretzels, the fifth pretzel is free.
The cost of soft pretzels is $3.90
You order 12 soft pretzels
So, you need to pay for (4 + 4 + 4) – 3 = 12 – 3 = 9
The cost for 9 soft pretzels = 9 x 3.90 =35.1
The mean cost per pretzel = (35.1)/12 = $2.925

Dividing Integers Homework & Practice 2.2

Review & Refresh

Find the product.

Question 1.
8 • 10

Answer:
8 • 10 = 80

Explanation:
The product of two integers with the same sign is positive.
8 • 10 = 80

Question 2.
-6(9)

Answer:
-6(9) = -54

Explanation:
The product of two integers with different signs is negative.
-6(9) = -54

Question 3.
4(7)

Answer:
4(7) = 28

Explanation:
The product of two integers with the same sign is positive.
4(7) = 28

Question 4.
-9(-8)

Answer:
-9(-8) = 72

Explanation:
The product of two integers with the same sign is positive.
-9(-8) = 72

Order the numbers from least to greatest.

Question 5.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 17

Answer:
0.24, 1/4, 28%

Explanation:
28% = 28/100 = 0.28
1/4 = 0.25
0.24
The order of numbers from the least to greatest is 0.24, 0.25, 0.28

Question 6.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 18

Answer:
2/5, 42%, 0.45

Explanation:
42% = 42/100 = 0.42
0.45
2/5 = 0.4
The order of numbers from the least to greatest is 0.4, 0.42, 0.45

Question 7.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 19

Answer:
0.69, 7/10, 71%, 0.84, 9/10

Explanation:
7/10 = 0.7
0.69
71% = 71/100 = 0.71
9/10 = 0.9
0.84
The order of numbers from the least to greatest is 0.69, 0.7, 0.71, 0.84, 0.9

Write an addition expression and write a subtraction expression represented by the number line. Then evaluate the expressions.

Question 8.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 20

Answer:
Addition expression is 0 + 5 = 5
Subtraction expression is 5 – 1 = 4

Explanation:
The red line on the number line represents
5 – 1 = 4
The blue line on the number line represents
0 + 5 = 5

Question 9.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 21

Answer:
The addition expression is -3 + 3 = 0
The subtraction expression is 0 – 3 = -3

Explanation:
The red line on the number line represents
0 – 3 = -3
The blue line on the number line represents
-3 + 3 = 0

Concepts, Skills, & Problem Solving
CHOOSE TOOLS
Complete the table. (See Exploration 1, p. 55.)
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 22

Answer:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 17

Explanation:
10. 14 ÷ (-2) = -7
11. -24 ÷ 12 = -2
12. -55 ÷ (-5) = 11

DIVIDING INTEGERS
Find the quotient, if possible.

Question 13.
4 ÷ (-2)

Answer:
4 ÷ (-2) = -2

Explanation:
The quotient of two integers with the different signs is negative.
4 ÷ (-2) = -2

Question 14.
21 ÷ (-7)

Answer:
21 ÷ (-7) = -3

Explanation:
The quotient of two integers with the different signs is negative.
21 ÷ (-7) = -3

Question 15.
-20 ÷ 4

Answer:
-20 ÷ 4 = -5

Explanation:
The quotient of two integers with the different signs is negative.
-20 ÷ 4 = -5

Question 16.
-18 ÷ (-3)

Answer:
-18 ÷ (-3) = 6

Explanation:
The quotient of two integers with the same sign is positive.
-18 ÷ (-3) = 6

Question 17.
\(\frac{-14}{2}\)

Answer:
-14 ÷ 2 = -7

Explanation:
The quotient of two integers with the different signs is negative.
-14 ÷ 2 = -7

Question 18.
\(\frac{0}{6}\)

Answer:
0 ÷ 6 = 0

Explanation:
If any of the integers is zero in the division expression, then the quotient is zero.
0 ÷ 6 = 0

Question 19.
\(\frac{-15}{-5}\)

Answer:
-15 ÷ -5 = 3

Explanation:
The quotient of two integers with the same sign is positive.
-15 ÷ -5 = 3

Question 20.
\(\frac{54}{-9}\)

Answer:
54 ÷ -9 = -6

Explanation:
The quotient of two integers with the different signs is negative.
54 ÷ -9 = -6

Question 21.
\(-\frac{33}{11}\)

Answer:
-33 ÷ 11 = -3

Explanation:
The quotient of two integers with the different signs is negative.
-33 ÷ 11 = -3

Question 22.
-49 ÷ (-7)

Answer:
-49 ÷ (-7) = 7

Explanation:
The quotient of two integers with the same sign is positive.
-49 ÷ (-7) = 7

Question 23.
0 ÷ (-2)

Answer:
0 ÷ (-2) = 0

Explanation:
If any of the integers is zero in the division expression, then the quotient is zero.
0 ÷ (-2) = 0

Question 24.
\(\frac{60}{-6}\)

Answer:
60 ÷ -6 = -10

Explanation:
The quotient of two integers with the different signs is negative.
60 ÷ -6 = -10

Question 25.
\(\frac{-56}{14}\)

Answer:
-56 ÷ 14 = -4

Explanation:
The quotient of two integers with the different signs is negative.
-56 ÷ 14 = -4

Question 26.
\(\frac{18}{0}\)

Answer:
18 ÷ 0 = 0

Explanation:
If any of the integers is zero in the division expression, then the quotient is zero.
18 ÷ 0 = 0

Question 27.
\(-\frac{65}{5}\)

Answer:
-65 ÷ 5 = -13

Explanation:
The quotient of two integers with the different signs is negative.
-65 ÷ 5 = -13

Question 28.
\(\frac{-84}{-7}\)

Answer:
-84 ÷ -7 = 12

Explanation:
The quotient of two integers with the same sign is positive.
-84 ÷ -7 = 12

YOU BE THE TEACHER
Your friend finds the quotient. Is your friend correct? Explain your reasoning.

Question 29.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 23

Answer:
Wrong

Explanation:
The quotient of two integers with the same sign is positive.
-63 ÷ -9 = 7

Question 30.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 24

Answer:
0 ÷ (-5) = 0

Explanation:
If any of the integers is zero in the division expression, then the quotient is zero.
0 ÷ (-5) = 0

Question 31.
MODELING REAL LIFE
You read 105 pages of a novel over 7 days. What is the mean number of pages you read each day?
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 24.1

Answer:
The mean is 15 pages a day.

Explanation:
To find the mean of the pages we read each day we will evaluate the quotient of the division of the number of pages we read over these days (105 days) by the number of days (7 days).
105 / 7 = 15
The mean is 15 pages a day.

USING ORDER OF OPERATIONS
Evaluate the expression.

Question 32.
-8 – 14 ÷ 2 + 5

Answer:
-8 – 14 ÷ 2 + 5 = -10

Explanation:
The given expression is -8 – 14 ÷ 2 + 5
-8 – (14 / 2) + 5
= -8 – 7 + 5
= -15 + 5 = -10

Question 33.
24 ÷ (-4) + (-2) • (-5)

Answer:
24 ÷ (-4) + (-2) • (-5) = 4

Explanation:
The given expression is 24 ÷ (-4) + (-2) • (-5)
= -6 + (-2) . (-5)
= -6 + 10
= 4

EVALUATING EXPRESSIONS
Evaluate the expression when x = 10, y = -2, and z = -5.

Question 34.
x ÷ y

Answer:
-5

Explanation:
The given expression is x ÷ y
Put x = 10, y = -2
= 10 ÷ -2
The quotient of two integers with the different signs is negative.
= -5

Question 35.
12 ÷ 3y

Answer:
-2

Explanation:
The given expression is 12 ÷ 3y
Put y = -2
= 12 ÷ 3(-2)
= 12 ÷ -6
The quotient of two integers with the different signs is negative.
= -2

Question 36.
\(\frac{2 z}{y}\)

Answer:
5

Explanation:
The given expression is 2z/y
Put y = -2, and z = -5.
= 2(-5)/(-2)
= -10/-2
The quotient of two integers with the same sign is positive.
= 5

Question 37.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 25

Answer:
-2

Explanation:
The given expression is (-x + y)/6
Put x = 10, y = -2
= (-10 + (-2))/6
= (-10 – 2)/6
= -12/6
The quotient of two integers with the different signs is negative.
= -2

Question 38.
100 ÷ (-z2)

Answer:
4

Explanation:
The given expression is 100 ÷ (-z2)
Put z = -5
= 100 ÷(-(-5)²)
= 100 ÷ (25)
The quotient of two integers with the same sign is positive.
= 4

Question 39.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 25.1

Answer:
-8

Explanation:
The given expression is (10y²)/z
Put y = -2, and z = -5
= (10(-2)²)/-5
= 10(4)/-5
= 40/-5
The quotient of two integers with the different signs is negative.
= -8

Question 40.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 25.2

Answer:
25

Explanation:
The given expression is | (xz)/-y |
Put x = 10, y = -2, and z = -5
= | (10 . -5)/-(-2) |
= | -50/2 |
= 50/2
= 25

Question 41.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 25.3

Answer:
65

Explanation:
The given expression is (-x² + 6z)/y
Put x = 10, y = -2, and z = -5
= (-(10)² + 6(-5))/-2
= (-100 – 30)/-2
= -130/-2
= 65

Question 42.
PATTERNS
Find the next two numbers in the pattern -128, 64, -32, 16, . . .. Explain your reasoning.

Answer:
The next two numbers in the pattern are -8, 4.

Explanation:
Divide each integer by -2
-128/-2 = 64
64/-2 = -32
-32/-2 = 16
16/-2 = -8
-8/-2 = 4
So, the next two numbers in the pattern are -8, 4.

Question 43.
MODELING REAL LIFE
The Detroit-Windsor Tunnel is an underwater highway that connects the cities of Detroit, Michigan, and Windsor, Ontario. How many times deeper is the roadway than the bottom of the ship?
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 26

Answer:
5 times deeper is the roadway than the bottom of the ship.

Explanation:
The deep of the bottom of the ship = -15 ft
The deep of the roadway = -75 ft
To find out how many times deeper is the roadway than the bottom of the ship, divide the deep of the roadway by the deep of the bottom of the ship
-75 / -15 = 5 times
So, 5 times deeper is the roadway than the bottom of the ship

Question 44.
MODELING REAL LIFE
A snowboarder descends from an elevation of 2253 feet to an elevation of 1011 feet in 3 minutes. What is the mean change in elevation per minute?

Answer:
The mean change in elevation per minute is 414 ft.

Explanation:
A snowboarder descends from an elevation of 2253 feet to an elevation of 1011 feet in 3 minutes
So, the mean change in elevation per minute = (2253 – 1011)/3
= 1242/3 = 414 ft

Question 45.
REASONING
The table shows a golfer’s scores relative to par for three out of four rounds of a tournament.
a. What was the golfer’s mean score per round for the first 3 rounds?
b. The golfer’s goal for the tournament is to have a mean score no greater than -3. Describe how the golfer can achieve this goal.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 25.5
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 28

Answer:
a. The golfer’s mean score per round for the first 3 rounds is -2
b. The score in round 4 should be less than -6.

Explanation:
a. The golfer’s mean score per round for the first 3 rounds = (1 + (-4) + (-3))/3
= (1 – 4 – 3)/3 = (1 – 7)/3
= -6/3 = -2
b. The golfer’s goal for the tournament is to have a mean score no greater than -3.
(1 + (-4) + (-3) + x)/4 < -3
(1 – 4 – 3 + x)/4 <-3
(1 – 7 + x)/4 <-3
(-6 + x)/4 < -3
(-6 + x) < -3 . 4
(-6 + x) < -12
x < -12 + 6
x < -6
The score at the round 4 should be less than -6.

Question 46.
PROBLEM SOLVING
The regular admission price for an amusement park is $72. For a group of 15 or more, the admission price is reduced by $25 per person. How many people need to be in a group to save $500?

Answer:
20 people needed in the group to save $500.

Explanation:
Let the number of people is x
The price of the person reduced by $25
The total price we want to save is $500
x = 500/25 = 20
So, the number of people x needs to be in the group to save $500 is 20 people.

Question 47.
DIG DEEPER!
Write a set of five different integers that has a mean of -10. Explain how you found your answer.

Answer:
The set of five different integers whose mean is -10 are (-12, -11, -10, -9 -8).

Explanation:
Let us take the 5 integers as x, x + 1, x + 2, x + 3, x + 4
The mean of these integers is -10
(x + x + 1 + x + 2 + x + 3 + x + 4)/5 = -10
(5x + 10)/5 = -10
5x + 10 = -10 . 5
5x + 10 = -50
5x = -50 – 10
5x = -60
x = -60/5
x = -12
So, the set of 5 integers are -12, -12 + 1 = -11, -12 + 2 = -10, -12 +3 = -9, -12 + 4 = -8

Lesson 2.3 Converting Between Fractions and Decimals

EXPLORATION 1

Analyzing Denominators of Decimal Fractions
Work with a partner.
a. Write each decimal as a fraction or mixed number.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 29
b. What do the factors of the denominators of the fractions you wrote have in common? Is this always true for decimal fractions?
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 30

EXPLORATION 2
Exploring Decimal Representations
Work with a partner.
a. A fraction \(\frac{a}{b}\) can be interpreted as a ÷ b. Use a calculator to convert each unit fraction to a decimal. Do some of the decimals look different than the others? Explain.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 31
b. Compare and contrast the fractions in part(a) with the fractions you wrote in Exploration 1. What conclusions can you make?
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 32
c. Does every fraction have a decimal form that either terminates or repeats? Explain your reasoning.

2.3 Lesson

Try It

Write the fraction or mixed number as a decimal.

Question 1.
\(-\frac{6}{5}\)

Answer:
-6/5 = -1.2

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 19

Question 2.
-7\(\frac{3}{8}\)

Answer:
-7(3/8) = -7.375

Explanation:
-7(3/8) = -59/8
Use long division to divide 59 by 8
g Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 20

Question 3.
\(-\frac{3}{11}\)

Answer:
-3/11 = 0.2727

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 21
The remainder repeats. So, it is a repeating decimal.

Question 4.
1\(\frac{5}{27}\)

Answer:
1(5/27) =1.185

Explanation:
1(5/27) =32/27
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 22

Try It

Write the decimal as a fraction or mixed number in simplest form.

Question 5.
-0.3

Answer:
-0.3 = -3/10

Explanation:
-0.3 = -3/10

Question 6.
0.125

Answer:
0.125 = 1/8

Explanation:
0.125 = 125/1000
= (5 . 25)/(5 . 200)
= (5 . 5)/(5 . 40)
= 5/(8 . 5)
= 1/8

Question 7.
-3.1

Answer:
-3.1 = -31/10

Explanation:
-3.1 = -31/10

Question 8.
-10.25

Answer:
-10.25 = -41/4

Explanation:
-10.25 = -1025/100
= -(5 . 205)/(20 . 5)
= -(5 . 41)/(5 . 4)
= -41/4

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 9.
WRITING
Compare and contrast terminating decimals and repeating decimals.

Answer:
A rational number can be expressed as either a terminating decimal or a repeating decimal. Divide numerator by the denominator you will get a remainder of 0, then you have a terminating decimal. The remainders will begin to repeat after some point, and you have a repeating decimal.
The example for terminating decimal is 5/8 = 0.625
The example for repeating decimal is 7/12 = 0.58333.

WRITING A FRACTION OR MIXED NUMBER AS A DECIMAL
Write the fraction or mixed number as a decimal.

Question 10.
\(\frac{3}{16}\)

Answer:
3/16 = 0.1875

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 23

Question 11.
–\(\frac{7}{15}\)

Answer:
-7/15 = -0.4666

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 24

Question 12.
6\(\frac{17}{20}\)

Answer:
6(17/20) = 6.85

Explanation:
6(17/20) = 137/20
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 25

WRITING A DECIMAL AS A FRACTION OR MIXED NUMBER
Write the decimal as a fraction or mixed number in simplest form.

Question 13.
0.6

Answer:
0.6 = 3/5

Explanation:
0.6 = 6/10
= 3/5

Question 14.
-12.48

Answer:
-12.48 = -312/25

Explanation:
-12.48 = -1248/100
= -(4 . 312)/(4 . 25)
= -312/25

Question 15.
0.408

Answer:
0.408 = 51/125

Explanation:
0.408 = 408/1000
= (51 . 8)/(125 . 8)
= 51/125

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 16.
A box turtle hibernates in sand at an elevation of 1.625 feet. A spotted turtle hibernates at an elevation of -1\(\frac{7}{12}\) feet. Which turtle hibernates deeper in the sand? How much deeper?
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 33

Answer:
Box turtle hibernates deeper in the sand.

Explanation:
A box turtle hibernates in sand at an elevation of 1.625 feet.
A spotted turtle hibernates at an elevation of -1(7/12) feet
= -19/12 = -1.58333
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 26
1.625 is greater than -1.5833.
So, box turtle hibernates deeper in the sand.

Question 17.
A red sprite is an electrical flash that occurs in Earth’s upper atmosphere. The table shows the elevations of four red sprites. What is the range of the elevations?
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 34

Answer:
The range of elevations are 51.66 miles, 50.6 miles, 50.53 miles, 50.52 miles.

Explanation:
First, write each fraction or mixed fraction as a decimal.
50.6
50(8/15) = 758/15 = 50.533
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 27
50(13/25) = 1263/25 = 50.52
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 28
155/3 = 51.66
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 29
So, the range of elevations are 51.66, 50.6, 50.53, 50.52

Converting Between Fractions and Decimals Homework & Practice 2.3

Review & Refresh

Find the quotient.

Question 1.
12 ÷ (-6)

Answer:
12 ÷ (-6) = -2

Explanation:
The quotient of two integers with the different signs is negative.
12 ÷ (-6) = -2

Question 2.
-48 ÷ 8

Answer:
-48 ÷ 8 = -6

Explanation:
The quotient of two integers with the different signs is negative.
-48 ÷ 8 = -6

Question 3.
-42 ÷ (-7)

Answer:
-42 ÷ (-7) = 6

Explanation:
The quotient of two integers with the same sign is positive.
-42 ÷ (-7) = 6

Question 4.
-33 ÷ (-3)

Answer:
-33 ÷ (-3) = 11

Explanation:
The quotient of two integers with the same sign is positive.
-33 ÷ (-3) = 11

Find the product.

Question 5.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 35

Answer:
35.28

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 30

Question 6.
2.0035 • 4

Answer:
2.0035 • 4 = 8.0140

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 31

Question 7.
5.49 × 13.509

Answer:
5.49 × 13.509 = 74.16441

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 32

Question 8.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 36

Answer:
0.0030018

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 33

Question 9.
Find the missing values in the ratio table. Then write the equivalent ratios.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 37

Answer:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 34

Explanation:
72/18 = 4. So, x/2 = 4
x = 4 . 2
x = 8
2 . 2/3 = 4/3
So, 18 . 2/3 = 36/3 = 12

Concepts, Skills, & Problem Solving

STRUCTURE
Without dividing, determine whether the decimal form of the terminates or repeats. Explain. (See Explorations 1 & 2, p. 61.)

Question 10.
\(\frac{3}{8}\)

Answer:
3/8 is a terminating decimal.

Explanation:
3, 8 have no common factors.
The denominator 8 is in the form of 2m x 5n
Hence, 3/8 is a terminating decimal.
3/8 = 0.375

Question 11.
\(\frac{5}{7}\)

Answer:
5/7 is a repeating decimal.

Explanation:
5, 7 have no common factors
The denominator 7 is not in the form of 2m x 5n
Hence, 5/7 is a repeating decimal.

Question 12.
\(\frac{11}{40}\)

Answer:
11/40 is a terminating decimal.

Explanation:
11, 40 have no common factors
The denominator 40 is in the form of 2³ x 5¹
Hence, 11/40 is a terminating decimal.

Question 13.
\(\frac{5}{24}\)

Answer:
5/24 is a repeating decimal.

Explanation:
5, 24 have no common factors
The denominator 24 is not in the form of 2m x 5n
Hence, 5/24 is a repeating decimal.

WRITING A FRACTION OR MIXED NUMBER AS A DECIMAL
Write the fraction or mixed number as a decimal.

Question 14.
\(\frac{7}{8}\)

Answer:
7/8 = 0.875

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 35

Question 15.
\(\frac{1}{11}\)

Answer:
1/11 = 0.9090

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 36

Question 16.
-3\(\frac{1}{2}\)

Answer:
-3(1/2) = -3.5

Explanation:
-3(1/2) = -7/2
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 37

Question 17.
–\(\frac{7}{9}\)

Answer:
-7/9 = -0.77

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 38

Question 18.
–\(\frac{17}{40}\)

Answer:
-17/40 = -0.425

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 39

Question 19.
1\(\frac{5}{6}\)

Answer:
1(5/6) = 1.83333

Explanation:
1(5/6) = 11/6
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 40

Question 20.
4\(\frac{2}{15}\)

Answer:
4(2/15) = 4.133

Explanation:
4(2/15) = 62/15
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 41

Question 21.
\(\frac{25}{24}\)

Answer:
25/24 = 1.04166

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 42

Question 22.
–\(\frac{13}{11}\)

Answer:
-13 / 11 = -1.1818

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 43

Question 23.
-2\(\frac{17}{18}\)

Answer:
-2(17/18) = -2.944

Explanation:
-2(17/18) = -53/18
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 44

Question 24.
-5\(\frac{7}{12}\)

Answer:
-5(7/12) = -5.5833

Explanation:
-5(7/12) = -67/12
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 45

Question 25.
8\(\frac{15}{22}\)

Answer:
8(15/22) = 8.681818

Explanation:
8(15/22) = 191/22
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 46

Question 26.
YOU BE THE TEACHER
Your friend writes –\(\frac{7}{11}\) as a decimal. Is your friend correct? Explain your reasoning.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 38

Answer:
Correct

Explanation:
-7/11 = -0.636363
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 47

WRITING A DECIMAL AS A FRACTION OR MIXED NUMBER
Write the decimal as a fraction or mixed number in simplest form.

Question 27.
-0.9

Answer:
-0.9 = -9/10

Explanation:
-0.9 = -9/10

Question 28.
0.45

Answer:
0.45 = 9/20

Explanation:
0.45 = 45/100
= (9 . 5)/(20 . 5)
= 9/20

Question 29.
-0.258

Answer:
-0.258 = -129/500

Explanation:
-0.258 = -258/1000
= -(129 . 2)/(500 . 2)
= -129/500

Question 30.
-0.312

Answer:
-0.312 = 39/125

Explanation:
-0.312 = -312/1000
= (39 . 8) / (125 . 8)
= 39/125

Question 31.
-2.32

Answer:
-2.32 = -58/25

Explanation:
-2.32 = -232/100
= -(58 . 4)/(25 . 4)
= -58/25

Question 32.
-1.64

Answer:
-1.64 = -41/25

Explanation:
-1.64 = -164/100
= -(41 . 4)/(25 . 4)
= -41/25

Question 33.
6.012

Answer:
6.012 = 1503/250

Explanation:
6.012 = 6012/1000
= (1503 . 4)/(250 . 4)
= 1503/250

Question 34.
-12.405

Answer:
-12.405 = -2481/200

Explanation:
-12.405 = -12405/1000
= -(2481 . 5)/(200 . 5)
= -2481/200

Question 35.
MODELING REAL LIFE
You find one quarter, two dimes, and two nickels.
a. Write the dollar amount as a decimal.
b. Write the dollar amount as a fraction or mixed number in simplest form.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 39

Answer:
a. $0.55
b. 11/20

Explanation:
You find one quarter, two dimes, and two nickels.
a. Convert each one into dollars
1 quarter is equal to 0.25 dollars
1 dime is equal to 0.1 dollars.
1 nickels is equal to 0.05 dollars.
$0.25 + 2(0.1) + 2(0.05)
= 0.25 + 0.2 + 0.1
= $0.55
b. $0.55 = 55/100
= (5 . 11)/(5. 20)
= 11/20

COMPARING RATIONAL NUMBERS
Copy and complete the statement using < or >.

Question 36.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 40

Answer:
-4(6/10) > -4.65

Explanation:
-4(6/10) = -46/10 = -4.6
-4.65 < -4.6
So, -4(6/10) > -4.65

Question 37.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 41

Answer:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 49

Explanation:
-5(3/11) = -58/11 = -5.2727
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 48
-5.2727 < -5.222

Question 38.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 42

Answer:
-2(13/16) < -2(11/14)

Explanation:
-2(13/16) = -45/16 = -2.8125
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 50
-2(11/14) = -39/14 = -2.7857
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 51
-2(13/16) < -2(11/14)

Question 39.
MODELING REAL LIFE
Is the half pipe deeper than the skating bowl? Explain.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 43

Answer:
No. They have the same depth.

Explanation:
As a decimal, 5/6 = 0.833333
9(5/6) = 59/6 = 9.838383
This means that half-pipe and the skating bowl have the same depth.
No. They have the same depth.

Question 40.
MODELING REAL LIFE
In softball, a batting average is the number of hits divided by the number of times at bat. Does Player 1 or Player 2 have the greater batting average?
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 44

Answer:
Player 2 has the greater batting average.

Explanation:
Batting average = Number of hits / number of times at bat
Player 1 average = 42 / 90 = 0.466
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 52
Player 2 average = 38/80 = 0.475
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 53
Player 2 has the greater batting average

ORDERING RATIONAL NUMBERS
Order the numbers from least to greatest.

Question 41.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 45

Answer:
The order from least to greatest -7/3, -3/4, 0.5, 2/3, 1.2

Explanation:
Express each term as a decimal
-3/4 = -0.75
2/3 = 0.666
-7/3 = -2.333
The order from least to greatest -7/3, -3/4, 0.5, 2/3, 1.2

Question 42.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 46

Answer:
The order from least to greatest is -2.5, -1.1, -4/5, 0.8, 9/5

Explanation:
Express each term as a decimal
9/5 = 1.8
-4/5 = -0.8
The order from least to greatest is -2.5, -1.1, -4/5, 0.8, 9/5

Question 43.
Big Ideas Math Answer Key Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 47

Answer:
The order from least to greatest is -8/5, -1.4, -0.9, 1/4, 0.6

Explanation:
Express each term as a decimal
-8/5 = -1.6
1/4 = 0.25
The order from least to greatest is -1.6 < -1.4 < -0.9 < 0.25 < 0.6

Question 44.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 48

Answer:
The order from least to greatest is -9/4, -0.75, -6/10, 5/3, 2.1

Explanation:
Express each term as a decimal
-6/10 = -0.6
-9/4 = -2.25
5/3 = 1.666
The order from least to greatest is -2.25 < -0.75 < -0.6 < 1.666 < 2.1

Question 45.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 49

Answer:
The order from least to greatest is -7/2, -2.8, -5/4, 1.3, 4/3

Explanation:
Express each term as a decimal
-7/2 = -3.5
-5/4 = -1.25
4/3 = 1.333
The order from least to greatest is -3.5 < -2.8 < -1.25 < 1.3 < 1.333

Question 46.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 50

Answer:
The order from least to greatest is -2.4 -2.25, -11/5, 15/10, 1.6

Explanation:
Express each term as a decimal
-11/5 = -2.2
15/10 = 1.5
The order from least to greatest is -2.4 < -2.25 < -2.2 < 1.5 < 1.6

Question 47.
MODELING REAL LIFE
The table shows the changes in the water level of a pond over several weeks. Order the numbers from least to greatest.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 51

Answer:
The order from the least to greatest is Week 4, Week 2, Week 3, Week 1.

Explanation:
Week 1 = -7/5 = -1.4
Week 2 = -1(5/11) = -1.4545
Week 3 = -1.45
Week 4 = -1(91/200) = -1.455
The order from the least to greatest is Week 4 < Week 2 < Week 3 < Week 1

Question 48.
OPEN-ENDED
Find one terminating decimal and one repeating decimal between \(-\frac{1}{2}\) and \(-\frac{1}{3}\).

Answer:
-23/60 = -0.383333 is a repeating decimal
-24/60 = -0.4 is a terminating decimal.

Explanation:
To find one terminating decimal and one repeating decimal between -1/2 and -1/3 multiply each fraction by the denominator of the other fraction
-1/2 . 3/3 = -3/6 and -1/3 . 2/2 = -2/6
Multiply the resulting fractions by 10
-3/6 . 10/10 = -30/60 and -2/6 . 10/10 = -20/60
Find two numbers between -20 and -30
-23/60 = -0.383333 is a repeating decimal
-24/60 = -0.4 is a terminating decimal.

Question 49.
PROBLEM SOLVING
You miss 3 out of 10 questions on a science quiz and 4 out of 15 questions on a math quiz. On which quiz did you have a greater percentage of correct answers?

Answer:
You have a higher percent of correct answers on a math quiz.

Explanation:
You miss 3 out of 10 questions on a science quiz
So, the coorect answers = 10 – 3 = 7
The percent of correct answers on a science quiz = 7/10 . 100 = 70%
You miss 4 out of 15 questions on a math quiz
So, the correct answers = 15 – 4 = 11
The percent of correct answers on a math quiz = 11/15 . 100 = 73.3%
Thus, you have a higher percent of correct answers on a math quiz.

Question 50.
CRITICAL THINKING
A hackberry tree has roots that reach a depth of 6\(\frac{5}{12}\) meters. The top of the tree is \(18.2 \overline{8}\) meters above the ground. Find the total height from the bottom of the roots to the top of the tree.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 52

Answer:
The total height from the bottom of the roots to the top of the tree is 23.70544 meters.

Explanation:
The depth of the tree = 6(5/12) = 65/12 meters
The top of the tree = 18.288 meters
The total height from the bottom of the roots to the top of the tree = 65/12 + 18.288
= 5.41666 + 18.2888
= 23.70544 meters
So, the total height from the bottom of the roots to the top of the tree is 23.70544 meters.

Question 51.
DIG DEEPER!
Let a and b be integers.
a. When can –\(\frac{1}{a}\) be written as a positive, repeating decimal?
b. When can \(\frac{1}{ab}\) be written as a positive, terminating decimal?

Answer:
a. a = -7
b. b = -2

Explanation:
a. Let us take a = -7
Then -1/a = -1/-7 = 0.142857142
b. 1/ab = 1/(-7)(-2) = 1/14 = 0.7142

Lesson 2.4 Multiplying Rational Numbers

EXPLORATION 1
Finding Products of Rational Numbers
Work with a partner.
a. Write a multiplication expression represented by each area model. Then find the product.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 53
b. Complete the table.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 54
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 54.1
c. Do the rules for multiplying integers apply to all rational numbers? Explain your reasoning.

Answer:
a. 9 x 10 = 90
5 x 10 = 50
b. Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 54
c. The rules for multiplying integers apply to all rational numbers.

2.4 Lesson

Try It

Find the product. Write fractions in simplest form.

Question 1.
-5.1 × 1.8

Answer:
-5.1 × 1.8 = -9.18

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 55

Question 2.
-6.3(-0.6) = 3.78

Answer:
-6.3(-0.6)

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 56

Question 3.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 55

Answer:
-4/5(-2/3) = 8/15

Explanation:
-4/5(-2/3) = (-4 . -2)/(5 . 3)
= 8/15

Question 4.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 56

Answer:
4(1/2) . (-2(1/3)) = -21/2

Explanation:
4(1/2) . (-2(1/3)) = 9/2 . (-7/3)
= (9 . -7)/(2 . 3)
= (-7 . 3)/2 = -21/2

Try It

Find the product. Write fractions in simplest form.

Question 5.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 57

Answer:
-2/3 . 7(7/8) . 3/2 = -63/8

Explanation:
-2/3 . 7(7/8) . 3/2 = -2/3 . 63/8 . 3/2
= (-2 . 63 . 3)/(3 . 8 . 2)
= -63/8

Question 6.
-7.02(0.1)(100)(-10)

Answer:
-7.02(0.1)(100)(-10) = 702

Explanation:
-7.02(0.1)(100)(-10) = (-7.02 . 0.1)(100 . -10)
= (-0.702)(-1000)
= 702

Self-Assessmentfor Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 7.
WRITING
Explain how to determine whether a product of two rational numbers is positive or negative.

Answer:
The product of two rational numbers is positive when they have the same sign.
The product of two rational numbers is negative when they have different signs.

MULTIPLYING RATIONAL NUMBERS
Find the product. Write fractions in simplest form.

Question 8.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 58

Answer:
-3/10 x (-8/15) = 4/25

Explanation:
-3/10 x (-8/15) = (-3 x -8)/(10 x 15)
= 24/150 = 4/25

Question 9.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 59

Answer:
-2/3 . 1(1/3) = -8/9

Explanation:
-2/3 . 1(1/3) = -2/3 . 4/3
= (-2 . 4)/(3 . 3) = -8/9

Question 10.
-2.8(-1.7)

Answer:
-2.8(-1.7) = 4.76

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 57

Question 11.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 60

Answer:
1(3/5) . (-3(3/4)) = -10

Explanation:
1(3/5) . (-3(3/4)) = 8/3 . -15/4
= (8 . -15)/(3 . 4)
= (2 . -5) = -10

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 12.
A swimmer’s best time in an event is 53.87 seconds. On average, his best time decreases by 0.28 second each of the next five times he swims the event. Does he accomplish his goal of swimming the event in less than 52.5 seconds?
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 61

Answer:
Yes. This is because his fifth attempt was 52.47 seconds

Explanation:
From the question, we are informed that Swimmers best time in an event is 53.87 seconds and that on average, his best time decreases by 0.28 seconds each of the next five times he swims the event.
The time for the fifth time he swims will be = 53.87 – 5(0.28)
= 53.87 – 1.4
= 52.47 seconds
This means that he accomplishes his goal of swimming the event in less than 52.5 seconds.

Question 13.
DIG DEEPER!
Terminal velocity is the fastest speed that an object can fall through the air. A skydiver reaches a terminal velocity of 120 miles per hour. What is the change in elevation of the skydiver after falling at terminal velocity for 15 seconds? Justify your answer.

Answer:
The change in elevation of the skydiver after falling at terminal velocity for 15 seconds is 30 miles.

Explanation:
A skydiver reaches a terminal velocity of 120 miles per hour = 120/60 = 2 miles per seconds
The change in elevation of the skydiver after falling at terminal velocity for 15 seconds is 2 x 15 = 30 miles

Multiplying Rational Numbers Homework & Practice 2.4

Review & Refresh

Write the fraction or mixed number as a decimal.

Question 1.
\(\frac{5}{16}\)

Answer:
5/16 = 0.3125

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 58

Question 2.
–\(\frac{9}{22}\)

Answer:
-9/22 = -0.4090909

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 59

Question 3.
6\(\frac{8}{11}\)

Answer:
6(8/11) = 6.727272

Explanation:
6(8/11) = 74/11
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 60

Question 4.
–\(\frac{26}{24}\)

Answer:
-26/24 = -1.08333

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 61

Find the area of the figure.

Question 5.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 62

Answer:
Area is 36 sq inches

Explanation:
Given that,
a = 2 in, b = 10 in, h = 6 in
Area of the trapezoid = 1/2 (a + b) . h
= 1/2 (2 + 10) . 6
= (12) . 3
= 36 sq inches

Question 6.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 63

Answer:
Area is 9 m².

Explanation:
p = 1.5 + 3 = 4.5 m
q = 2 + 2 = 4 m
Area of rhombus = (pq)/2
= (4.5 . 4)/2
= 18/2 = 9 m²

Question 7.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 64

Answer:
The area is 121 ft².

Explanation:
The area of the rectangle formed by extending the base line and the top line is l x b
= 13 x 11 = 143 ft²
The area of the formed triangle is 1/2 x b x h
base = 13 – 9 = 4 ft
height = 11 ft
Triangle area = 1/2 x 4 x 11
= 2 x 11 = 22 ft²
Area of the given shape = Area of the rectangle – area of the triangle
= 143 – 22 = 121 ft²

Concepts, Skills, &Problem Solving
FINDING PRODUCTS OF RATIONAL NUMBERS
Write a multiplication expression represented by the area model. Then find the product. (See Exploration 1, p. 67.)

Question 8.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 65

Answer:
The area is 90 sq units.

Explanation:
The number of shaded rows = 9
The number of shaded columns = 10
Area model = rows x columns
= 9 . 10 = 90

Question 9.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 66

Answer:
The area is 50 sq units.

Explanation:
The number of shaded rows = 5
The number of shaded columns = 10
Area model = rows x columns
= 5 . 10 = 50

REASONING
Without multiplying, tell whether the value of the expression is positive or negative. Explain your reasoning.

Question 10.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 67

Answer:
The expression is negative.

Explanation:
When you multiply a positive fraction by a negative integer, you will get a negative fraction.

Question 11.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 68

Answer:
The expression is negative.

Explanation:
The product of two fractions with different signs is negative.

Question 12.
-0.25(-3.659)

Answer:
The expression is positive.

Explanation:
The product of two fractions with different signs is positive.

MULTIPLYING RATIONAL NUMBERS
Find the product. Write fractions in simplest form.

Question 13.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 69

Answer:
-1/4 x (-4/3) = 1/3

Explanation:
-1/4 x (-4/3) = (-1 . -4)/(4 . 3)
= 1/3

Question 14.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 70

Answer:
5/6(-8/15) = -4/9

Explanation:
5/6(-8/15) = (5 . -8) / (6 . 15)
= (5 . -2 . 4) / (3 . 2 . 5 . 3)
= -4/9

Question 15.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 71

Answer:
-2(-1(1/4)) = 5/2

Explanation:
-2(-1(1/4)) = -2(-5/4)
= -2(-5/2 . 2) = 5/2

Question 16.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 72

Answer:
-3(1/3) . (-2(7/10)) = 9

Explanation:
-3(1/3) . (-2(7/10)) = -10/3 . -27/10
= (-10 . -27)/(3 . 10)
= (9 . 3)/3 = 9

Question 17.
0.4 × (-0.03)

Answer:
0.4 × (-0.03) = -3/250

Explanation:
0.4 × (-0.03) = 4/10 . (-3/100)
= (4 . -3)/(10 . 100)
= (2 . 2 . -3)/(5 . 2 . 50 . 2)
= -3/250

Question 18.
-0.05 × (-0.5)

Answer:
-0.05 × (-0.5) = 1/40

Explanation:
-0.05 × (-0.5) = -5/100 x -5/10
= (-5 x -5)/(100 x 10)
= (-5 x -5)/(5 x 20 x 5 x 2)
= 1/40

Question 19.
-8(0.09)(-0.5)

Answer:
-8(0.09)(-0.5) = 9/25

Explanation:
-8(0.09)(-0.5) = -8(9/100)(-5/10)
= (-8 . 9 . -5)/(100 . 10)
= 9/25

Question 20.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 74

Answer:
5/6 . (-4(1/2)) . (-2(1/5)) = 33/4

Explanation:
5/6 . (-4(1/2)) . (-2(1/5)) = 5/6 . -9/2 . -11/5
= (5 . -9 . -11)/(6 . 2 . 5) = 33/4

Question 21.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 75

Answer:
(-1(2/3))³ = -125/27

Explanation:
(-1(2/3))³ = (-5/3)³
= (-5 . -5 . -5)/(3 . 3 . 3)
= -125/27

YOU BE THE TEACHER
Your friend evaluates the expression. Is your friend correct? Explain your reasoning.

Question 22.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 76

Answer:
Correct

Explanation:
-14 x 3/2 = (-1 . 3)/(4 . 2)
= -3/8

Question 23.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 77

Answer:
Wrong

Explanation:
-2.2 x (-3.7) = 8.14

Question 24.
MODELING REAL LIFE
The hour hand of a clock moves 30° every hour. How many degrees does it move in 2\(\frac{1}{5}\) hours?
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 78

Answer:
In 2(1/5) hours, the hour hand of a clock moves -66 degrees.

Explanation:
2(1/5) = 11/5 = 2.2You can here use the rule of three as an easier way, and let x be the degrees it moves in 2(1/5) hours.
1 hour –> -30
2.2 hour –>x
x = 2.2 * -30
x = -66
So, in 2(1/5) hours, the hour hand of a clock moves -66 degrees.

Question 25.
MODELING REAL LIFE
A 14.5-gallon gasoline tank is \(\frac{3}{4}\) full. How many gallons will it take to fill the tank?

Answer:
We need 3.625 gallons to fill the tank.

Explanation:
3/4 of the tank is full so, 1/4 of the tank is empty
The number of gallons will it take to fill the tank = 1/4 * 14.5
= 0.25 * 14.5 = 3.625
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 62
We need 3.625 gallons to fill the tank.

Question 26.
OPEN-ENDED
Write two fractions whose product is –\(\frac{3}{5}\).

Answer:
The two fractions are -2/3 and 9/10

Explanation:
= -2/3 . 9/10
= (-2 . 9)/(3 . 10)
= -3/5

USING PROPERTIES
Find the product. Write fractions in simplest form.

Question 27.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 79

Answer:
1/5 . 3/8 . (-5) = -3/8

Explanation:
1/5 . 3/8 . (-5) = (1 . 3 . -5)/(5 . 8)
= -3/8

Question 28.
0.01(4.6)(-200)

Answer:
0.01(4.6)(-200) = -46/5

Explanation:
0.01(4.6)(-200) = 1/100 . 46/10 . -200
= (1 . 46 . -200)/(100 . 10)
= -46/5

Question 29.
(-17.2 × 2.5) × 4

Answer:
(-17.2 × 2.5) × 4 = -172

Explanation:
(-17.2 × 2.5) × 4 = (-172/10 x 25/10) x 4
= (-172 x 25)/(10 x 10) x 4
= (-172 / 2 x 2) x 4
= -172

Question 30.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 80

Answer:
(-5/9 x 2/7) x (-7/2) = 5/9

Explanation:
(-5/9 x 2/7) x (-7/2) = (-5 x 2)/(9 x 7) x (-7/2)
= (-10/63)  (-7/2)
= (-10 x -7)/(63 x 2)
= 5/9

Question 31.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 81

Answer:
[-2/3 . (-5/7)] . (-9/4) = -15/14

Explanation:
[-2/3 . (-5/7)] . (-9/4) = (-2 . -5)/(3 . 7) . (-9/4)
= 10/21 . (-9/4)
= (10 . -9)/(21 . 4)
= (5 . -3)/(7 . 2)
= -15/14

Question 32.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 82

Answer:
(-4.5 . 8.61) . (-2/9) = 861/100

Explanation:
(-4.5 . 8.61) . (-2/9) = (-45/10 . 861/100) . (-2/9)
= (-45 . 861)/(10 . 100) . (-2/9)
= 861/100

Question 33.
PROBLEM SOLVING
Fencing costs $25.80 per yard. How much does it cost to enclose two adjacent rectangular pastures as shown? Justify your answer.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 83

Answer:
The cost of fencing is $3558.249312.

Explanation:
Fencing costs $25.80 per yard.
Length = 30(2/9) = 272/9 yd
Width = 50(5/8) = 405/8 yd
The rectangular pastures perimeter = 2(length + width) + length
= 2(272/9 + 405/8) + 272/9
= 2(30.222 + 50.625) + 30.2222
= 2(53.8472) + 30.2222
= 107.6944 + 30.2222
= 137.91664 yards
Multiply the perimeter by $25.80 to get the cost
= 137.91664 x 25.80 = $3558.249312
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 63
So, the cost of fencing is $3558.249312.

ALGEBRA
Evaluate the expression when x = -2, y = 3, and z = –\(\frac{1}{5}\).

Question 34.
x • z

Answer:
2/5

Explanation:
The given expression is x • z
Put x = -2, z = -1/5
= -2 . (-1/5)
= 2/5

Question 35.
xyz

Answer:
6/5

Explanation:
The given expression is xyz
x = -2, y = 3, and z = –\(\frac{1}{5}\)
= -2 . 3 . (-1/5)
= -6 . (-1/5)
= 6/5

Question 36.
\(\frac{1}{3}\) + x • z

Answer:
11/15

Explanation:
The given expression is 1/3 + x . z
Put x = -2, z = -1/5
= 1/3 + (-2) . (-1/5)
= 1/3 + 2/5
= (5 + 6)/15
= 11/15

Question 37.
\(\frac{1}{2}\)z – \(\frac{2}{3}\)y

Answer:
-21/10

Explanation:
The given expression is 1/2 z – 2/3 y
Put y = 3 , z = -1/5
= 1/2 . (-1/5) – 2/3 . 3
= -1/10 – 2
= (-1 – 20)/10
= -21/10

EVALUATING AN EXPRESSION
Evaluate the expression. Write fractions in simplest form.

Question 38.
-4.2 + 8.1 × (-1.9)

Answer:
-4.2 + 8.1 × (-1.9) = -19.59

Explanation:
-4.2 + 8.1 × (-1.9) = -4.2 + (8.1 x -1.9)
= -4.2 – 15.39
= -19.59

Question 39.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 84

Answer:
-3(3/4) x 5/6 – 2(1/3) = -131/24

Explanation:
-3(3/4) x 5/6 – 2(1/3) = (-15/4) x 5/6 – 7/3
= (-15 . 5)/(4 . 6) – 7/3
= -25/8 – 7/3
= (-75 – 56)/24
= -131/24

Question 40.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 85

Answer:
(-2/3)² – 3/4 (2(1/3)) = -47/36

Explanation:
(-2/3)² – 3/4 (2(1/3)) = (-2/3).(-2/3) – 3/4 (7/3)
= 4/9 – 7/4
= (16 – 63)/36
= -47/36

Question 41.
DIG DEEPER!
Use positive or negative integers to fill in the blanks so that the product is \(\frac{1}{4}\). Justify your answer.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 86

Answer:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 64= 1/4

Explanation:
One of the possibilities of arranging numbers in the fill in the blanks are as follows:
9/2 x (-5/144) x (8/-5) = (9 x -5 x 8)/(2 x  x -5)
= 1/4

Lesson 2.5 Dividing Rational Numbers

EXPLORATION 1
Work with a partner
a. Write two division expressions represented by the area model. Then find the quotients.
Big Ideas Math Answers 7th Grade Chapter 2 Multiplying and Dividing Rational Numbers 87
b. Complete the table.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 88
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 89
c. Do the rules for dividing integers apply to all rational numbers? Explain your reasoning.
d. Write a real-life story involving the quotient 0.75 ÷ 3. Interpret the quotient in the context of the story.

Answer:
a. 100 ÷ 60 = 1.666, 200 ÷ 120 = 1.666
b. Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 66
c. Yes
d. 0.75 ÷ 3 = 0.25

2.5 Lesson

Try It

Find the quotient. Write fractions in simplest form.

Question 1.
-2.4 ÷ 3.2

Answer:
-2.4 ÷ 3.2 = -0.75

Explanation:
-2.4 ÷ 3.2
Write the division expression as a fraction.
= -24/32 = -0.75
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 67

Question 2.
-6 ÷ (-1.1)

Answer:
-6 ÷ (-1.1) = 5.454545

Explanation:
-6 ÷ (-1.1)
= 60/11
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 68

Question 3.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 90

Answer:
-6/5 ÷ (-1/2) = 12/5

Explanation:
-6/5 ÷ (-1/2)
= 6/5 ÷ 1/2
= 6/5 . (2/1)
= (6 . 2)/(5 . 1)
= 12/5

Question 4.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 91

Answer:
-1/3 ÷ 2(2/3) = -1/8

Explanation:
-1/3 ÷ 2(2/3)
= -1/3 ÷ 8/3
= -1/3 . (3/8)
= (-1 . 3)/(3 . 8)
= -1/8

Try It

Evaluate the expression. Write fractions in simplest form.

Question 5.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 92

Answer:
-1/2 / 6 = -1/12

Explanation:
-1/2 / 6 = (-1/2) . (1/6)
= (-1 . 1)/(2 . 6)
= -1/12

Question 6.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 93

Answer:
-2(1/2) / -3/4 = 10/3

Explanation:
-2(1/2) / -3/4 = -5/2 / -3/4
= (-5/2) . (4/-3)
= (-5 . 4)/(2 . -3)
= 10/3

Question 7.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 94

Answer:
[-1(2/3) . (-3/5)] / (1/3)² = 9

Explanation:
[-1(2/3) . (-3/5)] / (1/3)² = [(-5/3) . (-3/5)] / (1/9)
= [(-5 . -3)/(3 . 5)]/(1/9)
= (1/1) / (1/9)
= (1/1) . (9/1)
= 9

Self-Assessmentfor Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 8.
WRITING
Explain how to determine whether a quotient of two rational numbers is positive or negative.

Answer:
The simple and easy strategy to find whether the quotient of two rational numbers is positive or negative is mentioned here.
The quotient of two rational numbers is positive when those numbers have the same sign.
The quotient of two rational numbers is negative when they have different signs.

EVALUATING AN EXPRESSION
Evaluate the expression. Write fractions in simplest form.

Question 9.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 95

Answer:
3/8 ÷ (-9/5) = -5/24

Explanation:
3/8 ÷ (-9/5) = 3/8 . (-5/9)
= (3 . -5)/(8 . 9)
= -5/(8 . 3)
= -5/24

Question 10.
-6.8 ÷ (-3.6)

Answer:
-6.8 ÷ (-3.6) = 17/9

Explanation:
-6.8 ÷ (-3.6) = -68/10 ÷ (-36/10)
= -68/10 . (-10/36)
= (-68 . -10)/(10 . 36)
= 68/36
= 17/9

Question 11.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 97

Answer:
(-2/9)/(2(2/5)) = -5/54

Explanation:
(-2/9)/(2(2/5)) = (-2/9)/(12/5)
= -2/9 . 5/12
= (-2 . 5)/(9 . 12)
= (-5)/(9 . 6)
= -5/54

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 12.
DIG DEEPER!
Soil is composed of several layers. A geologist measures the depths of the subsoil and the bedrock, as shown. Find and interpret two quotients involving the depths of the subsoil and the bedrock.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 98

Answer:
The depths of the subsoil and the bedrock is 2.244 ft

Explanation:
The depth of the subsoil = -22.5 ft
The depth of the bedrock = -50.5 ft
The distance between subsoil and bedrock =50.5 – 22.5
= 28 ft
The depths of the subsoil and the bedrock = -50.5/-22.5
= 2.244
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 69

Question 13.
The restaurant in Example 3 receives additional scores of 0.75, 1.5, 1.25, 4.75, 0.25, 0.5, 5, and 0.5 for the lasagna. Given the additional data, should the restaurant consider changing the recipe? Explain.

Answer:
The restaurant should not change the recipe.

Explanation:
The restaurant received scores are 2.25, -3.5, 0, -4.5, 1.75, -1, 3.5, -2.5, -0.75, -1.5, -1.25, 4.75, -0.25, -0.5, 5 and -0.5
The mean of scores = sum of scores / number of scores
= (2.25 + (-3.5) + 0 + (-4.5) + 1.75 + (-1) + 3.5 + (-2.5) + (-0.75) + (-1.5) + (-1.25) + 4.75 + (-0.25) + (-0.5) + 5 + (-0.5))/16
= (2.25 – 3.5 – 4.5 + 1.75 – 1 + 3.5 – 2.5 – 0.75 – 1.5 – 1.25 + 4.75 – 0.25 – 0.5 + 5 – 0.5)/16
= 1/16 = 0.0625
The mean score is above 0.
So, the restaurant should not change the recipe.

Dividing Rational Numbers Homework & Practice 2.5

Review & Refresh

Find the product. Write fractions in simplest form.

Question 1.
-0.5(1.31)

Answer:
-0.5(1.31) = -131/200

Explanation:
-0.5(1.31) = -5/10 (131/100)
= (-5 . 131) / (10 . 100)
= -131/(2 . 100)
= -131/200

Question 2.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 99

Answer:
9/10 (-1(1/4)) = -9/8

Explanation:
9/10 (-1(1/4)) = 9/10 (-5/4)
= (9 . -5)/(10 . 4)
= -9/(2 . 4)
= -9/8

Question 3.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 100

Answer:
-7/12 (-3/14) = 1/8

Explanation:
-7/12 (-3/14) = (-7 . -3) / (12 . 14)
= (-1 . -1)/(4 . 2)
= 1/8

Identify the terms, coefficients, and constants in the expression.

Question 4.
3b + 12

Answer:
The coefficients are 3, the constant is 12, terms are 3b, 12

Explanation:
The coefficients are 3, the constant is 12, terms are 3b, 12

Question 5.
14 + z + 6f

Answer:
The terms are 14, z, 6f, coefficients are 6, 1 and constant is 14 in 14 + z + 6f

Explanation:
The terms are 14, z, 6f, coefficients are 6, 1 and constant is 14 in 14 + z + 6f

Question 6.
8g + 14 + 5c + 7

Answer:
The terms are 8g, 14, 5c, 7 and coefficients are 8, 5, and constants are 14, 7

Explanation:
The terms are 8g, 14, 5c, 7 and coefficients are 8, 5, and constants are 14, 7

Question 7.
42m + 18 + 12c2

Answer:
The terms are 42m, 18, 12c², coefficients are 42, 12 and constants are 18.

Explanation:
The terms are 42m, 18, 12c², coefficients are 42, 12 and constants are 18.

Concepts, Skills, &Problem Solving
USING TOOLS
Write two division expressions represented by the area model. Then find the quotients. (See Exploration 1, p. 73.)

Question 8.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 101

Answer:
20/50, 40/100

Explanation:
The first division expression is 20/50 = 0.4
The second division expression is 40/100 = 0.4

Question 9.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 102

Answer:
6/10, 54/100

Explanation:
The first division expression is 6/10 = 0.6
The second division expression is 54/100 = 0.54

DIVIDING RATIONAL NUMBERS
Find the quotient. Write fractions in simplest form.

Question 10.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 103

Answer:
-7/5 ÷ 2/5 = -3.5

Explanation:
-7/5 ÷ 2/5 = -7/5 . 5/2
= (-7 . 5)/(5 . 2)
= -7/2
= -3.5

Question 11.
-0.18 ÷ 0.03

Answer:
-0.18 ÷ 0.03 = -6

Explanation:
-0.18 ÷ 0.03 = -18/100 ÷ 3/100
= -18/100 . 100/3
= (-18 . 100) / (100 . 3)
= -6

Question 12.
-3.45 ÷ (-15)

Answer:
-3.45 ÷ (-15) = 0.03

Explanation:
-3.45 ÷ (-15) = -45/100 ÷ -15/1
= -45/100 . -1/15
= (-45 . -1)/(100 . 15)
= 3/100
= 0.03

Question 13.
-8 ÷ (-2.2)

Answer:
-8 ÷ (-2.2) = 3.636363

Explanation:
-8 ÷ (-2.2) = -8 ÷ -22/10
= -8/1 . -10/22
= (-8 . -10) / (1 . 22)
= (-4 . -10) / 11
= 40/11 = 3.636363
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 70

Question 14.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 104

Answer:
1/4 ÷ (-3/8) = -0.6666

Explanation:
1/4 ÷ (-3/8) = 1/4 . (-8/3)
= (1 . -8) / (4 . 3)
= -2/3
= -0.66666

Question 15.
8.722 ÷ (-3.56)

Answer:
8.722 ÷ (-3.56) = -2.45

Explanation:
8.722 ÷ (-3.56) = 8722/1000 ÷ (-356/100)
= 8722/1000 . (100/-356)
= (8722 . 100)/(1000 . -356)
= (8722) / (10 . -356)
= -8722/3560 = -2.45
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 71

Question 16.
12.42 ÷ (-4.8)

Answer:
12.42 ÷ (-4.8) = -2.5875

Explanation:
12.42 ÷ (-4.8) = 1242/100 ÷ (-48/10)
= 1242/100 . (-10/48)
= (1242 . -10)/(100 . 48)
= (-1242) / (480)
= -2.5875
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 72

Question 17.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 105

Answer:
-2(4/5) ÷ (-7) = 0.4

Explanation:
-2(4/5) ÷ (-7) = -14/5 ÷ (-7)
= -14/5 . -1/7
= (-14 . -1) / (7 . 5)
= 2/5
= 0.4

Question 18.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 106

Answer:
-10(2/7) ÷ (-4(4/11)) = 2.3571

Explanation:
-10(2/7) ÷ (-4(4/11)) = -72/7 ÷ -48/11
= -72/7 . (-11/48)
= (-72 . -11) / (7 . 48)
= 99/42 = 2.3571
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 73

YOU BE THE TEACHER
Your friend evaluates the expression. Is your friend correct? Explain your reasoning.

Question 19.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 107

Answer:
wrong

Explanation:
-2/3 ÷ 4/5 = -2/3 . 5/4
= (-2 . 5)/(3 . 4)
= -5/6

Question 20.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 108

Answer:
Wrong

Explanation:
-4.25 ÷ 1.7 = -2.5
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 74

Question 21.
MODELING REAL LIFE
How many 0.75-pound packages can you make with 4.5 pounds of sunflower seeds?

Answer:
6 0.75-pound packages are required to make 4.5 pounds of sunflower seeds.

Explanation:
Divide 4.5 by 0.75 to get the solution.
= 4.5 ÷ 0.75 = 45/10 ÷ 75/100
= 45/10 . 100/75
= (45 . 100)/ (10 . 75)
= 6
So, 6 0.75-pound packages are required to make 4.5 pounds of sunflower seeds.

EVALUATING AN EXPRESSION
Evaluate the expression. Write fractions in simplest form.

Question 22.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 109

Answer:
(14/9) / (-1/3-1/6) = -28/9

Explanation:
(14/9) / (-1/3-1/6) = (14/9) / ((-2 – 1)/6)
= 14/9 / -3/6
= 14/9 . (-6/3)
= (14 . -6) / (3 . 9)
= -28/9

Question 23.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 110

Answer:
(-125 + 3/10) / (11/4 – (-9/14)) = -77/100

Explanation:
(-125 + 3/10) / (11/4 – (-9/14)) = (-24 + 13)/10 / (11/14 + 9/14)
= -11/10 / (20/14)
= -11/10 . 14/20
= (-11 . 14) / (10 . 20)
= (-11 . 7) / (5 . 20)
= -77/100

Question 24.
-0.42 ÷ 0.8 + 0.2

Answer:
-0.42 ÷ 0.8 + 0.2 = -13/40

Explanation:
-0.42 ÷ 0.8 + 0.2 = -4.2 ÷ 8 + 0.2
= -0.525 + 0.2
= -0.325 = -325/1000
= -13/40

Question 25.
2.85 ÷ 6.2 ÷ 22

Answer:
2.85 ÷ 6.2 ÷ 2² = 28.25/248

Explanation:
2.85 ÷ 6.2 ÷ 2² = 2.85 ÷ 6.2 ÷ 4
= (2.825 ÷ 6.2) ÷ 4
= 2.825/6.2 . 1/4
= (2.825 . 1) / (6.2 . 4)
= 2.825/24.8
= 28.25/248

Question 26.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 111

Answer:
3/4 + 7/10 – 1/8 ÷ (-1/2) = 17/10

Explanation:
3/4 + 7/10 – 1/8 ÷ (-1/2) = 3/4 + 7/10 + (1/8 ÷ 1/2)
= 3/4 + 7/10 + (1/8 . 2)
= 3/4 + 7/10 + 1/4
= 1 + 7/10
= 17/10

Question 27.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 112

Answer:
7/6 / [(-11/5)(10(1/2))(-5/11)] = 1/9

Explanation:
7/6 / [(-11/5)(10(1/2))(-5/11)] = 7/6 / [(-11/5)(21/2)(-5/11)]
= 7/6 / [(-11 . 21 . -5) / (5 . 2 . 11)]
= 7/6 / [21/2]
= 7/6 . 2/21
= (7 . 2) / (6 . 21)
= 1/9

Question 28.
PROBLEM SOLVING
The section of the boardwalk shown is made using boards that are each 9\(\frac{1}{4}\)inches wide. The spacing between each board is equal. What is the width of the spacing between each board?
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 113

Answer:
The width of the spacing between each section is 5.25 inches

Explanation:
15 boards each board is 9(1/4) inches wide
The total width of 15 boards = 9(1/4) . 15
= 37/4 . 15
= 555/4 = 138.75
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 77
The total width of 15 boards = 138.75 inches
The total width of the section = 144 inches
The width of the spacing between each section = 144 – 138.75 = 5.25 inches

Question 29.
REASONING
The table shows the daily changes in the barometric pressure(in inches of mercury) for four days.
a. What is the mean change?
b. The mean change for Monday through Friday is -0.01 inch. What is the change in the barometric pressure on Friday? Explain.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 114

Answer:
a. Mean change is -0.02
b. The change in the barometric pressure on Friday is 0.03

Explanation:
a. Mean change = sum of observations / total number of observations
= (-0.05 + 0.09 – 0.04 – 0.08)/4
= -0.08/4
= -0.02
b. The mean change for Monday through Friday is -0.01 inch
Mean change = sum of observations / total number of observations
-0.01 = (-0.05 + 0.09 – 0.04 – 0.08 + x)/5
-0.01 =  (-0.08 + x)/5
5 * -0.01 = -0.08 + x
-0.05 = -0.08 + x
-0.05 + 0.08 = x
0.03 = x
So, the change in the barometric pressure on Friday is 0.03

Question 30.
LOGIC
In an online survey, gym members react to the statement shown by adjusting the position of the needle. The responses have values of -4.2, 1.6, 0.4, 0, 2.1, -5.0, -4.7, 0.6, 1.1, 0.8, 0.4, and 2.1. Explain how two people can use the results of the survey to reach different conclusions about whether the gym should adjust its membership prices.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 115

Answer:
The gym should adjust its membership prices.

Explanation:
Use mean to determine whether adjust the gym membership prices or not.
Mean = sum of observations / total number of observations
= (-4.2 + 1.6 + 0.4 + 0 + 2.1 – 5.0 – 4.7 + 0.6 + 1.1 + 0.8 + 0.4 + 2.1)/12
= -4.8/12
= -0.4
The mean score is below 0.
So, the gym should adjust its membership prices.

Question 31.
CRITICAL THINKING
Determine whether the statement is sometimes, always, or never true. Explain your reasoning.
a. The product of two terminating decimals is a terminating decimal.
b. The quotient of two terminating decimals is a terminating decimal.

Answer:
a. The product of two terminating decimals is always a terminating decimal
b. The quotient of two terminating decimals is always a terminating decimal.

Explanation:
a. The product of two terminating decimals is always a terminating decimal
The example to check the product of terminating decimals is a terminating decimal
4.5 x 6.27 = 28.215
b. The quotient of two terminating decimals is a terminating decimal.
The example is 36.257 / 24.85
= 1.459034205

Multiplying and Dividing Rational Numbers Connecting Concepts

Using the Problem-Solving Plan

Question 1.
You feed several adult hamsters equal amounts of a new food recipe over a period of 1 month. You record the changes in the weights of the hamsters in the table. Use the data to answer the question “What is the typical weight change of a hamster that is fed the new recipe?
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 116
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 117

Understand the problem.
You know the weight changes of 15 hamsters. You want to use this information to find the typical weight change.
Make a plan.
Display the data in a dot plot to see the distribution of the data. Then use the distribution to determine the most appropriate measure of center.
Solve and check.
Use the plan to solve the problem. Then check your solution.

Answer:
The typical weight change of a hamster that is fed the new recipe is -0.06266 ounces.

Explanation:
The typical weight change is measured by calculating the mean change.
Mean = (-0.07 – 0.03 – 0.11 – 0.04 – 0.08 + 0.02 – 0.08 – 0.08 – 0.06 – 0.05 – 0.11 – 0.1 + 0 – 0.07 – 0.08)/15
= -0.94/15
= -0.06266
So, typical weight change of a hamster that is fed the new recipe is -0.06266 ounces

Question 2.
Evaluate the expression shown at the right. Write your answer in simplest form.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 118

Answer:
-4/9

Explanation:
(-1/2 + 2/3) / [3/5(3/4 – 11/8)] = [(-3 + 4)/6] / [3/5((6 – 11)/8)]
= 1/6 / [3/5(-5/8)
= 1/6 / -3/8
= 1/6 . -8/3
= (1 . -8) / (3 . 6)
= -4/9

Question 3.
You drop a racquetball from a height of 60 inches. On each bounce, the racquetball bounces to a height that is 70% of its previous height. What is the change in the height of the racquetball after 3 bounces?

Answer:
The change in height of the racquetball after 3 bounces is 20.58 inches

Explanation:
You drop a racquetball from a height of 60 inches. On each bounce, the racquetball bounces to a height that is 70% of its previous height.
The change in height of the racquetball after 1 bounce = (60 x 70)/100
= 4200 / 100 = 42 inches
The change in height of the racquetball after 2 bounces = (42 x 70)/100
= 29.4
The change in height of the racquetball after 3 bounces = (29.4 x 70)/100
= 2058/100 = 20.58 inches

Performance Task

Precisely Perfect

At the beginning of this chapter, you watched a STEAM Video called “Carpenter or Joiner.” You are now ready to complete the performance task related to this video, available at BigIdeasMath.com. Be sure to use the problem-solving plan as you work through the performance task.
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 119

Multiplying and Dividing Rational Numbers Chapter Review

Review Vocabulary

Write the definition and give an example of each vocabulary term.
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 120

Graphic Organizers

You can use an Information Frame to help organize and remember a concept. Here is an example of an Information Frame for multiplying integers.
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 121
Choose and complete a graphic organizer to help you study the concept.

  1. dividing integers
  2. writing fractions or mixed numbers as decimals
  3. writing decimals as fractions or mixed numbers
  4. multiplying rational numbers
  5. dividing rational numbers

Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 122

Chapter Self-Assessment

As you complete the exercises, use the scale below to rate your understanding of the success criteria in your journal.
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 123

2.1 Multiplying Integers (pp. 49–54)

Find the product.

Question 1.
-8 • 6

Answer:
-8 • 6 = -48

Explanation:
The product of two integers with different signs is negative.
-8 • 6 = -48

Question 2.
10(-7)

Answer:
10(-7) = -70

Explanation:
The product of two integers with different signs is negative.
10(-7) = -70

Question 3.
-3 • (-6)

Answer:
-3 • (-6) = 18

Explanation:
-3 • (-6) = 18
The product of two integers with the same sign is positive.

Question 4.
You and a group of friends participate in a game where you must use clues to escape from a room. You have a limited amount of time to escape and are allowed 3 free clues. Additional clues may be requested, but each removes 5 minutes from your remaining time. What integer represents the total change in the time when you use 5 clues?

Answer:
The total change in time when you use 5 clues is -10 minutes

Explanation:
You are allowed 3 clues for free
The amount of time removes for each clue is 5 minutes
If you want to take 2 clues, then 5 x 2 = 10 minutes are removed
So, the total change in time when you use 5 clues is -10 minutes

Evaluate the expression.

Question 5.
(-3)3

Answer:
(-3)³ = -27

Explanation:
(-3)³ = -3 • -3 • -3
= 9 • -3
= -27

Question 6.
(-3)(-4)(10)

Answer:
(-3)(-4)(10) = 120

Explanation:
(-3)(-4)(10) = 12(10)
= 120

Question 7.
24 – 3(2 – 42)

Answer:
24 – 3(2 – 4²) = 66

Explanation:
24 – 3(2 – 4²) = 24 – 3(2 – 16)
= 24 – 3(-14)
= 24 + 42
= 66

Question 8.
Write three integers whose product is negative.

Answer:
-5, -2, 6

Explanation:
If three integers product is negative, then all integers would have negative signs or only one integer should have a negative sign.
(-5)(-2)6 = 10(6)
= 60

Question 9.
You are playing laser tag. The table shows how many points you gain or lose when you tag or are tagged by another player in different locations. You are tagged three times on the back, twice on the shoulder, and twice on the laser. You tag two players on the front, four players on the back, and one player on the laser. What is your score?
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 124

Answer:
Score = 727 points

Explanation:
You are tagged three times on the back, twice on the shoulder, and twice on the laser.
You have tagged means points lost.
= 3(25) + 2(12) + 2(12)
= 123
You tag two players on the front, four players on the back, and one player on the laser.
you tagged others means points gained
= 2(200) + 4(100) + 1(50)
= 850
Score = points gained – points lost
= 850 – 123 = 727

Question 10.
The product of three integers is positive. How many of the integers can be negative? Explain.

Answer:
If the product of three integers is positive, then only 2 integers can be negative.

Explanation:
If the product of three integers is positive, then only 2 integers can be negative.
We know the product of two negative integers is positive.
Find the product of an obtained positive integer with the third integer.

Question 11.
Two integers, c and d, have a product of -6. What is the greatest possible sum of c and d?

Answer:
The greatest possible sum of c and d are {-1, 6}

Explanation:
Two integers, c and d, have a product of -6
cd = -6
The possibilities of c, d are {-1, 6}, {1, -6}, {6, -1}, {-6, 1}, {-2, 3}, {3, -2}, {2, -3}, {-3, 2}
Find sum of c and d = 5, -5, 5, -5, 1, 1, -1, -1
The greatest possible sum of c and d are {-1, 6}

Dividing Integers (pp. 55–60)

Find the quotient.

Question 12.
-18 ÷ 9

Answer:
-18 ÷ 9 = -2

Explanation:
-18 ÷ 9 = -2
The quotient of two integers with the different signs is negative.

Question 13.
\(\frac{-42}{-6}\)

Answer:
-42/-6 = 7

Explanation:
The quotient of two integers with the same sign is positive.
-42/-6 = 7

Question 14.
\(\frac{-30}{6}\)

Answer:
-30/6 = -5

Explanation:
The quotient of two integers with the different signs is negative.
-30/6 = -5

Question 15.
84 ÷ (-7)

Answer:
84 ÷ (-7) = -12

Explanation:
The quotient of two integers with the different signs is negative.
84 ÷ (-7) = -12

Evaluate the expression when x = 3, y = -4, and z = -6.

Question 16.
z ÷ x

Answer:
z ÷ x = -2

Explanation:
The given expression is z ÷ x
Put x = 3, z = -6
-6 ÷ 3 = -2

Question 17.
\(\frac{xy}{z}\)

Answer:
xy/z = 2

Explanation:
The given expression is xy/z
Put x = 3, y = -4, and z = -6
= (3 . -4)/-6
= -4/-2
= 2

Question 18.
\(\frac{z – 2x}{y}\)

Answer:
(z – 2x)/y = 3

Explanation:
The given expression is (z – 2x)/y
Put x = 3, y = -4, and z = -6
= (-6 – 2(3))/-4
= (-6 – 6)/-4
= -12/-4
= 3

Find the mean of the integers.

Question 19.
-3, -8, 12, -15, 9

Answer:
Mean = -1

Explanation:
Mean = sum of integers / total number of integers
= (-3 – 8 + 12 – 15 + 9)/5
= -5/5
= -1

Question 20.
-54, -32, -70, -25, -65, -42

Answer:
Mean = -48

Explanation:
Mean = (-54 – 32 – 70 – 25 – 65 – 42)/6
= -288/6
= -48

Question 21.
The table shows the weekly profits of a fruit vendor. What is the mean profit for these weeks?
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 125
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 126

Answer:
The mean profit for 4 weeks is -$48

Explanation:
The mean profit = (sum of the profits) / number of weeks
= (-125 – 86 + 54 – 35)/4
= -192/4
= -48
The mean profit for 4 weeks is -$48.

2.3 Converting Between Fractions and Decimals (pp. 61–66)

Write the fraction or mixed number as a decimal.

Question 22.
– \(\frac{8}{15}\)

Answer:
-8/15 = -0.533333

Explanation:
-8/15 = -0.533333
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 78

Question 23.
\(\frac{5}{8}\)

Answer:
5/8 = 0.625

Explanation:
5/8 = 0.625
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 79

Question 24.
–\(\frac{13}{6}\)

Answer:
-13/6 = -2.16666

Explanation:
-13/6 = -2.16666
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 80

Question 25.
1\(\frac{7}{16}\)

Answer:
1\(\frac{7}{16}\) = 1.4375

Explanation:
1(7/16) = 23/16
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 81

Write the decimal as a fraction or mixed number in simplest form.

Question 26.
-0.6

Answer:
-0.6 = -3/5

Explanation:
-0.6 = -6/10
= -3/5

Question 27.
-0.35

Answer:
-0.35 = -7/20

Explanation:
-0.35 = -35/100
= -7/20

Question 28.
-5.8

Answer:
-5.8 = -29/5

Explanation:
-5.8 = -58/10
= -29/5

Question 29.
24.23

Answer:
24.23 = 2423/100

Explanation:
24.23 = 2423/100

Question 30.
The table shows the changes in the average yearly precipitation (in inches) in a city for several months. Order the numbers from least to greatest.
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 127

Answer:
The order of numbers from least to greatest is -1(7/9), -1.75, 3/11, 0.3

Explanation:
Order the numbers -1.75, 3/11, 0.3, -1(7/9) from least to greatest
Express each number as a decimal
3/11 = 0.272727
-1(7/9) = -16/9 = -1.77777
-1.7777 < -1.75 < 0.272727 < 0.3
The order of numbers from least to greatest is -1(7/9), -1.75, 3/11, 0.3

2.4 Multiplying Rational Numbers (pp. 67–72)

Find the product. Write fractions in simplest form.

Question 31.
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 128

Answer:
-4/9(-7/9) = 28/81

Explanation:
-4/9(-7/9) = (-4 . -7)/(9 . 9)
= 28/81

Question 32.
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 129

Answer:
8/15(-2/3) = -16/45

Explanation:
8/15(-2/3) = (8 . -2)/(15 . 3)
= -16/45

Question 33.
-5.9(-9.7)

Answer:
-5.9(-9.7) = 5723/100

Explanation:
-5.9(-9.7) = -59/10 (-97/10)
= (-59 . -97)/100
= 5723/100
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 82

Question 34.
4.5(-5.26)

Answer:
4.5(-5.26) = 2367/100

Explanation:
4.5(-5.26) = 45/10 (-526/100)
= (45 . -526) / (10 . 100)
= (9 . 263) / 100
= 2367/100
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 83

Question 35.
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 130

Answer:
-2/3 (2(1/2))(-3) = -5

Explanation:
-2/3 (2(1/2))(-3) = -2/3 (5/2) (-3)
= (-2 . 5 . -3) / (2 . 3)
= -5

Question 36.
-1.6(0.5)(-20)

Answer:
-1.6(0.5)(-20) = 16

Explanation:
-1.6(0.5)(-20) = -16/10(5/10)(-20)
= (-16 . 5 . -20)/(10 . 10)
= 16

Question 37.
The elevation of a sunken ship is -120 feet. You are in a submarine at an elevation that is \(\frac{5}{8}\) of the ship’s elevation. What is your elevation?
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 131

Answer:
Your elevation is -300 feet.

Explanation:
You are in a submarine at an elevation that is 5/8 of the ship’s elevation
Ship elevation = -120 feet
Your elevation = 5/8 (-120)
= 15(-20) = -300

Question 38.
Write two fractions whose product \(\frac{1}{5}\) and \(\frac{1}{2}\), and whose sum is negative.

Answer:
Two fractions are-1/2 and -1/2

Explanation:
The product of two fractions is between 1/5 and 1/2 and sum is negative.
Let us say the product of fractions is 1/4.
Then two fractions are -1/2 and -1/2
the sum is -1/2 – 1/2 = -2/2 = -1

2.5 Dividing Rational Numbers (pp. 73–78)

Find the quotient. Write fractions in simplest form.

Question 39.
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 132

Answer:
-3/4

Explanation:
9/10 ÷ (-6/5) = 9/10 • (-5/6)
= (9 • -5)/ (10 . 6)
= -3/4

Question 40.
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 133

Answer:
-14/11

Explanation:
-4/11 ÷ 2/7 = -4/11 • 7/2
= (-4 • 7) / (2 • 11)
= -14/11

Question 41.
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 134

Answer:
21/10

Explanation:
-7/8 ÷ (-5/12) = -7/8 • (-12/5)
= (-7 • -12) / (8 • 5)
= 21/10

Question 42.
6.4 ÷ (-3.2)

Answer:
-512/25

Explanation:
6.4 ÷ (-3.2) = 64/10 ÷ (-32/10)
= (64 • -32) / (10 • 10)
= -512/25

Question 43.
-15.4 ÷ (-2.5)

Answer:
77/2

Explanation:
-15.4 ÷ (-2.5) = -154/10 ÷(-25/10)
= (-154 • -25)/(10 • 10)
= 77/2

Question 44.
-23.8 ÷ 5.6

Answer:
-3332/25

Explanation:
-23.8 ÷ 5.6 = -238/10 ÷ 56/10
= (-238 • 56) / (10 • 10)
= -3332/25

Question 45.
You use a debit card to purchase several shirts. Your account balance after buying the shirts changes by -$30.60. For each shirt you purchased, the change in your account balance was -$6.12. How many shirts did you buy?

Answer:
The number of T-shirts bought was 5

Explanation:
After using a debit card, to purchase several t-shirts. Your account balance after buying the t-shirts changes by -$30.60. The negative sign means there was a total debit of $30.6 after your transactions.
For each t-shirt you purchased, the changes in your account balance were -6.12. If you purchased n T-shirts, the changes would be n × -6.12 = -6.12n. This means a total debit of 6.12n for all the T-shirts you bought.
Therefore, 6.12n = 30.6
n = 30.6/6.12 = 5
So the number of T-shirts bought was 5

Question 46.
Evaluate Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 136 when x = 4, y = -3, and \(-\frac{1}{8}\).

Answer:
-1/2

Explanation:
The given expression is z / (y – 3/4 + x)
Put x = 4, y = -3 and z = -1/8
= -1/8 / (-3 – 3/4 + 4)
= -1/8 / ((-12 – 3 + 16)/4)
= -1/8 / (1/4)
= -1/8 • 4/1
= -1/2

Multiplying and Dividing Rational Numbers Practice Test

Evaluate the expression. Write fractions in simplest form.

Question 1.
-9 • 2

Answer:
-9 • 2 = -18

Explanation:
-9 • 2 = -18
The product of two integers with different signs is negative.

Question 2.
-72 ÷ (-3)

Answer:
-72 ÷ (-3) = 24

Explanation:
-72 ÷ (-3) = 24
The quotient of two integers with the same sign is positive.

Question 3.
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 136.1

Answer:
-52/5

Explanation:
3(9/10) x (-8/3) = 39/10 x (-8/3)
= (39 . -8) / (10 . 3)
= (13 . -4)/5
= -52/5

Question 4.
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 137

Answer:
-11/25

Explanation:
-1(5/6) ÷ 4(1/6) = -11/6 ÷ 25/6
= -11/6 • 6/25
= (-11 • 6) / (6 • 25)
= -11/25

Question 5.
-4.4 × (-6.02)

Answer:
-4.4 × (-6.02) = 6622/25

Explanation:
-4.4 × (-6.02) = -44/10 x -602/10
= (-44 x -602) / (10 x 10)
= (-11 x -602)/25
= 6622/25

Question 6.
-5 ÷ 1.5

Answer:
-5 ÷ 1.5 = -10/3

Explanation:
-5 ÷ 1.5 = -5 ÷ 15/10
= -5 • 10/15
=(-5 • 10) / 15
= -10/3

Write the fraction or mixed number as a decimal.

Question 7.
\(\frac{7}{40}\)

Answer:
\(\frac{7}{40}\) = 0.175

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 84

Question 8.
\(-\frac{1}{9}\)

Answer:
\(-\frac{1}{9}\) = -0.11111

Explanation:
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 85

Question 9.
-1\(\frac{5}{16}\)

Answer:
-1\(\frac{5}{16}\) = -1.3125

Explanation:
-1\(\frac{5}{16}\) = -21/16
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 86

Write the decimal as a fraction or mixed number in simplest form.

Question 10.
-0.122

Answer:
-0.122 = -61/500

Explanation:
-0.122 = -122/1000
= (-2 x 61) / (2 x 500)
= -61/500

Question 11.
0.33

Answer:
0.33 = 33/100

Explanation:
0.33 = 33/100

Question 12.
-7.09

Answer:
-7.09 = -709/100

Explanation:
-7.09 = -709/100

Evaluate the expression when x = 5, y = -3, and z = -2.

Question 13.
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 138

Answer:
-6/5

Explanation:
The given expression is (y + z)/x
Put x = 5, y = -3, and z = -2
= (-3 + (-2)) / 5
= (-3 – 2)/5
= -6/5

Question 14.
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 139

Answer:
-5

Explanation:
The given expression is (x – 5z)/y
Put x = 5, y = -3, and z = -2
= (5 – 5(-2))/-3
= (5 + 10)/-3
= 15/-3 = -5

Question 15.
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 140

Answer:
10/9

Explanation:
The given expression is 1/3 x / y/z
Put x = 5, y = -3, and z = -2
= [1/3 (5)]/[-3/-2]
= 5/3 / 3/2
= 5/3 . 2/3
= 10/9

Question 16.
Find the mean of 11, -7, -14, 10, and -5.

Answer:
Mean = -1

Explanation:
Mean = (11 – 7 – 14 + 10 – 5)/5
= -5/5
= -1

Question 17.
A driver receives -25 points for each rule violation. What integer represents the change in points after 4 rule violations?
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 141

Answer:
The change in points after 4 rule violations is -100 points

Explanation:
A driver receives -25 points for each rule violation.
The change in points after 4 rule violations = 4(-25)
= -100

Question 18.
How many 2.25-pound containers can you fill with 24.75 pounds of almonds?

Answer:
The number of containers = 11

Explanation:
The number of containers = 24.75 / 2.25
= 2475/225 = (495 . 5)/(45 . 5)
= (99 . 5) / (9 . 5)
= 11

Question 19.
In a recent 10-year period, the change in the number of visitors to U.S.national parks was about 11,150,000 visitors.
a. What was the mean yearly change in the number of visitors?
b. During the seventh year, the change in the number of visitors was about 10,800,000. Explain how the change for the 10-year period can be negative.
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 142

Answer:
a. Mean yearly change in the number of visitors = 1,15,000
b. The change is -35000

Explanation:
a. Mean yearly change in the number of visitors = 11,150,000/10
= 1,15,000
b. During the seventh year, the change in the number of visitors was about 10,800,000
The change in the number of visitors to U.S.national parks was about 11,150,000 visitors
(10,800,000 – 11,150,000)/10 = -350000/10 = -35000

Question 20.
You have a $50 gift card to go shopping for school supplies. You buy 2 packs of pencils, 5 notebooks, 6 folders, 1 pack of pens, 3 packs of paper, 1 pack of highlighters, and 2 binders.
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 143
a. What number represents the change in the value of the gift card after buying your school supplies?
b. What percentage of the value remains on your gift card?

Answer:
a. The change in the value of the gift card after buying your school supplies = $12.06
b. The percentage of the value that remains on your gift card = 24.12%

Explanation:
You buy 2 packs of pencils, 5 notebooks, 6 folders, 1 pack of pens, 3 packs of paper, 1 pack of highlighters, and 2 binders.
a. The change in the value of the gift card after buying your school supplies = 50 – [2(1.98) + 5(2.95) + 6(0.75) + 1(1.57) + 3(0.89) + 1(3.45) + 2(3.55)]
= 50 – [3.9 + 14.75 + 4.5 + 1.57 + 2.67 + 3.45 + 7.1]
= 50 – 37.94
= 12.06
b. The amount remains on the gift card = $12.06
The percentage of the value that remains on your gift card = (100 x 12.06)/50
= 2 x 12.06 = 24.12%

Multiplying and Dividing Rational Numbers Cumulative Practice

Question 1.
When José and Sean were each 5 years old, José was 1\(\frac{1}{2}\) inches taller than Sean. Then José grew at an average rate of 2\(\frac{3}{4}\) inches per year until he was 13 years old. José was 63 inches tall when he was 13 years old. How tall was Sean when he was 5 years old?
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 146

Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 145

Answer:
A. 39(1/2)

Explanation:
José grew at an average rate of 2\(\frac{3}{4}\) inches per year until he was 13 years old.
2.75 * (13 – 5) = 2.75 (8) =  22
José was 63 inches
= 63 – 22 = 41
41 – 1.5 = 39.5 = 39(1/2)
sean was only 39.5 inches tall when he was 5.

Question 2.
Whatis the value of -5 + (-7) ?
F. -12
G. -2
H. 2
I. 12

Answer:
F. -12

Explanation:
-5 + (-7) = -5 – 7
= -12

Question 3.
What is the value of the expression?
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 147

Answer:
9/16

Explanation:
-9/16 + 9/8 = (-9 + 18)/16
= 9/16

Question 4.
What is the value of Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 158 when a = -2, b = 3, and c = -5?
A. -9
B. -1
C. 1
D. 9

Answer:
C. 1

Explanation:
| a² – 2ac + 5b |
Put a = -2, b = 3, and c = -5
= | (-2)² – 2(-2)(-5) + 5(3) |
= | 4 – 20 + 15 |
= | -1 |
= 1

Question 5.
Your friend evaluated the expression.
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 148
What should your friend do to correct the error that he made?
F. Subtract 5 from -5 instead of adding.
G. Rewrite 2 – 3 as -1.
H. Subtract -5 from 3 before subtracting 3 from 2.
I. Rewrite -5 + 5 as -10

Answer:
H. Subtract -5 from 3 before subtracting 3 from 2.

Explanation:
2 – 3 – (-5) = 2 – 3 + 5
= -1 + 5
= 4

Question 6.
What is the value of Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 149?
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 149.1

Answer:
B. 1/4

Explanation:
-1(1/2) – (-1(3/4)) = -3/2 + 7/4
= (-6 + 7)/4
= 1/4

Question 7.
What is the value of the expression when q = -2, r = -12, and s = 8?
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 150
F. -2
G. -1
H. 1
I. 2

Answer:
H. 1

Explanation:
The given expression is (-q² – r)/s
Put q = -2, r = -12, and s = 8
= (-(-2)² – (-12))/8
= (-4 + 12)/8
= 8/8 = 1

Question 8.
You are stacking wooden blocks with the dimensions shown. How many blocks do you need to stack vertically to build a block tower that is 7\(\frac{1}{2}\) inches tall?
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 151
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 152

Answer:
We need 6 blocks to stack vertically to build a block tower.

Explanation:
The length of block tower = 7(1/2) = 15/2 inches
The length of each block = 1(1/4) = 5/4 inches
So, 5/4 x = 15/2
x = 15/2 . 4/5
x = 6
Therefore, we need 6 blocks to stack vertically to build a block tower.

Question 9.
Your friend evaluated an expression.
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 153
What should your friend do to correct the error that she made?
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 154

Answer:
C.

Explanation:
-4(3/4) + 2(1/5) = -19/4 + 11/5
= (-95 + 44)/20
= -51/20

Question 10.
Which expression has the greatest value when x = 2 and y = -3?
F. -xy
G. xy
H. x – y
I. -x – y

Answer:
F. -xy

Explanation:
Put x = 2 and y = -3
F. -xy
= -2(-3) = 6
G. xy = 2(-3) = -6
H. x – y = 2 – (-3) = 2 + 3 = 5
I. -x – y = -2 – (-3) = -2 + 3 = 1

Question 11.
Four points are graphed on the number line.
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 155
Part A
Choose the two points whose values have the greatest sum. Approximate this sum. Explain your reasoning.
Part B
Choose the two points whose values have the greatest difference. Approximate this difference. Explain your reasoning.
Part C
Choose the two points whose values have the greatest product. Approximate this product. Explain your reasoning.
Part D
Choose the two points whose values have the greatest quotient. Approximate this quotient. Explain your reasoning.

Answer:
A. T + U
B. R – S
C. R . S
D. U/T

Explanation:
Values of the points are R = -2.75, S = -1.25, T = 0.4, U = 2.1
A. T + U = 0.4 + 2.1 = 2.5
B. R – S = -2.75 – (-1.25) = -2.75 + 1.25 = -1.5
S – T = -1.25 – 0.4 = -1.65
T – U = 0.4 – 2.1 = -1.7
S – U = -1.25 – 2.1 = -3.35
R – T = -2.75 – 0.4 = -3.15
R – U = -2.75 – 2.1 = -4.85
Out of all R – S has the greatest difference.
C. R . S = -2.75 . -1.25 = 3.4375
T. U = 0.4 . 2.1 = 0.84
D. R/s = -2.75/1.25 = 2.2
T/U = 0.4/2.1 = 0.19
U/T = 2.1/0.4 = 5.25

Question 12.
What number belongs in the box to make the equation true?
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 156
A. -1
B. -0.2
C. 0.2
D. 1

Answer:
A. -1

Explanation:
-0.4/-1 + 0.8 = 0.4 + 0.8 = 1.2
-0.4/1 + 0.8 = -0.4 + 0.8 = 0.4
-0.4/0.2 + 0.8 = -2

Question 13.
Which expression has a negative value when x = -4 and y = 2?
F. -x + y
G. y – x
H. x – y
I. -x – y

Answer:
H. x – y

Explanation:
Put x = -4 and y = 2
F. -x + y = -(-4) + 2 = 4 + 2 = 6
G. y – x = 2 – (-4) = 6
H. x – y = -4 – 2 = -6
I. -x – y = -(-4) – 2 = 4 – 2 = 2

Question 14.
What is the area of a triangle with a base of 2\(\frac{1}{2}\) inches and a height of 2 inches?
Big Ideas Math Solutions Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 157

Answer:
B

Explanation:
Area of triangle = 1/2 . base . height
= 1/2 . 2(1/2) . 2
= 2(1/2)

Question 15.
Which decimal is equivalent to \(\frac{2}{9}\)?
F. 0.2
G. \(0 . \overline{2}\)
H. 0.29
I. 4.5

Answer:
F. 0.2

Explanation:
2/9 = 0.222
Big Ideas Math Answers Grade 7 Chapter 2 Multiplying and Dividing Rational Numbers 87

Conclusion:

The final verdict of Multiplying and Dividing Rational Numbers is that you get various problems and solutions that helps you in your preparation. With the help of the pdfs given above, you can practice even in the offline mode. Check out all the topics and concepts and feel free to clarify your doubts by adding them in the comments box. Hope you are satisfied with the information given in the article. We wish all the luck to all the candidates for the exam preparation.

Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions

Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions

For the best practice, the Big Ideas Math Grade 7 Chapter 5 Ratios and Proportions Answer Sheet is given here. A detailed explanation of solutions prepared by great math experts which are included in the below sections. Click on the Big Ideas Math Book Grade 7 Answer Key Chapter 5 Ratios and Proportions link on our website and start your preparation. Get the free pdfs here in the following sections.

Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions preparation material is here. Candidates can quickly get this material without much search because we are giving the lesson-wise information in detail here. This will act as a guide for your complete preparation. Get a clear idea of ratios and their tables. Follow the below sections and know more about Ratios and Proportions.

Big Ideas Math Book 7th Grade Answer Key Chapter 5 Ratios and Proportions

Feeling difficult to get the best solutions for all the math problems? If you get a guide with clear explanations and short solutions, then you will feel it easy and fun learning. Therefore, check out Big Ideas Math Book 7th Grade Answer Key Chapter 5 Ratios and Proportions Pdf here which is given with a clear explanation. Know the various topics involved in ratios and proportions.

Various topics like graphs of proportional relationships, rates, and unit rates, identifying proportional relationships, writing and solving proportions, ratios, and ratio tables, scale drawings, and so on. Check Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions solved examples in the next sections.

Performance Task

Lesson: 1 Ratios and Ratio Tables

Lesson: 2 Rates and Unit Rates

Lesson: 3 Identifying Proportional Relationships

Lesson: 4 Writing and Solving Proportions

Lesson: 5 Graphs of Proportional Relationships

Lesson: 6 Scale Drawings

Chapter: 5 – Ratios and Proportions

Ratios and Proportions STEAM Video/ Performance Task

STEAM Video

Painting a Large Room
Shades of paint can be made by mixing other paints. What colors of paints can you mix to make green paint?
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 1
Watch the STEAM Video “Painting a Large Room.” Then answer the following questions.
1. Enid estimates that they need 2 gallons of paint to apply two coats to the wall shown. How many square feet does she expect \(\frac{1}{2}\) gallon of paint will cover?
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 2

Answer:
1/2 gallon of paint will cover 60 sq feet.

Explanation:
Enid estimates that they need 2 gallons of paint to apply two coats to the wall of 240 sq ft
The area of the shown figure = 24 x 10
= 240 square feet
To know how many sq feet does 1/2 gallon of paint will cover (240 . 1/2) . 1/2
= 240 . 1/4
= 60
So, 1/2 gallon of paint will cover 60 sq feet.

2. Describe a room that requires 5\(\frac{1}{2}\) gallons of paint to apply one coat of paint to each of the four walls.

Answer:
The room has 4 walls each wall is 330 sq feet.

Explanation:
A room requires 5(1/2) gallons of paint to apply one coat of paint to each of the four walls.
Enid estimates that they need 2 gallons of paint to apply two coats to the wall of 240 sq ft
If they coat only once, she would require 1 gallon of paint for a wall of 240 sq feet.
If she wants to use 5(1/2) = 11/2 gallons of paint, then the area of walls will be
= 240 . (11/2)
= 120 . 11 = 1320 Square feet
Each wall = 1320/4 =330 sq feet
The room has 4 walls each wall is 330 sq feet.

Performance Task

Mixing Paint
After completing this chapter, you will be able to use the concepts you learned to answer the questions in the STEAM Video Performance Task. You will be given the amounts of each tint used to make different colors of paint. For example:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 3
You will be asked to solve various ratio problems about mixing paint. Given any color of paint, how can you make the paint slightly lighter in color?

Ratios and Proportions Getting Ready for Chapter 5

Chapter Exploration

The Meaning of a Word Rate
When you rent snorkel gear at the beach, rate you should pay attention to the rental. The rental rate is in dollars per hour.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 4
1. Work with a partner. Complete each step.
• Match each description with a rate.
• Match each rate with a fraction.
• Give a reasonable value for each fraction. Then give an unreasonable value.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5
2. Work with a partner Describe a situation to which the given fraction can apply. Show how to rewrite each expression as a division problem. Then simplify and interpret your result.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 6
Vocabulary
The following vocabulary terms are defined in this chapter. Think about what each term might mean and record your thoughts.
proportional
constant of proportionality
scale drawing

Lesson 5.1 Ratios and Ratio Tables

EXPLORATION 1

Describing Ratio Relationships
Work with a partner. Use the recipe shown.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 1
a. Identify several ratios in the recipe.
b. You halve the recipe. Describe your ratio relationships in part (a) using the new quantities. Is the relationship between the ingredients the same as in part(a)? Explain.

Answer:
a. Stewed tomatoes : chicken broth = 9 ounces : 15 ounces
Stewed tomatoes : Chopped Spinach = 9 ounces : 9 ounces = 1 : 1
Chopped Spinach : chicken broth = 9 ounces : 15 ounces
Chopped Chicken : grated parmesan = 1 cup : 5 tablespoons
Chicken broth : Chopped Chicken = 15 ounces : 1 cup
Stewed tomatoes : chopped chicken = 9 ounces : 1 cup = Chopped Spinach : chopped chicken
Stewed tomatoes : grated parmesan = 9 ounces : 5 tablespoons = Chopped Spinach : grated parmesan
chicken broth : grated parmesan = 15 ounces : 5 tablespoons = 5 ounces : 1 tablespoon
b. The relationship between the ingredients the same as in part(a).

Explanation:
a. The several ratios of the recipe are Stewed tomatoes : chicken broth = 9 ounces : 15 ounces
Stewed tomatoes : Chopped Spinach = 9 ounces : 9 ounces = 1 : 1
Chopped Spinach : chicken broth = 9 ounces : 15 ounces
Chopped Chicken : grated parmesan = 1 cup : 5 tablespoons
Chicken broth : Chopped Chicken = 15 ounces : 1 cup
Stewed tomatoes : chopped chicken = 9 ounces : 1 cup = Chopped Spinach : chopped chicken
Stewed tomatoes : grated parmesan = 9 ounces : 5 tablespoons = Chopped Spinach : grated parmesan
chicken broth : grated parmesan = 15 ounces : 5 tablespoons = 5 ounces : 1 tablespoon
b. The relationship between the ingredients the same as in part(a).

EXPLORATION 2

Completing Ratio Tables
Work with a partner. Use the ratio tables shown.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 2
a. Complete the first ratio table using multiple operations. Use the same operations to complete the second ratio table.
b. Are the ratios in the first table equivalent? the second table? Explain.
c. Do the strategies for completing ratio tables of whole numbers work for completing ratio tables of fractions? Explain your reasoning.

Answer:
a. Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 2
b. Yes

Explanation:
a. 5 x 2 = 10, 1 x 2 = 2, 1/4 x 2 = 1/2, 1/2 x 2 = 1
5 x 1.5 = 7.5, 1 x 1.5 = 1.5, 1/4 x 3/2 = 3/8, 1/2 x 3/2 = 3/4
5 x 4 = 20, 1 x 4 = 4, 1/4 x 4 = 1, 1/2 x 4= 2
b. Yes the ratios in the first table are equivalent to the second table.

Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 3

Try It

Question 1.
You mix \(\frac{2}{3}\) teaspoon of baking soda with 3 teaspoons of salt. Find and interpret the value of the ratio of baking soda to salt.

Answer:
The ratio of baking soda to salt is 2 : 1.

Explanation:
Given that,
You mix \(\frac{2}{3}\) teaspoon of baking soda with 3 teaspoons of salt.
The ratio of baking soda to salt = 2/3 to 3 = 2/3 : 3
= 2/3 / 3 = 2/3 . 3/1 = 2/1 = 2 : 1
The ratio of baking soda to salt is 2 : 1.

Find the missing values in the ratio table. Then write the equivalent ratios.
Question 2.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 4

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 3

Explanation:
The missing values in the ratio table are
4 x 4 = 16. So, 5/2 x 4 = 10
5/2 . x = 5
x = 2
So, 4 . 2 = 8
The equivalent ratios are 5/2 : 4, 10 : 16, 5 : 8.

Question 3.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 5

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 4

Explanation:
0.4 . x = 1.2
x = 1.2/0.4 = 3
So, 0.75 . 3 = 2.25
0.4 . y = 1.6
y = 1.6/0.4 = 4
So, 0.75 . 4 = 3
The equivalent ratios are 0.4 : 0.75, 1.2 : 2.25, 1.6 : 3

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 4.
WRITING AND INTERPRETING RATIOS
You include \(\frac{1}{2}\) tablespoon of essential oils in a solution for every 12 tablespoons of jojoba oil. Find and interpret the value of the ratio of jojoba oil to essential oils.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 6

Answer:
The amount of jojoba oil in the solution is the 24th amount of essential oil.

Explanation:
You include \(\frac{1}{2}\) tablespoon of essential oils in a solution for every 12 tablespoons of jojoba oil
The ratio of jojoba oil to essential oil = 12 : 1/2
= 12 ÷ 1/2
= 12 . 2/1
= 24
The amount of jojoba oil in the solution is the 24th amount of essential oil.

Question 5.
NUMBER SENSE
Find the missing values in the ratio table. Then write the equivalent ratios.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 7

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 5

Explanation:
1/12 . x = 2/3
x = 2/3 . 12
x = 8
So, Pounds = 3/2 . 8 = 12
3/2 . 7 = 21/2
1/12 . 7 = 7/12
The equivalent ratios are 3/2 : 1/12, 12 : 2/3, 21/2 : 7/12

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 6.
DIG DEEPER!
A satellite orbiting Earth travels 14\(\frac{1}{2}\) miles every 3 seconds. How far does the satellite travel in \(\frac{3}{4}\) minute?
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 8

Answer:
The satellite travels 217(1/2) miles in 3/4 minutes.

Explanation:
A satellite orbiting Earth travels 14\(\frac{1}{2}\) miles every 3 seconds.
So, it travels 14.5/3 miles = 29/6 miles in every 1 second
3/4 minutes = 3/4 . 60
= 45 seconds
Therefore, it travels 45 . 29/6 miles in 3/4 minutes
= 217(1/2) miles in 3/4 minutes.
Hence, the satellite travels 217(1/2) miles in 3/4 minutes.

Question 7.
An engine runs on a mixture of 0.1 quart of oil for every 3.5 quarts of gasoline. You make 3 quarts of the mixture. How much oil and how much gasoline do you use?

Answer:
We use 0.083 quarts of oil and 2.917 quarts of gasoline.

Explanation:
The ratio of oil to gasoline = 0.1 : 3.5 = 1 : 35
use the ratio table to find an equivalent ratio in which the total mixture is 3 quarts.
For 3 quarts mixture
Oil required is 1/36 * 3 = 3/36
= 1/12 = 0.083 quarts
Gasoline required is
35/36 * 3 = 35/12 = 2.917 quarts
We use 0.083 quarts of oil and 2.917 quarts of gasoline.

Ratios and Ratio Tables Homework & Practice 5.1

Review & Refresh

Solve the inequality. Graph the solution.
Question 1.
4p + 7 ≥ 19

Answer:
p ≥ 3
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 6

Explanation:
Given that,
4p + 7 ≥ 19
Subtract 7 from both sides
4p + 7 – 7 ≥ 19 – 7
4p ≥ 12
Divide both sides by 4
4p/4 ≥ 12/4
p ≥ 3

Question 2.
14 < – 6n – 10

Answer:
-4 > n
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 7

Explanation:
Given that,
14 < – 6n – 10
Add 10 to both sides
14 + 10 < -6n – 10 + 10
24 < -6n
Divide both sides by -6
24/-6 > -6n/-6
-4 > n

Question 3.
– 3(2 + d) ≤ 15

Answer:
d ≥ -7
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 8

Explanation:
Given that,
– 3(2 + d) ≤ 15
Divide both sides by -3
– 3(2 + d)/-3 ≥ 15/-3
2 + d ≥ -5
d ≥ -5 – 2
d ≥ -7

Find the quotient. Write fractions in simplest form.
Question 4.
\(\frac{2}{9}\) ÷ \(\frac{4}{3}\)

Answer:
\(\frac{2}{9}\) ÷ \(\frac{4}{3}\) = 1/6 = 0.166

Explanation:
\(\frac{2}{9}\) ÷ \(\frac{4}{3}\) = 2/9 . 3/4
= (2 . 3) / (9 . 4)
= 1/6
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 9

Question 5.
10.08 ÷ 12

Answer:
10.08 ÷ 12 = 3024/25 = 120.96

Explanation:
10.08 ÷ 12 = 1008/100 ÷ 12
= 1008/100 . 12/1
= (1008 . 12)/100
= (100.8 . 3)/25
= 3024/25 = 120.96
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 10

Question 6.
– \(\frac{5}{6}\) ÷ \(\frac{3}{10}\) = -25/9 = -2.7777

Answer:
– \(\frac{5}{6}\) ÷ \(\frac{3}{10}\)

Explanation:
– \(\frac{5}{6}\) ÷ \(\frac{3}{10}\) = -5/6 . 10/3
= (-5 . 10)/(3 . 6)
= -25/9 = -2.7777
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 11

Question 7.
Which ratio can be represented by the tape diagram?
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 9
A. 3 : 4
B. 4 : 5
C. 4 : 9
D. 8 : 12

Answer:
D. 8 : 12

Explanation:
Quantity 1 has 2 boxes, quantity 2 has 3 boxes.
Out of all given ratios, 8 : 12 satisfy the condition
The ratio of given quantity = 2 : 3
2 * 4 : 3 * 4 = 8 : 12

Concepts, Skills, & Problem Solving

OPEN-ENDED Complete the ratio table using multiple operations. Are the ratios in the table equivalent? Explain. (See Exploration 2, p. 183.)
Question 8.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 10

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 12

Explanation:
4 x 2 = 8, 10  2 = 20
8 x 2 = 16, 20 x 2 = 40
16/8 = 2, 40/8 = 5
The equivalent ratios are 4:10, 8:20, 16:40, 2:5.

Question 9.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 11

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 14

Explanation:
4/5 x 10 = 8, 1/2 x 10 = 5
4/5 x 5 = 4, 1/2 x 5 = 5/2
4 x 1/25 = 4/25, 5/2 x 1/25 = 1/10

WRITING AND INTERPRETING RATIOS Find the ratio. Then find and interpret the value of the ratio.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 12
Question 10.
club soda : white grape juice

Answer:
club soda : white grape juice = 2 : 1

Explanation:
Club soda = 4 cups
white grape juice = 2 cups
club soda : white grape juice = 4 : 2
= 2 : 1

Question 11.
mint leaves : chopped watermelon

Answer:
mint leaves : chopped watermelon = 1 : 6

Explanation:
mint leaves = 1/2 cup
chopped watermelon = 3 cups
mint leaves : chopped watermelon = 1/2 : 3
= 1 : 3 x 2
= 1 : 6

Question 12.
white grape juice to sugar

Answer:
white grape juice : sugar = 8 : 3

Explanation:
white grape juice = 2 cups
sugar=3/4 cup
white grape juice : sugar = 2 : 3/4
= 2 x 4: 3
= 8 : 3

Question 13.
lime juice to mint leaves

Answer:
lime juice to mint leaves is 3 : 2

Explanation:
lime juice = 3/4 cup
mint leaves = 1/2 cup
lime juice to mint leaves = 3/4 : 1/2
= 3/2 : 1
= 3 : 2

Question 14.
You have blue ribbon and red ribbon in the ratio \(\frac{1}{2}\) : \(\frac{1}{5}\) . Your friend finds the value of the ratio. Is your friend correct? Explain your reasoning.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 13

Answer:
Wrong.

Explanation:
1/2 : 1/5 = 1/2 ÷ 1/5
= 1/2 . 5/1 = 5/2

COMPLETING A RATIO TABLE Find the missing values in the ratio table. Then write the equivalent ratios.
Question 15.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 14

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 15

Explanation:
To find the missing values,
1/6 . x = 2/3
x = 2/3 . 6
x = 4
So, calories = 20 . 4 = 80
20 . y = 10
y = 10/20 = 1/2
Miles = 1/6 . 1/2 = 1/12
10 . z = 90
z = 90/10
z = 9
Miles = 1/12 . 9 = 3/4
The equivalent ratios are 20 : 1/6, 80 : 2/3, 10 : 1/12, 90 : 3/4

Question 16.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 15

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 16

Explanation:
To find the missing values,
8/2 = 4
Minutes = 1/3/2 = 1/3 . 2 = 1/6
1/3 . x = 1/4
x = 1/4 . 3 = 3/4
Meters = 8 . 3/4 = 6
1/3 . y = 5/12
y = 5/12 . 3 = 5/4
Meters = 8 . 5/4 = 10
The equivalent ratios are 8 : 1/3, 4 : 2/3, 6 : 1/4, 10 : 5/12

Question 17.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 16

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 17

Explanation:
To find the missing values,
1/2 . x = 1
x = 2
1/24 . 2 = 1/12 = Feet
1/24 . y = 1/8
y = 1/8 . 24 = 3
Inches = 1/2 . 3 = 3/2
1/2 . z = 1/4
z = 1/4 . 2 = 1/2
Feet = 1/24 . 1/2 = 1/48
The equivalent ratios are 1/24 : 1/2, 1/12 : 1, 1/8 : 3, 1/48 : 1/4

Question 18.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 17

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 18

Explanation:
To find missing values,
1.5 . x = 1
x = 1/1.5 = 2/3
Tea = 3.75 . 2/3 = 2.5
1.5 . y = 3.5
y = 35/15 = 7/3
Tea = 3.75 . 7/3 = 8.75
1.5 . z = 2.5
z = 5/3
3.75 . 5/3 = 6.25

Question 19.
CRITICAL THINKING
Are the two statements equivalent? Explain your reasoning.
The ratio of boys to girls is 2 to 3.
The ratio of girls to boys is 3 to 2.

Answer:
Yes, both the statements are equivalent.

Explanation:
The ratio of boys to girls is 2 to 3.
boys : girls = 2 : 3
The ratio of girls to boys is 3 to 2.
girls : boys = 3 : 2

Question 20.
MODELING REAL LIFE
A city dumps plastic shade balls into a reservoir to prevent water from evaporating during a drought. It costs $5760 for 16,000 shade balls. How much does it cost for 12,000 shade balls?
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 18

Answer:
The cost for 12,000 shade balls is $4320

Explanation:
It costs $5760 for 16,000 shade balls.
The cost for 12,000 shade balls = (5760 x 12,000)/16000
= 69120/16
= 4320
So, the The cost for 12,000 shade balls is $4320

Question 21.
MODELING REAL LIFE
An oil spill spreads 25 square meters every \(\frac{1}{6}\) hour. What is the area of the oil spill after 2 hours?

Answer:
The area that the oil spill covers after 2 hours is 300 sq meters.

Explanation:
An oil spill spreads 25 square meters every 1/6 hour
The unit rate = 25 ÷ 1/6
= 25 x 6 = 150 square meters per hour
Every 1 hour spreads 150 square meters
The area that the oil spill covers after 2 hours = 2 x 150 = 300 sq meters

Question 22.
MODELING REAL LIFE
You mix 0.25 cup of juice concentrate for every 2 cups of water to make 18 cups of juice. How much juice concentrate do you use? How much water do you use?
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 19

Answer:
To make 18 cups of juice we use 16 cups of water and 2 cups of juice concentrate

Explanation:
The ratio between cups of water and cups of juice concentration is 2 to 1/4
The unit rate = 2 / 1/4
= 2 x 4 = 8 cups of water per cup of juice concentrate
So, to make 9 cups of juice we use 8 cups of water and 1 cup of juice concentrate
To make 18 cups of juice we use 16 cups of water and 2 cups of juice concentrate

Question 23.
A store sells 2\(\frac{1}{4}\) pounds of mulch for every 1\(\frac{1}{2}\) pounds of gravel sold. The store sells 180 pounds of mulch and gravel combined. How many pounds of each item does the store sell?

Answer:
Mulch = 108 pounds, gravel = 72 pounds

Explanation:
Let 2(1/4)x = 9/4 x be the amount of mulch so that 1(1/2)x = 3x/2 is the amount of gravel the store sell, both in pounds.
Given that thestore sells a total of 180 pounds of mulch and gravel, we can write
9x/4 + 3x/2 = 180
9x + 6x = 180 x 4
15x = 720
x = 720/15
x = 48
So, the store sells 9/4(48) = 108 pounds of mulch and 3/2(48) = 72 pounds of gravel.

Question 24.
DIG DEEPER!
You mix \(\frac{1}{4}\) cup of red paint for every \(\frac{1}{2}\) cup of blue paint to make 3 gallons of purple paint.
a. How much red paint do you use? How much blue paint do you use?
b. You decide that you want to make a lighter purple paint. You make the new mixture by adding \(\frac{1}{4}\) cup of white paint for every \(\frac{1}{4}\) cup of red paint and \(\frac{1}{2}\) cup of blue paint. How much red paint, blue paint, and white paint do you use to make 1\(\frac{1}{2}\) gallons of the lighter purple paint?

Answer:
a. We use 12 cups of red paint, 24 cups of blue paint
b. white paint = 6 cups, red paint = 6 cups, blue paint = 12 cups.

Explanation:
You mix \(\frac{1}{4}\) cup of red paint for every \(\frac{1}{2}\) cup of blue paint to make 3 gallons of purple paint.
a. The ratio of red paint to blue paint = 1/4 : 1/2
1/4x + 1/2x = (x + 2x)/4 = 3x/4
3x/4 = 3
x = 3 . 4/3
x = 4 cups
1 cup = 1/16 gallons
So, 4 cups = 4/16 = 1/4 gallons
12 . 4 = 48 cups = 1/4 . 12 = 3 gallons
So, 1/4(48) = 12 cups of red paint and 1/2(48) = 24 cups of blue paint is required to make 3 gallons
b. You make the new mixture by adding \(\frac{1}{4}\) cup of white paint for every \(\frac{1}{4}\) cup of red paint and \(\frac{1}{2}\) cup of blue paint.
(1/4 + 1/4 +1/2) = 1
1 cup = 1/16 gallons
The total lighter purple paint = 1(1/2) = 3/2 gallons
Total number of cups = (3/2) 16
= 24
white paint = 1/4 (24) = 6 cups
red paint = 1/4 (24) = 6 cups
blue paint = 1/2 (24) = 12 cups

Lesson 5.2 Rates and Unit Rates

EXPLORATION 1

Writing Rates
Work with a partner.
a. How many degrees does the minute hand on a clock move every 15 minutes? Write a rate that compares the number of degrees moved by the minute hand to the number of hours elapsed.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.2 1
b. Can you use the rate in part(a) to determine how many degrees the minute hand moves in \(\frac{1}{2}\) hour? Explain your reasoning.
c. Write a rate that represents the number of degrees moved by the minute hand every hour. How can you use this rate to find the number of degrees moved by the minute hand in 2\(\frac{1}{2}\) hours?
d. Draw a clock with hour and minute hands. Draw another clock that shows the time after the minute hand moves 900°. How many degrees does the hour hand move in this time? in one hour? Explain your reasoning.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.2 2

Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.2 3

Try It

Question 1.
There is \(\frac{1}{4}\) gram of fat for every \(\frac{1}{3}\) tablespoon of powdered peanut butter. How many grams of fat are there for every tablespoon of the powder?

Answer:
We have 3/4 grams of fat for every tablespoon of the powder.

Explanation:
There is \(\frac{1}{4}\) gram of fat for every \(\frac{1}{3}\) tablespoon of powdered peanut butter.
There are 1/4 / 1/3 = 1/4. 3 = 3/4 grams of fat for every tablespoon of the powder.

Question 2.
WHAT IF?
The scientist later states that the iron travels 3 feet every 10 minutes. Does this change your answer in Example 2? Explain.

Answer:
The liquid iron travels about 432 feet in 1 day.

Explanation:
The iron travels 3 feet for every 10 minutes
The ratio of feet to minutes is 3 : 10
Divide the quantity by 10 to get the unit rate per minute. Then multiply each quantity by 1440 to find the distance traveled in 24 hours.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 19
So, the liquid iron travels about 432 feet in 1 day.

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 3.
VOCABULARY
How can you tell when a rate is a unit rate?

Answer:
A unit rate is described as hoe many units of the first type of quantity corresponds to one unit of the second type of quantity. When the denominator is 1, then you can say that that rate is a unit rate. Few examples of unit rate are m/sec, feet/hour.

Question 4.
WRITING
Explain why rates are usually written as unit rates.

Answer:
Generally, a rate is a ratio of two quantities. Rates are usually written as unit rates because they are easier to read, easier to understand and easier to compare.

Find the unit rate.
Question 5.
$1.32 for 12 ounces

Answer:
$0.11 for 1 ounce

Explanation:
$1.32 for 12 ounces = 1.32 : 12
= 1.32/12 : 12/12
= 0.11 : 1

Question 6.
\(\frac{1}{4}\) gallon for every \(\frac{3}{10}\) mile

Answer:
5/6 gallon for every 1 mile

Explanation:
\(\frac{1}{4}\) gallon for every \(\frac{3}{10}\) mile = 1/4 : 3/10
= 1/4 x 10/3 : 3/10 x 10/3
= 5/6 : 1

Question 7.
USING TOOLS
Find the missing values in the ratio table. Then write the unit rate of grams per cup and the unit rate of cups per gram.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.2 4

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.2 1
The unit rate of grams per cup = 15/4 : 1
The unit rate of cups per gram = 1 : 4/15

Explanation:
2/3 . x = 1/6
x = 1/6 . 3/2 = 1/4
1/4 . 5/2 = 5/8 = grams
5/2 . y = 1
y = 1 . 2/5 = 2/5
2/3 . 2/5 = 4/15 = cups
5/2 . 3/2 = 15/4
So, 2/3 . 3/2 = 1 = cups
2/3 . z = 4
z = 4 . 3/2 = 6
So, 5/2 . 6 = 15
grams: cups = 5/2 : 2/3
The unit rate of grams per cup = 5/2 . 3/2 : 1 = 15/4 : 1
cups : grams = 4/15 : 1

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 8.
Two people compete in a five-mile go-kart race. Person A travels \(\frac{1}{10}\) mile every 15 seconds. Person B travels \(\frac{3}{8}\) mile every 48 seconds. Who wins the race? What is the difference of the finish times of the competitors?
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.2 5

Answer:
Person B wins the race.
The difference of the finish times of the competitors = 1.833 minutes

Explanation:
Two people compete in a five-mile go-kart race.
Person A travels 1/10 miles for 15 seconds = 1/10 : 15
Person A unit rate = 1/150 : 1
It means, A travels 1/150 miles per1 second
So, person A completes the race in 5 x 150 = 750 seconds = 750/60 = 12.5 minutes
Person B travels 3/8 mile for 48 seconds = 3/8 : 48
Person B unit rate = 3/384 : 1
It means B travels 3/384 miles in 1 second.
So, person B completes the race in 5 . (384/3) = 1920/3 = 640
= 640/60 = 10.666 minutes
Hence, person B wins the race.
The difference of the finish times of the competitors = 12.5 – 10.66 = 1.8333 minutes

Question 9.
DIG DEEPER!
A bus travels 0.8 mile east every 45 seconds. A second bus travels 0.55 mile west every 30 seconds. The buses start at the same location. Use two methods to determine how far apart the buses are after 15 minutes. Explain your reasoning.

Answer:
Two buses are 1/2 mile apart after 15 minutes.

Explanation:
A bus travels 0.8 mile east every 45 seconds = 0.8 : 45
The unit rate = 0.8/45 : 1
A second bus travels 0.55 mile west every 30 seconds = 0.55 : 30
The unit rate = 0.55/30 : 1
Find how much distance, busses travelled after 15 minutes = 15 x 60 = 900 seconds
First bus travels (0.8/45) x 900 = 16 miles
Second bus travels (0.55/30) x 900 = 16.5 miles
The difference in their distances = 16.5 – 16 = 1/2 mile

Rates and Unit Rates Homework & Practice 5.2

Review & Refresh

Find the missing values in the ratio table. Then write the equivalent ratios.
Question 1.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.2 6

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.2 2
The equivalent ratios are 3/4 : 1/3, 3/2 : 2/3, 3 : 3/4, 1 : 4/9

Explanation:
To find the missing values,
1/3 . x = 2/3
x = 2
3/4 . 2 = 3/2 = flour
3/4 . y = 3
y = 4
1/3 . 4 = 4/3 = oats1
3/4 . z = 1
z = 4/3
4/3 . 1/3 = 4/9 = oats2
The equivalent ratios are 3/4 : 1/3, 3/2 : 2/3, 3 : 3/4, 1 : 4/9

Question 2.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.2 7

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.2 3
The equivalent ratios are 1/4 : 1/2, 3/4 : 3/2, 3/2 : 3, 5 : 10

Explanation:
To find the missing values,
1/4 . x = 3/4
x = 3
1/2 . 3 = 3/2 = minutes1
1/2 . y = 3
y = 6
1/4 . 6 = 3/2 = pages
1/4 . z = 5
z = 20
1/2 . 20 = 10 = minutes 2
The equivalent ratios are 1/4 : 1/2, 3/4 : 3/2, 3/2 : 3, 5 : 10

Copy and complete the statement using <, >, or =.
Question 3.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.2 8

Answer:
9/2 > 8/3

Explanation:
9/2 = 4.5
8/3 = 2.6666
So, 9/2 > 8/3

Question 4.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.2 9

Answer:
-8/15 < 10/18

Explanation:
-8/15 = -0.5333
10/18 = 0.555
So, -8/15 < 10/18

Question 5.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.2 10

Answer:
-6/24 = -2/8

Explanation:
-6/24 = -0.25
-2/8 = -0.25
So, -6/24 = -2/8

Concepts, Skills, & Problem Solving

WRITING RATES Find the number of degrees moved by the minute hand of a clock in the given amount of time. Explain your reasoning. (See Exploration 1, p. 189.)
Question 6.
\(\frac{2}{3}\) hour

Answer:
240 degrees.

Explanation:
The minute hand passes through 60 minutes ( = 360 degrees) in 1 hour.
In 2/3 hours it passes through 2/3 * 360 = 240 degrees.

Question 7.
\(\frac{7}{12}\) hour

Answer:
210 degrees

Explanation:
The minute hand passes through 60 minutes ( = 360 degrees) in 1 hour.
In 7/12 hours it passes through 7/12 * 360 = 210 degrees

Question 8.
1\(\frac{1}{4}\) hours

Answer:
450 degrees = (360 + 90) degrees

Explanation:
The minute hand passes through 60 minutes ( = 360 degrees) in 1 hour.
In 1(1/4) = 5/4 hours it passes through 5/4 * 360 = 450 degrees

FINDING UNIT RATES Find the unit rate.
Question 9.
180 miles in 3 hours

Answer:
6 miles per 1 hour

Explanation:
180 miles in 3 hours = 18 : 3
The unit rate is 18/3 : 1 = 6 : 1

Question 10.
256 miles per 8 gallons

Answer:
32 miles per 1 gallon

Explanation:
256 miles per 8 gallons = 256 : 8
The unit rate is 256/8 : 1 = 32 : 1

Question 11.
\(\frac{1}{2}\) pound : 5 days

Answer:
1/10 pounds for 1 day

Explanation:
\(\frac{1}{2}\) pound : 5 days = 1/2 : 5
The unit rate is 1/2/5 : 1
= 1/10 : 1

Question 12.
4 grams for every \(\frac{3}{4}\) serving

Answer:
16/3 grams per serving

Explanation:
4 grams for every \(\frac{3}{4}\) serving = 4 : 3/4
The unit rate is = 4 x (4/3) : 1
= 16/3 : 1

Question 13.
$9.60 for 4 pounds

Answer:
$2.4 per 1 pound

Explanation:
$9.60 for 4 pounds = 9.60 : 4
The unit rate is 9.60/4 : 1
= 2.4 : 1

Question 14.
$4.80 for 6 cans

Answer:
$0.8 per 1 can

Explanation:
$4.80 for 6 cans = 4.80 : 6
The unit rate is 4.80/6 : 1
= 0.8 : 1

Question 15.
297 words in 5.5 minutes

Answer:
54 words in 1 minute

Explanation:
297 words in 5.5 minutes = 297 : 5.5
The unit rate is 297/5.5 : 1
= 54 : 1

Question 16.
\(\frac{1}{3}\) kilogram: \(\frac{2}{3}\) foot

Answer:
1/2 kilogram per 1 foot

Explanation:
\(\frac{1}{3}\) kilogram: \(\frac{2}{3}\) foot = 1/3 : 2/3
The unit rate is 1/3 x (3/2) : 1
= 1/2 : 1

Question 17.
\(\frac{5}{8}\) ounce per \(\frac{1}{4}\) pint

Answer:
5/2 ounce per 1 pint

Explanation:
\(\frac{5}{8}\) ounce per \(\frac{1}{4}\) pint = 5/8 : 1/4
The unit rate is 5/8 x 4 : 1
= 5/2 : 1

Question 18.
21\(\frac{3}{4}\) meters in 2\(\frac{1}{2}\) hours

Answer:
87 meters in 1 hour

Explanation:
21\(\frac{3}{4}\) meters in 2\(\frac{1}{2}\) hours = 21(3/4) : 2(1/2)
= 87/4 : 5/2
The unit rate is 87/4 x (2/5) : 1
= 87/10 : 1

USING TOOLS Find the missing values in the ratio table. Then write the equivalent ratios.
Question 19.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.2 11

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.2 5
The equivalent ratios are 25 : 1/3, 50 : 2/3, 75 : 1, 100 : 4/3

Explanation:
To find the missing values,
25 . x = 50
x = 50/25 = 2
1/3 . 2 = 2/3 = servings
1/3 . y = 1
y = 3
25 . 3 = 75 = calories1
1/3 . z = 4/3
z = 4
25 . 4 = 100 = calories2
The equivalent ratios are 25 : 1/3, 50 : 2/3, 75 : 1, 100 : 4/3

Question 20.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.2 12

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.2 4
The equivalent ratios are 4 : 3/4, 4/3 : 1/4, 16/3 : 1, 16 : 3

Explanation:
To find the missing values,
4x = 4/3
x = 1/3
3/4 . 1/3 = 1/4 = time1
3/4 y = 1
y = 4/3
4 . 4/3 = 16/3 = oxygen
4z = 16
z = 16/4 = 4
3/4 . 4 = 3 = time2
The equivalent ratios are 4 : 3/4, 4/3 : 1/4, 16/3 : 1, 16 : 3

Question 21.
PROBLEM SOLVING
In January 2012, the U.S.population was about 313 million people. In January 2017, it was about 324 million. What was the average rate of population change per year?

Answer:
The average rate of population change per year = 2.2 million

Explanation:
In January 2012, the U.S.population was about 313 million people
In January 2017, it was about 324 million
After 5 years, the population change = 324 – 313 = 11 million
The average rate of population change per year = 11/5 = 2.2 million

Question 22.
MODELING REAL LIFE
You can sand \(\frac{4}{9}\) square yard of wood in \(\frac{1}{2}\) hour. How many square yards can you sand in 3.2 hours? Justify your answer.

Answer:
128/45 square yards can you sand in 3.2 hours.

Explanation:
You can sand \(\frac{4}{9}\) square yard of wood in \(\frac{1}{2}\) hour
In 3.2 hours, you can sand 4/9 x 3.2 x 2 sq yads
= 25.6/9 = 128/45
So, 128/45 square yards can you sand in 3.2 hours.

Question 23.
REASONING
Tell whether the rates are equivalent. Justify your answer.
Question 23.
75 pounds per 1.5 years
38.4 ounces per 0.75 year

Answer:
Rates are not equivalent.

Explanation:
75 pounds per 1.5 years = 75 : 1.5
= 750/15 = 50
38.4 ounces per 0.75 year = 38.4 : 0.75
= 384 : 7.5 = 51.2
So, rates are not equivalent

Question 24.
7\(\frac{1}{2}\) miles for every \(\frac{3}{4}\) hour
\(\frac{1}{2}\) mile for every 3 minutes

Answer:
Rates are not equivalent.

Explanation:
7\(\frac{1}{2}\) miles for every \(\frac{3}{4}\) hour = 7(1/2) : 3/4
= 15/2 : 3/4
= 15/2 . 4/3 = 10
\(\frac{1}{2}\) mile for every 3 minutes = 1/2 : 3
= 1 : 6
So, rates are not equivalent

Question 25.
PROBLEM SOLVING
The table shows nutritional information for three beverages.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.2 13
a. Which has the most calories per fluid ounce?
b. Which has the least sodium per fluid ounce?

Answer:
a. whole milk has the most calories per fluid ounce
b. Oange juice has the least sodium per fluid ounce.

Explanation:
a.
Convert serving size to fluid ounce
Whole Milk = 1 c = 8 fl oz
Orange juice = 1 pt = 16 fl oz
Whole milk = 146 : 8 = 146/8 : 1
= 18.25
There are 18.25 calories in 1 fluid ounce of Whole Milk.
Orange juice = 210 : 16 = 210/16 : 1
= 13.125
There are 13.125 calories in 1 fluid ounce of Orange Juice.
Apple juice = 351 : 24
= 351/24 : 1
There are 14.625 calories in 1 fluid ounce of Apple Juice.
So, whole milk has the most calories per fluid ounce
b. Whole milk = 98 : 8
= 98/8 : 1
= 12.25
Orange juice = 10 : 16
= 10/16 : 1
= 0.625
Apple juice = 21 : 24
= 21/24 : 1
= 0.875
So, orange juice has the least sodium per fluid ounce.

Question 26.
MODELING REAL LIFE
A shuttle leaving Earth’s atmosphere travels 15 miles every 2 seconds. When entering the Earth’s atmosphere, the shuttle travels 2\(\frac{3}{8}\) miles per \(\frac{1}{2}\) second. Find the difference in the distances traveled after 15 seconds when leaving and entering the atmosphere.

Answer:
The difference in the distances traveled is 2503 miles.

Explanation:
A shuttle leaving Earth’s atmosphere travels 15 miles every 2 seconds. = 15 : 2
= 15/2 : 1
= 7.5 miles for every second
When entering the Earth’s atmosphere, the shuttle travels 2\(\frac{3}{8}\) miles per \(\frac{1}{2}\) second = 2(3/8) : /2
= 19/8 : 1/2
= 19/8 . 2 = 19/4
= 4.75 miles per second
After 15 minutes = 15 x 60 = 900 seconds,
A shuttle leaving Earth’s atmosphere travels = 7.5 x 900
= 6750 miles
When entering the Earth’s atmosphere, the shuttle travels = 4.75 x 900
= 4247 miles
The difference in the distances traveled = 6750 – 4247
= 2503 miles

Question 27.
RESEARCH
Fire hydrants are one of four different colors to indicate the rate at which water comes from the hydrant.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.2 14
a. Use the Internet to find the ranges of rates indicated by each color.
b. Research why a fire fighter needs to know the rate at which water comes out of a hydrant.

Answer:
a. Blue – 1500 or more gallons per minute
Green – 1000 to 1499 gallons per minute
Red – Less than 500 gallons per minute
Orange – 500 to 999 gallons per minute
b. Fire hydrants are flow-tested at a residual pressure of 20 psi. Therefore, firefighters should understand the typical flow rates of fire hydrants at a pressure. They should not expect that the fire hydrant will be supplied at an increased pressure, resulting in a greater flow rate.

Explanation:
a. Blue – 1500 or more gallons per minute
Green – 1000 to 1499 gallons per minute
Red – Less than 500 gallons per minute
Orange – 500 to 999 gallons per minute

Question 28.
DIG DEEPER!
You and a friend start riding bikes toward each other from opposite ends of a 24-mile biking route. You ride 2\(\frac{1}{6}\) miles every \(\frac{1}{4}\) hour. Your friend rides 7\(\frac{1}{3}\) miles per hour.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.2 15
a. After how many hours do you meet?
b. When you meet, who has traveled farther? How much farther?

Answer:
a. They meet after 1(1/2) hour.
b. You have traveled farther 2 miles.

Explanation:
You ride 2\(\frac{1}{6}\) miles every \(\frac{1}{4}\) hour.
= 2(1/6) : 1/4
= 13/6 : 1/4
= 13/6 . 4 = (13 . 2)/3 = 26/3 : 1
Your friend rides 7\(\frac{1}{3}\) miles per hour.
= 7(1/3) : 1
= 22/3 : 1
After 1 hour, you traveled = 26/3 miles, your friend traveled 22/3 miles
= 26/3 + 22/3 = 48/3
= 16 miles
Since you and your friend moving towards each other at 16 miles per hour
we can write 24/16 = 3/2 = 1.5 hours.
So, they meet after 1(1/2) hour.
b. You have traveled 26/3 (1.5) = 13 miles at the time of the meeting
Your friend has traveled 22/3 (1.5) = 11 miles at the time of the meeting.
You have traveled farther 2 miles.

Lesson 5.3 Identifying Proportional Relationships

EXPLORATION 1

Determining Proportional Relationships
Work with a partner.
a. You can paint 50 square feet of a surface every 40 minutes. How long does it take you to paint the mural shown? Explain how you found your answer.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 1
b. The number of square feet you paint is proportional to the number of minutes it takes you. What do you think it means for a quantity to be proportional to another quantity?
c. Assume your friends paint at the same rate as you. The table shows how long it takes you and different numbers of friends to paint a fence. Is x proportional to y in the table? Explain.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 2
d. How long will it take you and four friends to paint the fence? Explain how you found your answer.

Answer:
a. It takes 3 hours to paint the mural.
b. It means if the number of squares feet increases or decreases then the number of minutes to paint also increases or decreases respectively.
c. x is not proportional to y.

Explanation:
a. The area of mural = 25 x 9 = 225 sq ft
You can paint 50 square feet of a surface every 40 minutes
To paint the given mural it takes (40 x 225)/50 = 180 minutes = 3 hours
b. The number of square feet you paint is proportional to the number of minutes it takes you.
It means if the number of squares feet increases or decreases then the number of minutes to paint also increases or decreases respectively.
c. x : y = 1 : 4, 2 : 2 = 1 : 1
3 : 4/3 = 9 : 4, 4 : 1
All those are not equa so, x is not proportional to y.

Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 3

Try It

Tell whether the ratios form a proportion.
Question 1.
1 : 2 and 5 : 10

Answer:
1 : 2 and 5 : 10 form a proportion.

Explanation:
Compare the values of the ratios
1/2
5/10 = (5 ÷ 5) / (10 ÷ 5) = 1/2
The values of the ratios are equivalent
So, 1 : 2 and 5 : 10 form a proportion.

Question 2.
4 : 6 and 18 : 24

Answer:
4 : 6 and 18 : 24 do not form a proportion.

Explanation:
Compare the values of the ratios
4/6 = (4 ÷ 2)/(6 ÷ 2) = 2/3
18/24 = (18 ÷ 6)/(24 ÷ 6) = 3/4
The values of the ratios are not equivalent
So, 4 : 6 and 18 : 24 do not form a proportion.

Question 3.
4.5 to 3 and 6 to 9

Answer:
4.5 to 3 and 6 to 9 do not form a proportion.

Explanation:
Compare the values of the ratios
4.5/3 = 45/30
= (45 ÷ 15) / (30 ÷ 15) =3/2
6/9 = (6 ÷ 3) / (9 ÷ 3)
= 2/3
The values of the ratios are not equivalent
So, 4.5 to 3 and 6 to 9 do not form a proportion.

Question 4.
\(\frac{1}{2}\) to \(\frac{1}{4}\) and 8 to 4

Answer:
\(\frac{1}{2}\) to \(\frac{1}{4}\) and 8 to 4 form a proportion

Explanation:
Compare the values of the ratios
1/2 : 1/4 = (1/2) / (1/4)
= 1/2 . 4 = 2 : 1
8 : 4 = (8 ÷ 4) / (4 ÷ 4) = 2 : 1
The values of the ratios are equivalent
So, \(\frac{1}{2}\) to \(\frac{1}{4}\) and 8 to 4 form a proportion

Tell whether the ratios form a proportion.
Question 5.
6 : 2 and 12 : 1

Answer:
6 : 2 and 12 : 1 do not form a proportion.

Explanation:
Compare the values of the ratios
6 : 2 = (6 ÷ 2) : (2 ÷ 2) = 3 : 1
12 : 1 = (12 ÷ 1) : (1 ÷ 1) = 12 : 1
The values of the ratios are not equivalent
So, 6 : 2 and 12 : 1 do not form a proportion.

Question 6.
8 : 12 and \(\frac{2}{3}\) : 1

Answer:
8 : 12 and \(\frac{2}{3}\) : 1 form a proportion

Explanation:
Use the cross product property to determine whether the ratios form a proportion.
8/12 = 2/3 : 1
8/12 = 2/3
8 . 3 = 12 . 2
24 = 24
The cross productsare equal.
So, 8 : 12 and \(\frac{2}{3}\) : 1 form a proportion

Tell whether x and y are proportional.
Question 7.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 4

Answer:
x and y are proportional.

Explanation:
Compare the values of ratios x to y
1/2, 2/4 = 1/2, 3/6 = 1/2, 4/8 = 1/2
The values of the ratios are equivalent.
So, x and y are proportional.

Question 8.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 5

Answer:
x and y are not proportional.

Explanation:
Compare the values of ratios x to y
2/4 = 1/2, 4/2 = 2, 6/1 = 6, 8/1/2 = 16, 10/1/4 = 40
The values of the ratios are not equivalent.
So, x and y are not proportional.

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

PROPORTIONS Tell whether the ratios form a proportion.
Question 9.
4 : 14 and 12 : 40

Answer:
4 : 14 and 12 : 40 do not form a proportion.

Explanation:
Use the cross product property to determine whether the ratios form a proportion.
4/14 = 12/40
Cross multiply
4 . 40 = 12 . 14
160 ≠ 168
The cross products are not equal
So, 4 : 14 and 12 : 40 do not form a proportion

Question 10.
9 : 3 and 45 : 15

Answer:
9 : 3 and 45 : 15 form a proportion.

Explanation:
Compare the values of the ratios
9/3 = (9 ÷ 3) / (3 ÷ 3) = 3/1
45/15 = (45 ÷ 15) / (15 ÷ 15) = 3/1
The ratios are equivalent
So, 9 : 3 and 45 : 15 form a proportion

Question 11.
VOCABULARY
Explain how to determine whether two quantities are proportional.

Answer:
The two quantities are proportional means they are having equivalent ratios.

Question 12.
WHICH ONE DOESN’T BELONG?
Which ratio does not belong with the other three? Explain your reasoning.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 6

Answer:
3/5 does not belong with the other three.

Explanation:
4/10 = 2/5
2/5
3/5
6/15 = 2/5
So, 3/5 does not belong with the other three.

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 13.
After making 20 servings of pasta, a chef has used 30 cloves of garlic. The chef used 6 cloves to make the first 4 servings. How many cloves of garlic are used to make 10 servings? Justify your answer.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 7

Answer:
15 cloves of garlic are used to make 10 servings?

Explanation:
After making 20 servings of pasta, a chef has used 30 cloves of garlic.
The ratio of garlic cloves to serving of pasta = 30 : 20
= 30/20 : 1
= 3/2 : 1
The chef used 6 cloves to make the first 4 servings
The ratio of garlic cloves to serving of pasta = 6 : 4
= 6/4 : 1
= 3/2 : 1
It means 1.5 garlic cloves are used to make 1 serving.
The ratios are proportional
So, to make 10 servings, multiply 1.5 by 10
= 1.5 x 10 = 15 cloves
Therefore, 15 cloves of garlic are used to make 10 servings.

Question 14.
DIG DEEPER!
A runner completes a 25-mile race in 5 hours. The runner completes the first 7.5 miles in 1.5 hours.
a. Do these rates form a proportion? Justify your answer.
b. Can you determine, with certainty, the time it took the runner to complete 10 miles? Explain your reasoning.

Answer:
a. Yes, these form a proportion
b. It takes 2 hours for the runner to complete 10 miles.

Explanation:
a. A runner completes a 25-mile race in 5 hours.
The ratio of miles to hours = 25 : 5
= 25/5 : 1
= 5 : 1
The runner completes the first 7.5 miles in 1.5 hours.
The ratio of miles to hours = 7.5/1.5
= 75/15 : 1
= 5 : 1
It means the runner completes 5 miles in 1 hour
The ratios are proportional
b. So, it takes 10/5 = 2 hours for the runner to complete 10 miles.

Identifying Proportional Relationships Homework & Practice 5.3

Review & Refresh

Find the unit rate.
Question 1.
30 inches per 5 years

Answer:
6 inches per 1 year

Explanation:
30 inches per 5 years = 30 : 5
= 30/5 : 1
= 6 : 1
6 inches per 1 year

Question 2.
486 games every 3 seasons

Answer:
162 games every season

Explanation:
486 games every 3 seasons = 486 : 3
= 486/3 : 1
= 162 : 1
162 games every season

Question 3.
8750 steps every 1.25 hours

Answer:
7000 steps every hour

Explanation:
8750 steps every 1.25 hours = 8750 : 1.25
= 8750/1.25 : 1
= 7000 : 1
7000 steps every hour

Question 4.
3.75 pints out of every 5 gallons

Answer:
0.75 prints out of every gallon

Explanation:
3.75 pints out of every 5 gallons = 3.75 : 5
= 3.75/5 : 1
= 3/4 : 1
0.75 prints out of every gallon

Add or subtract.
Question 5.
– 28 + 15

Answer:
– 28 + 15 = -13

Explanation:
– 28 + 15 = -13

Question 6.
– 6 + (- 11)

Answer:
– 6 + (- 11) = -17

Explanation:
– 6 + (- 11) = -6 – 11
= -17

Question 7.
– 10 – 8

Answer:
– 10 – 8 = -18

Explanation:
– 10 – 8 = -18

Question 8.
– 17 – (- 14)

Answer:
– 17 – (- 14) = -3

Explanation:
– 17 – (- 14) = -17 + 14
= -3

Solve the equation.
Question 9.
\(\frac{x}{6}\) = 25

Answer:
x = 150

Explanation:
\(\frac{x}{6}\) = 25
Multiply both sides by 6
x/6 • 6 = 25 • 6
x = 150

Question 10.
8x = 72

Answer:
x = 9

Explanation:
8x = 72
Divide both sides by 8
8x/8 = 72/8
x = 9

Question 11.
150 = 2x

Answer:
x = 75

Explanation:
150 = 2x
Divide both sides by 2
150/2 = 2x/2
75 = x

Question 12.
35 = \(\frac{x}{4}\)

Answer:
x = 140

Explanation:
35 = \(\frac{x}{4}\)
Multiply both sides by 4
35 • 4 = x/4 • 4
140 = x

Concepts, Skills, & Problem Solving

REASONING You can paint 75 square feet of a surface every 45 minutes. Determine how long it takes you to paint a wall with the given dimensions. (See Exploration 1, p. 195.)
Question 13.
8 ft × 5 ft

Answer:
24 minutes

Explanation:
You can paint 75 square feet of a surface every 45 minutes
= 75 : 45
= 75/45 : 1
= 5/3 : 1
So, you can paint 5/3 sq feet of a surface in 1 minute.
The given area is 8 ft × 5 ft = 40 sq ft
Divide 40 by 5/3
= 40 / 5/3
= 40 . 3/5
= 24 minutes

Question 14.
7 ft × 6 ft

Answer:
25 minutes 12 seconds

Explanation:
The given area is 7 ft × 6 ft = 42 sq ft
Divide 42 by 5/3
= 42/5/3
= 42 . 3/5
= 126/5
= 25(1/5)
= 25 minutes 12 seconds

Question 15.
9 ft × 9 ft

Answer:
48 minutes 36 seconds

Explanation:
The given area is 9 ft × 9 ft = 81 sq ft
Divide 81 by 5/3
= 81/5/3
= 81 . 3/5
= 243/5
= 48(3/5)
= 48 minutes 36 seconds

PROPORTIONS Tell whether the ratios form a proportion.
Question 16.
1 to 3 and 7 to 21

Answer:
1 to 3 and 7 to 21 form a proportion.

Explanation:
Compare the values of the ratios
1 to 3 = 1 : 3
7 to 21 = 7 : 21
= (7 ÷ 7) : (21 ÷ 7)
= 1 : 3
The ratios are equivalent
So, 1 to 3 and 7 to 21 form a proportion.

Question 17.
1 : 5 and 6 : 30

Answer:
1 : 5 and 6 : 30 form a proportion

Explanation:
Compare the values of the ratios
1 : 5 = 1/5
6 : 30 = (6 ÷ 6) : (30 ÷ 6)
= 1/5
The ratios are equivalent
So, 1 : 5 and 6 : 30 form a proportion

Question 18.
3 to 4 and 24 to 18

Answer:
3 to 4 and 24 to 18 do not form a proportion

Explanation:
Compare the values of the ratios
3 to 24 = 3 : 24
= (3 ÷ 3) : (24 ÷ 3)
= 1 : 8
24 to 18 = 24 : 18
= (24 ÷ 6) : (18 ÷ 6)
= 4 : 3
The ratios are not equivalent
So, 3 to 4 and 24 to 18 do not form a proportion

Question 19.
3.5 : 2 and 14 : 8

Answer:
3.5 : 2 and 14 : 8 do not form a proportion

Explanation:
Compare the values of the ratios
35 : 2 = 35/2
14 : 8 = (14 ÷ 2) : (8 ÷ 2)
= 7 : 4 = 7/4
The ratios are not equivalent
So, 3.5 : 2 and 14 : 8 do not form a proportion

Question 20.
24: 30 and 3 : \(\frac{7}{2}\)

Answer:
24: 30 and 3 : \(\frac{7}{2}\) do not form a proportion.

Explanation:
Compare the values of the ratios
24 : 30 = 24/30
= (24 ÷ 2)/(30 ÷ 2)
= 12/15
3 : 7/2 = 6 : 7
= 6/7
The ratios are not equivalent
So, 24: 30 and 3 : \(\frac{7}{2}\) do not form a proportion.

Question 21.
\(\frac{21}{2}\) : 3 and 16 : 6

Answer:
\(\frac{21}{2}\) : 3 and 16 : 6 do not form a proportion.

Explanation:

21/2 : 3 = 21 : 6
= (21 ÷ 3) : (6 ÷ 3)
= 7 : 2
16 : 6 = (16 ÷ 2) : (6 ÷ 2)
= 8 : 3
The ratios are not equivalent
So, \(\frac{21}{2}\) : 3 and 16 : 6 do not form a proportion.

Question 22.
0.6 : 0.5 and 12 : 10

Answer:
0.6 : 0.5 and 12 : 10 form a proportion

Explanation:
Compare the values of the ratios
0.6 : 0.5 = 6/5
12 : 10 = (12 ÷ 2) : (10 ÷ 2)
= 6 : 5
The ratios are equivalent
So, 0.6 : 0.5 and 12 : 10 form a proportion

Question 23.
2 to 4 and 11 to \(\frac{11}{2}\)

Answer:
2 to 4 and 11 to \(\frac{11}{2}\) do not form a proportion.

Explanation:
Compare the values of the ratios
2 to 4 = 2 : 4
= (2 ÷ 2) : (4 ÷ 2)
= 1 : 2
11 to \(\frac{11}{2}\) = 11 : 11/2
= 22 : 11
= (22 ÷ 11) : (11 ÷ 11)
= 2 : 1
The ratios are not equivalent
So, 2 to 4 and 11 to \(\frac{11}{2}\) do not form a proportion.

Question 24
\(\frac{5}{8}\) : \(\frac{2}{3}\) and \(\frac{1}{4}\) : \(\frac{1}{3}\)

Answer:
\(\frac{5}{8}\) : \(\frac{2}{3}\) and \(\frac{1}{4}\) : \(\frac{1}{3}\) do not form a proportion.

Explanation:
Compare the values of the ratios
\(\frac{5}{8}\) : \(\frac{2}{3}\) = 5/8 / 2/3
= 5/8 . 3/2
= 15/16
\(\frac{1}{4}\) : \(\frac{1}{3}\) = 1/4 / 1/3
= 1/4 . 3 = 3/4
The ratios are not equivalent
So, \(\frac{5}{8}\) : \(\frac{2}{3}\) and \(\frac{1}{4}\) : \(\frac{1}{3}\) do not form proportion

IDENTIFYING PROPORTIONAL RELATIONSHIPS Tell whether x and y are proportional.
Question 25.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 8

Answer:
x and y are not proportional.

Explanation:
Compare the values of the ratios x to y.
1/7, 2/8 = 1/4, 3/9 = 1/3
The values of the ratios are not equivalent.
So, x and y are not proportional.

Question 26.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 9

Answer:
x and y are proportional.

Explanation:
Compare the values of the ratios x to y.
2/5, 4/10 = 2/5, 6/15 = 2/5
The values of the ratios are equivalent
So, x and y are proportional.

Question 27.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 10

Answer:
x and y are proportional.

Explanation:
Compare the values of the ratios x to y.
0.25/4 = 1/16, 0.5/8 = 1/6, 0.75/12 = 1/16
The values of the ratios are equivalent
So, x and y are proportional.

Question 28.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 11

Answer:
x and y are not proportional.

Explanation:
Compare the values of the ratios x to y.
2/3 / 7/10 = 2/3 . 10/7 = 20/21, 1/3/5 = 1/3 . 5 = 5/3
4/3 / 1/2 = 4/3 . 2 = 8/3
The values of the ratios are not equivalent
So, x and y are not proportional.

YOU BE THE TEACHER Your friend determines whether x and y are proportional. Is your friend correct? Explain your reasoning.
Question 29.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 12

Answer:
Correct.

Explanation:
Compare the values of the ratios x to y.
8 + 1 = 9
3 + 1 = 4
The values of the ratios x to y are equal.
So, x and y are proportional.

Question 30.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 13

Answer:
Wrong

Explanation:
Compare the values of the ratios x to y.
2/6 = 1/3
4/12 = 1/3
8/18 = 4/9
The values of the ratios x to y are not equal.
So, x and y are not proportional.

PROPORTIONS Tell whether the rates form a proportion.
Question 31.
7 inches in 9 hours;
42 inches in 54 hours

Answer:
Ratios form a proportion.

Explanation:
7 inches in 9 hours = 7 : 9
42 inches in 54 hours = 42 : 54
= (42 ÷ 6) : (54 ÷ 6)
= 7 : 9
The ratios are equivalent
So, ratios form a proportion.

Question 32.
12 players from 21 teams;
15 players from 24 teams

Answer:
The ratios do not form a proportion.

Explanation:
12 players from 21 teams; = 12 : 21
= (12 ÷ 3) : (21 ÷ 3)
= 4 : 7
15 players from 24 teams = 15 : 24
= (15 ÷ 3) : (24 ÷ 3)
= 5 : 8
The ratios are not equivalent
So, ratios do not form a proportion.

Question 33.
385 calories in 3.5 servings; 300 calories in 3 servings

Answer:
385 calories in 3.5 servings; 300 calories in 3 servings do not form a proportion.

Explanation:
385 calories in 3.5 servings = 385 : 3.5
= 110
300 calories in 3 servings = 300 : 3
= 100
The ratios are not equivalent
So, 385 calories in 3.5 servings; 300 calories in 3 servings do not form a proportion.

Question 34.
4.8 laps every 8 minutes; 3.6 laps every 6 minutes

Answer:
4.8 laps every 8 minutes; 3.6 laps every 6 minutes form a proportion.

Explanation:
4.8 laps every 8 minutes = 4.8 : 8
= (4.8 ÷ 8) : (8 ÷ 8)
= 3/5 : 1
3.6 laps every 6 minutes = 3.6 : 6
= (3.6 ÷ 6) : (6 ÷ 6)
= 3/5 : 1
The ratios are equivalent
So, 4.8 laps every 8 minutes; 3.6 laps every 6 minutes form a proportion.

Question 35.
\(\frac{3}{4}\) pound for every 5 gallons; \(\frac{4}{5}\) pound for every 5\(\frac{1}{3}\) gallons

Answer:
\(\frac{3}{4}\) pound for every 5 gallons; \(\frac{4}{5}\) pound for every 5\(\frac{1}{3}\) gallons do not form a proportion.

Explanation:
\(\frac{3}{4}\) pound for every 5 gallons = 3/4 : 5
= 3 : 20
\(\frac{4}{5}\) pound for every 5\(\frac{1}{3}\) gallons = 4/5 : 5(1/3)
= 4/5 : 16/3
= 4/5 . 3/16
= 15/16
The ratios are not equivalent
So, \(\frac{3}{4}\) pound for every 5 gallons; \(\frac{4}{5}\) pound for every 5\(\frac{1}{3}\) gallons do not form a proportion.

Question 36.
MODELING REAL LIFE
You do 90 sit-ups in 2 minutes. Your friend does 126 sit-ups in 2.8 minutes. Do these rates form a proportion? Explain.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 14

Answer:
The rates form a proportion

Explanation:
You do 90 sit-ups in 2 minutes = 90/2
= 45 sit-ups in 1 minute
Your friend does 126 sit-ups in 2.8 minutes = 126/2.8
= 45 sit-ups in 1 minute
They are equivalent.
So, the rates form a proportion

Question 37.
MODELING REAL LIFE
Find the heart rates of you and your friend. Do these rates form a proportion? Explain.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 15

Answer:
The rates do not form a proportion

Explanation:
Your heart rate = 22/20
= 11/10
Your friend heat rate = 18/15 = 6/5
The ratios are not equivalent
So, the rates do not form a proportion

Question 38.
PROBLEM SOLVING
You earn $56 walking your neighbor’s dog for 8 hours. Your friend earns $36 painting your neighbor’s fence for 4 hours. Are the pay rates equivalent? Explain.

Answer:
The pay rates are not equivalent.

Explanation:
You earn $56 walking your neighbor’s dog for 8 hours.
= 56 : 8
= 7
Your friend earns $36 painting your neighbor’s fence for 4 hours
= 36 : 4
= 9
So, the pay rates are not equivalent.

Question 39.
GEOMETRY
Are the heights and bases of the two triangles proportional? Explain.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 16

Answer:
The heights and bases of the two triangles proportional

Explanation:
Height to base of first triangle = 12 : 15
= (12 ÷ 3) : (15 ÷ 3)
= 4 : 5
Height to base of second triangle = 8 : 10
= (8 ÷ 2) : (10 ÷ 5)
= 4 : 5
The ratios are equivalent
So, the heights and bases of the two triangles proportional

Question 40.
REASONING
A pitcher coming back from an injury limits the number of pitches thrown in bullpen sessions as shown.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 17
a. Which quantities are proportional?
b. How many pitches that are not curveballs will the pitcher likely throw in Session 5?

Answer:
a. None of the quantities are proportional.
b. Curveballs are 20, pitches are 50.

Explanation:
a. By observing the table we can say that,
None of the quantities are proportional.
b. In session 5, the pitches are 5 . 10 = 50
curveballs are 5 . 4 = 20

Question 41.
STRUCTURE
You add the same numbers of pennies and dimes to the coins shown. Is the new ratio of pennies to dimes proportional to the original ratio of pennies to dimes? If so, illustrate your answer with an example. If not, show why with a counterexample.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 18

Answer:
The new ratio of pennies to dimes is not proportional to the original ratio of pennies to dimes.

Explanation:
Number of pennies to dimes in image a = 3 : 2
Number of pennies to dimes in image b = 4 : 4
= 1 : 1
The ratios are not equivalent
So, the new ratio of pennies to dimes is not proportional to the original ratio of pennies to dimes.

Question 42.
REASONING
You are 13 years old, and your cousin is 19 years old. As you grow older, is your age proportional to your cousin’s age? Explain your reasoning.

Answer:
Your age is not proportional to your cousin’s age

Explanation:
You are 13 years old, and your cousin is 19 years old.
= 13 : 19
As you grow older
Suppose after 3 years the ratio is (13 + 3) / (19 + 3) = 16/21
13/19≠ 16/21
So, your age is not proportional to your cousin’s age

Question 43.
MODELING REAL LIFE
The shadow of the moon during a solar eclipse travels 2300 miles in 1 hour. In the first 20 minutes, the shadow traveled 766\(\frac{2}{3}\) miles. How long does it take for the shadow to travel 1150 miles? Justify your answer.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 19

Answer:
It takes 30 minutes for the shadow to travel 1150 miles

Explanation:
The shadow of the moon during a solar eclipse travels 2300 miles in 1 hour
= 2300 : 1
In the first 20 minutes, the shadow traveled 766\(\frac{2}{3}\) miles.
= 766(2/3) : 20
= 2300/3 : 20
So, it travels 2300/3 miles in 20 minutes
The time taken for the shadow to travel 1150 miles is 1150 . 20 x (3/2300)
= 69000/2300
= 30
Therefore, The time taken for the shadow to travel 1150 miles is 30 minutes

Question 44.
MODELING REAL LIFE
In 60 seconds, a car in a parade travels 0.2 mile. The car traveled the last 0.05 mile in 12 seconds. How long did it take for the car to travel 0.1 mile? Justify your answer.

Answer:
It takes 32 seconds for the car to travel 0.1 mile.

Explanation:
In 60 seconds, a car in a parade travels 0.2 mile.
Car travels to time = 0.2 : 60
The car traveled the last 0.05 mile in 12 seconds
= 0.05 : 12
So, the car travels (0.2 – 0.05 = 0.15 miles) in (60 – 12 = 48 seconds)
The time taken to travel 0.1 mile = (48 x 0.1)/0.15 = 32 seconds.

Question 45.
OPEN-ENDED
Describe (a) a real-life situation where you expect two quantities to be proportional and (b) a real-life situation where you do not expect two quantities to be proportional. Explain your reasoning.

Answer:
(a) We will the real-life situation as the relationship between the number of gallons of fuel that we put in the tank and the amount of money we have to pay.
(b) The real-life situation is 2 persons buy different items at a store and pay amount.

Explanation:
(a) Let us take two people to put fuel their cars. Person 1 puts 5 gallons of fuel and pays 20 dollars.
Person 2 puts 8 gallons of fuel pays 32 dollars.
The ratio to the number of gallons to dollars is 5 : 20, 8 : 32
= 1 : 4, 1 : 4
So, the ratios are proportional.
(b) Let us assume 2 persons buy different products at the store and pays the bill.
Person 1 buys 2 items per 15 dollars and person 2 buys 4 items for 32 dollars.

Question 46.
PROBLEM SOLVING
A specific shade of red nail polish requires 7 parts red to 2 parts yellow. A mixture contains 35 quarts of red and 8 quarts of yellow. Is the mixture the correct shade? If so, justify your answer. If not, explain how you can fix the mixture to make the correct shade of red.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 20

Answer:
To fix the mixture add 2 more quarts of yellow.

Explanation:
The ratio of nail polish = 7/2 = (7 . 5) / (2 . 5) = 35/10 red/yellow
The ratio of mixture = 35/8 red/yellow
To fix the mixture make the two ratios 35/10 and 35/8 equivalent
Add 2 more quarts of yellow to the mixture
35/10 = 35/(8 + 2)
To fix the mixture add 2 more quarts of yellow.

Question 47.
LOGIC
The quantities x and y are proportional. Use each of the integers 1–5 to complete the table. Justify your answer.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions 5.3 21

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.3 1

Explanation:
The quantities x and y are proportional.
Let us take x/2 = y
So, 10/2 = 5
6/2 = 3
0.5 x 2 = 1
4/2 = 2

Question 48.
CRITICAL THINKING
Ratio A and Ratio B form a proportion. Ratio B and Ratio C also form a proportion. Do Ratio A and Ratio C form a proportion? Justify your answer.

Answer:
Ratio A and Ratio C form a proportion.

Explanation:
Ratio A and Ratio B form a proportion
Ratio B and Ratio C also form a proportion
So, Ratio A : Ratio B = Ratio B : Ratio C
Ratio A = (Ratio B)/Ratio C x Ratio B
Ratio C = (Ratio B x Ratio B)/Ratio A
Ratio A : Ratio C = [(Ratio B)/Ratio C x Ratio B] : [(Ratio B x Ratio B)/Ratio A]
= 1/Ratio C : 1/Ratio A
= Ratio A : Ratio C
So, Ratio A and Ratio C form a proportion

Lesson 5.4 Writing and Solving Proportions

EXPLORATION 1

Solving a Ratio Problem
Work with a partner. A train travels 50 miles every 40 minutes. To determine the number of miles the train travels in 90 minutes, your friend creates the following table.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 1
a. Explain how you can find the value of x.
b. Can you use the information in the table to write a proportion? If so, explain how you can use the proportion to find the value of x. If not, explain why not.
c. How far does the train below travel in 2 hours?
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 2
d. Share your results in part(c) with other groups. Compare and contrast methods used to solve the problem.

Answer:
a. x = 112.5
b. yes
c. 120 miles

Explanation:
a. 50/40 = x/90
(50/40) . 90 = x
4500/40 = x
x = 112.5
b. We can use information in the table to write a proportion.
c. The train travels 30 miles in 1/2 hour.
The distance traveled in 2 hours is 30. 2 . 2 = 120 miles

Try It

Solve the proportion.
Question 1.
\(\frac{5}{8}=\frac{20}{d}\)

Answer:
d = 32

Explanation:
\(\frac{5}{8}=\frac{20}{d}\)
cross multiply the fractions
5d = 20 . 8
5d = 160
d = 160/5
d = 32

Question 2.
\(\frac{7}{z}=\frac{14}{10}\)

Answer:
z = 5

Explanation:
\(\frac{7}{z}=\frac{14}{10}\)
cross multiply the fractions
7 . 10 = 14 . z
70 = 14z
70/14 = z
5 = z

Question 3.
\(\frac{21}{24}=\frac{x}{8}\)

Answer:
x = 7

Explanation:
\(\frac{21}{24}=\frac{x}{8}\)
cross multiply the fractions
21 . 8 = 24x
168 = 24x
168/24 = x
x = 7

Solve the proportion.
Question 4.
\(\frac{w}{6}=\frac{6}{9}\)

Answer:
w = 4

Explanation:
\(\frac{w}{6}=\frac{6}{9}\)
cross multiply the fractions
9w = 6 . 6
9w = 36
w = 36/9
w = 4

Question 5.
\(\frac{12}{10}=\frac{a}{15}\)

Answer:
a = 18

Explanation:
\(\frac{12}{10}=\frac{a}{15}\)
cross multiply the fractions
12 . 15 = 10a
180 = 10a
a = 180/10
a = 18

Question 6.
\(\frac{y}{10}=\frac{3}{5}\)

Answer:
y = 6

Explanation:
\(\frac{y}{10}=\frac{3}{5}\)
cross multiply the fractions
5y = 3 . 10
5y = 30
y = 30/5
y = 6

Solve the proportion.
Question 7.
\(\frac{2}{7}=\frac{x}{28}\)

Answer:
x = 8

Explanation:
\(\frac{2}{7}=\frac{x}{28}\)
cross multiply the fractions
2 . 28 = 7x
56 = 7x
x = 56/7
x = 8

Question 8.
\(\frac{12}{5}=\frac{6}{y}\)

Answer:
y = 5/2

Explanation:
\(\frac{12}{5}=\frac{6}{y}\)
cross multiply the fractions
12y = 6 . 5
12y = 30
y = 30/12
y = 5/2

Question 9.
\(\frac{40}{z+1}=\frac{15}{6}\)

Answer:
z = 15

Explanation:
\(\frac{40}{z+1}=\frac{15}{6}\)
cross multiply the fractions
40 . 6 = 15(z + 1)
240 = 15z + 15
240 – 15 = 15z
225 = 15z
z = 225/15
z = 15

Find the value of x so that the ratios are equivalent.
Question 10.
2 : 4 and x : 6

Answer:
x = 3

Explanation:
2/4 = x/6
cross multiply the fractions
2 . 6 = 4x
12 = 4x
x = 12/4
x = 3

Question 11.
x : 5 and 8 : 2

Answer:
x = 20

Explanation:
x/5 = 8/2
x/5 = 4
x = 4 . 5
x = 20

Question 12.
4 to 3 and 10 to x

Answer:
x = 15/2

Explanation:
4/3 = 10/x
cross multiply the fractions
4x = 3 . 10
4x = 30
x = 30/4
x = 15/2

Question 13.
Write a proportion that can be used to find the number of tomatoes in the new recipe.

Answer:
The number of tomatoes in the new recipe are 4.

Explanation:
In the original recipe, the ratio of the black beans to the number of tomatoes is 1.5 : 1
For the new recipe to be proportional to the original recipe, these ratios must be equivalent.
So the vales of the ratios must be equal
1.5/1 = 6/x
1.5 = 6/x
1.5x = 6
x = 6/1.5
x = 4

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

SOLVING A PROPORTION Solve the proportion.
Question 14.
\(\frac{5}{12}=\frac{b}{36}\)

Answer:
b = 15

Explanation:
\(\frac{5}{12}=\frac{b}{36}\)
Cross multiply the fractions
(5 x 36) = 12b
180 = 12b
b = 180/12
b = 15

Question 15.
\(\frac{6}{p}=\frac{42}{35}\)

Answer:
p = 5

Explanation:
\(\frac{6}{p}=\frac{42}{35}\)
Cross multiply the fractions
6 x 35 = 42p
210 = 42p
p = 210/42
p = 5

Question 16.
WRITING AND SOLVING A PROPORTION
Find the value of x so that the ratios x : 9 and 5 : 6 are equivalent.

Answer:
x = 15/2

Explanation:
The ratios x : 9 and 5 : 6 are equivalent.
x/9 = 5/6
Cross multiply the fractionsx
6x = 9 . 5
6x = 45
x = 45/6
x = 15/2

Question 17.
DIFFERENT WORDS, SAME QUESTION
Which is different? Find “both” answers.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 3

Answer:
Solve 12/x = 3/8 is different, x = 32
For remaining x = 2

Explanation:
3/x = 12/8
3 • 8 = 12x
24 = 12x
x = 2
3 : x and 12 : 8 are equivalent
3/x = 12/8
So, x = 2
3 : 12 and x : 8 are equivalent
3/12 = x/8
3 • 8 = 12x
x = 2
12/x = 3/8
12 • 8 = 3x
3x= 96
x = 96/3 = 32

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 18.
You burn 35 calories every 3 minutes running on a treadmill. You want to run for at least 15 minutes, but no more than 30 minutes. What are the possible numbers of calories that you will burn? Justify your answer.

Answer:
The possible number of calories burned in between 560/3 and 350.

Explanation:
You burn 35 calories every 3 minutes running on a treadmill.
35 : 3
= 35/3 : 1
You want to run for at least 15 minutes, but no more than 30 minutes means you want to run in between 16 and 30 minutes
If you run for 16 minutes then, the number of calories burn = (35/3) x 16
= 560/3
If you run for 30 minutes, then the number of calories burn = (35/3) x 30
= 1050/3 = 350
So, the possible number of calories burned in between 560/3 and 350.

Question 19.
DIG DEEPER!
Two boats travel at the same speed to different destinations. Boat A reaches its destination in 12 minutes. Boat B reaches its destination in 18 minutes. Boat B travels 3 miles farther than Boat A. How fast do the boats travel? Justify your answer.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 4

Answer:
The boat travels with 1/2 mile/hr.

Explanation:
Boat A reaches its destination in 12 minutes
Boat B reaches its destination in 18 minutes
Let us take the speed as x miles/minute
So, Boat A travels 12x miles
Boat B travels 18x miles
Boat B travels 3 miles farther than Boat A
18x + 3 = 12x
18x – 12x = -3
6x = -3
x = 3/6
x = 1/2 mile/hr
So, the boat travels with 1/2 mile/hr

Writing and Solving Proportions Homework & Practice 5.4

Review & Refresh

Tell whether and are proportional.
Question 1.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 5

Answer:
x and y are not proportional.

Explanation:
Compare the values of the ratios x to y
4/6 = 2/3
6/8 = 3/4
8/10 = 4/5
The values of the ratios are not equivalent
So, x and y are not proportional.

Question 2.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 6

Answer:
x and y are proportional.

Explanation:
Compare the values of the ratios x to y
2/5/3 = 2/15
4/5/6 = 2/15
4/30 = 2/15
The values of the ratios are equivalent
So, x and y are proportional.

Plot the ordered pair in a coordinate plane.
Question 3.
A (- 5, – 2)

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 1

Explanation:
In point A (- 5, – 2)
The x coordinate and y coordinate values are negative.
so, the point lies in 3rd quadrant.
Take 5 units on the x-axis, 2 units on the y-axis, and locate the point.

Question 4.
B (- 3, 0)

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 2

Explanation:
In the point B (- 3, 0)
The x coordinate, y coordinates are negative and zero.
So, the point lies in the x-axis.

Question 5.
C (- 1, 2)

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 3

Explanation:
In point C (- 1, 2) has x coordinate negative value and y coordinate positive value.
so, the point lies in the 2nd quadrant.
Take -1 units on the x-axis, 2 units on the y-axis, and mark the point.

Question 6.
D (1, 4)

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 4

Explanation:
In point D (1, 4) the x, y coordinates are positive.
So, the point lies in quadrant 1.
Take 1 unit on the x-axis, 4 units on the y-axis, and mark the point.

Question 7.
Which expression is equivalent to (3w – 8) – 4(2w + 3)?
A. 11w + 4
B. – 5w – 5
C. – 5w + 4
D. – 5w – 20

Answer:
D. – 5w – 20

Explanation:
(3w – 8) – 4(2w + 3) = 3w – 8 – 8w – 12
= -5w -20

Concepts, Skills, & Problem Solving

SOLVING A RATIO PROBLEM Determine how far the vehicle travels in 3 hours. (See Exploration 1, p. 203.)
Question 8.
A helicopter travels 240 miles every 2 hours.

Answer:
The helicopter travels 360 miles in 3 hours.

Explanation:
A helicopter travels 240 miles every 2 hours = 240 : 2
= 240/2 : 1
= 120 : 1
The helicopter travels 120 miles in 1 hour
The distance traveled by the vehicle in 3 hours = 120 * 3
= 360 miles

Question 9.
A motorcycle travels 25 miles every 0.5 hour.

Answer:
A motorcycle travels 150 miles in 3 hours.

Explanation:
A motorcycle travels 25 miles every 0.5 hour = 25 : 0.5
= 25/0.5 : 1
= 50 : 1
The motorcycle travels 50 miles in 1 hour
So, the distance traveled by the vehicle in 3 hours = 50 * 3 = 150 miles

Question 10.
A train travels 10 miles every \(\frac{1}{4}\) hour.

Answer:
A train travels 120 miles in 3 hours.

Explanation:
A train travels 10 miles every \(\frac{1}{4}\) hour = 10 : 1/4
= 4 * 10 : 1
= 40 : 1
A train travels 40 miles in 1 hour
So, the distance traveled by the vehicle in 3 hours = 40 * 3 = 120 miles

Question 11.
A ferry travels 45 miles every 1\(\frac{1}{2}\) hours.

Answer:
A ferry travels 90 miles in 3 hours

Explanation:
A ferry travels 45 miles every 1\(\frac{1}{2}\) hours = 45 : 1(1/2)
= 45 : 3/2
= 45 * 2 : 3
= 90 : 3
= 30 : 1
A ferry travels 30 miles in 1 hour
So, the distance traveled by the vehicle in 3 hours = 30 * 3 = 90

SOLVING A PROPORTION Solve the proportion. Explain your choice of method.
Question 12.
\(\frac{1}{4}=\frac{z}{20}\)

Answer:
z = 5

Explanation:
\(\frac{1}{4}=\frac{z}{20}\)
Cross multiply the fractions
20 = 4z
z = 20/4
z = 5

Question 13.
\(\frac{3}{4}=\frac{12}{y}\)

Answer:
y = 16

Explanation:
\(\frac{3}{4}=\frac{12}{y}\)
The product of 3 and waht number is 12?
Because the product pf 3 and 4 is 12, multiply the denominator by 4 to find y
4 * 4 = 16
So, y = 16

Question 14.
\(\frac{35}{k}=\frac{7}{3}\)

Answer:
k = 15

Explanation:
\(\frac{35}{k}=\frac{7}{3}\)
Divide both sides by 35
(35/k)/35 = (7/3)/35
1/k = 1/15
k = 15

Question 15.
\(\frac{b}{36}=\frac{5}{9}\)

Answer:
b = 20

Explanation:
\(\frac{b}{36}=\frac{5}{9}\)
Cross multiply the proportions
9b = 5 * 36
9b = 180
b = 180/9
b = 20

Question 16.
\(\frac{x}{8}=\frac{3}{12}\)

Answer:
x = 2

Explanation:
\(\frac{x}{8}=\frac{3}{12}\)
Cross multiply the fractions
12x = 3 * 8
12x = 24
x = 24/12
x = 2

Question 17.
\(\frac{3}{4}=\frac{v}{14}\)

Answer:
v = 21/2

Explanation:
\(\frac{3}{4}=\frac{v}{14}\)
Cross multiply the fractions
3 * 14 = 4v
42 = 4v
v = 42/4
v = 21/2

Question 18.
\(\frac{15}{8}=\frac{45}{c}\)

Answer:
c = 24

Explanation:
\(\frac{15}{8}=\frac{45}{c}\)
Cross multiply the fractions
15c = 45 * 8
15c = 360
c = 360/15
c = 24

Question 19.
\(\frac{35}{28}=\frac{n}{12}\)

Answer:
n = 15

Explanation:
\(\frac{35}{28}=\frac{n}{12}\)
Cross multiply the fractions
35 * 12 = 28n
420 = 28n
n = 420/28
n = 15

Question 20.
\(\frac{a}{6}=\frac{15}{2}\)

Answer:
a = 45

Explanation:
\(\frac{a}{6}=\frac{15}{2}\)
Cross multiply the fractions
2a = 15 * 6
2a = 90
a = 90/2
a = 45

Question 21.
\(\frac{y}{9}=\frac{44}{54}\)

Answer:
y = 22/3

Explanation:
\(\frac{y}{9}=\frac{44}{54}\)
Cross multiply the fractions
54y = 44 * 9
54y = 396
y = 396/54
y = 22/3

Question 22.
\(\frac{4}{24}=\frac{c}{36}\)

Answer:
c = 6

Explanation:
\(\frac{4}{24}=\frac{c}{36}\)
Cross multiply the fractions
4 * 36 = 24c
144 = 24c
c = 144/24
c = 6

Question 23.
\(\frac{20}{16}=\frac{d}{12}\)

Answer:
d = 15

Explanation:
\(\frac{20}{16}=\frac{d}{12}\)
Cross multiply the fractions
20 * 12 = 16d
240 = 16d
d = 240/16
d = 15

Question 24.
\(\frac{10}{7}=\frac{8}{k}\)

Answer:
k = 5.6

Explanation:
Cross multiply the fractions
10k = 8 * 7
10k = 56
k = 56/10
k = 5.6

Question 25.
\(\frac{5}{n}=\frac{16}{32}\)

Answer:
n = 10

Explanation:
\(\frac{5}{n}=\frac{16}{32}\)
Cross multiply the fractions
5 * 32 = 16n
160 = 16n
n = 160/16
n = 10

Question 26.
\(\frac{9}{10}=\frac{d}{6.4}\)

Answer:
d = 5.76

Explanation:
\(\frac{9}{10}=\frac{d}{6.4}\)
Cross multiply the fractions
10d = 6.4 * 9
10d = 57.6
d = 57.6/10
d = 5.76

Question 27.
\(\frac{2.4}{1.8}=\frac{7.2}{k}\)

Answer:
k = 5.4

Explanation:
\(\frac{2.4}{1.8}=\frac{7.2}{k}\)
Cross multiply the fractions
2.4k = 7.2 * 1.8
2.4k = 12.96
k = 12.96/2.4
k = 5.4

Question 28.
YOU BE THE TEACHER
Your friend solves the proportion \(\frac{m}{8}=\frac{15}{24}\). Is your friend correct? Explain your reasoning.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 7

Answer:
Correct

Explanation:
m/8 = 15/24
Cross multiply the fractions
24m = 15 * 8
24m = 120
m = 120/24
m = 5

Question 29.
NUMBER SENSE
Without solving, determine whether \(\frac{x}{4}=\frac{15}{3}\) and \(\frac{x}{15}=\frac{4}{3}\) have the same solution. Explain your reasoning.

Answer:
Both have same solution.

Explanation:
\(\frac{x}{4}=\frac{15}{3}[/latex
Cross multiply the fractions
3x = 15 * 4
[latex]\frac{x}{15}=\frac{4}{3}\)
Cross multiply the fractions
3x = 4 * 15
We got same equation
So, both have same solution.

WRITING A PROPORTION Use the table to write a proportion.
Question 30.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 8

Answer:
6/7 = 18/w, w = 6

Explanation:
12/14 = 18/w
Cross multiply the fractions
12w = 18 * 4
w = 72/12
w = 6
12/14 = 18/w
6/7 = 18/w

Question 31.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 9

Answer:
n/85 = 1/5, n = 17

Explanation:
n/85 = 34/170
n/85 = 1/5
Cross multiply the fractions
5n = 85
n = 85/5
n = 17

Question 32.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 10

Answer:
15/2.5 = m/4, m = 24

Explanation:
15/2.5 = m/4
Cross multiply the fractions
15 * 4 = 2.5m
60 = 2.5m
m = 60/2.5
m = 24

Question 33.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 11

Answer:
x = 11.2

Explanation:
100/x = 200/22.4
Cross multiply the fractions
100 * 22.4 = 200x
2240 = 200x
x = 2240/200
x = 11.2

WRITING AND SOLVING A PROPORTION Find the value of x so that the ratios are equivalent.
Question 34.
1 : 8 and 4 : x

Answer:
x = 32

Explanation:
1/8 = 4/x
Cross multiply the fractions
x = 8 * 4
x = 32

Question 35.
4 to 5 and x to 20

Answer:
x = 16

Explanation:
4/5 = x/20
Cross multiply the fractions
20 * 4 = 5x
80 = 5x
x = 80/5
x = 16

Question 36.
3 : x and 12 : 40

Answer:
x = 10

Explanation:
3/x = 12/40
Cross multiply the fractions
3 * 40 = 12x
120 = 12x
x = 120/12
x = 10

Question 37.
x to 0.25 and 6 to 1.5

Answer:
x = 1

Explanation:
x/0.25 = 6/1.5
Cross multiply the fractions
1.5x = 6 * 0.25
1.5x = 1.5
x = 1.5/1.5
x = 1

Question 38.
x : \(\frac{5}{2}\) and 8 : 10

Answer:
x = 2

Explanation:
x : 5/2 = 8 : 10
Cross multiply the fractions
10x = 8 * 5/2
10x = 20
x = 20/10
x = 2

Question 39.
\(\frac{7}{4}\) to 14 and x to 32

Answer:
x = 4

Explanation:
7/4 : 14 = x : 32
Cross multiply the fractions
14x = 32 * (7/4)
14x = 56
x = 56/14
x = 4

Question 40.
WRITING A PROPORTION
Your science teacher has a photograph of the space shuttle Atlantis. Every 1 centimeter in the photograph represents 200 centimeters on the actual shuttle. Which of the proportions can you use to find the actual length x of Atlantis? Explain.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 12

Answer:
1/200 = x/19.5

Explanation:
Every 1 centimeter in the photograph represents 200 centimeters on the actual shuttle
= 1 : 200
Length of atlantis on model = 19.5
The actual length on Atlantis = x
Scale 1:200
When length on model = 1
Actual length = 200
When actual length = x
Length on model = 19.5
Scale = x : 19.5
Equating both scales
1/200 = x/19.5

Question 41.
MODELING REAL LIFE
In an orchestra, the ratio of trombones to violas is 1 to 3. There are 9 violas. How many trombones are in the orchestra?

Answer:
There are 3 trombones in the orchestra.

Explanation:
t/9 = 1/3
3t = 9
t = 9/3
t = 3
There are 3 trombones in the orchestra.

Question 42.
MODELING REAL LIFE
A dance team has 80 dancers. The ratio of seventh-grade dancers to all dancers is 5:16. Find the number of seventh-grade dancers on the team.

Answer:
The number of seventh-grade dancers on the team is 25.

Explanation:
A dance team has 80 dancers
Let us take the seventh-grade dancers as x
The ratio of seventh-grade dancers to all dancers is 5:16
x : 80 = 5 : 16
x/80 = 5/16
Cross multiply the fractions
16x = 5 *80
16x = 400
x = 400/16
x = 25
The number of seventh-grade dancers on the team is 25.

Question 43.
MODELING REAL LIFE
There are 144 people in an audience. The ratio of adults to children is 5 to 3. How many are adults?

Answer:
The number of adults in the audience are 18.

Explanation:
The ratio of adults to children is 5 to 3
adults : children = 5 : 3
There are 144 people in an audience.
5x + 3x = 144
8x = 144
x = 144/8
x = 18
So, the number of adults in the audience are 18.

Question 44.
PROBLEM SOLVING
You have $50 to buy T-shirts. You can buy 3 T-shirts for $24. Do you have enough money to buy 7 T-shirts? Justify your answer.

Answer:
No.

Explanation:
You can buy 3 T-shirts for $24
= 24 : 3
= 24/3 : 1
= 8 : 1
So, you can buy 1 T-shirt per $8.
The money required to buy 7 T-shirts = 7 * 8 = $56
The remaining money after buying 3 T-shirts is 50 – 24 = $26
$26 is not enough to buy 7 T-shirts.

Question 45.
PROBLEM SOLVING
You buy 10 vegetarian pizzas and pay with $100. How much change do you receive?
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 13

Answer:
The change you receive = $15

Explanation:
3 vegetarian pizzas for $25.50 = 25.50 : 3
= 25.50/3 : 1
= 8.5 : 1
So, you have to pay $8.5 for 1 vegetarian pizza
If you buy 10 vegetarian pizzas, then amount is 10 * 8.5 = $85
The change you receive = 100 – 85 = 15

Question 46.
MODELING REAL LIFE
A person who weighs 120 pounds on Earth weighs 20 pounds on the Moon. How much does a 93-pound person weigh on the Moon?

Answer:
The weight of a 93-pound person weigh on the Moon is 15.5 pounds

Explanation:
The ratio of a person weight on earth to moon = 120 : 20
= 120/20 : 1
= 6 : 1
The weight of a 93-pound person weigh on the Moon is 93/6 = 31/2 = 15.5 pounds.

Question 47.
PROBLEM SOLVING
Three pounds of lawn seed covers 1800 square feet. How many bags are needed to cover 8400 square feet?
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 14

Answer:
The number of bags required to cover 8400 sq ft is 14.

Explanation:
Three pounds of lawn seed covers 1800 square feet.
The ratio of lawn to seed cover = 1800 : 3
= 1800/3 : 1
= 600 : 1
So, 1 seed bag covers 600 sq ft
The number of bags required to cover 8400 sq ft is 8400/600
= 14 bags

Question 48.
MODELING REAL LIFE
There are 180 white lockers in a school. There are 3 white lockers for every 5 blue lockers. How many lockers are in the school?

Answer:
There are 480 lockers in the school.

Explanation:
There are 3 white lockers for every 5 blue lockers
= 3 : 5
Let b be the number of blue lockers
3/5 = 180/b
3b = 180 * 5
3b = 900
b = 900/3
b = 300
300 + 180 = 400
So, there are 480 lockers in the school.

CONVERTING MEASURES Use a proportion to complete the statement. Round to the nearest hundredth if necessary.
Question 49.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 15

Answer:
3.73 miles

Explanation:
1 km = 0.621371
6 km = 6 * 0.621371
= 3.72823 miles
= 3.73 miles

Question 50.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 16

Answer:
0.66 gal

Explanation:
1 L = 0.264172 gal
2.5 L = 0.264172 * 2.5
= 0.66043
2.5 L = 0.66 gal

Question 51.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 17

Answer:
40.82 kg

Explanation:
1 lb = 0.453592 kgs
90 lb = 0.453592 * 90
= 40.8233
90 lb = 40.82 kg

SOLVING A PROPORTION Solve the proportion.
Question 52.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 18

Answer:
x = 3/2

Explanation:
2x/5 = 9/15
Cross-multiply the fractions
15 * 2x = 9 * 5
30x = 45
x = 45/30
x = 3/2

Question 53.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 19

Answer:
d = 12

Explanation:
5/2 = (d – 2)/4
Cross-multiply the fractions
20 = 2(d – 2)
20 = 2d – 4
20 + 4 = 2d
24 = 2d
d = 24/2
d = 12

Question 54.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 20

Answer:
k = 4

Explanation:
4/(k + 3) = 8/14
Cross-multiply the fractions
14 * 4 = 8(k + 3)
56 = 8k + 24
56 – 24 = 8k
32 = 8k
k = 32/8
k = 4

Question 55.
LOGIC
It takes 6 hours for 2 people to build a swing set. Can you use the proportion \(\frac{2}{6}=\frac{5}{h}\) to determine the number of hours h it will take 5 people h6to build the swing set? Explain.

Answer:
It will take 15 hours for 5 people to build the swing set.

Explanation:
It takes 6 hours for 2 people to build a swing set
2 people – 6 hours
5 people – ?
We have a proportion,
2/6 = 5/h
2h = 6 * 5
2h = 30
h = 30/2
h = 15
It will take 15 hours for 5 people to build the swing set.

Question 56.
STRUCTURE
The ratios a : b and c : d are equivalent. Which of the following equations are proportions? Explain your reasoning.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions 5.4 21

Answer:
a/d = c/b is not equivalent proportion.

Explanation:
a/b = c/d
ad = bc
b/a = d/c
bc = ad
a/c = b/d
ad = bc
a/d = c/b
ab = cd
c/a = d/b
bc = ad
So, a/d = c/b is not equivalent proportion.

Question 57.
CRITICAL THINKING
Consider the proportions \(\frac{m}{n}=\frac{1}{2}\) and \(\frac{n}{k}=\frac{2}{5}\). What is \(\frac{m}{k}\) ? Explain your reasoning.

Answer:
m/k = 1/5

Explanation:
m/n = 1/2
So m = x, n = 2x
n/k = 2/5
n = 2x, k = 5x
So, m/k = x/5x
= 1/5

Lesson 5.5 Graphs of Proportional Relationships

EXPLORATION 1

Representing Relationships Graphically

Work with a partner. The tables represent two different ways that red and blue food coloring are mixed.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 1
a. Represent each table in the same coordinate plane. Which graph represents a proportional relationship? How do you know?
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 2
b. Find the unit rate of the proportional relationship. How is the unit rate shown on the graph?
c. What is the multiplicative relationship between x and y for the proportional relationship? How can you use this value to write an equation that relates y and x?

Answer:
Mixture 1
a. Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 5
Mixture 2
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 6
b. If the line passes through the origin, then x and y are proportional.

Explanation:
a.The points in mixture 1 are A (1, 2), B (2, 4), C (3, 6), D (4, 8)
The points in mixture 2 are E (0, 2), F (2, 4), G (4, 6), H (6, 8)
b. If the line passes through the origin, then x and y are proportional.

Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 3

Try It

Tell whether x and y are proportional. Explain your reasoning.

Question 1.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 4

Answer:
The line does not pass through the origin. So, x and y are not proportional.

Explanation:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 7
The line does not pass through the origin. So, x and y are not proportional.

Question 2.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 5

Answer:
x and y are not proportional.

Explanation:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 8
The line pass through the origin. So, x and y are not proportional.

Question 3.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 6

Answer:
x and y are not proportional.

Explanation:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 9
The line pass through the origin. So, x and y are not proportional.

Question 4.
WHAT IF
Does your answer change when you use the point (\(\frac{1}{2}\), \(\frac{1}{4}\))to find the speed of the subway car? Explain your reasoning.

Answer:
No.

Explanation:
The point (1/2, 1/4) indicates that the subway car travels 1/4 mile every 1/2 minutes.
1/4 : 1/2
= 2/4 : 1
= 1/2 : 1
So, the unit rate is 1/2 mile per minute
The speed of the subway car is 1/2 mile per minute.

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 7
Question 5.
IDENTIFYING A PROPORTIONAL RELATIONSHIP Use the graph shown to tell whether x and y are proportional. Explain your reasoning.

Answer:
x and y are proportional.

Explanation:
x/y = 0/0
1.5/1 = 15/10 = 3/2
4.5/3 = 45/30 = 3/2
As the line pass through the origin, so, x and y are proportional.

Question 6.
FINDING A UNIT RATE
Interpret each plotted point in the graph. Then identify the unit rate, if possible.

Answer:
The unit rate is 1.5

Explanation:
time : distance = 1.5/1
= 15/10 = 3/2
The unit rate is 1.5

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 7.
The table shows the temperature (in degrees Fahrenheit), hours after midnight.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 8
a. Describe a proportional relationship between time and temperature shown by the table. Explain your reasoning.
b. Find the temperature 3.5 hours after midnight.

Answer:
b. 161 degrees Fahrenheit

Explanation:
a. The table shows the proportional relationship between hours and temperature.
0.5/44 = 1/88
1/46
1.5/48 = 1/32
The temperature after 3.5 hours, is 3.5 * 46 = 161 degrees Fahrenheit

Question 8.
DIG DEEPER!
Show how you can use a proportional relationship to plan the heights of the vertical supports of a waterskiing ramp. Then explain how increasing the steepness of the ramp affects the proportional relationship.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 9

Answer:
The vertical supports tell the height of the ramp. As the height of the ramp increases the distance from the ramp is increases.

Graphs of Proportional Relationships Homework & Practice 5.5

Review & Refresh

Find the value of x so that the ratios are equivalent.
Question 1.
2 : 7 and 8 : x

Answer:
x = 28

Explanation:
2/7 = 8/x
Cross multiply the fractions
2x = 8 * 7
2x = 56
x = 56/2
x = 28

Question 2.
3 to 2 and x to 18

Answer:
x = 27

Explanation:
3/2 = x/18
Cross multiply the fractions
3 * 18 = 2x
54 = 2x
x = 54/2
x = 27

Question 3.
9 : x and 54 : 8

Answer:
x = 4/3

Explanation:
9/x = 54/8
Cross multiply the fractions
54x = 9 * 8
54x = 72
x = 72/54
x = 4/3

Find the quotient, if possible.
Question 4.
36 ÷ 4

Answer:
36 ÷ 4 = 9

Explanation:
The quotient of two integers of the same sign is positive.
36 ÷ 4 = 9

Question 5.
42 ÷ (- 6)

Answer:
42 ÷ (- 6) = -7

Explanation:
The quotient of two integers of the different signs is negative.
42 ÷ (- 6) = -7

Question 6.
– 39 ÷ 3

Answer:
– 39 ÷ 3 = -13

Explanation:
The quotient of two integers of the different signs is negative.
– 39 ÷ 3 = -13

Question 7.
– 44 ÷ (- 4)

Answer:
– 44 ÷ (- 4) = 11

Explanation:
The quotient of two integers of the same sign is positive.
– 44 ÷ (- 4) = 11

Solve the inequality. Graph the solution.
Question 8.
– \(\frac{x}{3}\) < 2

Answer:
x > -6
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 10

Explanation:
– \(\frac{x}{3}\) < 2
Multiply each side by 3
-x/3 . 3 < 2 . 3
-x < 6
x > -6

Question 9.
\(\frac{1}{3}\)p ≥ 4

Answer:
p ≥ 12
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 11

Explanation:
\(\frac{1}{3}\)p ≥ 4
Multiply each side by 3
\(\frac{1}{3}\)3p ≥ 4 . 3
p ≥ 12

Question 10.
– 8 < \(\frac{2}{3}\)n

Answer:
-24 < n
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 12

Explanation:
– 8 < \(\frac{2}{3}\)n
Multiply each side by 3/2
-8 x (3/2) < 2n/3 x (3/2)
-24 < n

Question 11.
– 2w ≤ 10

Answer:
w ≥ 5
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 13

Explanation:
– 2w ≤ 10
Divide each side by 2
– 2w/2 ≤ 10/2
-w ≤ 5
w ≥ 5

Concepts, Skills, & Problem Solving

REPRESENTING RELATIONSHIPS GRAPHICALLY Represent the table graphically. Does the graph represent a proportional relationship? How do you know? (See Exploration 1, p. 211.)
Question 12.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 10

Answer:
x and y are not proportional.

Explanation:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 14
The line does not pass through the origin.
So, x and y are not proportional.

Question 13.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 11

Answer:
x and y are proportional.

Explanation:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 15
The line pass through the origin.
So, x and y are proportional.

IDENTIFYING A PROPORTIONAL RELATIONSHIP Tell whether x and y are proportional. Explain your reasoning.
Question 14.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 12

Answer:
x and y are proportional.

Explanation:
Compare the values of ratios x to y
x/y = 1/2
2/4 = 1/2
3/6 = 1/2
4/8 = 1/2
The ratios are equivalent.
So, x and y are proportional.

Question 15.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 13

Answer:
x and y are not proportional.

Explanation:
Compare the values of ratios x to y
x/y = -2/0 = 0
-1/2
0/4 = 0
1/6
The ratios are not equivalent
So, x and y are not proportional.

Question 16.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 14

Answer:
x and y are not proportional.

Explanation:
Compare the values of ratios x to y
x/y = -1/-2 = 1/2
0/-1 = 0
1/0 = 0
2/1
All the ratios are not equivalent
So, x and y are not proportional.

Question 17.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 15

Answer:
x and y are proportional.

Explanation:
Compare the values of ratios x to y
x/y = 3/2
6/4 = 3/2
9/6 = 3/2
12/8 = 3/2
All the ratios are equivalent
So, x and y are proportional.

Question 18.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 16

Answer:
x and y are not proportional.

Explanation:
Compare the values of ratios x to y
x/y = 1/3
2/4 = 1/2
3/5
4/6 = 2/3
All the ratios are not equivalent
So, x and y are not proportional.

Question 19.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 17

Answer:
x and y are proportional.

Explanation:
Compare the values of ratios x to y
x/y = 1/0.5 = 2
3/1.5 = 2
5/2.5 = 2
7/3.5 = 2
The ratios are equivalent
So, x and y are proportional.

Question 20.
YOU BE THE TEACHER
Your friend uses the graph to determine whether x and y are proportional. Is your friend correct? Explain your reasoning.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 18

Answer:
The line does not pass through the origin.
so, x and y are not proportional.

FINDING A UNIT RATE Interpret each plotted point in the graph. Then identify the unit rate.
Question 21.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 19

Answer:
Tnit rate is 1/15

Explanation:
The points are (1, 15), (4, 60)
x/y = 1/15
4/60 = (4 ÷ 4)/(60 ÷ 4)
= 1/15
So, unit rate is 1/15

Question 22.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 20

Answer:
The unit rate is 0.2 seconds per feet.

Explanation:
The points are (1, 5), (6, 30)
x/y = 1/5
6/30 = 1/5
The unit rate is 0.2 seconds per feet.

IDENTIFYING A PROPORTIONAL RELATIONSHIP Tell whether x and y are proportional. If so, identify the constant of proportionality. Explain your reasoning.
Question 23.
x – y = 0

Answer:
x and y are proportional.

Explanation:
x – y = 0
x = 0 + y
x = y
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 16
So, x and y are proportional.

Question 24.
\(\frac{x}{y}\) = 2

Answer:
x and y are proportional.

Explanation:
\(\frac{x}{y}\) = 2
x = 2y
If y = 0, then x = 2(0) = 0
If y = 1, then x = 2(1) = 2
If y = 2, then x = 2(2) = 4
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 17
So, x and y are proportional.

Question 25.
8 = xy

Answer:
x and y are proportional.

Explanation:
8 = xy
y = 8/x
If x = 0, then y = 8/0 = 0
If x = 1, then y = 8/1 = 8
If x = 2, then y = 8/2 = 4
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 18
So, x and y are proportional.

Question 26.
x2 = y

Answer:
x and y are proportional.

Explanation:
x2 = y
If x = 0, then y = 0
If x = 1, then y = 1
If x = 2, then y = 4
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 19
So, x and y are proportional.

WRITING AN EQUATION The variables and are proportional. Use the values to find the constant of proportionality. Then write an equation that relates x and y.
Question 27.
When y = 72, x = 3.

Answer:
y = 24x

Explanation:
y/x = 72/3
y/x = 24
y = 24x

Question 28.
When y = 20, x = 12.

Answer:
5x = 3y

Explanation:
y/x = 20/12
y/x = 5/3
Cross multiply the fractions
3y = 5x

Question 29.
When y = 45, x = 40.

Answer:
9x = 8y

Explanation:
y/x = 45/40
y/x = 9/8
Cross multiply the fractions
8y = 9x

Question 30.
MODELING REAL LIFE
The table shows the profit y for recycling x pounds of aluminum. Find the profit for recycling 75 pounds of aluminum.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 21

Answer:
The profit for recycling 75 pounds of aluminum is $33.75

Explanation:
The profit is $4.50 for recycling 10 pounds of aluminum
= 4.50 : 10
= 4.50/10 : 1
= 0.45 : 1
The profit is 40.45 for recycling 1 pound of aluminum.
The profit for recycling 75 pounds of aluminum is $135/4

Question 31.
MODELING REAL LIFE
The graph shows the cost of buying concert tickets. Tell whether x and y are proportional. If so, find and interpret the constant of proportionality. Then find the cost of 14 tickets.
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 22

Answer:
x and y are proportional.
The cost for buying 14 tickets is $182
13x = y

Explanation:
The line in the graph passes through the origin. so, x and y are proportional.
The cost for buying 2 tickets is 26
= 26 : 2
=13 : 1
The cost for buying 1 ticket is $13.
So, the cost for buying 14 tickets is 14 * 13 = $182
x/y = 2/26
x/y = 1/13
Cross multiply the fractions
13x = y

Question 32.
REASONING
The graph of a proportional relationship passes through (12, 16) and (1, y) Find y.

Answer:
y = 4/3

Explanation:
12/16 = 1/y
3/4 = 1/y
Cross multiply the fractions
3y = 4
y = 4/3

Question 33.
PROBLEM SOLVING
The amount of chlorine in a swimming pool is proportional to the volume of water. The pool has 2.5 milligrams of chlorine per liter of water. How much chlorine is in the pool?
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 23

Answer:
The amount of chlorine in the pool is 75708.225 milligrams.

Explanation:
The amount of chlorine in a swimming pool varies directly with the volume of water. The pool has 2.5 milligrams of chlorine per liter of water.
1 gallon = 3.78541 litre
8000 gallons = 8000 * 3.78541 = 30283.29 litres
The amount of chlorine in the pool = 30283.29 * 2.5
= 75708.225 milligrams.

Question 34.
DIG DEEPER!
A vehicle travels 250 feet every 3 seconds. Find the value of the ratio, the unit rate, and the constant of proportionality. How are they related?

Answer:
The ratio is 250 : 3
The unit rate is 250/3 : 1
3x = 250y

Explanation:
A vehicle travels 250 feet every 3 seconds
= 250 : 3
= 250/3 : 1
The unit rate is 250/3 : 1
x/y = 250/3
Cross multiply the proportions
3x = 250y

Lesson 5.6 Scale Drawings

EXPLORATION 1

Creating a Scale Drawing

Work with a partner. Several sections in a zoo are drawn on 1-centimeter grid paper as shown. Each centimeter in the drawing represents 4 meters.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.6 1
a. Describe the relationship between the lengths of the fences in the drawing and the actual side lengths of the fences.
b. Describe the relationship between the areas of the sections in the drawing and the actual areas of the sections.
c. Are the relationships in parts (a) and (b) the same? Explain your reasoning.
d. Choose a different distance to represent each centimeter on a piece of 1-centimeter grid paper. Then create a new drawing of the sections in the zoo using the distance you chose. Describe any similarities or differences in the drawings.

Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.6 2

Try It

Question 1.
What is the actual distance between Traverse City and Marquette?

Answer:
The distance between Traverse City and Marquette is 150 miles

Explanation:
Use the centimeter ruler to find the distance on the map between traverse city and Marquette.
the map distance is about 3 centimeters
Use the scale 1 cm : 50 mi and the ratio 3 cm : d mi to write and solve a proportion
1/50 = 3/d
d = 50 * 3
d = 150
So, the distance between Traverse City and Marquette is 150 miles

Question 2.
A drawing has a scale of 1 mm : 20 cm. What is the scale factor of the drawing?

Answer:
The scale factor is 1/200

Explanation:
Write the scale with the same units. Use the factor 1 cm = 10 mm
1 mm : 20 cm = 1 mm : (20 • 10) mm
= 1 : 200
So, the scale factor is 1/200

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 3.
VOCABULARY
In your own words, explain the meaning of the scale and scale factor of a drawing or model.

Answer:
A scale factor is a number that multiplies times a given quantity to produce a smaller or longer version of the original number. It is also defined as the ratio of a drawing or blueprint to the actual object or distance.
The measurements in scale drawings are proportional to the measurements of the actual object. The scale is the ratio that compares the measurements of the drawings with the actual measurements.

Question 4.
FINDING AN ACTUAL DISTANCE
Consider the scale drawing of Balanced Rock in Arches National Park. What is the actual height of the structure?
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.6 3

Answer:
h = 1/975.36

Explanation:
scale drawing is 1 cm : 32 ft
1 foot = 30.48 cm
So, 32 ft = 975.36 cm
1 cm : 32 ft = 1 : 975.36
h = 1/975.36

Question 5.
FINDING A SCALE FACTOR
A drawing has a scale of 3 in. : 2 ft. What is the scale factor of the drawing?

Answer:
The scale factor is 1/8

Explanation:
3 in. : 2 ft
1 foot = 12 inches
2 ft = 24 inches
The scale is 3 : 24 inches = 1/8

Question 6.
REASONING
Describe the scale factor of a model that is (a) larger than the actual object and (b) smaller than the actual object.

Answer:
If the scale of the factor is larger than the actual object, then every point is considered larger in the image. It means we represent a lion in a smaller box.
If the scale of the factor is less than the actual object, it means we represent the pen as a larger box.

Self-Assessment for Problem Solving
Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 7.
A scale drawing of the Parthenon is shown. Find the actual perimeter and area of the rectangular face of the Parthenon. Then recreate the scale drawing with a scale factor of 0.2. Find the perimeter and area of the rectangular face in your drawing.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.6 4

Answer:
The actual perimeter of the rectangular face of the Parthenon is 26 ft
The actual area of the rectangular face of the Parthenon is 36 sq ft
the perimeter of the rectangular face in your drawing is 5.2 ft
area of the rectangular face in your drawing is 1.44 sq ft.

Explanation:
Perimeter of the rectangular face of the Parthenon = 2(l + b)
= 2(4 + 9) = 13 * 2
= 26 ft
Area of the rectangular face of the Parthenon = l * b
= 4 * 9
= 36 sq ft
Scale factor = 0.2
The length of the rectangular face in your drawing = 0.2 * 9
= 1.8
The breadth of the rectangular face in your drawing = 4 * 0.2
= 0.8
Perimeter is 2(1.8 + 0.8) = 5.2
Area is 0.8 * 1.8 = 1.44

Question 8.
DIG DEEPER!
You are in charge of creating a billboard advertisement that is 16 feet long and 8 feet tall. Choose a product. Create a scale drawing of the billboard using words and a picture. What is the scale factor of your design?

Answer:
The scale factor is 2

Explanation:
The details of the billboard advertisement is 16 : 8
= 2 : 1
1 unit is 4 units on the scale
So, the billboard advertisement is 16 * 4 : 8 * 4
= 64 : 32
= 2 : 1
So, the scale factor is 2

Scale Drawings Homework & Practice 5.6

Review & Refresh

Tell whether x and y are proportional. Explain your reasoning.
Question 1.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.6 5

Answer:
x and y are not proportional

Explanation:
Compare the values of ratios x to y
10/5 = 2
9/4 = 2.25
8/3 = 2.6666
7/2 = 3.5
The ratios are not equivalent
So, x and y are not proportional

Question 2.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.6 6

Answer:
x and y are proportional

Explanation:
Compare the values of ratios x to y
6/7
12/14 = 6/7
18/21 = 6/7
24/28 = 6/7
The ratios are equivalent
So, x and y are proportional

Simplify the expression.
Question 3.
7p + 6p

Answer:
7p + 6p = 13p

Explanation:
The given expression is 7p + 6p
= 13p

Question 4.
8 + 3d – 17

Answer:
8 + 3d – 17 = 3d – 9

Explanation:
The given expression is 8 + 3d – 17
= 3d – 9

Question 5.
– 2 + \(\frac{2}{5}\)b – \(\frac{1}{4}\)b + 6

Answer:
– 2 + \(\frac{2}{5}\)b – \(\frac{1}{4}\)b + 6 = 4 + 3b/20

Explanation:
The given expression is – 2 + \(\frac{2}{5}\)b – \(\frac{1}{4}\)b + 6
= 4 + (8b – 5b)/20
= 4 + 3b/20

Write the word sentence as an inequality.
Question 6.
A number is less than – 3.

Answer:
n < -3

Explanation:
Let us the number as n
n < -3

Question 7.
7 plus a number z is more than 5.

Answer:
7 + z > 5, z > -2

Explanation:
more than means > symbol
7 + z > 5
z > 5 – 7
z > -2

Question 8.
The product of a number m and 6 is no less than 30.

Answer:
6m > 30

Explanation:
No less than means >
m . 6 > 30
6m > 30
Divide both sides by 6
6m/6 > 30/6
m > 30/6

Concepts, Skills, & Problem Solving

CREATING A SCALE DRAWING Each centimeter on the 1-centimeter grid paper represents 8 inches. Create a proportional drawing of the figure that is larger or smaller than the figure shown. (See Exploration 1, p. 217.)
Question 9.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.6 7

Answer:
The base of the traingle is 16 inches

Explanation:
1 cm = 8 inches
The base of triangle = 2 cm
= 2 * 8 = 16 inches
Actually, 1 cm = 0.393701 inches
The size of drawing/real size = 1/8
2/real size = 1/8
16 = real size

Question 10.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.6 8

Answer:
The bottom surface is 24 inches, the height is 24 inches, the top surface is 8 inches.

Explanation:
1 cm = 8 inches
Bottom surface is 3 cm
= 3 * 8 = 24 inches
Height is 3 cm
= 3 * 8 = 24 inches
Top surface = 1 cm
= 1 * 8 = 8 inches

FINDING AN ACTUAL DISTANCE Use the map in Example 1 to find the actual distance between the cities.
Question 11.
Kalamazoo and Ann Arbor

Answer:
The distance between Kalamazoo and Ann Arbor is 100 miles.

Explanation:
Use the centimeter ruler to find the distance on the map between Kalamazoo and Ann Arbor
The map distance is about 2 cm
Use the scale 1 cm : 50 mi and the ratio 2 cm : d mi to write and solve a proportion
1/50 = 2/d
d = 50 * 2
d = 100
So, the distance between Kalamazoo and Ann Arbor is 100 miles.

Question 12.
Lansing and Flint

Answer:
The distance between Lansing and Flint is 50 miles.

Explanation:
Use the centimeter ruler to find the distance on the map between Lansing and Flint
The map distance is about 1 cm
Use the scale 1 cm : 50 mi and the ratio 1 cm : d mi to write and solve a proportion
1/50 = 1/d
d = 50 * 1
d = 50
So, the distance between Lansing and Flint is 50 miles.

Question 13.
Grand Rapids and Escanaba

Answer:
The distance between Grand Rapids and Escanaba is 200 miles.

Explanation:
Use the centimeter ruler to find the distance on the map between Grand Rapids and Escanaba
The map distance is about 4 cm
Use the scale 1 cm : 50 mi and the ratio 4 cm : d mi to write and solve a proportion
1/50 = 1/d
d = 50 * 4
d = 200
So, the distance between Grand Rapids and Escanaba is 200 miles.

Question 14.
Saginaw and Alpena

Answer:
The distance between Saginaw and Alpena is 150 miles.

Explanation:
Use the centimeter ruler to find the distance on the map between Saginaw and Alpena
The map distance is about 3 cm
Use the scale 1 cm : 50 mi and the ratio 4 cm : d mi to write and solve a proportion
1/50 = 1/d
d = 50 * 3
d = 150
So, the distance between Saginaw and Alpena is 150 miles.

USING A SCALE Find the missing dimension. Use the scale 1 : 12.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.6 9

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.6 1

Explanation:
15. 1 inch = 12 inches
So, 6.25 x 12 = 75 inches
16. 1 ft = 12 inches
x in = 15 * 12
x in = 180 inches
17. 1 m = 100 cm
32 cm = 0.32 m
32 * 1 = .32 * 12
= 3.84 m
18. 1 ft = 0.333333 yard
5.4 ft = 5.4 * 0.333333
= 1.8 yard * 12 = 21.6 yard
19. 1 cm = 10 mm
21 cm = 210 mm
210 * 12 = 2520 mm

FINDING A SCALE FACTOR Use a centimeter ruler to find the scale and the scale factor of the drawing.
Question 20.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.6 10

Answer:
1 cm = 30 m

Explanation:
Using the centimeter ruler, the length is 4 cm
So, 4 cm = 120 m
1 cm = 120/4
1 cm = 30 m

Question 21.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.6 11

Answer:
1 cm = 8 mm

Explanation:
Using the centimeter ruler, the length is 3 cm
So, 3 cm = 24 mm
1 cm = 24/3
= 8 mm

Question 22.
CRITICAL THINKING
You know the length and the width of a scale model. What additional information do you need to know to find the scale of the model? Explain.

Answer:
You need to know the scale factor to know the scale of the model.

Question 23.
MODELING REAL LIFE
Central Park is a rectangular park in New YorkCity.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.6 12
a. Find the perimeter and the area of the scale drawing of Central Park.
b. Find the actual perimeter and area of Central Park.

Answer:
a. The perimeter of the scale drawing of Central Park = 26 cm
The area of the scale drawing of Central Park = 30 sq cm
b. The perimeter of the scale drawing of Central Park = 8320 cm
The area of the scale drawing of Central Park = 3072000 sq cm

Explanation:
a. The length of the central park is 10 cm
The breadth of the central park is 3 cm
The perimeter of the scale drawing of Central Park = 2(10 + 3)
= 2(13)
= 26 cm
The area of the scale drawing of Central Park = 10 * 3
= 30 sq cm
b. 1 cm = 320 m
The length of the central park is 10 * 320 = 3200
The breadth of the central park is 3 * 320 = 960
The perimeter of the scale drawing of Central Park = 2(3200 + 960)
= 8320 cm
The area of the scale drawing of Central Park = 3200 * 960
= 3072000 sq cm

Question 24.
PROBLEM SOLVING
In a blueprint,each square has a side length of \(\frac{1}{4}\) inch.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.6 13
a. Ceramic tile costs $5 per square foot. How much does it cost to tile the bathroom?
b. Carpet costs $18 per square yard. How much does it cost to carpet the bedroom and living room?

Answer:
a. The cost to the bathroom = $0.06075
b. The cost to carpet the bedroom and living room = $0.02430

Explanation:
Square side length = 1/4 inch
1 feet = 12 inch
1 inch : 16 ft = 1 : 16 * 12 = 1 : 192
a. one square side length is 1/4
1 foot = 12 inch
So, the length of the bathroom = 4(1/4) = 1 = 1 * 0.0833333
= 0.0833333
The breadth of the bathroom = 7(1/4) = 7/4
= (7 * 0.0833333)/4
= 0.583333/4
= 0.14583325
The area of bathroom = 0.0833333 * 0.14583325
= 0.01215 sq in
Ceramic tile costs $5 per square foot
The cost to the bathroom = 0.01215 * 5 = $0.06075
b. 1 inch = 0.0277778 yard
length of bathroom + living room = 1 * 0.0277778 = 0.0277778
breadth of bathroom + living room = 7/4 (0.0277778)
= 0.04861115
The area of bathroom + living room = 0.0277778 * 0.04861115
= 0.00135031080247
Carpet costs $18 per square yard.
The cost to carpet the bedroom and living room = 0.00135031080247 * 18 = $0.02430

REPRODUCING A SCALE DRAWING Recreate the scale drawing so that it has a scale of 1 cm : 4 m.
Question 25.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.6 14

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.6 2

Explanation:
1 m = 100 cm
Actual length = 1 cm * (1 cm / 400 cm)
= 1/400 cm
Actual breadth = 8 m * (1 cm / 4 m)
= 2 cm

Question 26.
Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.6 15

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.6 3

Explanation:
1 cm = 100 m
Actual length = 1 cm * (1 cm / 400 cm)
= 1/400 cm
Actual breadth = 2 m * ( 1 cm / 4 m)
= 1/2 cm

Question 27.
DIG DEEPER!
Make a conjecture about the relationship between the scale factor of a drawing and the quotients Big Ideas Math Answers 7th Grade Chapter 5 Ratios and Proportions 5.6 16. Explain your reasoning.

Answer:
drawing perimeter/ actual perimeter = scale factor
drawing area/actual area = scale factor

Ratios and Proportions Connecting Concepts

Using the Problem-Solving Plan
Question 1.
The table shows the toll y(in dollars) for traveling x miles on a turnpike. You have $8.25 to pay your toll. How far can you travel on the turnpike?
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions cc 1
Understand the problem.
The table shows the tolls for traveling several different distances on a turnpike. You have $8.25 to pay the toll. You are asked to find how far you can travel on the turnpike with $8.25 for tolls.

Make a plan.
First, determine the relationship between x and y and write an equation to represent the relationship. Then use the equation to determine the distance you can travel.

Solve and check.
Use the plan to solve the problem. Then check your solution.

Answer:
You can travel 55 miles with $8.25 for tolls.

Explanation:
x : y = 40 : 6
= 40/6 : 1
= 20/3 : 1
You need to pay $1 for 20/3 miles
So, 20/3 : 1 = x : 8.25
8.25 (20/3) = x
55 = x
So, you can travel 55 miles with $8.25 for tolls.

Question 2.
A company uses a silo in the shape of a rectangular prism to store bird seed. The base of the silo is a square with side lengths of 20 feet. Are the height and the volume of the silo proportional? Justify your answer.

Answer:
The height and the volume of the silo proportional

Explanation:
The base of the silo is a square with side lengths of 20 feet.
The area of silo = side² = 20²
= 400 sq ft
Height = h
Volume = lwh
= 400h
h : 400h = 1 : 400
The height and the volume of the silo proportional

Question 3.
A rectangle is drawn in a coordinate plane as shown. In the same coordinate plane, create a scale drawing of the rectangle that has a vertex at (0, 0) and a scale factor of 3.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions cc 2

Answer:
The length of rectangle = 2/3
Breadth = 1/3

Explanation:
The length of rectangle = 2 units
The breadth of rectangle = 1 unit
length : breadth = 2 : 1
length = 2breadth
The scale factor = 3
The length of rectangle = 2/3
Breadth = 1/3

Performance Task

Mixing Paint
At the beginning of this chapter, you watched a STEAM Video called “Painting a Large Room.” You are now ready to complete the performance task related to this video, available at BigIdeasMath.com. Be sure to use the problem-solving plan as you work through the performance task.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions cc 3

Ratios and Proportions Chapter Review

Review Vocabulary

Write the definition and give an example of each vocabulary term.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions cr 1

Graphic Organizers

You can use an Example and Non-Example Chart to list examples and non-examples of a concept. Here is an Example and Non-Example Chart for scale factor.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions cr 2

Choose and complete a graphic organizer to help you study the concept.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions cr 3
1. ratio
2. equivalent ratios
3. rate
4. unit rate
5. equivalent rates
6. proportion
7. cross products
8. proportional
9. scale

Chapter Self-Assessment

As you complete the exercises, use the scale below to rate your understanding of the success criteria in your journal.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions cr 4

5.1 Ratios and Ratio Tables (pp. 183–188)
Learning Target: Understand ratios of rational numbers and use ratio tables to represent equivalent ratios.

Write the ratio. Then find and interpret the value of the ratio.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions cr 5
Question 1.
salt: flour

Answer:
1/2 : 2

Explanation:
salt : flour = 1/2 cup : 2 cups

Question 2.
water to flour

Answer:
3/4 cup : 2 cups

Explanation:
water to flour = 3/4 : 2

Question 3.
salt to water

Answer:
1/2 cup : 3/4 cup

Explanation:
salt to water = 1/2 cup : 3/4 cup

Find the missing values in the ratio table. Then write the equivalent ratios.
Question 4.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions cr 6

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 21
The equivalent ratios are 3/2 : 1/2, 3 : 1, 9/2 : 3/2, 6 : 2

Explanation:
The missing values in the ratio table are
3/2 • x = 3
x = 3 • 2/3
x = 2
Milk1 = 2 • 1/2 = 1
1/2 • y = 3/2
y = 3
Flour1 = 3/2 • 3
= 9/2
1/2 • z = 2
z = 4
Flour2 = 3/2 • 4
= 6
The equivalent ratios are 3/2 : 1/2, 3 : 1, 9/2 : 3/2, 6 : 2

Question 5.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions cr 7

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.1 22
The equivalent ratios are 45 : 0.75, 135 : 2.25, 180 : 3, 90 : 1.5

Explanation:
The missing values in the ratio table are
45 • x = 135
x = 135/45
x = 3
Hours1 = 0.75 • 3
= 2.25
0.75 • y = 3
y = 3/0.75
y = 4
Miles1 = 45 • 4 = 180
45 • z = 90
z = 90/45 = 2
Hours2 = 0.75 • 2 = 1.5
The equivalent ratios are 45 : 0.75, 135 : 2.25, 180 : 3, 90 : 1.5

Question 6.
The cost for 16 ounces of cheese is $3.20. What is the cost for 20 ounces of cheese?

Answer:
The cost for 20 ounces of cheese is $3.95

Explanation:
The cost for 16 ounces of cheese is $3.20
The cost for 1 ounce of cheese is 3.20/16
The cost for 20 ounces of cheese is 20(3.20/16)
= 63.2/16
= 3.95

5.2 Rates and Unit Rates (pp. 189–194)
Learning Target: Understand rates involving fractions and use unit rates to solve problems.

Find the unit rate.
Question 7.
289 miles on 10 gallons

Answer:
28.9 miles per 1 gallon

Explanation:
289 miles on 10 gallons
= 289 : 10
= 289/10 : 1
= 28.9 : 1

Question 8.
6 \(\frac{2}{5}\) revolutions in 2\(\frac{2}{3}\) seconds

Answer:
2.4 revolutions in 1 second

Explanation:
6 \(\frac{2}{5}\) revolutions in 2\(\frac{2}{3}\) seconds = 32/5 : 8/3
= 32/5 • 3/8 : 1
= 12/5 : 1

Question 9.
You can mow 23,760 square feet in \(\frac{1}{2}\) hour. How many square feet can you mow in 2 hours? Justify your answer.

Answer:
95040 sq ft you can mow in 2 hours.

Explanation:
You can mow 23,760 square feet in \(\frac{1}{2}\) hour
= 23760 : 1/2
= 23760 • 2 : 1
= 47520 : 1
So you can mow 47520 sq ft in 1 hour
The number of sq ft you can mow in 2 hours = 47520 • 2
= 95040

Tell whether the rates are equivalent. Justify your answer.
Question 10.
60 centimeters every 2.5 years
30 centimeters every 15 months

Answer:
The rates are equivalent.

Explanation:
60 centimeters every 2.5 years = 60 : 2.5
= 600 : 25
= 24 : 1
24 cm every year
= 24 : 12
= 2 : 1
2 cm every month
30 centimeters every 15 months = 30 : 15
= 2 : 1
So, The rates are equivalent.

Question 11.
2.56 per \(\frac{1}{2}\) pound
$0.48 per 6 ounces

Answer:
The ratios are not equivalent.

Explanation:
2.56 per \(\frac{1}{2}\) pound = 2.56 : 1/2
= 2.56 * 2 : 1
= 5.12 : 1
1 pound = 16 ounces
$0.48 per 6 ounces = 0.48 : 6
= 0.48 : 6 * 16
= 0.48 : 96
= 1 : 200
So, the ratios are not equivalent.

5.3 Identifying Proportional Relationships (pp. 195–202)
Learning Target: Determine whether two quantities are in a proportional relationship.

Tell whether the ratios form a proportion.
Question 12.
4 to 9 and 2 to 3

Answer:
The rates do not form a proportion.

Explanation:
4 to 9 = 4 : 9
2 to 3 = 2 : 3
So, the rates do not form a proportion.

Question 13.
12 : 22 and 18 : 33

Answer:
The rates form a proportion.

Explanation:
12 : 22 = 12 : 22
= 6 : 11
18 : 33 = 18 : 33
= 6 : 11
So, the rates form a proportion.

Question 14.
\(\frac{1}{2}\) : 2 and \(\frac{1}{4}\) : \(\frac{1}{10}\)

Answer:
The rates do not form a proportion

Explanation:
\(\frac{1}{2}\) : 2 = 1 : 4
\(\frac{1}{4}\) : \(\frac{1}{10}\) = 1/4 : 1/10
= 10 : 4
= 5 : 2
So, the rates do not form a proportion.

Question 15.
3.2 to 8 and 1.2 to 3

Answer:
The ratios are equivalent.

Explanation:
3.2 to 8 = 3.2 : 8
= 2/5
1.2 to 3 = 1.2 : 3
= 2/5
So, the ratios are equivalent.

Question 16.
Tell whether x and y are proportional.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions cr 16

Answer:
The x and y are proportional

Explanation:
x/y = 1/4
3/12 = (3 • 1)/(4 • 3) = 1/4
6/24 = (6 • 1)/(6 • 4) = 1/4
8/32 = (8 • 1)/(8 • 4) = 1/4
So, the x and y are proportional.

Question 17.
You can type 250 characters in 60 seconds. Your friend can type 375 characters in 90 seconds. Do these rates form a proportion? Explain.

Answer:
The rates form a proportion.

Explanation:
You can type 250 characters in 60 seconds = 250 : 60
= (25 • 10) : (6 • 10) = 25 : 6
Your friend can type 375 characters in 90 seconds = 375 : 90
= (25 • 15) : (6 • 15)
= 25 : 6
So, the rates form a proportion.

5.4 Writing and Solving Proportions (pp. 203–210)
Learning Target: Use proportions to solve ratio problems.

Solve the proportion. Explain your choice of method.
Question 18.
\(\frac{3}{8}=\frac{9}{x}\)

Answer:
x = 24

Explanation:
\(\frac{3}{8}=\frac{9}{x}\)
Cross multiply the fractions
3x = 9 * 8
x = 3 * 8
x = 24

Question 19.
\(\frac{x}{4}=\frac{2}{5}\)

Answer:
x = 8/5

Explanation:
\(\frac{x}{4}=\frac{2}{5}\)
Cross multiply the fractions
5x = 2 * 4
5x = 8
x = 8/5

Question 20.
\(\frac{5}{12}=\frac{y}{15}\)

Answer:
y = 75/12

Explanation:
\(\frac{5}{12}=\frac{y}{15}\)
Cross multiply the fractions
15 * 5 = 12y
75 = 12y
y = 75/12

Question 21.
\(\frac{s+1}{4}=\frac{4}{8}\)

Answer:
s = 1

Explanation:
\(\frac{s+1}{4}=\frac{4}{8}\)
Cross multiply the fractions
8(s + 1) = 4 * 4
8s + 8 = 16
8s = 16 – 8
8s = 8
s = 1

Use the table to write a proportion.
Question 22.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions cr 22

Answer:
6/12 = 8/m, m = 12

Explanation:
The ratios are proportional.
6/12 = 8/m
Cross multiply the fractions
6m = 8 * 12
6m = 96
m = 96/8
m = 12

Question 23.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions cr 23

Answer:
15/h = 18/2.5

Explanation:
The ratios are proportional.
So, 15/h = 18/2.5

Question 24.
Find the value of x so that the ratios 8 : 20 and 6 : x are equivalent.

Answer:
x = 15

Explanation:
8/20 = 6/x
Cross multiply the fractions
8x = 6 * 20
8x = 120
x = 120/8
x = 15

Question 25.
Swamp gas consists primarily of methane, a chemical compound consisting of a 1 : 4 ratio of carbon to hydrogen atoms. If a sample of methane contains 1564 hydrogen atoms, how many carbon atoms are present in the sample?
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions cr 25

Answer:
The number of carbon atoms present in the sample is 391.

Explanation:
Swamp gas consists primarily of methane, a chemical compound consisting of a 1 : 4 ratio of carbon to hydrogen atoms
The number of carbon atoms present in the sample is 1564/4
= 391

5.5 Graphs of Proportional Relationships (pp. 211–216)
Learning Target: Represent proportional relationships using graphs and equations.

Question 26.
Tell whether x and y are proportional. Explain your reasoning.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions cr 26

Answer:
x and y are proportional

Explanation:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.5 20
The line passes through origin.
So, x and y are proportional

Question 27.
The graph shows the number of visits your website received over the past 6 months. Interpret each plotted point in the graph. Then identify the unit rate.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions cr 27

Answer:
50 : 1

Explanation:
Number of visitors : months = 150 : 3
= 150/3 : 1
= 50 : 1

Tell whether x and y are proportional. If so, identify the constant of proportionality. Explain your reasoning.
Question 28.
x + y = 6

Answer:
x and y are not proportional.

Explanation:
x + y = 6
y = 6 – x
If x = 1, then y = 6 – 1 = 5
If x = 2, then y = 6 – 2 = 4
If x = 3, y = 6 – 3 = 3
1/5, 2/4, 3/3 are not equivalent ratios
So, x and y are not proportional.

Question 29.
y – x = 0

Answer:
x and y are proportional.

Explanation:
y – x = 0
y = x
If x = 1, then y = 1
If x = 2, then y = 2
If x = 3, then y = 3
1/2, 2/2, 3/3 are equivalent ratios
So, x and y are proportional.

Question 30.
\(\frac{x}{y}\) = 20

Answer:
x and y are proportional.

Explanation:
\(\frac{x}{y}\) = 20
x = 20y
If y = 1, then x = 20(1) = 20
If y = 2, then x = 20(2) = 40
If y = 3, then x = 20(3) = 60
20/1, 40/2, 60/3 are equivalent ratios
So, x and y are proportional.

Question 31.
x = y + 2

Answer:
x and are not proportional.

Explanation:
x = y + 2
If y = 1, then x = 1 + 2 = 3
If y = 2, then x = 2 + 2 = 4
If y = 3, then x = 3 + 2 = 6
3/1, 4/2, 6/3 are not equivalent
So, x and are not proportional.

Question 32.
The variables x and y are proportional. When y = 4, x = \(\frac{1}{2}\). Find the constant of proportionality. Then write an equation that relates x and y.

Answer:
x = 8y

Explanation:
x/y = k
(1/2)/4 = k
k = 1/8
x/y = 8
x = 8y

5.6 Scale Drawings (pp. 217–222)
Learning Target: Solve problems involving scale drawings.

Find the missing dimension. Use the scale factor 1 : 20.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions cr 33

Answer:
Big Ideas Math Answer Key Grade 7 Chapter 5 Ratios and Proportions 5.6 4

Explanation:
33. Scale factor = 1/20
Use the scale 1 : 20
90(1/20) = 9/2 = 4.5
34. x/20 = 3.75
x = 3.75 * 20
x = 75
Actual legth = 75 ft

Use a centimeter ruler to find the scale and the scale factor of the drawing.
Question 35.
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions cr 35

Answer:
The scale is 7.62, scale factor is 39.3701 in

Explanation:
The length of drawing = 10 cm
10 cm = 30 in
1 cm = 0.393701
10 cm = 39.3701 in
10 cm : 30 in = 1 cm : 3 in
3 inch = 7.62
The actual length is 39.3701 inch
So, the scale is 7.62, scale factor is 39.3701 in

Question 36
Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions cr 36

Answer:
The scale is 19.05, scale factor is 19.05

Explanation:
Uisng the centimeter ruler, length is 4 cm
4 cm = 7.5 in
1 cm = 0.393701
4 cm = 1.5748 in
4 cm : 7.5 in
7.5 inch = 19.05
4 cm : 7.5 inch = 4 cm : 19.05 cm
the scale is 19.05, scale factor is 19.05

Question 37.
A scale model of a lighthouse has a scale of 1 in.: 8ft. The scale model is 20 inches tall. How tall is the lighthouse?

Answer:

Explanation:
A scale model of a lighthouse has a scale of 1 in.: 8ft
The scale model is 20 inches tall

Ratios and Proportions Practice Test

Find the unit rate.
Question 1.
84 miles in 12 days

Answer:
7 miles in 1 day

Explanation:
84 miles in 12 days
= 84 : 12
= 84/12 : 1
= 7 : 1

Question 2.
2 \(\frac{2}{5}\) kilometers in 3\(\frac{3}{4}\) minutes

Answer:
48 kilometers in 75 minutes.

Explanation:
2 \(\frac{2}{5}\) kilometers in 3\(\frac{3}{4}\) minutes = 12/5 : 15/4
= 12/5 • 4/15 : 1
= 48/75 : 1

Tell whether the ratios form a proportion.
Question 3.
1 to 0.4 and 9 to 3.6

Answer:
The ratios form a proportion.

Explanation:
1 to 0.4 = 1 : 0.4
= 5/2
9 to 3.6 = 9 : 3.6
= 5/2
So, the ratios form a proportion.

Question 4.
2 : \(\frac{8}{3}\) and \(\frac{2}{3}\) : 6

Answer:
The ratios do not form a proportion.

Explanation:
2 : \(\frac{8}{3}\) = 6 : 8
= 3/4
\(\frac{2}{3}\) : 6 = 2 : 18
= 1/9
So, the ratios do not form a proportion.

Tell whether and are proportional. Explain your reasoning.
Question 5.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions pt 5

Answer:
x and y are proportional

Explanation:
x/y = 2/10 = 1/5
4/20 = 1/5
6/30 = 1/5
8/40 = 1/5
So, x and y are proportional

Question 6.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions pt 6

Answer:
x and y are not proportional.

Explanation:
x/y = 1/3, 3/7, 5/11, 7/15
So, x and y are not proportional.

Question 7.
Use the table to write a proportion.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions pt 7

Answer:
1/30 = 8/m

Explanation:
the ratios are proportional
so, 6/180 = 8/m
1/30 = 8/m

Solve the proportion.
Question 8.
\(\frac{x}{8}=\frac{9}{4}\)

Answer:
x = 18

Explanation:
\(\frac{x}{8}=\frac{9}{4}\)
Cross multiply the fractions
4x = 9 * 8
4x = 72
x = 72/4
x = 18

Question 9.
\(\frac{17}{4}=\frac{y}{6}\)

Answer:
y = 51/2

Explanation:
\(\frac{17}{4}=\frac{y}{6}\)
Cross multiply the fractions
17 * 6 = 4y
102 = 4y
y = 102/4
y = 51/2

Tell whether and are proportional. If so, identify the constant of proportionality. Explain your reasoning.
Question 10.
xy – 11 = 5

Answer:
x, y are not proportional.

Explanation:
xy – 11 = 5
xy = 5 + 11
xy = 16
x = 16/y

Question 11.
\(\frac{y}{x}\) = 8

Answer:
x and y are proportional

Explanation:
\(\frac{y}{x}\) = 8
y = 8x
So, x and y are proportional

Question 12.
A recipe calls for \(\frac{2}{3}\) cup flour for every cup sugar. Write the ratio of sugar to flour. Then find and interpret the value of the ratio.

Answer:
The ratio of sugar to flour is 3 : 2.

Explanation:
A recipe calls for \(\frac{2}{3}\) cup flour for every cup sugar
Flour : sugar = 2/3 : 1
Sugar to flour = 1 : 2/3
= 3 : 2

Question 13.
The graph shows the number of cycles of a crosswalk signal during the day and during the night.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions pt 13
a. Write equations that relate x and y for both the day and night periods.
b. Find how many more cycles occur during the day than during the night for a six-hour period.

Answer:
a. The equation for day is 40 x = y
the equation for night is 30x = y
b. 60 more cycles occur during the day than during the night for a six-hour period.

Explanation:
a. For day, 2 hours is 80 cycles
x/y = 2/80 = 1/40
40x = y
For night, 3 hours is 90
x/y = 3/90 = 1/30
30x = y
a. For day, the number of cycles for 3 hours is 90
90 : 3 = 30 : 1
So, 30 cycles per 1 hour
The number of cycles per 6 hours is 30 * 6 = 180
For night,
the number of cycles is 80 for 2 hours
80 : 2 = 40 : 1
The number of cycles for 6 hours is 40 * 6 = 240
240 – 180 = 60

Question 14.
An engineer is using computer-aided design (CAD) software to design a component for a space shuttle. The scale of the drawing is 1 cm : 60 in. The actual length of the component is 12.75 feet. What is the length of the component in the drawing?

Answer:
The length of the component in the drawing is 25 cm

Explanation:
Write the proportion relating the model length to the actual length. the scale has inches for the actual length units so you must use 12.5 feet = 15 inches in the proportion
model/actual = 1 cm/60 in = x cm/150 in
60x = 150
x = 150/6
= 25

Question 15.
A specific shade of green glaze is made of 5 parts blue glaze to 3 parts yellow glaze. A glaze mixture contains 25 quarts of blue glaze and 9 quarts of yellow glaze. How can you fix the mixture to make the specific shade of green glaze?

Answer:
25 parts blue to 15 parts yellow

Explanation:
25 blue to 9 yellow
The rate is not equal to the specific rate, 5 parts blue to 3 parts yellow
25 parts blue to 15 parts yellow

Ratios and Proportions Cumulative Practice

Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions cp 1
Question 1.
The school store sells 4 pencils for $0.80. What is the unit cost of a pencil?
A. $0.20
B. $0.80
C. $3.20
D. $5.00

Answer:
A. $0.20

Explanation:
The school store sells 4 pencils for $0.80
= 0.80 : 4
= 0.80/4 : 1
= 0.2 : 1

Question 2.
What is the simplified form of the expression?
3x – (2x – 5)
F. x – 5
G. x + 5
H. 5x – 5
I. – x – 5

Answer:
G. x + 5

Explanation:
The given expression is 3x – (2x – 5)
= 3x – 2x + 5
= x + 5

Question 3.
Which fraction is equivalent to – 1.25?”
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions cp 3

Answer:
B.

Explanation:
-1.25 = -125/100
= -5/4
-1(1/4) = -5/4

Question 4.
What is the value of for the proportion \(\frac{8}{12}=\frac{x}{18}\)?
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions cp 4

Answer:
x = 12

Explanation:
\(\frac{8}{12}=\frac{x}{18}\)
Cross multiply the fractions
8 * 18 = 12x
144 = 12x
x = 144/12
x = 12

Question 5.
What inequality is represented by the graph?
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions cp 5
F. x – 3 < 7
G. x + 6 ≤ 10
H. – 5 + x < – 1 I. x – 8 > – 4

Answer:
G. x + 6 ≤ 10

Explanation:
the graph represents x ≤ 4.
Solve all the given options
x – 3 < 7
x < 7 + 3
x < 10
G. x + 6 ≤ 10
x ≤ 10 – 6
x ≤ 4
H. – 5 + x < – 1
x < -1 + 5
x < 4
I. x – 8 > – 4
x > -4 + 8
x > 4

Question 6.
What is the missing value in the ratio table?
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions cp 6

Answer:
B. 30

Explanation:
2/3 • x = 10/3
x = 10/3 • 3/2
x = 5
6 • 5 = 30

Question 7.
Which expression shows factoring 12x + 54 using the GCF?
F. 2(6x + 27)
G. 3(4x + 18)
H. 6(2x + 9)
I. 12(x + \(\frac{9}{2}\))

Answer:
H. 6(2x + 9)

Explanation:
12x = 3 • 2 • 2 • x
54 = 2 • 3 • 9
The common prime factors are 3 • 2 = 6
So, the GCF of 12x + 54 is 6
12x + 54 = 6(2x) + 6(9)
= 6(2x + 9)

Question 8.
The distance traveled by a high-speed train is proportional to the number of hours traveled. Which of the following is not a valid interpretation of the graph?
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions cp 8
A. The train travels 0 kilometers in 0 hours.
B. The unit rate is 200 kilometers per hour.
C. After 4 hours, the train is traveling 800 kilometers per hour.
D. The train travels 800 kilometers in 4 hours.

Answer:
B. The unit rate is 200 kilometers per hour.

Explanation:
The distance traveled by a high-speed train is proportional to the number of hours traveled
200 proportional to 1 = 200 : 1

Question 9.
Which graph represents a number that is at most – 2?
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions cp 9

Answer:
H.

Explanation:
At most means less than or equal to
x ≤ -2

Question 10.
A map of the state where your friend lives has the scale \(\frac{1}{2}\) in. : 10 mi.
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions cp 10
Part A Your friend measured the distance between her town and the state capital on the map. Her measurement was 4\(\frac{1}{2}\) inches. Based on your friend’s measurement, what is the actual distance (in miles) between her town and the state capital? Show your work and explain your reasoning.
Part B Your friend wants to mark her favorite campsite on the map. She knows that the campsite is 65 miles north of her town. What distance on the map (in inches) represents an actual distance of 65 miles? Show your work and explain your reasoning.

Answer:
A. 90 miles
B. 3(1/4) inch

Explanation:
A. Write the proportion relating the model distance on the map to the actual distance where x is the actual distance. Then solve the proportion by cross multiplying
model/actual = 1/2/10 = 4(1/2)/x
0.5/10 = 4.5/x
0.5x = 45
x = 45/0.5
x = 90 miles
B. Write the proportion relating the model distance to the actual distance where y is the model distance.
0.5/10 = y/65
cross multiply
10y = 0.5 * 65
10y = 32.5
y = 32.5/10
y = 3.25
= 3(1/4) inch

Question 11.
What is the value of the expression – 56 ÷ (- 8)?
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions cp 4

Answer:
– 56 ÷ (- 8) = 7

Explanation:
– 56 ÷ (- 8)
The quotient of two negative integers is positive
56 ÷ 8 = 7

Question 12.
The quantities and are proportional. What is the missing value in the table?
Big Ideas Math Solutions Grade 7 Chapter 5 Ratios and Proportions cp 12
A. 38
B. 42
C. 46
D. 56

Answer:
D. 56

Explanation:
Two quantities are proportional
5/7x = 4
x = 4 (7/5)
x = 28/5
Missing value = 10(28/5) = 2(28) = 56

Question 13.
To begin a board game, you place a playing piece at START. On your first three turns, you move ahead 8 spaces, move back 3 spaces, and then move ahead 2 spaces. How many spaces are you from START?
F. 2
G. 3
H. 7
I. 13

Answer:
H. 7

Explanation:
For the first three turns, you move ahead 8 spaces and move back 3 spaces
= 8 – 3 = 5
move ahead 2 spaces
5 + 2 = 7

Final Words:

Big Ideas Math Answers Grade 7 Chapter 5 Ratios and Proportions detailed pdf is here. Check Big Ideas Math Book Grade 7 Chapter 5 Ratios and proportions and make the learning easy. Therefore collect Big Ideas Math 7th Grade Chapter 5 Ratios and Proportions Answer Key and complete your preparation. Stay tuned to our website to know the trending information regarding Ratios and Proportions. Bookmark our page to know all the details of Grade 7. We wish all the best for all students.

Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles

Big Ideas Math Answers Grade 8 Chapter 3

Middle School Students who are struggling with the concepts of Big Ideas Math Grade 8 Ch 3 Angles and Triangles need not worry anymore. Big Ideas Math Book 8th Grade Chapter 3 Angles and Triangles help you finish your homework in time and gives you assistance whenever you need it. Detailed Solutions provided in Big Ideas Math Grade 8 Answers Chapter 3 make it easy for you to attain knowledge regarding the particular topic in a matter of seconds. Access the BIM Book Grade 8 Ch 3 Angles and Triangles Answer Key via direct links and prepare effectively.

Big Ideas Math Book 8th Grade Answer Key Chapter 3 Angles and Triangles

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Performance

Lesson: 1 Parallel Lines and Transversals

Lesson: 2 Angles of Triangles

Lesson: 3 Angles of Polygons

Lesson: 4 Using Similar Triangles

Chapter 3 – Angles and Triangles

Angles and Triangles STEAM Video/Performance

STEAM Video

Each cell in a honeycomb is in the shape of a regular hexagon. Why might bees use this shape?
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 1

Watch the STEAM Video “Honeycombs.” Then answer the following questions.

Question 1.
Enid and Tony show regular tilings made out of squares, equilateral triangles, and regular hexagons. What is the sum of the interior angle measures of the tiling made from equilateral triangles, outlined below in yellow?
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 2

Answer:
The sum of interior angles of the equilateral triangle = 180°
x + x + x = 180°
3x° = 180°
x = 180/3
x° = 60°

Question 2.
The cells in a honeycomb use a tiling pattern of the regular hexagon shown. A cell is 10 millimeters deep. About how much honey can one cell hold? Explain.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 3

Performance Task

Turtle Shells

After completing this chapter, you will be able to use the concepts you learned to answer the questions in the STEAM Video Performance Task. You will be given angle measures of shapes seen on a turtle shell.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 4
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 5
You will be asked to find angle sums and missing angle measures. What other animals have features that resemble geometric shapes?

Angles and Triangles Getting Ready for Chapter 3

Chapter Exploration

When an object is transverse, it is lying or extending across something. In the drawing, the fallen tree lying across the railroad track is transverse to the track.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 6
1. Work with a partner.
• Discuss what it means for two lines to be parallel. Decide on a strategy for drawing parallel lines. Then draw two parallel lines.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 7
• Draw a third line that intersects the parallel lines. This line is called a transversal
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 8
a. How many angles are formed by the parallel lines and the transversal? Label each angle.

Answer: 8 angles are formed by the parallel lines and the transversal
b. Which of these angles have equal measures? Explain your reasoning.

Vocabulary

The following vocabulary terms are defined in this chapter. Think about what the terms might mean and record your thoughts.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 9

Lesson 3.1 Parallel Lines and Transversals

EXPLORATION 1

Work with a partner. Use geometry software and the lines A and B shown.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 10
a. Are line A and B line parallel? Explain your reasoning.
b. Draw a line that intersects both line A and line B. What do you notice about the measures of the angles that are created?
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 11
c. Rotate line A or line B until the angles created by the intersection of line A and line C are congruent to the angles created by the intersection of line B and line C. What do you notice about line A and line B?
d. Rotate line to create different angle measures. Are the angles that were congruent in part(c) still congruent?
e. Make a conjecture about the measures of the angles created when a line intersects two parallel lines.

3.1 Lesson

Try It

Use the figure to find the measure of the angle. Explain your reasoning

Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 12

Question 1.
∠1

Answer: 63°

Explanation:
Big Ideas Math Grade 8 Answers Chapter 3 img_1
∠1 and 63° angle are corresponding angles are formed by transversal intersecting parallel lines. The angles are congruent.
So, the measure of ∠1 is 63°

Question 2.
∠2

Answer: 117°

Explanation:
BIM Grade 8 Chapter 3 Angles and triangles answer key img_2
∠1 and ∠2 are supplementary angle.
∠1 + ∠2 = 180°
63° + ∠2 = 180°
∠2 = 180° – 63°
∠2 = 117°
So, the measure of ∠2 = 117°

Try It

Question 3.
Use the figureto find the measures of the numbered angles.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 13

Answer:
∠1 and 59° are the supplementary angles
∠1 + 59° = 180°
∠1 = 180° – 59°
∠1 = 121°
∠2 and 59° are vertical angles. They are congruent.
So, the measure of ∠1 is 121°
∠3 and 59° are supplementary angles.
∠3 + 59° = 180°
∠3 = 180° – 59°
∠3 = 121°
∠4, ∠5, ∠6, ∠7 corresponding angles are congruent because they are formed by a transversal intersecting parallel side.
the measure of  ∠4 is 121°
the measure of ∠5 is 59°
the measure of  ∠6 is 121°
the measure of ∠7 is 59°

Try It

In Example 3, the measure of ∠4 is 84°. Find the measure of the angle. Explain your reasoning.

Question 4.
∠3

Answer:
Bigideas Math Answers Grade 8 Chapter 3 Angles and Triangles img_3
The measure of ∠4 is 84°.
∠3 and ∠4 are supplementary angles.
∠3 + ∠4 = 180°
∠3 + 84° = 180°
∠3 = 180° – 84°
∠3 = 96°

Question 5.
∠5

Answer:
∠4 and ∠5 are alternate interior angles formed by transversal intersecting parallel lines. The angles are congruent.
So, the measure of ∠5 is 84°

Question 6.
∠6

Answer:
∠3 and ∠6 are alternate exterior angles formed by transversal intersecting parallel lines. The angles are congruent.
So, the measure of ∠6 is 96°

Self-Assessment for Concepts & Skills
Solve each exercise. Then rate your understanding of the success criteria in your journal.

FINDING ANGLE MEASURES
Use the figure to find the measures of the numbered angles.

Question 7.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 14

Answer:
∠1 and 120° are the supplementary angles.
∠1 + 120° = 180°
∠1 = 180 – 120
∠1 = 60°
Thus the measure of ∠1 is 60°
∠2 and 120° are the vertical angles. They are congruent.
Thus the measure of ∠2 is 120°
∠3 and 120° are the supplementary angles.
∠3 + 120° = 180°
∠3 = 180 – 120
∠3 = 60°
∠4, ∠5, ∠6, ∠7 are corresponding angles are formed by transversal intersecting parallel lines. The angles are congruent.
Thus the measure of ∠4 is 60°
Thus the measure of ∠5 is 120°
Thus the measure of ∠6 is 120°
Thus the measure of ∠7 is 60°

Question 8.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 15

Answer:
∠1 and 35° are the supplementary angles.
∠1 + 35° = 180°
∠1 = 180 – 35
∠1 = 145°
Thus the measure of ∠1 is 145°
∠2 and 35° are the supplementary angles.
∠2 + 35° = 180°
∠2 = 180 – 35
∠2 = 145°
Thus the measure of ∠2 is 145°
∠3 and 35° are the vertical angles. They are congruent.
Thus the measure of ∠3 is 35°
∠4, ∠5, ∠6, ∠7 are corresponding angles are formed by transversal intersecting parallel lines. The angles are congruent.
Thus the measure of ∠4 is 35°
Thus the measure of ∠5 is 145°
Thus the measure of ∠6 is 145°
Thus the measure of ∠7 is 35°

Question 9.
WHICH ONE DOESN’T BELONG?
Which angle measure does not belong with the other three? Explain your reasoning.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 16

Answer:
∠2, ∠6 are corresponding angles are formed by transversal intersecting parallel lines.
∠6, ∠8 are vertical angles are formed by transversal intersecting parallel lines.
∠5 does not belong to the other three because all the other three measure are equal.

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 10.
A cross section of a pier is shown. Find the value of a. Justify your answer.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 17

Answer:
The angle a and the angle of 70 degrees are complementary angles because they belong to a right triangle, where the third angle is the right angle.
∠a + 70 = 90
∠a = 90 – 70
∠a = 20°

Question 11.
The head tube angle of a bike determines how easy the bike is to steer. A bike frame with angle approximations is shown. What is the head tube angle of the bike?
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 18

Answer:
The lines AB and CD are parallel.
ABC and BCD are the corresponding angles formed by transversal intersecting parallel lines.
∠BCD = 55°
∠BAC + ∠ABC + ∠ACB = 180°
The sum of the angles in a triangle is 180°
∠BAC + 55°+ 52° = 180°
∠BAC + 107° = 180°
∠BAC = 180° – 107°
∠BAC = 73°
So, the head tube angle of a bike is 73°

Parallel Lines and Transversals Homework & Practice 3.1

Review & Refresh

Find the values of the ratios (red to blue) of the perimeters and areas of the similar figures.

Question 1.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 19

Answer:
perimeter of red hexagon/perimeter of blue hexagon = \(\frac{3}{5}\)
The values of the ratios of the perimeter is \(\frac{3}{5}\)
Area of red hexagon/Area of blue hexagon = (\(\frac{3}{5}\))² = \(\frac{9}{25}\)
The values of the ratios of the area is \(\frac{9}{25}\)

Question 2.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 20

Answer:
perimeter of red trapezium /perimeter of blue trapezium = \(\frac{7}{6}\)
The values of the ratios of the perimeter is \(\frac{7}{6}\)
Area of red hexagon/Area of blue hexagon = (\(\frac{7}{6}\))² = \(\frac{49}{36}\)
The values of the ratios of the area is \(\frac{49}{36}\)

Evaluate the expression.

Question 3.
4 + 32

Answer:
4 + 9 = 13

Question 4.
5(2)2 – 6

Answer:
5(4) – 6
20 – 6 = 14

Question 5.
11 + (-7)2 – 9

Answer:
11 + 49 – 9
11 + 40 = 50

Concepts, Skills, & Problem Solving
EXPLORING INTERSECTIONS OF LINES
Use a protractor to determine whether lines a and b are parallel. (See Exploration 1, p. 103.)

Question 6.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 21

Answer:
Use a protractor to measure ∠1 and ∠2
∠1 ≈ 60°
∠2 ≈ 60°
∠1 and ∠2, it means the two angles are congruent. The angles are exterior alternate angles.
According to the converse of the exterior alternate angles theorem, the two lines are parallel.
a || b

Question 7.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 22

Answer:
Use a protractor to measure ∠1 and ∠2
∠1 ≈ 50°
∠2 ≈ 60°
∠1 and ∠2, it means the two angles are not congruent. The angles are exterior alternate angles.
According to the converse of the exterior alternate angles theorem, the two lines are not parallel.

FINDING ANGLE MEASURES
Use the figure to find the measures of the numbered angles. Explain your reasoning.

Question 8.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 23

Answer:
∠1 and 107° are corresponding angles. They are congruent.
So, the measure of ∠1 is 107°.
∠1 and ∠2 are supplementary angles.
∠1 + ∠2 = 180°
107° + ∠2 = 180°
∠2 = 180° – 107°
∠2 = 73°
So, the measure of ∠2 is 73°

Question 9.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 24

Answer:
∠3 and 95° are corresponding angles. They are congruent.
Thus the measure of ∠3 is 95°
∠3 and ∠4 are supplementary angles.
∠3 + ∠4 = 180°
95° + ∠4 = 180°
∠4 = 180 – 95
∠4 = 85°
So the measure of ∠4 is 85°

Question 10.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 25

Answer:
∠5 and 49° are corresponding angles. They are congruent.
So, the measure of ∠5 is 49°
∠5 and ∠6 are supplementary angles.
∠5 + ∠6 = 180°
49° + ∠6 = 180°
∠6 = 180° – 49°
∠6 = 131°
So, the measure of ∠6 is 131°

Question 11.
YOU BE THE TEACHER
Your friend describes a relationship between the angles shown. Is your friend correct? Explain your reasoning.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 26

Answer:
Since the two lines are not parallel. Hence ∠5 is not congruent to ∠6.
By this, we can say that your friend is not correct.

Question 12.
PROBLEM SOLVING
The painted lines that separate parking spaces are parallel. The measure of ∠1 is 60°. What is the measure of ∠2? Explain.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 27

Answer:
∠1 and ∠2 are corresponding angles formed by a transversal intersecting parallel lines. The angles are congruent.
The measure of ∠1 is 60° so the measure of ∠2 is 60°

Question 13.
OPEN-ENDED
Describe two real-life situations that use parallel lines.

Answer:
Example 1: The railroad tracks and the tram tracks are parallel lines.
Example 2:  The shelves of a bookcase.

USING CORRESPONDING ANGLES
Use the figure to find the measures of the numbered angles.

Question 14.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 28

Answer:
∠1 and 60° are corresponding angles formed by a transversal intersecting parallel lines. The angles are congruent.
∠1 and ∠2 are supplementary angles.
∠1 + ∠2 = 180°
60° + ∠2 = 180°
∠2 = 180° – 60°
∠2 = 119°
So, the measure of ∠2 is 119°
∠3 and ∠1 are vertical angles. They are congruent.
So, the measure of ∠3 is 61°
∠4 and ∠2 are vertical angles. They are congruent.
∠5, ∠6, ∠7 corresponding angles are congruent because they are formed by a transversal intersecting parallel lines.
So, the measure of ∠5 is 119°
So, the measure of ∠6 is 61°
So, the measure of ∠7 is 119°

Question 15.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 29

Answer:
∠1 and 99° are supplementary angles.
∠1 + 99° = 180°
∠1 = 180° – 99°
∠1 = 81°
Thus the measure of ∠1 is 81°
∠2 and 99° are vertical angles. They are congruent.
The measure of ∠2 is 99°
∠3 and ∠1 are vertical angles. They are congruent.
So, the measure of ∠3 is 81°
∠4, ∠5, ∠6, ∠7 corresponding angles are congruent because they are formed by a transversal intersecting parallel lines.
So, the measure of ∠4 is 99°
So, the measure of ∠5 is 81°
So, the measure of ∠6 is 99°
So, the measure of ∠7 is 81°

Question 16.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 30

Answer:
∠1 and 90° are supplementary angles.
∠1 + 90° = 180°
∠1 = 180° – 90°
∠1 = 90°
Thus the measure of ∠1 is 90°
∠2 and 90° are vertical angles. They are congruent.
Thus the measure of ∠2 is 90°
∠3 and ∠1 are vertical angles. They are congruent.
So, the measure of ∠3 is 90°
∠4, ∠5, ∠6, ∠7 corresponding angles are congruent because they are formed by a transversal intersecting parallel lines.
So, the measure of ∠4 is 90°
So, the measure of ∠5 is 90°
So, the measure of ∠6 is 90°
So, the measure of ∠7 is 90°

USING CORRESPONDING ANGLES
Complete the statement. Explain your reasoning.

Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 30.1

Question 17.
If the measure of ∠1 = 124°, then the measure of Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 31

Answer:
∠1 and ∠8 are corresponding angles. They are congruent.
The measure of ∠1 = 124°, then the measure of ∠8 is 124°
∠8 and ∠4 are supplementary angles.
∠8 + ∠4 = 180°
124° + ∠4 = 180°
∠4 = 180° – 124°
∠4 = 56°
So, the measure of ∠4 is 56°

Question 18.
If the measure of ∠2 = 48°, then the measure of Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 32

Answer:
∠2 and ∠7 are corresponding angles. They are congruent.
The measure of ∠2 = 48°, then the measure of ∠7 is 48°
∠7 and ∠3 are supplementary angles.
∠7 + ∠3 = 180°
48° + ∠3 = 180°
∠3 = 180° – 48°
∠3 = 132°
Thus the measure of ∠3 = 132°

Question 19.
If the measure of ∠4 = 55°, then the measure of Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 33

Answer:
∠4 and ∠2 are alternate interior angles formed by a transversal intersecting parallel lines. The angles are congruent.
So, the measure of ∠2 is 55°

Question 20.
If the measure of ∠6 = 120°, then the measure of Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 34

Answer:
∠6 and ∠8 are alternate exterior angles formed by a transversal intersecting parallel lines. The angles are congruent.
So, the measure of ∠8 is 120°

Question 21.
If the measure of ∠7 = 50.5°, then the measure of Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 35

Answer:
∠7 and ∠2 are corresponding angles. They are congruent.
The measure of ∠7 is 50.5°, so the measure of ∠2 is 50.5°
∠2 and ∠6 are supplementary angle.
∠2 + ∠6 = 180°
50.5° + ∠6 = 180°
∠6 = 180° – 50.5°
∠6 = 129.5°
So, the measure of ∠6 is 129.5°

Question 22.
If the measure of ∠3 = 118.7°, then the measure of Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 35.1

Answer:
∠3 and ∠6 are corresponding angles. They are congruent.
The measure of ∠3 is 118.7°
So, the measure of ∠6 is 118.7°
∠6 and ∠2 are supplementary angles.
∠6 + ∠2 = 180°
118.7° + ∠2 = 180°
∠2 = 180° – 118.7°
∠2 = 61.3°
So, the measure of ∠2 is 61.3°

Question 23.
MODELING REAL LIFE
A rainbow forms when sunlight reflects of raindrops at different angles. For blue light, the measure ∠2 is 40°. What is the measure of ∠1?
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 31.1

Answer:
∠4 and ∠5 are alternate interior angles formed by a transversal intersecting parallel lines. The angles are congruent.
So, the measure of ∠1 is 40°

Question 24.
REASONING
Is there a relationship between exterior angles that lie on the same side of a transversal? interior angles that lie on the same side of a transversal? Explain.

Answer:
∠7 and ∠8 are Exterior angles that lie on the same side of the transversal. Hence ∠7 and ∠8 are supplementary angles.
Big Ideas Math Answers grade 8 Chapter 3 Angles and Triangles img_4
∠3 and ∠4 are interior angles that lie on the same side of the transversal. Hence ∠3 and ∠4 are supplementary angles.

Question 25.
REASONING
When a transversal is perpendicular to two parallel lines, all the angles formed measure 90°. Explain why.

Answer:
When a transversal is perpendicular to two parallel lines, all the angles formed measure 90°.
Big Ideas Math Grade 8 Answers Chapter 3 img
All the angles formed are 90 degrees because perpendicular lines form 90 degree angles.

Question 26.
REASONING
Two horizontal lines are cut by a transversal. What is the least number of angle measures you need to know to find the measure of every angle? Explain your reasoning.

Answer:
BIM Grade 8 Chapter 3 Angles and triangles answers img_6
In the below example two horizontal lines a and b are cut by a transversal line t, we know only one angle 61 the measure of all the angles are find with the help of one known measure, 61°
∠1 and 61° are corresponding angles formed by a transversal intersecting parallel lines. the angles are congruent.
Thus the measure of ∠1 is 61°
∠1 and ∠2 are supplementary angles.
∠1 + ∠2 = 180°
61° + ∠2 = 180°
∠2 = 180° – 61°
∠2 = 119°
Thus the measure of ∠2 is 119°
∠3 and ∠1 are vertical angles. They are congruent.
Thus the measure of ∠3 is 61°
∠4 and ∠2 are vertical angles. They are congruent.
Thus the measure of ∠4 is 119°
∠5, ∠6, ∠7 corresponding angles are formed by transversal intersecting parallel lines. The angles are congruent.
Thus the measure of ∠5 is 119°
Thus the measure of ∠6 is 61°
Thus the measure of ∠7 is 119°

Question 27.
LOGIC
Describe two ways you can show that ∠1 is congruent to ∠7.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 32.1

Answer:
∠1 and ∠7 are alternate exterior angles formed by a transeversal intersecting parallel lines. So, ∠1 and ∠7 are congruent.
∠1 and ∠5 are corresponding angles formed by a transeversal intersecting parallel lines. So, ∠1 and ∠5 are congruent.
∠5 and ∠7 are vertical angles so they are congruent.
Hence ∠1 and ∠7 are congruent.

FINDING A VALUE
Find the value of x.

Question 28.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 33.1

Answer:
∠1 and 50° are alternate interior angles. They are congruent.
So, the measure of ∠1 is 50°
∠2 and ∠1 are corresponding angles. They are congruent.
So, the measure of ∠2 is 50°
∠2 and x are supplementary angle.
∠2 + x = 180°
50° + x = 180°
x = 180° – 50°
x = 130°
So, the measure of x is 130°

Question 29.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 34.1

Answer:
∠1 and 115° are corresponding angles. They are congruent.
So, the measure of ∠1 is 115°
∠1 and x are alternate exterior angles. They are congruent.
So, the measure of x is 115°

Question 30.
PROJECT
Trace line p and line t on a piece of paper. Label ∠1. Move the paper so that ∠1 aligns with ∠8. Describe the transformations that you used to show that ∠1 is congruent to ∠8.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 35.2

Answer: 180° rotation, translation about line t.

Question 31.
OPEN-ENDED
Refer to the figure.
a. Do the horizontal lines appear to be parallel? Explain.

Answer: The three horizontal lines seem to spread apart, even though in reality they are parallel.

b. Draw your own optical illusion using parallel lines.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 36

Answer:
Big Ideas Math Solution Key Grade 8 Chapter 3 img_7

Question 32.
DIG DEEPER!
The figure shows the angles used to make a shot on an air hockey table.
a. Find the value of x.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 37

Answer:
As the lines AB and CD are parallel and ∠BCD are alternate interior angles transversal BC, they are congruent.
∠ABC ≅ ∠BCD
x = 64
b. How does the angle the puck hits the edge of the table relate to the angle it leaves the edge of the table?

Answer:
m∠MBA + m∠ABC + m∠CBN = 180°
58 ° + 64° + m∠CBN = 180°
122 ° + m∠CBN = 180°
m∠CBN = 180° – 122 °
m∠CBN = 58°

Lesson 3.2 Angles of Triangles

EXPLORATION 1

Exploring Interior and Exterior Angles of Triangles
Work with a partner.
a. Draw several triangles using geometry software. What can you conclude about the sums of the angle measures?
b. You can extend one side of a triangle to form an exterior angle as shown.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 38
Use geometry software to draw a triangle and an exterior angle. Compare the measure of the exterior angle with the measures of the interior angles. Repeat this process for several different triangles. What can you conclude?

Answer:

EXPLORATION 2
Using Parallel Lines and Transversals
Work with a partner. Describe what is shown in the figure below. Then use what you know about parallel lines and transversals to justify your conclusions in Exploration 1.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 39

Answer:

3.2 Lesson

Try It

Find the measures of the interior angles of the triangle.

Question 1.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 40

Answer: 81°, 25°, 74°

Explanation:
Sum of all the angles in a triangle = 180°
x° + 81° + 25° = 180°
x° = 180° – 81° – 25°
x = 74°
Thus the measure of the interior angle is 74°

Question 2.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 41

Answer: 43°, 51°, 86°

Explanation:
Sum of all the angles in a triangle = 180°
x° + (x – 35)° + 43° = 180°
x° + x° – 35° + 43° = 180°
2x° + 8° = 180°
2x° = 180° – 8°
2x° = 172°
x° = 172°/2
x° = 86°
The measure of the interior angle of the triangle
(x – 35)° = 86 – 35
(x – 35)° = 51°
x° = 51° + 35°
x° = 86°

Self-Assessment for Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 4.
VOCABULARY
How many exterior angles does a triangle have at each vertex? Explain.

Answer:
BIM 8th Grade Answers Chapter 3 img_8
At each vertex of a triangle, there are two exterior angles, which are congruent.

FINDING ANGLE MEASURES
Find the value of x.

Question 5.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 42

Answer:
Sum of all the angles in a triangle = 180°
x° + 25° + 40° = 180°
x° + 65° = 180°
x° = 180°
x° = 180° – 65°
x° = 115°
Thus the value of x is 115°

Question 6.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 43

Answer:
x° = 50° + 55°
x° = 105°
Thus the value of x is 105°

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 7.
The Historic Triangle in Virginia connects Jamestown, Williamsburg, and Yorktown. The interior angle at Williamsburg is 120°. The interior angle at Jamestown is twice the measure of the interior angle at Yorktown. Find the measures of the interior angles at Jamestown and Yorktown. Explain your reasoning.

Answer:
The interior angle at Williamsburg is 120°.
Let the interior angles at Jamestown be x°
Let the interior angles at Yorktown be 2x°
Big Ideas math Answers Grade 8 ch3 angles and triangle img_9
Sum of all the angles in a triangle = 180°
x° + 2x° + 120° = 180°
3x° + 120° = 180°
3x° = 180° – 120°
3x° = 60°
x° = 60/3
x° = 20°
The interior angles at Jamestown be x° = 20°
The interior angles at Yorktown be 2x° = 2(20)° = 40°

Question 8.
A helicopter travels from point C to point A to perform a medical supply drop. The helicopter then needs to land at point B. How many degrees should the helicopter turn at point A to travel towards point B? Justify your answer.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 44

Answer:
Given,
A helicopter travels from point C to point A to perform a medical supply drop.
The helicopter then needs to land at point B.
A = 90° + 32°
A = 122°
Thus the helicopter should turn 122° at point A to travel towards point B.

Angles of Triangles Homework & Practice 3.2

Review & Refresh

Use the figure to find the measure of the angle. Explain your reasoning.

Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 45

Question 1.
∠2

Answer: 82°

∠2 and 82° are alternate exterior angles formed by transversal intersecting parallel lines. The angles are congruent.
Thus the measure of ∠2 is 82°

Question 2.
∠6

Answer: 82°

∠6 and 82° are vertical angles formed by transversal intersecting parallel lines. The angles are congruent.
Thus the measure of ∠6 is 82°

Question 3.
∠4

Answer: 82°

∠4 and 82° are corresponding angles formed by transversal intersecting parallel lines. The angles are congruent.
Thus the measure of ∠4 is 82°

Question 4.
∠1

Answer: 98°

∠4 and 82° are corresponding angles formed by transversal intersecting parallel lines. The angles are congruent.
Thus the measure of ∠4 is 82°
∠4 and ∠1 are supplementary angles
∠4 + ∠1 = 180°
82° + ∠1 = 180°
∠1 = 180° – 82°
∠1 = 98°

You spin the spinner shown.

Question 5.
What are the favorable outcomes of spinning a number less than 4?

Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 46

Answer: 1, 2, 3

Explanation:
The favorable outcome of spinning a number less than 4 is 1, 2, and 3.

Question 6.
In how many ways can spinning an odd number occur?

Answer: two ways
Odd numbers = 1 and 3
So, in two ways spinning an odd number can occur.

Concepts, Skills, & Problem Solving

USING PARALLEL LINES AND TRANSVERSALS
Consider the figure below. (See Exploration 2, p. 111.)

Question 7.
Use a protractor to find the measures of the labeled angles.

Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 47

Answer:
Use a protractor to determine the measures of the angles A, B, C.
m∠A = 30°
m∠B = 105°
m∠C = 45°
m∠D = 150°
m∠E = 75°
m∠F = 105°
m∠G = 30°

Question 8.
Is ∠F an exterior angle of Triangle ABC ? Justify your answer.

Answer:
An exterior angle is the angle between one side of a triangle and the extension of an adjacent side. ∠F is not an exterior angle of triangle ABC because it has a side of triangle ABC, but not the extension of the adjacent side DF.

USING INTERIOR ANGLE MEASURES
Find the measures of the interior angles of the triangle.

Question 9.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 48

Answer:
Sum of all the angles in a triangle = 180°
x° + 90° + 30° = 180°
x° + 120° = 180°
x° = 180° – 120°
x° = 60°

Question 10.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 49

Answer:
Sum of all the angles in a triangle = 180°
x° + 65° + 40° = 180°
x° + 105° = 180°
x° = 180° – 105°
x° = 75°

Question 11.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 50

Answer:
Sum of all the angles in a triangle = 180°
x° + 35° + 45° = 180°
x° + 80° = 180°
x° = 180° – 80°
x° = 100°

Question 12.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 51

Answer:
Sum of all the angles in a triangle = 180°
x° + (x + 65)° + 25° = 180°
x° + x° + 65° + 25° = 180°
2x° + 90° = 180°
2x° = 180° – 90°
2x° = 90°
x° = 90°/2
x° = 45°
(x + 65)° = 45 + 65 = 110
x° = 25°

Question 13.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 52

Answer:
Sum of all the angles in a triangle = 180°
x° + (x – 44)° + 48° = 180°
x° + x° – 44° + 48° = 180°
2x° + 4° = 180°
2x° = 180° – 4°
2x° = 176°
x° = 176°/2
x° = 88°
(x – 44)° = 88 – 44 = 44
x° = 44°

Question 14.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 53

Answer:
Sum of all the angles in a triangle = 180°
x° + (x – 11)° + 73° = 180°
x° + x° – 11° + 73° = 180°
2x° + 62° = 180°
2x° = 180° – 62°
2x° = 118°
x° = 118°/2
x° = 59°
(x – 11)° = 59 – 11 = 48
x° = 48°

FINDING EXTERIOR ANGLE MEASURES
Find the measure of the exterior angle.

Question 15.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 54

Answer:
x° = 38° + 90°
x° = 128°
The measure of exterior angle is 128°

Question 16.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 55

Answer:
k° = 64° + 76°
k° = 140°
The measure of an exterior angle is 140°

Question 17.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 56

Answer:
2a° = (a + 10°) + 44°
2a° = a + 54°
2a° – a° = 54
a° = 54
The measure of the exterior angle = 2a = 2(54°) = 108°

Question 18.
MODELING REAL LIFE
A tornado is located between city hall and a cell phone tower and is heading towards the cell phone tower. By what angle does the tornado’s direction need to change so that it passes over the radar station instead? Justify your answer.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 57

Answer:
Sum of all the angles in a triangle = 180°
x° + 75° + 75° = 180°
x° + 150° – 150° = 180° – 150°
x° = 30°
Thus the angle that tornado direction needs to change is 30°.

Question 19.
YOU BE THE TEACHER
Your friend finds the measure of the exterior angle shown. Is your friend correct? Explain your reasoning.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 58

Answer:
Your friend is not correct because the measure of the exterior angle is equal to the sum of two non-adjacent interior angles.

Question 20.
REASONING
The ratio of the interior angle measures of a triangle is 2 : 3 : 5. What are the angle measures?

Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 59

Answer:
Sum of all the angles in a triangle = 180°
2x° + 3x° + 5x° = 180°
10x° = 180°
x = 180/10
x = 18°
2x° = 2(18°) = 36°
3x° = 3(18) = 54°
5x° = 5(18) = 90°

Question 21.
PROBLEM SOLVING
The support for a window air-conditioning unit forms a triangle and an exterior angle. What is the measure of the exterior angle?

Answer:
The measure of the exterior angle DBC is
m∠DBC = m∠ABC + m∠ACB
m∠ABC + m∠ACB = 90°
5x – 6 + 3x = 90
8x – 6 = 90
8x = 90 + 6
8x = 96
x = 96/8
x = 12
m∠DBC = m∠BAC+ m∠ACB
= 90° + 3(12)°
= 126°

Question 22.
REASONING
A triangle has an exterior angle with a measure of 120°. Can you determine the measures of the interior angles? Explain.

Answer:
A triangle has an exterior angle with a measure of 120°
m∠ACB = m∠A + m∠B
m∠A + m∠B = 120°
According to the exterior angles
We have
m∠C + m∠ACD = 180°
m∠C + 120° = 180°
m∠C = 180° – 120°
m∠C = 60°

ANGLES OF TRIANGLES

Determine whether the statement is always, sometimes, or never true. Explain your reasoning.

Question 23.
Given three angle measures, you can construct a triangle.

Answer:
We can construct a triangle if the sum of the measure of the 3 angles is 180°.
As a matter of fact, if the sum of the measures of the 3 angles is 180°
We can build an infinity of triangles that are similar.

Question 24.
The acute interior angles of a right triangle are complementary.

Answer:
Let A, B, C be the angles of a right triangle with m∠A = 90°
m∠A + m∠B + m∠C = 180°
90° + m∠B + m∠C = 180°
m∠B + m∠C = 180° – 90°
m∠B + m∠C = 90°
This means ∠B and ∠C are complementary.

Question 25.
A triangle has more than one vertex with an acute exterior angle.

Answer:
An exterior angle of a triangle and the adjacent triangle’s angle are complementary. If an exterior angle is acute, it means the adjacent triangle’s angle is obtuse.
Since we are given that more than one exterior angle is acute, it means the triangle would have more than one obtuse angle, which is impossible.
The statement is never true.

Question 26.
DIG DEEPER!
Using the figure at the right, show that z = x + y. (Hint: Find two equations involving w.)
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 60

Answer:
The angles z and w are supplementary
z + w = 180°
The sum of a triangle is 180°
x + y + w = 180°
z = 180° – w
x + y = 180° – w
z = x + y

Lesson 3.3 Angles of Polygons

EXPLORATION 1
Work with a partner. In parts (a)-(f), use what you know about the interior angle measures of triangles to find the sum of the interior angle measures of each figure.
Big Ideas Math Answer Key Grade 8 Chapter 3 Angles and Triangles 61
g. REPEATED REASONING
Use your results in parts (a)–(f) to complete the table. Then write an equation that represents the sum of the interior angle measures of a polygon with n sides.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 62

Answer:

3.3 Lesson

Try It

Find the sum of the interior angle measures of the green polygon.

Question 1.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 63

Answer:
S = (n – 2) . 180°
S = (7 – 2) . 180°
S = 5 . 180°
S = 900°
Thus the sum of the interior angle measure is 900°

Question 2.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 64

Answer:
S = (n – 2) . 180°
S = (6 – 2) . 180°
S = 4 . 180°
S = 720°
Thus the sum of the interior angle measure is 720°

Self-Assessment for Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 5.
WRITING
Explain how to find the sum of the interior measures of a polygon.

Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 65

Answer:
Steps to find the sum of the interior measurements of the polygon:
1. Count the number of sides of the polygon.
2. Subtract the number of sides by 2.
3. Multiply the result of the subtraction by 180°

Question 6.
FINDING THE SUM OF INTERIOR ANGLE MEASURES
Find the sum of the interior angle measures of the green polygon.

Answer:
S = (n – 2) . 180°
S = (4 – 2) . 180°
S = 2 . 180°
S = 360°
Thus the sum of the interior angle measure is 360°

FINDING AN INTERIOR ANGLE MEASURE

Find the value of x.

Question 7.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 66

Answer:
S = (n – 2) . 180°
S = (5 – 2) . 180°
S = 3 . 180°
S = 540°
Thus the sum of the interior angle measure is 540°
x° + 160° + 110° + 105° + 95° = 540°
x° + 470° = 540°
x° = 540° – 470°
x° = 70°
Thus the value of x is 70°.

Question 8.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 67

Answer:
S = (n – 2) . 180°
S = (9 – 2) . 180°
S = 7 . 180°
S = 1260°
Thus the sum of the interior angle measure is 1260°
x° + 165° + 155° + 150° + 140° + 135° + 130° + 125° + 110° = 1260°
x° + 1105° = 1260°
x° = 1260° – 1105°
x° = 155°
Thus the value of x is 155°

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 9.
A company installs an octagonal swimming pool.
a. Find the value of a for the pool shown at the left.

Answer:
S = (n – 2) . 180°
S = (8 – 2) . 180°
S = 6 . 180°
S = 1080°
Thus the sum of the interior angle measure is 1080°
a° + 120° + a° + 120° + a° + 120° + a° + 120° = 1080°
4a° + 480° = 1080°
4a° = 1080° – 480°
4a° = 600°
a° = 600/4
a° = 150°
Thus the value of x is 150°.

b. The company installs a different pool that is also in the shape of an octagon. The second pool has twice the length and one-third the width of the first pool. Are the sums of the interior angles of the pools different? Justify your answer.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 67.1

Answer:
No for any octagon the sum of the interior angles is 1080 degrees.

Question 10.
DIG DEEPER!
A Bronze Star Medal A is shown.
a. How many interior angles are there?

Answer: 10 interior angles are there

b. What is the sum of the interior angle measures?
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 68

Answer:
S = (n – 2) . 180°
S = (10 – 2) . 180°
S = 8 . 180°
S = 1440°
Thus the sum of the interior angle measure is 1440°

Angles of Polygons Homework & Practice 3.3

Find the value of x.

Question 1.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 69

Answer: 60°

Explanation:
Sum of all the angles = 180°
x° + 60° + 60° = 180°
x° + 120° = 180°
x° = 180° – 120°
x° = 60°

Question 2.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 70

Answer: 45°

Explanation:
Sum of all the angles = 180°
x° + x° + 90° = 180°
2x° + 90° = 180°
2x° = 180° – 90°
2x° = 90°
x° = 45°

Question 3.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 71

Answer: 113°

Explanation:
x° = 65° + 48°
x° = 113°
Thus the measure of an exterior angle is 113°

Solve the proportion.

Question 4.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 72

Answer: 9

Explanation:
\(\frac{x}{12}\) = \(\frac{3}{4}\)
12 . \(\frac{x}{12}\) = \(\frac{3}{4}\) . 12
x = 3 . 3
x = 9

Question 5.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 73

Answer: 2

Explanation:
\(\frac{14}{21}\) = \(\frac{x}{3}\)
3 . \(\frac{14}{21}\) = \(\frac{x}{3}\) . 3
x = 2

Question 6.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 74

Answer: 3

Explanation:
\(\frac{9}{x}\) = \(\frac{6}{2}\)
2. \(\frac{9}{x}\) = 6
18 = 6x
x = 3

Concepts, Skills, & Problem Solving
EXPLORING INTERIOR ANGLES OF POLYGONS
Use triangles to find the sum of the interior angle measures of the polygon. (See Exploration 1, p. 117.)

Question 7.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 75

Answer: 360°

Explanation:
Number of sides = 4
Number of interior triangles in the given figure = 2
The Sum of the measures of the interior angles using triangle = 2 . 180° = 360°

Question 8.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 76

Answer: 1260°

Explanation:
Number of sides = 9
Number of interior triangles in the given figure = 7
The Sum of the measures of the interior angles using triangle = 7 . 180° = 1260°

Question 9.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 77

Answer: 540°

Explanation:
Number of sides = 5
Number of interior triangles in the given figure = 3
The Sum of the measures of the interior angles using triangle = 3 . 180° = 540°

FINDING THE SUM OF INTERIOR ANGLE MEASURES
Find the sum of the interior angle measures of the polygon.

Question 10.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 78

Answer: 360°

Explanation:
S = (n – 2) . 180°
S = (4- 2) . 180°
S = 2 . 180°
S = 360°
Thus the sum of the interior angle measure is 360°

Question 11.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 79

Answer: 1080°

Explanation:
S = (n – 2) . 180°
S = (8- 2) . 180°
S = 6 . 180°
S = 1080°
Thus the sum of the interior angle measure is 1080°

Question 12.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 80

Answer: 1260°

Explanation:
S = (n – 2) . 180°
S = (9- 2) . 180°
S = 7 . 180°
S = 1260°
Thus the sum of the interior angle measure is 1260°

Question 13.
YOU BE THE TEACHER
Your friend finds the sum of the interior angle measures of a 13-gon. Is your friend correct? Explain your reasoning.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 81

Answer:
To find the sum of the interior angle measures he should subtract 2 from the number of sides of the polygon and then multiply by 180°
S = (n – 2) . 180°
By this, we can say that your friend is not correct.

FINDING AN INTERIOR ANGLE MEASURE
Find the value of x.

Question 14.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 82

Answer:
S = (n – 2) . 180°
S = (4- 2) . 180°
S = 2 . 180°
S = 360°
Thus the sum of the interior angle measure is 360°
x° + 155° + 25° + 137° = 360°
x° + 317° = 360°
x° = 360° – 317°
x° = 43°

Question 15.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 83

Answer:
S = (n – 2) . 180°
S = (6- 2) . 180°
S = 4 . 180°
S = 720°
Thus the sum of the interior angle measure is 720°
x° + x° + x° + x° + 90° + 90° = 720°
4x° + 180° = 720°
4x° = 720° – 180°
4x° = 540°
x° = 540/4
x° = 135°

Question 16.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 84

Answer:
S = (n – 2) . 180°
S = (6- 2) . 180°
S = 4 . 180°
S = 720°
Thus the sum of the interior angle measure is 720°
3x° + 45° + 135° + x° + 135° + 45° = 720°
4x° + 360° = 720°
4x° = 720° – 360°
4x° = 360°
x° = 360/4
x° = 90°

FINDING A MEASURE
Find the measure of each interior angle of the regular polygon.

Question 17.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 85

Answer:
S = (n – 2) . 180°
S = (3- 2) . 180°
S = 1 . 180°
S = 180°
Thus the sum of the interior angle measure is 180°
In a regular polygon, each interior angle is congruent. So, divide the sum of the interior angle measures by the number of interior angles, 3.
180 ÷ 3 = 60°

Question 18.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 86

Answer:

S = (n – 2) . 180°
S = (9 – 2) . 180°
S = 7 . 180°
S = 1260°
Thus the sum of the interior angle measure is 1260°
In a regular polygon, each interior angle is congruent. So, divide the sum of the interior angle measures by the number of interior angles, 9.
1260 ÷ 9 = 140°

Question 19.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 87

Answer:

S = (n – 2) . 180°
S = (12 – 2) . 180°
S = 10 . 180°
S = 1800°
Thus the sum of the interior angle measure is 1800°
In a regular polygon, each interior angle is congruent. So, divide the sum of the interior angle measures by the number of interior angles, 12.
1800 ÷ 12 = 150°

Question 20.
YOU BE THE TEACHER
Your friend finds the measure of each interior angle of a regular 20-gon. Is your friend correct? Explain your reasoning.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 88

Answer:
No, my friend is not correct because to find the measure of each interior angle of a regular 20-gon, he should divide the sum of the measured interior angles by the number of interior angles, in this case, 20 but your friend divide it by 18 so he is not correct.

Question 21.
MODELING REAL LIFE
A firehydrant bolt is in the shape of a regular pentagon.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 89
a. What is the measure of each interior angle?

Answer:
S = (n – 2) . 180°
S = (5- 2) . 180°
S = 3 . 180°
S = 540°
Thus the sum of the interior angle measure is 540°
In a regular polygon, each interior angle is congruent. So, divide the sum of the interior angle measures by the number of interior angles, 5.
540÷ 5 = 108°

b. RESEARCH
Why are firehydrants made this way?

Question 22.
PROBLEM SOLVING
The interior angles of a regular polygon each measure 165°. How many sides does the polygon have?

Answer:
(n – 2) . 180 = 165 . n
180n – 360 = 165n
180n – 360 + 360 – 165n = 165n + 360 – 165n
15n = 360
n = 360/15
n = 24
Therefore the polygon has 24 sides

Question 23.
STRUCTURE
A molecule can be represented by a polygon with interior angles that each measure 120°. What polygon represents the molecule? Does the polygon have to be regular? Justify your answers.

Answer:
(n – 2) . 180 = 120 . n
180n – 360 = 120n
180n – 120n = 360
60n = 360
n = 6

Question 24.
PROBLEM SOLVING
The border of a Susan B. Anthony dollar is in the shape of a regular polygon.
a. How many sides does the polygon have?

Answer: The polygon has 11 sides.

b. What is the measure of each interior angle of the border? Round your answer to the nearest degree.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 91

Answer:
S = (n – 2) . 180°
S = (11 – 2) . 180°
S = 9 . 180°
S = 1620°
Thus the sum of the interior angle measure is 1620°
In a regular polygon, each interior angle is congruent. So, divide the sum of the interior angle measures by the number of interior angles, 11.
1620 ÷ 11 = 147°

Question 25.
REASONING
The center of the stained glass window is in the shape of a regular polygon. What are the measures of the interior angles of the green triangle?

Answer:
(n-2)180°/n = (8-2)180°/8 = 135°
m∠OAB = m∠OBA = 135/2 = 67.5°
m∠AOB + m∠OAB + m∠OBA = 180°
m∠AOB + 67.5° + 67.5° = 180°
m∠AOB + 135° = 180°
m∠AOB = 180° – 135°
m∠AOB = 45°

Question 26.
GEOMETRY
Draw a pentagon that has two right interior angles, two 45° interior angles, and one 270° interior angle.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 92

Answer:
Big Ideas Math 8th Grade Solution Key Ch 3 Angles and Triangles img_9
Big Ideas Math 8th Grade Solution Key Ch 3 Angles and Triangles img_10

Question 27.
DIG DEEPER!
The floor of a gazebo is in the shape of a heptagon, a seven-sided polygon. Four of the interior angles measure 135°. The other interior angles have equal measures. Find their measures.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 93

Answer:
The given polygon has 7 sides.
S = (n – 2) . 180°
S = (7 – 2) . 180°
S = 5 . 180°
S = 900°
Thus the sum of the interior angle measure is 900°
4 . 135° + 3 . x° = 900°
540° + 3x° = 900°
3x° = 900° – 540°
3x° = 360°
x° = 360/3
x° = 120°

Lesson 3.4 Using Similar Triangles

Using Similar Triangles

EXPLORATION 1

Work with a partner. Use geometry software.
a. Draw a triangle that has a 50° angle and a 30° angle. Then draw a triangle that is either larger or smaller that has the same two angle measures. Are the triangles congruent? similar? Explain your reasoning.
a. Choose any two angle measures whose sum is less than 180°. Repeat part(a) using the angle measures you chose.
c. Compare your results in parts (a) and (b) with other pairs of students. Make a conjecture about two triangles that have two pairs of congruent angles.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 93.1

Answer:

EXPLORATION 2
Using Indirect Measurement
Work with a partner. Use the fact that two rays from the Sun are parallel to make a plan for how to find the height of the flagpole. Explain your reasoning.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 94

Answer:

3.4 Lesson

Try It

Tell whether the triangles are similar. Explain.

Question 1.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 95

Answer: No

Explanation:
x° + 28° + 80° = 180°
x° + 108° = 180°
x° = 180° – 108°
x° = 72°
BIM Grade 8 Answer Key Chapter 3 Angles and triangles img_11
y° + 28° + 71° = 180°
y° + 99° = 180°
y° = 180° – 99°
y° = 81°
The triangles do not have two pairs of congruent angles.
So, the triangles are not similar.

Question 2.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 96

Answer: Yes

Explanation:
x° + 66° + 90° = 180°
x° + 156° = 180°
x° = 180° – 156°
x° = 24°
y° + 24° + 90° = 180°
y° + 114° = 180°
y° = 180° – 114°
y° = 66°
The triangles have two pairs of congruent angles.
Thus the triangles are similar.

Try It

Question 3.
Can you determine whether △PQR and △TSRand are similar? Explain.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 97

Answer: No

Explanation:
We are not given any information about the lengths of the sides either, therefore with only a pair of congruent angles, we cannot tell whether the triangles are similar.

Self-Assessment for Concepts & Skills

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 4.
IDENTIFYING SIMILAR TRIANGLES
Tell whether the triangles are similar. Explain.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 98

Answer: Yes

Explanation:
x° + 54° + 63° = 180°
x° + 107° = 180°
x° = 180° – 107°
x° = 63°

Question 5.
DIFFERENT WORDS, SAME QUESTION
Which is different? Find “both” answers.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 98.1
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 99

Answer: Option B

Explanation:
ΔPQR and ΔTSR are congruent as TS || PQ leads to two pairs of correspondent congruent angles.
ΔPQR is a dilation of ΔTSR because their sides are proportional, the constant of proportionality being greater than 1.
ΔPQR is a scale drawing of ΔTSR because their sides are proportional.
The question that does not fit is
“Are ΔPQR and ΔTSR the same size and shape?”
because the triangles do not have the same size, but they have the same shape.

Self-Assessment for Problem Solving

Solve each exercise. Then rate your understanding of the success criteria in your journal.

Question 6.
DIG DEEPER!
Engineers plan to construct an aqueduct to transport water from the top of a ridge to farmland. A portion of the project is complete. Find the length of the entire aqueduct.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 100
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 101

Answer:
Aqueduct/2.6 = 5/1
Aqueduct = 5 × 2.6
Aqueduct = 13
Thus the length of the Aqueduct is 13 km.

Question 7.
You want to go on a swamp tour. How long does it take a swamp vehicle that travels at 3.2 miles per hour to travel across the swamp, from point Z to point Y? Justify your answer.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 102

Answer:
a/10 = 3/6
6 × a = 3 × 10
6a = 30
a = 30/6
a = 5
The length from point Z to point Y is 5 miles.
Time to travel from point Z to point Y = 5/3.5 = 1.56 hour

Using Similar Triangles Homework & Practice 3.4

Review & Refresh

Find the measure of each interior angle of the regular polygon.

Question 1.
octagon

Answer: The measure of each interior angle is 135°

Explanation:
S = (n – 2) . 180°
S = (8- 2) . 180°
S = 6 . 180°
S = 1080°
Thus the sum of the interior angle measure is 1080°
In a regular polygon, each interior angle is congruent. So, divide the sum of the interior angle measures by the number of interior angles, 8.
1080÷ 8= 135°

Question 2.
decagon

Answer: The measure of each exterior angle is 144°

Explanation:
S = (n – 2) . 180°
S = (10 – 2) . 180°
S = 8 . 180°
S = 1440°
Thus the sum of the interior angle measure is 1440°
In a regular polygon, each interior angle is congruent. So, divide the sum of the interior angle measures by the number of interior angles, 10.
1440÷ 10= 144°

Question 3.
18-gon

Answer: The measure of each interior angle is 160°

Explanation:
S = (n – 2) . 180°
S = (18- 2) . 180°
S = 16 . 180°
S = 2880°
Thus the sum of the interior angle measure is 2880°
In a regular polygon, each interior angle is congruent. So, divide the sum of the interior angle measures by the number of interior angles, 18.
2880 ÷ 18= 160°

Solve the equation. Check your solution.

Question 4.
3.5 + y = -1

Answer:
Given the equation
3.5 + y = -1
y = -1 – 3.5
y = -4.5

Question 5.
9x = 54

Answer:
Given the equation
9x = 54
x = 54/9
x = 6

Question 6.
-4 = \(\frac{2}{7}\)p

Answer:
Given the equation
-4 = \(\frac{2}{7}\)p
-4 × 7 = 2p
2p = -28
p = -28/2
p = -14

Concepts, Skills, & Problem Solving
CREATING SIMILAR TRIANGLES
Draw a triangle that is either larger or smaller than the one given and has two of the same angle measures. Explain why the new triangle is similar to the original triangle. (See Exploration 1, p. 123.)

Question 7.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 103

Answer:
BIM Answers for Grade 8 chapter 3 img_12
The above triangle and the given triangle are similar because the two angles in both the triangles are the same so the third angle is also the same.

Question 8.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 104

Answer:
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 104
The above triangle and the given triangle are similar because the two angles in both the triangles are the same so the third angle is also the same.

IDENTIFYING SIMILAR TRIANGLES
Tell whether the triangles are similar. Explain.

Question 9.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 105

Answer: The triangles have two pairs of congruent angles.
So, the third angles are congruent, and the triangles are similar.

Question 10.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 106

Answer:
x° + 36° + 72° = 180°
x° + 108° = 180°
x° = 180° – 108°
x° = 72°
y° + 33° + 72° = 180°
y° + 105° = 180°
y° = 180° – 105°
y° = 72°
The triangles do not have two pairs of congruent angles.
Therefore the triangles are not similar.

Question 11.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 107

Answer:
x° + 64° + 85° = 180°
x° + 149° = 180°
x° = 180° – 149°
x° = 31°
y° + 26° + 85° = 180°
y° + 111° = 180°
y° = 180° – 111°
y° = 69°
The triangles do not have two pairs of congruent angles.
Therefore the triangles are not similar.

Question 12.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 108

Answer:
x° + 48° + 81° = 180°
x° + 129° = 180°
x° = 180° – 129°
x° = 51°
y° + 48° + 51° = 180°
y° + 99° = 180°
y° = 180° – 99°
y° = 81°
The triangles have two pairs of congruent angles.
Therefore the triangles are similar.

Question 13.
GEOMETRY
Which of the rulers are similar in shape? Explain.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 109

Answer:
2x + 90 = 180°
2x = 180 – 90°
2x = 90°
x = 90/2
x = 45°
The ruler on the left and the ruler on the right both have the shape of a right triangle with 45° angles, therefore they are similar in shape, while the middle ruler has 60°, 30° angles.

STRUCTURE
Tell whether the triangles are similar. Explain.

Question 14.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 110

Answer:
m∠APB + m∠B = 90°
m∠APB + 51° = 90°
m∠APB = 90° – 51°
m∠APB = 39°
m∠APB + m∠BPD + m∠DPC = 180°
39° + 102° + m∠DPC = 180°
m∠DPC + 141° = 180
m∠DPC = 180 – 141°
m∠DPC = 39°
m∠A = m∠C
m∠APB = m∠DPC

Question 15.
Big Ideas Math Answers 8th Grade Chapter 3 Angles and Triangles 111

Answer:
∠APB ≅ ∠CPD
m∠APB = m∠CPD
m∠APB = 29°
m∠A + m∠B + m∠APB = 180°
m∠A + 88° + 29° = 180°
m∠A  + 117° = 180°
m∠A = 180° – 117°
m∠A = 63°
m∠PDC + m∠PDE = 180°
m∠PDC + 91° = 180°
m∠PDC = 180° – 91°
m∠PDC = 89°

IDENTIFYING SIMILAR TRIANGLES
Can you determine whether the triangles are similar? Explain.

Question 16.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 112

Answer:
PS || QR
∠PSQ and ∠SQR are interior angles using the transversal QS, thus they are congruent.
∠PSQ ≅ ∠SQR

Question 17.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 113

Answer:
As AB || DE there are two pairs of congruent alternate interior angles, using the transversals AE and BD.
∠A≅ ∠E
∠B≅ ∠D
The two pairs of congruent angles are enough to prove that the triangles are similar.
ΔABC ∼ ΔEDC

Question 18.
PROBLEM SOLVING
A water sample must be taken from water atleast 20 feet deep. Find the depth of the water 50 feet from shore. Is this an appropriate location for a water sample?
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 114

Answer:
ΔAMN ∼ ΔABC
MN/BC = AM/AB
1.5/d = 5/50
d = 1.5 × 10
d = 15 feet
Therefore 15 feet is not an appropriate location.

Question 19.
MODELING REAL LIFE
A map shows the number of steps you must take to get to a treasure. However, the map is old, and the last dimension is unreadable. Explain why the triangles are similar. How many steps do you take from the pyramids to the treasure?
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 115

Answer:
The two triangles are similar because they are right triangles and ∠AXB ≅ ∠PXQ because they are vertical angles.
PQ/300 = 80/240
240PQ = 24000
PQ = 24000/240
PQ = 100 steps

Question 20.
PROBLEM SOLVING
A person who is 6 feet tall casts a 3-foot-long shadow. A nearby pine tree casts a 15-foot-long shadow. What is the height h of the pine tree?
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 116

Answer:
Given,
A person who is 6 feet tall casts a 3-foot-long shadow.
A nearby pine tree casts a 15-foot-long shadow.
ΔXAB ∼ ΔXPQ
AB/PQ = XB/XQ
6/PQ = 3/15
PQ = 30 ft

Question 21.
OPEN-ENDED
You place a mirror on the ground 6 feet from the lamppost. You move back 3 feet and see the top of the lamppost in the mirror. What is the height of the lamppost?

Answer:
Grade 8 BIM Chapter 3 Answer Key img_13
ΔXAB ∼ ΔXPQ
AB/PQ = XB/XQ
h/PQ = 6/3
h = 2PQ

Question 22.
DIG DEEPER!
In each of two right triangles, one angle measure is two times another angle measure. Can you determine that the triangles are similar? Explain your reasoning.

Answer:
We are given the right triangle ABC
m∠A = 2m∠B
Case 1:
m∠A = 90°
90° = 2m∠B
m∠B = 45°
m∠C = 180° – 90° – 45° = 45°
Case 2:
m∠B = 90°
m∠A = 2 × 90° = 180°
Case 3:
m∠C = 90°
m∠A + m∠B = 180 – m∠C = 180° – 90° = 90°
2m∠B + m∠B = 90°
3m∠B = 90°
m∠B = 30°
m∠A = 2 . 30° = 60°

Question 23.
GEOMETRY
In the diagram, \(\overline{B G}\), \(\overline{C F}\) and \(\overline{D E}\) are parallel. The length of \(\overline{B D}\) is 6.32 feet, and the length of \(\overline{D E}\) is 6 feet. Name all pairs of similar triangles in the diagram. Then find the lengths of \(\overline{B G}\) and \(\overline{C F}\)
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 117

Answer:
ΔABG ∼ ΔACF
ΔACF ∼ ΔADE
ΔABG ∼ ΔADE
AB = BC = CD = BD/2 = 6.32/2 = 3.16
AB/CD = BG/DE
3BG = 6
BG = 2 feet
ΔACF ∼ ΔADE
AC/AD = CF/DE
2/3 = CF/6
3CF = 2(6)
CF = 4 feet

Angles and Triangles Connecting Concepts

Using the Problem-Solving Plan

Question 1.
A dog park is divided into sections for large and small dogs. The ratio of the perimeter of the small dog section to the perimeter of the entire dog park is 7 : 12. Find the area of each section.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 118

Understand the problem
You know two dimensions of a dog park and the ratio of the perimeter of the small dog section to the perimeter of the entire park. You are asked to find the area of each section.
Make a plan
Verify that the small triangle and the large triangle are similar. Then use the ratio of the perimeters to find the base or the height of each triangle and calculate the areas.
Solve and check.
Use the plan to solve the problem. Then check your solution.

Answer:

Question 2.
You rotate lines m and t 180° about point P. The image of line m is parallel to the original line. Use the diagram to show that when a transversal intersects parallel lines, each of the following pairs of angles are congruent. Explain your reasoning.
a. alternate interior angles
b. alternate exterior angles
c. corresponding angles
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 119

Answer:

Performance Task

Turtle Shells

At the beginning of this chapter, you watched a STEAM Video called “Honeycombs.” You are now ready to complete the performance task related to this video, available at BigIdeasMath.com. Be sure to use the problem-solving plan as you work through the performance task.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 120

Angles and Triangles Chapter Review

Review Vocabulary

Write the definition and give an example of each vocabulary term.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 121

Graphic Organizers
You can use an Example and Non-Example to list examples and non-examples of a concept. Here is an Example and Non-Example Chart for transversals.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 122

Choose and complete a graphic organizer to help you study the concept.

  1. interior angles formed by parallel lines and a transversal
  2. exterior angles formed by parallel lines and a transversal
  3. interior angles of a triangle
  4. exterior angles of a triangle
  5. polygons
  6. similar triangles

Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 123

Chapter Self-Assessment

As you complete the exercises, use the scale below to rate your understanding of the success criteria in your journal.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 124

3.1 Parallel Lines and Transversals (pp. 103–110)

Use the figure to find the measure of the angle. Explain your reasoning.

Question 1.
∠8

Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 125

Answer: 140°

Explanation:
∠8 and 140 degrees angle are alternate exterior angles formed by a transversal intersecting parallel lines. The angles are congruent.
So, the measure of ∠8 is 140°

Question 2.
∠5

Answer: 140°

Explanation:
∠5 and 140 degrees angle are corresponding angles formed by a transversal intersecting parallel lines. The angles are congruent.
So, the measure of ∠5 is 140°

Question 3.
∠7

Answer: 40°

Explanation:
∠5 and 140 degrees angle are corresponding angles formed by a transversal intersecting parallel lines. The angles are congruent.
So, the measure of ∠5 is 140°
∠5 and ∠7 are supplementary angle.
∠5 + ∠7 = 180°
140° + ∠7 = 180°
∠7 = 180° – 140°
∠7 = 40°
So, the measure of ∠7 is 40°

Question 4.
∠2

Answer: 40°

Explanation:
140 and ∠2 are supplementary angle.
140° + ∠2 = 180°
∠2 = 180° – 140°
∠2 = 40°
So, the measure of ∠2 is 40°

Question 5.
∠6

Answer: 40°

Explanation:
∠5 and 140 degrees angle are corresponding angles formed by a transversal intersecting parallel lines. The angles are congruent.
So, the measure of ∠5 is 140°
∠5 and ∠6 are supplementary angle.
140° + ∠6 = 180°
∠6 = 180° – 140°
∠6 = 40°
So, the measure of ∠6 is 40°

Complete the statement. Explain your reasoning.

Question 6.
If the measure of ∠1 = 123°, then the measure of ∠7 = Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 126

Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 127

Answer: 123°

Explanation:
∠1 and ∠7 are alternate exterior angles formed by a transversal intersecting parallel lines. The angles are congruent.
So, the measure of ∠7 is 123°

Question 7.
If the measure of ∠2 = 58°, then the measure of Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 127.1

Answer: 122°

Explanation:
∠2 and ∠6 are corresponding angles formed by a transversal intersecting parallel lines. The angles are congruent.
So, the measure of ∠6 is 58°
∠5 and ∠6 are supplementary angle.
∠5 + ∠6 = 180°
58° + ∠5 = 180°
∠5 = 180° – 58°
∠5 = 122°
So, the measure of ∠5 is 122°

Question 8.
If the measure of ∠5 = 119°, then the measure of Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 128

Answer: 119°

Explanation:
∠3 and ∠5 are alternate interior angles formed by a transversal intersecting parallel lines. The angles are congruent.
So, the measure of ∠3 is 119°

Question 9.
If the measure of ∠4 = 60°, then the measure of Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 129

Answer: 60°

Explanation:
∠4 and ∠6 are alternate exterior angles formed by a transversal intersecting parallel lines. The angles are congruent.
So, the measure of ∠4 is 60°

Question 10.
In Exercises 6–9, describe the relationship between ∠2 and ∠8.

Answer: ∠2 ≅ ∠8

Question 11.
In a park, a bike path and a horse riding path are parallel. In one part of the park, a hiking trail intersects the two paths. Find the measures of ∠1 and ∠2. Explain your reasoning.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 129.1

Answer: ∠1 = 108°, ∠2 = 108°

Explanation:
∠3 and 72° are alternate interior angles. They are congruent.
So, the measure of ∠3 is 72°
∠3 + ∠1 = 180°
72° + ∠1 = 180°
∠1 = 180° – 72°
∠1 = 108°
So, the measure of ∠1 is 108°
∠1 and ∠2 are alternating interior angles. They are congruent.

3.2 Angles of Triangles (pp. 111 – 116)

Find the measures of the interior angles of the triangle.

Question 12.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 129.2

Answer:
Sum of all the angles in a triangle = 180°
x° + 50° + 55° = 180°
x° + 105° = 180°
x° = 180° – 105°
x° = 75°

Question 13.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 130

Answer:
Sum of all the angles in a triangle = 180°
x° + (x + 8)° + 90° = 180°
2x° + 8° + 90° = 180°
2x° + 98° = 180°
2x° = 180° – 98°
2x° = 82
x° = 82/2
x° = 41°
(x + 8)° = (41 + 8)° = 49°

Find the measure of the exterior angle.

Question 14.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 131

Answer:
s° = 50° + 75°
s° = 125°
Thus the measure of the exterior angle is 125°

Question 15.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 132

Answer:
Sum of all the angles in a triangle = 180°
t° + (t + 10)° + (t + 20)° = 180°
3t° + 10° + 20° = 180°
3t° + 30° = 180°
3t° = 180° – 30°
3t° = 150°
t° = 150/3
t° = 50°
Exterior angle:
t° + (t + 10)°
t° + t° + 10°
2t° + 10°
2(50)° + 10°
= 100° + 10°
= 110°
Thus the measure of the exterior angle is 110°.

Question 16.
What is the measure of each interior angle of an equilateral triangle? Explain.

Answer:
S = (n – 2) . 180°
S = (3- 2) . 180°
S = 1 . 180°
S = 180°
Thus the sum of the interior angle measure is 180°
In a regular polygon, each interior angle is congruent. So, divide the sum of the interior angle measures by the number of interior angles, 3.
180 ÷ 3 = 60°

Question 17.
You draw the Leo constellation. You notice that the three stars Denebola, Zosma, and Chertan form a triangle. In your drawing, you find the measure of the interior angle at Denebola is 30° and the measure of the interior angle of the triangle at Zosma is 56°. What is the measure of the interior angle of the triangle at Chertan?
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 133

Answer:
Sum of all the angles in a triangle = 180°
x° + 30° + 56° = 180°
x° + 86° = 180°
x° = 180° – 86°
x° = 94°
Thus the measure of the interior angle of the triangle at Chertan = 94°

3.3 Angles of Polygons (pp. 117–122)

Find the sum of the interior angle measures of the polygon.

Question 18.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 134

Answer:
The polygon has 13 sides
S = (n – 2) . 180°
S = (13- 2) . 180°
S = 11 . 180°
S = 1980°
Thus the sum of the interior angle measure is 1980°

Question 19.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 135

Answer:
The polygon has 9 sides
S = (n – 2) . 180°
S = (9- 2) . 180°
S = 7 . 180°
S = 1260°
Thus the sum of the interior angle measure is 1260°

Find the value of x.

Question 20.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 136

Answer:
S = (n – 2) . 180°
S = (4 – 2) . 180°
S = 2 . 180°
S = 360°
Thus the sum of the interior angle measure is 360°
x° + 60° + 128° + 95° = 360°
x° + 283° = 360°
x° = 360° – 283°
x° = 77°
Thus the value of x is 77°.

Question 21.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 137

Answer:
S = (n – 2) . 180°
S = (7 – 2) . 180°
S = 5 . 180°
S = 900°
Thus the sum of the interior angle measure is 900°
x° + 135° + 125° + 135° + 105° + 150° + 140° = 900°
x° + 790° = 900°
x° = 900° – 790°
x° = 110°

Question 22.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 138

Answer:
S = (n – 2) . 180°
S = (6 – 2) . 180°
S = 4 . 180°
S = 720°
Thus the sum of the interior angle measure is 720°
x° + 120° + 140° + 92° + 125° + 130° = 720°
x° + 607° = 720°
x° = 720° – 607°
x° = 113°
The value of x° is 113°

Question 23.
Find the measure of each interior angle of the regular polygon.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 139

Answer:
The given polygon is an octagon. It has 8 sides.
S = (n – 2) . 180°
S = (8 – 2) . 180°
S = 6 . 180°
S = 1080°
Thus the sum of the interior angle measure is 1080°
In a regular polygon, each interior angle is congruent. So, divide the sum of the interior angle measures by the number of interior angles, 8.
1080 ÷ 3 = 135°

3.4 Using Similar Triangles (pp. 123–128)

Tell whether the triangles are similar. Explain.

Question 24.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 140

Answer:
x° + 68° + 90° = 180°
x° = 180° – 158°
x° = 22°
y° + 22° + 90° = 180°
y° + 112° = 180°
y° = 180° – 112°
y° = 68°
The triangles have two pairs of congruent angles.
So, the triangles are similar.

Question 25.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 141

Answer:
x° + 100° + 30° = 180°
x° + 130° = 180°
x° = 180° – 130°
x° = 50°
y° + 100° + 50° = 180°
y° + 150° = 180°
y° = 180° – 150°
y° = 30°
The triangles have two pairs of congruent angles.
So, the triangles are similar.

Question 26.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 142

Answer:
x° + 50° + 85° = 180°
x° + 135° = 180°
x° = 180° – 135°
x° = 45°
y° + 85° + 35° = 180°
y° + 120° = 180°
y° = 180° – 120°
y° = 60°
The triangles do not have two pairs of congruent angles.
So, the triangles are not similar.

Question 27.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 143

Answer:
∠B ≅ ∠D
∠A ≅ ∠C
∠AXB ≅ ∠CXD
∠AXB and ∠CXD are vertical angles.
ΔAXB ∼ ΔCXD

Question 28.
A person who is 5 feet tall casts a shadow that is 4 feet long. A nearby building casts a shadow that is 24 feet long. What is the height of the building?

Answer:
Given,
A person who is 5 feet tall casts a shadow that is 4 feet long.
A nearby building casts a shadow that is 24 feet long.
Let the height of the building = x ft
x/24 = 5/4
24 . x/24 = 5/4 . 24
x = 30
Thus the height of the building is 30 ft.

Angles and Triangles Practice Test

Practice Test

Use the figure to find the measure of the angle. Explain your reasoning.

Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 144

Question 1.
∠7

Answer: 47°

Explanation:
∠7 and 47° angles are alternate exterior angles formed by a transversal intersecting parallel lines. The angles are congruent.
Thus the measure of ∠7 is 47°

Question 2.
∠6

Answer: 47°

Explanation:
∠6 and 47° angles are corresponding angles formed by a transversal intersecting parallel lines. The angles are congruent.
Thus the measure of ∠6 is 47°

Question 3.
∠4

Answer: 133°

Explanation:
∠4 and 47° are supplementary angles.
47° + ∠4 = 180°
∠4 = 180° – 47°
∠4 = 133°
Thus the measure of ∠4 = 133°

Question 4.
∠5

Answer: 133°

Explanation:
∠6 and 47° angles are corresponding angles formed by transversal intersecting parallel lines. The angles are congruent.
Thus the measure of ∠6 is 47°
∠6 + ∠5 = 180°
47° + ∠5 = 180°
∠5 = 180° – 47°
∠5 = 133°
Thus the measure of ∠5 = 133°

Question 5.
Find the value of x.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 144.1

Answer: 28°

Explanation:
Sum of all the angles in a triangle = 180°
x° + 129° + 23° = 180°
x° + 152° = 180°
x° = 180° – 152°
x° = 28°
Thus the value of x° is 28°

Question 6.
Find the measures of the interior angles.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 145

Answer: 68°

Explanation:
Sum of all the angles in a triangle = 180°
x° + (x – 24)° + 68° = 180°
x° + x° – 24° + 68° = 180°
2x° + 44° = 180°
2x° = 180° – 44°
2x° = 136°
x° = 68°
(x – 24)° = (68 – 24)° = 44°

Question 7.
Find the measure of the exterior angle.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 146

Answer:
j° = 40° + 90°
j° = 130°
The measure of an exterior angle is 130°.

Question 8.
Find the measure of the interior angle measures of the border of the coin.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 147

Answer:
The coin has 7 sides.
S = (n – 2) . 180°
S = (7 – 2) . 180°
S = 5 . 180°
S = 900°
Thus the sum of the interior angle measure is 900°

Question 9.
Find the value of x.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 148

Answer:
S = (n – 2) . 180°
S = (5 – 2) . 180°
S = 3 . 180°
S = 540°
Thus the sum of the interior angle measure is 540°
2x° + 125° + 90° + 2x° + 125° = 540°
4x° + 340° = 540°
4x° = 540° – 340°
4x° = 200°
x° = 200/4
x° = 50°
The value of x° is 50°

Question 10.
Find the measure of each interior angle of the regular polygon.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 149

Answer:
S = (n – 2) . 180°
S = (6 – 2) . 180°
S = 4 . 180°
S = 720°
Thus the sum of the interior angle measure is 720°
In a regular polygon, each interior angle is congruent. So, divide the sum of the interior angle measures by the number of interior angles, 6.
720 ÷ 6 = 120°

Tell whether the triangles are similar. Explain.

Question 11.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 150

Answer:
To find x°:
x° + 61° + 70° = 180°
x° + 131° = 180°
x° = 180° – 131°
x° = 49°
To find y°:
x° + 39° + 70° = 180°
x° + 109° = 180°
x° = 180° – 109°
x° = 71°
The triangles do not have two pairs of congruent angles.
So, the triangles are not similar.

Question 12.
Big Ideas Math Solutions Grade 8 Chapter 3 Angles and Triangles 151

Answer:
∠A ≅ ∠QPB
∠C ≅ ∠PQB
ΔBPQ ∼ ΔBAC

Question 13.
Describe two ways you can find the measure of ∠5.
Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles 152

Answer:
One way: ∠3 and 65° are supplementary angles. ∠5 and ∠3 are alternate interior angles.
Another way: ∠8 and 65° are alternate exterior angles. ∠5 and ∠8 are supplementary angles.

Question 14.
You swim 3.6 kilometers per hour. How long (in minutes) will it take you to swim the distance d across the pond?
Big Ideas Math Solutions Grade 8 Chapter 3 Angles and Triangles 153

Answer:
Given,
You swim 3.6 kilometers per hour.
d/105 = 80/140
105 . d/105 = 80/140 . 105
d = 60
The length of the pond is 60 m.
Speed = 3.6 km per hour = 1 m sec
Distance = d = 60m
Time it will take to swim across the pond
= distance/speed
= 60/1
= 60 sec = 1 min

Angles and Triangles Cumulative Practice

Question 1.
The border of a Canadian one-dollar coin is shaped like an 11-sided regular polygon. The shape was chosen to help visually impaired people identify the coin. How many degrees are in each interior angle along the border? Round your answer to the nearest degree.
Big Ideas Math Solutions Grade 8 Chapter 3 Angles and Triangles 154
Big Ideas Math Solutions Grade 8 Chapter 3 Angles and Triangles 154.1

Answer:
S = (n – 2) . 180°
S = (11 – 2) . 180°
S = 9 . 180°
S = 1620°
Thus the sum of the interior angle measure is 1620°
In a regular polygon, each interior angle is congruent. So, divide the sum of the interior angle measures by the number of interior angles, 11.
1620 ÷ 11 = 147°

Question 2.
A public utility charges its residential customers for natural gas based on the number of therms used each month. The formula shows how the monthly cost tin dollars is related to the number of terms used.
C = 11 + 1.6t
Solve this formula for t.
Big Ideas Math Solutions Grade 8 Chapter 3 Angles and Triangles 155

Answer:
C = 11 + 1.6t
C – 11 = 1.6t
1.6t = C – 11
t = (C – 11)/1.6
Thus the correct answer is option B.

Question 3.
What is the value of x?
Big Ideas Math Solutions Grade 8 Chapter 3 Angles and Triangles 156

Answer:
5(x – 4) = 3x
5x – 20 = 3x
5x – 3x = 20
2x = 20
x = 20/2
x = 10
Thus the correct answer is option I.

Question 4.
In the figures, △PQR is similar to △STU. What is the value of x?
Big Ideas Math Solutions Grade 8 Chapter 3 Angles and Triangles 157
A. 9.6
B. 10\(\frac{2}{3}\)
C. 13.5
D. 15

Answer:
△PQR is similar to △STU
PQ = 12
ST = 16
SU = 20
TU = 18
PQ/ST = QR/TU
12/16 = X/18
16X = 12 × 18
X = 216/16
X = 13.5 cm
Thus the correct answer is option C.

Question 5.
What is the value of x?
Big Ideas Math Solutions Grade 8 Chapter 3 Angles and Triangles 158

Answer:
∠y and 125° are supplementary angles.
125° + ∠y = 180°
∠y = 180° – 125°
∠y = 55°
So, the measure of ∠y = 55°
∠x and ∠y are alternate interior angles. They are congruent.
So, the measure of ∠x = 55°

Question 6.
Your friend was solving an equation in the box shown.
Big Ideas Math Solutions Grade 8 Chapter 3 Angles and Triangles 159
What should your friend do to correct the error that she made?
F. Multiply both sides by –\(\frac{5}{2}\) instead of –\(\frac{2}{5}\).
G. Multiply both sides by \(\frac{2}{5}\) instead of –\(\frac{2}{5}\).
H. Distribute –\(\frac{2}{5}\) to get 4x – 6.
I. Add 15 to -30.

Answer:
My friend made the error by multiplying both sides by –\(\frac{2}{5}\).
To correct the error she should multiply both sides by –\(\frac{5}{2}\) instead of –\(\frac{2}{5}\)
Thus the correct answer is option F.

Question 7.
In the coordinate plane below, ∆XYZ is plotted and its vertices are labeled.
Big Ideas Math Solutions Grade 8 Chapter 3 Angles and Triangles 160
Which of the following shows ∆X’Y’Z’, the image of ∆XYZ after it is reflected in the y-axis?
Big Ideas Math Solutions Grade 8 Chapter 3 Angles and Triangles 161

Answer:
Given,
X(-6,-1)
Y(-3,-5)
X(-2,-3)
Reflecting a point (x,y) in the y-axis.
(x, y) = (-x, y)
X(-6,-1) = X'(6, -1)
Y(-3,-5) = Y'(3, -5)
X(-2,-3) = Z'(2, -3)
Thus the correct answer is option B.

Question 8.
The sum S of the interior angle measures of a polygon with n sides can be found by using a formula.
Big Ideas Math Solutions Grade 8 Chapter 3 Angles and Triangles 162
Part A
Write the formula.

Answer:
S = (n – 2) . 180°
Part B
A quadrilateral has angles measuring 100°, 90°, and 90°. Find the measure of its fourth angle. Show your work and explain your reasoning.

Answer:
The quadrilateral has 4 sides
S = (n – 2) . 180°
S = (4 – 2) . 180°
S = 2 . 180°
S = 360 °
Thus the sum of the interior angles is 360 °
x° + 100° + 90° + 90° = 360°
x° + 280° = 360°
x° = 360° – 280°
x° = 80°
Thus the value of x° is 80°

Part C
The sum of the measures of the angles of the pentagon shown is 540°. Divide the pentagon into triangles to show why this must be true. Show your work and explain your reasoning.
Big Ideas Math Solutions Grade 8 Chapter 3 Angles and Triangles 163

Answer:
Number of sides = 3
The number of interior triangles in the given figure = 3
Sum of the interior angles measure using triangle = 3 × 180° = 540

Conclusion:

I wish the details prevailed in the above article is beneficial for all the 8th grade students. Hope our Big Ideas Math Answers Grade 8 Chapter 3 Angles and Triangles helped you a lot to overcome the difficulties in this chapter. Feel free to post your comments in the comment box. Stay tuned to our ccssmathanswers.com to get step by step explanation for all the Grade 8 chapters.