Eureka Math

Engage NY Eureka Math 3rd Grade Module 7 Lesson 30 Answer Key

Eureka Math Grade 3 Module 7 Lesson 30 Pattern Sheet Answer Key

Multiply.

multiply by 9 (6–10)
Answer:

Eureka Math Grade 3 Module 7 Lesson 30 Problem Set Answer Key

Use this form to critique your classmate’s problem-solving work.

Classmate:		Problem Number:
Strategies My Classmate Used:
Things My Classmate Did Well:
Suggestions for Improvement:
Strategies I Would Like to Try Based on My Classmate’s Work:

Answer:

Eureka Math Grade 3 Module 7 Lesson 30 Exit Ticket Answer Key

Jayden solves the problem as shown below.
The recreation center soccer field measures 35 yards by 65 yards. Chris dribbles the soccer ball around the field 4 times. What is the total number of yards Chris dribbles the ball?

Question 1.
What strategies did Jayden use to solve this problem?
Answer:

Question 2.
What did Jayden do well?
Answer:

Eureka Math Grade 3 Module 7 Lesson 30 Homework Answer Key

Use this form to critique Student A’s problem-solving work on the next page.

Student:	Student A	Problem Number:
Strategies Student A Used:
Things Student A Did Well:
Suggestions for Improvement:
Strategies I Would Like to Try Based on Student A’s Work:

Question 1.
Katherine puts 2 squares together to make the rectangle below. The side lengths of the squares measure 8 inches.

a. What is the perimeter of Katherine’s rectangle?
b. What is the area of Katherine’s rectangle?
c. Katherine draws 2 of the rectangles in Problem 1 side by side. Her new, larger rectangle is shown below. What is the area of the new, larger rectangle?

Answer:

Engage NY Eureka Math 3rd Grade Module 7 Lesson 29 Answer Key

Eureka Math Grade 3 Module 7 Lesson 29 Sprint Answer Key

A
Multiply or Divide by 8

Question 1.
2 × 8 =
Answer:

Question 2.
3 × 8 =
Answer:

Question 3.
4 × 8 =
Answer:

Question 4.
5 × 8 =
Answer:

Question 5.
1 × 8 =
Answer:

Question 6.
16 ÷ 8 =
Answer:

Question 7.
24 ÷ 8 =
Answer:

Question 8.
40 ÷ 8 =
Answer:

Question 9.
8 ÷ 8 =
Answer:

Question 10.
32 ÷ 8 =
Answer:

Question 11.
6 × 8 =
Answer:

Question 12.
7 × 8 =
Answer:

Question 13.
8 × 8 =
Answer:

Question 14.
9 × 8 =
Answer:

Question 15.
10 × 8 =
Answer:

Question 16.
64 ÷ 8 =
Answer:

Question 17.
56 ÷ 8 =
Answer:

Question 18.
72 ÷ 8 =
Answer:

Question 19.
48 ÷ 8 =
Answer:

Question 20.
80 ÷ 8 =
Answer:

Question 21.
___ × 8 = 40
Answer:

Question 22.
___ × 8 = 8
Answer:

Question 23.
___ × 8 = 80
Answer:

Question 24.
___ × 8 = 16
Answer:

Question 25.
___ × 8 = 24
Answer:

Question 26.
80 ÷ 8 =
Answer:

Question 27.
40 ÷ 8 =
Answer:

Question 28.
8 ÷ 8 =
Answer:

Question 29.
16 ÷ 8 =
Answer:

Question 30.
24 ÷ 8 =
Answer:

Question 31.
___ × 8 = 48
Answer:

Question 32.
___ × 8 = 56
Answer:

Question 33.
___ × 8 = 72
Answer:

Question 34.
___ × 8 = 64
Answer:

Question 35.
56 ÷ 8 =
Answer:

Question 36.
72 ÷ 8 =
Answer:

Question 37.
48 ÷ 8 =
Answer:

Question 38.
64 ÷ 8 =
Answer:

Question 39.
11 × 8 =
Answer:

Question 40.
88 ÷ 8 =
Answer:

Question 41.
12 × 8 =
Answer:

Question 42.
96 ÷ 8 =
Answer:

Question 43.
14 × 8 =
Answer:

Question 44.
112 ÷ 8 =
Answer:

B
Multiply or Divide by 8

Question 1.
1× 8 =
Answer:

Question 2.
2 × 8 =
Answer:

Question 3.
3 × 8 =
Answer:

Question 4.
4 × 8 =
Answer:

Question 5.
5 × 8 =
Answer:

Question 6.
24 ÷ 8 =
Answer:

Question 7.
16 ÷ 8 =
Answer:

Question 8.
32 ÷ 8 =
Answer:

Question 9.
8 ÷ 8 =
Answer:

Question 10.
40 ÷ 8 =
Answer:

Question 11.
10 × 8 =
Answer:

Question 12.
6 × 8 =
Answer:

Question 13.
7 × 8 =
Answer:

Question 14.
8 × 8 =
Answer:

Question 15.
9 × 8 =
Answer:

Question 16.
56 ÷ 8 =
Answer:

Question 17.
8 ÷ 8 =
Answer:

Question 18.
64 ÷ 8 =
Answer:

Question 19.
80 ÷ 8 =
Answer:

Question 20.
72 ÷ 8 =
Answer:

Question 21.
___ × 8 = 8
Answer:

Question 22.
___ × 8 = 40
Answer:

Question 23.
___ × 8 = 16
Answer:

Question 24.
___ × 8 = 80
Answer:

Question 25.
___ × 8 = 24
Answer:

Question 26.
16 ÷ 8 =
Answer:

Question 27.
8 ÷ 8 =
Answer:

Question 28.
80 ÷ 8 =
Answer:

Question 29.
40 ÷ 8 =
Answer:

Question 30.
24 ÷ 8 =
Answer:

Question 31.
___ × 8 = 24
Answer:

Question 32.
___ × 8 = 32
Answer:

Question 33.
___ × 8 = 72
Answer:

Question 34.
___ × 8 = 56
Answer:

Question 35.
64 ÷ 8 =
Answer:

Question 36.
72 ÷ 8 =
Answer:

Question 37.
48 ÷ 8 =
Answer:

Question 38.
56 ÷ 8 =
Answer:

Question 39.
11 × 8 =
Answer:

Question 40.
88 ÷ 8 =
Answer:

Question 41.
12 × 8 =
Answer:

Question 42.
96 ÷ 8 =
Answer:

Question 43.
13 × 8 =
Answer:

Question 44.
104 ÷ 8 =
Answer:

Eureka Math Grade 3 Module 7 Lesson 29 Problem Set Answer Key

Question 1.
Kyle puts two rectangles together to make the L-shaped figure below. He measures some of the side lengths and records them as shown.

a. Find the perimeter of Kyle’s shape.
b. Find the area of Kyle’s shape.
c. Kyle makes two copies of the L-shaped figure to create the rectangle shown below. Find the perimeter of the rectangle.

Answer:

Question 2.
Jeremiah and Hayley use a piece of rope to mark a square space for their booth at the science fair. The area of their space is 49 square feet. What is the length of the rope that Jeremiah and Hayley use if they leave a 3-foot opening so they can get in and out of the space?
Answer:

Question 3.
Vivienne draws four identical rectangles as shown below to make a new, larger rectangle. The perimeter of one of the small rectangles is 18 centimeters, and the width is 6 centimeters. What is the perimeter of the new, larger rectangle?

Answer:

Question 4.
A jogging path around the outside edges of a rectangular playground measures 48 yards by 52 yards. Maya runs 3\(\frac{1}{2}\) laps on the jogging path. What is the total number of yards Maya runs?
Answer:

Eureka Math Grade 3 Module 7 Lesson 29 Exit Ticket Answer Key

Jeannette draws four identical squares as shown below to make a new, larger square. The length of one of the small square sides is 8 centimeters. What is the perimeter of the new, larger square?

Answer:

Eureka Math Grade 3 Module 7 Lesson 29 Homework Answer Key

Question 1.
Katherine puts two squares together to make the rectangle below. The side lengths of the squares measure 8 inches.

a. What is the perimeter of the rectangle Katherine made with her 2 squares?
b. What is the area of Katherine’s rectangle?
c. Katherine decides to draw another rectangle of the same size. What is the area of the new, larger rectangle?

Answer:

Question 2.
Daryl draws 6 equal-sized rectangles as shown below to make a new, larger rectangle. The area of one of the small rectangles is 12 square centimeters, and the width of the small rectangle is 4 centimeters..

a. What is the perimeter of Daryl’s new rectangle?
b. What is the area of Daryl’s new rectangle?
Answer:

Question 3.
The recreation center soccer field measures 35 yards by 65 yards. Chris dribbles the soccer ball around the perimeter of the field 4 times. What is the total number of yards Chris dribbles the ball?
Answer:

Engage NY Eureka Math 3rd Grade Module 7 Lesson 27 Answer Key

Eureka Math Grade 3 Module 7 Lesson 27 Sprint Sheet Answer Key

A
Multiply or Divide by 7

Question 1.
2 × 7 =
Answer:

Question 2.
3 × 7 =
Answer:

Question 3.
4 × 7 =
Answer:

Question 4.
5 × 7 =
Answer:

Question 5.
1 × 7 =
Answer:

Question 6.
14 ÷ 7 =
Answer:

Question 7.
21 ÷ 7 =
Answer:

Question 8.
35 ÷ 7 =
Answer:

Question 9.
7 ÷ 7 =
Answer:

Question 10.
28 ÷ 7 =
Answer:

Question 11.
6 × 7 =
Answer:

Question 12.
7 × 7 =
Answer:

Question 13.
8 × 7 =
Answer:

Question 14.
9 × 7 =
Answer:

Question 15.
10 × 7 =
Answer:

Question 16.
56 ÷ 7 =
Answer:

Question 17.
49 ÷ 7 =
Answer:

Question 18.
63 ÷ 7 =
Answer:

Question 19.
42 ÷ 7 =
Answer:

Question 20.
70 ÷ 7 =
Answer:

Question 21.
___ × 7 = 35
Answer:

Question 22.
___ × 7 = 7
Answer:

Question 23.
___ × 7 = 70
Answer:

Question 24.
___ × 7 = 14
Answer:

Question 25.
___ × 7 = 21
Answer:

Question 26.
70 ÷ 7 =
Answer:

Question 27.
35 ÷ 7 =
Answer:

Question 28.
7 ÷ 7 =
Answer:

Question 29.
14 ÷ 7 =
Answer:

Question 30.
21 ÷ 7 =
Answer:

Question 31.
___ × 7 = 42
Answer:

Question 32.
___ × 7 = 49
Answer:

Question 33.
___ × 7 = 63
Answer:

Question 34.
___ × 7 = 56
Answer:

Question 35.
49 ÷ 7 =
Answer:

Question 36.
63 ÷ 7 =
Answer:

Question 37.
42 ÷ 7 =
Answer:

Question 38.
56 ÷ 7 =
Answer:

Question 39.
11 × 7 =
Answer:

Question 40.
77 ÷ 7 =
Answer:

Question 41.
12 × 7 =
Answer:

Question 42.
84 ÷ 7 =
Answer:

Question 43.
14 × 7 =
Answer:

Question 44.
98 ÷ 7 =
Answer:

B
Multiply or Divide by 7

Question 1.
1 × 7 =
Answer:

Question 2.
2 × 7 =
Answer:

Question 3.
3 × 7 =
Answer:

Question 4.
4 × 7 =
Answer:

Question 5.
5 × 7 =
Answer:

Question 6.
21 ÷ 7 =
Answer:

Question 7.
14 ÷ 7 =
Answer:

Question 8.
28 ÷ 7 =
Answer:

Question 9.
7 ÷ 7 =
Answer:

Question 10.
35 ÷ 7 =
Answer:

Question 11.
10 × 7 =
Answer:

Question 12.
6 × 7 =
Answer:

Question 13.
7 × 7 =
Answer:

Question 14.
8 × 7 =
Answer:

Question 15.
9 × 7 =
Answer:

Question 16.
49 ÷ 7 =
Answer:

Question 17.
42 ÷ 7 =
Answer:

Question 18.
56 ÷ 7 =
Answer:

Question 19.
70 ÷ 7 =
Answer:

Question 20.
63 ÷ 7 =
Answer:

Question 21.
___ × 7 = 7
Answer:

Question 22.
___ × 7 = 35
Answer:

Question 23.
___ × 7 = 14
Answer:

Question 24.
___ × 7 = 70
Answer:

Question 25.
___ × 7 = 21
Answer:

Question 26.
14 ÷ 7 =
Answer:

Question 27.
7 ÷ 7 =
Answer:

Question 28.
70 ÷ 7 =
Answer:

Question 29.
35 ÷ 7 =
Answer:

Question 30.
21 ÷ 7 =
Answer:

Question 31.
___ × 7 = 21
Answer:

Question 32.
___ × 7 = 28
Answer:

Question 33.
___ × 7 = 63
Answer:

Question 34.
___ × 7 = 49
Answer:

Question 35.
56 ÷ 7 =
Answer:

Question 36.
63 ÷ 7 =
Answer:

Question 37.
42 ÷ 7 =
Answer:

Question 38.
49 ÷ 7 =
Answer:

Question 39.
11 × 7 =
Answer:

Question 40.
77 ÷ 7 =
Answer:

Question 41.
12 × 7 =
Answer:

Question 42.
84 ÷ 7 =
Answer:

Question 43.
13 × 7 =
Answer:

Question 44.
91 ÷ 7 =
Answer:

Eureka Math Grade 3 Module 7 Lesson 27 Problem Set Answer Key

Question 1.
Use the chart below to evaluate your friend’s robot. Measure the width and length of each rectangle. Then, calculate the perimeter. Record that information in the chart below. If your measurements differ from those listed on the project, put a star by the letter of the rectangle.

Item	Width and Length	Student’s Perimeter	Required Perimeter
J			About 25 cm
K	__________ cm by __________cm		82 cm
L			About 30 cm
M	__________ cm by __________cm		30 cm
N			About 20 cm
O	__________ cm by __________cm		20 cm
P
Q

Answer:

Question 2.
Is the perimeter of the robot’s body double that of the arm? Show calculations below.
Answer:

Question 3.
Is the perimeter of the robot’s neck half the perimeter of the head? Show calculations below.
Answer:

Question 4.
Use the chart below to evaluate your friend’s robot environment. Measure the width and length of each rectangle. Then, calculate the perimeter. Use your string to measure the perimeters of nonrectangular items. Record that information in the chart below. If your measurements differ from those listed on the project, put a star by the letter of the shape.

Rectangle:	Width and Length:	Perimeter	Area
A	_________ cm by _________cm
B	_________ cm by _________cm

Answer:

Eureka Math Grade 3 Module 7 Lesson 27 Exit Ticket Answer Key

Question 1.
Record the perimeters and areas of Rectangles A and B in the chart below.

tableee
Answer:

Question 2.
What is the same about Rectables A and B? What is different?
Answer:

Eureka Math Grade 3 Module 7 Lesson 27 Homework Answer Key

Record the perimeters and areas of the rectangles in the chart on the next page.

Question 1.
Find the area and perimeter of each rectangle.

Rectangle	Width and Length	Perimeter	Area
A	__________ cm by __________cm
B	__________ cm by __________cm
C	__________ cm by __________cm
D	__________ cm by __________cm
E	_________ cm by __________cm
F	__________ cm by __________cm

Answer:

Question 2.
What do you notice about the perimeters of Rectangles A, B, and C?
Answer:

Question 3.
What do you notice about the perimeters of Rectangles D, E, and F?
Answer:

Question 4.
Which two rectangles are squares? Which square has the greater perimeter?
Answer:

Eureka Math Grade 3 Module 7 Lesson 27 Evaluation Rubric Answer Key

Evaluation Rubric

4	3	2	2	Subtotal
Perimeter calculations for all shapes are correct, and both evaluations of a classmate’s project have been completed.	Perimeter calculations include 1 to 2 errors, and both evaluations of a classmate’s project have been completed.	Perimeter calculations include 3 to 4 errors, and at least 1 evaluation of a classmate’s project has been completed.	Perimeter calculations include 5 or more errors, and at least 1 evaluation of a classmate’s project has been completed.	_____/4

Engage NY Eureka Math 3rd Grade Module 7 Lesson 26 Answer Key

Eureka Math Grade 3 Module 7 Lesson 26 Pattern Sheet Answer Key

Multiply.

multiply by 7 (6–10)
Answer:

Explanation:
7 × 6 = 42
7 × 7 = 49
7 × 8 = 56
7 × 9 = 63
7 × 10 = 70.

Eureka Math Grade 3 Module 7 Lesson 26 Problem Set Answer Key

Question 1.
Collect the area measurements of your classmates’ robot bodies. Make a line plot using everyone’s area measurements.
Areas of Robot Bodies

a. How many different measurements are on the line plot? Why are the measurements different?
b. What does this tell you about the relationship between area and perimeter?
Answer:
a.
There are four different kinds of measurements represented on the number line. They are different in values because the values of every rectangle is different from each other.

b. Perimeter is the measurement of the distance around a shape. Area is the measurement of space inside a shape. Area and Perimeter are not having any relationship because they are totally two different things. Perimeter is going to be more than the area of the rectangle.

Explanation:
a.

Area of the A rectangle = Length × Width = 4cm × 4cm = 16 square cm.
Area of the B rectangle = Length × Width = 2cm × 2cm = 16 square cm.
Area of the C rectangle = Length × Width = 8cm × 6cm = 48 square cm.
Area of the D rectangle = Length × Width = 5cm × 2cm = 10 square cm.
Area of the E rectangle = Length × Width = 5cm × 2cm = 10 square cm.
Area of the F rectangle = Length × Width = 7cm × 2cm = 14 square cm.
Area of the G rectangle = Length × Width = 7cm × 2cm = 14 square cm.
There are four different kinds of measurements represented on the number line. They are different in values because the values of every rectangle is different from each other.

b. Perimeter is the measurement of the distance around a shape. Area is the measurement of space inside a shape.
For Example : If a rectangle having length as 2cm and width as 1cm.
Perimeter = 2 (Length + Width) = 2 ( 2cm + 1cm) = 2 × 3cm = 6cm.
Area = length × Width = 2cm × 1cm = 2 square cm.
Area and Perimeter are not having any relationship because they are totally two different things.

 

Question 2.
Measure and calculate the perimeter of your construction paper in inches. Show your work below.
Answer:
Perimeter of my construction paper = 80 inches.

Explanation:
This is my construction paper.

Length of my construction paper = 28 inches.
Width of my construction paper = 12 inches.
Perimeter of my construction paper = 2 ( Length + Width )
= 2 ( 28 inches + 12 inches )
= 2 × 40 inches
= 80 inches.

 

Question 3.
Sketch and label two shapes with the same perimeter from the robot’s environment. What do you notice about the way they look?
Answer:
Even though my two figure have the same Perimeter as 20cm yet they appearances are complete different in size and looks.

Explanation:

Same in perimeter the figure are yet different in size and appearance.

 

 

Question 4.
Write two or three sentences describing your robot and the environment in which it lives.
Answer:
My Robot name is Mr. Kool. He lives in machine land, where there are different kinds of Robots.  He is very friendly in nature. He loves to help others in their works. He is taller than other Robots in his locality. He does all kinds of works and loves to be around people. He makes difficult works in a easy way.

Explanation:
My Robot name is Mr. Kool. He lives in machine land, where there are different kinds of Robots. He is taller than other Robots in his locality. He is very friendly in nature. He loves to help others in their works.

 

Eureka Math Grade 3 Module 7 Lesson 26 Exit Ticket Answer Key

Question 1.
Use string to help you sketch a circle with a perimeter of about 15 centimeters.
Answer:

Explanation:
A figure is the circle having its Perimeter as 15 centimeters.

 

Question 2.
Estimate to draw a rectangle with a perimeter of 15 centimeters. Label the width and length.
Answer:
Perimeter of the ABCD rectangle = 15 centimeters.

Explanation:

Length of the ABCD rectangle = 4.5cm
Width of the ABCD rectangle =  3cm
Perimeter of the ABCD rectangle = 2 ( Length + Width )
= 2 ( 4.5cm + 3cm )
= 2 × 7.5cm
= 15 centimeters.

 

Eureka Math Grade 3 Module 7 Lesson 26 Homework Answer Key

Question 1.
Use Rectangles A and B to answer the questions below.

a. What is the perimeter of Rectangle A?
b. What is the perimeter of Rectangle B?
c. What is the area of Rectangle A?
d. What is the area of Rectangle B?
e. Use your answers to parts (a–d) to help you explain the relationship between area and perimeter.

Answer:
a. Perimeter of the Rectangle A =  16cm.
b. Perimeter of the Rectangle B = 16cm.
c. Area of the Rectangle A = 16 Square cm.
d. Area of the Rectangle B = 15 square cm.
e. The Perimeter of Rectangle A and Rectangle B are same 16cm. The Area of the Rectangle A is 16 square cm and Rectangle B is 15 square cm. There is no connection between the Perimeter and the Area. It is observed that the Perimeter values are more than the Area values of the rectangles.

Explanation:
a.
Length of the Rectangle A = 4cm
Width of the Rectangle A =  4cm
Perimeter of the Rectangle A = 2 ( Length + Width )
= 2 ( 4cm + 4cm )
= 2 × 8cm
= 16cm.

b. Length of the Rectangle B = 5cm
Width of the Rectangle B =  3cm
Perimeter of the Rectangle B = 2 ( Length + Width )
= 2 ( 5cm + 3cm )
= 2 × 8cm
= 16cm.

c. Length of the Rectangle A = 4cm
Width of the Rectangle A =  4cm
Area of the Rectangle A =  Length × Width
=  4cm × 4cm
= 16 Square cm.

d. Length of the Rectangle B = 5cm
Width of the Rectangle B =  3cm
Area of the Rectangle B =  Length × Width
=  5cm × 3cm
= 15 square cm.

e. There is no connection between the Perimeter and the Area. It is observed that the Perimeter values are more than the Area values of the rectangles.

 

Question 2.
Each student in Mrs. Dutra’s class draws a rectangle with whole number side lengths and a perimeter of 28 centimeters. Then, they find the area of each rectangle and create the table below.

Area in Square Centimeters	Number of Students
13	2
24	1
33	3
40	5
45	4
48	2
49	2

a. Give two examples from Mrs. Dutra’s class to show how it is possible to have different areas for rectangles that have the same perimeter.
b. Did any students in Mrs. Dutra’s class draw a square? Explain how you know.
c. What are the side lengths of the rectangle that most students in Mrs. Dutra’s class made with a perimeter of 28 centimeters?
Answer:
a.
b. Yes, among all students in  Mrs. Dutra’s class there is one student whose rectangle is said to be a square because all the sides are of 6cm each and have an area as 24 square cm.

c.

Explanation:
a. Here are two students rectangles having same perimeters yet different in areas for their rectangles are shown.

b. Area of the rectangles whose is 24 square cm, is said to be a square of having side length value as 6 cm.

c. Well, the side lengths of the rectangle that most students in Mrs. Dutra’s class made with a perimeter of 28 centimeters are: ( Length, Width)
(12,2);  (11,3);  (10,4);  (9,5);  (8,6);  (7,7).

Engage NY Eureka Math 3rd Grade Module 1 Mid Module Assessment Answer Key

Eureka Math Grade 3 Module 1 Answer Key

Eureka Math Grade 3 Module 1 Mid Module Assessment Task Answer Key

Question 1.
Mrs. Tran plants 2 rows of 5 carrots in her garden.
a. Draw an array that represents Mrs. Tran’s carrots. Use an X to show each carrot.

Explanation:
Given Mrs. Tran plants 2 rows of 5 carrots in her garden,
Drawn an array that represents Mrs. Tran’s carrots,
Using  an X to show each carrot as shown above.

b. Mrs. Tran adds 3 more rows of 5 carrots to her garden.
• Use circles to show her new carrots on the array in Part (a).
• Fill in the blanks below to show how she added the five rows.
__ fives + __ fives = __ fives
• Write a sentence to explain your thinking.

(_2) X_ fives + (3)_X_ fives = _(5)_X fives,
2 times 5 and 3 times 5 makes 5 times fives,

Explanation:
Given Mrs. Tran adds 3 more rows of 5 carrots to her garden.
Using circles shown her new carrots on the array in Part (a),
To show how she added the five rows as 2 X 5 + 3 X 5 = 5 X 5,
Sentence is 2 times by five and 3 times by five makes 5 by five times.

c. Find the total number of carrots Mrs. Tran planted.

Total number of carrots Mrs. Tran planted are 25,

Explanation:
Total number of carrots Mrs. Tran planted are ( 2 X 5 + 3 X 5) =
10 + 15 = 25 carrots.

d. Write a multiplication sentence to describe the array
representing the total number of carrots Mrs. Tran planted.

Multiplication Sentence : (2 + 3) X 5 = 5 X 5,

Explanation:
Multiplication sentence to describe the array
representing the total number of carrots Mrs. Tran planted is
(2 + 3) X 5 = 5 X 5 = 25.

Question 2.
Mrs. Tran picks 15 tomatoes from her garden.
She puts 5 tomatoes in each bag.
a. Draw Mrs. Tran’s bags of tomatoes.
b. Write a multiplication sentence that describes your drawing in Part (a).

a.
Explanation:
Drawn to show Mrs. Tran’s bags of tomatoes,
5 tomatoes in each bag.

b. Multiplication Sentence : 5 X 3 = 15,

Explanation:
Multiplication sentence that describes my drawing in Part (a)
is we have 5 tomatoes in each bag so 5 X 3 = 15 and Mrs. Tran’s
picked 15 tomatoes from her garden.

Question 3.
Mrs. Tran plants 12 sunflowers in her garden. She plants them in 3 rows.
a. Fill in the blanks below to make a true division sentence.
What does the answer represent?
__ ÷ __ = __

a. Division sentence : 12 ÷ 3 = 4,
4 sunflowers in a row,

Explanation:
Given Mrs. Tran plants 12 sunflowers in her garden.
She plants them in 3 rows.
Division sentence is 12 ÷ 3 = 4,
The 4 represents there are 4 sunflower plants in a row.

b. Mrs. Tran adds 2 more identical rows of sunflowers to
her 3 original rows. Draw an array to show how many flowers she has now.

Explanation:
Drawn an array to show the number of sun flowers
Mrs. Tran has 24 now.

c. Mrs. Tran figured out how many flowers she planted.
Her work is shown in the box below. Would Mrs. Tran get
the same result if she multiplied 5 × 4? Explain why or why not.

Yes, Mrs. Tran get the same result if she
multiplied 5 X 4,

Explanation:
Mrs. Tran worked as (3 X 4) + (2 X 4) = 12 + 8 = 20,
and Mrs. Tran got the same result if she multiply 5 X 4 = 20,
because in the equation both 3 and 2 are multiplied by 4,
So we add 3 and 2 first we get 5 and multiply by 4, So
the result remains same 20 for 5 X 4 also.

Engage NY Eureka Math 3rd Grade Module 7 Lesson 25 Answer Key

Eureka Math Grade 3 Module 25 Lesson 4 Sprint Answer Key

A
Multiply or Divide by 6

Answer:

Question 1.
2 × 6 =
Answer:
2 × 6 = 12.

Question 2.
3 × 6 =
Answer:
3 × 6 = 18.

Question 3.
4 × 6 =
Answer:
4 × 6 = 24.

Question 4.
5 × 6 =
Answer:
5 × 6 = 30.

Question 5.
1 × 6 =
Answer:
1 × 6 = 6.

Question 6.
12 ÷ 6 =
Answer:
12 ÷ 6 = 2.

Question 7.
18 ÷ 6 =
Answer:
18 ÷ 6 = 3.

Question 8.
30 ÷ 6 =
Answer:
30 ÷ 6 = 5.

Question 9.
6 ÷ 6 =
Answer:
6 ÷ 6 = 1.

Question 10.
24 ÷ 6 =
Answer:
24 ÷ 6 = 4.

Question 11.
6 × 6 =
Answer:
6 × 6 = 36.

Question 12.
7 × 6 =
Answer:
7 × 6 = 42.

Question 13.
8 × 6 =
Answer:
8 × 6 = 48.

Question 14.
9 × 6 =
Answer:
9 × 6 = 54.

Question 15.
10 × 6 =
Answer:
10 × 6 = 60.

Question 16.
48 ÷ 6 =
Answer:
48 ÷ 6 = 8.

Question 17.
42 ÷ 6 =
Answer:
42 ÷ 6 = 7.

Question 18.
54 ÷ 6 =
Answer:
54 ÷ 6 = 9.

Question 19.
36 ÷ 6 =
Answer:
36 ÷ 6 = 6.

Question 20.
60 ÷ 6 =
Answer:
60 ÷ 6 = 10.

Question 21.
___ × 6 = 30
Answer:
_5__ × 6 = 30.

Question 22.
___ × 6 = 6
Answer:
_1__ × 6 = 6.

Question 23.
___ × 6 = 60
Answer:
_10__ × 6 = 60.

Question 24.
___ × 6 = 12
Answer:
_2__ × 6 = 12.

Question 25.
___ × 6 = 18
Answer:
_3__ × 6 = 18.

Question 26.
60 ÷ 6 =
Answer:
60 ÷ 6 = 10.

Question 27.
30 ÷ 6 =
Answer:
30 ÷ 6 = 5.

Question 28.
6 ÷ 6 =
Answer:
6 ÷ 6 = 1.

Question 29.
12 ÷ 6 =
Answer:
12 ÷ 6 = 2.

Question 30.
18 ÷ 6 =
Answer:
18 ÷ 6 = 3.

Question 31.
___ × 6 = 36
Answer:
_6__ × 6 = 36.

Question 32.
___ × 6 = 42
Answer:
_7__ × 6 = 42.

Question 33.
___ × 6 = 54
Answer:
_9__ × 6 = 54.

Question 34.
___ × 6 = 48
Answer:
_8__ × 6 = 48.

Question 35.
42 ÷ 6 =
Answer:
42 ÷ 6 = 7.

Question 36.
54 ÷ 6 =
Answer:
54 ÷ 6 = 9.

Question 37.
36 ÷ 6 =
Answer:
36 ÷ 6 = 6.

Question 38.
48 ÷ 6 =
Answer:
48 ÷ 6 = 8.

Question 39.
11 × 6 =
Answer:
11 × 6 = 66.

Question 40.
66 ÷ 6 =
Answer:
66 ÷ 6 = 11.

Question 41.
12 × 6 =
Answer:
12 × 6 = 72.

Question 42.
72 ÷ 6 =
Answer:
72 ÷ 6 = 12.

Question 43.
14 × 6 =
Answer:
14 × 6 = 84.

Question 44.
84 ÷ 6 =
Answer:
84 ÷ 6 = 14.

B
Multiply or Divide by 6

Answer:

Question 1.
1 × 6 =
Answer:
1 × 6 = 6.

Question 2.
2 × 6 =
Answer:
2 × 6 = 12.

Question 3.
3 × 6 =
Answer:
3 × 6 = 18.

Question 4.
4 × 6 =
Answer:
4 × 6 = 24.

Question 5.
5 × 6 =
Answer:
5 × 6 = 30.

Question 6.
18 ÷ 6 =
Answer:
18 ÷ 6 = 3.

Question 7.
12 ÷ 6 =
Answer:
12 ÷ 6 = 2.

Question 8.
24 ÷ 6 =
Answer:
24 ÷ 6 = 4.

Question 9.
6 ÷ 6 =
Answer:
6 ÷ 6 = 1.

Question 10.
30 ÷ 6 =
Answer:
30 ÷ 6 = 5.

Question 11.
10 × 6 =
Answer:
10 × 6 = 60.

Question 12.
6 × 6 =
Answer:
6 × 6 = 36.

Question 13.
7 × 6 =
Answer:
7 × 6 = 42.

Question 14.
8 × 6 =
Answer:
8 × 6 = 48.

Question 15.
9 × 6 =
Answer:
9 × 6 = 54.

Question 16.
42 ÷ 6 =
Answer:
42 ÷ 6 = 7.

Question 17.
36 ÷ 6 =
Answer:
36 ÷ 6 = 6.

Question 18.
48 ÷ 6 =
Answer:
48 ÷ 6 = 8.

Question 19.
60 ÷ 6 =
Answer:
60 ÷ 6 = 10.

Question 20.
54 ÷ 6 =
Answer:
54 ÷ 6 = 9.

Question 21.
___ × 6 = 6
Answer:
__1_ × 6 = 6.

Question 22.
___ × 6 = 30
Answer:
_5__ × 6 = 30.

Question 23.
___ × 6 = 12
Answer:
_2__ × 6 = 12.

Question 24.
___ × 6 = 60
Answer:
_10__ × 6 = 60.

Question 25.
___ × 6 = 18
Answer:
_3__ × 6 = 18.

Question 26.
12 ÷ 6 =
Answer:
12 ÷ 6 = 2.

Question 27.
6 ÷ 6 =
Answer:
6 ÷ 6 = 1.

Question 28.
60 ÷ 6 =
Answer:
60 ÷ 6 = 10.

Question 29.
30 ÷ 6 =
Answer:
30 ÷ 6 = 5.

Question 30.
18 ÷ 6 =
Answer:
18 ÷ 6 = 3.

Question 31.
___ × 6 = 18
Answer:
_3__ × 6 = 18 .

Question 32.
___ × 6 = 24
Answer:
_4__ × 6 = 24.

Question 33.
___ × 6 = 54
Answer:
_9__ × 6 = 54.

Question 34.
___ × 6 = 42
Answer:
_7__ × 6 = 42.

Question 35.
48 ÷ 6 =
Answer:
48 ÷ 6 = 8.

Question 36.
54 ÷ 6 =
Answer:
54 ÷ 6 = 9.

Question 37.
36 ÷ 6 =
Answer:
36 ÷ 6 = 6.

Question 38.
42 ÷ 6 =
Answer:
42 ÷ 6 = 7.

Question 39.
11 × 6 =
Answer:
11 × 6 = 66.

Question 40.
66 ÷ 6 =
Answer:
66 ÷ 6 = 11.

Question 41.
12 × 6 =
Answer:
12 × 6 = 72.

Question 42.
72 ÷ 6 =
Answer:
72 ÷ 6 = 12.

Question 43.
13 × 6 =
Answer:
13 × 6 = 78.

Question 44.
78 ÷ 6 =
Answer:
78 ÷ 6 = 13.

Eureka Math Grade 3 Module 7 Lesson 25 Problem Set Answer Key

Draw a picture of your robot in its environment in the space below. Label the widths, lengths, and perimeters of all rectangles. Label the perimeters of all circular shapes.
Answer:

Explanation:
Here is the picture of my Robot with all the labeling of its body parts and their perimeters.

Eureka Math Grade 3 Module 7 Lesson 25 Exit Ticket Answer Key

Question 1.
1. Sketch rectangles with the following perimeters. Label the side lengths.
a. 22 cm
b. 30 cm
Answer:
a.

b.
Explanation:
a. We could draw four different rectangles for having Perimeter as 22cm.
b. We could draw five different rectangles for having Perimeter as 30cm.

 

Question 2.
Explain the steps you took to create the rectangles with the given perimeters.
Answer:
Step 1 : Considered the perimeter value.
Step 2 : Later, considered the formula of perimeter of rectangle = 2 ( Length + Width ).
Step 3 : Divided the perimeter value by 2.
Step 4 : Result  is taken and divided into two parts where one value is going to be higher than the other.
Step 5 : Considered higher value as Length and smaller as Width.

Explanation:
Steps taken to create the rectangles with the given perimeters are:
Step 1 : Considered the perimeter value.
Step 2 : Later, considered the formula of perimeter of rectangle = 2 ( Length + Width ).
Step 3 : Divided the perimeter value by 2.
Step 4 : Result  is taken and divided into two parts where one value is going to be higher than the other.
Step 5 : Considered higher value as Length and smaller as Width.

 

Eureka Math Grade 3 Module 7 Lesson 25 Homework Answer Key

The robot below is made of rectangles. The side lengths of each rectangle are labeled. Find the perimeter of each rectangle, and record it in the table on the next page.

Rectangle	Perimeter
A	P = 4 × 4 cm P = 16 cm
B
C
D
E
F
G

Answer:

Explanation:
The Robot all body Parts  Perimeters are calculated in the above chart.

 

Eureka Math Grade 3 Module 7 Lesson 25 Evaluation Rubric Answer Key

Evaluation Rubric

4	3	2	1	Subtotal
Perimeter calculations for all shapes are correct, and both evaluations of a classmate’s project have been completed.	Perimeter calculations include 1 to 2 errors, and both evaluations of a classmate’s project have been completed.	Perimeter calculations include 3 to 4 errors, and at least 1 evaluation of a classmate’s project has been completed.	Perimeter calculations include 5 or more errors, and at least 1 evaluation of a classmate’s project has been completed.	_____/4 Perimeter calculations include 1 2 3  to 5 errors, and all evaluation of a classmate’s project has been completed.

Engage NY Eureka Math 3rd Grade Module 7 Lesson 24 Answer Key

Eureka Math Grade 3 Module 7 Lesson 24 Pattern Sheet Answer Key

Multiply.

multiply by 6 (6–10)
Answer:

Explanation:
6 × 6 = 36
6 × 7 = 42
6 × 8 = 48
6 × 9 = 54
6 × 10 = 60.

Eureka Math Grade 3 Module 7 Lesson 24 Problem Set Answer Key

Use the given perimeters in the chart below to choose the widths and lengths of your robot’s rectangular body parts. Write the widths and lengths in the chart below. Use the blank rows if you want to add extra rectangular body parts to your robot.

Letter	Body Part	Perimeter	Width and Length
A	arm	14 cm	__________ cm by __________cm
B	arm	14 cm	__________ cm by __________cm
C	leg	18 cm	__________ cm by __________cm
D	leg	18 cm	__________ cm by __________cm
E	body	Double the perimeter of one arm = _______ cm	__________ cm by __________cm
F	head	16 cm	__________ cm by __________cm
G	neck	Half the perimeter of the head = _______ cm	__________ cm by __________cm
H			__________ cm by __________cm
I			__________ cm by __________cm
My robot has 7 to 9 rectangular body parts.  Number of body parts:  _______

Answer:

Use the information in the chart below to plan an environment for your robot. Write the width and length for each rectangular item. Use the blank rows if you want to add extra circular or rectangular items to your robot’s environment.

Letter	Item	Shape	Perimeter	Width and Length
J	sun	circle	about 25 cm
K	house	rectangle	82 cm	__________ cm by __________cm
L	tree top	circle	about 30 cm
M	tree trunk	rectangle	30 cm	__________ cm by __________cm
N	tree top	circle	about 20 cm
O	tree trunk	rectangle	20 cm	__________ cm by __________cm
P
Q
My robot’s environment has 6 to 8 items.  Number of items:  _______

Answer:

Eureka Math Grade 3 Module 7 Lesson 24 Exit Ticket Answer Key

Estimate to draw three different rectangles with a perimeter of 16 centimeters. Label the width and length of each rectangle.
Answer:

Explanation:
Using the Perimeter of 16 cm we can draw three rectangles ABCD, EFGH, IJKL with different lengths and width.

 

Eureka Math Grade 3 Module 7 Lesson 24 Homework Answer Key

Question 1.
Brian draws a square with a perimeter of 24 inches. What is the length of the side of the square?
Answer:
Length of the side of the square = 6 inches.

Explanation:
Perimeter of the Square = 24 inches
Number of sides in the square = 4
Length of the side of the square = Perimeter of the Square  ÷ Number of sides in the square
= 24 inches ÷ 4
= 6 inches.

Question 2.
A rectangle has a perimeter of 18 centimeters.
a. Estimate to draw as many different rectangles as you can that have a perimeter of 18 centimeters. Label the width and length of each rectangle.
b. How many different rectangles did you find?
c. Explain the strategy you used to find the rectangles.
Answer:
a.

b. I could find three different rectangles having perimeter as 18 centimeters.

c. The strategy which I used to find the rectangles is that :
Step 1:  Considered the Perimeter formula 2 ( Length + Width ) and its perimeter value 18 centimeters.
Step 2: Calculated the Length and width values.
Step 3: Keeping in mind highest value as length and lesser as Width.

Explanation:
a.
b. I could find three different rectangles having perimeter as 18 centimeters.
c. The strategy which I used to find the rectangles is that :
Step 1:  Considered the Perimeter formula 2 ( Length + Width ) and its perimeter value 18 centimeters.
Step 2: Calculated the Length and width values.
Step 3: Keeping in mind highest value as length and lesser as Width.

 

Question 3.
The chart below shows the perimeters of three rectangles.
a. Write possible widths and lengths for each given perimeter.

Rectangle	Perimeter	Width and Length
A	6 cm	__________ cm by __________ cm
B	10 cm	__________ cm by __________ cm
C	14 cm	__________ cm by __________ cm

b. Double the perimeters of the rectangles in part (a). Then, find possible widths and lengths.

Rectangle	Perimeter	Width and Length
A	12 cm	__________ cm by __________ cm
B		__________ cm by __________ cm
C		__________ cm by __________ cm

Answer:
a.
b.
Explanation:
a. For the perimeter of 6cm, we have a rectangle length as 2cm and width as 1cm.
For the perimeter of 10cm, we have a rectangle length as 2cm and width as 3cm.
For the perimeter of 14cm, we have a rectangle length as 3cm and width as 4cm.

b. For the perimeter of 12cm, we have a rectangle length as 2cm and width as 4cm.

 

Engage NY Eureka Math 3rd Grade Module 1 Lesson 21 Answer Key

Eureka Math Grade 3 Module 1 Answer Key

Engage NY Math Grade 3 Module 1 Lesson 21 Pattern Sheet Answer Key

Multiply.

multiply by 5 (1–5)


Explanation :
Multiplied the given numbers and wrote respectively.

Eureka Math Grade 3 Module 1 Lesson 21 Problem Set Answer Key

Question 1.
Jason earns $6 per week for doing all his chores.
On the fifth week, he forgets to take out the trash,
so he only earns $4. Write and solve an equation to show
how much Jason earns in 5 weeks.

Jason earns ___$28__________.

Jason earns $28 in 5 weeks,

Explanation:
Given Jason earns $6 per week for doing all his chores.
On the fifth week, he forgets to take out the trash,
so he only earns $4. Equation of Jason’s earnings is
$6 +$6 + $6 +$6 + $4 = $28 is Jason earnings in 5 weeks.

Question 2.
Miss Lianto orders 4 packs of 7 markers. After passing out
1 marker to each student in her class, she has 6 left.
Label the tape diagram to find how many students are in Miss Lianto’s class.

There are __22__ students in Miss Lianto’s class.

There are __22__ students in Miss Lianto’s class.

Explanation:
Given Miss Lianto orders 4 packs of 7 markers. After passing out
1 marker to each student in her class, she has 6 left.
Labeled the tape diagram to show how many students
are in Miss Lianto’s class as
4 packs of 7 markers means number of markers are
7 X 4 = 28 or 7 + 7 + 7 + 7 = 28,
Each student got 1 marker in her class and 6 left,
means number of students in Miss Lianto’s class are
28 – 6 = 22 students as labeled in the tape diagram.
Therefore, there are  22 students in Miss Lianto’s class.

Question 3.
Orlando buys a box of 18 fruit snacks. Each box comes with
an equal number of strawberry-, cherry-, and grape-flavored snacks.
He eats all of the grape-flavored snacks. Draw and label a tape
diagram to find how many fruit snacks he has left.

Fruit snacks Orlando left are 12,

Explanation:
Given Orlando buys a box of 18 fruit snacks. Each box comes with
an equal number of strawberry-, cherry-, and grape-flavored snacks,
Orlando eats all of the grape-flavored snacks.
Drawn and labeled a tape
diagram to show how many fruit snacks Orlando has left are
Total fruit snacks 18, equal number of 3 fruit flavored snacks,
So each flavor is 18 ÷ 3 = 6 each, Now Orlando ate all of the grape –
flavored snacks, So fruit snacks Orlando has left are 18 – 6 = 12.
Therefore, Orlando has left 12 fruit snacks.

Question 4.
Eudora buys 21 meters of ribbon. She cuts the ribbon so that each
piece measures 3 meters in length.
a. How many pieces of ribbon does she have?
b. If Eudora needs a total of 12 pieces of the shorter ribbon,
how many more pieces of the shorter ribbon does she need?

a. Eudora has 7 pieces of ribbon,

Explanation:
Given Eudora buys 21 meters of ribbon. She cuts the ribbon
so that each piece measures 3 meters in length,
So number of pieces of ribbon she has is 21 ÷ 3 = 7 pieces of
ribbon.

b. Eudora needs more 5 pieces of the shorter ribbon,

Explanation:
If Eudora needs a total of 12 pieces of the shorter ribbon,
She needs more pieces of the shorter ribbon as 12 – 7 = 5 pieces.

Engage NY Math 3rd Grade Module 1 Lesson 21 Exit Ticket Answer Key

Ms. Egeregor buys 27 books for her classroom library.
She buys an equal number of fiction, nonfiction, and poetry books.
She shelves all of the poetry books first. Draw and label a tape diagram
to show how many books Ms. Egeregor has left to shelve.

Ms. Egeregor has left with 18 more books to shelve,

Explanation:
Given Ms. Egeregor buys 27 books for her classroom library.
She buys an equal number of fiction, nonfiction, and poetry books.
So each numbers of books are 27 ÷ 3 = 9,
9 books of fiction, 9 books of nonfiction and 9 books of poetry.
She shelves all of the poetry books first.
Drawn and labeled a tape diagram
to show number of books Ms. Egeregor has left to shelve is
27 – 9 = 18 more books.

Eureka Math 3rd Grade Module 1 Lesson 21 Homework Answer Key

Question 1.
Tina eats 8 crackers for a snack each day at school.
On Friday, she drops 3 and only eats 5. Write and solve
an equation to show the total number of crackers Tina eats during the week.

Tina eats ____37______ crackers.

Tina eats 37 crackers during the week,

Explanation:
Given Tina eats 8 crackers for a snack each day at school.
On Friday, she drops 3 and only eats 5. So Wrote and solved
an equation to show the total number of crackers Tina
ate during the week is 8 + 8 + 8 + 8 + 5 = 37 crackers.

Question 2.
Ballio has a reading goal. He checks 3 boxes of 9 books
out from the library. After finishing them, he realizes that
he beat his goal by 4 books! Label the tape diagrams to find
Ballio’s reading goal.

Ballio’s goal is to read ___23____ books.

Explanation :
Given Ballio has a reading goal. He checks 3 boxes of 9 books
out from the library. 3 X 9 = 27 books,
After finishing them, he realizes that he beat his goal by 4 books!
So his goal was 27 – 4 = 23 books,
Labeled the tape diagrams to show Ballio’s reading goal as 23 books.

Question 3.
Mr. Nguyen plants 24 trees around the neighborhood pond.
He plants equal numbers of maple, pine, spruce, and birch trees.
He waters the spruce and birch trees before it gets dark.
How many trees does Mr. Nguyen still need to water?
Draw and label a tape diagram.

Mr. Nguyen still needs to water 12 trees,

Explanation:
Given Mr. Nguyen plants 24 trees around the neighborhood pond.
He plants equal numbers of maple, pine, spruce, and birch trees.
So each numbers of trees are 24 ÷ 4 = 6 trees,
He waters the spruce and birch trees before it gets dark.
So number of more trees Mr. Nguyen still need to water is
24 – 12 = 12 trees.

Drawn and labeled a tape diagram to show Mr. Nguyen
still needs to water 12 trees.

Question 4.
Anna buys 24 seeds and plants 3 in each pot. She has 5 pots.
How many more pots does Anna need to plant all of her seeds?

Anna needs 3 more pots to plant all of her seeds.

Explanation:
Given Anna buys 24 seeds and plants 3 in each pot. She has 5 pots.
So she planted 5 X 3 = 15 seeds, Seeds left are 24 – 15 = 9 seeds,
As each pot she can plant 3 seeds she needs pots for 9 seeds as 9 ÷ 3 = 3,
Therefore, number of more pots Anna need to plant all of her seeds
are 3 pots.

Engage NY Eureka Math 3rd Grade Module 1 Lesson 20 Answer Key

Eureka Math Grade 3 Module 1 Answer Key

Eureka Math Grade 3 Module 1 Lesson 20 Sprint Answer Key

A
Skip-Count by 5

Question 1.
0, 5, __
0, 5, 10,

Explanation:
Given 0, 5, ___ skip count by 5,
0, 0 + 5 = 5, 5 + 5 = 10,
So, 0, 5, 10.

Question 2.
5, 10, __
5, 10, 15,

Explanation:
Given 5, 10, ___ skip count by 5,
5, 5 + 5 = 10, 10 + 5 = 15,
So, 5, 10, 15.

Question 3.
10, 15, __
10, 15, 20,

Explanation:
Given 10, 15, ___ skip count by 5,
10, 10 + 5 = 15, 15 + 5 = 20,
So, 10, 15, 20.

Question 4.
15, 20, __
15, 20, 25,

Explanation:
Given 15, 20, ___ skip count by 5,
15, 15 + 5 = 20, 20 + 5 = 25,
So, 15, 20, 25.

Question 5.
20, 25, __
20, 25, 30,

Explanation:
Given 20, 25, ___ skip count by 5,
20, 20 + 5 = 25, 25 + 5 = 30,
So, 20, 25, 30.

Question 6.
25, 30, __
25, 30, 35,

Explanation:
Given 25, 30, ___ skip count by 5,
25, 25 + 5 = 30, 30 + 5 = 35,
So, 25, 30, 35.

Question 7.
30, 35, __
30, 35, 40,

Explanation:
Given 30, 35, ___ skip count by 5,
30, 30 + 5 = 35, 35 + 5 = 40,
So, 30, 35, 40.

Question 8.
35, 40, __
35, 40, 45,

Explanation:
Given 35, 40, ___ skip count by 5,
35, 35 + 5 = 40, 40 + 5 = 45,
So, 35, 40, 45.

Question 9.
40, 45, __
40, 45, 50,

Explanation:
Given 40, 45, ___ skip count by 5,
40, 40 + 5 = 45, 45 + 5 = 50,
So, 40, 45, 50.

Question 10.
50, 45, __
50, 45, 40,

Explanation:
Given 50, 45, ___ skip count by 5,
50, 50 – 5 = 45, 45 – 5 = 40,
So, 50, 45, 40.

Question 11.
45, 40, __
45, 40, 35,

Explanation:
Given 45, 40, ___ skip count by 5,
45, 45 – 5 = 40, 40 – 5 = 35,
So, 45, 40, 35.

Question 12.
40, 35, __
40, 35, 30,

Explanation:
Given 40, 35, ___ skip count by 5,
40, 40 – 5 = 35, 35 – 5 = 30,
So, 40, 35, 30.

Question 13.
35, 30, __
35, 30, 25,

Explanation:
Given 35, 30, ___ skip count by 5,
35, 35 – 5 = 30, 30 – 5 = 25,
So, 35, 30, 25.

Question 14.
30, 25, __
30, 25, 20

Explanation:
Given 30, 25, ___ skip count by 5,
30, 30 – 5 = 25, 25 – 5 = 20,
So, 30, 25, 20.

Question 15.
25, 20, __
25, 20,15,

Explanation:
Given 25, 20, ___ skip count by 5,
25, 25 – 5 = 20, 20 – 5 = 15,
So, 25, 20, 15.

Question 16.
20, 15, __
20, 15, 10,

Explanation:
Given 20, 15, ___ skip count by 5,
20, 20 – 5 = 15, 15 – 5 = 10,
So, 20, 15, 10.

Question 17.
15, 10, __
15, 10, 5,

Explanation:
Given 15, 10, ___ skip count by 5,
15, 15 – 5 = 10, 10 – 5 = 5,
So, 15, 10, 5.

Question 18.
0, __, 10
0, 5, 10,

Explanation:
Given 0, ___, 10 skip count by 5,
0, 0 + 5 = 5, 5 + 5 = 10,
So, 0, 5, 10.

Question 19.
25, __, 35
25, 30, 35,

Explanation:
Given 25, ___, 35 skip count by 5,
25, 25 + 5 = 30, 30 + 5 = 35,
So, 25, 30, 35.

Question 20.
5, __, 15
5, 10, 15,

Explanation:
Given 5, ___, 15 skip count by 5,
5, 5 + 5 = 10, 10 + 5 = 15,
So, 5, 10, 15.

Question 21.
30, __, 40
30, 35, 40,

Explanation:
Given 30, ___, 40 skip count by 5,
30, 30 + 5 = 35, 35 + 5 = 40,
So, 30, 35, 40.

Question 22.
10, __, 20
10, 15, 20,

Explanation:
Given 10, ___, 20 skip count by 5,
10, 10 + 5 = 15, 15 + 5 = 20,
So, 10, 15, 20.

Question 23.
35, __, 45
35, 40, 45,

Explanation:
Given 35, ___, 45 skip count by 5,
35, 35 + 5 = 40, 40 + 5 = 45,
So, 35, 40, 45.

Question 24.
15, __, 25
15, 20, 25,

Explanation:
Given 15, ___, 25 skip count by 5,
15, 15 + 5 = 20, 20 + 5 = 25,
So, 15, 20, 25.

Question 25.
40, __, 50
40, 45, 50,

Explanation:
Given 40, ___, 50 skip count by 5,
40, 40 + 5 = 45, 45 + 5 = 50,
So, 40, 45, 50.

Question 26.
25, __, 15
25, 20, 15,

Explanation:
Given 25, ___, 15 skip count by 5,
25, 25 – 5 = 20, 20 – 5 = 15,
So, 25, 20, 15.

Question 27.
50, __, 40
50, 45, 40,

Explanation:
Given 50, ___, 40 skip count by 5,
50, 50 – 5 = 45, 45 – 5 = 40,
So, 50, 45, 40.

Question 28.
20, __, 10
20, 15, 10,

Explanation:
Given 20, ___, 10 skip count by 5,
20, 20 – 5 = 15, 15 – 5 = 10,
So, 20, 15, 10.

Question 29.
45, __, 35
45, 40, 35,

Explanation:
Given 45, ___, 35 skip count by 5,
45, 45 – 5 = 40, 40 – 5 = 35,
So, 45, 40, 35.

Question 30.
15, __, 5
15, 10, 5,

Explanation:
Given 15, ___, 5 skip count by 5,
15, 15 – 5 = 10, 10 – 5 = 5,
So, 15, 10, 5.

Question 31.
40, __, 30
40, 35, 30,

Explanation:
Given 40, ___, 30 skip count by 5,
40, 40 – 5 = 35, 35 – 5 = 30,
So, 40, 35, 30.

Question 32.
10, __, 0
10, 5, 0,

Explanation:
Given 10, ___, 0 skip count by 5,
10, 10 – 5 = 5, 5 – 5 = 0,
So, 10, 5, 0.

Question 33.
35, __, 25
35, 30, 25,

Explanation:
Given 35, ___, 25 skip count by 5,
35, 35 – 5 = 30, 30 -5 = 25,
So, 35, 30, 25.

Question 34.
__, 10, 5
15, 10, 5,

Explanation:
Given  ___,10, 5 skip count by 5,
15, 5 + 5 = 10, 5 + 0 = 5,
So, 15, 10, 5.

Question 35.
__, 35, 30
40, 35, 30,

Explanation:
Given  ___,35, 30 skip count by 5,
40, 30 + 5 = 35, 25 + 5 = 30,
So, 40, 35, 30.

Question 36.
__, 15, 10
20, 15, 10,

Explanation:
Given  ___,15, 10 skip count by 5,
20, 10 + 5 = 15, 5 + 5 = 10,
So, 20, 15, 10.

Question 37.
__, 40, 35
45, 40, 35,

Explanation:
Given  ___,40, 35 skip count by 5,
45 = 40 + 5, 40 = 35 + 5, 35 = 30 + 5,
So, 45, 40, 35.

Question 38.
__, 20, 15
25, 20, 15,

Explanation:
Given  ___,20, 15 skip count by 5,
25 = 20 + 5, 20 = 15 + 5, 15 = 10 + 5,
So, 25, 20, 15.

Question 39.
__, 45, 40
50, 45, 40,

Explanation:
Given  ___,45, 40 skip count by 5,
50 = 45 + 5, 45 = 40 + 5, 40 = 35 + 5,
So, 50, 45, 40.

Question 40.
50, 55, __
50, 55, 60,

Explanation:
Given 50, 55, ___ skip count by 5,
50, 50 + 5 = 55, 55 + 5 = 60,
So, 50, 55, 60.

Question 41.
45, 50, __
45, 50, 55,

Explanation:
Given 45, 50, ___ skip count by 5,
45, 45 + 5 = 50, 50 + 5 = 55,
So, 45, 50, 55.

Question 42.
65, __, 55
65, 60, 55

Explanation:
Given 65, ___, 55 skip count by 5,
65, 55 + 5 = 60, 50 + 5 = 55,
So, 65, 60, 55.

Question 43.
55, 60, __
55, 60, 65,

Explanation:
Given 55, 60, ___ skip count by 5,
50 + 5 = 55, 55 + 5 = 60, 60 + 5 = 65,
So, 55, 60, 65.

Question 44.
60, 65, __
60, 65, 70

Explanation:
Given 60, 65, ___ skip count by 5,
55 + 5 = 60, 60 + 5 = 65, 65 + 5 = 70,
So, 60, 65, 70.

B
Skip-Count by 5

Question 1.
5, 10, __
5, 10, 15,

Explanation:
Given 5, 10, ___skip count by 5,
0 + 5 = 5, 5 + 5 = 10, 10 + 5 = 15,
So, 5, 10, 15.

Question 2.
10, 15, __
10, 15, 20

Explanation:
Given 10, 15, ___skip count by 5,
5 + 5 = 10, 10 + 5 = 15, 15 + 5 = 20,
So, 10, 15, 20.

Question 3.
15, 20, __
15, 20, 25.

Explanation:
Given 15, 20, ___skip count by 5,
10 + 5 = 15, 15 + 5 = 20, 20 + 5 = 25,
So, 15, 20, 25.

Question 4.
20, 25, __
20, 25, 30.

Explanation:
Given 20 25, ___skip count by 5,
15 + 5 = 20, 20 + 5 = 25, 25 + 5 = 30,
So, 20, 25, 30.

Question 5.
25, 30, __
25, 30, 35.

Explanation:
Given 25, 30, ___skip count by 5,
20 + 5 = 25, 25 + 5 = 30, 30 + 5 = 35,
So, 25, 30, 35.

Question 6.
30, 35, __
30, 35,40.

Explanation:
Given 30, 35, ___skip count by 5,
25 + 5 = 30, 30 + 5 = 35, 35 + 5 = 40,
So, 30, 35, 40.

Question 7.
35, 40, __
35, 40, 45.

Explanation:
Given 35, 40, ___skip count by 5,
30 + 5 = 35, 35 + 5 = 40, 40 + 5 = 45,
So, 35, 40, 45.

Question 8.
40, 45, __
40, 45, 50.

Explanation:
Given 40, 45, ___skip count by 5,
35 + 5 = 40, 40 + 5 = 45, 45 + 5 = 50,
So, 40, 45, 50.

Question 9.
50, 45, __
50, 45, 40.

Explanation:
Given 50, 45, ___skip count by 5,
55 – 5 = 50, 50 – 5 = 45, 45 – 5 = 40,
So, 50, 45, 40.

Question 10.
45, 40, __
45, 40, 35.

Explanation:
Given 45, 40, ___skip count by 5,
50 – 5 = 45, 45 – 5 = 40, 40 – 5 = 35,
So, 45, 40, 35.

Question 11.
40, 35, __
40, 35, 30,

Explanation:
Given 40, 35, ___skip count by 5,
45 – 5 = 40, 40 – 5 = 35, 35 – 5 = 30,
So, 40, 35, 30.

Question 12.
35, 30, __
35, 30, 25,

Explanation:
Given 35, 30, ___skip count by 5,
40 – 5 = 35, 35 – 5 = 30, 30 – 5 = 25,
So, 35, 30, 25.

Question 13.
30, 25, __
30, 25, 20,

Explanation:
Given 30, 25, ___skip count by 5,
35 – 5 = 30, 30 – 5 = 25, 25 – 5 = 20,
So, 30, 25, 20.

Question 14.
25, 20, __
25, 20, 15

Explanation:
Given 25, 20, ___skip count by 5,
30 – 5 = 25, 25 – 5 = 20, 20 – 5 = 15,
So, 25, 20, 15.

Question 15.
20, 15, __
20, 15, 10,

Explanation:
Given 20, 15, ___skip count by 5,
25 – 5 = 20, 20 – 5 = 15, 15 – 5 = 10,
So, 20, 15, 10.

Question 16.
15, 10, __
15, 10, 5,

Explanation:
Given 15, 10, ___skip count by 5,
20 – 5 = 15, 15 – 5 = 10, 10 – 5 = 5,
So, 15, 10, 5.

Question 17.
0, __, 10
0, 5, 10,

Explanation:
Given 0, ___, 10 skip count by 5,
0 + 0 = 0, 0 + 5 = 5, 5 + 5 = 10,
So, 0, 5, 10.

Question 18.
25, __, 35
25, 30, 35,

Explanation:
Given 25, ___, 35 skip count by 5,
20 + 5 = 25, 25 + 5 = 30, 30 + 5 = 35,
So,  25, 30, 35.

Question 19.
5, __, 15
5, 10, 15,

Explanation:
Given 5, ___, 15 skip count by 5,
0 + 5 = 5, 5 + 5 = 10, 10 + 5 = 15,
So, 5, 10,15.

Question 20.
30, __, 40
30, 35, 40,

Explanation:
Given 30, ___, 40 skip count by 5,
25 + 5 = 30, 30 + 5 = 35, 35 + 5 = 40,
So, 30, 35, 40.

Question 21.
10, __, 20
10, 15, 20,

Explanation:
Given 10, ___, 20 skip count by 5,
5 + 5 = 10, 10 + 5 = 15, 15 + 5 = 20,
So, 10, 15, 20.

Question 22.
35, __, 45
35, 40, 45,

Explanation:
Given 35, ___, 45 skip count by 5,
30 + 5 = 35, 35 + 5 = 40, 40 + 5 = 45,
So, 35, 40, 45.

Question 23.
15, __, 25
15, 20, 25,

Explanation:
Given 15, ___, 25 skip count by 5,
10 + 5 = 15, 15 + 5 = 20, 20 + 5 = 25,
So, 15, 20, 25.

Question 24.
35, __, 45
35, 40, 45,

Explanation:
Given 35, ___, 45 skip count by 5,
30 + 5 = 35, 35 + 5 = 40, 40 + 5 = 45,
So, 35, 40, 45.

Question 25.
20, __, 30
20, 25, 30,

Explanation:
Given 20, ___, 30 skip count by 5,
15 + 5 = 20, 20 + 5 = 25, 25 + 5 = 30,
So, 20, 25, 30.

Question 26.
25, __, 15
25, 20, 15,

Explanation:
Given 25, ___, 15 skip count by 5,
30 – 5 = 25, 25 – 5 = 20, 20 – 5 = 15,
So, 25, 20, 15.

Question 27.
50, __, 60
50, 55, 60,

Explanation:
Given 50, ___, 60 skip count by 5,
45 + 5 = 50, 50 + 5 = 55, 55 + 5 = 60,
So, 50, 55, 60.

Question 28.
20, __, 10
20, 15, 10,

Explanation:
Given 20, ___, 10 skip count by 5,
25 – 5 = 20, 20 – 5 = 15, 15 – 5 = 10,
So, 20, 15, 10.

Question 29.
45, __, 35
45, 40, 35,

Explanation:
Given 45, ___, 35 skip count by 5,
50 – 5 = 45, 45 – 5 = 40, 40 – 5 = 35,
So, 45, 40, 35.

Question 30.
15, __, 5
15, 10, 5,

Explanation:
Given 15, ___, 5 skip count by 5,
20 – 5 = 15, 15 – 5 = 10, 10 – 5 = 5,
So, 15, 10, 5.

Question 31.
35, __, 25
35, 30, 25,

Explanation:
Given 35, ___, 25 skip count by 5,
40 + 5 = 35, 35 – 5 = 30, 30 – 5 = 25,
So, 35, 30, 25.

Question 32.
10, __, 0
10, 5, 0,

Explanation:
Given 10, ___, 0 skip count by 5,
15 – 0 = 10, 10 – 5 = 5, 5 – 5 = 0,
So, 10, 5, 0.

Question 33.
35, __, 25
35, 30, 25,

Explanation:
Given 35, ___, 25 skip count by 5,
35, 35 – 5 = 30, 30 – 5 = 25,
So, 35, 30, 25.

Question 34.
__, 15, 10
20, 15, 10,

Explanation:
Given ___, 15, 10 skip count by 5,
20 = 15 + 5, 15 = 10 + 5, 10 = 5 + 5,
So, 20, 15, 10.

Question 35.
__, 40, 35
45, 40, 35,

Explanation:
Given ___, 40, 35 skip count by 5,
45 = 40 + 5, 40 = 35 + 5, 35 = 30 + 5,
So, 45, 40, 35.

Question 36.
__, 20, 15
25, 20, 15,

Explanation:
Given ___, 20, 15 skip count by 5,
25 = 20 + 5, 20 = 15 + 5, 15 = 10 + 5,
So, 25, 20, 15.

Question 37.
__, 45, 40
50, 45, 40,

Explanation:
Given ___, 45, 40 skip count by 5,
50 = 45 + 5, 45 = 40 + 5, 40 = 35 + 5,
So, 50, 45, 40.

Question 38.
__, 10, 5
15, 10, 5

Explanation:
Given ___, 10, 5 skip count by 5,
15 = 10 + 5, 10 = 5 + 5, 5 = 5 + 0,
So, 15, 10, 5.

Question 39.
__, 35, 30
40, 35, 30,

Explanation:
Given ___, 35, 30 skip count by 5,
40 = 35 + 5, 35 = 30 + 5, 30 = 25 + 5,
So, 40, 35, 30.

Question 40.
45, 50, __
45, 50, 55,

Explanation:
Given 45, 50, ___ skip count by 5,
45, 45 + 5 = 50, 50 + 5 = 55,
So, 45, 50, 55.

Question 41.
50, 55, __
50, 55, 60,

Explanation:
Given 55, 55, ___ skip count by 5,
50, 50 + 5 = 55, 55 + 5 = 60,
So, 50, 55, 60.

Question 42.
55, 60, __
55, 60, 65,

Explanation:
Given 55, 60, ___ skip count by 5,
55, 55 + 5 = 60, 60 + 5 = 65,
So, 55, 60, 65.

Question 43.
65, __, 55
65, 60, 55,

Explanation:
Given 65, 60, ___ skip count by 5,
65, 65 – 5 = 60, 60 – 5 = 55,
So, 65, 60, 55.

Question 44.
__, 60, 55
65, 60, 55,

Explanation:
Given 65, 60, ___ skip count by 5,
65 = 60 +5, 60 = 55 + 5, 55 = 50 + 5,
So, 65, 60, 55.

Eureka Math Grade 3 Module 1 Lesson 20 Problem Set Answer Key

Question 1.
Ted buys 3 books and a magazine at the book store.
Each book costs $8. A magazine costs $4.

a. What is the total cost of the books?
b. How much does Ted spend altogether?

a. Total cost of the books is $24,

Explanation:
Given Ted buys 3 books and each book costs $8,
So, total cost of the books is 3 X $8 = $24.

b. Ted has spend $28 altogether,

Explanation:
Given Ted buys 3 books and a magazine at the book store.
Each book costs $8 and  A magazine costs $4, So total
amount spent is Cost of books + Cost of magazine =
(3 X $ 8) + $4  = $24 + $4 = $28.

Question 2.
Seven children share 28 silly bands equally.

a. How many silly bands does each child get?
b. How many silly bands do 3 children get?

a. Each child gets 4 silly bands,

Explanation:
Given seven children share 28 silly bands equally,
so each child get 28 ÷ 7 = 4.

b. 3 children gets 12 silly bands,

Explanation:
We know each child gets 4 silly bands, So 3 children gets
3 X 4 = 12 silly bands.

Question 3.
Eighteen cups are equally packed into 6 boxes.
Two boxes of cups break. How many cups are unbroken?

12 cups are unbroken,

Explanation:
Given eighteen cups are equally packed into 6 boxes
means each box has 18 ÷ 6 = 3 cups.
Two boxes of cups break means 2 X 3 = 6 cups are broken,
Now number of cups unbroken are 18 – 6 = 12 cups.

Question 4.
There are 25 blue balloons and 15 red balloons at a party.
Five children are given an equal number of each color balloon.
How many blue and red balloons does each child get?

Each child gets 5 blue balloons and 3 red balloons in the party,

Explanation:
Given there are 25 blue balloons and 15 red balloons at a party.
Five children are given an equal number of each color balloon.
So each child gets blue balloons as 25 ÷ 5 = 5 and
red balloons as 15 ÷ 5 = 3.

Question 5.
Twenty-seven pears are packed in bags of 3.
Five bags of pears are sold. How many bags of pears are left?

4 bags of pears are left,

Explanation:
Given Twenty-seven pears are packed in bags of 3,
So number of bags of pears are 27 ÷ 3 = 9 bags,
and 5 bags of pears are sold, therefore left bags of pears
are 9 – 5 = 4 bags.

Eureka Math Grade 3 Module 1 Lesson 20 Exit Ticket Answer Key

Question 1.
Thirty-two jelly beans are shared by 8 students.

a. How many jelly beans will each student get?
b. How many jelly beans will 4 students get?

a. 4 jelly beans each student will get.

Explanation:
Given Thirty-two jelly beans are shared by 8 students,
So each student will get 32 ÷ 8 = 4 jelly beans.

b. 4 students will get 4 X 4 = 16 jelly beans,

Explanation:
As we know each student will get 4 jelly beans,
for 4 students it will be 4 x 4 = 16 jelly beans.

Question 2.
The teacher has 30 apple slices and 20 pear slices.
Five children equally share all of the fruit slices.
How many fruit slices does each child get?

Each child gets 6 apple slices and 4 pear slices,

Explanation:
Given the teacher has 30 apple slices and 20 pear slices,
Five children equally share all of the fruit slices.
So number of fruit slices each child gets is
30 ÷ 5 = 6 apple slices and 20 ÷ 5 = 4 pear slices.

Eureka Math Grade 3 Module 1 Lesson 20 Homework Answer Key

Question 1.
Jerry buys a pack of pencils that costs $3. David buys 4 sets of markers.
Each set of markers also costs $3.

a. What is the total cost of the markers?
b. How much more does David spend on 4 sets of markers than
Jerry spends on a pack of pencils?

a. Total cost of markers are $12,

Explanation:
Given David buys 4 sets of markers,
Each set of markers costs $3, So total cost
of markers are 4 X $3 = $12,

b. $9 more David has spend on 4 sets of markers than
Jerry spends on a pack of pencils,

Explanation:
Given Jerry buys a pack of pencils that costs $3.
David buys 4 sets of markers. Each set of markers also costs $3
and we know total cost of markers is $12, Now more David has
than Jerry is $12 – $3 = $9.

Question 2.
Thirty students are eating lunch at 5 tables. Each table has
the same number of students.
a. How many students are sitting at each table?

b. How many students are sitting at 4 tables?

a. 6 students are sitting on each table,

Explanation:
Given thirty students are eating lunch at 5 tables.
Each table has the same number of students.
So number of students sitting at each table are
30 ÷ 5 = 6.

b. 24 students are sitting at 4 tables,

Explanation:
We know at each table there are 6 students sitting and
eating lunch, So at 4 tables there are 6 x 4 = 24 students
having lunch.

Question 3.
The teacher has 12 green stickers and 15 purple stickers.
Three students are given an equal number of each color sticker.
How many green and purple stickers does each student get?

Each student will get 4 green stickers and 5 purple stickers,

Explanation:
Given the teacher has 12 green stickers and 15 purple stickers.
Three students are given an equal number of each color sticker.
So number of green and purple stickers each student gets is
12 ÷ 3 = 4 green stickers and 15 ÷ 3 = 5 purple stickers.

Question 4.
Three friends go apple picking. They pick 13 apples on
Saturday and 14 apples on Sunday. They share the apples equally.
How many apples does each person get?

Each person will get 9 apples,

Explanation:
Given three friends go for apple picking. They pick 13 apples on
Saturday and 14 apples on Sunday and they share the apples equally.
Therefore number of apples each person will get is 13 + 14 = 27 apples,
27 ÷ 3 = 9 apples each.

Question 5.
The store has 28 notebooks in packs of 4. Three packs of
notebooks are sold. How many packs of notebooks are left?

4 packs of notebooks are left,

Explanation:
Given the store has 28 notebooks in packs of 4.
Three packs of notebooks are sold. So, number of
packs of notebooks are 28 ÷ 4 = 7 packs,
Now from 7 packs of notebooks 4 packs are sold,
So, left packs of notebooks are 7 – 3 = 4 packs.

Engage NY Eureka Math 3rd Grade Module 7 Lesson 23 Answer Key

Eureka Math Grade 3 Module 7 Lesson 23 Sprint Answer Key

A
Multiply or Divide by 5

Answer:

Question 1.
2 × 5 =
Answer:
2 × 5 = 10.

Question 2.
3 × 5 =
Answer:
3 × 5 = 15.

Question 3.
4 × 5 =
Answer:
4 × 5 = 20.

Question 4.
5 × 5 =
Answer:
5 × 5 = 25.

Question 5.
1 × 5 =
Answer:
1 × 5 = 5.

Question 6.
10 ÷ 5 =
Answer:
10 ÷ 5 = 2.

Question 7.
15 ÷ 5 =
Answer:
15 ÷ 5 = 3.

Question 8.
25 ÷ 5 =
Answer:
25 ÷ 5 = 5.

Question 9.
5 ÷ 5 =
Answer:
5 ÷ 5 = 1.

Question 10.
20 ÷ 5 =
Answer:
20 ÷ 5 = 4.

Question 11.
6 × 5 =
Answer:
6 × 5 = 30.

Question 12.
7 × 5 =
Answer:
7 × 5 = 35.

Question 13.
8 × 5 =
Answer:
8 × 5 = 40.

Question 14.
9 × 5 =
Answer:
9 × 5 = 45.

Question 15.
10 × 5 =
Answer:
10 × 5 = 50.

Question 16.
40 ÷ 5 =
Answer:
40 ÷ 5 = 8.

Question 17.
35 ÷ 5 =
Answer:
35 ÷ 5 = 7.

Question 18.
45 ÷ 5 =
Answer:
45 ÷ 5 = 9.

Question 19.
30 ÷ 5 =
Answer:
30 ÷ 5 = 6.

Question 20.
50 ÷ 5 =
Answer:
50 ÷ 5 = 10.

Question 21.
___ × 5 = 25
Answer:
_5__ × 5 = 25.

Question 22.
___ × 5 = 5
Answer:
_1__ × 5 = 5.

Question 23.
___ × 5 = 50
Answer:
_10__ × 5 = 50.

Question 24.
___ × 5 = 10
Answer:
_2__ × 5 = 10.

Question 25.
___ × 5 = 15
Answer:
_3__ × 5 = 15.

Question 26.
50 ÷ 5 =
Answer:
50 ÷ 5 = 10.

Question 27.
25 ÷ 5 =
Answer:
25 ÷ 5 = 5.

Question 28.
5 ÷ 5 =
Answer:
5 ÷ 5 = 1.

Question 29.
10 ÷ 5 =
Answer:
10 ÷ 5 = 2.

Question 30.
15 ÷ 5 =
Answer:
15 ÷ 5 = 3.

Question 31.
___ × 5 = 30
Answer:
_6__ × 5 = 30.

Question 32.
___ × 5 = 35
Answer:
_7__ × 5 = 35.

Question 33.
___ × 5 = 45
Answer:
__9_ × 5 = 45.

Question 34.
___ × 5 = 40
Answer:
__8_ × 5 = 40.

Question 35.
35 ÷ 5 =
Answer:
35 ÷ 5 = 7.

Question 36.
45 ÷ 5 =
Answer:
45 ÷ 5 = 9.

Question 37.
30 ÷ 5 =
Answer:
30 ÷ 5 = 6.

Question 38.
40 ÷ 5 =
Answer:
40 ÷ 5 = 8.

Question 39.
11 × 5 =
Answer:
11 × 5 = 55.

Question 40.
55 ÷ 5 =
Answer:
55 ÷ 5 = 11.

Question 41.
15 ÷ 5 =
Answer:
15 ÷ 5 = 3.

Question 42.
60 ÷ 5 =
Answer:
60 ÷ 5 = 12.

Question 43.
12 × 5 =
Answer:
12 × 5 = 60.

Question 44.
70 ÷ 5 =
Answer:
70 ÷ 5 = 14.

B
Multiply or Divide by 5

Answer:

Question 1.
1 × 5 =
Answer:
1 × 5 = 5.

Question 2.
2 × 5 =
Answer:
2 × 5 = 10.

Question 3.
3 × 5 =
Answer:
3 × 5 = 15.

Question 4.
4 × 5 =
Answer:
4 × 5 = 20.

Question 5.
5 × 5 =
Answer:
5 × 5 = 25.

Question 6.
15 ÷ 5 =
Answer:
15 ÷ 5 = 3.

Question 7.
10 ÷ 5 =
Answer:
10 ÷ 5 = 2.

Question 8.
20 ÷ 5 =
Answer:
20 ÷ 5 = 4.

Question 9.
5 ÷ 5 =
Answer:
5 ÷ 5 = 1.

Question 10.
25 ÷ 5 =
Answer:
25 ÷ 5 = 5.

Question 11.
10 × 5 =
Answer:
10 × 5 = 50.

Question 12.
6 × 5 =
Answer:
6 × 5 = 30.

Question 13.
7 × 5 =
Answer:
7 × 5 = 35.

Question 14.
8 × 5 =
Answer:
8 × 5 = 40.

Question 15.
9 × 5 =
Answer:
9 × 5 = 45.

Question 16.
35 ÷ 5 =
Answer:
35 ÷ 5 = 7.

Question 17.
30 ÷ 5 =
Answer:
30 ÷ 5 = 6.

Question 18.
40 ÷ 5 =
Answer:
40 ÷ 5 = 8.

Question 19.
50 ÷ 5 =
Answer:
50 ÷ 5 = 10.

Question 20.
45 ÷ 5 =
Answer:
45 ÷ 5 = 9.

Question 21.
___ × 5 = 5
Answer:
_1__ × 5 = 5.

Question 22.
___ × 5 = 25
Answer:
_5__ × 5 = 25.

Question 23.
___ × 5 = 10
Answer:
_2__ × 5 = 10.

Question 24.
___ × 5 = 50
Answer:
_10__ × 5 = 50.

Question 25.
___ × 5 = 15
Answer:
_3__ × 5 = 15.

Question 26.
10 ÷ 5 =
Answer:
10 ÷ 5 = 50.

Question 27.
5 ÷ 5 =
Answer:

Question 28.
50 ÷ 5 =
Answer:

Question 29.
25 ÷ 5 =
Answer:

Question 30.
15 ÷ 5 =
Answer:

Question 31.
___ × 5 = 15
Answer:

Question 32.
___ × 5 = 20
Answer:

Question 33.
___ × 5 = 45
Answer:

Question 34.
___ × 5 = 35
Answer:

Question 35.
40 ÷ 5 =
Answer:

Question 36.
45 ÷ 5 =
Answer:

Question 37.
30 ÷ 5 =
Answer:

Question 38.
35 ÷ 5 =
Answer:

Question 39.
11 × 5 =
Answer:

Question 40.
55 ÷ 5 =
Answer:

Question 41.
12 × 5 =
Answer:

Question 42.
60 ÷ 5 =
Answer:

Question 43.
13 × 5 =
Answer:

Question 44.
65 ÷ 5 =
Answer:

Eureka Math Grade 3 Module 7 Lesson 23 Problem Set Answer Key

Question 1.
Gale makes a miniature stop sign, a regular octagon, with a perimeter of 48 centimeters for the town he built with blocks. What is the length of each side of the stop sign?
Answer:
The length of each side of the stop sign = 6 centimeters.

Explanation:
Perimeter of Gale a miniature stop sign, a regular octagon = 48 centimeters
Number of sides of Gale a miniature stop sign, a regular octagon = 8
The length of each side of the stop sign = Perimeter of Gale a miniature stop sign, a regular octagon  ÷ Number of sides of Gale a miniature stop sign, a regular octagon
= 48 centimeters ÷  8
= 6 centimeters.

 

Question 2.
Travis bends wire to make rectangles. Each rectangle measures 34 inches by 12 inches. What is the total length of the wire needed for two rectangles?
Answer:
The total length of the wire needed for two rectangles = 184 inches.

Explanation:
Length of the Travis’s rectangle = 34 inches
Width of the Travis’s rectangle = 12 inches
Perimeter of the Travis’s rectangle = 2 ( Length + Width)
= 2 ( 34 inches + 12 inches )
= 2 × 46 inches
= 92 inches.
The total length of the wire needed for two rectangles = 2 ×  Perimeter of the Travis’s rectangle
= 2 ×  92 inches
= 184 inches.

 

Question 3.
The perimeter of a rectangular bathroom is 32 feet. The width of the room is 8 feet. What is the length of the room?
Answer:
The length of the room = 8 feet.

Explanation:
Perimeter of a rectangular bathroom = 32 feet.
Width of a rectangular bathroom = 8 feet.
Length of a rectangular bathroom = ??
Perimeter of a rectangular bathroom = 2 ( Length + Width)
=> 32 feet = (2 × Length) + (2 × 8 feet)
=> 32 feet = (2 × Length) + 16 feet
=> 32 feet – 16 feet = (2 × Length)
=> 16 feet = (2 × Length)
=> 16 feet ÷ 2 = Length
=> 8 feet = Length

 

Question 4.
Raj uses 6-inch square tiles to make a rectangle, as shown below. What is the perimeter of the rectangle in inches?

Answer:
Perimeter of the rectangle in inches =96-inches.

Explanation:

Length of the side square tiles Raj uses to make a rectangle = 6-inch
Number of side of square tiles in the rectangle = 16
Perimeter of the rectangle in inches = Length of the side square tiles Raj uses to make a rectangle × Number of side of square tiles in the rectangle
= 6-inch × 16
= 96-inches.

 

Question 5.
Mischa makes a 4-foot by 6-foot rectangular banner. She puts ribbon around the outside edges. The ribbon costs $2 per foot. What is the total cost of the ribbon?
Answer:
Total cost of the ribbon = $20.

Explanation:
Length of the rectangular banner = 6-foot
Width of the rectangular banner = 4-foot
Perimeter of the rectangular banner = 2 ( Length + Width)
= 2 ( 6-foot + 4-foot )
= 2 × 10-foot
= 20- foot.
Cost of the ribbon per foot = $2
Total cost of the ribbon = Perimeter of the rectangular banner × Cost of the ribbon per foot
= 20- foot × $2
= $40.

 

Question 6.
Colton buys a roll of wire fencing that is 120 yards long. He uses it to fence in his 18-yard by 24-yard rectangular garden. Will Colton have enough wire fencing left over to fence in a 6-yard by 8-yard rectangular play space for his pet rabbit?
Answer:
Yes, Colton has wire fencing left over to fence for rectangular play space for his pet rabbit.

Explanation:
Total length of wire Colton purchased = 120 yards.
Length of the rectangular garden = 24-yard
Width of the rectangular garden = 18-yard
Perimeter of the rectangular garden = 2 ( Length + Width)
= 2 ( 24-yard + 18-yard )
= 2 × 42-yard
= 84-yard.
Wire used = Total length of wire Colton purchased – Perimeter of the rectangular garden
= 120 yards – 84 yards
= 36 yards.
Length of the rectangular play space for his pet rabbit = 8-yard
Width of the rectangular play space for his pet rabbit = 6-yard
Perimeter of the rectangular play space for his pet rabbit = 2 ( Length + Width)
= 2 ( 8-yard + 6-yard )
= 2 × 14-yard
= 28-yard.
Wire left = Wire used – Perimeter of the rectangular play space for his pet rabbit
= 36 yards – 28 yards
= 8 yards.

 

Eureka Math Grade 3 Module 7 Lesson 23 Exit Ticket Answer Key

Adriana traces a regular triangle to create the shape below. The perimeter of her shape is 72 centimeters. What are the side lengths of the triangle?

Answer:
The side lengths of the triangle = 9 centimeters.

Explanation:

Perimeter of Adriana’s shape = 72 centimeters
Number of sides of the triangle shape = 8
The side lengths of the triangle = Perimeter of Adriana’s shape  ÷ Number of sides of the triangle shape
= 72 centimeters ÷ 8
= 9 centimeters.

 

Eureka Math Grade 3 Module 7 Lesson 23 Homework Answer Key

Question 1.
Rosie draws a square with a perimeter of 36 inches. What are the side lengths of the square?
Answer:
The side lengths of the square = 9 inches.

Explanation:
Perimeter of the Square = 36 inches
Number of sides in the square = 4
The side lengths of the square = Perimeter of the Square  ÷ Number of sides in the square
= 36 inches ÷ 4
= 9 inches.

 

Question 2.
Judith uses craft sticks to make two 24-inch by 12-inch rectangles. What is the total perimeter of the 2 rectangles?
Answer:
Total perimeter of the 2 rectangles = 144 inches.

Explanation:
Length of the rectangle = 24-inch
Width of the rectangle = 12-inch
Perimeter of the rectangle = 2 ( Length + Width)
= 2 ( 24-inch + 12-inch )
= 2 × 36-inch
= 72 inches.
Total perimeter of the 2 rectangles = Perimeter of the rectangle × 2
= 72 inches × 2
= 144 inches.

 

Question 3.
An architect draws a square and a rectangle, as shown below, to represent a house that has a garage. What is the total perimeter of the house with its attached garage?

Answer:
Perimeter of the attached garage = 250 ft.

Explanation:

Length of the side AB in the attached garage = 55 ft
Length of the side BC in the attached garage = 10 ft
Length of the side CD in the attached garage = 30 ft
Length of the side DE in the attached garage = 30 ft
Length of the side EF in the attached garage = 30 ft
Length of the side FG in the attached garage = 55 ft
Length of the side GA in the attached garage = 40 ft
Perimeter of the attached garage = Length of the side AB in the attached garage  +  Length of the side BC in the attached garage + Length of the side CD in the attached garage + Length of the side DE in the attached garage + Length of the side EF in the attached garage + Length of the side FG in the attached garage + Length of the side GA in the attached garage
= 55 ft + 10 ft + 30 ft + 30 ft + 30 ft + 55 ft + 40 ft
= 65 ft + 30 ft + 30 ft + 30 ft + 55 ft + 40 ft
= 95 ft + 30 ft + 30 ft + 55 ft + 40 ft
= 125 ft + 30 ft + 55 ft + 40 ft
= 155 ft + 55 ft + 40 ft
= 210 ft + 40ft
= 250 ft.

 

Question 4.
Manny draws 3 regular pentagons to create the shape shown below. The perimeter of 1 of the pentagons is 45 inches. What is the perimeter of Manny’s new shape?

Answer:
Perimeter of Manny’s new shape = 99 inches.

Explanation:

Perimeter of the regular pentagons Manny draws = 45 inches
Number of side in the regular pentagons Manny draws = 5
Length of the side of the regular pentagons Manny draws = Perimeter of the regular pentagons Manny draws ÷ Number of side in the regular pentagons Manny draws
= 45 inches ÷ 5
= 9 inches.
Number of side Manny’s new shape  has = 11 ( Side AB + Side BC +Side CD + Side DE + Side EF +Side FG + Side GH + Side HI + Side IJ +Side JK + Side KA )
Perimeter of Manny’s new shape = Number of side Manny’s new shape has × Length of the side of the regular pentagons Manny draws
= 11 × 9 inches
= 99 inches.

 

Question 5.
Johnny uses 2-inch square tiles to make a square, as shown below. What is the perimeter of Johnny’s square?

Answer:
Perimeter of Johnny’s square = 24 inches.

Explanation:

Number of side in the Johnny’s square = 12
Length of  side  in the Johnny’s square = 2 inches
Perimeter of Johnny’s square = Number of side in the Johnny’s square  × Length of side in the Johnny’s square
= 12 × 2 inches
= 24 inches.

Question 6.
Lisa tapes three 7-inch by 9-inch pieces of construction paper together to make a happy birthday sign for her mom. She uses a piece of ribbon that is 144 inches long to make a border around the outside edges of the sign. How much ribbon is leftover?

Answer:
Ribbon  leftover = 76 inches.

Explanation:

Length of the Lisa’s piece of construction paper = 9-inch
Width of the Lisa’s piece of construction paper = 7-inch
Perimeter of the pieces of construction paper used to make a happy birthday sign for her mom = Side AB + Side BC + Side CD + Side DE + Side EF + Side FG + Side GH +Side HA
= 9-inch + 9-inch + 9-inch + 7-inch + 9-inch + 9-inch + 9-inch + 7-inch
= 18-inch + 9-inch + 7-inch + 9-inch + 9-inch + 9-inch + 7-inch
= 27-inch + 7-inch + 9-inch + 9-inch + 9-inch + 7-inch
= 34-inch + 9-inch + 9-inch + 9-inch + 7-inch
= 43-inch + 9-inch + 9-inch + 7-inch
= 52-inch + 9-inch + 7-inch
= 61-inch + 7-inch
= 68-inch.
Piece of ribbon Lisa’s  has = 144 inches
Ribbon  leftover = Piece of ribbon Lisa’s  has  – Perimeter of the pieces of construction paper used to make a happy birthday sign for her mom
= 144 inches – 68-inch.
= 76 inches.

Engage NY Eureka Math 3rd Grade Module 7 Lesson 22 Answer Key

Eureka Math Grade 3 Module 7 Lesson 22 Sprint Answer Key

A
Multiply or Divide by 4

Answer:

Question 1.
2 × 4 =
Answer:
2 × 4 = 8.

Question 2.
3 × 4 =
Answer:
3 × 4 = 12.

Question 3.
4 × 4 =
Answer:
4 × 4 = 16.

Question 4.
5 × 4 =
Answer:
5 × 4 = 20.

Question 5.
1 × 4 =
Answer:
1 × 4 = 4.

Question 6.
8 ÷ 4 =
Answer:
8 ÷ 4 = 2.

Question 7.
12 ÷ 4 =
Answer:
12 ÷ 4 = 3.

Question 8.
20 ÷ 4 =
Answer:
20 ÷ 4 = 5.

Question 9.
4 ÷ 4 =
Answer:
4 ÷ 4 = 1.

Question 10.
16 ÷ 4 =
Answer:
16 ÷ 4 = 4.

Question 11.
6 × 4 =
Answer:
6 × 4 = 24.

Question 12.
7 × 4 =
Answer:
7 × 4 = 28.

Question 13.
8 × 4 =
Answer:
8 × 4 = 32.

Question 14.
9 × 4 =
Answer:
9 × 4 = 36.

Question 15.
10 × 4 =
Answer:
10 × 4 = 40.

Question 16.
32 ÷ 4 =
Answer:
32 ÷ 4 = 8.

Question 17.
28 ÷ 4 =
Answer:
28 ÷ 4 = 7.

Question 18.
36 ÷ 4 =
Answer:
36 ÷ 4 = 9.

Question 19.
24 ÷ 4 =
Answer:
24 ÷ 4 = 6.

Question 20.
40 ÷ 4 =
Answer:
40 ÷ 4 = 10.

Question 21.
___ × 4 = 20
Answer:
_5__ × 4 = 20.

Question 22.
___ × 4 = 4
Answer:
_1__ × 4 = 4.

Question 23.
___ × 4 = 40
Answer:
_10__ × 4 = 40.

Question 24.
___ × 4 = 8
Answer:
_2__ × 4 = 8.

Question 25.
___ × 4 = 12
Answer:
_3__ × 4 = 12.

Question 26.
40 ÷ 4 =
Answer:
40 ÷ 4 = 10.

Question 27.
20 ÷ 4 =
Answer:
20 ÷ 4 = 5.

Question 28.
4 ÷ 4 =
Answer:
4 ÷ 4 = 1.

Question 29.
8 ÷ 4 =
Answer:
8 ÷ 4 = 2.

Question 30.
12 ÷ 4 =
Answer:
12 ÷ 4 = 3.

Question 31.
___ × 4 = 24
Answer:
_6__ × 4 = 24.

Question 32.
___ × 4 = 28
Answer:
_7__ × 4 = 28.

Question 33.
___ × 4 = 36
Answer:
_9__ × 4 = 36.

Question 34.
___ × 4 = 32
Answer:
_8__ × 4 = 32.

Question 35.
28 ÷ 4 =
Answer:
28 ÷ 4 = 7.

Question 36.
36 ÷ 4 =
Answer:
36 ÷ 4 = 9.

Question 37.
24 ÷ 4 =
Answer:
24 ÷ 4 = 6.

Question 38.
32 ÷ 4 =
Answer:
32 ÷ 4 = 8.

Question 39.
11 × 4 =
Answer:
11 × 4 = 44.

Question 40.
44 ÷ 4 =
Answer:
44 ÷ 4 = 11.

Question 41.
12 ÷ 4 =
Answer:
12 ÷ 4 = 3.

Question 42.
48 ÷ 4 =
Answer:
48 ÷ 4 = 12.

Question 43.
14 × 4 =
Answer:
14 × 4 = 56.

Question 44.
56 ÷ 4 =
Answer:
56 ÷ 4 = 14.

B
Multiply or Divide by 4

Answer:

Question 1.
1 × 4 =
Answer:
1 × 4 = 4.

Question 2.
2 × 4 =
Answer:
2 × 4 = 8.

Question 3.
3 × 4 =
Answer:
3 × 4 = 12.

Question 4.
4 × 4 =
Answer:
4 × 4 = 16.

Question 5.
5 × 4 =
Answer:
5 × 4 = 20.

Question 6.
12 ÷ 4 =
Answer:
12 ÷ 4 = 3.

Question 7.
8 ÷ 4 =
Answer:
8 ÷ 4 = 2.

Question 8.
16 ÷ 4 =
Answer:
16 ÷ 4 = 4.

Question 9.
4 ÷ 4 =
Answer:
4 ÷ 4 = 1.

Question 10.
20 ÷ 4 =
Answer:
20 ÷ 4 = 5.

Question 11.
10 × 4 =
Answer:
10 × 4 = 40.

Question 12.
6 × 4 =
Answer:
6 × 4 = 24.

Question 13.
7 × 4 =
Answer:
7 × 4 = 28.

Question 14.
8 × 4 =
Answer:
8 × 4 = 32.

Question 15.
9 × 4 =
Answer:
9 × 4 = 36.

Question 16.
28 ÷ 4 =
Answer:
28 ÷ 4 = 7.

Question 17.
24 ÷ 4 =
Answer:
24 ÷ 4 = 6.

Question 18.
32 ÷ 4 =
Answer:
32 ÷ 4 = 8.

Question 19.
40 ÷ 4 =
Answer:
40 ÷ 4 = 10.

Question 20.
36 ÷ 4 =
Answer:
36 ÷ 4 = 9.

Question 21.
___ × 4 = 4
Answer:
_1__ × 4 = 4.

Question 22.
___ × 4 = 20
Answer:
_5__ × 4 = 20.

Question 23.
___ × 4 = 8
Answer:
_2__ × 4 = 8.

Question 24.
___ × 4 = 40
Answer:
_10__ × 4 = 40.

Question 25.
___ × 4 = 12
Answer:
_3__ × 4 = 12.

Question 26.
8 ÷ 4 =
Answer:
8 ÷ 4 = 2.

Question 27.
4 ÷ 4 =
Answer:
4 ÷ 4 = 1.

Question 28.
40 ÷ 4 =
Answer:
40 ÷ 4 = 10.

Question 29.
20 ÷ 4 =
Answer:
20 ÷ 4 = 10.

Question 30.
12 ÷ 4 =
Answer:
12 ÷ 4 = 3.

Question 31.
___ × 4 = 12
Answer:
_3__ × 4 = 12.

Question 32.
___ × 4 = 16
Answer:
_4__ × 4 = 16.

Question 33.
___ × 4 = 36
Answer:
_9__ × 4 = 36.

Question 34.
___ × 4 = 28
Answer:
_7__ × 4 = 28.

Question 35.
32 ÷ 4 =
Answer:
32 ÷ 4 = 8.

Question 36.
36 ÷ 4 =
Answer:
36 ÷ 4 = 9.

Question 37.
24 ÷ 4 =
Answer:
24 ÷ 4 = 6.

Question 38.
28 ÷ 4 =
Answer:
28 ÷ 4 = 7.

Question 39.
11 × 4 =
Answer:
11 × 4 = 44.

Question 40.
44 ÷ 4 =
Answer:
44 ÷ 4 = 11.

Question 41.
12 × 4 =
Answer:
12 × 4 = 48.

Question 42.
48 ÷ 4 =
Answer:
48 ÷ 4 = 12.

Question 43.
13 × 4 =
Answer:
13 × 4 = 52.

Question 44.
52 ÷ 4 =
Answer:
52 ÷ 4 = 13.

Eureka Math Grade 3 Module 7 Lesson 22 Problem Set Answer Key

Question 1.
Use the data you gathered from your Problem Sets to create a line plot for the number of rectangles you created with each given perimeter.
Number of Rectangles Made with a Given Perimeter

Answer:

Explanation:
The data  gathered from Problem Sets to create a line plot for the number of rectangles created with each given perimeter are : 10 units, 12 units, 14 units, 16 units,18 units, 20 units.

Question 2.
Why are all of the perimeter measurements even? Do all rectangles have an even perimeter?
Answer:
Well all perimeters of the rectangles are even because we have used the whole numbers and when we add them twice, we get the even numbers as the result.

Explanation:
Well all perimeters of the rectangles are even because we have used the whole numbers and when we add them twice, we get the even numbers as the result. Generally we used rulers to find the lengths of rectangles not the string. We have used string to show to get an odd perimeter.

 

Question 3.
Compare the two line plots we created. Is there any reason to think that knowing only the area of a rectangle would help you to figure out its perimeter or knowing only the perimeter of a rectangle would help you figure out its area?
Answer:
No, there is no reason to think that knowing only the area of a rectangle would help you to figure out its perimeter or knowing only the perimeter of a rectangle would help you figure out its area.

Explanation:
There is no connection between the area and perimeter of rectangle. Knowing one, doesnot help you to find the other.

 

Question 4.
Sumi uses unit square tiles to build 3 rectangles that have an area of 32 square units. Does knowing this help her find the number of rectangles she can build for a perimeter of 32 units? Why or why not?
Answer:
No, knowing the number of rectangles she built with the area of 32 square units does not help her to find the number of rectangles she can build for a perimeter of 32 units.

Explanation:
For example, if we do half 32 square units, we have the chance to make more than 3 pairs of number that add to 16. No, knowing the number of rectangles she built with the area of 32 square units does not help her to find the number of rectangles she can build for a perimeter of 32 units.

Question 5.
George draws 3 rectangles that have a perimeter of 14 centimeters. Alicia tells George that there are more than 3 rectangles that have a perimeter of 14 centimeters. Explain why Alicia is correct.
Answer:
Yes, I completely agree with Alicia because George  probably drew the rectangles using the whole numbers side lengths. He could have drawn more rectangles using fraction values as lengths.

Explanation:
Yes, I completely agree with Alicia ” George that there are more than 3 rectangles that have a perimeter of 14 centimeters. ” because George  probably drew the rectangles using the whole numbers side lengths. He could have drawn more rectangles using fraction values as lengths.

 

Eureka Math Grade 3 Module 7 Lesson 22 Exit Ticket Answer Key

Suppose you have a rectangle with a perimeter of 2 cm. What can you conclude about the side lengths? Can all 4 sides of the rectangle measure a whole number of centimeters?
Answer:
Well, if the rectangles perimeter is 2cm, I do not think the lengths are going to be whole numbers of centimeters. Because perimeter  is the total distance covered by the rectangle around its outside.

Explanation:
Perimeter  is the total distance covered by the rectangle around its outside. Well, if the rectangles perimeter is 2cm, I do not think the lengths are going to be whole numbers of centimeters.

 

Eureka Math Grade 3 Module 7 Lesson 22 Homework Answer Key

Question 1.
The following line plot shows the number of rectangles a student made using square unit tiles. Use the line plot to answer the questions below.

a. Why are all of the perimeter measurements even? Do all rectangles have even perimeters?
b. Explain the pattern in the line plot. What types of side lengths make this pattern possible?
c. How many X’s would you draw for a perimeter of 32? Explain how you know.
Answer:
a. Well all perimeters of the rectangles are even because the student has used the whole numbers and when they are added twice, we get the even numbers as the result.  Yes, mostly all rectangles have even perimeters as we use whole numbers not fractions.

b. The pattern in the line plot is showing all rectangles Perimeters which are even in numbers. Whole numbers types of side lengths make this pattern possible.

c. Number of X’s would be drawn for a perimeter of 32 are six or 6: : (2,14) (3,13) (4,12) (5,11) (6,10) (7,9).

Explanation:
a.  Well all perimeters of the rectangles are even because the student has used the whole numbers and when they are added twice, we get the even numbers as the result. Generally we used rulers to find the lengths of rectangles not the string. We have used string to show to get an odd perimeter.

b. The whole numbers are the part of the number system in which it includes all the positive integers from 0 to infinity. The pattern in the line plot is showing all rectangles Perimeters which are even in numbers.

c. Number of X’s would be drawn for a perimeter of 32 are six or 6 : (2,14) (3,13) (4,12) (5,11) (6,10) (7,9).

Question 2.
Luis uses square inch tiles to build a rectangle with a perimeter of 24 inches. Does knowing this help him find the number of rectangles he can build with an area of 24 square inches? Why or why not?
Answer:
Luis uses square inch tiles to build a rectangle with a perimeter of 24 inches.
No, knowing this cannot help him find the number of rectangles he can build with an area of 24 square inches because there is no connection  between the area and perimeter to find the number of rectangles to be obtained.

Explanation:
No, knowing this cannot help him find the number of rectangles he can build with an area of 24 square inches because there is no connection  between the area and perimeter to find the number of rectangles to be obtained.

 

Question 3.
Esperanza makes a rectangle with a piece of string. She says the perimeter of her rectangle is 33 centimeters. Explain how it’s possible for her rectangle to have an odd perimeter.
Answer:
Well, Esperanza  is correct in what she says ” the perimeter of her rectangle is 33 centimeters.”
because she is using her string to find the lengths of her rectangle.

Explanation:
Well, Esperanza  is correct in what she says ” the perimeter of her rectangle is 33 centimeters.”
because she is using her string to find the lengths of her rectangle. The measurements of rectangles forming an odd perimeter of Esperanza rectangles can be: (2,14.5) (4,12.5) (4.5,12) (5,11.5) (6, 10.5) ( 7, 9.5).

Engage NY Eureka Math 3rd Grade Module 1 Lesson 19 Answer Key

Eureka Math Grade 3 Module 1 Answer Key

Eureka Math Grade 3 Module 1 Lesson 19 Problem Set Answer Key

Question 1.
Label the array. Then, fill in the blanks to make true number sentences.
a. 36 ÷ 3 = 12__

a. 36 ÷ 3 = 12,

Explanation:
36 ÷ 3 can be written as (30 ÷ 3) + (6 ÷ 3) = 10 + 2 = 12 or
36 ÷ 3 = 12. Filled the blanks to make true number sentences.

b. 25 ÷ 5 = _5_

b. 25 ÷ 5 = 5,

Explanation:
25 ÷ 5 can be written as (20 ÷ 5) + (5 ÷ 5) = 4  + 1 = 5 or
25 ÷ 5 = 5. Filled the blanks to make true number sentences.

c. 28 ÷ 4 = __7___

28 ÷ 4 =7,

Explanation:
28 ÷ 4 can be written as (20 ÷ 4) + (8 ÷ 4) = 5  + 2 = 7 or
28 ÷ 4 = 7. Filled the blanks to make true number sentences.

d. 32 ÷ 4 = _8_

32 ÷ 4 = 8,

Explanation:
32 ÷ 4 can be written as (20 ÷ 4) + (12 ÷ 4) = 5  + 3 = 8 or
32 ÷ 4 = 8. Filled the blanks to make true number sentences.

Question 2.
Match the equal expressions.

Matched the equal expressions as

Explanation:
Matching the equal expressions as
24 ÷ 2 = (20 ÷ 2) + (4 ÷  2),
24 is written as (20 + 4) ÷ 2.
36 ÷ 3 = (30 ÷ 3) + (6 ÷ 3),
36 is written as (30 + 6) ÷ 3.
39 ÷  3 = (30 ÷  3) + (9 ÷  3),
39 is written as (30 + 9) ÷ 3.
26 ÷ 2 = ( 20 ÷ 2) + (6 ÷ 2),
26 is written as (20 + 6) ÷ 2.

Question 3.
Nell draws the array below to find the answer to 24 ÷ 2. Explain Nell’s strategy.

Nell’s strategy is 24 ÷ 2 = (12 ÷ 2) + (12 ÷ 2),
6 + 6 = 12, So, 24 ÷ 2 = 12,

Explanation:
To find answer for 24 ÷ 2 Nell draws an array
his strategy is he divided 24 as 12 + 12 then has
divided with 2, So equation for Nell’s drawing is
24 ÷ 2 = (12 ÷ 2) + (12 ÷ 2), 6 + 6 = 12.
Therefore 24 ÷ 2 = 12.

Eureka Math Grade 3 Module 1 Lesson 19 Exit Ticket Answer Key

Complete the equations below to solve 22 ÷ 2 = __11___.

22 ÷ 2 = 11,

Explanation:

We solve 22 ÷ 2 as below first we write 22 as 20 + 2
and divide by 2, (20 + 2) ÷ 2 = (20 ÷ 2) +(2 ÷ 2) =
10 + 1 = 11, So 22 ÷ 2 = 11.

Eureka Math Grade 3 Module 1 Lesson 19 Homework Answer Key

Question 1.
Label the array. Then, fill in the blanks to make true number sentences.
a. 18 ÷ 3 = _6_


18 ÷ 3 = 6,

Explanation:
Labelled the array, filled the blanks to make
true number sentences as 18 ÷ 3 = ( 9 ÷ 3) + (9 ÷ 3) =
3 + 3 = 6 or 18 ÷ 3 = 6.
We wrote 18 ÷ 3 as (9 + 9) ÷ 3.

b. 21 ÷ 3 = _7_


21 ÷ 3 = 7,

Explanation:
Labelled the array, filled the blanks to make
true number sentences as 21÷ 3 = (15 ÷ 3) + (6 ÷ 3) =
5 + 2 = 7 or 21 ÷ 3 = 7.
We wrote 21 ÷ 3 as (15 + 6) ÷ 3.

c. 24 ÷ 4 = _6_

24 ÷ 4 = 6,

Explanation:
Labelled the array, filled the blanks to make
true number sentences as 24 ÷ 4 = (20÷ 4) + (4 ÷ 4) =
5 + 1 = 6 or 24÷ 4 = 6.
We wrote 24 ÷ 4 as (20 + 4) ÷ 4.

d. 36 ÷ 4 = _9_


36 ÷ 4 = 9,

Explanation:
Labelled the array, filled the blanks to make
true number sentences as 36 ÷ 4 = (20÷ 4) + (16 ÷ 4) =
5 + 4 = 9 or 36÷ 4 = 9.
We wrote 36 ÷ 4 as (20 + 16) ÷ 4.

Question 2.
Match equal expressions.

Matched the equal expressions as

Explanation:
Matching the equal expressions as
28 ÷ 2 = (20 ÷ 2) + (8 ÷  2),
28 is written as (20 + 8) ÷ 2.
33 ÷ 3 = (30 ÷ 3) + (3 ÷ 3),
33 is written as (30 + 3) ÷ 3.
36 ÷  3 = (30 ÷  3) + (6 ÷  3),
36 is written as (30 + 6) ÷ 3.
26 ÷ 2 = ( 20 ÷ 2) + (6 ÷ 2),
26 is written as (20 + 6) ÷ 2.

Question 3.
Alex draws the array below to find the answer to 35 ÷ 5. Explain Alex’s strategy.

Alex’s strategy is 35 ÷ 5 = (20 ÷ 5) + (15 ÷ 5) =
4 + 3 = 7, So, 35 ÷ 5 = 7,

Explanation:
To find answer for 35 ÷ 5 Alex draws an array
his strategy is he divided 35 as 20 + 15 then has
divided with 5, So equation for Alex’s drawing is
35 ÷ 5 = (20 ÷ 5) + (15 ÷ 5), 4 + 3 = 7,
Therefore 35 ÷ 5 = 7.

Engage NY Eureka Math 3rd Grade Module 1 Lesson 18 Answer Key

Eureka Math Grade 3 Module 1 Answer Key

Eureka Math Grade 3 Module 1 Lesson 18 Sprint Answer Key

A
Add or Subtract Using 5

Question 1.
0 + 5 =
0 + 5 = 5,

Explanation:
Given 0 + 5 = adding 5 to 0 we get 5,
So, 0 + 5 = 5.

Question 2.
5 + 5 =
5 + 5 = 10,

Explanation:
Given 5 + 5 = adding 5 to 5 we get 10,
So, 5 + 5 = 10.

Question 3.
10 + 5 =
10 + 5 = 15,

Explanation:
Given 10 + 5 = adding 5 to 10 we get 15,
So, 10 + 5 = 15.

Question 4.
15 + 5 =
15 + 5 = 20,

Explanation:
Given 15 + 5 = adding 5 to 15 we get 20,
So, 15 + 5 = 20.

Question 5.
20 + 5 =
20 + 5 =25,

Explanation:
Given 20 + 5 = adding 5 to 20 we get 25,
So, 20 + 5 = 5.

Question 6.
25 + 5 =
25 + 5 = 30,

Explanation:
Given 25 + 5 = adding 5 to 25 we get 30,
So, 25 + 5 = 30.

Question 7.
30 + 5 =
30 + 5 = 35,

Explanation:
Given 30 + 5 = adding 5 to 30 we get 35,
So, 30 + 5 = 35.

Question 8.
35 + 5 =
35 + 5 = 40,

Explanation:
Given 35 + 5 = adding 5 to 35 we get 40,
So, 35 + 5 = 40.

Question 9.
40 + 5 =
40 + 5 = 45,

Explanation:
Given 40 + 5 = adding 5 to 40 we get 45,
So, 40 + 5 = 45.

Question 10.
45 + 5 =
45 + 5 = 50,

Explanation:
Given 45 + 5 = adding 5 to 45 we get 50,
So, 45 + 5 = 50.

Question 11.
50 – 5 =
50 – 5 = 45,

Explanation:
Given 50 – 5 = subtracting 5 from 50 we get 45,
So, 50 – 5 = 45.

Question 12.
45 – 5 =
45 – 5 = 40,

Explanation:
Given 45 – 5 = subtracting 5 from 45 we get 40,
So, 45 – 5 = 40.

Question 13.
40 – 5 =
40 – 5 = 35,

Explanation:
Given 40 – 5 = subtracting 5 from 40 we get 35,
So, 40 – 5 = 35.

Question 14.
35 – 5 =
35 – 5 = 30,

Explanation:
Given 35 – 5 = subtracting 5 from 35 we get 30,
So, 35 – 5 = 30.

Question 15.
30 – 5 =
30 – 5 = 25,

Explanation:
Given 30 – 5 = subtracting 5 from 30 we get 25,
So, 30 – 5 = 25.

que25 16.
25 – 5 =
25 – 5 = 20,

Explanation:
Given 25 – 5 = subtracting 5 from 25 we get 20,
So, 25 – 5 = 20.

Question 17.
20 – 5 =
20 – 5 = 15,

Explanation:
Given 20 – 5 = subtracting 5 from 20 we get 15,
So, 20 – 5 = 15.

Question 18.
15 – 5 =
15 – 5 = 10,

Explanation:
Given 15 – 5 = subtracting 5 from 15 we get 10,
So, 15 – 5 = 10.

Question 19.
10 – 5 =
10 – 5 = 5,

Explanation:
Given 10 – 5 = subtracting 5 from 10 we get 5,
So, 10 – 5 = 5.

Question 20.
5 – 5 =
5 – 5 = 0,

Explanation:
Given 5 – 5 = subtracting 5 from 5 we get 0,
So, 5 – 5 = 0.

Question 21.
5 + 0 =
5 + 0 = 5,

Explanation:
Given 5 + 0 = adding 5 to 0 we get 5,
So, 5 + 0 = 5.

Question 22.
5 + 5 =
5 + 5 = 10,

Explanation:
Given 5 + 5 = adding 5 to 5 we get 10,
So, 5 + 5 = 10.

Question 23.
10 + 5 =
10 + 5 = 15,

Explanation:
Given 10 + 5 = adding 5 to 10 we get 15,
So, 10 + 5 = 15.

Question 24.
15 + 5 =
15 + 5 = 20,

Explanation:
Given 15 + 5 = adding 5 to 15 we get 20,
So, 15 + 5 = 20.

Question 25.
20 + 5 =
20 + 5 = 25,

Explanation:
Given 20 + 5 = adding 5 to 20 we get 25,
So, 20 + 5 = 25.

Question 26.
25 + 5 =
25 + 5 = 30,

Explanation:
Given 25 + 5 = adding 5 to 25 we get 30,
So, 25 + 5 = 30.

Question 27.
30 + 5 =
30 + 5 = 35,

Explanation:
Given 30 + 5 = adding 5 to 30 we get 35,
So, 30 + 5 = 35.

Question 28.
35 + 5 =
35 + 5 = 40,

Explanation:
Given 35 + 5 = adding 5 to 35 we get 40,
So, 35 + 5 = 40.

Question 29.
40 + 5 =
40 + 5 = 45,

Explanation:
Given 40 + 5 = adding 5 to 40 we get 45,
So, 40 + 5 = 45.

Question 30.
45 + 5 =
45 + 5 = 50,

Explanation:
Given 45 + 5 = adding 5 to 45 we get 50,
So, 45 + 5 = 50.

Question 31.
0 + 50 =
0 + 50 = 50,

Explanation:
Given 0 + 50 = adding 0 to 50 we get 50,
So, 0 + 50 = 50.

Question 32.
50 + 50 =
50 + 50 = 100,

Explanation:
Given 50 + 50 = adding 50 to 50 we get 100,
So, 50 + 50 = 100.

Question 33.
50 + 5 =
50 + 5 = 55,

Explanation:
Given 50 + 5 = adding 5 to 50 we get 55,
So, 50 + 5 = 55.

Question 34.
55 + 5 =
55 + 5 = 60,

Explanation:
Given 55 + 5 = adding 5 to 55 we get 60,
So, 55 + 5 = 55.

Question 35.
60 – 5 =
0 + 50 = 50,

Explanation:
Given 0 + 50 = adding 0 to 50 we get 50,
So, 0 + 50 = 50.

Question 36.
55 – 5 =
55 – 5 = 50,

Explanation:
Given 55 – 5 = subtracting 5 from 55 we get 50,
So, 55 – 5 = 50.

Question 37.
60 + 5 =
60 + 5 = 65,

Explanation:
Given 60 + 5 = adding 5 to 60 we get 65,
So, 60 + 5 = 15.

Question 38.
65 + 5 =
65 + 5 = 70,

Explanation:
Given 65 + 5 = adding 5 to 65 we get 70,
So, 65 + 5 = 70.

Question 39.
70 – 5 =
70 – 5 = 65,

Explanation:
Given 70 – 5 = subtracting 5 from 70 we get 65,
So, 70 – 5 = 65.

Question 40.
65 – 5 =
65 – 5 = 60,

Explanation:
Given 65 – 5 = subtracting 5 from 65 we get 60,
So, 65 – 5 = 60.

Question 41.
100 + 50 =
100 + 50 = 150,

Explanation:
Given 100 + 50 = adding 50 to 100 we get 150,
So, 100 + 50 = 150.

Question 42.
150 + 50 =
150 + 50 = 200,

Explanation:
Given 150 + 50 = adding 50 to 150 we get 200,
So, 150 + 50 = 200.

Question 43.
200 – 50 =
200 – 50 = 150,

Explanation:
Given 200 – 50 = subtracting 50 from 200 we get 150,
So, 200 – 50 = 150.

Question 44.
150 – 50 =
150 – 50 = 100,

Explanation:
Given 150 – 50 = subtracting 50 from 150 we get 100,
So, 150 – 50 = 100.

B
Add or Subtract Using 5

Question 1.
5 + 0 =
5 + 0 = 5,

Explanation:
Given 5 + 0 = adding 5 to 0 we get 5,
So, 5 + 0 = 5.

Question 2.
5 + 5 =
5 + 5 = 10,

Explanation:
Given 5 + 5 = adding 5 to 5 we get 10,
So, 5 + 5 = 10.

Question 3.
5 + 10 =
5 + 10 = 15,

Explanation:
Given 5 + 10 = adding 5 to 10 we get 15,
So, 5 + 10 = 15.

Question 4.
5 + 15 =
5 + 15 = 20,

Explanation:
Given 5 + 15 = adding 5 to 15 we get 20,
So, 5 + 15 = 20.

Question 5.
5 + 20 =
5 + 20 = 25,

Explanation:
Given 5 + 20 = adding 5 to 20 we get 25,
So, 5 + 20 = 25.

Question 6.
5 + 25 =
5 + 25 = 30,

Explanation:
Given 5 + 25 = adding 5 to 25 we get 30,
So, 5 + 25 = 30.

Question 7.
5 + 30 =
5 + 30 = 35,

Explanation:
Given 5 + 30 = adding 5 to 30 we get 35,
So, 5 + 30 = 35.

Question 8.
5 + 35 =
5 + 35 = 40,

Explanation:
Given 5 + 35 = adding 5 to 35 we get 40,
So, 5 + 35 = 40.

Question 9.
5 + 40 =
5 + 40 = 45,

Explanation:
Given 5 + 40 = adding 5 to 40 we get 45,
So, 5 + 40 = 45.

Question 10.
5 + 45 =
5 + 45 = 50,

Explanation:
Given 5 + 45 = adding 5 to 45 we get 50,
So, 5 + 45 = 50.

Question 11.
50 – 5 =
50 – 5 = 45,

Explanation:
Given 50 – 5 = subtracting 5 from 50 we get 45,
So, 50 – 5 = 45.

Question 12.
45 – 5 =
45 – 5 = 40,

Explanation:
Given 45 – 5 = subtracting 5 from 45 we get 40,
So, 45 – 5 = 40.

Question 13.
40 – 5 =
40 – 5 = 35,

Explanation:
Given 40 – 5 = subtracting 5 from 40 we get 35,
So, 40 – 5 = 35.

Question 14.
35 – 5 =
35 – 5 = 30,

Explanation:
Given 35 – 5 = subtracting 5 from 35 we get 30,
So, 35 – 5 = 30.

Question 15.
30 – 5 =
30 – 5 = 25,

Explanation:
Given 30 – 5 = subtracting 5 from 30 we get 25,
So, 30 – 5 = 25.

Question 16.
25 – 5 =
25 – 5 = 20,

Explanation:
Given 25 – 5 = subtracting 5 from 25 we get 20,
So, 25 – 5 = 20.

Question 17.
20 – 5 =
20 – 5 = 15,

Explanation:
Given 20 – 5 = subtracting 5 from 20 we get 15,
So, 20 – 5 = 15.

Question 18.
15 – 5 =
15 – 5 = 10,

Explanation:
Given 15 – 5 = subtracting 5 from 15 we get 10,
So, 15 – 5 = 10.

Question 19.
10 – 5 =
10 – 5 = 5,

Explanation:
Given 10 – 5 = subtracting 5 from 10 we get 5,
So, 10 – 5 = 5.

Question 20.
5 – 5 =
5 – 5 = 0,

Explanation:
Given 5 – 5 = subtracting 5 from 5 we get 0,
So, 5 – 5 = 0.

Question 21.
0 + 5 =
0 + 5 = 5,

Explanation:
Given 0 + 5 = adding 5 to 0 we get 5,
So, 0 + 5 = 5.

Question 22.
5 + 5 =
5 + 5 = 10,

Explanation:
Given 5 + 5 = adding 5 to 5 we get 10,
So, 5 + 5 = 10.

Question 23.
10 + 5 =
10 + 5 = 15,

Explanation:
Given 10 + 5 = adding 5 to 10 we get 15,
So, 10 + 5 = 15.

Question 24.
15 + 5 =
15 + 5 = 20,

Explanation:
Given 15 + 5 = adding 5 to 15 we get 20,
So, 15 + 5 = 20.

Question 25.
20 + 5 =
20 + 5 = 25,

Explanation:
Given 20 + 5 = adding 5 to 20 we get 25,
So, 20 + 5 = 25.

Question 26.
25 + 5 =
25 + 5 = 30,

Explanation:
Given 25 + 5 = adding 5 to 25 we get 30,
So, 25 + 5 = 30.

Question 27.
30 + 5 =
30 + 5 = 35,

Explanation:
Given 30 + 5 = adding 5 to 30 we get 35,
So, 30 + 5 = 35.

Question 28.
35 + 5 =
35 + 5 = 40,

Explanation:
Given 35 + 5 = adding 5 to 35 we get 40,
So, 35 + 5 = 40.

Question 29.
40 + 5 =
40 + 5 = 45,

Explanation:
Given 40 + 5 = adding 5 to 40 we get 45,
So, 40 + 5 = 45.

Question 30.
45 + 5 =
45 + 5 = 50,

Explanation:
Given 45 + 5 = adding 5 to 45 we get 50,
So, 45 + 5 = 50.

Question 31.
50 + 0 =
50 + 0 = 50,

Explanation:
Given 50 + 5 = adding 0 to 50 we get 50,
So, 50 + 0 = 50.

Question 32.
50 + 50 =
50 + 50 = 100,

Explanation:
Given 50 + 50 = adding 50 to 50 we get 100,
So, 50 + 50 = 100.

Question 33.
5 + 50 =
5 + 50 = 55,

Explanation:
Given 5 + 50 = adding 5 to 50 we get 55,
So, 5 + 50 = 55.

Question 34.
5 + 55 =
5 + 55 = 60,

Explanation:
Given 5 + 55 = adding 5 to 55 we get 60,
So, 5 + 55 = 60.

Question 35.
60 – 5 =
60 – 5 = 55,

Explanation:
Given 60 – 5 = subtracting 5 from 60 we get 55,
So, 60 – 5 = 55.

Question 36.
55 – 5 =
55 – 5 = 50,

Explanation:
Given 55 – 5 = subtracting 5 from 55 we get 50,
So, 55 – 5 = 50.

Question 37.
5 + 60 =
5 + 60 = 65,

Explanation:
Given 5 + 60 = adding 5 to 60 we get 65,
So, 5 + 60 = 65.

Question 38.
5 + 65 =
5 + 65 = 70,

Explanation:
Given 5 + 65 = adding 5 to 65 we get 70,
So, 5 + 65 = 70.

Question 39.
70 – 5 =
70 – 5 = 65,

Explanation:
Given 70 – 5 = subtracting 5 from 70 we get 65,
So, 65 – 5 = 60.

Question 40.
65 – 5 =
65 – 5 = 60,

Explanation:
Given 65 – 5 = subtracting 5 from 65 we get 60,
So, 65 – 5 = 60.

Question 41.
50 + 100 =
50 + 100 = 150,

Explanation:
Given 50 + 100 = adding 50 to 100 we get 150,
So, 50 + 100 = 150.

Question 42.
50 + 150 =
50 + 150 = 200,

Explanation:
Given 50 + 150 = adding 50 to 150 we get 200,
So, 50 + 150 = 200.

Question 43.
200 – 50 =
200 – 50 = 150,

Explanation:
Given 200 – 50 = subtracting 50 from 200 we get 150,
So, 200 – 50 = 150.

Question 44.
150 – 50 =
150 – 50 = 100,

Explanation:
Given 150 – 50 = subtracting 50 from 150 we get 100,
So, 150 – 50 = 100.

Eureka Math Grade 3 Module 1 Lesson 18 Problem Set Answer Key

Question 1.
8 × 10 = __80____

5 tens + ______3 tens_________ = 8 tens
(5 × 10) + (___3___ × 10) = 8 × 10
50 + ___30______ = ___80______
8 × 10 = ____80________

8 × 10 = 80

5 tens + 3 tens = 8 tens
(5 × 10) + (3 × 10) = 8 × 10
50 + 30 = 80
8 × 10 = 80

Explanation:
Given 8 X 10 =
We can write 8 X 10 as 5 tens + 3 tens,
(5 X 10) + (3 X 10) = 8 X 10,
50 + 30 = 80 or 8 X 10 = 80.

Question 2.
7 × 4 = ___28___

5 fours + ______2 fours____ = 7 fours
(5 × 4) + (___2___ × 4) = 7 × 4
20 + ____8_____ = ____28_____
7 × 4 = _____28_______

7 x 4 = 28,

5 fours + 2 fours = 7 fours
(5 × 4) + (2 × 4) = 7 × 4
20 + 8 = 28
7 × 4 = 28,

Explanation:
Given 7 X 4 =
We can write 7 x 4 as 5 fours + 2 fours,
(5 X 4) + (2 X 4) = 7 X 4,
20 + 8 = 28 or 7 X 4 = 28.

Question 3.
9 × 10 = ___90___

5 tens + _____4 tens__________ = 9 tens
(5 × 10) + (___4___ × 10) = 9 × 10
___50______ + ___40______ = ___ 90______
9 × 10 = _____90_______

9 X 10 = 90,

5 tens + 4 tens = 9 tens
(5 × 10) + (4 × 10) = 9 × 10
50 + 40 =  90
9 × 10 = 90

Explanation:
Given 9 X 10 =
We can write 9 X 10 as 5 tens + 4 tens,
(5 X 10) + (4 X 10) = 9 X 10,
50 + 40 = 90 or 9 X 10 = 90.

Question 4.
10 × 10 = __100____

____5 tens_________ + ___5 tens_________ = 10 tens
(___5___ × 10) + (__5____ × 10) = 10 × 10
___50_____ + ___50______ = ___100______
10 × 10 = ____100________

10 X 10 = 100

5 tens + 5 tens = 10 tens
(5 × 10) + (5 × 10) = 10 × 10
50 + 50 = 100
10 × 10 = 100

Explanation:
Given 10 X 10 =
We can write 10 X 10  as 5 tens + 5 tens,
(5 X 10) + (5 X 10) = 10 X 10,
50 + 50 = 100 or 10 X 10 = 100.

Question 5.
There are 7 teams in the soccer tournament.
Ten children play on each team. How many children are
playing in the tournament? Use the break apart and
distribute strategy, and draw a number bond to solve.
There are ____70______ children playing in the tournament.

There are 70 children playing in the tournament,
7 X 10 =

5 tens + 2 tens = 7 tens
(5 × 10) + (2 × 10) = 7 × 10
50 + 20 = 70
7 × 10 = 70

Explanation:
Given there are 7 teams in the soccer tournament.
Ten children play on each team. So number of children
playing in the tournament are 7 X 10 = 70,
Used the break apart and distribute strategy,
drawn a number bond to solve 7 X 10 =
wrote 7 as 5 tens + 2 tens = 7 tens,
(5 × 10) + (2 × 10) = 7 × 10,
50 + 20 = 70,
7 × 10 = 70,
Therefore, there are 70 children playing in the tournament.

Question 6.
What is the total number of sides on 8 triangles?

Total number of 24 sides on 8 triangles,

Explanation:
Given to find the total number of sides on 8 triangles,
as we know a triangle has 3 sides so 8 triangles means
3 sides X  8  = 24 sides,
therefore, total number of 24 sides on 8 triangles.

Question 7.
There are 12 rows of bottled drinks in the vending machine.
Each row has 10 bottles. How many bottles are in the vending machine?

There are 120 bottles in total in the vending machine,

Explanation:
Given there are 12 rows of bottled drinks in the vending machine
and each row has 10 bottles, So total number of bottles in
the vending machine are 12 X 10 = 120 bottles.

Eureka Math Grade 3 Module 1 Lesson 18 Exit Ticket Answer Key

Dylan used the break apart and distribute strategy to
solve a multiplication problem. Look at his work below,
write the multiplication problem Dylan solved,
and complete the number bond.

Explanation:
Given Dylan used the break apart and distribute strategy to
solve a multiplication problem. Looking at his work,
wrote the multiplication problem Dylan solved,
and completed the number bond as shown above,
as 6 X 4 = (5 X 4) + (1 X 4) = 20 + 4 =24, or 6 X 4 = 24.

Eureka Math Grade 3 Module 1 Lesson 18 Homework Answer Key

Question 1.
Match.

Matched as shown below :

Explanation:
Matched expressions as
7 tens = 5 tens + 2 tens = (5 X 10) + (2 X 10) = 70,
8 fours = 5 fours + 3 fours = (5 X 4) + (3 X 4) = 32,
9 tens =  6 tens + 3 tens = (6 X 10) + (3 X 10) = 90,
7 threes = 5 threes + 2 threes = (5 X 3) + (2 X 3) = 21.

Question 2.
9 × 4 = ___36___

(_5_ × 4) + (_4_ × 4) = 9 × 4
_20__ + _16_ = _36_
9 × 4 = _36_.

9 X 4 = 36,

(5 X 4 + 4 X 4) = 9 X 4,
20 + 16 = 36,
9 X 4 = 36,

Explanation:
Given 9 X 4 =
We can write 9 X 4 as 5 fours + 4 fours,
(5 X 4) + (4 X 4) = 9 X 4,
20 + 16 = 36 or 9 X 4 = 36.

Question 3.
Lydia makes 10 pancakes. She tops each pancake with
4 blueberries. How many blueberries does Lydia use in all?
Use the break apart and distribute strategy, and
draw a number bond to solve.
Lydia uses __40__ blueberries in all.

Lydia uses 40 blueberries in all,

Explanation:
Given Lydia makes 10 pancakes. She tops each pancake with
4 blueberries. So number of  blueberries Lydia use in all are
4 X 10 = 40, Used the break apart and distribute strategy as
(2 X 10) + (2 X 10) = 20 + 20 = 40 and drawn a
number bond to solve 4 x 10 as 40.

Question 4.
Steven solves 7 × 3 using the break apart and distribute strategy.
Show an example of what Steven’s work might look like below.

7 X 3 = 21,

Example: Steven has 7 friends and each friend has
3 balloons, how many total balloons Steven will collect
from his friends?

Explanation:
Given Steven has 7 friends and each friend has
3 balloons, how many total balloons Steven will collect
from his friends?
Steven solves 7 × 3 using the
break apart and distribute strategy shown above as
7 X 3 = (4 X 3) + (3 X 3) = 12 + 9 = 21,
or 7 X 3 = 21.
So Steven collects 21 balloons in all.

Question 5.
There are 7 days in 1 week. How many days are there in 10 weeks?

There are 70 days in 10 weeks,

Explanation:
Given there are 7 days in 1 week. So number of days
in 10 weeks are 7 X 10 = 70 days.
therefore there are 70 days in 10 weeks.

Engage NY Eureka Math 3rd Grade Module 7 Lesson 21 Answer Key

Eureka Math Grade 3 Module 7 Lesson 21 Sprint Answer Key

A
Multiply or Divide by 3

Answer:

Question 1.
2 × 3 =
Answer:
2 × 3 = 6.

Question 2.
3 × 3 =
Answer:
3 × 3 = 9.

Question 3.
4 × 3 =
Answer:
4 × 3 = 12.

Question 4.
5 × 3 =
Answer:
5 × 3 = 15.

Question 5.
1 × 3 =
Answer:
1 × 3 = 3.

Question 6.
6 ÷ 3 =
Answer:
6 ÷ 3 = 2.

Question 7.
9 ÷ 3 =
Answer:
9 ÷ 3 = 3.

Question 8.
15 ÷ 3 =
Answer:
15 ÷ 3 = 5.

Question 9.
3 ÷ 3 =
Answer:
3 ÷ 3 = 1.

Question 10.
12 ÷ 3 =
Answer:
12 ÷ 3 = 4.

Question 11.
6 × 3 =
Answer:
6 × 3 = 18.

Question 12.
7 × 3 =
Answer:
7 × 3 = 21.

Question 13.
8 × 3 =
Answer:
8 × 3 = 24.

Question 14.
9 × 3 =
Answer:
9 × 3 = 27.

Question 15.
10 × 3 =
Answer:
10 × 3 = 30.

Question 16.
24 ÷ 3 =
Answer:
24 ÷ 3 = 8.

Question 17.
21 ÷ 3 =
Answer:
21 ÷ 3 = 7.

Question 18.
27 ÷ 3 =
Answer:
27 ÷ 3 = 9.

Question 19.
18 ÷ 3 =
Answer:
18 ÷ 3 = 6.

Question 20.
30 ÷ 3 =
Answer:
30 ÷ 3 = 10.

Question 21.
___ × 3 = 15
Answer:
_5__ × 3 = 15.

Question 22.
___ × 3 = 3
Answer:
__1_ × 3 = 3.

Question 23.
___ × 3 = 30
Answer:
_10__ × 3 = 30.

Question 24.
___ × 3 = 6
Answer:
_2__ × 3 = 6.

Question 25.
___ × 3 = 9
Answer:
_3__ × 3 = 9.

Question 26.
30 ÷ 3 =
Answer:
30 ÷ 3 = 10.

Question 27.
15 ÷ 3 =
Answer:
15 ÷ 3 = 5.

Question 28.
3 ÷ 3 =
Answer:
3 ÷ 3 = 1.

Question 29.
6 ÷ 3 =
Answer:
6 ÷ 3 = 2.

Question 30.
9 ÷ 3 =
Answer:
9 ÷ 3 = 3.

Question 31.
___ × 3 = 18
Answer:
_6__ × 3 = 18.

Question 32.
___ × 3 = 21
Answer:
_7__ × 3 = 21.

Question 33.
___ × 3 = 27
Answer:
_9__ × 3 = 27.

Question 34.
___ × 3 = 24
Answer:
_8__ × 3 = 24.

Question 35.
21 ÷ 3 =
Answer:
21 ÷ 3 = 7.

Question 36.
27 ÷ 3 =
Answer:
27 ÷ 3 = 9.

Question 37.
18 ÷ 3 =
Answer:
18 ÷ 3 = 6.

Question 38.
24 ÷ 3 =
Answer:
24 ÷ 3 = 8.

Question 39.
11 × 3 =
Answer:
11 × 3 = 33.

Question 40.
33 ÷ 3 =
Answer:
33 ÷ 3 = 11.

Question 41.
12 × 3 =
Answer:
12 × 3 = 36.

Question 42.
36 ÷ 3 =
Answer:
36 ÷ 3 = 12.

Question 43.
13 × 3 =
Answer:
13 × 3 = 39.

Question 44.
39 ÷ 3 =
Answer:
39 ÷ 3 = 13.

 

B
Multiply or Divide by 3

Answer:

Question 1.
1 × 3 =
Answer:
1 × 3 = 3.

Question 2.
2 × 3 =
Answer:
2 × 3 = 6.

Question 3.
3 × 3 =
Answer:
3 × 3 = 9.

Question 4.
4 × 3 =
Answer:
4 × 3 = 12.

Question 5.
5 × 3 =
Answer:
5 × 3 = 15.

Question 6.
9 ÷ 3 =
Answer:
9 ÷ 3 = 3.

Question 7.
6 ÷ 3 =
Answer:
6 ÷ 3 = 2.

Question 8.
12 ÷ 3 =
Answer:
12 ÷ 3 = 4.

Question 9.
3 ÷ 3 =
Answer:
3 ÷ 3 = 1.

Question 10.
15 ÷ 3 =
Answer:
15 ÷ 3 = 5.

Question 11.
10 × 3 =
Answer:
10 × 3 = 30.

Question 12.
6 × 3 =
Answer:
6 × 3 = 18.

Question 13.
7 × 3 =
Answer:
7 × 3 = 21.

Question 14.
8 × 3 =
Answer:
8 × 3 = 24.

Question 15.
9 × 3 =
Answer:
9 × 3 = 27.

Question 16.
21 ÷ 3 =
Answer:
21 ÷ 3 = 7.

Question 17.
18 ÷ 3 =
Answer:
18 ÷ 3 = 6.

Question 18.
24 ÷ 3 =
Answer:
24 ÷ 3 = 8.

Question 19.
30 ÷ 3 =
Answer:
30 ÷ 3 = 10.

Question 20.
27 ÷ 3 =
Answer:
27 ÷ 3 = 9.

Question 21.
___ × 3 = 3
Answer:
__1_ × 3 = 3.

Question 22.
___ × 3 = 15
Answer:
_5__ × 3 = 15.

Question 23.
___ × 3 = 6
Answer:
_2__ × 3 = 6.

Question 24.
___ × 3 = 30
Answer:
_10__ × 3 = 30.

Question 25.
___ × 3 = 9
Answer:
_3__ × 3 = 9.

Question 26.
6 ÷ 3 =
Answer:
6 ÷ 3 = 2.

Question 27.
3 ÷ 3 =
Answer:
3 ÷ 3 = 1.

Question 28.
30 ÷ 3 =
Answer:
30 ÷ 3 = 10.

Question 29.
15 ÷ 3 =
Answer:
15 ÷ 3 = 5.

Question 30.
9 ÷ 3 =
Answer:
9 ÷ 3 = 3.

Question 31.
___ × 3 = 18
Answer:
_6__ × 3 = 18.

Question 32.
___ × 3 = 24
Answer:
_8__ × 3 = 24.

Question 33.
___ × 3 = 27
Answer:
_9__ × 3 = 27.

Question 34.
___ × 3 = 21
Answer:
_7__ × 3 = 21.

Question 35.
24 ÷ 3 =
Answer:
24 ÷ 3 = 8.

Question 36.
27 ÷ 3 =
Answer:
27 ÷ 3 = 9.

Question 37.
18 ÷ 3 =
Answer:
18 ÷ 3 = 6.

Question 38.
21 ÷ 3 =
Answer:
21 ÷ 3 = 7.

Question 39.
11 × 3 =
Answer:
11 × 3 = 33.

Question 40.
33 ÷ 3 =
Answer:
33 ÷ 3 = 11.

Question 41.
12 × 3 =
Answer:
12 × 3 = 36.

Question 42.
36 ÷ 3 =
Answer:
36 ÷ 3 = 12.

Question 43.
13 × 3 =
Answer:
13 × 3 = 39.

Question 44.
39 ÷ 3 =
Answer:
39 ÷ 3 = 13.

Eureka Math Grade 3 Module 7 Lesson 21 Problem Set Answer Key

Question 1.
On your centimeter grid paper, shade and label as many rectangles as you can with a perimeter of 16 centimeters.
a. Sketch the rectangles below, and label the side lengths.
b. Find the area of each rectangle you drew above.
Answer:
a.
b. Area of the ABCD Rectangle = 7 square cm.
Area of the EFGH Rectangle = 12 square cm.
Area of the IJKL Rectangle = 15 square cm.

Explanation:
a.
b.
Figure 1 : ABCD Rectangle
Length of the ABCD Rectangle = 7cm
Width of the ABCD Rectangle = 1cm
Area of the ABCD Rectangle = Length  × Width
= 7cm × 1cm
= 7 square cm.

Figure 2 : EFGH Rectangle
Length of the EFGH Rectangle = 6cm
Width of the EFGH Rectangle = 2cm
Area of the EFGH Rectangle = Length  × Width
= 6cm × 2cm
= 12 square cm.

Figure 3 : IJKL Rectangle
Length of the IJKL Rectangle = 5cm
Width of the IJKL Rectangle = 3cm
Area of the IJKL Rectangle = Length  × Width
= 5cm × 3cm
= 15 square cm.

 

 

Question 2.
On your centimeter grid paper, shade and label as many rectangles as you can with a perimeter of 18 centimeters.
a. Sketch the rectangles below, and label the side lengths.
b. Find the area of each rectangle you drew above.
Answer:
a.
b. Area of the ABCD Rectangle = 8 square cm.
Area of the EFGH Rectangle = 14 square cm.
Area of the IJKL Rectangle = 18 square cm.
Area of the MNOP Rectangle = 20 square cm.

Explanation:
a.

b.

Figure 1 : ABCD Rectangle
Length of the ABCD Rectangle = 8cm
Width of the ABCD Rectangle = 1cm
Area of the ABCD Rectangle = Length  × Width
= 8cm × 1cm
= 8 square cm.

Figure 2 : EFGH Rectangle
Length of the EFGH Rectangle = 7cm
Width of the EFGH Rectangle = 2cm
Area of the EFGH Rectangle = Length  × Width
= 7cm × 2cm
= 14 square cm.

Figure 3 : IJKL Rectangle
Length of the IJKL Rectangle = 6cm
Width of the IJKL Rectangle = 3cm
Area of the IJKL Rectangle = Length  × Width
= 6cm × 3cm
= 18 square cm.

Figure 4 : MNOP Rectangle
Length of the MNOP Rectangle = 5cm
Width of the MNOP Rectangle = 4cm
Area of the MNOP Rectangle = Length  × Width
= 5cm × 4cm
= 20 square cm.

 

 

Question 3.
Use centimeter grid paper to shade in as many rectangles as you can with the given perimeters.
a. Use the charts below to show how many rectangles you shaded for each given perimeter. You might not use all the spaces in the charts.

Perimeter = 10 cm Number of rectangles I made:  _____
Width	Length	Area
1 cm	4 cm	4 square cm

Perimeter = 20 cm Number of rectangles I made:  _____
Width	Length	Area
1 cm	9 cm	9 square cm
3 cm	7 cm	21 square cm
4 cm	6 cm	24 square cm
5 cm	5 cm	25 square cm

b. Did you make a square with either of the given perimeters? How do you know?
Answer:
Yes, I  have made a square with lengths of the given perimeters of 20cm. I know it  because a rectangle with the side length all  equal to 5cm and a rectangle with all equal sides is to be known as Square.

Explanation:
Yes, because a rectangle with side length all  equal to 5cm and a rectangle with all equal sides is to be known as Square.

 

Question 4.
Macy and Gavin both draw rectangles with perimeters of 16 centimeters. Use words and pictures to explain how it is possible for Macy’s and Gavin’s rectangles to have the same perimeters but different areas.
Answer:

Area of the ABCD Macy’s rectangle = 7 Square cm.
Perimeter of the ABCD Macy’s rectangle = 16cms.
Area of the EFGH Gavin’s rectangle = 12 Square cm.
Perimeter of the EFGH Gavin’s rectangle = 16cms.
Here, Macy and Gavin has drawn two different rectangles with different lengths  perimeters same 16cms yet different areas. Well, its possible to draw as many as rectangles with perimeters of 16 centimeters but different areas.

Explanation:

Figure1: Macy’s rectangle:
Length of the ABCD Macy’s rectangle = 7cm
Width of the ABCD Macy’s rectangle = 1cm
Area of the ABCD Macy’s rectangle = Length × Width
= 7cm ×  1cm
= 7 Square cm.
Perimeter of the ABCD Macy’s rectangle =  2 ( Length + Width )
= 2 ( 7cm + 1cm)
= 2 ×  8cm
= 16 cms.

Figure2: Gavin’s rectangle:
Length of the EFGH Gavin’s rectangle = 7cm
Width of the EFGH Gavin’s rectangle = 1cm
Area of the EFGH Gavin’s rectangle = Length × Width
= 6cm ×  2cm
= 12 Square cm.
Perimeter of the EFGH Gavin’s rectangle =  2 ( Length + Width )
= 2 ( 6cm + 2cm)
= 2 ×  8cm
= 16 cms .

 

Eureka Math Grade 3 Module 7 Lesson 21 Exit Ticket Answer Key

On the grid below, shade and label at least two different rectangles with a perimeter of 20 centimeters.

Answer:

Explanation:
I have drawn three rectangles having lengths as ABCD Rectangle ( 8cm,2cm) , EFGH Rectangle  ( 6cm,4cm)  and IJKL Rectangle ( 7cm,3cm).

 

 

Eureka Math Grade 3 Module 7 Lesson 21 Homework Answer Key

Question 1.
Margo finds as many rectangles as she can with a perimeter of 14 centimeters.
a. Shade Margo’s rectangles on the grid below. Label the length and width of each rectangle.

b. Find the areas of the rectangles in part (a) above.
c. The perimeters of the rectangles are the same. What do you notice about the areas?
Answer:
a.

b. Area of the ABCD Rectangle = 12 square cm.
Area of the EFGH Rectangle = 10 square cm.
Area of the IJKL Rectangle = 6 square cm.

c. Perimeters of the three rectangles are the same having 14 cms, where as their areas are completely different from each other.

Explanation:
a.

b. Figure 1 : ABCD Rectangle
Length of the ABCD Rectangle = 4cm
Width of the ABCD Rectangle = 3cm
Area of the ABCD Rectangle = Length  × Width
= 4cm × 3cm
= 12 square cm.

Figure 2 : EFGH Rectangle
Length of the EFGH Rectangle = 5cm
Width of the EFGH Rectangle = 2cm
Area of the EFGH Rectangle = Length  × Width
= 5cm × 2cm
= 10 square cm.

Figure 3 : IJKL Rectangle
Length of the IJKL Rectangle = 6cm
Width of the IJKL Rectangle = 1cm
Area of the IJKL Rectangle = Length  × Width
= 6cm × 1cm
= 6 square cm.

c. Perimeter of the ABCD  rectangle =  2 ( Length + Width )
= 2 ( 4cm + 3cm)
= 2 ×  7cm
= 14 cms.

Perimeter of the EFGH rectangle =  2 ( Length + Width )
= 2 ( 5cm + 2cm)
= 2 ×  7cm
= 14 cms.

Perimeter of the IJKL rectangle =  2 ( Length + Width )
= 2 ( 6cm + 1cm)
= 2 ×  7cm
= 14 cms.
Perimeters of the three rectangles are the same having 14 cms, where as their areas are completely different from each other.
Perimeter requires only the lengths of the four sides of rectangle to be added where as for area we require length and width of the rectangle.

 

Question 2.
Tanner uses unit squares to build rectangles that have a perimeter of 18 units. He creates the chart below to record his findings.
a. Complete Tanner’s chart. You might not use all the spaces in the chart.

Perimeter = 18 units Number of rectangles I made:  _____
Width	Length	Area
1 unit	8 units	8 square units
2 unit	7 unit	14 square units
3 unit	6 unit	18 square units
4 unit	5 unit	20 square units

b. Explain how you found the widths and lengths in the chart above.
Answer:
The chart in itself has the labelling heading of the columns as length and width and their areas.
If not always length value is going to be more than the value of width in the measurements of rectangle.

Explanation:
The chart in itself has the labelling heading of the columns as length and width and their areas. If not always length value is going to be more than the value of width in the measurements of rectangle. This is how I found the widths and lengths in the chart above.

 

 

Question 3.
Jason and Dina both draw rectangles with perimeters of 12 centimeters, but their rectangles have different areas. Explain with words, pictures, and numbers how this is possible.
Answer:

Area of the Jason’s ABCD Rectangle = 8 square cm.
Perimeter of the Jason’s ABCD Rectangle = 12 cm.
Area of the Dina’s EFGH Rectangle = 5 square cm.
Perimeter of the Dina’s EFGH Rectangle = 12 cm.
Perimeter requires only the lengths of the four sides of rectangle to be added where as for area we require length and width of the rectangle. Jason’s ABCD rectangle and Dina’s EFGH rectangle are having same perimeter yet different areas.

Explanation:
Jason’s ABCD Rectangle:
Length of the Jason’s ABCD Rectangle = 4cm
Width of the Jason’s ABCD Rectangle = 2cm
Area of the Jason’s ABCD Rectangle = Length × Width
= 4cm ×  2cm
= 8 square cm.
Perimeter of the Jason’s ABCD Rectangle = 2 ( Length + Width )
= 2 ( 4cm + 2cm )
= 2 × 6cm
= 12 cm.

Dina’s EFGH Rectangle:
Length of the Dina’s EFGH Rectangle = 5cm
Width of the Dina’s EFGH Rectangle = 1cm
Area of the Dina’s EFGH Rectangle = Length × Width
= 5cm ×  1cm
= 5 square cm.
Perimeter of the Dina’s EFGH Rectangle = 2 ( Length + Width )
= 2 ( 5cm + 1cm )
= 2 × 6cm
= 12 cm.
Jason’s ABCD rectangle and Dina’s EFGH rectangle are having same perimeter yet different areas.

 

 

 

Eureka Math Grade 3 Module 7 Lesson 21 Data Sheet Answer Key

Use the data you gathered from Problem Sets 20 and 21 to complete the charts to show how many rectangles you can create with a given perimeter. You might not use all the spaces in the charts.

Perimeter = 10 units Number of rectangles you made:  _1____
Width	Length	Area
1 unit	4 units	4 square units
2 units	3 units	6 square units

Perimeter = 12 units Number of rectangles you made:  _2____
Width	Length	Area
1 unit	5 units	5 square units
2 units	4 units	8 square units

Perimeter = 14 units Number of rectangles you made:  __3___
Width	Length	Area
1 unit	6 units	6 square units
2 units	5 units	10 square units
3 units	4 units	12 square units

Perimeter = 16 units Number of rectangles you made:  __4___
Width	Length	Area
1 unit	7 units	7 square units
2 units	6 units	12 square units
3 units	5 units	15 square units
4 units	4 units	16 square units

Perimeter = 18 units Number of rectangles you made:  _4____
Width	Length	Area
1 unit	8 units	8 square units
2 units	7 units	14 square units
3 units	6 units	18 square units
4 units	5 units	20 square units

Perimeter = 20 units Number of rectangles you made:  __3___
Width	Length	Area
2 units	8 units	16 square units
4 units	6 units	24 square units
3 units	7 units	21 square units

Engage NY Eureka Math 3rd Grade Module 1 Lesson 17 Answer Key

Eureka Math Grade 3 Module 1 Answer Key

Eureka Math Grade 3 Module 1 Lesson 17 Sprint Answer Key

A
Multiply or Divide by 4

Explanation:
Multiplied or divided the given number by 4,
as shown above.

B
Multiply or Divide by 4

Eureka Math Grade 3 Module 1 Lesson 17 Problem Set Answer Key

Question 1.
Use the array to complete the related equations.

Explanation:
Used the array to complete the related equations as shown above and as
1 X 4 = 4,   4 ÷ 4 = 1,
2 X 4 = 8,   8 ÷ 4 = 2,
3 X 4 = 12, 12 ÷ 4 = 3,
4 X 4 = 16, 16 ÷ 4 = 4,
5 X 4 = 20, 20 ÷ 4 = 5,
6 X 4 = 24, 24 ÷ 4 = 6,
7 X 4 = 28, 28 ÷ 4 = 7,
8 X 4 = 32, 32 ÷ 4 = 8,
9 X 4 = 36, 36 ÷ 4 = 9,
10 X 4 = 40, 40 ÷ 4 = 10.

Question 2.
The baker packs 36 bran muffins in boxes of 4.
Draw and label a tape diagram to find the number of boxes he packs.

The baker packs 9 boxes of muffins,

Explanation:
The baker packs 36 bran muffins in boxes of 4.
Drawn and labeled a tape diagram,
The number of boxes baker packs is 36 ÷ 4 = 9 boxes.
Therefore, the baker packs 9 boxes of muffins.

Question 3.
The waitress arranges 32 glasses into 4 equal rows.
How many glasses are in each row?

There are 8 glasses in each row,

Explanation:
Given the waitress arranges 32 glasses into 4 equal rows.
Number of glasses in each row are 32 ÷ 4 = 8 (8 X 4 = 32),
Therefore, there are 8 glasses in each row.

Question 4.
Janet paid $28 for 4 notebooks. Each notebook costs the same amount.
What is the cost of 2 notebooks?

The cost of 2 notebooks is $14,

Explanation:
Given Janet paid $28 for 4 notebooks and each
notebook costs the same amount, So cost of each
notebook is $28 ÷ 4 = $7 (4 X 7 = 28),
Now cost for 2 notebooks is 2 X $7 = $14.

Eureka Math Grade 3 Module 1 Lesson 17 Exit Ticket Answer Key

Question 1.
Mr. Thomas organizes 16 binders into stacks of 4.
How many stacks does he make? Draw and label a
number bond to solve.

Mr. Thomas makes 4 stacks of 4,

Explanation:
Given Mr. Thomas organizes 16 binders into stacks of 4.
So number of stacks does he make are 16 ÷ 4 = 4 ( 4 X 4 = 16),
Drawn and labeled a number bond to solve number of stacks
Mr. Thomas makes as shown above in the picture.

Question 2.
The chef uses 28 avocados to make 4 batches of guacamole.
How many avocados are in 2 batches of guacamole?
Draw and label a tape diagram to solve.

In 2 batches of guacamole the chef uses 14 avocados,

Explanation:
Given the chef uses 28 avocados to make 4 batches of guacamole.
So number of avocados in one batch of guacamole are
28 ÷ 4 =7 (7 X 4 = 28),
Now number of avocados are in 2 batches of guacamole are
2 X 7 = 14 avocados.
Drawn and labeled a tape diagram as shown above.

Eureka Math Grade 3 Module 1 Lesson 17 Homework Answer Key

Question 1.
Use the array to complete the related equations.

Explanation:
Used the array to complete the related equations as shown above and as
1 X 4 = 4,   4 ÷ 4 = 1,
2 X 4 = 8,   8 ÷ 4 = 2,
3 X 4 = 12, 12 ÷ 4 = 3,
4 X 4 = 16, 16 ÷ 4 = 4,
5 X 4 = 20, 20 ÷ 4 = 5,
6 X 4 = 24, 24 ÷ 4 = 6,
7 X 4 = 28, 28 ÷ 4 = 7,
8 X 4 = 32, 32 ÷ 4 = 8,
9 X 4 = 36, 36 ÷ 4 = 9,
10 X 4 = 40, 40 ÷ 4 = 10.

Question 2.
The teacher puts 32 students into groups of 4.
How many groups does she make? Draw and label a
tape diagram to solve.

Teacher makes 8 groups,

Explanation :
Given the teacher puts 32 students into groups of 4.
Teacher makes 32 ÷ 4 = 8 (4 X 8 = 32) groups,
Drawn and labeled tape diagram to solve number of
groups teacher has made.

Question 3.
The store clerk arranges 24 toothbrushes into 4 equal rows.
How many toothbrushes are in each row?

In each row there are 6 toothbrushes,

Explanation:
Given the store clerk arranges 24 toothbrushes into 4 equal rows.
So number of toothbrushes in each row are 24 ÷ 4 = 6 (6 X 4 = 24).

Question 4.
An art teacher has 40 paintbrushes. She divides them equally
among her 4 students. She finds 8 more brushes and divides
these equally among the students, as well. How many brushes
does each student receive?

Each student will receive 12 paintbrushes,

Explanation:
Given An art teacher has 40 paintbrushes. She divides them equally
among her 4 students. She finds 8 more brushes and divides
these equally among the students, as well.
So number of brushes she has 40 + 8 = 48 brushes,
Now number of brushes each student will receive are
48 ÷ 4 = 12 ( 12 X 4 = 48).
Therefore, each student will receive 12 paintbrushes.