Eureka Math Grade 7 Module 6 Lesson 1 Answer Key

Engage NY Eureka Math 7th Grade Module 6 Lesson 1 Answer Key

Eureka Math Grade 7 Module 6 Lesson 1 Example Answer Key

Example 1.
The measures of two supplementary angles are in the ratio of 2:3. Find the measurements of the two angles.
Answer:
Engage NY Math 7th Grade Module 6 Lesson 1 Example Answer Key 1
2x + 3x = 180
5x = 180
(\(\frac{1}{5}\))5x = (\(\frac{1}{5}\))180
x = 36
Angle 1 = 2(36)° = 72°
Angle 2 = 3(36)° = 108°

Example 2.
Two lines meet at a point that is also the vertex of an angle. Set up and solve an appropriate equation for x and y.
Engage NY Math 7th Grade Module 6 Lesson 1 Example Answer Key 2
Answer:
16 + y = 90 Complementary angles
16 – 16 + y = 90-16
y = 74

x + (74) = 180 Supplementary angles
x + 74 – 74 = 180 – 74
x = 106

Eureka Math Grade 7 Module 6 Lesson 1 Exercise Answer Key

Exercise 1.
In a complete sentence, describe the relevant angle relationships in the diagram. Write an equation for the angle relationship shown in the figure and solve for x. Confirm your answers by measuring the angle with a protractor.
Engage NY Math Grade 7 Module 6 Lesson 1 Exercise Answer Key 1
Answer:
The angles x° and 22° are supplementary and sum to 180°.
x + 22 = 180
x + 22 – 22 = 180 – 22
x = 158
The measure of the angle is 158°.

Exercise 2.
In a pair of complementary angles, the measurement of the larger angle is three times that of the smaller angle. Find the measurements of the two angles.
Answer:
x + 3x = 90
4x = 90
(\(\frac{1}{4}\))4x = (\(\frac{1}{4}\))90
x = 22.5
Angle 1 = 22.5°
Angle 2 = 3(22.5)° = 67.5°

Exercise 3.
The measure of a supplement of an angle is 6° more than twice the measure of the angle. Find the measurement of the two angles.
Answer:
x + (2x + 6) = 180
3x + 6 = 180
3x + 6 – 6 = 180 – 6
3x = 174
(\(\frac{1}{3}\))3x = (\(\frac{1}{3}\))174
x = 58
Angle 1 = 58°
Angle 2 = 2(58)° + 6° = 122°

Exercise 4.
The measure of a complement of an angle is 32° more than three times the angle. Find the measurement of the two angles.
Answer:
x + (3x + 32) = 90
4x + 32 – 32 = 90 – 32
4x = 58
(\(\frac{1}{4}\))4x = (\(\frac{1}{4}\))58
x = 14.5
Angle 1 = 14.5°
Angle 2 = 3(14.5)° + 32° = 75.5°

Scaffolding solutions:
a. The x° angle and the 22° angle are supplementary and sum to 180°.
b. x + 22 = 180
c. The equation shows that an unknown value, x (which is the unknown angle in the diagram) plus 22 is equal to 180. The 22 represents the angle that we know, which is 22 degrees.
d.
x + 22 = 180
x + 22 – 22 = 180 – 22
x = 158
x = 158 means that in the diagram, the missing angle measures 158°.
The answer of 158° is correct. If we substitute 158 for x, we get 158 + 22 = 180, which is a true number sentence. This is reasonable because when we look at the diagram, we would expect the angle to be obtuse.

Eureka Math Grade 7 Module 6 Lesson 1 Problem Set Answer Key

Question 1.
Two lines meet at a point that is also the endpoint of a ray. Set up and solve the appropriate equations to determine x and y.
Eureka Math 7th Grade Module 6 Lesson 1 Problem Set Answer Key 1
Answer:
x + 55 = 90 Complementary angles
x + 55 – 55 = 90 – 55
x = 35

55 + y = 180 Supplementary angles
55 – 55 + y = 180 – 55
y = 125

Question 2.
Two lines meet at a point that is also the vertex of an angle. Set up and solve the appropriate equations to determine x and y.
Eureka Math 7th Grade Module 6 Lesson 1 Problem Set Answer Key 2
Answer:
y + x = 90 Complementary angles

x + 32 = 90 Complementary angles
x + 32 – 32 = 90 – 32
x = 58

y + (58) = 90 Complementary angles
y + 58 – 58 = 90 – 58
y = 32

Question 3.
Two lines meet at a point that is also the vertex of an angle. Set up and solve an appropriate equation for x and y.
Eureka Math 7th Grade Module 6 Lesson 1 Problem Set Answer Key 3
Answer:
x + y = 180 Supplementary angles

28 + y = 90 Complementary angles
28 – 28 + y = 90 – 28
y = 62

x + (62) = 180 Supplementary angles
x + 62-62 = 180 – 62
x = 118

Question 4.
Set up and solve the appropriate equations for s and t.
Eureka Math 7th Grade Module 6 Lesson 1 Problem Set Answer Key 4
Answer:
79 + t = 90 Complementary angles
79 – 79 + t = 90 – 79
t = 11

19 + (11) + 79 + s = 180 Angles on a line
109 + s = 180
109 – 109 + s = 180 – 109
s = 71

Question 5.
Two lines meet at a point that is also the endpoint of two rays. Set up and solve the appropriate equations for m and n.
Eureka Math 7th Grade Module 6 Lesson 1 Problem Set Answer Key 5
Answer:
43 + m = 90 Complementary angles
43-43 + m = 90-43
m = 47

38 + 43 + (47) + n = 180 Angles on a line
128 + n = 180
128-128 + n = 180-128
n = 52

Question 6.
The supplement of the measurement of an angle is 16° less than three times the angle. Find the measurement of the angle and its supplement.
Answer:
x + (3x-16) = 180
4x-16 + 16 = 180 + 16
4x = 196
(\(\frac{1}{4}\))4x = (\(\frac{1}{4}\))196
x = 49
Angle = 49°
Supplement = 3(49)°-16° = 131°

Question 7.
The measurement of the complement of an angle exceeds the measure of the angle by 25%. Find the measurement of the angle and its complement.
Answer:
x + (x + \(\frac{1}{4}\) x) = 90
x + \(\frac{5}{4}\) x = 90
\(\frac{9}{4}\)x = 90
(\(\frac{4}{9}\)) \(\frac{9}{4}\)x = (\(\frac{4}{9}\))90
x = 40
Angle = 40°
Complement = \(\frac{5}{4}\)(40)° = 50°

Question 8.
The ratio of the measurement of an angle to its complement is 1:2. Find the measurement of the angle and its complement.
Answer:
x + 2x = 90
3x = 90
(\(\frac{1}{3}\))3x = (\(\frac{1}{3}\))90
x = 30
Angle = 30°
Complement = 2(30)° = 60°

Question 9.
The ratio of the measurement of an angle to its supplement is 3:5. Find the measurement of the angle and its supplement.
Answer:
3x + 5x = 180
8x = 180
(\(\frac{1}{8}\))8x = (\(\frac{1}{8}\))180
x = 22.5
Angle = 3(22.5)° = 67.5°
Supplement = 5(22.5)° = 112.5°

Question 10.
Let x represent the measurement of an acute angle in degrees. The ratio of the complement of x to the supplement of x is 2:5. Guess and check to determine the value of x. Explain why your answer is correct.
Answer:
Solutions will vary; x = 30°.
The complement of 30° is 60°. The supplement of 30° is 150°. The ratio of 60 to 150 is equivalent to 2:5.

Eureka Math Grade 7 Module 6 Lesson 1 Exit Ticket Answer Key

Question 1.
Set up and solve an equation for the value of x. Use the value of x and a relevant angle relationship in the diagram to determine the measurement of ∠EAF.
Eureka Math Grade 7 Module 6 Lesson 1 Exit Ticket Answer Key 1
Answer:
x + 63 = 90
x + 63 – 63 = 90 – 63
x = 27
∠CAG and ∠EAF are the complements of 63°. The measurement of ∠CAG is 27°; therefore, the measurement of ∠EAF is also 27°.

Question 2.
The measurement of the supplement of an angle is 39° more than half the angle. Find the measurement of the angle and its supplement.
Answer:
x + (\(\frac{1}{2}\)x + 39) = 180
1.5x + 39 = 180
1.5x + 39 – 39 = 180 – 39
1.5x = 141
1.5x ÷ 1.5 = 141 ÷ 1.5
x = 94
The measurement of the angle is 94°.
The measurement of the supplement is \(\frac{1}{2}\)(94)° + 39° = 86°.
OR
x + (\(\frac{1}{2}\)x + 39) = 180
\(\frac{3}{2}\)x + 39 = 180
\(\frac{3}{2}\)x + 39 – 39 = 180 – 39
\(\frac{3}{2}\)x = 141
(\(\frac{2}{3}\))(\(\frac{3}{2}\)x) = (\(\frac{2}{3}\))141
x = 94
The measurement of the angle is 94°.
The measurement of the supplement is \(\frac{1}{2}\)(94)° + 39° = 86°.

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Eureka Math Grade 5 Answer Key | Engage NY Math 5th Grade Answer Key Solutions

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EngageNY Math Grade 5 Answer Key | Eureka Math 5th Grade Answers Key PDF Free Download

Eureka Grade 5 Mathematics Module 1 to Module 6 Lesson-wise Answer key PDF links are provided online to access and download for free of cost. After downloading the Engage NY Math Fifth Grade Solutions Pdf, you can practice more with the help of Mid Module and End Module Assessments, Practice Tools. These resources boost up your confidence and identify your level of preparation and areas your lagging. So, download the Eureka Math Grade 5 Answer Keys for all modules and ace up your preparation.

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Eureka Math Grade 4 Answer Key | Engage NY Math 4th Grade Answer Key Solutions

eureka-math-grade-4-answer-key

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EngageNY Math Grade 4 Answer Key | Eureka Math 4th Grade Answers Key PDF Free Download

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Eureka Math Answer Key for Grades Pre K – 12 | Engage NY Math Book Answers for Grades Pre K, K, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12

eureka-math-answer-key-for-grades-pre-k-k-1-2-3-4-5-6-7-8-algebra-geometry-precalculus

Eureka Math Answer Key provided drives equity and sparks the student’s love for math. Eureka Math Book Solutions provided are built by subject experts adhering to today’s fluid learning environment. You can access these resources whenever you need them anytime and anywhere. Download the Eureka Math Solutions for Grades Pre K -12 in PDF format and make your toggling between homework and classroom quite seamless.

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EngageNY Math Answers Free Download | Great Minds Eureka Math Answer Key

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Elementary School Eureka Math Answers

Intermediate School Eureka Math Answers

High School/Commencement Level Eureka Math Answers

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Eureka Math Grade 3 Module 6 End of Module Assessment Answer Key

Engage NY Eureka Math 3rd Grade Module 6 End of Module Assessment Answer Key

Eureka Math Grade 3 Module 6 End of Module Assessment Task Answer Key

Question 1.
The picture graph below represents all the trees in the park.
Engage NY Math 3rd Grade Module 6 End of Module Assessment Answer Key 1
Use the grid to create and label a scaled bar graph representing the data in the picture graph above.
Engage NY Math 3rd Grade Module 6 End of Module Assessment Answer Key 2
b. How many more maple and oak trees are there than birch trees?
Answer:
a.
Engage-NY-Math-3rd-Grade-Module-6-End-of-Module-Assessment-Answer-Key-2
b. 4 trees
Maple trees =3×4=12
Oka trees =5×4= 20
Birch trees = 7×4=28
Total Maple and Oak trees = 12 + 20 =32
32-28=4

Question 2.
2. The table below shows the number of flowers that were planted by the science club.
a. Complete the table by filling in the number of marigolds that were planted.

Flowers Planted by Science Club

Type of FlowerNumber Planted
Roses24
Lilies12
Marigolds________
TOTAL Flowers Planted:54

b. Use the lines below to create and label a picture graph using the data in the table. Determine a picture and scale to represent the number of each type of flower.
Engage NY Math 3rd Grade Module 6 End of Module Assessment Answer Key 3
Answer:
a.18
Explanation:
24+12+x=54
36+x=54
x=54-36
x=18
Engage-NY-Math-3rd-Grade-Module-6-End-of-Module-Assessment img 2
b.Engage-NY-Math-3rd-Grade-Module-6-End-of-Module-Assessment-Answer-Key-3

Question 3.
Fred measures the heights of all the sunflowers in his backyard. His measurements in inches are shown on the line plot below.
Engage NY Math 3rd Grade Module 6 End of Module Assessment Answer Key 4
a. How many sunflowers are in Fred’s backyard? Explain how you know.
b. What are the three most frequent measurements on the line plot? Write them in order from shortest to longest.
Answer:
a. 18
The plot shoes that x= one sunflower
and ther are total of 18 x’s in the plot whuch mean thet there are total of 18 sunflowers
b.The three most frequent measurements on the line plot are 20\(\frac{1}{2}\),19\(\frac{1}{2}\) ,19\(\frac{3}{4}\).
Where
19\(\frac{3}{4}\) = 3 sunflowers
19\(\frac{1}{2}\) = 4 sunflowers
20\(\frac{1}{2}\) = 5 sunflowers

Question 4.
Carol measures 16 bamboo shoots. Her measurements are recorded in the table below.

Heights of Bamboo Shoots (in Inches)

94\(\frac{1}{2}\)94\(\frac{1}{4}\)93\(\frac{3}{4}\)94\(\frac{3}{4}\)
94\(\frac{3}{4}\)9594\(\frac{3}{4}\)95\(\frac{1}{4}\)
94\(\frac{1}{2}\)94\(\frac{3}{4}\)94\(\frac{3}{4}\)94\(\frac{1}{2}\)
9594\(\frac{3}{4}\)94\(\frac{3}{4}\)95

a. Make a line plot of the bamboo shoot data. Explain your choice of scale.
b. How many more bamboo shoots measured 94\(\frac{3}{4}\) inches than both 95 and 94\(\frac{1}{2}\) inches combined?
Answer:
a.The recordings vary from 93\(\frac{3}{4}\) to 95\(\frac{1}{4}\)
There by the line plot scale is considered from 93\(\frac{3}{4}\) to 95\(\frac{1}{4}\)
Engage-NY-Math-Grade-3-Module-6-Lesson-7-Problem
b.  1 more Bambbo shoot
Number of Bamboo shoots measured 94\(\frac{3}{4}\) inches = 7 Bamboo shoots
Number of Bamboo shoots measured combines of 95 and 94\(\frac{1}{2}\) inches =6 Bamboo shoots
Explanation:
7-6=1

Eureka Math Grade 3 Module 6 Answer Key

Eureka Math Grade 3 Module 6 Lesson 9 Answer Key

Engage NY Eureka Math 3rd Grade Module 6 Lesson 9 Answer Key

Eureka Math Grade 3 Module 6 Lesson 9 Pattern Sheet Answer Key

Multiply.
Engage NY Math 3rd Grade Module 6 Lesson 9 Sprint Answer Key 1
Engage NY Math 3rd Grade Module 6 Lesson 9 Sprint Answer Key 2
multiply by 7 (6–10)
Answer:
Engage-NY-Math-3rd-Grade-Module-6-Lesson-8-Pattern-Sheet-Answer-Key-1

Eureka Math Grade 3 Module 6 Lesson 9 Problem Set Answer Key

Question 1.
Four children went apple picking. The chart shows the number of apples the children picked.

Name

Number of Apples Picked

Stewart16
Roxanne______
Trisha12
Philip20
Total:                 72

a. The number of apples Roxanne picked to complete the chart is 24
Engage-NY-Math-3rd-Grade-Module-6-Lesson-8-Pattern-Sheet-Answer-Key-2

b. Create a picture graph below using the data in the table.
Engage NY Math Grade 3 Module 6 Lesson 9 Problem Set Answer Key p 1
Answer:
Engage-NY-Math-Grade-3-Module-6-Lesson-9-Problem-Set-Answer-Key-p-1

Question 2.
Use the chart or graph to answer the following questions.
a. How many more apples did Stewart and Roxanne pick than Philip and Trisha?
b. Trisha and Stewart combine their apples to make apples pies. Each pie takes 7 apples. How many pies can they make?
Answer:
a. eight more apples Stewart and Roxanne pick than Philip and Trisha
b. Trisha and Stewart combine their apples to make apples pies. Each pie takes 7 apples.  they can make are 5 pies

Question 3.
Ms. Pacho’s science class measured the lengths of blades of grass from their school field to the nearest \(\frac{1}{4}\) inch. The lengths are shown below.

Lengths of Blades of Grass (in Inches)

2\(\frac{1}{4}\)2\(\frac{3}{4}\)3\(\frac{1}{4}\)32\(\frac{1}{2}\)2\(\frac{3}{4}\)
2\(\frac{3}{4}\)3\(\frac{3}{4}\)22\(\frac{3}{4}\)3\(\frac{3}{4}\)3\(\frac{1}{4}\)
32\(\frac{1}{2}\)3\(\frac{1}{4}\)2\(\frac{1}{4}\)2\(\frac{3}{4}\)3
3\(\frac{1}{4}\)2\(\frac{1}{4}\)3\(\frac{3}{4}\)33\(\frac{1}{4}\)2\(\frac{3}{4}\)

a. Make a line plot of the grass data. Explain your choice of scale.
b. How many blades of grass were measured? Explain how you know.
c. What was the length measured most frequently on the line plot? How many blades of grass had this length?
d. How many more blades of grass measured 2\(\frac{3}{4}\) inches than both 3\(\frac{3}{4}\) inches and 2 inches combined?
Answer:
a. The recordings vary from 2 to 3\(\frac{3}{4}\)
So the scale vary from 2 to 3\(\frac{3}{4}\)
Engage-NY-Math-Grade-3-Module-6-Lesson-7-Problem 1 img
b. 27 blades of grass were measured because each X in the plot indicates a blades of grass.
c. 2\(\frac{3}{4}\) length measured most frequently on the line plot.
6 blades of grass had this length
d. 2 more
Explination:
3\(\frac{3}{4}\) inches and 2 inches combined = 3+1 = 4
2\(\frac{3}{4}\) = 6
6-4=2

Eureka Math Grade 3 Module 6 Lesson 9 Exit Ticket Answer Key

Mr. Gallagher’s science class goes bird watching. The picture graph below shows the number of birds the class observes.
Eureka Math 3rd Grade Module 6 Lesson 9 Exit Ticket Answer Key t 1
a. How many more birds did Mr. Gallagher’s class observe on Wednesday and Thursday than on Monday and Tuesday?
b. Mr. Manning’s class observed 104 birds. How many more birds did Mr. Gallagher’s class observe?
Answer:
a. 12 more birds
Birds observed on Wednes day and Thursday = (5×6)+(5×6) = 30+30 =60
Birds observed on Monday and Tuesday  = (4×6)+(4×6) = 24+24 =48
60-48=12
b. 4 more birds
Explination:
Mr. Manning’s class observed =104 birds
Mr. Gallagher’s class observe:
(4×6)+(4×6)+(5×6)+(5×6)=24+24+30+30=108 birds
108-104=4

Eureka Math Grade 3 Module 6 Lesson 9 Homework Answer Key

Question 1.
The table below shows the amount of money Danielle saves for four months.

Month

Money Saved

January$9
February$18
March$36
April$27

Create a picture graph below using the data in the table.
Eureka Math Grade 3 Module 6 Lesson 9 Homework Answer Key h 1
Answer:
Eureka-Math-Grade-3-Module-6-Lesson-9-Homework-Answer-Key-h-1

Question 2.
2. Use the table or graph to answer the following questions.
a. How much money does Danielle save in four months?
b. How much more money does Danielle save in March and April than in January and February?
c. Danielle combines her savings from March and April to buy books for her friends. Each book costs $9. How many books can she buy?
d. Danielle earns $33 in June. She buys a necklace for $8 and a birthday present for her brother. She saves the $13 she has left. How much does the birthday present cost?
Answer:
a.$90
Explination:
$9+$18+$36+$27 =$90
b. $36 more
Explination:
Total amount saved on March and April combined = $9+$18 =$27
Total amount saved on January  and February combined = $36+$27 =$63
$63-$27 =$36
c. 3 books
Explination:
Given:
Savings of March and April = $27
One book cost = $9
Therefor
$9+$9+$9=$27
d. $12
Explination:
Given:
Necklace cost = $8
Saved amount = $13
Total earning of june =$33
There by
$8+$13+x=$33
$21+x=$33
x=$33-$21
x=$12

Eureka Math Grade 3 Module 6 Answer Key

Eureka Math Grade 3 Module 6 Lesson 8 Answer Key

Engage NY Eureka Math 3rd Grade Module 6 Lesson 8 Answer Key

Eureka Math Grade 3 Module 6 Lesson 8 Pattern Sheet Answer Key

Multiply.
Engage NY Math 3rd Grade Module 6 Lesson 8 Pattern Sheet Answer Key 1
Engage NY Math 3rd Grade Module 6 Lesson 8 Pattern Sheet Answer Key 2
multiply by 7 (1–5)
Answer:
Engage-NY-Math-3rd-Grade-Module-6-Lesson-8-Pattern-Sheet-Answer-Key-1

Eureka Math Grade 3 Module 6 Lesson 8 Problem Set Answer Key

Question 1.
Delilah stops under a silver maple tree and collects leaves. At home, she measures the widths of the leaves to the nearest \(\frac{1}{4}\) inch and records the measurements as shown below.

Widths of Silver Maple Tree Leaves (in Inches)

5\(\frac{3}{4}\)66\(\frac{1}{4}\)65\(\frac{3}{4}\)
6\(\frac{1}{2}\)6\(\frac{1}{4}\)5\(\frac{1}{2}\)5\(\frac{3}{4}\)6
6\(\frac{1}{4}\)666\(\frac{1}{2}\)6\(\frac{1}{4}\)
6\(\frac{1}{2}\)5\(\frac{3}{4}\)6\(\frac{1}{4}\)66\(\frac{3}{4}\)
66\(\frac{1}{4}\)65\(\frac{3}{4}\)6\(\frac{1}{2}\)

a. Use the data to create a line plot below.
b. Explain the steps you took to create the line plot.
c. How many more leaves were 6 inches wide than 6\(\frac{1}{2}\) inches wide?
d. Find the three most frequent measurements on the line plot. What does this tell you about the typical width of a silver maple tree leaf?
Answer:
a. line plot below
Eureka-Math-Grade-3-Module-6-Lesson-7-Homework-Answer-Key-h-2 f
b. The steps you took to create the line plot
To create a line plot, ​first, create a number line that includes all the values in the data set. Next, place an X  above each data value on the number line. If a value occurs more than once in a data set, place ​an Xs​ over that number for each time it occurs.
c. There are eight more leaves that were 6 inches wide than 6\(\frac{1}{2}\) inches wide
d. The three most frequent measurements on the line plot are 6 inches leaves and 6\(\frac{1}{4}\) inches leaves. this tell you about the typical width of a silver maple tree leaf are there are most frequent measurements on the line plot are 6 inches leaves and 6\(\frac{1}{4}\) inches leaves

Eureka Math Grade 3 Module 6 Lesson 8 Exit Ticket Answer Key

Question 1.
The line plot below shows the lengths of fish the fishing boat caught.
Lengths of Fish
Eureka Math 3rd Grade Module 6 Lesson 8 Exit Ticket Answer Key t 1
a. Find the three most frequent measurements on the line plot.
b. Find the difference between the lengths of the longest and shortest fish.
c. How many more fish were 23\(\frac{1}{4}\) inches long than 24 inches long?
Answer:
a. The three most frequent measurements on the line plot are 23\(\frac{1}{4}\) and 23\(\frac{1}{2}\)
b. The difference between the lengths of the longest and shortest fish is longest fish length is 2 inches as the longest fish length is 24 inches and the shortest fish length is 22 inches
c. There are 3 more fish were 23\(\frac{1}{4}\) inches longer than 24 inches long?

Eureka Math Grade 3 Module 6 Lesson 8 Homework Answer Key

Question 1.
Mrs. Leah’s class uses what they learned about simple machines to build marshmallow launchers. They record the distances their marshmallows travel in the chart below.

Distance Traveled (in Inches)

48\(\frac{3}{4}\)4949\(\frac{1}{4}\)5049\(\frac{3}{4}\)
49\(\frac{1}{2}\)48\(\frac{1}{4}\)49\(\frac{1}{2}\)48\(\frac{3}{4}\)49
49\(\frac{1}{4}\)49\(\frac{3}{4}\)4849\(\frac{1}{4}\)48\(\frac{1}{4}\)
4948\(\frac{3}{4}\)494948\(\frac{3}{4}\)

a. Use the data to create a line plot below.
b. Explain the steps you took to create the line plot.
c. How many more marshmallows traveled 48\(\frac{3}{4}\) inches than 48\(\frac{1}{4}\) inches?
d. Find the three most frequent measurements on the line plot. What does this tell you about the distance that most of the marshmallows traveled?
Answer:
a. Used the data to create a line plot below.
Eureka-Math-Grade-3-Module-6-Lesson-7-Homework-Answer-Key-h-2 v
b. The steps you took to create the line plot.
To create a line plot, ​first, create a number line that includes all the values in the data set. Next, place an X  above each data value on the number line. If a value occurs more than once in a data set, place ​an Xs​ over that number for each time it occurs.
c. Two more marshmallows traveled 48\(\frac{3}{4}\) inches than 48\(\frac{1}{4}\) inches
d. The three most frequent measurements on the line plot are 48\(\frac{3}{4}\) and 49. the 49 inches tell you about the distance that most of the marshmallows traveled

Eureka Math Grade 3 Module 6 Answer Key